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Analysis and numerical simulation of fractional-order blood alcohol model with singular and non-singular kernels

  • Amit Prakash , Neha Kalyan and Sanjeev Ahuja EMAIL logo
Published/Copyright: April 8, 2024

Abstract

In this manuscript, we examine the blood alcohol model to investigate the dynamics of alcohol concentration in the human body. The classical model of blood alcohol concentration is converted into the fractional model by using Caputo, Caputo-Fabrizio (CF), and Atangana-Baleanu-Caputo derivatives. The existence and uniqueness theory for the model’s solution is constructed using the Banach fixed point theory. Also, the stability of the solution is established by Ulam-Hyers conditions. For the numerical simulation of the considered model, the Adams-Bashforth method with a two-step Lagrange polynomial is used and the numerical solution of the model with three different derivatives is presented in the tabular and graphical form. The comparison between the exact solution and observed solution is made by root mean square technique which is found to be in good agreement. Finally, the results from the three fractional derivatives are also compared with the exact data, which revealed that the CF fractional derivative performs better than the other two fractional derivatives.

MSC 2010: 26A33; 65L99; 34A08

1 Introduction

Fractional calculus is an area of applied mathematics concerned with fractional-order derivatives and integrals. Real-world situations involving fractional calculus can capture the physical description of the concept better than classical calculus. Due to numerous important applications in science and engineering, non-integer-order (fractional) derivatives have caught the interest of many scientists. Fractional differential equations [22,27] have been used to model a variety of engineering and physical phenomena. The fractional-order models have received a lot of attention recently since they are more accurate and realistic than classical-order models. The classical- or integer-order derivatives are local in nature, i.e., it does not capture the model’s entire memory, whereas non-integer derivatives carry their present as well as past information [35]. Several researchers have utilized these fractional derivatives to solve various problems with different techniques such as homotopy analysis transform technique (HATM) [36,37], conformable fractional differential transform method [43], q-homotopy analysis transform method [28,30], iterative method [38,39], and fractional variational iteration method [20], homotopy perturbation transform method [18].

Alcohol is a poisonous and intoxicating substance that can cause addiction. In today’s societies, many people use alcoholic beverages on a regular basis. The liver uses enzymes to metabolize alcohol. In contrast, the liver can process a little amount of alcohol at one time, enabling the excess to spread all over the body. Alcohol has an effect on all of the body’s organs. The effect of alcohol on the human body depends on the amount consumed. According to the World Health Organization [25], worldwide, 3 million people die every year from unhealthy alcohol usage, accounting for 5.3% of all deaths. Harmful alcohol usage has been connected to more than 200 diseases and injuries. Alcohol is responsible for 13.5% of all deaths in the 20- to 39-year-old age group. At first, Ludwin [24] solves a set of differential equations that describe blood alcohol concentration as a function of time given as

(1) d S d t = k 1 S ( t ) , d B d t = k 1 S ( t ) k 2 B ( t ) .

The exact solution for the classical blood alcohol model by direct integration of the system of equation (1) is given in Table 1.

Table 1

Exact data for blood alcohol levels [24]

Time (min) Blood alcohol level (mg/L)
0 0
10 147.54
20 172.95
30 161.38
45 129.99
80 70.99
90 59.49
110 41.74
170 14.41

Now, we generalize the integer-order differential equations of the considered model into the fractional differential equations as the fractional model more appropriately represents the system because of its additional remembrance and inheritance qualities, which make it particularly effective in replicating and analyzing real occurrences. This is primarily due to two factors: (a) it is possible to choose any arbitrary order of fractional operators, whereas this is not possible with standard order derivatives, and (b) because classical-order derivatives are local in nature, they do not describe the entire memory and physical aspects of the model, whereas fractional-order derivatives are non-local in nature and thus describe the entire memory and physical behavior of the system. So, we convert the blood alcohol model into the fractional version by using three fractional operators:

  1. Caputo differential operator:

    (2) D t α 0 C S ( t ) = k 1 S ( t ) , D t α 0 C B ( t ) = k 1 S ( t ) k 2 B ( t ) .

  2. Caputo-Fabrizio (CF) differential operator:

    (3) D t α 0 CF ( t ) = k 1 S ( t ) , D t α 0 CF B ( t ) = k 1 S ( t ) k 2 B ( t ) .

