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Discussion on optical solitons, sensitivity and qualitative analysis to a fractional model of ion sound and Langmuir waves with Atangana Baleanu derivatives

  • Mohammed Aldandani , Syed T. R. Rizvi , Abdulmohsen Alruwaili and Aly R. Seadawy EMAIL logo
Published/Copyright: September 16, 2024

Abstract

This research explores new soliton solutions to the Atangana–Baleanu derivative (ABD) fractional system of equations for ion sound and Langmuir waves (FISLW). We utilize the fractional ABD operator to convert our system into an ordinary differential equations. In recent years, machine learning (ML) evolves significantly in the context of data analysis and computing different solutions, which typically enables systems to operate wisely. Now, we are going to use numerous ML tools including matplotlib. pyplot as plt, scipy.integrate, mpl toolkits.mplot3d, and Axes3D to generate various types of optical solutions by using complete discriminant of the polynomial method. We will also analyze solutions for the hyperbolic function, trigonometric function, Jacobian elliptic function (JEF), and other solitary wave solutions. Solitons have extensive uses in pure and applied mathematics, including nonlinear partial differential equations: the Boussinesq equation, the nonlinear Schrödinger equation, and the sine-Gordon equation, Lie groups, Lie algebras, and differential and algebraic geometry. In addition, we study the chaotic behaviour, i.e., 2D, 3D, time series, Poincarè maps, and sensitivity analysis of our governing model. Sensitivity analysis explores how changes in a system’s variables affects its behaviour.

1 Introduction

Over the past 25 years, investigations on soliton solutions have been one of the most significant research areas. Solitons are solitary waves (SWs) that preserve their form and speed while traveling with a constant velocity. In a number of applied scientific fields, the idea of soliton has been used. By using a technique known as the inverse scattering transform (IST), which is essentially a nonlinear analogue of the Fourier transform for linear partial differential equations, it has been possible to determine that many dynamical systems that are known to be “integrable” have soliton solutions. Currently, integer-order (nonlinear partial differential equations (NLPDEs)) have been used to formulate a variety of real phenomena. Solitons are a useful tool for modelling natural events in almost all engineering problems. The fundamental reason for this is that NLPDEs and nonlinear evolution equations (NLEEs) may be used for modelling each and every natural event that occurs in our environment. These supermodels are investigated in many scientific fields, including physics, optics, engineering, chemistry, and biology. Due to its importance for research and potential applications, nonlinear equations has received a lot of attention in recent years [14]. The nonlocal nonlinear Schrodinger equation (NLSE) governs the propagation of nonlocal nonlinear media in optics. On the other hand, as laser technology has advanced, it has been discovered that angular momentum applies a torque to the beams, there is a lot of interest in the propagation of beams and solitons in strongly nonlocal nonlinear media [58]. Numerous studies have been conducted on the propagation of beams and solitons in strongly nonlocal nonlinear media. Sun et al. investigated the coherent interaction between solitons and airy beams in nonlocal nonlinear media [9]. Shen et al. specifically determined a soliton solution of the nonlocal NLSE in nonlocal nonlinear media employing complex-valued astigmatic cosine-Gaussian in transmission of light intensity patterns and second-order moment beam widths [10]. In Laguerre–Gaussian and Hermite–Gaussian solitons solution, the propagation expression was also produced by Song et al., along with the evaluation of the propagation parameters, which included the axial light intensity, phase change, and intensity distribution [11]. By using nonzero boundary conditions, Zou and Guo methodically provided the IST for the higher-order G-I problem. By resolving the matrix Riemann–Hilbert problem, they have derived the expression for the N-soliton solution with the reflectionless potentials [12]. Shen et al. investigated the propagation properties of complex-valued hyperbolic-cosine-Gaussian beams in strongly nonlocal nonlinear media using the nonlocal nonlinear Schrödinger equation [1315]. Li and Guo looked into semi-rational solutions on periodic backdrops for the coupled Lakshmanan–Porsezian–Daniel equations as well as nonlinear waves such as solitons, breathers, rogue waves, and others. In addition, the dynamic behaviours of various nonlinear waves were investigated along with their interactions [16].

Different methods have been systematized in fractional NLPDEs to identify this type of similarity because it is insufficient to employ integer order when the nonlocal attribute does not show in these forms. Certain derivatives can effectively explain the relationship among the several definitions of fractional derivatives in the local and nonlocal categories. A notable benefit of fractional derivatives is their ability to adjust the memories, inheritance characteristics in various materials, and processes. One of the shortcomings of the well-known Riemann–Liouville and Caputo derivatives is the singularity of the kernel in these derivatives [17]. Jeelani et al. choose the Mittag–Leffler nonsingular function as the fractional derivative kernel [18]. This function is important in the theory of fractional calculus [19]. Using various integration strategies like ( ϕ 6 )-model expansion [20], ( G G )-expansion [21], tan( Φ ( ρ ) 2 )-expansion [22], Kudryashove scheme [23], exp( ( Ψ Ψ ) η )-expansion [24], extended auxiliary equation technique [25], and so on, these operators have been used to estimate the precise and numerical solutions of fractional order NLPDEs. Li et al. used the Riemann–Hilbert method to solve the cauchy problem of the general N-soliton solutions. They utilized parameter modulation to examine their multisoliton solutions in depth like parallel propagation, elastic collision, soliton reflection, time-periodic propagation, and (space, time)-periodic propagation. Several hypotheses regarding the dynamic characteristics of N-soliton solutions were observed. Several extremely amazing characteristics of integral NLEE included traveling wave solutions, which typically took the shape of SWs, precise N-soliton solutions, bilinear forms, and bi-Hamiltonian structures [26]. Li et al. discussed the Cauchy problem of the Wadati–Konno–Ichikawa (WKI) equation for asymptotic stability of N-soliton and their resolution with finite density initial data [27]. They also studied the WKI and complex short equations with -steepest descent method having initial conditions in weighted Sobolev space H ( R ) [28,29]. In this article, we consider fractional system of equations for ion sound and Langmuir waves (FISLW) model as follows [30]:

(1) i D t β AB a + 1 2 a x x b a = 0 , D 2 AB β t b b x x 2 ( a 2 ) x x = 0 , t > 0 , 0 < β 1 ,

where a e i α q t and b , respectively, represent the normalized electric field of the intensity disturbance and the wavelength of the Langmuir oscillation. Normalized variables are x and t , and D t β AB is the AB fractional operator in the t direction. The definition of an Atangana–Baleanu derivative (ABD) operator is as follows:

(2) D c + β ABD P ( t ) = Z ( β ) 1 β d d t c t P ( x ) F β β ( t β ) β 1 β d x ,

F β is the Mittag–Leffler function, defined as follows:

(3) F β β ( t β ) β 1 β = n = 0 β 1 β g ( t x ) β g Γ ( β g + 1 ) ,

Z ( β ) is a normalized function, which satisfies Z ( 1 ) = Z ( 0 ) = 1 . Since, we have

(4) D c + β ABD P ( t ) = Z ( β ) 1 β n = 0 β 1 β g ( I β β g RL P ( t ) ) .

For further information on this operator’s properties, this leads to the following form:

(5) a ( x , t ) = h ( u ) e i γ , b ( x , t ) = j ( u ) ,

where γ = c x + α ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) , u = l x + ζ ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) , and β , α are arbitrary constants.

(6) 1 2 l 2 h + i ( ζ + c l ) h 1 2 ( c 2 + 2 α ) h h j = 0 , ( ζ 2 l 2 ) h 4 l 2 ( h 2 + h h ) = 0 ,

where h and j are the function of u . Now by solving imaginary part of above first equation we have

(7) ζ + c l = 0 , ζ = c l ,

and finally, by integrating the second part of Eq. (6) twice with respect to u , we obtain

(8) j = 2 l 2 h 2 l 2 + ζ 2 = 2 h 2 c 2 1 ,

Eqs (7) and (8) alter Eq. (6) into the following form:

(9) h 4 h 3 l 2 ( c 2 1 ) ( c 2 + 2 α ) h l 2 = 0 ,

The objective of our current work is to apply the complete discriminant of the polynomial method (CDSPM) approach via machine learning (ML) technologies to find exact solutions of Eq. (1), sensitivity analysis and Quasi periodic behaviour through the usage of several Python packages [31,32]. A subfield of computer science is called ML. Nowadays, everything is linked to a data source, and our entire life is digitally recorded because we are living in the era of data. The fundamentals of various ML approaches in a wide range of real-world application areas, including e-commerce, health care, agriculture, smart cities, cyber security, and among many others. The two primary goals of ML are to streamline model-related data and generate future outcomes that are predicted by these models. Mainly, the quality and attributes of the data as well as the functionality of the learning algorithms determine how successful and efficient a ML solution is. To improve the organization and depiction of our model, we offer a thorough overview of the many kinds of ML techniques in this work.

The remaining part of this article is arranged as follows: Section 3 examines the quasi-periodic behaviour of the governing model; sensitivity analysis is presented in Section 4; exact and solitary wave solutions are offered in Sections 6 and 7; a detailed explanation of the results is provided in Section 8; and a summary of the study is given in Section 9.

2 Analysis of the method

To determine the soliton solutions of NLPDEs, we give a brief overview of CDSPM, that has been utilized to solve numerous nonlinear models [33,34]. first, consider NLPDE:

(10) M ( Θ , Θ t , Θ x x , ) = 0 .

Step 1: By using the transformation Θ ( x , t ) = Θ ( ε ) exp i κ , and ε = x ω t . We have the following ordinary differential equation (ODE):

(11) M ( Θ , Θ , Θ , ) = 0 ,

Step 2: After various modifications, the previously mentioned nonlinear ODE is reduced to the following ODE form:

(12) ( Θ ) 2 = Θ 4 + q 2 Θ 2 + q 1 Θ + q 0 ,

The integral form is as follows:

(13) ± ( ε ε 0 ) = d Θ Θ 4 + q 2 Θ 2 + q 1 Θ + q 0 .

Step 3: Let, P ( Θ ) = Θ 4 + q 2 Θ 2 + q 1 Θ + q 0 . By using CDSPM of fourth-order polynomial, we have

(14) Y 1 = 4 , Y 2 = q 2 , Y 3 = 2 q 2 3 + 8 q 2 q 0 9 q 1 2 , Y 4 = q 2 3 q 1 2 + 4 q 2 2 q 0 + 36 q 2 q 1 2 q 0 32 q 2 2 q 0 27 4 q 1 4 + 63 q 0 3 , Z 2 = 9 q 2 2 32 q 2 q 0 .

It will be possible to categorize the equation’s solutions.

3 Mathematical description

In this section, the first step is integrate after multiply Eq. (6) by h is as follows [3539]:

(15) ( h ) 2 2 h 4 l 2 ( c 2 1 ) ( c 2 + 2 α ) l 2 h 2 2 + G = 0 ,

Now multiply above Eq. (15) by 2 then we have,

(16) ( h ) 2 = 2 h 4 l 2 ( c 2 1 ) + ( c 2 + 2 α ) h 2 l 2 2 G

where G is integration constant. Let a 1 = 2 l 2 ( c 2 1 ) , a 2 = ( c 2 + 2 α ) l 2 , a 4 = 2 G , and a 3 = 0 to determine the fourth degree polynomial qualitative behaviour. Then Eq. (16) becomes:

(17) ( h ) 2 = a 1 h 4 a 2 a 1 h 2 + a 3 a 1 h a 4 a 1 .

