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A generalization of weak commutativity between two isomorphic groups

  • Bruno C. R. Lima EMAIL logo and Said N. Sidki
Published/Copyright: December 2, 2016

Abstract

The operator χ of weak commutativity between isomorphic groups H and Hψ, defined by

χ(H)=H,Hψ[h,hψ]=1 for all hH,

is known to preserve group properties such as finiteness, solvability and polycyclicity. We introduce here the group construction

(H)=H,Hψ[[h1,h2ψ],h3-1h3ψ]=1 for all h1,h2,h3H.

The group (H) maps onto χ(H) and onto HH, the non-abelian tensor square. The operator preserves solvability and preserves polycyclicity provided the abelianization HH is finite. Moreover, if H is perfect, then (H) is perfect and (H)χ(H). Furthermore, (H) is a finite group if and only if H is a finite perfect group.

1 Introduction

The concept of weak permutability between two groups was introduced in 1980 [9] and a finiteness criterion result was established for a group generated by two such groups. In Section 4 of the same work, the notion of weak commutativity motivated the definition of the group

χ(H)=H,Hψ[h,hψ]=1 for all hH.

It was shown then that χ, when interpreted as an operator acting on groups, preserves the group properties: finite P-group for any finite set P of primes, solvable, finite nilpotent, perfect. Later, it was proven that if H is finitely generated nilpotent of nilpotency class c, then χ(H) is nilpotent and bounds for the nilpotency degree of χ(H) were found in terms of c (see [3]). Recently, the properties polycyclic and polycyclic-by-finite were added to this list [5]. Moreover, a study of homological and homotopical properties of χ(H) have lead to proving that χ preserves the property of solvable of type FP (see [4]).

The definition of χ(H) implies that the relations

[h1,h2ψ]h3ψ=[h1,h2ψ]h3

(equivalently, [[h1,h2ψ],h3-1h3ψ]=1) hold for all h1,h2,h3H. These same relations form an essential part of the definition of the non-abelian tensor square

HH=h1h2h1h2h3=((h1)h2(h3)h2)(h2h3),
h1h2h3=(h1h3)((h1)h2(h3)h2)
for all h1,h2,h3H,

by Brown–Loday in 1987 [2] and of the definition of

ν(H)=H,Hψ[h1,h2ψ]h3ψ=[h1,h2ψ]h3=[h1h3,(h2h3)ψ]
for all h1,h2,h3H

by Rocco in 1991 [7] who proved the subgroup [H,Hψ] of ν(H) to be isomorphic to HH.

We focus here on the similarity between these constructions by defining the group

(H)=H,Hψ[[h1,h2ψ],h3-1h3ψ]=1 for all h1,h2,h3H).

The group (H) admits an automorphism hhψ of order 2, which will be denoted by the same symbol ψ.

It is easy to see that if H is cyclic of order 2, then (H) is the infinite dihedral group. Though fails to preserve finiteness and nilpotency, still it preserves many features of χ. Some of our main results are gathered together in

Theorem 1.

The following statements hold.

  1. Let H be a solvable group with derived series of length k. Then (H) is a solvable group of length at most k+2.

  2. Suppose H is a polycyclic group. Then (H) is polycyclic if and only if the abelianization H/H is a finite group.

  3. Suppose H is a perfect group. Then (H) is perfect and (H)χ(H).

  4. The group (H) is finite if and only if H is a finite perfect group.

2 Preliminaries

We use standard notation as can be found in [8].

2.1 Some epimorphisms

We start by defining four epimorphisms of (H) and stating some of their properties:

ρ:(H)H,hh,hψhfor all hH,

with

ker(ρ)=(H)=[H,ψ]=h-1hψhH,(H)=(H)H,(H)H=1;

and

π:(H)H×H,h(h,1),hψ(1,h)for all hH,

with

ker(π)=𝒟(H)=[H,Hψ]=[h1,h2ψ]h1,h2H,(H)=(𝒟(H)H).Hψ,𝒟(H)(HHψ)=1;

and

δ:(H)χ(H),hh,hψhψfor all hH,

with

ker(δ)=Δ(H)=[h,hψ]hH(H);

and

ξ:(H)ν(H),hh,hψhψfor all hH.