  3. Atangana-Baleanu-Caputo (ABC) differential operator:

    (4) D t α 0 ABC S ( t ) = k 1 S ( t ) , D t α 0 ABC B ( t ) = k 1 S ( t ) k 2 B ( t ) ,

subject to the initial conditions:

S ( 0 ) = S 0 , B ( 0 ) = B 0 = 0 ,

where S ( t ) represents the alcohol concentration (mg/L) at time t (min) in the stomach, B ( t ) represents the alcohol concentration (mg/L) at time t (min) in the blood, k 1 is the first constant of rate law and k 2 is the second constant of rate law, and S 0 and B 0 represents the initial alcohol concentration in the stomach and blood, respectively.

Because of the serious consequences on human life, alcohol addiction has caught the interest of many scholars and researchers from a wide range of fields: Almeida et al. [4] compared the integer- and fractional-order modeling approaches to some real-world problems including the blood alcohol concentration problem with real data and found that the fractional-order equation more accurately describes the model’s dynamics. Singh [35] studied the blood alcohol model with the Sumudu transform via the Hilfer fractional operator. Qureshi et al. [32] investigated the fractional blood ethanol model with Caputo, CF, and ABC derivatives, and for the solution, the Laplace transform is used. The Caputo and ABC derivative operators outperform the standard order model in estimating real data; however, the CF operator produces the same results as the original integer-order model. Bunonyo and Amadi [13] studied the movement of alcohol in the gastrointestinal tract and bloodstream, as well as its impact on the human body.

In this article, we solve a set of differential equations of the blood alcohol model. To calculate an approximate fractional solution of the considered problem, the two-step Adams-Bashforth numerical method with Lagrange polynomial is used. Several researchers have successfully used the Adams-Bashforth method (ABM) to solve fractional differential equations such as the time fractional Tricomi equation [21], stem cell differentiation [40], the tumor dynamics model [5], the predator-prey problem [26], and Influenza A epidemic model [17]. Several fractional derivatives including Riemann-Liouville, Caputo, Riesz, Grunwald-Letnikov, CF, and ABC have been developed in the literature. In this work, we utilize Caputo, CF, and ABC to solve the proposed problem. The Caputo fractional derivative uses a power law kernel, which is singular whereas CF and ABC fractional derivatives use the exponential kernel and the Mittag-Leffler kernel, respectively, which are non-singular kernels. These fractional derivatives have been used by many researchers for solving linear and non-linear problems [3,6,7,912,14,19,23,29,31,34,42]. Also, the existence and uniqueness for the solution are done by fixed point theory, and Ulam-Hyers (UH) stability is discussed, which is widely investigated by numerous researchers [16,41,46,47].

This article is organized in various sections as follows: in Section 1, we present the introduction and description of the model used in this study. In Section 2, important definitions that are used in this article are given. Section 3 includes the existence and uniqueness conditions for the solution of the problem. In Section 4, stability conditions are constructed for the solution of the considered model. In Section 5, the numerical algorithm for the solution of the blood alcohol model is constructed using the two-step ABM. In Section 6, numerical simulation, a graphical representation of the solution of the fractional blood alcohol model via MATLAB-21 software, and a comparison between the experimental data and data obtained by this study are presented. Finally, Section 7 contains the conclusion.

2 Mathematical preliminaries

The fractional derivatives and integrals of Caputo, CF, and ABC are provided in this section as follows:

Definition 2.1

The fractional-order derivative of the function f ( t ) in the Caputo sense with order α > 0 , where m 1 α m , m N , is given as [27]

D t α 0 C [ f ( t ) ] = 1 Γ ( m α ) 0 t ( t τ ) m α 1 f m ( τ ) d τ .

Definition 2.2

The fractional integration of the function f ( t ) in the Caputo sense with order α > 0 , where m 1 α m , m N , is given as [27]

I t α 0 C [ f ( t ) ] = 1 Γ ( α ) 0 t ( t τ ) α 1 f ( τ ) d τ .

