Startseite Joint approximation of analytic functions by the shifts of Hurwitz zeta-functions in short intervals
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Joint approximation of analytic functions by the shifts of Hurwitz zeta-functions in short intervals

  • Antanas Laurinčikas und Darius Šiaučiūnas EMAIL logo
Veröffentlicht/Copyright: 11. August 2025

Abstract

In the article, we obtain that, for algebraically independent over Q parameters α 1 , , α r , there are infinitely many shifts ( ζ ( s + i τ , α 1 ) , , ζ ( s + i τ , α r ) ) of Hurwitz zeta-functions with τ [ T , T + H ] , T 27 82 H T 1 2 , that approximate any r -tuple of analytic functions on the strip { s C : 1 2 < σ < 1 } . More precisely, the latter set of shifts has a positive density. For the proof, a probabilistic approach is applied.

MSC 2010: 11M35

1 Introduction

Denote, as usual, by P , N , N 0 , Z , Q , R , and C the sets of all prime, positive integer, non-negative integer, integer, rational, real and complex numbers, respectively. Let s = σ + i t , σ , t R , i 2 = 1 , be a complex variable, and 0 < α 1 be a fixed parameter. The Hurwitz zeta-function ζ ( s , α ) was introduced in [1], and, for σ > 1 , is defined by the Dirichlet series

ζ ( s , α ) = m = 0 1 ( m + α ) s .

Moreover, ζ ( s , α ) has analytic continuation to the whole complex plane, except for a simple pole at the point s = 1 with residue 1.

The function ζ ( s , α ) is a generalization of the Riemann zeta-function ζ ( s ) because, for σ > 1 ,

ζ ( s , 1 ) = m = 0 1 ( m + 1 ) s = m = 1 1 m s = ζ ( s )

and

ζ s , 1 2 = 2 s m = 0 1 ( 2 m + 1 ) s = 2 s m = 1 1 m s m = 1 1 ( 2 m ) s = ( 2 s 1 ) ζ ( s ) .

On the other hand, the functions ζ ( s ) and ζ ( s , α ) have one essential difference: the function ζ ( s ) , for σ > 1 ,

has the representation by the Euler product:

ζ ( s ) = p P 1 1 p s 1 ,

while the function ζ ( s , α ) , except for the cases α = 1 and α = 1 2 , has no such representation. Moreover, it is well known that ζ ( s ) satisfies the symmetric functional equation:

ξ ( s ) = ξ ( 1 s ) , ξ ( s ) = π s 2 Γ s 2 ζ ( s ) , s C ,

where Γ ( s ) is the Euler gamma-function, while, for ζ ( s , α ) , the following nonsymmetric equations connecting s and 1 s are true:

ζ ( 1 s , α ) = Γ ( s ) ( 2 π ) s e π i s 2 m = 1 e 2 π i m α m s + e π i s 2 m = 1 e 2 π i m α m s , σ > 1

or

ζ ( s , α ) = 2 Γ ( 1 s ) ( 2 π ) 1 s sin π s 2 m = 1 cos ( 2 π m α ) m 1 s + cos π s 2 m = 1 sin ( 2 π m α ) m 1 s , σ < 0 .

This is one of the causes of differences in value distribution of ζ ( s ) and ζ ( s , α ) and also reflects in the approximate functional equation for ζ ( s , α ) , which is the main ingredient for the proof of the mean square estimate in short intervals [2]. Regardless of that difference, the Hurwitz zeta-function is an important analytic object of number theory having a wide field of applications. Since Dirichlet L -functions have a representation by Hurwitz zeta-functions with rational parameters, the functions ζ ( s , α ) play an important role in the investigation of prime numbers in arithmetic progressions. In addition, Hurwitz zeta-functions have deep applications in algebraic number theory and special function theory.

