Home On a weighted elliptic equation of N-Kirchhoff type with double exponential growth
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On a weighted elliptic equation of N-Kirchhoff type with double exponential growth

  • Imed Abid EMAIL logo , Sami Baraket and Rached Jaidane
Published/Copyright: October 5, 2022
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Abstract

In this work, we study the weighted Kirchhoff problem

g B σ ( x ) u N d x div ( σ ( x ) u N 2 u ) = f ( x , u ) in B , u > 0 in B , u = 0 on B ,

where B is the unit ball of R N , σ ( x ) = log e x N 1 , the singular logarithm weight in the Trudinger-Moser embedding, and g is a continuous positive function on R + . The nonlinearity is critical or subcritical growth in view of Trudinger-Moser inequalities. We first obtain the existence of a solution in the subcritical exponential growth case with positive energy by using minimax techniques combined with the Trudinger-Moser inequality. In the critical case, the associated energy does not satisfy the condition of compactness. We provide a new condition for growth, and we stress its importance to check the compactness level.

MSC 2010: 35J20; 35J25; 35J60

1 Introduction

In this article, we consider the following non-local weighted problem:

(1) L ( N , σ , g ) = g B σ ( x ) u N d x div ( σ ( x ) u N 2 u ) = f ( x , u ) in B u > 0 in B u = 0 on B ,

where B = B ( 0 , 1 ) is the unit open ball in R N , f ( x , t ) is a radial function with respect to x , and the weight σ ( x ) is given by

(2) σ ( x ) = log e x N 1

and g : R + R + is a positive continuous function which will be specified later.

In 1883, Kirchhoff studied the following parabolic problem:

(3) ρ 2 u t 2 P 0 h + E 2 L 0 L u x 2 d x 2 u x 2 = 0 ,

for free vibrations of elastic strings. The parameters in equation (3) have the following meanings: L is the length of the string, h is the area of cross-section, E is the Young’s modulus of the material, ρ is the mass density, and P 0 is the initial tension.

These kinds of problems have physical motivations. Indeed, the Kirchhoff operator G B u 2 d x Δ u also appears in the nonlinear vibration equation, namely,

(4) 2 u t 2 G B u 2 d x div ( u ) = f ( x , u ) in B × ( 0 , T ) u > 0 in B × ( 0 , T ) u = 0 on B u ( x , 0 ) = u 0 ( x ) in B u t ( x , 0 ) = u 1 ( x ) in B

which have received the attention of several researchers, mainly as a result of the work of Lions [1]. We mention that non-local problems also arise in other areas, e.g., biological systems where the function u describes a process that depends on the average of itself (e.g., population density), see, e.g., [2,3] and references therein.

In the non-weighted case, i.e., when σ ( x ) 1 and when N = 2 , problem (1) can be seen as a stationary version of the evolution problem (4).

Recently, Xiu et al. [4] studied the following singular nonlocal elliptic problem:

M R N x a p u p div ( x a p u p 2 u ) = h ( x ) u r 2 u + H ( x ) u q 2 u , u ( x ) 0 as x + ,

where x R N , M ( t ) = b ¯ + a ¯ t , a ¯ , b ¯ > 0 , a < N p p , h ( x ) and H ( x ) are nonnegative function . They proved that this problem has infinitely many solutions by variational methods and the genus theorem.

In order to motivate our study, we begin by giving a brief survey on Trudinger-Moser inequalities. In the past few decades, Moser gives the famous result about the Trudinger-Moser inequality [5,6]; many applications take place as in conformal deformation theory on manifolds, the study of the prescribed Gauss curvature and mean field equations. After that, a logarithmic Trudinger-Moser inequality was used in a crucial way in [7] to study the Liouville equation of the form

(5) Δ u = λ e u Ω e u in Ω u = 0 on Ω ,

where Ω is an open domain of R N , N 2 , and λ a positive parameter. Equation (5) has a long history and has been derived in the study of multiple condensate solution in the Chern-Simons-Higgs theory [8,9] and also it appeared in the study of Euler flow [10,11, 12,13].

Later, the Trudinger-Moser inequality was improved to weighted inequalities [14,15]. The influence of the weight in the Sobolev norm was studied as the compact embedding [16,17].

When the weight is of logarithmic type, Calanchi and Ruf [18] extended the Trudinger-Moser inequality and gave some applications when N = 2 and for prescribed nonlinearities. After that, Calanchi et al. [19] considered more general nonlinearities and proved the existence of radial solutions.

We point out that recently, in the case g ( t ) = 1 , Deng et al. [20] have proved the existence of a nontrivial solution for the following boundary value problem:

div ( w ( x ) u ( x ) N 2 u ( x ) ) = f ( x , u ) in B u = 0 on B ,

where B is the unit ball in R N , N 2 , the radial positive weight w ( x ) is of logarithmic type, the function f ( x , u ) is continuous in B × R and has critical double exponential growth.

Also recently, de Figueiredo and Severo [21] studied the following problem:

m B u 2 d x div ( u ) = f ( x , u ) in Ω u > 0 in Ω u = 0 on Ω ,

where Ω is a smooth-bounded domain in R 2 , the nonlinearity f behaves like exp ( α t 2 ) as t + , for some α > 0 . The authors proved that this problem has a positive ground state solution. The existence result was proved by combining minimax techniques and Trudinger-Moser inequalities.

Inspired by the last two works, we investigate our problem by adapting weighted Sobolev space setting. We use the Trudinger-Moser inequality to study and prove the existence of solutions of (1).

Let Ω R N be a bounded domain and σ L 1 ( Ω ) be a nonnegative function. We define the weighted Sobolev space as follows:

W 0 1 , N ( Ω , σ ) = closure u C 0 ( Ω ) B u N σ ( x ) d x < ,

we will limit our attention to radial functions and then consider the subspace,

W W 0 , rad 1 , N ( B , σ ) = closure u C 0 , rad ( B ) B u N σ ( x ) d x < ,

equipped with the norm

u = B u N σ ( x ) d x 1 N .

The choice of the weight and the space W = W 0 , rad 1 , N ( B , σ ) are motivated by the following exponential inequalities.

Theorem 1.1

[15] Let σ be given by (2), then

(6) B exp e u N N 1 d x < + , u W ,

and

(7) sup u W u 1 B exp β e ω N 1 1 N 1 u N N 1 d x < + β N ,

where ω N 1 is the area of the unit sphere S N 1 in R N .

Let N be the Hölder conjugate of N that is N = N N 1 In view of inequalities (6) and (7), we say that f has subcritical growth at + , if

lim s + f ( x , s ) exp ( N e α s N ) = 0 , for all α > 0 uniformly in x B ¯

and f has critical growth at + , if there exists some α 0 > 0 , such that

lim s + f ( x , s ) exp ( N e α s N ) = 0 , α > α 0 and lim s + f ( x , s ) exp ( N e α s N ) = + , α < α 0 uniformly in x B ¯ .

