Startseite Simpson, midpoint, and trapezoid-type inequalities for multiplicatively s-convex functions
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Simpson, midpoint, and trapezoid-type inequalities for multiplicatively s-convex functions

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Abstract

In this study, we establish new generalizations and results for Simpson, midpoint, and trapezoid-type integral inequalities within the framework of multiplicative calculus. We begin by proving a new identity for multiplicatively differentiable functions. Using this identity, we then obtain a new Simpson-type inequality for multiplicatively s -convex functions. Additionally, we derive novel integral inequalities related to the right and left sides of the Hermite-Hadamard inequality for multiplicatively s -convex functions. We also demonstrate that some of the results obtained here improve upon known results, while others are generalizations. Finally, we present some applications to special means.

MSC 2010: 26D07; 26D10; 26D15; 26A51

1 Introduction

Let I be an interval of real numbers. A function f : I R is said to be convex, if

(1) f ( t ϰ + ( 1 t ) y ) t f ( ϰ ) + ( 1 t ) f ( y )

holds for all ϰ , y I and all t [ 0 , 1 ] .

Convexity of functions is a powerful approach extensively employed to address various challenges in both pure and applied research. The application of convexity has led to the discovery of numerous extensions and generalizations of integral inequalities, along with their valuable applications [119]. Several studies have demonstrated that many of the results obtained concerning these inequalities are direct outcomes of the applications of convex functions. The Hermite-Hadamard inequality, which is a highly important mathematical inequality associated with convex functions, finds widespread application in numerous other fields of mathematics.

The theory of convexity is a fundamental aspect in various domains, such as mathematical finance, economics, engineering, management sciences, and optimization theory. Several studies have demonstrated that many of the results obtained concerning these inequalities are direct outcomes of the applications of convex functions. The Hermite-Hadamard inequality stands as one of the most renowned inequalities related to the integral mean of a convex function. This double inequality is expressed as follows (see, [2022]).

Theorem 1

Let f : I R R be a convex function and a , b I with a < b . Then,

(2) f a + b 2 1 b a a b ( f ( ϰ ) ) d ϰ f ( a ) + f ( b ) 2 .

Both inequalities hold in the reversed direction if ϒ is concave.

The Hermite-Hadamard inequality can be viewed as an enhancement of the concept of convexity. In recent times, several generalizations and extensions have been explored for classical convexity. Additionally, numerous investigations have been dedicated to establishing new bounds for both the left and right-hand sides of inequality (2). For some illustrative instances, please refer the monographs [2333].

The following inequality, identified as Simpson’s inequality, ranks among the most widely recognized outcomes in the literature.

Theorem 2

Let f : [ a , b ] R be a four times continuously differentiable mapping on ( a , b ) and f ( 4 ) = sup ϰ ( a , b ) f ( 4 ) ( ϰ ) < . Then, the following inequality holds:

(3) 1 3 f ( a ) + f ( b ) 2 + 2 f a + b 2 1 b a a b f ( ϰ ) d ϰ 1 2,880 f ( 4 ) ( b a ) 4 .

For some extensions and generalizations of the Simpson’s-type inequalities using novel and innovative methods, refer [3447] and the corresponding references cited therein.

Dragomir et al. [34] gave the following Simpson’s inequality for which the remainder is expressed in terms of derivatives lower than the fourth.

Theorem 3

Let f : [ a , b ] R be a differentiable mapping whose derivative is continuous on ( a , b ) and f L [ a , b ] . Then, the following inequality holds:

1 3 f ( a ) + f ( b ) 2 + 2 f a + b 2 1 b a a b f ( ϰ ) d ϰ b a 3 f 1

where f 1 = a b f ( ϰ ) d ϰ .

In [34], the bound of inequality (3) for L -Lipschitzian mapping was given by 5 36 L ( b a ) .

In the investigation of inequalities, the multiplicatively convex function is of paramount importance, and in [22], it is defined as follows.

Definition 4

A function f : I ( 0 , ) is said to be multiplicatively convex, if

f ( ( 1 t ) ϰ + t y ) [ f ( ϰ ) ] 1 t [ f ( y ) ] t

for all ϰ , y I and t [ 0 , 1 ] .

