Home Mathematics The asymptotic behaviors of solutions for higher-order (m1, m2)-coupled Kirchhoff models with nonlinear strong damping
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The asymptotic behaviors of solutions for higher-order (m1, m2)-coupled Kirchhoff models with nonlinear strong damping

  • Penghui Lv EMAIL logo , Guoguang Lin and Xiaojun Lv
Published/Copyright: March 28, 2023
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Abstract

The Kirchhoff model is derived from the vibration problem of stretchable strings. This article focuses on the long-time dynamics of a class of higher-order coupled Kirchhoff systems with nonlinear strong damping. The existence and uniqueness of the solutions of these equations in different spaces are proved by prior estimation and the Faedo-Galerkin method. Subsequently, the family of global attractors of these problems is proved using the compactness theorem. In this article, we systematically propose the definition and proof process of the family of global attractors and enrich the related conclusions of higher-order coupled Kirchhoff models. The conclusions lay a theoretical foundation for future practical applications.

MSC 2010: 35B41; 35G31

1 Introduction

In this study, we consider the dynamic behavior of the following higher-order coupled Kirchhoff models in a bounded smooth domain Ω R n :

(1) u t t + N 1 ( m 1 u 2 ) ( Δ ) m 1 u t + M ( m 1 u 2 + 2 m 2 v 2 ) ( Δ ) m 1 u + g 1 ( u , v ) = f 1 ( x ) , v t t + N 2 ( 2 m 2 v 2 ) ( Δ ) 2 m 2 v t + M ( m 1 u 2 + 2 m 2 v 2 ) ( Δ ) 2 m 2 v + g 2 ( u , v ) = f 2 ( x ) ,

under the following boundary conditions:

(2) u ( x ) = 0 , i u n i = 0 , i = 1 , , m 1 1 , m 1 > 1 v ( x ) = 0 , j v n j = 0 , j = 1 , , 2 m 2 1 , m 2 > 1 ,

and the following initial conditions:

(3) u ( x , 0 ) = u 0 ( x ) , u t ( x , 0 ) = u 1 ( x ) , v ( x , 0 ) = v 0 ( x ) , v t ( x , 0 ) = v 1 ( x ) , x Ω ,

where Δ is the Laplace operator, N 1 , N 2 and M 1 , M 2 are scalar functions specified later, g 1 , g 2 are the given source terms, and f 1 , f 2 are the given functions.

(1) is a set of important generalized higher-order quasi-linear wave equations. The proposed equation in this article originated from Kirchhoff’s vibration problem of stretchable strings in 1883:

(4) ρ h 2 u t 2 = p 0 + E h 2 L 0 L u x 2 d x 2 u t 2 ,

where 0 < x < L , t 0 , u = u ( x , t ) is the lateral displacement at space coordinate x and time coordinate t , E represents the Young’s modulus, ρ represents the mass density, h represents the cross-sectional area, L represents the length, and p 0 represents the axial tension of the accident. The long-time behavior of various forms of Kirchhoff equations have attracted the attention of many scholars in recent decades, and abundant research results have been produced [113].

Chueshov [1] studied the well-posedness and long-time dynamical behavior of the following Kirchhoff equation with a nonlinear strong damping term:

(5) u t t + σ ( u 2 ) Δ u t ϕ ( u 2 ) Δ u + f ( u ) = h ( x ) .

Lin et al. [2] studied the global dynamics of the following generalized nonlinear Kirchhoff-Boussinesq equations with a strong damping:

(6) u t t + α u t β Δ u t + Δ 2 u = div ( g ( u 2 ) u ) + Δ h ( u ) + f ( x ) .

This article proved that the semi-group conformed to the squeezing property and demonstrated the existence of the exponential attractor of the system. Then, the spectral interval theory was used to prove that the system had an inertial manifold.

Ghisi and Gobbino [3] studied the global and local existence of solutions to the following Kirchhoff model with strong damping:

(7) u t t ( t ) + 2 δ A σ u t ( t ) + M ( A 1 / 2 u ( t ) 2 ) A u ( t ) = 0 .

Nakao [4] proved the initial-boundary value problem of the quasi-linear Kirchhoff-type wave equation with standard dissipation u t :

(8) u t t ( 1 + u ( t ) 2 2 ) Δ u + u t + g ( x , u ) = f ( x ) .

With the advance of research, scholars began to turn their attention to the dynamics of the higher-order Kirchhoff equations. Ye and Tao [14] studied the initial-boundary value problem of the following kind of higher-order Kirchhoff-type equation with a nonlinear dissipation term:

(9) u t t + Φ ( D m u 2 ) ( Δ ) m u + a u t q 2 u t = b u r 2 u .

Lin and Zhu [15] studied the initial and boundary value problems of the following nonlinear nonlocal higher-order Kirchhoff-type equations:

(10) u t t + M ( D m u 2 ) ( Δ ) m u + β ( Δ ) m u t + g ( x , u t ) = f ( x ) .

This study demonstrated the existence and uniqueness of the solution, proved the existence of a global attractor family of the problem through the compact method, and obtained the finite Hausdorff and Fractal dimensions.

Originated from physics, system coupling is a measure where two entities depend on each other. With suitable conditions or parameters, a connected system is coupled, and the potential energy of the system can enable the combination of structural functions of different systems and generate new functions. As a mathematical equation derived from physics, the Kirchhoff model is favorable for considering coupled system. Scholars gradually considered the dynamics of coupled Kirchhoff equations. For example, Wang and Zhang [16] studied the long-time dynamics problem of a class of coupled beam equations with strong damping under nonlinear boundary conditions. Lin and Zhang [17] studied the initial-boundary value problem of the following Kirchhoff coupling group with strong damping and source terms:

(11) u t t β Δ u t M ( u 2 + v 2 ) Δ u + g 1 ( u , v ) = f 1 ( x ) , v t t β Δ v t M ( u 2 + v 2 ) Δ v + g 2 ( u , v ) = f 2 ( x ) .

