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Blow-up solutions to the Hartree-Fock type Schrödinger equation with the critical rotational speed

  • Yuanyuan Tu and Jun Wang EMAIL logo
Published/Copyright: June 2, 2025

Abstract

In this article, we are concerned with the existence, non-existence, and blow-up behavior of normalized ground state solutions for the mass critical Hartree-Fock type Schrödinger equation with rotation

i t u = Δ u + 2 V ( x ) u + 2 Ω L z u λ u b u R N u ( y ) 2 x y 2 d y , ( t , x ) R × R N , u ( 0 , x ) = u 0 ( x ) ,

where N 3 , b > 0 , V ( x ) = x 2 2 , L z is the angular momentum operator with the critical rotational speed Ω = 1 , and the constant λ is the unknown Lagrange multiplier. We prove that the L 2 -constraint minimizers exist if and only if the parameter b satisfies b < b * = U 2 2 , where U is a positive radially symmetric ground state of Δ u + u u R N u 2 ( y ) x y 2 d y = 0 in R N . We also establish the orbital stability result of prescribed mass standing waves for the equation when b < b * . When b approaches b * , the system collapses to a profile obtained from the optimizer of a Gagliardo-Nirenberg inequality.

MSC 2010: 35J61; 35J20; 35Q55; 49J40

1 Introduction

In this article, we consider the focusing Hartree-Fock type Schrödinger equation with rotation

(1.1) i t u = Δ u + 2 V ( x ) u + 2 Ω L z u λ u b u R N u ( y ) 2 x y 2 d y , ( t , x ) R × R N , u ( 0 , x ) = u 0 ( x ) ,

under the constraint

(1.2) R N u 2 d x = 1 ,

where t is the time variable, u = u ( x , t ) : R N × R C is the wave function, N 3 , b > 0 , λ R is a Lagrange multiplier, V ( x ) is a harmonic potential of the form V ( x ) = x 2 2 , and Ω = 1 is a critical rotational speed. L z i ( x 2 x 1 x 1 x 2 ) is the angular momentum operator.

The consideration of (1.1) is prompted by recent studies on the nonlinear Schrödinger equation with rotation

(1.3) i t ψ = 1 2 Δ ψ + V ( x ) ψ + Ω L z ψ + λ u a 2 ψ p 2 ψ , ( t , x ) R × R N , ψ ( 0 , x ) = ψ 0 ( x ) and R N ψ 2 d x = c ,

where a > 0 , c > 0 , V ( x ) = 1 2 j = 1 N γ j 2 x j 2 , γ j represent the respective trapping frequencies in each spatial direction and γ = min j = , 1 , 2 , , N { γ j } > 0 . When the rotational speed Ω = 0 , equation (1.3) is recognized as a model describing the Bose-Einstein condensate under a magnetic trap (see [4,18,45]). When Ω 0 , equation (1.3) describes the Bose-Einstein condensate with rotation, which appears in a variety of physical settings, such as the description of nonlinear waves and propagation of a laser beam in the optical fiber [16,38]. Many articles studied the significance in theory and applications of (1.3), for example, see [2,3,23,29]. When Ω > γ , the rotational speed is larger than the trapping frequency, the centrifugal force caused by the rotation becomes stronger than the centripetal force created by the harmonic trap and the gas flies apart. In this regime, Bao et al. [7] proved the non-existence of ground state solutions for high rotational speed. When 0 < Ω < γ , the authors showed the existence and stability of prescribed mass standing waves for (1.3) with mass-subcritical 2 < p < 2 + 4 N nonlinearity in [3]. In the mass-critical case p = 2 + 4 N , papers [31,32] established the existence and stability of prescribed mass standing waves for (1.3). Additionally, Guo et al. [21,22] studied the limiting behavior of minimizers for (1.3) when c M ( Q ) , where

(1.4) M ( Q ) Q 2 2 ,

and Q is the unique positive radial solution to

1 2 Δ Q + Q Q 4 N Q = 0 .

In the mass-supercritical case 2 + 4 N < p < 2 N N 2 , the energy functional of (1.3) is no longer bounded from below. Luo and Yang [32] proved the existence of local minimizers and stability of the set of local minimizers. Ardila and Hajaiej [5] established the global well-posedness, blow-up and stability of standing waves for (1.3). When Ω = γ 0 min { γ 1 , γ 2 } , Dinh [13] proved the existence and stability of standing waves of (1.3) with an axially symmetric harmonic potential. In particular, in the mass-critical case, the authors showed that the normalized solutions of (1.3) exist if 0 < c < M ( Q ) , while no normalized solutions exist if c M ( Q ) . Recently, Dinh et al. [14] obtained the blow-up behavior of the ground state solutions of (1.3) for N = 2 and the critical rotational speed Ω = γ = 1 .

The Hartree-Fock type Schrödinger equation with a potential term has also been the focus of many recent theoretical studies

(1.5) i t u = Δ u + V ( x ) u + u ( J α u p ) u p 2 u , ( t , x ) R × R N ,

where α ( 0 , N ) and J α ( x ) : R N R is the Riesz potential defined by

J α ( x ) = A α x N α and A α = Γ N α 2 π N 2 2 α Γ ( α 2 ) .

When V = 0 , equation (1.5) is commonly referred to as the nonlinear Choquard equation (see [26,30,34]). This equation, with V = 0 , also arises from the model of wave propagation in a media with a large response length [1,25]. Fröhlich [17] investigated the existence of solutions to (1.5) with p = 2 . Ma and Zhao [34] and Xiang [44] established the unique and non-degeneracy positive solutions of (1.5) by using the moving plane method. The existence of positive and nodal solutions to (1.5) was demonstrated in [19,35]. Moroz and Van Schaftingen [36] proved the existence of nontrivial solutions of (1.5) with the lower critical case p = α N + 1 . When V 0 , Tu and Wang [39] established the existence of the normalized solutions with negative potential. Wang et al. [41] proved the existence of normalized solutions to (1.5) when the potential V is partial confinement. For the case p = 2 and N α = 2 , Deng et al. [12] considered the following nonlinear Hartree equation:

(1.6) Δ u + V ( x ) u b u R N u 2 ( y ) x y 2 d y = 0 , x R N

and proved that (1.6) admits minimizers if and only if

(1.7) 0 < b < b * U 2 2 ,

where U = U ( x ) > 0 denotes the positive radially symmetric ground state solution of the following equation (see [35]):

(1.8) Δ u + u u R N u 2 ( y ) x y 2 d y = 0 , N 3 , x R N .

Moreover, U is unique when N = 4 , and for other values of N , the uniqueness of U remains unclear (see [43]). There are also many works about the existence and multiplicity of solutions of (1.5), for example, see [6,11,19,3537] and references therein. Recently, Tu and Wang [40] considered the nonlocal elliptic equation with rotation

(1.9) 1 2 Δ u + V ( x ) u + Ω L z u + λ u = μ 1 ( J α u p ) u p 2 u , x R N , u 2 2 = a , a > 0 ,

and proved the existence and orbital stability of the normalized solutions at the low rotational speed 0 < Ω < γ and the critical rotational speed Ω = min { γ 1 , γ 2 } with γ 0 γ 1 = γ 2 .

Motivated by the recent works [13,14,40], this article is focused on establishing the existence, nonexistence, and the blow-up behavior of normalized solutions for (1.1) with critical rotational speed and mass critical condition under different value ranges of b . We shall concern first the stationary equation of (1.1):

(1.10) Δ u + x 2 u + 2 Ω L z u λ u = b u R N u ( y ) 2 x y 2 d y ,

with Ω = 1 and u 2 2 = 1 . Solutions to (1.10) can be obtained by searching critical points of the energy functional

(1.11) E Ω , b ( u ) R N u 2 d x + R N x 2 u 2 d x + 2 R N u ¯ L z u d x b 2 R N R N u ( x ) 2 u ( y ) 2 x y 2 d x d y

on the constraint

S ( 1 ) { u Σ : u 2 2 = 1 } ,

where u ¯ is the conjugate of u and Σ is the functional space:

Σ { u H 1 ( R N ) : x u L 2 ( R N ) } ,

equipped with the norm

u Σ 2 u 2 2 + u 2 2 + x u 2 2 .

