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Solutions of a coupled system of hybrid boundary value problems with Riesz-Caputo derivative

  • Dehong Ji , Shiqiu Fu and Yitao Yang EMAIL logo
Published/Copyright: January 24, 2024
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Abstract

Riesz-Caputo fractional derivative refers to a fractional derivative that reflects both the past and the future memory effects. This study gives sufficient conditions for the existence of solutions for a coupled system of fractional order hybrid differential equations involving the Riesz-Caputo fractional derivative. For this motive, the results are obtained via classical results due to Dhage.

MSC 2010: 34A08; 34A12

1 Introduction

The fractional differential equations have become a significant field of investigation due to their frequent use in biophysics, economics, chemistry, mechanics, control theory, image processing and signal, etc. [13]. Recently, existence theory of solutions to initial and boundary value problems for fractional system has received considerable attention from many researchers [411].

As is known to all, Riesz-Caputo derivative refers to a fractional derivative that reflects both the future and the past memory effects; consequently, the Riesz fractional operator plays an important role in characterizing anomalous diffusion, owing to successful applications to subdiffusive, superdiffusive, and evolution problems. Space fractional quantum mechanics is a natural generalization of standard quantum mechanics, which arises when the Brownian trajectories in Feynman path integrals are replaced by Levy flights. The classical Levy flight is a stochastic processes, which in one dimension, is described by a jump length probability density function. The position space representation of the α th power of the momentum operator is given by:

x P ˆ α ψ = h α D x α ψ ( x ) ,

where D x α is the Riesz fractional derivative operator of order α . The Riesz fractional derivative is regarded as an effective tool for studying nonlocal and memory effects in physics, engineering, and applied sciences. Therefore, many scholars are engaged in the study of the solutions of differential equations with the Riesz fractional derivative. Many works carried out so far discuss the numerical solutions of diffusion equations, which contain the Riesz derivative, and fractional variational problems, which contain the Riesz-Caputo derivative, and only a few works report on the existence results of fractional boundary value problems, which contain the Riesz-Caputo derivative.

Gu et al. [12] discussed a new class of differential equations that contains the Riesz-Caputo fractional derivative:

D 1 α 0 R C x ( ξ ) = h ( ξ , x ( ξ ) ) , ξ [ 0 , 1 ] , 0 < α 1 ,

x ( 0 ) = x 0 , x ( 1 ) = x 1 .

On the other hand, hybrid differential equation is a class of dynamical systems with quadratic perturbation. Nowadays, due to the wide range of application of hybrid differential equations in several areas of real-life problems, more researchers began to study the existence of solutions for hybrid differential equations with different perturbations (readers can refer to [1320]).

Houas [21] studied the results for the coupled hybrid system that contains integral boundary conditions as follows:

D α 1 u 1 ( t ) g 1 ( t , u 1 ( t ) , u 2 ( t ) ) = f 1 ( t , u 1 ( t ) , u 2 ( t ) ) , t [ 0 , 1 ] , α 1 ( 0 , 1 ) ,

D α 2 u 2 ( t ) g 2 ( t , u 1 ( t ) , u 2 ( t ) ) = f 2 ( t , u 1 ( t ) , u 2 ( t ) ) , t [ 0 , 1 ] , α 1 ( 0 , 1 ) ,

u 1 ( 0 ) = 0 θ 1 A 1 ( s ) u 1 ( s ) d s , θ 1 ( 0 , 1 ) ,

u 2 ( 0 ) = 0 θ 2 A 2 ( s ) u 2 ( s ) d s , θ 2 ( 0 , 1 ) ,

where D α i ( i = 1 , 2 ) stands for the Caputo’s derivative.

Derbazi et al. [22] considered the solutions for the fractional boundary value problem as follows:

D 0 + α C x ( t ) f ( t , x ( t ) ) g ( t , x ( t ) ) = h ( t , x ( t ) ) , 1 < α 2 , t J = [ 0 , T ] ,

a 1 x ( t ) f ( t , x ( t ) ) g ( t , x ( t ) ) t = 0 + b 1 x ( t ) f ( t , x ( t ) ) g ( t , x ( t ) ) t = T = λ 1 ,

a 2 D 0 + β C x ( t ) f ( t , x ( t ) ) g ( t , x ( t ) ) t = η + b 2 D 0 + β C x ( t ) f ( t , x ( t ) ) g ( t , x ( t ) ) t = T = λ 2 , 0 < η < T ,

where C D 0 + α and D 0 + β C stand for the Caputo fractional derivative.

Recently, Baleanu et al. [23] discussed the hybrid fractional coupled system as follows:

D ω x ( t ) H ( t , x ( t ) , z ( t ) ) = K 1 ( t , x ( t ) , z ( t ) ) , ω ( 2 , 3 ] ,

D ε z ( t ) g ( t , x ( t ) , z ( t ) ) = K 2 ( t , x ( t ) , z ( t ) ) , ε ( 2 , 3 ] ,

x ( t ) H ( t , x ( t ) , z ( t ) ) t = 1 = 0 , D μ x ( t ) H ( t , x ( t ) , z ( t ) ) t = δ 1 = 0 , x ( 2 ) ( 0 ) = 0 ,

z ( t ) g ( t , x ( t ) , z ( t ) ) t = 1 = 0 , D ν z ( t ) g ( t , x ( t ) , z ( t ) ) t = δ 2 = 0 , x ( 2 ) ( 0 ) = 0 ,

where D ω , D ε , D μ , and D ν stand for the Caputo’s fractional derivative.

By virtue of the aforementioned documents, in this work, the authors present the solutions for the hybrid fractional coupled system that contains the Riesz-Caputo derivative as follows:

(1) D 1 γ 0 R C x ( t ) f 1 ( t , x ( t ) , y ( t ) ) g 1 ( t , x ( t ) , y ( t ) ) = h 1 ( t , x ( t ) , y ( t ) ) , 0 < γ 1 ,

(2) D 1 ν 0 R C y ( t ) f 2 ( t , x ( t ) , y ( t ) ) g 2 ( t , x ( t ) , y ( t ) ) = h 2 ( t , x ( t ) , y ( t ) ) , 0 < ν 1 ,

(3) x ( 0 ) = a 1 , x ( 1 ) = b 1 ,

(4) y ( 0 ) = a 2 , y ( 1 ) = b 2 ,

where 0 < γ 1 , 0 < ν 1 , 0 t 1 , D 1 γ 0 R C , and D 1 ν 0 R C are Riesz-Caputo’s fractional derivative of orders γ , ν , f 1 , f 2 , h 1 , h 2 C ( [ 0 , 1 ] × R 2 , R ) , g 1 , g 2 C ( [ 0 , 1 ] × R 2 , R \ { 0 } ) and a 1 , a 2 , b 1 , and b 2 are the real constants. We will use “Dhage’s fixed point theorem” to find the sufficient conditions for the existence of solutions. This is the first time for us to present the existence of solutions of Systems (1)–(4).

