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The number of rational points of some classes of algebraic varieties over finite fields

  • Guangyan Zhu , Yingjue Fang , Yuanyuan Luo and Zongbing Lin EMAIL logo
Published/Copyright: May 29, 2025

Abstract

Let F q be the finite field of characteristic p and F q * = F q \ { 0 } . In this article, we use Smith normal form of exponent matrices to present exact formulas for the numbers of rational points on suitable affine algebraic varieties defined by the following systems of equations over F q :

a 1 x 1 e 11 x m 1 e 1 m 1 + + a m 1 x 1 e m 1 , 1 x m 1 e m 1 , m 1 = b 1 , a m 1 + 1 x 1 e m 1 + 1,1 x m 2 e m 1 + 1 , m 2 + + a m 2 x 1 e m 2 , 1 x m 2 e m 2 , m 2 = b 2

and

c 1 x 1 d 11 x n 1 d 1 n 1 + + c n 1 x 1 d n 1 , 1 x n 1 d n 1 , n 1 = l 1 , c n 1 + 1 x 1 d n 1 + 1,1 x n 2 d n 1 + 1 , n 2 + + c n 2 x 1 d n 2 , 1 x n 2 d n 2 , n 2 = l 2 , c n 2 + 1 x 1 d n 2 + 1,1 x n 3 d n 2 + 1 , n 3 + + c n 3 x 1 d n 3 , 1 x n 3 d n 3 , n 3 = l 3

when the determinants of exponent matrices are coprime to q 1 , where e i j , d i j Z + (the set of positive integers) , a i , c i F q * , 1 i , j m 2 , 1 i , j n 3 , and b 1 , b 2 , l 1 , l 2 , l 3 F q . These formulas extend the theorem obtained by Wang and Sun (An explicit formula of solution of some special equations over a finite field, Chinese Ann. Math. Ser. A 26 (2005), 391–396, https://www.cqvip.com/doc/journal/977048790. (in Chinese)). Our results also give a partial answer to an open problem of Hu et al. raised in (The number of rational points of a family of hypersurfaces over finite fields, J. Number Theory 156 (2015), 135–153, doi: https://doi.org/10.1016/j.jnt.2015.04.006).

MSC 2010: 11C20; 11A05; 15B36

1 Introduction

Let Z + denote the set of positive integers. Let F q be the finite field of characteristic p , and let F q * F q \ { 0 } be its multiplicative group. We denote S by the number of elements of the finite set S . For any m Z + , we define m { 1 , 2 , , m } . Let f i ( x 1 , , x n ) ( i m ) be a polynomial with n variables over F q and let V ( f 1 , , f m ) denote the algebraic variety defined by the simultaneous vanishing of f i ( x 1 , , x n ) ( i m ) . Let N ( V ) stand for the number of F q -rational points on the algebraic variety V ( f 1 , , f m ) in F q n . That is,

N ( V ) = { ( x 1 , , x n ) F q n : f i ( x 1 , , x n ) = 0 , i m } .

Particularly, we denote N ( f ) for N ( V ) if m = 1 . Determining the explicit value of N ( V ) is an important subject in finite fields. In general, it is difficult to present an explicit formula for N ( V ) . It is well known that there is an exact formula for the number N ( f ) when deg ( f ) 2 (see, for example, pp. 275–289 of [1]). Finding the formula for N ( V ) and relevant topics has attracted a lot of scholars in recent decades [224].

Sun [18] studied the number of rational points ( x 1 , , x n ) F q n on the following affine hypersurface

a 1 x 1 e 11 x n e 1 n + + a n x 1 e n 1 x n e n n b = 0

with e i j Z + , a i F q * , b F q , 1 i , j n by proving that if gcd ( det ( e i j ) , q 1 ) = 1 , then

N ( f ) = B ( n ) + q 1 q A ( n 1 ) if b = 0 , 1 q A ( n ) otherwise ,

where for any positive integers s , we have

(1.1) B ( s ) q s ( q 1 ) s

and

(1.2) A ( s ) ( q 1 ) s ( 1 ) s .

Zhu et al. [24] considered a special variety defined by two or three equations, which is taken from the one investigated by Sun [18]. Sun’s result [18] was extended by Wang and Sun [19] by presenting a formula for the number of rational points ( x 1 , , x n 2 ) F q n 2 on the affine hypersurface

a 1 x 1 d 11 x n 1 d 1 n 1 + + a n 1 x 1 d n 1 , 1 x n 1 d n 1 , n 1 + a n 1 + 1 x 1 d n 1 + 1,1 x n 2 d n 1 + 1 , n 2 + + a n 2 x 1 d n 2 , 1 x n 2 d n 2 , n 2 = b

with d i j Z + , a i F q * , 1 i , j n 2 . In 2015, Hu et al. [15] gave an uniform generalization to the results of [18] and [19]. In fact, they used the Smith normal form to present an explicit formula for N ( f ) of rational points ( x 1 , , x n t ) F q n t on the hypersurface defined by

f f ( x 1 , , x n t ) = j = 0 t 1 i = 1 r j + 1 r j a r j + i x 1 e r j + i , 1 x n j + 1 e r j + i , n j + 1 b ,

where the integers t > 0 , 0 = r 0 < r 1 < r 2 < < r t , 1 n 1 < n 2 < < n t , b F q , a i F q * , and e i j Z + , i r t , j n t . Zhu and Hong [23] followed the approach of [15] and gave an exact formula for the number of rational points on certain algebraic variety V = V ( f 1 , f 2 ) over F q as follows:

f 1 f 1 ( x 1 , , x n t ) = i = 1 r a i ( 1 ) x 1 e i 1 ( 1 ) x n e i n ( 1 ) b 1 , f 2 f 2 ( x 1 , , x n t ) = j = 0 t 1 i = 1 r j + 1 r j a r j + i ( 2 ) x 1 e r j + i , 1 ( 2 ) x n j + 1 e r j + i , n j + 1 ( 2 ) b 2 ,

where b i F q , i = 1 , 2, t Z + , 0 = n 0 < n 1 < n 2 < < n t , n k 1 < n n k for some 1 k t , 0 = r 0 < r 1 < r 2 < < r t , a i ( 1 ) , a i ( 2 ) F q * , i r , i r t , and the exponent of each variable is a positive integer.

