Home Asymptotic behavior of solutions of a viscoelastic Shear beam model with no rotary inertia: General and optimal decay results
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Asymptotic behavior of solutions of a viscoelastic Shear beam model with no rotary inertia: General and optimal decay results

  • Adel M. Al-Mahdi EMAIL logo
Published/Copyright: May 23, 2024

Abstract

In this study, we consider a viscoelastic Shear beam model with no rotary inertia. Specifically, we study

ρ 1 φ t t κ ( φ x + ψ ) x + ( g φ x x ) ( t ) = 0 , b ψ x x + κ ( φ x + ψ ) = 0 ,

where the convolution memory function g belongs to a class of L 1 ( 0 , ) functions that satisfies

g ( t ) ξ ( t ) ϒ ( g ( t ) ) , t 0 ,

where ξ is a positive nonincreasing differentiable function and ϒ is an increasing and convex function near the origin. Using just this general assumptions on the behavior of g at infinity, we provide optimal and explicit general energy decay rates from which we recover the exponential and polynomial rates when ϒ ( s ) = s p and p covers the full admissible range [ 1 , 2 ) . Given this degree of generality, our results improve some of earlier related results in the literature.

MSC 2010: 35B40; 93D20

1 Introduction

In 1921, Timoshenko [1] presented the following system:

(1.1) ρ 1 φ t t κ ( φ x + ψ ) x = 0 , in ( 0 , L ) × ( 0 , + ) , ρ 2 ψ t t b ψ x x + κ ( φ x + ψ ) = 0 , in ( 0 , L ) × ( 0 , + ) ,

as a model of a motion of a thick beam, where φ is the transverse displacement; ψ is the rotational angle of the filament of the beam; and ρ 1 , ρ 2 , b , and κ are the fixed positive physical parameters. The issue of stabilization of Timoshenko systems has attracted a great deal of research, and many results concerning the well posedness and long-time behavior of the system have been established. For this matter, various types of dissipation, such as boundary and/or internal feedback, heat or thermoelasticity, memory, and Kelvin-Voigt damping, have been used (see, for example, [24]). It is well known that the exponential stability of System (1.1) is achieved in the presence of linear dampings in both equations of (1.1) without imposing any condition on the speeds of wave propagation. But if the damping effect is acting on only one equation, the system is exponentially stable if and only if it has equal speeds of wave propagation, i.e.,

(1.2) κ ρ 1 = b ρ 2 .

The reader is advised to consult the above-cited references for detailed discussions on the stability analysis of Timoshenko systems.

It is worth mentioning that the original Timoshenko (1.1) is characterized by two natural frequencies, which lead to a physical paradox, known as the second spectrum, which was not noted in Timoshenko original work. This required (mathematically) some relation, called the equal-speed propagation. However, this is an unrealistic requirement. To overcome this paradox and to eliminate the anomaly of the second spectrum, Elishakoff [5] proposed the following truncated version of the classical Timoshenko system:

(1.3) ρ 1 φ t t κ ( φ x + ψ ) x = 0 , ρ 2 φ t t x b ψ x x + κ ( φ x + ψ ) = 0 ,

where ( x , t ) [ 0 , L ] × R + . Model (1.3) has not been well studied, and only a few results regarding the stability have been established. For example, Almeida Júnior et al. [7] considered the following Shear beam model with no rotary inertia:

(1.4) ρ 1 φ t t κ ( φ x + ψ ) x + μ φ t = 0 , b ψ x x + κ ( φ x + ψ ) = 0 ,

and proved that the energy of this system has exponential decay without imposing any relationship between the coefficients of the system. The Shear beam model (1.4) has only one finite wave speed for all wave numbers, which is κ ρ 1 . This property is unlike the one in the classical Timoshenko-type system which has two wave speeds κ ρ 1 and b ρ 1 (Table 1).

Table 1

Wave speed for Timoshenko beam models

Beam models Wave speeds Exponential decay Polynomial decay
Classical Timoshenk [1] κ ρ 1 , b ρ 2 κ ρ 1 = b ρ 2 κ ρ 1 b ρ 2
Truncated Timoshenk [5] b ρ 2 1 + b ρ 1 κ ρ 2 No matter wave speed
Shear model [6] κ ρ 1 No matter wave speed

Concerning the stabilization via heat dissipation, only a few works are available in the literature. We point out the work by Apalara et al. [8], where they considered the following system:

(1.5) ρ 1 φ t t κ ( φ x + ψ ) x = 0 , ρ 2 φ t t x b ψ x x + κ ( φ x + ψ ) + γ θ x = 0 , ρ 3 θ t β θ x x + γ ψ x t t = 0 ,

where θ is the temperature difference, and ρ 3 , β > 0 , and γ 0 are the capacity, diffusivity, and adhesive stiffness, respectively. The authors discussed briefly the well posedness and proved an exponential decay result irrespective of the coefficients of the system. Recently, Keddi et al. [9] looked into the following thermoelastic Timoshenko system:

(1.6) ρ 1 φ t t κ ( φ x + ψ ) x = 0 , in ( 0 , 1 ) × ( 0 , ) , ρ 2 φ t t x b ψ x x + κ ( φ x + ψ ) + δ θ x = 0 , in ( 0 , 1 ) × ( 0 , ) , c θ t + q x + δ ψ x t = 0 , in ( 0 , 1 ) × ( 0 , ) , τ q t + β q + θ x = 0 , in ( 0 , 1 ) × ( 0 , ) ,

and established the well posedness and an exponential decay result. For more results in this topic, we refer the reader to see [1027]. Motivated by the aforementioned works and discussion about the wave speeds, we are concerned with the following viscoelastic Shear beam model:

(1.7) ρ 1 φ t t κ ( φ x + ψ ) x + ( g φ x x ) ( t ) = 0 ,

(1.8) b ψ x x + κ ( φ x + ψ ) = 0 ,

where the convolution g φ x x is defined by

( g φ x x ) ( t ) = 0 t g ( t s ) φ x x ( s ) d s

and ( x , t ) [ 0 , 1 ] × R + . We consider (1.7)–(1.8) subject to the following initial and boundary conditions:

(1.9) φ ( x , 0 ) = φ 0 , φ t ( x , 0 ) = φ 1 , ψ ( x , 0 ) = ψ 0 , x [ 0 , 1 ] ,

(1.10) φ x ( 0 , t ) = φ x ( 1 , t ) = ψ ( 0 , t ) = ψ ( 1 , t ) = 0 , t > 0 .

Our aim is to prove the stability of Systems (1.7)–(1.10). To the best of my knowledge, the stability of (1.7)–(1.10) has not been discussed in the current nature. From the boundary conditions (1.10), Poincaré’s inequality cannot be implemented over φ . So, integration (1.7) over ( 0 , 1 ) and using the boundary conditions (1.10), we obtain

(1.11) d 2 d t 2 0 1 φ ( x , t ) d x = 0 .

Now, solving (1.11) and imposing the initial condition (1.9), we obtain

(1.12) 0 1 φ ( x , t ) d x = 0 1 φ 0 ( x ) d x + t 0 1 φ 1 ( x ) d x .

We introduce the following new variable:

φ ˜ ( x , t ) = φ ( x , t ) 0 1 φ ( x , t ) d x .

Therefore, we obtain

(1.13) 0 1 φ ˜ ( x , t ) d x = 0 .

Thus, we can use the application of Poincaré’s inequality on φ ˜ . Thus, we work with ( φ ˜ , ψ ) , instead of ( φ , ψ ) but, for simplicity, we write ( φ , ψ ) .

2 Assumptions

This section introduces some information that is necessary for the validation of our findings. The letter c is used to represent any positive constant in this article. We assume the following for the relaxation function g :

( A 1 ) : The memory kernel g : [ 0 , + ) ( 0 , + ) is a C 1 nonincreasing function satisfying

(2.1) g ( 0 ) > 0 and κ 3 0 + g ( s ) d s > 0 .

In addition, there exists a C 1 function ϒ : ( 0 , ) ( 0 , ) , which is linear, or it is strictly increasing and strictly convex C 2 function on ( 0 , r ] , r g ( 0 ) , with ϒ ( 0 ) = ϒ ( 0 ) = 0 , and a positive nonincreasing differentiable function ξ , such that

(2.2) g ( t ) ξ ( t ) ϒ ( g ( t ) ) , t 0 .

( A 2 ) : The coefficients b and κ satisfy

(2.3) b κ 2 > 0 .

Remark 2.1

Condition (2.2) was introduced by Alabau-Boussouira et al. [28] and improved by Mustafa [29].

We state without proof the existence result of the weak solutions of Systems (1.7)–(1.8) in the following theorem.

Theorem 2.2

If the initial date ( φ 0 , φ 1 , ψ 0 ) , then Systems (1.7)–(1.8) have a weak solution satisfying

φ L ( [ 0 , T ) ; H * 1 ( 0 , 1 ) ) , φ t L ( [ 0 , T ) ; L 2 ( 0 , 1 ) ) , ψ L ( [ 0 , T ) ; H 0 1 ( 0 , 1 ) ) ,

where

= H * 1 ( 0 , 1 ) × L 2 ( 0 , 1 ) × H 0 1 ( 0 , 1 ) , H * 1 ( 0 , 1 ) = H 1 ( 0 , 1 ) L * 2 ( 0 , 1 )

and

L * 2 ( 0 , 1 ) = u L 2 ( 0 , 1 ) : 0 1 u ( x ) d x = 0 .

The proof of the aforementioned theorem (and for more regularity of the solutions) can be proved using the Faedo-Galerkin method as the proof of Theorem 2.1 established by Almeida Júnior et al. [7].

Now, we introduce the “modified” energy associated with Systems (1.7)–(1.10) as follows:

(2.4) E ( t ) 1 2 0 1 φ t 2 + b ψ x 2 0 t g ( s ) d s φ x 2 + κ ( φ x + ψ ) 2 d x + 1 2 ( g φ x ) ( t ) .