2 Some lemmas

Suppose n 1 < α n , n N for α > 0 , and n = [ ω ] and [ ] stands for the ceiling of a number.

Definition 2.1

[24] The Riesz-Caputo fractional derivative for a function x ( t ) , 0 t T , can be written as follows:

D T α 0 R C x ( t ) = 1 Γ ( n α ) 0 T x ( n ) ( u ) t u α + 1 n d u = 1 2 ( D t α 0 C + ( 1 ) n t C D T α ) x ( t ) ,

where D t α 0 C is the left Caputo derivative and D T α t C is the right Caputo derivatives

D t α 0 C x ( t ) = 1 Γ ( n α ) 0 t x ( n ) ( u ) ( t u ) α + 1 n d u

and

t C D T α x ( t ) = ( 1 ) n Γ ( n α ) t T x ( n ) ( u ) ( u t ) α + 1 n d u .

Particularly, for x ( t ) C ( 0 , T ) , then

D T α 0 R C x ( t ) = 1 2 ( D t α 0 C t C D T α ) x ( t ) ,

if 0 < α 1 .

Definition 2.2

[24] The right, left, and fractional Riemann-Liouville integrals of order α can be written as follows:

I T α t x ( t ) = 1 Γ ( α ) t T ( u t ) α 1 x ( u ) d u ,

I t α 0 x ( t ) = 1 Γ ( α ) 0 t ( t u ) α 1 x ( u ) d u ,

I T α 0 x ( t ) = 1 Γ ( α ) 0 T u t α 1 x ( u ) d u .

Lemma 2.1

[24] Let x ( t ) C n [ 0 , T ] , we have

I t 0 α C 0 D t α x ( t ) = x ( t ) l = 0 n 1 x ( l ) ( 0 ) l ! ( t 0 ) l

and

I T t α C t D T α x ( t ) = ( 1 ) n x ( t ) l = 0 n 1 ( 1 ) l x ( l ) ( T ) l ! ( T t ) l .

From the aforementioned equations, thus we have

I T 0 α R C 0 D T α x ( t ) = 1 2 ( I t 0 α C 0 D t α + t I T 0 α C D t α ) x ( t ) + ( 1 ) n 1 2 ( I t t α C 0 D T α + I T t α C t D T α ) x ( t ) = 1 2 ( I t 0 α C 0 D t α + ( 1 ) n I T t α C t D T α ) x ( t ) .

Particularly, for x ( t ) C ( 0 , T ) , then

(5) I T 0 α R C 0 D T α x ( t ) = x ( t ) 1 2 ( x ( 0 ) + x ( T ) ) ,

if 0 < α 1 .

Lemma 2.2

[25] Let S be a closed convex, bounded, and nonempty subset of a Banach algebra E , and let A , C : E E and B : S E be three operators such that

  1. A and C are Lipschitzian with Lipschitz constants δ and ρ , respectively,

  2. B is compact and continuous,

  3. x = A x B y + C x x S for all y S ,

  4. δ M + ρ < 1 , where M = B ( S ) .

Then, there is a solution for the operator equation A x B x + C x = x in S .

3 Main results

The Banach space C [ 0 , 1 ] is recorded as X . The norm is defined as follows: x = max t [ 0 , 1 ] x ( t ) . Under the following norm definition ( x , y ) = x + y , we have E = X × X , which is a Banach space.

Definition 3.1

[26] If there is a constant μ > 0 that satisfies

F ( w , z ) F ( w ¯ , z ¯ ) μ ( w w ¯ + z z ¯ )

for all ( w , z ) , ( w ¯ , z ¯ ) E , we call F : E E as μ -Lipschitz. Moreover, if μ < 1 , we call F as a strict contraction.

Lemma 3.1

Let h C [ 0 , 1 ] . Then, the equation

(6) x ( t ) = g ( t , x ( t ) y ( t ) ) 1 2 a 1 f ( 0 , a 1 , a 2 ) g ( 0 , a 1 , a 2 ) + 1 2 b 1 f ( 1 , b 1 , b 2 ) g ( 1 , b 1 , b 2 ) + 1 Γ ( γ ) 0 t ( t s ) γ 1 h ( s ) d s + 1 Γ ( γ ) t 1 ( s t ) γ 1 h ( s ) d s + f ( t , x ( t ) , y ( t ) )

is the solution of the boundary value problem:

(7) D 1 γ 0 R C x ( t ) f ( t , x ( t ) , y ( t ) ) g ( t , x ( t ) , y ( t ) ) = h ( t ) , 0 < γ 1 ,

(8) x ( 0 ) = a 1 , x ( 1 ) = b 1 ,

(9) y ( 0 ) = a 2 , y ( 1 ) = b 2 .

Proof

Integrating on both sides of equation (7) and considering (5), (8), and (9), we obtain

x ( t ) f ( t , x ( t ) , y ( t ) ) g ( t , x ( t ) , y ( t ) ) = 0 I 1 γ h ( t ) + 1 2 a 1 f ( 0 , a 1 , a 2 ) g ( 0 , a 1 , a 2 ) + 1 2 b 1 f ( 1 , b 1 , b 2 ) g ( 1 , b 1 , b 2 ) .

Consequently, we find that

x ( t ) f ( t , x ( t ) , y ( t ) ) g ( t , x ( t ) , y ( t ) ) = 1 2 a 1 f ( 0 , a 1 , a 2 ) g ( 0 , a 1 , a 2 ) + 1 2 b 1 f ( 1 , b 1 , b 2 ) g ( 1 , b 1 , b 2 ) + 1 Γ ( γ ) 0 t ( t s ) γ 1 h ( s ) d s + 1 Γ ( γ ) t 1 ( s t ) γ 1 h ( s ) d s .

Therefore, (6) holds.□

Define the operator T mapping E to E

(10) T ( x , y ) ( t ) = ( T 1 ( x , y ) ( t ) , T 2 ( x , y ) ( t ) ) ,

where

(11) T 1 ( x , y ) ( t ) = g 1 ( t , x ( t ) , y ( t ) ) 1 2 a 1 f 1 ( 0 , a 1 , a 2 ) g 1 ( 0 , a 1 , a 2 ) + 1 2 b 1 f 1 ( 1 , b 1 , b 2 ) g 1 ( 1 , b 1 , b 2 ) + 1 Γ ( γ ) 0 t ( t s ) γ 1 h 1 ( s , x ( s ) , y ( s ) ) d s + 1 Γ ( γ ) t 1 ( s t ) γ 1 h 1 ( s , x ( s ) , y ( s ) ) d s + f 1 ( t , x ( t ) , y ( t ) ) ,

(12) T 2 ( x , y ) ( t ) = g 2 ( t , x ( t ) , y ( t ) ) 1 2 a 2 f 2 ( 0 , a 1 , a 2 ) g 2 ( 0 , a 1 , a 2 ) + 1 2 b 2 f 2 ( 1 , b 1 , b 2 ) g 2 ( 1 , b 1 , b 2 ) + 1 Γ ( ν ) 0 t ( t s ) ν 1 h 2 ( s , x ( s ) , y ( s ) ) d s + 1 Γ ( ν ) t 1 ( s t ) ν 1 h 2 ( s , x ( s ) , y ( s ) ) d s + f 2 ( t , x ( t ) , y ( t ) ) .

