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Normalized solutions to nonlinear Schrödinger equations with mixed fractional Laplacians

  • Anmin Mao EMAIL logo and Changchang Yan
Published/Copyright: July 25, 2025

Abstract

We consider the following elliptic problem with mixed local and nonlocal operators:

( Δ ) s 1 u + ( Δ ) s 2 u + λ u = f ( u ) in R N , R N u ( x ) 2 d x = c , u H s 2 ( R N ) ,

where 0 < s 1 < s 2 < 1 , ( Δ ) s i is fractional Laplacian. We get a sharp description of the existence and nonexistence of the global minimizer on the mass constraint, which is called energy ground state. By using of concentration-compactness principle, we show that there exists a constant c 0 such that there exists an energy ground state if c > c 0 and there exists no energy ground state if 0 < c < c 0 . Some almost critical conditions which determine c 0 = 0 or c 0 > 0 are established. In the case c = c 0 , under certain conditions, we establish the existence result of energy ground state. Finally, by using the method of mountain pass type characterization, we show that any energy ground state is action ground state of the corresponding action functional.

MSC 2010: 35J05; 35J20; 35J60

1 Introduction and main results

In this article, we study the following elliptic problem with local and nonlocal operators:

(1.1) ( Δ ) s 1 u + ( Δ ) s 2 u + λ u = f ( u ) in R N , R N u ( x ) 2 d x = c , u H s 2 ( R N ) ,

where N 2 , f C ( R , R ) , 0 < s 1 < s 2 < 1 , c > 0 is given constant and λ R is considered as Lagrange multiplier. The fractional Laplacian is given by

( Δ ) s i u C N , s i R N u ( x ) u ( y ) x y N + 2 s i d y , i = 1 , 2 ,

with C N , s i 2 2 s i π N 2 s i Γ ( N + 2 s i 2 ) Γ ( 1 s i ) , which Γ is the Gamma function [21].

A strong motivation to study problem (1.1) is that it arises in the search of standing waves for nonlinear scalar field equations of the form

(1.2) i t ψ ( t , x ) + ( Δ ) s 1 ψ ( t , x ) + ( Δ ) s 2 ψ ( t , x ) = f ( ψ ( t , x ) ) ,

where ( t , x ) R + × R N , λ R , 0 < s 1 < s 2 < 1 and ( Δ ) s i is fractional Laplacian. By standing waves, we know that solutions to (1.2) is of special form ψ ( t , x ) = e i λ t u ( x ) , where u H s 2 ( R N ) and λ R is the frequency.

The study of such type of equations, which already saw major contributions 40 years ago, now lies at the root of several models linked with current physical applications. Equation (1.2) arises as superposition of classical random walk and a Lévy flight [3]. It showed that mixed fractional Laplacian imitates population dynamics in [8], what is more, equation (1.2) simulates some cardiac abnormalities caused by arterial problems. Those heart problems can be modeled thanks to the composition of two to five mixed fractional Laplacians since it is not necessarily the same anomaly in the five arteries [19,20]. Equation (1.2) also plays an important role in other fields (such as nonlinear optics, the theory of water waves, and so on).

An important feature of problem (1.1) is that the L 2 -norms of the wave functions are conserved. For these equations, finding solutions with a prescribed L 2 -norm is particularly relevant since this quantity is preserved along the time evolution, which have important physical significance: in Bose-Einstein condensates, for example, prescribed L 2 -norms represent the number of particles of each component; in the nonlinear optics framework, prescribed L 2 -norms represent the power supply. Furthermore, if the solutions correspond to energy ground states, then, in most situations, it is possible to prove that the associated standing waves are orbitally stable.

Fractional Schrödinger equations have attracted scientists from different fields in the past few decades. Motivated by various applications, there has been increasing attention to equations like (1.1) on the existence and symmetry of minimizers, positive solutions, radial sign-changing solutions, regularity results and Cauchy problem: Correria and Figueiredo [4] studied the following problem:

(1.3) ( Δ ) s u + λ u = u p u in Ω ,

where Ω R N is unbounded, Ω , 0 < p < 2 s * = 2 N N 2 s , 0 < s < 1 , λ R + , and N > 2 s , and the authors showed that equation (1.3) has at least one positive solution by using variational method together with Brouwer degree theory. What is more, Su et al. [24] obtained that solution is unique and actually belongs to C 1 , α to equation like (1.3) when α ( 0 , 1 ) and s ( 0 , 1 2 ] . In [23], by using the Brouwer degree theory and the variational method, Wang and Zhou proved the existence of a radial sign-changing solution. In addition, Frank et al. [10] showed that there exists a unique positive radial energy ground state depending on parameters λ = 1 and 0 < p < 2 s * . Recently, Luo and Zhang [18] studied the following problem:

(1.4) ( Δ ) s u = λ u + μ u q u + u p u in R N

where 0 < p < 2 s * , N 2 , s ( 0 , 1 ) , and q < p , and the authors proved that equation (1.4) has a unique positive radial energy ground state if 0 < p < 2 + 4 s N and μ = 0 . Furthermore, there exists a unique positive radial energy ground state if μ > 0 and 2 < q < p < 2 + 4 s N , and there no exists energy ground state if μ < 0 . Here, we also want to mention several papers related to this topic [6,7].

Another topic that has increasing received interest in recent years is the existence of energy ground state of equation like (1.1). Luo and Hajaiej [17] studied the following issue:

(1.5) ( Δ ) s 1 u + ( Δ ) s 2 u + λ u = u p u in R N ,

where N 1 , 0 < p < 4 s 2 N and 0 < s 1 < s 2 < 1 , which is considered as power nonlinearity with mass-subcritical case, and the authors proved the existence of the energy ground state with p ( 0 , 4 s 1 N ) by using the method of scaling argument. Recently, Chergui et al. [5] showed existence and dynamics of normalized solutions to nonlinear Schrödinger equations with mixed fractional Laplacians. However, there are no works on the general nonlinearity f .

To our best knowledge, as f in problem (1.1) is not homogeneous, the scaling argument used in [17,18] is no longer used, there are few results on the existence of ground states to mass-constrained problem (1.1) with general nonlinearity f . Our first purpose is to study the existence of ground states with prescribed L 2 -norms to problem (1.1), and to explore the relationship between the energy ground state and action ground state is our second purpose.

It is known that problem (1.1) has variational structure. We introduce the fractional Sobolev space for s i ( 0 , 1 )

H s i ( R N ) u : R N R u L 2 ( R N ) , R N × R N u ( x ) u ( y ) 2 x y N + 2 s i d x d y < ,

and for u H s i ( R N ) , denote

s i u 2 2 R N × R N u ( x ) u ( y ) 2 x y N + 2 s i d x d y , i = 1 , 2 .

For 0 < s 1 < s 2 < 1 , N 2 , according to [11], H s 2 ( R N ) H s 1 ( R N ) :

H s 2 ( R N ) H s 1 ( R N ) = H s 2 ( R N ) .

Consider the minimization problem

(1.6) E c inf u S c I ( u ) ,

where the energy function I ( u ) is defined by

(1.7) I ( u ) 1 2 s 1 u 2 2 + 1 2 s 2 u 2 2 R N F ( u ) d x , u H s 2 ( R N ) ,

F ( t ) = 0 t f ( τ ) d τ and

S c u H s 2 ( R N ) R N u ( x ) 2 d x = c .

A minimizer of (1.6) is often called the energy ground state and E c is ground state energy. And the solution of (1.1) be considered as critical points of I under the constraint.

