Generalized Picone inequalities and their applications to (p,q)-Laplace equations

Vladimir Bobkov; Mieko Tanaka

doi:10.1515/math-2020-0065

Article Open Access

Generalized Picone inequalities and their applications to (p,q)-Laplace equations

Vladimir Bobkov and Mieko Tanaka

Published/Copyright: September 30, 2020

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$Open Mathematics$

From the journal Open Mathematics Volume 18 Issue 1

Abstract

We obtain a generalization of the Picone inequality which, in combination with the classical Picone inequality, appears to be useful for problems with the ( p , q ) -Laplace-type operators. With its help, as well as with the help of several other known generalized Picone inequalities, we provide some nontrivial facts on the existence and nonexistence of positive solutions to the zero Dirichlet problem for the equation − Δ p u − Δ q u = f μ ( x , u , ∇ u ) in a bounded domain Ω ⊂ ℝ N under certain assumptions on the nonlinearity and with a special attention to the resonance case f μ ( x , u , ∇ u ) = λ 1 ( p ) | u | p − 2 u + μ | u | q − 2 u , where λ 1 ( p ) is the first eigenvalue of the p-Laplacian.

Keywords: Picone inequality; Picone identity; (p,q)-Laplacian; nonexistence; positive solutions

MSC 2010: 35J62; 35J20; 35P30; 35A01

1 Picone inequalities

Throughout this section, we denote by Ω a nonempty connected open set in ℝ N , N ≥ 1 . The current classical version of the Picone inequality (also commonly referred to as the Picone identity) for the p-Laplacian can be stated as follows.

Theorem 1.1

[1, Theorem 1.1] Let p > 1 and let u , v be differentiable functions in Ω such that u > 0 , v ≥ 0 . Then

(1.1) | ∇ u | p − 2 ∇ u ∇ v p u p − 1 ≤ | ∇ v | p .

Moreover, the equality in (1.1) is satisfied in Ω if and only if u ≡ k v for some constant k > 0 .

In the linear case p = 2 , inequality (1.1) is a direct consequence of the simple identity

(1.2) ∇ u ∇ v 2 u = | ∇ v | 2 − ∇ v − v u ∇ u 2

whose one-dimensional version was used by M. Picone in [2, Section 2] to prove the Sturm comparison theorem. Subsequently, due to the nontrivial and convenient choice of the test function v p u p − 1 , identity (1.2) and inequality (1.1) appeared to be effective in the study of many other properties of various ordinary and partial differential equations and systems of both linear and nonlinear nature. In particular, one can mention the uniqueness and nonexistence of positive solutions, Hardy-type inequalities, bounds on eigenvalues, Morse index estimates, etc. Such a wide range of applications particularly motivated a search of reasonable generalizations of the Picone inequality, see, e.g., the works in [3,4,5,6,7,8,9,10,11], although this list is far from being comprehensive.

On the other hand, during the last few decades, there has been growing interest in the investigation of various composite-type operators such as the sum of the p- and q-Laplacians with p ≠ q , the so-called ( p , q ) -Laplacian. The motivation for corresponding studies comes from both the intrinsic mathematical interest and applications in natural sciences, see, for instance, [12,13,14,15,16,17,18,19] and references therein, to mention a few. Clearly, most of the properties indicated above can be posed for problems with such operators, too. It is then natural to ask which generalizations of the Picone inequality are favourable to be applied to the ( p , q ) -Laplacian. If one tries to use v p u p − 1 or v q u q − 1 as a test function, then, taking into account (1.1), the following two quantities have to be estimated:

| ∇ u | p − 2 ∇ u ∇ v q u q − 1 and | ∇ u | q − 2 ∇ u ∇ v p u p − 1 .

There are at least two known generalized Picone inequalities in this regard. The first one was obtained in [7], where its equivalence to two convexity principles for variational integrals is also shown. Its particular form can be stated as follows.

Theorem 1.2

[7, Proposition 2.9 and Remark 2.10] Let p , q > 1 and let u , v be differentiable functions in Ω such that u > 0 , v ≥ 0 . If q ≤ p , then

(1.3) | ∇ u | p − 2 ∇ u ∇ v q u q − 1 ≤ q p | ∇ v | p + p − q p | ∇ u | p .

Remark 1.3

Although the case of equality in (1.3) is not discussed in [7], one can show that if q < p , then the equality in (1.3) is satisfied in Ω if and only if u ≡ v .

The second generalization of (1.1) was obtained in [8] in the context of study of an equation with indefinite nonlinearity. Later, this result was also applied in [5] to an eigenvalue problem for the ( p , q ) -Laplacian.

Theorem 1.4

[8, Lemma 1] Let p , q > 1 and let u , v be differentiable functions in Ω such that u > 0 , v ≥ 0 . If p ≤ q , then

(1.4) | ∇ u | p − 2 ∇ u ∇ v q u q − 1 ≤ | ∇ v | p − 2 ∇ v ∇ v q − p + 1 u q − p .

Moreover, the equality in (1.4) is satisfied in Ω if and only if u ≡ k v for some constant k > 0 .

Remark 1.5

For convenience of further applications of (1.4), we rewrite it, assuming q ≤ p , as follows:

(1.5) | ∇ u | q − 2 ∇ u ∇ v p u p − 1 ≤ | ∇ v | q − 2 ∇ v ∇ v p − q + 1 u p − q .

Note that both (1.3) and (1.4) turn to the Picone inequality (1.1) when p = q . Moreover, we emphasize that (1.3) requires q ≤ p , while (1.4) asks for p ≤ q . Our main result, Theorem 1.8, posits the fact that inequality (1.4) remains valid for some p > q , although the set of feasible values of p and q is not of a trivial structure (Figure 1). This set is defined and characterized in the following lemma.

$Figure 1 The grey set schematically depicts the set of points ( p , q ) (p,q) with p ∈ I ( q ) p\in I(q) .$

Figure 1

The grey set schematically depicts the set of points ( p , q ) with p ∈ I ( q ) .

Lemma 1.6

Let q > 1 be fixed. Let the function g : [ 0 , + ∞ ) × ( 1 , + ∞ ) → ℝ be defined as

g ( s ; p ) = ( q − 1 ) s p + q s p − 1 − ( p − q ) s + ( q − p + 1 ) ,

let

I ( q ) ≔ { p > 1 : g ( s ; p ) ≥ 0 f o r a l l s ≥ 0 } ,

and set p ˜ = p ˜ ( q ) ≔ sup { p > 1 : p ∈ I ( q ) } . Then max { 2 , q } < p ˜ < q + 1 . Moreover, there exists q ˜ ∈ ( 1 , 2 ] such that the following assertions hold:

if q < q ˜ , then there exist p ∗ = p ∗ ( q ) and p ∗ = p ∗ ( q ) satisfying q < p ∗ < p ∗ < 2 such that ( 1 , p ∗ ] ∪ [ p ∗ , p ˜ ] ⊂ I ( q ) and ( p ∗ , p ∗ ) ⊄ I ( q ) ;
if q ≥ q ˜ , then I ( q ) = ( 1 , p ˜ ] .