Taking p = 2 , μ 1 = b 2 , α = N 2 , V ( x ) = x 2 2 , and a = 1 in (1.9), system (1.9) becomes (1.10) and γ 0 = 1 . It is well-known that if 0 < Ω < 1 , the following equivalent norm holds (see [13, Lemma 2.1]):

(1.12) u 2 2 + x u 2 2 2 Ω R N u ¯ L z u d x u 2 2 + x u 2 2 .

Theorem 1.1 in [40] proved the existence of a normalized ground state of (1.9) for the mass-subcritical N + α N < p < N + α + 2 N case, and the existence of a normalized local minimizer of (1.9) for the mass-critical p = N + α + 2 N and mass-supercritical N + α + 2 N < p < N + α N 2 case by applying the compact embedding Σ L q for all 2 q < 2 * with (1.12). If Ω = 1 (critical rotational speed), the main difficulty to prove the existence of prescribed mass standing waves for (1.1) comes from the fact that the equivalent norm (1.12) is no longer available. To overcome the difficulty, in [40], another norm ( i + P ) u 2 2 is introduced with P defined in this way

(1.13) P ( x ) ( x 2 , x 1 , 0 , , 0 )

and

( i + P ) u 2 2 = u 2 2 + R N ( x 1 2 + x 2 2 ) u 2 d x + 2 R N u ¯ L z u d x .

Motivated by [32], the authors obtained a local minimizer of (1.9) at the critical rotational speed for the mass-critical case and mass-supercritical case. Similar to [40], it is then equivalent to rewriting the energy functional (1.11) as

(1.14) E Ω , b ( u ) = ( i + P ) u 2 2 + R N V Ω ( x ) u 2 d x b 2 R N R N u ( x ) 2 u ( y ) 2 x y 2 d x d y ,

where V Ω ( x ) i = 3 N x i 2 . The working space is defined as

Σ Ω u H P 1 ( R N ) : R N V Ω ( x ) u 2 d x < ,

where H P 1 ( R N ) is the magnetic Sobolev space defined by

(1.15) H P 1 ( R N ) { u L 2 ( R N ) : ( i + P ) u L 2 ( R N ) } .

The corresponding norm of Σ Ω is

u Σ Ω 2 ( i + P ) u 2 2 + R N V Ω ( x ) u 2 d x + u 2 2 .

We consider the minimization problem

(1.16) e Ω , b inf { E Ω , b ( u ) : u S ( 1 ) Σ Ω } .

In order to state our results, we give the following definitions. A set M Σ is orbitally stable under the flow associated with (1.1) in the sense that for any ε > 0 , there exists δ > 0 such that for any initial data u 0 Σ satisfying

inf φ M u 0 φ Σ < δ ,

the corresponding solution u ( t , ) of (1.1) exists globally in time and satisfies

inf φ M u ( t , ) φ Σ < ε , t R .

Let the solution u C ( ( T 1 , T 2 ) , Σ ) to (1.1). We say that the maximal time of existence satisfies the blow-up alternative: if T 1 < (resp. T 2 < ), then lim t T 1 u ( t ) 2 = (resp. lim t T 2 u ( t ) 2 = ).

The mass and energy are two important physical quantities, which are formally conserved by the time-evolution associated with (1.1) (see [40, Lemma 3.3]):

u ( t ) 2 2 = u 0 2 2 , E Ω , b ( u ( t ) ) = E Ω , b ( u 0 ) .

Our first result concerns the existence, non-existence and stability of standing waves for (1.1) and (1.2) with prescribed mass.

Theorem 1.1

Assume that N 3 , Ω = 1 , V ( x ) = x 2 2 . b * is defined in (1.7). Then, we have the following conclusions.

  1. If 0 < b < b * , there exists a u ˜ Σ Ω such that e Ω , b = E ( u ˜ ) . Moreover, the set of minimizers for e Ω , b denoted by

    = { u S ( 1 ) Σ Ω : E Ω , b ( u ) = e Ω , b }

    is orbitally stable under the flow of (1.1).

  2. If b b * , there is no minimizer for e Ω , b .

Remark 1.2

  1. When Ω = 0 , the existence and non-existence of minimizers of (1.1) were established in [12]. When Ω 0 , the existence and the orbital stability results of (1.1) at the lower rotational speed and the critical rotational speed were proved in [40]. Noting that in [40], the authors did not show that the energy functional is bounded from below for the mass-critical case and obtained a local minimizer of (1.1) at the critical rotational speed with critical mass. Here, we can prove the existence of normalized ground state solutions under the assumption of b < b * , which is different from Theorem 1.5 in [40].

  2. When N = 2 , i.e., V Ω = 0 , the existence and the orbital stability results of (1.3) were proved in [15] and [9]. The proof of the existence result is based on a variant of the celebrated concentration-compactness principle adapted to the magnetic Sobolev space H P 1 ( R N ) (see (1.15)). However, when N 3 , this argument does not work due to the presence of a partial harmonic confinement V Ω . We follow the idea of [13, Theorem 1.2], and by applying the diamagnetic inequality and Lemma 2.1 which rules out the vanishing possibility, we establish the above results.

The following result shows the blow-up behavior of ground states for e Ω , b with the critical rotation speed Ω = 1 when b approaches b * (see (1.7)).

Theorem 1.3

Assume that 3 N < 6 , Ω = 1 , V ( x ) = x 2 2 , b b * , ( u n ) be the sequence of ground states for e Ω , b n . Then, we have

(1.17) lim n ε n N 2 u n ( ε n x + y n ) e i ε n P ( y n ) x + i θ n = U 0 ( x ) in H 1 ( R N ) ,

where y n = ( y n 1 , y n 2 , 0 , , 0 ) R N , ( θ n ) [ 0 , 2 π ) , U 0 U U 2 2 , U is a ground state solution of (1.8), and ε n > 0 satisfies

ε n u n 2 1 0 as n .

Moreover, we have

(1.18) ( b * b ) 1 2 2 R N V Ω ( x ) U 0 2 d x 1 2 b * 1 2 e Ω , b ( b * b ) 1 2 2 x U 0 2 b * 1 2 + o ( 1 ) .

Remark 1.4

When N = 2 , i.e., V Ω = 0 , a M ( Q ) (see (1.4)), the blow-up result of ground states of (1.3) was established in [14]. However, N 3 means that the partial harmonic confinement V Ω exists. Moreover, the interaction is Hartree-Fock type, which causes several difficulties to our work. For more detailed information, refer to Section 4. In order to prove the uniform bound of the sequence S n = τ n 2 (see (4.5)), the condition N < 6 is necessary. Here, we cannot obtain the blow-up limit of e Ω , b n , since the lack of the non-degeneracy property of U , which is a problem worth studying in the future.

The rest of this article is organized as follows: In Section 2, we introduce the main notations and some preliminary results. In Section 3, we provide the proof of Theorem 1.1. Section 4 is devoted to the proof of Theorem 1.3.

2 Preliminaries

We shall use the following notations and conclusions:

  • H 1 is the norm of H 1 ( R N ) defined by u H 1 2 R N ( u 2 + u 2 ) d x .

  • p is the norm of L p ( R N ) defined by u p R N u p d x 1 p .

  • u , v R e R N u v ¯ d x , where u , v L 2 ( R N , C ) and v ¯ denotes the complex conjugate v .

  • The embedding H 1 ( R N ) L q ( R N ) is continuous for 2 < q < 2 * , where 2 * = 2 N N 2 for N 3 and 2 * = for N = 1 , 2 .

