Home Entire radial bounded solutions for Leray-Lions equations of (p, q)-type
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Entire radial bounded solutions for Leray-Lions equations of (p, q)-type

  • Federica Mennuni , Dimitri Mugnai and Addolorata Salvatore EMAIL logo
Published/Copyright: February 18, 2025

Abstract

We prove the existence of entire, radial, and signed bounded solutions for a quasilinear elliptic equation in R N driven by a Leray-Lions operator of the (p, q)-type. For this, we need an extension of related results by Boccardo-Murat-Puel and a variational approach in intersections of Banach spaces introduced by Candela-Palmieri.

MSC 2010: 35J20; 35J62; 58E30

1 Introduction

This article aims to investigate the existence of weak bounded solutions for the generalized quasilinear Schrödinger equation:

(1.1) div ( a ( x , u , u ) ) + A t ( x , u , u ) + u p 2 u + u q 2 u = g ( x , u ) in  R N ,

where 1 < q p , N 2 , A : R N × R × R N R is C 1 -Carathéodory function with partial derivatives

A t ( x , t , ξ ) = A t ( x , t , ξ ) , a ( x , t , ξ ) = ξ A ( x , t , ξ ) ,

while g : R N × R R is a given Carathéodory function. The Leray-Lions operators we can handle include the case of the so-called double-phase operator A ( x , t , ξ ) = A 1 ( x ) ξ p + A 2 ( x ) ξ q , which, in particular, covers the fundamental example:

div ( a ( x , u , u ) ) + A t ( x , u , u ) = Δ p u Δ q u ,

where Δ Q u = div ( u Q 2 u ) for any Q > 1 . Such an operator permits to consider more general equations than the classical Schrödinger one, and it is useful to treat some phenomena in biophysics [18], plasma physics [30], chemical reaction design [16], quantum field theory [2,25], and nonlinear optics and fluid mechanics [2]. Thus, it is not surprising that it has been widely investigated in the last decade, both in bounded and in unbounded domains, for instance, see [4,26,28] and the recent overview on this topic given in [24].

We notice that equation (1.1) has a variational structure since its solutions coincide, at least formally, with critical points of the functional

J ( u ) = R N A ( x , u , u ) d x + 1 p R N u p d x + 1 q R N u q d x R N G ( x , u ) d x ,

with G ( x , t ) = 0 t g ( x , s ) d s , whose formal Euler-Lagrange equation is precisely (1.1).

Such a functional has two basic difficulties, which arise independently on G . First, the problem being settled in R N , there is a natural lack of compactness; hence, standard variational tools cannot work directly; second, in general, J is Gâteaux differentiable only along directions in the space W 1 , p ( R N ) W 1 , q ( R N ) L ( R N ) .

Let us point out that even if p = q , G = 0 , A ( x , t , ξ ) = 1 p A 1 ( x , t ) ξ p and we look for solutions verifying homogeneous Dirichlet condition in a bounded domain Ω , the corresponding action functional

J ¯ ( u ) = 1 p Ω A 1 ( x , u ) u p d x

is not well defined on W 0 1 , p ( Ω ) if A 1 ( x , t ) is unbounded with respect to t . Moreover, even if A 1 ( x , t ) is strictly positive and bounded with respect to t but A 1 t ( x , t ) 0 , then J ¯ is well defined on W 0 1 , p ( Ω ) , but it is Gâteaux differentiable only along special directions in the space W 0 1 , p ( Ω ) .

For this reason, several abstract approaches have been introduced, see [1,8,9]. In particular, in the last two papers, the authors have introduced an approach in which the natural space is the intersection of L ( R N ) with the reference Sobolev one and the classical Palais-Smale condition is replaced by a weak Cerami-type one, see Definition 2.1. Such an approach has been fruitfully used in several situations, such as [6,12,13] (for equations in bounded domains), and [10,14,15, 2022,29] (for equations in the entire space).

In particular, in [20], the authors consider a quasilinear elliptic equation driven by a general operator of Leray-Lions type when the terms u p 2 u and u q 2 u are multiplied by two suitable unbounded potentials V ( x ) and W ( x ) . By using an approximation argument over bounded domains, they prove the existence of two bounded solutions, one negative and one positive (see also [22] if p = q ). An approximation method has been used also in [29], where V and W are as in [20], but the main term has the simplest form A ( x , t , ξ ) = 1 p A 1 ( x , t ) ξ p + 1 q A 2 ( x , t ) ξ q and g ( x , t ) has a super- p -linear growth.

Differently from [20,29], in this article, the coefficients V and W are constant, and we look for solutions of equation (1.1) by working directly in the whole Euclidean space and assuming that g is sub- p -linear at infinity.

Proving the validity of a weak Cerami-type condition is the core of our study, since the non compactness of R N is the main obstruction. For this reason, we assume that the problem is radially symmetric and we restrict our investigation to the subspace of radial functions, which turns out to be a natural constraint, in the spirit of the celebrated Palais’ result [27]. However, the setting being so general, the required convergence is not easy at all even in this framework. Indeed, we need a convergence result in the spirit of the one proved by Boccardo, Murat and Puel in [3, Lemma 5] (Lemma 3.9), but the novelty of our result is that it holds when we deal with Leray-Lions operators having (p, q)-growth. In particular, the q -growth introduces several difficulties since no compact embedding is possible when working with entire functions and low exponents, as q is. However, with the aid of a suitable a priori L -estimate, see Lemma 3.6, we are able to establish the desired result.

This article is organized as follows. In Section 2, we introduce the abstract framework and the general assumptions we make for our problem and we state our main theorem, which establishes the existence of two signed solutions (Theorem 2.14). In Section 3, we make precise the variational approach and we give some preliminary properties of the problem, together with the Boccardo-Murat-Puel-type result. In Section 4, we prove the weak Cerami-Palais-Smale condition for the functional J , and finally, we establish the existence of two radial weak bounded solutions for (1.1), one being positive and the other one being negative.

2 Abstract setting and statement of the main result

In this section, we assume that

  • ( X , X ) is a Banach space with dual ( X , X ) ;

  • ( S , S ) is a Banach space such that X S continuously, i.e., X S and a constant σ 0 > 0 exists such that

    u S σ 0 u X for all  u X ;

  • J : D S R and J C 1 ( X , R ) with X D .

Just to fix the ideas, one may think to X as the intersection of a Sobolev space with L and to S as the Sobolev space itself.

If β R , we say that a sequence ( u n ) n X is a Cerami-Palais-Smale sequence at level β , briefly ( CPS ) β -sequence, if

lim n + J ( u n ) = β and lim n + d J ( u n ) X ( 1 + u n X ) = 0 .

Moreover, β is a Cerami-Palais-Smale level, briefly (CPS)-level, if there exists a ( CPS ) β -sequence. We say that J satisfies the Cerami-Palais-Smale condition in X at level β if every ( CPS ) β -sequence converges in X (up to subsequences). However, considering the general setting of our problem, it may happen that a ( CPS ) β -sequence may be unbounded in X but being convergent with respect to S . In light of this, we need to weaken the classical Cerami-Palais-Smale condition in an appropriate way according to ideas developed in previous papers [79].

Definition 2.1

The functional J satisfies the weak Cerami-Palais-Smale condition at level β R , briefly ( wCPS ) β condition, if for every ( CPS ) β -sequence ( u n ) n , a point u X exists such that

  1. lim n + u n u S = 0 (up to subsequences),

  2. J ( u ) = β , d J ( u ) = 0 .

If J satisfies the ( wCPS ) β condition at each level β I , I real interval, we say that J satisfies the (wCPS) condition in I .

Let us point out that, due to the convergence only in S , the ( wCPS ) β condition implies that the set of critical points of J at the β level is compact with respect to S ; this is enough to prove a Deformation Lemma and some abstract theorems about critical points [9]. In particular, the following generalized version of the Weierstrass theorem holds true (see the Minimum Principle given in [9, Theorem 1.6]).

Proposition 2.2

If J C 1 ( X , R ) is bounded from below in X and ( wCPS ) β holds at level β = inf X J R , then J attains its infimum, i.e., u 0 X exists such that J ( u 0 ) = β and d J ( u 0 ) = 0 .

As it is clear, norms play a crucial role in our setting. For this reason, now we need to make precise the notation we will use throughout this article.

Here and in the following, let N = { 1 , 2 , } be the set of strictly positive integers, denote by x y the inner product in R N and by the standard norm on any Euclidean space as the dimension of the considered vector is clear and no ambiguity arises. Furthermore, we denote by:

  • B R ( x ) = { y R N : y x < R } the open ball in R N with center in x R N and radius R > 0 ;

  • B R c = R N \ B R ( 0 ) the complement of the open ball B R ( 0 ) in R N ;

  • meas ( Ω ) the usual Lebesgue measure of a measurable set Ω in R N ;

  • L ( R N ) the Lebesgue space with norm u = R N u d x 1 if 1 < + ;

  • L ( R N ) the space of Lebesgue-measurable and essentially bounded functions u : R N R with norm u = ess sup R N u ;

  • W 1 , l ( R N ) the classical Sobolev space with norm u l = ( u l l + u l l ) 1 l if 1 l < + ;

  • W r 1 , l ( R N ) = { u W 1 , l ( R N ) : u ( x ) = u ( x ) a.e. x R N } the subspace of radial functions of W 1 , l ( R N ) equipped with the same norm l ;

  • W = W 1 , p ( R N ) W 1 , q ( R N ) with norm W = p + q .