We give the hypotheses of this study.

( H 1 ) f 1 , f 2 , h 1 , h 2 : [ 0 , 1 ] × R 2 R and g 1 , g 2 : [ 0 , 1 ] × R 2 R \ { 0 } are continuous functions;

( H 2 ) ϕ 0 , ϕ 1 , ϕ 0 ¯ , ϕ 1 ¯ are four positive functions such that

(13) f 1 ( t , x , y ) f 1 ( t , x ¯ , y ¯ ) ϕ 0 ( t ) [ x x ¯ + y y ¯ ] ,

(14) f 2 ( t , x , y ) f 2 ( t , x ¯ , y ¯ ) ϕ 0 ¯ ( t ) [ x x ¯ + y y ¯ ] ,

(15) g 1 ( t , x , y ) g 1 ( t , x ¯ , y ¯ ) ϕ 1 ( t ) [ x x ¯ + y y ¯ ] ,

(16) g 2 ( t , x , y ) g 2 ( t , x ¯ , y ¯ ) ϕ 1 ¯ ( t ) [ x x ¯ + y y ¯ ] ,

for all t [ 0 , 1 ] , x , x ¯ , y , and y ¯ are the elements in R ;

( H 3 ) Functions p 1 , p 2 L ( J , R + ) and four continuous nondecreasing functions ψ 1 , ψ 2 , ξ 1 , ξ 2 : [ 0 , ) ( 0 , ) satisfy

(17) h 1 ( t , x , y ) p 1 ( t ) ψ 1 ( x ) ξ 1 ( y ) ,

(18) h 2 ( t , x , y ) p 2 ( t ) ψ 2 ( x ) ξ 2 ( y ) ,

for all t [ 0 , 1 ] , x and y are the elements in R ;

( H 4 ) The positive number r satisfies

(19) 1 1 ρ g 1 Λ + f 1 1 ϕ 1 Λ ϕ 0 + g 2 Λ + f 2 1 ϕ 1 ¯ Λ ϕ 0 ¯ < r ,

where

(20) ρ = max ϕ 1 Λ + ϕ 0 1 ϕ 1 Λ ϕ 0 , ϕ 1 ¯ Λ + ϕ 0 ¯ 1 ϕ 1 ¯ Λ ϕ 0 ¯ ,

(21) Λ = 1 2 a 1 f 1 ( 0 , a 1 , a 2 ) g 1 ( 0 , a 1 , a 2 ) + 1 2 b 1 f 1 ( 1 , b 1 , b 2 ) g 1 ( 1 , b 1 , b 2 ) + 2 ψ 1 ( r ) ξ 1 ( r ) p 1 Γ ( γ + 1 ) + 1 2 a 2 f 2 ( 0 , a 1 , a 2 ) g 2 ( 0 , a 1 , a 2 ) + 1 2 b 2 f 2 ( 1 , b 1 , b 2 ) g 2 ( 1 , b 1 , b 2 ) + 2 ψ 2 ( r ) ξ 2 ( r ) p 2 Γ ( ν + 1 ) ,

and ϕ 1 Λ + ϕ 0 < 1 2 , ϕ 1 ¯ Λ + ϕ 0 ¯ < 1 2 , f 1 = sup t [ 0 , 1 ] f 1 ( t , 0 , 0 ) , f 2 = sup t [ 0 , 1 ] f 2 ( t , 0 , 0 ) , g 1 = sup t [ 0 , 1 ] g 1 ( t , 0 , 0 ) , g 2 = sup t [ 0 , 1 ] g 2 ( t , 0 , 0 ) .

Theorem 3.2

Problems (1)–(4) have a solution, if Conditions ( H 1 )–( H 4 ) are true.

Proof

Let

(22) S = { ( x , y ) E : ( x , y ) r } .

Then, S is a bounded convex closed subset of E .

Define operators A i , C i : E X and B i : S X ( i = 1 , 2 ) by

(23) A 1 ( x ( t ) , y ( t ) ) = g 1 ( t , x ( t ) , y ( t ) ) , A 2 ( x ( t ) , y ( t ) ) = g 2 ( t , x ( t ) , y ( t ) ) ,

(24) B 1 ( x ( t ) , y ( t ) ) = 1 2 a 1 f 1 ( 0 , a 1 , a 2 ) g 1 ( 0 , a 1 , a 2 ) + 1 2 b 1 f 1 ( 1 , b 1 , b 2 ) g 1 ( 1 , b 1 , b 2 ) + 1 Γ ( γ ) 0 t ( t s ) γ 1 h 1 ( s , x ( s ) , y ( s ) ) d s + 1 Γ ( γ ) t 1 ( s t ) γ 1 h 1 ( s , x ( s ) , y ( s ) ) d s ,

(25) B 2 ( x ( t ) , y ( t ) ) = 1 2 a 2 f 2 ( 0 , a 1 , a 2 ) g 2 ( 0 , a 1 , a 2 ) + 1 2 b 2 f 2 ( 1 , b 1 , b 2 ) g 2 ( 1 , b 1 , b 2 ) + 1 Γ ( ν ) 0 t ( t s ) ν 1 h 2 ( s , x ( s ) , y ( s ) ) d s + 1 Γ ( ν ) t 1 ( s t ) ν 1 h 2 ( s , x ( s ) , y ( s ) ) d s ,

(26) C 1 ( x ( t ) , y ( t ) ) = f 1 ( t , x ( t ) , y ( t ) ) , and C 2 ( x ( t ) , y ( t ) ) = f 2 ( t , x ( t ) , y ( t ) ) .

Then, operators T 1 and T 2 given by equations (11) and (12) are equivalent to

(27) T 1 ( x ( t ) , y ( t ) ) = A 1 ( x ( t ) , y ( t ) ) B 1 ( x ( t ) , y ( t ) ) + C 1 ( x ( t ) , y ( t ) ) ,

(28) T 2 ( x ( t ) , y ( t ) ) = A 2 ( x ( t ) , y ( t ) ) B 2 ( x ( t ) , y ( t ) ) + C 2 ( x ( t ) , y ( t ) ) .

Therefore, the operator T in equation (10) can be written as follows:

T ( x , y ) ( t ) = ( T 1 ( x , y ) ( t ) , T 2 ( x , y ) ( t ) ) = A ( x ( t ) , y ( t ) ) B ( x ( t ) , y ( t ) ) + C ( x ( t ) , y ( t ) ) ,

where A = ( A 1 , A 2 ) , B = ( B 1 , B 2 ) , and C = ( C 1 , C 2 ) . In the following, we prove that the conditions in Lemma 2.2 can be satisfied.