It can be easily seen that

f ( t ϰ + ( 1 t ) y ) [ f ( ϰ ) ] 1 t [ f ( y ) ] t t f ( ϰ ) + ( 1 t ) f ( y ) ,

which implies that every multiplicatively convex function is a convex function; however, the opposite is not true.

In [48], Hermite-Hadamard inequality for multiplicatively convex functions is given as follows.

Theorem 5

Let f be a positive and multiplicatively convex function on [ a , b ] . Then,

f a + b 2 a b ( f ( ϰ ) ) d ϰ 1 b a G ( f ( a ) , f ( b ) ) ,

where G ( , ) is the geometric mean.

Multiplicatively convex functions have been generalized into various types of multiplicatively convex functions by different mathematicians until today [4957]. One of these generalizations was obtained by Xi and Qi [33].

Definition 6

A function f : I ( 0 , ) is said to be multiplicatively s -convex, where s ( 0 , 1 ] , if

(4) f ( ( 1 t ) ϰ + t y ) [ f ( ϰ ) ] ( 1 t ) s [ f ( y ) ] t s

for all ϰ , y I and t [ 0 , 1 ] .

It is obvious that for s = 1 , inequality (4) reduces to inequality (1).

2 Multiplicative calculus

During the seventeenth century, Isaac Newton and Gottfried Wilhelm Leibniz separately unveiled the principles of differential and integral calculus. These groundbreaking discoveries have since played a pivotal role in the realm of analysis and calculus. The fundamental operations involved, differentiation and integration, permit the manipulation of numbers at an infinitesimal level.

In a significant departure from convention, a novel form of calculus emerged between 1967 and 1970 through the pioneering efforts of Grossman and Katz. This innovative framework reimagined the traditional notions of addition and subtraction by introducing division and multiplication as the central operations. Referred to as “multiplicative calculus,” this new approach is tailored exclusively to positive functions. Due to its narrower scope of application, multiplicative calculus has not garnered the same level of recognition as the calculus conceived by Leibniz and Newton. Nonetheless, it has revealed intriguing outcomes across various domains.

The foundations of multiplicative calculus were initially laid out by Bashirov et al. [58] in the 1970s, as they revisited and modified the classical calculus proposed by Newton and Leibniz. While its domain of applicability remains constrained to positive functions, multiplicative calculus has yielded remarkable results, evidenced by its diverse applications.

For instance, Bashirov et al. [59] introduced a fundamental theorem that underpins multiplicative calculus. Furthermore, Bashirov et al. [59] saw Bashirov and Riza pioneering the concept of complex multiplicative calculus. The realm of stochastic multiplicative calculus was explored by Bashirov and Ríza [60], where various properties were examined.

For a comprehensive exploration of the applications and dimensions within this discipline, one can refer to [6165] and references therein.

2.1 Multiplicative derivatives and integrals

Now, let us recall certain definitions, properties, and concepts related to differentiation and multiplicative integration.

Definition 7

[59] Let f : R R +  be a positive function. The multiplicative derivative of the function f noted by f * is defined as follows:

d * f d t = f * ( t ) = lim h 0 f ( t + h ) f ( t ) 1 h .

Remark 8

If f has positive values and is differentiable at t , then f * exists and the relation between f * and ordinary derivative f is as follows:

f * ( t ) = e ( ln f ( t ) ) = e f ( t ) f ( t ) .

The multiplicative derivative admits the following properties.

Theorem 9

[59] Let f and g be multiplicatively differentiable functions, and c is the arbitrary constant. Then, functions c f , f g , f + g , f g , and f g are * differentiable and

  1. ( c f ) * ( t ) = f * ( t ) ,

  2. ( f g ) * ( t ) = f * ( t ) g * ( t ) ,

  3. ( f + g ) * ( t ) = f * ( t ) f ( t ) f ( t ) + g ( t ) g * ( t ) g ( t ) f ( t ) + g ( t ) ,

  4. f g * ( t ) = f * ( t ) g * ( t ) ,

  5. ( f g ) * ( t ) = f * ( t ) g ( t ) f ( t ) g ( t ) .