From the Sobolev embedding theorems, for any [ l , l * ] with l * = l N N l if N > l , or any [ l , + [ if l = N , the Sobolev space W 1 , l ( R N ) is continuously embedded in L ( R N ) , i.e., there exists a constant σ > 0 such that

u σ u l for all  u W 1 , l ( R N )

[5, Corollaries 9.10 and 9.11]. Clearly, it is σ l = 1 . On the other hand, if l > N , then W 1 , l ( R N ) is continuously imbedded in L ( R N ) [5, Theorem 9.12].

Finally, we define

X W L ( R N ) W 1 , p ( R N ) W 1 , q ( R N ) L ( R N ) , u X = u W + u .

Remark 2.3

If u L q ( R N ) L ( R N ) , then u L ( R N ) L ( R N ) for any > q , since

u = R N u d x 1 = R N u q u q d x 1 u 1 q u q q < + .

In particular, if u X , by Young’s inequality with conjugate exponents p p q and p q , we have

u p u 1 q p u q q p q p u q + 1 q p u .

Thus, if necessary, in the space X , we can consider the equivalent norm

u X = u q + u p + u .

From now on, we assume 1 < q p N as, otherwise X = W 1 , p ( R N ) W 1 , q ( R N ) and the proofs can be simplified.

Lemma 2.4

X L ( R N ) for any q .

Proof

Remark 2.3 implies that

W 1 , q ( R N ) L ( R N ) L q ( R N ) L ( R N ) L ( R N ) .

From Remark 2.3, if ( u n ) n L q ( R N ) L ( R N ) and u L q ( R N ) L ( R N ) are such that u n u in L q ( R N ) L ( R N ) , then u n u also in L ( R N ) for any q .

This result can be weakened as follows.

Lemma 2.5

If ( u n ) n L q ( R N ) L ( R N ) , u L q ( R N ) L ( R N ) , M > 0 are such that

u n u q 0 i f n + , u n M f o r a l l n N ,

then u n u also in L ( R N ) for any q .

Proof

If > q , we have

R N u n u d x u n u q R N u n u q d x ( M + u ) q u n u q q 0 .

From now on, we consider A : R N × R × R N R and g : R N × R R such that:

  1. A is a C 1 -Carathéodory function, i.e., A ( , t , ξ ) is measurable for all ( t , ξ ) R × R N , and A ( x , , ) is C 1 for a.e. x R N ;

  2. positive continuous functions φ i , Φ i , ψ i , Ψ i : R R , i { 0 , 1 , 2 } , exist such that

    A ( x , t , ξ ) φ 0 ( t ) t p + Φ 0 ( t ) ξ p + ψ 0 ( t ) t q + Ψ 0 ( t ) ξ q , A t ( x , t , ξ ) φ 1 ( t ) t p 1 + Φ 1 ( t ) ξ p + ψ 1 ( t ) t q 1 + Ψ 1 ( t ) ξ q , a ( x , t , ξ ) φ 2 ( t ) t p 1 + Φ 2 ( t ) ξ p 1 + ψ 2 ( t ) t q 1 + Ψ 2 ( t ) ξ q 1

    for a.e. x R N and for all ( t , ξ ) R × R N ;

  3. a constant α 0 > 0 exists such that

    A ( x , t , ξ ) α 0 ( ξ p + ξ q ) for a.e.  x R N  and for all  ( t , ξ ) R × R N ;

  4. a constant η 0 > 0 exists such that

    A ( x , t , ξ ) η 0 a ( x , t , ξ ) ξ for a.e.  x R N  and for all  ( t , ξ ) R × R N ;

  5. a constant α 1 > 0 exists such that

    a ( x , t , ξ ) ξ + A t ( x , t , ξ ) t α 1 a ( x , t , ξ ) ξ for a.e.  x R N  and for all  ( t , ξ ) R × R N ;

  6. constants μ > p and α 2 > 0 exist such that

    μ A ( x , t , ξ ) a ( x , t , ξ ) ξ A t ( x , t , ξ ) t α 2 A ( x , t , ξ ) for a.e.  x R N  and for all  ( t , ξ ) R × R N ;

  7. for all ξ , ξ * R N , ξ ξ * , for a.e. x R N and for all t R , we have

    [ a ( x , t , ξ ) a ( x , t , ξ * ) ] [ ξ ξ * ] > 0 ;

  8. A ( x , t , ξ ) = A ( x , t , ξ ) for a.e. x R N , and for all ( t , ξ ) R × R N ;

  9. some real constants l 1 , l 2 , η 1 , η 2 exist such that

    lim t 0 ψ 1 ( t ) t η 1 = l 1 , lim t 0 ψ 2 ( t ) t η 2 = l 2 ,

    with ψ 1 , ψ 2 as in ( h 1 ) and

    (2.1) η 1 > q N 1 η 2 > q 1 N 1 ;

  1. g ( x , t ) is a Carathéodory function;

  2. real numbers r ( 1 , p ) and s ( 1 , q ) and functions η L p p r ( R N ) L ( R N ) and ζ L q q s ( R N ) L ( R N ) exist such that

    0 g ( x , t ) t η ( x ) t r + ζ ( x ) t s for a.e.  x R N ,  for all  t R ,

  3. g ( x , t ) = g ( x , t ) for a.e. x R N , for all t R :

  4. we have that

    lim t 0 + g ( x , t ) t q 1 = + uniformly with respect to  x R N .

Example 2.6

The term

A ( x , t , ξ ) = 1 p ( A 1 * ( x ) + A 1 * * ( x ) t γ ) ξ p + 1 q ( A 2 * ( x ) + A 2 * * ( x ) t δ ) ξ q

for a.e. x R N and for all ( t , ξ ) R × R N , with γ , δ > 1 , verifies assumptions ( h 0 ) ( h 8 ) if coefficients A 1 * ( x ) , A 1 * * ( x ) , A 2 * ( x ) , A 2 * * ( x ) are bounded radial functions such that

A 1 * ( x ) α 0 > 0 , A 2 * ( x ) α 0 > 0 , A 1 * * ( x ) 0 , A 2 * * ( x ) 0 a.e. in  R N .

In particular, if A 1 * * ( x ) = A 2 * * ( x ) = 0 , we obtain the double-phase operator.

Remark 2.7

From ( h 1 ) , we obtain

A ( x , 0 , 0 ) = A t ( x , 0 , 0 ) = 0 and a ( x , 0 , 0 ) = 0 for a.e.  x R N .

Moreover, from ( g 1 ) , we have that

g ( x , 0 ) = 0 for a.e.  x R N ,

so that (1.1) admits the trivial solution.

We point out some direct consequences of the previous hypotheses.

Remark 2.8

In the assumptions ( h 2 ) ( h 4 ) , we may always suppose α 0 1 and α 1 1 .

Remark 2.9

From ( h 2 ) and ( h 3 ) , we obtain that

a ( x , t , ξ ) ξ α 0 η 0 ( ξ p + ξ q ) for a.e.  x R N  and for all  ( t , ξ ) R × R N .

Remark 2.10

From ( h 4 ) ( h 5 ) we have that

( μ α 2 ) A ( x , t , ξ ) α 1 a ( x , t , ξ ) ξ for a.e.  x R N  and for all  ( t , ξ ) R × R N ;

hence, if also ( h 2 ) ( h 3 ) hold, it is α 2 < μ . So,

(2.2) A ( x , t , ξ ) α 3 a ( x , t , ξ ) ξ for a.e.  x R N  and for all  ( t , ξ ) R × R N

with α 3 = α 1 μ α 2 > 0 . Moreover, from (2.2) and ( h 5 ) we have that

μ A ( x , t , ξ ) a ( x , t , ξ ) ξ A t ( x , t , ξ ) t α 2 α 3 a ( x , t , ξ ) ξ ,

for a.e. x R N and for all ( t , ξ ) R × R N .

Remark 2.11

We note that from ( h 2 ) ( h 5 ) it is

( 1 α 1 ) a ( x , t , ξ ) ξ A t ( x , t , ξ ) t ( μ α 2 ) A ( x , t , ξ ) ( μ α 2 ) η 0 a ( x , t , ξ ) ξ ,

which implies that

(2.3) A t ( x , t , ξ ) t c a ( x , t , ξ ) ξ

with c = max { ( μ α 2 ) η 0 , ( 1 α 1 ) } .

Remark 2.12

From ( h 8 ) , we notice that l 1 , l 2 0 and η 1 , η 2 > 0 .

Remark 2.13

From ( g 0 ) ( g 1 ) , we obtain that G ( x , t ) = 0 t g ( x , s ) d s is a well-defined C 1 -Carathéodory function in R N × R with

(2.4) 0 G ( x , t ) 1 r η ( x ) t r + 1 s ζ ( x ) t s for a.e.  x R N  and for all  t R .

Now, we are ready to state our main result.

Theorem 2.14

If assumptions ( h 0 ) ( h 8 ) and ( g 0 ) ( g 3 ) hold true, then problem (1.1) admits at least two weak nontrivial bounded solutions, one being positive and one negative.

Remark 2.15

We note that if q = p , Theorem 2.14 has been already proved in [23], which is thus covered by our result.

3 Variational approach and preliminary tools

First of all, we want to make precise the variational approach to the problem.

Let us start noticing the following facts.

Proposition 3.1

Assumptions ( g 0 ) ( g 1 ) imply that for all u , v W 1 , p ( R N ) W 1 , q ( R N )

R N G ( x , u ) d x R a n d R N g ( x , u ) v d x R .

