Home Mathematics On a blow-up criterion for solution of 3D fractional Navier-Stokes-Coriolis equations in Lei-Lin-Gevrey spaces
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On a blow-up criterion for solution of 3D fractional Navier-Stokes-Coriolis equations in Lei-Lin-Gevrey spaces

  • Xiaochun Sun , Gaoting Xu EMAIL logo and Yulian Wu
Published/Copyright: December 31, 2023

Abstract

In this article, we researched the existence of the solution to the fractional Navier-Stokes equations with the Coriolis force under initial data, which belong to the Lei-Lin-Gevrey spaces. Moreover, we showed a blow-up criterion, i.e., when the maximal time of existence T * is finite, we proved that the norm of this same solution, in a specific Lei-Lin-Gevrey space, goes to infinity, as time tends to the maximal time of its existence.

MSC 2010: 35A01; 35Q35; 76D06

1 Introduction

In this article, we consider the 3D Navier-Stokes-Coriolis equations:

(1.1) t u + ν ( Δ ) α u + Ω e 3 × u + ( u ) u = p , in R 3 × ( 0 , ) , div u = 0 , in R 3 × ( 0 , ) , u t = 0 = u 0 , in R 3 ,

where u = ( u 1 , u 2 , u 3 ) denotes the velocity field of the fluid and p is the pressure. The positive constant ν is the viscosity coefficient; the Coriolis parameter Ω R , which denotes twice the speed of rotation around the vertical unit vector e 3 = ( 0 , 0 , 1 ) ; α is a positive parameter; and ( Δ ) α ( α > 0 ) denotes the fractional Laplacian, which is defined as:

( ( Δ ) α u ) ( t , ξ ) = ξ 2 α ( u ) ( t , ξ ) ,

where ( u ) is the Fourier transform of u with respect to spatial variable x .

When α = 1 and Ω 0 , equation (1.1) reduces to the classical Navier-Stokes equations with Coriolis force. Babin et al. [1,2] proved the global existence and regularity of the solution to the 3D rotating Navier-Stokes equations in the case Ω is large enough. Wang and Wu [3] proved the global well-posedness of the mild solution to the Navier-Stokes equations with the Coriolis force if the initial data are in χ 1 2 α spaces. Iwabuchi and Takada [4] proved the existence of global unique solutions to the Navier-Stokes equations with the Coriolis force in Sobolev spaces H ˙ s with 1 2 < s < 3 4 if the speed of rotation Ω is sufficiently large. Iwabuchi and Takada [5] also obtained the global in time existence and the uniqueness of the mild solution for small initial data in Fourier-Besov spaces ℱℬ 1 , 2 1 ( R 3 ) . Hieber and Shibata [6] proved that the Navier-Stokes equations with the Coriolis force possess a unique global mild solution for arbitrary speed of rotation provided the initial data u 0 is small enough in H 1 2 ( R 3 ) .

When α 1 and Ω = 0 , equation (1.1) reduces to the fractional Navier-Stokes equations. Ding and Sun [7] studied the uniqueness of the weak solution to the fractional Navier-Stokes equations. Sun and Liu [8] obtained the uniqueness of the weak solution to the fractional anisotropic Navier-Stokes system. Sun and Liu [9] studied the long time decay of the fractional Navier-Stokes equations in Sobolev-Gevrey spaces.

When α = 1 and Ω = 0 , equation (1.1) reduces to the classical Navier-Stokes equations. Benameur and Jlali [10] proved a global well-posedness of three-dimensional incompressible Navier-Stokes equations under initial data u 0 in the Lei-Lin-Gevrey space and proved blow-up criterion. Cannone and Wu [11] proved the global well-posedness for the 3D Navier-Stokes equations in critical Fourier-Herz spaces. Jlali [12] studied the long time decay of global solution to the 3D incompressible Navier-Stokes equations in Fourier-Lei-Lin spaces.

Besides, Cannone and Karch [13] proved the existence of singular solutions of the incompressible Navier-Stokes system with singular external forces. Guterres et al. [14] proved the results concerning upper and lower decay estimates for homogeneous Sobolev norms of solutions to a rather general family of parabolic equations. We can refer to [15] for more questions about Navier-Stokes equations.