It is worth noting that the concept of the multiplicative integral, denoted as * integral, takes the form a b ( f ( ϰ ) ) d ϰ , diverging from the classical Riemann integral represented as a b ( f ( ϰ ) ) d ϰ . This distinction arises from the utilization of different summation methods. Specifically, the classical Riemann integral employs term summation, while the * integral relies on products of raised terms within the interval [ a , b ] .

The relationship connecting the Riemann integral to the * integral can be expressed as follows.

Proposition 10

[59] If f is Riemann integrable on [ a , b ] , then f is * integrable on [ a , b ] and

a b ( f ( ϰ ) ) d ϰ = e a b ln ( f ( ϰ ) ) d ϰ .

* integral yields the following results and properties:

Theorem 11

[59] Let f be positive and Riemann integrable on [ a , b ] , then f is * integrable on [ a , b ] and

  1. a b ( ( f ( ϰ ) ) p ) d ϰ = a b ( f ( ϰ ) ) d ϰ p ,

  2. a b ( f ( ϰ ) g ( ϰ ) ) d ϰ = a b ( f ( ϰ ) ) d ϰ a b ( g ( ϰ ) ) d ϰ ,

  3. a b f ( ϰ ) g ( ϰ ) d ϰ = a b ( f ( ϰ ) ) d ϰ a b ( g ( ϰ ) ) d ϰ ,

  4. a b ( f ( ϰ ) ) d ϰ = a c ( f ( ϰ ) ) d ϰ c b ( f ( ϰ ) ) d ϰ , a < c < b ,

  5. a a ( f ( ϰ ) ) d ϰ = 1 and a b ( f ( ϰ ) ) d ϰ = b a ( f ( ϰ ) ) d ϰ 1 .

* integration by parts is given as follows.

Theorem 12

[59] Let f : [ a , b ] R be multiplicatively differentiable, let g : [ a , b ] R be differentiable so the function f g is * integrable, and

a b ( f * ( ϰ ) g ( ϰ ) ) d ϰ = f ( b ) g ( b ) f ( a ) g ( a ) × 1 a b ( f ( ϰ ) g ( ϰ ) ) d ϰ .

In order to prove our results, we need the following lemmas.

Lemma 13

[50] Let f : [ a , b ] R + be a * differentiable mapping on [ a , b ] with a < b . If f is * integrable on [ a , b ] , then

f a + b 2 a b ( f ( ϰ ) ) d ϰ 1 a b = 0 1 f ( 1 t ) a + t a + b 2 t d t b a 4 0 1 f ( 1 t ) a + b 2 + t b t 1 d t b a 4 .

Lemma 14

[54] Let f : [ a , b ] R + be a * differentiable mapping on [ a , b ] with a < b . If f is * integrable on [ a , b ] , then

G ( f ( a ) , f ( b ) ) a b ( f ( ϰ ) ) d ϰ 1 a b = 0 1 f ( ( 1 t ) a + t b ) 1 2 t d t b a ,

where G is the geometric mean.

3 Main results

In this section, we establish some new Simpson, midpoint, and trapezoid-type inequalities for multiplicatively s -convex functions. First we give the following lemma.

Lemma 15

Let f : [ a , b ] R + be a * differentiable mapping on [ a , b ] with a < b . If f is * integrable on [ a , b ] , then

( f ( a ) ) 1 6 f a + b 2 2 3 ( f ( b ) ) 1 6 a b ( f ( ϰ ) ) d ϰ 1 a b = 0 1 f 1 + t 2 b + 1 t 2 a t 2 1 3 d t b a 2 0 1 f 1 + t 2 a + 1 t 2 b 1 3 t 2 d t b a 2 .

Proof

Let

I 1 = 0 1 f 1 + t 2 b + 1 t 2 a t 2 1 3 d t b a 2

and

I 2 = 0 1 f 1 + t 2 a + 1 t 2 b 1 3 t 2 d t b a 2 .