Since, above equation transformed is as follows:

(18) ( h ) 2 = a 1 ( h 4 + ξ 2 h 2 + ξ 1 h ξ 0 ) ,

where ξ 2 = a 2 a 1 , ξ 1 = a 3 a 1 , and ξ 0 = a 4 a 1 . The a 1 < 0 and a 1 > 0 cases are now addressed in Eq. (18). Eq. (18)’s integral form is:

(19) d h h 4 + ξ 2 h 2 + ξ 1 h ξ 0 = ± a 1 ( u u 0 ) ,

It contains an integration constant, i.e., u 0 . In this instance, ϒ ( h ) = h 4 + ξ 2 h 2 + ξ 1 h ξ 0 and CDSPM as follows:

(20) E 1 = 4 , E 2 = ξ 2 , E 3 = 2 ξ 2 3 + 8 ξ 2 ξ 0 9 ξ 1 2 , E 4 = ξ 2 3 ξ 1 2 + 4 ξ 2 2 ξ 0 + 36 ξ 2 ξ 1 2 ξ 0 32 ξ 2 2 ξ 0 27 4 ξ 1 4 + 63 ξ 0 3 , F 2 = 9 ξ 2 2 32 ξ 2 ξ 0 .

Here is a representation of the dynamical system of Eq. (18) (Table 1).

(21) h = q ( u ) , q = a 1 ( 4 h 3 2 ξ 2 h + ξ 1 ) ,

Table 1

Regression learner python libraries for qualitative analysis, exact, and SW solutions

Library Usage
Pandas and numpy Data analysis
matplotlib.pyplot as plt Graphical and plotting interface
mpl toolkits.mplot3d Access to further abilities for creating and modifying 3D plots
Axes3D To create and manipulate 3D axes
solve_ivp Designed for resolving first order ode problems easily also for dynamical system
scipy.integrate Offers a platform for conducting multiple approaches of numerical integration

4 Phase patterns for quasi-periodic behaviour

Quasi-periodic behaviour is made up of a number of chaotic and predictable patterns. It occurs when several wave motions are joined mistakenly. For this reason, as compared to a fundamental pattern, the pattern is nonrepeating and intricate. It is not particularly organized, but it’s not as chaotic as chaos either. Through analyzing particular elements of these patterns and identifying a structure within the complexity, we may be able explore more deeply. Sophisticated phase patterns associated with quasi-periodic behaviour provide a unique perspective on dynamic systems [40]. We now explore how the system exhibits quasi-periodic and chaotic behaviour, which is as follows:

(22) h = q ( u ) , q = a 1 ( 4 h 3 2 ξ 2 h + ξ 1 ) + ϖ 0 cos ( ζ ψ ) ,

where a 1 = 2 l 2 ( c 2 1 ) , ξ 2 = a 2 a 1 , ξ 1 = a 3 a 1 , and a 3 = 0 .

Here, ζ indicates the frequency of the disruption and ϖ 0 indicates its strength in the system (22) that was already presented. In system (21), the external periodic force of ϖ 0 cos ( ζ ψ ) , which is present in system (22) is absent and required to examine the periodic and chaotic patterns of Eq. (1). Our approaches for addressing this issue include phase portrait approach, time series profile, and Poincarè maps. To study the problem from various perspectives, we will analyze the influence of the parameters ξ 1 , ξ 2 , a 1 , ϖ 0 , and ζ using two different situations. We keep ξ 1 , ξ 2 , a 1 , and ζ unchanged for the first condition and examine the impact of ϖ 0 . In the other situation, we will examine the effects of changing additional elements: ξ 1 , ξ 2 , and a 1 while maintaining ϖ 0 and ζ constants.

For the following values: a 1 = 0.96 , ξ 2 = 4.28 , ξ 1 = 0 , ϖ 0 = 3.5 , and ζ = 2 π , Figure 1 shows Poincarè maps, 3D, 2D phase plots, and time analysis graphs. System (22) shows up to be functioning quasi-periodically at ϖ 0 = 3.5 . With the same components as shown in Figures 1 and 2 for ϖ 0 = 2.5 shows 2D, 3D plots, time analysis graphs, and Poincarè maps. System (22), for ϖ 0 = 2.5 , seems to exhibit quasi-periodic characteristics. With the following values, a 1 = 3.3 , ξ 2 = 0.28 , ξ 1 = 0 , ϖ 0 = 1.5 , and ζ = 2 π , Figure 3 displays time series profiles, Poincarè maps, and 3D, 2D plots. System (22) appears to demonstrate quasi-periodic features, whereas the Poincarè section includes several disordered points indicating chaotic motion for the parameters that have been specified. While keeping the same value of ϖ 0 = 1.5 , Figure 4 displays time series profiles, 3D and 2D plots, and Poincarè maps for a 1 = 1.96 , ξ 2 = 3.28 , ξ 1 = 0 , and ζ = 2 π . The quasi-periodic pattern of System (22) combines with the chaotic behaviour and significant variety of discontinuous points of the Poincarè map. For a very long period, the chaos has been researched. Poincarè is usually recognized to be the first person to study chaos.

Figure 1 
               Poincarè maps, 3D, 2D phase plots, and time analysis graphs with 
                     
                        
                        
                           
                              
                                 a
                              
                              
                                 1
                              
                           
                           =
                           ‒
                           0.96
                        
                        {a}_{1}=&#x2012;0.96
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 2
                              
                           
                           =
                           4.28
                        
                        {\xi }_{2}=4.28
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 1
                              
                           
                           =
                           0
                        
                        {\xi }_{1}=0
                     
                  , 
                     
                        
                        
                           
                              
                                 ϖ
                              
                              
                                 0
                              
                           
                           =
                           3.5
                        
                        {\varpi }_{0}=3.5
                     
                  , and 
                     
                        
                        
                           ζ
                           =
                           2
                           π
                        
                        \zeta =2\pi 
                     
                  .
Figure 1

Poincarè maps, 3D, 2D phase plots, and time analysis graphs with a 1 = 0.96 , ξ 2 = 4.28 , ξ 1 = 0 , ϖ 0 = 3.5 , and ζ = 2 π .

Figure 2 
               The use of several chaos-detecting techniques for the initial condition (0.08, 1.08) indicates the nonlinear dynamical system (22) for the following values: 
                     
                        
                        
                           
                              
                                 a
                              
                              
                                 1
                              
                           
                           =
                           ‒
                           0.96
                        
                        {a}_{1}=&#x2012;0.96
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 2
                              
                           
                           =
                           4.28
                        
                        {\xi }_{2}=4.28
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 1
                              
                           
                           =
                           0
                        
                        {\xi }_{1}=0
                     
                  , 
                     
                        
                        
                           
                              
                                 ϖ
                              
                              
                                 0
                              
                           
                           =
                           3.5
                        
                        {\varpi }_{0}=3.5
                     
                  , and 
                     
                        
                        
                           ζ
                           =
                           2
                           π
                        
                        \zeta =2\pi 
                     
                  .
Figure 2

The use of several chaos-detecting techniques for the initial condition (0.08, 1.08) indicates the nonlinear dynamical system (22) for the following values: a 1 = 0.96 , ξ 2 = 4.28 , ξ 1 = 0 , ϖ 0 = 3.5 , and ζ = 2 π .

Figure 3 
               Time series profiles, Poincarè maps, and 3D, 2D plots With the following values, 
                     
                        
                        
                           
                              
                                 a
                              
                              
                                 1
                              
                           
                           =
                           ‒
                           3.3
                        
                        {a}_{1}=&#x2012;3.3
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 2
                              
                           
                           =
                           ‒
                           0.28
                        
                        {\xi }_{2}=&#x2012;0.28
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 1
                              
                           
                           =
                           0
                        
                        {\xi }_{1}=0
                     
                  , 
                     
                        
                        
                           
                              
                                 ϖ
                              
                              
                                 0
                              
                           
                           =
                           1.5
                        
                        {\varpi }_{0}=1.5
                     
                  , and 
                     
                        
                        
                           ζ
                           =
                           2
                           π
                        
                        \zeta =2\pi 
                     
                  .
Figure 3

Time series profiles, Poincarè maps, and 3D, 2D plots With the following values, a 1 = 3.3 , ξ 2 = 0.28 , ξ 1 = 0 , ϖ 0 = 1.5 , and ζ = 2 π .

Figure 4 
               Considering the nonlinear dynamical system (22) with the initial condition (1.08, 1.08) determined through numerous chaos-detecting computations for the following values: 
                     
                        
                        
                           
                              
                                 a
                              
                              
                                 1
                              
                           
                           =
                           ‒
                           0.96
                        
                        {a}_{1}=&#x2012;0.96
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 2
                              
                           
                           =
                           4.28
                        
                        {\xi }_{2}=4.28
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 1
                              
                           
                           =
                           0
                        
                        {\xi }_{1}=0
                     
                  , 
                     
                        
                        
                           
                              
                                 ϖ
                              
                              
                                 0
                              
                           
                           =
                           2.5
                        
                        {\varpi }_{0}=2.5
                     
                  , and 
                     
                        
                        
                           ζ
                           =
                           2
                           π
                        
                        \zeta =2\pi 
                     
                  .
Figure 4

Considering the nonlinear dynamical system (22) with the initial condition (1.08, 1.08) determined through numerous chaos-detecting computations for the following values: a 1 = 0.96 , ξ 2 = 4.28 , ξ 1 = 0 , ϖ 0 = 2.5 , and ζ = 2 π .

5 Sensitivity analysis

A mathematical model or system’s output variation or uncertainty can be attributed to modifications or uncertainties in its input variables by using the sensitivity analysis approach. It presents important insights into the functioning of the model and helps decision-makers fully understand the impact of various scenarios and uncertainties [40]. The objective was initially approached from three distinct beginning points: the black curve plots ( h , q ) = ( 0.18 , 0 ) , the blue curve plots ( h , q ) = ( 0.17 , 0 ) , and the red solid line indicates ( h , q ) = ( 0.16 , 0 ) . Maintaining the identical beginning conditions under examination, two distinct situations are investigated.

Now, with a small modification to the beginning values shown in Figures 5 and 6, the outcomes are obtained with the same properties as in the preceding system. This indicates that the outcome is unaffected by even slight changes to the starting conditions. As a result, we observe that the proposed explanation is not very sensitive.

Figure 5 
               Time series, Poincarè maps, and 2D and 3D phase patterns.
Figure 5

Time series, Poincarè maps, and 2D and 3D phase patterns.

Figure 6 
               The approximate values of the nonlinear dynamical system (76) are 
                     
                        
                        
                           
                              
                                 a
                              
                              
                                 1
                              
                           
                           =
                           ‒
                           3.3
                        
                        {a}_{1}=&#x2012;3.3
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 2
                              
                           
                           =
                           ‒
                           0.28
                        
                        {\xi }_{2}=&#x2012;0.28
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 1
                              
                           
                           =
                           0
                        
                        {\xi }_{1}=0
                     
                  , 
                     
                        
                        
                           
                              
                                 ϖ
                              
                              
                                 0
                              
                           
                           =
                           1.5
                        
                        {\varpi }_{0}=1.5
                     
                  , and 
                     
                        
                        
                           ζ
                           =
                           2
                           π
                        
                        \zeta =2\pi 
                     
                  , whereas the initial condition (1.08, 1.08) demonstrates a variety of chaos-detecting strategies.
Figure 6

The approximate values of the nonlinear dynamical system (76) are a 1 = 3.3 , ξ 2 = 0.28 , ξ 1 = 0 , ϖ 0 = 1.5 , and ζ = 2 π , whereas the initial condition (1.08, 1.08) demonstrates a variety of chaos-detecting strategies.