Furthermore, if 1 < q 1 < q 2 and p ∈ I ( q 1 ) , then p ∈ I ( q 2 ) , i.e., I ( q 1 ) ⊂ I ( q 2 ) .

In particular, each of the following two explicit assumptions is sufficient to guarantee that p ∈ I ( q ) :

1 < q < p ≤ 2 and p ≤ q + q p − 1 ( q − 1 ) 2 − p ;
2 ≤ p < q + 1 and ( q + 1 − p ) p − 2 q ≥ ( p − q ) p − 1 .

Remark 1.7

Assertions (i) and (ii) of Lemma 1.6 yield 2 ∈ I ( q ) for any q > 1 . A numerical investigation of the function g indicates that q ˜ = 1.051633991 … and that p ∗ , p ∗ in assertion (i) can be chosen such that p ∗ , p ∗ ∩ I ( q ) = ∅ , that is, if q < q ˜ , then I ( q ) = ( 1 , p ∗ ] ∪ [ p ∗ , p ˜ ] (Figure 1).

Now we are ready to state our main result.

Theorem 1.8

Let p , q > 1 and let u , v be differentiable functions in Ω such that u > 0 , v > 0 . Assume that one of the following assumptions is satisfied:

p ∈ I ( q ) , where I ( q ) is given by Lemma 1.6;
p ≤ q + 1 and ∇ u ∇ v ≥ 0 .

Then

(1.6) | ∇ u | p − 2 ∇ u ∇ v q u q − 1 ≤ | ∇ v | p − 2 ∇ v ∇ v q − p + 1 u q − p .

Moreover, if p < q + 1 and ∇ u ∇ v ≥ 0 , then the equality in (1.6) is satisfied in Ω if and only if u ≡ k v for some constant k > 0 .

Furthermore, assumptions (i) and (ii) are optimal in the following sense:

if p ∉ I ( q ) , then there exist u , v and a point x ∈ Ω such that (1.6) is violated at x;
if p > q + 1 , then there exist u , v with ∇ u ∇ v ≥ 0 and a point x ∈ Ω such that (1.6) is violated at x.

A closer look at the proof of Theorem 1.8(ii) reveals that inequality (1.6) remains valid under assumption (ii) also for q = 1 . In fact, even the following stronger result, which reduces to the commutativity of the scalar product in W 1 , 2 ( Ω ) at p = 2 , can be obtained by the same method of proof.

Proposition 1.9

Let u , v be differentiable functions in Ω such that u > 0 , v > 0 , and ∇ u ∇ v ≥ 0 . Then the following assertions hold:

if p ∈ ( 1 , 2 ] , then
(1.7) | ∇ u | p − 2 ∇ u ∇ v ≤ | ∇ v | p − 2 ∇ v ∇ ( u p − 1 v 2 − p ) ;
if p ≥ 2 , then
(1.8) | ∇ u | p − 2 ∇ u ∇ v ≥ | ∇ v | p − 2 ∇ v ∇ ( u p − 1 v 2 − p ) .

Moreover, if p ≠ 2 , then the equality in (1.7) or (1.8) is satisfied in Ω if and only if u ≡ k v for some constant k > 0 .

Apart from the choice of v p u p − 1 or v q u q − 1 as a test function, one could also consider more general test functions of the form v p f ( u ) or v q f ( u ) . In this direction, the following partial case of a generalized Picone inequality obtained in [10] by applying an inequality from [9, Lemma 2.1] can be effectively used.

Theorem 1.10

[10, Theorem 2.2] Let p > 1 and let u , v be differentiable functions in Ω such that u > 0 , v ≥ 0 . Assume that f ∈ C 1 ( 0 , + ∞ ) satisfies f ( s ) , f ′ ( s ) > 0 for all s ∈ ( 0 , + ∞ ) . Then

(1.9) | ∇ u | p − 2 ∇ u ∇ v p f ( u ) ≤ ( p − 1 ) p − 1 f ( u ) p − 2 f ′ ( u ) p − 1 | ∇ v | p .

Moreover, the equality in (1.9) is satisfied in Ω if and only if f ( u ) ≡ k v p − 1 for some constant k > 0 .

Remark 1.11

Let q > 1 . Since v p = ( v p / q ) q , we get from (1.9) the complementary inequality

(1.10) | ∇ u | q − 2 ∇ u ∇ v p f ( u ) ≤ ( q − 1 ) q − 1 f ( u ) q − 2 f ′ ( u ) q − 1 | ∇ ( v p / q ) | q .

Note that the term | ∇ ( v p / q ) | is well-defined if either q ≤ p and v ≥ 0 , or q ≠ p and v > 0 . In particular, under any of these assumptions, taking f ( s ) = s p − 1 , we obtain

(1.11) | ∇ u | q − 2 ∇ u ∇ v p u p − 1 ≤ q − 1 p − 1 q − 1 p q q v u p − q | ∇ v | q .

Moreover, under the assumption q < p , the application of Young’s inequality gives

(1.12) | ∇ u | q − 2 ∇ u ∇ v p u p − 1 ≤ q − 1 p − 1 q − 1 p q q p − q p v u p + q p | ∇ v | p .

Evidently, (1.11) and (1.12) reduce to the Picone inequality (1.1) if q = p .

As a complementary fact, we provide the following optimal refinement of a generalized Picone inequality obtained in [5, Proposition 8], by analysing the right-hand sides of inequalities (1.9) and (1.10).

Proposition 1.12

Let p , q > 1 , α , β > 0 , and let u , v be differentiable functions in Ω such that u > 0 , v ≥ 0 . If q < p , then

| ∇ u | p − 2 ∇ u ∇ v p α u p − 1 + β u q − 1 ≤ 1 α C | ∇ v | p

and

| ∇ u | q − 2 ∇ u ∇ v p α u p − 1 + β u q − 1 ≤ 1 β | ∇ ( v p / q ) | q ,

where C = 1 if p ≤ q + 1 , and C = ( q − 1 ) p − 2 ( p − q ) ( p − 2 ) p − 2 if p ≥ q + 1 .

