Home Weighted Fractional Sobolev Inequality in ℝN
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Weighted Fractional Sobolev Inequality in ℝN

  • Xiaoli Chen and Jianfu Yang EMAIL logo
Published/Copyright: March 12, 2016

Abstract

In this paper, we show that the minimizing problem

Λ s , N , k , α = inf u H ˙ s ( N ) , u 0 N | ( - Δ ) s 2 u ( x ) | 2 𝑑 x ( N | u ( x ) | 2 s , α * | y | α 𝑑 x ) 2 2 s , α *

is achieved by a positive, cylindrically symmetric and strictly decreasing function u(x) provided 0<s<N2, 0<α<2s, where x=(y,z)k×N-k and 2s,α*=2(N-α)N-2s. Decaying laws for the minimizer u are also established.

1 Introduction

In this paper, we investigate the minimizing problem

(1.1) Λ s , N , k , α = inf u H ˙ s ( N ) , u 0 N | ( - Δ ) s 2 u ( x ) | 2 𝑑 x ( N | u ( x ) | 2 s , α * | y | α 𝑑 x ) 2 2 s , α * ,

which is associated with fractional Sobolev–Hardy inequalities with the weight 1|y|α:

( N | u ( x ) | 2 s , α * | y | α 𝑑 x ) 2 2 s , α * Λ s , N , k , α - 1 N | ( - Δ ) s 2 u ( x ) | 2 𝑑 x ,

where x=(y,z)k×N-k, 0<α<2s, N>2s and 2s,α*=2(N-α)N-2s. We refer to the weight 1|y|α as partial weight. The space H˙s(N) is defined as the completion of C0(N) under the norm

u H ˙ s ( N ) = ( N | ξ | 2 s | u ^ ( ξ ) | 2 𝑑 ξ ) 1 2 ,

where u^ denotes the Fourier transform of u. We define the operator (-Δ)s2, s, by the Fourier transform

( ( - Δ ) s 2 u ( ξ ) ) ^ = | ξ | s u ^ ( ξ )

for uC0(N). Therefore, for s>0, we have

( - Δ ) s 2 u L 2 ( N ) 2 = N | ξ | 2 s | u ^ ( ξ ) | 2 𝑑 ξ .

It is well known that a minimizer u of Λs,N,k,α weakly solves the problem

( - Δ ) s u = | u | 2 s , α * - 2 u | y | α in N

up to a multiplying constant. The constant Λs,N,k,α is closely related to various best constants of Sobolev type embedding. Indeed, if s=1 and α=0, the constant Λs,N,k,α is reduced to the best Sobolev constant

S = inf u D 1 , 2 ( N ) , u 0 N | u ( x ) | 2 𝑑 x ( N | u ( x ) | 2 * 𝑑 x ) 2 2 * ,

where 2*=2NN-2, N3 and D1,2(N) is the closure of C0(N) under the norm

u D 1 , 2 ( N ) = ( N | u | 2 𝑑 x ) 1 2 .

It was shown in [2, 22] that S is achieved in N by a family of functions

U λ ( x ) = ( λ λ 2 + | x - x 0 | 2 ) N - 2 2

for λ>0. Such functions play an important role in studying the existence of solutions of critical elliptic problems, see [6].

If s=1, α0, then the constant Λs,N,k,α becomes the best Sobolev–Hardy constant

(1.2) S N , k , α = inf u D 1 , 2 ( N ) , u 0 N | u ( x ) | 2 𝑑 x ( N | u ( x ) | 2 α * | y | α 𝑑 x ) 2 2 α * ,

where 2α*=2(N-α)N-2, N3, 2kN. The extremal problem (1.2) is attained by a cylindrically symmetric decreasing function, see [3, 19] for details. A minimizer of SN,k,α weakly solves the problem

(1.3) - Δ u = | u | 2 α * - 2 u | y | α in N

up to a multiplying constant. Equation (1.3) is related to a model describing the dynamics of elliptic galaxies, see [4, 9]. Existence and symmetry of solutions were studied in [3, 19]. In the case α=1, all positive finite energy solutions of (1.3) were classified in [18]. Such solutions are given by

V ( y , z ) = ( ( N - 2 ) ( k - 1 ) ) N - 2 2 ( ( 1 + | y | ) 2 + | z | 2 ) N - 2 2

or its scaling and translations in the z-variable.

For N>2s, the fractional Sobolev embedding H˙s(N)L2NN-2s(N) was considered in [8, 10]. The continuity of this inclusion corresponds to the inequality

(1.4) u L 2 s * ( N ) 2 Λ s - 1 u H ˙ s ( N ) 2

with 2s*=2NN-2s. The best constant Λs in (1.4) was computed in [10]. Using the moving plane method for integral equations, Chen, Li and Ou classified in [8] the solutions of an integral equation related to the problem

(1.5) ( - Δ ) s u = | u | 2 s * - 2 u in N .

They showed that positive regular solutions of (1.5) are precisely given by

(1.6) U λ ( x ) = ( λ λ 2 + | x - x 0 | 2 ) N - 2 s 2

for λ>0 and x0N.

Recently, the second author showed in [25] that in the case k=N, the minimizing problem (1.1) is achieved by a positive, radially symmetric and strictly decreasing function.

In this paper, we investigate minimization problem (1.1). We first show that Λs,N,k,α is achieved, then we consider properties of minimizers, including symmetry and decay at infinity.

We commence with the existence of minimizers of problem (1.1). At the beginning, we justify that the problem is well defined in the sense that Λs,N,k,α>0. In the proof of this fact, we need to establish a fractional Hardy inequality with partial weights, or precisely the following result.

Theorem 1.1

Let N2s, N>k1 and 0<s<1. For uW˙s,p(N) if 1p<ks and for uW˙s,p(N\{0}) if p>ks, there holds

(1.7) N × N | u ( x ) - u ( x ) | p | x - x | N + p s 𝑑 x 𝑑 x 𝒟 N , k , s , p N | u ( x ) | p | y | p s 𝑑 x

with

𝒟 N , k , s , p = π N - k 2 Γ ( k + p s 2 ) Γ ( N + p s 2 ) 𝒞 k , s , p ,

where

(1.8) 𝒞 k , s , p = 2 0 1 r p s - 1 | 1 - r k - p s p | p Φ k , s , p ( r ) 𝑑 r

and

Φ k , s , p ( r ) : = | 𝕊 k - 2 | - 1 1 ( 1 - t 2 ) k - 3 2 ( 1 - 2 r t + r 2 ) k + p s 2 d t , k 2 ,
Φ 1 , s , p ( r ) : = 1 ( 1 - r ) 1 + p s + 1 ( 1 + r ) 1 + p s , k = 1 .