In this article, we consider problem (1) with subcritical or critical growth nonlinearities f ( x , t ) . Furthermore, we suppose that f ( x , t ) satisfies the following hypotheses:

  1. The nonlinearity f : B ¯ × R R is positive, continuous, radial in x , and f ( x , t ) = 0 for t 0 .

  2. There exist t 0 > 0 and M 0 > 0 , such that for all t > t 0 and for all x B , we have

    0 < F ( x , t ) M 0 f ( x , t ) ,

    where F ( x , t ) = 0 t f ( x , s ) d s .

  3. For each x B , f ( x , t ) t 2 N 1 is increasing for t > 0 .

  4. In the critical case, there exists a constant γ 0 with γ 0 > 1 α 0 N 1 e N g ω N 1 α 0 N 1 such that

    lim t f ( x , t ) t exp ( N e α 0 t N ) γ 0 uniformly in x B ¯ .

The condition ( H 2 ) implies that for any ε > 0 , there exists a real t ε > 0 , such that

(8) F ( x , t ) ε t f ( x , t ) , t > t ε uniformly in x B ¯ .

Also, we have that condition ( H 3 ) leads to

(9) lim t 0 f ( x , t ) t θ = 0 for all 0 θ < 2 N 1 uniformly in x B ¯ .

The condition asymptotic ( H 4 ) would be crucial to identify the minmax level of the energy associated with problem (1). We give an example of f . Let f ( t ) = F ( t ) , with F ( t ) = t 2 N + 2 2 N + 2 + t τ exp ( N e α 0 t N ) , with τ > 2 N . A simple calculation shows that f verifies conditions ( H 1 ) , ( H 2 ) , ( H 3 ) , and ( H 4 ) .

We define the function G ( t ) = 0 t g ( s ) d s . The function g is continuous on R + and verifies

  1. There exists g 0 > 0 , such that g ( t ) g 0 for all t 0 and

    G ( t + s ) G ( t ) + G ( s ) s , t 0 .

  2. g ( t ) t is nonincreasing for t > 0 .

The assumption ( G 2 ) implies that g ( t ) t g ( 1 ) for all t 1 . Then, one has g ( t ) g ( 1 ) t for t 1 .

Another consequence of ( G 2 ) is that a simple calculation shows that

1 N G ( t ) 1 2 N g ( t ) t is nondecreasing for t 0 .

So, one has

(10) 1 N G ( t ) 1 2 N g ( t ) t 0 , t 0 .

A typical example of a function g fulfilling conditions ( G 1 ) and ( G 2 ) is given by

g ( t ) = g 0 + a t , g 0 , a > 0 .

Another example is given by g ( t ) = 1 + ln ( 1 + t ) .

The major difficulty in this problem lies in the concurrence between the growths of g and f .

It will be said that u is a solution to problem (1), if u is a weak solution in the following sense.

Definition 1.1

A function u is called a solution to (1) if u W and

g ( u N ) B ( σ ( x ) u N 2 u φ ) d x = B f ( x , u ) φ d x , for all φ W .

The energy functional, also known as the Euler-Lagrange functional associated with (1), is defined by J : W R

(11) J ( u ) = 1 N G ( u N ) B F ( x , u ) d x .

It is quite clear that finding weak solutions to problem (1) is equivalent to finding non-zero critical points of the functional J over W .

In the subcritical exponential growth case, we will prove the following result.

Theorem 1.2

Let f ( x , t ) be a function that has a subcritical growth at + and satisfies ( H 1 ) , ( H 2 ) , and ( H 3 ) . Assume that g satisfies ( G 1 ) and ( G 2 ) . Then, problem (1) has a non-trivial radial solution.

In the context of the critical double exponential growth, the study of problem (1) becomes more difficult than in the subcritical case. Our Euler-Lagrange function is losing compactness at a certain level. To overcome this lack of compactness, we choose test functions, which are extremal for the Trudinger-Moser inequality (7). Our result is as follows.

Theorem 1.3

Assume that f ( x , t ) has a critical growth at + and satisfies conditions ( H 1 ) , ( H 2 ) , ( H 3 ) , and ( H 4 ) . Assume that g satisfies ( G 1 ) and ( G 2 ) . Then, problem (1) has a nontrivial solution.

This article is organized as follows. In Section 2, we give some useful lemmas for the compactness analysis. In Section 3, we prove that the functional J satisfies the two geometric properties. Section 4 is devoted to estimate the minmax level of the energy. We conclude with the proofs of Theorems 1.2 and 1.3 in Section 5.

We shall use the notation u p for the norm in the Lebesgue space L p ( B ) . We will also use the Sobolev weighted space defined by

W 2 , p ( Ω , σ ) = { u L p ( B ) such that D α u L p ( B , σ ) for all 1 α 2 } ,

equipped with the norm

u W 2 , p ( B , σ ) = u p p + 1 α 2 D α u p , σ p 1 p

and where the Lebesgue weighted space,

L p ( B , σ ) = u : B R mesurable ; B σ ( x ) u p d x < ,

is endowed with the norm u p , σ = B σ ( x ) u p d x 1 p .

2 Preliminaries for the variational formulation

In this section, we will present a number of technical lemmas for our future use. We begin with the radial lemma.

Lemma 1

[15] Let u be a radially symmetric function in C 0 1 ( B ) . Then, we have

u ( x ) 1 ω N 1 1 N log 1 N log e x u ,

where ω N 1 is the area of the unit sphere S N 1 R N .

The second important lemma is given as follows:

Lemma 2

[22] Let Ω R N be a bounded domain and f : Ω ¯ × R be a continuous function. Let { u n } n be a sequence in L 1 ( Ω ) converging to u in L 1 ( Ω ) . Assume that f ( x , u n ) and f ( x , u ) are also in L 1 ( Ω ) . If

Ω f ( x , u n ) u n d x C ,

where C is a positive constant, then

f ( x , u n ) f ( x , u ) i n L 1 ( Ω ) .

In an attempt to prove a compactness condition for the energy , we need a Lions-type result [23] about an improved TM-inequality when we deal with weakly convergent sequences and double exponential case.

Lemma 3

Let { u k } k be a sequence in W . Suppose that u k = 1 , u k u weakly in W , u k ( x ) u ( x ) a.e. x B , u k ( x ) u ( x ) a.e. x B and u 0 . Then

sup k B exp N e p ω N 1 1 N 1 u k N d x < +

for all 1 < p < U where U is given by:

U = ( 1 u N ) 1 N 1 if u < 1 + if u = 1 ,

Proof

For a , b R , q > 1 . If q is a conjugate, i.e., 1 q + 1 q = 1 , we have, by Young’s inequality, that

e a + b 1 q e q a + 1 q e q b ,

and so

exp ( N e a + b ) exp N q e q a + N q e q b

Therefore,

exp ( N e a + b ) 1 q exp ( N e q a ) + 1 q exp ( N e q b ) .