One of the most interesting analytic properties of the Hurwitz zeta-function is its universality, i.e., the ability to approximate analytic functions defined in the strip D = { s C : 1 2 < σ < 1 } by shifts ζ ( s + i τ , α ) , τ R . Universality is a common feature of the functions ζ ( s ) and ζ ( s , α ) ; however, the shifts ζ ( s + i τ ) approximate only nonvanishing on D functions.

Universality of the function ζ ( s ) and Dirichlet L -functions was proved by Voronin [3], see [48]. His discovery is a certain infinite-dimensional generalization of the Bohr-Courant theorem [9] on the denseness of the set:

{ ζ ( σ + i t ) : t R } ,

with fixed 1 2 < σ < 1 .

Value distribution of the function ζ ( s , α ) , including universality, depends on the arithmetic of the parameter α . The final universality results are known only for transcendental and rational α . Let K be the class of compact subsets of the strip D with connected complements, and H ( K ) with K K the class of continuous functions on K that are analytic in the interior of K . Moreover, let meas A stand for the Lebesgue measure of a measurable set A R . Then the following statement is known.

Proposition 1

Suppose that the parameter α is transcendental or rational 1 or 1/2. Let K K and f ( s ) H ( K ) . Then, for every ε > 0 ,

liminf T 1 T meas { τ [ 0 , T ] : sup s K ζ ( s + i τ , α ) f ( s ) < ε } > 0 .

Moreover, the lower limit can be replaced by the limit for all but at most countably many ε > 0 .

The first part of the proposition was obtained by S.M.Gonek in his thesis [10]. In the case of rational α = a q , ( a , q ) = 1 , the representation

ζ s , a q = q s φ ( q ) χ ( mod q ) χ ¯ ( a ) L ( s , χ ) ,

where L ( s , χ ) denotes the Dirichet L -function, and φ ( q ) is the Euler totient function, and the joint hybrid universality of Dirichlet L -functions that, if 0 θ p < 1 , p P , p q , then for every ε > 0 , there exists τ R such that

τ log p 2 π θ p < ε , p q

and

sup s K L ( s + i τ , χ ) e f ( s ) < ε

were applied. Here, u denotes the distance of u to the nearest integer.

In the case of transcendental α , the set { log ( m + α ) : m N 0 } is linearly independent over Q ; therefore, methods of Diophantine analysis can be applied.

Bagchi in the thesis [11] proposed a new method for the proof of universality for zeta-functions based on probabilistic limit theorems for weakly convergent probability measures in the space H ( D ) of analytic functions on D . This method is also convenient for the proof of Proposition 1.

In the cases α = 1 and α = 1 2 , the assertion of Proposition 1 remains valid with a remark that the function f ( s ) is nonvanishing on K .

The case of algebraic irrational α is the most complicated. The best result in this case is given in [12] with a certain restriction for the degree of α .

The second assertion of Proposition 1 was given in [13].

Proposition 1, as the other universality theorems for zeta-functions, is not effective. Though Proposition 1 implies that there are infinitely many shifts ζ ( s + i τ , α ) approximating a given function, any concrete shift is not known. A weaker problem is to indicate the interval containing τ with the approximating property. For the Riemann zeta-function, this was considered in [1416] and in [12] for the function ζ ( s , α ) with algebraic irrational α . Another way toward effectively realized universality theorems for zeta-functions is shortening of the length of the interval. The latter way for ζ ( s ) was proposed in [17], and improved in [18]. A universality theorem in short intervals for ζ ( s , α ) with transcendental α was obtained in [2].

Proposition 2

[2] Suppose that α is transcendental, and T 27 82 H T 1 2 . Let K K and f ( s ) H ( K ) . Then, for every ε > 0 ,

liminf T 1 H meas { τ [ T , T + H ] : sup s K ζ ( s + i τ , α ) f ( s ) < ε } > 0 .

Moreover, “ liminf can be replaced by lim for all but at most countably many ε > 0 .