In this article, our first task is to obtain the existence of the energy ground state to problem (1.1). We shall assume f C ( R , R ) satisfies the following hypotheses.

  1. lim t 0 f ( t ) t = 0 .

  2. When N 3 ,

    limsup t f ( t ) t 2 s 2 * 1 < ,

    when N = 2 ,

    lim t f ( t ) e α t 2 2 s 2 = 0 , α > 0 ;

    and also for N 2 ,

    limsup t f ( t ) t t 2 + 4 s 2 N 0 ,

    where 2 s 2 * = 2 N N 2 s 2 .

  3. There exists t 0 > 0 such that F ( t 0 ) > 0 .

Definition 1.1

For the given λ > 0 , a nontrivial solution w H s 2 ( R N ) of the problem

(1.8) ( Δ ) s 1 u + ( Δ ) s 2 u + λ u = f ( u ) in R N , u H s 2 ( R N )

is called action ground state if it attains the infimum of the action functional

J λ ( u ) I ( u ) + 1 2 λ R N u 2 d x

among all the nontrivial solutions.

Nehari manifold related with J λ ( u ) is defined as follows:

N λ { u H s 2 ( R N ) \ { 0 } J λ ( u ) u = 0 } .

In what follows, we state our first main result, in which we obtain a sharp description of the existence and nonexistence of the global minimizer on the mass constraint.

Theorem 1.1

Suppose N 2 , f satisfies ( f 1 ) ( f 3 ) , then the following results hold.

  1. There exists c 0 [ 0 , ) such that

    E c = 0 i f 0 < c c 0 , E c < 0 i f c > c 0 .

  2. E c inf u S c I ( u ) > , c E c is nonincreasing and continuous.

  3. When c > c 0 , the global infimum E c is achieved.

  4. When 0 < c < c 0 , there no exists global minimizer, namely, E c is not achieved.

Remark 1.1

According to Theorem 1.1(iii), we obtain that any minimizing sequence of (1.6) is convergent in H s 2 ( R N ) by up to a subsequence and up to translation in R N . Meanwhile we obtain a sharp description of the existence and nonexistence of the minimizer based on Theorem 1.1. When 0 < c < c 0 , the global infimum E c is not achieved. But it does not mean that there are no positive critical points. If the v S c is energy ground state of the E c , then associated Lagrange multiplier λ = λ ( v ) is positive. In fact, according to Pohožaev identity corresponding to (1.1),

(1.9) P ( v ) N 2 s 1 2 N R N s 1 v 2 d x + N 2 s 2 2 N R N s 2 v 2 d x + 1 2 λ R N v 2 d x R N F ( v ) d x = 0 ,

and I ( v ) = E c 0 , we obtain

0 I ( v ) = I ( v ) P ( v ) = s 1 N R N s 1 v 2 d x + s 2 N R N s 2 v 2 d x 1 2 λ c ,

and thus, λ > 0 .

To prove the solvability of the (1.6), we shall make use of concentration-compactness principle which is introduced [15,16]. First, under the ( f 1 )–( f 2 ), we found that energy functional I is coercive and bounded from the below on the sphere S c . In addition, we show that the vanishing scenario is not valid by the fact that E c is negative for given c > c 0 . Finally, energy functional I satisfies subadditivity condition, the dichotomy case does not hold truly. To derive the sharp threshold mass c 0 , we need the monotonicity and continuity of E c , which is proved in Lemma 2.5. Regarding the condition ( f 3 ) , it plays a crucial role in Lemma 2.5 ( v ) to show that E c < 0 holds when c is large enough.

Due to the behavior of f near 0 plays an important role to prove whether c 0 > 0 holds, thus we have the following results.

Theorem 1.2

Assume that N 2 , f satisfies ( f 1 ) ( f 3 ) , the following results hold.

  1. c 0 = 0 if liminf t 0 F ( t ) t 2 + 4 s 2 N = .

  2. c 0 > 0 if limsup t 0 F ( t ) t 2 + 4 s 2 N < .

Remark 1.2

In [11], Jeanjean and Lu obtained that there exist global minimizers by using concentration-compactness principle as presented in [15,16], and to obtain sharp threshold mass c 0 , the authors showed that E c is monotone and continuous. However, in our article, as I ( u ) is not bounded above by using the method of [11], this is challenging to obtain E c < 0 when c is large enough. Compared to [11], we make use of the cut-off function to obtain E c < 0 when c is large enough and demonstrate E c 0 by using different scaling functions which is uncomplicated.

In the case c = c 0 , it is still unknown whether there exists a global minimum for E c 0 . In what follows, we give a positive answer in Theorem 1.4. Before proving that E c 0 is achieved, we need in Theorem 1.3 to discuss compactness property of minimizing sequences with respect to E c 0 .

Theorem 1.3

Assume that N 2 , f satisfies ( f 1 ) ( f 3 ) , and c > 0 . If { u n } is a minimizing sequence with respect to E c , one of the following states holds.

  1. lim n sup z R N B ( z , 1 ) u n 2 d x = 0 .

  2. Taking a subsequence if necessary, there exist u S c and a family { y n } R N satisfying u n ( y n ) u in H s 2 ( R N ) . In particular, u is energy ground state.

On the basis of the aforementioned compactness properties, we obtain the following existence results.

Theorem 1.4

Assume that N 2 , f satisfies ( f 1 ) ( f 3 ) , then the following results hold.

  1. If limsup t 0 F ( t ) t 2 + 4 s 2 N 0 , then the global infimum E c 0 is achieved.

  2. If there exists positive constants C and t 1 such that F ( t ) = C t 2 + 4 s 2 N if t t 1 , then E c 0 is achieved.

Remark 1.3

First, to prove the convergence of minimizing sequence, the splitting property lim n I ( u n + v ) = lim n I ( u n ) + I ( v ) plays an important role. Different from [22], due to the existence of fractional Laplacian, it is challenging to obtain splitting result by using the method of [22]. Fortunately, we adopt the idea given by Luo and Hajaiej in [17] to obtain the aforementioned splitting result.

Second, under the certain condition that is enlarged for [22], we show that E c 0 is achieved by using of concentration-compactness principle of Lion [15,16], and in this respect, our approach is different from Luo and Hajaiej in [17], where the nonlinearity f is homogeneous and scaling arguments played a major role.

It is now known that there may exist action ground solutions, which are not energy ground states. Remains, however, the possibility that any energy ground state is a action ground solution. We make this issue precise by stating the following problem.

Theorem 1.5

Assume that N 2 , f satisfies ( f 1 ) ( f 3 ) , λ is the Lagrange multiplier corresponding to an arbitrary minimizer v S c of (1.6), then the following results hold.

  1. Any minimizer v S c of (1.6) is action ground state. In particular,

    J λ ( w ) = E c + 1 2 λ c .

  2. Any action ground state w H s 2 ( R N ) is minimizer of (1.6), and the following results hold

    w 2 2 = c , I ( w ) = E c ,

    where λ { λ ( v ) v S c is a m i n i m i z e r o f ( 1.6 ) } .

Remark 1.4

Different from [9] where Dovetta et al. showed that energy ground state is action ground state, which depending on the function t f ( t ) t is nondecreasing on ( 0 , ) , we here make no monotonic hypothesis.

The idea and the core of the proof of Theorem 1.5 is to use mountain pass type characterization of the nontrivial solutions (Lemma 2.3) to show that any energy ground state is action ground state of the corresponding action functional. Such a characterization is of independent interest. Indeed, a related characterization of least action solutions proved to be very fruitful to control the possible loss of compactness at infinity in nonautonomous problems [2,13,14] in that direction. The present version, which highlights the role of the L 2 mass, seems to have not been formulated ealier.