3 Technical lemmas

In this section, we state and establish several lemmas needed for the proofs of our main results.

Lemma 3.1

The energy E ( t ) satisfies

(3.1) E ( t ) = 1 2 ( g φ x ) ( t ) 1 2 g ( t ) 0 1 φ x 2 d x 0 .

Proof

By multiplying (1.7) by φ t and (1.8) by ψ t , using integration by parts and adding the results, it is easy to arrive at the proof of (3.1).□

Remark 3.2

To prove that the energy is positive, using the positivity of g and using Poincaré’s inequality, we note that

(3.2) b ψ x 2 0 t g ( s ) d s φ x 2 + κ ( φ x + ψ ) 2 = b ψ x 2 3 0 t g ( s ) d s + κ φ x 2 + 2 κ φ x ψ + κ ψ 2 + 2 0 t g ( s ) d s b κ 2 ψ 2 + φ x + κ ψ 2 0 ,

where = κ 3 0 + g ( s ) d s > 0 (from Assumption ( A 2 ) ).

Lemma 3.3

[29] There exist positive constants ϱ and t 1 such that

(3.3) g ( t ) ϱ g ( t ) , t [ 0 , t 1 ] .

Lemma 3.4

[29] For any 0 < θ < 1 ,

(3.4) 0 1 0 t g ( t s ) φ x ( s ) φ x ( t ) d s 2 d x C θ ( Θ φ x ) ( t ) ,

where

(3.5) C θ = 0 g 2 ( s ) θ g ( s ) g ( s ) d s a n d Θ ( t ) = θ g ( t ) g ( t ) .

Lemma 3.5

Assume that ( A 1 ) ( A 2 ) hold. Then, for all t R + , the derivative of the functional

Δ 1 ( t ) ρ 1 0 1 φ x 0 x φ t ( y ) d y d x 1 2 0 1 φ x 2 d x

satisfies

(3.6) Δ 1 ( t ) ρ 1 0 1 φ t 2 d x κ 4 ε 1 0 g ( s ) d s 0 1 φ x 2 d x + κ 2 0 1 ψ x 2 d x + C ε 1 C θ ( Θ φ x ) ( t ) .

Proof

Differentiating Δ 1 , then using (1.7)–(1.8), we end up with

(3.7) Δ 1 ( t ) = ρ 1 0 1 φ x t 0 x φ t ( y ) d y d x 0 1 φ x 0 x κ ( φ y + ψ ) y 0 t g ( t s ) φ y y ( s ) d y .

Integrating by parts and using the boundary conditions (1.10), (3.7) becomes

(3.8) Δ 1 ( t ) = ρ 1 0 1 φ t 2 d x κ 0 1 φ x 2 d x κ 0 1 φ x ψ d x + 0 1 φ x 0 t g ( t s ) φ x ( s ) d s d x I .

Using Young’s and Poincaré’s inequalities gives, for any ε 1 > 0 ,

(3.9) κ 0 1 φ x ψ d x 4 0 1 φ x 2 d x + κ 2 0 1 ψ x 2 d x .

We observe that

I = 0 t g ( s ) d s 0 1 φ x 2 d x + 0 1 φ x 0 t g ( t s ) ( φ x ( s ) φ x ( t ) ) d s d x I 2 .

Using Young’s inequality, we obtain

I 2 ε 1 0 1 φ x 2 d x + 1 4 ε 1 0 1 0 t g ( t s ) ( φ x ( s ) φ x ( t ) ) d s 2 d x .

Then, using (3.4), we obtain

1 4 ε 1 0 1 0 t g ( t s ) ( φ x ( s ) φ x ( t ) ) d s 2 d x C ε 1 C θ ( Θ φ x ) ( t ) .

So,

I ε 1 + 0 + g ( s ) d s 0 1 φ x 2 d x + C ε 1 C θ ( Θ φ x ) ( t ) .

Combining all the above, the proof of the estimate (3.6) is completed.□

Lemma 3.6

Assume that ( A 1 ) ( A 2 ) hold, the functional

Δ 2 ( t ) = ρ 1 0 1 φ t φ d x ,

satisfies, along the solution of Systems (1.7)–(1.10), for any ε 2 > 0 ,

(3.10) Δ 2 ( t ) ρ 1 0 1 φ t 2 d x b 0 1 ψ x 2 d x κ 0 1 ( φ x + ψ ) 2 d x + ε 2 + 0 + g ( s ) d s 0 1 φ x 2 d x + C ε 2 C θ ( Θ ψ x ) ( t ) .

Proof

Taking the derivative of Δ 2 ( t ) , using (1.7), and integrating by parts, we obtain

(3.11) Δ 2 ( t ) = ρ 1 0 1 φ t 2 d x κ 0 1 ( φ x + ψ ) φ x d x 0 1 φ 0 t g ( t s ) φ x x ( s ) d s d x .

