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Scattering threshold for the focusing energy-critical generalized Hartree equation

  • Saleh Almuthaybiri , Congming Peng and Tarek Saanouni EMAIL logo
Published/Copyright: April 19, 2024

Abstract

This work investigates the asymptotic behavior of energy solutions to the focusing nonlinear Schrödinger equation of Choquard type

i t u + Δ u + u p 2 ( I α * u p ) u = 0 , p = 1 + 2 + α N 2 , N 3 .

Indeed, in the energy-critical spherically symmetric regime, one proves a global existence and scattering versus finite time blow-up dichotomy. Precisely, if the data have an energy less than the ground state one, two cases are possible. If the kinetic energy of the radial data is less than the ground state one, then the solution is global and scatters. Otherwise, if the data have a finite variance or is spherically symmetric and have a finite mass, then the solution is nonglobal. The main difficulty is to deal with the nonlocal source term. The argument is the concentration-compactness-rigidity method introduced by Kenig and Merle (Global well-posedness, scattering and blow-up for the energy-critical, focusing, non-linear Schrödinger equation in the radial case, Invent. Math. 166 (2006), no. 3, 645–675). This note naturally complements the work by Saanouni (Scattering theory for a class of defocusing energy-critical Choquard equations, J. Evol. Equ. 21 (2021), 1551–1571), where the scattering of the defocusing energy-critical generalized Hartree equation was obtained.

MSC 2010: 35Q55

1 Introduction

This article studies the Cauchy problem for an energy-critical focusing generalized Hartree equation

(NLS) i t u + Δ u + u p 2 ( I α * u p ) u = 0 ; u t = 0 = u 0 .

In this note, the space dimension is N 3 , the wave function is u : R × R N C . Moreover, 0 < α < N and the Riesz-potential stands for

I α ( x ) Γ N α 2 Γ α 2 π N 2 2 α x N α , 0 x R N .

Introduced by Ph. Choquard in 1976, the Choquard equation models a one-component plasma [1]. It appears also in Fröhlich and Pekar’s model of the polaron, which describes the interaction of an electron with its own hole [24].

If u is a solution to (NLS), one gets a family of solutions

λ 2 + α 2 ( p 1 ) u ( λ 2 , λ ) , λ > 0 .

The equation (NLS) is called H ˙ s c critical, where

s c N 2 2 + α 2 ( p 1 )

is the unique index keeping the following Sobolev norm invariant

λ 2 + α 2 ( p 1 ) u ( λ 2 t , λ ) H ˙ s c = u ( λ 2 t ) H ˙ s c .

This note treats the energy-critical case corresponding to s c = 1 , equivalently

p = p * 1 + α + 2 N 2 .

The particular case p * = 2 in (NLS) corresponds to the repulsive energy-critical nonlinear equations of Hartree type. The global existence and scattering versus finite time blow-up of solutions were established for radial setting in the study by Miao et al. [5]. This result was extended to the nonradial case [6]. For p * > 2 , it seems that the study by Arora and Roudenko [7] is the only work dealing with the energy-critical generalized Hartree equation (NLS). Indeed, the global well-posedness in H s c , s c 0 was established for small data. A natural complementing of the study by Arora and Roudenko [7] is to establish the scattering of global solutions with a precise data size in H ˙ 1 . This is the goal of this note. The argument is the concentration-compactness-rigidity method used first by [8] in the energy-critical focusing NLS. Note that (NLS) is a part of the nonlinear evolution equations with nonlocal source term [9,10].

This article naturally complements the work [11], where the scattering of the defocusing energy-critical generalized Hartree equation was obtained by the third author in the spirit of the study by Miao et al. [5]. This helps to understand the asymptotic behavior of the energy-critical Choquard problem in different regimes. Note also that the intercritical regime was investigated by Saanouni [12]. It was also revisited with an alternative proof in the study by Arora [13], using a new method suggested by Dodson and Murphy [14], which relies on a scattering criterion [15], combined with the radial Sobolev and Morawetz-type estimates.

This article is organized as follows: Section 2 contains some technical estimates and the main result. Section 3 is devoted to prove the linear profile decomposition of bounded sequences in H ˙ 1 . In Section 4, one collects some variational estimates about energy solutions to (NLS). The goal of Section 5 is to obtain the nonexistence of global solutions. In Section 6, one proves the global existence and scattering of solutions. Finally, in the Appendix, we prove a scattering criteria and give a second proof of the profile decomposition.

Here and hereafter, for simplicity, one denotes the spaces

L r L r ( R N ) , H ˙ 1 H ˙ 1 ( R N ) ; H ˙ r d 1 { f H ˙ 1 , f ( x ) = f ( x ) , x R N } ,

and the norms

r L r , 2 .

Finally, T * T * ( u 0 ) > 0 denotes the lifespan for a possible solution to the Schrödinger problem (NLS).

2 Background and main result

This section contains the contribution of this note and some useful estimates.

2.1 Notations

Here and hereafter, define, for u H ˙ 1 ,

N N ( u ) R N u p * ( I α * u p * ) d x ; ( u ) ( I α * u p * ) u p * 2 u ; E ( u ) u 2 1 p * N .

Definition 2.1

A ground state of (NLS) resolves the elliptic problem

(1) Δ Q + ( I α * Q p * ) Q p * 2 Q = 0 , 0 Q H ˙ 1

and minimizes the problem

inf 0 u H ˙ 1 E ( u ) s.t. u 2 = R N u p * ( I α * u p * ) d x 1 p * .

According to [16], the following explicit function is a ground state of (NLS),

(2) Q S α ( 2 N ) 4 ( 2 + α ) C * 2 N 4 ( 2 + α ) 1 + 2 N ( N 2 ) N N 2 ,

where S is the best Sobolev injection constant in u 2 C u 2 N N 2 2 and

C * 1 2 π α Γ N α 2 Γ ( N + α 2 ) Γ ( N ) Γ ( N 2 ) α N .

Note that global solutions to (NLS) such as this ground state may not scatter. Finally, let us denote, for an interval I R , the Strichartz spaces

S ( I ) L 2 p * ( I , L 2 N p * N p * 2 ) , S 1 ( I ) L 2 p * ( I , L 2 N p * ( p * 1 ) 2 + α p * ) .

2.2 Preliminary

Solutions to the Schrödinger problem (NLS) will be considered with an equivalent way as a fixed point of the integral equation:

e i t Δ u 0 + i 0 t e i ( t s ) Δ [ ( I α * u p * ) u p * 2 u ] d s ,

where

e i t Δ u 1 ( e i t 2 ) * u .

In the study by Du and Yang [16], a sharp Gagliardo-Nirenberg type inequality related to (NLS) was established.

Proposition 2.1

Let N 3 and 0 < α < N . Then,

  1. R N u p * ( I α * u p * ) d x C N , α u 2 p * , for any u H ˙ 1 ;

  2. the best constant in the previous inequality is

    C N , α = C * S α + N N 2 .

The problem (NLS) has a local solution in the energy space, which is global for small data [7].

Proposition 2.2

Let N 3 , 0 < α < N 4 + α , and u 0 H ˙ 1 . Then, there exists T * > 0 such that (NLS) admits a unique maximal solution

u C T * ( H ˙ 1 ) .

Moreover,

  1. u L loc 2 p * ( ( 0 , T * ) , W ˙ 1 , 2 N p * N p * 2 ) ;

  2. the energy is conserved E ( u ( t ) ) = E ( u 0 ) ;

  3. if T * < , then, u S 1 ( 0 , T * ) = .

Furthermore, there exists δ ( u 0 ) > 0 such that if e i Δ u 0 S 1 ( R ) δ , then, T * = and
  1. u S 1 ( R ) 2 e i Δ u 0 S 1 ( R ) ;

  2. u S ( R ) u 0 S ( R ) .

For the reader convenience, the next scattering criterion will be proved in the Appendix.