First, we prove that A and C are Lipschitz on the space E . Given ( x 1 , y 1 ) , ( x 2 , y 2 ) E , and t [ 0 , 1 ] , then by ( H 2 ) , we obtain

(29) A 1 ( x 1 , y 1 ) ( t ) A 1 ( x 2 , y 2 ) ( t ) = g 1 ( t , x 1 ( t ) , y 1 ( t ) ) g 1 ( t , x 2 ( t ) , y 2 ( t ) ) ϕ 1 ( t ) ( x 1 ( t ) x 2 ( t ) + y 1 ( t ) y 2 ( t ) ) .

Similarly,

(30) A 2 ( x 1 , y 1 ) ( t ) A 2 ( x 2 , y 2 ) ( t ) = g 2 ( t , x 1 ( t ) , y 1 ( t ) ) g 2 ( t , x 2 ( t ) , y 2 ( t ) ) ϕ 1 ¯ ( t ) ( x 1 ( t ) x 2 ( t ) + y 1 ( t ) y 2 ( t ) ) .

From equations (29) and (30), we obtain

A ( x 1 , y 1 ) ( t ) A ( x 2 , y 2 ) ( t ) = ( A 1 , A 2 ) ( x 1 , y 1 ) ( A 1 , A 2 ) ( x 2 , y 2 ) ( ϕ 1 ( t ) + ϕ 1 ¯ ( t ) ) ( x 1 ( t ) x 2 ( t ) + y 1 ( t ) y 2 ( t ) )

for all t on the interval [ 0 , 1 ] . Taking the supremum on both sides of the aforementioned formula with respect to t , we have

A ( x 1 , y 1 ) A ( x 2 , y 2 ) ( ϕ 1 + ϕ 1 ¯ ) ( x 1 x 2 + y 1 y 2 ) ,

which implies that A is Lipschitz on the space E with Lipschitz constant ϕ 1 + ϕ 1 ¯ .

We consider C : E X , ( x 1 , y 1 ) , ( x 2 , y 2 ) E , then

(31) C 1 ( x 1 , y 1 ) ( t ) C 1 ( x 2 , y 2 ) ( t ) = f 1 ( t , x 1 ( t ) , y 1 ( t ) ) f 1 ( t , x 2 ( t ) , y 2 ( t ) ) ϕ 0 ( t ) ( x 1 ( t ) x 2 ( t ) + y 1 ( t ) y 2 ( t ) ) .

Similarly,

(32) C 2 ( x 1 , y 1 ) ( t ) C 2 ( x 2 , y 2 ) ( t ) = f 2 ( t , x 1 ( t ) , y 1 ( t ) ) f 2 ( t , x 2 ( t ) , y 2 ( t ) ) ϕ 0 ¯ ( t ) ( x 1 ( t ) x 2 ( t ) + y 1 ( t ) y 2 ( t ) ) .

From equations (31) and (32), we obtain

C ( x 1 , y 1 ) ( t ) C ( x 2 , y 2 ) ( t ) = ( C 1 , C 2 ) ( x 1 , y 1 ) ( C 1 , C 2 ) ( x 2 , y 2 ) ( ϕ 0 ( t ) + ϕ 0 ¯ ( t ) ) ( x 1 ( t ) x 2 ( t ) + y 1 ( t ) y 2 ( t ) )

for all t on the interval [ 0 , 1 ] . Taking the supremum on both sides of the aforementioned formula with respect to t , we obtain

C ( x 1 , y 1 ) C ( x 2 , y 2 ) ( ϕ 0 + ϕ 0 ¯ ) ( x 1 x 2 + y 1 y 2 ) ,

which implies that C is Lipschitz on the space E with Lipschitz constant ϕ 0 + ϕ 0 ¯ .

Second, we prove that B is completely continuous mapping S to X . In Step 1, we show that B is a continuous operator on S . To prove this, assume that { x n } , { y n } are convergent sequences and satisfy x n x , y n y as n + . By the Lebesgue dominated convergence theorem, we have

(33) lim n B 1 ( x n , y n ) = lim n 1 2 a 1 f 1 ( 0 , a 1 , a 2 ) g 1 ( 0 , a 1 , a 2 ) + 1 2 b 1 f 1 ( 1 , b 1 , b 2 ) g 1 ( 1 , b 1 , b 2 ) + 1 Γ ( γ ) 0 t ( t s ) γ 1 h 1 ( s , x n ( s ) , y n ( s ) ) d s + 1 Γ ( γ ) t 1 ( s t ) γ 1 h 1 ( s , x n ( s ) , y n ( s ) ) d s = 1 2 a 1 f 1 ( 0 , a 1 , a 2 ) g 1 ( 0 , a 1 , a 2 ) + 1 2 b 1 f 1 ( 1 , b 1 , b 2 ) g 1 ( 1 , b 1 , b 2 ) + 1 Γ ( γ ) lim n 0 t ( t s ) γ 1 h 1 ( s , x n ( s ) , y n ( s ) ) d s + 1 Γ ( γ ) lim n t 1 ( s t ) γ 1 h 1 ( s , x n ( s ) , y n ( s ) ) d s = 1 2 a 1 f 1 ( 0 , a 1 , a 2 ) g 1 ( 0 , a 1 , a 2 ) + 1 2 b 1 f 1 ( 1 , b 1 , b 2 ) g 1 ( 1 , b 1 , b 2 ) + 1 Γ ( γ ) 0 t ( t s ) γ 1 lim n h 1 ( s , x n ( s ) , y n ( s ) ) d s + 1 Γ ( γ ) t 1 ( s t ) γ 1 lim n h 1 ( s , x n ( s ) , y n ( s ) ) d s = 1 2 a 1 f 1 ( 0 , a 1 , a 2 ) g 1 ( 0 , a 1 , a 2 ) + 1 2 b 1 f 1 ( 1 , b 1 , b 2 ) g 1 ( 1 , b 1 , b 2 ) + 1 Γ ( γ ) 0 t ( t s ) γ 1 h 1 ( s , x ( s ) , y ( s ) ) d s + 1 Γ ( γ ) t 1 ( s t ) γ 1 h 1 ( s , x ( s ) , y ( s ) ) d s = B 1 ( x , y ) .