In this article, we studied the existence and blow-up criterion of the solution to the 3D fractional Navier-Stokes-Coriolis equations in Lei-Lin-Gevrey spaces. Recently, many authors have made considerable progresses regarding the existence, uniqueness, and blow-up of solutions for the generalized magnetohydrodynamics equations in Lei-Lin and Lei-Lin-Gevrey spaces, which can be refer to [1618]. This article is inspired by [18], and on this basis, our main results are as follows.

Theorem 1.1

Assume that a 0 , σ 1 , 1 2 α < s 0 , α ( 1 2 , 1 ] , then there exists a time T > 0 , such that for any u 0 χ a , σ s ( R 3 ) , Navier-Stokes-Coriolis equation (1.1) has a unique solution u C ( [ 0 , T ) , χ a , σ s ( R 3 ) ) L 1 ( [ 0 , T * ) , χ a , σ s + 2 α ( R 3 ) ) . Moreover, u L 2 ( [ 0 , T * ) , χ a , σ s + α ( R 3 ) ) .

Theorem 1.2

Suppose that a 0 , σ 1 , 1 2 α < s 0 , α ( 1 2 , 1 ] , and 0 t < T * . Let u C ( [ 0 , T ) , χ a , σ s ( R 3 ) ) L 1 ( [ 0 , T * ) , χ a , σ s + 2 α ( R 3 ) ) be a maximal solution of the Navier-Stokes-Coriolis system. If T * is finite, then

limsup t T * u ( t ) χ a , σ s ( R 3 ) = .

2 Preliminaries

In this section, we recall some notations, definitions, and lemmas that will be used later.

  1. The Fourier transform of f is defined by:

    ( f ) ( ξ ) = f ^ ( ξ ) = R 3 e i x ξ f ( x ) d x , ξ R 3 , f L 1 ( R 3 ) ,

    and the Fourier inverse transform of f is defined by:

    1 ( f ) ( x ) = ( 2 π ) 3 R 3 e i x ξ f ( ξ ) d ξ , x R 3 , f L 1 ( R 3 ) .

  2. Lei-Lin-Gevrey space is defined by:

    χ a , σ s ( R 3 ) = f S : f ^ L loc 1 , u ( t ) χ a , σ s ( R 3 ) = R 3 ξ s e a ξ 1 σ f ^ ( ξ ) d ξ < ,

    where s R , a 0 , and σ 1 .

  3. Assuming that ( X , ) is a normed vector space and T > 0 , the space L T p ( X ) , 1 p , contains all measurable functions f : [ 0 , T ] X for which the following norms are finite:

    f L T ( X ) = esssup t [ 0 , T ] f , L T p ( X ) = 0 T f p d t 1 p ( 1 p < ) .

    C T ( X ) = { f : [ 0 , T ] X continuous } is endowed with the norm L T ( X ) .

  4. The tensor product and the usual convolution, respectively, are given by:

    f g = ( g 1 f , g 2 f , g 3 f ) , u v ( x ) = R 3 u ( x y ) v ( y ) d y ,

    where f , g : R 3 R 3 , and u , v : R 3 R .

Lemma 2.1

[18] Let a 0 , σ 1 , s 0 , then χ a , σ s ( R 3 ) is a Banach space.

Lemma 2.2

[18] Let a 0 , γ 1 2 , and σ 1 . The following inequalities hold

  1. f χ a , σ s + 1 f χ a , σ s 1 1 2 γ f χ a , σ s + 2 γ 1 2 γ , if s R ;

  2. f χ a , σ 0 f χ a , σ s 1 + s 2 γ f χ a , σ s + 2 γ s 2 γ , if 2 γ s 0 .