This article is organized as follows. In Section 2, we give some nondegenerate results of equation (1.1) and necessary lemmas. Section 3 is devoted to show the existence of minimizer of I , and give the proof of Theorems 1.1, 1.2, 1.3, and 1.4. Section 4 is devoted to the relationship between action ground state and energy ground state and gives the proof of Theorem 1.5.

2 Preliminaries

In this section, we use some notations for convenience.

  • u q ( R N u q ) 1 q for 1 q < and u L q ( R N ) .

  • C , C i denote (possibly different) various positive constant.

  • (Gagliardo-Nirenberg inequality)

    u p + 2 p + 2 B ( p , N , s ) u 2 p + 2 N p 2 s s u 2 N p 2 s , u H s ( R N ) ,

    where B ( p , N , s ) is optimal constant, N 2 and 0 < p < 4 s 2 ( N 2 s 2 ) .

In what follows, we state the well-known Brézis-Lieb lemma [1] and its fractional version given by Luo and Hajaiej in their recent work, see [17, Lemma A.1].

Lemma 2.1

[1] Assume that { u n } is bounded in L p ( R N ) , u L p ( R N ) and u n u a.e. R N , then

lim n ( u n p p u n u p p ) = u p p .

Lemma 2.2

[17] Assume that { u n } H s ( R N ) and u H s ( R N ) , being such that

u n u i n H s ( R N ) ,

then

lim n ( s u n 2 2 s ( u n u ) 2 2 ) = s u 2 2 .

We note that the core of the proof of Theorem 1.5 is a mountain pass type characterization of the nontrivial solutions, see Lemma 2.3. During the proof of Lemma 2.3, we adopt the idea from [2] in which Byeon et al. studied standing waves for nonlinear Schrödinger equations with a general nonlinearity, and such idea has also been used by Jeanjean and Lu in [11] to study the existence of global minimizers for a mass constrained problem.

Lemma 2.3

Suppose that N 2 , λ > 0 , and f satisfies ( f 1 ) and ( f 2 ) , and w H s 2 ( R N ) is nontrivial critical point of J λ . Then, for arbitrary δ > 0 and M > 0 , there exist a constant T = T ( w , δ , M ) > 0 and a continuous path ζ : [ 0 , T ] H s 2 ( R N ) such that

  1. ζ ( 0 ) = 0 , J λ ( ζ ( T ) ) < 1 , max t [ 0 , T ] J λ ( ζ ( t ) ) = J λ ( w ) ;

  2. ζ ( θ ) = w for some θ ( 0 , T ) , and

    J λ ( ζ ( t ) ) < J λ ( w )

    for any t [ 0 , T ] satisfying ζ ( t ) w H s 2 ( R N ) δ ;

  3. c ( t ) ζ ( t ) 2 2 is continuous and strictly increasing with c ( T ) > M .

Proof

Case 1. N 3 . Define

ζ ( t ) w . t , if t > 0 , 0 , if t = 0 , c ( t ) ζ ( t ) 2 2 .

Note that c ( t ) = t N w 2 2 , by Pohožaev identity (1.9), we obtain

J λ ( ζ ( t ) ) = I ( ζ ( t ) ) + 1 2 λ R N ζ ( t ) 2 d x = 1 2 s 1 ζ ( t ) 2 2 + 1 2 s 2 ζ ( t ) 2 2 + 1 2 λ R N ζ ( t ) 2 d x R N F ( ζ ( t ) ) d x = 1 2 s 1 w x t 2 2 + 1 2 s 2 w x t 2 2 + 1 2 λ R N w x t 2 d x R N F w x t d x = 1 2 t N 2 s 1 s 1 w 2 2 + 1 2 t N 2 s 2 s 2 w 2 2 + 1 2 λ t N R N w 2 d x t N R N F ( w ) d x = 1 2 ( t N 2 s 1 N 2 s 1 N t N ) s 1 w 2 2 + 1 2 ( t N 2 s 2 N 2 s 2 N t N ) s 2 w 2 2 ,

and

d d t J λ ( ζ ( t ) ) = 1 2 ( ( N 2 s 1 ) t N 2 s 1 1 ( N 2 s 1 ) t N 1 ) s 1 w 2 2 + 1 2 ( ( N 2 s 2 ) t N 2 s 2 1 ( N 2 s 2 ) t N 1 ) s 2 w 2 2 = 1 2 ( N 2 s 1 ) t N 2 s 1 1 ( 1 t 2 s 1 ) s 1 w 2 2 + 1 2 ( N 2 s 2 ) t N 2 s 2 1 ( 1 t 2 s 2 ) s 2 w 2 2 .

It is clear that the function J λ ( ζ ( t ) ) has a unique maximum at t = 1 and d d t J λ ( ζ ( t ) ) as t . Therefore, for any M > 0 , there exists a sufficiently large constant T = T ( w , δ , M ) > 0 such that the continuous path ζ : [ 0 , T ] H s 2 ( R N ) satisfies (i)–(iii) of Lemma 2.3.

Case 2. N = 2 . For the given ω H s 2 ( R 2 ) , we define g : ( θ , s ) ( 0 , + ) × ( 0 , + ) R as follows:

g ( θ , s ) J λ θ w x s = 1 2 s 1 θ w x s 2 2 + 1 2 s 2 θ w x s 2 2 + 1 2 λ R 2 θ w x s 2 d x R 2 F θ w x s d x = 1 2 s 2 2 s 1 θ 2 s 1 w 2 2 + 1 2 s 2 2 s 2 θ 2 s 2 w 2 2 + 1 2 λ s 2 θ 2 w 2 2 s 2 R 2 F ( θ w ) d x ,

then

g s ( θ , s ) = ( 1 s 1 ) s 1 2 s 1 θ 2 s 1 w 2 2 + ( 1 s 2 ) s 1 2 s 2 θ 2 s 2 w 2 2 + λ θ 2 s w 2 2 2 s R 2 F ( θ w ) d x , g θ ( θ , s ) = s 2 2 s 1 θ s 1 w 2 2 + s 2 2 s 2 θ s 2 w 2 2 + λ θ s 2 w 2 2 s 2 R 2 f ( θ w ) w d x .

It follows from Nehari and Pohožaev identity (1.9) that

( 1 s 1 ) s 1 w 2 2 + ( 1 s 2 ) s 2 w 2 2 + λ R 2 w 2 d x 2 R 2 F ( w ) d x = 0 ,

R 2 f ( w ) w d x = s 1 w 2 2 + s 2 w 2 2 + λ R 2 w 2 d x ,

thus

R 2 f ( θ w ) w d x = θ s 1 w 2 2 + θ s 2 w 2 2 + λ θ R 2 w 2 d x ,

and

g θ ( θ , 1 ) = θ s 1 w 2 2 + θ s 2 w 2 2 + λ θ R 2 w 2 d x R 2 f ( θ w ) w d x = 0 .