As a consequence, the statements are true for every u X .

Proof

Although the proof is the same as in [20, Proposition 2.13], we briefly recollect it since it introduces some inequalities needed also in the following. Let u , v W 1 , p ( R N ) W 1 , q ( R N ) . From (2.4) and Hölder’s inequality with p p r and p r as conjugate exponents, and similarly with q q s and q s , we obtain

(3.1) R N G ( x , u ) d x 1 r η p p r u p r + 1 s ζ q q s u q s .

Moreover, by applying again Hölder inequality with p p r , p r 1 and p conjugate exponents, and similarly with q q s , q s 1 and q , we have

(3.2)□ R N g ( x , u ) v d x η p p r u p r 1 v p + ζ q q s u q s 1 v q .

Let us point out that assumptions ( h 0 ) ( h 1 ) and the definition of the Banach space X imply that A ( , u , u ) L 1 ( R N ) for any u X .

Therefore, by Proposition 3.1, the functional

(3.3) J ( u ) = R N A ( x , u , u ) d x + 1 p R N u p d x + 1 q R N u q d x R N G ( x , u ) d x

is well defined for all u X . Moreover, taking v X , the Gâteaux differential of the functional J in u along the direction v is given by

(3.4) d J ( u ) , v = R N a ( x , u , u ) v d x + R N A t ( x , u , u ) v d x + R N u p 2 u v d x + R N u q 2 u v d x R N g ( x , u ) v d x .

The following regularity result holds (for the proof, see [20, Proposition 2.14]).

Proposition 3.2

Assume that hypotheses ( h 0 ) ( h 1 ) and ( g 0 ) ( g 1 ) hold. If ( u n ) n X , u X , and M > 0 are such that

u n u a . e . i n R N , u n u p 0 , u n u q 0 a s n + , u n M f o r a l l n N ,

then

J ( u n ) J ( u ) a n d d J ( u n ) d J ( u ) X 0 a s n + .

Hence, J is a C 1 functional on X.

Thanks to Proposition 3.2, the search for solutions of equation (1.1) reduces to the search for critical points of the functional J ; thus, our aim is to prove that J satisfies the hypotheses of Proposition 2.2.

Let us start with the following simple facts.

Proposition 3.3

Assume that conditions ( h 0 ) ( h 2 ) and ( g 0 ) ( g 1 ) hold. Then, some positive constants c 1 , c 2 , c 3 , and c 4 exist such that

J ( u ) c 1 u p p + c 2 u q q c 3 u p r c 4 u q s f o r a n y u X .

Hence, a constant Γ R exists such that

J ( u ) Γ f o r a n y u X , w i t h Γ = min γ 1 , γ 2 0 ( c 1 γ 1 p c 2 γ 2 q c 3 γ 1 r c 4 γ 2 s ) .

Proof

From (3.3), ( h 2 ) , and (3.1), we have

J ( u ) = R N A ( x , u , u ) d x + 1 p R N u p d x + 1 q R N u q d x R N G ( x , u ) d x α 0 R N u p d x + 1 p R N u p d x + α 0 R N u q d x + 1 q R N u q d x 1 r η p p r u p r 1 s ζ q q s u q s c 1 u p p + c 2 u q q c 3 u p r c 4 u q s .

where c 1 = min { α 0 , 1 p } , c 2 = min { α 0 , 1 q } , c 3 = 1 r η p p r , and c 4 = 1 s ζ q q s .□

Lemma 3.4

Assume that g satisfies conditions ( g 0 ) ( g 1 ) and consider ( w n ) n , ( v n ) n X and w , v X such that

(3.5) w n p + w n q M 1 f o r a l l n N , w n w a . e . i n R N

and

(3.6) v n p + v n q M 2 f o r a l l n N , v n v a . e . i n R N ,

for some constants M 1 , M 2 > 0 . Then,

g ( x , w n ) v n g ( x , w ) v i n L 1 ( R N ) .

Proof

From (3.5), (3.6), and ( g 0 ) , we have

g ( x , w n ) v n g ( x , w ) v a.e. in  R N .

Moreover, from (3.2) and by applying again (3.5) and (3.6), we obtain that

R N g ( x , w n ) v n d x η p p r w n p r 1 v n p + ζ q q s w n q s 1 v n q M 1 r 1 M 2 η p p r + M 1 s 1 M 2 ζ q q s .

Since η L p p r ( R N ) and ζ L q q s ( R N ) , given ε > 0 , there exists R > 0 such that

(3.7) R N \ B R ( 0 ) g ( x , w n ) v n d x < ε

for every n N . On the other hand, by the absolute continuity of the Lebesgue integral, taking ε = min ε 2 M 1 r 1 M 2 p p r , ε 2 M 1 s 1 M 2 q q s , there exists δ ε > 0 such that

A η p p r d x ε , and A ζ q q s d x ε

for all measurable set A with meas ( A ) < δ ε , so that

A g ( x , w n ) v n d x ε

for all n N and for all measurable set A B R ( 0 ) with meas ( A ) < δ ε . Hence, by Vitali’s theorem, if v = 0 , then

(3.8) g ( x , w n ) v n 0 in L 1 ( B R ( 0 ) ) .

In conclusion, by (3.7) and (3.8), we obtain the claim if v = 0 .

In the general case, noticing that

g ( x , w n ) v n g ( x , w ) v = g ( x , w n ) ( v n v ) + ( g ( x , w n ) g ( x , w ) ) v ,

the integral of the first term in the right-hand side converges to 0 as mentioned earlier. Concerning the second term, by the weak lower semi-continuity of the norm, we have

R N ( g ( x , w n ) g ( x , w ) ) v d x η p p r ( w n p r 1 + w p r 1 ) v p + ζ q q s ( w n q s 1 + w q s 1 ) v q 2 M 1 r 1 M 2 η p p r + 2 M 1 s 1 M 2 ζ q q s .

Proceeding as mentioned earlier, we obtain the claim.□

From now on, in order to overcome the lack of compactness of the problem, we shall work in the space of radial functions, which is a natural constraint if the problem is radially invariant [27]. Thus, in our setting, we consider the space of radial functions in X , i.e.,

X r W r 1 , p ( R N ) W r 1 , q ( R N ) L ( R N )

endowed with norm X , which has dual space ( X r , X r ) .

Remark 3.5

Due to assumptions ( h 7 ) and ( g 2 ) , we can reduce to look for critical points of the restriction of J to X r , which we still denote by J , for the sake of simplicity. We notice that from Proposition 3.2 functional J is C 1 on the Banach space X r , too, if also ( h 0 ) ( h 1 ) and ( g 0 ) ( g 1 ) hold. Moreover, from Proposition 3.3, J is bounded from below in X r .

The following results will be useful in order to prove that J satisfies the weak Cerami-Palais-Smale condition in X r .

Lemma 3.6

(Radial lemma) If N 2 and q > 1 , for all u W r 1 , q ( R N ) , it is

(3.9) u ( x ) C u q x N 1 q a . e . i n R N ,

for a suitable constant C depending only on N and q.

Proof

For the proof, see [19, Lemma II.1].□

Lemma 3.7

If q > 1 , then the following embeddings hold:

  1. X r L ( R N ) f o r a l l [ q , + ] ,

  2. X r L ( R N ) f o r a l l ] q , + ) .

Proof

Condition ( i ) is a consequence of Lemma 2.4.

Now we prove condition ( i i ) . Since from [11, Theorem 3.2]  W r 1 , q ( R N ) L ( R N ) for all ] q , q * [ , we obtain that X r L ( R N ) for all ] q , q * [ . Thus, if u n u in X r and q * , taking ε > 0 so small that q < q * ε < q * , we have

R N u n u d x = R N u n u q * ε u n u q * + ε d x u n u q * + ε u n u q * ε q * ε M u n u q * ε q * ε 0 .

The following weaker result will be useful in the following.

Corollary 3.8

Let ( u n ) n X r , u X r , and R , M > 0 be such that

  1. u n ( x ) M f o r a . e . x R N w i t h x R , n N ;

  2. u n u w e a k l y i n W 1 , p ( R N ) W 1 , q ( R N ) .

Then, u n u in L ( R N ) for all ] q , p * [ . Moreover, if ( i ) holds for a.e. x R N , then u n u in L ( R N ) for all ] q , + ) .

Proof

We recall that for all l > 1

(3.10) W 1 , l ( B R ( 0 ) ) L ( B R ( 0 ) ) for all  [ l , l * ]

and, using again [11, Theorem 3.2]

(3.11) W r 1 , l ( R N ) L ( R N ) for all  ] l , l * [ .

Thus, from (3.11), the thesis holds for all ] q , q * [ ] p , p * [ .

If q * p and [ q * , p ] , taking ε > 0 such that q < q * ε < q * , assumptions ( i ) ( i i ) and (3.10)–(3.11) imply

R N u n u d x = B R C u n u q * ε u n u q * + ε d x + B R ( 0 ) u n u d x ( M + u ) q * + ε u n u q * ε q * ε + B R ( 0 ) u n u d x 0 .

Now, we prove the following convergence result in X r , generalizing a celebrated one stated in bounded domains in [3, Lemma 5] (see also [20, Lemma 4.5]).

Lemma 3.9

Assume that ( h 0 ) ( h 3 ) , ( h 7 ) , and ( h 8 ) hold. Let ( u n ) n X r , u X r be such that

(3.12) u n u w e a k l y i n W r 1 , p ( R N ) W r 1 , q ( R N ) ,

(3.13) u n u a . e . i n R N ,

(3.14) u n M f o r a l l n N ,

and

(3.15) R N [ a ( x , u n , u n ) a ( x , u n , u ) ] ( u n u ) d x 0 .

