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The Brezis–Oswald Result for Quasilinear Robin Problems

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Published/Copyright: June 20, 2016

Abstract

In this paper we consider a nonlinear elliptic problem driven by a nonhomogeneous differential operator with Robin boundary conditions. We produce conditions on the reaction term near 0+ and near +, which imply the existence and uniqueness of a positive solution. In the particular case of equations driven by the p-Laplacian, we show that these conditions are also necessary, extending in this way the semilinear Dirichlet work of Brezis and Oswald [5].

MSC 2010: 35J20; 35J60

1 Introduction

Let ΩN be a bounded domain with a C2-boundary Ω. In an interesting paper, Brezis and Oswald [5] examined the semilinear Dirichlet problem

(1.1) { - Δ u ( z ) = f ( z , u ( z ) ) in Ω , u = 0 on Ω , u 0 ,

and, under very general conditions on the reaction term f(z,x), established necessary and sufficient conditions for the existence of nontrivial solutions for problem (1.1).

The purpose of this work is to extend the Brezis–Oswald result to the following nonlinear Robin problem:

(1.2) { - div a ( D u ( z ) ) = f ( z , u ( z ) ) in Ω , u n a + β ( z ) u p - 1 = 0 on Ω , u 0 .

In this problem the map a:NN, involved in the definition of the differential operator, is continuous, strictly monotone (hence maximal monotone too) and satisfies certain other regularity and growth conditions, listed in hypotheses (Ha) below. These hypotheses provide a broad analytic framework, in which we can fit many nonlinear differential operators of interest, such as the p-Laplacian (1<p<). However, we stress that the differential operator in (1.2) need not be homogeneous and this is the source of difficulties in the analysis of problem (1.2). The reaction term f(z,x) is a Carathéodory function (that is, the map zf(z,x) is measurable for all x, and the map xf(z,x) is continuous for a.a. zΩ). On f(z,) we impose only a unilateral growth restriction from above. In the boundary condition, /na denotes the generalized directional derivative defined by

u n a = ( a ( D u ) , n ) N for all u W 1 , p ( Ω ) ,

with n() being the outward unit normal on Ω. This generalized directional derivative is dictated by the nonlinear Green’s identity and was also used by Lieberman [15].

With the setting above, in this work we produce conditions which are sufficient for the existence of positive smooth solutions. In this special case of the p-Laplacian, we show that these conditions are also necessary, extending this way the work of Brezis and Oswald [5].

For references on the subject, see [3, 8, 10, 13, 25] for semilinear Dirichlet problems and [9, 12, 14] for Dirichlet problems driven by the p-Laplacian.

2 Auxiliary Results

Let ΘC1(0,) be a function such that

(2.1) 0 < c ^ Θ ( t ) t Θ ( t ) c 0 and c 1 t p - 1 Θ ( t ) c 2 ( 1 + t p - 1 )

for all t>0 and some c1,c2>0.

  1. a(y)=a0(|y|)y for all yN with a0(t)>0 for all t>0 and, in addition, the following hold:

    1. a0C1(0,), the map ta0(t)t is strictly increasing,

      lim t 0 + a 0 ( t ) t = 0 and lim t 0 + a 0 ( t ) t a 0 ( t ) > - 1 .

    2. We have

      | a ( y ) | c 3 Θ ( | y | ) | y | for all y N { 0 } and some c 3 > 0 .

    3. We have

      ( a ( y ) ξ , ξ ) N Θ ( | y | ) | y | | ξ | 2 for all y N { 0 } and all ξ N .

    4. If G0(t)=0tsa0(s)𝑑s, then there exist 1<qp, δ>0 and c~>0 such that the map tG0(t1q) is convex on [0,+) and

      G 0 ( t ) c ~ t q for all t [ 0 , δ ] .

Remark 2.1

Hypotheses (Ha) (i)–(iii) are dictated by the nonlinear regularity theory of Lieberman [5] and by the nonlinear maximum principle of Pucci and Serrin [24]. Hypothesis (Ha) (iv) is used to prove the uniqueness of the positive solution.

Note that the primitive G0(t), t0, is strictly convex and strictly increasing. By setting G(y)=G0(|y|) for all yN, we have that G() is convex and continuously differentiable. Moreover,

G ( 0 ) = 0 and G ( y ) = G 0 ( | y | ) y | y | = a 0 ( | y | ) y = a ( y )

for all yN{0}. Therefore, G() is the primitive of a() vanishing at y=0. Finally, the convexity of G() implies that

(2.2) G ( y ) ( a ( y ) , y ) N for all y N .

The next lemma summarizes the main properties of the map a() and is an easy consequence of hypotheses (Ha) above.

Lemma 2.2

If hypotheses (Ha)(i)–(iii) hold, then

  1. y a ( y ) is continuous and strictly monotone, hence maximal monotone too,

  2. |a(y)|c4(1+|y|p-1) for all yN and some c4>0,

  3. (a(y),y)Nc1p-1|y|p for all yN.

Using this lemma together with (2.1) and (2.2), we have the following growth estimates for the primitive G().

Corollary 2.3

If hypotheses (Ha)(i)–(iii) hold, then

c 1 p ( p - 1 ) | y | p G ( y ) c 5 ( 1 + | y | p )

for all yN and some c5>0.

Examples

The following maps satisfy hypotheses (Ha):

  1. The map

    a ( y ) = | y | p - 2 y with 1 < p < ,

    which corresponds to the p-Laplace differential operator

    Δ p u = div ( | D u | p - 2 D u ) for all u W 1 , p ( Ω ) .

  2. The map

    a ( y ) = | y | p - 2 y + | y | q - 2 y with 1 < q < p < ,

    which corresponds to the (p,q)-differential operator defined by

    Δ p u + Δ q u for all u W 1 , p ( Ω ) .

    Such operators arise in problems of mathematical physics; see [4] and [6] for examples in quantum and plasma physics, respectively. Recently there have been some existence and multiplicity results for equations driven by such operators, see [7, 16, 20, 22, 23, 26].

  3. The map

    a ( y ) = ( 1 + | y | 2 ) p - 2 2 y with 1 < p < ,

    which corresponds to the generalized p-mean curvature differential operator defined by

    div ( ( 1 + | D u | 2 ) p - 2 2 D u ) for all u W 1 , p ( Ω ) .

  4. The map

    a ( y ) = | y | p - 2 y ( 1 + 1 1 + | y | p ) with 1 < p < .

The hypothesis on the boundary term β() is the following:

  1. βC0,α(Ω) with 0<α<1 and β(z)0 for all zΩ.

We start by considering the following Robin eigenvalue problem for the negative p-Laplacian plus an indefinite potential ξ():

(2.3) { - Δ p u ( z ) + ξ ( z ) | u ( z ) | p - 2 u ( z ) = λ ^ | u ( z ) | p - 2 u ( z ) in Ω , u n p + β ( z ) | u | p - 2 u = 0 on Ω ,

where 1<p< and

u n p = | D u | p - 2 ( D u , n ) N ,

with n() the outward unit normal on Ω. The Neumann version of this eigenvalue problem (that is, β0), was investigated by Mugnai and Papageorgiou [18]. On the other hand, Papageorgiou and Rădulescu [21] studied the case ξ0.