The subgroups (H),𝒟(H),Δ(H) are ψ-invariant. In addition to these, we have the normal ψ-invariant subgroups of (H)

𝒲(H)=𝒟(H)(H),
(H)=[[H,(H)],Hψ].

We mention two more normal subgroups

1(H)=[(H),H],2(H)=[(H),Hψ];

these are interchanged by ψ.

Maintaining the notation used for subgroups of χ(H), we write

(H)δ=L(H),𝒟(H)δ=D(H),𝒲(H)δ=W(H),
(H)δ=R(H),1(H)δ=L1(H),2(H)δ=L2(H).

The subgroup (H) is key to understanding the structure of (H). We will prove later

Theorem 2.

Let ξ:E(H)ν(H) be as defined above. Then ker(ξ)=R(H).

Remark 1.

(i) It follows directly from the definition of (H) that

[𝒟(H),(H)]=1

and therefore 𝒲(H) is central in the product 𝒟(H)(H). We conclude from

[hψ,h]=[h(h-1hψ),h]=[h-1hψ,h]𝒟(H)(H)=𝒲(H)

that

Δ(H)𝒲(H).

(ii) Using [9, Proposition 4.1.4], the quotient group (H)𝒲(H)(χ(H)W(H)) embeds into the triple product H×H×H by

τ:𝒲(H)h(h,h,1),𝒲(H)hψ(1,h,h)

for all hH. Thus,

τ:𝒲(H)(h-1hψ)(h-1,1,h),
𝒲(H)[h1,h2ψ](1,[h1,h2],1),
𝒲(H)([h1-1h1ψ,h2])([h1-1,h2],1,1),
𝒲(H)([h1-1h1ψ,h2ψ])(1,1,[h1,h2])

for all h,h1,h2H.

2.2 Commutator relations

It is convenient to denote h-1hψ by [h,ψ].

Lemma 1.

The following statements hold.

  1. Let h1,h2,h3H. Then:

    1. [h1,ψ] commutes with [h2,h3ψ],

    2. [h1,h2ψ]=[ψ,h2,h1][h1,h2] (thus 𝒟(H)[(H),H]H),

    3. in (H),

      [h1,h3(h3ψ)-1,h2ψ]h3ψ=[h1,h2ψ]-h3ψ[h1h3,(h2h3)ψ].

  2. Let w=w(z1ϵ1,z2ϵ2,,znϵn) be a word in z1ϵ1,z2ϵ2,,znϵn of length n, where ziH, ϵk{1,ψ,}. Also, let w=w(z1,z2,,zn). Then

    [h1,h2ψ]w=[h1,h2ψ]w for all h1,h2H.
  3. Elements of 𝒲(H) have the form

    [h1,h2ψ][hs,hs+1ψ],

    where h1,h2,,hs+1H and s is an odd number such that

    [h1,h2][hs,hs+1]=1.

Proof.

(1) (i) The assertion follows from the definition of (H).

(ii) Note that

[h1,h2ψ]=[h1,h2[h2,ψ]]=[h1,[h2,ψ]][h1,h2][h2,ψ]

and since by item (i) [h1,h2ψ] commutes with [ψ,h2], we obtain

[h1,h2ψ]=[h1,[h2,ψ]][ψ,h2][h1,h2]=[ψ,h2,h1][h1,h2].

(iii) We compute

[h1h3,(h2h3)ψ]=[h1h3,(h2ψ)h3ψ]=[h1h3(h3ψ)-1,h2ψ]h3ψ
=[h1[h1,h3(h3ψ)-1],h2ψ]h3ψ
=([h1,h2ψ][h1,h3(h3ψ)-1][[h1,h3(h3ψ)-1],h2ψ]).h3ψ

Since [h1,h2ψ]𝒟(H) and [h1,h3(h3ψ)-1](H), it follows that

[h1h3,(h2h3)ψ]=([h1,h2ψ][[h1,h3(h3ψ)-1],h2ψ])h3ψ
=[h1,h2ψ]h3ψ[[h1,h3(h3ψ)-1],h2ψ]h3ψ

and therefore,

[[h1,h3(h3ψ)-1],h2ψ]h3ψ=[h1,h2ψ]-h3ψ[h1h3,(h2h3)ψ].

(2) By item (i),

[h1,h2ψ]z1z2ψ=[h1,h2ψ]z1z2.