6 Exact solutions

It has been demonstrated by earlier research that periodic and soliton solutions are authentic. Using CDSPM to ascertain the precise solution is the next step. The subsequent nine options are examined in the manner described as follows:

Case 1: If E 2 < 0 , E 3 = 0 , and E 4 = 0 ,

(23) ϒ ( h ) = ( ( h M ) 2 + N 2 ) 2 ,

where a 1 > 0 For, N > 0 putting Eq. (23) into Eq. (19). Then, we obtain

(24) h = M + N tan ( N a 1 ( u u 0 ) ) .

In this way, we evaluate the following solutions

(25) a ( x , t ) = ( M + N tan ( N a 1 ( u u 0 ) ) ) e i γ ,

(26) b ( x , t ) = 2 l 2 l 2 + ζ 2 ( M + N tan ( N a 1 ( u u 0 ) ) ) 2 e i γ ,

where γ = c x + α ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) , u = l x + ζ ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) . Eqs (25) and (26) give triangular periodic solution.

Case 2: E 2 > 0 , E 3 = 0 , E 4 = 0 , and F 2 > 0 . Then,

(27) ϒ ( h ) = ( h R ) 2 ( h S ) 2 ,

where h < S , h > R , a 1 > 0 , and R < S . Since, we obtain

(28) h = S R 2 coth ( S R ) a 1 ( u u 0 ) 2 1 + S ,

when S < h < R , thus, we have

(29) h = S R 2 tanh ( S R ) a 1 ( u u 0 ) 2 1 + S ,

In addition, we reach at the following conclusions:

(30) a ( x , t ) = S R 2 coth ( S R ) a 1 ( u u 0 ) 2 1 + S e i γ .

(31) a ( x , t ) = S R 2 tanh ( S R ) a 1 ( u u 0 ) 2 1 + S e i γ .

(32) b ( x , t ) = 2 l 2 l 2 + ζ 2 S R 2 coth ( S R ) a 1 ( u u 0 ) 2 1 ) + S ) 2 e i γ .

(33) b ( x , t ) = 2 l 2 l 2 + ζ 2 S R 2 tanh ( S R ) a 1 ( u u 0 ) 2 1 ) + S ) 2 e i γ .

Here γ = c x + α ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) , u = l x + ζ ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) .

Eqs (30)–(33) represents SW solitons.

Case 3: E 2 = 0 , E 3 = 0 , and E 4 = 0 . Since,

(34) ϒ ( h ) = h 4 .

Then, we have

(35) h = 1 a 1 ( u 0 u ) 1 ,

where a 1 > 0 . Hence, the following solutions are obtained

(36) a ( x , t ) = 1 a 1 ( u 0 u ) 1 e i γ ,

(37) b ( x , t ) = 2 l 2 l 2 + ζ 2 1 a 1 ( u 0 u ) 1 2 e i γ ,

where γ = c x + α ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) , u = l x + ζ ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) .

Eqs (36) and (37) are a rational function solution.

Case 4: E 2 > 0 , E 3 = 0 , E 4 = 0 , and F 2 = 0 . Thus,

(38) ϒ ( h ) = ( h χ 1 ) 3 ( h χ 2 ) ,

where a 1 < 0 , h > χ 1 , h > χ 2 , or h < χ 1 , h < χ 2 . Hence, we have

(39) h = 4 a 1 ( χ 1 χ 2 ) ( χ 2 χ 1 ) 2 ( u u 0 ) 2 4 + χ 1 ,

(40) h = 4 a 1 ( χ 1 χ 2 ) ( χ 2 χ 1 ) 2 ( u u 0 ) 2 4 + χ 1 .

In addition, we have the following solutions:

(41) a ( x , t ) = 4 a 1 ( χ 1 χ 2 ) ( χ 2 χ 1 ) 2 ( u u 0 ) 2 4 + χ 1 e i γ .

(42) a ( x , t ) = 4 a 1 ( χ 1 χ 2 ) ( χ 2 χ 1 ) 2 ( u u 0 ) 2 4 + χ 1 e i γ .

(43) b ( x , t ) = 2 l 2 l 2 + ζ 2 4 a 1 ( χ 1 χ 2 ) ( χ 2 χ 1 ) 2 ( u u 0 ) 2 4 + χ 1 2 e i γ .

(44) b ( x , t ) = 2 l 2 l 2 + ζ 2 4 a 1 ( χ 1 χ 2 ) ( χ 2 χ 1 ) 2 ( u u 0 ) 2 4 + χ 1 2 e i γ .

Here γ = c x + α ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) , u = l x + ζ ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) .

Eqs (41)–(44) gives rational function solutions.

Case 5: E 2 E 3 < 0 , and E 4 = 0 . Then,

(45) ϒ ( h ) = ( h β 1 ) 2 ( ( h β 2 ) 2 + β 3 2 ) ,

where β 1 , β 2 , and β 3 are real coefficients. Since, we have

(46) h = ( e ± ( β 1 β 2 ) 2 + β 3 2 a 1 ( u u 0 ) ν ) + ( β 1 β 2 ) 2 + β 3 2 ( 2 ν ) ( e ± ( β 1 β 2 ) 2 + β 3 2 a 1 ( u u 0 ) ν ) 2 1 ,

where a 1 > 0 and ν = β 1 2 β 2 ( β 1 β 2 ) 2 + β 3 2 .

(47) a ( x , t ) = ( e ± ( β 1 β 2 ) 2 + β 3 2 a 1 ( u u 0 ) ν ) + ( β 1 β 2 ) 2 + β 3 2 ( 2 ν ) ( e ± ( β 1 β 2 ) 2 + β 3 2 a 1 ( u u 0 ) ν ) 2 1 e i γ ,

(48) b ( x , t ) = 2 l 2 l 2 + ζ 2 × ( e ± ( β 1 β 2 ) 2 + β 3 2 a 1 ( u u 0 ) ν ) + ( β 1 β 2 ) 2 + β 3 2 ( 2 ν ) ( e ± ( β 1 β 2 ) 2 + β 3 2 a 1 ( u u 0 ) ν ) 2 1 2 e i γ ,

where γ = c x + α ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) , u = l x + ζ ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) .

Eqs (47) and (48) represents SW solution.

Case 6: E 2 > 0 , E 3 > 0 , and E 4 > 0 . Since,

(49) ϒ ( h ) = ( h p 1 ) ( h p 2 ) ( h p 3 ) ( h p 4 ) ,

where p 1 > p 2 > p 3 > p 4 , and p 1 , p 2 , p 3 , and p 4 are real numbers. If h > p 1 or h < p 4 , then we obtain

(50) h = p 2 ( p 1 p 4 ) sn 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) , ν p 1 ( p 2 p 4 ) ( p 1 p 4 ) sn 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) , ν ( p 2 p 4 ) .

On the other hand, if p 3 < h < p 2 , then we obtain

(51) h = p 4 ( p 2 p 3 ) sn 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) , ν p 3 ( p 2 p 4 ) ( p 2 p 3 ) sn 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) , ν ( p 2 p 4 ) ,

where a 1 > 0 and ν = ( p 1 p 4 ) ( p 2 p 3 ) ( p 1 p 3 ) ( p 2 p 4 ) . Furthermore, we have the following circumstances:

(52) a ( x , t ) = p 2 ( p 1 p 4 ) sn 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) , ν p 1 ( p 2 p 4 ) ( p 1 p 4 ) sn 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) , ν ( p 2 p 4 ) e i γ ,

(53) a ( x , t ) = p 4 ( p 2 p 3 ) sn 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) , ν p 3 ( p 2 p 4 ) ( p 2 p 3 ) sn 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) , ν ( p 2 p 4 ) e i γ ,

(54) b ( x , t ) = 2 l 2 l 2 + ζ 2 p 2 ( p 1 p 4 ) sn 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) , ν p 1 ( p 2 p 4 ) ( p 1 p 4 ) sn 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) , ν ( p 2 p 4 ) 2 e i γ ,

(55) b ( x , t ) = 2 l 2 l 2 + ζ 2 p 4 ( p 2 p 3 ) sn 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) , ν p 3 ( p 2 p 4 ) ( p 2 p 3 ) sn 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) , ν ( p 2 p 4 ) 2 e i γ ,

where γ = c x + α ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) , u = l x + ζ ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) .

Eqs (52)–(55) solutions represents jacobian elliptic double periodic soliton.

Case 7: E 2 E 3 0 , and E 4 < 0 . Since,

(56) ϒ ( h ) = ( h A ) ( h B ) ( ( h C ) 2 + D 2 ) ,

where A , B , C , and D are all real numbers. If A > B , D > 0 , then

(57) c 1 = 1 2 ( A + B ) d 1 1 2 ( A B ) d 2 , c 2 = 1 2 ( A + B ) d 2 1 2 ( A B ) d 1 , d 1 = A C D s 2 , d 2 = A C D s 2 , s 1 = D 2 + ( A C ) ( B C ) D ( A B ) , s 2 = s 1 ± s 1 2 + 1 .

Since,

(58) h = c 1 cn ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) , ν + c 2 d 1 cn ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) , ν + d 2 ,

where a 1 > 0 , ν = 2 1 + s 2 2 and s 2 > 0 . As a result, we obtain the following solutions:

(59) a ( x , t ) = c 1 cn ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) , ν + c 2 d 1 cn ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) , ν + d 2 e i γ ,

(60) b ( x , t ) = 2 l 2 l 2 + ζ 2 c 1 cn ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) , ν + c 2 d 1 cn ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) , ν + d 2 2 e i γ ,

where γ = c x + α ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) , u = l x + ζ ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) .

Eqs (59) and (60) are jacobian elliptic double periodic soliton.

Case 8: E 2 E 3 0 , and E 4 > 0 . Then,

(61) ϒ ( h ) = ( ( h w 1 ) 2 + w 2 2 ) ( ( h w 3 ) 2 + w 4 2 ) ,

where w 2 w 4 > 0 and w 1 , w 2 , w 3 , and w 3 are real coefficients. Since,

(62) c 1 = w 1 d 1 + w 2 d 2 c 2 = w 1 d 1 w 2 d 2 , d 1 = w 1 w 2 s 2 , d 2 = w 1 w 3 , s 1 = ( w 1 w 3 ) 2 + w 2 2 + w 4 2 2 w 2 w 4 , s 2 = s 1 + s 1 2 1 .