Inequality (1.7) is a fractional counterpart of Hardy’s inequality with partial weight. The classical Hardy’s inequality states that the inequality

(1.9) N | u | p 𝑑 x ( | N - p | p ) p N | u ( x ) | p | x | p 𝑑 x

holds for uC0(N) if 1p<N and for uC0(N\{0}) if p>N. The constant on the right-hand side of (1.9) is sharp and for p>1 this constant is not attained in the corresponding homogeneous Sobolev spaces W˙1,p(N) and W˙1,p(N\{0}), respectively, which are the completion of C0(N) and C0(N\{0}) with respect to the norm on the left-hand side of (1.9). Similarly, in [13], Frank and Seiringer proved a fractional analog of Hardy’s inequality (1.9):

(1.10) N × N | u ( x ) - u ( y ) | p | x - y | N + p s 𝑑 x 𝑑 y 𝒞 N , p , s N | u ( x ) | p | x | p s 𝑑 x

with 𝒞N,s,p given by (1.8), for uW˙s,p(N) if 1p<Ns and for uW˙s,p(N\{0}) if p>Ns. The best constant 𝒞N,s,p was shown in [24]. Inequality (1.10) is the particular case k=N of Theorem 1.1.

Now, we consider the existence of minimizers of problem (1.1). In general, this can be done by using the concentration-compactness principle in [16, 17]. Technically, the method involves an estimate of the commutator of smooth functions and fractional Laplacian if problem (1.1) is considered. Another way to deal with the problem is given in [20, 25] by a refinement of Sobolev–Hardy inequalities in terms of Morrey space p,γ (see Section 3 for its definition). Observing that Lévy concentration functions are special cases of norms of Morrey spaces, it is then possible to avoid directly using the concentration-compactness principle. For this purpose, we establish a refinement of Sobolev–Hardy inequalities with partial weight, which is of interest itself and stated as follows.

Theorem 1.2

For 0<s<N2, 0<α<2s, there exists C>0 such that for r and θ satisfying 1r<2s,α* and max{N-2sN-α,2s-αN-α}θ<1 there holds

(1.11) ( N | u | 2 s , α * | y | α 𝑑 x ) 1 2 s , α * C u H ˙ s θ u r , r ( N - 2 s ) / 2 1 - θ

for uH˙s(N), where 2s,α*=2(N-α)N-2s and x=(y,z)k×N-k.

Using inequality (1.11), we show that every minimizing sequence of Λs,N,k,α is compact up to translations and dilations. Hence, Λs,N,k,α is achieved. The result is as follows.

Theorem 1.3

Assume 0<s<N2, 0<α<2s. Let {un} be a minimizing sequence of Λs,N,k,α. Then, there exist a sequence {λn} with λn>0 and a sequence of points {zn}N-k, such that λn-(N-2s)/2un(x-xnλn) has a convergent subsequence, where xn=(0,zn)N. As a result, Λs,N,k,α is achieved.

It seems difficult to give a precise form as (1.6) for minimizers of Λs,N,k,α. In many cases, special properties of minimizers are adequate for further applications. Particularly, besides it is important itself, symmetric and decay property of minimizers are significant in studying existence of solutions for problems involving critical Sobolev–Hardy terms. Our next result concerns the symmetry of minimizers. We show that minimizers of Λs,N,k,α are cylindrically symmetric.

Theorem 1.4

Any positive minimizer u of Λs,N,k,α is cylindrically symmetric, i.e., if Λs,N,k,α is attained at a positive function uH˙s(N), then

  1. u ( , z ) is symmetric decreasing in k for z N - k ;

  2. there exists z0N-k such that u(y,) is symmetric decreasing about z0 in N-k for yk, y0.

Theorem 1.4 is proved by the argument in [19]. It requires an equivalent partial weighted Hardy–Littlewood–Sobolev inequality, which is established in Section 5. This inequality, combined with a weighted Riesz’s rearrangement inequality, enables us to prove Theorem 1.4.

Finally, we establish the following decaying laws for the minimizers.

Theorem 1.5

Suppose u is a positive minimizer of Λs,N,k,α. Then, there exist positive constants C2>C1>0 such that, for xN,

C 1 1 + | x | N - s u ( x ) C 2 1 + | x | N - s .

In proving Theorem 1.5, we consider the related extension problem. Hence, we show a Harnack inequality by Nash–Moser iteration. An application of the Harnack inequality to the Kelvin transform of the minimizer yields the result.

The paper is organized as follows. In Section 2, we establish a sharp fractional Hardy inequality with partial weight. Then, we establish the improved Sobolev–Hardy inequality in Section 3. Theorem 1.3 and Theorem 1.4 are proved in Sections 4 and 5, respectively. Finally, in Section 6, we establish the decaying law for the minimizer u of Λs,N,k,α.

2 Fractional Hardy Inequality with Partial Weight

In this section, we show the Hardy type inequality with the fractional Laplacian, that is, we will prove Theorem 1.1. The following result was shown in [13].

Lemma 2.1

There holds

2 lim ε 0 { y k : | | y | - | y | | > ε } ( | y | - β - | y | - β ) | | y | - β - | y | - β | p - 2 | y - y | N + p s 𝑑 y = 𝒞 k , s , p | y | p s + β ( p - 1 )

for y uniformly in compact sets in k\{0}, where 𝒞k,s,p is defined in (1.8).

Suppose N2s, k1, 0<s<1 and denote x=(y,z)k×N-k, x=(y,z)k×N-k. We have a counterpart of Lemma 2.1 for partial Hardy weights.

Lemma 2.2

There holds

2 lim ε 0 { x N : | | y | - | y | | > ε } ( | y | - β - | y | - β ) | | y | - β - | y | - β | p - 2 | x - x | N + p s 𝑑 x = 𝒟 N , k , s , p | y | p s + β ( p - 1 )

for x uniformly in compact sets in N\{0}, where 𝒟N,k,s,α is given in Theorem 1.1.

Proof.

By [1, (6.2.1), (6.2.2)] we have

N - k 1 ( r 2 + | z - z | 2 ) N + p s 2 𝑑 z = | 𝕊 N - k - 1 | r - k - p s 0 r N - k - 1 ( r 2 + 1 ) N + p s 2 𝑑 r
= | 𝕊 N - k - 1 | r - k - p s 1 2 0 t N - k 2 - 1 ( t + 1 ) N - k 2 + k + p s 2 𝑑 t
= 1 2 r - k - p s | 𝕊 N - k - 1 | Γ ( N - k 2 ) Γ ( k + p s 2 ) Γ ( N + p s 2 ) .

Thus we deduce from Lemma 2.1 that

2 lim ε 0 { x N : | | y | - | y | | > ε } ( | y | - β - | y | - β ) | | y | - β - | y | - β | p - 2 1 ( | y - y | 2 + | z - z | 2 ) N + p s 2 𝑑 x
= 2 lim ε 0 { y k : | | y | - | y | | > ε } ( | y | - β - | y | - β ) | | y | - β - | y | - β | p - 2 ( N - k 1 ( | y - y | 2 + | z - z | 2 ) N + p s 2 𝑑 z ) 𝑑 y
= | 𝕊 N - k - 1 | Γ ( N - k 2 ) Γ ( k + p s 2 ) Γ ( N + p s 2 ) lim ε 0 { y k : | | y | - | y | | > ε } ( | y | - β - | y | - β ) | | y | - β - | y | - β | p - 2 | y - y | k + p s 𝑑 y
= 1 2 | 𝕊 N - k - 1 | Γ ( N - k 2 ) Γ ( k + p s 2 ) Γ ( N + p s 2 ) 𝒞 k , s , p | y | p s + β ( p - 1 )
= π N - k 2 Γ ( k + p s 2 ) Γ ( N + p s 2 ) 𝒞 k , s , p | y | p s + β ( p - 1 ) .