Finally, let us note that the Picone inequality (1.1) can be used to derive the Díaz-Saa inequality [20]:

(1.13) ∫ Ω − Δ p w 1 w 1 p − 1 + Δ p w 2 w 2 p − 1 ( w 1 p − w 2 p ) d x ≥ 0 ,

which, in particular, holds (in the sense of distributions) for all w 1 , w 2 ∈ W 0 1 , p ( Ω ) such that w i > 0 a.e. in Ω , and w 1 w 2 , w 2 w 1 ∈ L ∞ ( Ω ) , assuming that Ω is smooth and bounded, see [21, Theorem 2.5]. Inequality (1.13) appeared to be a useful tool in the study of uniqueness of positive solutions to boundary value problems with the p-Laplacian. Its generalization to the ( p , q ) -Laplacian, together with the corresponding applications, was obtained in [17], see also [3,21]. Under the same assumptions on w 1 , w 2 and Ω as above, it can be stated as follows. If 1 < q < p and μ > 0 , then

(1.14) ∫ Ω − Δ p w 1 + μ Δ q w 1 w 1 q − 1 + Δ p w 2 + μ Δ q w 2 w 2 q − 1 ( w 1 q − w 2 q ) d x ≥ 0 .

Inequality (1.14) can be established by applying the generalized Picone inequality (1.3).

The rest of the article is organized as follows. In Section 2, we prove Theorem 1.8 and Lemma 1.6. In Section 3, we provide several applications of Theorem 1.8, as well as of Theorems 1.2 and 1.4, to problems with the ( p , q ) -Laplacian.

2 Proofs of Theorem 1.8 and Lemma 1.6

Proof of Theorem 1.8

Since the case p ≤ q is covered by Theorem 1.4, we will assume hereinafter that p > q . Moreover, under any of the assumptions (i) and (ii), p has the upper bound p ≤ q + 1 (see Lemma 1.6 in the case of assumption (i)).

By straightforward calculations, we get

(2.1) | ∇ u | p − 2 ∇ u ∇ v q u q − 1 = q | ∇ u | p − 2 ∇ u ∇ v v u q − 1 − ( q − 1 ) | ∇ u | p v u q

and

(2.2) | ∇ v | p − 2 ∇ v ∇ v q − p + 1 u q − p = ( q − p + 1 ) | ∇ v | p v u q − p + ( p − q ) | ∇ v | p − 2 ∇ v ∇ u v u q − p + 1 .

We see from (2.1) and (2.2) that the desired inequality (1.6) is equivalent to

(2.3) q | ∇ u | p − 2 ∇ u ∇ v v u q − 1 − ( p − q ) | ∇ v | p − 2 ∇ v ∇ u v u q − p + 1 ≤ ( q − 1 ) | ∇ u | p v u q + ( q − p + 1 ) | ∇ v | p v u q − p .

Dividing by v q u p − q , we reduce (2.3) to

(2.4) ∇ u ∇ v u v q | ∇ u | u p − 2 − ( p − q ) | ∇ v | v p − 2 ≤ ( q − 1 ) | ∇ u | u p + ( q − p + 1 ) | ∇ v | v p .

Recalling that q − p + 1 ≥ 0 , we see that (2.4) is satisfied if its left-hand side is nonpositive. Therefore, let us assume that the left-hand side of (2.4) is positive. In particular, we have ∇ u ∇ v ≠ 0 , and hence | ∇ u | , | ∇ v | > 0 . We consider two separate cases.

Suppose that
∇ u ∇ v > 0 and q | ∇ u | u p − 2 − ( p − q ) | ∇ v | v p − 2 > 0 .
In this case, in order to validate (2.4) it is sufficient to prove that
(2.5) | ∇ u | | ∇ v | u v q | ∇ u | u p − 2 − ( p − q ) | ∇ v | v p − 2 ≤ ( q − 1 ) | ∇ u | u p + ( q − p + 1 ) | ∇ v | v p .
Denoting s = | ∇ u | u v | ∇ v | , we see that (2.5) holds provided
(2.6) f ( s ) ≔ ( q − 1 ) s p − q s p − 1 + ( p − q ) s + ( q − p + 1 ) ≥ 0 for all s ≥ 0 .
Let us show that (2.6) is satisfied. We have
f ″ ( s ) = p ( p − 1 ) ( q − 1 ) s p − 2 − q ( p − 1 ) ( p − 2 ) s p − 3 > 0 if and only if s > max 0 , q ( p − 2 ) p ( q − 1 ) .
Combining this strict convexity of f with the facts that f ( 1 ) = f ′ ( 1 ) = 0 and q ( p − 2 ) p ( q − 1 ) < 1 , we see that
f ( s ) ≥ 0 for all s ≥ max 0 , q ( p − 2 ) p ( q − 1 ) ,
and the equality f ( s ) = 0 for such s happens if and only if s = 1 . In particular, f ( s ) ≥ 0 for all s ≥ 0 provided p ≤ 2 . Assume that p > 2 . Since f is concave on 0 , q ( p − 2 ) p ( q − 1 ) , f q ( p − 2 ) p ( q − 1 ) > 0 , f ( 0 ) > 0 for p < q + 1 , and f ( 0 ) = 0 for p = q + 1 , we conclude that
f ( s ) ≥ 0 for all s ∈ 0 , q ( p − 2 ) p ( q − 1 ) ,
and the equality f ( s ) = 0 for such s happens if and only if s = 0 and p = q + 1 . Thus, we have derived that f ( s ) ≥ 0 for all s ≥ 0 provided p ≤ q + 1 . In particular, this implies that (1.6) is satisfied under assumption (ii). Moreover, we have shown that if p < q + 1 , then f ( s ) = 0 if and only if s = 1 . Therefore, if p < q + 1 , ∇ u ∇ v ≥ 0 , and the equality in (1.6) is satisfied in Ω , then we conclude that ∇ u ∇ v = | ∇ u | | ∇ v | and | ∇ u | u = | ∇ v | v , which yields ∇ v u = 0 in Ω , that is, u ≡ k v for some constant k > 0 .
Suppose that

(2.7) ∇ u ∇ v < 0 and q | ∇ u | u p − 2 − ( p − q ) | ∇ v | v p − 2 < 0 .

To establish (2.4) under assumption (2.7), it is sufficient to show that

(2.8) | ∇ u | | ∇ v | u v − q | ∇ u | u p − 2 + ( p − q ) | ∇ v | v p − 2 ≤ ( q − 1 ) | ∇ u | u p + ( q − p + 1 ) | ∇ v | v p .

Introducing again the notation s = | ∇ u | u v | ∇ v | , we see that inequality (2.8) holds if

(2.9) g ( s ; p ) ≔ ( q − 1 ) s p + q s p − 1 − ( p − q ) s + ( q − p + 1 ) ≥ 0 for all s ≥ 0 .