Define H : H s 2 ( R 2 ) R as follows:

H ( w ) 1 2 ( 1 s 1 ) s 1 w 2 2 1 2 ( 1 s 2 ) s 2 w 2 2 1 2 λ R 2 w 2 d x + R 2 F ( w ) d x ,

it is clear that

H ( θ w ) = 1 2 ( 1 s 1 ) θ 2 s 1 w 2 2 1 2 ( 1 s 2 ) θ 2 s 2 w 2 2 1 2 λ θ 2 R 2 w 2 d x + R 2 F ( θ w ) d x ,

and there exist two positive constant 0 < θ 1 < 1 < θ 2 such that for any θ [ θ 1 , θ 2 ] ,

θ H ( θ w ) = ( 1 s 1 ) θ s 1 w 2 2 ( 1 s 2 ) θ s 2 w 2 2 λ θ R 2 w 2 d x + R 2 f ( θ w ) w d x = θ s 1 s 1 w 2 2 + θ s 2 s 2 w 2 2 > 0 ,

and

(2.1) H ( θ w ) = < 0 , if θ [ θ 1 , 1 ) , 0 , if θ = 1 , > 0 , if θ ( 1 , θ 2 ] .

By the definition of H ,

g s ( θ , s ) = 2 s H ( θ w ) d x + ( 1 s 1 ) s 1 2 s 1 θ 2 s 1 w 2 2 s ( 1 s 1 ) θ 2 s 1 w 2 2 + ( 1 s 2 ) s 1 2 s 2 θ 2 s 2 w 2 2 s ( 1 s 2 ) θ 2 s 2 w 2 2 = 2 s H ( θ w ) + ( 1 s 1 ) s 1 2 s 1 ( 1 s 2 s 1 ) θ 2 s 1 w 2 2 + ( 1 s 2 ) s 1 2 s 2 ( 1 s 2 s 2 ) θ 2 s 2 w 2 2 ,

as a direct consequence

(2.2) g s ( θ , s ) = > 0 , if ( θ , s ) [ θ 1 , 1 ) × ( 0 , 1 ] , > 0 , if ( θ , s ) { 1 } × ( 0 , 1 ) , 0 , if ( θ , s ) { 1 } × { 1 } , < 0 , if ( θ , s ) { 1 } × ( 1 , ) , < 0 , if ( θ , s ) ( 1 , θ 2 ] × [ 1 , ) .

What is more, noting that

g θ ( 1 , s ) = s 2 2 s 1 ( 1 s 2 s 1 ) s 1 w 2 2 + s 2 2 s 2 ( 1 s 2 s 2 ) s 2 w 2 2 + ( 1 s 2 ) w 2 2 ,

thus, for any s 1 , there exists ζ s ( 0 , 1 )

(2.3) g θ ( θ , s ) = > 0 , if ( θ , s ) [ 1 ζ s , 1 + ζ s ] × ( 0 , 1 ) , < 0 , if ( θ , s ) [ 1 ζ s , 1 + ζ s ] × ( 1 , ) .

In addition, there exists a sufficiently small s 0 ( 0 , 1 ) such that for ( θ , s ) ( 0 , 1 ] × ( 0 , s 0 ] ,

(2.4) g θ ( θ , s ) = s 2 2 s 1 ( 1 s 2 s 1 ) θ s 1 w 2 2 + s 2 2 s 2 θ ( 1 s 2 s 2 ) s 2 w 2 2 + ( 1 s 2 ) θ w 2 2 = θ ( s 2 2 s 1 ( 1 s 2 s 1 ) s 1 w 2 2 + s 2 2 s 2 ( 1 s 2 s 2 ) s 2 w 2 2 + ( 1 s 2 ) w 2 2 ) > 0 .

For the given ε > 0 , define

η ( t ) ( θ ( t ) , s ( t ) ) : [ 0 , ) R 2

the piecewise linear curve joining

(2.5) ( 0 , s 0 ) ( 1 θ 0 , s 0 ) ( 1 θ 0 , 1 ε ) ( 1 , 1 ε ) ( 1 , 1 ) ( 1 , 1 + ε ) ( 1 + θ 0 , 1 + ε ) ( 1 + θ 0 , ) ,

where θ 0 is chosen such that 1 θ 0 [ θ 1 , 1 ) and 1 + θ 0 [ 1 , θ 2 ) , and each segment is horizontal or vertical. Let 0 t 0 < t 1 < < t 6 < t 7 be such that for each i = 0, …, 7, η ( t i ) is an end point of a linear segment of the piecewise linear curve η (Figure 1).

We define

ζ ( t ) θ ( t ) w s ( t ) .

Then we obtain that J λ ( ζ ( t ) ) = g ( η ( t ) ) is the strictly increasing on ( t 0 , t 1 ) , ( t 1 , t 2 ) , ( t 2 , t 3 ) , ( t 3 , t 4 ) by (2.2), (2.3), (2.4) and strictly decreasing on ( t 4 , t 5 ) , ( t 5 , t 6 ) , ( t 6 , t 7 ) by (2.3). It is also clear that the function of J λ has maximum at t = t 4 . What is more, by (2.1),

(2.6) J λ ( ζ ( t ) ) = 1 2 ( 1 + θ 0 ) 2 s 2 2 s 1 s 1 w 2 2 + 1 2 ( 1 + θ 0 ) 2 s 2 2 s 2 s 2 w 2 2 + 1 2 λ ( 1 + θ 0 ) 2 w 2 2 s 2 R 2 F ( ( 1 + θ 0 ) w ) d x = 1 2 ( 1 + θ 0 ) 2 s 2 2 s 1 s 1 w 2 2 1 2 ( 1 + θ 0 ) 2 s 2 ( 1 s 1 ) s 1 w 2 2 + 1 2 ( 1 + θ 0 ) 2 s 2 2 s 2 s 2 w 2 2 1 2 ( 1 + θ 0 ) 2 s 2 ( 1 s 2 ) s 2 w 2 2 s 2 R 2 H ( ( 1 + θ 0 ) w ) d x ( t ) .

Finally we obtain that c ( t ) = ζ ( t ) 2 2 = θ 2 ( t ) s 2 ( t ) w 2 2 is strictly increasing and

(2.7) c ( t ) = ( 1 + θ 0 ) 2 s 2 ( t ) w 2 2 as t .

Therefore, for any M > 0 , by (2.6) and (2.7), we see that there exists a sufficiently large constant T = T ( w , δ , M ) > 0 such that

J λ ( ζ ( T ) ) < 1 and c ( T ) > M ,

the continuous path ζ : [ 0 , T ] H s 2 ( R 2 ) is desired and satisfies Lemma 2.4.□

Figure 1 
               Functional relationship.
Figure 1

Functional relationship.

As a necessary preparation, we present another lemma.

Lemma 2.4

Suppose that N 2 , f C ( R , R ) satisfies ( f 1 ) and ( f 2 ) , the following statements hold.

  1. Let { u n } be a bounded sequence in H s 2 ( R N ) ,

    lim n R N F ( u n ) d x = 0

    if lim n u n L ( R N ) = 0 , and

    limsup n R N F ( u n ) d x 0

    if lim n u n q = 0 , for the arbitrary q ( 2 , 2 s 2 * ) .

  2. There exists C = C ( f , N , c ) > 0 such that

    I ( u ) 1 4 s 2 u 2 2 + 1 2 s 1 u 2 2 C ( f , N , c ) ,

    for any u H s 2 ( R N ) satisfying u 2 2 c .

  3. For any c > 0 , there exists ρ = ρ ( N , c ) > 0 small enough such that for all u H s 2 ( R N ) satisfying both u 2 2 c and s 2 u 2 ρ , we obtain

    (2.8) I ( u ) 1 4 s 2 u 2 2 + 1 2 s 1 u 2 2 i f limsup t 0 F ( t ) t 2 + 4 s 2 N 0 .

Proof

(i) If lim n u n L ( R N ) = 0 .