Also, we have

( 1 + a ) q ( 1 + ε ) a q + 1 1 ( 1 + ε ) 1 q 1 1 q , a 0 , ε > 0 q > 1 .

So, we obtain

u k N = u k u + u N ( u k u + u ) N ( 1 + ε ) u k u N + 1 1 ( 1 + ε ) N 1 1 N 1 u N

This implies that

B exp N e p ω N 1 1 N 1 u k N d x 1 q B exp ( N e p q ω N 1 1 N 1 ( 1 + ε ) u k u N ) d x + 1 q B exp N e p q ω N 1 1 N 1 1 1 ( 1 + ε ) N 1 1 N 1 u N d x ,

for any p > 1 . From (6), the last integral is finite. To complete the proof, we have to prove that for every p such that 1 < p < U ,

(12) sup k B exp N e p q ω N 1 1 N 1 ( 1 + ε ) u k u N d x < + ,

for some ε > 0 and q > 1 .

In the following, we suppose that u < 1 , and in the case of u = 1 , the proof is similar. When

u < 1

and

p < 1 ( 1 u N ) 1 N 1 ,

there exists ν > 0 , such that

p ( 1 u N ) 1 N 1 ( 1 + ν ) < 1 .

On the other hand, by Brezis-Lieb’s lemma [24] we have

u k u N = u k N u N + o ( 1 ) where o ( 1 ) 0 as k + .

Then,

u k u N = 1 u N + o ( 1 ) ,

and so,

lim k + u k u N = 1 u N ,

that is,

lim k + u k u N = ( 1 u N ) 1 N 1 .

Therefore, for every ε > 0 , there exists k ε 1 such that

u k u N ( 1 + ε ) ( 1 u N ) 1 N 1 , k k ε .

If we take q = 1 + ε with ε = 1 + ν 3 1 , then k k ε , we have

p q ( 1 + ε ) u k u N 1 .

Consequently,

B exp N e p q ω N 1 1 N 1 ( 1 + ε ) u k u N d x B exp N e ( 1 + ε ) p q ω N 1 1 N 1 u k u u k u N u k u N d x B exp N e ω N 1 1 N 1 u k u u k u N d x sup u 1 B exp N e ω N 1 1 N 1 u N d x < + .

Now, (12) follows from (7). This completes the proof.□

3 The mountain pass geometry of the energy

Since the nonlinearity f is critical or subcritical at + , there exist a , C > 0 positive constants and there exists t 2 > 1 such that

(13) f ( x , t ) C exp ( e a t N ) , t > t 2 .

So the functional J given by (11) is well defined and of class C 1 .

In order to prove the existence of nontrivial solution to problem (1), we will prove the existence of nonzero critical point of the functional J by using the theorem introduced by Ambrosetti and Rabinowitz in [25] (mountain pass theorem) without the Palais-Smale condition.

Theorem 3.1

[25] Let E be a Banach space and J : E R a C 1 functional satisfying J ( 0 ) = 0 . Suppose that there exist ρ , β > 0 , and e E with e > ρ such that

inf u = ρ J ( u ) β and J ( e ) 0 .

Then, there is a sequence ( u n ) E such that

J ( u n ) c and J ( u n ) 0 ,

where

c inf γ Γ max t [ 0 , 1 ] J ( γ ( t ) ) β

and

Γ { γ C ( [ 0 , 1 ] , E ) such that γ ( 0 ) = 0 and γ ( 1 ) = e } .

The number c is called mountain pass level or minimax level of the functional J.

Before starting the proof of the geometric properties for the functional J , it follows from the continuous embedding W L q ( B ) for all q 1 , that there exists a constant C > 0 such that u N q c u , for all u W .

In the next lemmas, we prove that the functional J has the mountain pass geometry of Theorem 3.1.

Lemma 4

Suppose that f has critical or subcritical growth at + . In addition, if ( H 1 ) , ( H 3 ) , and ( G 1 ) hold, then there exist ρ , β > 0 such that J ( u ) β for all u W with u = ρ .

Proof

It follows from (9) that there exists δ 0 > 0

F ( x , t ) ε t N for t < δ 0 .

From (13), for all q > N , there exists a positive constant δ 1 > 0 such that

F ( x , t ) C t q exp ( e a t N ) , t > δ 1 .

Using the continuity of F , we obtain

F ( x , t ) ε t N + C t q exp ( e a t N ) for t R .

We obtain from ( G 1 ),

J ( u ) g 0 N u N ε B u N d x C B u q exp ( e a u N ) d x .

From the Hölder inequality, we obtain

J ( u ) g 0 N u N ε B u N d x C B exp ( N e a u N ) d x 1 N u N q q

If we choose u W such that

(14) a u N ω N 1 1 N 1 ,

then from Theorem 1.1, we obtain

B exp ( N e a u N ) d x = B exp N e a u N u u N d x < C ,

with C not depending on u .

On the other hand, u N q C 1 u , so

J ( u ) g 0 N u N ε C 1 u N C u q = u N g 0 N ε C 1 C u q N ,

for all u W satisfying (14). Since N < q , we can choose ρ = u ω N 1 1 N a N and for fixed ε such that g 0 N ε C 1 > 0 , there exists β = ρ N g 0 N ε C 1 C ρ q N > 0 with J ( u ) β > 0 .□

By the following lemma, we prove the second geometric property for the functional J .

Lemma 5

Suppose that ( H 1 ) , ( H 2 ) , and ( G 2 ) hold. Then, there exists e W with J ( e ) < 0 and e > ρ .

Proof

From condition ( G 2 ) , for all t 1 , we have that

(15) G ( t ) g ( 1 ) 2 t 2 .

It follows from condition ( H 2 ) , for all t t 0

f ( x , t ) = t F ( x , t ) 1 M 0 F ( x , t )

So

F ( x , t ) C e t M 0 , t t 0 .

In particular, for p > 2 N , there exist C 1 and C 2 such that

F ( x , t ) C 1 t p C 2 t R , x B .

Next, one arbitrarily picks u ¯ W such that u ¯ = 1 . Thus from (15), for all t 1 ,

J ( t u ¯ ) g ( 1 ) 2 N t 2 N C 1 u ¯ p p , t p ω N 1 N C 2 .

Therefore,

lim t + J ( t u ¯ ) = .