Now, inequality (1.7) follows by the approach of Frank and Seiringer [13]. Their proof relies on a ground state substitution, i.e., it relies on writing u(x)=ω(x)v(x), where ω(x)=|x|-(N-ps)/p is a solution of the Euler–Lagrange equation corresponding to (1.10).

Proof of Theorem 1.1.

We choose in [13, Assumption 2.1] that

ω ( x ) = | y | - β , k ( x , x ) = | x - x | - N - p s , V ( x ) = 𝒟 N , k , s , p | y | - p s ,

where x=(y,z)k×N-k, x=(y,z)k×N-k, β=k-psp. Inequality (1.7) then follows by Lemma 2.2 and [13, Proposition 2.2]. ∎

3 Improved Sobolev–Hardy Inequality

In this section, we prove inequality (1.11). For each s0, we recall that the fractional Sobolev space H˙s(N) is defined by

H ˙ s ( N ) = { u : | ξ | s u ^ ( ξ ) L 2 ( N ) }

via the Fourier transform

u ^ ( ξ ) = 1 ( 2 π ) N 2 N e - i x ξ u ( x ) 𝑑 x .

For s(0,1), it is known from [11] that there holds

(3.1) N | ξ | 2 s | u ^ ( ξ ) | 2 𝑑 ξ = C s , N N N | u ( x ) - u ( y ) | 2 | x - y | N + 2 s 𝑑 x 𝑑 y ,

where

C s , N = 2 - 2 s π - s Γ ( N - 2 s 2 ) Γ ( N + 2 s 2 ) [ Γ ( N ) Γ ( N 2 ) ] 2 s N .

This provides an alternative norm

u H ˙ s ( N ) = ( N N | u ( x ) - u ( y ) | 2 | x - y | N + 2 s 𝑑 x 𝑑 y ) 1 2

of H˙s(N). Equation (3.1) and Theorem 1.1 imply, for N>2s, the fractional partial Hardy inequality

(3.2) N | u ( x ) | 2 | y | 2 s 𝑑 x 1 𝒟 N , k , s , 2 C s , N N | ξ | 2 s | u ^ ( ξ ) | 2 𝑑 ξ ,

where uH˙s(N). Let

L 2 s , α * ( N , | y | - α ) = { u : N | u | 2 s , α * | y | α 𝑑 x < }

with 2s,α*=2(N-α)N-2s. We claim that Λs,N,k,α defined in (1.1) is positive.

Lemma 3.1

Suppose 0<α<2s and N>2s. Then, there exists C>0 such that, for any uH˙s(N),

(3.3) ( N | u ( x ) | 2 s , α * | y | α 𝑑 x ) 2 2 s , α * C N | ( - Δ ) s 2 u ( x ) | 2 𝑑 x .

As a result, Λs,N,k,α>0.

Proof.

By partial Hardy’s inequality (3.2), Hölder’s inequality and the Sobolev inequality, we have

N | u ( x ) | 2 s , α * | y | α 𝑑 x = N | u ( x ) | α s | y | α | u ( x ) | 2 s , α * - α s 𝑑 x
( N | u ( x ) | 2 | y | 2 s 𝑑 x ) α 2 s ( N | u ( x ) | 2 N N - 2 s 𝑑 x ) 2 s - α 2 s
C ( N | ( - Δ ) s 2 u | 2 𝑑 x ) α 2 s ( N | ( - Δ ) s 2 u | 2 𝑑 x ) 2 s - α 2 s ,

which yields inequality (3.3). ∎

Now, we recall the definition of Morrey space. A measurable function u:N belongs to the Morrey space p,γ(N) with p[1,) and γ(0,N], if and only if

u p , γ ( N ) p = sup R > 0 , x N R γ - N B R ( x ) | u ( x ) | p 𝑑 y < .

By Hölder’s inequality, we may verify (as in [11]) that

L 2 s * ( N ) p , N - 2 s 2 p ( N ) for 1 p < 2 s *

and

p , N - 2 s 2 p ( N ) q , N - 2 s 2 q ( N ) for 1 < q < p < 2 s * .

Moreover, we have p,γ(N)1,γp(N) provided that p(1,) and γ(0,N).

Inequality (1.11) will be proved by the weighted estimates on Riesz potential in [21]. For any uH˙s(N), let gL2(N) be a function such that g^(ξ)=|ξ|su^(ξ). By Plancherel’s theorem we have

u H ˙ s ( N ) = ( - Δ ) s 2 u L 2 ( N ) = g L 2 ( N ) .

Thus,

u ( x ) = ( 1 | ξ | s ) * g ( x ) = s g ( x ) ,

where sg denotes the Riesz potential of order s, namely

s g ( x ) = N g ( y ) | x - y | N - s 𝑑 y .

The following result was established in [21].

Lemma 3.2

Suppose 0<s<N, 1<pq<, N1, and that V and W are nonnegative measurable functions on N. If, for some σ>1,

(3.4) | Q | s N + 1 q - 1 p ( 1 | Q | Q V σ 𝑑 x ) 1 q σ ( 1 | Q | Q W ( 1 - p ) σ 𝑑 x ) 1 p σ C σ

for all cubes QN, then for any function fLp(N,W(x)dx) we have

( N | s f ( x ) | q V ( x ) 𝑑 x ) 1 q C C σ ( N | f ( x ) | p W ( x ) 𝑑 x ) 1 p .

Proof of Theorem 1.2.

Choose in (3.4) W1 and p=2. Then (3.4) becomes

(3.5) | Q | s N + 1 q - 1 2 ( 1 | Q | Q V σ 𝑑 x ) 1 q σ C σ ,

where σ>1 is to be determined. For any fixed q, 2q<2s,α* and uH˙s(N), we choose V=|u|2s,α*-q|y|α, and then, for any xN,

| u | 2 s , α * | y | α = | u | q | u | 2 s , α * - q | y | α = V ( x ) | u | q .

Now, we verify condition (3.5). Replacing Q by the ball BR(x0) and choosing q and then σ so that (2s,α*-q)σ<1, we deduce by Hölder’s inequality that

R - N B R ( x 0 ) V σ 𝑑 x = R - N B R ( x 0 ) | u | ( 2 s , α * - q ) σ | y | σ α 𝑑 x
R - N ( B R ( x 0 ) 1 | y | α σ 1 - ( 2 s , α * - q ) σ 𝑑 x ) 1 - ( 2 s , α * - q ) σ ( B R ( x 0 ) | u | 𝑑 x ) ( 2 s , α * - q ) σ
C R - ( 2 s , α * - q ) N σ - α σ ( B R ( x 0 ) | u | 𝑑 x ) ( 2 s , α * - q ) σ .