Using the integration by parts for * integrals, we have

I 1 = 0 1 f 1 + t 2 b + 1 t 2 a t 2 1 3 d t b a 2

= 0 1 f 1 + t 2 b + 1 t 2 a b a 2 t 2 1 3 d t = ( f ( b ) ) 1 6 f a + b 2 1 3 . 1 0 1 f 1 + t 2 b + 1 t 2 a 1 2 d t = ( f ( b ) ) 1 6 f a + b 2 1 3 0 1 f 1 + t 2 b + 1 t 2 a d t 1 2 = ( f ( b ) ) 1 6 f a + b 2 1 3 a + b 2 b ( f ( ϰ ) ) d ϰ 1 a b ,

I 2 = 0 1 f 1 + t 2 a + 1 t 2 b 1 3 t 2 d t b a 2 = 0 1 f 1 + t 2 a + 1 t 2 b a b 2 t 2 1 3 d t = ( f ( a ) ) 1 6 f a + b 2 1 3 . 1 0 1 f 1 + t 2 a + 1 t 2 b 1 2 d t = ( f ( a ) ) 1 6 f a + b 2 1 3 0 1 f 1 + t 2 a + 1 t 2 b d t 1 2 = ( f ( a ) ) 1 6 f a + b 2 1 3 a a + b 2 ( f ( ϰ ) ) d ϰ 1 a b .

Multiplying above equalities, we have

I 1 × I 2 = ( f ( b ) ) 1 6 f a + b 2 1 3 a + b 2 b ( f ( ϰ ) ) d ϰ 1 a b ( f ( a ) ) 1 6 f a + b 2 1 3 a a + b 2 ( f ( ϰ ) ) d ϰ 1 a b = ( f ( a ) ) 1 6 f a + b 2 2 3 ( f ( b ) ) 1 6 a a + b 2 ( f ( ϰ ) ) d ϰ a + b 2 b ( f ( ϰ ) ) d ϰ 1 a b = ( f ( a ) ) f a + b 2 4 ( f ( b ) ) 1 6 a b ( f ( ϰ ) ) d ϰ 1 a b .

So, the proof is completed.□

Now, we are in a position to derive new integral inequalities for multiplicatively s -convex functions related to multiplicative integrals.

Theorem 16

Let f : [ a , b ] R + be a * differentiable mapping on [ a , b ] with a < b . If f is multiplicatively s-convex on [ a , b ] , then the following Simpson-type inequality holds:

(5) ( f ( a ) ) f a + b 2 4 ( f ( b ) ) 1 6 a b ( f ( ϰ ) ) d ϰ 1 a b ( ( f ( a ) ) ( f ( b ) ) ) ( s 4 ) 6 s + 1 + 2 × 5 s + 2 2 × 3 s + 2 + 2 6 s + 2 ( s + 1 ) ( s + 2 ) ( b a ) .

Proof

From Lemma 15 and properties of * integral, we obtain

( f ( a ) ) f a + b 2 4 ( f ( b ) ) 1 6 a b ( f ( ϰ ) ) d ϰ 1 a b exp b a 2 0 1 ln f 1 + t 2 b + 1 t 2 a t 2 1 3 d t × exp b a 2 0 1 ln f 1 + t 2 a + 1 t 2 b 1 3 t 2 d t = exp b a 2 0 1 t 2 1 3 ln f 1 + t 2 b + 1 t 2 a d t × exp b a 2 0 1 1 3 t 2 ln f 1 + t 2 a + 1 t 2 b d t .

By using the multiplicative s -convexity of f , we have

( f ( a ) ) f a + b 2 4 ( f ( b ) ) 1 6 a b ( f ( ϰ ) ) d ϰ 1 a b exp b a 2 0 1 t 2 1 3 ln ( f ( b ) ) 1 + t 2 s ( f ( a ) ) 1 t 2 s d t × exp b a 2 0 1 1 3 t 2 ln ( f ( a ) ) 1 + t 2 s ( f ( b ) ) 1 t 2 s d t = exp b a 2 0 1 t 2 1 3 1 + t 2 s ln ( f ( b ) ) + 1 t 2 s ln ( f ( a ) ) d t × exp b a 2 0 1 1 3 t 2 1 + t 2 s ln ( f ( a ) ) + 1 t 2 s ln ( f ( b ) ) d t = exp b a 2 s + 1 0 1 t 2 1 3 [ ( 1 + t ) s + ( 1 t ) s ] [ ln ( f ( a ) ) + ln ( f ( b ) ) ] d t .

