Startseite Boundary Singularities of Solutions to Semilinear Fractional Equations
Artikel Open Access

Boundary Singularities of Solutions to Semilinear Fractional Equations

  • Phuoc-Tai Nguyen und Laurent Véron EMAIL logo
Veröffentlicht/Copyright: 7. Februar 2018

Abstract

We prove the existence of a solution of (-Δ)su+f(u)=0 in a smooth bounded domain Ω with a prescribed boundary value μ in the class of Radon measures for a large class of continuous functions f satisfying a weak singularity condition expressed under an integral form. We study the existence of a boundary trace for positive moderate solutions. In the particular case where f(u)=up and μ is a Dirac mass, we show the existence of several critical exponents p. We also demonstrate the existence of several types of separable solutions of the equation (-Δ)su+up=0 in +N.

1 Introduction

Let ΩN be a bounded domain with C2 boundary and s(0,1). Define the s-fractional Laplacian as

( - Δ ) s u ( x ) := lim ε 0 ( - Δ ) ε s u ( x ) ,

where

( - Δ ) ε s u ( x ) := a N , s N B ε ( x ) u ( x ) - u ( y ) | x - y | N + 2 s 𝑑 y , a N , s := Γ ( N / 2 + s ) π N / 2 Γ ( 2 - s ) s ( 1 - s ) .

We denote by GsΩ and MsΩ the Green kernel and the Martin kernel, respectively, of (-Δ)s in Ω. Denote by 𝔾sΩ and 𝕄sΩ the Green operator and the Martin operator, respectively (see Section 2 for more details). Further, for ϕ0, denote by 𝔐(Ω,ϕ) the space of Radon measures τ on Ω satisfying Ωϕd|τ|<, and by 𝔐(Ω) the space of bounded Radon measures on Ω. Let ρ(x) be the distance from x to Ω. For β>0, set

Ω β := { x Ω : ρ ( x ) < β } , D β := { x Ω : ρ ( x ) > β } , Σ β := { x Ω : ρ ( x ) = β } .

Definition 1.1.

We say that a function uLloc1(Ω) possesses an s-boundary trace on Ω if there exists a measure μ𝔐(Ω) such that

lim β 0 β 1 - s Σ β | u - 𝕄 s Ω [ μ ] | 𝑑 S = 0 .

The s-boundary trace of u is denoted by trs(u).

Let τ𝔐(Ω,ρs), μ𝔐(Ω) and let fC() be a nondecreasing function with f(0)=0. In this paper, we study the boundary singularity problem for semilinear fractional equations of the form

(1.1) { ( - Δ ) s u + f ( u ) = τ in  Ω , tr s ( u ) = μ , u = 0 in  Ω c .

We denote by 𝕏s(Ω)C(N) the space of test functions ξ satisfying

  1. supp ( ξ ) Ω ¯ ,

  2. ( - Δ ) s ξ ( x ) exists for all xΩ, and |(-Δ)sξ(x)|C for some C>0,

  3. there exist φL1(Ω,ρs) and ε0>0 such that |(-Δ)εsξ|φ a.e. in Ω for all ε(0,ε0].

Definition 1.2.

Let τ𝔐(Ω,ρs) and μ𝔐(Ω). A function u is called a weak solution of (1.1) if uL1(Ω), f(u)L1(Ω,ρs) and

(1.2) Ω ( u ( - Δ ) s ξ + f ( u ) ξ ) 𝑑 x = Ω ξ 𝑑 τ + Ω 𝕄 s Ω [ μ ] ( - Δ ) s ξ 𝑑 x for all  ξ 𝕏 s ( Ω ) .

The boundary value problem with measure data for semilinear elliptic equations

(1.3) { - Δ u + f ( u ) = 0 in  Ω , u = μ on  Ω ,

was first studied by Gmira and Véron in [18], and then the typical model, i.e. problem (1.3) with f(u)=up (p>1), has been intensively investigated by numerous authors (see [22, 23, 24, 25, 26] and references therein). They proved that if f is a continuous, nondecreasing function satisfying

1 [ f ( t ) - f ( - t ) ] s - 1 - p c 𝑑 t < ,

where pc:=N+1N-1, then problem (1.3) admits a unique weak solution. In particular, when f(u)=up with 1<p<pc and μ=kδ0 with 0Ω and k>0, there exists a unique solution uk of (1.3). It was shown [22, 26] that the sequence {uk} is increasing and converges to a function u which is a solution of the equation in (1.3).

To our knowledge, few papers concerning boundary singularity problems for nonlinear fractional elliptic equations have been published in the literature. The earliest works in this direction are the papers [17, 10] by Felmer et al., which deal with the existence, nonexistence and asymptotic behavior of large solutions for equations involving fractional Laplacians. Afterwards, Abatangelo [1] presented a suitable setting for the study of fractional Laplacian equations in a measure framework and provided a fairly comprehensive description of large solutions which improve the results in [17, 10]. Recently, Chen, Alhomedan, Hajaiej and Markowich [9] investigated semilinear elliptic equations involving measures concentrated on the boundary by employing an approximate method.

In the present paper, we aim to establish the existence and uniqueness of weak solutions of (1.1). To this end, we develop a theory for linear equations associated to (1.1):

(1.4) { ( - Δ ) s u = τ in  Ω , tr s ( u ) = μ , u = 0 in  Ω c .

An existence and uniqueness result for (1.4) is stated in the following proposition.

Proposition 1.3.

Assume s(12,1). Let τM(Ω,ρs) and μM(Ω). Then problem (1.4) admits a unique weak solution. The solution is given by

(1.5) u = 𝔾 s Ω [ τ ] + 𝕄 s Ω [ μ ] .

Moreover, there exists a positive constant c=c(N,s,Ω) such that

(1.6) u L 1 ( Ω ) c ( τ 𝔐 ( Ω , ρ s ) + μ 𝔐 ( Ω ) ) .

This proposition allows us to study the semilinear equation (1.1). We first deal with the case of L1 data.

Theorem 1.4.

Assume s(12,1). Let fC(R) be a nondecreasing function satisfying tf(t)0 for every tR.

  1. Existence and uniqueness: For every τL1(Ω,ρs) and μL1(Ω), problem (1.1) admits a unique weak solution u. Moreover,

    (1.7) u = 𝔾 s Ω [ τ - f ( u ) ] + 𝕄 s Ω [ μ ] in  Ω ,
    (1.8) - 𝔾 s Ω [ τ - ] - 𝕄 s Ω [ μ - ] u 𝔾 s Ω [ τ + ] + 𝕄 s Ω [ μ + ] in  Ω .

  2. Monotonicity: The mapping (τ,μ)u is nondecreasing.

Remark.

The restriction s(12,1) is due to the fact that in this range of s one has trs(𝔾[τ])=0 for every τ𝔐(Ω,ρs) (see Proposition 2.11). We conjecture that this still holds if s(0,12].

We reveal that, in measures framework, because of the interplay between the nonlocal operator (-Δ)s and the nonlinearity term f(u), the analysis is much more intricate and there are three critical exponents

p 1 * := N + 2 s N , p 2 * := N + s N - s , p 3 * := N N - 2 s .

This yields substantial new difficulties and leads to disclose new types of results. The new aspects are both on the technical side and on the one of the new phenomena observed.

Theorem 1.5.

Assume s(12,1). Let fC(R) be a nondecreasing function, tf(t)0 for every tR and

(1.9) 1 [ f ( s ) - f ( - s ) ] s - 1 - p 2 * 𝑑 s < .

  1. Existence and Uniqueness: For every τ𝔐(Ω,ρs) and μ𝔐(Ω), there exists a unique weak solution of (1.1). This solution satisfies (1.7) and (1.8). Moreover, the mapping (τ,μ)u is nondecreasing.

  2. Stability: Assume that {τn}𝔐(Ω,ρs) converges weakly to τ𝔐(Ω,ρs) and {μn}𝔐(Ω) converges weakly to μ𝔐(Ω). Let u and un be the unique weak solutions of (1.1) with data (τ,μ) and (τn,μn), respectively. Then unu in L1(Ω) and f(un)f(u) in Lp(Ω,ρs).

If μ is a Dirac mass concentrated at a point on Ω, we obtain the behavior of the solution near that boundary point.

Theorem 1.6.

Under the assumption of Theorem 1.5, let zΩ, k>0 and let uz,kΩ be the unique weak solution of

{ ( - Δ ) s u + f ( u ) = 0 in  Ω , tr s ( u ) = k δ z , u = 0 in  Ω c .

Then

(1.10) lim Ω x z u z , k Ω ( x ) M s Ω ( x , z ) = k .

We next assume that 0Ω. Let 0<p<p2* and denote by ukΩ the unique weak solution of

(1.11) { ( - Δ ) s u + u p = 0 in  Ω , tr s ( u ) = k δ 0 , u = 0 in  Ω c .

By Theorem 1.5, ukΩkMsΩ(,0) and kukΩ is increasing. Hence, it is natural to investigate limkukΩ. This is accomplishable thanks to the study of separable solutions of

(1.12) { ( - Δ ) s u + u p = 0 in  + N , u = 0 in  - N ¯ ,

with p>1. Denote by

S N - 1 := { σ = ( cos ϕ σ , sin ϕ ) : σ S N - 2 , - π 2 ϕ π 2 }

the unit sphere in N, and by S+N-1:=SN-1+N the upper hemisphere. Writing separable solution under the form u(x)=u(r,σ)=r-2s/(p-1)ω(σ), with r>0 and σS+N-1, we obtain that ω satisfies

(1.13) { 𝒜 s ω - s , 2 s p - 1 ω + ω p = 0 in  S + N - 1 , ω = 0 in  S - N - 1 ¯ ,

where 𝒜s is a nonlocal operator naturally associated to the s-fractional Laplace–Beltrami operator, and s,2s/(p-1) is a linear integral operator with kernel. In analyzing the spectral properties of 𝒜s, we prove the following theorem.

Theorem 1.7.

Let N2, s(0,1) and p>p1*.

  1. If p 2 * p < p 3 * , there exists no positive solution of ( 1.13 ) belonging to W 0 s , 2 ( S + N - 1 ) .

  2. If p 1 * < p < p 2 * , there exists a unique positive solution ω * W 0 s , 2 ( S + N - 1 ) of ( 1.13 ).

As a consequence of this result, we obtain the behavior of ukΩ when k.

Theorem 1.8.

Assume s(12,1). Let Ω=R+N or let Ω be a bounded domain with C2 boundary containing 0.

  1. If p ( p 1 * , p 2 * ) , then u Ω := lim k 0 u k Ω is a positive solution of

    (1.14) { ( - Δ ) s u + u p = 0 in  Ω , u = 0 in  Ω c .

    1. If Ω = + N , then

      u + N ( x ) = | x | - 2 s p - 1 ω * ( σ ) with  σ = x | x | for all  x + N .

    2. If Ω is a bounded C2 domain with Ω containing 0 , then

      (1.15) lim Ω x 0 x | x | = σ S + N - 1 | x | 2 s p - 1 u Ω ( x ) = ω * ( σ )

      locally uniformly on S + N - 1 . In particular, there exists a positive constant c depending on N, s, p and the C2 norm of Ω such that

      c - 1 ρ ( x ) s | x | - ( p + 1 ) s p - 1 u Ω ( x ) c ρ ( x ) s | x | - ( p + 1 ) s p - 1 for all  x Ω .