Applying Lemma 1.6, we deduce that (2.9) is satisfied whenever p ∈ I ( q ) .

Combining cases (1) and (2), we conclude that (1.6) holds under assumption (i), which finishes the proof of the first part of the theorem.

Let us now obtain the optimality of assumptions (i) and (ii) stated in (I) and (II), respectively. Assume first that p ∉ I ( q ) and let s 0 ≥ 0 be such that g ( s 0 ; p ) < 0 . Consider

u ( x 1 , … , x N ) = 1 − α x 1 and v ( x 1 , … , x N ) = 1 + x 1

for some α ≥ 0 . Noting that | ∇ u ( 0 ) | u ( 0 ) v ( 0 ) | ∇ v ( 0 ) | = α and taking α = s 0 , we conclude that the violation of (2.9) at s 0 implies the violation of (2.8) at x = 0 . On the other hand, we have ∇ u ∇ v = − | ∇ u | | ∇ v | . Thus, the violation of (2.8) at x = 0 is equivalent to the violation of (2.4) at x = 0 , which, in its turn, is equivalent to the violation of (1.6) at x = 0 . This establishes case (I).

Assume now that p > q + 1 . Set u ≡ const > 0 and let v > 0 be any differentiable function not identically equal to a constant. We readily see that ∇ u ∇ v ≡ 0 and (2.3) is violated at points where | ∇ v | > 0 , which establishes case (II).□

Now we provide the proof of Lemma 1.6.

Proof of Lemma 1.6

To prove that max { 2 , q } < p ˜ < q + 1 , we first note that

(2.10) g ( s ; 2 ) = ( q − 1 ) s 2 + 2 ( q − 1 ) s + ( q − 1 ) ≥ q − 1 > 0 ,

g ( s ; q ) = ( q − 1 ) s q + q s q − 1 + 1 ≥ 1 ,

for all s ≥ 0 . This yields 2 , q ∈ I ( q ) , and hence max { 2 , q } ≤ p ˜ . Second, we have g ( 0 ; p ) = q − p + 1 < 0 for any p > q + 1 , which implies that p ˜ ≤ q + 1 . Third, we see that

g ( s ; q + 1 ) = ( q − 1 ) s q + 1 + q s q − s < 0 for all sufficiently small s > 0 ,

and

(2.11) g ( s ; p ) ≥ ( q − 1 ) s p + ( 2 q − p ) s + ( q − p + 1 ) > 0 for all s ≥ 1 and 2 ≤ p ≤ q + 1 .

Therefore, since g is uniformly continuous on compact subsets of [ 0 , 1 ] × ( 1 , + ∞ ) , we conclude that max { 2 , q } < p ˜ < q + 1 . Moreover, the continuity of g gives p ˜ ∈ I ( q ) .

Let us prove assertions (i) and (ii). To this end, we note that

(2.12) g ( s ; p 1 ) > g ( s ; p 2 ) for every s ∈ [ 0 , 1 ] provided 1 < p 1 < p 2 .

In view of this monotonicity, inequalities (2.10) and (2.11) yield [ 2 , p ˜ ] ⊂ I ( q ) . At the same time, we see that if p ≤ q , then

g ( s ; p ) ≥ ( q − 1 ) s p + q s p − 1 − ( p − q ) s ≥ ( q − 1 ) s p + q s p − 1 ≥ 0 for all s ≥ 0 ,

which shows, in particular, that ( 1 , q ] ⊂ I ( q ) . Thus, we deduce that I ( q ) = ( 1 , p ˜ ] provided q ≥ 2 . Let us now define the critical value

q ˜ = inf { q > 1 : I ( q ) = ( 1 , p ˜ ] } .

Clearly, q ˜ ≤ 2 . Since q is presented in the function g only as a positive coefficient, we see that p ∈ I ( q 1 ) implies p ∈ I ( q 2 ) provided q 1 < q 2 , i.e., I ( q 1 ) ⊂ I ( q 2 ) . Combining this fact with the already obtained inclusion [ 2 , p ˜ ] ⊂ I ( q ) , we conclude that if q > q ˜ , then I ( q ) = ( 1 , p ˜ ] . Note that if q is sufficiently close to 1, then I ( q ) ≠ ( 1 , p ˜ ] , and so q ˜ > 1 . Indeed, choosing, for instance, q = 1.05 , we have g ( 60 ; 1.3 ) = − 0.417508 … , which yields 1.3 ∉ I ( q ) , and hence q ˜ ≥ 1.05 > 1 . This implies, by the continuity of g, that I ( q ) = ( 1 , p ˜ ] also for q = q ˜ , and this completes the proof of assertion (ii).

Assume now that 1 < q < q ˜ . In particular, recalling that q ˜ ≤ 2 , we have 1 < q < 2 . We start by showing that, in addition to (2.11), there exists p ⁎ ∈ ( q , 2 ) with the property that g ( s ; p ) ≥ 0 for all s ≥ 1 and p ∈ [ p ∗ , 2 ] . Indeed, suppose, by contradiction, that for any n ∈ ℕ one can find p n ∈ ( q , 2 ) and s n ≥ 1 such that g ( s n ; p n ) < 0 , and p n → 2 as n → + ∞ . Then { s n } must be bounded, since otherwise g ( s n ; p n ) → + ∞ as n → + ∞ . Therefore, passing to the limit along appropriate subsequences of { p n } and { s n } , we get a contradiction to (2.11). Thus, the monotonicity (2.12) in combination with (2.10) and (2.11) yields [ p ∗ , p ˜ ] ⊂ I ( q ) , which establishes the existence of p ∗ from assertion (i).

Now, we show the existence of p ∗ ∈ ( q , 2 ) such that g ( s ; p ) ≥ 0 for all s ≥ 0 and p ∈ ( q , p ∗ ] . Suppose, by contradiction, that for any n ∈ ℕ one can find p n ∈ ( q , 2 ) and s n > 0 satisfying g ( s n ; p n ) < 0 , and p n → q as n → + ∞ . Since the term ( p n − q ) s n is the only term in g ( s n ; p n ) with negative sign, we conclude that s n → + ∞ as n → + ∞ . But then we deduce that

0 > g ( s n ; p n ) ≥ ( q − 1 ) s n q + q s n q − 1 − ( 2 − q ) s n + ( q − 1 ) > 0

for all sufficiently large n, since ( q − 1 ) s n q is the leading term as s n → + ∞ , which is impossible. Recalling that ( 1 , q ] ⊂ I ( q ) , we conclude that ( 1 , p ∗ ] ⊂ I ( q ) . Since q < q ˜ , we deduce that q < p ∗ < p ∗ < 2 and ( p ∗ , p ∗ ) \ I ( q ) ≠ ∅ , which completes the proof of assertion (i).