Motivated by the works of [15,18,19,23], we consider the questions of counting F q -rational points of the variety V ( f 1 , f 2 ) determined by

(1.3) f 1 a 1 x 1 e 11 x m 1 e 1 m 1 + + a m 1 x 1 e m 1 , 1 x m 1 e m 1 , m 1 b 1 , f 2 a m 1 + 1 x 1 e m 1 + 1,1 x m 2 e m 1 + 1 , m 2 + + a m 2 x 1 e m 2 , 1 x m 2 e m 2 , m 2 b 2

and the variety V ( f 1 , f 2 , f 3 ) determined by

(1.4) f 1 c 1 x 1 d 11 x n 1 d 1 n 1 + + c n 1 x 1 d n 1 , 1 x n 1 d n 1 , n 1 l 1 , f 2 c n 1 + 1 x 1 d n 1 + 1,1 x n 2 d n 1 + 1 , n 2 + + c n 2 x 1 d n 2 , 1 x n 2 d n 2 , n 2 l 2 , f 3 c n 2 + 1 x 1 d n 2 + 1,1 x n 3 d n 2 + 1 , n 3 + + c n 3 x 1 d n 3 , 1 x n 3 d n 3 , n 3 l 3 ,

where e i j , d i j Z + , a i , c i F q * , 1 i , j m 2 , 1 i , j n 3 , and b 1 , b 2 , l 1 , l 2 , l 3 F q .

Let

(1.5) E = e 11 e 1 m 1 0 0 e m 1 , 1 e m 1 , m 1 0 0 e m 1 + 1,1 e m 1 + 1 , m 1 e m 1 + 1 , m 1 + 1 e m 1 + 1 , m 2 e m 2 , 1 e m 2 , m 1 e m 2 , m 1 + 1 e m 2 , m 2

with e i j ( 1 i , j m 2 ) being given as in (1.3), and let

(1.6) F = d 11 d 1 n 1 0 0 0 0 d n 1 , 1 d n 1 , n 1 0 0 0 0 d n 1 + 1,1 d n 1 + 1 , n 1 d n 1 + 1 , n 1 + 1 d n 1 + 1 , n 2 0 0 d n 2 , 1 d n 2 , n 1 d n 2 , n 1 + 1 d n 2 , n 2 0 0 d n 2 + 1,1 d n 2 + 1 , n 1 d n 2 + 1 , n 1 + 1 d n 2 + 1 , n 2 d n 2 + 1 , n 2 + 1 d n 2 + 1 , n 3 d n 3 , 1 d n 3 , n 1 d n 3 , n 1 + 1 d n 3 , n 2 d n 3 , n 2 + 1 d n 3 , n 3

with d i j ( 1 i , j n 3 ) being given as in (1.4).

The main results of this article can be stated as follows.

Theorem 1.1

Let V = V ( f 1 , f 2 ) be the variety determined by (1.3). If gcd ( q 1 , det ( E ) ) = 1 , then

(1.7) N ( V ) = q m 2 m 1 B ( m 1 ) + q 1 q A ( m 1 1 ) B ( m 2 m 1 ) + ( q 1 ) 2 q 2 A ( m 1 1 ) A ( m 2 m 1 1 ) , if b 1 = b 2 = 0 , A ( m 1 ) B ( m 2 m 1 ) q + q 1 q 2 A ( m 1 ) A ( m 2 m 1 1 ) , if b 1 0 , b 2 = 0 , q 1 q 2 A ( m 1 1 ) A ( m 2 m 1 ) , if b 1 = 0 , b 2 0 , A ( m 1 ) A ( m 2 m 1 ) q 2 , i f b 1 0 , b 2 0 .

Theorem 1.2

Let V = V ( f 1 , f 2 , f 3 ) be the variety determined by (1.4). If gcd ( q 1 , det ( F ) ) = 1 , then

(1.8) N ( V ) = q n 3 n 1 B ( n 1 ) + ( q 1 ) q n 3 n 2 1 A ( n 1 1 ) B ( n 2 n 1 ) + ( q 1 ) 2 q 2 A ( n 1 1 ) A ( n 2 n 1 1 ) × B ( n 3 n 2 ) + ( q 1 ) 3 q 3 A ( n 1 1 ) A ( n 2 n 1 1 ) A ( n 3 n 2 1 ) , i f l 1 = l 2 = l 3 = 0 , q n 3 n 2 1 A ( n 1 ) B ( n 2 n 1 ) + q 1 q 2 A ( n 1 ) A ( n 2 n 1 1 ) B ( n 3 n 2 ) + ( q 1 ) 2 q 3 A ( n 1 ) A ( n 2 n 1 1 ) A ( n 3 n 2 1 ) , i f l 1 0 , l 2 = l 3 = 0 , q 1 q 2 A ( n 1 1 ) A ( n 2 n 1 ) B ( n 3 n 2 ) + ( q 1 ) 2 q 3 A ( n 1 1 ) A ( n 2 n 1 ) A ( n 3 n 2 1 ) , i f l 1 = 0 , l 2 0 , l 3 = 0 , 1 q 2 A ( n 1 ) A ( n 2 n 1 ) B ( n 3 n 2 ) + q 1 q 3 A ( n 1 ) A ( n 2 n 1 ) A ( n 3 n 2 1 ) , i f l 1 0 , l 2 0 , l 3 = 0 , ( q 1 ) 2 q 3 A ( n 1 1 ) A ( n 2 n 1 1 ) A ( n 3 n 2 ) , i f l 1 = l 2 = 0 , l 3 0 , q 1 q 3 A ( n 1 1 ) A ( n 2 n 1 ) A ( n 3 n 2 ) , i f l 1 = 0 , l 2 0 , l 3 0 , q 1 q 3 A ( n 1 ) A ( n 2 n 1 1 ) A ( n 3 n 2 ) , i f l 1 0 , l 2 = 0 , l 3 0 , 1 q 3 A ( n 1 ) A ( n 2 n 1 ) A ( n 3 n 2 ) , i f l 1 0 , l 2 0 , l 3 0 .