We take e = t u ¯ , for some t > 0 large enough. So, Lemma 5 follows.□

4 The minimax estimate of the energy

According to Lemmas 4 and 5, let

d inf γ Λ max t [ 0 , 1 ] J ( γ ( t ) ) > 0

and

Λ { γ C ( [ 0 , 1 ] , W ) such that γ ( 0 ) = 0 and J ( γ ( 1 ) ) < 0 } .

We are going to estimate the minimax value d of the functional J . The idea is to construct a sequence of functions ( v n ) W , and estimate max { J ( t v n ) : t 0 } . For this goal, let us consider the following Moser sequence:

(16) ψ n ( t ) = log ( 1 + t ) log 1 N ( 1 + n ) if 0 t n , log N 1 N ( 1 + n ) if t n .

Let v n ( x ) be the function defined by

ψ n ( t ) = ω N 1 1 N v n ( x ) , where e t = x .

With this choice of ψ n , the sequence ( v n ) is normalized since

v n N = 1 ω N 1 B ψ n N log e x N 1 d x = 0 + ψ ( t ) N ( 1 + t ) N 1 d t = 1 .

We have the following elementary crucial result.

Lemma 6

We have

lim n + 0 + exp ( N e ψ n N N t ) d t = N + 1 N e N .

Proof

We make the changes of variable s = 1 + t and j = n + 1 , so

0 + exp ( N e ψ n N N t ) d t = e N N + 0 n exp N e log N ( 1 + t ) log 1 N 1 ( 1 + n ) N t d t = e N N + 1 j exp N s log s log j 1 N 1 N ( s 1 ) d s = e N N + e N 1 j exp N s log s log j 1 N 1 N s d s .

We claim that

lim j + 1 j exp N s log s log j 1 N 1 N s d s = 1 .

Indeed, for any j > 4 , we have

ψ j ( s ) N s log s log j 1 N 1 N s with s 1 .

The interval [ 1 , j ] is then divided as follows:

[ 1 , j ] = 1 , j 1 2 ( N 1 ) j 1 2 ( N 1 ) , j j 1 2 ( N 1 ) j j 1 2 ( N 1 ) , j .

First, we consider the interval 1 , j 1 2 ( N 1 ) . Since

χ 1 , j 1 2 ( N 1 ) ( s ) e ψ j ( s ) e N s 1 2 N s L 1 ( [ 1 , + ) ) ,

χ 1 , j 1 2 ( N 1 ) ( s ) e ψ j ( s ) e N N s for a.e s [ 1 , + ) , as j + ,

then, using the Lebesgue-dominated convergence theorem, we obtain

lim j + 1 j 1 2 ( N 1 ) exp N s log s log j 1 N 1 N s d s = lim j + 1 j χ 1 , j 1 2 ( N ) ( s ) e ψ j ( s ) d s = 1 N .

Now, we are going to study the limit of this integral on j 1 2 ( N 1 ) , j j 1 2 ( N 1 ) and j j 1 2 ( N 1 ) , j , so we compute

ψ j j 1 2 ( N 1 ) = N j 1 2 ( N 1 ) 1 j 1 2 N

and

(17) ψ j j 1 2 ( N 1 ) j 1 2 ( N 1 ) for all j 4 .

We have also

ψ j j j 1 2 ( N 1 ) = N exp 1 log 1 N 1 j log j + log 1 j 1 2 ( N 1 ) 1 N N j j 1 2 ( N 1 ) = N exp log j 1 + log 1 j 1 2 ( N 1 ) 1 log j N N j j 1 2 ( N 1 )

= N exp log j 1 N j 1 2 ( N 1 ) 1 log j + o j 1 2 ( N 1 ) 1 log j j + N j 1 2 ( N 1 ) = N j exp N j 1 2 ( N 1 ) 1 + o j 1 2 ( N 1 ) 1 log j 1 + N j 1 2 ( N 1 ) .

Therefore, for every ε ( 0 , 1 ) , there exists j ε 1 such that

(18) ψ j j j 1 2 ( N 1 ) N j 1 2 ( N 1 ) ( 1 ( 1 ε ) N ) for every j j ε .

Let j be fixed and large enough. A qualitative study conducted on ψ j in [ 1 , + ) shows that there exists a unique s j ( 1 , j ) such that the derivative of ψ j ( s j ) = 0 and consequently

j 1 2 ( N 1 ) j j 1 2 ( N 1 ) e ψ j ( s ) d s j 2 j 1 2 ( N 1 ) e max ψ j j 1 2 ( N 1 ) , ψ j j j 1 2 ( N 1 ) .

In addition, from (17) and (18) with ε = 1 N 2 , we obtain

max ψ j j 1 2 ( N 1 ) , ψ j j j 1 2 ( N 1 ) j 1 2 ( N 1 ) ,

as condition that j is large enough. Hence, there exists j ¯ 1 such that

j 1 2 ( N 1 ) j j 1 2 ( N 1 ) e ψ j ( s ) d s j 2 j 1 2 ( N 1 ) e j 1 2 ( N 1 ) for all j j ¯ .

Therefore,

lim j + j 1 2 ( N 1 ) j j 1 2 ( N 1 ) exp N e s log s log j 1 N 1 N s d s = 0 .

Finally, we will study the limit on the interval j j 1 2 N 1 , j . We mention that for a fixed j 1 large enough, ψ j is a convex function on j j 1 2 ( N 1 ) , + , and ψ j ( j ) = 0 , so we can obtain this estimate

ψ j ( s ) j s j 1 2 ( N 1 ) ψ j j j 1 2 ( N 1 ) , s j j 1 2 ( N 1 ) , j .

On the other hand, in view of (17) and (18), if ε ( 0 , 1 N 2 ) and j j ε , we have

(19) ψ j ( s ) N ( 1 ( 1 ε ) N ) ( j s ) , s j j 1 2 ( N 1 ) , j .

Furthermore, using the fact that ψ j is convex on j j 1 2 ( N 1 ) , + and ψ j ( j ) = N , we obtain

(20) ψ j ( s ) φ j ( j ) + φ j ( j ) ( s j ) = N ( s j ) , s [ j j 1 2 ( N 1 ) , j ] .

Then, by bringing together (19) and (20), we deduce

1 N lim j + j j 1 2 ( N 1 ) j e ψ j ( s ) d s 1 N ( 1 ( 1 ε ) N ) .

By tending ε to zero, we obtain

lim j + j 1 2 ( N 1 ) j j 1 2 ( N 1 ) exp N e s log s log j 1 N 1 N s d s = 1 N .

So, our claim is proved and the lemma follows.□

Finally, we give the desired estimate.

Lemma 7

Assume that if ( G 1 ), ( G 2 ), ( H 1 ), ( H 2 ), and ( H 4 ) hold, then

d < 1 N G ω N 1 α 0 N 1 .

Proof

We have v n 0 and v n = 1 . Then, from Lemma 5, J ( t v n ) as t + . As a consequence,

d max t 0 J ( t v n ) .