Adding and subtracting some terms, (3.11) becomes

(3.12) Δ 2 ( t ) = ρ 1 0 1 φ t 2 d x κ 0 1 ( φ x + ψ ) 2 d x + κ 0 1 ( φ x + ψ ) ψ d x + 0 1 φ x 0 t g ( t s ) ( φ x ( t ) φ x ( s ) ) d s d x + 0 t g ( s ) d s 0 1 φ x 2 d x .

By multiplying (1.8) by ψ and integrating over ( 0 , 1 ) , we obtain

(3.13) κ 0 1 ( φ x + ψ ) ψ d x = b 0 1 ψ x 2 d x .

Using (3.13), equation (3.12) becomes

(3.14) Δ 2 ( t ) = ρ 1 0 1 φ t 2 d x κ 0 1 ( φ x + ψ ) 2 d x b 0 1 ψ x 2 d x + 0 1 φ x 0 t g ( t s ) ( φ x ( t ) φ x ( s ) ) d s d x + 0 t g ( s ) d s 0 1 φ x 2 d x .

Using Young’s inequality, we obtain for ε 2 > 0

(3.15) 0 1 φ x 0 t g ( t s ) [ φ x ( t ) φ x ( s ) ] d s d x ε 2 0 1 φ x 2 d x + 1 4 ε 2 0 1 0 t g ( t s ) [ φ x ( s ) φ x ( t ) ] d s 2 d x ε 2 0 1 φ x 2 d x + C θ ε 2 ( Θ φ x ) ,

which implies (3.10).□

Lemma 3.7

Assume that ( A 1 ) ( A 2 ) hold. Then, for any t 1 > 0 , the functional

Δ 3 ( t ) ρ 1 0 1 φ t 0 t g ( t s ) ( φ ( t ) φ ( s ) ) d s d x

satisfies, for any δ 1 , δ 2 , δ 3 > 0 ,

(3.16) Δ 3 ( t ) ρ 1 g 1 2 0 1 φ t 2 d x + δ 1 0 1 φ x 2 d x + δ 3 0 1 ( φ x + ψ x ) 2 d x + c C θ δ 1 + c δ 2 ( 1 + C θ ) + c C θ δ 3 + C θ ( Θ φ x ) ( t ) ,

where g 1 = 0 t 1 g ( s ) d s .

Proof

Differentiating Δ 3 and integrating by parts, we obtain

(3.17) Δ 3 ( t ) = ρ 1 0 t g ( s ) d s 0 1 φ t 2 d x + κ 0 1 ( φ x + ψ ) 0 t g ( t s ) ( φ x ( t ) φ x ( s ) ) d s d x + 0 1 0 t g ( t s ) φ x ( s ) d s 0 t g ( t s ) ( φ x ( t ) φ x ( s ) ) d s d x ρ 1 0 1 φ t 0 t g ( t s ) ( φ ( t ) φ ( s ) ) d s d x = ρ 1 0 t g ( s ) d s 0 1 φ t 2 d x + 0 1 0 t g ( t s ) ( φ x ( t ) φ x ( s ) ) d s 2 d x + 0 t g ( s ) d s 0 1 φ x 0 t g ( t s ) ( φ x ( t ) φ x ( s ) ) d s d x + κ 0 1 ( φ x + ψ ) 0 t g ( t s ) ( φ x ( t ) φ x ( s ) ) d s d x ρ 1 0 1 φ t 0 t g ( t s ) ( φ ( t ) φ ( s ) ) d s d x .

Applying Young’s inequality, we obtain for δ 1 > 0

(3.18) 0 t g ( s ) d s 0 1 φ x 0 t g ( t s ) ( φ x ( t ) φ x ( s ) ) d s d x δ 1 0 1 φ x 2 ( t ) d x + c C θ δ 1 ( Θ φ x ) ( t ) .

Similarly, we can find, for any δ 2 > 0 ,

ρ 1 0 1 φ t ( t ) 0 t g ( t s ) ( φ ( t ) φ ( s ) ) d s d x = ρ 1 0 1 φ t 0 t Θ ( t s ) ( φ ( t ) φ ( s ) ) d s d x ρ 1 0 t φ t ( t ) 0 t θ g ( t s ) ( φ ( t ) φ ( s ) ) d s d x δ 2 0 1 φ t 2 ( t ) d x + ρ 1 2 0 t Θ ( s ) d s 2 δ 2 ( Θ φ ) ( t ) + ρ 1 2 θ 2 2 δ 2 0 1 0 t g ( t s ) φ ( t ) φ ( s ) d s 2 d x δ 2 0 1 φ t 2 ( t ) d x + c δ 2 ( Θ φ x ) ( t ) + θ 2 C θ δ 2 ( Θ φ x ) ( t ) δ 2 0 1 φ t 2 ( t ) d x + c δ 2 ( 1 + C θ ) ( Θ φ x ) ( t ) .

Using Young’s inequality and performing similar calculations as in (3.18), we obtain, for any δ 3 > 0 ,

(3.19) κ 0 1 ( φ x + ψ ) 0 t g ( t s ) ( φ x ( t ) φ x ( s ) ) d s d x δ 3 0 1 ( φ x + ψ ) 2 d x + c C θ δ 3 ( Θ φ x ) ( t ) .