This article is organized as follows. We present in Section 2 two preliminary lemmas that are needed in the proofs of our main results. Subsequently, we give the proof of Theorem 1.1 in Section 3. Section 4 is devoted to the proof of Theorem 1.2. In Section 5, we provide two examples to illustrate the validity of Theorems 1.1 and 1.2.

2 Auxiliary lemmas

In this section, we present two lemmas, which are needed in the proofs of our main results. We begin with a result due to Sun [18].

Lemma 2.1

[18] Let c 1 , , c k F q * and c F q . Let N ( c ) denote the number of rational points ( u 1 , , u k ) ( F q * ) k on the equation c 1 u 1 + + c k u k = c . Then

N ( c ) = q 1 q A ( k 1 ) i f c = 0 , 1 q A ( k ) o t h e r w i s e

with A ( k ) being defined as in (1.2).

We also need the following result due to Zhu and Hong [23].

Lemma 2.2

[23, Lemma 2.6] Let c i j F q * for all i m and j k i , and let c 1 , , c m F q . Let N ( c 1 , , c m ) denote the number of rational points

( u 11 , , u 1 k 1 , , u m 1 , , u m k m ) ( F q * ) k 1 + + k m

on the variety defined by the following system of equations:

c 11 u 11 + + c 1 k 1 u 1 k 1 = c 1 c m 1 u m 1 + + c m k m u m k m = c m .

Then

N ( c 1 , , c m ) = ( q 1 ) { 1 i m : c i = 0 } q m i = 1 c i = 0 m A ( k i 1 ) i = 1 c i 0 m A ( k i )

with A ( k i ) being defined as in (1.2).

3 Proof of Theorem 1.1

In this section, we present the proof of Theorem 1.1. Firstly, we introduce some definitions and notations, which will be used in proving Theorem 1.1.

Let

E 1 = e 11 e 12 e 1 m 1 e m 1 , 1 e m 1 , 2 e m 1 , m 1

with e i j ( 1 i , j m 1 ) being given as in (1.3). It is well known [25] that there are unimodular matrices U 1 , V 1 , U 2 , and V 2 such that

(3.1) U 1 E 1 V 1 = D 1 0 0 0

and

(3.2) U 2 E V 2 = D 2 0 0 0 ,

where E is given as in (1.5)

D 1 diag ( g 1 ( E 1 ) , , g v ( E 1 ) )

and

D 2 diag ( g 1 ( E ) , , g v ( E ) ) ,

with v and v being the ranks of the matrices E 1 and E , respectively. All elements

g 1 ( E 1 ) , , g v ( E 1 ) , g 1 ( E ) , , g v ( E ) Z + ( the set of positive integers )

satisfy that g i ( E 1 ) g i + 1 ( E 1 ) ( i v 1 ) and g i ( E ) g i + 1 ( E ) ( i v 1 ) . We say that the diagonal matrices D 1 0 0 0 in (3.1) and D 2 0 0 0 in (3.2) are the Smith normal form of the matrices E 1 and E and are abbreviated as SNF( E 1 ) and SNF( E ), respectively.

Set α F q * to be a primitive element of F q , for any β F q * , there is a unique integer γ [ 1 , q 1 ] such that β = α γ , where γ is called the index of β with regard to the primitive element α and denoted by ind α β γ .

Let M 1 denote the number of rational points ( u 1 , , u m 1 ) ( F q * ) m 1 on the affine hypersurface

(3.3) i = 1 m 1 a i u i = b 1

under the following additional condition:

(3.4) gcd ( q 1 , g j ( E 1 ) ) h j ( E 1 ) for j v ( q 1 ) h j ( E 1 ) for j m 1 \ v ,

where

( h 1 ( E 1 ) , , h m 1 ( E 1 ) ) T U 1 ( ind α ( u 1 ) , , ind α ( u m 1 ) ) T .

Let M 2 denote the number of rational points ( u 1 , , u m 2 ) ( F q * ) m 2 on the variety

(3.5) i = 1 m 1 a i u i = b 1 , i = m 1 + 1 m 2 a i u i = b 2

under the following additional condition:

(3.6) gcd ( q 1 , g j ( E ) ) h j ( E ) for j v ( q 1 ) h j ( E ) for j m 2 \ v ,

where

( h 1 ( E ) , , h m 2 ( E ) ) T U 2 ( ind α ( u 1 ) , , ind α ( u m 2 ) ) T .

Lemma 3.1

Let V = V ( f 1 , f 2 ) be the affine algebraic variety (1.3) and m 1 < m 2 . Then

(3.7) N ( V ) = q m 2 m 1 B ( m 1 ) + M 1 B ( m 2 m 1 ) A + M 2 C i f b 1 = b 2 = 0 , M 1 B ( m 2 m 1 ) A + M 2 C i f b 1 0 , b 2 = 0 , M 2 C i f b 2 0 ,

where B ( m 1 ) is given as in (1.1),

A = ( q 1 ) m 1 v j = 1 v gcd ( q 1 , g j ( E 1 ) ) a n d C = ( q 1 ) m 2 v j = 1 v gcd ( q 1 , g j ( E ) )

with v and v being the ranks of the matrices E 1 and E , respectively.

Proof

This follows immediately from [23, Theorem 1.2].□

Proof of Theorem 1.1

The condition gcd ( q 1 , det ( E ) ) = 1 means that det ( E ) 0 . Moreover, it is clear that det ( E 1 ) det ( E ) ; thus, det ( E 1 ) 0 . Hence, the ranks of the matrices E 1 and E are m 1 and m 2 , respectively. By taking determinants of both sides of (3.1) and (3.2), one can deduce that

det ( U 1 ) det ( E 1 ) det ( V 1 ) = g 1 ( E 1 ) g m 1 ( E 1 )

and

det ( U 2 ) det ( E ) det ( V 2 ) = g 1 ( E ) g m 2 ( E ) .

Since det ( U i ) = ± 1 and det ( V i ) = ± 1 for all i { 1 , 2 } , we have det ( E 1 ) = ± g 1 ( E 1 ) g m 1 ( E 1 ) and det ( E ) = ± g 1 ( E ) g m 2 ( E ) . The condition gcd ( q 1 , det ( E ) ) = 1 together with det ( E 1 ) det ( E ) implies that

gcd ( q 1 , g j ( E 1 ) ) = 1 for all j m 1 ,

and

gcd ( q 1 , g j ( E ) ) = 1 for all j m 2 .