It is easy to observe that

0 1 t 2 1 3 [ ( 1 + t ) s + ( 1 t ) s ] d t = 0 2 3 1 3 t 2 [ ( 1 + t ) s + ( 1 t ) s ] d t + 2 3 1 t 2 1 3 [ ( 1 + t ) s + ( 1 t ) s ] d t = J 1 + J 2 .

J 1 = 0 2 3 1 3 t 2 [ ( 1 + t ) s + ( 1 t ) s ] d t = 0 2 3 1 3 t 2 ( 1 + t ) s d t + 0 2 3 1 3 t 2 ( 1 t ) s d t = 5 ( 1 + t ) s + 1 6 ( s + 1 ) ( 1 + t ) s + 2 2 ( s + 2 ) 0 2 3 + 5 ( 1 + t ) s + 1 6 ( s + 1 ) ( 1 + t ) s + 2 2 ( s + 2 ) 0 2 3 = 5 s + 2 2 × 3 s + 2 + 1 2 × 3 s + 2 ( s + 1 ) ( s + 2 ) ,

J 2 = 2 3 1 t 2 1 3 [ ( 1 + t ) s + ( 1 t ) s ] d t = 2 3 1 t 2 1 3 ( 1 + t ) s d t + 2 3 1 t 2 1 3 ( 1 t ) s d t = ( 1 + t ) s + 2 2 ( s + 2 ) 5 ( 1 + t ) s + 1 6 ( s + 1 ) 2 3 1 + ( 1 + t ) s + 1 6 ( s + 1 ) + ( 1 t ) s + 2 2 ( s + 2 ) 2 3 1 = ( s 4 ) 6 s + 1 + 5 s + 2 + 1 2 × 3 s + 2 ( s + 1 ) ( s + 2 ) .

So, the proof is completed.□

Corollary 17

If we take s = 1 in Theorem 16, then f is a multiplicatively convex function on [ a , b ] and inequality (5) reduces to the following inequality:

( f ( a ) ) f a + b 2 4 ( f ( b ) ) 1 6 a b ( f ( ϰ ) ) d ϰ 1 a b ( ( f ( a ) ) ( f ( b ) ) ) 5 ( b a ) 72 .

Corollary 18

In Corollary 17, if f ( a ) = f a + b 2 = f ( b ) , then we have

(6) f a + b 2 a b ( f ( ϰ ) ) d ϰ 1 a b ( ( f ( a ) ) ( f ( b ) ) ) 5 ( b a ) 72 .

Corollary 19

In Corollary 18, if f K , then we have

f a + b 2 a b ( f ( ϰ ) ) d ϰ 1 a b K 5 ( b a ) 36 .

Remark 20

We note that the obtained inequality (6) is better than the inequality in Theorem 3.3 in [54].

Theorem 21

Let f : [ a , b ] R + be a * differentiable mapping on [ a , b ] with a < b . If f is multiplicatively s-convex on [ a , b ] , then the following midpoint-type inequality holds:

(7) f a + b 2 a b ( f ( ϰ ) ) d ϰ 1 a b ( f ( a ) ) f a + b 2 2 ( s + 1 ) ( f ( b ) ) b a 4 ( s + 1 ) ( s + 2 ) ( ( f ( a ) ) ( f ( b ) ) ) ( 2 2 s + 1 ) ( b a ) 4 ( s + 1 ) ( s + 2 ) .

Proof

From Lemma 13 and properties of * integral, we have

f a + b 2 a b ( f ( ϰ ) ) d ϰ 1 a b exp b a 4 0 1 ln f ( 1 t ) a + t a + b 2 t d t × exp b a 4 0 1 ln f ( 1 t ) a + b 2 + t b t 1 d t = exp b a 4 0 1 t ln f ( 1 t ) a + t a + b 2 d t × exp b a 4 0 1 ( 1 t ) ln f ( 1 t ) a + b 2 + t b d t .