Hence,

R s + N q - N 2 ( R - N B R ( x 0 ) V σ 𝑑 x ) 1 q σ C ( R ( s + N q - N 2 ) q 2 s , α * R - N B R ( x 0 ) | u | 𝑑 x ) 2 s , α * - q q

= C ( R N - 2 s 2 R - N B R ( x 0 ) | u | 𝑑 x ) 2 s , α * - q q
C u 1 , N - 2 s 2 2 s , α * - q q = C u γ , N - 2 s 2 γ 2 s , α * - q q = : C σ .

Since u=sg, and by Lemma 3.2,

N | u | 2 s , α * | y | α 𝑑 x = s g L q ( N , V d x ) q ( C C σ ) q g L 2 q C u H ˙ s q u r , r ( N - 2 s ) / 2 2 s , α * - q .

Therefore, (1.11) holds with θ=q2s,α*. ∎

4 Minimizer of Λs,N,k,α

In this section, we show that Λs,N,k,α is achieved. Precisely, we will prove Theorem 1.3. Further properties of minimizers of Λs,N,k,α will be discussed in the next section.

Proof of Theorem 1.3.

Let {un} be a minimizing sequence of Λs,N,k,α, that is,

u n H ˙ s 2 Λ s , N , k , α , N | u n | 2 s , α * | y | α 𝑑 x = 1 .

This, together with Theorem 1.2, yields

u n 2 , N - 2 s C > 0 .

On the other hand, by Hölder’s inequality we have L2s*(N)2,N-2s(N). This and the inclusion H˙s(N)L2s*(N) yield H˙s(N)2,N-2s(N), which implies

u n 2 , N - 2 s C .

Thus, there exists C>0 such that

0 < C u n 2 , N - 2 s C - 1 .

So we may find λn>0 and xnN such that

(4.1) λ n - 2 s B λ n ( x n ) | u n ( x ) | 2 𝑑 x u n 2 , N - 2 s 2 - C 2 n C 1 > 0 .

Now we set

v n ( x ) = λ n N - 2 s 2 u n ( λ n x ) .

In view of the scaling invariance of the H˙s(N) norm, the sequence {vn} is bounded in H˙s(N), therefore, vnv in H˙s(N) up to subsequences. Since Λs,N,k,α is invariant under the dilations given by vn, we see that {vn} is also a minimizing sequence of Λs,N,k,α. Thus it remains to show that vnv strongly in H˙s(N) and v0.

Now, we prove that v0. Inequality (4.1) implies

B 1 ( x n ) | v n ( x ) | 2 𝑑 x C 1 > 0 ,

where we denote xn/λn simply by xn. Denote xn=(yn,zn)k×N-k, xn=(0,zn). We observe that by Hölder’s inequality and the rearrangement inequality (see [15, Theorem 3.4]),

0 < C 1 B 1 ( x n ) | v n ( x ) | 2 𝑑 x
= B 1 ( x n ) | y | 2 α / 2 s , α * | v n ( x ) | 2 | y | 2 α / 2 s , α * 𝑑 x

C ( B 1 ( x n ) | y | α 2 s - α 𝑑 x ) 2 s - α α ( B 1 ( x n ) | v n ( x ) | 2 s , α * | y | α 𝑑 x ) 2 2 s , α *
C ( B 1 ( x n ) | v n ( x ) | 2 s , α * | y | α 𝑑 x ) 2 2 s , α * .

Therefore,

(4.2) B 1 ( x n ) | v n ( x ) | 2 s , α * | y | α 𝑑 x C > 0 .

We claim that {yn} is bounded. Indeed, if on the contrary, |yn|, then for any x=(y,z)B1(xn), |y||yn|-1 for n large. Therefore,

B 1 ( x n ) | v n ( x ) | 2 s , α * | y | α 𝑑 x 1 ( | y n | - 1 ) α B 1 ( x n ) | v n ( x ) | 2 s , α * 𝑑 x
1 ( | y n | - 1 ) α ( B 1 ( x n ) | v n ( x ) | 2 N N - 2 s 𝑑 x ) N - α N
1 ( | y n | - 1 ) α v n H ˙ s ( N ) N - α N
C ( | y n | - 1 ) α 0

as n, which contradicts (4.2). Hence, {yn} is bounded. Let v~n(x)=vn(x,y-yn). The sequence {v~n} is again a minimizing sequence. So we may find R>0 so that

B R ( 0 ) | v ~ n ( y ) | 2 𝑑 y C 1 > 0 .

The compact embedding H˙s(N)Lloc2(N) implies that v~nv~ in L2(BR(0)) and v~0. We also have v~nv~ almost everywhere in N.

As in the proof of the Brézis–Lieb lemma in [5] we may verify that

(4.3) 1 = N | v ~ n | 2 s , α * | y | α 𝑑 x = N | v ~ | 2 s , α * | y | α 𝑑 x + N | v ~ n - v ~ | 2 s , α * | y | α 𝑑 x + o ( 1 ) .

Since {v~n} is a minimizing sequence, we have

Λ s , N , k , α = lim n N | ( - Δ ) s 2 v ~ n | 2 𝑑 x .

By the weak convergence v~nv~ in H˙s(N) and (4.3),

Λ s , N , k , α = lim n N | ( - Δ ) s 2 v ~ n | 2 𝑑 x
= N | ( - Δ ) s 2 v ~ | 2 𝑑 x + lim n N | ( - Δ ) s 2 ( v ~ n - v ~ ) | 2 𝑑 x
Λ s , N , k , α ( N | v ~ | 2 s , α * | y | α 𝑑 x ) 2 2 s , α s + Λ s , N , k , α ( lim n N | v ~ n - v ~ | 2 s , α * | y | α 𝑑 x ) 2 2 s , α s
Λ s , N , k , α ( N | v ~ | 2 s , α * | y | α 𝑑 x + lim n N | v ~ n - v ~ | 2 s , α * | y | α 𝑑 x ) 2 2 s , α s = Λ s , N , k , α .

This gives

Λ s , N , k , α = N | ( - Δ ) s 2 v ~ | 2 𝑑 x , lim n N | ( - Δ ) s 2 ( v ~ n - v ~ ) | 2 𝑑 x = 0 .

Therefore, Λs,N,k,α is achieved. ∎

5 Cylindrical Symmetry of Extremals of the Fractional Partial Sobolev–Hardy Inequality

In this section, we discuss symmetric properties for minimizers of Λs,N,k,α. Inspired by [19], we first establish an equivalent weighted partial Hardy–Littlewood–Sobolev inequality, Proposition 5.1. Then, combining a weighted Riesz’s rearrangement inequality and [19, Lemma 3.2], we prove Theorem 1.4.

It is known from Section 4 that

(5.1) ( N | u ( x ) | 2 s , α * | y | α 𝑑 x ) 2 2 s , α * 1 Λ s , N , k , α N | ( - Δ ) s 2 u ( x ) | 2 𝑑 x .