  2. Assume p ( 0 , p 1 * ] . Then lim k u k Ω = in Ω.

The main ingredients of the present study are the following: estimates on the Green kernel and Martin kernel, theory for linear fractional equations in connection with the notion s-boundary trace as mentioned above, similarity transformation and the study of equation (1.13).

The paper is organized as follows: In Section 2, we present important properties of s-boundary trace, and prove Proposition 1.3. Theorems 1.41.6 and 1.8 are obtained in Section 3. Finally, in Appendix A, we discuss separable solutions of (1.12) and demonstrate Theorem 1.7.

2 Linear Problems

Throughout the present paper, we denote by c,c,c1,c2,C, positive constants that may vary from line to line. If necessary, the dependence of these constants will be made precise.

2.1 s-Harmonic Functions

We first recall the definition of s-harmonic functions (see [3, p. 46], [4, p. 230] and [6, p. 20]). Denote by (Xt,Px) the standard rotation invariant 2s-stable Lévy process in N (i.e. homogeneous with independent increments) with characteristic function

E 0 e i ξ X t = e - t | ξ | 2 s , ξ N , t 0 .

Denote by Ex the expectation with respect to the distribution Px of the process starting from xN. We assume that sample paths of Xt are right-continuous and have left-hand-side limits a.s. The process (Xt) is Markov with transition probabilities given by

P t ( x , A ) = P x ( X t A ) = μ t ( A - x ) ,

where μt is the one-dimensional distribution of Xt with respect to P0. It is well known that (-Δ)s is the generator of the process (Xt,Px).

For each Borel set DN, set tD:=inf{t0:XtD}, i.e. tD is the first exit time from D. If D is bounded, then tD< a.s. Denote

E x u ( X t D ) = E x { u ( X t D ) : t D < } .

Definition 2.1.

Let u be a Borel measurable function in N. We say that u is s-harmonic in Ω if for every bounded open set DΩ,

u ( x ) = E x u ( X t D ) , x D .

We say that u is singular s-harmonic in Ω if u is s-harmonic and u=0 in Ωc.

Put

𝒟 s := { u : N : Borel measurable such that N | u ( x ) | ( 1 + | x | ) N + 2 s } .

The following result follows from [5, Corollary 3.10 and Theorem 3.12] and [6, p. 20] (see also [20]).

Proposition 2.2.

Let uDs.

  1. u is s -harmonic in Ω if and only if (-Δ)su=0 in Ω in the sense of distributions.

  2. u is singular s -harmonic in Ω if and only if u is s-harmonic in Ω and u=0 in Ωc.

2.2 Green Kernel, Poisson Kernel and Martin Kernel

In what follows, the notation fg means that there exists a positive constant c such that c-1f<g<cf in the domain of the two functions or in a specified subset of this domain.

Denote by GsΩ the Green kernel of (-Δ)s in Ω. Namely, for every yΩ,

{ ( - Δ ) s G s Ω ( , y ) = δ y in  Ω , G s Ω ( , y ) = 0 in  Ω c ,

where δy is the Dirac mass at y. By combining [1, Lemma 3.2] and [14, Corollary 1.3]), we get the following proposition.

Proposition 2.3.

  1. G s Ω is continuous, symmetric and positive in { ( x , y ) Ω × Ω : x y } , and G s Ω ( x , y ) = 0 if x or y belongs to Ω c .

  2. ( - Δ ) s G s Ω ( x , ) L 1 ( Ω c ) for every x Ω , and ( - Δ ) s G s Ω ( x , y ) 0 for every x Ω and y Ω c .

  3. There holds

    (2.1) G s Ω ( x , y ) min { | x - y | 2 s - N , ρ ( x ) s ρ ( y ) s | x - y | - N } for all  ( x , y ) Ω × Ω , x y .

    The similarity constant in the above estimate depends only on Ω and s.

Denote by 𝔾sΩ the associated Green operator

𝔾 s Ω [ τ ] = Ω G s Ω ( , y ) 𝑑 τ ( y ) , τ 𝔐 ( Ω , ρ s ) .

Put

(2.2) k s , γ := { p 3 * if  γ [ 0 , N - 2 s N s ) , N + s N - 2 s + γ if  γ [ N - 2 s N s , s ] .

Chen and Véron obtained the following estimate for the Green operator [11, Proposition 2.3 and Proposition 2.6].

Lemma 2.4.

Assume γ[0,s] and let ks,γ be as in (2.2).

  1. There exists a constant c = c ( N , s , γ , Ω ) > 0 such that

    (2.3) 𝔾 s Ω [ τ ] M k s , γ ( Ω , ρ s ) c τ 𝔐 ( Ω , ρ γ ) for all  τ 𝔐 ( Ω , ρ γ ) .

  2. Assume { τ n } 𝔐 ( Ω , ρ γ ) converges weakly to τ 𝔐 ( Ω , ρ γ ) . Then 𝔾 s Ω [ τ n ] 𝔾 s Ω [ τ ] in L p ( Ω , ρ s ) for any p [ 1 , k s , γ ) .

Let PsΩ be the Poisson kernel of (-Δ)s defined by (see [7])

P s Ω ( x , y ) := - a N , - s Ω G s Ω ( x , z ) | z - y | N + 2 s 𝑑 z for all  x Ω , y Ω ¯ c .

The relation between PsΩ and GsΩ is expressed in [1, Proposition 2] (see also [14, Theorem 1.4], [4, Lemma 2] and [14, Theorem 1.5]).

Proposition 2.5.

  1. P s Ω ( x , y ) = - ( - Δ ) s G s Ω ( x , y ) for every x Ω and y Ω ¯ c . Furthermore, P s Ω is continuous in Ω × Ω ¯ c .

  2. There holds

    P s Ω ( x , y ) ρ ( x ) s ρ ( y ) s ( 1 + ρ ( y ) ) s 1 | x - y | N for all  x Ω , y Ω ¯ c .

    The similarity constant in the above estimate depends only on Ω and s.

Denote by sΩ the corresponding operator defined by

s Ω [ ν ] ( x ) = Ω ¯ c P s Ω ( x , y ) 𝑑 ν ( y ) , ν 𝔐 ( Ω ¯ c ) .

Fix a reference point x0Ω and denote by MsΩ the Martin kernel of (-Δ)s in Ω, i.e.

M s Ω ( x , z ) = lim Ω y z G s Ω ( x , y ) G s Ω ( x 0 , y ) for all  x N , z Ω .

By [15, Theorem 3.6], the Martin boundary of Ω can be identified with the Euclidean boundary Ω. Denote by 𝕄sΩ the associated Martin operator

𝕄 s Ω [ μ ] = Ω M s Ω ( , z ) 𝑑 μ ( z ) , μ 𝔐 ( Ω ) .

The next result [4, 15, 19] is important in the study of s-harmonic functions, which give a unique presentation of s-harmonic functions in terms of the Martin kernel.

Proposition 2.6.

  1. The mapping ( x , z ) M s Ω ( x , z ) is continuous on Ω × Ω . For any z Ω , the function M s Ω ( , z ) is singular s -harmonic in Ω with MsΩ(x0,z)=1. Moreover, if z,zΩ, zz then

    lim x z M s Ω ( x , z ) = 0 .

  2. There holds

    (2.4) M s Ω ( x , z ) ρ ( x ) s | x - z | - N for all  x Ω , z Ω .

    The similarity constant in the above estimate depends only on Ω and s.

  3. For every μ 𝔐 + ( Ω ) , the function 𝕄 s Ω [ μ ] is singular s -harmonic in Ω with u(x0)=μ(N). Conversely, if u is a nonnegative singular s-harmonic function in Ω then there exists a unique μ𝔐+(Ω) such that u=𝕄sΩ[μ] in N.

  4. If u is a nonnegative s -harmonic function in Ω , then there exists a unique μ𝔐+(Ω) such that

    u ( x ) = 𝕄 s Ω [ μ ] ( x ) + s Ω [ u ] ( x ) for all  x Ω .

Lemma 2.7.

  1. There exists a constant c = c ( N , s , γ , Ω ) such that

    (2.5) 𝕄 s Ω [ μ ] M N + γ N - s ( Ω , ρ γ ) c μ 𝔐 ( Ω ) for all  μ 𝔐 ( Ω ) , γ > - s .

  2. If { μ n } 𝔐 ( Ω ) converges weakly to μ 𝔐 ( Ω ) , then 𝕄 s Ω [ μ n ] 𝕄 s Ω [ μ ] in L p ( Ω , ρ γ ) for every 1 p < N + γ N - s .

Proof.

(i) Using (2.4) and an argument similar to the one in the proof of [2, Theorem 2.5], we obtain (2.5).

(ii) By combining the fact that MsΩ(x,z)=0 for every xΩc, zΩ and Proposition 2.6 (i), we deduce that for every xN we have MsΩ(x,)C(Ω). It follows that 𝕄sΩ[μn]𝕄sΩ[μ] everywhere in Ω. Due to (i) and the Holder inequality, we deduce that {𝕄sΩ[μn]} is uniformly integrable with respect to ργdx for any 1pN+γN-s. By invoking Vitali’s theorem, we obtain the convergence in Lp(Ω,ργ). ∎

2.3 Boundary Trace

We recall that, for β>0,

Ω β := { x Ω : ρ ( x ) < β } , D β := { x Ω : ρ ( x ) > β } , Σ β := { x Ω : ρ ( x ) = β } .

The following geometric property of C2 domains can be found in [26].

Proposition 2.8.

There exists β0>0 such that the following statements hold:

  1. For every point x Ω ¯ β 0 , there exists a unique point z x Ω such that | x - z x | = ρ ( x ) . This implies

    x = z x - ρ ( x ) 𝐧 z x .

  2. The mappings x ρ ( x ) and x z x belong to C 2 ( Ω ¯ β 0 ) and C 1 ( Ω ¯ β 0 ) , respectively. Furthermore,

    lim x z x ρ ( x ) = - 𝐧 z x .

Proposition 2.9.

Assume s(0,1). Then there exist positive constants c=c(N,Ω,s) such that, for every β(0,β0),

(2.6) c - 1 β 1 - s Σ β M s Ω ( x , y ) 𝑑 S ( x ) c for all  y Ω .

Proof.

For r0>0 fixed, by (2.4),

(2.7) Σ β B r 0 ( y ) M s Ω ( x , y ) 𝑑 S ( x ) c 1 β s ,

which implies

lim β 0 Σ β B r 0 ( y ) M s Ω ( x , y ) 𝑑 S ( x ) = 0 for all  y Ω .

Note that for r0 fixed the rate of convergence is independent of y.

In order to prove (2.6), we may assume that the coordinates are placed so that y=0 and the tangent hyperplane to Ω at 0 is xN=0 with the xN axis pointing into the domain. For xN, put x=(x1,,xN-1). Pick r0(0,β0) sufficiently small (depending only on the C2 characteristic of Ω) so that

1 2 ( | x | 2 + ρ ( x ) 2 ) | x | 2 for all  x Ω B r 0 ( 0 ) .