The more general statement follows by induction on n.

(3) Let ω=[h1,h2ψ][hs,hs+1ψ]𝒟(H). Then by item (ii),

ω=[ψ,h2,h1][h1,h2][ψ,hs+1,hs][hs,hs+1]=c[h1,h2][hs,hs+1],

where c(H). Since H(H)=1, we obtain

ω𝒲(H)[h1,h2][hs,hs+1]=1.

2.3 The subgroups 1(H),2(H)

Recall

1(H)=[(H),H],2(H)=[(H),Hψ].

By Remark 1 (ii),

τ:𝒲(H)[h1,h2ψ](1,[h1,h2],1),
𝒲(H)([h1-1h1ψ,h2])([h1-1,h2],1,1),
𝒲(H)([h1-1h1ψ,h2ψ])(1,1,[h1,h2])

for all h1,h2H. Therefore

τ:𝒟(H)𝒲(H)1×H×1,
𝒲(H)1(H)𝒲(H)H×1×1,
𝒲(H)2(H)𝒲(H)1×1×H

are epimorphisms.

Lemma 2.

We have

1(H)=(H)(𝒟(H)H),
2(H)=(H)(𝒟(H)(H)ψ),
1(H)2(H)=𝒲(H).

Proof.

Since

[h1ψh1-1,h2]=[h1ψ,h2]h1-1[h1-1,h2]

holds for all h1,h2H, we conclude

1(H)=[(H),H]𝒟(H)H(H)(𝒟(H)H).

By item (ii) of the previous lemma,

𝒟(H)[(H),H]H=1(H)H.

Therefore,

𝒲(H)(H)(𝒟(H)H)(H)(1(H)H)
1(H)((H)H)=1(H).

Hence,

1(H)=(H)(𝒟(H)H).

Apply ψ to 1(H), to obtain

2(H)=(H)(𝒟(H)(H)ψ).

Clearly,

𝒲(H)=(H)𝒟(H)1(H)2(H).

From [9, Lemma 4.1.10 (iii)], we know that the intersection L1(H)W(H)L2(H)W(H) is trivial in χ(H)W(H)((H)𝒲(H)); therefore,

1(H)2(H)=𝒲(H).

3 The groups (H) and ν(H)

Proposition 1.

The subgroup R(H) satisfies the following properties:

  1. (H)=[1(H),Hψ]=[2(H),H],

  2. [𝒲(H),(H)](H)𝒲(H).

Proof.

(i) By definition,

(H)=[H,(H),Hψ]=[1(H),Hψ].

Since [𝒟(H),(H)]=[H,Hψ,(H)]=1, we obtain, by the Hall–Witt identity, that

[Hψ,,H]=[H,,Hψ]

and consequently that (H)=[2(H),H].

(ii) We note

(H)1(H)2(H)=𝒲(H);

therefore,

[𝒲(H),H],[𝒲(H),Hψ](H),
[𝒲(H),(H)](H).

Proof of Theorem 2.

Recall

ν(H)=H,Hψ[h1,h2ψ]h3ψ=[h1,h2ψ]h3=[h1h3,(h2h3)ψ],h1,h2,h3H,

and

ξ:(H)ν(H),hh,hψhψfor all hH.

By Lemma 1 (iii), the commutator relations

[[h1,h3(h3ψ)-1],h2ψ]=(([h1,h2ψ]h3ψ)-1[h1h3,(h2h3)ψ])(h3ψ)-1

hold in R(H). Therefore, R(H)ker(ξ) and ξ induces an epimorphism

ξ¯:(H)(H)ν(H).

On the other hand, since both equalities

[h1,h2ψ]h3ψ=[h1,h2ψ]h3, [h1,h2ψ]h3ψ=[h1h3,(h2h3)ψ]

hold in (H) modulo (H), we obtain the epimorphism

ξ:ν(H)(H)(H)

defined by h(H)h, hψ(H)hψ. The composition ξ¯ξ is the identity map and thus, (H)(H)ν(H). With this the proof of the theorem is finished. ∎

4 Restrictions and inductions of

Proposition 2.

Let K,H1HE(H). Then:

  1. [K,H1ψ] and [Kψ,H1]H1,H1ψ,

  2. K,Kψ𝒟(H)=[K,Kψ],

  3. K,Kψ(H)=[K,ψ].

Proof.