Proposition 2.3

Let N 3 , 0 < α < N 4 + α , and u C ( R , H ˙ 1 ) be a global solution to (NLS) satisfying

u S 1 ( R ) < .

Then, u scatters in H ˙ 1 .

The following long-time perturbation theory [12] will be useful.

Proposition 2.4

Let N 3 , 0 < α < N 4 + α . Let T > 0 , u C T ( H ˙ 1 ) be a solution to (NLS) and u ˜ L T ( H ˙ 1 ) satisfying for some ε , A > 0 ,

u ˜ L T ( H ˙ 1 ) S 1 ( 0 , T ) A ; i t u ˜ + Δ u ˜ + ( u ˜ ) = e ; e S ( 0 , T ) ε , e i Δ [ u 0 u ˜ 0 ] S 1 ( 0 , T ) ε .

Thus, there exists ε 0 ε 0 ( A ) satisfying for any 0 < ε < ε 0 ,

u S 1 ( 0 , T ) C ( A ) .

The next linear profile decomposition for bounded radial sequences in H ˙ 1 is a key tool for the scattering proof [5,17].

Proposition 2.5

Let N 3 , 0 < α < N such that p * is an integer. Take ( u n ) be a bounded sequence in H ˙ r d 1 such that e i Δ u n S 1 ( R ) δ > 0 . Then, for any M N , there exist a subsequence denoted also ( u n ) and

  1. for any 1 j M , a profile ψ j H ˙ 1 ;

  2. for any 1 j M , a sequence ( t n j , λ n j ) R 2 satisfying for 1 i j M and n ,

    λ n j λ n i + λ n i λ n j + t n j t n i ( λ n j ) 2 ;

  3. a sequence of remainders W n M H ˙ r d 1 , such that, for ψ l j e i Δ ψ j ,

    u n = j = 1 M 1 ( λ n j ) N 2 2 e i t n j ( λ n j ) 2 Δ ψ j λ n j + W n M j = 1 M 1 ( λ n j ) N 2 2 ψ l j t n j ( λ n j ) 2 , λ n j + W n M .

    Moreover, ψ 1 > 0 and

    lim M [ lim n e i Δ W n M S 1 ( R ) ] = 0 .

    For fixed M, one has the next Pythagorean expansions

    u n 2 = j = 1 M ψ j 2 + W n M 2 + o n ( 1 ) ; E ( u n ) = j = 1 M E ψ l j t n j ( λ n j ) 2 + E ( W n M ) + o n ( 1 ) .

Finally, one recalls the notion of nonlinear profile.

Definition 2.2

Let a sequence of real numbers ( t n ) such that lim n t n t ¯ [ , + ] and v 0 H ˙ 1 . One says that u ( t , x ) is a nonlinear profile associated to ( v 0 , t n ) if there exists an interval I t ¯ , ( I = [ a , ) or I = ( , a ] , if t ¯ = ) and u ( t , x ) a solution to (NLS) on I such that

lim n u ( t n ) e i t n Δ v 0 H ˙ 1 = 0 .

The main result proved in this article is given in the following subsection.

2.3 Main result

The novelty in this work is the next dichotomy of global existence and scattering versus nonexistence of global energy solutions to the Schrödinger problem (NLS).

Theorem 2.1

Let N 3 , 0 < α < N 4 + α , Q be the ground state solution to (1) given in (2) and u 0 H ˙ 1 satisfying

(3) E [ u 0 ] < E [ Q ] .

Take u C T * ( H ˙ 1 ) be the unique maximal solution to (NLS). Then,

  1. T * < if x u 0 L 2 and

    (4) u 0 > Q .

  2. T * = and u scatters if u 0 is radial and

    (5) u 0 < Q .

In view of the result stated in the aforementioned theorem, some comments are in order.

Remarks 2.1

  • The condition α N 4 avoids a singular source term if p * < 2 ;

  • the range of space dimensions N containing 3, is { 3 , 4 , 5 , 6 } ;

  • the scattering means the existence of ψ H ˙ 1 such that

    lim t u ( t ) e i t Δ ψ H ˙ 1 = 0 ;

  • in the proof of the finite time blow-up, we establish also that there is no global solution to (NLS) in the energy space if u 0 H r d 1 and N 2 ( 5 + α ) N α 0 . This extra assumption is related to the method and is needed in order to apply Young estimate;

  • the major part of the proof is devoted to prove the energy scattering;

  • the scattering in the defocusing regime was proved by Saanouni [11];

  • the local well-posedness of (NLS) for 1 < p < 2 was investigated for a class of data in weighted Sobolev spaces in [18];

  • the proof of the scattering follows the concentration-compactness-rigidity method due to the pioneering work [8], which has a deep influence in the NLS context.

  • the new method of Dodson and Murphy [14], used by Arora [13] in the intercritical regime fails in the energy critical case.

Section 2.4 presents some technical estimates needed in the sequel.

2.4 Tools

The next consequence of Hardy-Littlewood-Sobolev inequality [19] is adapted to estimate a possible solution to the Hartree equation (NLS).

Proposition 2.6

Let 0 < α < N 1 and 1 < s , r < . Then,

  1. if 1 + α N = 1 r + 1 s ,

    (6) R N ( I α * g ) ( x ) f ( x ) d x C N , α , s f r g s , ( f , g ) L r × L s .

  2. If 1 + α N = 1 q + 1 r + 1 s ,

    ( I α * f ) g r C N , α , s f s g q , ( f , g ) L s × L q .

Definition 2.3

A couple of real numbers ( q , r ) is said to be H ˙ s admissible (admissible if s = 0 ) if

N 1 2 1 r = 2 q + s ,

where

2 N N 2 s < r 2 N N 2 , if N 3 ; 2 1 s < r 2 1 s + , if N = 2 ; 2 1 2 s < r , if N = 1 .

Here, ( a + ) = a + a a + a . Finally, one says that ( q , r ) is said to be H ˙ s admissible if

N 1 2 1 r = 2 q s ,

where

2 N N 2 s + < r 2 N N 2 , if N 3 ; 2 1 s + < r 2 1 s + , if N = 2 ; 2 1 2 s + < r , if N = 1 .

For simplicity, one denotes Γ s the set of s admissible pairs.

A standard tool to control solutions of (NLS) is the Strichartz estimate [20,21].

Proposition 2.7

Let N 1 and s R . Then, there exists C > 0 such that

  1. sup ( q , r ) Γ s e i Δ u L q ( L r ) C s u ;

  2. sup ( q , r ) Γ s 0 . e i ( τ ) Δ f ( τ ) d τ L q ( L r ) C inf ( a , b ) Γ s f L a ( L b ) .

To investigate the nonexistence of global solutions to the Schrödinger problem (NLS), one will use the next variance identity [22].

Proposition 2.8

Let N 3 , 0 < α < N 4 + α , and u C T ( H ˙ 1 ) be a solution to (NLS) satisfying x u 0 L 2 . Then, the variance defined on [ 0 , T ) by

V : t R N x u ( t , x ) 2 d x

satisfies V C 2 ( T , T ) and

V = 8 u 2 R N u p * ( I α * u p * ) d x .

3 Profile decomposition

In this section, one proves Proposition 2.5. Taking account of [17], it is sufficient to prove the last equation, which reads

(7) N ( u n ) = j = 1 M N ψ l j t n j ( λ n j ) 2 + N ( W n M ) + o n ( 1 ) .

For this, one needs to establish that

(8) 0 = lim n ( N ( u n ) N ( u n ( ψ ˜ l 1 ) n ) N ( ( ψ ˜ l 1 ) n ) ) lim n I n ,

where, one denotes the sequence

( ψ ˜ l 1 ) n 1 ( λ n 1 ) N 2 2 ψ l 1 t n 1 ( λ n 1 ) 2 , λ n 1 .