Case 1. N 3 . According to the assumption ( f 1 ) and ( f 2 ) , for any ε > 0 , there exists a positive constant C ( f , ε ) , which depends on ε and f such that

F ( t ) ε t 2 + C ( f , ε ) t 2 s 2 * 1 .

Due to the boundedness of { u n } H s 2 ( R N ) , there exists a constant M > 0 such that

R N F ( u n ) d x ε u n 2 2 + C ( f , ε ) u n 2 s 2 * 1 2 s 2 * 1 ε M + M u n L ( R N ) ,

which gives the desired results.

Case 2. N = 2 . According to assumption ( f 1 ) and ( f 2 ) , for any ε > 0 , there exists a positive constant C ( f , ε ) , which depends on ε and f such that

F ( t ) ε t 2 + C ( f , ε ) t 2 + 2 s 2 .

Due to the boundedness of { u n } H s 2 ( R N ) , there exists a constant M > 0 such that

R 2 F ( u n ) d x ε u n 2 2 + C ( f , ε ) u n 2 + 2 s 2 2 + 2 s 2 ε M + M u n L ( R 2 ) ,

which gives the desired results.

If lim n u n q = 0 , for the arbitrary q ( 2 , 2 s 2 * ) .

According to the assumption ( f 1 ) and ( f 2 ) , for any ε > 0 , there exists a positive constant C ( f , ε ) , which depends on ε and f such that

F ( t ) ε t 2 + C ( f , ε ) t 2 + 4 s 2 N .

For the { u n } H s 2 ( R 2 ) , we obtain

R 2 F ( u n ) d x ε u n 2 2 + C ( f , ε ) u n 2 + 4 s 2 N 2 + 4 s 2 N ε M + ε ,

which gives the desired results.

(ii) According to ( f 1 ) and ( f 2 ) , it follows that

R N F ( u ) d x C ( f , ε ) u 2 2 + ε u 2 + 4 s 2 N 2 + 4 s 2 N .

By the Gagliardo-Nirenberg inequality, we have

R N F ( u ) d x C ( f , ε ) u 2 2 + ε C N c 2 s 2 N s 2 u 2 2 ,

so, for ε > 0 satisfying ε C N C 2 s 2 N 1 4 , one has

I ( u ) 1 4 s 2 u 2 2 + 1 2 s 1 u 2 2 C ( f , N , c ) .

(iii) Case 1. N = 2 . For the given α = 1 c + 1 and arbitrary ε > 0 , by ( f 2 ) , there exist C ε > 0 and R > 1 such that

f ( t ) C ε t s 2 2 s 2 + 2 + 4 s 2 e α t 2 2 s 2 2 , t > R .

Since, for t > 0

0 t τ s 2 2 s 2 + 2 + 4 s 2 e α τ 2 2 s 2 2 d τ = c 1 α 0 t τ 2 + 4 s 2 d ( e α τ 2 2 s 2 2 1 ) = c 1 α t 2 + 4 s 2 ( e α t 2 2 s 2 2 1 ) c 1 α 0 t ( 2 + 4 s 2 ) τ ( 2 + 4 s 2 1 ) ( e α τ 2 2 s 2 2 1 ) d τ c 1 α t 2 + 4 s 2 ( e α t 2 2 s 2 2 1 ) ,

thus,

F ( t ) 1 α C ε ( e α t 2 2 s 2 2 1 ) t 2 + 4 s 2 + ε t 2 + 2 s 2 .

By Moser-Trudinger inequality, for some C 1 > 0 ,

R 2 ( e α u 2 2 s 2 1 ) d x C 1 2 , for any u 2 2 c and s 2 u 2 ρ .

For any u H s 2 ( R N ) with u 2 2 c and s 2 u 2 ρ , using also Hölder inequality and Gagliardo-Nirenberg inequality, we have

R 2 F ( u ) d x 1 α C ε R 2 u 2 + 4 s 2 ( e α t 2 2 s 2 2 1 ) d x + ε R 2 u 2 + 2 s 2 d x ε R 2 u 2 + 2 s 2 d x + 1 α C ε R 2 u 2 + 4 s 2 d x 1 2 R 2 ( e α t 2 2 s 2 2 1 ) 2 d x 1 2 ε C c s 2 u 2 2 + C 1 C 2 C ε c 1 2 ( c + 1 ) R 2 s 2 u 2 d x 3 2 ( ε C c + C 1 C 2 C ε c 1 2 ( c + 1 ) ρ ) R 2 s 2 u 2 d x 1 4 R 2 s 2 u 2 d x ,

where ρ ( 0 , 1 ) be enough small, C and C 2 > 0 are independent of c , ε , δ , and u . Thus,

I ( u ) 1 4 s 2 u 2 2 + 1 2 s 1 u 2 2 .

Case 2. N 3 . By using ( f 1 ) and ( f 2 ) , for any u S c , we obtain

F ( t ) ε t 2 + 4 s 2 N + C ε t 2 N N 2 s 2 .

By Gagliardo-Nirenberg inequality, then

R N F ( u ) d x ε R N u 2 + 4 s 2 N d x + C ε R N u 2 N N 2 s 2 d x ε C N u 2 4 s 2 N R N s 2 u 2 d x + C N C ε R N s 2 u 2 d x N N 2 s 2 ε C N c 2 s 2 N + C ε C N R N s 2 u 2 d x 2 s 2 N 2 s 2 R N s 2 u 2 d x ,

set ε = 1 8 C N c 2 s 2 N , ρ = 1 8 C N C ε N 2 s 2 4 s 2 , which implies (2.8) holds.□

Firstly, we prove the following Lemma 2.5, which introduces the properties of E c .

Lemma 2.5

Assume that f C ( R , R ) satisfies ( f 1 ) ( f 3 ) , then the following results hold.

  1. < E c 0 for any c > 0 .

  2. E a + b E a + E b .

  3. The function c E c is nonincreasing and continous on ( 0 , ) .

  4. E c < 0 when c is large enough.

Proof

(i) According to Lemma 2.4 (ii), I is bounded below on S c ; thus, E c > . For given u S c L ( R N ) , we consider the scaling function u λ ( x ) λ N 2 u ( λ x ) .

Since

u λ ( x ) L ( R N ) = sup λ 2 N u ( λ x ) 0 as λ 0 ,

thus, by Lemma 2.4 (i), we obtain

lim λ 0 R N F ( u λ ) d x = 0 .

It is clear that s i u λ 2 2 = λ 2 s i s i u 2 2 i = 1, 2, which means

lim λ 0 s i u λ 2 2 = 0 , i = 1 , 2 .

In view of (1.6) and (1.7), we have lim λ 0 I ( u ) = 0 and E c 0 .

(ii) By the definition of E a and E b , we obtain there exist u S a C 0 ( R N ) and v S b C 0 ( R N ) such that I ( u ) E a + ε , I ( v ) E b + ε . We assume that supp v supp u = , then

E a + b I ( u + v ) = I ( u ) + I ( v ) E a + E b + 2 ε .

Due to ε is arbitrary, thus E a + b E a + E b holds.

(iii) In view of (i) and (ii), it is clear that E a + b E a + E b E a , thus c E c is nonincreasing.

To prove the continuity, we set for the given u S 1 and c > 0 the real function

ψ u ( c ) = 1 c I u c 1 N x = 1 c 1 2 s 1 u ( c 1 N x ) 2 2 + 1 2 s 2 u ( c 1 N x ) 2 2 R N F ( u ( c 1 N x ) ) d x = 1 2 c 2 s 1 N s 1 u 2 2 + 1 2 c 2 s 2 N s 2 u 2 2 R N F ( u ) d x .