Hence, we obtain

(63) h = c 1 sn ( η a 1 ( u u 0 ) , ν ) + c 2 cn ( η a 1 ( u u 0 ) , ν ) c 2 sn ( η a 1 ( u u 0 ) , ν ) + d 2 cn ( η a 1 ( u u 0 ) , ν ) ,

where a 1 > 0 , ν 2 = s 2 2 1 s 2 2 , and η = w 4 ( d 1 2 + d 2 2 ) ( s 2 2 d 1 2 + d 2 2 ) d 1 2 + d 2 2 . Subsequently, we acquire

(64) a ( x , t ) = c 1 sn ( η a 1 ( u u 0 ) , ν ) + c 2 cn ( η a 1 ( u u 0 ) , ν ) c 2 sn ( η a 1 ( u u 0 ) , ν ) + d 2 cn ( η a 1 ( u u 0 ) , ν ) e i γ ,

(65) b ( x , t ) = 2 l 2 l 2 + ζ 2 c 1 sn ( η a 1 ( u u 0 ) , ν ) + c 2 cn ( η a 1 ( u u 0 ) , ν ) c 2 sn ( η a 1 ( u u 0 ) , ν ) + d 2 cn ( η a 1 ( u u 0 ) , ν ) 2 e i γ ,

where γ = c x + α ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) , u = l x + ζ ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) .

Eqs (64) and (65) are double periodic elliptic function solution.

Case 9: E 3 > 0 , E 4 = 0 , and E 2 > 0 . Since,

(66) ϒ ( h ) = ( h s ) 2 ( h a ) ( h n ) ,

where s = a + n 2 , p = ( s a ) ( s n ) and s , a , and n are real numbers.

If ϒ > a and a > h > n , then

(67) h = 2 p 2 a + ( a n ) sinh ( p a 1 ( u u 0 ) ) ,

and if a 1 > 0 , s > a and s < n , then

(68) h = 2 p 2 a + ( a n ) cosh ( p a 1 ( u u 0 ) ) ,

Consequently, we obtain

(69) a ( x , t ) = 2 p 2 a + ( a n ) sinh ( p a 1 ( u u 0 ) ) e i γ ,

(70) a ( x , t ) = 2 p 2 a + ( a n ) cosh ( p a 1 ( u u 0 ) ) e i γ ,

(71) b ( x , t ) = 2 l 2 l 2 + ζ 2 2 p 2 a + ( a n ) sinh ( p a 1 ( u u 0 ) ) 2 e i γ ,

(72) b ( x , t ) = 2 l 2 l 2 + ζ 2 2 p 2 a + ( a n ) cosh ( p a 1 ( u u 0 ) ) 2 e i γ ,

where γ = c x + α ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) , u = l x + ζ ( 1 β ) t g Z ( β ) n = 0 β 1 β g Γ ( 1 β g ) .

Eqs (69)–(72) give SW solutions.

Conclusions indicate that the CDSPM allows us to immediately offer a variety of solutions in explicit form and characterize the crucial area.

7 The SW solutions

Analyzing multiple exact and precise localized solutions scattered throughout a fiber optic system is an interesting problem. To obtain the SW solution in the aforementioned instance, we convert JEF to hyperbolic and trigonometric functions. In the long-wave limit, the JEF transforms into trigonometric and hyperbolic functions, representing ν 0 and ν 1 , accordingly.

7.1 Double hyperbolic type-I

By using the limit ν 1 in Eqs (52)–(55), it becomes

( sn ) 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) , ν tanh 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) .

The SW solution is provided by [41]:

(73) a ( x , t ) = p 2 ( p 1 p 4 ) tanh 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) p 1 ( p 2 p 4 ) ( p 1 p 4 ) tanh 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) ( p 2 p 4 ) e i γ ,

(74) a ( x , t ) = p 4 ( p 2 p 3 ) tanh 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) p 3 ( p 2 p 4 ) ( p 2 p 3 ) tanh 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) ( p 2 p 4 ) e i γ ,

(75) b ( x , t ) = 2 l 2 l 2 + ζ 2 p 2 ( p 1 p 4 ) tanh 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) p 1 ( p 2 p 4 ) ( p 1 p 4 ) tanh 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) ( p 2 p 4 ) 2 e i γ ,

(76) b ( x , t ) = 2 l 2 l 2 + ζ 2 p 4 ( p 2 p 3 ) tanh 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) p 3 ( p 2 p 4 ) ( p 2 p 3 ) tanh 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) ( p 2 p 4 ) 2 e i γ .

7.2 Double periodic type-I

Containing the limit ν 0 in Eqs. (52)–(55), it turns into

( sn ) 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) , ν sin 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 )

that offer the SW solution [41]:

(77) a ( x , t ) = p 2 ( p 1 p 4 ) sin 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) p 1 ( p 2 p 4 ) ( p 1 p 4 ) sin 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) ( p 2 p 4 ) e i γ ,

(78) a ( x , t ) = p 4 ( p 2 p 3 ) sin 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) p 3 ( p 2 p 4 ) ( p 2 p 3 ) sin 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) ( p 2 p 4 ) e i γ ,

(79) b ( x , t ) = 2 l 2 l 2 + ζ 2 p 2 ( p 1 p 4 ) tanh 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) p 1 ( p 2 p 4 ) ( p 1 p 4 ) sin 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) ( p 2 p 4 ) 2 e i γ ,

(80) b ( x , t ) = 2 l 2 l 2 + ζ 2 p 4 ( p 2 p 3 ) tanh 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) p 3 ( p 2 p 4 ) ( p 2 p 3 ) sin 2 ( p 1 p 3 ) ( p 2 p 4 ) 2 a 1 ( u u 0 ) ( p 2 p 4 ) 2 e i γ .

7.3 Double hyperbolic type-II

By using the limit ν 1 in Eqs. (59) and (60), the function transforms into

cn ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) , ν sech ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) , ν ,

which demonstrates the SW resolution [41]:

(81) a ( x , t ) = c 1 sech ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) + c 2 d 1 sech ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) + d 2 e i γ

(82) b ( x , t ) = 2 l 2 l 2 + ζ 2 c 1 sech ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) + c 2 d 1 sech ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) + d 2 2 e i γ .

7.4 Double periodic type-II SW

By taking limit ν 0 in Eqs (59) and (60), then the function changes into

cn ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) , ν cos ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) , ν ,

which exhibits the SW accuracy [41]:

(83) a ( x , t ) = c 1 cos ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) + c 2 d 1 cos ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) + d 2 e i γ ,

(84) b ( x , t ) = 2 l 2 l 2 + ζ 2 c 1 cos ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) + c 2 d 1 cos ± 2 D s 2 ( A B ) 2 s 2 ν a 1 ( u u 0 ) + d 2 2 e i γ .

7.5 Double hyperbolic type-III

Considering the limit ν 1 in Eqs (64) and (65), the functions turns into

sn ( η a 1 ( u u 0 ) , ν ) tanh ( η a 1 ( u u 0 ) )

and

cn ( η a 1 ( u u 0 ) , ν ) sech ( η a 1 ( u u 0 ) , ν ) ,

and this demonstrates the SW resolution [41]:

(85) a ( x , t ) = c 1 tanh ( η a 1 ( u u 0 ) ) + c 2 sech ( η a 1 ( u u 0 ) ) c 2 tanh ( η a 1 ( u u 0 ) ) + d 2 sech ( η a 1 ( u u 0 ) ) e i γ ,

(86) b ( x , t ) = 2 l 2 l 2 + ζ 2 × c 1 tanh ( η a 1 ( u u 0 ) ) + c 2 sech ( η a 1 ( u u 0 ) ) c 2 tanh ( η a 1 ( u u 0 ) ) + d 2 sech ( η a 1 ( u u 0 ) ) 2 e i γ ,

where η = w 4 ( d 1 2 + d 2 2 ) ( s 2 2 d 1 2 + d 2 2 ) d 1 2 + d 2 2 .

7.6 Double periodic type-III

By using the limit μ 0 in Eqs (64) and (65), the functions turns into

sn ( η a 1 ( u u 0 ) , ν ) sin ( η a 1 ( u u 0 ) )

and

cn ( η a 1 ( u u 0 ) , ν ) cos ( η a 1 ( u u 0 ) , ν ) ,

which indicates the SW solution [41]:

(87) a ( x , t ) = c 1 sin ( η a 1 ( u u 0 ) ) + c 2 cos ( η a 1 ( u u 0 ) ) c 2 sin ( η a 1 ( u u 0 ) ) + d 2 cos ( η a 1 ( u u 0 ) ) e i γ

and

(88) b ( x , t ) = 2 l 2 l 2 + ζ 2 × c 1 sin ( η a 1 ( u u 0 ) ) + c 2 cos ( η a 1 ( u u 0 ) ) c 2 sin ( η a 1 ( u u 0 ) ) + d 2 cos ( η a 1 ( u u 0 ) ) 2 e i γ ,

where η = w 4 ( d 1 2 + d 2 2 ) ( s 2 2 d 1 2 + d 2 2 ) d 1 2 + d 2 2 .

8 Results and discussion

In this section, our findings and the present phase of research on our suggested approach will be compared. Younas et al. investigated the construction of analytical wave solutions to the conformable fractional dynamical system of ion sound and Langmuir waves [35]. Atangana and Koca examined the chaos in a simple nonlinear system with ABD fractional order [36]. Algahtani studied the comparison of ABD and Caputo Fabrizio derivative with fractional order [37]. Alkahtani obtained Chua’s circuit model with ABD with fractional order [38]. Seadawy et al. described the application of mathematical methods on the system of dynamical equations for the ion sound and Langmuir waves [39]. The CDSPM technique is one of the most effective methods for solving NLPDEs. Moreover, we convert our model into a dynamic system and look at the qualitative analysis of the model under discussion displayed in Figures 14 to achieve a quasi-periodic behaviour. When a system’s trajectory is plotted in time space, a quasi- periodic cycle can be seen as a dense layer covering a toroidal surface (a surface of revolution with a hole in the middle). Toroidal shapes demonstrate quasi periodicity, as their motions cover their surfaces extensively without precisely repeating. Also when an external periodic strength is applied in dynamical system, quasi-periodic behaviours are observed. A number of methods are discussed to identify chaos including: time series, Poincarè maps, and 2D and 3D phase patterns. In addition, sensitivity analysis is conducted under different initial conditions as illustrated in Figures 5, 6, 7, 8. The sensitivity analysis for the three initial conditions shown in red, black, and green can be seen in these figures. Sensitivity analysis along with periodic structure indicate a nonlinear dynamical system. We made a small modification to the starting condition, and with the same parameters, we saw that the solution was unaffected by the change, suggesting that the model we were given was not extremely sensitive.

Figure 7 
               Time series, Poincarè maps, and 2D and 3D phase patterns.
Figure 7

Time series, Poincarè maps, and 2D and 3D phase patterns.

Figure 8 
               The nonlinear dynamical system (22) is described using several chaos-detecting techniques and initial conditions (1.08, 1.08), assuming the following assumptions: 
                     
                        
                        
                           
                              
                                 a
                              
                              
                                 1
                              
                           
                           =
                           ‒
                           1.96
                        
                        {a}_{1}=&#x2012;1.96
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 2
                              
                           
                           =
                           ‒
                           3.28
                        
                        {\xi }_{2}=&#x2012;3.28
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 1
                              
                           
                           =
                           0
                        
                        {\xi }_{1}=0
                     
                  , 
                     
                        
                        
                           
                              
                                 ϖ
                              
                              
                                 0
                              
                           
                           =
                           1.5
                        
                        {\varpi }_{0}=1.5
                     
                  , and 
                     
                        
                        
                           ζ
                           =
                           2
                           π
                        
                        \zeta =2\pi 
                     
                  .
Figure 8

The nonlinear dynamical system (22) is described using several chaos-detecting techniques and initial conditions (1.08, 1.08), assuming the following assumptions: a 1 = 1.96 , ξ 2 = 3.28 , ξ 1 = 0 , ϖ 0 = 1.5 , and ζ = 2 π .