So (3.4), and (3.6) hold. It follows from (3.7) that

(3.8) N ( V ) = q m 2 m 1 B ( m 1 ) + M 1 B ( m 2 m 1 ) + M 2 if b 1 = b 2 = 0 , M 1 B ( m 2 m 1 ) + M 2 if b 1 0 , b 2 = 0 , M 2 if b 2 0 .

From Lemmas 2.1 and 2.2, one derives that

(3.9) M 1 = ( u 1 , , u m 1 ) ( F q * ) m 1 such that (3.3) holds 1 = q 1 q A ( m 1 1 ) if b 1 = 0 , 1 q A ( m 1 ) if b 1 0 ,

and

(3.10) M 2 = ( u 1 , , u m 2 ) ( F q * ) m 2 such that (3.5) holds 1 = ( q 1 ) 2 q 2 A ( m 1 1 ) A ( m 2 m 1 1 ) if b 1 = b 2 = 0 , q 1 q 2 A ( m 1 ) A ( m 2 m 1 1 ) if b 1 0 , b 2 = 0 , q 1 q 2 A ( m 1 1 ) A ( m 2 m 1 ) if b 1 = 0 , b 2 0 , 1 q 2 A ( m 1 ) A ( m 2 m 1 ) if b 1 0 , b 2 0 .

Putting (3.9) and (3.10) into (3.8) yields (1.7) as expected. This concludes the proof of Theorem 1.1.□

4 Proof of Theorem 1.2

Let h i j , b i ( 1 i z , 1 j a ) and b be integers. For the vectors Y = ( y 1 , , y a ) T and B = ( b 1 , , b z ) T , and the z × a matrix H = ( h i j ) , we can form system of congruences as follows:

(4.1) H Y B ( mod b ) .

From [25], we can find unimodular matrices U of order z and V of order a such that

U H V = SNF ( H ) = D 0 0 0 ,

where D diag ( d 1 , , d r ) with all diagonal elements d i being positive integers and satisfying that d i d i + 1 ( 1 i < r ) . The following result is known.

Lemma 4.1

[15, Lemma 2.3] Let B = ( b 1 , , b z ) T = U B . Then the system (4.1)  of linear congruences is solvable if and only if gcd ( b , d i ) b i for all i r and b b i for all integers i with r + 1 i z . Besides, the number of solutions of (4.1) is equal to b a r i = 1 r gcd ( b , d i ) .

To state Lemma 4.2, we first introduce several relevant concepts and notations as follows. Let

F 1 = d 11 d 12 d 1 n 1 d n 1 , 1 d n 1 , 2 d n 1 , n 1

and

F 2 = d 11 d 1 n 1 0 0 d n 1 , 1 d n 1 , n 1 0 0 d n 1 + 1,1 d n 1 + 1 , n 1 d n 1 + 1 , n 1 + 1 d n 1 + 1 , n 2 d n 2 , 1 d n 2 , n 1 d n 2 , n 1 + 1 d n 2 , n 2

with d i j ( 1 i , j n 3 ) being given as in (1.4). By [25], we know that there are unimodular matrices M 1 , W 1 , M 2 , W 2 , M 3 , and W 3 such that

(4.2) M 1 F 1 W 1 = G 1 0 0 0 ,

(4.3) M 2 F 2 W 2 = G 2 0 0 0 ,

and

(4.4) M 3 F W 3 = G 3 0 0 0 ,

where F is given as in (1.6),

G 1 diag ( g 1 ( F 1 ) , , g u ( F 1 ) ) , G 2 diag ( g 1 ( F 2 ) , , g u ( F 2 ) ) ,

and

G 3 diag ( g 1 ( ) , , g u ( F ) )

with u , u and u being the ranks of the matrices F 1 , F 2 , and F , respectively. All elements

g 1 ( F 1 ) , , g u ( F 1 ) , g 1 ( F 2 ) , , g u ( F 2 ) , g 1 ( F ) , , g u ( F )

are positive integers and

g i ( F 1 ) g i + 1 ( F 1 ) ( i u 1 ) , g i ( F 2 ) g i + 1 ( F 2 ) ( i u 1 ) , g i ( F ) g i + 1 ( F ) ( i u 1 ) .

Let N 1 denote the number of rational points ( v 1 , , v n 1 ) ( F q * ) n 1 on the affine hypersurface

(4.5) i = 1 n 1 c i v i = l 1

under the following extra condition:

(4.6) gcd ( q 1 , g j ( F 1 ) ) h j ( F 1 ) for j u ( q 1 ) h j ( F 1 ) for j n 1 \ u ,

where

( h 1 ( F 1 ) , , h n 1 ( F 1 ) ) T M 1 ( ind α ( v 1 ) , , ind α ( v n 1 ) ) T .

Let N 2 denote the number of rational points ( v 1 , , v n 2 ) ( F q * ) n 2 on the variety

(4.7) i = 1 n 1 c i v i = l 1 , i = n 1 + 1 n 2 c i v i = l 2

under the following extra condition:

(4.8) gcd ( q 1 , g j ( F 2 ) ) h j ( F 2 ) for j u ( q 1 ) h j ( F 2 ) for j n 2 \ u ,

where

( h 1 ( F 2 ) , , h n 2 ( F 2 ) ) T M 2 ( ind α ( v 1 ) , , ind α ( v n 2 ) ) T .

Let N 3 denote the number of rational points ( v 1 , , v n 3 ) ( F q * ) n 3 on the variety

(4.9) i = 1 n 1 c i v i = l 1 , i = n 1 + 1 n 2 c i v i = l 2 , i = n 2 + 1 n 3 c i v i = l 3

under the following extra condition:

(4.10) gcd ( q 1 , g j ( F ) ) h j ( F ) for j u , ( q 1 ) h j ( F ) for j n 3 \ u ,

where

( h 1 ( F ) , , h n 3 ( F ) ) T M 3 ( ind α ( v 1 ) , , ind α ( v n 3 ) ) T .

We have the following result.