Using Lemma 3.4, we find

(3.20) 0 1 0 t g ( t s ) ( φ x ( t ) φ x ( s ) ) d s 2 d x C θ ( Θ φ x ) ( t ) .

Combining all the aforementioned estimates, we find, for any t t 1 ,

(3.21) Δ 3 ( t ) ρ 1 0 t g ( s ) d s δ 2 0 1 φ t 2 d x + δ 1 0 1 φ x 2 d x + δ 3 0 1 ( φ x + ψ ) 2 d x + c C θ δ 1 + c δ 2 ( 1 + C θ ) + c C θ δ 3 + C θ ( Θ φ x ) ( t ) .

By taking δ 2 = g 1 2 , we obtain the desired Inequality (3.16).□

Lemma 3.8

Under Assumptions ( A 1 ) ( A 2 ) , the functional

(3.22) Δ 4 ( t ) 0 1 0 t Λ ( t s ) φ x ( s ) 2 d s d x

satisfies, along the solution of Systems (1.7)–(1.10), the estimate

(3.23) Δ 4 ( t ) 1 2 ( g φ x ) ( t ) + 3 ( κ ) 0 1 φ x ( s ) 2 d x ,

where Λ ( t ) = 3 t + g ( s ) d s .

Proof

The proof is similar to the one in [30].□

Lemma 3.9

The functional defined by

(3.24) ( t ) = Ξ E ( t ) + Δ 1 ( t ) + Δ 2 ( t ) + Ξ 3 Δ 3 ( t ) ,

satisfies, for suitable choice of Ξ , Ξ 3 > 0 and for all t t 1 ,

(3.25) ( t ) ( κ ) 4 0 1 φ x 2 d x 0 1 ψ x 2 d x 0 1 φ t 2 d x 0 1 ( φ x + ψ ) 2 d x + 1 64 ( g φ x ) ( t ) ,

where t 1 = g 1 ( r ) as introduced earlier in this article, and the following equivalence relation

(3.26) ( t ) E ( t ) .

Proof

By taking the derivative of the functional and using the aforementioned estimates,

( t ) Ξ θ 2 ( g φ x ) ( t ) κ 4 2 0 g ( s ) d s ε 1 ε 2 δ 1 Ξ 3 0 1 φ x 2 d x ( κ δ 3 Ξ 3 ) 0 1 ( φ x + ψ ) 2 d x b κ 2 0 1 ψ x 2 d x c 0 2 Ξ 3 2 ρ 1 0 1 φ t 2 d x Ξ 2 Ξ 3 c C θ δ 1 + c δ 2 ( 1 + C θ ) + c C θ δ 3 + C θ C θ C ε C θ ( Θ φ x ) ( t ) .

By fixing ε 1 = ε 2 = ε , then

( t ) Ξ θ 2 ( g φ x ) ( t ) 1 4 4 κ 8 0 g ( s ) d s 8 ε 4 δ 1 Ξ 3 0 1 φ x 2 d x ( κ δ 3 Ξ 3 ) 0 1 ( φ x + ψ ) 2 d x b κ 2 0 1 ψ x 2 d x c 0 2 Ξ 3 2 ρ 1 0 1 φ t 2 d x Ξ 2 Ξ 3 c C θ δ 1 + c δ 2 ( 1 + C θ ) + c C θ δ 3 + C θ C θ C ε C θ ( Θ φ x ) ( t ) .

Recall that κ 3 0 g ( s ) = > 0 . This gives that

3 κ 9 0 g ( s ) = 3 > 0 .

By choosing 8 ε = 0 g ( s ) . From this, we note that

( t ) Ξ θ 2 ( g φ x ) ( t ) 1 4 κ + 3 κ 9 0 g ( s ) d s 4 δ 1 Ξ 3 0 1 φ x 2 d x ( κ δ 3 Ξ 3 ) 0 1 ( φ x + ψ ) 2 d x b κ 2 0 1 ψ x 2 d x c 0 2 Ξ 3 2 ρ 1 0 1 φ t 2 d x Ξ 2 Ξ 3 c C θ δ 1 + c δ 2 ( 1 + C θ ) + c C θ δ 3 + C θ C θ c C θ ( Θ φ x ) ( t ) .

By choosing δ 3 = κ 2 Ξ 3 , δ 1 = 3 4 Ξ 3 , and Ξ 3 > 4 c 0 and since θ g 2 ( s ) θ g ( s ) g ( s ) < g ( s ) , then using the Lebesgue-dominated convergence theorem, we obtain

(3.27) θ C θ = 0 δ g 2 ( s ) δ g ( s ) g ( s ) d s 0 , as θ 0 .

Hence, there exists some 0 < θ * < 1 , such that if θ < θ * , then

(3.28) θ C θ < 1 128 1 + c + Ξ 3 c δ 1 + c δ 2 + c δ 3 + 1 .