In this section, we present some preliminary results. First, we give the following Gagliardo-Nirenberg inequality (see [42, the ineqaulity (2.13)]):

(2.1) R N R N u ( x ) p u ( y ) p x y N α d x d y S ˜ R N u 2 d x ( N + α ) p ( N 2 ) 2 R N u 2 d x p N ( N + α ) 2 ,

where α ( 0 , N ) , N + α N < p < N + α N 2 and S ˜ > 0 is a constant. We recall the following classical Hardy-Littlewood-Sobolev inequality (see [28, Theorem 2.3]):

(2.2) R N R N f ( x ) g ( y ) x y t d x d y c ( p 1 , q 1 , t ) f p 1 g q 1 , f L p 1 ( R N ) , g L p 1 ( R N ) ,

where 1 < p 1 < q 1 < , 0 < t < N , and 1 p 1 + 1 q 1 + t N = 2 . By the classical Hardy-Littlewood-Sobolev inequality, there exists a positive constant C ˜ > 0 such that

(2.3) R N R N u ( x ) p u ( y ) p x y N α d x d y C ˜ R N u 2 p N N + α d x N + α N .

In addition, the following inequality holds:

(2.4) R N R N f ( y ) x y N α d y q 1 d x 1 q 1 c f p 1 , f L p 1 ( R N ) ,

where 1 q 1 = 1 p 1 α N . From [20, Lemma 2.3], we know that if u n u in H 1 ( R N ) , then

(2.5) R N R N u n ( x ) p u n ( y ) p x y N α d x d y = R N R N u ( x ) p u ( y ) p x y N α d x d y + R N R N ( u n u ) ( x ) p ( u n u ) ( y ) p x y N α d x d y .

From [28, Theorem 7.21], we have the diamagnetic inequality

(2.6) u ( x ) ( i + P ) u ( x ) , a.e. x R N .

Moreover, as a direct conclusion from Young’s inequality, the rotational term can be controlled as follows: when N 2 , for any constant δ > 0 ,

(2.7) u , Ω L z u Ω x u 2 u 2 δ 2 u 2 2 + Ω 2 2 δ x u 2 2 .

As in [35, Proposition 3.1], we know that all solutions of (1.8) satisfy the following Pohozaev identity:

(2.8) N 2 2 R N u 2 d x + N 2 R N u 2 d x = N 1 2 R N R N u ( x ) 2 u ( y ) 2 x y 2 d x d y .

Hence, one deduces from (1.8) and (2.8) that any solution of (1.8) satisfies

(2.9) R N u 2 d x = R N u 2 d x = 1 2 R N R N u ( x ) 2 u ( y ) 2 x y 2 d x d y .

When p = 2 and α = N 2 in (2.1), from [10, Lemma 1.3], we know that the following Gagliardo-Nirenberg inequality

(2.10) R N R N u ( x ) 2 u ( y ) 2 x y 2 d x d y 2 b * R N u 2 d x R N u 2 d x , u H 1 ( R N )

is achieved by any positive radially symmetric ground state solution U = U ( x ) of (1.8), where b * is defined in (1.7).

We recall the following lemma, which is crucial for dealing with convergence in Σ Ω (see [40, Lemma 2.3]).

Lemma 2.1

Let ( u n ) be a sequence of Σ Ω -functions satisfying sup n 1 u n Σ Ω < . Assume that there exists ε 0 > 0 such that inf n 1 R N u n ( x ) p u n ( y ) p x y N α d x d y ε 0 for some N + α N < p < N + α N 2 . Then, there exists u ˜ Σ Ω \ { 0 } and ( y n ) R N with y n = ( y n 1 , y n 2 , 0 , , 0 ) such that up to a subsequence,

g n e i P ( y n ) x u n ( x + y n ) u ˜ weakly i n Σ Ω .

Moreover, the weak convergence in Σ Ω implies that

(2.11) ( i + P ) g n 2 2 = ( i + P ) u ˜ 2 2 + ( i + P ) ( g n u ˜ ) 2 2 + o n ( 1 )

and

(2.12) R N V Ω ( x ) g n 2 d x = R N V Ω ( x ) u ˜ 2 d x + R N V Ω ( x ) g n u ˜ 2 d x + o n ( 1 ) .

Similarly, if the workspace is Σ , we have the following lemma.

Lemma 2.2

Let ( u n ) be a sequence satisfying sup n 1 u n H 1 < . Assume that there exists ε 0 > 0 such that inf n 1 R N u n ( x ) p u n ( y ) p x y N α d x d y ε 0 for some N + α N < p < N + α N 2 . Then, there exists u ˜ H 1 ( R N ) \ { 0 } and ( y n ) R N with y n = ( y n 1 , y n 2 , 0 , , 0 ) such that up to a subsequence,

u n ( x + y n ) u ˜ weakly i n H 1 ( R N ) .

Proof

From (2.3) and inf n 1 R N u n ( x ) p u n ( y ) p x y N α d x d y ε 0 > 0 , we infer that there exists ε ˜ 0 > 0 such that inf n 1 u n 2 p N N + α ε ˜ 0 for N + α N < p < N + α N 2 . That is, inf n 1 u n q ε ˜ 0 > 0 for 2 < q < 2 * . According to [27], we have that there exists u ˜ H 1 ( R N ) \ { 0 } such that u n ( x + y n ) u ˜ weakly in H 1 ( R N ) .□

To prove the uniform boundedness of a solution, we need the following local boundedness result [24, Theorem 4.14].

Lemma 2.3

Let D be a connected open set with smooth boundary in R N . Assume that a j k L ( D ) satisfies

μ σ 2 Σ j , k σ j δ k ε σ 2 , x D , σ R N

for some positive constants μ and ε . Let u H 1 ( D ) be a non-negative subsolution in D in the following sense:

D a j k j u k ξ d x D f ξ d x , ξ H 0 1 ( D ) , ξ 0 in D .

Suppose that f L q ( D ) for some q > N 2 . Then, there holds for any B R ( x 0 ) D and any p > 0

sup B R 2 ( x 0 ) u ( x ) C R N p u L p ( B R ( x 0 ) ) + R 2 N q f L q ( B R ( x 0 ) ) ,

where C = C ( N , μ , ε , p , q ) is a positive constant.

3 Proof of Theorem 1.1

3.1 Case 0 < b < b *

In this section, we consider the case 0 < b < b * . First, we are devoted to proving the existence of ground states to (1.1) with the constraint (1.2). To begin with, we show that the energy functional E Ω , b ( u ) is bounded from below.

Lemma 3.1

Assume that N 3 , Ω = 1 , V ( x ) = x 2 2 , and 0 < b < b * . Then, e Ω , b > .

Proof

By using (1.14), (2.6), and (2.10) with the fact u S ( 1 ) , we have

(3.1) E Ω , b ( u ) ( i + P ) u 2 2 + R N V Ω u 2 d x b b * R N u 2 d x R N u 2 d x ( i + P ) u 2 2 + R N V Ω u 2 d x b b * ( i + P ) u 2 2 = 1 b b * ( i + P ) u 2 2 + R N V Ω u 2 d x .

It is straightforward to see that e Ω , b > for 0 < b < b * .□

By Lemma 3.1, it is easy to see that if ( u n ) Σ Ω be a minimizing sequence for e Ω , b , then ( u n ) is bounded.

Next, we show the following result, which is essential to utilize Lemmas 2.1 and 2.2. The proof is similar to that of Lemma 4.2 in [40]. Here, we omit it.

Lemma 3.2

Assume that N 3 , Ω = 1 , 0 < b < b * , and V ( x ) = x 2 2 . Then, there exists C > 0 such that the minimizing sequence ( u n ) for e Ω , b satisfies

lim inf n R N R N u n ( x ) 2 u n ( y ) 2 x y 2 d x d y C .