In this article, we are interested in the joint universality of Hurwitz zeta-functions, i.e., simultaneous approximation of a tuple of analytic functions by shifts ( ζ ( s + i τ , α 1 ) , , ζ ( s + i τ , α r ) ) . The first joint universality theorem was obtained by Voronin [19], who proved joint universality for Dirichlet L -functions with pairwise nonequivalent Dirichlet characters. Clearly, in the joint case, the approximating functions must be independent in a certain sense. In the case of Dirichlet L -functions [19], this independence is realized by the pairwise nonequivalence of Dirichlet characters. For Hurwitz zeta-functions, a sufficient independence is achieved by using algebraically independent over Q parameters α 1 . , α r , i.e., that there is no polynomial p ( s 1 , , s r ) 0 with rational coefficients such that p ( α 1 , , α r ) = 0 . The following joint universality theorem is known [20,21].

Proposition 3

Suppose that the numbers α 1 , , α r are algebraically independent over Q . For j = 1 , , r , let K j K and f j H ( K j ) . Then, for every ε > 0 ,

liminf T 1 T meas { τ [ 0 , T ] : sup 1 j r sup s K j ζ ( s + i τ , α j ) f j ( s ) < ε } > 0 .

In [22], the algebraic independence over Q of the parameters α 1 , , α r was replaced by a weaker requirement that the set

L ( α 1 , , α r ) = def { log ( m + α j ) : m N 0 , j = 1 , , r }

is linearly independent over Q .

Our aim is to give a joint generalization of Proposition 2. For the statement of the main results, some notation is needed. Denote by ( X ) the Borel σ -field of a topological space X . Define the set

Ω = m N 0 { s C : s = 1 } .

Elements of Ω are all functions defined on N 0 with values from the unit circle on C . With the product topology and pointwise multiplication, Ω is a compact topological Abelian group. Therefore, by the Tikhonov theorem [23], the Cartesian product

Ω r = j = 1 r Ω j ,

where Ω j = Ω for j = 1 , , r , again is a compact topological group. Therefore, on ( Ω r , ( Ω r ) ) , the probability Haar measure m H exists. Notice that the measure m H is the product of the Haar measures m j H on ( Ω j , ( Ω j ) ) , j = 1 , , r , i.e., if

A = A 1 × × A r ( Ω r )

with A j ( Ω j ) , then

m H ( A ) = m 1 H ( A 1 ) m r H ( A r ) .

Thus, we have the probability space ( Ω r , ( Ω r ) , m H ) . We equip the space H ( D ) of analytic functions with the topology of uniform convergence on compact sets and set

H r ( D ) = H ( D ) × × H ( D ) r .

Now, on the probability space ( Ω r , ( Ω r ) , m H ) , define the H r ( D ) -valued random element

ζ ( s , α ̲ , ω ) = ( ζ ( s , α 1 , ω 1 ) , , ζ ( s , α r , ω r ) ) ,

where α ̲ = ( α 1 , , α r ) , ω = ( ω 1 , , ω r ) Ω r , ω j Ω j , ω j = ( ω j ( m ) : m N 0 ) , j = 1 , , r , and

ζ ( s , α j , ω j ) = m = 0 ω j ( m ) ( m + α j ) s , j = 1 , , r .

The main result of the article is the following theorem.

Theorem 4

Suppose that the parameters α 1 , , α r are algebraically independent over Q , and T 27 82 H T 1 2 . For j = 1 , , r , let K j K and f j ( s ) H ( K j ) . Then, for every ε > 0 ,

liminf T 1 H meas { τ [ T , T + H ] : sup 1 j r sup s K j ζ ( s + i τ , α j ) f j ( s ) < ε } > 0 .

Moreover, the limit

lim T 1 H meas { τ [ T , T + H ] : sup 1 j r sup s K j ζ ( s + i τ , α j ) f j ( s ) < ε } = m H { ω Ω r : sup 1 j r sup s K j ζ ( s , α j , ω j ) f j ( s ) < ε }

exists and is positive for all but at most countably many ε > 0 .

The form of Theorem 4 suggests that, for its proof, probabilistic arguments connected to the space ( Ω r , ( Ω r ) , m H ) will be applied.