We rewrite inequality (5.1) as

(5.2) ( N | u ( x ) | p σ | y | σ p σ 𝑑 x ) 2 p σ 1 Λ s , N , k , σ N | ( - Δ ) s 2 u ( x ) | 2 𝑑 x ,

where 0<σ<s and pσ=2NN-2s+2σ. The best constant in (5.2),

(5.3) S s , N , k , σ := 1 Λ s , N , k , σ = sup u H ˙ s ( N ) , N | ( - Δ ) s 2 u | 2 = 1 ( N | u ( x ) | p σ | y | σ p σ 𝑑 x ) 2 p σ ,

is attained by uH˙s(N), which satisfies

N | u ( x ) | p σ - 2 u φ | y | σ p σ 𝑑 x = ( S s , N , k , σ ) p σ 2 N ( - Δ ) s 2 u ( - Δ ) s 2 φ for all φ H ˙ s ( N ) .

Let Gs(x)=C|x|N-2s be the fundamental solutions of (-Δ)s in N.

Proposition 5.1

Let σ[0,s), p=pσ=2NN-2s+2σ, 1p+1q=1. Suppose x=(y,z), x=(y,z) are two different points in N=k×N-k. Then

(5.4) sup h L q ( N ) , h q = 1 N N h ( x ) | y | σ G s ( x - x ) h ( x ) | y | σ 𝑑 x 𝑑 x = S s , N , k , σ .

Moreover, u is an extremal for (5.3) if and only if f:=|u|p-2u|y|σ(p-1) is an extremal for (5.4).

Proof.

First, we show the following doubly partial weighted Hardy–Littlewood–Sobolev inequality:

(5.5) N N f ( x ) | y | σ G s ( x - x ) g ( x ) | y | σ 𝑑 x 𝑑 x S s , N , k , σ f q g q for all f , h L q .

By a density argument, it is sufficient to prove (5.5) for positive functions in C0(N). For any gC0(N), let gσ(x)=g(x)|y|σ. Then, gσL2NN+2s(N).

Set u=Gsgσ=I2s(gσ). By the Fourier transforms of |x|γ-N, see [15, Theorem 5.9] and Plancherel’s identity, we obtain

| ξ | s u ^ L 2 = C | ξ | s | ξ | - 2 s g σ ^ L 2 = C | ξ | - s g σ ^ L 2 = C ( | ξ | - s + N g σ ) ^ L 2 = C I s ( g σ ) L 2 ,

and the classical Hardy–Littlewood–Sobolev inequality implies

I s ( g σ ) L 2 C g σ 2 N N + 2 s .

Consequently, |ξ|su^L2(N), and thus GsgσH˙s(N).

On the other hand, since Gs=C|x|N-2s is the fundamental solution of (-Δ)s in N, by the Parseval identity, we deduce for any φH˙s(N) that

N ( - Δ ) s 2 φ ( - Δ ) s 2 ( G s g σ ) 𝑑 x = ( 2 π ) - N N | ξ | s φ ^ ( ξ ) | ξ | s ( G s g σ ) ^ ( ξ ) 𝑑 ξ
(5.6) = N φ ( - Δ ) s ( G s g σ ) 𝑑 x = N φ g σ 𝑑 x .

If 0<σ<s, by Hölder’s inequality and (5.2), we have

f q ( N | G s g σ | p | y | σ p 𝑑 x ) 1 p .
(5.7) N ( G s g σ ) f σ 𝑑 x = N G s g σ | y | σ f σ | y | σ 𝑑 x
(5.8) f q ( S s , N , k , σ N | ( - Δ ) s 2 ( G s g σ ) | 2 𝑑 x ) 1 2 .

Choosing φ=Gsgσ in (5.6), we find by (5.8) that

N | ( - Δ ) s 2 ( G s g σ ) | 2 𝑑 x = N ( G s g σ ) g σ 𝑑 x g q ( S s , N , k , σ N | ( - Δ ) s 2 ( G s g σ ) | 2 𝑑 x ) 1 2 ,

that is,

(5.9) ( N | ( - Δ ) s 2 ( G s g σ ) | 2 𝑑 x ) 1 2 g q S s , N , k , σ 1 2 .

By (5.8) and (5.9), we see that (5.5) holds true for f,gC0. A density argument gives the result.

If σ=0, by the classical Hardy–Littlewood–Sobolev inequality again, we obtain GsgL2NN-2s(N) for gL2NN+2s(N). As a result, GsgH˙s(N) and (5.6) holds for gL2NN+2s(N), namely, for gL2NN+2s(N) and any φH˙s(N),

N φ ( - Δ ) s ( G s g ) 𝑑 x = N φ g 𝑑 x .

Now, equation (5.5) implies

(5.10) Λ := sup f q = 1 N N f ( x ) | y | σ G s ( x - x ) f ( x ) | y | σ 𝑑 x 𝑑 x S s , N , k , σ .

Next, we prove the reverse inequality. Since σ<1, Λs,N,k,α-1 is achieved by a nonnegative extremal function u, or equivalently, problem (5.3) is achieved by u. Note |u| is an extremal as well, it thus solves (5.3). We may assume that

(5.11) N | u | p | y | σ p 𝑑 x = 1 , N | u | p - 1 φ | y | σ p 𝑑 x = S s , N , k , σ N ( - Δ ) s 2 u ( - Δ ) s 2 φ for all φ H ˙ s ( N ) .

If

f := u p - 1 | y | σ ( p - 1 ) ,

then

N f q 𝑑 x = N u p | y | σ p 𝑑 x = 1 .

In particular, as noted above, we have that GsfσH˙s(N). By (5.11),

S s , N , k , σ N u f σ 𝑑 x = S s , N , k , σ N ( - Δ ) s 2 u ( - Δ ) s 2 ( G s f σ ) 𝑑 x = N | u | p - 1 | y | σ p G s f σ 𝑑 x .

By the fact that fσ=up-1|y|σp and Nfq=1, we have

S s , N , k , σ = N f σ G s f σ Λ .

This, together with (5.10), yields that Λ=Ss,N,k,σ and f=up-1|y|σ(p-1) is an extremal function for (5.4).

Finally, let f be an extremal function for the weighted Hardy–Littlewood–Sobolev quotient (5.4). We may assume f0. Therefore, for any gLq(N),

f q = 1 and N N f ( x ) | y | σ G s ( x - x ) g ( x ) | y | σ 𝑑 x 𝑑 x = S s , N , k , σ N f q - 1 g 𝑑 x .

Let u:=fq-1|y|σ, so that |u|p-1|y|σ(p-1)=fLq(N). The Euler–Lagrange equation for f can be rewritten as

N N g ( x ) | y | σ G s ( x - x ) u p - 1 ( x ) | y | σ p 𝑑 x 𝑑 x = S s , N , k , σ N u | y | σ g 𝑑 x for all g L q ( N ) .

In particular, we find that Ss,N,k,σu=Gsfσ and hence, as remarked above, uH˙s(N) and

S s , N , k , σ ( - Δ ) s u = f σ = | y | - σ p u p - 1 .

Thus

S s , N , k , σ N | ( - Δ ) s 2 | 2 𝑑 x = N | y | - σ p u p 𝑑 x = N f q 𝑑 x = 1 .