The finite Hausdorff dimension of the global attractor can be obtained in [17].

In recent years, Lin et al. [1820] focused on the dynamics of a class of higher-order coupled Kirchhoff equations and obtained a series of ideal results.

At present, few articles focus on the higher-order coupled Kirchhoff problems, and the problem of higher-order beam-plate coupled with nonlinear strong damping has not been studied. The main difficulty lies in the estimation and processing of the harmonic term and the nonlinear damping term and the nonlinear damping when proving the uniqueness. Therefore, under reasonable assumptions, this article overcomes these difficulties by using Holder’s inequality, Young’s inequality, Poincare inequality, and Gagliardo-Nirenberg inequality and obtains the global solution of the problem and the family of global attractors. This study could refine the definition and existence theorem of the family of global attractors. The conclusions could fill the gap of the family of global attractors of higher-order coupled models (regardless of whether m 1 is equal to m 2 ) and lay the foundation for subsequent engineering applications.

This article is organized as follows. Section 2 presents the fundamentals for this work. Section 3 states and proves the main results. Finally, conclusions of this article are presented in Section 4.

2 Preparatory knowledge

In this article, and ( , ) denote the norm and the inner product in H = L 2 ( Ω ) . Let H 0 1 = D ( ( Δ ) 1 2 ) be the scale of the Hilbert space generated by the Laplacian with Dirichlet boundary condition on H and endowed with standard inner product and norm, respectively, ( , ) H 0 1 = ( ( Δ ) 1 2 , ( Δ ) 1 2 ) and H 0 1 = ( Δ ) 1 2 . The main goal is to study the well-posedness and long-time dynamics of problems (1) to (3) under the following set of hypotheses:

(A1). M ( s ) is a continuous function on intervals [ 0 , + ) , M ( s ) C 1 ( R + ) , and

  1. M ( s ) 0 ,

  2. M ( 0 ) M 0 > 0 .

(A2). For any u , v H , let

J ( u , v ) = Ω [ G 1 ( u , v ) + G 2 ( u , v ) ] d x ,

where G 1 ( u , v ) = 0 u g 1 ( s , v ) d s , G 2 ( u , v ) = 0 v g 2 ( u , s ) d s , then for any μ 0 , there exists C 1 0 , C μ 0 , C μ 0 that

G 1 ( u , v ) + G 2 ( u , v ) C 1 J ( u , v ) + μ ( m 1 u 2 + 2 m 2 v 2 ) C μ , J ( u , v ) + μ ( m 1 u 2 + 2 m 2 v 2 ) C μ .

(A3). g j ( u , v ) ( j = 1 , 2 ) C 1 ( R ) , and

g j ( u , v ) C 2 ( 1 + u p j + v q j ) ; g j u ( u , v ) C 3 ( 1 + u p j 1 + v q j ) ; g j v ( u , v ) C 4 ( 1 + u p j + v q j 1 ) .

Specifically, when n = 1 , 2 , 1 p j ( q j ) ; when 3 n 4 m , 1 p j ( q j ) 2 m n 2 m , where m = min { m 1 , m 2 } .

(A4). N j ( s j ) N j 0 and N j 0 ( j = 1 , 2 ) are positive constants, and ρ > 0 . Thus, M ( s 1 + s 2 ) ρ N 1 ( s 1 ) ρ N 2 ( s 2 ) > 0 .

Then, the research phase space of this study is obtained:

V 0 = H , V k = H k ( Ω ) H 0 1 , X 0 × 0 = V m 1 ( Ω ) × H × V 2 m 2 × H , X k 1 × k 2 = V m 1 + k 1 ( Ω ) × V k 1 ( Ω ) × V 2 m 2 + 2 k 2 × V 2 k 2 ( Ω ) , k 1 = 0 , 1 , 2 , , m 1 , k 2 = 0 , 1 , 2 , , m 2 ,

and the norms of the corresponding spaces are as follows:

( u , y 1 , v , y 2 ) X k 1 × k 2 2 = m 1 + k 1 u 2 + k 1 y 1 2 + 2 m 2 + 2 k 2 v 2 + 2 k 2 y 2 2 .

Meanwhile, the general form of the Poincare inequality is as follows: λ 1 r u 2 r + 1 u 2 , where λ 1 is the first eigenvalue of Δ with a homogeneous Dirichlet boundary on Ω . In this article, C i is a constant, and C ( ) is a constant depending on the parameters in parentheses.

Lemma 1

[21] Let y : R + R + be an absolutely continuous positive function on [ 0 , + ) , which satisfies the following differential inequality for some δ > 0 :

d d t y ( t ) + 2 δ y ( t ) g ( t ) y ( t ) + K , t > 0 ,

where K 0 , and a 0 if t s 0 so that s t g ( τ ) d τ δ ( t s ) + a . Then,

y ( t ) e a y ( 0 ) e δ t + K e a δ , t 0 .

Lemma 2

[15] Let X be a Banach space, and the continuous operator semi-group { S ( t ) } t 0 satisfies the following:

  1. The semi-group { S ( t ) } t 0 is uniformly bounded in X , i.e., for all R 0 > 0 , and there exists a positive constant C 0 ( R 0 ) that when u X R 0 ,

    S ( t ) u X C 0 ( R 0 ) , ( f o r a l l t [ 0 , + ) ) ;

  2. there exists a bounded absorbing set B 0 in X , and for any bounded set B X , there exists a moment t 0 that

    S ( t ) B B 0 ( t t 0 ) ;

  3. if t > 0 , and S ( t ) is a fully continuous operator, then the semi-group { S ( t ) } t 0 has a global attractor A in X , and

    A = ω ( B 0 ) = τ 0 t τ S ( t ) B 0 ¯ .

3 Main conclusion

Let ε > 0 be small enough and λ 1 m N 10 2 4 ε 2 ε 2 0 , λ 1 2 m N 20 2 4 ε 2 ε 2 0 .