By the definition of E c , it follows that

E c c = inf u S 1 ψ u ( c ) .

Since ψ u ( c ) is a convex function of c , it follows that E c c is continuous at c > 0 , so E c is continuous.

(iv) Let u H s 2 ( R N ) , to prove E c < 0 , for the given t 0 , we define

u a ( x ) t 0 , if x < a , t 0 ( a + 1 x ) , if a x < a + 1 . 0 if x a + 1

and

A 1 B ( 0 , a + 1 ) , A 2 B ( 0 , a ) , A 3 B ( 0 , a + 1 ) \ B ( 0 , a ) , A 4 B ( 0 , a + 1 ) × B ( 0 , a + 1 ) A 5 B ( 0 , a ) × B ( 0 , a ) , A 6 B ( 0 , a ) × [ B ( 0 , a + 1 ) \ B ( 0 , a ) ] , A 7 [ B ( 0 , a + 1 ) \ B ( 0 , a ) ] × B ( 0 , a ) , A 8 [ B ( 0 , a + 1 ) \ B ( 0 , a ) ] × [ B ( 0 , a + 1 ) \ B ( 0 , a ) ] .

It is easy to calculate

I ( u a ) = 1 2 s 1 u a 2 2 + 1 2 s 2 u a 2 2 R N F ( u a ) d x = 1 2 A 4 u a ( x ) u a ( y ) 2 x y N + 2 s 1 d x d y + 1 2 A 4 u a ( x ) u a ( y ) 2 x y N + 2 s 2 d x d y A 1 F ( u a ) d x = Ψ + Φ ,

where

Ψ 1 2 A 4 u a ( x ) u a ( y ) 2 x y N + 2 s 1 d x d y + 1 2 A 4 u a ( x ) u a ( y ) 2 x y N + 2 s 2 d x d y , Φ A 1 F ( u a ) d x .

Ψ = 1 2 A 5 u a ( x ) u a ( y ) 2 x y N + 2 s 1 d x d y + 1 2 A 6 u a ( x ) u a ( y ) 2 x y N + 2 s 1 d x d y + 1 2 A 7 u a ( x ) u a ( y ) 2 x y N + 2 s 1 d x d y + 1 2 A 8 u a ( x ) u a ( y ) 2 x y N + 2 s 1 d x d y + 1 2 A 5 u a ( x ) u a ( y ) 2 x y N + 2 s 2 d x d y + 1 2 A 6 u a ( x ) u a ( y ) 2 x y N + 2 s 2 d x d y + 1 2 A 7 u a ( x ) u a ( y ) 2 x y N + 2 s 2 d x d y + 1 2 A 8 u a ( x ) u a ( y ) 2 x y N + 2 s 2 d x d y = 1 2 A 6 t 0 2 y a 2 x y N + 2 s 1 d x d y + 1 2 A 7 t 0 2 a x 2 x y N + 2 s 1 d x d y + 1 2 A 8 t 0 2 x y 2 x y N + 2 s 1 d x d y + 1 2 A 6 t 0 2 a y 2 x y N + 2 s 2 d x d y + 1 2 A 7 t 0 2 a x 2 x y N + 2 s 2 d x d y + 1 2 A 8 t 0 2 x y 2 x y N + 2 s 2 d x d y 3 2 A 4 t 0 2 x y 2 x y N + 2 s 1 d x d y + 3 2 A 4 t 0 2 x y 2 x y N + 2 s 2 d x d y 3 2 A 4 t 0 2 x y N + 2 s 1 2 d x d y + 3 2 A 4 t 0 2 x y N + 2 s 2 2 d x d y ,

Φ = A 2 F ( u a ) d x A 3 F ( u a ) d x A 2 F ( t 0 ) d x + A 3 sup 0 t t 0 F ( t ) d x = F ( t 0 ) s N 1 a N N + sup 0 t t 0 F ( t ) s N 1 ( a + 1 ) N a N N ,

where s N 1 represents the unit sphere in the N-dimension.

On the basis of the aforementioned results, we obtain

I ( u a ) 3 2 A 4 t 0 2 x y 2 x y N + 2 s 1 d x d y + 3 2 A 4 t 0 2 x y 2 x y N + 2 s 2 d x d y F ( t 0 ) s N 1 a N N + sup 0 t t 0 F ( t ) s N 1 ( a + 1 ) N a N N 3 2 A 4 t 0 2 x y N + 2 s 1 2 d x d y + 3 2 A 4 t 0 2 x y N + 2 s 2 2 d x d y F ( t 0 ) s N 1 a N N + sup 0 t t 0 F ( t ) s N 1 1 N ( C N 1 a N 1 + C N 2 a N 2 + + 1 ) .

Since 0 < N + 2 s i 2 < N when N 2 , 0 < s i < 1 , i = 1, 2, it is clear that

0 < A 4 t 0 2 x y N + 2 s i 2 d x d y <

Therefore, by letting a > 0 be enough large, one has I ( u a ) < 0 . What is more, it follows

u a 2 2 A 2 u a 2 d x = A 2 t 0 2 d x = a N t 0 2 s N 1 N .

Thus, there exits c 1 > 0 sufficiently large such that E c 1 < 0 . Due to the nonincreasing of E c , we obtain E c < 0 for all c > c 1 .□

Lemma 2.6

E t c t E c for any c > 0 and t > 1 .

Proof

For the given u S c , we set v ( x ) u t 1 N x ,

E t c I ( v ) = 1 2 s 1 v 2 2 + 1 2 s 2 v 2 2 R N F ( v ) d x = 1 2 t 1 2 s 1 N s 1 u 2 2 + 1 2 t 1 2 s 2 N s 2 u 2 2 t R N F ( u ) d x = t I ( u ) + 1 2 ( t 1 2 s 1 N t ) s 1 u 2 2 + 1 2 ( t 1 2 s 2 N t ) s 2 u 2 2 < t I ( u ) .

We immediately obtain E t c t E c for all u S c and t > 1 .□

Lemma 2.7

Assume, for some a > b , I ( w 1 ) = E a , and I ( w 2 ) = E b for some w 1 S a and w 2 S b , respectively. Then the following statements hold.

  1. For any s > a , E s < E a .

  2. E a + b < E b + E a .

Proof

(i) For t > 1 , we define w t w 1 t 1 N x , then w t 2 2 S t a and

(2.9) I ( w t ) = 1 2 s 1 w 1 t 1 N x 2 2 + 1 2 s 2 w 1 t 1 N x 2 2 R N F ( w 1 t 1 N x ) d x = 1 2 t 1 2 s 1 N s 1 w 1 2 2 + 1 2 t 1 2 s 2 N s 2 w 1 2 2 t R N F ( w 1 ) d x = t 1 2 t 2 s 1 N s 1 w 1 2 2 + 1 2 t 2 s 2 N s 2 w 1 2 2 R N F ( w 1 ) d x < t 1 2 s 1 w 1 2 2 + 1 2 s 2 w 1 2 2 R N F ( w 1 ) d x = t I ( w 1 ) = t E a .

In view of the definition of E t a and (2.9), we obtain E t a I ( w t ) < t E a holds for all t > 1 . For the given t = s a > 1 , by Lemma 2.5 (i), which means

E s < s a E a E a .

(ii) In view of (i), it is clear

E a + b = E a + b a a < a + b a E a = b a E a + E a = E a + b a E a b b < E a + E b .