Then,

(3.16) R N u n p d x R N u p d x a n d R N u n q d x R N u q d x a s n + .

Proof

We will use arguments similar to those ones used in bounded domains in [20, Lemma 4.5], inspired by [3, Lemma 5].

We will prove that any subsequence of ( u n ) n admits another subsequence verifying (3.16) and then (3.16) holds for the original sequence ( u n ) n .

Let f n be defined by

f n = [ a ( x , u n , u n ) a ( x , u n , u ) ] ( u n u ) .

From ( h 6 ) , we know that f n 0 a.e. in R N , and from (3.15), we have f n 0 in L 1 ( R N ) . Thus, from [5, Theorem 4.9], a function h ¯ L 1 ( R N ) and a subset Z of R N exist such that meas ( Z ) = 0 and, up to a subsequence,

(3.17) f n ( x ) 0 and f n ( x ) h ¯ ( x ) < for all  x R N \ Z , for all  n N .

Moreover, since u X r and (3.13) holds, we can assume that

(3.18) u n ( x ) u ( x ) , u ( x ) < + and u ( x ) < + for all  x R N \ Z .

From ( h 1 ) ( h 3 ) , we also have

f n ( x ) α 0 η 0 ( u n p + u p + u n q + u q ) φ 2 ( u n ) u n p 1 u Φ 2 ( u n ) u n p 1 u ψ 2 ( u n ) u n q 1 u Ψ 2 ( u n ) u n q 1 u φ 2 ( u n ) u n p 1 u n Φ 2 ( u n ) u p 1 u n ψ 2 ( u n ) u n q 1 u n Ψ 2 ( u n ) u q 1 u n .

Since φ 2 , Φ 2 , ψ 2 , and Ψ 2 are continuous functions, by (3.14), (3.17), and (3.18), we find that

( u n ( x ) ) n is bounded for all  x R N \ Z .

Let ξ * ( x ) be a cluster point of ( u n ( x ) ) n . We have ξ * ( x ) < and, since f n ( x ) 0 and a is a Carathéodory function, we obtain that

[ a ( x , u , ξ * ) a ( x , u , u ) ] ( ξ * u ) = 0 ,

hence ( h 6 ) implies that u ( x ) = ξ * ( x ) for all  x R N \ Z .

From this, we deduce that u n ( x ) converges to u ( x ) without passing to a subsequence. Hence,

(3.19) u n ( x ) u ( x ) for all  x R N \ Z .

Thus, from ( h 0 ) , (3.18), and (3.19) we have that

a ( x , u n ( x ) , u n ( x ) ) a ( x , u ( x ) , u ( x ) ) for all  x R N \ Z ,

and then

(3.20) a ( x , u n , u n ) u n a ( x , u , u ) u a.e. in  R N .

Now, from ( h 2 ) and ( h 3 ) , it is

(3.21) a ( x , u n , u n ) u n 0 a.e. in  R N .

From (3.14) and ( h 1 ) , we obtain that

(3.22) a ( x , u n , u n ) c ( u n p 1 + u n q 1 + u n p 1 + u n q 1 ) .

Since (3.12) holds, ( u n ) n in bounded in W 1 , p ( R N ) W 1 , p ( R N ) ; thus, from (3.22), the sequence ( a ( x , u n , u n ) ) n is bounded in ( L p p 1 ( R N ) ) N + ( L q q 1 ( R N ) ) N . Hence, from (3.20), we can conclude that, up to susequences, a ( x , u n , u n ) weakly converges to a ( x , u , u ) in ( L p p 1 ( R N ) ) N + ( L q q 1 ( R N ) ) N = ( ( L p p 1 ( R N ) ) N ( L q q 1 ( R N ) ) N ) .

Since u L p ( R N ) L q ( R N ) , we have

(3.23) R N a ( x , u n , u n ) u d x R N a ( x , u , u ) u d x .

In a similar way, we obtain

(3.24) R N a ( x , u n , u ) u d x R N a ( x , u , u ) u d x .

Now, we prove that

(3.25) R N a ( x , u n , u ) u n d x R N a ( x , u , u ) u d x .

Clearly, from ( h 0 ) , (3.13), and (3.19), it is

(3.26) a ( x , u n , u ) u n a ( x , u , u ) u a.e. in  R N .

Moreover,

(3.27) R N [ a ( x , u n , u ) u n a ( x , u , u ) u ] d x R N a ( x , u n , u ) u n d x + R N a ( x , u , u ) u d x ,

where a ( x , u , u ) u L 1 ( R N ) , while from ( h 1 ) , Hölder inequality, (3.12), and (3.14)

(3.28) R N a ( x , u n , u ) u n d x c ( u p p 1 + u q q 1 + u n p p 1 ) + ( ψ 2 ( u n ) ) 1 q 1 u n q q 1 .

From Corollary 3.8, it results u n u in L p ( R N ) ; thus, given ε > 0 , there exists n ε N such that

(3.29) u n p p 1 < u p p 1 + ε for all n n ε .

We notice that from ( h 8 ) , we have

lim t 0 ψ 2 ( t ) t η 2 = l 2 0 .

Hence, there exists δ ¯ > 0 such that

ψ 2 ( t ) < ( l 2 + 1 ) t η 2 for any  t R , t < δ ¯ .

Therefore, taking R ¯ such that C M R ¯ N 1 q < δ ¯ , using (3.9) in Radial lemma, it is

u n ( x ) C M x N 1 q C M R ¯ N 1 q < δ ¯ a.e.  x R N , x > R ¯

and therefore, using again Radial lemma for x > R ¯

(3.30) ( ψ 2 ( u n ) ) q q 1 u n q ( l 2 + 1 ) q q 1 u n η 2 q q 1 u n q C x ( N 1 ) η 2 q 1 + 1 L 1 ( B R ¯ C )

since from (2.1) and simple calculations it is ( N 1 ) η 2 q 1 + 1 > N . Thus, from (3.27)–(3.30), for any ε > 0 , there exists R > R ¯ such that

(3.31) B R C [ a ( x , u n , u ) u n a ( x , u , u ) u ] d x ε for  n  large enough.

On the other hand, since u n u in L p ( B R ( 0 ) ) and in L q ( B R ( 0 ) ) , arguing as mentioned earlier, for any ε > 0 ,

(3.32) B R ( 0 ) [ a ( x , u n , u ) u n a ( x , u , u ) u ] d x c ( u p , B R ( 0 ) p 1 + u q , B R ( 0 ) q 1 + u p , B R ( 0 ) p 1 + u q , B R ( 0 ) q 1 ) + ε

for n large enough. From the absolute continuity of the Lebesgue integral, there exists δ ε > 0 such that

(3.33) A [ a ( x , u n , u ) u n a ( x , u , u ) u ] d x < ε

for all measurable set A B R ( 0 ) with meas ( A ) < δ ε . Hence, from (3.26), Vitali’s theorem applies and

(3.34) B R ( 0 ) a ( x , u n , u ) u n d x B R ( 0 ) a ( x , u , u ) u d x .

Finally, (3.25) follows from (3.31) and (3.34).

Hence, by (3.15) and (3.23)–(3.25), we find that

(3.35) R N a ( x , u n , u n ) u n d x R N a ( x , u , u ) u d x .

Now, we set

y n = a ( x , u n , u n ) u n and y = a ( x , u , u ) u .

So, from (3.21), (3.20), ( h 1 ) , and (3.35), we obtain that

y n 0 , y n y a.e. in  R N , y L 1 ( R N ) , R N y n d x R N y d x .

From Brézis-Lieb’s lemma,

a ( x , u n , u n ) u n a ( x , u , u ) u in L 1 ( R N ) ;

hence, using again [5, Theorem 4.9], a function H L 1 ( R N ) exists such that

(3.36) a ( x , u n , u n ) u n H ( x ) a.e. in  R N .

Moreover, from ( h 2 ) , ( h 3 ) , and (3.36), we have that

α 1 ( u n p + u n q ) a ( x , u n , u n ) u n H ( x ) .

Thus, (3.16) follows from (3.19) and the Lebesgue dominated convergence theorem.□

4 Proof of the main result

The aim of this section is to prove that J satisfies the weak Cerami-Palais-Smale condition in X r and then to apply Proposition 2.2 to the functional J on X r . To do this, we need some preliminary lemmas.

Lemma 4.1

[15, Lemma 5.6] Let Ω be an open bounded domain in R N with boundary Ω , consider p, such that 1 < p < p * , p N , and take v W 1 , p ( Ω ) . If γ > 0 and k 0 N exist such that

k 0 ess sup Ω v ( x )

and

Ω k + v p d x γ k meas ( Ω k + ) + Ω k + v d x f o r a l l k k 0 ,

with Ω k + = { x Ω : v ( x ) > k } , then ess sup Ω v is bounded from above by a positive constant, which can be chosen so that it depends only on meas ( Ω ) , N , p , , γ , k 0 , v p * ( v l for some l > if p * = + ). Vice versa, if

k 0 ess inf Ω v ( x )

and inequality

Ω k v p d x γ k meas ( Ω k ) + Ω k v d x f o r a l l k k 0 ,

holds with Ω k = { x Ω : v ( x ) < k } , then ess sup Ω ( v ) is bounded from above by a positive constant, which can be chosen so that it depends only on meas ( Ω ) , N , p , , γ , k 0 , v p * ( v l for some l > if p * = + ).