Definition 2.3

The CF derivative of the function f ( t ) of order α > 0 is defined as [15]

D t α 0 CF f ( t ) = M ( α ) 1 α 0 t e α 1 α ( t τ ) d d τ [ f ( τ ) ] d τ ,

where M ( α ) is the normalization function that satisfies M ( 0 ) = M ( 1 ) = 1 , f H 1 ( 0 , 1 ) , and α ( 0 , 1 ] .

Definition 2.4

Integration of a function f ( t ) in CF sense of order α > 0 is defined as [15]

I t α 0 CF f ( t ) = 1 α M ( α ) f ( τ ) + α M ( α ) 0 t f ( τ ) d τ .

Definition 2.5

The fractional-order derivative of f ( t ) in ABC sense with order α > 0 is given by [8]

D t α 0 ABC f ( t ) = ABC ( α ) 1 α 0 t E α α 1 α ( t τ ) α d d τ [ f ( τ ) ] d τ ,

where ABC ( α ) = α 2 α is the normalization function, and E α is the “Mittag-Leffler function” given as

E α ( y ) = k = 0 y k Γ ( α k + 1 ) .

Definition 2.6

The fractional integration of the function f ( t ) in the ABC sense with order α > 0 is given by [8]

I t α 0 ABC f ( t ) = 1 α ABC ( α ) f ( t ) + α ABC ( α ) Γ ( α ) 0 t ( t τ ) α 1 f ( τ ) d τ .

3 Existence and uniqueness of solution

In this section, we prove the existence and uniqueness for the solution of the considered model with three fractional derivatives. For this purpose, we first take system (2) of differential equations with Caputo fractional operator, and for the existence of the solution, we define a Banach space ξ = ψ × ψ , where ψ = C ( ζ ) under the norm U = max t ζ [ S ( t ) + B ( t ) ] = ( S , B ) , where ζ = [ 0 , T ] , and U = ( S , B ) ξ .

Let us express the right-hand side of the proposed model as

(5) f 1 ( t , S , B ) = k 1 S ( t ) , f 2 ( t , S , B ) = k 1 S ( t ) k 2 B ( t ) .

So, Problem (2) can be written as

(6) D t α 0 C S ( t ) = f 1 ( t , S , B ) , D t α 0 C B ( t ) = f 2 ( t , S , B ) .

We can write this equation in the vector form as

(7) D t α 0 C U ( t ) = F ( t , U ( t ) ) , 0 < α 1 ,

U ( 0 ) = U 0 ,

where

(8) U ( t ) = S ( t ) B ( t ) , U 0 = S 0 B 0 , F ( t , U ( t ) ) = f 1 ( t , S , B ) f 2 ( t , S , B ) .

By integrating both sides of the (7), we obtain

(9) U ( t ) = U 0 + 1 Γ ( α ) 0 t F ( τ , U ( τ ) ) ( t τ ) α 1 d τ .

Let J : ξ ξ be an operator, which is defined by

(10) J ( U ) ( t ) = U 0 + 1 Γ ( α ) 0 t F ( τ , U ( τ ) ) ( t τ ) α 1 d τ .

We use the following theorems and hypotheses to prove the existence and uniqueness of the solution of Model (2):

Theorem 3.1

[2] Let J : ξ ξ be a completely continuous operator, and let

D ( J ) = { U ξ : U = λ J ( U ) , λ [ 0 , 1 ] }

be bounded. Then, there exists at least one fixed point of J in ξ .

Hypothesis (A). There exists a constant L > 0 such that for U , U ¯ ξ , we have

F ( t , U ( t ) ) F ( t , U ¯ ( t ) ) L U ( t ) U ( t ) ¯ .

For simplicity, we use the following notation:

Δ = T α Γ ( α + 1 ) .

Proof

To prove that the operator J is completely continuous. Let us take a sequence { U n } such that U n U in ξ , then for any t ζ , we have

J ( U n ) J ( U ) 1 Γ ( α ) max t ζ 0 t F ( τ , U n ( τ ) ) F ( τ , U ( τ ) ) ( t τ ) α 1 d τ , L Γ ( α ) U n U max t ζ 0 1 t α ( 1 z ) α 1 d z , L T α Γ ( α ) U n U max t ζ 0 1 ( 1 z ) α 1 d z , L T α α Γ ( α ) U n U , L T α Γ ( α + 1 ) U n U , L Δ U n U .