Hence if xΣβBr0(0), then 14(|x|+β)|x|. Combining this inequality and (2.4) leads to

Σ β B r 0 ( 0 ) M s Ω ( x , 0 ) 𝑑 S ( x ) c 2 β s Σ β , 0 ( | x | + β ) - N 𝑑 S ( x ) c 2 β s | x | < r 0 ( | x | + β ) - N 𝑑 x = c 3 β s - 1 .

Therefore, for β<r0,

(2.8) β 1 - s Σ β B r 0 ( 0 ) M s Ω ( x , 0 ) 𝑑 S ( x ) c 4 .

By combining estimates (2.7) and (2.8), we obtain the second estimate in (2.6). The first estimate in (2.6) follows from (2.4). ∎

As a consequence, we get the following estimates.

Corollary 2.10.

Assume s(0,1). For every μM+(Ω) and β(0,β0), there holds

c - 1 μ 𝔐 ( Ω ) β 1 - s Σ β 𝕄 s Ω [ μ ] 𝑑 S c μ 𝔐 ( Ω ) ,

with c being as in (2.6).

Proposition 2.11.

Assume s(12,1). Then there exists a constant c=c(s,N,Ω) such that for any τM(Ω,ρs) and any 0<β<β0,

(2.9) β 1 - s Σ β 𝔾 s Ω [ τ ] 𝑑 S c Ω ρ s d | τ | .

Moreover,

(2.10) lim β 0 β 1 - s Σ β 𝔾 s Ω [ τ ] 𝑑 S = 0 .

Proof.

Without loss of generality, we may assume that τ>0. Denote v:=𝔾sΩ[τ]. We first prove (2.9). By Fubini’s theorem and (2.4),

Σ β v ( x ) d S ( x ) c 5 ( Ω Σ β B β 2 ( y ) | x - y | 2 s - N d S ( x ) d τ ( y ) + β s Ω Σ β B β 2 ( y ) | x - y | - N d S ( x ) ρ ( y ) s d τ ( y ) ) = : I 1 , β + I 2 , β .

Note that if xΣβBβ2(y), then β2ρ(y)3β2. Therefore,

β 1 - s I 1 , β c 6 β 1 - 2 s Σ β B β 2 ( y ) | x - y | 2 s - N 𝑑 S ( x ) Ω ρ ( y ) s 𝑑 τ ( y )
c 6 β 1 - 2 s 0 β / 2 r 2 s - N r N - 2 𝑑 r Ω ρ ( y ) s 𝑑 τ ( y )
c 7 Ω ρ ( y ) s 𝑑 τ ( y ) ,

where the last inequality holds since s>12. On the other hand, we have

I 2 , β c 7 β s β / 2 r - N r N - 2 𝑑 r Ω ρ ( y ) s 𝑑 τ ( y ) = c 8 β s - 1 Ω ρ ( y ) s 𝑑 τ ( y ) .

Combining the above estimates, we obtain (2.9).

Next we demonstrate (2.10). Given ε(0,τ𝔐(Ω,ρs)) and β1(0,β0), put τ1=τχD¯β1 and τ2=τχΩβ1. We can choose β1=β1(ε) such that

Ω β 1 ρ ( y ) s 𝑑 τ ( y ) ε .

Thus the choice of β1 depends on the rate at which Ωβρs𝑑τ tends to zero as β0.

Put vi:=𝔾sΩ[τi]. Then, for 0<β<β12,

Σ β v 1 ( x ) 𝑑 S ( x ) c 9 β s β 1 - N Ω ρ ( y ) s 𝑑 τ 1 ( y ) ,

which yields

(2.11) lim β 0 β 1 - s Σ β v 1 ( x ) 𝑑 S ( x ) = 0 .

On the other hand, due to (2.9),

(2.12) β 1 - s Σ β v 2 𝑑 S c 10 Ω ρ s 𝑑 τ 2 c 11 ε for all  β < β 0 .

From (2.11) and (2.12) we obtain (2.10). ∎

Lemma 2.12.

Assume s(12,1). Let u,wDs be two nonnegative functions satisfying

{ ( - Δ ) s u 0 ( - Δ ) s w in  Ω , u = 0 in  Ω c .

If uw in RN, then (-Δ)suM(Ω,ρs) and there exists a measure μM+(Ω) such that

(2.13) lim β 0 β 1 - s Σ β | u - 𝕄 s Ω [ μ ] | 𝑑 S = 0 .

Moreover, if μ=0, then u=0.

Proof.

By the assumption, there exists a nonnegative Radon measure τ on Ω such that (-Δ)su=-τ.

We first prove that τ𝔐+(Ω,ρs). Define

M ~ s Ω ( x , z ) := lim Ω y z G s Ω ( x , y ) ρ ( y ) s .

By [1, p. 5547], there is a positive constant c=c(Ω,s) such that

M ~ s Ω ( x , z ) ρ ( x ) s | x - z | - N for all  x Ω , z Ω ,

where the similarity constant depends only on Ω and s. This implies

c 12 - 1 < c 13 - 1 Ω ρ ( x ) | x - z | - N 𝑑 S ( z )
ρ ( x ) 1 - s Ω M ~ s Ω ( x , z ) 𝑑 S ( z )
c 13 Ω ρ ( x ) | x - z | - N 𝑑 S ( z ) < c 12 for all  x Ω .

We define

𝔼 s Ω [ u ] ( z ) := lim Ω x z u ( x ) Ω M ~ s Ω ( x , y ) 𝑑 S ( y ) , z Ω .

For any β(0,β0), denote by τβ the restriction of τ to Dβ and by vβ the restriction of u on Σβ. By [1, Theorem 1.4], there exists a unique solution vβ of

{ ( - Δ ) s v β = - τ β in  D β , 𝔼 s D β [ v β ] = 0 on  Σ β , v β = u | D β c in  D β c .

Moreover, the solution can be written as

(2.14) v β + 𝔾 s D β [ τ β ] = s D β [ u | D β c ] in  D β .

By the maximum principle [1, Lemma 3.9], vβ=u and sDβ[u|Dβc]w a.e. in N. This, together with (2.14), implies that

𝔾 s D β [ τ β ] w in  D β .

Letting β0 yields 𝔾sΩ[τ]<. For fixed x0Ω, by (2.1), GsΩ(x0,y)>cρ(y)s for every yΩ. Hence the finiteness of 𝔾sΩ[τ] implies that τ𝔐+(Ω,ρs).

We next show that there exists a measure μ𝔐+(Ω) such that (2.13) holds. Put v=u+𝔾sΩ[τ]; then v is nonnegative singular s-harmonic in Ω due to the fact that 𝔾sΩ[τ]=0 in Ωc. By Proposition 2.2 and Proposition 2.6 (iii), there exists μ𝔐+(Ω) such that v=𝕄sΩ[μ] in N. By Proposition 2.11, we obtain (2.13). If μ=0, then v=0, and thus u=0. ∎

Definition 2.13.

A function u possesses an s-boundary trace on Ω if there exists a measure μ𝔐(Ω) such that

(2.15) lim β 0 β 1 - s Σ β | u - 𝕄 s Ω [ μ ] | 𝑑 S = 0 .

The s-boundary trace of u is denoted by trs(u).

Remark.

(i) The notation of s-boundary trace is well defined. Indeed, suppose that μ and μ satisfy (2.15). Put v=(𝕄sΩ[μ-μ])+. Clearly, v𝕄sΩ[|μ|+|μ|], v=0 in Ωc and

lim β 0 β 1 - s Σ β | v | 𝑑 S = 0 .

By Kato’s inequality [8, Theorem 1.2], (-Δ)sv0 in Ω. Therefore, we deduce v0 from Lemma 2.12. This implies 𝕄sΩ[μ-μ]0. By permuting the role of μ and μ, we obtain 𝕄sΩ[μ-μ]0. Thus μ=μ.

(ii) It is clear that for every μ𝔐(Ω) one has trs(𝕄sΩ[μ])=μ. Moreover, if s>12, by Proposition 2.11, for every τ𝔐(Ω,ρs) one has trs(𝔾sΩ[τ])=0.

(iii) This kind of boundary trace was first introduced by Nguyen and Marcus [21] in order to investigate semilinear elliptic equations with Hardy potential. In the present paper, we prove that it is still an effective tools in the study of nonlocal fractional elliptic equations.

2.4 Weak Solutions of Linear Problems

Definition 2.14.

Let τ𝔐(Ω,ρs) and μ𝔐(Ω). A function u is called a weak solution of (1.4) if uL1(Ω) and

(2.16) Ω u ( - Δ ) s ξ 𝑑 x = Ω ξ 𝑑 τ + Ω 𝕄 s Ω [ μ ] ( - Δ ) s ξ 𝑑 x for all  ξ 𝕏 s ( Ω ) .

Proof of Proposition 1.3.

The uniqueness follows from [11, Proposition 2.4]. Let u be as in (1.5). By [11],

Ω ( u - 𝕄 s Ω [ μ ] ) ( - Δ ) s ξ 𝑑 x = Ω 𝔾 s Ω [ τ ] ( - Δ ) s ξ 𝑑 x = Ω ξ 𝑑 τ for all  ξ 𝕏 s ( Ω ) .

This implies (2.16), and therefore u is the unique solution of (1.4). Since s(12,1), by Proposition 2.11, trs(u)=trs(𝕄sΩ[μ])=μ. Finally, estimate (1.6) follows from Lemma 2.4 and Lemma 2.7. ∎

3 Nonlinear Problems

In this section, we study the nonlinear problem (1.1). The definition of weak solutions of (1.1) is given in Definition 1.2.

3.1 Subcritical Absorption

Proof of Theorem 1.4.

We prove this theorem in several steps. Monotonicity. Let τ,τL1(Ω,ρs), μ,μL1(Ω) and let u and u be the weak solutions of (1.1) with data (τ,μ) and (τ,μ), respectively. We will show that if ττ and μμ, then uu in Ω. Indeed, by putting v:=(u-u)+, it is sufficient to prove that v0. Since (1.7) holds, it follows that

| u | 𝔾 s Ω [ | τ | + | f ( u ) | ] + 𝕄 s Ω [ | μ | ] in  Ω .

Similarly,

| u | 𝔾 s Ω [ | τ | + | f ( u ) | ] + 𝕄 s Ω [ | μ | ] in  Ω .

Therefore,

0 v | u | + | u | 𝔾 s Ω [ | τ | + | τ | + | f ( u ) | + | f ( u ) | ] + 𝕄 s Ω [ | μ | + | μ | ] = : w .

By Kato’s inequality, the assumption ττ and the monotonicity of f, we obtain

( - Δ ) s v sign + ( u - u ) ( τ - τ ) - sign + ( u - u ) ( f ( u ) - f ( u ) ) 0 .

Therefore,

( - Δ ) s v 0 ( - Δ ) s w in  Ω .

Since μμ, it follows that trs(v)=0. By Lemma 2.12, v=0, and thus uu.

Existence.

Step 1: Assume that τL(Ω) and μL(Ω). Put

f ^ ( t ) := f ( t + 𝕄 s Ω [ μ ] ) - f ( 𝕄 s Ω [ μ ] ) and τ ^ := τ - f ( 𝕄 s Ω [ μ ] ) .

Then f^ is nondecreasing and tf^(t)0 for every t and τ^L1(Ω,ρs). Consider the problem

(3.1) { ( - Δ ) s v + f ^ ( v ) = τ ^ in  Ω , v = 0 in  Ω c .