By re-indexing and adjusting profiles, one can assume that one of the two scenarios happens. The first one is t n 1 ( λ n 1 ) 2 . The second one is t n 1 ( λ n 1 ) 2 t ˜ .

Take the first case and recall the useful inequality [23], for any m 2 ,

(9) x m x y m y m m 2 m 1 ( x y m 1 y + x y y m 1 ) .

Let us write

(10) I n = R N ( I α * u n p * ) ( u n p * u n ( ψ ˜ l 1 ) n p * ( ψ ˜ l 1 ) n p * ) d x + R N u n ( ψ ˜ l 1 ) n p * [ I α * ( u n p * u n ( ψ ˜ l 1 ) n p * ) ] d x + R N ( ψ ˜ l 1 ) n p * [ I α * ( u n p * ( ψ ˜ l 1 ) n p * ) ] d x ( I n ) 1 + ( I n ) 2 + ( I n ) 3 .

Now, by (9), via Sobolev embeddings, Hölder estimate and (6), one writes for 2 N N 2 2 * ,

(11) ( I n ) 1 u n 2 * u n p * u n ( ψ ˜ l 1 ) n p * ( ψ ˜ l 1 ) n p * 2 N α + N u n p * u n ( ψ ˜ l 1 ) n p * ( ψ ˜ l 1 ) n p * 2 N α + N u n ( ψ ˜ l 1 ) n p * 1 ( ψ ˜ l 1 ) n + u n ( ψ ˜ l 1 ) n ( ψ ˜ l 1 ) n p * 1 2 N α + N u n ( ψ ˜ l 1 ) n 2 * p * 1 ( ψ ˜ l 1 ) n 2 * + u n ( ψ ˜ l 1 ) n 2 * ( ψ ˜ l 1 ) n 2 * p * 1 .

Using the dispersive estimate [24] of the free Schrödinger operator, e i t Δ r C t N 1 2 1 r r , for all r 2 , via (11) and (10), one gets lim n I n = 0 .

Now, take the second case and denote

(12) s n t n 1 ( λ n 1 ) 2 t ˜ ;

(13) v n 1 u n ( λ n 1 ) N 2 2 u n ( λ n 1 ) e i t ˜ Δ ψ 1 in H ˙ 1 ;

(14) ψ l 1 ( s n ) e i t ˜ Δ ψ 1 in L 2 * .

Let us write

(15) I n = N ( u n ) N ( u n ( ψ ˜ l 1 ) n ) N ( ( ψ ˜ l 1 ) n ) = N ( v n ) N ( v n ψ l 1 ( s n ) ) N ( ψ l 1 ( s n ) ) ( I n ) 1 + ( I n ) 2 + ( I n ) 3 .

Here, one takes

( I n ) 1 N ( v n ) N ( v n e i t ˜ Δ ψ 1 ) N ( e i t ˜ Δ ψ 1 ) ; ( I n ) 2 N ( v n e i t ˜ Δ ψ 1 ) N ( v n ψ l 1 ( s n ) ) ; ( I n ) 3 N ( e i t ˜ Δ ψ 1 ) N ( ψ l 1 ( s n ) ) .

Moreover, the aforementioned first term reads

(16) ( I n ) 1 = R N ( I α * v n p * ) ( v n p * v n e i t ˜ Δ ψ 1 p * e i t ˜ Δ ψ 1 p * ) d x + R N v n e i t ˜ Δ ψ 1 p * [ I α * ( v n p * v n e i t ˜ Δ ψ 1 p * ) ] d x + R N e i t ˜ Δ ψ 1 p * [ I α * ( v n p * e i t ˜ Δ ψ 1 p * ) ] d x ( I n ) 11 + ( I n ) 12 + ( I n ) 13 .

By (6) via Hölder estimate and (9), one obtains

(17) ( I n ) 11 = R N ( I α * v n p * ) ( v n p * v n e i t ˜ Δ ψ 1 p * e i t ˜ Δ ψ 1 p * ) d x v n 2 * v n e i t ˜ Δ ψ 1 p * 1 e i t ˜ Δ ψ 1 + v n e i t ˜ Δ ψ 1 e i t ˜ Δ ψ 1 p * 1 2 N α + N ( I n ) 111 + ( I n ) 112 .

By density argument, one takes χ C 0 ( R N ) such that χ e i t ˜ Δ ψ 1 H ˙ 1 1 . Thus, by (13), via Hölder estimate, it follows that

( I n ) 111 v n e i t ˜ Δ ψ 1 2 * p * 1 e i t ˜ Δ ψ 1 χ 2 * + v n e i t ˜ Δ ψ 1 2 * p * 2 χ ( v n e i t ˜ Δ ψ 1 ) 2 * 2 0 .

Moreover, by Hölder estimate, one has

(18) ( I n ) 112 = v n e i t ˜ Δ ψ 1 e i t ˜ Δ ψ 1 χ + χ p * 1 2 N α + N v n e i t ˜ Δ ψ 1 2 * e i t ˜ Δ ψ 1 χ 2 * p * 1 + χ ( v n e i t ˜ Δ ψ 1 ) 2 * 2 χ 2 * p * 2 0 .

Now, one considers the second term. Arguing as previously and taking account of (14), one obtains

(19) ( I n ) 12 = R N v n e i t ˜ Δ ψ 1 p * [ I α * ( v n p * v n e i t ˜ Δ ψ 1 p * ) ] d x R N v n e i t ˜ Δ ψ 1 p * [ I α * ( e i t ˜ Δ ψ 1 ψ l 1 ( s n ) ( v n p * 1 + e i t ˜ Δ ψ 1 p * 1 + ψ l 1 ( s n ) p * 1 ) ) ] d x ( v n 2 * p * 1 + e i t ˜ Δ ψ 1 2 * p * 1 + ψ l 1 ( s n ) 2 * p * 1 ) e i t ˜ Δ ψ 1 ψ l 1 ( s n ) 2 * 0 .

The third term is controlled similarly. This finishes the proof.

4 Variational analysis

In this section, one prepares the proof of the main result by collecting some useful estimates. Taking account of [16], the ground state Q given in (2) is a minimizer for

S N , α inf { 0 u H 1 } u 2 R N u p * ( I α * u p * ) d x 1 p * .

This ground state is a global solution to (NLS), which does not scatter. Thus, global solutions may not scatter. Moreover, the equation (1) gives

Q 2 = R N ( I α * Q p * ) Q p * d x .

Thus,

Q 2 = S N , α α + N α + 2 , E ( Q ) = α + 2 α + N S N , α α + N α + 2 .

Lemma 4.1

For δ ( 0 , 1 ) , there exists δ ¯ ( 0 , 1 ) such that if u H ˙ 1 satisfies

u < Q ; E ( u ) < ( 1 δ ) E ( Q ) < E ( Q ) ,

then,

(20) u 2 < ( 1 δ ¯ ) Q 2 ;

(21) u 2 N δ ¯ u 2 ;

(22) E ( u ) > 0 .

Proof

Take the real function f ( x ) x 1 p * S N , α p * x p * . Then,

f ( u 2 ) = u 2 1 p * S N , α p * u 2 p * u 2 1 p * N E ( u ) ( 1 δ ) E ( Q ) .

The equation f ( x ) = 0 is equivalent to

x = x * = S N , α p * p * 1 = Q 2 .

Moreover, f ( x * ) = E ( Q ) . Now, since f is positive and strictly increasing on [ 0 , x * ] , one has (20) and (22). Now, let the real function g ( x ) x ( x S N , α ) p * . Then,

u 2 N u 2 u 2 S N , α p * = g ( u 2 ) .

Moreover, g ( x ) = 0 if and only if x = 0 or x = x * . Thus, g ( x ) x on [ 0 , ( 1 δ ¯ ) x * ] . So, since 0 u 2 < ( 1 δ ¯ ) x * , one obtains (21).□

Corollary 4.1

If u H ˙ 1 satisfies u < Q , then E ( u ) 0 .