Finally, we justify the sufficient assumptions (I) and (II).

Let 1 < q < p ≤ 2 . Considering the sum of the second and third terms of g ( s ; p ) , we see that if s 2 − p ≤ q p − q , then g ( s ; p ) ≥ 0 . Thus, let us assume that s 2 − p > q p − q and p < 2 . Then we have
g ( s ; p ) ≥ ( q − 1 ) s p − ( p − q ) s = s p − q q ( q − 1 ) s p − 1 q p − q − q > s p − q q ( q − 1 ) q p − q p − 1 2 − p + 1 − q ≥ 0 ,
where the last inequality is satisfied if and only if p ≤ q + q p − 1 ( q − 1 ) 2 − p .
Let 2 ≤ p < q + 1 . As in the previous case, we see that if s p − 2 ≥ p − q q , then g ( s ; p ) ≥ 0 . Hence, we assume that s p − 2 < p − q q and p > 2 . Then we have

g ( s ; p ) ≥ − ( p − q ) s + ( q − p + 1 ) > − ( p − q ) p − 1 p − 2 q 1 p − 2 + ( q − p + 1 ) ≥ 0 ,

where the last inequality is satisfied if and only if ( q + 1 − p ) p − 2 q ≥ ( p − q ) p − 1 .□

3 Applications to (p,q)-Laplace equations

Throughout this section, we always assume that 1 < q < p and that Ω ⊂ ℝ N is a smooth bounded domain with boundary ∂ Ω , N ≥ 1 .

Denote by ∥ ⋅ ∥ r the standard norm of L r ( Ω ) , 1 ≤ r ≤ + ∞ . Let λ 1 ( r ) with 1 < r < + ∞ stand for the first eigenvalue of the Dirichlet r-Laplacian in Ω , and let φ r be the corresponding first eigenfunction which we assume to be positive and normalized as ∥ ∇ φ r ∥ r = 1 . That is,

λ 1 ( r ) = inf ∫ Ω | ∇ u | r d x ∫ Ω | u | r d x : u ∈ W 0 1 , r ( Ω ) \ { 0 } and λ 1 ( r ) ∥ φ r ∥ r r = ∥ ∇ φ r ∥ r r = 1 .

Note that λ 1 ( r ) is simple and φ r ∈ int C 0 1 ( Ω ¯ ) + , where

C 0 1 ( Ω ¯ ) ≔ { u ∈ C 1 ( Ω ¯ ) : u ( x ) = 0 for all x ∈ ∂ Ω } , int C 0 1 ( Ω ¯ ) + ≔ u ∈ C 0 1 ( Ω ¯ ) : u ( x ) > 0 for all x ∈ Ω , ∂ u ∂ ν ( x ) < 0 for all x ∈ ∂ Ω ,

and ν is the unit exterior normal vector to ∂ Ω . Finally, for a weight function m ∈ L 1 ( Ω ) satisfying ∫ Ω m ( x ) φ p q d x > 0 , we define

(3.1) β ∗ m = ∫ Ω | ∇ φ p | q d x ∫ Ω m ( x ) φ p q d x and β ∗ = ∫ Ω | ∇ φ p | q d x ∫ Ω φ p q d x .

We remark that β ∗ > λ 1 ( q ) , which follows from the simplicity of λ 1 ( q ) and linear independence of φ p and φ q , see [22, Proposition 13].

3.1 General problem with (p,q)-Laplacian

Consider the boundary value problem

(3.2) − Δ p u − Δ q u = f μ ( x , u , ∇ u ) in Ω , u = 0 on ∂ Ω ,

where the function f μ ( x , s , ξ ) : Ω × ℝ × ℝ N → ℝ is sufficiently regular in order that (3.2) possesses a weak formulation with respect to W 0 1 , p ( Ω ) and satisfies the following assumption:

(A) there exist M ⊆ ℝ and m ∈ L 1 ( Ω ) satisfying ∫ Ω m ( x ) φ p q d x > 0 such that

f μ ( x , s , ξ ) > λ 1 ( p ) s p − 1 + β ∗ m m ( x ) s q − 1

for all μ ∈ M , s > 0 , ξ ∈ ℝ N , and a.e. x ∈ Ω , where β ∗ m is given by (3.1).

We obtain the following nonexistence result in the class of int C 0 1 ( Ω ¯ ) + -solutions.

Theorem 3.1

Let p ∈ I ( q ) , where I ( q ) is defined in Lemma 1.6, and let (A) be satisfied. If μ ∈ M , then (3.2) has no solution in int C 0 1 ( Ω ¯ ) + .

Proof

Suppose, by contradiction, that (3.2) possesses a solution u ∈ int C 0 1 ( Ω ¯ ) + for some μ ∈ M . Noting that φ p u ∈ L ∞ ( Ω ) since φ p , u ∈ int C 0 1 ( Ω ¯ ) + , we choose φ p q u q − 1 as a test function for (3.2). Applying Theorems 1.1 and 1.8, we get

λ 1 ( p ) ∫ Ω u p − q φ p q d x + β ∗ m ∫ Ω m ( x ) φ p q d x < ∫ Ω f μ ( x , u , ∇ u ) φ p q u q − 1 d x = ∫ Ω | ∇ u | p − 2 ∇ u ∇ φ p q u q − 1 d x + ∫ Ω | ∇ u | q − 2 ∇ u ∇ φ p q u q − 1 d x ≤ ∫ Ω | ∇ φ p | p − 2 ∇ φ p ∇ φ p q − p + 1 u q − p d x + ∫ Ω | ∇ φ p | q d x = λ 1 ( p ) ∫ Ω u p − q φ p q d x + β ∗ m ∫ Ω m ( x ) φ p q d x ,

which is impossible.□

Note that we cannot claim that each weak solution of (3.2) belongs to int C 0 1 ( Ω ¯ ) + since we do not impose suitable “good” assumptions on the function f μ apart from those stated above; see, e.g., [23] for a related discussion. We also remark that neither of the generalized Picone inequalities (1.3), (1.4), and (1.9) can be used (at least, as directly as (1.6)) to establish Theorem 3.1.