By applying Lemma 4.1, we will prove that the weak limit in W r 1 , p ( R N ) W r 1 , q ( R N ) of a ( CPS ) β -sequence is bounded in R N .

For simplicity, in the following proofs, when a sequence ( u n ) n is involved, we use the notation ( ε n ) n for any infinitesimal sequence depending only on ( u n ) n while ( ε k , n ) n for any infinitesimal sequence depending not only on ( u n ) n but also on some fixed integer k . Moreover, c denotes any strictly positive constant independent of n and k , which is allowed to change from line to line.

Proposition 4.2

Assume that ( h 0 ) ( h 4 ) , ( h 7 ) , ( g 0 ) ( g 2 ) hold. Then, taking any β R and a ( CPS ) β -sequence ( u n ) n X r , we have that ( u n ) n is bounded in W r 1 , p ( R N ) W r 1 , q ( R N ) and a constant M > 0 exists such that

(4.1) u n ( x ) M f o r a l l x 1 a n d f o r a l l n N .

Moreover, there exists u X r such that, up to subsequences,

(4.2) u n u w e a k l y i n W r 1 , p ( R N ) W r 1 , q ( R N ) ,

(4.3) u n u s t r o n g l y i n L ( R N ) f o r e a c h ] q , p * [ ,

(4.4) u n u a . e . i n R N ,

as n + .

Proof

Let β R be fixed and consider a sequence ( u n ) n X r such that

(4.5) J ( u n ) β and d J ( u n ) X r ( 1 + u n X r ) 0 if  n + .

From Proposition 3.3, as r < p and s < q , we immediately obtain that ( u n ) n is bounded in W r 1 , p ( R N ) W r 1 , q ( R N ) , and therefore, Lemma 3.6 implies the uniform estimate (4.1) for some M > 0 . Furthermore, u W r 1 , p ( R N ) W r 1 , q ( R N ) exists such that, up to subsequences, (4.2)–(4.4) hold (Corollary 3.8).

Now, we have just to prove that u L ( R N ) . Clearly, (4.1) and (4.4) imply that

(4.6) ess sup x 1 u ( x ) M .

Then, it is enough to prove that

(4.7) ess sup x 1 u ( x ) < + .

Arguing by contradiction, let us assume that either

(4.8) ess sup x 1 u ( x ) = +

or

(4.9) ess sup x 1 ( u ( x ) ) = + .

If, for example, (4.8) holds, then, for any fixed k N with k > M , we would have

(4.10) meas ( B k + ) > 0 , where B k + = { x B 1 ( 0 ) : u ( x ) > k } .

We note that the choice of k and (4.6) imply that

(4.11) B k + = { x R N : u ( x ) > k } .

Furthermore, if we set

B k , n + = { x B 1 ( 0 ) : u n ( x ) > k } , n N ,

the choice of k and (4.1) imply that

(4.12) B k , n + = { x R N : u n ( x ) > k } for all  n N .

Now, we define R k + : R R as follows:

R k + t = 0 if  t k t k if  t > k .

Hence, definition of R k + and (4.11), respectively (4.12), imply that

(4.13) R k + u ( x ) = 0 if  x B k + u ( x ) k if  x B k + , R k + u n ( x ) = 0 if  x B k , n + u n ( x ) k if  x B k , n + .

Clearly, (4.1), (4.6), and k > M give that for all n N ,

(4.14) R k + u , R k + u n W r 1 , p ( R N ) W r 1 , q ( R N ) with  R k + u , R k + u n 0  in  R N \ B 1 ( 0 ) .

Moreover, (4.2) imply that R k + u n R k + u weakly in W r 1 , p ( R N ) W r 1 , q ( R N ) ; then, from (4.14), the same weak convergence holds in W 0 1 , p ( B 1 ( 0 ) ) W 0 1 , q ( B 1 ( 0 ) ) = W 0 1 , p ( B 1 ( 0 ) ) .

As W 0 1 , p ( B 1 ( 0 ) ) L ( B 1 ( 0 ) ) for any 1 < p * , then

(4.15) lim n + B 1 ( 0 ) R k + u n d x = B 1 ( 0 ) R k + u d x for any  1 < p * .

In particular, by the weak lower semi-continuity of the norm, we find that

(4.16) B k + u p d x + B k + u q d x liminf n + B k , n + u n p d x + liminf n + B k , n + u n q d x .

On the other hand, since R k + u n X r u n X r , we obtain that

d J ( u n ) , R k + u n d J ( u n ) X r u n X r .

Then (4.5) and (4.10) imply that n k N exists such that

(4.17) d J ( u n ) , R k + u n < meas ( B k + ) for all  n n k .

Let us point out that from ( h 2 ) ( h 4 ) , it is

d J ( u n ) , R k + u n = B k , n + a ( x , u n , u n ) u n d x + B k , n + A t ( x , u n , u n ) ( u n k ) d x + B k , n + u n p 2 u n ( u n k ) d x + B k , n + u n q 2 u n ( u n k ) d x B k , n + g ( x , u n ) R k + u n d x = B k , n + 1 k u n [ a ( x , u n , u n ) u n + A t ( x , u n , u n ) u n ] d x + B k , n + k u n a ( x , u n , u n ) u n d x + B k , n + 1 k u n u n p d x + B k , n + 1 k u n u n q d x B k , n + g ( x , u n ) R k + u n d x α 1 B k , n + a ( x , u n , u n ) u n d x B k , n + g ( x , u n ) R k + u n d x .

Hence, from the previous inequalities, ( h 2 ) and ( h 3 ) , we obtain that

(4.18) α 0 α 1 η 0 B k , n + u n p d x + B k , n + u n q d x d J ( u n ) , R k + u n + B k , n + g ( x , u n ) R k + u n d x .

From (4.14), (4.15), ( g 1 ) , and the Lebesgue dominated convergence theorem, we obtain

(4.19) lim n + R N g ( x , u n ) R k + u n d x = R N g ( x , u ) R k + u d x .

Therefore, (4.16)–(4.19) and ( g 1 ) ( g 2 ) imply that

B k + u p d x B k + u p d x + B k + u q d x c meas ( B k + ) + B k + g ( x , u ) R k + u d x c meas ( B k + ) + B k + η ( x ) u r d x + B k + ζ ( x ) u s d x c meas ( B k + ) + B k + u p ,

since

B k + η ( x ) u r d x B k + η ( x ) u p d x ess sup x 1 η ( x ) B k + u p d x

and

B k + ζ ( x ) u s d x B k + ζ ( x ) u p d x ess sup x 1 ζ ( x ) B k + u p d x ,

as r < p and s < q < p , and u ( x ) > 1 for all x B k + . In conclusion, we have found

B k + u p d x c meas ( B k + ) + B k + u p .

As this inequality holds for all k > M , Lemma 4.1 implies that (4.8) is not true. Similarly it can be proved that (4.9) is not true. More precisely, in this case, fixing any k N , k > M , we would have

meas ( B k ) > 0 , where  B k = { x B 1 ( 0 ) : u ( x ) < k } ,

and we would consider

R k t = 0 if  t k t + k if  t < k .

Reasoning as mentioned earlier, but replacing R k + with R k , and again by means of Lemma 4.1, we prove that (4.9) cannot hold. Hence, (4.7) has to be true.□

Proposition 4.3

If ( h 0 ) ( h 8 ) and ( g 0 ) ( g 2 ) hold, then functional J satisfies the weak Cerami-Palais-Smale condition in X r at each level β R .

Proof

Let β R be fixed and consider a sequence ( u n ) n X r verifying (4.5). By applying Proposition 4.2, the uniform estimate (4.1) holds, and there exists u X r such that, up to subsequences, (4.2)–(4.4) are satisfied. In order to conclude, we need to prove that u n u W 0 as n + with J ( u ) = β and d J ( u ) = 0 .

Instead of proving directly these facts, we introduce T k : R R defined as follows:

(4.20) T k t = t if  t k k t t if  t > k ,

with k > max { u , M } , where M is as in (4.1), and we will prove the following three steps:

  1. (4.21) J ( T k u n ) β as  n +

    and

    (4.22) d J ( T k u n ) X r 0 as  n + ;

  2. (4.23) T k u n u W 0 as  n + ,

    namely, R k u n 0 in W as n + ;

  3. J ( u ) = β and d J ( u ) = 0 .

Step 1 Claim 1: (4.21) holds. ̲

Taking any k > max { u , M } , if we set

(4.24) B k , n = { x B 1 ( 0 ) : u n ( x ) > k } , n N ,

the choice of k and (4.1) imply that

B k , n = { x R N : u n ( x ) > k } for all  n N .

From (4.20), we have that

T k u n k , T k u n W u n W for each  n N .

Defining R k : R R as follows:

R k t = t T k t = 0 if  t k t k t t if  t > k ,

Definition (4.24) imply that

(4.25) R k u n W 0 1 , p ( B 1 ( 0 ) ) for  n N .

Since k > u , we deduce that

T k u ( x ) = u ( x ) and R k u ( x ) = 0 for a.e.  x R N ;

thus, from (4.2), we obtain that R k u n 0 weakly in W r 1 , p ( R N ) W r 1 , q ( R N ) , and, from (4.25), in W 0 1 , p ( B 1 ( 0 ) ) . From the compact embedding of W 0 1 , p ( B 1 ( 0 ) ) in L ( B 1 ( 0 ) ) for any 1 < p * , we have that

(4.26) lim n + R N R k u n d x = 0 for any  1 < p * ,

so that, up to a subsequence,

(4.27) R k u n 0 a.e. in  R N  as  n .