2 Limit theorem

The main ingredient of the proof of Theorem 4 is a joint limit theorem for Hurwitz zeta-functions in the space H r ( D ) in short intervals. For A ( H r ( D ) ) , define

P T , H , α ̲ ( A ) = 1 H meas { τ [ T , T + H ] : ζ ( s + i τ , α ̲ ) A } ,

where

ζ ( s , α ̲ ) = ( ζ ( s , α 1 ) , , ζ ( s , α r ) ) .

Denote by P ζ , α ̲ the distribution of the H r ( D ) -valued random element ζ ( s , α ̲ , ω ) , i.e.,

P ζ , α ̲ ( A ) = m H { ω Ω r : ζ ( s , α ̲ , ω ) A } , A ( H r ( D ) ) .

Theorem 5

Suppose that the parameters α 1 , , α r are algebraically independent over Q , and T 27 82 H T 1 2 . Then P T , H , α ̲ converges weakly to P ζ , α ̲ as T . Moreover, the support of the measure P ζ , α ̲ is the whole space H r ( D ) .

Since joint limit theorems in short intervals for zeta-functions are not known, we will give a full proof of Theorem 5. For this, we will use separate lemmas.

For A ( Ω r ) , define

P T , H , α ̲ Ω r ( A ) = 1 H meas { τ [ T , T + H ] : ( ( ( m + α 1 ) i τ : m N 0 ) , , ( ( m + α r ) i τ : m N 0 ) ) A } .

Lemma 6

Suppose that the parameters α 1 , , α r are algebraically independent over Q , and T 27 82 H T 1 2 . Then P T , H , α ̲ Ω r converges weakly to the Haar measure m H as T .

Proof

A classical way for investigation of the weak convergence of probability measures in compact groups is the Fourier transform method, see, for example, [24]. The characters of the group Ω r are of the form

j = 1 r m N 0 ω j k j m ( m ) ,

where the sign indicates that only a finite number of k j m Z are not zero. Hence, the Fourier transform F T , H , α ̲ ( k ̲ 1 , , k ̲ r ) , k ̲ j = ( k j m : k j m Z , m N 0 ) , j = 1 , , r , of P T , H , α ̲ Ω r is

F T , H , α ̲ ( k ̲ 1 , , k ̲ r ) = Ω r j = 1 r m N 0 ω j k j m ( m ) d P T , H , α ̲ Ω r ,

and, by the definition of P T , H , α ̲ Ω r , we have

(1) F T , H , α ̲ ( k ̲ 1 , , k ̲ r ) = 1 H T T + H j = 1 r m N 0 ( m + α j ) i k j m τ d τ = 1 H T T + H exp i τ j = 1 r m N 0 k j m log ( m + α j ) d τ .

We need to show that F T , H , α ̲ ( k ̲ 1 , , k ̲ r ) , as T , converges to the Fourier transform of the Haar measure m H , i.e.,

(2) lim T F T , H , α ̲ ( k ̲ 1 , , k ̲ r ) = 1 if  ( k ̲ 1 , , k ̲ r ) = ( 0 ̲ , , 0 ̲ ) , 0 otherwise.

Obviously, equality (1) gives

(3) F T , H , α ̲ ( 0 ̲ , , 0 ̲ ) = 1 .

Now, suppose that ( k ̲ 1 , , k ̲ r ) ( 0 ̲ , , 0 ̲ ) , We will prove that, in this case,

(4) A ( k ̲ 1 , , k ̲ r ) = def j = 1 m N 0 k j m log ( m + α j ) 0 .

Actually, if, for some nonzero k l 1 m 1 , , k l v m v Z ,

k l 1 m 1 log ( m 1 + α l 1 ) + + k l v m v log ( m v + α l v ) = 0 ,

then

( m 1 + α l 1 ) k m 1 l 1 ( m v + α l v ) k m v l v = 1 ,

and this contradicts the algebraic independence of the numbers α 1 , , α r . Thus, (4) holds, and, after integration in (1), we find

F T , H , α ̲ ( k ̲ 1 , , k ̲ r ) = exp { i T A ( k ̲ 1 , , k ̲ r ) } exp { i ( T + H ) A ( k ̲ 1 , , k ̲ r ) } i H A ( k ̲ 1 , , k ̲ r ) .