By [12, Proposition 3.1], there exists a unique weak solution v of (3.1). This means vL1(Ω), f^(v)L1(Ω,ρs) and

(3.2) Ω ( v ( - Δ ) s ξ + f ^ ( v ) ξ ) 𝑑 x = Ω ξ τ ^ 𝑑 x for all  ξ 𝕏 s ( Ω ) .

Put u:=v+𝕄sΩ[μ]; then uL1(Ω) and f(u)L1(Ω,ρs). By (3.2), u satisfies (1.2).

Step 2: Assume that 0τL1(Ω,ρs) and 0μL1(Ω). Let {τn}C1(Ω¯) be a nondecreasing sequence converging to τ in L1(Ω,ρs) and let {μn}C1(Ω) be a nondecreasing sequence converging to μ in L1(Ω). Then {𝕄sΩ[μn]} is nondecreasing, and by Lemma 2.7 (ii) it converges to 𝕄sΩ[μ] a.e. in Ω and in Lp(Ω,ρs) for every 1p<p2*. Let un be the unique solution of (1.1) with τ and μ replaced by τn and μn, respectively. By step 1 and the monotonicity of f, we derive that {un} and {f(un)} are nondecreasing. Moreover,

(3.3) Ω ( u n ( - Δ ) s ξ + f ( u n ) ξ ) 𝑑 x = Ω ξ 𝑑 τ n + Ω 𝕄 s Ω [ μ n ] ( - Δ ) s ξ 𝑑 x for all  ξ 𝕏 s ( Ω ) .

Let ηC(Ω¯) be the solution of

(3.4) { ( - Δ ) s η = 1 in  Ω , η = 0 in  Ω c .

Then c-1ρs<η<cρs in Ω for some c>1. By choosing ξ=η in (3.3), we get

u n L 1 ( Ω ) + f ( u n ) L 1 ( Ω , ρ s ) c ( τ n L 1 ( Ω , ρ s ) + μ n L 1 ( Ω ) ) c ( τ L 1 ( Ω , ρ s ) + μ L 1 ( Ω ) ) .

Hence {un} and {f(un)} are uniformly bounded in L1(Ω) and L1(Ω,ρs), respectively. By the monotone convergence theorem, there exists uL1(Ω) such that unu in L1(Ω) and f(un)f(u) in L1(Ω,ρs). By letting n in (3.3), we deduce that u satisfies (1.2), namely u is a weak solution of (1.1).

The uniqueness follows from the monotonicity.

Step 3: Assume that τL1(Ω,ρs) and μL1(Ω). Let {τn}C1(Ω¯) be a sequence such that {τn+} and {τn-} are nondecreasing and τn±τ± in L1(Ω,ρs). Let {μn}C1(Ω) be a sequence such that {μn+} and {μn-} are nondecreasing and μn±μ± in L1(Ω). Let un be the unique weak solution of (1.1) with data (τn,μn). Then

(3.5) u n = 𝔾 s Ω [ τ n - f ( u n ) ] + 𝕄 s Ω [ μ n ] .

Let w1,n and w2,n be the unique weak solutions of (1.1) with data (τn+,μn+) and (-τn-,-μn-), respectively. Then

(3.6) w i , n L 1 ( Ω ) + f ( w i , n ) L 1 ( Ω , ρ s ) c ( τ L 1 ( Ω , ρ s ) + μ L 1 ( Ω ) ) , i = 1 , 2 .

Moreover, for any n, w2,n0w1,n and

- 𝔾 s Ω [ τ n - ] - 𝕄 s Ω [ μ n - ] w 2 , n u n w 1 , n 𝔾 s Ω [ τ n + ] + 𝕄 s Ω [ μ n + ] ,

it follows that

(3.7) | u n | w 1 , n - w 2 , n and | f ( u n ) | f ( w 1 , n ) - f ( w 2 , n ) .

This together with (3.6) implies

(3.8) u n L 1 ( Ω ) + f ( u n ) L 1 ( Ω , ρ s ) c ′′ ( τ L 1 ( Ω , ρ s ) + μ L 1 ( Ω ) ) .

Put vn:=𝔾sΩ[τn-f(un)]. By (3.8), the sequence {τn-f(un} is uniformly bounded in L1(Ω,ρs). Hence by [11, Proposition 2.6], the sequence {vn} is relatively compact in Lq(Ω) for 1q<NN-s. Consequently, up to a subsequence, {vn} converges in Lq(Ω) and a.e. in Ω to a function v. On the other hand, by Lemma 2.7 (ii), up to a subsequence, {𝕄sΩ[μn]} converges in Lq(Ω,ρs) for 1q<p2* and a.e. in Ω to 𝕄sΩ[μ]. Due to (3.5), we deduce that {un} converges a.e. in Ω to u=v+𝕄sΩ[μ]. Since f is continuous, {f(un)} converges a.e. in Ω to f(u).

By step 2, the sequences {w1,n}, {f(w1,n)}, {-w2,n} and {-f(w2,n)} are increasing and converge to w1 in L1(Ω), f(w1) in L1(Ω,ρs), -w2 in L1(Ω) and -f(w2) in L1(Ω,ρs), respectively. In the light of (3.7) and the generalized dominated convergence theorem, we obtain that {un} and {f(un)} converge to u and f(u) in L1(Ω) and L1(Ω,ρs), respectively. By passing to the limit in (3.3), we derive that u satisfies (1.2).

The uniqueness follows from the monotonicity. ∎

Define

C ( Ω ¯ , ρ - s ) := { ζ C ( Ω ¯ ) : ρ - s ζ C ( Ω ¯ ) } .

This space is endowed with the norm

ζ C ( Ω ¯ , ρ - s ) = ρ - s ζ C ( Ω ¯ ) .

We say that a sequence {τn}𝔐(Ω,ρs) converges weakly to a measure τ𝔐(Ω,ρs) if

lim n Ω ζ 𝑑 τ n = Ω ζ 𝑑 τ for all  ζ C ( Ω ¯ , ρ - s ) .

Proof of Theorem 1.5.

Monotonicity. The monotonicity can be proved by using an argument similar to the one in the proof of Theorem 1.4.

Existence. Let {τn}C1(Ω) and {μn}C1(Ω) such that τn±τ± weakly and μn±μ± weakly. Then there is a positive constant c independent of n such that

(3.9) τ n 𝔐 ( Ω , ρ s ) c τ 𝔐 ( Ω , ρ s ) and μ n 𝔐 ( Ω ) c μ 𝔐 ( Ω ) .

Let un, w1,n and w2,n as in the proof of Theorem 1.4. Then

| u n | max ( w 1 , n , - w 2 , n ) 𝔾 s Ω [ | τ n | ] + 𝕄 s Ω [ | μ n | ] .

This, together with (2.3), (2.5) and (3.9), implies that

(3.10) u n M p 2 * ( Ω , ρ s ) c ( τ n 𝔐 ( Ω , ρ s ) + μ n 𝔐 ( Ω ) ) c ( τ 𝔐 ( Ω , ρ s ) + μ 𝔐 ( Ω ) ) .

We have

Ω ( w 1 , n ( - Δ ) s ξ + f ( w 1 , n ) ξ ) 𝑑 x = Ω ξ 𝑑 τ n + + Ω 𝕄 s Ω [ μ n + ] ( - Δ ) s ξ 𝑑 x ,
Ω ( w 2 , n ( - Δ ) s ξ + f ( w 2 , n ) ξ ) 𝑑 x = - Ω ξ 𝑑 τ n - - Ω 𝕄 s Ω [ μ n - ] ( - Δ ) s ξ 𝑑 x for all  ξ 𝕏 s ( Ω ) .

From this

Ω [ ( w 1 , n - w 2 , n ) + ( f ( w 1 , n ) - f ( w 2 , n ) η ] d x = Ω η d | τ n | + Ω 𝕄 s Ω [ | μ n | ] d x

follows. We infer from (3.7) and the estimate c-1ρsηcρs that

u n L 1 ( Ω ) + f ( u n ) L 1 ( Ω , ρ s ) c ( τ n L 1 ( Ω , ρ s ) + μ n 𝔐 ( Ω ) ) c ( τ 𝔐 ( Ω , ρ s ) + μ 𝔐 ( Ω ) ) .

This implies that {un} and {f(un)} are uniformly bounded in L1(Ω) and L1(Ω,ρs), respectively. By an argument similar to the one in step 3 of the proof of Theorem 1.4, we deduce that, up to a subsequence, {un} converges a.e. in Ω to a function u and {f(un)} converges a.e. in Ω to f(u). By the Hölder inequality, we infer that {un} is uniformly integrable in L1(Ω).

Next we prove that {fun} is uniformly integrable in L1(Ω,ρs). Define f~(s):=f(|s|)-f(-|s|), s. Then f~ is nondecreasing in and |f(s)|f~(s) for every s. For >0 and n, set

A n ( ) := { x Ω : | u n ( x ) | > } , a n ( ) := A n ( ) ρ s 𝑑 x .

We take an arbitrary Borel set DΩ and estimate

(3.11) D | f ( u n ) | ρ s 𝑑 x = D A n ( ) | f ( u n ) | ρ s 𝑑 x + D A n ( ) | f ( u n ) | ρ s 𝑑 x A n ( ) f ~ ( u n ) ρ s 𝑑 x + f ~ ( ) D ρ s 𝑑 x .

On one hand, we have

A n ( ) f ~ ( u n ) ρ s 𝑑 x = a n ( ) f ~ ( ) + a n ( s ) 𝑑 f ~ ( s ) .

From (3.10), we infer an(s)c~s-p2*, where c~ is a positive constant independent of n. Hence, for any l>,

(3.12) a n ( ) f ~ ( ) + l a n ( s ) 𝑑 f ~ ( s ) c ~ - p 2 * f ~ ( ) + c ~ l s - p 2 * 𝑑 f ~ ( s ) c ~ l - p 2 * f ~ ( l ) + c ~ p 2 * + 1 l s - 1 - p 2 * f ~ ( s ) 𝑑 s .

By assumption (1.9), there exists a sequence {lk} such that lk and lk-p2*f~(lk)0 as k. Taking l=lk in (3.12) and then letting k, we obtain

(3.13) a n ( ) f ~ ( ) + a n ( s ) 𝑑 f ~ ( s ) c ~ p 2 * + 1 s - 1 - p 2 * f ~ ( s ) 𝑑 s .

From assumption (1.9), we see that the right-hand side of (3.13) tends to 0 as . Therefore, for any ε>0, one can choose >0 such that the right-hand side of (3.13) is smaller than ε2. Fix such ; one then can choose δ>0 small such that if Dρs𝑑x<δ, then f~()Dρs𝑑x<ε2. Therefore, from (3.11) we derive that

D ρ s 𝑑 x < δ implies D | f ( u n ) | ρ s 𝑑 x < ε .

This means {fun} is uniformly integrable in L1(Ω,ρs).

By Vitali’s convergence theorem, we deduce that, up to a subsequence, unu in L1(Ω) and f(un)f(u) in L1(Ω,ρs). Since un satisfies (3.3), by passing to the limit, we deduce that u is a weak solution of (1.1).