Now, arguing as in the proof of (4.18) but replacing R k + u n with R k u n , we obtain

(4.28) α 0 α 1 η 0 B k , n u n p d x + B k , n u n q d x α 1 B k , n a ( x , u n , u n ) u n d x d J ( u n ) , R k u n + B k , n g ( x , u n ) R k u n d x .

We note that (4.5) and R k u n X u n X imply that

(4.29) lim n + d J ( u n ) , R k u n = 0 ;

while the boundedness of the sequences ( u n ) n and ( R k u n ) n in L p ( R N ) L q ( R N ) , (4.4), (4.27), and Lemma 3.4 imply that

(4.30) lim n + B k , n g ( x , u n ) R k u n d x = 0 .

From (4.28)–(4.30), we obtain that

(4.31) lim n + B k , n u n p d x = 0 , lim n + B k , n u n q d x = 0

and

(4.32) lim n + B k , n a ( x , u n , u n ) u n d x = 0 .

Hence, from (4.26) and (4.31), noticing that

B k , n u n p d x = B k , n R k u n p d x ,

since T k u n is constant in B k , n , we obtain that

lim n + R k u n p = 0 , lim n + R k u n q = 0 .

Moreover, from (4.4), (4.24), and k > u , we obtain

(4.33) lim n + meas ( B k , n ) = 0 .

This fact, together with (4.26), implies that

(4.34) lim n + B k , n u n d x = 0 for any  1 < p * .

From (3.3) and (4.20), we have

(4.35) J ( T k u n ) = R N \ B k , n A ( x , u n , u n ) d x + B k , n A x , k u n u n , 0 d x + 1 p R N \ B k , n u n p d x + 1 p B k , n k p d x + 1 q R N \ B k , n u n q d x + 1 q B k , n k q d x R N G ( x , T k u n ) d x = J ( u n ) B k , n A ( x , u n , u n ) d x + B k , n A x , k u n u n , 0 d x 1 p B k , n u n p d x + 1 p B k , n k p d x 1 q B k , n u n q d x + 1 q B k , n k q d x R N ( G ( x , T k u n ) G ( x , u n ) ) d x .

By ( h 2 ) , ( h 3 ) , and (4.32), we infer that

(4.36) 0 B k , n A ( x , u n , u n ) d x η 0 B k , n a ( x , u n , u n ) u n d x 0 ,

while ( h 1 ) and (4.33) imply

(4.37) 0 B k , n A x , k u n u n , 0 d x B k , n φ 0 k u n u n k p d x + B k , n ψ 0 k u n u n k q d x [ ( max t k φ 0 ( t ) ) k p + ( max t k ψ 0 ( t ) ) k q ] meas ( B k , n ) 0

and (4.33) and (4.34) imply

(4.38) 1 p B k , n u n p d x + 1 p B k , n k p d x 0 , 1 q B k , n u n q d x + 1 q B k , n k q d x 0 .

Furthermore, from (4.20), (3.1), (4.33), and (4.34), it is

(4.39) R N ( G ( x , T k u n ) G ( x , u n ) ) d x = B k , n G x , k u n u n G ( x , u n ) d x 1 r η p p r k r ( meas ( B k , n ) ) r p + B k , n u n p d x r p + 1 s ζ q q s k s ( meas ( B k , n ) ) s q + B k , n u n q d x s q 0 .

Then, (4.21) follows from (4.5) and (4.35)–(4.39).

Claim 2: (4.22) holds. ̲

Let v X r such that v X = 1 ; hence, v 1 , v p 1 , v q 1 . From (3.4) and (4.20), we have that

d J ( T k u n ) , v = R N \ B k , n a ( x , u n , u n ) v d x + B k , n a x , k u n u n , 0 v d x + R N \ B k , n A t ( x , u n , u n ) v d x + B k , n A t x , k u n u n , 0 v d x + R N \ B k , n u n p 2 u n v d x + B k , n k p 1 u n u n v d x + R N \ B k , n u n q 2 u n v d x + B k , n k q 1 u n u n v d x R N g ( x , T k u n ) v d x = d J ( u n ) , v B k , n a ( x , u n , u n ) v d x B k , n A t ( x , u n , u n ) v d x B k , n u n p 2 u n v d x B k , n u n q 2 u n v d x + B k , n ( g ( x , u n ) g ( x , T k u n ) ) v d x + ε n ,

for some ε n 0 as n . Indeed, by ( h 1 ) , (4.33), Hölder’s inequality and v p 1 , v q 1 , v 1 , we have the following estimates:

(4.40) B k , n a x , k u n u n , 0 v d x B k , n φ 2 k u n u n k p 1 v d x + B k , n ψ 2 k u n u n k q 1 v d x ( max t k φ 2 ( t ) ) B k , n k p d x p 1 p v p + ( max t k ψ 2 ( t ) ) B k , n k q d x q 1 q v q 0 ,

(4.41) B k , n A t x , k u n u n , 0 v d x B k , n φ 1 k u n u n k p 1 d x + B k , n ψ 1 k u n u n k q 1 d x ( ( max t k φ 1 ( t ) ) k p 1 + ( max t k ψ 1 ( t ) ) k q 1 ) meas ( B k , n ) 0 ,

(4.42) B k , n k p 1 u n u n v d x k p 1 meas ( B k , n ) 0 , B k , n k q 1 u n u n v d x k q 1 meas ( B k , n ) 0 ,

where all the limits hold uniformly with respect to v .

Furthermore, from (2.3) and (4.32), we have that

lim n + B k , n A t ( x , u n , u n ) u n d x = 0 .

Then, since 1 k u n in B k , n and v 1 , we also obtain

(4.43) B k , n A t ( x , u n , u n ) v d x B k , n A t ( x , u n , u n ) d x B k , n A t ( x , u n , u n ) u n d x 0

uniformly with respect to v . Moreover, from Hölder inequality, (4.34) and v p 1 , v q 1 , we have

B k , n u n p 2 u n v d x B k , n u n p d x p 1 p 0 , B k , n u n q 2 u n v d x B k , n u n q d x q 1 q 0 .

Now, from (3.2), (4.33), (4.34), v p 1 , and v q 1 , we have

B k , n g ( x , u n ) v d x η p p r B k , n u n p d x r 1 p + ζ q q s B k , n u n q d x s 1 q 0

and

B k , n g ( x , T k u n ) v d x η p p r B k , n k p d x r 1 p + ζ q q s B k , n k q d x s 1 q 0 .

Since all the previous limits hold uniformly with respect to v , summing up, from (4.5), we obtain

(4.44) d J ( T k u n ) , v ε k , n + B k , n a ( x , u n , u n ) v d x .

Now, to estimate the last integral in (4.44), following the notations introduced in the proof of Proposition 4.2, let us consider the set B k , n + and the test function defined as follows:

φ k , n + = v R k + u n .

By definition, we have

φ k , n + X 2 u n X ,

thus, (4.5) implies that

d J ( u n ) X r φ k , n + X r ε n 0 as n .

Therefore, from (4.13) and direct computations, we note that

(4.45) d J ( u n ) , φ k , n + = B k , n + a ( x , u n , u n ) R k + u n v d x + B k , n + a ( x , u n , u n ) v u n d x + B k , n + A t ( x , u n , u n ) v R k + u n d x + B k , n + u n p 2 u n v R k + u n d x + B k , n + u n q 2 u n v R k + u n d x B k , n + g ( x , u n ) v R k + u n d x 0 ,

where, since B k , n + B k , n , from (4.33), we have

lim n + meas ( B k , n + ) = 0 .

Moreover, v 1 , ( h 2 ) , ( h 3 ) , (4.32), (4.43), (4.34), and (3.2) imply that

B k , n + a ( x , u n , u n ) v u n d x B k , n + a ( x , u n , u n ) u n d x 0 , B k , n + A t ( x , u n , u n ) v R k + u n d x B k , n + A t ( x , u n , u n ) u n k d x B k , n + A t ( x , u n , u n ) u n d x 0 , B k , n + u n p 2 u n v R k + u n d x B k , n + u n p d x 0 , B k , n + u n q 2 u n v R k + u n d x B k , n + u n q d x 0 , B k , n + g ( x , u n ) v R k + u n d x η p p r B k , n + u n p d x r 1 p + ζ q q s B k , n + u n q d x s 1 q 0

uniformly with respect to v . From (4.45) and the previous estimates, we find that

(4.46) lim n + B k , n + a ( x , u n , u n ) R k + u n v d x = 0 .

Now, if we fix k > max { u , M } + 1 , all the previous computations hold also for k 1 and then in particular, from (4.31), (4.34), and (4.46), we obtain that

(4.47) lim n + B k 1 , n u n p d x = 0 , lim n + B k 1 , n u n p d x = 0 lim n + B k 1 , n u n q d x = 0 , lim n + B k 1 , n u n q d x = 0

and

(4.48) lim n + B k 1 , n + a ( x , u n , u n ) R k 1 + u n v d x = 0 .

From (4.48), since B k , n + B k 1 , n + and R k 1 + u n = R k + u n + 1 in B k , n + , it is

ε k , n = B k 1 , n + a ( x , u n , u n ) R k 1 + u n v d x = B k , n + a ( x , u n , u n ) R k 1 + u n v d x + B k 1 , n + \ B k , n + a ( x , u n , u n ) R k 1 + u n v d x = B k , n + a ( x , u n , u n ) R k + u n v d x + B k , n + a ( x , u n , u n ) v d x + B k 1 , n + \ B k , n + a ( x , u n , u n ) R k 1 + u n v d x .