Since H as T , this shows that, for ( k ̲ 1 , , k ̲ r ) ( 0 ̲ , , 0 ̲ ) ,

lim T F T , H , α ̲ ( k ̲ 1 , , k ̲ r ) = 0 ,

and this together with (3) proves (2).□

We notice that H as T is the sufficient requirement for H in Lemma 6. Moreover, in place of algebraic independence of α 1 , , α r , we may use the linear independence over Q for the set L ( α 1 , , α r ) .

Next, we will apply Lemma 6 for the proof of a limit lemma in the space H r ( D ) . Let β > 1 2 be a fixed number, and, for n N , m N 0 and j = 1 , , r ,

v n ( m , α j ) = exp m + α j n β .

Define

ζ n ( s , α ̲ ) = ( ζ n ( s , α 1 ) , , ζ n ( s , α r ) ) ,

where

ζ n ( s , α j ) = m = 0 v n ( m , α j ) ( m + α j ) s , j = 1 , , r .

It is obvious, that the latter series are absolutely convergent in any half-plane σ > σ 0 with finite σ 0 .

For A ( H r ( D ) ) , set

P T , H , n , α ̲ ( A ) = 1 H meas { τ [ T , T + H ] : ζ n ( s + i τ , α ̲ ) A } .

For the definition of the limit measure of P T , H , n , α ̲ as T , we introduce the function u n , α ̲ : Ω r H r ( D ) given by

u n , α ̲ ( ω ) = ζ n ( s , α ̲ , ω ) ,

where

ζ n ( s , α ̲ , ω ) = ( ζ n ( s , α 1 , ω 1 ) , , ζ n ( s , α r , ω r ) )

and

ζ n ( s , α j , ω j ) = m = 0 ω j ( m ) v n ( m , α j ) ( m + α j ) s , j = 1 , , r .

In addition, the latter series converges absolutely for σ > σ 0 , thus, uniformly with respect to ω j . Hence, the function u n , α ̲ is continuous; therefore, it is ( ( Ω r ( D ) ) , ( H r ( D ) ) ) measurable. This shows that the Haar measure m H on ( Ω r , ( Ω r ) ) induces the unique probability measure m H u n , α ̲ 1 on ( H r ( D ) , ( H r ( D ) ) ) defined by

m H u n , α ̲ 1 ( A ) = m H ( u n , α ̲ 1 A ) , A ( H r ( D ) ) .

For brevity, let Q n , α ̲ = m H u n , α ̲ 1 .

Lemma 7

Suppose that the parameters α 1 , , α r are algebraically independent over Q , and T 27 82 H T 1 2 . Then P T , H , n , α ̲ converges weakly to Q n , α ̲ as T .

Proof

From the definitions of P T , H , α ̲ Ω r , P T , H , n , α ̲ and u n , α ̲ , it follows that, for A ( H r ( D ) ) ,

P T , H , n , α ̲ ( A ) = 1 T meas { τ [ T , T + H ] : ( ( ( m + α 1 ) i τ : m N 0 ) , , ( ( m + α r ) i τ : m N 0 ) ) u N , α ̲ 1 A } = P T , H , α ̲ Ω r ( u n , α ̲ 1 A ) = P T , H , α ̲ Ω r u n , α ̲ 1 ( A ) .