Finally, we give the following global well-posedness which is needed for the stability result.

Lemma 3.3

Assume that N 3 , Ω = 1 , 0 < b < b * , and V ( x ) = x 2 2 . Then, the corresponding solution to (1.1)exists globally in time.

Proof

Let u : ( T 1 , T 2 ) × R N C be the solution to (1.1), hence to (1.10). Arguing as in (3.1), we have

(3.2) E Ω , b ( u ( t ) ) 1 b b * ( i + P ) u ( t ) 2 2 + R N V Ω ( x ) u ( t , x ) 2 d x .

Combining the conservation of energy with 0 < b < b * , for all t ( T 1 , T 2 ) , we have

( i + P ) u ( t ) 2 2 + R N V Ω ( x ) u ( t , x ) 2 d x E Ω , b ( u 0 ) ,

which implies that sup t ( T 1 , T 2 ) u ( t ) Σ Ω < . By blow-up alternative, we infer that T 1 = T 2 = .□

Now, we establish the existence and orbital stability of the normalized ground state solution for (1.1)–(1.2) when 0 < b < b * .

Proof of Theorem 1.1 (i)

Let ( u n ) Σ Ω be a minimizing sequence for e Ω , b with u n 2 2 = 1 . From (3.1), we have that sup n 1 u n Σ Ω < as n . By Lemma 3.2, we know that there exists a subsequence still denoted by ( u n ) such that

lim inf n R N R N u n ( x ) 2 u n ( y ) 2 x y 2 d x d y C > 0 .

By Lemma 2.1, there exist u ˆ Σ Ω \ { 0 } such that

g n ( x ) e i P ( y n ) x u n ( x + y n ) u ˆ weakly in Σ Ω ,

where ( y n ) R N with y n = ( y n 1 , y n 2 , 0 , , 0 ) . By computation, we have

R N V Ω ( x ) g n ( x ) 2 d x = R N V Ω ( x ) u n ( x ) 2 d x , ( i + P ) g n 2 2 = ( i + P ) u n 2 2 .

We show that u ˆ 2 2 = 1 . In fact, we first have

0 < u ˆ 2 2 lim inf n g n 2 2 = lim inf n u n 2 2 = 1 .

Assume by contradiction that u ˆ 2 2 < 1 . For θ > 0 , we have

E Ω , b ( θ u ˆ ) = θ 2 E Ω , b ( u ˆ ) + b 2 ( θ 2 θ 4 ) R N R N u ˆ ( x ) 2 u ˆ ( y ) 2 x y 2 d x d y .

It follows that

(3.3) E Ω , b ( u ˆ ) = 1 θ 2 E Ω , b ( θ u ˆ ) + b 2 ( θ 2 1 ) R N R N u ˆ ( x ) 2 u ˆ ( y ) 2 x y 2 d x d y .

Taking θ 0 = 1 u ˆ 2 > 1 , we infer that θ 0 u ˆ 2 2 = 1 and

E Ω , b ( u ˆ ) = u ˆ 2 2 E Ω , b ( θ 0 u ˆ ) + b 2 ( θ 0 2 1 ) R N R N u ˆ ( x ) 2 u ˆ ( y ) 2 x y 2 d x d y > u ˆ 2 2 e Ω , b .

By Brezis-Lieb’s lemma [8], we have

g n 2 2 = g n u ˆ 2 2 + u ˆ 2 2 ,

Denote θ n 1 g n u ˆ 2 . We have that θ n 1 1 u ˆ 2 2 > 1 as n . From (3.3), we infer that

lim n E Ω , b ( g n u ˆ ) = lim n 1 θ n 2 E Ω , b ( θ n ( g n u ˆ ) ) + b 2 ( θ n 2 1 ) R N R N ( g n u ˆ ) ( x ) 2 ( g n u ˆ ) ( y ) 2 x y 2 d x d y ( 1 u ˆ 2 2 ) e Ω , b .

Combining (2.5), (2.11) with (2.12), we have that

e Ω , b = lim n E Ω , b ( u n ) = lim n E Ω , b ( g n ) = lim n E Ω , b ( g n u ˆ ) + E Ω , b ( u ˆ ) > e Ω , b .

This is a contraction, and we thus have u ˆ 2 2 = 1 . Next, we show u ˆ is a minimizer for e Ω , b . From (2.1), (2.5), and g n u ˆ 2 0 , we deduce that

R N R N g n ( x ) 2 g n ( y ) 2 x y 2 d x d y = R N R N u ˆ ( x ) 2 u ˆ ( y ) 2 x y 2 d x d y + o ( 1 ) .

By applying the lower semi-continuity, we have

e Ω , b E Ω , b ( u ˆ ) liminf n E Ω , b ( g n ) = liminf n E Ω , b ( u n ) = e Ω , b .

Therefore, g n u ˆ in Σ Ω and E Ω , b ( u ˆ ) = e Ω , b .

Finally, we prove the stability of . We follow an argument of [9]. Assume by contradiction that it is not true. Then, there exist ε > 0 , ν 0 , a sequence of initial data ( u 0 , n ) Σ Ω and a sequence of time ( t n ) R such that

(3.4) lim n u 0 , n ν 0 Σ Ω = 0 , inf ν e i P ( y ) x u n ( t n , x + y ) ν Σ Ω ε ,

where u n is the solution to (1.1) with initial data u n ( 0 , ) = u 0 , n ( ) and y R 2 × { 0 } R N 2 . Note that the solutions exist globally in time by Lemma 3.3. We have E Ω , b ( ν 0 ) = e Ω , b from the fact ν 0 . By the conservation of mass and (3.4), we have

u n ( t n , ) 2 2 = u 0 , n 2 2 ν 0 2 2 = 1 as n .

By the conservation of energy, by (2.1), (2.5), and (3.4), we have that

E Ω , b ( u n ( t n , ) ) = E Ω , b ( u 0 , n ) E Ω , b ( ν 0 ) = e Ω , b as n .

In particular, the continuity in time implies that u n ( t n , ) is a minimizing sequence in Σ Ω . Thus, we see that up to a subsequence, there exist υ and ( y n ) R 2 × { 0 } R N 2 such that

e i P ( y n ) x u n ( t n , x + y n ) υ Σ Ω 0 as n .

This however contradicts (3.4). The proof is complete.□

3.2 Case b b *

In this section, we follow the idea of [13, Proposition 1.3] and prove the non-existence of prescribed mass standing waves for (1.1) and (1.2) when b b * .

Proof of Theorem 1.1(ii)

Let ψ C 0 ( R N ) be radially symmetric satisfying ψ ( x ) = 1 for x 1 . Denote

g h ( x ) C h h N 2 ψ ( x ) U 0 ( h x ) , h > 0 ,

where U 0 ( x ) = U ( x ) U 2 and C h > 0 is such that g h 2 2 = 1 for all h > 0 . Then, we have

C h 2 = R N ψ ( h 1 x ) 2 U 0 2 ( x ) d x .

From [35, Theorem 4], we know that U 0 decays exponentially at infinity. For h > 0 sufficiently large and any δ > 0 , we infer that

C h 2 R N U 0 2 ( x ) d x R N ( 1 ψ ( h 1 x ) 2 ) U 0 2 ( x ) d x 1 x h e C x d x 1 x h x N δ d x 1 h δ .

It follows that C h 2 = 1 + O ( h ) as h , where O ( h ) = A h and A h C h δ for any δ > 0 with some constant C > 0 independent of h . By computation, we have

g h 2 2 = C h 2 R N ψ ( h 1 x ) 2 U 0 2 ( x ) d x + C h 2 h 2 R N ψ ( h 1 x ) 2 U 0 ( x ) 2 d x + 2 C h 2 h Re R N ψ ( h 1 x ) U 0 ( x ) ψ ( h 1 x ) U 0 ( x ) d x .