We argue by contradiction and suppose that for all n 1 ,

max t 0 J ( t v n ) 1 N G ω N 1 α 0 N 1 .

Since J possesses the mountain pass geometry, for any n 1 , there exists t n > 0 such that

max t 0 J ( t v n ) = J ( t n v n ) 1 N G ω N 1 α 0

Using the fact that F ( x , t ) 0 for all ( x , t ) B × R , we obtain

G ( t n N ) G ω N 1 α 0 N 1 .

On one hand, the condition ( G 1 ) implies that G : [ 0 , + ) [ 0 , + ) is an increasing bijection. So

(21) t n N ω N 1 α 0 N 1

On the other hand,

d d t J ( t v n ) t = t n = g ( t n N ) t n N 1 B f ( x , t n v n ) v n d x = 0 ,

that is,

(22) g ( t n N ) t n N = B f ( x , t n v n ) t n v n d x .

Now, we claim that the sequence ( t n ) is bounded in ( 0 , + ) .

Indeed, it follows from ( H 4 ) that for all ε > 0 , there exists t ε > 0 such that

(23) f ( x , t ) t ( γ 0 ε ) exp ( N e α 0 t N ) t t ε uniformly in x B .

From (16) and (22), we have

g ( t n N ) t n N = B f ( x , t n v n ) t n v n d x ω N 1 n + f e s , t n ψ n ω N 1 1 N t n ψ n ω N 1 1 N e N s d s .

Also,

t n ψ n ω N 1 1 N = t n log ( 1 + n ) ω N 1 1 N 1 1 N log ( 1 + n ) α 0 1 N ,

then, it follows from (23) that for all ε > 0 , there exists n 0 such that for all n n 0

(24) g ( t n N ) t n N ω N 1 ( γ 0 ε ) n + exp N e α 0 ω N 1 1 N 1 ( t n ψ n ) N N s d s ,

that is,

g ( t n N ) t n N ω N 1 N ( γ 0 ε ) exp N e α 0 ω N 1 1 N 1 t n N log ( 1 + n ) N n .

Using the condition ( G 2 ), we obtain

(25) g ( 1 ) t n 2 N ω N 1 N ( γ 0 ε ) exp N e α 0 ω N 1 1 N 1 t n N log ( 1 + n ) N n .

From (25), we obtain for n large enough

1 ω N 1 N ( γ 0 ε ) exp N e α 0 ω N 1 1 N 1 t n N log ( 1 + n ) N n log ( g ( 1 ) t n 2 N ) .

Therefore, ( t n ) is bounded in R . Now, suppose that

lim n + t n N > ω N 1 α 0 N 1 .

For n large enough, t n N > ω N 1 α 0 N 1 and in this case, the right-hand side of inequality (25) will give the unboundedness of the sequence ( t n ) . Since ( t n ) is bounded, we obtain

lim n + t n N = ω N 1 α 0 N 1 .

Now, we are going to estimate the expression in (22). So let

B n , + = { x B ; t n v n ( x ) t ε } and B n , = { x B ; t n v n ( x ) < t ε } .

We have

g ( t n N ) t n N ( γ 0 ε ) B n , + exp ( N e α 0 t n N v n N ) d x + B n , f ( x , t n v n ) t n v n d x ,

then

(26) g ( t n N ) t n N ( γ 0 ε ) B exp ( N e α 0 t n N v n N ) d x ( γ 0 ε ) B n , exp ( N e α 0 t n N v n N ) d x + B n , f ( x , t n v n ) t n v n d x .

The sequence ( v n ) converges to 0 in B and χ B n , converges to 1 a.e. in B . By using the dominated convergence theorem, we obtain

lim n + B n , f ( x , t n v n ) t n v n d x = 0

and

lim n + B n , exp ( N e α 0 t n N v n N ) d x ω N 1 N e N .

We also have

lim n + B exp N e ω N 1 1 N 1 v n N d x = lim n + ω N 1 0 + exp ( N e ψ n N N t ) d t .

Then using (21) and Lemma 6, we obtain

lim n + B exp ( N e α 0 t n N v n N ) d x lim n + B exp N e ω N 1 1 N 1 v n N d x = ω N 1 N + 1 N e N .

Passing to the limit in (26), we obtain

g ω N 1 α 0 N 1 ω N 1 α 0 N 1 ( γ 0 ε ) ω N 1 e N ,

for all ε > 0 . So,

γ 0 1 α 0 N 1 e N g ω N 1 α 0 N 1 ,

which contradicts the condition ( H 4 ) . Hence, the lemma is proved.□

5 Proof of main results

First, we begin by some crucial lemmas.

Now, we consider the Nehari manifold associated with the functional J , namely,

N = { u W : J ( u ) u = 0 , u 0 } ,

and the number c = inf u N J ( u ) . We have the following lemmas.

Lemma 8

Assume that the condition ( H 3 ) holds, then for each x B ,

t f ( x , t ) 2 N F ( x , t ) is increasing for t 0 .

Proof

Assume that 0 < t < s . For each x B , we have

t f ( x , t ) 2 N F ( x , t ) = f ( x , t ) t 2 N 1 t 2 N 2 N F ( x , s ) + 2 N t s f ( x , ν ) d ν < f ( x , s ) s 2 N 1 t 2 N 2 N F ( x , s ) + f ( x , s ) s 2 N 1 ( s 2 N t 2 N ) = s f ( x , s ) 2 N F ( x , s ) .

Lemma 9

If ( G 2 ) and ( H 3 ) are satisfied, then d c .

Proof

Let u ¯ N , u ¯ > 0 and consider the function ψ : ( 0 , + ) R defined by ψ ( t ) = J ( t u ¯ ) . ψ is differentiable and we have

ψ ( t ) = J ( t u ¯ ) u ¯ = g ( t N u ¯ N ) t N 1 u ¯ N B f ( x , t u ¯ ) u ¯ d x , for all t > 0 .

We have g ( u ¯ N ) u ¯ N = B f ( x , u ¯ ) u ¯ d x . Hence,

ψ ( t ) = t 2 N 1 u ¯ 2 N g ( t N u ¯ N ) t N u ¯ N g ( u ¯ N ) u ¯ N + t 2 N 1 B f ( x , u ¯ ) u ¯ 2 N 1 f ( x , t u ¯ ) ( t u ¯ ) 2 N 1 u ¯ 2 N d x .

We have that ψ ( 1 ) = 0 . We also have by conditions ( G 2 ) and ( H 3 ) that ψ ( t ) > 0 for all 0 < t < 1 and ψ ( t ) 0 for all t > 1 . It follows that

J ( u ¯ ) = max t 0 J ( t u ¯ ) .