Assumption ( h 1 ) , (4.13), the properties of B k 1 , n + \ B k , n + , Hölder’s inequality, v p 1 , and v q 1 imply that

B k 1 , n + \ B k , n + a ( x , u n , u n ) R k 1 + u n v d x k B k 1 , n + \ B k , n + a ( x , u n , u n ) v d x k p max t k φ 2 ( t ) B k 1 , n + \ B k , n + v d x + k q max t k ψ 2 ( t ) B k 1 , n + \ B k , n + v d x + k max t k Φ 2 ( t ) B k 1 , n + \ B k , n + u n p 1 v d x + k max t k Ψ 2 ( t ) B k 1 , n + \ B k , n + u n q 1 v d x k p max t k φ 2 ( t ) B k 1 , n + \ B k , n + v d x + k q max t k ψ 2 ( t ) B k 1 , n + \ B k , n + v d x + k max t k Φ 2 ( t ) B k 1 , n + \ B k , n + u n p d x p 1 p + k max t k Ψ 2 ( t ) B k 1 , n + \ B k , n + u n q d x q 1 q 0 ,

since meas ( B k 1 , n + \ B k , n + ) 0 and (4.47) holds. From (4.46) and the previous arguments, we conclude that

(4.49) B k , n + a ( x , u n , u n ) v d x 0 .

Similar arguments apply also if we consider B k , n and the test function

φ k , n = v R k u n ;

hence, we have

(4.50) B k , n a ( x , u n , u n ) v d x 0 .

Thus, (4.22) follows from (4.44), (4.49), and (4.50), as all ε k , n and all limits are independent of v .

Step 2: We shall prove (4.23), and for this, some intermediate points are needed.

First, we note that (4.2)–(4.4) and Step 1 imply that, if n + ,

T k u n u weakly in  W r 1 , p ( R N ) W r 1 , q ( R N ) , T k u n u strongly in  L ( R N ) for each ] q , p * [ , T k u n u a.e. in  R N .

Now, arguing as in [1], let us consider the odd map ψ : R R defined as follows:

ψ ( t ) = t e η ¯ t 2 ,

where η ¯ > β 2 α 2 will be fixed once α , β > 0 are chosen properly later on. By definition,

(4.51) α ψ ( t ) β ψ ( t ) > α 2 for all  t R .

If we define v k , n = T k u n u , since k > u , we have that v k , n 2 k for all n N . Therefore,

(4.52) ψ ( v k , n ) ψ ( 2 k ) , 0 < ψ ( v k , n ) ψ ( 2 k ) a.e. in  R N  for all  n N ,

and

(4.53) ψ ( v k , n ) 0 , ψ ( v k , n ) 1 a.e. in  R N   if  n + .

Furthermore, since

(4.54) ψ ( v k , n ) v k , n e 4 k 2 η ¯ 2 k e 4 k 2 η ¯ a.e. in  R N  for all  n N ,

direct computations and (4.52) imply that ( ψ ( v k , n ) X ) n is bounded, and so from (4.53), (4.54), and Corollary 3.8, up to subsequences, it is

(4.55) ψ ( v k , n ) 0 weakly in  W r 1 , p ( R N ) W r 1 , q ( R N ) , ψ ( v k , n ) 0 in  L ( R N ) for all  > q .

Moreover, from (4.22), we know that

d J ( T k u n ) , ψ ( v k , n ) 0 as  n + ,

where

d J ( T k u n ) , ψ ( v k , n ) = R N \ B k , n a ( x , u n , u n ) ψ ( v k , n ) d x + B k , n a x , k u n u n , 0 ψ ( v k , n ) d x + R N \ B k , n A t ( x , u n , u n ) ψ ( v k , n ) d x + B k , n A t x , k u n u n , 0 ψ ( v k , n ) d x + R N \ B k , n u n p 2 u n ψ ( v k , n ) d x + B k , n k p 1 u n u n ψ ( v k , n ) d x + R N \ B k , n u n q 2 u n ψ ( v k , n ) d x + B k , n k q 1 u n u n ψ ( v k , n ) d x R N g ( x , T k u n ) ψ ( v k , n ) d x .

Since ( ψ ( v k , n ) X ) n is bounded, arguing as in (4.40)–(4.42), we find that

lim n + B k , n a x , k u n u n , 0 ψ ( v k , n ) d x = 0 , lim n + B k , n A t x , k u n u n , 0 ψ ( v k , n ) d x = 0 , lim n + B k , n k p 1 u n u n ψ ( v k , n ) d x = 0 , lim n + B k , n k q 1 u n u n ψ ( v k , n ) d x = 0 .

Furthermore, from Lemma 3.4, with w n = T k u n and v n = ψ ( v k , n ) , we have

lim n + R N g ( x , T k u n ) ψ ( v k , n ) d x = 0 .

Moreover, since from (4.3) and (4.55) u n u and ψ ( v k , n ) 0 in  L p ( R N ) , we obtain that

(4.56) R N \ B k , n u n p 1 ψ ( v k , n ) d x 0 .

Hence, summing up, the previous relations imply that

(4.57) ε k , n = R N \ B k , n a ( x , u n , u n ) ψ ( v k , n ) v k , n d x + R N \ B k , n A t ( x , u n , u n ) ψ ( v k , n ) d x + R N \ B k , n u n q 2 u n ψ ( v k , n ) d x

for some ε k , n 0 as n .

We note that from ( h 1 ) , it is

(4.58) R N \ B k , n A t ( x , u n , u n ) ψ ( v k , n ) d x max t k φ 1 ( t ) R N \ B k , n u n p 1 ψ ( v k , n ) d x + max t k Φ 1 ( t ) R N \ B k , n u n p ψ ( v k , n ) d x + R N \ B k , n ψ 1 ( u n ) u n q 1 ψ ( v k , n ) d x + max t k Ψ 1 ( t ) R N \ B k , n u n q ψ ( v k , n ) d x .

Now, we prove that

(4.59) lim n + R N \ B k , n ψ 1 ( u n ) u n q 1 ψ ( v k , n ) d x = 0 .

In fact, since the sequence ( u n ) n is bounded in W r 1 , q ( R N ) , there exists a constant M > 0 such that

u n q M , u n u q M for any  n N .

Moreover, from assumption ( h 8 ) , it is

lim t 0 ψ 1 ( t ) t η 1 = l 1 with l 1 0 ,

hence, there exists δ 1 > 0 such that

(4.60) ψ 1 ( t ) < ( l 1 + 1 ) t η 1 for any  t R , t < δ 1 .

Now, taking R 1 large enough such that

(4.61) C M R 1 N 1 q < δ 1 ,

from (3.9) and (4.61), we obtain that

u n ( x ) C M x N 1 q C M R 1 N 1 q < δ 1 a.e.  x R N  with  x > R 1 .

Hence, (4.60) and (3.9) imply that for a.e. x R N \ B k , n , it is

ψ 1 ( u n ) u n q 1 ψ ( v k , n ) ( l 1 + 1 ) u n η 1 + q 1 u n u exp ( η ¯ u n u 2 ) ( l 1 + 1 ) ( C M ) η 1 + q exp η ¯ C 2 M 2 R 1 2 N 1 q 1 x ( η 1 + q ) N 1 q ,

where 1 x ( η 1 + q ) N 1 q L 1 ( ( R N \ B k , n ) B R 1 C ) , since ( η 1 + q ) N 1 q > N from (2.1). We note that ( R N \ B k , n ) B R 1 C = B R 1 C . As ψ 1 ( u n ) u n q 1 ψ ( v k , n ) 0 a.e. in  R N , the Lebesgue dominated convergence theorem implies that

(4.62) lim n + B R 1 C ψ 1 ( u n ) u n q 1 ψ ( v k , n ) d x = 0 .

On the other hand, from Hölder’s inequality

(4.63) ( R N \ B k , n ) B R 1 ψ 1 ( u n ) u n q 1 ψ ( v k , n ) d x max t k ψ 1 ( t ) ( R N \ B k , n ) B R ε u n q d x q 1 q ( R N \ B k , n ) B R 1 ψ ( v k , n ) q d x 1 q 0 ,

since (4.55) implies that ψ ( v k , n ) 0 in L loc q ( R N ) . Then, (4.59) follows from (4.62) and (4.63).

Moreover, using again the Lebesgue dominated convergence theorem, it is

(4.64) lim n R N \ B k , n a ( x , u , u ) u ψ ( v k , n ) d x = 0 ,

while from ( h 2 ) , ( h 3 ) , we know that

(4.65) ( u n p + u n q ) ψ ( v k , n ) η 0 α 0 a ( x , u n , u n ) u n ψ ( v k , n ) .

Hence, from (4.56)–(4.59), (4.64), and (4.65), we find that

ε k , n R N \ B k , n a ( x , u n , u n ) ψ ( v k , n ) v k , n d x η 0 α 0 max t k ( Φ 1 ( t ) + Ψ 1 ( t ) ) × R N \ B k , n a ( x , u n , u n ) v k , n ψ ( v k , n ) d x + R N \ B k , n u n q 2 u n ψ ( v k , n ) d x .