From the fact that U 0 decays exponentially at infinity and C h 2 = 1 + O ( h ) , we have

g h 2 2 = h 2 U 0 2 2 + O ( h ) as h .

By computation, it is easy to see that

R N R N g h ( x ) 2 g h ( y ) 2 x y 2 d x d y = R N R N h 2 U 0 2 ( x ) U 0 2 ( y ) x y 2 d x d y + O ( h ) as h .

Since g h is radially symmetric, we have R N g h ¯ L z g h d x = 0 . Moreover, we have

R N x 2 g h 2 d x = C h 2 R N x 2 h N ψ ( x ) 2 U 0 2 ( h x ) d x 0 as h ,

since h N U 0 2 ( h x ) converges weakly to the Dirac delta function at zero when h . Recalling U 0 = U U 2 and (2.9), we have U 0 2 2 = 1 and

(3.5) U 0 2 2 U 2 2 = 1 2 R N R N U 0 2 ( x ) U 0 2 ( y ) x y 2 d x d y .

It follows that

(3.6) e Ω , b E Ω , b ( g h ) = R N g h 2 d x b 2 R N R N g h ( x ) 2 g h ( y ) 2 x y 2 d x d y + o ( 1 ) = h 2 U 0 2 2 b 2 h 2 R N R N U 0 2 ( x ) U 0 2 ( y ) x y 2 d x d y + o ( 1 ) = h 2 U 0 2 2 1 b U 2 2 + o ( 1 )

as h . Obviously, letting h , if b > U 2 2 = b * , we have e Ω , b = . Hence, there is no minimizer for e Ω , b .

If b = U 2 2 = b * , we have from (3.6) that e Ω , b 0 . On the contrary, from (3.1), we have e Ω , b 0 . Hence, e Ω , b = 0 . Next, we show that there is no minimizer for e Ω , b . Assume by contradiction that there exists a minimizer ω for e Ω , b . We have from (3.1) that

0 = E Ω , b ( ω ) R N V Ω ω 2 d x 0 ,

which implies that R N V Ω ω 2 d x = 0 . By (1.14), (2.6), (2.10), and ω S ( 1 ) , we infer that

( i + P ) ω 2 2 = b * 2 R N R N ω ( x ) 2 ω ( y ) 2 x y 2 d x d y < R N ω 2 d x ( i + P ) ω 2 2 ,

which is a contradiction. The proof is complete.□

4 Proof of Theorem 1.3

In this section, we are interested in behavior of ground states for e Ω , b at the critical speed Ω = 1 when b b * and give the proof of Theorem 1.3. First, we give the energy upper bound when b b * .

Lemma 4.1

Assume that N 3 , Ω = 1 and V ( x ) = x 2 2 . Let ( b n ) be a positive sequence satisfying b n b * as n . Then, we have

lim n e Ω , b n = e Ω , b * = 0 .

More precisely,

(4.1) limsup n e Ω , b n ( b * b n ) 1 2 2 x U 0 2 b * 1 2 .

Proof

From (3.1), it is obvious that e Ω , b n 0 . Let u h ( x ) = h N 2 U 0 ( h x ) and h > 0 . Since u h is radially symmetric, we have L z u h , u h = 0 . We infer from (3.5) that

(4.2) e Ω , b n E Ω , b n ( u h ) = R N u h 2 d x + R N x 2 u h 2 d x b n 2 R N R N u h ( x ) 2 u h ( y ) 2 x y 2 d x d y = h 2 U 0 2 2 + h 2 x U 0 2 2 b n 2 h 2 R N R N U 0 2 ( x ) U 0 2 ( y ) x y 2 d x d y = h 2 1 b n b * U 0 2 2 + h 2 x U 0 2 2 = h 2 1 b n b * + h 2 x U 0 2 2 .

Optimizing over h , we have

(4.3) e Ω , b n ( b * b n ) 1 2 2 x U 0 2 b * 1 2 ,

which implies (4.1) and e Ω , b * = 0 .□

Next, we show that the sequence of ground state for e Ω , b n blows up when Ω = 1 and b n b * .

Lemma 4.2

Assume that N 3 , Ω = 1 , and V ( x ) = x 2 2 . Let ( b n ) be a positive sequence satisfying b n b * as n and u n be a ground state for e Ω , b n . Then, ( u n ) blows up in Σ Ω and H 1 ( R N ) .

Proof

First, we show that ( u n ) blows up in Σ Ω . Assume for contradiction that

(4.4) sup n 1 u n Σ Ω < ,

which implies that ( u n ) is bounded in Σ Ω . Combining with Lemmas 2.1 and 3.2, there exist u ˜ Σ Ω \ { 0 } and a sequence y n = ( y n 1 , y n 2 , 0 , , 0 ) such that up to a subsequence,

u ˜ n ( x ) e i P ( y n ) x u n ( x + y n ) u ˜ weakly in Σ Ω .

We infer from the similar proof of Theorem 1.1 ( i ) that u ˜ n u ˜ in L 2 ( R N ) . We then deduce that

e Ω , b * E Ω , b * ( u ˜ ) liminf n E Ω , b n ( u n ) = liminf n e Ω , b n = e Ω , b *

which implies that u ˜ is a ground state for e 1 , b * . However, this is a contraction with Theorem 1.1 ( i i ) . Thus, we have sup n 1 u n Σ Ω = .

Next, we show ( u n ) blows up in H 1 ( R N ) . We deduce that

0 = e 1 , b * = lim n e 1 , b n = lim n E 1 , b n ( u n ) = ( i + P ) u n 2 2 + R N V Ω ( x ) u n 2 d x b n 2 R N R N u n ( x ) 2 u n ( y ) 2 x y 2 d x d y .

Since ( i + P ) u n Σ Ω as n and u n 2 2 = 1 , we have

R N R N u n ( x ) 2 u n ( y ) 2 x y 2 d x d y as n .

We infer from (2.10) that u n 2 . Thus, ( u n ) blows up in H 1 ( R N ) .□

Obviously, the blow-up length ε n = u n 2 1 0 as n . To prove Theorem 1.3, we present the following lemma, which means that there exists convergence modulo of a magnetic translation of vector y n and holds significant importance in managing the blow-up behavior.

Lemma 4.3

Assume that N 3 , Ω = 1 , V ( x ) = x 2 2 , and b n b * as n . Let ( u n ) be the sequence of ground states for e Ω , b n . Let

τ n ( x ) ε n N 2 u n ( ε n x + y n ) e i ε n P ( y n ) x + i θ n .

Then, we have

(4.5) τ n ( x ) = ε n N 2 u n ( ε n x + y n ) U 0 in H 1 ( R N ) as n .

Proof

Denote ζ n ε n N 2 u n ( ε n x ) . It is easy to see that ζ n 2 2 = 1 and ζ n 2 2 = ε n 2 u n 2 2 = 1 . Thus, ( ζ n ) is a bounded sequence in H 1 ( R N ) . By (2.6) and (2.10), for u S ( 1 ) , we have

(4.6) ( i + P ) u 2 2 b 2 R N R N u ( x ) 2 u ( y ) 2 x y 2 d x d y u 2 2 b 2 R N R N u ( x ) 2 u ( y ) 2 x y 2 d x d y E b ( u ) 1 b b * u 2 2 .

Combining (1.14) with (4.6), we have

0 = lim n e Ω , b n = lim n E Ω , b n ( u n ) liminf n E b n ( u n ) 0 ,

which implies E b n ( u n ) 0 as n . Thus, E b n ( ζ n ) = ε n 2 E b n ( u n ) 0 as n . It follows that

inf n 1 b n 2 R N R N ζ n ( x ) 2 ζ n ( y ) 2 x y 2 d x d y = inf n 1 ζ n 2 2 = 1 .