That is, u is an extremal function for the partial Hardy–Littlewood–Sobolev inequality. ∎

A function f:N is said to be vanishing at if it satisfies |{|f|>t}|< for all t>0, where || denotes the Lebesgue measure.

For a function f vanishing at infinity we denote by f its symmetric decreasing rearrangement. Now, we state the classical Riesz’s rearrangement inequality, which can be found in [15].

Lemma 5.2

Let f,g,h be three nonnegative functions on N, vanishing at . Then

(5.12) N N f ( x ) g ( x - x ) h ( x ) 𝑑 x 𝑑 x N N f ( x ) g ( x - x ) h ( x ) 𝑑 x 𝑑 x .

Moreover, if g is strictly symmetric decreasing, then equality holds in (5.12) if and only if f(x)=f*(x-x0) and h(x)=h*(x-x0) for some common x0N.

The following weighted Riesz’s rearrangement inequality can be found in [19].

Lemma 5.3

Let f,g,h be three nonnegative functions on N, vanishing at . Then

(5.13) N N f ( x ) | x | σ g ( x - x ) h ( x ) | x | σ 𝑑 x 𝑑 x N N f ( x ) | x | σ g ( x - x ) h ( x ) | x | σ 𝑑 x 𝑑 x .

Moreover, if g=g, then equality holds in (5.13) if and only if f=f* and h=h*.

Proof of Theorem 1.4.

By Proposition 5.1, we need only to show that the extremals of (5.4) have the required cylindrical symmetry. Suppose hLq(N) satisfies

N h q = 1 , N N h ( x ) | y | σ G s ( x - x ) h ( x ) | y | σ 𝑑 x 𝑑 x = S s , N , k , σ .

Let h* and h′′* be the rearrangement of h in k-dimensional and N-k-dimensional variables, respectively. That is, for yk, zN-k, we have h*(,z)=h(,z)* and h′′*(y,)=h(y,)*.

Noticing that Gs is strictly symmetric decreasing and using the fact that h is an extremal of (5.4), we obtain from Lemma 5.3 that N(h*)q=1 and

S s , N , k , σ = N N h ( x ) | y | σ G s ( x - x ) h ( x ) | y | σ 𝑑 x 𝑑 x
N - k N - k ( k k h * ( y , z ) | y | σ G s ( y - y , z - z ) h * ( y , z ) | y | σ 𝑑 y 𝑑 y ) 𝑑 z 𝑑 z
= N N h * ( x ) | y | σ G s ( x - x ) h * ( x ) | y | σ 𝑑 x 𝑑 x S s , N , k , σ .

Therefore,

S s , N , k , σ = N N h ( x ) | y | σ G s ( x - x ) h ( x ) | y | σ 𝑑 x 𝑑 x = N N h * ( x ) | y | σ G s ( x - x ) h * ( x ) | y | σ 𝑑 x 𝑑 x .

By Lemma 5.3, h(,z) is symmetrically decreasing for almost all zN-k.

On the other hand, by Lemma 5.2, we have N(h′′*)q=1 and

S s , N , k , σ = k k 1 | y | σ 1 | y | σ ( N - K N - k h ( y , z ) G s ( y - y , z - z ) h ( y , z ) 𝑑 z 𝑑 z ) 𝑑 y 𝑑 y
k k 1 | y | σ 1 | y | σ ( N - k N - k h ′′ * ( y , z ) G s ( y - y , z - z ) h ′′ * ( y , z ) 𝑑 z 𝑑 z ) 𝑑 y 𝑑 y
= N N h ′′ * ( x ) | y | σ G s ( x - x ) h ′′ * ( x ) | y | σ 𝑑 x 𝑑 x S s , N , k , σ .

Thus, Lemma 5.2 implies that there exists z0N-k such that zh(y,z+z0) is symmetrically decreasing in N-k. This completes the proof of Theorem 1.4. ∎

6 Decay

In this section, we investigate the decaying law of the minimizer u of Λs,N,k,α. We may assume that the minimizer u satisfies

(6.1) ( - Δ ) s 2 u = u 2 s , β * - 1 ( x ) | y | β in N .

Denote by H0,L1(+N+1) the completion of C0(+N+1) under the norm

w H 0 , L 1 ( + N + 1 ) = ( κ α + N + 1 t 1 - α | w | 2 𝑑 x 𝑑 t ) 1 2 .

The space H0,L1(+N+1) is isometric to H˙s(N) by a trace operator, see [7]. By inequality (5.1), we have the following trace type inequality:

(6.2) ( N | w ( x , 0 ) | 2 s , α * | y | α 𝑑 x ) 2 2 s , α * C + N + 1 t 1 - α | w | 2 𝑑 x 𝑑 t

for some positive constant C independent of w. It is standard to know, see [7], that there is a unique extension function wH0,L1(+N+1) of u satisfying

(6.3) { div ( t 1 - s w ) = 0 in + N + 1 , lim t 0 ( t 1 - s w ν ) = w 2 s , β * - 1 | y | β in N .

Hence, it is sufficient to consider problem (6.3). For this purpose, we first consider the linear boundary value problem

(6.4) { div ( t 1 - s w ) = 0 in + N + 1 , lim t 0 ( t 1 - s w ν ) = f ( x ) | y | β w in N ,

where f is a fixed function.

Denote by X=(x,t) with xN and t a point in N+1. Let w(X) be a nonnegative measurable function in N+1. We say w is of class A2 if there exists a constant Cw such that, for any ball BN+1,

( 1 | B | B w ( X ) 𝑑 X ) ( 1 | B | B w - 1 ( X ) 𝑑 X ) C w ,

where || denotes the Lebesgue measure.

Denote QR=BR×(0,R), QR=BR×{0} and ′′QR=QR\QR. By the same argument as in [12, Theorem 1.2], the following result is obtained in [23].

Lemma 6.1

Let f(X)Cc1(QRQR) and w(X)A2. Then there exist constants C and δ>0 depending only on n and Cw such that, for any 1kN+1N+δ,

( 1 w ( Q R ) Q R | f | 2 k w 𝑑 X ) 1 2 k C R ( 1 w ( Q R ) Q R | f | 2 w 𝑑 X ) 1 2 ,

where w(QR)=QRw(X)𝑑X.

For p(0,) and ΩN+1, we denote by

L p ( t 1 - s , Ω ) = { u : Ω t 1 - s | w | p 𝑑 x 𝑑 t < }

the weighted space with the norm

w L p ( t 1 - s , Ω ) := ( Ω t 1 - s | w | p 𝑑 x 𝑑 t ) 1 p .

Now, we have the following Harnack type inequality.

Lemma 6.2

Suppose fLN-βs-β(N,1|y|βdx), and wH0,L1(+N+1) is a positive solution of (6.4). Then,

sup Q θ R w C ( R ( 1 - θ ) ) N + 2 - s p w L p ( t 1 - 2 s , Q R ) ,

where C>0 depends only on N,s.

Proof.