In addition to the Sobolev space W1,p(Ω), we will also use the Banach space C1(Ω¯). This is an ordered Banach space with positive cone

C + = { u C 1 ( Ω ¯ ) : u ( z ) 0 for all z Ω ¯ } .

This cone has a nonempty interior given by

int C + = { u C + : u ( z ) > 0 for all z Ω ¯ } .

Also, in the sequel, every Sobolev function restricted on Ω is understood in the sense of traces.

Proposition 2.4

If ξL(Ω) and hypothesis (Hβ) holds, then problem (2.3) admits a smallest eigenvalue λ^1(ξ,β,p), which is simple and isolated, and there exists a corresponding Lp-normalized eigenfunction u^1 (that is, u^1p=1) which satisfies

u ^ 1 C 1 , η ( Ω ¯ ) for some η ( 0 , 1 ) , u ^ 1 int C + .

Moreover, every eigenfunction corresponding to an eigenvalue λ^>λ^1 is nodal (that is, sign changing).

Proof.

Let γ:W1,p(Ω) be the C1-functional defined by

γ ( u ) = D u p p + Ω ξ ( z ) | u | p 𝑑 z + Ω β ( z ) | u | p 𝑑 σ for all u W 1 , p ( Ω ) .

Here σ() denotes the (N-1)-dimensional Hausdorff measure on Ω. Let MW1,p(Ω) the C1-Banach manifold defined by

M := { u W 1 , p ( Ω ) : u p = 1 } ,

and set

(2.4) λ ^ 1 ( ξ , β , p ) = inf { γ ( u ) : u M } .

Evidently,

λ ^ 1 ( ξ , β , p ) - ξ ,

see hypothesis (Hβ) and recall that ξL(Ω).

Let {un}n1M be a minimizing sequence for (2.4). So, γ(un)λ^1(ξ,β,p). Evidently, {un}n1W1,p(Ω) is bounded, and so we may assume that

(2.5) u n u ^ 1 in W 1 , p ( Ω )    and    u n u ^ 1 in L p ( Ω ) and in L p ( Ω ) .

Here we have used the Sobolev embedding theorem and the compactness of the trace map.

Because of (2.5), we have

(2.6) D u ^ 1 p p lim inf n D u n p p ,
(2.7) Ω ξ ( z ) | u n | p 𝑑 z Ω ξ ( z ) | u ^ 1 | p 𝑑 z , Ω β ( z ) | u n | p 𝑑 σ Ω β ( z ) | u ^ 1 | p 𝑑 σ .

Using (2.6)–(2.7), we obtain

(2.8) γ ( u ^ 1 ) λ ^ 1 ( ξ , β , p ) .

Note that u^1p=1, see (2.5). Hence, u^1M, and so (2.8) becomes

γ ( u ^ 1 ) = λ ^ 1 ( ξ , β , p ) .

The Lagrange multiplier rule (see, for example, [11, p. 701]), implies that λ^1(ξ,β,p) is an eigenvalue of problem (2.3), more precisely the smallest eigenvalue, with u^1W1,p(Ω) a corresponding eigenfunction. From [23], we know that u^1L(Ω). Then the regularity result of Lieberman [15] implies that u^1C1,η(Ω¯) for some η(0,1). Note that

γ ( | u | ) = γ ( u ) for all u M .

So, we infer that u^1 does not change sign and we may assume that u^10. The nonlinear maximum principle (see, for example, [11, p. 738] and [24, pp. 111, 120]) implies that u^1(z)>0 for all zΩ¯, hence u^1intC+.

Next we establish the simplicity of λ^1(ξ,β,p). To this end, let v^1W1,p(Ω) be another eigenfunction corresponding to λ^1(ξ,β,p). As we did for u^1, we can show that v^1intC+. Consider the function

R ( u ^ 1 , v ^ 1 ) ( z ) = | D u ^ 1 ( z ) | p - | D v ^ 1 ( z ) | p - 2 ( D v ^ 1 ( z ) , D ( u ^ 1 p v ^ 1 p - 1 ) ( z ) ) N .

Invoking the nonlinear Picone’s identity (see [2] and [17, p. 255]) and the nonlinear Green’s identity (see [11, p. 211]), we have

0 Ω R ( u ^ 1 , v ^ 1 ) 𝑑 z
= D u ^ 1 p p + Ω ( Δ p v ^ 1 ) u ^ 1 p v ^ 1 p - 1 𝑑 z + Ω β ( z ) u ^ 1 p 𝑑 σ
= D u ^ 1 p p + Ω ( ξ ( z ) - λ ^ 1 ( ξ , β , p ) ) u ^ 1 p 𝑑 z + Ω β ( z ) u ^ 1 p 𝑑 σ (see (2.3))
= γ ( u ^ 1 ) - λ ^ 1 ( ξ , β , p ) u ^ 1 p p
= 0 .

Recalling that R(u^1,v^1)(z)0, we get R(u^1,v^1)(z)=0 for a.a. zΩ, and so, by the nonlinear Picone’s identity, u^1=μv^1 for some μ>0.

Now, suppose that λ^>λ^1(ξ,β,p) is another eigenvalue of (2.3) with uW1,p(Ω) a corresponding Lp-normalized eigenfunction. Assume that u^ has constant sign and to fix things suppose that u^10. As before, the nonlinear regularity theory (see [15]) and the nonlinear maximum principle (see [11, 24]), imply that u^intC+. Using once again the nonlinear Picone’s identity and the nonlinear Green’s identity, we have

0 Ω R ( u ^ 1 , u ^ ) 𝑑 z
= D u ^ 1 p p + Ω ( Δ p u ^ ) u ^ 1 p u ^ p - 1 𝑑 z + Ω β ( z ) u ^ 1 p 𝑑 σ
= D u ^ 1 p p + Ω ( ξ ( z ) - λ ^ ) u ^ 1 p 𝑑 z + Ω β ( z ) u ^ 1 p 𝑑 σ
= γ ( u ^ 1 ) - λ ^ u ^ 1 p p
= λ ^ 1 ( ξ , β , p ) - λ ^
< 0 ,

a contradiction. So, u^C1(Ω¯) must be nodal.

Finally, we show that λ^1(ξ,β,p) is isolated in the spectrum of (2.3). Again we argue by contradiction. So, suppose that λ^1(ξ,β,p) is not isolated. Then we can find eigenvalues {λn}n1 such that λnλ^1(ξ,β,p) as n. Let {un}n1W1,p(Ω) be a sequence of corresponding Lp-normalized eigenfunctions. Evidently, {un}n1W1,p(Ω) is bounded. Then, from [23], we know that there exists M1>0 such that

u n M 1 for all n .

Therefore, from [15], it follows that there exist η(0,1) and M2>0 such that

u n C 1 , η ( Ω ¯ ) and u n C 1 , η ( Ω ¯ ) M 2 for all n .

Because of the compact embedding of C1,η(Ω¯) into C1(Ω¯), we may assume (at least for a subsequence) that

(2.9) u n u ~ 1 in C 1 ( Ω ¯ ) , u ~ 1 p = 1 .