By applying Lemma 2.2, there exists u ˜ H 1 ( R N ) \ { 0 } and ( x n ) R N with x n = ( x n 1 , x n 2 , 0 , , 0 ) such that up to a subsequence,

w n = ζ n ( x + x n ) u ˜ weakly in Σ .

Next, we show that u ˜ 2 2 = 1 . By the weak lower semi-continuity, we have

0 < u ˜ 2 2 liminf n w n 2 2 = lim n ζ n 2 2 = 1 .

Assume for contradiction that u ˜ 2 2 < 1 . From Brezis and Lieb [8], we have

(4.7) lim n R N ω n 2 u ˜ 2 ( ω n u ˜ ) 2 d x = 0 .

Combining (2.5), (4.6), and (4.7), we have

0 = lim n E b n ( ζ n ) = lim n E b n ( ω n ) = lim n E b n ( ω n u ˜ ) + lim n E b n ( u ˜ ) lim n E b * ( ω n u ˜ ) + E b * ( u ˜ ) 0 ,

which implies E b * ( u ˜ ) = 0 . On the contrary, we have

u ˜ 2 2 E b * u ˜ u ˜ 2 = u ˜ 2 2 b * 2 u ˜ 2 2 R N R N u ˜ ( x ) 2 u ˜ ( y ) 2 x y 2 d x d y = E b * ( u ˜ ) + 1 1 u ˜ 2 2 b * 2 R N R N u ˜ ( x ) 2 u ˜ ( y ) 2 x y 2 d x d y .

It follows that

E b * ( u ˜ ) = u ˜ 2 2 E b * u ˜ u ˜ 2 + 1 u ˜ 2 2 1 b * 2 R N R N u ˜ ( x ) 2 u ˜ ( y ) 2 x y 2 d x d y > 0 ,

which contradicts with the fact that E b * ( u ˜ ) = 0 . Thus, ω n u ˜ in L 2 ( R N ) . We infer from (2.1) and (2.5) that

0 = E b * ( u ˜ ) liminf n E b * ( ω n ) = liminf n E b n ( ζ n ) = 0 ,

which implies that

lim n ω n 2 2 = lim n b n 2 R N R N ω n ( x ) 2 ω n ( y ) 2 x y 2 d x d y = b * 2 R N R N u ˜ ( x ) 2 u ˜ ( y ) 2 x y 2 d x d y = u ˜ 2 2 .

This shows that ω n u ˜ in H 1 ( R N ) , and u ˜ is an optimizer of (2.10) with u ˜ 2 2 = 1 . Without loss of generality, we may assume that there exist h > 0 and x 0 = ( x 0,1 , x 0 , 2 , 0 , , 0 ) R N such that u ˜ = h N 2 U 0 ( h ( x + x 0 ) ) . Since u ˜ 2 2 = ω n 2 2 = ζ n 2 2 = 1 , we must have h = 1 . Setting y n = ε n ( x n x 0 ) , we obtain that (4.5) holds.□

Now, we are in a position to prove Theorem 1.3.

Proof of Theorem 1.3

The proof is divided into several steps.

( i ) We claim that ε n 2 λ n 1 as n . The minimizer u n of e 1 , b n satisfies the Euler-Lagrange equation

(4.8) ( i + P ) 2 u n + V Ω u n b n u n R N u n ( y ) 2 x y 2 d y = λ n u n , x R N ,

where λ n is the Lagrange multiplier. From (4.8) and u n S ( 1 ) , we have

(4.9) λ n = ( i + P ) 2 u n 2 2 + R N V Ω u n 2 d x b n R N R N u n ( x ) 2 u n ( y ) 2 x y 2 d x d y = E Ω , b n ( u n ) b n 2 R N R N u n ( x ) 2 u n ( y ) 2 x y 2 d x d y = e Ω , b n b n 2 R N R N u n ( x ) 2 u n ( y ) 2 x y 2 d x d y .

Denote η n ε n N 2 u n ( ε n x + y n ) e i ε n P ( y n ) x . We have τ n ( x ) = e i θ n η n and θ n [ 0 , 2 π ) satisfying

(4.10) τ n U 0 2 = lim θ n [ 0 , 2 π ) e i θ n η n U 0 2 .

By (3.5) and (4.5), we infer that

(4.11) lim n R N R N τ n ( x ) 2 τ n ( y ) 2 x y 2 d x d y = lim n ε n 2 R N R N u n ( x ) 2 u n ( y ) 2 x y 2 d x d y = R N R N U 0 2 ( x ) U 0 2 ( y ) x y 2 d x d y = 2 b * U 0 2 2 = 2 b * .

By applying Lemma 4.1, (4.9), and (4.11), we deduce that

lim n ε n 2 λ n = lim n ε n 2 e Ω , b n lim n ε n 2 b n 2 R N R N u n ( x ) 2 u n ( y ) 2 x y 2 d x d y = 1 .

( i i ) Denote S n τ n 2 . We claim that

(4.12) 1 2 Δ S n b n S n R N S n ( y ) x y 2 d y λ n ε n 2 S n 0 .

Write η n ( x ) = ε n N 2 η ˜ n ( ε n x ) with η ˜ n ( x ) u n ( x + y n ) e i P ( y n ) x . From (4.8), by direct computation, we have

( i + P ) 2 η ˜ n + V Ω η ˜ n b n η ˜ n R N η ˜ n ( y ) 2 x y 2 d y = λ n η ˜ n ,

which implies that η ˜ n satisfying

(4.13) Δ η ˜ n + x 2 η ˜ n + 2 L z η ˜ n b n η ˜ n R N η ˜ n ( y ) 2 x y 2 d y = λ n η ˜ n .

Recalling τ n ( x ) = e i θ n ε n N 2 u n ( ε n x + y n ) e i ε n P ( y n ) x , we obtain that τ n ( ε n 1 x ) = e i θ n ε n N 2 u n ( x + y n ) e i P ( y n ) x = e i θ n ε n N 2 η ˜ n . From (4.13), by computation, we infer that

(4.14) Δ τ n + ε n 4 x 2 τ n + 2 ε n 2 L z τ n b n τ n R N τ n ( y ) 2 x y 2 d y = λ n ε n 2 τ n .

Noting that

Re ( Δ τ n τ ¯ n ) = 1 2 Δ S n + τ n 2 , ( i + ε n 2 P ) τ n 2 = τ n 2 + ε n 4 ( x 1 2 + x 2 2 ) τ n 2 + 2 Re ( ε n 2 τ ¯ n L z τ n ) .

Multiplying both sides of (4.14) with τ ¯ n and taking the real part, we have

(4.15) 1 2 Δ S n + τ n 2 + ε n 4 x 2 S n + 2 Re ( ε n 2 τ ¯ n L z τ n ) b n S n ( x ) R N S n ( y ) x y 2 d y = λ n ε n 2 S n .

It follows that

1 2 Δ S n + ( i + ε n 2 P ) τ n 2 + ε n 4 V Ω S n b n S n ( x ) R N S n ( y ) x y 2 d y λ n ε n 2 S n = 0 ,

which implies that (4.12) holds. It means that in the weak sense, we have

R N 1 2 S n ξ d x R N b n S n ( x ) R N S n ( y ) x y 2 d y + λ n ε n 2 S n ξ d x .