3.2 Eigenvalue-type problem

In the special case f μ ( x , s , ξ ) = λ 1 ( p ) | s | p − 2 s + μ | s | q − 2 s , (3.2) can be seen as an eigenvalue problem for the ( p , q ) -Laplacian:

(3.3) − Δ p u − Δ q u = λ 1 ( p ) | u | p − 2 u + μ | u | q − 2 u in Ω , u = 0 on ∂ Ω ,

see, e.g., [5,18,22,24]. Note that any nonzero and nonnegative solution of (3.3) belongs to int C 0 1 ( Ω ¯ ) + , see, for instance, [5, Remark 1] or [18, Section 2.4]. Although in the works in [5,22] by the present authors the structure of the set of positive solutions to a general version of (3.3) with two parameters has been comprehensively studied, we were not able to characterize completely the range of values of μ for which (3.2) possesses a positive solution. Thanks to our generalized Picone inequality (1.6), as well as to inequalities (1.3) and (1.4), we can provide additional information in this regard.

First, the same reasoning as in Theorem 3.1 allows us to show the following result.

Theorem 3.2

Assume that one of the following assumptions is satisfied:

p ∈ I ( q ) , where I ( q ) is defined in Lemma 1.6;
p ≤ q + 1 and Ω is an N-ball.

Then (3.3) has no positive solution for μ > β ∗ , where β ∗ is given by (3.1). Moreover, if p < q + 1 and Ω is an N-ball, then (3.3) has no positive solution also for μ = β ∗ .

Proof

Let u be a positive solution of (3.3). Recall that u ∈ int C 0 1 ( Ω ¯ ) + . Moreover, under assumption (ii), both u and φ p are radially symmetric with respect to the centre of Ω and nonincreasing in the corresponding radial direction (see [25, Theorem 3.10]), which yields ∇ u ∇ φ p ≥ 0 in Ω . Clearly, f μ ( x , s , ξ ) = λ 1 ( p ) | s | p − 2 s + μ | s | q − 2 s satisfies (A) with m ≡ 1 (so β ∗ m = β ∗ ) and M = ( β ∗ , + ∞ ) . Therefore, applying Theorem 1.8 as in the proof of Theorem 3.1, we obtain the desired nonexistence for μ > β ∗ . On the other hand, if μ = β ∗ , p < q + 1 , and Ω is an N-ball, then Theorem 1.8 yields u ≡ k φ p for some k > 0 . Since u is a solution of (3.3), we see that u must also be an eigenfunction of the q-Laplacian associated with the eigenvalue β ∗ , which is impossible in view of [22, Proposition 13].□

Note that Theorem 3.2 is optimal for the considered range of p and q in the sense that for any μ ∈ ( λ 1 ( q ) , β ∗ ) problem (3.3) possesses a positive solution, see [22, Theorem 2.5 (i)]. Nevertheless, we are not aware of the corresponding existence result for μ = β ∗ under assumption (i) of Theorem 3.2, or if p = q + 1 and Ω is an N-ball.

Second, we provide the following general result without restrictions on p and q apart from the default assumption 1 < q < p , whose proof is based on a nontrivial application of Picone’s inequalities (1.3) and (1.4), and on the usage of results from [5,22].

Theorem 3.3

Let

μ ˜ ≔ sup μ ∈ ℝ : ( 3.3 ) h a s a p o s i t i v e s o l u t i o n .

Then β ∗ ≤ μ ˜ < + ∞ . Moreover, (3.3) has at least one positive solution if λ 1 ( q ) < μ < μ ˜ , and no positive solution if μ ≤ λ 1 ( q ) or μ > μ ˜ . Furthermore, if μ ˜ > β ∗ , then (3.3) has at least one positive solution if and only if λ 1 ( q ) < μ ≤ μ ˜ .

In order to prove Theorem 3.3, we need the following auxiliary information on the behaviour of positive solutions.

Proposition 3.4

Let { μ n } ⊂ ℝ be a sequence, and let u n be a positive solution of (3.3) with μ = μ n , n ∈ ℕ . Then the following assertions hold:

if lim n → + ∞ ∥ ∇ u n ∥ p = + ∞ , then lim n → + ∞ μ n = β ∗ and, up to a subsequence,
(3.4) v n ≔ u n ∥ ∇ u n ∥ p → φ p i n C 0 1 ( Ω ¯ ) a s n → + ∞ ;
if lim n → + ∞ ∥ ∇ u n ∥ p = 0 , then lim n → + ∞ μ n = λ 1 ( q ) .

Proof

We start with the observation that (3.3) has no nonzero solution for μ ≤ λ 1 ( q ) , see [5, Proposition 1] and [22, Proposition 13]. Thus, throughout the proof, we will assume that μ n > λ 1 ( q ) for all n ∈ ℕ . In particular, we have lim inf n → + ∞ μ n ≥ λ 1 ( q ) .

Let ∥ ∇ u n ∥ p → + ∞ as n → + ∞ . Note first that lim inf n → + ∞ μ n > λ 1 ( q ) . Indeed, suppose, by contradiction, that μ n → λ 1 ( q ) , up to a subsequence. Setting v n = u n ∥ ∇ u n ∥ p and taking u n as a test function for (3.3) with μ = μ n , we have
1 − λ 1 ( p ) ∫ Ω v n p d x = ∥ ∇ u n ∥ p q − p μ n ∫ Ω v n q d x − ∫ Ω | ∇ v n | q d x ≥ 0 ,
where the inequality follows from the definition of λ 1 ( p ) . Since q < p , ∥ ∇ u n ∥ p → + ∞ , and μ n → λ 1 ( q ) , we conclude that, simultaneously, v n → φ p and v n → k φ q strongly in L q ( Ω ) , up to a subsequence, where k > 0 is some constant. However, this contradicts the linear independence of φ p and φ q , see [22, Proposition 13], and hence lim inf n → + ∞ μ n > λ 1 ( q ) .