This means that Lemma 2.8 holds.□

3 Proof of Theorems 1.1–1.4

In this section, we take advantage of concentration-compactness principle of [15,16] to prove Theorem 1.1. What is more, we shall need to use some ideas from [11] to prove Theorem 1.2. Finally, we shall make use of some ideas from [22] to give the proof of 1.3 and 1.4.

Proof of Theorem 1.1

We define

c 0 inf { c > 0 E c < 0 } .

By Lemma 2.5 that c 0 [ 0 , ) ,

(3.1) E c = 0 if 0 < c c 0 , E c < 0 if c > c 0 .

For the given c > c 0 , let { w n } S c be any minimizing sequence with respect to E c ; thus, { w n } is bounded in H s 2 ( R N ) by Lemma 2.4 and assume that up to a subsequence lim n R N w n 2 d x and lim n R N F ( w n ) d x exist. Since E c < 0 holds by (3.1), we obtain { w n } is nonvanishing, that is to say

(3.2) lim n sup y R N B ( y , 1 ) w n 2 d x > 0 .

Assume that (3.2) is not true, namely, δ lim n ( sup y R N B ( y , 1 ) w n 2 d x ) = 0 . By Lions Lemma of [15], then w n 0 in L 2 + 4 s 2 N ( R N ) , and thus,

lim n R N F ( w n ) d x 0 .

There is a contradiction by Lemma 2.5 (i)

0 > E c = lim n I ( w n ) = lim n 1 2 s 1 w n 2 2 + 1 2 s 2 w n 2 2 R N F ( w n ) d x 0 .

Since { w n } is nonvanishing, there exists a sequence { y n } R N and a nontrival element ϑ H s 2 ( R N ) such that

w n ( + y n ) ϑ in H s 2 ( R N ) , w n ( + y n ) ϑ in L loc 2 ( R N ) , w n ( + y n ) ϑ in a.e. R N .

Let c = ϑ 2 2 ( 0 , c ] and ϑ n = w n ( + y n ) v , then

(3.3) lim n ϑ n 2 2 = c c .

According to the method of [12], we obtain

(3.4) E c = lim n I ( w n ) = lim n I ( ϑ + ϑ n ) = I ( ϑ ) + lim n I ( ϑ n ) .

Claim. lim n ϑ n 2 2 = 0 , then c = c .

Let s n ϑ n 2 2 for each n N + . If lim n s n > 0 , then c ( 0 , c ) . According to the definition of E s n and Lemma 2.5, we have

lim n I ( ϑ n ) lim n E s n = E c c .

In view of Lemma 2.6 and (3.4), it follows

E c = lim n I ( ϑ n ) + I ( ϑ ) I ( ϑ ) + E c c E c + E c c E c .

Therefore, we obtain I ( ϑ ) = E c and prove that E c is achieved at ϑ S c . But by Lemma 2.7 and (3.4) again, we obtain a contradiction:

E c E c + E c c > c c E c + c c c E c = E c ,

and thus, the claim is proved.

Conclusion. It is clear that ϑ S c by claim and I ( v ) E c . According to the claim and Lemma 2.4, it follows that

limsup n R N F ( ϑ n ) d x 0 ,

and lim n I ( ϑ n ) 0 hold. By (3.4), we obtain E c I ( ϑ ) . Thus, E c is attained at ϑ S c .

Finally, we prove that E c is not achieved if 0 < c < c 0 . Indeed, assuming by the contradiction E c is attained for some c ( 0 , c 0 ) , there exists ϑ S c such that

E c = I ( ϑ ) = 0 .

We infer from Lemma 2.7 (i)

E c 0 < c 0 c E c = 0 ,

which leads to contradiction by (3.1); thus, E c is not attained at 0 < c < c 0 .□

Proof of Theorem 1.2

(i) For the given c > 0 and find a function u S c C 0 ( R N ) \ { 0 } , set u θ ( x ) θ N 2 u ( θ x ) , for θ > 0 , which means u θ S c . According to the assumption of (i), for sufficiently large C , there exists a constant δ > 0 such that

F ( t ) C t 2 + 4 s 2 N if t < δ .

Choosing λ > 0 small enough satisfying u λ < δ , thus F ( u λ ) C u λ 2 + 4 s 2 N holds

I ( u λ ) = 1 2 s 1 u λ 2 2 + 1 2 s 2 u λ 2 2 R N F ( u λ ) d x 1 2 s 1 u λ 2 2 + 1 2 s 2 u λ 2 2 C R N u λ 2 + 4 s 2 N d x < 0 ,

for sufficiently large C . Thus, E c I ( u λ ) < 0 , that is to say E c < 0 for all c > 0 . According to the definition of c 0 , it means (i) holds.

(ii) By the assumption of (ii) and ( f 2 ) , there exists a constant C such that F ( t ) C t 2 + 4 s 2 N for all t R . By the Gagliardo-Nirenberg inequality, we obtain

R N F ( u ) d x C u 2 + 4 s 2 N 2 + 4 s 2 N C C ( N ) s 2 u 2 2 u 2 4 s 2 N = C C ( N ) c 2 s 2 N s 2 u 2 2 .

For any c sufficiently small such that C C ( N ) c 2 N < 1 2 , thus

I ( u ) = 1 2 s 1 u 2 2 + 1 2 s 2 u 2 2 R N F ( u ) d x 1 2 s 1 u 2 2 + 1 2 s 2 u 2 2 1 2 s 2 u 2 2 = 1 2 s 1 u 2 2 > 0 .

This indicates E c 0 for enough small c > 0 . According to the Lemma 2.5 (i), we obtain E c 0 . Thus, E c = 0 for enough small c > 0 . Then, the proof of this theorem is complete.□

Proof of Theorem 1.3

Assuming that { u n } S c is a minimizing sequence, which does not satisfy (i), next we prove that (ii) holds. By Lemma 2.4 and the definition of S c , { u n } is bounded sequence in H s 2 ( R N ) . Due to (i) does not hold, so there exits a family { y n } R N satisfying

0 < σ lim n B ( y n , 1 ) u n 2 d x < ,

so

0 < σ lim n B ( 0 , 1 ) u n ( y n ) 2 d x < .

We define u ¯ n u n ( y n ) , due to the boundedness of { u n } , so does { u ¯ n } ; therefore, there exists v H s 2 ( R N ) such that

u ¯ n v in H s 2 ( R N ) , u ¯ n v in L loc 2 ( R N ) , u ¯ n v a.e. in R N .

It follows from Lemmas 2.1 and 2.2 that,

(3.5) c = u ¯ n 2 2 = u ¯ n u 2 2 + u 2 2 + o n ( 1 ) ,

(3.6) E c = I ( u ¯ n ) = I ( u ¯ n u ) + I ( u ) + o n ( 1 ) .

If u 2 2 < c , then u ¯ n u 2 2 m > 0 by (3.5) and define

v n m u ¯ n u 2 ( u ¯ n u ) ,

thus v n 2 2 = m and u 2 2 = c m > 0 hold by (3.5). Then, by using the method of [12], we obtain

(3.7) E c = I ( u ¯ n ) = I ( v n ) + I ( u ) + o n ( 1 ) E m + E c m E c .

In particular, we obtain the following the conclusion by (3.7):

  1. E c m is achieved with respect to u S c m .

  2. E c = E m + E c m .

Applying the above arguments to the minimizing sequence { v n } of E m < 0 , there exists v H s 2 ( R N ) such that v n v in H s 2 ( R N ) ; thus, v 2 2 ( 0 , m ] .

Case 1. If v 2 2 = m , we obtain E m is achieved at v S m . By Lemma 2.7, we obtain

E c = E m + E c m > E c ,

which implies the contradiction.