By putting δ = 1 32 Ξ and choosing Ξ sufficiently large, we arrive at

Ξ 2 Ξ 3 c C θ δ 1 + c δ 2 ( 1 + C θ ) + c C θ δ 3 + C θ C θ c C θ > 0 .

Therefore, we show that (3.25) holds. Moreover, we can choose Ξ even larger (if needed) so that (3.26) is satisfied, which means that, for some constants μ 1 , μ 2 > 0 , we have

μ 1 E ( t ) ( t ) μ 2 E ( t ) .

Lemma 3.10

The energy functional associated with Systems (1.7)–(1.10) satisfies

(3.29) 0 E ( s ) d s < .

Proof

We introduce the following functional defined by

(3.30) ( t ) = ( t ) + 1 16 Δ 4 ( t ) .

Applying Lemma 3.8, we see that there exists a positive constant δ such that

(3.31) ( t ) ( κ ) 0 1 φ x 2 d x 0 1 ψ x 2 d x 0 1 φ t 2 d x 0 1 ( φ x + ψ ) 2 d x 1 64 ( g φ x ) ( t ) δ E ( t ) .

Then, integrating the result over ( 0 , t ) , we obtain

(3.32) δ 0 t E ( s ) d s ( t ) + ( 0 ) ( 0 ) .

Hence, the proof of the bound in (3.29) is completed.□

4 Main result

In this section, we state and prove our main results and give some examples to illustrate our theoretical result.

Theorem 4.1

Assume ( A 1 ) ( A 2 ) hold and the function ϒ islinear. Then, there exist positive constants c 1 and c 2 such that the energy of Systems (1.7)–(1.10) satisfies, for all t t 1 ,

(4.1) E ( t ) c 1 e c 2 t 1 t ξ ( s ) d s ,

where t 1 = g 1 ( r ) .

Proof

To prove Theorem 4.1, combine (2.4) and (3.25), to obtain, for some positive constants c and ϑ ,

( t ) ϑ E ( t ) + c 0 t 1 g ( t s ) 0 1 φ x ( t ) φ x ( s ) 2 d x d s + c t 1 t g ( t s ) 0 1 φ x ( t ) φ x ( s ) 2 d x d s .

Now, imposing Lemma 3.3 and recalling (3.1), we obtain

(4.2) Γ ( t ) ϑ E ( t ) + c t 1 t g ( t s ) 0 1 φ x ( t ) φ x ( s ) 2 d x d s ,

where Γ ( t ) = ( t ) + c E ( t ) . Since ϒ is linear, by multiplying (4.2) by ξ ( t ) , using the condition ( A 1 ) , and (3.1), we obtain

(4.3) ξ ( t ) Γ ( t ) ϑ ξ ( t ) E ( t ) + c ξ ( t ) t 1 t g ( t s ) 0 1 φ x ( t ) φ x ( s ) 2 d x d s ϑ ξ ( t ) E ( t ) + c t 1 t ξ ( s ) g ( t s ) 0 1 φ x ( t ) φ x ( s ) 2 d x d s ϑ ξ ( t ) E ( t ) c t 1 t g ( s ) 0 1 φ x ( t ) φ x ( t s ) 2 d x d s ϑ ξ ( t ) E ( t ) c E ( t ) .

Using the fact ξ ( t ) 0 , the functional Γ 1 ξ Γ + c E satisfies Γ 1 E and

(4.4) Γ 1 ( t ) ϑ ξ ( t ) E ( t ) ϑ 1 ξ ( t ) Γ 1 ( t ) , t t 1 .

After integrating the last inequality over ( t 1 , t ) , the proof of Theorem (4.1) is completed.□

Theorem 4.2

Assume ( A 1 ) ( A 2 ) hold and the function ϒ is nonlinear. Then, there exist positive constants c 1 and c 2 such that the energy of Systems (1.7)–(1.10) satisfies, for all t > t 1 ,

(4.5) E ( t ) c 2 ϒ 1 1 c 1 g 1 ( r ) t ξ ( s ) d s ,

where ϒ 1 ( t ) = t r 1 s ϒ ( s ) d s , is strictly decreasing and convex on ( 0 , r ] , with lim t 0 ϒ 1 ( t ) = + .

Proof

Thanks to the bound in (3.29), we can find a constant 0 < β < 1 so that the function I defined by

(4.6) 0 < Φ ( t ) β t 1 t 0 1 φ x ( t ) φ x ( s ) 2 d x d s < 1 , t t 1 .

Let us define

(4.7) Ψ ( t ) t 1 t g ( s ) 0 1 φ x ( t ) φ x ( t s ) 2 d x d s .

By (3.1), we see that Ψ ( t ) c E ( t ) . Since ϒ is strictly convex on ( 0 , r ] and ϒ ( 0 ) = 0 ,

(4.8) ϒ ( ε s ) θ ϒ ( s ) , 0 ε 1 , and s ( 0 , r ] .