Lemma 2.3

[18] Assume that f , g χ a , σ s + 1 ( R 3 ) χ a σ , σ 0 ( R 3 ) , with a 0 , σ 1 , and s 1 . Then, f g χ a , σ s + 1 ( R 3 ) . Moreover, the inequality holds

f g χ a , σ s + 1 ( R 3 ) 2 s 2 π 3 ( f χ a σ , σ 0 ( R 3 ) g χ a , σ s + 1 ( R 3 ) + f χ a , σ s + 1 ( R 3 ) g χ a σ , σ 0 ( R 3 ) ) .

Lemma 2.4

[18] Assume that a 0 , σ 1 , T > 0 , and 1 2 α s 0 , where α ( 1 2 , 1 ] . Then,

0 T f g χ a , σ s + 1 ( R 3 ) d τ C s T s 1 2 α + 1 f L T ( χ a σ , σ s ( R 3 ) ) 1 + s 2 α g L T ( χ a , σ s ( R 3 ) ) 1 1 2 α f L T 1 ( χ a σ , σ s + 2 α ( R 3 ) ) s 2 α g L T 1 ( χ a , σ s + 2 α ( R 3 ) ) 1 2 α + f L T ( χ a , σ s ( R 3 ) ) 1 1 2 α g L T ( χ a σ , σ s ( R 3 ) ) 1 + s 2 α f L T 1 ( χ a , σ s + 2 α ( R 3 ) ) 1 2 α g L T 1 ( χ a σ , σ s + 2 α ( R 3 ) ) s 2 α .

Remark 1

Lemma 2.8 in [18] can be taken as α = β .

Lemma 2.5

[18] Let a 0 , σ 1 , γ R , s R , and f S such that f = 0 , then

0 t e ( t τ ) ( ) γ P ( u ) u χ a , σ s ( R 3 ) d τ 0 t u u χ a , σ s + 1 ( R 3 ) d τ .

Proof

Helmholtz’s projector P satisfies

(2.1) [ P ( u ) ] ( ξ ) = u ^ ( ξ ) u ^ ( ξ ) ξ ξ 2 ξ , ξ R 3 .

0 t e ( t τ ) ( ) γ P ( u ) u χ a , σ s d τ = 0 t R 3 e ( t τ ) ξ 2 γ ξ s e a ξ 1 σ P ( u ) u ^ d ξ d τ 0 t R 3 ξ s e a ξ 1 σ ( u ) u ^ d ξ d τ 0 t R 3 ξ s + 1 e a ξ 1 σ u u ^ d ξ d τ = 0 t u u χ a , σ s + 1 d τ .

Lemma 2.6

[19] Let ( X , ) be a Banach space and B : X × X X be a bilinear continuous operator, and there exists a positive constant C such that

B ( x , y ) C x y , x , y X .

Then, for each x 0 X that satisfies 4 C x 0 < 1 , one has that equation

a = x 0 + B ( a , a )

admits a solution x = a X . Moreover, x obeys the inequality x 2 x 0 , and it is the only one such that x 1 2 C .

3 Proof of main results

First, we consider the following linear generalized problem:

(3.1) t u + ν ( Δ ) α u + Ω e 3 × u + P = 0 , in R 3 × ( 0 , ) , div u = 0 , in R 3 × ( 0 , ) , u t = 0 = u 0 , in R 3 .

The solution of this equation can be given by the generalized Stokes-Coriolis semigroup T Ω , α ( t ) , which has the following explicit representation:

T Ω , α ( t ) u = 1 cos Ω ξ 3 ξ t e ν t ξ 2 α I + sin Ω ξ 3 ξ t e ν t ξ 2 α R ( ξ ) u = 1 cos Ω ξ 3 ξ t I + sin Ω ξ 3 ξ t R ( ξ ) ( e ν t ( Δ ) α u ) ,

where divergence free vector field u S ( R 3 ) , I is the unit matrix in M 3 × 3 ( R ) , and R ( ξ ) is skew-symmetric matrix defined by:

R ( ξ ) 1 ξ 0 ξ 3 ξ 2 ξ 3 0 ξ 1 ξ 2 ξ 1 0 , ξ R 3 \ { 0 } .

Now, we prove our main results by using lemmas.