Stability. Assume {τn}𝔐(Ω,ρs) converges weakly to τ𝔐(Ω,ρs), and {μn}𝔐(Ω) converges weakly to μ𝔐(Ω). Let u and un be the unique weak solution of (1.1) with data (τ,μ) and (τn,μn), respectively. Then by an argument similar to the one in the existence part, we deduce that unu in L1(Ω) and f(un)f(u) in Lp(Ω,ρs). ∎

Proposition 3.1.

Assume f is a continuous nondecreasing function on R satisfying f(0)=0 and (1.9). Then for every zΩ,

lim Ω x z 𝔾 s Ω [ f ( M s Ω ( , z ) ) ] ( x ) M s Ω ( x , z ) = 0 .

Proof.

By (2.1),

G s Ω ( x , y ) c 14 ρ ( x ) s | x - y | - N min { ρ ( y ) s , | x - y | s } for all  x y .

Hence,

(3.14) 𝔾 s Ω [ f ( M s Ω ( , z ) ) ] ( x ) M s Ω ( x , z ) c 15 | x - z | N Ω | x - y | - N min { | x - y | s , | y - z | s } f ( | y - z | s - N ) 𝑑 y .

Put

(3.15) 𝒟 1 := Ω B ( x , | x - z | 2 ) , 𝒟 2 := Ω B ( z , | x - z | 2 ) , 𝒟 3 := Ω ( 𝒟 1 𝒟 2 ) ,
I i := | x - z | N 𝒟 i | x - y | - N min { | x - y | s , | y - z | s } f ( | y - z | s - N ) 𝑑 y , i = 1 , 2 , 3 .

Therefore, for every y𝒟1, |x-z|2|y-z|, we have

I 1 c 16 | x - z | N f ( | x - z | s - N ) 𝒟 1 | x - y | s - N 𝑑 y c 17 | x - z | N + s f ( | x - z | s - N ) .

Hence,

(3.16) lim x z I 1 c 17 lim x z | x - z | N + s f ( | x - z | s - N ) = 0 .

We next estimate I2. Thus, for every y𝒟2, |x-z|2|x-y|, we have

I 2 c 18 𝒟 2 | y - z | s f ( | y - z | s - N ) 𝑑 y c 37 | x - z | s - N t - 1 - p 2 * f ( t ) 𝑑 t .

Therefore, by (1.9),

(3.17) lim x z I 2 c 19 lim x z | x - z | s - N t - 1 - p 2 * f ( s ) 𝑑 s = 0 .

Finally, we estimate I3. Therefore, for every y𝒟3, |y-z|3|x-y|, we have

(3.18) I 3 c 20 | x - z | N 𝒟 3 | y - z | s - N f ( | y - z | s - N ) 𝑑 y c 21 | x - z | N 0 | x - z | s - N t - N N - s f ( t ) 𝑑 t .

Put

g 1 ( r ) = 0 r s - N t - N N - s f ( t ) 𝑑 t , g 2 ( r ) = r - N .

If limr0g1(r)<, then limxzI3=0 by (3.18). Otherwise, limr0g1(r)==limr0g2(r). Therefore, by L’Hôpital’s rule,

(3.19) lim r 0 g 1 ( r ) g 2 ( r ) = lim r 0 g 1 ( r ) g 2 ( r ) = lim r 0 N - s N r N + s f ( r s - N ) = 0 .

By combining (3.18) and (3.19), we obtain

(3.20) lim x z I 3 c 22 lim x z | x - z | N 0 | x - z | s - N t - N N - s f ( t ) 𝑑 t = 0 .

We deduce (3.14) by gathering (3.16), (3.17) and (3.20). ∎

Proof of Theorem 1.6.

From Theorem 1.5 we get

k M s Ω ( x , z ) - 𝔾 s Ω [ f ( M s Ω ( , z ) ) ] ( x ) u k , z Ω ( x ) k M s Ω ( x , z ) ,

which implies

k - 𝔾 s Ω [ f ( M s Ω ( , z ) ) ] ( x ) M s Ω ( x , z ) u k , z Ω ( x ) M s Ω ( x , z ) k .

We derive (1.10) due to Proposition 3.1. ∎

3.2 Power Absorption

In this subsection, we assume that 0Ω. Let 0<p<p2* and denote by ukΩ the unique solution of (1.11). By Theorem 1.5, ukΩkMsΩ(,0) and kukΩ is increasing. Therefore, it is natural to investigate limkukΩ.

For any >0, put

T [ u ] ( y ) := 2 s p - 1 u ( y ) , y Ω := - 1 Ω .

If u is a solution of (1.14) in Ω, then T[u] is a solution of (1.14) in Ω.

By Corollary A.9, the function

x U ( x ) = s , p | x | - 2 s p - 1 , x 0 ,

where s,p is a positive constant, is a radial singular solution of

( - Δ ) s u + u p = 0 in  N { 0 } .

Lemma 3.2.

Assume p(p1*,p2*). Then there exists a positive constant C depending on N, s, p and the C2 characteristic of Ω such that the following holds: if u is a positive solution of (1.14) satisfying uU in Ω, then there holds

(3.21) u ( x ) C ρ ( x ) s | x | - ( p + 1 ) s p - 1 for all  x Ω .

Proof.

Let P(Ω{0})B1(0) and put

d = d ( P ) := 1 2 | P | < 1 2 .

Put

u d ( y ) = T d [ u ] ( y ) , y Ω d := d - 1 Ω .

Then ud is a solution of

(3.22) { ( - Δ ) s u + u p = 0 in  Ω d , u = 0 in  ( Ω d ) c .

Moreover,

u d ( y ) T d [ U ] ( y ) = d 2 s p - 1 U ( d y ) = s , p | y | - 2 s p - 1 = U ( y ) .

Put Pd=d-1P and let β0 be the constant in Proposition 2.8. We may assume β014. Let ζPC(N) such that 0ζ1 in N, ζ=0 in Bβ0(Pd) and ζ=1 in NB2β0(Pd). Let ηdC(Ω¯d) be the solution of (3.4) with Ω replaced by Ωd. For l>0, denote

V d , l := ζ P U + l η d .

We will compare ud with Vd,l.

Step 1: We show that Vd,l is a supersolution of (3.22) for l large enough. For yΩdB4β0(Pd), we have ζP(y)=1, and hence

( - Δ ) s ( ζ P U ) ( y ) = lim ε 0 N B ε ( y ) U ( y ) - ζ P ( z ) U ( z ) | y - z | N + 2 s 𝑑 z
= ( - Δ ) s U ( y ) + lim ε 0 N B ε ( y ) U ( z ) - ζ P ( z ) U ( z ) | y - z | N + 2 s 𝑑 z
( - Δ ) s U ( y ) - B 1 2 ( P d ) U ( z ) | y - z | N + 2 s 𝑑 z
( - Δ ) s U ( y ) - c 26 ,

where c26=c26(N,s,p,β0). Since

( Ω d B 2 β 0 ( 0 ) ) ( Ω d B 4 β 0 ( P d ) ) ,

it follows that, for any yΩdB2β0(0){0},

( - Δ ) s V d , l ( y ) + ( V d , l ( y ) ) p = ( - Δ ) s ( ζ P U ) ( y ) + l ( - Δ ) s η d ( y ) + ( ζ P ( y ) U ( y ) + l η d ( y ) ) p
( - Δ ) s U ( y ) - c 26 + l + U ( y ) p .

Therefore, if we choose lc26, then

(3.23) ( - Δ ) s V d , l + ( V d , l ) p 0 in  Ω d B 2 β 0 ( 0 ) { 0 } .

Next we see that there exists c27>0 such that

| ( - Δ ) s ( ζ P U ) | c 27 in  Ω d B 2 β 0 ( 0 ) .

Consequently,

( - Δ ) s V d , l = ( - Δ ) s ( ζ P U ) + l ( - Δ ) s η d - c 27 + l .

Therefore, if we choose lc27, then

(3.24) ( - Δ ) s V d , l 0 in  Ω d B 2 β 0 ( 0 ) .

By combining (3.23) and (3.24), for lmax{c26,c27}, we deduce that Vd,l is a supersolution of (3.22).

Step 2: We show that udVd,l in Ωd. By contradiction, we assume that there exists x0Ωd such that

( u d - V d , l ) ( x 0 ) = max x Ω d ( u d - V d , l ) > 0 .

Then (-Δ)s(ud-Vd,l)(x0)0. It follows that

0 ( - Δ ) s ( u d - V d , l ) ( x 0 ) - ( u d ( x 0 ) p - V d , l ( x 0 ) p ) < 0 .

This contradiction implies that udVd,l in Ωd.

Step 3: End of proof. From step 2 we deduce that

u d l η d in  Ω d B β 0 ( P d ) .

We note that ηd(y)cdist(y,Ωd)s for every yΩd. Here the constant c depends on N, s and the C2 characteristic of Ωd. Since d<12, a C2 characteristic of Ωd can be taken as a C2 characteristic of Ω. Therefore, the constant c can be taken independently of P. Consequently,

u d ( y ) l c dist ( y , Ω d ) s for all  y Ω d B β 0 ( P d ) .

This implies

(3.25) u ( x ) c ρ ( x ) s d - ( p + 1 ) s p - 1 for all  x Ω B d β 0 ( P ) .

Put

1 := Ω β 0 B 1 1 + β 0 ( 0 ) { x : ρ ( x ) β 0 | x | } , 2 := Ω β 0 B 1 1 + β 0 ( 0 ) { x : ρ ( x ) > β 0 | x | } .

If x1, then let PΩ{0} such that ρ(x)=|x-P|. It follows that

(3.26) 1 2 ( 1 - β 0 ) | x | < d = 1 2 | P | 1 2 ( 1 + β 0 ) | x | < 1 2 .

By combining (3.25) and (3.26), we get

u ( x ) c ( 1 - β 0 ) - ( p + 1 ) s p - 1 ρ ( x ) s | x | - ( p + 1 ) s p - 1 .

If x2, then (3.21) follows from the assumption uU. Thus (3.21) holds for every xΩβ0B1/(1+β0)(0). If xΩB1/(1+β0)(0), then by an argument similar to the one in step 1 and step 2 without similarity transformation, we deduce that there exist constants c and β~(0,1/(2(1+β0))) depending on N, s, p and the C2 characteristic of Ω such that (3.21) holds in Bβ~(P)Ω for every PΩB1/(1+β0)(0). Finally, since uU, inequality (3.21) holds in Dβ~/2={xΩ:ρ(x)>β~/2}. Thus (3.21) holds in Ω. ∎

Lemma 3.3.

Let p(0,p2*). There exists a constant c=c(N,s,p,Ω)>0 such that for any xΩ and zΩ there holds

(3.27) 𝔾 s Ω [ M s Ω ( , z ) p ] ( x ) { c ρ ( x ) s | x - z | s - ( N - s ) p if  s N - s < p < p 2 * , - c ρ ( x ) s ln | x - z | if  p = s N - s , c ρ ( x ) s if  0 < p < s N - s .

Proof.

We use an argument similar to the one in the proof of Proposition 3.1. It is easy to see that for every xΩ and zΩ,

𝔾 s Ω [ M s Ω ( , z ) p ] ( x ) c 23 ρ ( x ) s Ω | x - y | - N | y - z | ( s - N ) p min { | x - y | s , | y - z | s } 𝑑 y .