Similarly, we have

(34) lim n B 2 ( x n , y n ) = lim n 1 2 a 2 f 2 ( 0 , a 1 , a 2 ) g 2 ( 0 , a 1 , a 2 ) + 1 2 b 2 f 2 ( 1 , b 1 , b 2 ) g 2 ( 1 , b 1 , b 2 ) + 1 Γ ( ν ) 0 t ( t s ) ν 1 h 2 ( s , x n ( s ) , y n ( s ) ) d s + 1 Γ ( ν ) t 1 ( s t ) ν 1 h 2 ( s , x n ( s ) , y n ( s ) ) d s = 1 2 a 2 f 2 ( 0 , a 1 , a 2 ) g 2 ( 0 , a 1 , a 2 ) + 1 2 b 2 f 2 ( 1 , b 1 , b 2 ) g 2 ( 1 , b 1 , b 2 ) + 1 Γ ( ν ) lim n 0 t ( t s ) ν 1 h 2 ( s , x n ( s ) , y n ( s ) ) d s + 1 Γ ( ν ) lim n t 1 ( s t ) ν 1 h 2 ( s , x n ( s ) , y n ( s ) ) d s = 1 2 a 2 f 2 ( 0 , a 1 , a 2 ) g 2 ( 0 , a 1 , a 2 ) + 1 2 b 2 f 2 ( 1 , b 1 , b 2 ) g 2 ( 1 , b 1 , b 2 ) + 1 Γ ( ν ) 0 t ( t s ) ν 1 lim n h 2 ( s , x n ( s ) , y n ( s ) ) d s + 1 Γ ( ν ) t 1 ( s t ) ν 1 lim n h 2 ( s , x n ( s ) , y n ( s ) ) d s = 1 2 a 2 f 2 ( 0 , a 1 , a 2 ) g 2 ( 0 , a 1 , a 2 ) + 1 2 b 2 f 2 ( 1 , b 1 , b 2 ) g 2 ( 1 , b 1 , b 2 ) + 1 Γ ( ν ) 0 t ( t s ) ν 1 h 2 ( s , x ( s ) , y ( s ) ) d s + 1 Γ ( ν ) t 1 ( s t ) ν 1 h 2 ( s , x ( s ) , y ( s ) ) d s = B 2 ( x , y ) .

In view of equations (33) and (34), for all t [ 0 , 1 ] , the operator B = ( B 1 , B 2 ) is a continuous operator.

In Step 2, we prove that in S , the set B ( S ) is uniformly bounded. For any ( x , y ) S , in consideration of ( H 3 ) , we obtain

(35) B 1 ( x ( t ) , y ( t ) ) 1 2 a 1 f 1 ( 0 , a 1 , a 2 ) g 1 ( 0 , a 1 , a 2 ) + 1 2 b 1 f 1 ( 1 , b 1 , b 2 ) g 1 ( 1 , b 1 , b 2 ) + 1 Γ ( γ ) 0 t ( t s ) γ 1 h 1 ( s , x ( s ) , y ( s ) ) d s + 1 Γ ( γ ) t 1 ( s t ) γ 1 h 1 ( s , x ( s ) , y ( s ) ) d s 1 2 a 1 f 1 ( 0 , a 1 , a 2 ) g 1 ( 0 , a 1 , a 2 ) + 1 2 b 1 f 1 ( 1 , b 1 , b 2 ) g 1 ( 1 , b 1 , b 2 ) + 1 Γ ( γ ) 0 t ( t s ) γ 1 p 1 ( s ) ψ 1 ( r ) ξ 1 ( r ) d s + 1 Γ ( γ ) t 1 ( s t ) γ 1 p 1 ( s ) ψ 1 ( r ) ξ 1 ( r ) d s = 1 2 a 1 f 1 ( 0 , a 1 , a 2 ) g 1 ( 0 , a 1 , a 2 ) + 1 2 b 1 f 1 ( 1 , b 1 , b 2 ) g 1 ( 1 , b 1 , b 2 ) + p 1 ψ 1 ( r ) ξ 1 ( r ) 1 Γ ( γ ) 0 t ( t s ) γ 1 d s + t 1 ( s t ) γ 1 d s = 1 2 a 1 f 1 ( 0 , a 1 , a 2 ) g 1 ( 0 , a 1 , a 2 ) + 1 2 b 1 f 1 ( 1 , b 1 , b 2 ) g 1 ( 1 , b 1 , b 2 ) + 2 p 1 ψ 1 ( r ) ξ 1 ( r ) Γ ( γ + 1 ) .

(36) B 2 ( x ( t ) , y ( t ) ) 1 2 a 2 f 2 ( 0 , a 1 , a 2 ) g 2 ( 0 , a 1 , a 2 ) + 1 2 b 2 f 2 ( 1 , b 1 , b 2 ) g 2 ( 1 , b 1 , b 2 ) + 1 Γ ( ν ) 0 t ( t s ) ν 1 h 2 ( s , x ( s ) , y ( s ) ) d s + 1 Γ ( ν ) t 1 ( s t ) ν 1 h 2 ( s , x ( s ) , y ( s ) ) d s 1 2 a 2 f 2 ( 0 , a 1 , a 2 ) g 2 ( 0 , a 1 , a 2 ) + 1 2 b 2 f 2 ( 1 , b 1 , b 2 ) g 2 ( 1 , b 1 , b 2 ) + p 2 ψ 2 ( r ) ξ 2 ( r ) 1 Γ ( ν ) 0 t ( t s ) ν 1 d s + t 1 ( s t ) ν 1 d s = 1 2 a 2 f 2 ( 0 , a 1 , a 2 ) g 2 ( 0 , a 1 , a 2 ) + 1 2 b 2 f 2 ( 1 , b 1 , b 2 ) g 2 ( 1 , b 1 , b 2 ) + 2 p 2 ψ 2 ( r ) ξ 2 ( r ) Γ ( ν + 1 ) .

Thus, B ( x , y ) Λ for all ( x , y ) S with Λ given in equation (21), which implies that the set B ( S ) is a uniformly bounded set in S .

In the following, we show that the operator B is equicontinuous. To prove this, given 0 t 1 t 2 1 , ( x , y ) S , we can find

(37) B 1 ( x , y ) ( t 2 ) B 1 ( x , y ) ( t 1 ) = 1 Γ ( γ ) 0 t 2 ( t 2 s ) γ 1 h 1 ( s , x ( s ) , y ( s ) ) d s + 1 Γ ( γ ) t 2 1 ( s t 2 ) γ 1 h 1 ( s , x ( s ) , y ( s ) ) d s 1 Γ ( γ ) 0 t 1 ( t 1 s ) γ 1 h 1 ( s , x ( s ) , y ( s ) ) d s 1 Γ ( γ ) t 1 1 ( s t 1 ) γ 1 h 1 ( s , x ( s ) , y ( s ) ) d s 1 Γ ( γ ) 0 t 1 ( ( t 2 s ) γ 1 ( t 1 s ) γ 1 ) h 1 ( s , x ( s ) , y ( s ) ) d s + 1 Γ ( γ ) t 1 t 2 ( ( t 2 s ) γ 1 ( s t 1 ) γ 1 ) h 1 ( s , x ( s ) , y ( s ) ) d s + 1 Γ ( γ ) t 2 1 ( ( s t 2 ) γ 1 ( s t 1 ) γ 1 ) h 1 ( s , x ( s ) , y ( s ) ) d s p 1 ψ 1 ( r ) ξ 1 ( r ) Γ ( γ ) 0 t 1 ( ( t 2 s ) γ 1 ( t 1 s ) γ 1 ) d s + t 1 t 2 ( ( t 2 s ) γ 1 ( s t 1 ) γ 1 ) d s + t 2 1 ( ( s t 2 ) γ 1 ( s t 1 ) γ 1 ) d s = p 1 ψ 1 ( r ) ξ 1 ( r ) Γ ( γ + 1 ) [ ( t 2 γ ( t 2 t 1 ) γ t 1 γ ) + ( 1 t 2 ) γ ( 1 t 1 ) γ + ( t 2 t 1 ) γ ] = p 1 ψ 1 ( r ) ξ 1 ( r ) Γ ( γ + 1 ) [ t 2 γ t 1 γ + ( 1 t 2 ) γ ( 1 t 1 ) γ ] .