We define the function λ : [ 0 , 1 ] W such that λ ( t ) = t t ¯ u ¯ , with J ( t ¯ u ¯ ) < 0 . We have λ Λ , and hence

d max t [ 0 , 1 ] J ( λ ( t ) ) max t 0 J ( t u ¯ ) = J ( u ¯ ) .

Since u ¯ N is arbitrary, then d c .□

5.1 Proof of Theorems 1.2 and 1.3

Since J possesses the mountain pass geometry, there exists u n W such that

(27) J ( u n ) = 1 N G ( u n N ) B F ( x , u n ) d x d , n +

and

(28) J ( u n ) φ = g ( u n N ) B σ ( x ) u n N 2 u n . φ d x B f ( x , u n ) φ d x ε n φ ,

for all φ W , where ε n 0 , when n + .

By (27), for all ε > 0 , there exists a constant C > 0

1 N G ( u n N ) C + B F ( x , u n ) d x .

From (8), we have

1 N G ( u n N ) C + u n t ε F ( x , u n ) d x + ε B f ( x , u n ) u n d x .

From (28) and (10), we obtain

1 2 N g ( u n N ) u n N 1 N G ( u n N ) C 1 + ε ε n u n + ε g ( u n N ) u n N ,

for some constant C 1 > 0 . Using the condition ( G 1 ), for all ε such that 0 < ε < 1 2 N , we obtain

g 0 1 2 N ε u n N C 1 + ε ε n u n ,

and we deduce that the sequence ( u n ) is bounded in W . As a consequence, there exists u W such that, up to subsequence, u n u weakly in W , u n u strongly in L q ( B ) , for all q 1 .

Furthermore, we have from (28) and (8) that

0 < B f ( x , u n ) u n C

and

0 < B F ( x , u n ) C .

Since by Lemma 2, we have

(29) f ( x , u n ) f ( x , u ) in L 1 ( B ) as n + ,

then, it follows from ( H 2 ) and the generalized Lebesgue-dominated convergence theorem that

(30) F ( x , u n ) F ( x , u ) in L 1 ( B ) as n + .

So,

(31) lim n + G ( u n N ) = N ( d + B F ( x , u ) d x ) .

Next, we are going to make some claims.

Claim 1. u n ( x ) u ( x ) a.e x B . Indeed, for any η > 0 , let A η = { x B , u n u η } . For all t R , for all positive c > 0 , we have

c t N e t + c 2 N .

It follows that for t = ω N 1 1 N 1 u n u u n u N , c = 1 ω N 1 1 N 1 u n u N , we obtain

u n u N N e ω N 1 1 N 1 u n u u n u N + 1 N 1 ω N 1 2 N 1 u n u 2 N N e ω N 1 1 N 1 u n u u n u N + C 1 ( N ) ,

where C 1 ( N ) is a constant depending only on N and the upper bound of u n . So, if we denote by ( A η ) the Lebesgue measure of the set A η , we obtain

( A η ) = A η e u n u N e u n u N d x e η N A η exp N e ω N 1 1 N 1 u n u u n u N + C 1 ( N ) d x e η N e C 1 ( N ) B exp N e ω N 1 1 N 1 u n u u n u N d x e η N C 2 ( N ) 0 as η + ,

where C 2 ( N ) is a positive constant depending only on N and the upper bound of u n . It follows that

(32) A η u n u d x C e 1 2 η N B u n u 2 σ ( x ) d x 1 2 0 as η + .

We define for η > 0 , the truncation function used in [26]

T η ( s ) s if s < η η s s if s η .

If we take φ = T η ( u n u ) W , then φ = χ B A η ( u n u ) . Considering φ in (28) we obtain

g ( u n N ) B A η σ ( x ) ( u n N 2 u n u N 2 u ) . ( u n u ) d x g ( u n N ) B A η σ ( x ) u N 2 u ( u n u ) d x + B f ( x , u n ) T η ( u n u ) d x + ε n T η ( u n u ) g ( u n N ) B σ ( x ) u N 2 u ( u n u ) d x + B f ( x , u n ) T η ( u n u ) d x + ε n T η ( u n u ) .

Since u n u weakly in W , then g ( u n N ) B A η σ ( x ) u N 2 u . ( u n u ) d x 0 . By (29) and the Lebesgue-dominated convergence theorem, we obtain

B f ( x , u n ) T η ( u n u ) d x 0 as n + .

Using the well-known inequality,

x N 2 x y N 2 y , x y 2 2 N x y N x , y R N , N 2 ,

, is the inner product in R N and the fact that 0 < g 0 g ( u n N ) , one has

B A η σ ( x ) u n u N d x 0 .

Therefore,

(33) B A η u n u N d x B A η σ ( x ) u n u N d x 1 N ( ( B A η ) ) 1 N 0 as n + .

From (32) and (33), we deduce that

B u n u d x 0 as n + .

Therefore, u n ( x ) u ( x ) a.e x B and claim 1 is proved.

Claim 2. At this stage, we affirm that u 0 . Indeed, we argue by contradiction and suppose that u 0 . Therefore, B F ( x , u n ) d x 0 , and consequently, we obtain

(34) 1 N G ( u n N ) d < 1 N G ω N 1 α 0 N 1 .

First, we claim that there exists q > 1 such that

(35) B f ( x , u n ) q d x C .

By (28), we have

g ( u n N ) u n N B f ( x , u n ) u n d x C ε n .

So,

g ( u n N ) u n N C ε n + B f ( x , u n ) q 1 q d x B u n q 1 q ,

where q is the conjugate of q . Since ( u n ) converges to 0 in L q ( B )

lim n + g ( u n N ) u n N = 0 .

From the condition ( G 1 ), we obtain

lim n + u n N = 0 ,

then u n 0 in W . Therefore, J ( u n ) 0 , which is in contradiction with d > 0 .

For the proof of claim (35), since f has critical growth, for every ε > 0 and q > 1 , there exists t ε > 0 and C > 0 such that for all t t ε , we have

f ( x , t ) q C exp ( N e α 0 ( ε + 1 ) t N ) .

Consequently,

B f ( x , u n ) q d x = { u n t ε } f ( x , u n ) q d x + { u n > t ε } f ( x , u n ) q d x ω N 1 max B ¯ × [ t ε , t ε ] f ( x , t ) q + C B exp ( N e α 0 ( ε + 1 ) u n N ) d x .

Since ( G 1 ( N d ) ) 1 N 1 < ω N 1 1 N 1 α 0 , there exists η ( 0 , 1 2 ) such that ( G 1 ( N d ) ) 1 N 1 = ( 1 2 η ) ω N 1 1 N 1 α 0 . From (34), u n N ( G 1 ( N d ) ) 1 N 1 , so there exist n η N such that α 0 u n N ( 1 η ) ω N 1 1 N 1 , for all n n η . Therefore,

α 0 ( 1 + ε ) u n u n N u n N ( 1 + ε ) ( 1 η ) u n u n N ω N 1 1 N 1 .