Let 𝒟i, i=1,2,3, be as in (3.15) and put

J i := ρ ( x ) s 𝒟 i | x - y | - N | y - z | ( s - N ) p min { | x - y | s , | y - z | s } 𝑑 y .

Now, by proceeding as in the proof of Proposition 3.1, we deduce easily that there is a positive constant c24=c24(N,s,p,Ω) such that

(3.28) J i c 24 ρ ( x ) s | x - z | s - ( N - s ) p , i = 1 , 2 ,

and

(3.29) J 3 c 24 ρ ( x ) s | x - z | / 2 diam ( Ω ) r s - 1 - ( N - s ) p d r { c 25 ρ ( x ) s | x - z | s - ( N - s ) p if  s N - s < p < p 2 * , - c 25 ρ ( x ) s ln | x - z | if  p = s N - s , c 25 ρ ( x ) s if  0 < p < s N - s .

Combining (3.28) and (3.29) implies (3.27). ∎

Proposition 3.4.

Assume p(p1*,p2*). Then uΩ:=limk0ukΩ is a positive solution of (1.14). Moreover, there exists c=c(N,s,p,Ω)>0 such that

(3.30) c - 1 ρ ( x ) s | x | - ( p + 1 ) s p - 1 u Ω ( x ) c ρ ( x ) s | x | - ( p + 1 ) s p - 1 for all  x Ω .

Proof.

We first claim that for any k>0,

(3.31) u k Ω U in  Ω .

Indeed, by (2.4),

u k Ω ( x ) k M s Ω ( x , 0 ) c 28 k ρ ( x ) s | x | - N c 28 k | x | s - N for all  x Ω .

Since p<p2*, it follows that

lim Ω x 0 u k Ω ( x ) U ( x ) = 0 .

By proceeding as in step 2 of the proof of Lemma 3.2, we deduce that ukΩU in Ω.

Consequently, uΩ:=limkukΩ is a solution of (1.14) vanishing on Ω{0} and satisfying uΩU in Ω. In the light of Lemma 3.2, we obtain the upper bound in (3.30).

Next we prove the lower bound in (3.30). By (2.4) and Lemma 3.3, for any k>0 and xΩ we have

u k Ω ( x ) k M s Ω ( x , 0 ) - k p 𝔾 s Ω [ M s Ω ( , 0 ) p ] ( x ) c 29 - 1 k ρ ( x ) s | x | - N ( 1 - c 29 c 30 k p - 1 | x | N + s - ( N - s ) p ) .

For xΩ, one can choose r>0 such that xΩ(B2r(0)Br(0)). Choose

k = a r - N + s - ( N - s ) p p - 1 ,

where a>0 will be made precise later on. Then

u k Ω ( x ) c 31 a ρ ( x ) s | x | - ( p + 1 ) s p - 1 ( 1 - c 29 c 30 a p - 1 ) .

By choosing a=(2c29c30)-1p-1, we deduce for any xΩ that there exists k>0 depending on |x| such that

u k Ω ( x ) c 32 ρ ( x ) s | x | - ( p + 1 ) s p - 1 .

Since uΩukΩ in Ω, we obtain the first inequality in (3.30). ∎

Proposition 3.5.

Assume 0<pp1*. There exist k0=k0(N,s,p) and c=c(N,s,p,Ω) such that the following holds: there exists a decreasing sequence of positive numbers {rk} such that limkrk=0 and for any k>k0,

(3.32) u k Ω ( x ) { c ρ ( x ) s | x | - N - s if  0 < p < p 1 * , c ρ ( x ) s | x | - N - s ( - ln | x | ) - 1 if  p = p 1 * , for all  x Ω B r k ( 0 ) .

Proof.

For any >0, we have

(3.33) u Ω ( x ) M s Ω ( x , 0 ) - p 𝔾 s Ω [ M s Ω ( , 0 ) p ] ( x ) for all  x Ω .

Case 1: p(sN-s,p1*). Put

k 1 := ( 2 c 29 c 30 ) s N + 2 s - N p

and take k>k1. For >0, put r=-1/s; then =r-s. Take arbitrarily xΩBrk(0); then one can choose (max(2-sk,k1),k) such that xΩ(Br(0)Br/2(0)). From (3.33) (2.4) and (3.27) we get

u Ω ( x ) c 29 - 1 ρ ( x ) s | x | - N ( 1 - c 29 c 30 p - 1 | x | N + s - ( N - s ) p )
c 29 - 1 ρ ( x ) s | x | - N r - s ( 1 - c 29 c 30 r N + 2 s - N p )
( 2 c 29 ) - 1 ρ ( x ) s | x | - N r - s
c 33 ρ ( x ) s | x | - N - s .

Here the first estimate holds since NN-s<p<p2*, and the third estimate holds since p<p1* and >k1. Since k>, we deduce that

(3.34) u k Ω ( x ) c 33 ρ ( x ) s | x | - N - s for all  x Ω B r k ( 0 ) .

Case 2: p=sN-s. Put

k 2 = ( 2 c 29 c 30 ( 1 + s ) s ) s N - s p

and take k>k2. For >0, put r=-1/s; then =r-s. Take arbitrarily xΩBrk(0); then one can choose (max(2-sk,k2),k) such that xΩ(Br(0)Br/2(0)). From (3.33), (2.4) and Lemma 3.3 we get

u Ω ( x ) c 29 - 1 ρ ( x ) s | x | - N ( 1 + c 29 c 30 p - 1 | x | N ln | x | )
c 29 - 1 ρ ( x ) s | x | - N r - s ( 1 + c 29 c 30 r N + s - s p ln ( r 2 ) )
( 2 c 29 ) - 1 ρ ( x ) s | x | - N r - s
c 33 ρ ( x ) s | x | - N - s .

Here the third estimate holds since >k2 and N-sp>0. Therefore, (3.34) holds.

Case 3: p(0,sN-s). Put

k 3 = ( 2 c 29 c 30 ) s N + s - s p

and take k>k3. For >0, put r=-1/s; then =r-s. Take arbitrarily xΩBrk(0); then one can choose (max(2-sk,k3),k) such that xΩ(Br(0)Br/2(0)). From (3.33), (2.4) and (3.27) we get

u Ω ( x ) c 29 - 1 ρ ( x ) s | x | - N ( 1 - c 29 c 30 p - 1 | x | N )
c 29 - 1 ρ ( x ) s | x | - N r - s ( 1 - c 29 c 30 r N + s - s p )
( 2 c 29 ) - 1 ρ ( x ) s | x | - N r - s
c 33 ρ ( x ) s | x | - N - s .

Here the third estimate holds since >k3 and N+s-sp>0. Therefore, (3.34) holds.

Case 4: p=p1*. Put

k 4 = exp ( ( 2 c 29 c 30 ) s N + s - ( N - s ) p )

and take k>k4. For >0, put r=(ln())-1/s; then ln()=r-s and <r-s when >3. Take arbitrarily xΩBrk(0); then one can choose (max(2-sk,k4),k) such that xΩ(Br(0)Br/2(0)). From (3.33), (2.4) and (3.27) we get

u Ω ( x ) c 29 - 1 ρ ( x ) s | x | - N ( 1 - c 29 c 30 p - 1 | x | N + s - ( N - s ) p )
c 29 - 1 ρ ( x ) s | x | - N ( 1 - c 29 c 30 p - 1 ( ln ( ) ) - N + s - ( N - s ) p s )
= c 29 - 1 ρ ( x ) s | x | - N ( 1 - c 29 c 30 ln ( ) - N + s - ( N - s ) p s )
( 2 c 29 ) - 1 ρ ( x ) s | x | - N
c 34 ρ ( x ) s | x | - N - s ( - ln | x | ) - 1 .

Here the inequality holds since p=p1*, and the last estimate follows from the estimate

= r - s ln ( ) > | x | - s - s 2 s ln | x | .

Since ukΩ(x)uΩ(x), we derive

u k Ω ( x ) c 34 ρ ( x ) s | x | - N - s ( - ln | x | ) - 1 .

By putting k0:=max(k1,k2,k3,k4), we obtain (3.32). ∎

Proposition 3.6.

Assume 0<pp1*. Then limkukΩ(x)= for every xΩ.

Proof.

The proposition can be obtained by adapting the argument in the proof of [9, Theorem 1.2]. Let r0>0 and put

θ k := B r 0 ( 0 ) u k Ω ( x ) 𝑑 x .

Then

θ k c ( B r 0 Ω ) B r k ( 0 ) ρ ( x ) s | x | N - s ( - ln | x | ) - 1 𝑑 x ,

which implies

(3.35) lim k θ k = .

Fix y0ΩB¯r0(0) and set δ:=12min{ρ(y0),|y0|-r0}. By [13, Lemma 2.4], there exists a unique classical solution wk of the following problem:

{ ( - Δ ) s w k + w k p = 0 in  B δ ( y 0 ) , w k = 0 in  N ( B δ ( y 0 ) B r 0 ( 0 ) ) , w k = u k Ω in  B r 0 ( 0 ) .

By [13, Lemma 2.2],

(3.36) u k Ω w k in  B δ ( y 0 ) .

Next put w~k:=wk-χBr0(0)uk; then w~k=wk in Bδ(y0). Moreover, for xBδ(y0),

( - Δ ) s w ~ k ( x ) = lim ε 0 B δ ( y 0 ) B ε ( x ) w k ( x ) - w k ( z ) | z - x | N + 2 s 𝑑 z + lim ε 0 B δ c ( y 0 ) B ε ( x ) w k ( x ) | z - x | N + 2 s 𝑑 z
= lim ε 0 N B ε ( x ) w k ( x ) - w k ( z ) | z - x | N + 2 s 𝑑 z + B r 0 ( 0 ) u k Ω ( z ) | z - x | N + 2 s 𝑑 z
( - Δ ) s w k ( x ) + A θ k ,

where A=(|y0|+r0)-N-2s. It follows that, for xBδ(y0),

( - Δ ) s w ~ k ( x ) + w ~ k p ( x ) ( - Δ ) s w k ( x ) + w k p ( x ) + A θ k = A θ k .

Therefore, w~kC(Bδ(y0)¯) is a supersolution of

(3.37) { ( - Δ ) s w + w p = A θ k in  B δ ( y 0 ) , w = 0 in  N B δ ( y 0 ) .

Let η0C(Bδ(y0)¯) be the unique solution of

{ ( - Δ ) s η 0 = 1 in  B δ ( y 0 ) , η 0 = 0 in  N B δ ( y 0 ) .

We can choose k large enough so that the function

η 0 ( A θ k ) 1 p 2 max N η 0

is a subsolution of (3.37). By [13, Lemma 2.2], we obtain

(3.38) w ~ k ( x ) η 0 ( A θ k ) 1 p 2 max N η 0 for all  x B δ ( y 0 ) .

Put

c ¯ := min x B δ ( y 0 ) η 0 2 max N η 0 .

Then we derive from (3.38) that

(3.39) w k ( x ) c ¯ ( A θ k ) 1 p for all  x B δ ( y 0 ) .

By combining (3.35), (3.36) and (3.39), we deduce that

lim k u k Ω ( x ) = for all  x B δ 2 ( y 0 ) .

This implies

lim k u k Ω ( x ) = for all  x Ω .

Theorem 3.7.