Similarly, we obtain

(38) B 2 ( x , y ) ( t 2 ) B 2 ( x , y ) ( t 1 ) = 1 Γ ( ν ) 0 t 2 ( t 2 s ) ν 1 h 2 ( s , x ( s ) , y ( s ) ) d s + 1 Γ ( ν ) t 2 1 ( s t 2 ) ν 1 h 2 ( s , x ( s ) , y ( s ) ) d s 1 Γ ( ν ) 0 t 1 ( t 1 s ) ν 1 h 2 ( s , x ( s ) , y ( s ) ) d s 1 Γ ( ν ) t 1 1 ( s t 1 ) ν 1 h 2 ( s , x ( s ) , y ( s ) ) d s p 2 ψ 2 ( r ) ξ 2 ( r ) Γ ( ν + 1 ) 0 t 1 ( ( t 2 s ) ν 1 ( t 1 s ) ν 1 ) d s + t 1 t 2 ( ( t 2 s ) ν 1 ( s t 1 ) ν 1 ) d s + t 2 1 ( ( s t 2 ) ν 1 ( s t 1 ) ν 1 ) d s = p 2 ψ 2 ( r ) ξ 2 ( r ) Γ ( ν + 1 ) [ t 2 ν t 1 ν + ( 1 t 2 ) ν ( 1 t 1 ) ν ] .

Using equations (37) and (38), we find that

B ( x , y ) ( t 2 ) B ( x , y ) ( t 1 ) p 1 ψ 1 ( r ) ξ 1 ( r ) Γ ( γ + 1 ) [ t 2 γ t 1 γ + ( 1 t 2 ) γ ( 1 t 1 ) γ ] + p 2 ψ 2 ( r ) ξ 2 ( r ) Γ ( ν + 1 ) [ t 2 ν t 1 ν + ( 1 t 2 ) ν ( 1 t 1 ) ν ] .

Thus, when t 2 t 1 , we have B ( x , y ) ( t 2 ) B ( x , y ) ( t 1 ) 0 , so that we can find that B is equicontinuous; therefore, we have the operator B that is compact according to the Arzela-Ascoli theorem.

Third, we prove that conditions (c) of Lemma 2.2 holds.

Take any two elements x , y from E and any two elements x ¯ , y ¯ from S , which satisfy ( x , y ) = A ( x , y ) B ( x , y ) + C ( x , y ) ; using ( H 2 ) , ( H 3 ) , and ( H 4 ) , we find

(39) x ( t ) A 1 ( x ( t ) , y ( t ) ) B 1 ( x ¯ ( t ) , y ¯ ( t ) ) + C 1 ( x ( t ) , y ( t ) ) g 1 ( t , x ( t ) y ( t ) ) 1 2 a 1 f 1 ( 0 , a 1 , a 2 ) g 1 ( 0 , a 1 , a 2 ) + 1 2 b 1 f 1 ( 1 , b 1 , b 2 ) g 1 ( 1 , b 1 , b 2 ) + 1 Γ ( γ ) 0 t ( t s ) γ 1 h 1 ( s , x ¯ ( s ) , y ¯ ( s ) ) d s + 1 Γ ( γ ) t 1 ( s t ) γ 1 h 1 ( s , x ¯ ( s ) , y ¯ ( s ) ) d s + f 1 ( t , x ( t ) y ( t ) ) ( g 1 ( t , x ( t ) y ( t ) ) g 1 ( t , 0 , 0 ) + g 1 ( t , 0 , 0 ) ) 1 2 a 1 f 1 ( 0 , a 1 , a 2 ) g 1 ( 0 , a 1 , a 2 ) + 1 2 b 1 f 1 ( 1 , b 1 , b 2 ) g 1 ( 1 , b 1 , b 2 ) + p 1 ψ 1 ( r ) ξ 1 ( r ) Γ ( γ ) 0 t ( t s ) γ 1 d s + t 1 ( s t ) γ 1 d s + ( f 1 ( t , x ( t ) y ( t ) ) f 1 ( t , 0 , 0 ) + f 1 ( t , 0 , 0 ) ) ( ϕ 1 ( x ( t ) + y ( t ) ) + g 1 ) Λ + ϕ 0 ( x ( t ) + y ( t ) ) + f 1 .

Taking the supremum on both sides of the aforementioned formula with respect to t ,

x ( ϕ 1 ( x + y ) + g 1 ) Λ + ϕ 0 ( x + y ) + f 1 ,

this equals to

x ( ϕ 1 Λ + ϕ 0 ) y + g 1 Λ + f 1 1 ϕ 1 Λ ϕ 0 .

Similarly, we obtain

(40) y ( t ) A 2 ( x ( t ) , y ( t ) ) B 2 ( x ¯ ( t ) , y ¯ ( t ) ) + C 2 ( x ( t ) , y ( t ) ) g 2 ( t , x ( t ) y ( t ) ) 1 2 a 2 f 2 ( 0 , a 1 , a 2 ) g 2 ( 0 , a 1 , a 2 ) + 1 2 b 2 f 2 ( 1 , b 1 , b 2 ) g 2 ( 1 , b 1 , b 2 ) + 1 Γ ( ν ) 0 t ( t s ) ν 1 h 2 ( s , x ¯ ( s ) , y ¯ ( s ) ) d s + 1 Γ ( ν ) t 1 ( s t ) ν 1 h 2 ( s , x ¯ ( s ) , y ¯ ( s ) ) d s + f 2 ( t , x ( t ) y ( t ) ) ( g 2 ( t , x ( t ) y ( t ) ) g 2 ( t , 0 , 0 ) + g 2 ( t , 0 , 0 ) ) 1 2 a 2 f 2 ( 0 , a 1 , a 2 ) g 2 ( 0 , a 1 , a 2 ) + 1 2 b 2 f 2 ( 1 , b 1 , b 2 ) g 2 ( 1 , b 1 , b 2 ) + p 2 ψ 2 ( r ) ξ 2 ( r ) Γ ( ν ) 0 t ( t s ) ν 1 d s + t 1 ( s t ) ν 1 d s + ( f 2 ( t , x ( t ) y ( t ) ) f 2 ( t , 0 , 0 ) + f 2 ( t , 0 , 0 ) ) ( ϕ 1 ¯ ( x ( t ) + y ( t ) ) + g 2 ) Λ + ϕ 0 ¯ ( x ( t ) + y ( t ) ) + f 2 .