Let A:W1,p(Ω)W1,p(Ω)* be the nonlinear map defined by

(2.10) A ( u ) , h = Ω | D u | p - 2 ( D u , D h ) N d z for all u , h W 1 , p ( Ω ) .

We have

A ( u n ) , h + Ω ξ ( z ) | u n | p - 2 u n h d z + Ω β ( z ) | u n | p - 2 u n h d σ = λ n Ω | u n | p - 2 u n h d z

for all hW1,p(Ω) and all n. Hence, passing to the limit as n and using (2.9), we find

A ( u ~ 1 ) , h + Ω ξ ( z ) | u ~ 1 | p - 2 u ~ 1 h d z + Ω β ( z ) | u ~ 1 | p - 2 u ~ 1 h d σ = λ ^ 1 ( ξ , β , p ) Ω | u ~ 1 | p - 2 u ~ 1 h d z

for all hW1,p(Ω), that is,

{ - Δ p u ~ 1 ( z ) + ξ ( z ) | u ~ 1 ( z ) | p - 2 u ~ 1 ( z ) = λ ^ 1 ( ξ , β , p ) | u ~ 1 ( z ) | p - 2 u ~ 1 ( z ) for a.a. z Ω , u ~ 1 n p + β ( z ) | u ~ 1 | p - 2 u ~ 1 = 0 on Ω ,

see [21]. This implies u~1=±u^1, see (2.9) and recall that λ^1(ξ,β,p) is simple. Then we can suppose that u~1intC+, and from (2.9) we have that unintC+ for all nn0, which contradicts the fact established earlier, that every non principal eigenvalue has nodal eigenfunctions. This proves that λ^1(ξ,β,p) is isolated in the spectrum of (2.3). ∎

3 Positive Solutions

In this section, we establish the existence of positive solutions for problem (1.2) under general conditions on the reaction term f(z,x). The precise hypotheses on the function f(z,x) are as follows:

  1. The reaction f:Ω× is a Carathéodory function with the following properties:

    1. f(,x)L(Ω) for all x0, and there exists c6>0 such that

      f ( z , x ) c 6 ( 1 + x p - 1 ) for a.a. z Ω and all x 0 .

    2. The function xf(z,x)/xq-1 is strictly decreasing on (0,+) for a.a. zΩ, with 1<qp as in hypothesis (Ha) (iv).

    3. If

      μ ( z ) := lim x + f ( z , x ) x p - 1 for a.a. z Ω , μ ^ = p - 1 c 1 μ , β ^ = p - 1 c 1 β ,

      then λ^1(-μ^,β^,p)>0.

    4. If

      μ 0 ( z ) = lim x 0 + f ( z , x ) x q - 1 for a.a. z Ω , μ ~ 0 = 1 c ~ q μ 0 , β ~ = 1 c ~ q β ,

      then λ^1(-μ~0,β~0,q)<0, where c~ is the constant appearing in (Ha) (iv).

Remark 3.1

  1. Since we are looking for positive solutions and all the above hypotheses concern the positive semiaxis +=[0,+), we may assume that

    f ( z , x ) = f ( z , 0 ) for a.a. z Ω and all x 0 .

  2. Hypothesis (Hf) (i) is a unilateral growth condition on f(z,). Clearly, both functions μ() and μ0() in (Hf) (iii) and (iv), respectively, are measurable functions.

  3. Hypothesis (Hf) (iii) covers the case μ=- in a set of positive measure.

  4. Hypothesis (Hf) (ii) implies that the function xf(z,x)/xp-1 is strictly decreasing on (0,+) for a.a. zΩ. Then, using hypothesis (Hf) (i), we have

    f ( z , x ) x p - 1 f ( z , 1 ) f ( , 1 ) = c 7 for a.a. z Ω and all x 1 .

    This implies μ(z)c7 for a.a. zΩ (see hypothesis (Hf) (iii)), hence

    λ ^ 1 ( - μ ^ , β ^ , p ) ( - , + ] .

    On the other hand, again from hypotheses (Hf) (i) and (ii), we have

    f ( z , x ) x q - 1 f ( z , 1 ) - f ( , 1 ) = - c 7 for a.a. z Ω and all x ( 0 , 1 ] .

    Thus, μ0(z)-c7 for a.a. zΩ and

    λ ^ 1 ( - μ ~ 0 , β ~ , q ) [ - , + ) .

    Of course, if μ,μ0L(Ω), then λ^1(-μ^,β^,p) and λ^1(-μ~0,β~,q) are principal eigenvalues of nonlinear eigenvalue problems similar to (2.3).

  5. If f(z,x)=f(x) (autonomous case), then hypotheses (Hf) (iii) and (iv) are equivalent to writing

    μ < 0 < μ 0 .

Example

Consider the function

f ( x ) = λ ( x q - 1 - x r - 1 ) for all x 0

with 1<qp<r and λ>0. This function satisfies hypotheses (Hf) with μ0=λ>0 and μ=-. Note that f(x) is the reaction term in the nonlinear logistic equation of sub-diffusive type, see [19].

We introduce the following Carathéodory function:

(3.1) k ( z , x ) = { f ( z , 0 ) if x 0 , f ( z , x ) + c 1 p - 1 x p - 1 if x > 0 .

Let 𝒦(z,x)=0xk(z,s)𝑑s, and consider the C1-functional φ:W1,p(Ω) defined by

φ ( u ) = Ω G ( D u ) 𝑑 z + c 1 p ( p - 1 ) u p p + 1 p Ω β ( z ) | u | p 𝑑 σ - Ω 𝒦 ( z , u ) 𝑑 z for all u W 1 , p ( Ω ) .

Proposition 3.2

If hypotheses (Ha)(i)–(iii), (Hβ), (Hf) hold, then the functional φ is coercive.

Proof.

We argue indirectly. So, suppose that φ is not coercive. Then, we can find {un}n1W1,p(Ω) such that

(3.2) u n +    and    φ ( u n ) M 1 for some M 1 > 0 and all n .

From (3.1) and hypothesis (Hf) (i), we have

(3.3) 𝒦 ( z , x ) c 8 ( 1 + | x | p ) for a.a. z Ω , all x and some c 8 > 0 .

Using Corollary 2.3 and (3.3), we have

(3.4) c 1 p ( p - 1 ) ( D u n p p + u n p p ) + 1 p Ω β ( z ) | u n | p 𝑑 σ c 9 ( 1 + u n p p )

for some c9>0 and all n. From (3.2), (3.4) and hypothesis (Hβ), it follows that

(3.5) u n p + as n .

Let yn=un/unp, n. Then

(3.6) y n p = 1 for all n ,

and from (3.4) we have

c 1 p ( p - 1 ) ( D y n p p + 1 ) c 9 ( 1 u n p p + 1 ) for all n ,

which implies that {yn}n1W1,p(Ω) is bounded by (3.5) and (3.6). So, we may assume that

(3.7) y n y in W 1 , p ( Ω )    and    y n y in L p ( Ω ) and in L p ( Ω ) , y p = 1 .