We choose ε > 0 small enough to obtain

( 1 + ε ) ( 1 η ) < 1 ,

hence the second integral is uniformly bounded in view of (7).

Claim 3. g ( u N ) u N B f ( x , u ) u d x . We proceed by contradiction and we suppose that g ( u N ) u N < B f ( x , u ) u d x . Hence, J ( u ) u < 0 . The function ψ : t ψ ( t ) = J ( t u ) u is positive for t small enough. Indeed, from (9) and the critical (resp subcritical) growth of the nonlinearity f , for every ε > 0 , for every q > N , there exist positive constants C and c such that

f ( x , t ) ε t N 1 + C t q exp ( e c t N ) , ( t , x ) R × B .

Then, using the condition ( G 1 ) , the last inequality, and the Hölder inequality, we obtain

ψ ( t ) = g ( t N u N ) t N 1 u N B f ( x , t u ) u d x g 0 t N 1 u N ε t N 1 B u N d x C B exp ( N e c t N u N ) d x 1 N B u N q d x 1 N .

In view of (7) the integral B exp ( N e c t N u N ) d x = B exp N e c t N u N u N u N d x < , provided t ω N 1 1 N c N u . Using the radial Lemma 1, we obtain u N q q C u q . Then,

ψ ( t ) g 0 t N 1 u N C 1 ε t N 1 u N C 2 u q = u N t N 1 [ ( g 0 C 1 ε ) C 2 t q ( N 1 ) u q N ] .

We chose ε > 0 , such that g 0 C 1 ε > 0 and since q > N , for small t , we obtain ψ : t ψ ( t ) = J ( t u ) u > 0 . So there exists η ( 0 , 1 ) such that ψ ( η u ) = 0 . Therefore, η u N . Using (10), the result of Lemma 7, the semicontinuity of norm, and Fatou’s lemma, we obtain

d c J ( η u ) = J ( η u ) 1 2 N J ( η u ) η u = 1 N G ( η u N ) 1 2 N g ( η u N ) η u N + 1 2 N B ( f ( x , η u ) η u 2 N F ( x , η u ) ) d x < 1 N G ( u N ) 1 2 N g ( u N ) u N + 1 2 N B ( f ( x , u ) u 2 N F ( x , u ) ) d x liminf n + 1 N G ( u n N ) 1 2 N g ( u n N ) u n N + 1 2 N B ( f ( x , u n ) u n 2 N F ( x , u n ) ) d x lim n + J ( u n ) 1 2 N J ( u n ) u n = d ,

which is absurd and Claim 3 is well established.

Claim 4. u > 0 . Indeed, since ( u n ) is bounded, up to a subsequence, u n ρ > 0 . In addition, J′ ( u n ) 0 leads to

g ( ρ N ) B σ ( x ) u N 2 u . φ d x = B f ( x , u ) φ d x , φ W .

By taking φ = u , with w ± = max ( ± w , 0 ) , we obtain u N = 0 and so u = u + 0 . Since the nonlinearity has critical growth at + and from the Trudinger-Moser inequality (7), f ( . , u ) L p ( B ) , for all p 1 . So, by elliptic regularity u W 2 , p ( B , σ ) , for all p 1 . Therefore, by Sobolev imbedding u C 1 , γ ( B ¯ ) .

Let us define B 0 = { x B : u ( x ) = 0 } . The set B 0 = . Indeed, suppose by contradiction that B 0 . Since f ( x , u ) 0 , by the Harnack inequality (see [16], Theorem 1.9), we can deduce that B 0 is an open and closed set of B . In virtue of the connectedness of B , we reach a contradiction. Hence, Claim 4 is proved.

We affirm that J ( u ) = d . Indeed, by Claim 3, (10), and Lemma 8, we obtain

(36) J ( u ) 1 N G ( u N ) 1 2 N g ( u N ) u N + 1 2 N B [ f ( x , u ) 2 N F ( x , u ) ] d x 0 .

Now, using the semicontinuity of the norm and (30), we obtain,

J ( u ) 1 N liminf n G ( u n N ) B F ( x , u ) d x = d .

Suppose that

J ( u ) < d .

Then

(37) u N < ρ N .

In addition,

(38) 1 N G ( ρ N ) = 1 N lim n + G ( u n N ) = d + B F ( x , u ) d x ,

which means that

ρ N = G 1 N d + N B F ( x , u ) d x .

Set

v n = u n u n and v = u ρ .

We have v n = 1 , v n v in W , v 0 , and v < 1 . So, by Lemma 3, we obtain

sup n B exp N e p ω N 1 1 N 1 v n N d x < ,

for 1 < p < ( 1 v N ) 1 N 1 .

By (27), (30), and (38), we have the following equality:

N d N J ( u ) = G ( ρ N ) G ( u N ) .

From (36), Lemma 7, and the last equality, we obtain

G ( ρ N ) N d + G ( u N ) < G ω N 1 α 0 N 1 + G ( u N ) .

Now, using the condition ( G 1 ), one has

(39) ρ N < G 1 G ω N 1 α 0 N 1 + G ( u N ) ω N 1 α 0 + u N .

Since

ρ N = ρ N u N 1 v N 1 N 1 ,

we deduce from (39) that

(40) ρ N < ω N 1 α 0 N 1 1 v N 1 N 1 .

On one hand, we have this estimate B f ( x , u n ) q d x < C . Indeed, for ε > 0 ,

B f ( x , u n ) q d x = { u n t ε } f ( x , u n ) q d x + { u n > t ε } f ( x , u n ) q d x ω N 1 max B × [ t ε , t ε ] f ( x , t ) q + C B exp ( N e α 0 ( 1 + ε ) u n N ) d x C ε + C B exp ( N e α 0 ( 1 + ε ) u n N v n N ) d x C

if we have α 0 ( 1 + ε ) u n N p ω N 1 1 N 1 , with 1 < p < ( 1 v N ) 1 N 1 .

From (40), there exists δ ( 0 , 1 2 ) such that ρ N = ( 1 2 δ ) ω N 1 α 0 N 1 1 v N 1 N 1 .

Since lim n + u n N = ρ N then, for n large enough

α 0 ( 1 + ε ) u n N ( 1 + ε ) ( 1 δ ) ω N 1 1 N 1 1 1 v N 1 N 1 .