Thus, setting

h k , n ( x ) = ψ ( v k , n ) η 0 α 0 max t k ( Φ 1 ( t ) + Ψ 1 ( t ) ) ψ ( v k , n ) ,

and choosing in the definition of ψ , α = 1 and β = η 0 α 0 max t k ( Φ 1 ( t ) + Ψ 1 ( t ) ) , from (4.51), we obtain

(4.66) h k , n ( x ) > 1 2 a.e. in  R N .

Moreover,

(4.67) ε k , n R N \ B k , n h k , n a ( x , u n , u n ) v k , n d x + R N \ B k , n u n q 2 u n ψ ( v k , n ) d x = R N \ B k , n a ( x , u , u ) v k , n d x + R N \ B k , n h k , n ( a ( x , u n , u n ) a ( x , u n , u ) ) v k , n d x + R N \ B k , n ( h k , n a ( x , u n , u ) a ( x , u , u ) ) v k , n d x + R N \ B k , n ( u n q 2 u n u q 2 u ) ψ ( v k , n ) d x + R N \ B k , n u q 2 u ψ ( v k , n ) d x ,

where (4.2) and (4.55) imply, respectively, that

(4.68) lim n + R N \ B k , n a ( x , u , u ) v k , n d x = 0 , lim n + R N \ B k , n u q 2 u ψ ( v k , n ) d x = 0 .

Claim ̲ :

(4.69) lim n + R N \ B k , n ( h k , n a ( x , u n , u ) a ( x , u , u ) ) v k , n d x = 0 .

Indeed, we know that ( v k , n ) n is bounded in L p ( R N ) and in L q ( R N ) , hence, arguing as in the proof of (3.31), from ( h 8 ) for all ε > 0 , there exists R > 0 such that

(4.70) B R C ( 0 ) ( h k , n a ( x , u n , u ) a ( x , u , u ) ) v k , n d x < ε

for n large enough and where ( R N \ B k , n ) B R C ( 0 ) = B R C ( 0 ) .

From Hölder’s inequality, we have that

(4.71) R N \ B k , n ( h k , n a ( x , u n , u ) a ( x , u , u ) ) v k , n d x c R N \ B k , n h k , n a ( x , u n , u ) a ( x , u , u ) p p 1 d x p 1 p .

As h k , n ( x ) 1 a.e. in R N , from ( h 0 ) and (4.4), we obtain that

h k , n a ( x , u n , u ) a ( x , u , u ) 0 a.e. in  R N .

Moreover,

h k , n a ( x , u n , u ) a ( x , u , u ) p p 1 c a ( x , u n , u ) p p 1 + a ( x , u , u ) p p 1 ,

where, by ( h 1 ) ,

a ( x , u , u ) p p 1 L 1 ( B R ( 0 ) ) for all  u X ,

and for all x ( R N \ B k , n ) B R ( 0 ) , it is

a ( x , u n , u ) p p 1 c u n p + u p + u n p q 1 p 1 + u p q 1 p 1 c ( u n p + u p ) c ( 1 + u p ) ,

since 0 < p q 1 p 1 p .

So, from all the previous estimates, by applying the Lebesgue dominated convergence theorem on B R ( 0 ) , we find that

B R ( 0 ) h k , n a ( x , u n , u ) a ( x , u , u ) p p 1 d x 0 ,

which, together with (4.70), implies (4.69), as claimed.

Conclusion: (4.23) holds ̲ .

Indeed, from (4.66)–(4.69), ( h 6 ) and e η ¯ v k , n 2 1 , we obtain

ε k , n 1 2 R N \ B k , n ( a ( x , u n , u n ) a ( x , u n , u ) ) ( u n u ) d x + R N \ B k , n ( u n q 2 u n u q 2 u ) ( u n u ) d x .

By using ( h 6 ) and the strong convexity of the power function with exponent q > 1 , we have

(4.72) lim n + R N \ B k , n ( a ( x , u n , u n ) a ( x , u n , u ) ) ( u n u ) d x = 0

and

lim n + R N \ B k , n ( u n q 2 u n u q 2 u ) ( u n u ) d x = 0 .

Now, if q 2 ,

R N \ B k , n u n u q d x c q R N \ B k , n ( u n q 2 u n u q 2 u ) ( u n u ) d x 0 ,

while if q ( 1 , 2 ) , since u n ( x ) < k a.e. x R N \ B k , n

R N \ B k , n u n u q d x c R N \ B k , n ( u n q 2 u n u q 2 u ) ( u n u ) ( u n + u ) 2 q d x c R N \ B k , n ( u n q 2 u n u q 2 u ) ( u n u ) d x 0 .

Arguing as in the proof of Proposition 4.3, T k u n u in L q ( R N ) . Finally, as T k u n u a.e. in R N and T k u n k for all n N , from (4.72) we can apply Lemma 3.9 to the sequence ( T k u n ) n , obtaining that T k u n u in L p ( R N ) and in L q ( R N ) . Thus, (4.23) follows.

Step 3: Claim 3 of Proposition 4.3 holds true.

The proof follows immediately from (4.23), Proposition 3.2, (4.21), and (4.22).□

Proof of the Theorem 2.14

The functional J is bounded from below (Proposition 3.3) and satisfies condition (wCPS) in R (Proposition 4.3); thus, from Proposition 2.2, J admits a minimum point u * in X r . Clearly, it is

J ( u * ) = min u X J ( u ) J ( 0 ) = 0 .

Now, our aim is to prove that u * is not trivial, proving that J ( u * ) < 0 . Thus, we consider φ 1 W 0 1 , p ( B 1 ( 0 ) ) such that

φ 1 p p = 1 , φ 1 p p + φ 1 q q = λ 1 ,

with

λ 1 = inf u W 0 1 , p ( B 1 ( 0 ) ) , u p = 1 ( u p p + u q q ) ,

i.e., φ 1 is the first eigenfunction associated with the first eigenvalue λ 1 of Δ p Δ q in W 0 1 , p ( B 1 ( 0 ) ) [17]. Let us remark that φ 1 is radial, since, by the Pólya-Szegö inequality, we have

λ 1 = φ 1 p p + φ 1 q q φ 1 p p + φ 1 q q ,

φ 1 being the Schwartz rearrangement of φ 1 . Denote still by φ 1 its null extension in R N \ B 1 ( 0 ) , so that φ 1 L ( R N ) , and thus, φ 1 X r . Taking τ ( 0 , 1 ) , from ( h 1 ) , we have

J ( τ φ 1 ) = R N A ( x , τ φ 1 , ( τ φ 1 ) ) d x + 1 p R N τ φ 1 p d x + 1 q R N τ φ 1 q d x R N G ( x , τ φ 1 ) d x B 1 ( 0 ) ( φ 0 ( τ φ 1 ( x ) ) τ φ 1 ( x ) p + Φ 0 ( τ φ 1 ( x ) ) ( τ φ 1 ( x ) ) p ) d x + B 1 ( 0 ) ( ψ 0 ( τ φ 1 ( x ) ) τ φ 1 ( x ) q + Ψ 0 ( τ φ 1 ( x ) ) τ φ 1 ( x ) q ) d x + τ p p B 1 ( 0 ) φ 1 p d x + τ q q B 1 ( 0 ) φ 1 q d x B 1 ( 0 ) G ( x , τ φ 1 ) d x τ p ( max 0 t φ 1 φ 0 ( t ) ) φ 1 p p + τ p ( max 0 t φ 1 Φ 0 ( t ) ) φ 1 p p + τ q ( max 0 t φ 1 ψ 0 ( t ) ) φ 1 q q + τ q ( max 0 t φ 1 Ψ 0 ( t ) ) φ 1 q q + τ p p φ 1 p p + τ q q φ 1 q q B 1 ( 0 ) G ( x , τ φ 1 ) d x c τ q B 1 ( 0 ) G ( x , τ φ 1 ) d x .

Now, from assumption ( g 3 ) , there exists a constant δ > 0 such that for any s [ 0 , δ ] and for a.e. x B 1 ( 0 ) , it is G ( x , s ) > 2 c s q φ 1 q q . Then, for any, τ 0 , δ φ 1 , we have that

B 1 ( 0 ) G ( x , τ φ 1 ) d x > 2 c τ q φ 1 q q B 1 ( 0 ) φ 1 q q d x = 2 c τ q .

Therefore, we conclude that

J ( τ φ 1 ) c τ q 2 c τ q < 0 .

Finally, by replacing g ( x , t ) with g ± ( x , t ) g ( x , t ± ) , one can find that (1.1) has one negative and one positive solution (for instance, see the last part of the proof of [20, Theorem 2.12]).□

Acknowledgements

The authors are grateful to the anonymous referees for their careful reading of the manuscript and their valuable comments.

  1. Funding information: The authors are members of the Research Group INdAM-GNAMPA. The second author is supported by the GNAMPA Project 2023 Variational and non-variational problems with lack of compactness and by the Fondo di finanziamento per le attività base di ricerca (FFABR) 2017. The third author is supported by the project PRIN PNRR MUR P2022YFAJH “Linear and nonlinear PDE’s: New directions and applications,” CUP: H53D23008950001. The second and third authors are also supported by the GNAMPA Project 2024 Nonlinear problems in local and nonlocal settings with applications.

  2. Author contributions: The authors contributed equally to the preparation, the revision, and the writing of the manuscript.

  3. Conflict of interest: The authors state no conflict of interest.

  4. Data availability statement: No data were used for the research described in the article.

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Received: 2024-01-19
Revised: 2024-05-31
Accepted: 2024-07-22
Published Online: 2025-02-18

© 2025 the author(s), published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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