Assume p(1,p2*) and that either Ω=R+N:={x=(x,xN):xN>0} or Ω is compact with 0Ω. Then, for any k>0, there exists a unique solution ukΩ of problem (1.11) satisfying ukΩkMsΩ(,0) in Ω and

lim | x | 0 u k Ω ( x ) M s Ω ( x , 0 ) = k .

Moreover, the map kukΩ is increasing.

Proof.

We divide the proof into two steps. Step 1: Existence. For R>0, we set ΩR=ΩBR and let u:=ukΩR be the unique solution of

{ ( - Δ ) s u + u p = 0 in  Ω R , tr s ( u ) = k δ 0 , u = 0 on  Ω R c .

Then

(3.40) u k Ω R ( x ) k M s Ω R ( x , 0 ) for all  x Ω R .

Since RMsΩR(,0) is increasing, it follows from (1.10) that RukΩR is increasing too with the limit u* and there holds

u * ( x ) k M s Ω ( x , 0 ) for all  x Ω .

From (3.40) we deduce that

u k Ω R ( x ) c k | x | s - N    for all  x Ω R ,

where c depends only on N, s and the C2 characteristic of Ω. Hence by the regularity up to the boundary [27], {ukΩR} is uniformly bounded in Clocs(Ω¯Bε) and in Cloc2s+α(ΩBε) for any ε>0. Therefore, {ukΩR} converges locally uniformly, as R, to u*C(Ω¯{0})C2s+α(Ω). Thus u* is a positive solution of (1.14). Moreover, by combining (1.10), (3.40) and the facts that MsΩRMsΩ and ukΩRukΩ, we deduce that trs(u*)=kδ0 and

lim Ω x 0 u * ( x ) M s Ω ( x , 0 ) = k .

Step 2: Uniqueness. Suppose u and u are two weak solutions of (1.14) satisfying max{u,u}kMsΩ(,0) in Ω and

(3.41) lim Ω x 0 u ( x ) M s Ω ( x , 0 ) = lim Ω x 0 u ( x ) M s Ω ( x , 0 ) = k .

Take ε>0 and put uε:=(1+ε)u+ε, v:=(u-uε)+. Then by (3.41) there exists a smooth bounded domain GΩ such that v=0 in Gc and trsG(v)=0. In the light of Kato’s inequality, we derive (-Δ)sv0 in G. Moreover, vkMsΩ(,0) in G. By Lemma 2.12, we obtain v=0 in G, and therefore u(1+ε)u+ε in Ω. Letting ε0 yields uu in Ω. By permuting the role of u and u, we derive u=u in Ω.

By an argument similar to the one in step 2, we can show that kukΩ is increasing. ∎

Proof of Theorem 1.8.

We have two cases. (i) Case 1: p1*<p<p2*.

Since ΩC2, there exist two open balls B and B such that BΩBc and BB={0}. Since MsB(x,0)MsΩ(x,0)MsBc(x,0), it follows from Theorem 3.7 that

(3.42) u k B u k Ω u k B c ,

where the first inequality holds in B and the second inequality holds in Ω.

Let 𝒪 be B, Ω or Bc. Because of the uniqueness, we have

(3.43) T [ u k 𝒪 ] = u k 2 s p - 1 + 1 - N 𝒪 for all  > 0 ,

with 𝒪=-1𝒪. By Theorem 3.7, the sequence {uk𝒪} is increasing, and by (3.31) we have uk𝒪U. It follows that {uk𝒪} converges to a function u𝒪 which is a positive solution of (1.14) with Ω replaced by 𝒪.

Step 1: 𝒪:=+N. Then 𝒪=+N. Letting k in (3.43) yields

T [ u + N ] = u + N for all  > 0 .

Therefore, u+N is self-similar, and thus it can be written in the separable form

u + N ( x ) = u + N ( r , σ ) = r - 2 s p - 1 ω ( σ ) ,

where r=|x|, σ=x|x|SN-1 and ω satisfies (1.13). Since p1*<p<p2*, it follows from Theorem 1.7 that ω=ω*, the unique positive solution of (1.13). This means

u + N ( x ) = r - 2 s p - 1 ω * ( σ ) .

This implies (3.30).

Step 2: 𝒪:=B or Bc. In accordance with our previous notations, we set B=-1B and (Bc)=-1Bc for >0, and we have

(3.44) T [ u B ] = u B and T [ u B c ] = u ( B c )

and

u B u B u + N u ( B c ) u ( B c ) ′′ , 0 < , ′′ 1 .

When 0, then uBu¯+N and u(Bc)u¯+N, where u¯+N and u¯+N are positive solutions of (3.31) in +N such that

u B u ¯ + N u + N u ¯ + N u ( B c ) , 0 < 1 .

Furthermore, there also holds for ,>0,

T [ u B ] = T [ T [ u B ] ] = u B  and  T [ u B c ] = T [ T [ u B c ] ] = u ( B c ) .

Letting 0 and using (3.44) and the above convergence, we obtain

u ¯ + N = T [ u ¯ + N ] and u ¯ + N = T [ u ¯ + N ] , > 0 .

Again this implies that u¯+N and u¯+N are separable solutions of (1.12). Since p1*<p<p2*, by Theorem 1.7,

u ¯ + N ( x ) = u ¯ + N ( x ) = u + N ( x ) = r - 2 s p - 1 ω * ( σ ) with  r = | x | , σ = x | x | , x 0 .

Step 3: End of the proof. From (3.42) and (3.44) there holds

(3.45) u B T [ u Ω ] u ( B c ) , 0 < 1 .

Since the left-hand side and the right-hand side of (3.45) converge to the same function u+N, we obtain

lim 0 2 s p - 1 u Ω ( x ) = | x | - 2 s p - 1 ω * ( x | x | ) ,

and this convergence holds in any compact subset of Ω. Taking |x|=1, we derive (1.15). Estimate (3.30) follows from Proposition 3.4.

(ii) Case 2: 0<pp1*. Then by Proposition 3.6, limkukΩ(x)= for every xΩ. ∎


Communicated by Ireneo Peral


Funding statement: The first author is supported by Fondecyt Grant 3160207. The second author is supported by collaboration programs ECOS C14E08.

A Separable Solutions

A.1 Separable s-Harmonic Functions

We denote by (r,σ)+×SN-1 the spherical coordinates in N. Consider the following parametric representation of the unit sphere:

S N - 1 = { σ = ( cos ϕ σ , sin ϕ ) : σ S N - 2 , - π 2 ϕ π 2 } .

Hence xN=rsinϕ. We define the spherical fractional Laplace–Beltrami operator 𝒜s by

𝒜 s ω ( σ ) := lim ε 0 𝒜 s , ε ω ( σ )

with

𝒜 s , ε ω ( σ ) := a N , s + × S N - 1 B ε ( σ ) ( ω ( σ ) - ω ( η ) ) τ N - 1 ( 1 + τ 2 - 2 τ σ , η ) N 2 + s 𝑑 S ( η ) 𝑑 τ ,

where σ=(1,σ). If u:(r,σ)u(r,σ)=r-βω(σ) is s-harmonic in N{0}, it satisfies, at least formally,

𝒜 s ω - s , β ω = 0 on  S N - 1 ,

where s,β is the integral operator

s , β ω ( σ ) := a N , s 0 S N - 1 ( τ - β - 1 ) τ N - 1 ( 1 + τ 2 - 2 τ σ , η ) N 2 + s ω ( η ) 𝑑 S ( η ) 𝑑 τ ,

whenever this integral is defined. We will see in the next two lemmas that the role of the exponent β0=N is fundamental for the definition of s,βω.

Lemma A.1.

If N2, s(0,1), β<N and (σ,η)RN-1×RN-1 such that σ,η1, we define

B s , β ( σ , η ) := 0 ( τ - β - 1 ) τ N - 1 ( 1 + τ 2 - 2 τ σ , η ) N 2 + s 𝑑 τ .

Then the following statements hold:

  1. B s , β ( σ , η ) < 0 if and only if β < N - 2 s .

  2. B s , β ( σ , η ) = 0 if and only if β = N - 2 s .

  3. B s , β ( σ , η ) > 0 if and only if β > N - 2 s .

Proof.

Since β<N, the integral in (A.1) is absolutely convergent. We write

B s , β ( σ , η ) = 0 1 ( τ - β - 1 ) τ N - 1 ( 1 + τ 2 - 2 τ σ , η ) N 2 + s d τ + 1 ( τ - β - 1 ) τ N - 1 ( 1 + τ 2 - 2 τ σ , η ) N 2 + s d τ = : I + I I .

By the change of variable ττ-1,

I I = - 0 1 ( τ - β - 1 ) τ N - 1 + c s ( 1 + τ 2 - 2 τ σ , η ) N 2 + s 𝑑 τ ,

where cs=β+2s-N. Since

(A.1) B s , β ( σ , η ) = 0 1 ( τ - β - 1 ) ( τ N - 1 - τ N - 1 + c s ) ( 1 + τ 2 - 2 τ σ , η ) N 2 + s 𝑑 τ ,

the claim follows.∎

As a byproduct of (A.1) we have the following monotonicity formula.

Lemma A.2.

If N2 and s(0,1), then for any (σ,η)SN-1×SN-1 the mapping βBs,β(σ,η) is continuous and increasing from (N-2s,N) onto (0,).

In the next result we analyze the behavior of Bs,β(σ,η) when σ-η0 on SN-1.

Lemma A.3.

Assume N2, s(0,1) and β<N with βN-2s.

  1. If N 3 , there exists c = c ( N , β , s ) > 0 such that

    (A.2) | B s , β ( σ , η ) | c | σ - η | 3 - N - 2 s for all  ( σ , η ) S N - 1 × S N - 1 .

  2. If N = 2 , then one of the following statements holds:

    1. s > 1 2 and ( A.2 ) holds with N = 2 .

    2. s = 1 2 and

      | B s , β ( σ , η ) | c ( - ln | σ - η | + 1 ) for all  ( σ , η ) S 1 × S 1 .

    3. 0 < s < 1 2 and

      | B s , β ( σ , η ) | c for all  ( σ , η ) S 1 × S 1 .

Proof.

First, notice that the quantity

0 1 2 ( τ - β - 1 ) ( τ N - 1 - τ N - 1 + c s ) ( 1 + τ 2 - 2 τ σ , η ) N 2 + s 𝑑 τ

is uniformly bounded with respect to (σ,η). The only possible singularity in the expression given in (A.1) occurs when σ,η=1 and τ=1. We write σ,η=1-12κ2 and t=1-τ. Hence,

( 1 + τ 2 - 2 τ σ , η ) N 2 + s = ( t 2 + ( 1 - t ) κ 2 ) N 2 + s κ N + 2 s ( 1 + ( t κ ) 2 ) N 2 + s

as t0. Moreover,

( τ - β - 1 ) ( τ N - 1 - τ N - 1 + c s ) = ( ( 1 - t ) - β - 1 ) ( ( 1 - t ) N - 1 - ( 1 - t ) N - 1 + c s ) = c s β t 2 + O ( t 3 ) as  t 0 .

Hence,

1 2 1 ( τ - β - 1 ) ( τ N - 1 - τ N - 1 + c s ) ( 1 + τ 2 - 2 τ σ , η ) N 2 + s 𝑑 τ = 0 1 2 ( ( 1 - t ) - β - 1 ) ( ( 1 - t ) N - 1 - ( 1 - t ) N - 1 + c s ) ( t 2 + ( 1 - t ) κ 2 ) N 2 + s 𝑑 t
c s κ 3 - N - 2 s 0 1 2 κ x 2 ( 1 + x 2 ) N 2 + s 𝑑 x .