We choose ε > 0 small enough such that ( 1 + ε ) ( 1 δ ) < 1 , which means

α 0 ( 1 + ε ) u n N < ω N 1 1 N 1 1 1 v N 1 N 1

and so, the sequence ( f ( x , u n ) ) is bounded in L q , q > 1 . Using the Hölder inequality, we deduce that

B f ( x , u n ) ( u n u ) d x B f ( x , u n ) q d x 1 q B u n u q 1 q d x C B u n u q 1 q d x 0 as n + ,

where 1 q + 1 q = 1 . Since J ( u n ) ( u n u ) = o n ( 1 ) , it follows that

g ( u n N ) B ( σ ( x ) u n N 2 u n ( u n u ) d x ) 0 .

On the other side,

g ( u n N ) B σ ( x ) u n N 2 u n ( u n u ) d x = g ( u n N ) u n N g ( u n N ) B σ ( x ) u n N 2 u n u d x .

Passing to the limit in the last equality, we obtain

g ( ρ N ) ρ N g ( ρ N ) u N = 0 ,

therefore u = ρ . This is in contradiction with (37). Therefore, J ( u ) = d . So, u is a solution of problem (1). The proof of Theorem 1.3 is complete.

Proof of Theorem 1.2

In the subcritical case, since u n is bounded, there exist M > 0 and subsequences such that

u n M in W u n u weakly in W u n u strongly in L q ( B ) q 1 u n ( x ) u ( x ) almost everywhere in B .

Since f is subcritical at + , there exists a constant C M > 0 such that

f ( x , s ) C M exp { e w N 1 1 N 1 M N s N } , ( x , s ) B × ( 0 , + ) .

Using the Hölder inequality

B f ( x , u n ) ( u n u ) d x B f ( x , u n ) ( u n u ) d x B f ( x , u n ) 2 d x 1 2 B u n u 2 d x 1 2 C M B exp 2 e w N 1 1 N 1 M N u n N d x 1 2 u n u 2 C M B exp { 2 e w N 1 1 N 1 M N u n N u n N u n N N 1 } d x 1 2 u n u 2 C M u n u 2 0 as n + .

It is easy to check that J ( u ) = d . Also, u is a solution of (1). This completes the proof of Theorem 1.2.□

Remark 5.1

The solution u is also called a ground state solution of problem (1).

Remark 5.2

By a slight modification of the previous proof, we can prove that the functional J satisfies the Palais-Smale condition at all levels d R for the subcritical case. However, in the critical case, J satisfies the Palais-Smale condition at all levels d < 1 N G ω N 1 α 0 N 1 .

Acknowledgments

The authors sincerely thank the anonymous reviewers for their careful reading, constructive comments, and suggesting some related references that improved the manuscript substantially.

  1. Funding information: The authors state no funding involved.

  2. Author Contributions: This study was carried out in collaboration with equal responsibility. All authors read and approved the final manuscript.

  3. Conflict of interest: Authors state no conflict of interest.

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Received: 2021-08-16
Revised: 2022-06-15
Accepted: 2022-07-29
Published Online: 2022-10-05

© 2022 Imed Abid et al., published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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  15. On solving pseudomonotone equilibrium problems via two new extragradient-type methods under convex constraints
  16. Local linear approach: Conditional density estimate for functional and censored data
  17. Some properties of graded generalized 2-absorbing submodules
  18. Eigenvalue inclusion sets for linear response eigenvalue problems
  19. Some integral inequalities for generalized left and right log convex interval-valued functions based upon the pseudo-order relation
  20. More properties of generalized open sets in generalized topological spaces
  21. An extragradient inertial algorithm for solving split fixed-point problems of demicontractive mappings, with equilibrium and variational inequality problems
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  23. On a weighted elliptic equation of N-Kirchhoff type with double exponential growth
  24. On split feasibility problem for finite families of equilibrium and fixed point problems in Banach spaces
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  26. Multiplication operators on the Banach algebra of bounded Φ-variation functions on compact subsets of ℂ
  27. Mannheim curves and their partner curves in Minkowski 3-space E13
  28. Characterizations of the group invertibility of a matrix revisited
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  31. A robust study of the transmission dynamics of zoonotic infection through non-integer derivative
  32. A Dai-Liao-type projection method for monotone nonlinear equations and signal processing
  33. Review Article
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  35. Special Issue on Recent Methods in Approximation Theory - Part I
  36. Coupled fixed point theorems under new coupled implicit relation in Hilbert spaces
  37. Approximation of integrable functions by general linear matrix operators of their Fourier series
  38. Sharp sufficient condition for the convergence of greedy expansions with errors in coefficient computation
  39. Approximation of conic sections by weighted Lupaş post-quantum Bézier curves
  40. On the generalized growth and approximation of entire solutions of certain elliptic partial differential equation
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  43. A note on the convergence of Phillips operators by the sequence of functions via q-calculus
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  46. Positive solutions for fractional differential equation at resonance under integral boundary conditions
  47. Source term model for elasticity system with nonlinear dissipative term in a thin domain
  48. A numerical study of anomalous electro-diffusion cells in cable sense with a non-singular kernel
  49. On Opial-type inequality for a generalized fractional integral operator
  50. Special Issue on Advances in Integral Transforms and Analysis of Differential Equations with Applications
  51. Mathematical analysis of a MERS-Cov coronavirus model
  52. Rapid exponential stabilization of nonlinear continuous systems via event-triggered impulsive control
  53. Novel soliton solutions for the fractional three-wave resonant interaction equations
  54. The multistep Laplace optimized decomposition method for solving fractional-order coronavirus disease model (COVID-19) via the Caputo fractional approach
  55. Special Issue on Problems, Methods and Applications of Nonlinear Analysis
  56. Some recent results on singular p-Laplacian equations
  57. Infinitely many solutions for quasilinear Schrödinger equations with sign-changing nonlinearity without the aid of 4-superlinear at infinity
  58. Special Issue on Recent Advances for Computational and Mathematical Methods in Scientific Problems
  59. Existence of solutions for a nonlinear problem at resonance
  60. Asymptotic stability of solutions for a diffusive epidemic model
  61. Special Issue on Computational and Numerical Methods for Special Functions - Part I
  62. Fully degenerate Bernoulli numbers and polynomials
  63. Wigner-Ville distribution and ambiguity function associated with the quaternion offset linear canonical transform
  64. Some identities related to degenerate Stirling numbers of the second kind
  65. Two identities and closed-form formulas for the Bernoulli numbers in terms of central factorial numbers of the second kind
  66. λ-q-Sheffer sequence and its applications
  67. Special Issue on Fixed Point Theory and Applications to Various Differential/Integral Equations - Part I
  68. General decay for a nonlinear pseudo-parabolic equation with viscoelastic term
  69. Generalized common fixed point theorem for generalized hybrid mappings in Hilbert spaces
  70. Computation of solution of integral equations via fixed point results
  71. Characterizations of quasi-metric and G-metric completeness involving w-distances and fixed points
  72. Notes on continuity result for conformable diffusion equation on the sphere: The linear case
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