Lemma 4.2

Let n 1 < n 2 < n 3 . Then

(4.11) ( v 1 , , v n 1 ) ( F q * ) n 1 ( 4.5 ) h o l d s { ( x 1 , , x n 1 ) ( F q * ) n 1 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 } = N 1 ( q 1 ) n 1 u i = 1 u gcd ( q 1 , g i ( F 1 ) ) ,

(4.12) ( v 1 , , v n 2 ) ( F q * ) n 2 ( 4.7 ) h o l d s ( x 1 , , x n 2 ) ( F q * ) n 2 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 = N 2 ( q 1 ) n 2 u i = 1 u gcd ( q 1 , g i ( F 2 ) )

and

(4.13) ( v 1 , , v n 3 ) ( F q * ) n 3 ( 4.9 ) h o l d s ( x 1 , , x n 3 ) ( F q * ) n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 = N 3 ( q 1 ) n 3 u i = 1 u gcd ( q 1 , g i ( F ) ) .

Proof

For any given ( v 1 , , v n 1 ) ( F q * ) n 1 satisfying (4.5), one has the system of congruences:

(4.14) j = 1 n 1 d i j ind α ( x i ) ind α ( v i ) ( mod q 1 ) , i n 1 ,

then

{ ( x 1 , , x n 1 ) ( F q * ) n 1 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 } = { ( x 1 , , x n 1 ) ( F q * ) n 1 : α j = 1 n 1 d i j ind α ( x i ) = α ind α ( v i ) , i n 1 } = { ( x 1 , , x n 1 ) ( F q * ) n 1 : (4.14) holds } .

From Lemma 4.1, we know that (4.14) is solvable if and only if (4.6) holds. Further, Lemma 4.1 tells us that if (4.14) has a solution, then the number of n 1 -tuples ( ind α ( x 1 ) , , ind α ( x n 1 ) ) q 1 n 1 satisfying (4.14) equals

( q 1 ) n 1 u i = 1 u gcd ( q 1 , g i ( F 1 ) ) .

In other words, if (4.6) holds, then

{ ( x 1 , , x n 1 ) ( F q * ) n 1 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 } = ( q 1 ) n 1 u i = 1 u gcd ( q 1 , g i ( F 1 ) ) .

So the left-hand side of (4.11) is equal to

(4.15) ( q 1 ) n 1 u i = 1 u gcd ( q 1 , g i ( F 1 ) ) × ( v 1 , , v n 1 ) ( F q * ) n 1 ( 4.5 ) and ( 4.6 ) hold 1

Notice that

(4.16) N 1 = ( v 1 , , v n 1 ) ( F q * ) n 1 such that (4.5) and (4.6) hold 1 .

Thus, (4.15) and (4.16) yield (4.11).

Similarly, we can show that (4.12) and (4.13) hold. Lemma 4.2 is proved.□

Associated to l 1 , l 2 , and l 3 , we define the set T ( l 1 , l 2 , l 3 ) of F q -rational points as follows:

(4.17) T ( l 1 , l 2 , l 3 ) { ( v 1 , , v n 3 ) ( F q ) n 3 : (4.9) holds } .

Let T ( 0 ) be the empty set when l 1 , l 2 , and l 3 are not all zero, and let T ( 0 ) denote the set consisting of the zero vector of dimension n 3 when l 1 = l 2 = l 3 = 0 . For any integer 1 n n 3 , let T ( n ) denote the subset of T ( l 1 , l 2 , l 3 ) in which the vector holds exactly n nonzero components.

Lemma 4.3

Let n 1 < n 2 < n 3 . Then each of the following assertions is true:

  1. T ( n ) is the subset of T ( l 1 , l 2 , l 3 ) in which the vector holds exactly the first n nonzero components.

  2. For any integer n with 0 < n < n 1 or n 1 < n < n 2 or n 2 < n < n 3 , T ( n ) = .

  3. T ( l 1 , l 2 , l 3 ) = T ( 0 ) T ( n 1 ) T ( n 2 ) T ( n 3 ) .

Proof

(i) First, recall that

v i = x 1 d i 1 x n 1 d i n 1 for i n 1 , v i = x 1 d i 1 x n 2 d i n 2 for i n 2 \ n 1 , v i = x 1 d i 1 x n 3 d i n 3 for i n 3 \ n 2 .

Because the set of x i variables appearing in v i for 1 i n 1 is contained in the set of the x i variables appearing in v j when j i , and the set of x i variables appearing in v i for n 1 + 1 i n 2 is also contained in the set of the x i variables appearing in v j when j i , it follows that if v i = 0 for any integer i with 1 i n 1 , then v j = 0 when j i . If v i = 0 for any integer i with n 1 + 1 i n 2 , then v j = 0 when j i . Part (i) is proved.

(ii) Since v 1 , , v n 1 are simultaneously zero or simultaneously nonzero, and v n 1 + 1 , , v n 2 are simultaneously zero or simultaneously nonzero, and v n 2 + 1 , , v n 3 are simultaneously zero or simultaneously nonzero, part (ii) follows immediately.

(iii) By parts (i) and (ii), we obtain the following disjoint unions:

T ( l 1 , l 2 , l 3 ) = n = 0 n 3 T ( n ) = T ( 0 ) T ( n 1 ) T ( n 2 ) T ( n 3 )

as desired.□

Lemma 4.4

Each of the following assertions is true:

  1. If l 2 0 or l 3 0 , then T ( n 1 ) = .

  2. If l 3 0 , then T ( n 2 ) = .

Proof

(i) Assume that T ( n 1 ) . Then by Lemma 4.3 (i), we have

v 1 0 , , v n 1 0 and v n 1 + 1 = = v n 3 = 0 .

Hence, l 2 = l 3 = 0 . This is impossible. Part (i) is proved.

(ii) Suppose that T ( n 2 ) . Then from Lemma 4.3 (i), we know that

v 1 0 , , v n 2 0 and v n 2 + 1 = = v n 3 = 0 .

This contradicts l 3 0 . Part (ii) is proved.□

Subsequently, we can prove the following important lemma of this section.