Lemma 3

Assume that assumptions (A1)–(A4) hold, if f j H ( j = 1 , 2 ) and initial data ( u 0 , u 1 , v 0 , v 1 ) X 0 × 0 , then for R 0 > 0 , there exist positive constants C ( R 0 ) and t 0 , so that when t t 0 , ( u , y 1 , v , y 2 ) determined by problems (1)–(3) satisfies

(12) ( u , y 1 , v , y 2 ) X 0 × 0 2 = m 1 u 2 + y 1 2 + 2 m 2 v 2 + y 2 2 C ( R 0 ) ,

where y 1 = u t + ε u , y 2 = v t + ε v .

Proof

Multiplying the first equation of (1) by y 1 in H and the second one by y 2 in H , we have

(13) 1 2 d d t y 1 2 + y 2 2 + 0 m 1 u 2 + 2 m 2 v 2 M ( τ ) d τ + 2 J ( u , v ) + ε M ( m 1 u 2 + 2 m 2 v 2 ) ( m 1 u 2 + 2 m 2 v 2 ) ε ( y 1 2 + y 2 2 ) + ε 2 ( ( u , y 1 ) + ( v , y 2 ) ) + N 1 ( m 1 u 2 ) m 1 y 1 2 + N 2 ( 2 m 2 v 2 ) 2 m 2 y 2 2 ε N 1 ( m 1 u 2 ) ( m 1 y 1 , m 1 u ) ε N 2 ( 2 m 2 v 2 ) ( 2 m 2 y 2 , 2 m 2 v ) + ε ( g 1 ( u , v ) , u ) + ε ( g 2 ( u , v ) , v ) = ( f 1 , y 1 ) + ( f 2 , y 2 ) .

By Holder’s inequality, Young’s inequality, and Poincare inequality, we have

(14) ε ( y 1 2 + y 2 2 ) + ε 2 ( ( u , y 1 ) + ( v , y 2 ) ) ε ε 2 2 ( y 1 2 + y 2 2 ) ε 2 2 ( u 2 + v 2 ) ε ε 2 2 ( y 1 2 + y 2 2 ) ε 2 2 λ 1 m 1 m 1 u 2 ε 2 2 λ 1 2 m 2 2 m 2 v 2 ,

(15) N 1 ( m 1 u 2 ) m 1 y 1 2 + N 2 ( 2 m 2 v 2 ) 2 m 2 y 2 2 ε N 1 ( m 1 u 2 ) ( m 1 y 1 , m 1 u ) ε N 2 ( 2 m 2 v 2 ) ( 2 m 2 y 2 , 2 m 2 v ) 1 2 N 1 ( m 1 u 2 ) m 1 y 1 2 + 1 2 N 2 ( 2 m 2 v 2 ) 2 m 2 y 2 2 ε 2 2 N 1 ( m 1 u 2 ) m 1 u 2 ε 2 2 N 2 ( 2 m 2 v 2 ) 2 m 2 v 2 1 2 λ 1 m 1 N 1 ( m 1 u 2 ) y 1 2 + 1 2 λ 1 2 m 2 N 2 ( 2 m 2 v 2 ) y 2 2 ε 2 2 N 1 ( m 1 u 2 ) m 1 u 2 ε 2 2 N 2 ( 2 m 2 v 2 ) 2 m 2 v 2 ,

(16) ( f 1 , y 1 ) + ( f 2 , y 2 ) f 1 y 1 + f 2 y 2 1 2 y 1 2 + 1 2 y 2 2 + 1 2 f 1 2 + 1 2 f 2 2 .

Inserting the aforementioned estimates into (13) gives

(17) 1 2 d d t y 1 2 + y 2 2 + 0 m 1 u 2 + 2 m 2 v 2 M ( τ ) d τ + 2 J ( u , v ) + 1 2 λ 1 m 1 N 1 ( m 1 u 2 ) 1 2 ε ε 2 2 y 1 2 + 1 2 λ 1 2 m 2 N 2 ( 2 m 2 v 2 ) 1 2 ε ε 2 2 y 2 2 + ε M ( m 1 u 2 + 2 m 2 v 2 ) ( m 1 u 2 + 2 m 2 v 2 ) ε 2 2 N 1 ( m 1 u 2 ) + ε 2 2 λ 1 m 1 m 1 u 2 ε 2 2 N 2 ( 2 m 2 v 2 ) + ε 2 2 λ 1 2 m 2 2 m 2 v 2 ε ( g 1 ( u , v ) , u ) ε ( g 2 ( u , v ) , v ) + 1 2 f 1 2 + 1 2 f 2 2 .

According to ( A 1 ) , we have

(18) ε M ( m 1 u 2 + 2 m 2 v 2 ) ( m 1 u 2 + 2 m 2 v 2 ) ε 4 0 m 1 u 2 + 2 m 2 v 2 M ( τ ) d τ + 3 ε 4 M ( m 1 u 2 + 2 m 2 v 2 ) ( m 1 u 2 + 2 m 2 v 2 ) ,

and according to ( A 2 ) , we have

(19) ε ( g 1 ( u , v ) , u ) ε ( g 2 ( u , v ) , v ) ε C 1 J ( u , v ) + ε μ ( m 1 u 2 + 2 m 2 v 2 ) + ε C μ .

Inserting (18) and (19) into (17) gives

(20) d d t y 1 2 + y 2 2 + 0 m 1 u 2 + 2 m 2 v 2 M ( τ ) d τ + 2 J ( u , v ) + ( λ 1 m 1 N 1 ( m 1 u 2 ) 1 2 ε ε 2 ) y 1 2 + ( λ 1 2 m 2 N 2 ( 2 m 2 v 2 ) 1 2 ε ε 2 ) y 2 2 + ε 2 0 m 1 u 2 + 2 m 2 v 2 M ( τ ) d τ + 2 ε C 1 J ( u , v ) + 3 ε 2 M ( m 1 u 2 + 2 m 2 v 2 ) 2 ε μ ε 2 N 1 ( m 1 u 2 ) ε 2 λ 1 m 1 m 1 u 2 + 3 ε 2 M ( m 1 u 2 + 2 m 2 v 2 ) 2 ε μ ε 2 N 2 ( 2 m 2 v 2 ) ε 2 λ 1 2 m 2 2 m 2 v 2 2 ε C μ + f 1 2 + f 2 2 .