Since sequence U n U , J ( U n ) J ( U ) 0 as n 0 . Thus, the operator J is continuous.

Suppose S ξ is a bounded set. Then, F ( t , U ( t ) ) C , C > 0 , U S .

Then, for each U S , we obtain

J ( U ) C Γ ( α ) max t ζ 0 t ( t τ ) α 1 d τ , C T α α Γ ( α ) , C Δ .

Hence, the operator J is uniformly bounded.

Now, take 0 t 2 t 1 T , then

J ( U ) ( t 1 ) J ( U ) ( t 2 ) C Γ ( α ) max t ζ 0 t 1 ( t 1 τ ) α 1 d τ 0 t 2 ( t 2 τ ) α 1 d τ , C Γ ( α ) max t ζ 0 t 1 ( t 1 τ ) α 1 d τ 0 t 2 ( t 2 τ ) α 1 d τ , C α Γ ( α ) ( t 1 α t 2 α ) 0 , as t 1 t 2 .

Hence, J is equicontinuous. Also, J is bounded and continuous, so relatively compact, and thus, J is completely continuous.

Now, we prove that D is a bounded set.

Let us take U D , then for any t ζ , we have

U ( t ) = λ J ( U ( t ) ) λ C Δ .

Therefore, D is bounded. Hence, with the use of Theorem 3.1, Model (2) has at least one solution.□

Theorem 3.2

[2] Problem (2) has a unique solution if we assume hypothesis (A) and Θ < 1 , where

Θ = Δ L .

Proof

For U , U ¯ ξ and each t ζ , we can obtain

(11) J ( U ) J ( U ¯ ) 1 Γ ( α ) max t ζ 0 t F ( τ , U ( τ ) ) ( t τ ) α 1 d τ 0 t F ( τ , U ¯ ( τ ) ) ( t τ ) α 1 d τ , Δ L U U ¯ , Θ U U ¯ .

Hence, J has a contraction. This shows that Problem (2) has a unique solution.□

Using a similar technique, we can prove the existence and uniqueness of the solution for the blood alcohol model with CF and ABC fractional operators [44,45].

4 Stability analysis

In this section, we prove the stability for the solution of the system of differential equations (2) using UH stability analysis technique.

For UH-stability, take a small perturbation Q C ( ζ ) ; Q ( 0 ) = 0 , and

  1. Q ( t ) ε , for ε > 0 ,

  2. D t α 0 C U ( t ) = F ( t , U ( t ) ) + Q ( t ) .

Lemma 4.1

The solution for the following problem:

(12) D t α 0 C U ( t ) = F ( t , U ( t ) ) + Q ( t ) , U ( 0 ) = U 0 ,

satisfies the relation given as

(13) U ( t ) U 0 + 1 Γ ( α ) 0 t F ( τ , U ( τ ) ) ( t τ ) α 1 d τ Δ ε .

Proof

Using equation (9), we obtain the solution for Problem (12) as:

(14) U ( t ) = U 0 + 1 Γ ( α ) 0 t ( F ( τ , U ( τ ) ) + Q ( τ ) ) ( t τ ) α 1 d τ .

Using the relation Q ( t ) ε in equation (14), we can easily obtain Relation (13).□

Theorem 4.1

[1] Let us suppose the hypothesis (A) and Relation (11) hold. Also, Θ < 1 , where Θ = Δ L . Then, the solution of Problem (2) is UH stable.

Proof

Let W be a unique solution of equation (9) and U be any solution of equation (9), then

U ( t ) W ( t ) = U ( t ) W 0 + 1 Γ ( α ) 0 t F ( τ , W ( τ ) ) ( t τ ) α 1 d τ , U ( t ) U 0 + 1 Γ ( α ) 0 t F ( τ , U ( τ ) ) ( t τ ) α 1 d τ + U 0 + 1 Γ ( α ) 0 t F ( τ , U ( τ ) ) ( t τ ) α 1 d τ W 0 + 1 Γ ( α ) 0 t F ( τ , W ( τ ) ) ( t τ ) α 1 d τ .

Using equations (11) and (13), we obtain

U ( t ) W ( t ) Δ ε + Θ U W .