Lemma 4.5

Let V = V ( f 1 , f 2 , f 3 ) be the affine algebraic variety (1.4). Then

(4.18) N ( V ) = q n 3 n 1 B ( n 1 ) + q n 3 n 2 B ( n 2 n 1 ) N 1 K + B ( n 3 n 2 ) N 2 L + N 3 E i f l 1 = l 2 = l 3 = 0 , q n 3 n 2 B ( n 2 n 1 ) N 1 K + B ( n 3 n 2 ) N 2 L + N 3 E i f l 1 0 , l 2 = l 3 = 0 , B ( n 3 n 2 ) N 2 L + N 3 E i f l 2 0 , l 3 = 0 , N 3 E i f l 3 0 ,

where

K = ( q 1 ) n 1 u i = 1 u gcd ( q 1 , g i ( F 1 ) ) , L = ( q 1 ) n 2 u i = 1 u gcd ( q 1 , g i ( F 2 ) ) ,

E = ( q 1 ) n 3 u i = 1 u gcd ( q 1 , g i ( F ) )

with u , u , and u being the ranks of the matrices F 1 , F 2 , and F , respectively.

Proof

Obviously, we have

(4.19) N ( V ) = ( v 1 , , v n 3 ) F q n 3 (4.9) holds ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 .

It follows from (4.17), (4.19), and Lemma 4.3 (iii) that

(4.20) N ( V ) = ( v 1 , , v n 3 ) T ( l 1 , l 2 , l 3 ) ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 = ( v 1 , , v n 3 ) T ( 0 ) T ( n 1 ) T ( n 2 ) T ( n 3 ) ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 .

Applying (4.11), we compute and obtain that

(4.21) ( v 1 , , v n 3 ) T ( n 1 ) ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 = ( v 1 , , v n 3 ) F q n 3 (4.5) holds , v 1 0 , , v n 1 0 v n 1 + 1 = = v n 3 = 0 ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 = ( v 1 , , v n 1 ) ( F q * ) n 1 (4.5) holds ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x n 1 + 1 x n 2 = 0 = q n 3 n 2 × { ( x n 1 + 1 , , x n 2 ) F q n 2 n 1 : x n 1 + 1 x n 2 = 0 } × ( v 1 , , v n 1 ) ( F q * ) n 1 (4.5) holds { ( x 1 , , x n 1 ) ( F q * ) n 1 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 } = q n 3 n 2 ( q n 2 n 1 ( q 1 ) n 2 n 1 ) N 1 ( q 1 ) n 1 u i = 1 u gcd ( q 1 , g i ( F 1 ) ) .

From (4.12), we can calculate and obtain

(4.22) ( v 1 , , v n 3 ) T ( n 2 ) ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 = ( v 1 , , v n 3 ) F q n 3 (4.7) holds , v 1 0 , , v n 2 0 v n 2 + 1 = = v n 3 = 0 ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 = ( v 1 , , v n 2 ) ( F q * ) n 2 (4.7) holds ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 , x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x n 2 + 1 x n 3 = 0 = { ( x n 2 + 1 , , x n 3 ) F q n 3 n 2 : x n 2 + 1 x n 3 = 0 } × ( v 1 , , v n 2 ) ( F q * ) n 2 (4.7) holds ( x 1 , , x n 2 ) ( F q * ) n 2 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 , x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 = ( q n 3 n 2 ( q 1 ) n 3 n 2 ) N 2 ( q 1 ) n 2 u i = 1 u gcd ( q 1 , g i ( F 2 ) ) .

From (4.13), one computes and gains that

(4.23) ( v 1 , , v n 3 ) T ( n 3 ) ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 = ( v 1 , , v n 3 ) F q n 3 (4.9) holds v 1 0 , , v n 3 0 ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 = ( v 1 , , v n 3 ) ( F q * ) n 3 (4.9) holds ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 = ( v 1 , , v n 3 ) ( F q * ) n 3 (4.9) holds ( x 1 , , x n 3 ) ( F q * ) n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 = N 3 ( q 1 ) n 3 u i = 1 u gcd ( q 1 , g i ( F ) ) .

On the other hand, we can calculate and obtain

(4.24) ( v 1 , , v n 3 ) T ( 0 ) ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 = { ( x 1 , , x n 3 ) F q n 3 : x 1 x n 1 = 0 } = q n 3 n 1 × { ( x 1 , , x n 1 ) F q n 1 : x 1 x n 1 = 0 } = q n 3 n 1 × ( q n 1 ( q 1 ) n 1 ) .

If l 1 = l 2 = l 3 = 0 , then using (4.20) to (4.24), we deduce that

N ( V ) = ( v 1 , , v n 3 ) T ( 0 ) T ( n 1 ) T ( n 2 ) T ( n 3 ) ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 = ( v 1 , , v n 3 ) T ( 0 ) ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 + ( v 1 , , v n 3 ) T ( n 1 ) ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 + ( v 1 , , v n 3 ) T ( n 2 ) ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 + ( v 1 , , v n 3 ) T ( n 3 ) ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 = q n 3 n 1 × ( q n 1 ( q 1 ) n 1 ) + q n 3 n 2 ( q n 2 n 1 ( q 1 ) n 2 n 1 ) N 1 K + ( q n 3 n 2 ( q 1 ) n 3 n 2 ) N 2 L + N 3 E ,

with K , L , and E being defined as in (4.18).

We conclude that if l 1 0 , l 2 = l 3 = 0 , then T ( 0 ) = . By (4.20) to (4.23), we have

N ( V ) = ( v 1 , , v n 3 ) T ( n 1 ) T ( n 2 ) T ( n 3 ) ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 = q n 3 n 2 ( q n 2 n 1 ( q 1 ) n 2 n 1 ) N 1 K + ( q n 3 n 2 ( q 1 ) n 3 n 2 ) N 2 L + N 3 E

with K , L , and E being defined as in (4.18).

If l 2 0 , l 3 = 0 , then T ( 0 ) = . Meanwhile, Lemma 4.4 (i) ensures that T ( n 1 ) = . Substituting (4.22) and (4.23) into (4.20) tells us that

N ( V ) = ( v 1 , , v n 3 ) T ( n 2 ) T ( n 3 ) ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 = ( q n 3 n 2 ( q 1 ) n 3 n 2 ) N 2 L + N 3 E

as required, where L and E are given as in (4.18).