Case 2. If v 2 2 < m , and there exists m 1 > 0 and m 2 > 0 such that m = m 1 + m 2 ,

E c = E m 1 + E m 2 + E c m ,

where E m 2 and E c m are achieved. By using Lemma 2.7, we have

E c = E m 1 + E m 2 + E c m > E m 1 + E m 2 + c m E m 1 + m 2 + c m = E c ,

which implies the contradiction.

So, just as mentioned earlier, we obtain that u 2 2 = c holds, then u ¯ n u 0 in L 2 ( R N ) . According to interpolation inequality, it follows

u ¯ n u q u ¯ n u 2 θ u ¯ n u 2 1 θ .

By Lemmas 2.1 and 2.4,

R N F ( u ¯ n ) d x R N F ( u ) d x .

Moreover, note that u S c , then

E c t I ( u ) lim n I ( u ¯ n ) = E c .

Therefore, E c is achieved at u S c , u ¯ n H s 2 ( R N ) u H s 2 ( R N ) . Then, we complete the proof of theorem.□

Proof of Theorem 1.4

(i) For the given c 0 > 0 , let c k = c 0 + 1 k ; thus, E c k < 0 by Theorem 1.1. We choose v k S c k such that

(3.8) E c k I ( v k ) 1 2 E c k < 0 ,

which implies { v k } is bounded in H s 2 ( R N ) , and up to subsequence lim k R N v k 2 d x and lim k R N F ( v k ) d x exist, we obtain lim k s i v k 2 > 0 by the Lemma 2.4 (iii). Then { v k } is nonvanishing, namely,

(3.9) σ limsup k sup y R N B ( y , 1 ) v k 2 d x > 0 .

Assume that (3.9) is not true, then v k 0 in L 2 + 4 s 2 N ( R N ) by Lions Lemma [16], and by Lemma 2.3, we obtain

lim n R N F ( v k ) d x 0 ,

so

lim n I ( v k ) 1 2 s 1 v k 2 2 + 1 2 s 2 v k 2 2 > 0 .

which contradicts with (3.8). Since { v k } is nonvanishing, there exists a family { y k } R N and v H s 2 ( R N ) satisfying

v k ( + y k ) v in H s 2 ( R N ) , v k ( + y k ) v in L loc 2 ( R N ) , v k ( + y k ) v in a.e. in R N .

Let c v 2 2 ( 0 , c 0 ] and ω k v k ( . + y k ) v , then lim n ω k 2 2 = c 0 c . It follows

lim k s i v k 2 2 = s i v 2 2 + lim k s i ω k 2 2 , i = 1 , 2 .

Furthermore, E c k E c 0 = 0 holds by using Theorem 1.1, one has

(3.10) 0 = lim n I ( v k ) = lim n I ( v + ω k ) = I ( v ) + lim n I ( ω k ) .

Since E c = 0 for all c ( 0 , c 0 ] , I ( v ) 0 and lim k I ( ω k ) 0 . By (3.10),

I ( v ) = 0 and lim k I ( ω k ) = 0 .

Due to the global infimum E c = 0 is not attained for c ( 0 , c 0 ) by Theorem 1.1 (iii), thus, c = c 0 holds and v S c 0 is a minimizer with respect to E c 0 .

(ii) For the given c 0 > 0 , let c k = c 0 + 1 k , u k denotes a global minimizer with respect to E c k . According to the symmetric rearrangement, we obtain that u k is radially symmetric with respect to the origin and nonincreasing.

Assuming that there is no global minimizer with respect to E c 0 , then it follows from Theorem 1.3 (i) that lim n u k L ( R N ) = 0 , and we choose a enough large k such that u k L ( R N ) t 1 2 .

Let v t ( x ) t N 2 u k ( t x ) , thus v t ( x ) S c 0 + 1 k , for t satisfying 1 < t N 2 2 , it follows

v t ( x ) = t N 2 u k ( t x ) t 1 ,

so by the assumption of Theorem (ii), F ( v t ) = C v t 2 + 4 s 2 N , then

I ( v t ) = 1 2 s 1 v t 2 2 + 1 2 s 2 v t 2 2 R N F ( v t ) d x = 1 2 s 1 t N 2 u k ( t x ) 2 2 + 1 2 s 2 t N 2 u k ( t x ) 2 2 C R N t N 2 u k ( t x ) 2 + 4 s 2 N d x = 1 2 t 2 s 1 s 1 u k 2 2 + 1 2 t 2 s 2 s 2 u k 2 2 C t 2 R N u k 2 + 4 s 2 N d x 1 2 t 2 s 1 u k 2 2 + 1 2 t 2 s 2 u k 2 2 C t 2 R N u k 2 + 4 s 2 N d x t 2 I ( u k ) .

By the definition of E c , it follows

E c 0 + 1 k I ( v t ) t 2 I ( u k ) < I ( u k ) = E c 0 + 1 k ,

which is a contradiction. Thus, there is global minimizer with respect to E c 0 .□

4 Action ground solution

In the section, we make use of Lemma 2.4 to give the proof of Theorem 1.5. More specifically, we prove that any energy ground state is action ground state of corresponding action functional.

Proof of Theorem 1.5

(i) Assume that w H s 2 ( R N ) is an arbitrary nontrivial critical point of J λ , according to the definition of J λ ( w )

J λ ( w ) J λ ( v ) = E c + 1 2 λ c .

We only need to show

J λ ( w ) J λ ( v ) = E c + 1 2 λ c .

For the given δ > 0 and M c > 0 , let ζ : [ 0 , T ] H s 2 ( R N ) be continuous path by given Lemma 2.4. According to the (i) and (iii), there exists t 0 ( 0 , T ) such that

ζ ( t 0 ) 2 2 = c ,

and thus,

J λ ( ω ) = max t [ 0 , T ] J λ ( ζ ( t ) ) J λ ( ζ ( t 0 ) ) = I ( ζ ( t 0 ) ) + 1 2 λ R N ζ ( t 0 ) 2 d x E c + 1 2 λ c .

(ii) We now prove (ii). According to (i), an arbitrary action ground state w H s 2 ( R N ) of (1.1) such that

(4.1) J λ ( w ) = E c + 1 2 λ c .

Suppose by contradiction that w 2 2 c , it follows

δ c ω 2 > 0 a n d M c ,

we find the continuous path ζ : [ 0 , T ] H s 2 ( R N ) given by Lemma 2.4. In the view of Lemma 2.4 (iii), there exists t 0 ( 0 , T ) such that

ζ ( t 0 ) 2 2 = c  and   ζ ( t 0 ) w 2 δ ,

it follows from Lemma 2.4 (ii) a contradiction

J λ ( w ) > J λ ( ζ ( t 0 ) ) = I ( ζ ( t 0 ) ) + 1 2 λ R N ζ ( t 0 ) 2 d x E c + 1 2 λ c .

Since we have proved w 2 2 = c , it is clear that I ( w ) = E c by (4.1). Then, we complete the proof of theorem.□

Acknowledgments

We thank all anonymous referees for the constructive remarks on this manuscript.

  1. Funding information: Supported by the NSFC (12171014, ZR2021MA096).

  2. Author contributions: All authors wrote and revised the manuscript.

  3. Conflict of interest: On behalf all authors, the corresponding author states that there is no conflict of interest.

  4. Data availability statement: On behalf all authors, the corresponding author states that there is no associated data.

References

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Received: 2024-10-10
Revised: 2025-01-25
Accepted: 2025-04-30
Published Online: 2025-07-25

© 2025 the author(s), published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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