Therefore, we can write

(15) U W P ,

where P = Δ ε 1 Θ . Thus, from (15), we conclude that Problem (2) is UH stable.□

Similarly, we can prove the stability of the blood alcohol model with CF and ABC fractional operators [33,47].

5 Numerical algorithm

In this section, the numerical algorithm for the solution of the blood alcohol model with three different fractional derivatives is constructed using the fractional two-step ABM.

5.1 Numerical solution of blood alcohol model in the sense of Caputo fractional derivative

Now, we evaluate the numerical solution of Model (2). For this, let us take the first equation of System (2) with the initial condition as

(16) D t α 0 C S ( t ) = f 1 ( t , S , B ) , S ( 0 ) = S 0 .

By integration, the solution of equation (16) is given by

(17) S ( t ) = S 0 + 1 Γ ( α ) 0 t f 1 ( τ , S , B ) ( t τ ) α 1 d τ .

Now, we develop the numerical algorithm for the considered system using t i + 1 in place of t in equation (17), we obtain

S i + 1 = S 0 + 1 Γ ( α ) 0 t i + 1 f 1 ( τ , S , B ) ( t i + 1 τ ) α 1 d τ .

Then, by approximating the above obtained integral, we obtain

(18) S i + 1 = S 0 + 1 Γ ( α ) m = 0 i t m t m + 1 f 1 ( τ , S , B ) ( t i + 1 τ ) α 1 d τ .

Now, using the two-step Lagrange polynomial, one can write over [ t m , t m + 1 ] the function f 1 ( τ , S , B ) with h = t m t m + 1 such that

(19) f 1 ( τ , S , B ) = 1 h [ ( τ t m 1 ) f 1 ( t m , S , B ) ( τ t m ) f 1 ( t m 1 , S , B ) ] .

By substituting equation (19) into equation (18), we have

(20) S i + 1 = S 0 + 1 Γ ( α ) m = 1 i t m t m + 1 1 h [ ( τ t m 1 ) f 1 ( t m , S , B ) ( t i + 1 τ ) α 1 ] [ ( τ t m ) f 1 ( t m 1 , S , B ) ] ( t i + 1 τ ) α 1 d τ .

After evaluating the integral of (20), we obtain the numerical solution for the first equation of the system (2) as:

(21) S i + 1 = S 0 + h α Γ ( α + 2 ) m = 1 i [ f 1 ( t m , S , B ) ( ( i + 1 m ) α ( i m + 2 + α ) ( i m ) α ( i m + 2 + 2 α ) ) f 1 ( t m 1 , S , B ) ( ( i + 1 m ) α + 1 ( i m ) α ( i m + 1 + α ) ) ] .

Similarly, we can obtain the numerical solution of the second equation of System (2) as

(22) B i + 1 = B 0 + h α Γ ( α + 2 ) m = 1 i [ f 2 ( t m , S , B ) ( ( i + 1 m ) α ( i m + 2 + α ) ( i m ) α ( i m + 2 + 2 α ) ) f 2 ( t m 1 , S , B ) ( ( i + 1 m ) α + 1 ( i m ) α ( i m + 1 + α ) ) ] .

5.2 Numerical solution of blood alcohol model in the sense of CF fractional derivative

Now, to solve System (3), we take the first equation of System (3) with the initial condition as

(23) D t α 0 CF ( t ) = f 1 ( t , S , B ) , S ( 0 ) = S 0 .

By integrating in the CF sense, we obtain

(24) S ( t ) = S 0 + 1 α M ( α ) f 1 ( t , S , B ) + α M ( α ) 0 t f 1 ( τ , S , B ) d τ .

Now, we develop the numerical algorithm for the considered system using t i + 1 in place of t in equation (24), and we obtain

S i + 1 = S 0 + 1 α M ( α ) f 1 ( t i , S , B ) + α M ( α ) 0 t i + 1 f 1 ( τ , S , B ) d τ .

Then, by approximating the above obtained integral, we obtain

(25) S i + 1 = S 0 + 1 α M ( α ) f 1 ( t i , S , B ) + α M ( α ) m = 0 i t m t m + 1 f 1 ( τ , S , B ) d τ .