From (3.2) and Corollary 2.3, we have

c 1 p ( p - 1 ) ( D y n p p + y n p p ) + 1 p Ω β ( z ) | y n | p 𝑑 σ
M 1 u n p p + Ω 𝒦 ( z , u n ) u n p p 𝑑 z
(3.8) M 1 u n p p + { u n > 0 } ( F ( z , u n ) u n p p + c 1 p ( p - 1 ) y n p ) 𝑑 z + { u n < 0 } f ( z , 0 ) u n u n p p 𝑑 z

for all n (see (3.1)), where F(z,s)=0sf(z,t)𝑑t.

Hypothesis (Hf) (ii) implies that

f ( z , x ) x p - 1 f ( z , 1 ) for a.a. z Ω and all x ( 0 , 1 ] ,

hence, by hypothesis (Hf) (i),

f ( z , x ) - f ( , 1 ) x p - 1 for a.a. z Ω and all x ( 0 , 1 ] .

Therefore, f(z,0)0 for a.a. zΩ, and so

(3.9) { u n 0 } f ( z , 0 ) u n u n p p 𝑑 z 0 for all n .

Using (3.9) in (3), we obtain

(3.10) c 1 p ( p - 1 ) ( D y n p p + y n p p ) M 1 u n p p + c 1 p ( p - 1 ) y n + p p + Ω F ( z , u n + ) u n p p 𝑑 z for all n .

If {un+}n1Lp(Ω) is bounded, then since yn+=un+/unp for all n, from (3.5) we infer that yn+0 in Lp(Ω), hence y0. Hypothesis (Hf) (i) implies that

(3.11) F ( z , x ) c 10 ( 1 + x p ) for a.a. z Ω , all x 0 and some c 10 > 0 ,

hence

Ω F ( z , u n + ) u n p p 𝑑 z c 10 u n p p + c 10 y n + p p for all n ,

and by (3.5),

(3.12) lim sup n Ω F ( z , u n + ) u n p p 𝑑 z 0 .

So, if in (3.10) we pass to the limit as n and use (3.7) and (3.12), then

c 1 p ( p - 1 ) ( D y p p + y p p ) 0 ,

and so y=0, in contradiction with (3.7).

If {un+}n1Lp(Ω) is unbounded, then we may assume that un+p+, and from (3.2) and (3.9) we have

(3.13) c 1 p ( p - 1 ) ( D y n + p p + y n + p p ) + 1 p Ω β ( z ) ( y n + ) p 𝑑 σ M 1 u n + p p + Ω F ( z , u n + ) u n + p p 𝑑 z for all n .

Note that

(3.14) Ω F ( z , u n + ) u n + p p 𝑑 z = { y + = 0 } F ( z , u n + ) u n + p p 𝑑 z + { y > 0 } { y n > 0 } F ( z , u n + ) u n + p p 𝑑 z for all n .

From (3.7) we have that yn+y+ in Lp(Ω), hence

y n + ( z ) y + ( z ) for a.a. z Ω ,

at least for a subsequence. Then

(3.15) u n + ( z ) + for a.a. z { y + > 0 } = { y > 0 }

and

(3.16) χ { y > 0 } { y n > 0 } χ { y > 0 } ( z ) for a.a. z Ω .

Let z{μ>-}E with |E|N=0 (by ||N we denote the Lebesgue measure on N) be such that (see hypothesis (Hf) (iii))

f ( z , x ) x p - 1 μ ( z ) as x + .

Given ϵ>0, we can find M2=M2(z)>0 such that

f ( z , x ) ( μ ( z ) + ϵ ) x p - 1 for all x M 2 ,

hence

F ( z , x ) 1 p ( μ ( z ) + ϵ ) x p for all x M 2 ,

so that

lim sup x + F ( z , x ) x p 1 p ( μ ( z ) + ϵ ) .

Since ϵ>0 is arbitrary, we let ϵ0 to conclude that

lim sup x + F ( z , x ) x p 1 p μ ( z ) .

Next suppose z{μ=-}E (recall that |E|N=0). We have

f ( z , x ) x p - 1 - as x + .

Then, given S>0, we can find M3=M3(S)>0 such that

f ( z , x ) - S x p - 1 for all x M 3 ,

thus

F ( z , x ) x p - S p for all x M 3 ,

and so

lim sup x + F ( z , x ) x p - S p .

Since S>0 is arbitrary, we let S+ to conclude that

lim x + F ( z , x ) x p = - = μ ( z ) .

From the discussion above, we infer that

(3.17) lim sup x + F ( z , x ) x p 1 p μ ( z ) for a.a. z Ω .

Using (3.15), (3.16), (3.17) and Fatou’s lemma, we have

(3.18) lim sup n { y > 0 } { y n > 0 } F ( z , u n + ) ( u n + ) p ( y n + ) p 𝑑 z 1 p { y + 0 } μ ( y + ) p 𝑑 z .

Also, we have

| { y + = 0 } F ( z , u n + ) u n + p p d z | c 10 { y + = 0 } ( 1 u n + p p + ( y n + ) p ) d z for all n

(see (3.11)), thus

(3.19) lim n { y + = 0 } F ( z , u n + ) u n + p 𝑑 z = 0 .

We return to (3.14), pass to the limit as n and use (3.18) and (3.19). Then

(3.20) lim sup n Ω F ( z , u n + ) u n + p p 𝑑 z 1 p { y + 0 } μ ( y + ) p 𝑑 z .

In (3.13), if we pass to the limit as n and use (3.7) and (3.20), then we obtain

c 1 p ( p - 1 ) [ D y + p p + Ω β ^ ( z ) ( y + ) p d σ ] 1 p { y + 0 } μ ( y + ) p d z .

Hence,

(3.21) D y + p p + Ω β ^ ( z ) ( y + ) p 𝑑 σ Ω μ ^ ( y + ) p 𝑑 z .

If y+=0, then from (3.7), (3.10) and (3.19), we have Dypp+ypp0, and thus y=0, in contradiction with (3.7). Therefore, y+0, and so from (3.21) we have (see the proof of Proposition 2.4) λ^1(-μ^,β^,p)0, which contradicts hypothesis (Hf) (iii). This proves the coercivity of φ. ∎

Proposition 3.3

If hypotheses (Ha)(i)–(iii), (Hβ), (Hf) hold, then the functional φ is sequentially weakly lower semicontinuous.

Proof.

Let γ^(u):W1,p(Ω) and ψ^:W1,p(Ω) be the C1-functionals defined by

γ ^ ( u ) = Ω G ( D u ) 𝑑 z + c 1 p ( p - 1 ) u p p + 1 p Ω β ( z ) | u | p 𝑑 σ

and

ψ ^ ( u ) = - Ω 𝒦 ( z , u ) 𝑑 z for all u W 1 , p ( Ω ) .

The convexity of G(), the Sobolev embedding Theorem and the compactness of the trace map, imply that γ^ is sequentially weakly lower semicontinuous. Since φ=γ^+ψ^, to prove the sequential weak lower semicontinuity of φ, we need to show that ψ^ is sequentially weakly lower semicontinuous.

To this end, let S and consider the set

L S := { u W 1 , p ( Ω ) : ψ ^ ( u ) S } .