Suppose 0<ri+1<ri<R1. Let ξC01(Q1Q1) with ξ=1 in Qri+1, ξ=0 outside Qri and |ξ|2ri+1-ri. Let k>0 be any number which is eventually sent to 0. Set q=p2* and w¯=w+k. Define

w ¯ m = { w ¯ if w ¯ < m , k + m if w ¯ m .

Choosing the test function

η = ξ 2 ( w ¯ m 2 q - 2 w ¯ - k 2 q - 1 ) H 0 , L 1 ( + N + 1 ) ,

we have

+ N + 1 t 1 - s w η d x d t = N f ( x ) | y | β w η 𝑑 x .

We deduce

+ N + 1 t 1 - s w η d x d t = + N + 1 t 1 - s ξ 2 w ¯ m 2 q - 2 [ ( 2 q - 2 ) | w ¯ m | 2 + | w | 2 ] 𝑑 x 𝑑 t
+ 2 + N + 1 t 1 - s ξ ( w ¯ m 2 q - 2 w ¯ - k 2 q - 1 ) ξ w d x d t
+ N + 1 t 1 - s ξ 2 w ¯ m 2 q - 2 [ ( 2 q - 2 ) | w ¯ m | 2 + | w | 2 ] 𝑑 x 𝑑 t
- + N + 1 t 1 - s ( 2 | ξ | 2 w ¯ m 2 q - 2 w ¯ 2 + 1 2 ξ 2 w ¯ m 2 q - 2 | w | 2 ) 𝑑 x 𝑑 t .
1 2 + N + 1 t 1 - s ξ 2 w ¯ m 2 q - 2 [ ( 2 q - 2 ) | w ¯ m | 2 + | w | 2 ] 𝑑 x 𝑑 t
(6.5) - 2 + N + 1 t 1 - s | ξ | 2 w ¯ m 2 q - 2 w ¯ 2 𝑑 x 𝑑 t .

Let U=w¯mq-1w¯. We have

| U | 2 2 ( 2 q - 1 ) [ ( 2 q - 2 ) w ¯ m 2 q - 2 | w ¯ m | 2 + w ¯ m 2 q - 2 | w ¯ | 2 ] ,

and then

+ N + 1 t 1 - s | ( ξ U ) | 2 𝑑 x 𝑑 t 2 ( + N + 1 t 1 - s ξ 2 | U | 2 𝑑 x 𝑑 t + + N + 1 t 1 - s U 2 | ξ | 2 𝑑 x 𝑑 t )
4 ( 2 q - 1 ) + N + 1 t 1 - s ξ 2 w m 2 q - 2 ( ( 2 q - 2 ) w ¯ m | 2 + | w ¯ | 2 ) d x d t
(6.6) + 2 + N + 1 t 1 - s U 2 | ξ | 2 𝑑 x 𝑑 t .

Equations (6.5) and (6.6) yield

+ N + 1 t 1 - s w η d x d t 1 8 ( 2 q - 1 ) + N + 1 t 1 - s | ( ξ U ) | 2 𝑑 x 𝑑 t - C ( r i - r i + 1 ) 2 Q r i t 1 - s U 2 𝑑 x 𝑑 t .

On the other hand, by Hölder’s inequality and (6.2),

N f ( x ) w ( x , 0 ) | y | β η ( x , 0 ) 𝑑 x ( N supp ξ | f ( x ) | N - β s - β | y | β 𝑑 x ) N - β s - β ( N | ξ U ( x , 0 ) | 2 s , α * | y | β 𝑑 x ) 2 2 s , α *
C ( N supp ξ | f ( x ) | N - β s - β | y | β 𝑑 x ) α - s N - s + N + 1 t 1 - s | ( ξ U ) | 2 𝑑 x 𝑑 t .

Since fLN-βs-β(N,1|y|βdx), we may choose R>0 small so that

Q r i + 1 t 1 - s | U | 2 𝑑 x 𝑑 t + N + 1 t 1 - s | ( ξ U ) | 2 𝑑 x 𝑑 t C ( 2 q - 1 ) ( r i - r i + 1 ) 2 Q r i t 1 - s U 2 𝑑 x 𝑑 t .

Observing that t1-sA2,

Q r i + 1 t 1 - s 𝑑 X = C N , s r i + 1 N + 2 - s ,

and invoking Lemma 6.1, we obtain

(6.7) ( Q r i + 1 t 1 - s U 2 χ 𝑑 x 𝑑 t ) 1 χ C ( 2 q - 1 ) r i + 1 N + s N + 1 ( r i - r i + 1 ) 2 Q r i t 1 - s U 2 𝑑 x 𝑑 t ,

where χ=N+1N>1. Since w¯mw¯, for γ=2, inequality (6.7) becomes

( Q r i + 1 t 1 - s w ¯ m γ χ 𝑑 x 𝑑 t ) 1 χ C ( 2 q - 1 ) r i + 1 N + s N + 1 ( r i - r i + 1 ) 2 Q r i t 1 - s w ¯ γ 𝑑 x 𝑑 t

provided that the integral on the right-hand side is bounded. Letting m, we conclude that

(6.8) w ¯ L γ χ ( t 1 - s , Q r i + 1 ) C ( r i + 1 N + s N + 1 ( r i - r i + 1 ) 2 ) 1 γ w ¯ L γ ( t 1 - s , Q r i ) ,

where C is a positive constant independent of γ.

To prove the lemma, we iterate (6.8). For i=0,1,2,, define γi=2χi and ri=R(θ+1-θ2i),θ(0,1). Then χγi=γi+1,ri-ri+1=R(1-θ)2i+1 and hence from (6.8), with γ=γi, we have

w ¯ L γ i + 1 ( t 1 - s , Q r i + 1 ) C ( ( R ( θ + 1 - θ 2 i + 1 ) ) N + s N + 1 ( R ( 1 - θ ) 2 i + 1 ) 2 ) 1 γ i w ¯ L γ i ( t 1 - s , Q r i )
( C ( R ( 1 - θ ) ) N + 2 - s N + 1 ) 1 γ i ( 4 i ) 1 γ i w ¯ L γ i ( t 1 - s , Q r i )

provided w¯Lγi(t1-s,Qri)<. Hence, by iteration we obtain

w ¯ L γ i + 1 ( t 1 - s , Q r i + 1 ) ( C ( R ( 1 - θ ) ) N + 2 - s N + 1 ) 1 γ i 4 i γ i w ¯ L 2 ( t 1 - s , Q R ) .

Letting i, we obtain

(6.9) sup Q θ R w ¯ C ( R ( 1 - θ ) ) N + 2 - s 2 w ¯ L 2 ( t 1 - s , Q R ) .

Now, we turn to the case p>2. Since

w ¯ L 2 ( t 1 - s , Q R ) = ( Q R t 1 - s w ¯ 2 𝑑 x 𝑑 t ) 1 2
( Q R t 1 - s w ¯ p 𝑑 x 𝑑 t ) 1 p ( Q R t 1 - s 𝑑 x 𝑑 t ) 1 2 - 1 p
(6.10) = C R ( N + 2 - s ) ( 1 2 - 1 p ) w ¯ L p ( t 1 - s , Q R ) ,

it readily follows from (6.9) and (6.10) that

sup Q θ R w ¯ C ( 1 - θ ) N + 2 - s 2 R N + 2 - s p w ¯ L p ( t 1 - s , Q R ) .