Now, using the two-step Lagrange polynomial for the function f 1 ( τ , S , B ) in the aforementioned equation, we obtain

(26) S i + 1 = S 0 + 1 α M ( α ) f 1 ( t i , S , B ) + α M ( α ) m = 1 i t m t m + 1 1 h [ ( τ t m 1 ) f 1 ( t m , S , B ) ( τ t m ) f 1 ( t m 1 , S , B ) ] d τ .

After evaluating the integral of (26), we obtain the numerical solution for the first equation of System (3) as

(27) S i + 1 = S 0 + 1 α M ( α ) f 1 ( t i , S , B ) + α h 2 M ( α ) m = 1 i [ 3 f 1 ( t m , S , B ) f 1 ( t m 1 , S , B ) ] .

Similarly, we can obtain the numerical solution of the second equation of System (3) as

(28) B i + 1 = B 0 + 1 α M ( α ) f 2 ( t i , S , B ) + α h 2 M ( α ) m = 1 i [ 3 f 2 ( t m , S , B ) f 2 ( t m 1 , S , B ) ] .

5.3 Numerical solution of blood alcohol model in the sense of ABC fractional derivative

Now, to find the solution for System (4), we take the first equation of the system with the initial condition as

(29) D t α 0 ABC S ( t ) = f 1 ( t , S , B ) , S ( 0 ) = S 0 .

By integrating in the Atangana-Baleanu sense, we obtain

(30) S ( t ) = S 0 + 1 α A B C ( α ) f 1 ( t , S , B ) + α A B C ( α ) Γ ( α ) 0 t f 1 ( τ , S , B ) ( t τ ) α 1 d τ .

Now, we develop the numerical algorithm for the considered system using t i + 1 in place of t in equation (30), we obtain

S i + 1 = S 0 + 1 α A B C ( α ) f 1 ( t i , S , B ) + α A B C ( α ) Γ ( α ) 0 t i + 1 f 1 ( τ , S , B ) ( t i + 1 τ ) α 1 d τ .

Then, by approximating the above obtained integral, we obtain

(31) S i + 1 = S 0 + 1 α A B C ( α ) f 1 ( t i , S , B ) + α A B C ( α ) Γ ( α ) m = 0 i t m t m + 1 f 1 ( τ , S , B ) ( t i + 1 τ ) α 1 d τ .

Now, using the two-step Lagrange polynomial for the function f 1 ( τ , S , B ) in the aforementioned equation, we obtain

(32) S i + 1 = S 0 + 1 α A B C ( α ) f 1 ( t i , S , B ) + α A B C ( α ) Γ ( α ) × m = 1 i t m t m + 1 1 h [ ( τ t m 1 ) f 1 ( t m , S , B ) ( τ t m ) f 1 ( t m 1 , S , B ) ] ( t i + 1 τ ) α 1 d τ .

After evaluating the integral of (32), we obtain the numerical solution for the first equation of System (4) as:

(33) S i + 1 = S 0 + 1 α ABC ( α ) f 1 ( t i , S , B ) + α h α ABC ( α ) Γ ( α + 2 ) × m = 1 i [ f 1 ( t m , S , B ) ( ( i + 1 m ) α ( i m + 2 + α ) ( i m ) α ( i m + 2 + 2 α ) ) f 1 ( t m 1 , S , B ) ( ( i + 1 m ) α + 1 ( i m ) α ( i m + 1 + α ) ) ] .

Similarly, we obtain the numerical solution of the second equation of System (4) as:

(34) B i + 1 = B 0 + 1 α A B C ( α ) f 2 ( t i , S , B ) + α h α A B C ( α ) Γ ( α + 2 ) × m = 1 i [ f 2 ( t m , S , B ) ( ( i + 1 m ) α ( i m + 2 + α ) ( i m ) α ( i m + 2 + 2 α ) ) f 2 ( t m 1 , S , B ) ( ( i + 1 m ) α + 1 ( i m ) α ( i m + 1 + α ) ) ] .

6 Numerical simulation and discussion

In this section, we present numerical simulations for the fractional derivatives with singular and non-singular kernels to demonstrate the adaptability and effectiveness of the suggested approach. We find the numerical solution of the concentrations of S ( t ) and B ( t ) at various orders of derivative values α with the two-step Adams-Bashforth approach. We have simulated the outcomes corresponding to the initial values and parameters values given in [24] as: S 0 = 245.8769 , B 0 = 0 , k 1 = 0.109456 , and k 2 = 0.017727 . We derive the numerical solution of Models (2), (3), and (4) with a step size of 0.01 and compare it with exact data (Table 1) by varying the order of derivative and present graphically.