Proof

The case E ( u ) E ( Q ) = α + 2 α + N S N , α α + N α + 2 > 0 is clear. Otherwise, the Lemma 4.1 gives the result.□

With a continuity argument via the conservation of the energy and Lemma 4.1, one has the following energy trapping.

Proposition 4.1

For δ ( 0 , 1 ) , there exists δ ¯ ( 0 , 1 ) such that if u 0 H ˙ 1 satisfies

u 0 < Q ; E ( u 0 ) < ( 1 δ ) E ( Q ) < E ( Q ) ,

then, the maximal solution to (NLS) satisfies for any t [ 0 , T * ) ,

(23) u ( t ) 2 < ( 1 δ ¯ ) Q 2 ;

(24) u ( t ) 2 N ( u ( t ) ) δ ¯ u ( t ) 2 ;

(25) E ( u ) > 0 .

Moreover,

E ( u ( t ) ) u ( t ) 2 u 0 2 .

Proof

For the last point, since E ( u ( t ) ) u ( t ) 2 , by (23), one has

E ( u ( t ) ) 1 1 p * u ( t ) 2 + 1 p * ( u ( t ) 2 N ( u ( t ) ) ) 1 1 p * u ( t ) 2 .

Taking account of Lemma 4.1, it is sufficient to prove that

u ( t ) < Q , t ( 0 , T * ) .

Assume that there exists t 0 ( 0 , T * ) such that

u ( t ) < Q , t ( 0 , t 0 ) and u ( t 0 ) = Q .

Thus, by Lemma 4.1, one obtains

u ( t ) 2 < ( 1 δ ¯ ) Q 2 , t ( 0 , t 0 ) .

With a continuity argument, it follows that

u ( t 0 ) < Q .

This contradiction finishes the proof.□

5 Nonexistence of global solutions

In this section, one proves the first part of the main result dealing with the nonexistence of global solutions to (NLS). The next result follows like Proposition 4.1.

Lemma 5.1

For δ ( 0 , 1 ) , there exists δ ¯ ( 0 , 1 ) such that if the maximal solution to (NLS) denoted by u C T * ( H ˙ 1 ) satisfies (4) and

E ( u ) < ( 1 δ ) E ( Q ) < E ( Q ) .

Then, holds on [ 0 , T * ) ,

u 2 > ( 1 + δ ¯ ) Q 2 .

Let us discuss two cases.

  1. x u 0 L 2 . Compute

    u 2 R N u p * ( I α * u p * ) d x = p * E ( u ) ( p * 1 ) u 2 p * E ( Q ) ( p * 1 ) ( 1 + δ ¯ ) Q 2 α + N N 2 2 + α N + α 2 + α N 2 ( 1 + δ ¯ ) S N , α N + α 2 + α δ ¯ ( p * 1 ) S N , α p * p * 1 .

Thus, by the variance identity in Proposition 2.8,

t 2 u ( t ) 2 = 8 u 2 R N u p * ( I α * u p * ) d x 8 δ ¯ ( p * 1 ) S N , α p * p * 1 .

Thus, integrating twice, one obtains

u ( t ) 2 4 δ ¯ ( p * 1 ) S N , α p * p * 1 t 2 + 4 t R N ( x . u 0 ) u 0 d x + x u 0 2 .

This quantity becomes negative for large time. Thus, T * < .

  1. Second case u 0 H r d 1 .

In the rest of this section, take a smooth radial function ψ C 0 ( R n ) satisfying ψ 1 and

ψ : x x 2 2 , if x 1 ; 0 , if x 2 .

Then, the truncated function ψ R R 2 ψ ( . R ) satisfies

ψ R 1 , ψ R ( r ) r and Δ ψ R N .

Denote the localized virial

V ψ [ u ( t ) ] R N ψ u ( t ) 2 d x and V R V ψ R .

The first derivative reads using the convention of summed repeated index,

t V ψ [ u ( t ) ] M ψ [ u ( t ) ] = 2 R N u ¯ ( t ) k ψ k u ( t ) d x .

Compute using the equation (NLS),

t ( k u u ¯ ) = ( k t u u ¯ ) + ( k u t u ¯ ) = ( i t u k u ¯ ) ( i k t u u ¯ ) = ( k u ¯ ( Δ u ) ) ( u ¯ k ( Δ u ) ) = ( u ¯ k Δ u k u ¯ Δ u ) + ( u ¯ k k u ¯ ) .

Recall the identity

1 2 k Δ ( u 2 ) 2 l ( k u l u ¯ ) = ( u ¯ k Δ u k u ¯ Δ u ) .

Then,

R N k ψ ( u ¯ k Δ u k u ¯ Δ u ) d x = R N k ψ 1 2 k Δ ( u 2 ) 2 l ( k u l u ¯ ) d x = 1 2 R N Δ 2 ψ u 2 d x + 2 R N l k ψ ( k u l u ¯ ) d x .

On the other hand,

R N k ψ ( u ¯ k k u ¯ ) d x = R N k ψ ( k [ u ¯ ] 2 k u ¯ ) d x = R N ( Δ ψ u ¯ + 2 ( k ψ k u ¯ ) ) d x = R N Δ ψ u p * ( I α * u p * ) d x 2 R N k ψ ( k u ¯ ) d x = R N Δ ψ u p * ( I α * u p * ) d x 2 p * R N k ψ k ( u p * ) ( I α * u p * ) d x .

By using the identity I α = ( N α ) 2 I α , one obtains

R N k ψ k ( u p * ) ( I α * u p * ) d x = R N Δ ψ u p * ( I α * u p * ) d x R N k ψ ( k I α * u p * ) u p * d x = R N Δ ψ u p * ( I α * u p * ) d x + ( N α ) R N k ψ x k 2 I α * u p * u p * d x .

Thus,

R N k ψ ( u ¯ k k u ¯ ) d x = R N Δ ψ u p * ( I α * u p * ) d x 2 p * R N k ψ k ( u p * ) ( I α * u p * ) d x = 2 p * 1 R N Δ ψ u p * ( I α * u p * ) d x 2 p * ( N α ) R N k ψ x k 2 I α * u p * u p * d x .

Regrouping previous computation, one obtains

t M ψ [ u ( t ) ] = R N Δ 2 ψ u 2 d x + 4 R N l k ψ ( k u l u ¯ ) d x + 2 2 p * 1 R N Δ ψ u p * ( I α * u p * ) d x 4 p * ( N α ) R N k ψ x k 2 I α * u p * u p * d x

= R N Δ 2 ψ u 2 d x + 4 R N l k ψ ( k u l u ¯ ) d x + 2 2 p * 1 R N Δ ψ u p * ( I α * u p * ) d x 2 p * ( N α ) R N R N ( k ψ ( x ) k ψ ( y ) ) ( x k y k ) I α ( x y ) x y 2 u ( x ) p * u ( y ) p * d x d y .

Denote, for simplicity, M R M ψ R . By using the properties of ψ , one has

t M R [ u ( t ) ] C R 2 + 4 u 2 + 2 2 p * 1 R N Δ ψ R ( I α * u p * ) u p * d x 2 p * ( N α ) R N R N ( k ψ R ( x ) k ψ R ( y ) ) ( x k y k ) I α ( x y ) x y 2 u ( x ) p * u ( y ) p * d x d y .

Following lines in [11], one has

( M ) R N × R N ( ψ R ( x ) ψ R ( y ) ) x y x y 2 I α ( x y ) u ( y ) p * u ( x ) p * d y d x = R N u p * ( I α * u p * ) d x + O { x > R } ( I α * u p * ) u p * d x .

Thus, using the equality Δ ψ R ( r ) N = 0 if r R ,

( N ) 2 ( N α ) p * ( M ) + 2 2 p * 1 R N Δ ψ R ( I α * u p * ) u p * d x = 2 N α p * + N 1 2 p * R N u p * ( I α * u p * ) d x + O { x > R } ( I α * u p * ) u p * d x + 2 2 p * 1 { x > R } ( Δ ψ R N ) ( I α * u p * ) u p * d x = 4 R N u p * ( I α * u p * ) d x + O { x > R } ( I α * u p * ) u p * d x .