We need to show that LS is sequentially weakly closed. So, let {un}n1LS and assume that

u n u in W 1 , p ( Ω ) ,

hence, by the Sobolev embedding theorem,

u n u in L p ( Ω ) .

This implies that

(3.22) u n + u + and u n - u - in L p ( Ω ) ,

and, in particular,

(3.23) u n + ( z ) u + ( z ) for a.a. z Ω ,

at least for a subsequence.

We have (see (3.1))

(3.24) S - Ω 𝒦 ( z , u n ) 𝑑 z = - Ω F ( z , u n + ) 𝑑 z - c 1 p ( p - 1 ) u n + p p - Ω f ( z , 0 ) ( - u n - ) 𝑑 z ,

Note that, by (3.22),

(3.25) c 1 p ( p - 1 ) u n + p p c 1 p ( p - 1 ) u + p p

and, by (3.22) and hypothesis (Hf) (i),

(3.26) Ω f ( z , 0 ) ( - u n - ) 𝑑 z Ω f ( z , 0 ) ( - u - ) 𝑑 z .

Also, from (3.23) and Fatou’s lemma,

(3.27) lim inf n ( - Ω F ( z , u n + ) d z ) = - lim sup n Ω F ( z , u n + ) d z - Ω F ( z , u + ) d z .

So, if in (3.24) we pass to the limit as n and use (3.25)–(3.27), then

S - Ω F ( z , u + ) 𝑑 z - c 1 p ( p - 1 ) u + p p - Ω f ( z , 0 ) ( - u - ) 𝑑 z = - Ω 𝒦 ( z , u ) 𝑑 z ,

see also (3.1).

Hence, uLS and LS is sequentially weakly closed. It follows that ψ^ is sequentially weakly lower semicontinuous, hence φ is sequentially weakly lower semicontinuous as well. ∎

Now, we are ready to produce a positive smooth solution for problem (1.2). So far we have not used hypothesis (Ha) (iv); in the next result we will use it to establish the nontriviality of the solution we produce.

Proposition 3.4

If hypotheses (Ha), (Hβ), (Hf) hold, then problem (1.2) has a positive solution u0intC+.

Proof.

Propositions 3.2 and 3.3 permit the use of the Weierstrass–Tonelli theorem. Therefore, we can find u0W1,p(Ω) such that

(3.28) φ ( u 0 ) = inf { φ ( u ) : u W 1 , p ( Ω ) } .

Claim 1

u00, u00.

If u0-0, then, using (3.1) and recalling that G0 and f(z,0)0 for a.a. zΩ, we have

φ ( u 0 + ) = Ω G ( D u 0 + ) 𝑑 z + 1 p Ω β ( z ) ( u 0 + ) p 𝑑 σ - Ω F ( z , u 0 + ) 𝑑 z
< Ω G ( D u 0 ) 𝑑 z + c 1 p ( p - 1 ) u 0 p p + 1 p Ω β ( z ) | u 0 | p 𝑑 σ - Ω F ( z , u 0 + ) 𝑑 z - Ω f ( z , 0 ) ( - u 0 - ) 𝑑 z
= φ ( u 0 ) .

But this contradicts (3.28). Thus, u0-0, and so u00.

Next we show that u00. By hypothesis (Hf) (iv) we have λ^1(-μ~0,β~,q)<0. The variational characterization of λ^1(-μ~0,β~,q) (see the proof of Proposition 2.4) and the density of W1,p(Ω) into W1,q(Ω), imply that we can find uW1,p(Ω) such that

(3.29) u q = 1 and D u q q + Ω β ~ ( z ) | u | q 𝑑 σ - Ω μ ~ 0 ( z ) | u | q 𝑑 z < 0 .

Clearly, we may assume that u0 (just replace, if necessary, u by |u|).

We can find {un}n1C1(Ω¯) such that

(3.30) u n u in W 1 , p ( Ω ) ,

see, for example, [11, p. 189]. Since we have that

u n + u + = u in W 1 , p ( Ω ) ,

we can always assume that un0 for all n. Let

u ^ n := min { u , u n } W 1 , p ( Ω ) L ( Ω ) for all n .

Then, by (3.30), u^nu in W1,p(Ω) and, in particular,

u ^ n ( z ) u ( z ) for a.a. z Ω ,

at least for a subsequence. Recall that hypothesis (Hf) (ii) implies that

μ ~ 0 ( z ) f ~ ( z , 1 ) - f ~ ( , 1 ) for a.a. z Ω ,

where f~=f/(c~q), see Remark 3.1 (4), so that

(3.31) μ 0 ( z ) u ^ n q ( z ) χ { u n 0 } ( z ) - f ~ ( , 1 ) u q ( z ) for a.a. z Ω .

Note that

(3.32) f ~ ( , 1 ) u q ( ) L 1 ( Ω )

and

(3.33) μ ~ 0 ( z ) u ^ n q ( z ) χ { u n 0 } ( z ) μ ~ 0 ( z ) u q ( z ) for a.a. z Ω .

Then (3.31)–(3.33) permit the use of Fatou’s lemma, obtaining

(3.34) lim inf n { u n 0 } μ ~ 0 ( z ) u ^ n q 𝑑 z { u 0 } μ ~ 0 ( z ) u q 𝑑 z .

Since u^nu in W1,p(Ω), using the trace theorem, we have

(3.35) D u ^ n q q + Ω β ~ ( z ) u ^ n q 𝑑 σ D u ^ q q + Ω β ~ ( z ) u q 𝑑 σ .

From (3.29), (3.34) and (3.35), we see that we can find n0 such that

D u ^ n q q + Ω β ~ ( z ) u ^ n q 𝑑 σ - { u n 0 } μ ~ 0 ( z ) u ^ n q 𝑑 z < 0 for all n n 0 .

This means that we can find uW1,p(Ω)L(Ω) such that

(3.36) D u q q + Ω β ~ ( z ) u q 𝑑 σ - Ω μ ~ 0 ( z ) u q 𝑑 z < 0 , u 0 .

The q-homogeneity of the left-hand side in (3.36) implies that we can always assume that uq=1.

Let F~(z,x)=0xf~(z,s)𝑑s. For every (z,x)Ω×(0,), by the chain rule, we have

F ~ ( z , x ) = 0 1 d d t F ~ ( z , t x ) 𝑑 t = 0 1 f ~ ( z , t x ) x 𝑑 t ,

hence, by (Hf) (ii),

F ~ ( z , x ) x q = 0 1 f ~ ( z , t x ) x q - 1 𝑑 t 0 1 f ~ ( z , x ) x q - 1 t q - 1 𝑑 t = 1 q f ~ ( z , x ) x q - 1 ,

and, by (Hf) (iv),

(3.37) lim inf x 0 + F ~ ( z , x ) x q 1 q μ ~ 0 ( z ) for a.a. z Ω .

Let uW1,p(Ω)L(Ω), uq=1 be as in (3.36). We can find τ(0,1] so small that

τ u ( z ) [ 0 , δ ] for a.a. z Ω .

Here δ(0,1] is the one given in (Ha) (iv); evidently, we can always assume δ1.