(i) Since H1ψ normalizes [K,H1ψ] and

[k,h1ψ]y=[k,h1ψ]yψ=[k,h1ψ]-1[k,h1ψyψ]

hold for all kK and h1,yH1, we conclude that H1 normalizes [K,H1ψ]. Analogously, [H1,Kψ]H1,H1ψ.

(ii) Denote K,Kψ by K^. It is clear that [K,Kψ]K^𝒟(H). On the other hand, consider the epimorphism π:(H)H×H. Since ker(π)=𝒟(H), we have that π induces an epimorphism

K^K^𝒟(H)K×K.

Consider the natural epimorphism

K×KK^[K,Kψ].

The composition of the last two epimorphisms leads to

K^K^𝒟(H)K^[K,Kψ]

defined by (K^𝒟(H))x[K,Kψ]x for all xK^. Therefore,

K^𝒟(H)[K,Kψ].

(iii) The proof here is similar to that of the last item, by considering the epimorphism ρ:(H)H and by taking the composition of the maps

K^K^KK^[K,ψ].

Proposition 3.

Let ϕ:HK be an epimorphism, N=ker(ϕ). Then ϕ extends naturally to an epimorphism ϕ^:E(H)E(K) such that

  1. ϕ^(𝒟(H))=𝒟(K), ϕ^((H))=(K),

  2. ker(ϕ^)=N,Nψ[N,Hψ][Nψ,H],

  3. ker(ϕ^𝒟(H))=[N,Hψ][Nψ,H].

Proof.

(i) The extension ϕ^ of ϕ is determined by hϕ^=hϕ and (hψ)ϕ^=(hϕ)ψ for all hH. Then

ϕ^(𝒟(H))=ϕ^([H,Hψ])=[ϕ^(H),ϕ^(Hψ)]=[K,Kψ]=𝒟(K)

and

ϕ^((H))=ϕ^([H,ψ])=[ϕ^(H),ψ])=[K,ψ].

(ii) Let M=N,Nψ[N,Hψ][H,Nψ]. We have that Mker(ϕ^), because N,Nψker(ϕ^). By the previous proposition, M is normal in (H). The map

μ:KKψ(H)M,kMϕ-1(k),kψM(ϕ-1(k))ψ

is well-defined, since N,NψM. The restrictions of μ to K and Kψ are homomorphisms and they extend uniquely to a homomorphism

μ:KKψ(H)/M.

Since the relations

[k1,k2ψ]k3=[k1,k2ψ]k3ψfor all k1,k2,k3K

are preserved by μ, it induces a homomorphism (K)(H)M. On the other hand, since Mker(ϕ^), we have a homomorphism ϕ~:(H)/M(K) such that ϕ~(Mh)=ϕ^(h) and ϕ~(Mhψ)=ϕ^(hψ) for all hH. The composition of μ and ϕ~ gives us

ϕ~μ(k)=ϕ~(Mϕ-1(k))=k,ϕ~μ(kψ)=ϕ~(M(ϕ-1(k))ψ)=kψ

for all kK. So, ϕ~μ=1(K), which shows that ϕ~ is an isomorphism.

(iii) This item follows from

𝒟(H)kerϕ^=𝒟(H)(N,Nψ[N,Hψ][H,Nψ])
=[N,Nψ][N,Hψ][Nψ,H]
=[N,Hψ][Nψ,H].

Proposition 4.

Let H and K be normal subgroups of a group G such that

G=HK.

Then

(G)=H,Hψ[H,Kψ][Hψ,K]K,Kψ,
(H)H,Hψ,
(K)K,Kψ.

Proof.

By the previous proposition, the projection ϕ:GH can be extended to an epimorphism ϕ^:(G)(H) such that

ker(ϕ^)=K,Kψ[HK,Kψ][HψKψ,K].

It follows that

[HK,Kψ]=[H,Kψ][K,Kψ],

since by Proposition 2 the subgroups K, Kψ, H and Hψ normalize [H,Kψ]. Similarly, it follows that

[HψKψ,K]=[Hψ,K][K,Kψ].

Thus,

(G)K,Kψ[H,Kψ][Hψ,K](H).