Thus,

y ( ϕ 1 ¯ ( x + y ) + g 2 ) Λ + ϕ 0 ¯ ( x + y ) + f 2 ,

which equals to

y ( ϕ 1 ¯ Λ + ϕ 0 ¯ ) x + g 2 Λ + f 2 1 ϕ 1 ¯ Λ ϕ 0 ¯ ,

so,

(41) ( x , y ) = x + y ( ϕ 1 Λ + ϕ 0 ) y + g 1 Λ + f 1 1 ϕ 1 Λ ϕ 0 + ( ϕ 1 ¯ Λ + ϕ 0 ¯ ) x + g 2 Λ + f 2 1 ϕ 1 ¯ Λ ϕ 0 ¯ = ( ϕ 1 Λ + ϕ 0 ) y 1 ϕ 1 Λ ϕ 0 + g 1 Λ + f 1 1 ϕ 1 Λ ϕ 0 + ( ϕ 1 ¯ Λ + ϕ 0 ¯ ) x 1 ϕ 1 ¯ Λ ϕ 0 ¯ + g 2 Λ + f 2 1 ϕ 1 ¯ Λ ϕ 0 ¯ .

Therefore, we have

( x , y ) 1 1 ρ g 1 Λ + f 1 1 ϕ 1 Λ ϕ 0 + g 2 Λ + f 2 1 ϕ 1 ¯ Λ ϕ 0 ¯ < r .

Fourth, we show that δ M + ρ < 1 .

Since M = B ( S ) = sup ( x , y ) S ( sup t [ 0 , 1 ] B ( x , y ) ( t ) ) < Λ , using ( H 4 ) , we find

( ϕ 1 + ϕ 1 ¯ ) M + ϕ 0 + ϕ 0 ¯ ( ϕ 1 + ϕ 1 ¯ ) Λ + ϕ 0 + ϕ 0 ¯ < 1 .

Therefore, all the conditions of Lemma 2.2 are satisfied, so that T ( x , y ) ( t ) = A ( x , y ) B ( x , y ) + C ( x , y ) has a coupled fixed point in S ; consequently, Problems (1)–(4) have a solution defined on [0,1].□

4 Example

We consider the hybrid boundary value systems with the Riesz–Caputo derivative:

(42) D 1 1 2 0 R C x ( t ) t 2 100 ( x ( t ) + y ( t ) + 10 ) x ( t ) 1 + x ( t ) + y ( t ) 1 + y ( t ) + 10 = t 10,000 sin x ( t ) y ( t ) 1 + y ( t ) ,

(43) D 1 1 2 0 R C y ( t ) t 2 50 ( x ( t ) + y ( t ) + 10 ) x ( t ) 1 + x ( t ) + y ( t ) 1 + y ( t ) + 11 = t 10,000 cos t 4 sin x ( t ) y ( t ) 1 + y ( t ) ,

(44) x ( 0 ) = 0 , x ( 1 ) = 1 ,

(45) y ( 0 ) = 0 , y ( 1 ) = 1 .

We note that γ = ν = 1 2 , a 1 = 0 , a 2 = 0 , b 1 = 1 , b 2 = 1 ,

f 1 ( t , x , y ) = t 2 100 ( x + y + 10 ) , f 2 ( t , x , y ) = t 2 50 ( x + y + 10 ) ,

g 1 ( t , x , y ) = x 1 + x + y 1 + y + 10 , g 2 ( t , x , y ) = x 1 + x + y 1 + y + 11 ,

h 1 ( t , x , y ) = t 10,000 sin x ( t ) y 1 + y , and h 2 ( t , x , y ) = t 10,000 cos t 4 sin x ( t ) y 1 + y .

We can show that

f 1 ( t , x , y ) f 1 ( t , x ¯ , y ¯ ) t 2 100 ( x x ¯ + y y ¯ ) , f 2 ( t , x , y ) f 2 ( t , x ¯ , y ¯ ) t 2 50 ( x x ¯ + y y ¯ ) , g 1 ( t , x , y ) g 1 ( t , x ¯ , y ¯ ) x x ¯ + y y ¯ , g 2 ( t , x , y ) g 2 ( t , x ¯ , y ¯ ) x x ¯ + y y ¯ .

Hence, we obtain φ 0 ( t ) = t 2 100 , φ 0 ¯ ( t ) = t 2 50 , φ 1 ( t ) = 1 , φ 1 ¯ ( t ) = 1 , Γ ( γ + 1 ) = Γ ( ν + 1 ) = Γ ( 3 2 ) = 0.886 , then φ 0 = 1 100 , φ 0 ¯ = 1 50 , φ 1 = 1 , and φ 1 ¯ = 1 ,

h 1 ( t , x , y ) p 1 ( t ) ψ 1 ( x ) ξ 1 ( y ) , h 2 ( t , x , y ) p 2 ( t ) ψ 2 ( x ) ξ 2 ( y ) ,

where

p 1 ( t ) = t 10,000 , ψ 1 ( x ) = x , ξ 1 ( y ) = y , p 2 ( t ) = t 10,000 cos t 4 , ψ 2 ( x ) = x , ξ 2 ( y ) = y ,

then p 1 = 1 10,000 , p 2 = 1 10,000 , and

f 1 = sup t [ 0 , 1 ] f 1 ( t , 0 , 0 ) = sup t [ 0 , 1 ] t 2 10 = 1 10 , f 2 = sup t [ 0 , 1 ] f 2 ( t , 0 , 0 ) = sup t [ 0 , 1 ] t 2 5 = 1 5 ,

g 1 = sup t [ 0 , 1 ] g 1 ( t , 0 , 0 ) = sup t [ 0 , 1 ] 10 = 10 , g 2 = sup t [ 0 , 1 ] g 2 ( t , 0 , 0 ) = sup t [ 0 , 1 ] 11 = 11 ,

f 1 ( 0 , 0 , 0 ) = 0 , f 2 ( 0 , 0 , 0 ) = 0 , f 1 ( 1 , 1 , 1 ) = 12 100 , f 2 ( 1 , 1 , 1 ) = 12 50 , g 1 ( 1 , 1 , 1 ) = 11 , and g 2 ( 1 , 1 , 1 ) = 12 .

We choose r = 10 ; by calculation Λ = 0.1168 , ρ = 0.158 ; thus,

1 1 ρ g 1 Λ + f 1 1 ϕ 1 Λ ϕ 0 + g 2 Λ + f 2 1 ϕ 1 ¯ Λ ϕ 0 ¯ = 3.768 < 10 = r .