( i i i ) We claim that S n is uniform bounded. Let M > 0 , D M = { x R N : x M } . Applying Lemma 2.3 to (4.12) with D = D M , a j k = 1 2 δ j k , δ j k = 1 , j = k 0 , j k , f = b n S n ( x ) R N S n ( y ) x y 2 d y + λ n ε n 2 S n , p = 1 , R = 2 , and B 2 ( x 0 ) D M , we have

(4.16) sup S n ( x ) B 1 ( x 0 ) C S n L 1 ( B 2 ( x 0 ) ) + R N S n ( y ) x y 2 d y S n L q ( B 2 ( x 0 ) ) C S n L 1 ( x M ) + R N S n ( y ) x y 2 d y S n L q ( x M )

for some universal constant C > 0 and q > N 2 . From (4.5), we know that τ n U 0 in L r ( R N ) for all r [ 2 , 2 * ] . By the Hölder inequality, we have

(4.17) S n U 0 2 1 τ n + U 0 2 τ n U 0 2 ,

which implies S n U 0 2 in L 1 ( R N ) . Moreover, (2.4) together with the Hölder inequality yields

(4.18) R N S n ( y ) x y 2 d y S n L q ( x M ) R N R N S n ( y ) x y 2 d y p 1 q d x 1 p 1 q S n q 1 q ( x M ) C S n m S n q 1 q ( x M ) ,

where 1 p 1 + 1 q 1 = 1 , 1 < p 1 , q 1 < , 1 m = 1 p 1 q + α N . Noting that q > N 2 , α = N 2 , we infer that 1 < m < 2 * 2 . Thus, S n U 0 2 in L m ( R N ) . Since N < 6 , by the Hölder inequality, we have that S n U 0 2 in L q 1 q ( R N ) by choosing suitable q 1 . Combining (4.16), (4.17) with (4.18), we infer that

sup S n ( x ) B 1 ( x 0 ) U 0 2 L 1 ( x M ) + U 0 2 L q 1 q ( x M ) .

It follows from the exponential decay of U 0 that for κ > 0 , there exists n κ N and M κ sufficiently large such that for all n n κ and all M M κ

sup S n ( x ) B 1 ( x 0 ) κ for all B 1 ( x 0 ) D M κ .

As B 1 ( x 0 ) is arbitrarily in D M κ , we have

sup S n ( x ) κ for all x M κ and all n sufficiently large .

Applying Lemma 2.3 again to (4.12) with D = R N , a j k = 1 2 δ j k , f = b n R N S n ( y ) x y 2 d y S n ( x ) + λ n ε n 2 S n , p = 1 , and R = 2 M κ , we have

sup S n ( x ) B M κ ( 0 ) C M κ N U 0 2 L 1 ( B 2 M κ ( 0 ) ) + M κ 2 N q U 0 2 L q 1 q ( B 2 M κ ( 0 ) )

for some universal constant C > 0 , q > N 2 , and suitable q 1 > 1 as above. Then, we obtain sup B M κ ( 0 ) S n ( x ) C ( M κ ) for all n sufficiently large. Thus, 0 sup x R N S n ( x ) C for all n sufficiently large, where C > 0 is a constant independent of n .

( i v ) We claim that S n is uniform exponential decay. Testing (4.12) with e ε x S n for some constant ε > 0 to be chosen shortly, we have

(4.19) 1 2 R N Δ S n e ε x S n d x b n R N R N S n ( y ) x y 2 d y S n e ε x S n d x R N λ n ε n 2 S n e ε x S n d x 0 .

By computation, we have

R N Δ S n e ε x S n d x = 1 2 R N S n 2 ε 2 + ε x e ε x d x R N S n 2 e ε x d x

and

R N ( S n e ε x 2 ) 2 d x = ε 2 4 R N S n 2 e ε x d x + R N S n 2 e ε x d x 1 2 R N S n 2 ε 2 + ε x e ε x d x .

It follows that

R N Δ S n e ε x S n d x = ε 2 4 R N S n 2 e ε x d x R N ( S n e ε x 2 ) 2 d x ,

which implies

1 2 R N ( S n e ε x 2 ) 2 d x ε 2 8 R N S n 2 e ε x d x b n R N R N S n ( y ) x y 2 d y e ε x S n 2 d x λ n R N ε n 2 e ε x S n 2 d x 0 .

We then deduce that

(4.20) R N ε 2 8 b n R N S n ( y ) x y 2 d y λ n ε n 2 e ε x S n 2 d x 0 .

Recalling λ n ε n 2 1 as n , picking ε = 1 and M , R > 0 , we infer from (4.20) that

(4.21) R N \ B M ( 0 ) λ n ε n 2 1 8 b n R N S n ( y ) x y 2 d y e x S n 2 d x B M ( 0 ) λ n ε n 2 1 8 b n R N S n ( y ) x y 2 d y e x S n 2 d x = B M ( 0 ) λ n ε n 2 1 8 + b n B R ( 0 ) S n ( y ) x y 2 d y + b n R N \ B R ( 0 ) S n ( y ) x y 2 d y e x S n 2 d x .

Let r = x y and Ω ˜ be an open and bounded subset of R N . Noting that S n is uniform bounded, we have

B R ( 0 ) S n ( y ) x y 2 d y C Ω ˜ r N 1 r 2 d r C

for some constant C > 0 and all n sufficiently large. It is easy to see that for R M

R N \ B R ( 0 ) S n ( y ) x y 2 d y δ for x M ,

where δ > 0 is a constant. Thus, from (4.21), we have

(4.22) R N \ B M ( 0 ) λ n ε n 2 1 8 b n R N S n ( y ) x y 2 d y e x S n 2 d x C e M S n L 2 ( B M ( 0 ) ) 2 C e M ,

for all n sufficiently large. On the contrary, we have from the Hölder inequality that

R N S n ( y ) x y 2 d y = R N S n ( y ) U 0 2 ( y ) x y 2 d y + R N U 0 2 ( y ) x y 2 d y = R N ( τ n ( y ) U 0 ( y ) ) ( τ n ( y ) + U 0 ( y ) ) x y 2 d y + R N U 0 2 ( y ) x y 2 d y C τ n ( y ) U 0 ( y ) p R N ( τ n ( y ) + U 0 ( y ) ) q x y 2 q d y 1 q + R N U 0 2 ( y ) x y 2 d y ,

where C > 0 , 1 p + 1 q = 1 and 1 < p , q < . Since U 0 is the exponential decay, by applying Lemma 2.3 in [33], for M sufficiently large, there exists δ > 0 such that

R N U 0 2 ( y ) x y 2 d y < δ and R N τ n ( y ) U 0 ( y ) x y 2 q d y < δ as x M .

It follows that

(4.23) R N S n ( y ) x y 2 d y τ n ( y ) U 0 ( y ) p R N τ n q ( y ) x y 2 q d y 1 q + o ( 1 ) as x M .

We next claim that

(4.24) R N S n ( y ) x y 2 d y 0 as x M , n .

For N 4 , picking p = q = 2 , letting y x = t , we have

(4.25) R N τ n q ( y ) x y 2 q d y = R N τ n 2 ( x + t ) t 4 d t = B R ( 0 ) τ n 2 ( x + t ) t 4 d t + R N \ B R ( 0 ) τ n 2 ( x + t ) t 4 d t 0 R r N 5 d r + 1 R 4 t R τ n 2 ( x + t ) d t C ,

where C > 0 and we used the fact that S n is the uniform bounded. For N = 3 , picking p = 3 , q = 3 2 , letting y x = t , by the Hölder inequality, we have

(4.26) R N τ n q ( y ) x y 2 q d y = B R ( 0 ) τ n 3 2 ( x + t ) t 3 d t + R N \ B R ( 0 ) τ n 3 2 ( x + t ) t 3 d t 0 R r N 4 d r + t R τ n 3 ( x + t ) d t 1 2 t R t 6 d t 1 2 0 R r N 4 d r + R r N 7 d r 1 2 C .

Since τ n U 0 in L r ( R N ) with r [ 2 , 2 * ] , combining (4.23), (4.25) with (4.26), we have that (4.24) holds for N 3 , which implies

(4.27) λ n ε n 2 1 8 b n R N S n ( y ) x y 2 d y > 1 4 for x M , n .