Since A ( H r ( D ) ) is arbitrary, we have P T , H , n , α ̲ = P T , H , α ̲ Ω r u n , α ̲ 1 . Now, this equality, continuity of the function u n , α ̲ and preservation of weak convergence under continuous mappings, see, for example, Section 5 of [25], together with Lemma 6 show that P T , H , n , α ̲ converges weakly to the measure Q n , α ̲ as T .□

In addition, define two measures

P T , α ̲ ( A ) = 1 T meas { τ [ 0 , T ] : ζ ( s + i τ , α ̲ ) A } , A ( H r ( D ) ) ,

and

P T , n , α ̲ ( A ) = 1 T meas { τ [ 0 , T ] : ζ n ( s + i τ , α ̲ ) A } , A ( H r ( D ) ) .

Then in [22], using the linear independence of the set L ( α 1 , , α r ) , it was obtained that P T , n , α ̲ converges weakly to Q n , α ̲ , and P T , α ̲ converges weakly to P ζ , α ̲ as T . Moreover, Q n , α ̲ , as n , and P T , α ̲ , as T , converges weakly to the same limit measure, i.e., to P ζ , α ̲ . Since the algebraic independence over Q of numbers α 1 , , α r implies the linear independence of L ( α 1 , , α r ) , we have the following statement.

Lemma 8

Suppose that the parameters α 1 , , α r are algebraically independent over Q . Then Q n , α ̲ converges weakly to P ζ , α ̲ as n .

From Lemma 8, it follows that, for the proof of Theorem 5, it suffices to show that the measures P T , H , α ̲ , as T , and Q n , α ̲ , as n , have the same limit measure. For this aim, we need some mean value estimate. Before the statement of a mean value lemma, we recall a metric in H r ( D ) . For g 1 , g 2 H ( D ) , set

d ( g 1 , g 2 ) = m = 1 2 m sup s K m g 1 ( s ) g 2 ( s ) 1 + sup s K m g 1 ( s ) g 2 ( s ) ,

where { K m : m N } D is the sequence of compact embedded sets such that the strip D is the union of all K m , and each compact set K D lies in some K m . Then d is a metric in H ( D ) , which induces the topology of uniform

convergence on compacta. Setting, for g ̲ 1 = ( g 11 , , g 1 r ) , g ̲ 2 = ( g 21 , g 2 r ) H r ( D ) ,

d r ( g ̲ 1 , g ̲ 2 ) = max 1 j r d ( g 1 j , g 2 j )

gives the metric in H r ( D ) which induces the product topology.

Lemma 9

Suppose that the parameters α 1 , , α r are algebraically independent over Q , and T 27 82 H T 1 2 . Then

lim n limsup T 1 H T T + H d r ( ζ ( s + i τ , α ̲ ) , ζ n ( s + i τ , α ̲ ) ) d τ = 0 .

Proof

Since the numbers α 1 , , α r are algebraically independent over Q , they are transcendental. Therefore, in view of Lemma 5 of [2],

(5) lim n limsup T 1 H T T + H d ( ζ ( s + i τ , α j ) , ζ n ( s + i τ , α j ) ) d τ = 0 , j = 1 , , r .

This and the definition of the metric d r prove the lemma.

For the convenience of the reader, we will present a proof of (5). By the definition of the metric d , the latter equalities follow from

(6) lim n limsup T 1 H T T + H sup s K ζ ( s + i τ , α j ) ζ n ( s + i τ , α j ) d τ , j = 1 , r ,

for every compact set K D .

Let

l n ( s ) = 1 β Γ s β n s .

Then the classical Mellin formula implies, for σ > 1 , the representation ( α j = α )

(7) ζ n ( s , α ) = 1 2 π i β i β + i ζ ( s + z , α ) l n ( z ) d z .

Suppose K D is a compact set. Then there exists δ > 0 such that 1 2 + 2 δ σ 1 δ for all σ + i t K . Let β = 1 2 + δ and β 1 = 1 2 + δ σ . Then the residue theorem, in view of (7), gives

ζ n ( s , α ) ζ ( s , α ) = 1 2 π β 1 i β 1 + i ζ ( s + z , α ) l n ( z ) d z + l n ( 1 s ) .