Let H 1 ( t ) = y 1 2 + y 2 2 + 0 m 1 u 2 + 2 m 2 v 2 M ( τ ) d τ + 2 J ( u , v ) , and σ 1 = min { λ 1 m 1 N 10 1 2 ε ε 2 , λ 1 2 m 2 N 20 1 2 ε ε 2 , ε 2 , ε C 1 } , we can infer from (20) that

(21) d d t H 1 ( t ) + σ 1 H 1 ( t ) 2 ε C μ + f 1 2 + f 2 2 .

According to Gronwall’s inequality, we have

(22) H 1 ( t ) H 1 ( 0 ) e σ 1 t + 2 ε C μ + f 1 2 + f 2 2 σ 1 ,

and according to ( A 1 ) ( A 2 ) , we have

(23) H 1 ( t ) y 1 2 + y 2 2 + M 0 ( m 1 u 2 + 2 m 2 v 2 ) + 2 J ( u , v ) y 1 2 + y 2 2 + M 0 2 ( m 1 u 2 + 2 m 2 v 2 ) 2 C μ C 5 ( y 1 2 + y 2 2 + m 1 u 2 + 2 m 2 v 2 ) 2 C μ ,

where μ = M 0 4 , C 5 = min 1 , M 0 2 , then

(24) ( u , y 1 , v , y 2 ) X 0 × 0 2 = m 1 u 2 + y 1 2 + 2 m 2 v 2 + y 2 2 ( H 1 ( t ) + 2 C μ ) C 5 H 1 ( 0 ) e σ 1 t + 2 C μ C 5 + 2 ε C μ + f 1 2 + f 2 2 σ 1 C 5 ,

i.e.,

(25) lim t ¯ ( u , y 1 , v , y 2 ) X 0 × 0 2 2 C μ C 5 + 2 ε C μ + f 1 2 + f 2 2 σ 1 C 5 = R 0 .

Therefore, there exist positive constants C ( R 0 ) and t 0 that when t t 0 , we have

(26) ( u , y 1 , v , y 2 ) X 0 × 0 2 = m 1 u 2 + y 1 2 + 2 m 2 v 2 + y 2 2 C ( R 0 ) .

Thus, Lemma 3 is proved.□

Lemma 4

Assume that assumptions (A1)–(A4) hold, if f 1 V k 1 , f 2 V 2 k 2 , k 1 = 1 , 2 , , m 1 , k 2 = 1 , 2 , , m 2 , and initial data ( u 0 , u 1 , v 0 , v 1 ) X k 1 × k 2 . Then for R k 1 × k 2 > 0 , there exist positive constants C ( R k 1 × k 2 ) and t k 1 × k 2 that when t t k 1 × k 2 , ( u , y 1 , v , y 2 ) determined by problems (1)–(3) satisfies

(27) ( u , y 1 , v , y 2 ) X k 1 × k 2 2 = m 1 + k 1 u 2 + k 1 y 1 2 + 2 m 2 + 2 k 2 v 2 + 2 k 2 y 2 2 C ( R k 1 × k 2 ) ,

where y 1 = u t + ε u , y 2 = v t + ε v .

Proof

Multiplying the first equation of (1) by ( Δ ) k 1 y 1 , k 1 = 1 , 2 , , m 1 in H , the second one by ( Δ ) 2 k 2 y 2 , k 2 = 1 , 2 , , m 2 in H , and then integrating over Ω , we have

(28) 1 2 d d t [ k 1 y 1 2 + 2 k 2 y 2 2 + M ( m 1 u 2 + 2 m 2 v 2 ) ( m 1 + k 1 u 2 + 2 m 2 + 2 k 2 v 2 ) ] + ε M ( m 1 u 2 + 2 m 2 v 2 ) ( m 1 + k 1 u 2 + 2 m 2 + 2 k 2 v 2 ) ε ( k 1 y 1 2 + 2 k 2 y 2 2 ) + ε 2 ( ( k 1 u , k 1 y 1 ) + ( 2 k 2 v , 2 k 2 y 2 ) ) + N 1 ( m 1 u 2 ) m 1 + k 1 y 1 2 + N 2 ( 2 m 2 v 2 ) 2 m 2 + 2 k 2 y 2 2 ε N 1 ( m 1 u 2 ) ( m 1 + k 1 y 1 , m 1 + k 1 u ) ε N 2 ( 2 m 2 v 2 ) ( 2 m 2 + 2 k 2 y 2 , 2 m 2 + 2 k 2 v ) + ( g 1 ( u , v ) , ( Δ ) k 1 y 1 ) + ( g 2 ( u , v ) , ( Δ ) 2 k 2 y 2 ) = m 1 + k 1 u 2 + 2 m 2 + 2 k 2 v 2 2 d d t M ( m 1 u 2 + 2 m 2 v 2 ) + ( f 1 , ( Δ ) k 1 y 1 ) + ( f 2 , ( Δ ) 2 k 2 y 2 ) .