Proof of Theorem 1.1

First, we know that the solution of equation (1.1) is as follows:

(3.2) u ( t ) = T Ω , α u 0 0 t T Ω , α ( t τ ) P div ( u u ) ( τ ) d τ ,

where P = I ( ) 1 div is the Leray-Hopf projection. So, the solution of equation (1.1) can be rewritten as:

u ( t ) = T Ω , α u 0 + B ( u , u ) ,

where

B ( u , v ) ( t ) = 0 t T Ω , α ( t τ ) P div ( u v ) ( τ ) d τ .

Moreover, T > 0 , χ T = C ( [ 0 , T ) , χ a , σ s ( R 3 ) ) L 1 ( [ 0 , T * ) , χ a , σ s + 2 α ( R 3 ) ) is endowed with the norm:

u χ T = u L T ( χ a , σ s ( R 3 ) ) + u L T 1 ( χ a , σ s + 2 α ( R 3 ) ) .

Step 1. Estimate of u in χ a , σ s ( R 3 ) .

Using the norm definition, the Hölder inequality, and the boundedness of multiplier T Ω , α , we have

T Ω , α u 0 χ a , σ s ( R 3 ) = R 3 ξ s e a ξ 1 σ T Ω , α u 0 ^ d ξ = R 3 ξ s e a ξ 1 σ 1 cos Ω ξ 3 ξ t I + sin Ω ξ 3 ξ t R ( ξ ) * e ν ( ) α t u 0 d ξ = R 3 ξ s e a ξ 1 σ cos Ω ξ 3 ξ t I + sin Ω ξ 3 ξ t R ( ξ ) e ν t ξ 2 α u 0 ^ d ξ R 3 ξ s e a ξ 1 σ e ν t ξ 2 α u 0 ^ d ξ u 0 χ a , σ s ( R 3 ) .

By boundedness of (2.1) and multipliers T Ω , α , we obtain

B ( u , v ) χ a , σ s ( R 3 ) R 3 ξ s e a ξ 1 σ 0 t [ T Ω , α ( t τ ) P div ( u v ) ( τ ) ] d τ d ξ R 3 ξ s + 1 e a ξ 1 σ 0 t cos Ω ξ 3 ξ ( t τ ) I + sin Ω ξ 3 ξ ( t τ ) R ( ξ ) e ν ( t τ ) ξ 2 α u v ^ d τ d ξ R 3 ξ s + 1 e a ξ 1 σ 0 T u v ^ d τ d ξ 0 T u v ^ χ a , σ s + 1 ( R 3 ) d τ .

By applying Lemma 2.4 and Young’s inequality, we deduce

B ( u , v ) χ a , σ s ( R 3 ) C s T s 1 2 α + 1 u L T ( χ a σ , σ s ( R 3 ) ) 1 + s 2 α v L T ( χ a , σ s ( R 3 ) ) 1 1 2 α u L T 1 ( χ a σ , σ s + 2 α ( R 3 ) ) s 2 α v L T 1 ( χ a , σ s + 2 α ( R 3 ) ) 1 2 α + u L T ( χ a , σ s ( R 3 ) ) 1 1 2 α v L T ( χ a σ , σ s ( R 3 ) ) 1 + s 2 α u L T 1 ( χ a , σ s + 2 α ( R 3 ) ) 1 2 α v L T 1 ( χ a σ , σ s + 2 α ( R 3 ) ) s 2 α C s , α T s 1 2 α + 1 ( u L T ( χ a σ , σ s ( R 3 ) ) + u L T 1 ( χ a σ , σ s + 2 α ( R 3 ) ) ) ( v L T ( χ a , σ s ( R 3 ) ) + v L T 1 ( χ a , σ s + 2 α ( R 3 ) ) ) + ( v L T ( χ a σ , σ s ( R 3 ) ) + v L T 1 ( χ a σ , σ s + 2 α ( R 3 ) ) ) ( u L T ( χ a , σ s ( R 3 ) ) + u L T 1 ( χ a , σ s + 2 α ( R 3 ) ) ) C s , α T s 1 2 α + 1 u χ T v χ T .

Step 2. Estimate of u in L 1 ( [ 0 , T * ) , χ a , σ s + 2 α ( R 3 ) ) .