By using Hardy-Littlewood-Sobolev inequality, one has

{ x > R } ( I α * u p * ) u p * d x u L 2 N N 2 ( x > R ) p * u L 2 N N 2 p * u L 2 N N 2 p * u L ( x > R ) p * 1 α N u α + N N .

Thanks to Hardy-Littlewood-Sobolev and Strauss inequalities via the mass conservation and Sobolev injections, one obtains

{ x > R } ( I α * u p * ) u p * d x u p * u L ( x > R ) p * 1 α N u p * 1 R N 1 u L 2 ( x > R ) u 1 2 ( p * 1 α N ) 1 R ( N 1 ) ( α + N ) N ( N 2 ) u ( α + N ) ( 1 + N ) N ( N 2 ) .

So, by Young inequality, since N 2 ( 5 + α ) N α 0 , there exists C ( R ) 0 when R , such that

t M R [ u ( t ) ] 4 u 2 4 R N u p * ( I α * u p * ) d x + C R 2 + C R ( N 1 ) ( α + N ) N ( N 2 ) u ( 1 + N ) ( α + N ) N ( N 2 ) 4 u 2 4 R N u p * ( I α * u p * ) d x + C ( R ) ( 1 + u 2 ) .

Compute using the previous lemma

( 1 + ε ) u 2 R N u p * ( I α * u p * ) d x = p * E ( u ) ( p * 1 ε ) u 2 p * E ( Q ) ( p * 1 ε ) ( 1 + δ ¯ ) Q 2 α + N N 2 2 + α N + α 2 + α N 2 ε ( 1 + δ ¯ ) S N , α N + α 2 + α ( δ ¯ ( p * 1 ) ε ( 1 + δ ¯ ) ) S N , α p * p * 1 .

Finally, taking R 1 , there exists ε > 0 such that

t M R [ u ( t ) ] < ε for all 0 < t < T * .

By integrating twice the previous estimate, one obtains

0 < V R < V R ( 0 ) + t V R ( 0 ) ε 2 t 2 for all 0 < t < T * .

This implies that T * < and the proof is achieved.

6 Global existence and scattering of radial solutions

Let us recall for any time slab I R , the Strichartz spaces

S ( I ) L 2 p * ( I , L 2 N p * N p * 2 ) , S 1 ( I ) L 2 p * ( I , L 2 N p * ( p * 1 ) 2 + α p * ) .

Remarks 6.1

  1. ( 2 p * , 2 N p * N p * 2 ) Γ 0 and ( 2 p * , 2 N p * ( p * 1 ) 2 + α p * ) Γ 1 ;

  2. S S ( R ) and S 1 S 1 ( R ) .

One says that the statement ( S C ) ( u 0 ) holds if:

For u 0 H ˙ 1 with u 0 < Q and E ( u 0 ) < E ( Q ) , the corresponding solution to (NLS) is global and satisfies

u S 1 ( R ) .

By using Sobolev injection and Strichartz estimate, one has

e i Δ u 0 S 1 e i Δ u 0 S u 0 .

Thus, if u 0 1 , by the small data theory in Proposition 2.2, ( S C ) ( u 0 ) holds. Now, for each δ > 0 , define the set

S δ { u 0 H ˙ r d 1 , E [ u 0 ] < δ and u 0 < Q } .

Define also

E c sup { δ > 0 s.t. u 0 S δ ( S C ) ( u 0 ) holds } .

The goal is to prove that E c = E [ Q ] . By contradiction, assume that

(26) E c < E [ Q ] .

Then, there is a sequence u n of solutions to (NLS) such that the data u n , 0 H ˙ 1 satisfies u n , 0 < Q and E [ u n , 0 ] E c as n and ( S C ) ( u n , 0 ) does not hold for any n .

The goal in this section is to show the existence of a critical solution u c to (NLS) with data u c , 0 such that

u c , 0 < Q , E [ u c ] = E c and ( S C ) ( u c , 0 ) does not hold .

In the next result, the constant δ is given by Proposition 2.2.

Lemma 6.1

Let a sequence u n H ˙ r d 1 satisfying

u n < Q a n d E ( u n ) E c .

Assume that e i Δ u n S 1 ( R ) δ > 0 and that the profile decomposition of u n satisfies one of the two following hypothesis

  1. liminf n E ( ψ l 1 ( t n 1 ( λ n 1 ) 2 ) ) < E c ;

  2. liminf n E ( ψ l 1 ( t n 1 ( λ n 1 ) 2 ) ) = E c . Moreover, if s n 1 t n 1 ( λ n 1 ) 2 s * [ , + ] and U 1 is the nonlinear profile associated to ( ψ 1 , s n 1 ) , then U 1 is global and U 1 S 1 ( R ) < .

Then, ( S C ) ( u n ) holds, for a subsequence and large n.

Proof

Thanks to the profile decomposition, one has

u n = j = 1 M 1 ( λ n j ) N 2 2 e i t n j ( λ n j ) 2 Δ ψ j λ n j + W n M = j = 1 M 1 ( λ n j ) N 2 2 ψ l j t n j ( λ n j ) 2 , λ n j + W n M .

Moreover,

Q 2 > u n 2 = j = 1 M ψ j 2 + W n M 2 + o n ( 1 ) = j = 1 M ψ l j t n j ( λ n j ) 2 2 + W n M 2 + o n ( 1 ) ;

and

E c E ( u n ) = j = 1 M E ψ l j t n j ( λ n j ) 2 + E ( W n M ) + o n ( 1 ) .

By Corollary 4.1, one obtains, for 1 j M ,

min E ψ l j t n j ( λ n j ) 2 , E ( W n M ) 0 .

One discusses two cases.

(1) Take for a subsequence lim n E ( ψ l 1 ( t n 1 ( λ n 1 ) 2 ) ) < E c . Write

ψ l 1 t n 1 ( λ n 1 ) 2 = ψ 1 < Q ; E ( ψ l 1 t n 1 ( λ n 1 ) 2 ) E c + o n ( 1 ) < E ( Q ) .

Lemma 4.1 implies that

E ψ l 1 t n 1 ( λ n 1 ) 2 = ψ l 1 t n 1 ( λ n 1 ) 2 2 1 p * R N I α * ψ l 1 t n 1 ( λ n 1 ) 2 p * ψ l 1 t n 1 ( λ n 1 ) 2 , x p * d x = 1 p * ψ l 1 t n 1 ( λ n 1 ) 2 2 R N I α * ψ l 1 t n 1 ( λ n 1 ) 2 p * ψ l 1 t n 1 ( λ n 1 ) 2 , x p * d x + 1 1 p * ψ l 1 t n 1 ( λ n 1 ) 2 2 ψ 1 2 .

Thus,

E c E ( u n ) C ψ 1 2 + j = 2 M E ψ l j t n j ( λ n j ) 2 + E ( W n M ) + o n ( 1 ) .

So,

liminf n E ψ l j t n j ( λ n j ) 2 < E c , 2 j M .

Let U j be the nonlinear profile associated to ( ψ j , t n j ( λ n j ) 2 ) . Then, for large n ,

(27) U j = ψ l j t n j ( λ n j ) 2 + o n ( 1 ) < Q ; E ( U j ) = E ψ l j t n j ( λ n j ) 2 + o n ( 1 ) < E ( Q ) .

Then, with Proposition 4.1, one has

E ( U j ) U j ( t ) 2 U j ( 0 ) 2 .

By the aforementioned estimates, one has

j = 1 M ψ j 2 u n 2 + o n ( 1 ) Q 2 .