So far, we have proved that all conditions in Theorem 3.2 are satisfied, which implies that Problems (42)–(45) have a solution.

5 Conclusion

We have presented the existence results of a coupled system of hybrid boundary value problems with the Riesz-Caputo derivative with the aid of the Dhage fixed point theorem. The novelty of this kind of fractional derivative is Riesz-Caputo fractional derivative that can reflect both the past and the future memory effects.

Acknowledgements

We express our sincere thanks to the anonymous reviewers for their valuable comments and suggestions. This work was supported by the Natural Science Foundation of Tianjin (No. 19JCYBJC30700), Ministry of Education Industry-University Cooperative Education Project in 2022 (Nos. 220503009174427 and 220505265245612). Tianjin University of Technology Teaching Fund (No. KG21-04).

  1. Funding information: This study was funded by National Science Foundation of Tianjin (No. 19JCYBJC30700), the first batch of the cooperation and education projects of the Ministry of Education in 2022 (Nos 220503009174427 and 220505265245612), and Tianjin University of Technology Teaching Fund (No. KG21-04).

  2. Author contributions: All authors accepted responsibility for the entire content of this manuscript and approved its submission.

  3. Conflict of interest: The authors state that there is no conflict of interest.

  4. Ethical approval: The conducted research is not related to either human or animal use.

  5. Data availability statement: Data sharing is not applicable to this article as no datasets were generated or analyzed during this study.

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Received: 2023-03-06
Revised: 2023-05-16
Accepted: 2023-10-06
Published Online: 2024-01-24

© 2024 the author(s), published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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  78. Differential sandwich theorems for p-valent analytic functions associated with a generalization of the integral operator
  79. Special Issue on Development of Fuzzy Sets and Their Extensions - Part II
  80. Higher-order circular intuitionistic fuzzy time series forecasting methodology: Application of stock change index
  81. Binary relations applied to the fuzzy substructures of quantales under rough environment
  82. Algorithm selection model based on fuzzy multi-criteria decision in big data information mining
  83. A new machine learning approach based on spatial fuzzy data correlation for recognizing sports activities
  84. Benchmarking the efficiency of distribution warehouses using a four-phase integrated PCA-DEA-improved fuzzy SWARA-CoCoSo model for sustainable distribution
  85. Special Issue on Application of Fractional Calculus: Mathematical Modeling and Control - Part II
  86. A study on a type of degenerate poly-Dedekind sums
  87. Efficient scheme for a category of variable-order optimal control problems based on the sixth-kind Chebyshev polynomials
  88. Special Issue on Mathematics for Artificial intelligence and Artificial intelligence for Mathematics
  89. Toward automated hail disaster weather recognition based on spatio-temporal sequence of radar images
  90. The shortest-path and bee colony optimization algorithms for traffic control at single intersection with NetworkX application
  91. Neural network quaternion-based controller for port-Hamiltonian system
  92. Matching ontologies with kernel principle component analysis and evolutionary algorithm
  93. Survey on machine vision-based intelligent water quality monitoring techniques in water treatment plant: Fish activity behavior recognition-based schemes and applications
  94. Artificial intelligence-driven tone recognition of Guzheng: A linear prediction approach
  95. Transformer learning-based neural network algorithms for identification and detection of electronic bullying in social media
  96. Squirrel search algorithm-support vector machine: Assessing civil engineering budgeting course using an SSA-optimized SVM model
  97. Special Issue on International E-Conference on Mathematical and Statistical Sciences - Part I
  98. Some fixed point results on ultrametric spaces endowed with a graph
  99. On the generalized Mellin integral operators
  100. On existence and multiplicity of solutions for a biharmonic problem with weights via Ricceri's theorem
  101. Approximation process of a positive linear operator of hypergeometric type
  102. On Kantorovich variant of Brass-Stancu operators
  103. A higher-dimensional categorical perspective on 2-crossed modules
  104. Special Issue on Some Integral Inequalities, Integral Equations, and Applications - Part I
  105. On parameterized inequalities for fractional multiplicative integrals
  106. On inverse source term for heat equation with memory term
  107. On Fejér-type inequalities for generalized trigonometrically and hyperbolic k-convex functions
  108. New extensions related to Fejér-type inequalities for GA-convex functions
  109. Derivation of Hermite-Hadamard-Jensen-Mercer conticrete inequalities for Atangana-Baleanu fractional integrals by means of majorization
  110. Some Hardy's inequalities on conformable fractional calculus
  111. The novel quadratic phase Fourier S-transform and associated uncertainty principles in the quaternion setting
  112. Special Issue on Recent Developments in Fixed-Point Theory and Applications - Part I
  113. A novel iterative process for numerical reckoning of fixed points via generalized nonlinear mappings with qualitative study
  114. Some new fixed point theorems of α-partially nonexpansive mappings
  115. Generalized Yosida inclusion problem involving multi-valued operator with XOR operation
  116. Periodic and fixed points for mappings in extended b-gauge spaces equipped with a graph
  117. Convergence of Peaceman-Rachford splitting method with Bregman distance for three-block nonconvex nonseparable optimization
  118. Topological structure of the solution sets to neutral evolution inclusions driven by measures
  119. (α, F)-Geraghty-type generalized F-contractions on non-Archimedean fuzzy metric-unlike spaces
  120. Solvability of infinite system of integral equations of Hammerstein type in three variables in tempering sequence spaces c 0 β and 1 β
  121. Special Issue on Nonlinear Evolution Equations and Their Applications - Part I
  122. Fuzzy fractional delay integro-differential equation with the generalized Atangana-Baleanu fractional derivative
  123. Klein-Gordon potential in characteristic coordinates
  124. Asymptotic analysis of Leray solution for the incompressible NSE with damping
  125. Special Issue on Blow-up Phenomena in Nonlinear Equations of Mathematical Physics - Part I
  126. Long time decay of incompressible convective Brinkman-Forchheimer in L2(ℝ3)
  127. Numerical solution of general order Emden-Fowler-type Pantograph delay differential equations
  128. Global smooth solution to the n-dimensional liquid crystal equations with fractional dissipation
  129. Spectral properties for a system of Dirac equations with nonlinear dependence on the spectral parameter
  130. A memory-type thermoelastic laminated beam with structural damping and microtemperature effects: Well-posedness and general decay
  131. The asymptotic behavior for the Navier-Stokes-Voigt-Brinkman-Forchheimer equations with memory and Tresca friction in a thin domain
  132. Absence of global solutions to wave equations with structural damping and nonlinear memory
  133. Special Issue on Differential Equations and Numerical Analysis - Part I
  134. Vanishing viscosity limit for a one-dimensional viscous conservation law in the presence of two noninteracting shocks
  135. Limiting dynamics for stochastic complex Ginzburg-Landau systems with time-varying delays on unbounded thin domains
  136. A comparison of two nonconforming finite element methods for linear three-field poroelasticity
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