Using the norm definition and the boundedness of multiplier T Ω , α , we obtain

T Ω u 0 L T 1 ( χ a , σ s + 2 α ( R 3 ) ) = R 3 ξ s + 2 α e a ξ 1 σ 0 T cos Ω ξ 3 ξ t I + sin Ω ξ 3 ξ t R ( ξ ) e ν t ξ 2 α u 0 ^ d t d ξ R 3 ξ s + 2 α e a ξ 1 σ u 0 ^ 0 T e ν t ξ 2 α d t d ξ 1 ν u 0 χ a , σ s ( R 3 ) .

Applying Minkowski’s inequality and Lemma 2.4, we obtain

B ( u , v ) L T 1 ( χ a , σ s + 2 α ( R 3 ) ) 0 T R 3 ξ s + 2 α e a ξ 1 σ 0 t [ T Ω , α ( t τ ) P div ( u v ) ( τ ) ] d τ d ξ d t 0 T R 3 ξ s + 2 α e a ξ 1 σ 0 t e ν ( t τ ) ξ 2 α u v ^ d τ d ξ d t R 3 ξ s + 2 α e a ξ 1 σ 0 T u v ^ τ T e ν ( t τ ) ξ 2 α d t d τ d ξ 1 ν R 3 ξ s + 2 α e a ξ 1 σ 0 T u v ^ d τ d ξ 1 ν 0 T u v ^ χ a , σ s + 1 ( R 3 ) d τ 1 ν C s , α T s 1 2 α + 1 u χ T v χ T .

Therefore,

T Ω , α u 0 χ T 1 + 1 ν u 0 χ a , σ s .

B : χ T × χ T χ T is a continuous bilinear operator that satisfies the following inequality:

B ( u , v ) χ T C s , α , ν T s 1 2 α + 1 u χ T v χ T .

Thereby, we can apply Lemma 2.6 to obtain a unique solution u χ T for equation (1.1).

Finally, we show that the solution obtained above for equation (1.1) also belongs to L 2 ( [ 0 , T * ) , χ a , σ s + α ( R 3 ) ) .

Using the definition, we obtain

T Ω , α u 0 L T 2 ( χ a , σ s + α ( R 3 ) ) R 3 0 T ( ξ s + α e a ξ 1 σ T Ω , α u 0 ^ ) 2 d t 1 2 d ξ R 3 ξ s + α e a ξ 1 σ u 0 ^ ( ξ ) 0 T e 2 ν t ξ 2 α d t 1 2 d ξ = R 3 ξ s + α e a ξ 1 σ u 0 ^ ( ξ ) 1 e 2 ν T ξ 2 α 2 ν ξ 2 α 1 2 d ξ 1 2 ν u 0 χ a , σ s ( R 3 ) .

Applying Minkowski’s inequality and Lemma 2.4, we obtain

B ( u , u ) L T 2 ( χ a , σ s + α ( R 3 ) ) 0 T R 3 ξ s + α + 1 e a ξ 1 σ 0 t [ T Ω , α ( t τ ) P div ( u u ) ( τ ) ] d τ d ξ 2 d t 1 2 R 3 0 T τ T ξ s + α + 1 e a ξ 1 σ e ν ( t τ ) ξ 2 α u u ^ 2 d t 1 2 d τ d ξ = R 3 ξ s + α + 1 e a ξ 1 σ 0 T u u ^ 1 e 2 ν ( T τ ) ξ 2 α 2 ν ξ 2 α 1 2 d τ d ξ 1 2 ν 0 T u u ^ χ a , σ s + 1 ( R 3 ) d τ C s , ν T s 1 2 α + 1 u χ T u χ T .

Thus, we conclude that u L 2 ( [ 0 , T * ) , χ a , σ s + α ( R 3 ) ) .□

Proof of Theorem 1.2

Suppose by contradiction that Theorem 1.2 does not hold, i.e.,

(3.3) limsup t T * u ( t ) χ a , σ s ( R 3 ) < .