So, there exists j 0 > 0 such that for j j 0 , ψ j is small enough. With Strichartz estimate, it follows that e i Δ ψ j S 1 ( R ) < δ given by the small data theory. Then, the integral formula via the small data theory gives

U j S 1 ( R ) ψ j , j j 0 .

Now, take for ε 0 > 0 , the near solution

H n , ε 0 j = 1 M ( ε 0 ) 1 ( λ n j ) N 2 2 U j t n j ( λ n j ) 2 , λ n j , e i Δ W n M ( ε 0 ) S 1 ( R ) < ε 0 ,

and the rest

R n , ε 0 j = 1 M ( ε 0 ) 1 ( λ n j ) N 2 2 U j t n j ( λ n j ) 2 , λ n j ( H n , ε 0 ) .

Thus,

u n = H n , ε 0 + R n , ε 0 , e i Δ R n , ε 0 S 1 ( R ) < 2 ε 0 .

Using (27), one writes

H n , ε 0 2 Q 2 .

Moreover,

H n , ε 0 S ( R ) 2 p * R N j = 1 M ( ε 0 ) 1 ( λ n j ) N 2 2 U j t t n j ( λ n j ) 2 , λ n j 2 N p * N p * 2 2 p * d t j = 1 M ( ε 0 ) R N 1 ( λ n j ) N 2 2 U j t t n j ( λ n j ) 2 , λ n j 2 N p * N p * 2 2 p * d t + I [ 1 , 2 p * ] , I < 2 p * R N j k I 1 ( λ n j k ) N 2 2 U j k t t n j k ( λ n j k ) 2 , λ n j k 2 N p * N p * 2 d t ( A n ) + ( B n ) .

Now, there exists C 0 independent of M ( ε 0 ) such that

( A n ) j = 1 j 0 + 1 + j 0 M ( ε 0 ) U j S 1 ( R ) 2 p * j = 1 j 0 U j S 1 ( R ) 2 p * + 1 + j 0 M ( ε 0 ) ψ j 2 p * C 0 .

Arguing as previously, the orthogonality condition gives

lim n ( B n ) = 0 .

Thus,

H n , ε 0 L 2 p * ( R , L 2 N p * N p * 2 ) C 0 .

Moreover, for large n ,

e i Δ ( u n H n , ε 0 ( 0 ) ) S 1 ( R ) e i Δ W ˜ n M ( ε 0 ) S 1 ( R ) 0 .

Now,

R n , ε 0 S ( R ) = j = 1 M ( ε 0 ) 1 ( λ n j ) N 2 2 U j t n j ( λ n j ) 2 , λ n j j = 1 M ( ε 0 ) 1 ( λ n j ) N 2 2 U j t n j ( λ n j ) 2 , λ n j S ( R ) = I α * j = 1 M ( ε 0 ) 1 ( λ n j ) N 2 2 U j t n j ( λ n j ) 2 , λ n j p * j = 1 M ( ε 0 ) 1 ( λ n j ) N 2 2 U j t n j ( λ n j ) 2 , λ n j p * 2 × j = 1 M ( ε 0 ) 1 ( λ n j ) N 2 2 U j t n j ( λ n j ) 2 , λ n j j = 1 M ( ε 0 ) 1 ( λ n j ) ( N 2 ) ( 2 p * 1 ) 2 I α * U j t n j ( λ n j ) 2 , λ n j p * U j t n j ( λ n j ) 2 , λ n j p * 2 U j t n j ( λ n j ) 2 , λ n j S ( R ) .

Take a term of the previous quantity expansion

( I ) = I α * I [ 1 , M ( ε 0 ) ] , I = p * 2 j I 1 ( λ n j ) N 2 2 U j t n j ( λ n j ) 2 , λ n j 1 ( λ n k ) N 1 U k t n k ( λ n k ) 2 , λ n k U ¯ k t n k ( λ n k ) 2 , λ n k × I [ 1 , M ( ε 0 ) ] , I = p * 2 j I 1 ( λ n j ) N 2 2 U j t n j ( λ n j ) 2 , λ n j 1 ( λ n k ) N 2 2 U k t n k ( λ n k ) 2 , λ n k I α * 1 ( λ n k ) α k ( N 2 ) 2 U k t n k ( λ n k ) 2 , λ n k p * 2 1 ( λ n k ) N 1 U k t n k ( λ n k ) 2 , λ n k U ¯ k t n k ( λ n k ) 2 , λ n k × 1 ( λ n k ) N 2 2 U k t n k ( λ n k ) 2 , λ n k p * 2 1 ( λ n k ) N 2 2 U k t n k ( λ n k ) 2 , λ n k = I α * I [ 1 , M ( ε 0 ) ] , I = p * 2 j I 1 ( λ n j ) N 2 2 U j t n j ( λ n j ) 2 , λ n j 1 ( λ n k ) α k ( N 2 ) 2 U k t n k ( λ n k ) 2 , λ n k p * 2 × 1 ( λ n k ) N 1 U k t n k ( λ n k ) 2 , λ n k U ¯ k t n k ( λ n k ) 2 , λ n k 1 ( λ n k ) N 2 2 U k t n k ( λ n k ) 2 , λ n k p * 2 × 1 ( λ n k ) N 2 2 U k t n k ( λ n k ) 2 , λ n k + ( I I ) ,

where ( I I ) is a mixed term. Now, with the triangular and Hardy-Littlewood-Paley inequalities, one obtains

( I ) ( I I ) S ( R ) I [ 1 , M ( ε 0 ) ] , I = p * 2 I α * j I , j k 1 ( λ n j ) N 2 2 U j t n j ( λ n j ) 2 , λ n j 1 ( λ n k ) N 1 U k t n k ( λ n k ) 2 , λ n k × U ¯ k t n k ( λ n k ) 2 , λ n k × 1 ( λ n k ) N 2 2 U k t n k ( λ n k ) 2 , λ n k p * 1 S ( R ) 1 ( λ n j ) N 2 2 U j t n j ( λ n j ) 2 , λ n j 1 ( λ n k ) N 2 2 U k t n k ( λ n k ) 2 , λ n k L p * ( R , L r 1 2 ) , j k λ n k λ n j 2 ( N 1 ) ( N 2 ) α + N + N 2 1 U j ( t n j ) ( λ n k ) 2 ( λ n j ) 2 , λ n k λ n j U k ( t n k ) L p * R , L r 1 2 , j k .

Here, r 1 2 N p * ( p * 1 ) 2 + α p * and one used the estimate

S S 1 2 ( p 1 ) S .

Thus, with the orthogonality property of the profile decomposition, it follows that

R n , ε 0 S ( R ) 0 .

Then, applying the perturbation theory in Proposition 2.4, the property S C ( u n ) holds.

(2) By Proposition 4.1, one obtains, for 2 j M ,

ψ j = 0 , W n M 0 .

Thus, W n 1 0 and

u n = 1 ( λ n 1 ) N 2 2 ψ l 1 s n 1 , λ n 1 + W n 1 .

Taking the scaling

z n ( λ n 1 ) N 2 2 u n ( λ n 1 ) , W ¯ n ( λ n 1 ) N 2 2 W n ( λ n 1 ) .

Then,

z n = u n < Q

and

z n = ψ l 1 ( s n 1 , ) + W ¯ n 1 , W ¯ n 1 0 .

Moreover,

U 1 ( s n 1 ) ψ l 1 ( s n 1 ) 0 .

Then,

z n = ψ l 1 ( s n 1 , ) + W ¯ n 1 ; E ( U 1 ( s n 1 ) ) = E ( ψ l 1 ( s n 1 ) ) + o n ( 1 ) E c ; U 1 ( s n 1 ) = ψ l 1 ( s n 1 ) + o n ( 1 ) = ψ 1 + o n ( 1 ) < Q .

This case follows by applying the long time perturbation theory in Proposition 2.4 with e = 0 , u ˜ = U 1 and u 0 = z n .□

The proof of the next result, about the existence of a critical solution with a pre-compact flow, is omitted because it follows like in he study by Miao et al. [5].