But as ϕ^(H,Hψ)=(H), and (H) maps onto H,Hψ, it follows that

ker(ϕ^)H,Hψ=1,(H)H,Hψ.

We conclude

(G)K,Kψ[H,Kψ][Hψ,K]K,Kψ.

The isomorphism (K)K,Kψ follows in a similar manner. ∎

5 The augmentation ideal of (H/H)

Let G~=(H/H)H denote the semidirect product of the group ring (H/H) of the abelianization of H by the group H, where H acts on (H/H) by right multiplication

(xHhHh)h1=xHh Hhh1

for all h,h1H. Denote the elements of G~ as pairs (w,h) with w(H/H), hH. Identify the complement H with {0}×H, write h¯ for the coset Hh for any hH and let u=(1¯,1)G~. Also, let 𝒜(H/H) be the augmentation ideal of the group ring (H/H) and let G be the subgroup of G~ generated by 𝒜(H/H) and H. Note that H acts trivially on (H/H).

Proposition 5.

The map ε:HHψG~ defined by hh, hψhu for all hH extends to an epimorphism ε:E(H)G~. Moreover, if H is abelian, then ker(ε)=L(H), the commutator subgroup of L(H).

Proof.

Consider

[H,u]=[h,u]hHG~.

It is easy to see that

[h,u]=h-1hu=u-hu=(1¯-h¯,1).

Therefore, [H,u]=𝒜(H/H)×{1} and G=H,Hu. Since (H/H) is abelian and H acts trivially on (H/H), we find that

[[h1,h2u],[h,u]]=[h1-1u-1h2-1uh1u-1h2u,[h,u]]
=[u-h1(h1-1h2-1uh1h2)u-h2u,[h,u]]
=[u-h1uh2h1[h1,h2]u-h2u,u-hu]
=1.

Thus ε extends to an epimorphism (H)𝒜(H/H)H.

By [9, Theorem 2.1.1], G=𝒜(H)His isomorphic to the group

H,Hψ[H,ψ]=1

and so, when H is abelian, we obtain ker(ε)=(H). ∎

Next, we specialize H to a finite cyclic group.

Corollary 1.

Let H=x be a cyclic group of order n. Then

(H)n-1H.

Proof.

We need to show ker(ε)=1; that is, (H) is abelian. We note that

1=[xn,ψ]=[x,ψ]xn-1[x,ψ]xn-2[x,ψ],
[x,ψ]xn-1=[x,ψ]-xn-2[x,ψ]-1;

therefore,

(H)=[x,ψ],[x,ψ]x2,,[x,ψ]xn-2.

We compute

[xi,xψ]=[xi,x.x-1xψ]=[xi,[x,ψ]]=[x,ψ]-xi[x,ψ]for all i.

Since [𝒟(H),(H)]=1, it follows that

1=[[xi,xψ],[x,ψ]]=[[x,ψ]-xi,[x,ψ]]

and thus (H) is an abelian group. ∎

6 of solvable groups

Proof of Theorem 1 (i).

Since H is a solvable group with derived length k, we apply [9, Corollary 4.1.8] to conclude χ(H)(k+1)=1. As ker(δ)=Δ(H) is abelian, we conclude further that (H)(k+2)=1 and this ends the proof. ∎

6.1 Abelian groups

Given a group G we denote its center by Z(G).

Proposition 6.

Let H be an abelian group. Then:

  1. we have

    𝒟(H)=𝒲(H)=[(H),H]=[(H),Hψ],(H)=[𝒟(H),H]=[(H),H,H],
  2. (H) is nilpotent of class at most 2,

    (H)𝒟(H)Z((H)),(H)Z((H)).

Proof.

(i) By Lemma 2,

1(H)=[(H),H]=(H)𝒟(H)H,
2(H)=[(H),Hψ]=(H)𝒟(H)Hψ.

Since H is abelian group, we have that

𝒲(H)=(H)𝒟(H)=1(H)=2(H).

Since 𝒟(H)[(H),H]H and H abelian, we obtain

𝒟(H)[(H),H](H)𝒟(H)=𝒲(H);

therefore, 𝒟(H)=[(H),H]=[(H),Hψ]. From this last equality, we obtain

=[H,(H),Hψ]=[𝒟(H),Hψ]=[𝒟(H),H]=[(H),H,H].