Now we prove the convergence (3.4). Let v 0 ∈ W 0 1 , p ( Ω ) be such that v n → v 0 weakly in W 0 1 , p ( Ω ) and strongly in L p ( Ω ) , up to a subsequence. First, we show that v 0 ≡ 0 in Ω . Suppose, by contradiction, that v 0 ≡ 0 in Ω . Then, by Egorov’s theorem, v n converges to 0 uniformly on a subset of Ω of positive measure. In particular, we have
(3.5) ∫ Ω v n q − p φ q p d x → + ∞ as n → + ∞ .
Note that the integral in (3.5) is well-defined since φ q v n ∈ L ∞ ( Ω ) due to the int C 0 1 ( Ω ¯ ) + -regularity of v n and φ q . Using now the Picone inequalities (1.1) and (1.5), we get from (3.3) with μ = μ n and the test function φ q p u n p − 1 ∈ W 0 1 , p ( Ω ) that
(3.6) λ 1 ( p ) ∫ Ω φ q p d x + μ n ∫ Ω u n q − p φ q p d x = ∫ Ω | ∇ u n | p − 2 ∇ u n ∇ φ q p u n p − 1 d x + ∫ Ω | ∇ u n | q − 2 ∇ u n ∇ φ q p u n p − 1 d x ≤ ∫ Ω | ∇ φ q | p d x + ∫ Ω | ∇ φ q | q − 2 ∇ φ q ∇ φ q p − q + 1 u n p − q d x = ∫ Ω | ∇ φ q | p d x + λ 1 ( q ) ∫ Ω u n q − p φ q p d x .
This implies that
(3.7) ( μ n − λ 1 ( q ) ) ∫ Ω u n q − p φ q p d x ≤ ∫ Ω | ∇ φ q | p d x − λ 1 ( p ) ∫ Ω φ q p d x < + ∞ ,
and hence, since lim inf n → + ∞ μ n > λ 1 ( q ) , there exists a constant C > 0 independent of n such that
(3.8) μ n ∫ Ω v n q − p φ q p d x ≤ C ∥ ∇ u n ∥ p p − q .
On the other hand, choosing u n as a test function for (3.3) with μ = μ n , we get
μ n ∫ Ω v n q d x − ∫ Ω | ∇ v n | q d x = ∥ ∇ u n ∥ p p − q 1 − λ 1 ( p ) ∫ Ω v n p d x .
Since we suppose that v 0 ≡ 0 in Ω , we have v n → 0 strongly in L p ( Ω ) and L q ( Ω ) , which yields
(3.9) 2 μ n ∫ Ω v n q d x ≥ ∥ ∇ u n ∥ p p − q for sufficiently large n ∈ ℕ .
Combining (3.8) and (3.9), we obtain
2 C ∫ Ω v n q d x ≥ ∫ Ω v n q − p φ q p d x for sufficiently large n ∈ ℕ ,
which gives a contradiction to (3.5) and the strong convergence v n → 0 in L q ( Ω ) . Therefore, v 0 ≢ 0 in Ω .

Second, we show that v 0 = φ p . Since u n is a solution of (3.3) with μ = μ n , we see that v n satisfies
(3.10) ∫ Ω | ∇ v n | p − 2 ∇ v n ∇ φ d x + 1 ∥ ∇ u n ∥ p p − q ∫ Ω | ∇ v n | q − 2 ∇ v n ∇ φ d x = λ 1 ( p ) ∫ Ω v n p − 1 φ d x + μ n ∥ ∇ u n ∥ p p − q ∫ Ω v n q − 1 φ d x for any φ ∈ W 0 1 , p ( Ω ) .
Taking φ = v n and recalling that ∥ ∇ v n ∥ p = 1 and that v n converges in L p ( Ω ) to a nonzero function v 0 , we conclude that there exists a constant B ≥ 0 such that
B n ≔ μ n ∥ ∇ u n ∥ p p − q → B as n → + ∞ .
Taking now φ = v n − v 0 in (3.10), we see that the boundedness of B n implies
lim n → + ∞ ∫ Ω | ∇ v n | p − 2 ∇ v n ( ∇ v n − ∇ v 0 ) d x = 0 ,
which guarantees that v n → v 0 strongly in W 0 1 , p ( Ω ) , see, e.g., [26, Lemma 5.9.14]. Passing to the limit in (3.10), we deduce that v 0 is a nonzero and nonnegative solution of the problem
− Δ p u = λ 1 ( p ) | u | p − 2 u + B | u | q − 2 u in Ω , u = 0 on ∂ Ω .
The standard regularity result [27] and the strong maximum principle yield v 0 ∈ int C 0 1 ( Ω ¯ ) + , and so φ p p v 0 p − 1 ∈ W 0 1 , p ( Ω ) . Thus, applying the Picone inequality (1.1), we get
λ 1 ( p ) ∫ Ω φ p p d x + B ∫ Ω v 0 q − p φ p p d x = ∫ Ω | ∇ v 0 | p − 2 ∇ v 0 ∇ φ p p v 0 p − 1 d x ≤ ∫ Ω | ∇ φ p | p d x = λ 1 ( p ) ∫ Ω φ p p d x ,
which yields B = 0 , and hence v 0 ≡ φ p in Ω .

Now we are ready to prove that v n → φ p in C 0 1 ( Ω ¯ ) . Thanks to the boundedness of B n , using the Moser iteration process in (3.10), we can find M 1 > 0 independent of n such that ∥ v n ∥ ∞ ≤ M 1 for all n. Thus, since 1 / ∥ ∇ u n ∥ p p − q is also bounded, applying to Eq. (3.10) the regularity results [28, Theorem 1.7] and [27], we derive the existence of θ ∈ ( 0 , 1 ) and M 2 > 0 , both independent of n, such that v n ∈ C 0 1 , θ ( Ω ¯ ) and ∥ v n ∥ C 0 1 , θ ( Ω ¯ ) ≤ M 2 for every sufficiently large n. Since C 0 1 , θ ( Ω ¯ ) is compactly embedded into C 0 1 ( Ω ¯ ) , we conclude that v n → φ p in C 0 1 ( Ω ¯ ) , up to a subsequence.