Using (4.6), Assumption ( A 1 ) , and Jensen’s inequality, we obtain

(4.9) Ψ ( t ) = 1 β Φ ( t ) t 1 t Φ ( t ) ( g ( s ) ) β 0 1 φ x ( t ) φ x ( t s ) 2 d x d s 1 β Φ ( t ) t 1 t Φ ( t ) ξ ( s ) ϒ ( g ( s ) ) β 0 1 φ x ( t ) φ x ( t s ) 2 d x d s ξ ( t ) β Φ ( t ) t 1 t ϒ ( Φ ( t ) g ( s ) ) β 0 1 φ x ( t ) φ x ( t s ) 2 d x d s ξ ( t ) β ϒ 1 Φ ( t ) t 1 t Φ ( t ) g ( s ) β 0 1 φ x ( t ) φ x ( t s ) 2 d x d s = ξ ( t ) β ϒ β t 1 t g ( s ) 0 1 φ x ( t ) φ x ( t s ) 2 d x d s = ξ ( t ) β ϒ ¯ β t 1 t g ( s ) 0 1 φ x ( t ) φ x ( t s ) 2 d x d s ,

where ϒ ¯ is an extension of ϒ such that ϒ ¯ is strictly increasing and strictly convex C 2 function on ( 0 , ) . Hence, we obtain

(4.10) t 1 t g ( s ) 0 1 φ x ( t ) φ x ( t s ) 2 d x d s 1 β ϒ ¯ 1 β Ψ ( t ) ξ ( t ) .

Therefore, (4.2) becomes

(4.11) Γ ( t ) σ 1 E ( t ) + c ϒ ¯ 1 β Ψ ( t ) ξ ( t ) , t t 1 .

Now, for ε 0 < r , let

(4.12) Γ 1 ( t ) ϒ ¯ ε 0 E ( t ) E ( 0 ) Γ ( t ) + E ( t ) ,

which is equivalent to E . Using the fact that E 0 , ϒ ¯ > 0 , ϒ ¯ > 0 , then (4.11) converts to

(4.13) Γ 1 ( t ) = ε 0 E ( t ) E ( 0 ) ϒ ¯ ε 0 E ( t ) E ( 0 ) Γ ( t ) + ϒ ¯ ε 0 E ( t ) E ( 0 ) Γ ( t ) + E ( t ) σ 1 E ( t ) ϒ ¯ ε 0 E ( t ) E ( 0 ) + c ϒ ¯ ε 0 E ( t ) E ( 0 ) ϒ ¯ 1 β Ψ ( t ) ξ ( t ) + E ( t ) .

Thanks to the argument given in Arnold [31], we obtain

(4.14) ϒ ¯ * ( s ) = s ( ϒ ¯ ) 1 ( s ) ϒ ¯ ( ( ϒ ¯ ) 1 ( s ) ) , if s ( 0 , ϒ ¯ ( r ) ] ,

where ϒ ¯ * is the conjugate of ϒ ¯ in the sense of Young [31] and ϒ ¯ * satisfies the following Young’s inequality:

(4.15) A B ϒ ¯ * ( A ) + ϒ ¯ ( B ) , if A ( 0 , ϒ ¯ ( r ) ] , B ( 0 , r ] .

So, with A = ϒ ¯ ε 0 E ( t ) E ( 0 ) and B = ϒ ¯ 1 β Ψ ( t ) ξ ( t ) , using (3.1) and (4.13)–(4.15), we arrive at

(4.16) Γ 1 ( t ) σ 1 E ( t ) ϒ ¯ ε 0 E ( t ) E ( 0 ) + c ϒ ¯ * ϒ ¯ ε 0 E ( t ) E ( 0 ) + c β Ψ ( t ) ξ ( t ) + E ( t ) σ 1 E ( t ) ϒ ¯ ε 0 E ( t ) E ( 0 ) + c ε 0 E ( t ) E ( 0 ) ϒ ¯ ε 0 E ( t ) E ( 0 ) + c β Ψ ( t ) ξ ( t ) + E ( t ) .

Using the fact that ε 0 E ( t ) E ( 0 ) < r , then ϒ ¯ ε 0 E ( t ) E ( 0 ) = ϒ ε 0 E ( t ) E ( 0 ) , and multiplying (4.16) by ξ ( t ) , we find

(4.17) ξ ( t ) Γ 1 ( t ) σ 1 ξ ( t ) E ( t ) ϒ ε 0 E ( t ) E ( 0 ) + c ε 0 ξ ( t ) E ( t ) E ( 0 ) ϒ ε 0 E ( t ) E ( 0 ) + c β Ψ ( t ) + ξ ( t ) E ( t ) σ 1 ξ ( t ) E ( t ) ϒ ε 0 E ( t ) E ( 0 ) + c ε 0 ξ ( t ) E ( t ) E ( 0 ) ϒ ε 0 E ( t ) E ( 0 ) c E ( t ) .

Hence, by taking ϒ 2 ( t ) = ξ ( t ) Γ 1 ( t ) + c E ( t ) , we find for some positive constants b 1 , b 2 > 0 ,

(4.18) b 1 Γ 2 ( t ) E ( t ) b 2 Γ 2 ( t ) .