Figure 1 represents the plots of alcohol concentration in the blood, and Figure 2 represents the plots of alcohol concentration in the stomach at different orders of derivatives with the use of Caputo fractional derivative, and the comparison of the obtained concentration in the blood with the exact data (Table 1) is given in Table 2. Figure 3 represents the plots of alcohol concentration in the blood, and Figure 4 represents the plots of alcohol concentration in the stomach at different orders of derivatives with the use of CF fractional derivative, and the comparison of the obtained concentration in the blood with the exact data is given in Table 3. Figure 5 represents the plots of alcohol concentration in the blood, and Figure 6 represents the plots of alcohol concentration in the stomach at different orders of derivatives with the use of ABC fractional derivative and the comparison of the obtained concentration in the blood with the exact data is given in Table 4. The comparison of the obtained solution with the exact solution at order of derivative 1 is shown in Table 5. Finally, the comparison of the solutions obtained via three different fractional derivatives (Caputo, C-F, and ABC) at order 0.98 with the exact solution is given in Table 6 and graphically in Figure 7.

Figure 1 
               Numerical solution of concentration of alcohol in the blood for distinct values of fractional order in Caputo sense.
Figure 1

Numerical solution of concentration of alcohol in the blood for distinct values of fractional order in Caputo sense.

Figure 2 
               Numerical solution of concentration of alcohol in the stomach for distinct values of fractional order in Caputo sense.
Figure 2

Numerical solution of concentration of alcohol in the stomach for distinct values of fractional order in Caputo sense.

Table 2

Numerical simulation of blood alcohol concentration at different orders of fractional derivative for h = 0.01

Time (min) Exact solution (mg/L) ABM via Caputo derivative
( α = 1 ) ( α = 0.95 ) ( α = 0.90 ) ( α = 0.85 )
0 0 0 0 0 0
10 147.54 147.4738 138.2144 129.2469 120.5841
20 172.95 172.9503 166.9093 159.6504 151.4678
30 161.38 161.3998 163.1713 162.0004 158.3290
45 129.99 130.0232 141.6989 149.3290 153.0784
80 70.99 71.0143 92.3180 110.9856 126.0763
90 59.49 59.5015 81.4995 101.5619 118.5125
110 41.74 41.7492 63.7829 85.2951 104.7590
170 14.41 14.4126 32.0424 52.5126 74.0149
Figure 3 
               Numerical solution of alcohol concentration in the blood for distinct values of fractional order in CF sense.
Figure 3

Numerical solution of alcohol concentration in the blood for distinct values of fractional order in CF sense.

Figure 4 
               Numerical solution of alcohol concentration in the stomach for distinct values of fractional order in CF sense.
Figure 4

Numerical solution of alcohol concentration in the stomach for distinct values of fractional order in CF sense.

Table 3

Numerical simulation of blood alcohol concentration at different orders of fractional derivative for h = 0.01

Time (min) Exact solution (mg/L) ABM via CF derivative
( α = 1 ) ( α = 0.95 ) ( α = 0.90 ) ( α = 0.85 )
0 0 0 0 0 0
10 147.54 147.4738 143.9327 140.1599 136.1480
20 172.95 172.9503 172.4876 171.6417 170.3714
30 161.38 161.3998 163.8521 166.0410 167.9077
45 129.99 130.0232 134.7196 139.4344 144.1239
80 70.99 71.0143 76.2304 81.8065 87.7594
90 59.49 59.5015 64.4616 69.8193 75.6019
110 41.74 41.7492 46.0576 50.8007 56.0202
170 14.41 14.4126 16.7839 19.5401 22.7428
Figure 5 
               Numerical solution of alcohol concentration in the blood for distinct values of fractional order in ABC sense.
Figure 5

Numerical solution of alcohol concentration in the blood for distinct values of fractional order in ABC sense.

Figure 6 
               Numerical solution of alcohol concentration in the stomach for distinct values of fractional order in ABC sense.
Figure 6

Numerical solution of alcohol concentration in the stomach for distinct values of fractional order in ABC sense.