We are now conducting a detailed analysis of the findings. The periodic solutions for triangle functions obtained from Eqs (25) and (26) are displayed in Figures 9 and 10. In the fields of science and engineering, periodic solutions which exhibit recurring behaviours are crucial. The shapes of these figures remain constant and repeat at regular intervals; notable peaks indicate the point at which the function value is significantly greater than the surroundings. The color shift indicates the function’s magnitude, the color transition depicts the traveling structure, and the abrupt change close to the peak indicates a steep gradient. The SW solutions for Eqs (30)–(33), (47), (48), (69)–(72) are shown in Figures 11, 12, 13, 14, 15, 16, 17, 18, 19, and 20. Because of their unique properties, SW solutions find application in many fields of science, including physics, biology, nonlinear optics, and plasma physics. Furthermore, the surrounding oscillatory pattern suggests that periodic solutions or multi-soliton interactions may exist, these figures represents both the stability and the complex dynamics of the system also the property of troughs and crests represents the stable localized solitons. Figures 21, 22, 23, 24, 25, and 26 show the rational solutions for Eqs (36), (37), and (41)–(44). When considering fields like physics, mathematics, and engineering, geometry plays a crucial role in comprehending the behaviour of rational solutions. The shape of rational soliton is stable when they propagate from one medium to another, and the prominent peak indicates that the shape of the soliton is conserved because it is a component of nonlinear waves. The Jacobi elliptic functions (JEF) are a set of basic elliptic functions in mathematics. Different approaches for JEF double periodic are found in Eqs (52)–(55), (59), (60), (64), and (65) are illustrated in Figures 27, 28, 29, 30, 31, 32, 33, and 34. It is a soliton that is a generalization of trigonometry and hyperbolic functions. It has multiple localized peaks, and the amplitude of these peaks is consistent, indicating a repeating and stable structure. This also suggests that the elliptic function is periodic. Eqs (52)–(55) transformed into SW double hyperbolic type-I and SW double periodic type-I in Eqs (73)–(76) and Eqs (77)–(80), respectively, by applying ν 1 and ν 0 , while the variables and characteristics of the solutions demonstrate in Figures 35, 36, 37, 38, 39, 40, 41, 42. Meanwhile, JEF double periodic solutions in Eqs (59) and (60) becomes a double hyperbolic type-II SW in Eqs (81) and (82) and a double periodic type-II SW in Eqs (83) and (46), by utilizing the limit ν 1 and ν 0 ; however, Figures 43, 44, 45, and 46 provide a graphical representation of these solutions. Although Eqs (64) and (65) are also the JEF double periodic solution, they become the double hyperbolic type-III in Eqs (85) and (86) and the double periodic type-III in Eqs (87) and (88) upon examination of the limits ν 1 and ν 0 . These equations can be seen graphically in Figures 47, 48, 49, 50. A number of soliton solutions provide important insights into the functions performed by wave phenomena in many physical systems. They are useful in quantum mechanics, plasma physics, and telecommunications. They are also crucial to our understanding of the dispersion of stable, confined waveforms. Moreover, solitons have been employed to investigate a broad variety of significant real-world problems in domains like fluid dynamics, astronomy, molecular biology, plasma, and nonlinear optics (Figures 51, 52, 53, 54).

Figure 9 
               The variables in the system Eq. (22) sensitivity profile are 
                     
                        
                        
                           
                              
                                 a
                              
                              
                                 1
                              
                           
                           =
                           0.7
                        
                        {a}_{1}=0.7
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 2
                              
                           
                           =
                           ‒
                           2.3
                        
                        {\xi }_{2}=&#x2012;2.3
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 1
                              
                           
                           =
                           0
                        
                        {\xi }_{1}=0
                     
                  , 
                     
                        
                        
                           
                              
                                 ϖ
                              
                              
                                 0
                              
                           
                           =
                           3.5
                        
                        {\varpi }_{0}=3.5
                     
                  , and 
                     
                        
                        
                           ζ
                           =
                           2
                           π
                        
                        \zeta =2\pi 
                     
                  , with initial values of (0.18, 0) in black, (0.17, 0) in blue, and (0.16, 0) in red.
Figure 9

The variables in the system Eq. (22) sensitivity profile are a 1 = 0.7 , ξ 2 = 2.3 , ξ 1 = 0 , ϖ 0 = 3.5 , and ζ = 2 π , with initial values of (0.18, 0) in black, (0.17, 0) in blue, and (0.16, 0) in red.

Figure 10 
               With the parameters as follows: 
                     
                        
                        
                           
                              
                                 a
                              
                              
                                 1
                              
                           
                           =
                           1.5
                        
                        {a}_{1}=1.5
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 2
                              
                           
                           =
                           ‒
                           4.2
                        
                        {\xi }_{2}=&#x2012;4.2
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 1
                              
                           
                           =
                           0
                        
                        {\xi }_{1}=0
                     
                  , 
                     
                        
                        
                           
                              
                                 ϖ
                              
                              
                                 0
                              
                           
                           =
                           2.5
                        
                        {\varpi }_{0}=2.5
                     
                  , and 
                     
                        
                        
                           ζ
                           =
                           2
                           π
                        
                        \zeta =2\pi 
                     
                  , the sensitivity profile of Eq. (2)) is displayed. The beginning points are (0.15, 0) in red, (0.16, 0) in black, and (0.27, 0) in blue.
Figure 10

With the parameters as follows: a 1 = 1.5 , ξ 2 = 4.2 , ξ 1 = 0 , ϖ 0 = 2.5 , and ζ = 2 π , the sensitivity profile of Eq. (2)) is displayed. The beginning points are (0.15, 0) in red, (0.16, 0) in black, and (0.27, 0) in blue.

Figure 11 
               Sensitivity profile for System (22), with initial values in blue (0.10, 0), red (0.19, 0), and black (0.40, 0), with the following parameters: 
                     
                        
                        
                           
                              
                                 a
                              
                              
                                 1
                              
                           
                           =
                           0.7
                        
                        {a}_{1}=0.7
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 2
                              
                           
                           =
                           ‒
                           2.3
                        
                        {\xi }_{2}=&#x2012;2.3
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 1
                              
                           
                           =
                           0
                        
                        {\xi }_{1}=0
                     
                  , 
                     
                        
                        
                           
                              
                                 ϖ
                              
                              
                                 0
                              
                           
                           =
                           3.5
                        
                        {\varpi }_{0}=3.5
                     
                  , and 
                     
                        
                        
                           ζ
                           =
                           2
                           π
                        
                        \zeta =2\pi 
                     
                  .
Figure 11

Sensitivity profile for System (22), with initial values in blue (0.10, 0), red (0.19, 0), and black (0.40, 0), with the following parameters: a 1 = 0.7 , ξ 2 = 2.3 , ξ 1 = 0 , ϖ 0 = 3.5 , and ζ = 2 π .

Figure 12 
               Using starting values of (0.30, 0) in red, (0.46,0) in black, and (0.57, 0) in blue, the variables that constitute the sensitivity of system equation (23) are: 
                     
                        
                        
                           
                              
                                 a
                              
                              
                                 1
                              
                           
                           =
                           1.5
                        
                        {a}_{1}=1.5
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 2
                              
                           
                           =
                           ‒
                           4.2
                        
                        {\xi }_{2}=&#x2012;4.2
                     
                  , 
                     
                        
                        
                           
                              
                                 ξ
                              
                              
                                 1
                              
                           
                           =
                           0
                        
                        {\xi }_{1}=0
                     
                  , 
                     
                        
                        
                           
                              
                                 ϖ
                              
                              
                                 0
                              
                           
                           =
                           2.5
                        
                        {\varpi }_{0}=2.5
                     
                  , and 
                     
                        
                        
                           ζ
                           =
                           2
                           π
                        
                        \zeta =2\pi 
                     
                  .
Figure 12

Using starting values of (0.30, 0) in red, (0.46,0) in black, and (0.57, 0) in blue, the variables that constitute the sensitivity of system equation (23) are: a 1 = 1.5 , ξ 2 = 4.2 , ξ 1 = 0 , ϖ 0 = 2.5 , and ζ = 2 π .

Figure 13 
               The graphical illustration of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   in Eq. (25) can be generated by setting: 
                     
                        
                        
                           M
                           =
                           1.9
                        
                        M=1.9
                     
                  , 
                     
                        
                        
                           N
                           =
                           ‒
                           1.009
                        
                        N=&#x2012;1.009
                     
                  , and 
                     
                        
                        
                           β
                           =
                           ‒
                           2.5
                        
                        \beta =&#x2012;2.5
                     
                  .
Figure 13

The graphical illustration of a ( x , t ) in Eq. (25) can be generated by setting: M = 1.9 , N = 1.009 , and β = 2.5 .

Figure 14 
               The graphical representation of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                  , as defined in Eq. (26) can be developed by modifying: 
                     
                        
                        
                           M
                           =
                           0.2
                        
                        M=0.2
                     
                  , 
                     
                        
                        
                           N
                           =
                           ‒
                           3.009
                        
                        N=&#x2012;3.009
                     
                  , 
                     
                        
                        
                           l
                           =
                           ‒
                           4.5
                        
                        l=&#x2012;4.5
                     
                  , 
                     
                        
                        
                           g
                           =
                           4.008
                        
                        g=4.008
                     
                  .
Figure 14

The graphical representation of b ( x , t ) , as defined in Eq. (26) can be developed by modifying: M = 0.2 , N = 3.009 , l = 4.5 , g = 4.008 .

Figure 15 
               Eq. (41) illustrates the behaviour of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   for: 
                     
                        
                        
                           
                              
                                 χ
                              
                              
                                 2
                              
                           
                           =
                           0.8
                        
                        {\chi }_{2}=0.8
                     
                  , 
                     
                        
                        
                           g
                           =
                           1.5
                        
                        g=1.5
                     
                  , 
                     
                        
                        
                           β
                           =
                           ‒
                           5.3
                        
                        \beta =&#x2012;5.3
                     
                  , and 
                     
                        
                        
                           c
                           =
                           0.6
                        
                        c=0.6
                     
                  .
Figure 15

Eq. (41) illustrates the behaviour of a ( x , t ) for: χ 2 = 0.8 , g = 1.5 , β = 5.3 , and c = 0.6 .

Figure 16 
               Eq. (42) represents the graph of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   for: 
                     
                        
                        
                           
                              
                                 χ
                              
                              
                                 1
                              
                           
                           =
                           0.8
                        
                        {\chi }_{1}=0.8
                     
                  , 
                     
                        
                        
                           g
                           =
                           ‒
                           0.5
                        
                        g=&#x2012;0.5
                     
                  , 
                     
                        
                        
                           
                              
                                 χ
                              
                              
                                 2
                              
                           
                           =
                           ‒
                           4.3
                        
                        {\chi }_{2}=&#x2012;4.3
                     
                  , and 
                     
                        
                        
                           β
                           =
                           3.6
                        
                        \beta =3.6
                     
                  .
Figure 16

Eq. (42) represents the graph of a ( x , t ) for: χ 1 = 0.8 , g = 0.5 , χ 2 = 4.3 , and β = 3.6 .