Finally, we consider the case 0<p<2. By (6.9),

sup Q θ R w ¯ C ( R ( 1 - θ ) ) N + 2 - s 2 ( Q R t 1 - s | w ¯ | 2 𝑑 x 𝑑 t ) 1 2
C ( R ( 1 - θ ) ) N + 2 - s 2 ( sup Q R w ¯ ) 1 - p 2 ( Q R t 1 - s | w ¯ | p 𝑑 x 𝑑 t ) 1 2 .

Using Young’s inequality, we obtain

sup Q θ R w ¯ 1 2 sup Q R w ¯ + C ( R ( 1 - θ ) ) N + 2 - s p ( Q R t 1 - s | w ¯ | p 𝑑 x 𝑑 t ) 1 p .

Denote ψ(l)=supQlw¯. Choose l=θR and t=R. Then

ψ ( l ) 1 2 ψ ( t ) + C ( t - l ) N + 2 - s p w ¯ L p ( t 1 - s , Q R )

for 0<l<tR. By [14, Lemma 4.3], we have

ψ ( θ R ) C ( ( 1 - θ ) R ) N + 2 - s p w ¯ L p ( t 1 - s , Q R ) ,

that is,

sup Q θ R w ¯ C ( ( 1 - θ ) R ) N + 2 - s p w ¯ L p ( t 1 - s , Q R ) .

The proof of Lemma 6.2 is complete. ∎

Next, we deal with the so-called weak Harnack inequality.

Lemma 6.3

Suppose fLN-βs-β(N,1|y|βdx) and wH0,L1(+N+1) is a positive solution of (6.4). Then,

inf Q θ R w C ( R ( 1 - θ ) ) N + 2 - s p w L p ( t 1 - 2 s , Q R ) ,

where C>0 depends only on N,s.

Proof.

Let w¯=w+k, where k>0 is a constant which is eventually sent to 0. Let φ0 be a function in H0,L1(+N+1) with compact support in QRQR. Multiplying both sides of the first equality of (6.4) by φw¯-2 and integrating by parts, we find

- + N + 1 t 1 - s w φ w ¯ 2 𝑑 x 𝑑 t + 2 + N + 1 t 1 - s w w ¯ φ w ¯ 3 d x d t + N f ( x ) | y | β w w ¯ - 2 φ 𝑑 x 𝑑 t = 0 .

Let v=w¯-1. Then, w=w¯ and v=-w¯-2w¯, which imply

+ N + 1 t 1 - s v φ d x d t + N f ~ ( x ) | y | β v φ 𝑑 x 𝑑 t = 0 ,

where f~=fww¯. Obviously, f~LN-βs-β(N,1|y|βdx). Thus, Lemma 6.2 implies that, for any θ(0,1),

sup Q θ R v C ( ( 1 - θ ) R ) N + 2 - s p v L p ( t 1 - 2 s , Q R ) ,

or

inf Q θ R w ¯ C ( ( 1 - θ ) R ) N + 2 - s p ( Q R t 1 - s w ¯ - p 𝑑 x 𝑑 t ) - 1 p
= C ( ( 1 - θ ) R ) N + 2 - s p ( Q R t 1 - s w ¯ - p 𝑑 x 𝑑 t Q R t 1 - s w ¯ p 𝑑 x 𝑑 t ) - 1 p ( Q R t 1 - s w ¯ p 𝑑 x 𝑑 t ) 1 p .

Hence, we need only to show that there exists p0>0 such that

Q R t 1 - s w ¯ - p 0 𝑑 x 𝑑 t Q R t 1 - s w ¯ p 0 𝑑 x 𝑑 t C ,

where C>0 depends only on N,s,R, or equivalently, we need to show

(6.11) Q R e p 0 | W | 𝑑 x 𝑑 t C ,

where W=logw¯-(logw¯)0,R. As usual (see [23, 14]), inequality (6.11) follows from the John–Nirenberg type lemma if WBMO(t1-sdX).

Multiplying both sides of the first equation of (6.4) by w¯-1φ and integrating by parts, we have

+ N + 1 t 1 - s | W | 2 φ 𝑑 x 𝑑 t = + N + 1 t 1 - s W φ d x d t + N f ~ ( x ) | y | β φ 𝑑 x 𝑑 t .

Notice that φ has compact support in QRQR. We have

Q R t 1 - s | W | 2 φ 𝑑 x 𝑑 t = Q R t 1 - s W φ d x d t + Q R f ~ ( x ) | y | β φ 𝑑 x 𝑑 t .

Replacing φ by φ2, it follows from the Cauchy inequality and the Sobolev inequality that

Q R t 1 - s | W | 2 φ 2 𝑑 x 𝑑 t C Q R t 1 - s | φ | 2 𝑑 x 𝑑 t .

Now, the proof can be completed in much the same way as the proof of [23, Proposition 3.2]. ∎

Finally, we establish the decaying law for positive solutions of (6.3).

Proposition 6.4

Suppose w is a positive solution of (6.3). Then, there exist positive constants C2>C1>0 such that, for X+N+1,

C 1 1 + | X | N - s w ( X ) C 2 1 + | X | N - s .

Proof.

Consider the Kelvin transformation

w ~ ( X ) = | X | - N + s w ( X | X | 2 )

of w. If w is a solution of (6.3), so is w~. Moreover, we have

+ N + 1 t 1 - s | w ~ | 2 𝑑 x 𝑑 t C , N | w ~ ( x , 0 ) | 2 s , β * | y | β 𝑑 x C .

In equation (6.4), we choose f(x)=w~2s,β*-2(x,0). We may verify that fLN-βs-β(N,1|y|β). By Lemmas 6.2 and 6.3, w~Lloc(+N+1) and for XQ1, we may find C2>C1>0 such that C1w~(X)C2. Hence,

C 1 | X | s - N w ( X ) C 2 | X | s - N for | X | 1 .

The assertion follows. ∎

Proof of Theorem 1.5.

Let u>0 be a minimizer of Λs,N,k,α, then it weakly solves equation (6.1) up to a multiplying constant. Thus we know from [7] that there exists a unique extension function w(x,t)H0,L1(+N+1) of u satisfying equation (6.3) and u(x)=w(x,0). So Theorem 1.5 immediately follows from Proposition 6.4. ∎

Award Identifier / Grant number: 11461033

Award Identifier / Grant number: 11401269

Award Identifier / Grant number: 11271170

Award Identifier / Grant number: 11361029

Funding statement: X. Chen is supported by the NNSF of China (no. 11461033 and 11401269) and the NNSF of Jangxi Province (no. 20142BAB201003). J. Yang is supported by the NNSF of China (no. 11271170 and 11361029) and the GAN PO 555 program of Jiangxi.

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Received: 2015-05-27
Revised: 2015-09-20
Accepted: 2015-09-27
Published Online: 2016-03-12
Published in Print: 2016-08-01

© 2016 by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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