Therefore,

sup s K ζ n ( s + i τ , α ) ζ ( s + i τ , α ) ζ 1 2 + δ + i τ + i v , α sup s K l n 1 2 + δ s + i v d v + sup s K l n ( 1 s i τ ) .

Hence, we have

(8) 1 H T T + H sup s K ζ n ( s + i τ , α ) ζ ( s + i τ , α ) d τ δ , α , K log 2 T log 2 T 1 H T T + H ζ 1 2 + δ + i τ + i v , α d τ sup s K l n 1 2 + δ s + i v d v + 1 H T T + H sup s K l n ( 1 s i τ ) d τ + n δ exp { c 1 log 2 T } H T T + H ( τ + 1 ) 1 2 d τ = def I 1 + I 2 + I 3 , c 1 > 0 .

For estimation of I 1 , the mean square estimate in short intervals obtained in [2] is applied. Namely, if α 1 2 and 1, and 1 2 < σ 7 12 , then, for T 27 82 H T σ , uniformly in H ,

T T + H ζ ( σ + i t , α ) 2 d τ σ , α H .

Application of the latter result gives, for v log 2 T ,

1 H T T + H ζ 1 2 + δ + i τ + i v , α d τ δ , α 1 H ( H + v ) 1 2 δ , α ( 1 + v ) ,

and

(9) I 1 δ , α n δ .

Properties of the function Γ ( s ) lead to

(10) I 2 K n 1 2 2 δ H .

Since I 3 = o ( 1 ) as T , this (8) and (9) prove (6)□

For convenience, we additionally state one lemma on the convergence of random elements in distribution ( D ).

Lemma 10

Suppose that the metric space ( X , ρ ) is separable, the X -valued random elements X n k and Y n , k , n N , are defined on the same probability space ( Ω ^ , A , ν ) , for every k N ,

X n k n D X k

and

X k k D X .

If, for every δ > 0 ,

lim k limsup n ν { ρ ( X n k , Y n ) δ } = 0 ,

then Y n n D X .

Proof of the lemma can be found, for example, in [25], Theorem 4.2.

Proof of Theorem 5

On a certain probability space ( Ω ^ , A , ν ) , define a random variable θ T , H , and suppose that it is uniformly distributed on [ T , T + H ] . Introduce the H r ( D ) -valued random elements

ζ T , H , α ̲ = ζ T , H , α ̲ ( s ) = ζ ( s + i θ T , H , α ̲ )

and

ζ T , H , n , α ̲ = ζ T , H , n , α ̲ ( s ) = ζ n ( s + i θ T , H , α ̲ ) ,

and let ζ n , α ̲ = ζ n , α ̲ ( s ) be the H r ( D ) -valued random element having the distribution Q n , α ̲ , where the measure Q n , α ̲ is the same as in Lemma 8. Lemma 8 implies the relation

(11) ζ n , α ̲ n D P ζ , α ̲ ,

while Lemma 7 gives

(12) ζ T , H , n , α ̲ T D ζ n , α ̲ .

Moreover, using Lemma 9, we obtain that, for every δ > 0 ,

lim n limsup T ν { d r ( ζ T , H , α ̲ , ζ T , H , n , α ̲ ) δ } = lim n limsup T 1 H meas { τ [ T , T + H ] : d r ( ζ ( s + i τ , α ̲ ) , ζ n ( s + i τ , α ̲ ) ) δ } lim n limsup T 1 δ H T T + H d r ( ζ ( s + i τ , α ̲ ) , ζ n ( s + i τ , α ̲ ) ) d τ = 0 .

This together with relations (11) and (12) shows that all conditions of Lemma 10 satisfied for the random elements ζ T , H , α ̲ , ζ T , H , n , α ̲ and ζ n , α ̲ . Therefore, we have

ζ T , H , α ̲ T D P ζ , α ̲ ,

and this gives the first assertion of the theorem.