In other words, there exists a constant C > 0 such that

(3.4) u ( t ) χ a , σ s ( R 3 ) C , t [ 0 , T * ) .

By applying the Fourier transform and taking the scalar product in C 3 of the first equation of (1.1) with u ^ ( t ) , one has

t u ^ , u ^ + ν ( Δ ) α u ^ , u ^ + ( u ) u ^ , u ^ + Ω e 3 × u ^ , u ^ + p ^ , u ^ = 0 ,

we all know that

Ω e 3 × u ^ , u ^ = Ω ( u 2 ^ , u 1 ^ , 0 ) ( u 1 ^ , u 2 ^ , u 3 ^ ) = Ω [ u 2 ^ u 1 ^ ¯ + u 1 ^ u 2 ^ ¯ ] = 2 Ω i Im ( u 1 ^ u 2 ^ ¯ ) .

Hence, we have

Re Ω e 3 × u ^ , u ^ = 0 .

Therefore, we can write

1 2 t u ^ 2 + ν ξ 2 α u ^ 2 ( u ) u ^ , u ^ .

For ε > 0 arbitrary,

1 2 t u ^ 2 = 1 2 t ( u ^ 2 + ε ) = u ^ 2 + ε t u ^ 2 + ε .

Thus, we can obtain

u ^ 2 + ε t u ^ 2 + ε + ν ξ 2 α u ^ 2 ( u ) u ^ , u ^ , t u ^ 2 + ν ξ 2 α u ^ 2 u ^ 2 + ε ( u ) u ^ .

By integrating from [ 0 , t ] , we conclude

u ( t ) ^ 2 + ε + ν 0 t ξ 2 α u ^ 2 u ^ 2 + ε d τ u 0 ^ 2 + ε + 0 t ( u ) u ^ d τ .

Passing to the limit as ε 0

u ( t ) ^ + ν ξ 2 α 0 t u ^ d τ u 0 ^ + 0 t ( u ) u ^ d τ .

Multiplying by ξ s e a ξ 1 σ and integrating over ξ , we deduce

u χ a , σ s ( R 3 ) + ν 0 t u χ a , σ s + 2 α ( R 3 ) d τ u 0 χ a , σ s ( R 3 ) + 0 t u u χ a , σ s ( R 3 ) d τ .

Therefore, applying Lemmas 2.4 and 2.5, we can obtain

u χ a , σ s ( R 3 ) + ν 0 t u χ a , σ s + 2 α ( R 3 ) d τ u 0 χ a , σ s ( R 3 ) + 0 t u u χ a , σ s + 1 ( R 3 ) d τ u 0 χ a , σ s ( R 3 ) + C s 0 t u χ a , σ s ( R 3 ) 2 + s 1 2 α u χ a , σ s + 2 α ( R 3 ) 1 s 2 α d τ .

As a consequence, by (3.4), we have

u χ a , σ s ( R 3 ) + ν 0 t u χ a , σ s + 2 α ( R 3 ) d τ u 0 χ a , σ s ( R 3 ) + C s C 2 + s 1 2 α 0 t u χ a , σ s + 2 α ( R 3 ) 1 s 2 α d τ .

Hence, for all t [ 0 , T * ) , we obtain

(3.5) 0 T * u χ a , σ s + 2 α ( R 3 ) d τ C a , σ , s , α , u 0 , T * .

Assume that ( k n ) is a sequence such that k n T * , where k n k m , for all m , n N with m n . Let us prove that

limsup n , m u ( k m ) u ( k n ) χ a , σ s ( R 3 ) = 0 .

According to (3.2), we can obtain

u ( k m ) u ( k n ) = [ T Ω , α ( k m ) T Ω , α ( k n ) ] u 0 0 k m [ T Ω , α ( k m τ ) T Ω , α ( k n τ ) ] P ( u ) u d τ + k m k n [ T Ω , α ( k n τ ) ] P ( u ) u d τ I 1 + I 2 + I 3 .

Observe that

I 1 χ a , σ s ( R 3 ) R 3 ξ s e a ξ 1 σ ( e k m ξ 2 α e T * ξ 2 α ) u 0 ^ ( ξ ) d ξ .