By using the multiplicative s -convexity of f , we have

f a + b 2 a b ( f ( ϰ ) ) d ϰ 1 a b exp b a 4 0 1 t ln ( f ( a ) ) ( 1 t ) s f a + b 2 t s d t × exp b a 4 0 1 ( 1 t ) ln f a + b 2 ( 1 t ) s ( f ( b ) ) t s d t = exp b a 4 0 1 t ( 1 t ) s ln ( f ( a ) ) + t s + 1 ln f a + b 2 d t × exp b a 4 0 1 ( 1 t ) s + 1 ln f a + b 2 + t s ( 1 t ) ln ( f ( b ) ) d t = exp b a 4 ln ( f ( a ) ) 0 1 t ( 1 t ) s d t + ln f a + b 2 0 1 t s + 1 d t × exp b a 4 ln f a + b 2 0 1 ( 1 t ) s + 1 d t + ln ( f ( b ) ) 0 1 t s ( 1 t ) d t = exp b a 4 1 ( s + 1 ) ( s + 2 ) ln ( f ( a ) ) + 1 s + 2 ln f a + b 2 × exp b a 4 1 s + 2 ln f a + b 2 + 1 ( s + 1 ) ( s + 2 ) ln ( f ( b ) ) .

Thus we have

(8) f a + b 2 a b ( f ( ϰ ) ) d ϰ 1 a b ( f ( a ) ) 1 ( s + 1 ) ( s + 2 ) f a + b 2 2 s + 2 ( f ( b ) ) 1 ( s + 1 ) ( s + 2 ) b a 4 = ( f ( a ) ) f a + b 2 2 ( s + 1 ) ( f ( b ) ) b a 4 ( s + 1 ) ( s + 2 )

and the first inequality in (7) is proved. To prove the second inequality in (7), by using the multiplicative s -convexity of f , we obtain

(9) f a + b 2 2 s 1 ( ( f ( a ) ) ( f ( b ) ) ) 1 s + 1 .

A combination of (8) and (9) gives the inequality

f a + b 2 a b ( f ( ϰ ) ) d ϰ 1 a b ( f ( a ) ) f a + b 2 2 ( s + 1 ) ( f ( b ) ) b a 4 ( s + 1 ) ( s + 2 ) ( f ( a ) ) ( ( f ( a ) ) ( f ( b ) ) ) 1 s + 1 2 ( s + 1 ) 2 1 s ( f ( b ) ) b a 4 ( s + 1 ) ( s + 2 ) = ( ( f ( a ) ) ( f ( b ) ) ) ( 2 2 s + 1 ) ( b a ) 4 ( s + 1 ) ( s + 2 ) ,

which proves the second inequality in (7).

So, the proof is completed.□

Corollary 22

In Theorem 7, if we take s = 1 , then we obtain

f a + b 2 a b ( f ( ϰ ) ) d ϰ 1 a b ( f ( a ) ) f a + b 2 4 ( f ( b ) ) b a 4 ( s + 1 ) ( s + 2 ) ( ( f ( a ) ) ( f ( b ) ) ) ( b a ) 8 .

Theorem 23

Let f : [ a , b ] R + be a * differentiable mapping on [ a , b ] with a < b . If f is multiplicatively s-convex on [ a , b ] , then the following trapezoid-type inequality holds:

G ( f ( a ) , f ( b ) ) a b ( f ( ϰ ) ) d ϰ 1 a b ( f ( a ) f ( b ) ) s . 2 s + 1 2 s + 1 ( s + 1 ) ( s + 2 ) ( b a ) ,

where G is the geometric mean.