According to Holder’s inequality, Young’s inequality, and Poincare inequality, we have

(29) ε ( k 1 y 1 2 + 2 k 2 y 2 2 ) + ε 2 ( ( k 1 u , k 1 y 1 ) + ( 2 k 2 v , 2 k 2 y 2 ) ) ε ε 2 2 ( k 1 y 1 2 + 2 k 2 y 2 2 ) ε 2 2 ( k 1 u 2 + 2 k 2 v 2 ) ε ε 2 2 ( k 1 y 1 2 + 2 k 2 y 2 2 ) ε 2 2 λ 1 m 1 m 1 + k 1 u 2 ε 2 2 λ 1 2 m 2 2 m 2 + 2 k 2 v 2 ,

(30) N 1 ( m 1 u 2 ) m 1 + k 1 y 1 2 + N 2 ( 2 m 2 v 2 ) 2 m 2 + 2 k 2 y 2 2 ε N 1 ( m 1 u 2 ) ( m 1 + k 1 y 1 , m 1 + k 1 u ) ε N 2 ( 2 m 2 v 2 ) ( 2 m 2 + 2 k 2 y 2 , 2 m 2 + 2 k 2 v ) 1 2 N 1 ( m 1 u 2 ) m 1 + k 1 y 1 2 + 1 2 N 2 ( 2 m 2 v 2 ) 2 m 2 + 2 k 2 y 2 2 ε 2 2 N 1 ( m 1 u 2 ) m 1 + k 1 u 2 ε 2 2 N 2 ( 2 m 2 v 2 ) 2 m 2 + 2 k 2 v 2 ,

(31) ( g 1 ( u , v ) , ( Δ ) k 1 y 1 ) + ( g 2 ( u , v ) , ( Δ ) 2 k 2 y 2 ) g 1 ( u , v ) 2 k 2 y 1 + g 2 ( u , v ) 4 k 2 y 2 N 10 4 m 1 + k 1 y 1 2 + λ 1 k 1 m 1 N 10 g 1 ( u , v ) 2 + N 20 4 2 m 2 + 2 k 2 y 2 2 + λ 1 2 k 2 2 m 2 N 20 g 2 ( u , v ) 2 ,

(32) ( f 1 , ( Δ ) k 1 y 1 ) + ( f 2 , ( Δ ) 2 k 2 y 2 ) k 1 f 1 k 1 y 1 + 2 k 2 f 2 2 k 2 y 2 1 2 k 1 y 1 2 + 1 2 2 k 2 y 2 2 + 1 2 k 1 f 1 2 + 1 2 2 k 2 f 2 2 ,

and according to ( A 3 ) , we have

(33) g 1 ( u , v ) 2 = Ω g 1 ( u , v ) 2 d x Ω C 2 ( 1 + u p 1 + v q 1 ) 2 d x C 6 Ω ( 1 + u 2 p 1 + v 2 q 1 ) d x C 7 ( 1 + u 2 p 1 2 p 1 + v 2 q 1 2 q 1 ) , g 2 ( u , v ) 2 C 8 ( 1 + u 2 p 2 2 p 2 + v 2 q 2 2 q 2 ) .

Furthermore, on the basis of the Gagliardo-Nirenberg inequality, we can conclude that

u 2 p j 2 p j C 9 j m 1 u n ( p j 1 ) m 1 u 2 m 1 p j n ( p j 1 ) m 1 , v 2 q j 2 q j C 10 j 2 m 2 v n ( q j 1 ) 2 m 2 v 4 m 2 q j n ( q j 1 ) 2 m 2 .

Thus, we have

(34) g 1 ( u , v ) 2 + g 2 ( u , v ) 2 C ( R 0 ) .

By inserting (29)–(32) and (34) into (28), we obtain

(35) 1 2 d d t [ k 1 y 1 2 + 2 k 2 y 2 2 + M ( m 1 u 2 + 2 m 2 v 2 ) ( m 1 + k 1 u 2 + 2 m 2 + 2 k 2 v 2 ) ] + ( 2 N 1 ( m 1 u 2 ) N 10 ) λ 1 m 1 2 4 ε 2 ε 2 4 k 1 y 1 2 + ( 2 N 2 ( 2 m 2 v 2 ) N 20 ) λ 1 2 m 2 2 4 ε 2 ε 2 4 × 2 k 2 y 2 2 + ( ε M ( m 1 u 2 + 2 m 2 v 2 ) ε 2 2 N 1 ( m 1 u 2 ) ε 2 2 λ 1 m 1 ) m 1 + k 1 u 2 + ( ε M ( m 1 u 2 + 2 m 2 v 2 ) ε 2 2 N 2 ( 2 m 2 v 2 ) ε 2 2 λ 1 2 m 2 ) 2 m 2 + 2 k 2 v 2 m 1 + k 1 u 2 + 2 m 2 + 2 k 2 v 2 2 d d t M ( m 1 u 2 + 2 m 2 v 2 ) + 1 2 k 1 f 1 2 + 1 2 2 k 2 f 2 2 + C ( R 0 , λ 1 ) ( m 1 + k 1 u 2 + 2 m 2 + 2 k 2 v 2 ) M ( m 1 u 2 + 2 m 2 v 2 ) × ( ( m 1 u , m 1 u t ) + ( 2 m 2 v , 2 m 2 v t ) ) + 1 2 k 1 f 1 2 + 1 2 2 k 2 f 2 2 + C ( R 0 , λ 1 ) C 8 ( m 1 u t + 2 m 2 v t ) ( m 1 + k 1 u 2 + 2 m 2 + 2 k 2 v 2 ) + 1 2 k 1 f 1 2 + 1 2 2 k 2 f 2 2 + C ( R 0 , λ 1 ) .

Let H 2 ( t ) = k 1 y 1 2 + 2 k 2 y 2 2 + M ( m 1 u 2 + 2 m 2 v 2 ) ( m 1 + k 1 u 2 + 2 m 2 + 2 k 2 v 2 ) , and σ 2 = min { λ 1 m 1 N 10 2 4 ε 2 ε 2 2 , λ 1 2 m 2 N 20 2 4 ε 2 ε 2 2 , ε 2 } , we have

(36) d d t H 2 ( t ) + σ 2 H 2 ( t ) C 9 ( m 1 u t + 2 m 2 v t ) H 2 ( t ) + k 1 f 1 2 + 2 k 2 f 2 2 + C ( R 0 , λ 1 ) .