Finally, let us show that lim n → + ∞ μ n = β ∗ . First, let { μ n k } be a subsequence such that lim k → + ∞ μ n k = lim inf n → + ∞ μ n . Taking u n k as a test function for (3.3) with μ = μ n k , we get
μ n k ∫ Ω v n k q d x − ∫ Ω | ∇ v n k | q d x = ∥ ∇ u n k ∥ p p − q 1 − λ 1 ( p ) ∫ Ω v n k p d x ≥ 0 ,
and hence the convergence of v n k to φ p along a sub-subsequence yields
lim inf n → + ∞ μ n ≥ ∫ Ω | ∇ φ p | q d x ∫ Ω φ p q d x = β ∗ .
Second, we choose a subsequence { μ n k } such that lim k → + ∞ μ n k = lim sup n → + ∞ μ n and denote it, for simplicity, as { μ k } . Using Picone’s inequalities (1.1) and (1.5) with v = φ p , we get from (3.3) with μ = μ k that
λ 1 ( p ) ∫ Ω φ p p d x + μ k ∫ Ω u k q − p φ p p d x = ∫ Ω | ∇ u k | p − 2 ∇ u k ∇ φ p p u k p − 1 d x + ∫ Ω | ∇ u k | q − 2 ∇ u k ∇ φ p p u k p − 1 d x ≤ ∫ Ω | ∇ φ p | p d x + ∫ Ω | ∇ φ p | q − 2 ∇ φ p ∇ φ p p − q + 1 u k p − q d x ,
which implies that
(3.11) μ k ∫ Ω u k q − p φ p p d x ≤ ∫ Ω | ∇ φ p | q − 2 ∇ φ p ∇ φ p p − q + 1 u k p − q d x .
Note that both sides of (3.11) share the same homogeneity with respect to u k , and hence we can replace u k by the normalized function v k :
(3.12) μ k ∫ Ω v k q − p φ p p d x ≤ ∫ Ω | ∇ φ p | q − 2 ∇ φ p ∇ φ p p − q + 1 v k p − q d x .
The convergence v k → φ p in C 0 1 ( Ω ¯ ) along a sub-subsequence yields the existence of a constant C > 0 such that φ p ( x ) ≤ C v k ( x ) for all x ∈ Ω and all sufficiently large k ∈ ℕ . Therefore, since 0 < φ p v k ≤ C in Ω , and φ p v k → 1 pointwise in Ω , the Lebesgue dominated convergence theorem guarantees
∫ Ω v k q − p φ p p d x → ∫ Ω φ p q d x and ∫ Ω | ∇ φ p | q − 2 ∇ φ p ∇ φ p p − q + 1 v k p − q d x → ∫ Ω | ∇ φ p | q d x .
Here, the latter convergence can be easily seen from the expansion
∫ Ω | ∇ φ p | q − 2 ∇ φ p ∇ φ p p − q + 1 v k p − q d x = ( p − q + 1 ) ∫ Ω | ∇ φ p | q φ p v k p − q d x − ( p − q ) ∫ Ω | ∇ φ p | q − 2 ∇ φ p ∇ v k φ p v k p − q + 1 d x .
Thus, letting k → + ∞ in (3.12), we obtain
lim sup n → + ∞ μ n = lim k → + ∞ μ k ≤ ∫ Ω | ∇ φ p | q d x ∫ Ω φ p q d x = β ∗ .
Consequently, the proof of assertion (i) is complete.
Let ∥ ∇ u n ∥ p → 0 as n → + ∞ . This implies that u n → 0 a.e. in Ω . Consequently, by Egorov’s theorem, u n → 0 uniformly on some subset of Ω of positive measure, which yields

∫ Ω u n q − p φ q p d x → + ∞ as n → + ∞ .

Thus, using the Picone inequalities (1.1) and (1.5) as in (3.6), we get (3.7):

( μ n − λ 1 ( q ) ) ∫ Ω u n q − p φ q p d x ≤ ∫ Ω | ∇ φ q | p d x − λ 1 ( p ) ∫ Ω φ q p d x < + ∞ ,

and therefore lim sup n → + ∞ μ n ≤ λ 1 ( q ) . Recalling now that lim inf n → + ∞ μ n ≥ λ 1 ( q ) , we finish the proof of assertion (ii).□

Proof of Theorem 3.3

First, we recall that (3.3) has a positive solution if μ ∈ ( λ 1 ( q ) , β ∗ ) , see [22, Theorem 2.5 (i)]. Therefore, μ ˜ ≥ β ∗ . Let { μ n } be a sequence convergent to μ ˜ such that (3.3) with μ = μ n has a positive solution u n . Fixing any v ∈ C 0 1 ( Ω ¯ ) and applying Picone’s inequalities (1.3) and (1.1), we get from (3.3) with μ = μ n that

(3.13) λ 1 ( p ) ∫ Ω u n p − q v q d x + μ n ∫ Ω v q d x = ∫ Ω | ∇ u n | p − 2 ∇ u n ∇ v q u n q − 1 d x + ∫ Ω | ∇ u n | q − 2 ∇ u n ∇ v q u n q − 1 d x ≤ q p ∫ Ω | ∇ v | p d x + p − q p ∫ Ω | ∇ u n | p d x + ∫ Ω | ∇ v | q d x .

If we suppose that μ ˜ = + ∞ , then Proposition 3.4(i) guarantees the boundedness of ∥ ∇ u n ∥ p , whence we get a contradiction to (3.13). Thus, μ ˜ < + ∞ .

By the definition of μ ˜ , (3.3) has no positive solution for any μ > μ ˜ . Moreover, there is no nonzero solution if μ ≤ λ 1 ( q ) , see [5, Proposition 1] and [22, Proposition 13]. Furthermore, [5, Theorem 2.2(i)] implies that (3.3) has at least one positive solution for any μ ∈ ( λ 1 ( q ) , μ ˜ ) .

It remains to prove that if μ ˜ > β ∗ , then (3.3) with μ = μ ˜ possesses a positive solution. Choose a sequence { μ n } such that μ n → μ ˜ and (3.3) with μ = μ n has a positive solution u n . Proposition 3.4(i) guarantees the boundedness of ∥ ∇ u n ∥ p . So, we may assume, by passing to a subsequence, that u n converges to some nonnegative function u 0 weakly in W 0 1 , p ( Ω ) and strongly in L p ( Ω ) . Letting n → + ∞ in

∫ Ω | ∇ u n | p − 2 ∇ u n ∇ ( u n − u 0 ) d x + ∫ Ω | ∇ u n | q − 2 ∇ u n ∇ ( u n − u 0 ) d x = λ 1 ( p ) ∫ Ω u n p − 1 ( u n − u 0 ) d x + μ n ∫ Ω u n q − 1 ( u n − u 0 ) d x ,

we get

lim n → + ∞ ∫ Ω | ∇ u n | p − 2 ∇ u n ( ∇ u n − ∇ u 0 ) d x + ∫ Ω | ∇ u n | q − 2 ∇ u n ( ∇ u n − ∇ u 0 ) d x = 0 ,

which yields the strong convergence u n → u 0 in W 0 1 , p ( Ω ) , see [22, Remark 3.5]. At the same time, since μ ˜ > β ∗ > λ 1 ( q ) , Proposition 3.4(ii) gives ∥ ∇ u 0 ∥ p = lim n → + ∞ ∥ ∇ u n ∥ p > 0 , and hence u 0 is nonzero. Thus, u 0 is a positive solution of (3.3) with μ = μ ˜ .□

Acknowledgements

V. Bobkov was supported by the project LO1506 of the Czech Ministry of Education, Youth and Sports, and by the grant 18-03253S of the Grant Agency of the Czech Republic. M. Tanaka was supported by JSPS KAKENHI Grant Number JP 19K03591. The authors would like to thank the anonymous reviewers whose comments and suggestions helped to improve and clarify the manuscript.

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Received: 2020-04-06

Revised: 2020-06-23

Accepted: 2020-07-24

Published Online: 2020-09-30

This work is licensed under the Creative Commons Attribution 4.0 International License.

Articles in the same Issue

https://doi.org/10.1515/math-2020-0065

Keywords for this article

Picone inequality; Picone identity; (p,q)-Laplacian; nonexistence; positive solutions

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