In [22], under a hypothesis that the set L ( α 1 , , α r ) is linearly independent over Q , it was proved that the support of the measure P ζ , α ̲ is the whole space H r ( D ) . Since the algebraic independence of α 1 , , α r implies the linear independence of L ( α 1 , , α r ) , this proves the second assertion of the theorem.□

3 Proof of universality

We recall the Mergelyan theorem on approximation of analytic functions by polynomials [26,27].

Lemma 11

[26] Let K be a compact set with a connected complement on the complex plane, and g ( s ) a continuous function on K analytic in the interior of K. Then, for every δ > 0 , there exists a polynomial p ( s ) such that

sup s K g ( s ) p ( s ) < δ .

Proof of Theorem 4

Consider the set

G ε = ( g 1 , , g r ) H r ( D ) : sup 1 j r sup s K j g j ( s ) p j ( s ) < ε 2 ,

where p 1 ( s ) , , p r ( s ) are polynomials such that

(13) sup 1 j r sup s K j f j ( s ) p j ( s ) < ε 2 .

This is possible by Lemma 11. Since, by Theorem 5, the support S ζ , α ̲ of P ζ , α ̲ is the set H r ( D ) , ( p 1 ( s ) , , p r ( s ) ) is an element of S ζ , α ̲ . Therefore, the set G ε is an open neighborhood of an element of the support S ζ , α ̲ . Hence, by the property of supports,

(14) P ζ , α ̲ ( G ε ) > 0 .

Let

G ε = { ( g 1 , , g r ) H r ( D ) : sup 1 j r sup s K j g j ( s ) f j ( s ) < ε } .

Then (13), and the definitions of G ε and G ε show that the set G ε lies in G ε . Thus, taking into account (14), we have

(15) P ζ , α ̲ ( G ε ) > 0 .

The latter inequality, Theorem 5 and the equivalence of weak convergence of probability measures in terms of open sets (see Theorem 2.1 of [25]) lead to

liminf T P T , H , α ̲ ( G ε ) P ζ , α ̲ ( G ε ) > 0 ,

and the definitions of P T , H , α ̲ and G ε prove the first assertion of the theorem.

To prove the second assertion of the theorem, we will apply the equivalent of weak convergence in terms of continuity sets. We recall that A ( H r ( D ) ) is a continuity set of P ζ , α ̲ if P ζ , α ̲ ( A ) = 0 , where A denotes the boundary of A .

Observing that the boundary of G ε of the set G ε lies in the set

{ ( g 1 , , g r ) H r ( D ) : sup 1 j r sup s K j g j ( s ) f j ( s ) = ε } ,

we obtain that the boundaries G ε 1 and G ε 2 have no common elements for ε 1 ε 2 . This remark implies that P ζ , α ̲ ( G ε ) > 0 for at most countably many ε > 0 . Therefore, the set G ε is a continuity set of the measure P ζ , α ̲ for all but at most countably many ε > 0 . Hence, Theorem 5 and the equivalence of weak convergence of probability measures in terms of continuity sets (see Theorem 2.1 of [25]) give, by (15), that

lim T P T , H , α ̲ ( G ε ) = P ζ , α ̲ ( G ε ) > 0

for all but at most countably many ε > 0 . The definitions of P T , H , α ̲ , G ε and P ζ , α ̲ show that the limit

lim T 1 H meas { τ [ T , T + H ] : sup 1 j r sup s K j ζ ( s + i τ , α j ) f j ( s ) < ε } = m H { ω Ω r : sup 1 j r sup s K j ζ ( s , α j , ω j ) f j ( s ) < ε }

exists and is positive for all but at most countably many ε > 0 . The theorem is proved.□

Acknowledgments

The authors thank the referees for useful remarks and suggestions.

  1. Funding information: Authors state no funding involved.

  2. Author contributions: The authors contributed equally to the content of this article.

  3. Conflict of interest: The authors state no conflict of interest.

  4. Data availability statement: Data sharing is not applicable to this article as no new data were created or analyzed in this study.

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Received: 2025-02-05
Revised: 2025-06-07
Accepted: 2025-06-10
Published Online: 2025-08-11

© 2025 the author(s), published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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