If l 3 0 , then T ( 0 ) = . Further, from Lemma 4.4, one has T ( n 1 ) = T ( n 2 ) = . By (4.20) and (4.23), we have

N ( V ) = ( v 1 , , v n 3 ) T ( n 3 ) ( x 1 , , x n 3 ) F q n 3 : x 1 d i 1 x n 1 d i n 1 = v i , i n 1 x 1 d i 1 x n 2 d i n 2 = v i , i n 2 \ n 1 x 1 d i 1 x n 3 d i n 3 = v i , i n 3 \ n 2 = N 3 ( q 1 ) n 3 u i = 1 u gcd ( q 1 , g i ( F ) ) .

as expected.

This concludes the proof of Lemma 4.5.□

Proof of Theorem 1.2

Taking determinants of both sides of (4.2) to (4.4), one can deduce that

det ( M i ) det ( F i ) det ( W i ) = g 1 ( F i ) g n i ( F i ) for all i { 1 , 2 }

and

det ( M 3 ) det ( F ) det ( W 3 ) = g 1 ( F ) g n 3 ( F ) .

Since

det ( M i ) = ± 1 , det ( W i ) = ± 1 for all i { 1 , 2 , 3 }

and det ( F 1 ) det ( F 2 ) det ( F ) , the condition gcd ( q 1 , det ( F ) ) = 1 guarantees that

gcd ( q 1 , g j ( F 1 ) ) = 1 for all j n 1 , gcd ( q 1 , g j ( F 2 ) ) = 1 for all j n 2 ,

and

gcd ( q 1 , g j ( F ) ) = 1 for all j n 3 .

So (4.6), (4.8), and (4.10) are all satisfied. It follows from Lemma 4.5 that

N ( V ) = q n 3 n 1 B ( n 1 ) + q n 3 n 2 B ( n 2 n 1 ) N 1 + B ( n 3 n 2 ) N 2 + N 3 if l 1 = l 2 = l 3 = 0 , q n 3 n 2 B ( n 2 n 1 ) N 1 + B ( n 3 n 2 ) N 2 + N 3 if l 1 0 , l 2 = l 3 = 0 , B ( n 3 n 2 ) N 2 + N 3 if l 2 0 , l 3 = 0 , N 3 if l 3 0 .

From Lemmas 2.1 and 2.2, one derives that

(4.25) N 1 = ( v 1 , , v n 1 ) ( F q * ) n 1 (4.5) holds 1 = q 1 q A ( n 1 1 ) if l 1 = 0 , 1 q A ( n 1 ) if l 1 0 ,

(4.26) N 2 = ( v 1 , , v n 2 ) ( F q * ) n 2 (4.7) holds 1 = ( q 1 ) 2 q 2 A ( n 1 1 ) A ( n 2 n 1 1 ) if l 1 = l 2 = 0 , q 1 q 2 A ( n 1 ) A ( n 2 n 1 1 ) if l 1 0 , l 2 = 0 , q 1 q 2 A ( n 1 1 ) A ( n 2 n 1 ) if l 1 = 0 , l 2 0 , 1 q 2 A ( n 1 ) A ( n 2 n 1 ) if l 1 0 , l 2 0 ,

and

(4.27) N 3 = ( v 1 , , v n 3 ) ( F q * ) n 3 such that (4.9) holds 1 = ( q 1 ) 3 q 3 A ( n 1 1 ) A ( n 2 n 1 1 ) A ( n 3 n 2 1 ) if l 1 = l 2 = l 3 = 0 , ( q 1 ) 2 q 3 A ( n 1 ) A ( n 2 n 1 1 ) A ( n 3 n 2 1 ) if l 1 0 , l 2 = l 3 = 0 , ( q 1 ) 2 q 3 A ( n 2 n 1 ) A ( n 1 1 ) A ( n 3 n 2 1 ) if l 1 = 0 , l 2 0 , l 3 = 0 , q 1 q 3 A ( n 1 ) A ( n 2 n 1 ) A ( n 3 n 2 1 ) if l 1 0 , l 2 0 , l 3 = 0 , ( q 1 ) 2 q 3 A ( n 1 1 ) A ( n 2 n 1 1 ) A ( n 3 n 2 ) if l 1 = l 2 = 0 , l 3 0 , q 1 q 3 A ( n 1 1 ) A ( n 2 n 1 ) A ( n 3 n 2 ) if l 1 = 0 , l 2 0 , l 3 0 , q 1 q 3 A ( n 1 ) A ( n 2 n 1 1 ) A ( n 3 n 2 ) if l 1 0 , l 2 = 0 , l 3 0 , 1 q 3 A ( n 1 ) A ( n 2 n 1 ) A ( n 3 n 2 ) if l 1 0 , l 2 0 , l 3 0 .

Hence, by (4.25) to (4.27), the identity (1.8) follows immediately. This completes the proof of Theorem 1.2.□

5 Examples

In this section, we supply two examples to demonstrate the validity of Theorems 1.1 and 1.2.

Example 5.1

We use Theorem 1.1 to compute the number N ( V ) of rational points on the following variety over F 7 :

f 1 ( x 1 , , x 5 ) = x 1 x 2 x 3 + x 1 x 2 2 x 3 3 + x 1 2 x 2 2 x 3 2 , f 2 ( x 1 , , x 5 ) = x 1 3 x 2 x 3 2 x 4 3 x 5 + x 1 2 x 2 3 x 3 4 x 4 x 5 2 .

Clearly, we have b 1 = 2 , b 2 = 0 , q = 7 , q 1 = 6 , m 1 = 3 , m 2 = 5 , and

E = 1 1 1 0 0 1 2 3 0 0 2 2 1 0 0 3 1 2 3 1 2 3 4 1 2 .

Since det ( E ) = 5 , one derives that gcd ( q 1 , det ( E ) ) = 1 . By Theorem 1.1, we can calculate and obtain that

N ( V ) = 6 3 ( 1 ) 3 7 ( 7 2 6 2 ) + 6 3 ( 1 ) 3 7 6 2 + ( 1 ) 2 × 6 7 = 589 .