Figure 17 
               The configuration of dynamical plot of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   in Eq. (59) can be observed by using: 
                     
                        
                        
                           A
                           =
                           0.2
                           ,
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           0.3
                           ,
                           B
                           =
                           0.9
                           ,
                           C
                           =
                           0.1
                        
                        A=0.2,{u}_{0}=0.3,B=0.9,C=0.1
                     
                  , and 
                     
                        
                        
                           g
                           =
                           0.09
                        
                        g=0.09
                     
                  .
Figure 17

The configuration of dynamical plot of a ( x , t ) in Eq. (59) can be observed by using: A = 0.2 , u 0 = 0.3 , B = 0.9 , C = 0.1 , and g = 0.09 .

Figure 18 
               The graphical behaviour of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   in Eq. (60) can be determined by setting: 
                     
                        
                        
                           D
                           =
                           0.2
                        
                        D=0.2
                     
                  , 
                     
                        
                        
                           g
                           =
                           0.3
                        
                        g=0.3
                     
                  , 
                     
                        
                        
                           A
                           =
                           0.9
                        
                        A=0.9
                     
                  , 
                     
                        
                        
                           l
                           =
                           0.1
                        
                        l=0.1
                     
                  , and 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           0.09
                        
                        {u}_{0}=0.09
                     
                  .
Figure 18

The graphical behaviour of b ( x , t ) in Eq. (60) can be determined by setting: D = 0.2 , g = 0.3 , A = 0.9 , l = 0.1 , and u 0 = 0.09 .

Figure 19 
               The fluctuating trajectory of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   in Eq. (64) can be produced by using: 
                     
                        
                        
                           
                              
                                 w
                              
                              
                                 1
                              
                           
                           =
                           1.8
                        
                        {w}_{1}=1.8
                     
                  , 
                     
                        
                        
                           g
                           =
                           2.3
                           i
                        
                        g=2.3i
                     
                  , 
                     
                        
                        
                           c
                           =
                           1.8
                        
                        c=1.8
                     
                  , 
                     
                        
                        
                           
                              
                                 w
                              
                              
                                 4
                              
                           
                           =
                           0.63
                        
                        {w}_{4}=0.63
                     
                  , and 
                     
                        
                        
                           
                              
                                 w
                              
                              
                                 2
                              
                           
                           =
                           0.01
                        
                        {w}_{2}=0.01
                     
                  .
Figure 19

The fluctuating trajectory of a ( x , t ) in Eq. (64) can be produced by using: w 1 = 1.8 , g = 2.3 i , c = 1.8 , w 4 = 0.63 , and w 2 = 0.01 .

Figure 20 
               The configuration of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   in Eq. (65) can be represented by using: 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           4.8
                        
                        {u}_{0}=4.8
                     
                  , 
                     
                        
                        
                           l
                           =
                           9.3
                           i
                        
                        l=9.3i
                     
                  , 
                     
                        
                        
                           g
                           =
                           9.8
                        
                        g=9.8
                     
                  , 
                     
                        
                        
                           
                              
                                 w
                              
                              
                                 1
                              
                           
                           =
                           0.85
                        
                        {w}_{1}=0.85
                     
                  , 
                     
                        
                        
                           
                              
                                 w
                              
                              
                                 4
                              
                           
                           =
                           ‒
                           2.84
                        
                        {w}_{4}=&#x2012;2.84
                     
                  , and 
                     
                        
                        
                           β
                           =
                           1.01
                        
                        \beta =1.01
                     
                  .
Figure 20

The configuration of b ( x , t ) in Eq. (65) can be represented by using: u 0 = 4.8 , l = 9.3 i , g = 9.8 , w 1 = 0.85 , w 4 = 2.84 , and β = 1.01 .

Figure 21 
               To obtained the graphical plot of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   in Eq. (30) set: 
                     
                        
                        
                           S
                           =
                           0.8
                        
                        S=0.8
                     
                  , 
                     
                        
                        
                           R
                           =
                           0.9
                        
                        R=0.9
                     
                  , 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           9.8
                        
                        {u}_{0}=9.8
                     
                  , and 
                     
                        
                        
                           c
                           =
                           9.008
                        
                        c=9.008
                     
                  .
Figure 21

To obtained the graphical plot of a ( x , t ) in Eq. (30) set: S = 0.8 , R = 0.9 , u 0 = 9.8 , and c = 9.008 .

Figure 22 
               The configuration of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   according to Eq. (31) is visualized when: 
                     
                        
                        
                           S
                           =
                           0.9
                        
                        S=0.9
                     
                  , 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           0.3
                           ,
                           R
                           =
                           2.4
                           ,
                           β
                           =
                           3.006
                        
                        {u}_{0}=0.3,R=2.4,\beta =3.006
                     
                  , and 
                     
                        
                        
                           g
                           =
                           6.008
                        
                        g=6.008
                     
                  .
Figure 22

The configuration of a ( x , t ) according to Eq. (31) is visualized when: S = 0.9 , u 0 = 0.3 , R = 2.4 , β = 3.006 , and g = 6.008 .

Figure 23 
               The graphical representation of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   in Eq. (32) for: 
                     
                        
                        
                           S
                           =
                           0.8
                        
                        S=0.8
                     
                  , 
                     
                        
                        
                           g
                           =
                           0.9
                        
                        g=0.9
                     
                  , 
                     
                        
                        
                           R
                           =
                           0.4
                        
                        R=0.4
                     
                  , and 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           9.8
                        
                        {u}_{0}=9.8
                     
                  .
Figure 23

The graphical representation of b ( x , t ) in Eq. (32) for: S = 0.8 , g = 0.9 , R = 0.4 , and u 0 = 9.8 .

Figure 24 
               The visual illustration of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   in Eq. (33) for: 
                     
                        
                        
                           S
                           =
                           0.76
                        
                        S=0.76
                     
                  , 
                     
                        
                        
                           g
                           =
                           0.5
                        
                        g=0.5
                     
                  , 
                     
                        
                        
                           R
                           =
                           0.5
                        
                        R=0.5
                     
                  , and 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           8.9
                        
                        {u}_{0}=8.9
                     
                  .
Figure 24

The visual illustration of b ( x , t ) in Eq. (33) for: S = 0.76 , g = 0.5 , R = 0.5 , and u 0 = 8.9 .

Figure 25 
               Eq. (36) illustrates the fluctuating trajectory of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   for: 
                     
                        
                        
                           g
                           =
                           6.4
                        
                        g=6.4
                     
                  , 
                     
                        
                        
                           c
                           =
                           4.05
                        
                        c=4.05
                     
                  , 
                     
                        
                        
                           β
                           =
                           2.008
                        
                        \beta =2.008
                     
                  , and 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           0.8
                        
                        {u}_{0}=0.8
                     
                  .
Figure 25

Eq. (36) illustrates the fluctuating trajectory of a ( x , t ) for: g = 6.4 , c = 4.05 , β = 2.008 , and u 0 = 0.8 .

Figure 26 
               Eq. (37) shows the graphical behaviour of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   for: 
                     
                        
                        
                           l
                           =
                           0.4
                        
                        l=0.4
                     
                  , 
                     
                        
                        
                           c
                           =
                           ‒
                           9.05
                        
                        c=&#x2012;9.05
                     
                  , 
                     
                        
                        
                           g
                           =
                           6.008
                        
                        g=6.008
                     
                  , and 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           ‒
                           9.8
                        
                        {u}_{0}=&#x2012;9.8
                     
                  .
Figure 26

Eq. (37) shows the graphical behaviour of b ( x , t ) for: l = 0.4 , c = 9.05 , g = 6.008 , and u 0 = 9.8 .

Figure 27 
               Eq. (43) gives the graphical behaviour of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   for: 
                     
                        
                        
                           l
                           =
                           0.8
                        
                        l=0.8
                     
                  , 
                     
                        
                        
                           g
                           =
                           ‒
                           4.3
                        
                        g=&#x2012;4.3
                     
                  , 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           3.6
                        
                        {u}_{0}=3.6
                     
                  , and 
                     
                        
                        
                           c
                           =
                           ‒
                           0.5
                        
                        c=&#x2012;0.5
                     
                  .
Figure 27

Eq. (43) gives the graphical behaviour of b ( x , t ) for: l = 0.8 , g = 4.3 , u 0 = 3.6 , and c = 0.5 .

Figure 28 
               Eq. (44) represents the variation of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   for: 
                     
                        
                        
                           
                              
                                 χ
                              
                              
                                 2
                              
                           
                           =
                           1.8
                        
                        {\chi }_{2}=1.8
                     
                  , 
                     
                        
                        
                           
                              
                                 χ
                              
                              
                                 1
                              
                           
                           =
                           ‒
                           0.4
                        
                        {\chi }_{1}=&#x2012;0.4
                     
                  , 
                     
                        
                        
                           g
                           =
                           4.3
                        
                        g=4.3
                     
                  , and 
                     
                        
                        
                           c
                           =
                           3.6
                        
                        c=3.6
                     
                  .
Figure 28

Eq. (44) represents the variation of b ( x , t ) for: χ 2 = 1.8 , χ 1 = 0.4 , g = 4.3 , and c = 3.6 .

Figure 29 
               The configuration of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   in Eq. (47) shows graphical behaviour for: 
                     
                        
                        
                           β
                           =
                           0.8
                        
                        \beta =0.8
                     
                  , 
                     
                        
                        
                           
                              
                                 β
                              
                              
                                 1
                              
                           
                           =
                           ‒
                           0.5
                        
                        {\beta }_{1}=&#x2012;0.5
                     
                  , 
                     
                        
                        
                           
                              
                                 β
                              
                              
                                 2
                              
                           
                           =
                           ‒
                           4.3
                        
                        {\beta }_{2}=&#x2012;4.3
                     
                  , and 
                     
                        
                        
                           
                              
                                 β
                              
                              
                                 3
                              
                           
                           =
                           3.6
                        
                        {\beta }_{3}=3.6
                     
                  .
Figure 29

The configuration of b ( x , t ) in Eq. (47) shows graphical behaviour for: β = 0.8 , β 1 = 0.5 , β 2 = 4.3 , and β 3 = 3.6 .

Figure 30 
               The configuration of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   in Eq. (48) is visual illustrated by setting: 
                     
                        
                        
                           
                              
                                 β
                              
                              
                                 3
                              
                           
                           =
                           0.8
                        
                        {\beta }_{3}=0.8
                     
                  , 
                     
                        
                        
                           
                              
                                 β
                              
                              
                                 2
                              
                           
                           =
                           ‒
                           0.5
                        
                        {\beta }_{2}=&#x2012;0.5
                     
                  , 
                     
                        
                        
                           l
                           =
                           ‒
                           4.3
                        
                        l=&#x2012;4.3
                     
                  , and 
                     
                        
                        
                           c
                           =
                           3.6
                        
                        c=3.6
                     
                  .
Figure 30

The configuration of b ( x , t ) in Eq. (48) is visual illustrated by setting: β 3 = 0.8 , β 2 = 0.5 , l = 4.3 , and c = 3.6 .