Hence, by (Hf) (ii), we have

F ~ ( z , τ u ( z ) ) τ q = 1 τ q 0 τ u ( z ) f ~ ( z , s ) 𝑑 s
- 1 τ q f ~ ( , 1 ) 0 τ u ( z ) s q - 1 𝑑 s
= - f ~ ( , 1 ) q u q ( z )
(3.38) - f ~ ( , 1 ) q u q .

Then (3) permits the use of Fatou’s lemma and thus, by (3.37), we have

lim inf τ 0 + { u 0 } F ~ ( z , τ u ) τ q 𝑑 z 1 q { u 0 } μ ~ 0 ( z ) u q 𝑑 z .

Then, from (3.36) and for τ(0,1) small, we have

c ~ D ( τ u ) q q + 1 q Ω β ( z ) ( τ u ) q 𝑑 σ - c ~ Ω q F ~ ( z , τ u ) 𝑑 z < 0 ,

recall that β~=β/(c~q). Thus, from hypothesis (Ha) (iv) and by recalling that δ(0,1] and qp, we have

Ω G ( D ( τ u ) ) 𝑑 z + 1 p Ω β ( z ) ( τ u ) p 𝑑 σ - Ω F ( z , τ u ) 𝑑 z < 0 .

From (3.1) and the fact that u0, this implies φ(τu)<0. Hence, from (3.28), φ(u0)<0=φ(0) and u00 with u00. This proves Claim 1.

Claim 2

u0L(Ω).

For every k, we introduce the following truncation of the reaction f(z,):

f k ( z , x ) = { f ( z , 0 ) if x 0 , max { f ( z , x ) , - k x p - 1 } if x > 0

(recall that f(z,0)0 for a.a. zΩ). This is a Carathéodory function and fk(,x)L(Ω) for all x (see hypothesis (Hf) (i)). Also, we have

(3.39) | f k ( z , x ) | c 11 ( 1 + | x | p - 1 ) for a.a. z Ω , all x and some c 11 > 0 .

We set

μ 0 k ( z ) = lim inf x 0 + f k ( z , x ) x q - 1 and μ k ( z ) = lim sup x + f k ( z , x ) x p - 1 .

Note that

f k ( z , x ) f ( z , x ) for a.a. z Ω and all x ,

hence

μ 0 k μ 0 and λ ^ 1 ( - μ ~ 0 k , β ~ , q ) λ ^ 1 ( - μ ~ 0 , β ~ , q ) for all k .

Here μ~0k=μ0k/(c~q). Moreover, we have μkμ as k+, thus

λ ^ 1 ( - μ ^ k , β ^ , p ) λ ^ 1 ( - μ ^ , β ^ , p ) > 0 and λ ^ 1 ( - μ k , β ^ , p ) > 0

for all k sufficiently large, where μ^k=(p-1)μk/c1.

Let φk:W1,p(Ω) be the C1-functional defined as φ, with the primitive F(z,x)=0xf(z,s)𝑑s replaced by Fk(z,x)=0xfk(z,s)𝑑s. Reasoning as for φ, via the direct method, we can find u0k0, u0k0 such that

φ k ( u 0 k ) = inf { φ k ( u ) : u W 1 , p ( Ω ) } .

Then φk(u0k)=0, thus, by (2.10) we have

A ( u 0 k ) , h + Ω β ( z ) ( u 0 k ) h 𝑑 σ = Ω f k ( z , u 0 k ) h 𝑑 z for all h W 1 , p ( Ω )

and (see [21])

{ - div a ( D u 0 k ( z ) ) = f k ( z , u 0 k ( z ) ) for a.a. z Ω , u 0 k n a + β ( z ) ( u 0 k ) p - 1 = 0 on Ω .

Because of (3.39), from [23] we have u0kL(Ω). Then, from [15] we have that

u 0 k C 1 ( Ω ¯ ) for all k .

Let

y k = min { u 0 , u 0 k } W 1 , p ( Ω ) L ( Ω ) for all k .

Recalling that u0k is a minimizer of the functional φk, we get

(3.40) φ k ( u 0 k ) φ k ( v ) for all v W 1 , p ( Ω ) .

Taking v:=max{u0,u0k}W1,p(Ω) and using (3.40), we have

{ u 0 k < u 0 } G ( D u 0 k ) 𝑑 z + 1 p { γ 0 ( u 0 k ) < γ 0 ( u 0 ) } β ( z ) ( u 0 k ) p 𝑑 σ - { u 0 k < u 0 } F k ( z , u 0 k ) 𝑑 z
{ u 0 k < u 0 } G ( D u 0 ) 𝑑 z + 1 p { γ 0 ( u 0 k ) < γ 0 ( u 0 ) } β ( z ) u 0 p 𝑑 σ - { u 0 k < u 0 } F k ( z , u 0 ) 𝑑 z ,

with γ0() being the trace map. Thus,

(3.41) { u 0 k < u 0 } [ G ( D u 0 k ) - G ( D u 0 ) ] 𝑑 z + 1 p { γ 0 ( u 0 k ) < γ 0 ( u 0 ) } β ( z ) ( ( u 0 k ) p - u 0 p ) 𝑑 σ { u 0 k < u 0 } [ F k ( z , u 0 k ) - F k ( z , u 0 ) ] 𝑑 z .

Then, using (3.41) and recalling that fkf, we have

φ ( y k ) - φ ( u 0 ) = { u 0 k < u 0 } [ G ( D u 0 k ) - G ( D u 0 ) ] 𝑑 z + 1 p { γ 0 ( u 0 k ) < γ 0 ( u 0 ) } β ( z ) ( ( u 0 k ) p - u 0 p ) 𝑑 σ - { u 0 k < u 0 } [ F ( z , u 0 k ) - F ( z , u 0 ) ] 𝑑 z
{ u 0 k < u 0 } [ F k ( z , u 0 k ) - F k ( z , u 0 ) - F ( z , u 0 k ) + F ( z , u 0 ) ] 𝑑 z
= { u 0 k < u 0 } u 0 k u 0 ( - f k ( z , s ) + f ( z , s ) ) 𝑑 s 𝑑 z 0 .

Hence, φ(yk)φ(u0), and so, by (3.28),

φ ( y k ) = φ ( u 0 ) = inf { φ ( u ) : u W 1 , p ( Ω ) } .

Since ykL(Ω), we may assume that u0L(Ω). This proves Claim 2.

Conclusion. Let hC1(Ω¯). We set

d ( h ) = Ω [ 𝒦 ( z , u 0 + h ) - 𝒦 ( z , u 0 ) - k ( z , u 0 ) h ] 𝑑 z .

Then, using Fubini’s theorem and Hölder’s inequality, we have

| d ( h ) | Ω | h | 0 1 | k ( z , u 0 + t h ) - k ( z , u 0 ) | d t d z h p 0 1 N k ( u 0 + t h ) - N k ( u 0 ) p d t ,

where Nk(v)=k(,v()) for all vW1,p(Ω) and 1/p+1/p=1.

Note that u0+thL(Ω) (see Claim 2). By hypothesis (Hf) (ii), for a.a. z{u0+th>0}, we have

f ( z , ( u 0 + t h ) ( z ) ) f ( z , u 0 + t h ) u 0 + t h ( u 0 + t h ) ( z )
- f ( , u 0 + t h ) ( u 0 + t h ) q - 1 ( z ) u 0 + t h q - 1
- f ( , u 0 + t h ) for a.a. z Ω .