Example 5.2

We use Theorem 1.2 to compute the number N ( V ) of rational points on the variety over F 17 determined by

f 1 ( x 1 , , x 7 ) = x 1 x 2 2 x 3 3 x 4 4 x 5 5 + x 1 2 x 2 5 x 3 4 x 4 5 x 5 3 + x 1 3 x 2 4 x 3 2 x 4 3 x 5 2 + x 1 2 x 2 3 x 3 5 x 4 2 x 5 + x 1 2 x 2 6 x 3 3 x 4 2 x 5 2 1 , f 2 ( x 1 , , x 7 ) = x 1 2 x 2 2 x 3 3 x 4 3 x 5 5 x 6 3 + x 1 2 x 2 2 x 3 4 x 4 5 x 5 3 x 6 5 x 7 3 2 , f 2 ( x 1 , , x 7 ) = x 1 2 x 2 2 x 3 4 x 4 5 x 5 3 x 6 5 x 7 3 x 8 3 .

Clearly, we have l 1 = 1 , l 2 = 2 , l 3 = 3 , q = 17 , q 1 = 16 , n 1 = 5 , n 2 = 7 , n 3 = 8 , and

F = 1 2 3 4 5 0 0 0 2 5 4 5 3 0 0 0 3 4 2 3 2 0 0 0 2 3 5 2 1 0 0 0 2 6 3 2 2 0 0 0 2 2 3 3 5 3 0 0 2 2 4 5 3 5 3 0 2 2 4 5 3 5 3 1 .

Since det ( F ) = 2889 , we deduce that gcd ( q 1 , det ( F ) ) = 1 . By Theorem 1.2, we can calculate and obtain

N ( V ) = 1 1 7 3 ( ( 17 1 ) 5 ( 1 ) 5 ) ( ( 17 1 ) 2 ( 1 ) 2 ) ( ( 17 1 ) ( 1 ) ) = 925215 .

Acknowledgments

The authors would like to thank Prof. Shaofang Hong for suggesting the problem studied in this article and for his helpful comments on this article. The authors are grateful for the reviewers’ valuable comments that improved the manuscript.

  1. Funding information: Y. Y. Luo was supported partially by National Science Foundation of China (Grant No. 12161012), and also supported in part by The Scientific Research Foundation for the Introduction of Talent in GUFE (No. 2018YJ85).

  2. Author contributions: All authors have accepted responsibility for the entire content of this manuscript and consented to its submission to the journal, reviewed all the results and approved the final version of the manuscript. GZ and ZL conceptualized the study design and developed the theoretical framework. YF and YL performed the formal analysis and computational work. GZ drafted the manuscript with critical input from all co-authors.

  3. Conflict of interest: The authors state no conflict of interest.

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Received: 2024-09-21
Revised: 2024-12-14
Accepted: 2025-03-31
Published Online: 2025-05-29

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  32. On the spectral radius and energy of the degree distance matrix of a connected graph
  33. Solving the quartic by conics
  34. A topology related to implication and upsets on a bounded BCK-algebra
  35. On a subclass of multivalent functions defined by generalized multiplier transformation
  36. Local minimizers for the NLS equation with localized nonlinearity on noncompact metric graphs
  37. Approximate multi-Cauchy mappings on certain groupoids
  38. Multiple solutions for a class of fourth-order elliptic equations with critical growth
  39. A note on weighted measure-theoretic pressure
  40. Majorization-type inequalities for (m, M, ψ)-convex functions with applications
  41. Recurrence for probabilistic extension of Dowling polynomials
  42. Unraveling chaos: A topological analysis of simplicial homology groups and their foldings
  43. Global existence and blow-up of solutions to pseudo-parabolic equation for Baouendi-Grushin operator
  44. A characterization of the translational hull of a weakly type B semigroup with E-properties
  45. Some new bounds on resolvent energy of a graph
  46. Carmichael numbers composed of Piatetski-Shapiro primes in Beatty sequences
  47. The number of rational points of some classes of algebraic varieties over finite fields
  48. Singular direction of meromorphic functions with finite logarithmic order
  49. Pullback attractors for a class of second-order delay evolution equations with dispersive and dissipative terms on unbounded domain
  50. Eigenfunctions on an infinite Schrödinger network
  51. Boundedness of fractional sublinear operators on weighted grand Herz-Morrey spaces with variable exponents
  52. On SI2-convergence in T0-spaces
  53. Bubbles clustered inside for almost-critical problems
  54. Classification and irreducibility of a class of integer polynomials
  55. Existence and multiplicity of positive solutions for multiparameter periodic systems
  56. Averaging method in optimal control problems for integro-differential equations
  57. On superstability of derivations in Banach algebras
  58. Investigating the modified UO-iteration process in Banach spaces by a digraph
  59. The evaluation of a definite integral by the method of brackets illustrating its flexibility
  60. Existence of positive periodic solutions for evolution equations with delay in ordered Banach spaces
  61. Tilings, sub-tilings, and spectral sets on p-adic space
  62. The higher mapping cone axiom
  63. Continuity and essential norm of operators defined by infinite tridiagonal matrices in weighted Orlicz and l spaces
  64. A family of commuting contraction semigroups on l 1 ( N ) and l ( N )
  65. Pullback attractor of the 2D non-autonomous magneto-micropolar fluid equations
  66. Maximal function and generalized fractional integral operators on the weighted Orlicz-Lorentz-Morrey spaces
  67. On a nonlinear boundary value problems with impulse action
  68. Normalized ground-states for the Sobolev critical Kirchhoff equation with at least mass critical growth
  69. Decompositions of the extended Selberg class functions
  70. Subharmonic functions and associated measures in ℝn
  71. Some new Fejér type inequalities for (h, g; α - m)-convex functions
  72. The robust isolated calmness of spectral norm regularized convex matrix optimization problems
  73. Multiple positive solutions to a p-Kirchhoff equation with logarithmic terms and concave terms
  74. Joint approximation of analytic functions by the shifts of Hurwitz zeta-functions in short intervals
  75. Green's graphs of a semigroup
  76. Some new Hermite-Hadamard type inequalities for product of strongly h-convex functions on ellipsoids and balls
  77. Infinitely many solutions for a class of Kirchhoff-type equations
  78. On an uncertainty principle for small index subgroups of finite fields
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