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Two Rationales for Insufficient Entry

  • Linfeng Chen EMAIL logo , Tan Li und Bing Qian
Veröffentlicht/Copyright: 11. Juni 2019

Abstract

This study offers two new rationales for insufficient entry in a given industry. The first is the presence of complementary industries. Suppose there is free entry in an industry and the complementary industries are monopolistic. If the number of complementary industries is sufficiently high, then there is insufficient entry. However, if these industries are substitutes, then there is always excessive entry. The second rationale is that there is cost-reducing R&D investment and spillover. When the spillover rate is sufficiently high, there is insufficient entry. Further, we consider the general model and obtain similar results.

JEL Classification: D21; D43; L13; L22

Acknowledgements

We would like to thank the editor, Ronald Peeters, and referees for helpful comments. We would like to thank Zijun Luo, Wing Suen, Chi-Wa Yuen, and Rong Zhu for their valuable comments. All errors remain our own.

Appendix

A Appendix for Section 2 Model 1: Complementary Industries

Firm l maximizes πl by choosing ql , and firm i maximizes πi by choosing Qi. Then, we obtain the first-order conditions as follows.

πiQi=(pic)bQi=a2bQirj=1,jij=mQjrj=1j=nqjc=0,πlql=(p0c)bql=ab(j=1j=nqj)r(j=1j=mQj)cbql=0.

By symmetry, we have Qj=Q for j=1,2,m , and qj=q for j=1,2,n . Then, we obtain the equilibrium quantity as follows.

qj=q=(ac)(2br)2b2(n+1)+br(m1)(n+1)mnr2,Qj=Q=(ac)(b+nbnr)2b2(n+1)+br(m1)(n+1)mnr2.

The profit for firms in industry 0 is

bq2=b((ac)(2br)2b2(n+1)+br(m1)(n+1)mnr2)2.

Free entry requires that the profit of firms in industry 0 is equal to f. Hence

bq2=b((ac)(2br)2b2(n+1)+br(m1)(n+1)mnr2)2=f.

Due to linear demand, we obtain the social welfare as follows.

sw=aj=1j=nqj+aj=1j=mQj12(b(j=1j=nqj)2+bj=1j=mQj2+2r(j=1j=nqj)(j=1j=mQj)+ri,j=1,iji,j=mQiQj)cj=1j=nqjcj=1j=mQj=anq+amQ12(b(nq)2+bmQ2+2rnqmQ+rm(m1)Q2)cnqcmQ=(ac)2X2(2b2(n+1)+br(m1)(n+1)mnr2)2,X=b3(3m(n+1)2+4n(n+2))+b2(m2(n+1)24n(n+2)m(n+1)(3n+1))rb(m+1)n(2n+2m(n+1))r2+m(m+1)n2r3.

Social efficiency requires that

sw(n)=b2(ac)2(2br)(4b2+br(m4mn)+(1+m(n1))r2)(2b2(n+1)+br(m1)(n+1)mnr2)3=f.

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Supplementary Material

The online version of this article offers supplementary material (DOI:https://doi.org/10.1515/bejte-2018-0054).


Published Online: 2019-06-11

© 2019 Walter de Gruyter GmbH, Berlin/Boston

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