Figure 31 
               The graphical depiction of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   as given by Eq. (52) is presented under the following parameter values: 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 1
                              
                           
                           =
                           0.5
                        
                        {p}_{1}=0.5
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 2
                              
                           
                           =
                           4.03
                        
                        {p}_{2}=4.03
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 3
                              
                           
                           =
                           ‒
                           0.6
                        
                        {p}_{3}=&#x2012;0.6
                     
                  , 
                     
                        
                        
                           c
                           =
                           ‒
                           0.3
                        
                        c=&#x2012;0.3
                     
                  , 
                     
                        
                        
                           g
                           =
                           ‒
                           0.4
                        
                        g=&#x2012;0.4
                     
                  , and 
                     
                        
                        
                           β
                           =
                           0.8
                        
                        \beta =0.8
                     
                  .
Figure 31

The graphical depiction of a ( x , t ) as given by Eq. (52) is presented under the following parameter values: p 1 = 0.5 , p 2 = 4.03 , p 3 = 0.6 , c = 0.3 , g = 0.4 , and β = 0.8 .

Figure 32 
               The graphical illustration of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   in Eq. (53) for: 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 1
                              
                           
                           =
                           2.5
                        
                        {p}_{1}=2.5
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 2
                              
                           
                           =
                           6.03
                        
                        {p}_{2}=6.03
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 3
                              
                           
                           =
                           1.4
                        
                        {p}_{3}=1.4
                     
                  , 
                     
                        
                        
                           c
                           =
                           0.48
                        
                        c=0.48
                     
                  , 
                     
                        
                        
                           g
                           =
                           ‒
                           0.086
                        
                        g=&#x2012;0.086
                     
                  , and 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           1.8
                        
                        {u}_{0}=1.8
                     
                  .
Figure 32

The graphical illustration of a ( x , t ) in Eq. (53) for: p 1 = 2.5 , p 2 = 6.03 , p 3 = 1.4 , c = 0.48 , g = 0.086 , and u 0 = 1.8 .

Figure 33 
               The visual representation of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   in Eq. (54) can be obtained by setting following parameter: 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 1
                              
                           
                           =
                           0.5
                        
                        {p}_{1}=0.5
                     
                  , 
                     
                        
                        
                           g
                           =
                           4.03
                        
                        g=4.03
                     
                  , 
                     
                        
                        
                           l
                           =
                           ‒
                           0.6
                        
                        l=&#x2012;0.6
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 2
                              
                           
                           =
                           ‒
                           0.3
                        
                        {p}_{2}=&#x2012;0.3
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 3
                              
                           
                           =
                           ‒
                           0.4
                        
                        {p}_{3}=&#x2012;0.4
                     
                  , and 
                     
                        
                        
                           β
                           =
                           0.8
                        
                        \beta =0.8
                     
                  .
Figure 33

The visual representation of b ( x , t ) in Eq. (54) can be obtained by setting following parameter: p 1 = 0.5 , g = 4.03 , l = 0.6 , p 2 = 0.3 , p 3 = 0.4 , and β = 0.8 .

Figure 34 
               Eq. (55) describes the graphical illustration of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   for: 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 1
                              
                           
                           =
                           0.5
                        
                        {p}_{1}=0.5
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 2
                              
                           
                           =
                           1.3
                        
                        {p}_{2}=1.3
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 4
                              
                           
                           =
                           1.4
                        
                        {p}_{4}=1.4
                     
                  , 
                     
                        
                        
                           β
                           =
                           4.03
                        
                        \beta =4.03
                     
                  , 
                     
                        
                        
                           c
                           =
                           1.6
                        
                        c=1.6
                     
                  , and 
                     
                        
                        
                           g
                           =
                           0.4
                        
                        g=0.4
                     
                  .
Figure 34

Eq. (55) describes the graphical illustration of b ( x , t ) for: p 1 = 0.5 , p 2 = 1.3 , p 4 = 1.4 , β = 4.03 , c = 1.6 , and g = 0.4 .

Figure 35 
               The graph of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   in Eq. (69) are observed under the following conditions: 
                     
                        
                        
                           a
                           =
                           0.8
                        
                        a=0.8
                     
                  , 
                     
                        
                        
                           g
                           =
                           0.3
                        
                        g=0.3
                     
                  , 
                     
                        
                        
                           n
                           =
                           0.25
                        
                        n=0.25
                     
                  , and 
                     
                        
                        
                           β
                           =
                           5.01
                        
                        \beta =5.01
                     
                  .
Figure 35

The graph of a ( x , t ) in Eq. (69) are observed under the following conditions: a = 0.8 , g = 0.3 , n = 0.25 , and β = 5.01 .

Figure 36 
               The plot for 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   in Eq. (70) can be represented by setting: 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           5.8
                        
                        {u}_{0}=5.8
                     
                  , 
                     
                        
                        
                           g
                           =
                           8.3
                        
                        g=8.3
                     
                  , 
                     
                        
                        
                           l
                           =
                           3.8
                        
                        l=3.8
                     
                  , and 
                     
                        
                        
                           β
                           =
                           3.1
                        
                        \beta =3.1
                     
                  .
Figure 36

The plot for a ( x , t ) in Eq. (70) can be represented by setting: u 0 = 5.8 , g = 8.3 , l = 3.8 , and β = 3.1 .

Figure 37 
               For the visual representation of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   in Eq. (71) by using: 
                     
                        
                        
                           β
                           =
                           2.8
                        
                        \beta =2.8
                     
                  , 
                     
                        
                        
                           s
                           =
                           0.6
                        
                        s=0.6
                     
                  , 
                     
                        
                        
                           g
                           =
                           0.75
                        
                        g=0.75
                     
                  , 
                     
                        
                        
                           n
                           =
                           1.8
                        
                        n=1.8
                     
                  , and 
                     
                        
                        
                           l
                           =
                           0.01
                        
                        l=0.01
                     
                  .
Figure 37

For the visual representation of b ( x , t ) in Eq. (71) by using: β = 2.8 , s = 0.6 , g = 0.75 , n = 1.8 , and l = 0.01 .

Figure 38 
               Graph of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   in Eq. (72) is determined by setting: 
                     
                        
                        
                           β
                           =
                           8.8
                        
                        \beta =8.8
                     
                  , 
                     
                        
                        
                           a
                           =
                           0.5
                        
                        a=0.5
                     
                  , 
                     
                        
                        
                           n
                           =
                           0.2
                        
                        n=0.2
                     
                  , 
                     
                        
                        
                           g
                           =
                           0.854
                        
                        g=0.854
                     
                  , and 
                     
                        
                        
                           l
                           =
                           3.68
                        
                        l=3.68
                     
                  .
Figure 38

Graph of b ( x , t ) in Eq. (72) is determined by setting: β = 8.8 , a = 0.5 , n = 0.2 , g = 0.854 , and l = 3.68 .

Figure 39 
               Eq. (73) gives the graphical behaviour of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   by using following parameters: 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 1
                              
                           
                           =
                           ‒
                           0.6
                        
                        {p}_{1}=&#x2012;0.6
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 2
                              
                           
                           =
                           0.08
                        
                        {p}_{2}=0.08
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 3
                              
                           
                           =
                           0.5
                        
                        {p}_{3}=0.5
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 4
                              
                           
                           =
                           ‒
                           0.4
                        
                        {p}_{4}=&#x2012;0.4
                     
                  , and 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           4.03
                        
                        {u}_{0}=4.03
                     
                  .
Figure 39

Eq. (73) gives the graphical behaviour of a ( x , t ) by using following parameters: p 1 = 0.6 , p 2 = 0.08 , p 3 = 0.5 , p 4 = 0.4 , and u 0 = 4.03 .

Figure 40 
               Eq. (74) determined the visual illustration of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   by using: 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 1
                              
                           
                           =
                           9.36
                        
                        {p}_{1}=9.36
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 2
                              
                           
                           =
                           2.1
                        
                        {p}_{2}=2.1
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 3
                              
                           
                           =
                           1.9
                        
                        {p}_{3}=1.9
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 4
                              
                           
                           =
                           5.2
                        
                        {p}_{4}=5.2
                     
                  , and 
                     
                        
                        
                           u
                           =
                           0.9
                        
                        u=0.9
                     
                  .
Figure 40

Eq. (74) determined the visual illustration of a ( x , t ) by using: p 1 = 9.36 , p 2 = 2.1 , p 3 = 1.9 , p 4 = 5.2 , and u = 0.9 .

Figure 41 
               The configuration of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   in Eq. (75) can be determined by setting: 
                     
                        
                        
                           l
                           =
                           4.1
                        
                        l=4.1
                     
                  , 
                     
                        
                        
                           g
                           =
                           4.238
                        
                        g=4.238
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 1
                              
                           
                           =
                           3.5
                        
                        {p}_{1}=3.5
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 3
                              
                           
                           =
                           ‒
                           4.325
                        
                        {p}_{3}=&#x2012;4.325
                     
                  , and 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 4
                              
                           
                           =
                           0.368
                        
                        {p}_{4}=0.368
                     
                  .
Figure 41

The configuration of b ( x , t ) in Eq. (75) can be determined by setting: l = 4.1 , g = 4.238 , p 1 = 3.5 , p 3 = 4.325 , and p 4 = 0.368 .

Figure 42 
               The visual illustration of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   in Eq. (76) can be determined by setting: 
                     
                        
                        
                           l
                           =
                           0.3
                        
                        l=0.3
                     
                  , 
                     
                        
                        
                           g
                           =
                           2.8
                        
                        g=2.8
                     
                  , 
                     
                        
                        
                           ζ
                           =
                           ‒
                           4.24
                        
                        \zeta =&#x2012;4.24
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 3
                              
                           
                           =
                           ‒
                           9.325
                        
                        {p}_{3}=&#x2012;9.325
                     
                  , and 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 4
                              
                           
                           =
                           ‒
                           3.368
                        
                        {p}_{4}=&#x2012;3.368
                     
                  .
Figure 42

The visual illustration of b ( x , t ) in Eq. (76) can be determined by setting: l = 0.3 , g = 2.8 , ζ = 4.24 , p 3 = 9.325 , and p 4 = 3.368 .

Figure 43 
               Eq. (77) shows the graphical behaviour of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   by using: 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 1
                              
                           
                           =
                           0.43
                        
                        {p}_{1}=0.43
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 2
                              
                           
                           =
                           9.6
                        
                        {p}_{2}=9.6
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 3
                              
                           
                           =
                           ‒
                           3.6
                        
                        {p}_{3}=&#x2012;3.6
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 4
                              
                           
                           =
                           ‒
                           4.3
                        
                        {p}_{4}=&#x2012;4.3
                     
                  , and 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           0.5
                        
                        {u}_{0}=0.5
                     
                  .
Figure 43

Eq. (77) shows the graphical behaviour of a ( x , t ) by using: p 1 = 0.43 , p 2 = 9.6 , p 3 = 3.6 , p 4 = 4.3 , and u 0 = 0.5 .

