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Competitive equilibrium cycles for small discounting in discrete-time two-sector optimal growth models

  • Alain Venditti EMAIL logo
Published/Copyright: April 17, 2019

Abstract

We study the existence of endogenous competitive equilibrium cycles under small discounting in a two-sector discrete-time optimal growth model. We provide precise concavity conditions on the indirect utility function leading to the existence of period-two cycles with a critical value for the discount factor that can be arbitrarily close to one. Contrary to the continuous-time case where the existence of periodic-cycles is obtained if the degree of concavity is close to zero, we show that in a discrete-time setting the driving condition does not require a close to zero degree of concavity but a symmetry of the indirect utility function’s concavity properties with respect to its two arguments.

JEL Classification: C62; E32; O41

Acknowledgement

This paper has been written in honor of Professor Kazuo Nishimura, a very close friend, who has made outstanding contributions to economic theory, and in particular to the literature on endogenous fluctuations in optimal growth models. This work was supported by French National Research Agency Grants ANR-08-BLAN-0245-01 and ANR-17-EURE-0020. I would like to thank Makoto Yano and an anonymous referee for useful comments and suggestions.

This paper is dedicated to the memory of Pierre Cartigny (1946–2019), my PhD advisor and a very close friend.

A Appendix

A.1 Proof of Lemma 1

i) This is a standard result (see Montrucchio (1987), Rockafellar (1976)).

ii) From i) we get

νt[D2f(x)+αI]ν0

which means that the matrix [D2f(x)ν+αI] should be negative semi-definite for all xD, i.e. there must exist a ν~0 such that

ν~t[D2f(x)+αI]ν~=0

This means therefore that

Det[D2f(x)+αI]Det[D2f(x)(α)I]=0

It follows that α is an eigenvalue of the matrix D2f(x). Considering λi(x) an eigenvalue of D2f(x), we may define for all xD

λ(x)=mini=1,,n{|λi(x)|}

and we conclude therefore that α=infxDλ(x). If f is α-concave over D then α ≠ 0 since the Hessian matrix is non-singular for all xD. □

A.2 Proof of Lemma 2

The arguments are the same as in the proof of Lemma 1. □

A.3 Proof of Proposition 2

Consider first the case V12δ>0. We know from (14) that P(0)=V12δ>0 and limλ±P(λ)=+. It follows that the steady state is a saddle-point if and only if

P(1)=δV11δ+V22δ+(1+δ)V12δ<0

If V(x, y) is (α, β)-concave, we derive from Lemma 1 that the following quadratic form holds

(11)(V11δ+αV12δV12δV22δ+β)(11)0

which implies

α+β2V12δV11δV22δ

If V(.,kδ) is concave-γ, we derive from Lemma 2 that γV11δ. We then derive

α+βγ2V12δ+V11δ+V22δV11δ

Assume now that 1δ>1(α+β)/γ. We derive from the previous inequality

δ>2V12δ+V22δV11δ

which implies

δV11δ+V22δ+2V12δ<0

Since 2V12δ(1+δ)V12δ we conclude that

P(1)=δV11δ+V22δ+(1+δ)V12δ<0

and the steady state is a saddle-point.

Consider now the case V12δ<0. We know from (14) that P(0)=V12δ<0 and limλ±P(λ)=. It follows that the steady state is a saddle-point if and only if

P(1)=[δV11δ+V22δ(1+δ)V12δ]>0

If V(x, y) is (α, β)-concave, we derive from Lemma 1 that the following quadratic form holds

(11)(V11δ+αV12δV12δV22δ+β)(11)0

which implies

α+β2V12δV11δV22δ

If V(.,kδ) is concave-γ, we derive from Lemma 2 that γV11δ. We then derive

α+βγ2V12δ+V11δ+V22δV11δ

Assume now that 1δ>1(α+β)/γ. We derive from the previous inequality

δ>2V12δV22δV11δ

which implies

δV11δ+V22δ2V12δ<0

Since 2V12δ(1+δ)V12δ we conclude that

P(1)=[δV11δ+V22δ(1+δ)V12δ]>0

and the steady state is a saddle-point. The results of the Proposition follow. □

A.4 Proof of Proposition 3

Consider in a first step the case δ = 1. Assumption 4 implies that V111V221. Since we assume V12δ<0, we derive from the proof of Proposition 2 that

P(1)=V111+V2212V121

The singularity of the Hessian matrix of V at the steady state implies then V111V221(V121)2=0 or equivalently V121=V111V221. Substituting this into P(−1) yields

P(1)=(|V111||V221|)2<0

It follows that when δ = 1 the steady state is a saddle-point. Let us then assume that there is a value δ¯(0,1) such that

δ¯V11δ¯+V22δ¯(1+δ¯)V12δ¯>0

Then there exists δ(δ¯,1) such that

(18)P(1)=[δV11δ+V22δ(1+δ)V12δ]=0

and there exists an eigenvalue λ(δ)=1 leading to the existence of a flip bifurcation, i.e. period-two cycles in a neighborhood of δ*. Solving equation (18), we conclude that the bifurcation value δ* is implicitly defined by

δ=V22δV12δV12δV11δ

A.5 Proof of Proposition 4

Using Lemma 2 and Definition 5, we have that the following matrix is positive semi-definite:

(V11δ+γ1V12δV12δV22δ+γ2)

This means in particular that its determinant is equal to zero:

(V11δ+γ1)(V22δ+γ2)(V12δ)2=0

Using also the fact that V11δV22δ(V12δ)2=0 we obtain that:

γ1=2V11δ,γ2=2V22δ

Let us now consider the bifurcation value given by equation (16). We then have:

(19)δ=γ1γ2γ2γ1γ1γ2=γ2γ1

We first note that for the bifurcation value to be less than 1, we need to assume that γ2<γ1. Second, we conclude that if (γ1γ2)0 then the bifurcation value δ1. □

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Published Online: 2019-04-17

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