Table 4

Numerical simulation of blood alcohol concentration at different orders of fractional derivative for h = 0.01

Time (min) Exact solution (mg/L) ABM via ABC derivative
( α = 1 ) ( α = 0.95 ) ( α = 0.90 ) ( α = 0.85 )
0 0 0 0 0 0
10 147.54 147.4738 134.7580 122.3870 110.5157
20 172.95 172.9503 165.7525 155.9312 144.2809
30 161.38 161.3998 164.4906 162.3382 155.8272
45 129.99 130.0232 145.3076 154.1171 156.5160
80 70.99 71.0143 97.2955 119.9231 136.8142
90 59.49 59.5015 86.4386 110.8435 130.2508
110 41.74 41.7492 68.4356 94.7477 117.7008
170 14.41 14.4126 35.3526 60.7350 87.3530
Table 5

Comparison of our method solution with the exact solution at order of derivative, α = 1

Time (min) Exact solution (mg/L) Our method solution
0 0 0
10 147.54 147.4738
20 172.95 172.9503
30 161.38 161.3998
45 129.99 130.0232
80 70.99 71.0143
90 59.49 59.5015
110 41.74 41.7492
170 14.41 14.4126
Table 6

Comparison of exact blood alcohol content data with data obtained by using three different types of derivatives with h = 0.01 and order of derivative, α = 0.98

Time (min) Exact solution (mg/L) Caputo derivative CF derivative ABC derivative
0 0 0 0 0
10 147.54 143.7359 146.0847 142.3574
20 172.95 170.7002 172.8087 170.4388
30 161.38 162.4889 162.4089 163.3129
45 129.99 135.1813 131.8972 136.8909
80 70.99 79.7794 73.0587 81.8079
90 59.49 68.4465 61.4396 70.4041
110 41.74 50.5203 43.4230 52.2713
170 14.41 21.0200 15.3185 22.0867
Figure 7 
               Comparison of the solutions with exact data at order of derivative 
                     
                        
                        
                           α
                           =
                           0.98
                        
                        \alpha =0.98
                     
                  .
Figure 7

Comparison of the solutions with exact data at order of derivative α = 0.98 .

The comparison between the obtained solution with the proposed method and the exact solution (from [24]) is made by calculating the root mean square error (RMSE) using equation (35) and is found to be 0.027, and the average accuracy of the numerical technique is found to be 99.9%.

(35) RMSE = i = 1 n ( e i o i ) 2 n ,

where e i and o i are the exact and observed values, respectively, and n is the number of values obtained. So, from the obtained results, we can say that the technique used is capable for solving such types of problems with great accuracy. Also, it is clear from the obtained results that the values obtained by the CF differential operator give values closer to the exact data as compared to the values obtained by Caputo and ABC operators in the case of fractional order, which is evidenced by Table 6. So, the CF operator gives satisfactory results as compared to Caputo and ABC operators.

7 Conclusion

In this article, we investigated the blood alcohol model using three different fractional derivative operators. First, we utilize the Banach fixed point theorem to construct the existence and uniqueness requirements for the solution of the considered model, and UH stability analysis is performed to show the stability of the method. The solution for the alcohol concentration in the blood and stomach has been discussed by applying the Adams-Bashforth approach. The graphical data for alcohol concentrations in the stomach and blood are given for distinct values of fractional derivatives. The comparison between the proposed technique and the exact solution is made by finding RMSE and found to be in good agreement. Also, the comparison of the solutions via three derivatives with exact data revealed that the CF operator shows better performance than the other two operators. Hence, we can conclude that ABM with the CF fractional derivative works quite well for mathematical modeling of real-world difficulties, as evidenced by the examination of the blood alcohol model.

Acknowledgements

We thank anonymous reviewers for their constructive suggestions that have helped to improve the quality of the article.

  1. Funding information: This research received no specific grant from any funding agency, commercial or non profit sector.

  2. Conflict of interest: The authors declare that there is no conflict of interest in this article.

  3. Ethics statement: This research did not require ethical approval.

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Received: 2023-11-30
Revised: 2024-02-16
Accepted: 2024-02-29
Published Online: 2024-04-08

© 2024 the author(s), published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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