Figure 44 
               Eq. (78) shows the visual illustration of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   by setting: 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 1
                              
                           
                           =
                           2.3
                        
                        {p}_{1}=2.3
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 2
                              
                           
                           =
                           ‒
                           0.6
                        
                        {p}_{2}=&#x2012;0.6
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 3
                              
                           
                           =
                           4.05
                        
                        {p}_{3}=4.05
                     
                  , and 
                     
                        
                        
                           u
                           =
                           0
                        
                        u=0
                     
                  .
Figure 44

Eq. (78) shows the visual illustration of a ( x , t ) by setting: p 1 = 2.3 , p 2 = 0.6 , p 3 = 4.05 , and u = 0 .

Figure 45 
               The graphical depiction of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   as given by Eq. (79) is presented under the following parameter values: 
                     
                        
                        
                           l
                           =
                           0.2
                        
                        l=0.2
                     
                  , 
                     
                        
                        
                           g
                           =
                           4.3
                        
                        g=4.3
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 1
                              
                           
                           =
                           2.6
                        
                        {p}_{1}=2.6
                     
                  , and 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 4
                              
                           
                           =
                           ‒
                           9.5
                        
                        {p}_{4}=&#x2012;9.5
                     
                  .
Figure 45

The graphical depiction of b ( x , t ) as given by Eq. (79) is presented under the following parameter values: l = 0.2 , g = 4.3 , p 1 = 2.6 , and p 4 = 9.5 .

Figure 46 
               For the following parameters: 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 1
                              
                           
                           =
                           4.6
                        
                        {p}_{1}=4.6
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 2
                              
                           
                           =
                           1.6
                        
                        {p}_{2}=1.6
                     
                  , 
                     
                        
                        
                           
                              
                                 p
                              
                              
                                 3
                              
                           
                           =
                           9.1
                        
                        {p}_{3}=9.1
                     
                  , and 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           0.008
                        
                        {u}_{0}=0.008
                     
                  , a graph of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   is shown in Eq. (80).
Figure 46

For the following parameters: p 1 = 4.6 , p 2 = 1.6 , p 3 = 9.1 , and u 0 = 0.008 , a graph of b ( x , t ) is shown in Eq. (80).

Figure 47 
               Eq. (81) represents the dynamic illustration of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   occurs when: 
                     
                        
                        
                           A
                           =
                           0.1
                        
                        A=0.1
                     
                  , 
                     
                        
                        
                           B
                           =
                           1.03
                        
                        B=1.03
                     
                  , 
                     
                        
                        
                           D
                           =
                           ‒
                           2.4
                        
                        D=&#x2012;2.4
                     
                  , and 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           1.09
                        
                        {u}_{0}=1.09
                     
                  .
Figure 47

Eq. (81) represents the dynamic illustration of a ( x , t ) occurs when: A = 0.1 , B = 1.03 , D = 2.4 , and u 0 = 1.09 .

Figure 48 
               For Eq. (82), a dynamical representation of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   occurs when: 
                     
                        
                        
                           l
                           =
                           3.6
                        
                        l=3.6
                     
                  , 
                     
                        
                        
                           g
                           =
                           4.3
                        
                        g=4.3
                     
                  , 
                     
                        
                        
                           A
                           =
                           ‒
                           3.9
                        
                        A=&#x2012;3.9
                     
                  , 
                     
                        
                        
                           D
                           =
                           3.9
                           ,
                        
                        D=3.9,
                     
                   and 
                     
                        
                        
                           B
                           =
                           1.9
                        
                        B=1.9
                     
                  .
Figure 48

For Eq. (82), a dynamical representation of b ( x , t ) occurs when: l = 3.6 , g = 4.3 , A = 3.9 , D = 3.9 , and B = 1.9 .

Figure 49 
               Eq. (83) display the graph of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   under the following conditions: 
                     
                        
                        
                           A
                           =
                           ‒
                           3.3
                        
                        A=&#x2012;3.3
                     
                  , 
                     
                        
                        
                           B
                           =
                           1.4
                        
                        B=1.4
                     
                  , 
                     
                        
                        
                           D
                           =
                           ‒
                           4.2
                        
                        D=&#x2012;4.2
                     
                  , 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           0.09
                        
                        {u}_{0}=0.09
                     
                  , and 
                     
                        
                        
                           
                              
                                 a
                              
                              
                                 1
                              
                           
                           =
                           3.7
                        
                        {a}_{1}=3.7
                     
                  .
Figure 49

Eq. (83) display the graph of a ( x , t ) under the following conditions: A = 3.3 , B = 1.4 , D = 4.2 , u 0 = 0.09 , and a 1 = 3.7 .

Figure 50 
               Eq. (84) shows the graphical behaviour of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   under the following conditions: 
                     
                        
                        
                           A
                           =
                           0.3
                        
                        A=0.3
                     
                  , 
                     
                        
                        
                           B
                           =
                           4.4
                        
                        B=4.4
                     
                  , 
                     
                        
                        
                           l
                           =
                           ‒
                           1.2
                        
                        l=&#x2012;1.2
                     
                  , 
                     
                        
                        
                           g
                           =
                           9.34
                        
                        g=9.34
                     
                  , and 
                     
                        
                        
                           
                              
                                 a
                              
                              
                                 1
                              
                           
                           =
                           2.86
                        
                        {a}_{1}=2.86
                     
                  .
Figure 50

Eq. (84) shows the graphical behaviour of b ( x , t ) under the following conditions: A = 0.3 , B = 4.4 , l = 1.2 , g = 9.34 , and a 1 = 2.86 .

Figure 51 
               A graphical depiction of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   can be identified in Eq. (85) under the following circumstances: 
                     
                        
                        
                           
                              
                                 d
                              
                              
                                 1
                              
                           
                           =
                           ‒
                           0.008
                        
                        {d}_{1}=&#x2012;0.008
                     
                  , 
                     
                        
                        
                           
                              
                                 d
                              
                              
                                 2
                              
                           
                           =
                           0.8
                        
                        {d}_{2}=0.8
                     
                  , 
                     
                        
                        
                           
                              
                                 a
                              
                              
                                 1
                              
                           
                           =
                           ‒
                           0.46
                        
                        {a}_{1}=&#x2012;0.46
                     
                  , 
                     
                        
                        
                           
                              
                                 s
                              
                              
                                 2
                              
                           
                           =
                           ‒
                           0.9
                        
                        {s}_{2}=&#x2012;0.9
                     
                  , and 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           0.8
                        
                        {u}_{0}=0.8
                     
                  .
Figure 51

A graphical depiction of a ( x , t ) can be identified in Eq. (85) under the following circumstances: d 1 = 0.008 , d 2 = 0.8 , a 1 = 0.46 , s 2 = 0.9 , and u 0 = 0.8 .

Figure 52 
               A graphical behaviour of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   for Eq. (79) presented by using: 
                     
                        
                        
                           l
                           =
                           ‒
                           2.4
                        
                        l=&#x2012;2.4
                     
                  , 
                     
                        
                        
                           g
                           =
                           2.56
                        
                        g=2.56
                     
                  , 
                     
                        
                        
                           
                              
                                 d
                              
                              
                                 1
                              
                           
                           =
                           1.4
                        
                        {d}_{1}=1.4
                     
                  , and 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           0
                        
                        {u}_{0}=0
                     
                  .
Figure 52

A graphical behaviour of b ( x , t ) for Eq. (79) presented by using: l = 2.4 , g = 2.56 , d 1 = 1.4 , and u 0 = 0 .

Figure 53 
               When 
                     
                        
                        
                           
                              
                                 a
                              
                              
                                 1
                              
                           
                           =
                           ‒
                           0.9
                        
                        {a}_{1}=&#x2012;0.9
                     
                  , 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           0
                        
                        {u}_{0}=0
                     
                  , 
                     
                        
                        
                           
                              
                                 s
                              
                              
                                 2
                              
                           
                           =
                           ‒
                           0.74
                        
                        {s}_{2}=&#x2012;0.74
                     
                  , 
                     
                        
                        
                           
                              
                                 c
                              
                              
                                 1
                              
                           
                           =
                           2.7
                        
                        {c}_{1}=2.7
                     
                  , and 
                     
                        
                        
                           
                              
                                 c
                              
                              
                                 2
                              
                           
                           =
                           1.5
                        
                        {c}_{2}=1.5
                     
                  , the dynamics of 
                     
                        
                        
                           a
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        a\left(x,t)
                     
                   is represented in Eq. (87).
Figure 53

When a 1 = 0.9 , u 0 = 0 , s 2 = 0.74 , c 1 = 2.7 , and c 2 = 1.5 , the dynamics of a ( x , t ) is represented in Eq. (87).

Figure 54 
               The visual representation of 
                     
                        
                        
                           b
                           
                              (
                              
                                 x
                                 ,
                                 t
                              
                              )
                           
                        
                        b\left(x,t)
                     
                   in Eq. (88) can be determined by using: 
                     
                        
                        
                           
                              
                                 s
                              
                              
                                 2
                              
                           
                           =
                           ‒
                           1.8
                        
                        {s}_{2}=&#x2012;1.8
                     
                  , 
                     
                        
                        
                           g
                           =
                           2.3
                        
                        g=2.3
                     
                  , 
                     
                        
                        
                           ζ
                           =
                           ‒
                           0.43
                        
                        \zeta =&#x2012;0.43
                     
                  , 
                     
                        
                        
                           
                              
                                 d
                              
                              
                                 1
                              
                           
                           =
                           0.35
                        
                        {d}_{1}=0.35
                     
                  , 
                     
                        
                        
                           l
                           =
                           5.9
                        
                        l=5.9
                     
                  , and 
                     
                        
                        
                           
                              
                                 u
                              
                              
                                 0
                              
                           
                           =
                           0
                        
                        {u}_{0}=0
                     
                  .
Figure 54

The visual representation of b ( x , t ) in Eq. (88) can be determined by using: s 2 = 1.8 , g = 2.3 , ζ = 0.43 , d 1 = 0.35 , l = 5.9 , and u 0 = 0 .

9 Conclusion

With the use of the ABD, we were able to effectively derive a few novel analytical solutions for FISLWS in this research. These exact solutions are obtained in the form of JEF, hyperbolic, trigonometric, and exponential functions. Consequently, rational, periodic, SW, bright and dark solitons, and other new travelling wave solutions are obtained and visually presented in 2D and 3D plots. Also we used ML tools like: solve_ivp, Pandas and numpy, and scipy.integrate in this work. Furthermore, after transforming the model into a dynamic system, we conducted a quasi-periodic behaviour analysis and sensitivity analysis on it. A variety of methods, including time analysis, Poincarè maps, and 2D and 3D plots, were utilized to identify chaos. In addition, sensitivity analysis under different initial conditions was carried out, and the outcome demonstrated that the governing model is not very sensitive. These solutions have significant applications in various fields of engineering, physics, and other disciplines. Finally, by comparing our solutions with earlier studies, we found that they are distinct and more precise.



  1. Funding information: This work was funded by the Deanship of Graduate Studies and Scientific Research at Jouf University under grant No. DGSSR-2023-02-02535.

  2. Author contribution: All authors have accepted responsibility for the entire content of this manuscript and approved its submission.

  3. Conflict of interest: The authors state no conflict of interest.

  4. Data availability statement: The datasets generated and/or analysed during the current study are available from the corresponding author on reasonable request.

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Received: 2024-06-03
Revised: 2024-08-04
Accepted: 2024-08-06
Published Online: 2024-09-16

© 2024 the author(s), published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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