On the other hand, from hypothesis (Hf) (i) we have

f ( z , ( u 0 + t h ) ( z ) ) c 12 for a.a. z { u 0 + t h > 0 } and some c 12 > 0 .

Therefore, from (3.1) and the Lebesgue dominated convergence theorem,

0 1 N k ( u 0 + t h ) - N k ( u 0 ) p d s 0 as h 0 ,

thus

1 h | d ( h ) | 0 as h 0 .

It follows that φ is Gateaux differentiable at u0 in the direction of all hC1(Ω¯). Let φG(u0) denote this Gateaux derivative. We have

φ G ( u 0 ) , h = 0 for all h C 1 ( Ω ¯ ) .

Using the fact that C1(Ω¯) is dense in W1,p(Ω), one has

φ G ( u 0 ) , h = 0 for all h W 1 , p ( Ω ) .

Hence, by (2.10) and (3.1),

A ( u 0 ) , h + Ω β ( z ) u 0 p - 1 h 𝑑 σ = Ω f ( z , u 0 ) h 𝑑 z for all h W 1 , p ( Ω ) .

This implies that (see [21])

(3.42) { - div a ( D u 0 ( z ) ) = f ( z , u 0 ( z ) ) for a.a. z Ω , u 0 n a + β ( z ) u 0 p - 1 = 0 on Ω .

Thus, u0C+{0} (see [15]). For a.a. z{u0>0}, hypothesis (Hf) (ii) implies also that

f ( z , u 0 ( z ) ) u 0 p - 1 ( z ) f ( z , u 0 ) u 0 p - 1 .

Hence,

(3.43) f ( z , u 0 ( z ) ) - f ( , u 0 ) u 0 p - 1 ( z ) u 0 p - 1 .

Recall that f(z,0)0 for a.a. zΩ. Therefore, from (3.42) and (3.43), it follows that

div a ( D u 0 ( z ) ) c 13 u 0 p - 1 ( z ) for a.a. z Ω and some c 13 > 0 .

Thus, u0intC+ (see [24, pp. 111, 120]). ∎

Next we show the uniqueness of this positive solution.

Theorem 3.5

If hypotheses (Ha), (Hβ), (Hf) hold, then problem (1.2) admits a unique positive solution u0intC+.

Proof.

From Proposition 3.4, we already have a positive solution u0intC+. To show the uniqueness of this positive solution, we proceed as follows. Let j:L1(Ω)¯={+} be the integral functional defined by

j ( u ) = { Ω G ( D u 1 q ) 𝑑 z + 1 p Ω β ( z ) u p q 𝑑 σ if u 0 , u 1 q W 1 , p ( Ω ) , + , otherwise .

Let u1,u2domj={uL1(Ω):j(u)<+} (the effective domain of j()), and set

v = ( ( 1 - t ) u 1 + t u 2 ) 1 q with t [ 0 , 1 ] .

From [9, Lemma 1] we have

| D v ( z ) | [ ( 1 - t ) | D u 1 1 q ( z ) | q + t | D u 2 1 q ( z ) | q ] 1 q for a.a. z Ω .

In this way, since G0() is increasing, we get

G 0 ( | D v ( z ) | ) G 0 ( ( ( 1 - t ) | D u 1 1 q ( z ) | q + t | D u 2 1 q ( z ) | q ) 1 q )
( 1 - t ) G 0 ( | D u 1 1 q ( z ) | ) + t G 0 ( | D u 2 1 q ( z ) | ) ,

see hypothesis (Ha) (iv). Hence,

G ( D v ( z ) ) ( 1 - t ) G ( D u 1 1 q ( z ) ) + t G ( D u 2 1 q ( z ) ) for a.a. z Ω ,

and it follows that the function uΩG(Du1q)𝑑z is convex on domj.

Since pq, using hypothesis (Hβ), we see that

u 1 p Ω β ( z ) u p q 𝑑 σ

is convex on domj too. So, it follows that j() is convex. Also, by Fatou’s lemma, it is lower semicontinuous.

Suppose that u^W1,p(Ω) is another positive solution of problem (1.2). As we did for u0 (see the proof of Proposition 3.4), we can show that u^intC+. Then, for hC1(Ω¯) and |t| small, we have

u 0 q + t h , u ^ q + t h dom j .

Then we can easily check that j() is Gateaux differentiable at both u0q and u^q in the direction h. Moreover, the chain rule and the nonlinear Green’s identity imply that

j ( u 0 q ) ( h ) = 1 q Ω - div a ( D u 0 ) u 0 q - 1 h 𝑑 z , j ( u ^ q ) ( h ) = 1 q Ω - div a ( D u ^ ) u ^ q - 1 h 𝑑 z for all h C 1 ( Ω ¯ ) .

The convexity of j() implies the monotonicity of j(). Hence,

0 j ( u 0 q ) - j ( u ^ q ) , u 0 q - u ^ q
= 1 q Ω ( - div a ( D u 0 ) u 0 q - 1 - - div a ( D u ^ ) u ^ q - 1 ) ( u 0 q - u ^ q ) 𝑑 z
= 1 q Ω ( f ( z , u 0 ) u 0 q - 1 - f ( z , u ^ ) u ^ q - 1 ) ( u 0 q - u ^ q ) 𝑑 z .

This implies u0=u^ (see hypothesis (Hf) (ii)), and thus u0intC+ is the unique positive solution of (1.2). ∎

Remark 3.6

In the case where the differential operator is the p-Laplacian, the proof of the uniqueness can be based on the nonlinear Picone’s identity (see the proof of Proposition 2.4), thus extending the result of Abdellaoui and Peral (see [1, Corollary 4.4]). We present this proof. Note that if the differential operator is the p-Laplacian, then a(y)=|y|p-2y for all yN and q=p in hypothesis (Ha) (iv). Thus, suppose that u0,u^ are two positive solutions of problem (1.2). From Proposition 3.4, we know that u0,u^intC+. We consider the function R(u0,u^)() introduced in the proof of Proposition 2.4. Recall that

(3.44) 0 R ( u 0 , u ^ ) ( z ) for a.a. z Ω .

By the nonlinear Green’s identity (see [11, p. 211]), we have

Ω f ( z , u 0 ) u 0 p - 1 ( u 0 p - u ^ p ) 𝑑 z = Ω ( - Δ p u 0 ) ( u 0 - u ^ p u 0 p - 1 ) 𝑑 z
= Ω | D u 0 | p - 2 ( D u 0 , D ( u 0 - u ^ p u 0 p - 1 ) ) N d z + Ω β ( z ) u 0 p - 1 ( u 0 - u ^ p u 0 p - 1 ) d σ
(3.45) = D u 0 p p - D u ^ p p + Ω R ( u ^ , u 0 ) 𝑑 z + Ω β ( z ) ( u 0 p - u ^ p ) 𝑑 σ .