By taking the scalar product in H of (1) with u t , v t , we have

(37) 1 2 d d t u t 2 + v t 2 + 0 m 1 u 2 + 2 m 2 v 2 M ( τ ) d τ + 2 J ( u , v ) 2 ( f 1 , u ) 2 ( f 2 , v ) + N 1 ( m 1 u 2 ) m 1 u t 2 + N 2 ( 2 m 2 v 2 ) 2 m 2 v t 2 = 0 ,

and integrating (37) in d t on ( 0 , t ) derives

(38) 0 t ( m 1 u t ( τ ) 2 + 2 m 2 v t ( τ ) 2 ) d τ 1 min { N 10 , N 20 } 0 t ( N 1 ( m 1 u ( τ ) 2 ) m 1 u t ( τ ) 2 + N 2 ( 2 m 2 v ( τ ) 2 ) 2 m 2 v t ( τ ) 2 ) d τ 1 min { N 10 , N 20 } u 1 2 + v 1 2 + 0 m 1 u 0 2 + 2 m 2 v 0 2 M ( τ ) d τ + 2 J ( u 0 , v 0 ) 2 ( f 1 , u 0 ) 2 ( f 2 , v 0 ) C 10 ,

then, we have

(39) C 9 s t ( ( m 1 u t ( τ ) + 2 m 2 v t ( τ ) ) ) d τ σ 2 2 ( t s ) + a ,

for t > s 0 and some a > 0 . Together with (36), (39), and Lemma 1, we can obtain that

(40) H 2 ( t ) C 11 H 2 ( 0 ) e σ 2 2 t + C 12 .

According to ( A 1 ) , we have

(41) H 2 ( t ) k 1 y 1 2 + 2 k 2 y 2 2 + M ( m 1 u 2 + 2 m 2 v 2 ) ( m 1 + k 1 u 2 + 2 m 2 + 2 k 2 v 2 ) C 13 ( k 1 y 1 2 + 2 k 2 y 2 2 + m 1 + k 1 u 2 + 2 m 2 + 2 k 2 v 2 ) ,

then,

(42) ( u , y 1 , v , y 2 ) X k 1 × k 2 2 = k 1 y 1 2 + 2 k 2 y 2 2 + m 1 + k 1 u 2 + 2 m 2 + 2 k 2 v 2 C 11 H 2 ( 0 ) e σ 2 2 t + C 12 C 13 ,

i.e.,

(43) lim t ¯ ( u , y 1 , v , y 2 ) X k 1 × k 2 2 R k 1 × k 2 .

Therefore, there exist positive constants C ( R k 1 × k 2 ) and t k 1 × k 2 that when t t k 1 × k 2 , ( u , y 1 , v , y 2 ) satisfies

(44) ( u , y 1 , v , y 2 ) X k 1 × k 2 2 = k 1 y 1 2 + 2 k 2 y 2 2 + m 1 + k 1 u 2 + 2 m 2 + 2 k 2 v 2 C ( R k 1 × k 2 ) , k 1 = 1 , 2 , , m 1 , k 2 = 1 , 2 , , m 2 .

Thus, Lemma 4 is proved.□

Theorem 1

Assume that assumptions (A1)–(A4) hold, if f 1 V k 1 , f 2 V 2 k 2 and initial data ( u 0 , u 1 , v 0 , v 1 ) X k 1 × k 2 , k 1 = 0 , 1 , 2 , , m 1 , k 2 = 0 , 1 , 2 , , m 2 , then problems (1)–(3) admit a unique solution ( u , v ) satisfying

u L ( 0 , ; V m 1 + k 1 ) ; u t L ( 0 , ; H ) L 2 ( 0 , T ; V k 1 ) ; v L ( 0 , ; V 2 m 2 + 2 k 2 ) ; v t L ( 0 , ; H ) L 2 ( 0 , T ; V 2 k 2 ) .

Proof

According to [15] and the Faedo-Galerkin method, (1)–(3) have global solutions combining with Lemmas 3 and 4.

Let u 1 , v 1 and u 2 , v 2 be two solutions of problems (1)–(3) corresponding to the same initial data, respectively, w = u 1 u 2 , z = v 1 v 2 . Then, ( w , z ) solves

(45) w t t + 1 2 σ 12 ( t ) ( Δ ) m 1 w t + 1 2 Φ 12 ( t ) ( Δ ) m 1 w + G 1 ( u 1 , u 2 , v 1 , v 2 ; t ) = 0 , z t t + 1 2 σ 34 ( t ) ( Δ ) 2 m 2 z t + 1 2 Φ 12 ( t ) ( Δ ) 2 m 2 z + G 2 ( u 1 , u 2 , v 1 , v 2 ; t ) = 0 ,

where σ 12 = σ 1 ( t ) + σ 2 ( t ) , Φ 12 ( t ) = Φ 1 ( t ) + Φ 2 ( t ) , σ i ( t ) = N 1 ( m 1 u i 2 ) , Φ i ( t ) = M ( m 1 u i 2 + 2 m 2 v i 2 ) , i = 1 , 2 , σ 34 = σ 3 ( t ) + σ 4 ( t ) , σ j ( t ) = N 2 ( 2 m 2 v j 2 ) , j = 3 , 4 , G 1 ( u 1 , u 2 , v 1 , v 2 ; t ) = 1 2 { [ σ 1 ( t ) σ 2 ( t ) ] ( Δ ) m 1 ( u t 1 + u t 2 ) + [ Φ 1 ( t ) Φ 2 ( t ) ] ( Δ ) m 1 ( u 1 + u 2 ) } + g 1 ( u 1 , v 1 ) g 1 ( u 2 , v 2 ) , G 2 ( u 1 , u 2 , v 1 , v 2 ; t ) = 1 2 { [ σ 3 ( t ) σ 4 ( t ) ] ( Δ ) 2 m 2 ( v t 1 + v t 2 ) + [ Φ 1 ( t ) Φ 2 ( t ) ] ( Δ ) 2 m 2 ( v 1 + v 2 ) } + g 2 ( u 1 , v 1 ) g 2 ( u 2 , v 2 ) .