Consequently, with a suitable choice of ε 0 , we obtain, for a constant Λ > 0 and t t 1 ,

(4.19) Γ 2 ( t ) Λ ξ ( t ) E ( t ) E ( 0 ) ϒ ε 0 E ( t ) E ( 0 ) = Λ ξ ( t ) ϒ 2 E ( t ) E ( 0 ) ,

where ϒ 2 ( t ) = t ϒ ( ε 0 t ) . Since ϒ 2 ( t ) = ϒ ( ε 0 t ) + ε 0 t ϒ ( ε 0 t ) , using the convexity of ϒ on ( 0 , r ] , we find that ϒ 2 ( t ) , ϒ 2 ( t ) > 0 on ( 0 , 1 ] . Thus, with

(4.20) Δ ( t ) = b 1 Γ 2 ( t ) E ( 0 ) E ( t ) .

By (4.19), we find for some positive constant β 1 > 0 ,

(4.21) Δ ( t ) β 1 ξ ( t ) ϒ 2 ( Δ ( t ) ) , t t 1 .

Then, integration over ( t 1 , t ) yields

(4.22) t 1 t Δ ( t ) ϒ 2 ( Δ ( t ) ) d s β 1 t 1 t ξ ( s ) d s ,

which gives

(4.23) ε 0 Δ ( t ) ε 0 Δ ( t 1 ) 1 s ϒ ( s ) d s β 1 t 1 t ξ ( s ) d s .

Hence, if ϒ 1 ( t ) = t r 1 s ϒ ( s ) d s , then using the properties of ϒ , the fact ϒ 1 is strictly decreasing function on ( 0 , r ] and lim t 0 ϒ 1 ( t ) = + , we obtain

(4.24) Δ ( t ) 1 ε 0 ϒ 1 1 β 1 t 1 t ξ ( s ) d s .

Consequently, from (4.20) and (4.24), we obtain the desired result (4.5).□

Example 4.3

  1. If g ( t ) = e ζ t , t 0 , , ζ > 0 are the constants. is chosen such that ( A 1 ) is valid, then

    g ( t ) = ζ ϒ ( g ( t ) ) , with ξ ( t ) = ζ and ϒ ( s ) = s .

    So under the assumptions of Theorem 4.1, we conclude that the solution of (1.7)–(1.10) satisfies, for two constants ϰ 1 , ϰ 2 > 0 , the energy estimate

    E ( t ) ϰ 1 e ϰ 2 t , t > t 1 .

  2. Let g ( t ) = e ( 1 + t ) ν , for t 0 , 0 < ν < 1 . is chosen such that condition ( A 1 ) is valid, then

    g ( t ) = ξ ( t ) ϒ ( g ( t ) ) , with ξ ( t ) = ν ( 1 + t ) ν 1 and ϒ ( s ) = s .

    So under the assumptions of Theorem 4.1, we conclude that the energy (2.4) satisfies, for some constant ϱ > 0 ,

    E ( t ) ϱ e ϱ ( 1 + t ) ν , when t is large enough .

  3. For

    g ( t ) = ( 1 + t ) ν , t 0 ,

    for ν > 1 and is chosen so that hypothesis ( A 1 ) remains valid. Then,

    g ( t ) = ζ ϒ ( g ( t ) ) , with ξ ( t ) = ζ and ϒ ( s ) = s p ,

    where ζ is a fixed constant, p = 1 + ν ν , which satisfies 1 < p < 2 . So under the assumptions of Theorem 4.2, we conclude that the energy (2.4) satisfies, for some constant ϱ > 0 and t 1 > 0 ,

    E ( t ) ϱ ( 1 + t ) ν , t > t 1 .

Remark 4.4

From the aforementioned examples, we note that the decay rate of the energy E ( t ) is consistent with the decay rate of the relaxation function g . So, the decay rate of the energy E ( t ) is optimal.

5 Conclusion

In this work, we investigated the asymptotic behavior of solutions of the viscoelastic Shear beam model (no rotary inertia). This model has only one finite wave speed for all wave numbers. We proved that the dissipative Shear beam model has general and optimal decay results. These results improve and generalize some earlier results in the literature.

Acknowledgements

The author would like to express his profound gratitude to King Fahd University of Petroleum and Minerals (KFUPM) for its continuous support. The support provided by the Interdisciplinary Research Center for Construction & Building Materials (IRC-CBM) at King Fahd University of Petroleum & Minerals (KFUPM), Saudi Arabia, for funding this work through Project No. INCB2403, is also greatly acknowledged.

  1. Funding information: This work was funded by KFUPM, Grant No. INCB2403.

  2. Author contributions: The author confirms the sole responsibility for the conception of the study, presented results and manuscript preparation. The author read and approved the final version of the manuscript.

  3. Conflict of interest: The author declares no competing interests.

  4. Data availability statement: No data were used to support this study.

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Received: 2023-12-01
Revised: 2024-03-24
Accepted: 2024-03-29
Published Online: 2024-05-23

© 2024 the author(s), published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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