By (4.22) and (4.27), we have

1 4 R N \ B M ( 0 ) e x S n 2 d x C e M

for all M and n sufficiently large. Obviously, B M ( 0 ) e x S n 2 d x C for some constant C > 0 independent of n . This proves that

R N e x S n 2 d x C ,

for all n sufficiently large. Moreover, we deduce that

R N S n e x 4 d x = R N S n e x 2 e x 4 d x R N S n 2 e x d x 1 2 R N e x 2 d x 1 2 C

for all n sufficiently large. Thus, S n is the uniform exponential decay.

( v ) Now, we prove that (1.17) holds. By the definition of τ n and the fact P ( y n ) y n = 0 , we have

u n ( x ) = ε n N 2 τ n ( ε n 1 ( x y n ) ) e i P ( y n ) x i θ n .

Since u n is a ground state for e 1 , b n , we infer from (1.14) and (2.6) that

(4.28) e 1 , b n = E 1 , b n ( u n ) ε n 2 τ n 2 2 b n 2 ε n 2 R N R N τ n ( x ) 2 τ n ( y ) 2 x y 2 d x d y ,

which implies that

τ n 2 2 ε n 2 e 1 , b n + b n 2 R N R N τ n ( x ) 2 τ n ( y ) 2 x y 2 d x d y ε n 2 e 1 , b n + b n 2 C ˜ R N τ n 4 N N + α N + α N .

Recalling ε n 0 , e 1 , b n 0 as n and τ n U 0 in L r ( R N ) for r [ 2 , 2 * ] , we obtain that ( τ n ) is bounded in H 1 ( R N ) . Moreover, from (1.11), we have

e 1 , b n = ε n 2 τ n 2 2 + ε n 2 x τ n 2 2 + 2 R N τ ¯ n L z τ n d x b n 2 ε n 2 R N R N τ n ( x ) 2 τ n ( y ) 2 x y 2 d x d y .

It follows that

τ n 2 2 b * 2 R N R N τ n ( x ) 2 τ n ( y ) 2 x y 2 d x d y = ε n 2 e 1 , b n ε n 4 x τ n 2 2 2 ε n 2 R N τ ¯ n L z τ n d x b * b n 2 R N R N τ n ( x ) 2 τ n ( y ) 2 x y 2 d x d y .

By the uniform exponential decay of S n , we have x τ n x U 0 in L 2 ( R N ) . From (2.7), we know that

ε n 2 R N τ ¯ n L z τ n d x 0 as n .

Thus, when b n b * , we infer that

lim n τ n 2 2 b * 2 R N R N τ n ( x ) 2 τ n ( y ) 2 x y 2 d x d y = 0 .

Since τ n 2 2 = 1 and τ n U 0 in H 1 ( R N ) , there exists z n R N , some θ R such that

τ n ( x + z n ) e i θ U 0 ( x ) in H 1 ( R N ) .

It is clear that U 0 ( + z n ) U 0 H 1 0 if and only if z n 0 . One deduces that z n 0 . Moreover,

τ n e i θ U 0 H 1 = τ n ( + z n ) e i θ U 0 ( + z n ) H 1 τ n ( + z n ) e i θ U 0 H 1 + e i θ ( U 0 U 0 ( + z n ) ) H 1 0 ,

which implies that τ n e i θ U 0 in H 1 ( R N ) . It follows that

(4.29) R N ( Re ( τ n e i θ U 0 ) ) 2 + ( Im ( τ n e i θ U 0 ) ) 2 d x 0 .

Let τ n = a n ( x ) + i d n ( x ) with a n and d n being the real and imaginary parts of τ n , respectively. It is easy to see that

R N ( d n U 0 sin θ ) 2 d x 0 .

Writing τ n = f n e i θ = f n ( cos θ + i sin θ ) , θ [ 0 , 2 π ) , then we have

τ n U 0 2 2 = R N ( τ n U 0 ) ( τ ¯ n U 0 ) d x = R N τ n 2 + U 0 2 2 f n cos θ U 0 d x T ( θ ) .

From (4.10), one infers that T ( θ ) = 0 . It follows that

R N f n sin θ U 0 d x = 0 ,

which implies

(4.30) R N U 0 d n d x = 0 .

Then, we have

R N d n 2 + U 0 2 sin 2 θ d x 0 ,

which shows that

R N d n 2 0 and sin 2 θ = 0 .

Thus, we obtain θ = 0 and τ n U 0 in H 1 ( R N ) .

( v i ) Finally, we prove that (1.18) holds. By (2.6) and (2.10), one infers that

(4.31) ( i + P ) u n 2 2 b n 2 R N R N u n ( x ) 2 u n ( y ) 2 x y 2 d x d y u n 2 2 1 b n b * 0 .

Then, from (1.14), we have

(4.32) e 1 , b n = E 1 , b n ( u n ) R N V Ω u n 2 d x = ε n 2 R N V Ω τ n 2 d x .

Denote

β n ε n ( b * b n ) 1 4 .

By using (4.31) and the definition of ε n , we have that e 1 , b n ε n 2 1 b n b * . From (4.1), one infers that

ε n 2 1 b n b * C ( b * b n ) 1 2 ,

where C > 0 . This implies that ε n 2 C ( b * b n ) 1 2 with C > 0 . Moreover, we obtain that β n 2 C > 0 . On the contrary, we derive from (4.1) and (4.32) that there exists some C ˆ > 0 ,

C ˆ e 1 , b n ( b * b n ) 1 2 ε n 2 R N V Ω τ n 2 d x ( b * b n ) 1 2 = β n 2 R N V Ω τ n 2 d x .

This shows that ( β n ) is bounded above and below away from zero. Passing to a subsequence, we have β n β > 0 as n . By using (1.14), (2.6), and (2.10) again, we have

(4.33) e 1 , b n b * b n 2 R N R N u n ( x ) 2 u n ( y ) 2 x y 2 d x d y + R N V Ω u n 2 d x = b * b n 2 ε n 2 R N R N τ n ( x ) 2 τ n ( y ) 2 x y 2 d x d y + ε n 2 R N V Ω τ n 2 d x = ( b * b n ) 1 2 2 β n 2 R N R N τ n ( x ) 2 τ n ( y ) 2 x y 2 d x d y + β n 2 ( b * b n ) 1 2 R N V Ω τ n 2 d x .

It follows that

e 1 , b n ( b * b n ) 1 2 1 2 β n 2 R N R N τ n ( x ) 2 τ n ( y ) 2 x y 2 d x d y + β n 2 R N V Ω τ n 2 d x .

Since x i τ n x i U 0 in L 2 ( R N ) , τ n U 0 in H 1 ( R N ) , we deduce from (2.3), (2.5), and (4.11) that

e 1 , b n ( b * b n ) 1 2 1 2 β 2 R N R N U 0 2 ( x ) U 0 2 ( y ) x y 2 d x d y + β 2 R N V Ω U 0 2 d x = 1 2 β 2 2 b * + β 2 R N V Ω U 0 2 d x .

Optimizing over β > 0 , we have

liminf n e 1 , b n ( b * b n ) 1 2 2 R N V Ω ( x ) U 0 2 d x 1 2 b * 1 2 ,

with

β = 1 b * 1 4 R N V Ω ( x ) U 0 2 d x 1 4 .

This completes the proof of Theorem 1.3.□

Acknowledgments

The authors express their gratitude to the anonymous referees for their insightful comments and thoughtful suggestions, which have significantly enhanced the quality of the results.

  1. Funding information: J. Wang was supported by the NNSF of China (No. 12371114) and National Key R&D Program of China (No. 2022YFA1005601).

  2. Author contributions: The authors contributed equally in this article. They have all read and approved the final manuscript.

  3. Conflict of interest: The authors declare that they have no competing interests.

  4. Data availability statement: No data were used to support this study.

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Received: 2024-09-08
Revised: 2025-02-24
Accepted: 2025-04-07
Published Online: 2025-06-02

© 2025 the author(s), published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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