According to Lemma 3, σ 12 C ( R 0 ) ( m 1 u t 1 + m 1 u t 2 ) , σ 34 C ( R 0 ) ( 2 m 2 v t 1 + 2 m 2 v t 2 ) .

By taking the scalar product in H of (45) with w t , z t , we can obtain that

(46) 1 2 d d t w t 2 + z t 2 + 1 4 Φ 0 ( m 1 w 2 + 2 m 2 z 2 ) + 1 2 σ 12 ( t ) m 1 w t 2 + 1 2 σ 34 ( t ) 2 m 2 z t 2 + ( G 1 ( u 1 , u 2 , v 1 , v 2 ; t ) , w t ) + ( G 2 ( u 1 , u 2 , v 1 , v 2 ; t ) , z t ) = 0 .

According to Lemma 3 and ( A 1 ) , M 0 M C ( R 0 , H 1 ( 0 ) ) M 1 . When d d t ( m 1 w 2 + 2 m 2 z 2 ) 0 , Φ 0 = 2 M 0 ; otherwise Φ 0 = 2 M 1 .

Let ( G 1 ( u 1 , u 2 , v 1 , v 2 ; t ) , w t ) = G 11 + G 12 + G 13 , ( G 2 ( u 1 , u 2 , v 1 , v 2 ; t ) , z t ) = G 21 + G 22 + G 23 , we have

(47) G 11 = 1 2 ( σ 1 ( t ) σ 2 ( t ) ) ( m 1 ( u t 1 + u t 2 ) , m 1 w t ) C ( R 0 ) ( m 1 u t 1 + m 1 u t 2 ) m 1 w m 1 w t σ 120 8 m 1 w t 2 + 2 C ( R 0 ) σ 120 ( m 1 u t 1 2 + m 1 u t 2 2 ) m 1 w 2 ,

(48) G 12 = 1 2 ( Φ 1 ( t ) Φ 2 ( t ) ) ( m 1 ( u 1 + u 2 ) , m 1 w t ) C ( R 0 ) ( m 1 w + 2 m 2 z ) m 1 w t σ 120 8 m 1 w t 2 + 2 C ( R 0 ) σ 120 ( m 1 w 2 + 2 m 2 z 2 ) ,

(49) G 13 = ( g 1 ( u 1 , v 1 ) g 1 ( u 2 , v 2 ) , w t ) C ( R 0 ) ( w t 2 + m 1 w 2 + 2 m 2 z 2 ) ,

(50) G 21 = 1 2 ( σ 3 ( t ) σ 4 ( t ) ) ( 2 m 2 ( v t 1 + v t 2 ) , 2 m 2 z t ) C ( R 0 ) ( 2 m 2 v t 1 + 2 m 2 v t 2 ) 2 m 2 z 2 m 2 z t σ 340 8 2 m 2 z t 2 + 2 C ( R 0 ) σ 340 ( 2 m 2 v t 1 2 + 2 m 2 v t 2 2 ) 2 m 2 z 2 ,

(51) G 22 = 1 2 ( Φ 1 ( t ) Φ 2 ( t ) ) ( 2 m 2 ( v 1 + v 2 ) , 2 m 2 z t ) C ( R 0 ) ( m 1 w + 2 m 2 z ) 2 m 2 z t σ 340 8 2 m 2 z t 2 + 2 C ( R 0 ) σ 340 ( m 1 w 2 + 2 m 2 z 2 ) ,

(52) G 23 = ( g 2 ( u 1 , v 1 ) g 2 ( u 2 , v 2 ) , z t ) C ( R 0 ) ( z t 2 + m 1 w 2 + 2 m 2 z 2 ) ,

where σ 120 = 2 N 10 , σ 340 = 2 N 20 .

By inserting (46)–(52) into (45), we have

(53) 1 2 d d t w t 2 + z t 2 + 1 4 Φ 0 ( m 1 w 2 + 2 m 2 z 2 ) C 14 ( 1 + 2 m 2 v t 1 2 + 2 m 2 v t 2 2 ) w t 2 + z t 2 + 1 4 Φ 0 ( m 1 w 2 + 2 m 2 z 2 ) .

Solving this differential inequality yields

(54) w t 2 + z t 2 + 1 4 Φ 0 ( m 1 w 2 + 2 m 2 z 2 ) w 1 2 + z 1 2 + 1 4 Φ 0 ( m 1 w 0 2 + 2 m 2 z 0 2 ) exp 0 t C 14 ( 1 + 2 m 2 v t 1 2 + 2 m 2 v t 2 2 ) d s .

Thus, the uniqueness of the solution is proved.□

Therefore, problems (1)–(3) possess a unique solution u , v . Theorem 1 is proved.

According to Theorem 1, we define a nonlinear operator { S ( t ) } t 0 on space X 0 × 0 : S ( t ) ( u 0 , u 1 , v 0 , v 1 ) = ( u , u t , v , v t ) , for all t 0 . Theorem 1 shows that { S ( t ) } t 0 compose a continuous semi-group in X 0 × 0 . Before proving the family of global attractors, we first give their definition.

Definition 1

Let X 0 be a Banach space, and { S ( t ) } t 0 be a continuous operator semi-group, if there exist compact sets A k 1 × k 2 that satisfies

  1. Invariance: all A k 1 × k 2 are invariant sets under the action of the semi-group { S ( t ) } t 0 ,

    S ( t ) A k 1 × k 2 = A k 1 × k 2 ; for all t 0 .

  2. Attractiveness: all A k 1 × k 2 attract all bounded sets in X 0 , i.e., for any bounded B X 0 ,

    dist ( S ( t ) B , A k 1 × k 2 ) = sup x B inf y A k 1 × k 2 S ( t ) x y X 0 0 , t .