Proposition 6.1

Assume that E c < E [ Q ] . Then, there exists a global solution u c to (NLS) with data u c , 0 such that

u c , 0 < Q , E [ u c ] = E c a n d ( S C ) ( u c , 0 ) d o e s n o t h o l d .

Moreover, there exists a real function λ : ( T * , T * ) R + such that the following set is pre-compact in H ˙ 1 ,

K 1 λ ( t ) N 2 2 u c t , x λ ( t ) , t ( T * , T * ) .

6.1 Rigidity theorem

The aim of this subsection is to establish the following Liouville-type result.

Theorem 6.1

Let N 3 and 0 < α < N 4 + α . Let u 0 H ˙ r d 1 satisfying (3) and (5) and u C ( ( T * , T * ) , H ˙ r d 1 ) be the maximal solution to (NLS). If there exists a real function λ : ( T * , T * ) R + such that the following set is pre-compact in H ˙ 1 ,

K 1 λ ( t ) N 2 2 u c t , x λ ( t ) , t ( T * , T * ) .

Then u 0 = 0 .

Proof

Let u u c given in the previous theorem and v 1 λ N 2 2 u c ( , λ ) . One discusses two cases.

(1) First case: inf λ ( t ) > λ 0 > 0 . Following lines in the study by Miao et al. [5], one has T * = . Moreover, by Hardy inequality

u 2 N 2 u , N 3

and the variational analysis, one has, for any ε > 0 , there exists R ( ε ) > 0 such that

x > R ( ε ) u 2 x 2 + u 2 d x + x > R ( ε ) y > R ( ε ) ( I α * u p * ) u p * d x d y < ε .

Indeed, with Hardy-Littlewood-Sobolev inequality, via the fact that u L ( R , L 2 ) , one has

x > R ( ε ) y > R ( ε ) ( I α * u p * ) u p * d x d y C u L 2 N N 2 ( x > R ( ε ) ) p * u L 2 N N 2 p * C u L 2 ( x > R ( ε ) ) p * u p * < ε 2 .

Take the truncated variance defined in Section 5,

V R R N ψ R ( x ) u ( . , x ) 2 d x .

Taking account of computation in section 5 via Hardy inequality, one writes

1 4 V R = u 2 R N u p * ( I α * u p * ) d x + o R ( 1 ) .

By computing using the variational estimates, we obtain

F u 2 Q 2 u Q 2 u Q 2 p * u Q 2 1 Q 2 p * S N , α p * R N u p * ( I α * u p * ) d x 1 Q 2 u 2 R N u p * ( I α * u p * ) d x .

Now, since p * > 1 , there exists C δ > 0 such that F ( x ) > C δ x for 0 < x < 1 δ . Thus, by Proposition 4.1, one obtains

V R > C δ u 0 2 .

On the other hand, by Hardy and Hölder inequalities,

V R = 2 R R N ψ x R u ¯ u d x R { x < 2 R } u u d x R 2 u u 1 R 2 u 0 2 .

Then, integrating in time, one obtains

t u 0 2 V R ( t ) V R ( 0 ) R 2 u 0 2 .

This gives u 0 = 0 .

(2) The case inf t λ ( t ) = 0 follows similarly as in the study by Kenig and Merle [8].□

6.2 Proof of the global existence and scattering

Now, we are ready to establish the second part of Theorem 2.1. Theorem 6.1 applied to u c , via Proposition 6.1, gives u c , 0 = 0 . This contradicts the equality u c S 1 ( R ) = . This absurdity means that (26) is false. Thus, the H ˙ 1 scattering holds by Proposition 2.3.

Acknowledgements

Authors would like to thank the Deanship of Graduate Studies and Scientific Research at Qassim University for financial support (QU-APC-2024-9/1).

  1. Funding information: The second author is partially supported by NSF of Gansu Province (China) (Nos. 20JR5RA498 and 21JR7RE176) and Innovation Ability Promotion Foundation of Universities in Gansu Province (No. 2020B-185).

  2. Conflict of interest: Authors state no conflict of interest.

  3. Data availability statement: No datasets were generated or analyzed during the current study.

Appendix

This section contains two parts. The first one is about a proof of the scattering criteria in Proposition 2.3, and the second one gives an elementary proof of the linear profile decomposition in Proposition 2.5.

A.1 Proof of a scattering criteria

Let us prove Proposition 2.3. By Duhamel formula, one writes

u e i Δ u 0 = i 0 e i ( s ) Δ d s ; ϕ u 0 = i 0 e i s Δ d s ; u ( t ) e i Δ ϕ = i e i ( s ) Δ d s .

Take the admissible pair ( q , r ) ( 2 p * , 2 N p * N p * 2 ) Γ . Thanks to Strichartz estimate and Hardy-Littlewood-Sobolev inequality, it follows that

( u e i t Δ ϕ ) S ( R ) ( I α * u p * ) u p * 2 u L q ( ( t , ) , L r ) + ( I α * u p * 2 ( u ¯ u ) ) u p * 2 u L q ( ( t , ) , L r ) u L 2 p * ( ( t , ) , L 2 N p * ( p * 1 ) 2 + α p * ) 2 ( p * 1 ) u L 2 p * ( ( t , ) , L 2 N p * N p * 2 ) u S 1 ( ( t , ) ) 2 ( p * 1 ) u S ( ( t , ) ) .

Letting t 1 so that u S 1 ( t , ) 1 , one obtains

u S ( R ) .

Then,

( u e i t Δ ϕ ) S ( R ) u S 1 ( t , ) 2 ( p * 1 ) u S ( t , ) 0 , if t .

This achieves the proof.

A.2 Proof of the profile decomposition

This subsection contains a variant proof of Proposition 2.5. This elementary proof is available for an integer p * . Taking account of [17], the last equality is the only point to prove. It is sufficient to prove that

N ( u n ) = j = 1 M N ψ l j t n j ( λ n j ) 2 + N ( W n M ) + o n ( 1 ) .

First step: one proves that

N j = 1 M 1 ( λ n j ) N 2 2 ψ l j t n j ( λ n j ) 2 , λ n j = j = 1 M N ψ l j t n j ( λ n j ) 2 + o n ( 1 ) .

By re-indexing and adjusting profiles, one can assume that there exists 1 M 0 M such that

  1. t n j ( λ n j ) 2 = 0 , for any 1 j M 0 ;

  2. t n j ( λ n j ) 2 , for any M 0 < j M .

Now, for 1 j < k M 0 , we computed with some integrations by parts

( A n ) N j = 1 M 0 1 ( λ n j ) N 2 2 ψ j λ n j j = 1 M 0 N ( ψ j ) = R N R N I α ( x y ) j = 1 M 0 1 ( λ n j ) N 2 2 ψ j y λ n j p * k = 1 M 0 1 ( λ n k ) N 2 2 ψ k x λ n k p * j = 1 M 0 ψ j ( y ) p * ψ j ( x ) p * d x d y l 1 + + l M 0 = p * , h 1 + + h M 0 = p * , ( l j , h j ) ( p * , p * ) R N R N I α ( x y ) j , k = 1 M 0 1 ( λ n j ) N 2 2 ψ j y λ n j l j 1 ( λ n k ) N 2 2 ψ k x λ n k h k d x d y .