(ii) It is clear that H centralizes (H) modulo [(H),H](=𝒟(H)) and Hψ centralizes (H) modulo [(H),Hψ](=𝒟(H)); therefore,

(H)[(H),(H)]𝒟(H).

On the other hand

[𝒟(H),(H)]=[(H),H,(H)]=[H,(H),(H)]=1;

therefore,

[(H),(H),H]=[(H),H]=1.

Proceeding in the same way, we obtain

1=[𝒟(H),(H)]=[(H),Hψ,(H)]=[Hψ,(H),(H)]

and

[(H),(H),Hψ]=[(H),Hψ]=1.

We have reached the desired conclusion:

(H)Z((H)).

Proposition 7.

Let H be an abelian group. Then

(H)=[aψ,b][a,bψ] for all a,bH.

Proof.

Consider l1,l2(H). Then

l1=[h1,ψ][h2,ψ][hs,ψ],
l2=[h1,ψ][h2,ψ][hr,ψ]

for some s,r and h1,h2,,hs,h1,h2,,hrH.

Since (H)𝒟(H) and [(H),𝒟(H)]=1 we have

[l1,l2]=i=1sj=1r[[hi,ψ],[hj,ψ]].

However,

[[hi,ψ],[hj,ψ]]=[hi-1hiψ,hj-1hjψ]
=[hi-1,hj-1hjψ]hiψ[hiψ,hj-1hjψ]
=[hi-1,hjψ]hiψ[hiψ,hj-1]hjψ
=[hi-1,hjψ]hi[hiψ,hj-1]hj
=[hi,hjψ]-1[hiψ,hj]-1
=[hjψ,hi][hj,hiψ],

which proves the assertion. ∎

Proposition 8.

Let H be an abelian group and let a,bH, have orders n and m, respectively. Then the element [a,bψ][aψ,b] has order a divisor of gcd(n,m).

Proof.

From

1=[an,bψ]=[a,bψ]an-1[a,bψ]an-2[a,bψ],

we obtain

1=[aψ,b](an-1)ψ[aψ,b](an-2)ψ[aψ,b],

since[𝒟(H),(H)]=1. Also, since 𝒟(H)=𝒲(H), by multiplying together these two equations, we obtain

1=[a,bψ]an-1[a,bψ]an-2[a,bψ][aψ,b](an-1)[aψ,b](an-2)[aψ,b]
=([a,bψ][aψ,b])(an-1)([a,bψ][aψ,b])(an-2)[a,bψ][aψ,b]
=([a,bψ][aψ,b])n,

since Z((H)). Similarly, ([a,bψ][aψ,b])m=1; therefore, the order of [a,bψ][aψ,b] divides gcd(n,m). ∎

The next corollary follows directly from the above proposition.

Corollary 2.

If H is a finite abelian group, then so is L(H).

6.2 Polycyclic groups

A. McDermott defined in his thesis [6] the subgroup of the free product HHψ,

K=[h1,h2ψ]h3[h1h3,h2h3ψ]-1h1,h2,h3HHHψ

which is clearly related to our group (H). The following result is a consequence of [6, Theorem 2.2.8].

Theorem 3.

Let H be a polycyclic group with polycyclic generating sequence S={ai1ain}. Then the set of generators of K can be reduced:

K=[ai,ajψ]ak[aiak,ajakψ]-1ai,aj,akSHHψ.

Proposition 9.

Let T be a transversal of H in H. Then

(H)=[h1,h2ψ]h3[h1h3,h2h3ψ]-1h1,h2,h3HT.

Proof.

Define the subgroup

𝒥(H)=[h1,h2ψ]h3[h1h3,h2h3ψ]-1h1,h2,h3H(H)

of (H), normal in (H). We recall the epimorphism ξ:(H)ν(H) defined by hh, hψhψ for all hH, with kernel (H). Then ξ induces

ξ¯:(H)𝒥(H)ν(H).

On the other hand, the map σ:ν(H)(H)J(H) defined by

h𝒥(H)h,hψ𝒥(H)hψ

extends to an epimorphism σ¯:ν(H)(H)J(H), and the relations

[h1,h2ψ]h3ψ=[h1,h2ψ]h3=[h1h3,(h2h3)ψ]for all h1,h2,h3H

hold in (H)𝒥(H). Since σ¯ξ¯ is the identity on (H)𝒥(H), we have

(H)=𝒥(H).