In particular, when t , all trajectories S ( t ) u 0 from u 0 converge to A k 1 × k 2 , i.e.,

dist ( S ( t ) u 0 , A k 1 × k 2 ) 0 , t .

Then, compact sets A k are all global attractors of the semi-group { S ( t ) } t 0 . Let A = { A k 1 × k 2 X 0 : k 1 = 1 , 2 , , m 1 , k 2 = 1 , 2 , , m 2 } be a family of subsets in X 0 . Finally, the family A is the family of global attractors in X 0 .

Theorem 2

Assume that assumptions (A1)–(A4) hold, if f 1 V m 1 , f 2 V 2 m 2 and initial data ( u 0 , u 1 , v 0 , v 1 ) X m 1 × m 2 , then, problems (1)–(3) have a family of global attractors A in X 0 × 0

A = { A k 1 × k 2 } , A k 1 × k 2 = ω ( B k 1 × k 2 , 0 ) = τ 0 t τ S ( t ) B k 1 × k 2 , 0 ¯ , k 1 = 1 , 2 , , m 1 , k 2 = 1 , 2 , , m 2 ,

where B k 1 × k 2 , 0 = { ( u , u t , v , v t ) X k 1 × k 2 : ( u , u t , v , v t ) X k 1 × k 2 2 = m 1 + k 1 u 2 + k 1 u t 2 + 2 m 2 + 2 k 2 v 2 + 2 k 2 v t 2 C ( R 0 ) + C ( R k 1 × k 2 ) } are bounded absorbing sets in X 0 × 0 , B k 1 × k 2 , 0 are compact in X 0 × 0 , A k 1 × k 2 X 0 × 0 .

  1. S ( t ) A k 1 × k 2 = A k 1 × k 2 , (for all t 0 ),

  2. A k 1 × k 2 attract all bounded sets in X 0 × 0 , i.e., for all B k 1 × k 2 X 0 × 0 are bounded sets in X 0 × 0 , and

    dist ( S ( t ) B k 1 × k 2 , A k 1 × k 2 ) = sup x B k 1 × k 2 inf y A k 1 × k 2 S ( t ) x y X 0 × 0 0 ( t ) ,

    where { S ( t ) } t 0 is the solution semi-group generated by problems (1)–(3).

Proof

According to Lemma 3, for all R 0 > 0 , ( u 0 , u 1 , v 0 , v 1 ) X 0 × 0 R 0 . Thus,

S ( t ) ( u 0 , u 1 , v 0 , v 1 ) X 0 × 0 2 = u V m 1 2 + u t V 0 2 + v V 2 m 2 2 + v t V 0 2 C ( R 0 )

show that { S ( t ) } t 0 are uniformly bounded in X 0 × 0 ; further, B k 1 × k 2 , 0 = { ( u , u t , v , v t ) X k 1 × k 2 : ( u , u t , v , v t ) X k 1 × k 2 2 = m 1 + k 1 u 2 + k 1 u t 2 + 2 m 2 + 2 k 2 v 2 + 2 k 2 v t 2 C ( R 0 ) + C ( R k 1 × k 2 ) } are bounded absorbing sets of the semi-group { S ( t ) } t 0 in X 0 × 0 ; because X k 1 × k 2 X 0 × 0 are compactly embedding, i.e., the bounded sets in X k 1 × k 2 are compact sets in X 0 × 0 , the solution semi-group { S ( t ) } t 0 is a fully continuous operator.

To sum up, we obtained the family of global attractors A = { A k 1 × k 2 } of the solution semi-group { S ( t ) } t 0 in X 0 × 0 , and

A k 1 × k 2 = ω ( B k 1 × k 2 , 0 ) = τ 0 t τ S ( t ) B k 1 × k 2 , 0 ¯ , A k 1 × k 2 X 0 × 0 , k 1 = 1 , 2 , , m 1 , k 2 = 1 , 2 , , m 2 .

Theorem 2 is proved.□

Note 1. Lemma 4 and Theorem 2 show that the bounded absorbing sets B k 1 × k 2 , 0 = { ( u , u t , v , v t ) X k 1 × k 2 : ( u , u t , v , v t ) X k 1 × k 2 2 = m 1 + k 1 u 2 + k 1 u t 2 + 2 m 2 + 2 k 2 v 2 + 2 k 2 v t 2 C ( R 0 ) + C ( R k 1 × k 2 ) } are compact bounded absorbing sets in X 0 × 0 . Therefore, based on condition 3 in Lemma 2, the operator semi-group { S ( t ) } t 0 only needs to be a continuous operator. According to Theorem 1, the semi-group { S ( t ) } t 0 is already a continuous semi-group. Thus, the family of global attractors A = { A k 1 × k 2 } of problems (1)–(3) in X 0 × 0 can also be obtained.

4 Conclusion

In this article, we studied a class of higher-order coupled Kirchhoff systems with nonlinear strong damping. For the first time, we systematically defined the family of global attractors and proved the existence of the family of global attractors of problems (1)–(3). The results enriched the related conclusions of higher-order coupled Kirchhoff models and laid a theoretical foundation for future practical applications.

Acknowledgments

The authors would like to thank the anonymous referees for their comments and suggestions, which helped greatly improve the article.

  1. Funding information: This work was partially supported by the basic science (Natural Science) research project of colleges and universities in Jiangsu Province (21KJB110013) and the fundamental research fund of Yunnan Education Department (2020J0908).

  2. Author contributions: All authors have accepted responsibility for the entire content of this manuscript and approved its submission.

  3. Conflict of interest: The authors state no conflict of interest.

  4. Data availability statement: Data sharing is not applicable to this article as no data sets were generated or analyzed during this study.

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Received: 2022-10-10
Revised: 2023-01-01
Accepted: 2023-01-24
Published Online: 2023-03-28

© 2023 the author(s), published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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