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Liebauite, Ca3Cu5Si9O26: A new silicate mineral with 14er single chain

Published/Copyright: August 25, 2010
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Abstract

The new calcium copper silicate liebauite has been found in cavities of a mudstone xenolith from the Sattelberg scoria cone near Kruft in the Eifel district, Germany. It occurs as bluish-green transparent crystals with a vitreous lustre and a Mohs hardness between 5 and 6. The analytical formula for liebauite based on 26 oxygen atoms is Ca2.99Cu4.91Si9.05O26, the idealized formula is Ca3Cu5Si9O26, and the structural formula Ca6Cu10{1B, 11}[14Si18O52]. The mineral is monoclinic, space group C2/c with a = 10.160(1), b = 10.001(1), c = 19.973(2) Å, β = 91.56(1)°, V = 2028.7 Å3 and Z = 4. The strongest lines in the X-ray powder diffraction pattern are [d(Å), I, hkl] 7.13(60) (110), 6.70(70) (11[unk], 111), 3.58(40) (220), 3.12(90) (131, 131), 3.00(100) (116, 312), 2.45(60) (226), 2.41(70) (226), 1.78(50) (440). Liebauite is biaxial positive with α = 1.722, β = 1.723, and ε = 1.734 (λ = 589 nm). Determination and refinement of the crystal structure led to a conventional R value of 0.046 for 818 observed reflections

Published Online: 2010-08-25
Published in Print: 1992

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