Consequently, by the dominated convergence theorem, we have

limsup n , m I 1 χ a , σ s ( R 3 ) = 0 .

Furthermore,

I 2 χ a , σ s ( R 3 ) 0 k m R 3 ξ s e a ξ 1 σ ( e ( k m τ ) ξ 2 α e ( k n τ ) ξ 2 α ) u u ^ d ξ d τ 0 T * R 3 ξ s e a ξ 1 σ [ 1 e ( T * k m ) ξ 2 α ] u u ^ d ξ d τ 0 T * u u χ a , σ s d τ .

Using Lemma 2.4, Lemma 2.5, and (3.4), one deduces

0 T * u u χ a , σ s d τ C s T * 1 + 1 s 2 α u L T * ( χ a , σ s ( R 3 ) ) 2 + s 1 2 α u L T * 1 ( χ a , σ s + 2 α ( R 3 ) ) 1 s 2 α C s T * 1 + 1 s 2 α C 2 + s 1 2 α C a , σ , s , α , u o , T * 1 s 2 α .

As a result, by the dominated convergence theorem, we deduce

limsup n , m I 2 χ a , σ s ( R 3 ) = 0 .

Finally, using Hölder’s inequality and (3.5), we obtain

I 3 χ a , σ s ( R 3 ) k m k n T Ω , α ( k n τ ) P ( u ) u χ a , σ s ( R 3 ) d τ C s k m T * u χ a , σ s ( R 3 ) 2 + s 1 2 α u χ a , σ s + 2 α ( R 3 ) 1 s 2 α d τ C a , σ , s , α , u 0 , T * k m T * u χ a , σ s + 2 α ( R 3 ) 1 s 2 α d τ C a , σ , s , α , u 0 , T * ( T * k m ) 1 1 s 2 α .

Consequently, by taking n , m , we obtain

limsup n , m I 3 χ a , σ s ( R 3 ) = 0 .

Thus, we show that u ( k n ) is a Cauchy sequence in the Banach space χ a , σ s . There is u 1 χ a , σ s such that

limsup n u ( k n ) u 1 χ a , σ s ( R 3 ) = 0 .

The aforementioned limit does not depend on k n , and choose ( ρ n ) n N ( 0 , T * ) such that ρ n T * ,

limsup n u ( ρ n ) u 2 χ a , σ s ( R 3 ) = 0 ,

for u 2 χ a , σ s ( R 3 ) . Define ( ς n ) n N ( 0 , T * ) by ς 2 n = k n , and ς 2 n 1 = ρ n , for all n N . It is easy to check that ς n T * . There is u 3 χ a , σ s ( R 3 ) such that

limsup n u ( ς n ) u 3 χ a , σ s ( R 3 ) = 0 .

Consequently, we infer u 1 = u 2 = u 3 . We proved that the solution u can be extended beyond t = T * , by the existence and uniqueness of u ¯ C T ¯ ( χ a , σ s ( R 3 ) ) ( T ¯ > 0 ) , for the GNSC System (1.1). u ˜ C T ¯ + T * ( χ a , σ s ( R 3 ) ) given by:

(3.6) u ˜ ( t ) = u ( t ) , t [ 0 , T * ) ; u ¯ ( t T * ) , t [ T * , T ¯ + T * ] ,

solves (1.1) in [ 0 , T ¯ + T * ] ; this is a contradiction. Thus, we have

limsup t T * u ( t ) χ a , σ s ( R 3 ) = .

Acknowledgements

The authors would like to thank the anonymous referee and editor for their valuable comments and suggestions, which greatly helped us improve the presentation of this article.

  1. Funding information: This work was supported by the National Natural Science Foundation of China (11601434).

  2. Author contributions: All authors have accepted responsibility for the entire content of this manuscript and approved its submission.

  3. Conflict of interest: Authors state that there is no conflict of interest.

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Received: 2023-08-01
Revised: 2023-11-28
Accepted: 2023-12-10
Published Online: 2023-12-31

© 2023 the author(s), published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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