Thus, with Hardy-Littlewood-Sobolev inequality and denoting for short R N × R N ,

( A n ) l 1 + + l M 0 = p * , h 1 + + h M 0 = p * , ( l j , h j ) ( p * , p * ) I α ( x y ) ( λ n 1 ) N α ( λ n 1 ) 2 N j , k = 1 M 0 1 ( λ n j ) N 2 2 ψ j λ n 1 λ n j y l j 1 ( λ n k ) N 2 2 ψ k λ n 1 λ n k x h k d x d y l 1 + + l M 0 = p * , h 1 + + h M 0 = p * , ( l j , h j ) ( p * , p * ) I α ( x y ) j , k = 1 M 0 λ n 1 λ n j N 2 2 ψ j λ n 1 λ n j y l j λ n 1 λ n k N 2 2 ψ k λ n 1 λ n k x h k d x d y ,

where without loss of generality, one assumes that , for 1 < j M 0 , yield λ n j λ n 1 and l 1 0 . Then,

N j = 1 M 0 1 ( λ n j ) N 2 2 ψ j λ n j = j = 1 M 0 N ( ψ j ) + o n ( 1 ) .

Now, an expansion gives

( B n ) N j = 1 M 0 1 ( λ n j ) N 2 2 ψ j λ n j + j = 1 + M 0 M 1 ( λ n j ) N 2 2 e i t n j ( λ n j ) 2 Δ ψ l j λ n j N j = 1 M 0 ψ j = R N I α * j = 1 M 0 1 ( λ n j ) N 2 2 ψ j λ n j + j = 1 + M 0 M 1 ( λ n j ) N 2 2 e i t n j ( λ n j ) 2 Δ ψ j λ n j p * × j = 1 M 0 1 ( λ n j ) N 2 2 ψ j x λ n j + j = 1 + M 0 M 1 ( λ n j ) N 2 2 e i t n j ( λ n j ) 2 Δ ψ j x λ n j p * d x R N I α * j = 1 M 0 ψ j p * j = 1 M 0 ψ j p * d x .

Thus,

( B n ) I α ( x y ) j = 1 M 0 1 ( λ n j ) N 2 2 ψ j x λ n j + j = 1 + M 0 M 1 ( λ n j ) N 2 2 e i t n j ( λ n j ) 2 Δ ψ j x λ n j p * j = 1 M 0 1 ( λ n j ) N 2 2 ψ j y λ n j + j = 1 + M 0 M 1 ( λ n j ) N 2 2 e i t n j ( λ n j ) 2 Δ ψ j y λ n j p * j = 1 M 0 ψ j ( x ) p * j = 1 M 0 ψ j ( y ) p * d x d y k 1 + + k M = p * , h 1 + + h M = p * , k i + h i 2 p * I α ( x y ) j = 1 M 0 1 ( λ n j ) N 2 2 ψ j x λ n j k j j = 1 + M 0 M 1 ( λ n j ) N 2 2 e i t n j ( λ n j ) 2 Δ ψ j x λ n j k j × i = 1 M 0 1 ( λ n i ) N 2 2 ψ i y λ n i h i i = 1 + M 0 M 1 ( λ n i ) N 2 2 e i t n i ( λ n i ) 2 Δ ψ i y λ n i h i d x d y .

Thus, taking account of Corollary 2.6, one obtains

( B n ) k 1 + + k M = p * , h 1 + + h M = p * , k i + h i 2 p * j = 1 M 0 1 ( λ n j ) k j ( N 2 ) 2 ψ j λ n j 2 N p * α + N k j j = 1 + M 0 M 1 ( λ n j ) k j ( N 2 ) 2 e i t n j ( λ n j ) 2 Δ ψ j λ n j 2 N p * α + N k j × i = 1 M 0 1 ( λ n j ) h i ( N 2 ) 2 ψ i λ n i 2 N p * α + N h i i = 1 + M 0 M 1 ( λ n i ) h i ( N 2 ) 2 e i t n i Δ ψ i 2 N p * α + N h i k 1 + + k M = p * , h 1 + + h M = p * , k i + h i 2 p j = 1 M 0 ψ j H ˙ 1 k j j = 1 + M 0 M e i t n j ( λ n j ) 2 Δ ψ j 2 N N 2 k j i = 1 M 0 ψ i H ˙ 1 h i i = 1 + M 0 M e i t n i ( λ n i ) 2 Δ ψ i 2 N N 2 h i .

For M 0 < j M , via Hardy-Littlewood-Sobolev inequality, the free kernel Schrödinger decay and a density argument [25], one obtains

ψ l j t n j ( λ n j ) 2 2 N N 2 ( λ n j ) 2 t n j ψ j 2 N N + 2 0 .

Thus, ( B n ) 0 . This finishes the first step. Now, one writes using Hardy-Littlewood-Sobolev injection

N [ W n M 1 ] sup t N [ e i t Δ W n M 1 ] sup t R N ( I α * e i t Δ W n M 1 p * ) e i t Δ W n M 1 p * d x sup t e i t Δ W n M 1 2 N N 2 2 p * .

Then, by the asymptotic smallness,

lim M 1 ( lim n N [ W n M 1 ] ) = 0 .

Take M 1 and ε > 0 . By Sobolev injections, Hölder inequality and Proposition 2.1, one obtains

sup n N [ u n ] + sup n N [ W n M ] 1 .

Thus, one can choose M 1 M and N 1 > 0 such that for n N 1 ,

( C n ) N [ u n W n M 1 ] N [ u n ] + N [ W n M W n M 1 ] N [ W n M ] I α ( x y ) ( u n ( x ) W n M 1 ( x ) ) p * ( u n ( y ) W n M 1 ( y ) ) p * ( u n ( x ) u n ( y ) ) p * d x d y + I α ( x y ) ( W n M ( x ) W n M 1 ( x ) ) p * ( W n M ( y ) W n M 1 ( y ) ) p * ( W n M ( x ) W n M ( y ) ) p * d x d y i j + l j = i k + l k = p * , i j , i k < p * R N R N I α ( x y ) 1 j , l p u n ( x ) i j u n ( y ) i k W n M 1 ( x ) l j W n M 1 ( y ) l k d x d y + i j + l j = i k + l k = p , i j , i k < p R N R N I α ( x y ) 1 j , l p W n M ( x ) i j W n M ( y ) i k W n M 1 ( x ) l j W n M 1 ( y ) l k d x d y i j + l j = i k + l k = p * , i j , i k < p * u n 2 N p * α + N i j + i k W n M 1 2 N p * α + N l j + l k + i j + l j = i k + l k = p * , i j , i k < p * W n M 2 N p * α + N i j + i k W n M 1 2 N p * α + N l j + l k .

Thus,

( C n ) i j + l j = i k + l k = p * , i j , i k < p * u n 2 N N 2 i j + i k W n M 1 2 N N 2 l j + l k + i j + l j = i k + l k = p , i j , i k < p W n M 2 N N 2 i j + i k W n M 1 2 N N 2 l j + l k i j + l j = i k + l k = p * , i j , i k < p * u n H ˙ 1 i j + i k W n M 1 2 N N 2 l j + l k + i j + l j = i k + l k = p , i j , i k < p W n M H ˙ 1 i j + i k W n M 1 2 N N 2 l j + l k i j + l j = i k + l k = p * , i j , i k < p * W n M 1 2 N N 2 l j + l k ε .

By the first step and the profile expansion, one takes N 2 N 1 such that for n N 2 ,

N [ u n W n M 1 ] j = 1 M 1 N e i t n j ( λ n j ) 2 Δ ψ j λ n j < ε .

By the profile expansion,

W n M W n M 1 = j = 1 + M M 1 1 ( λ n j ) N 2 N e i t n j ( λ n j ) 2 Δ ψ j λ n j .

So, with the first step, one takes N 3 N 2 such that for n N 3 ,

N [ W n M W n M 1 ] j = 1 + M M 1 N 1 ( λ n j ) N 2 N e i t n j ( λ n j ) 2 Δ ψ j λ n j < ε .

Taking account of the last three inequalities with right hand side ε , one obtains

N [ u n ] j = 1 M N 1 ( λ n j ) N 2 N e i t n j ( λ n j ) 2 Δ ψ j λ n j N [ W n M ] ε .

This finishes the proof.

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Received: 2023-10-24
Revised: 2024-02-06
Accepted: 2024-02-27
Published Online: 2024-04-19

© 2024 the author(s), published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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