Interchanging the roles of u0 and u^, we also have

(3.46) Ω f ( z , u ^ ) u ^ p - 1 ( u ^ p - u 0 p ) 𝑑 z = D u ^ p p - D u 0 p p + Ω R ( u 0 , u ^ ) 𝑑 z - Ω β ( z ) ( u 0 p - u ^ p ) 𝑑 σ .

Adding (3.6) and (3.46), and using (3.44), we obtain

(3.47) Ω ( f ( z , u 0 ) u 0 p - 1 - f ( z , u ^ ) u ^ p - 1 ) ( u 0 p - u ^ p ) 𝑑 z = Ω [ R ( u ^ , u 0 ) + R ( u 0 , u ^ ) ] 𝑑 z 0 .

As we already remarked at the beginning of this section, hypothesis (Hf) (ii) implies that the function xf(z,x)/xp-1 is strictly decreasing on (0,+) for a.a. zΩ. Therefore, from (3.47) we infer that u0=u^, and this proves the uniqueness of the positive solution for the particular case of problem (1.2) in which the differential operator is the p-Laplacian.

4 The p-Laplacian Case

In this section we continue with the setting introduced in the last Remark. Namely, we deal with the particular case of problem (1.2) in which the differential operator is the p-Laplacian. So, now the problem under consideration is

(4.1) { - Δ p u ( z ) = f ( z , u ( z ) ) in Ω , u n p + β ( z ) u p - 1 = 0 on Ω , u 0 .

Problem (4.1) is a particular case of problem (1.2) with

a ( y ) = | y | p - 2 y for all y N .

Therefore, c1=p-1, and so we have

μ ^ = μ and β ^ = β .

Moreover, q=p and c~=1/p (see hypothesis (Ha) (iv), and hypotheses (Hf) (ii) and (iv)). Then

μ ~ 0 = μ 0 and β ~ = β .

In this case we show that hypotheses (Hf) (iii) and (iv) are also necessary for the existence of a unique positive solution for problem (4.1).

Theorem 4.1

If hypothesis (Hβ) holds and f:Ω× is a Carathéodory function which satisfies hypotheses (Hf) (i) and (ii), then problem (4.1) admits a unique positive solution u0intC+ if and only if

λ ^ 1 ( - μ 0 , β , p ) < 0 < λ ^ 1 ( - μ , β , p ) .

Proof.

” This was established in Theorem 3.5 for a broader class of problems.

” From the proof of Proposition 2.4, we have

(4.2) λ ^ 1 ( - μ 0 , β , p ) γ ( u 0 ) - Ω μ 0 ( z ) u 0 p 𝑑 z u 0 p p = Ω f ( z , u 0 ) u 0 𝑑 z - Ω μ 0 ( z ) u 0 p 𝑑 z u 0 p p .

Denoting m0=minΩ¯u0>0 (recall that u0intC+), then, from hypothesis (Hf) (ii) (since q=p), we have

f ( z , u 0 ( z ) ) u 0 p - 1 ( z ) f ( z , m 0 ) m 0 p - 1 < μ 0 ( z ) for a.a. z Ω .

Using this in (4.2), we infer that

λ ^ 1 ( - μ 0 , β , p ) < Ω μ 0 ( z ) u 0 p ( z ) 𝑑 z - Ω μ 0 ( z ) u 0 p ( z ) 𝑑 z u 0 p p = 0 .

Now, set

ξ ( z ) = - f ( z , u 0 + 1 ) ( u 0 + 1 ) p - 1 ;

clearly ξL(Ω) (see hypothesis (Hf) (i)).

Consider the eigenvalue problem (2.3) with this particular ξ() as potential function. From Proposition 2.4, we know that this eigenvalue problem has a principal eigenfunction u^1intC+. We choose τ>0 so big that

(4.3) u 0 < τ u ^ 1 = u ~ 1 int C + .

We use (3.6) first with f(z,x) (replacing u^ with u~1), and then with (λ^1(ξ,β,p)-ξ(z))xp-1x0 and u~1 as solution to the related problem (2.3). We have

(4.4) Ω f ( z , u 0 ) u 0 p - 1 ( u 0 p - u ~ 1 p ) 𝑑 z = Ω R ( u ~ 1 , u 0 ) 𝑑 z + D u 0 p p - D u ~ 1 p p + Ω β ( z ) ( u 0 p - u ~ 1 p ) 𝑑 σ ,
(4.5) Ω ( λ ^ 1 ( ξ , β , p ) - ξ ( z ) ) ( u ~ 1 p - u 0 p ) 𝑑 z = Ω R ( u 0 , u ~ 1 ) 𝑑 z + D u ~ 1 p p - D u 0 p p + Ω β ( z ) ( u ~ 1 p - u 0 p ) 𝑑 σ .

Adding (4.4) and (4.5) we obtain

(4.6) Ω [ f ( z , u 0 ) u 0 p - 1 + ξ ( z ) - λ ^ 1 ( ξ , β , p ) ] ( u 0 p - u ~ 1 p ) 𝑑 z = Ω [ R ( u ~ 1 , u 0 ) + R ( u 0 , u ~ 1 ) ] 𝑑 z 0 .

Note that (see hypothesis (Hf) (ii) and recall that q=p)

f ( z , u 0 ) u 0 p - 1 > f ( z , u 0 + 1 ) ( u 0 + 1 ) p - 1 = - ξ ( z ) for a.a. z Ω .

Hence,

(4.7) f ( z , u 0 ) u 0 p - 1 + ξ ( z ) > 0 for a.a. z Ω .

From (4.3) we have

(4.8) ( u 0 p - u ~ 1 p ) ( z ) < 0 for all z Ω ¯ .

From (4.6) we have

Ω [ f ( z , u 0 ) u 0 p - 1 + ξ ( z ) ] ( u 0 p - u ~ 1 p ) 𝑑 z λ ^ 1 ( ξ , β , p ) Ω ( u 0 p - u ~ 1 p ) 𝑑 z .

Thus, by (4.7) and (4.8), we get

0 > λ ^ 1 ( ξ , β , p ) Ω ( u 0 p - u ~ 1 p ) 𝑑 z ,

which, by (4.8), implies that

(4.9) λ ^ 1 ( ξ , β , p ) > 0 .

But, by (Hf) (ii), note that

ξ ( z ) - μ ( z ) for a.a. z Ω ,

hence

λ ^ 1 ( ξ , β , p ) λ ^ 1 ( - μ , β , p ) ,

and, by (4.9),

λ ^ 1 ( - μ , β , p ) > 0 .

Funding statement: The first author is a member of the INDAM “Gruppo Nazionale per l’Analisi Matematica, la Probabilità e le loro Applicazioni” (GNAMPA). Research partially supported by the GNAMPA project 2015 Analysis and control of nonlinear PDE’s. The second author is a member of the INDAM “Gruppo Nazionale per l’Analisi Matematica, la Probabilità a e le loro Applicazioni” (GNAMPA). Research supported by the M.I.U.R. project Variational Methods and Nonlinear Differential Equations. This paper was written during the stay of the third author at the Dipartimento di Matematica, Università di Bari, as visiting professor supported by GNAMPA, whose financial support is here acknowledged.

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Received: 2016-02-02
Accepted: 2016-04-11
Published Online: 2016-06-20
Published in Print: 2016-08-01

© 2016 by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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