By Lemma 1 (ii),

(H)𝒲(H)Z(𝒟(H));

therefore,

(H)=[h1,h2ψ]h3[h1h3,(h2h3)ψ]-1h1,h2,h3HH,

and

[(H),H]=[(H),𝒟(H)]=1.

Thus

(H)=[h1,h2ψ]h3[h1h3,h2h3ψ]-1h1,h2,h3HT.

Proposition 10.

Let H be a polycyclic group, with polycyclic generating sequence S={a1,a2,,an} and let T be a transversal of H in H. Then

(H)=[ai,ajψ]ak[aiak,ajakψ]-1ai,aj,akST.

Proof.

Considering the natural epimorphism ϕ:HHψ(H), we have that ϕ(K)=(H). By the above proposition,

(H)=[ai,ajψ]ak[aiak,ajakψ]-1ai,aj,akS(H)
=[ai,ajψ]ak[aiak,ajakψ]-1ai,aj,akST.

Proof of Theorem 1 (ii).

In one direction, let (H) be polycyclic. Then, on recalling the epimorphism ε:(H)A(H/H)H, we conclude that A(H/H) is finitely generated and therefore H/H is finite. In the other direction, on letting H/H be finite, we obtain that R(H) is a finitely generated abelian group. Since by [1], ν(H) is polycyclic and since (H)(H)ν(H), we conclude that (H) is polycyclic.

This ends the proof of part (ii) of Theorem 1. ∎

7 of perfect groups

When H is a perfect group, one finds a complete description of χ(H) in [9, Section 4.4], where it is shown that χ(H) is a certain stem extension of H×H×H by the Schur multiplier M(H) of H.

Proof of Theorem 1 (iii).

(a) Since (H)𝒟(H)L(H)HH, it follows that

(H)=𝒟(H)(H)

and therefore, 𝒲(H)Z((H)). From the formula

(H)=𝒟(H)(H)[𝒟(H),(H)],

we derive

(H)=𝒟(H)(H).

By [9, Lemma 4.4.6], χ(H) and its subgroups D=[H,Hψ],L=[H,ψ] are all perfect groups. We conclude

Δ(H)𝒲(H)Z((H)),
𝒟(H)=Δ(H)𝒟(H),
(H)=Δ(H)(H),
(H)=𝒟(H)(H)=Δ(H)𝒟(H)(H)=(H).

(b) Consider (H)¯=(H)𝒟(H). Then

𝒟(H)¯(=[H,Hψ]¯)=𝒲(H)¯,

which is contained in the center of (H)¯. Therefore,

[Hψ¯,H¯,Hψ¯]=[H¯,Hψ¯,Hψ¯]=1

and by the Witt identity,

[Hψ¯,Hψ¯,H¯]=1,
[(H)ψ¯,H¯]=[Hψ¯,H¯]=1.

Thus,

𝒟(H)=𝒟(H), a stem extension of H.

(c) From the structure of χ(H), we have that W(H) is central in D(H),

D(H)W(H)HandW(H)M(H);

that is, D(H) is a total covering of H. As H is perfect, D(H) is the total covering of H. Therefore the map γ from the generating set {[h,hψ]hH} of D(H) into the generating set {[h,hψ]hH} of D(H) defined by

[h,hψ][h,hψ],

extends to an epimorphism γ:D(H)D(H). Hence, the composition

δγ:D(H)D(H)

is the identity and Δ(H)=1 follows.

This ends the proof of part (iii) of Theorem 1. ∎

Proof of Theorem 1 (iv).

Assume that H is a finite group. Since (H) maps onto A(H/H)H, on supposing (H) finite, we obtain H=H. Reciprocally, on supposing H perfect, we obtain by the previous theorem, (H)χ(H).

This proves the final part of Theorem 1. ∎


Communicated by Dessislava H. Kochloukova


Acknowledgements

The authors would like to thank the referee for suggestions which improved the readability of the original text.

References

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Received: 2016-4-11
Revised: 2016-9-14
Published Online: 2016-12-2
Published in Print: 2017-7-1

© 2017 Walter de Gruyter GmbH, Berlin/Boston

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