Proof

From Lemma 14, properties of * integral and the multiplicative s -convexity of f , we have

G ( f ( a ) , f ( b ) ) a b ( f ( ϰ ) ) d ϰ 1 a b exp ( b a ) 0 1 ln f ( ( 1 t ) a + t b ) 1 2 t d t = exp ( b a ) 0 1 t 1 2 ln f ( ( 1 t ) a + t b ) d t = exp ( b a ) 0 1 t 1 2 ln ( f ( a ) ) ( 1 t ) s ( f ( b ) ) t s d t = exp ( b a ) 0 1 t 1 2 ( ( 1 t ) s ln ( f ( a ) ) + t s ln ( f ( b ) ) ) d t = exp ( b a ) ln ( f ( a ) ) 0 1 t 1 2 ( 1 t ) s d t + ln ( f ( b ) ) 0 1 t 1 2 t s d t

= exp ( b a ) ln ( f ( a ) ) 0 1 t 1 2 ( 1 t ) s d t exp b a 2 ln ( f ( b ) ) 0 1 t 1 2 t s d t = exp ( b a ) s 2 s + 1 2 s + 1 ( s + 1 ) ( s + 2 ) ln ( f ( a ) ) exp ( b a ) s 2 s + 1 2 s + 1 ( s + 1 ) ( s + 2 ) ln ( f ( b ) ) = ( f ( a ) f ( b ) ) s . 2 s + 1 2 s + 1 ( s + 1 ) ( s + 2 ) ( b a ) .

So, the proof is completed.□

Corollary 24

In Theorem 23, if s = 1 , then we have

G ( f ( a ) , f ( b ) ) a b ( f ( ϰ ) ) d ϰ 1 a b ( f ( a ) f ( b ) ) b a 8 ,

which is established by Khan and Budak in [54].

Corollary 25

In Corollary 24, if f M , then we obtain

G ( f ( a ) , f ( b ) ) a b ( f ( ϰ ) ) d ϰ 1 a b M b a 4 .

4 Applications to special means

We shall consider the means for arbitrary real numbers a , b .

  1. The Arithmetic mean: A ( a 1 , a 2 ) = a 1 + a 2 2 .

  2. The Harmonic mean: H ( a 1 , a 2 ) = 2 a 1 a 2 a 1 + a 2 , a 1 , a 2 > 0 .

  3. The Logarithmic mean: L ( a 1 , a 2 ) = a 2 a 1 ln a 2 ln a 1 , a 1 , a 2 > 0 , and a 1 a 2 .

  4. The p -Logarithmic mean: L p ( a 1 , a 2 ) = a 2 p + 1 a 1 p + 1 ( p + 1 ) ( a 2 a 1 ) 1 p , a 1 , a 2 > 0 , a 1 a 2 and p R \ { 1 , 0 } .

Proposition 26

Let a , b R with 0 < a < b . Then, we have

e A p ( a , b ) L p p ( a , b ) ( e a p 1 + b p 1 ) 5 p ( b a ) 72 .

Proof

The assertion follows from Corollary 18, applied to the function f ( t ) = e t p with p 2 whose f ( t ) = e p t p 1 and a b ( f ( ϰ ) ) d ϰ 1 a b = exp ( L p p ( a , b ) ) .

Proposition 27

Let a , b R with 0 < a < b and r > 0 . Then, we have

e H 1 ( a , b ) L 1 ( a , b ) e ( b a ) 4 r 2 .

Proof

The assertion follows from Corollary 25, applied to the function f ( t ) = e 1 t whose f ( t ) = e 1 t 2 , M = e 1 r 2 and a b ( f ( ϰ ) ) d ϰ 1 a b = exp ( L 1 ( a , b ) ) .

5 Conclusion

In this study, first, a new identity for multiplicatively differentiable functions is presented. Using this identity, a new Simpson-type integral inequality for multiplicatively s -convex functions is obtained. Additionally, new integral inequalities of the midpoint and trapezoid-types for multiplicative integrals are derived. It is shown that some of our results improve upon those in the existing literature, while others are generalizations of known results. Applications of these results to special means are also presented. The findings of this study may inspire further research by scholars in this field.

Acknowledgement

I would like to express my deepest gratitude to the referees and the handling editor for their valuable comments.

  1. Funding information: The author states that no funding was involved.

  2. Author contributions: The author has accepted responsibility for the entire content of this article and approved its submission.

  3. Conflict of interest: The author states that there is no conflict of interest.

  4. Ethical approval: The conducted research is not related to either human or animal use.

  5. Data availability statement: No data were used to support the study.

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Received: 2023-08-17
Revised: 2024-03-17
Accepted: 2024-05-24
Published Online: 2025-02-22

© 2025 the author(s), published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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