If N=2 and s<12, then

| κ 1 - 2 s 0 1 2 κ x 2 ( 1 + x 2 ) 1 + s 𝑑 x | M

for some M>0 independent of κ. If N=2 and s=12, then

0 1 2 κ x 2 ( 1 + x 2 ) 1 + 1 2 𝑑 x = ln ( 1 κ ) ( 1 + o ( 1 ) ) ,

and if N=3 or N=2 and s>12, then

0 1 2 κ x 2 ( 1 + x 2 ) N 2 + s 𝑑 x 0 x 2 ( 1 + x 2 ) N 2 + s 𝑑 x

as κ0. Since σ,ηSN-1, there holds κ2=2(1-σ,η)=|σ-η|2. Thus the claim follows.∎

Proposition A.4.

Assume N2, s(0,1) and β<N with βN-2s. Then ωLs,βω is a continuous linear operator from Lq(SN-1) into Lr(SN-1) for any 1q,r such that

(A.3) 1 r > 1 q - 2 ( 1 - s ) N - 1 .

Furthermore, Ls,β is a positive (resp. negative) operator if β<N-2s (resp. N-2s<β<N).

Proof.

By Lemma A.3, for any ηSN-1, we have Bs,β(,η)La(SN-1) for all 1<a<N-1N+2s-3 if N3 or N=2 and s>12. Furthermore,

B s , β ( , η ) 1 a < L a ( S 1 )

if N=2 and s=12, and Bs,β(,η) is uniformly bounded on S1 if N=2 and 0<s<12. The continuity result follows from Young’s inequality and the sign assertion from Lemma A.1. ∎

The above calculations justify the name of the fractional Laplace–Beltrami operator given to 𝒜s since we have the following relation.

Lemma A.5.

Assume N2 and s(0,1). Then

𝒜 s ω ( σ ) = b N , s C P V S N - 1 ( ω ( σ ) - ω ( η ) ) | σ - η | N - 1 + 2 s 𝑑 S ( η ) + s ω ( σ ) ,

where Bs is a bounded linear operator from Lq(SN-1) into Lr(SN-1) for q and r satisfying (A.3) and

b N , s := 2 a N , s 0 d x ( x 2 + 1 ) N 2 + s .

Proof.

If (σ,η)SN-1×SN-1, we set σ,η=1-12κ2. Then

0 τ N - 1 d τ ( 1 + τ 2 - 2 τ σ , η ) N 2 + s = 0 1 ( τ N - 1 + τ 2 s - 1 ) d τ ( 1 + τ 2 - 2 τ σ , η ) N 2 + s .

Then we put t=1-τ. Hence when t0, we have after some straightforward computation

( τ N - 1 + τ 2 s - 1 ) ( 1 + τ 2 - 2 τ σ , η ) N 2 + s = ( 2 - ( N + 2 s - 2 ) t + O ( t 2 ) ) ( 1 + ( N + 2 s ) t κ 2 2 ( t 2 + κ 2 ) + O ( ( t κ 2 t 2 + 2 κ 2 ) 2 ) ) ( t 2 + κ 2 ) N 2 + s = 2 + 2 t + O ( t 2 ) ( t 2 + κ 2 ) N 2 + s .

This implies

0 1 ( τ N - 1 + τ 2 s - 1 ) d τ ( 1 + τ 2 - 2 τ σ , η ) N 2 + s = 2 κ 1 - N - 2 s 0 1 κ d x ( x 2 + 1 ) N 2 + s + 2 κ 2 - N - 2 s 0 1 κ x d x ( x 2 + 1 ) N 2 + s + O ( κ 3 - N - s ) 0 1 κ x 2 d x ( x 2 + 1 ) N 2 + s
= 2 κ 1 - N - 2 s 0 d x ( x 2 + 1 ) N 2 + s + O ( 1 ) + O ( κ 3 - N - s ) 0 1 κ x 2 d x ( x 2 + 1 ) N 2 + s .

Since κ=|σ-η|, the claim follows from Proposition A.4 and the kernel estimate in Lemma A.3.∎

Lemma A.6.

Under the assumption of Lemma A.5, there holds

(A.4) | S N - 1 ω s , β ω 𝑑 S | c 35 S N - 1 ω 2 𝑑 S for all  ω L 2 ( S N - 1 ) ,

where

c 35 = 0 1 ( S N - 1 d S ( η ) ( 1 + τ 2 - 2 τ 𝐞 N , η ) N 2 + s ) ( τ - β - 1 ) | τ N - 1 - τ N - 1 + c s | 𝑑 τ .

Proof.

There holds, by the Cauchy–Schwarz inequality,

| S N - 1 ω s , β ω 𝑑 S | 0 1 ( S N - 1 S N - 1 | ω ( η ) | | ω ( σ ) | d S ( η ) d S ( σ ) ( 1 + τ 2 - 2 τ σ , η ) N 2 + s ) ( τ - β - 1 ) | τ N - 1 - τ N - 1 + c s | 𝑑 τ
0 1 ( S N - 1 S N - 1 ω 2 ( η ) ( 1 + τ 2 - 2 τ σ , η ) N 2 + s 𝑑 S ( η ) 𝑑 S ( σ ) ) × ( τ - β - 1 ) | τ N - 1 - τ N - 1 + c s | 𝑑 τ
S N - 1 ( 0 1 ( S N - 1 d S ( σ ) ( 1 + τ 2 - 2 τ σ , η ) N 2 + s ) ( τ - β - 1 ) | τ N - 1 - τ N - 1 + c s | 𝑑 τ ) ω 2 ( η ) 𝑑 S ( η ) .

Since by invariance by rotation we have

S N - 1 d S ( σ ) ( 1 + τ 2 - 2 τ σ , η ) N 2 + s = S N - 1 d S ( σ ) ( 1 + τ 2 - 2 τ 𝐞 N , σ ) N 2 + s ,

we derive (A.4).∎

We denote the upper hemisphere of the unit sphere in N by S+N-1=SN-1+N.

Proposition A.7.

Let N2, s(0,1) and N-2s<β<N. Then there exist a unique λs,β>0 and a unique (up to a homothety) positive ψ1W0s,2(S+N-1) such that

(A.5) 𝒜 s ψ 1 = λ s , β s , β ψ 1 in  S + N - 1 .

Furthermore, the mapping βλs,β is continuous and decreasing from (N-2s,N) onto (0,). Finally, λs,β=1 if and only if β=N-s and ψ1(σ)=(sinϕ)s.

Proof.

We first notice that

(A.6) S + N - 1 ω 𝒜 s ω 𝑑 S = 1 2 S + N - 1 0 S + N - 1 ( ω ( σ ) - ω ( η ) ) 2 ( 1 + τ 2 - 2 τ σ , η ) N 2 + s τ N - 1 𝑑 S ( η ) 𝑑 τ 𝑑 S ( σ )

for any ωC01(S+N-1). By Lemma A.5 and (A.3) with r=q=2,

S + N - 1 0 S + N - 1 ( ω ( σ ) - ω ( η ) ) 2 ( 1 + τ 2 - 2 τ σ , η ) N 2 + s τ N - 1 𝑑 S ( η ) 𝑑 τ 𝑑 S ( σ ) c 36 ω W 0 s , 2 ( S + N - 1 ) 2 + c 37 ω L 2 ( S + N - 1 ) 2 ,

where

ω W 0 s , 2 ( S + N - 1 ) 2 = S + N - 1 S + N - 1 ( ω ( σ ) - ω ( η ) ) 2 | η - σ | N - 1 + 2 s 𝑑 S ( η ) 𝑑 S ( σ ) .

Since by the Poincaré inequality [16] there holds

ω W 0 s , 2 ( S + N - 1 ) 2 c 38 ω L 2 ( S + N - 1 ) 2 ,

we obtain that the right-hand side of (A.6) is bounded from above by

( 1 2 c 36 + c 37 2 c 38 ) ω W 0 s , 2 ( S + N - 1 ) 2 .

Next we use the expansion estimates in Lemma A.5 to obtain that

τ N - 1 + τ 2 s - 1 ( 1 + τ 2 - 2 τ σ , η ) N 2 + s 1 ( t 2 + κ 2 ) N 2 + s for all  t = 1 - τ ( 0 , ε 0 )  and all  ( σ , η ) S + N - 1 × S + N - 1 ,

where κ=|σ-η|2. Hence,

0 τ N - 1 d τ ( 1 + τ 2 - 2 τ σ , η ) N 2 + s 0 ε 0 d t ( t 2 + κ 2 ) N 2 + s = κ 1 - N - 2 s 0 ε 0 2 d t ( t 2 + 1 ) N 2 + s .

Therefore,

S + N - 1 ω 𝒜 s ω 𝑑 S 0 ε 0 2 d t 2 ( t 2 + 1 ) N 2 + s ω W 0 s , 2 ( S + N - 1 ) 2 .

Finally, we obtain

1 c 39 ω W 0 s , 2 ( S + N - 1 ) 2 S + N - 1 0 S + N - 1 ( ω ( σ ) - ω ( η ) ) 2 ( 1 + τ 2 - 2 τ σ , η ) N 2 + s τ N - 1 𝑑 S ( η ) 𝑑 τ 𝑑 S ( σ ) c 39 ω W 0 s , 2 ( S + N - 1 ) 2 .

We consider the following bilinear form in W0s,2(S+N-1):

𝔸 ( ω , ζ ) := S + N - 1 0 S + N - 1 ( ω ( σ ) - ω ( η ) ) ζ ( σ ) ( 1 + τ 2 - 2 τ σ , η ) N 2 + s τ N - 1 𝑑 S ( η ) 𝑑 τ 𝑑 S ( σ ) .

Then 𝔸 is symmetric and there hold

𝔸 ( ω , ω ) = S + N - 1 ω 𝒜 s ω 𝑑 S 1 2 c 39 ω W 0 s , 2 ( S + N - 1 ) 2

and

| 𝔸 ( ω , ζ ) | ( S + N - 1 ω 𝒜 s ω 𝑑 S ) 1 2 ( S + N - 1 ζ 𝒜 s ζ 𝑑 S ) 1 2 c 39 2 ω W 0 s , 2 ( S + N - 1 ) ζ W 0 s , 2 ( S + N - 1 ) .

By the Riesz theorem, for any LW-s,2(S+N-1) there exists ωLW0s,2(S+N-1) such that

𝔸 ( ω L , ζ ) = L ( ζ ) for all  ζ W 0 s , 2 ( S + N - 1 ) .

We set ωL=𝒜s-1(L). It is clear that 𝒜s-1 is positive, and since the embedding of W0s,2(S+N-1) into L2(S+N-1) is compact by the Rellich–Kondrachov theorem [16], 𝒜s-1 is a compact operator. Hence the operator

ω 𝒜 s - 1 s , β ω

is a compact positive operator (here we use the fact that β>N-2s, which makes s,β positive). By the Krein–Rutman theorem, there exist μ>0 and ψ1W0s,2(S+N-1), ψ10, such that

𝒜 s - 1 s , β ψ 1 = μ ψ 1 .

The function ψ1 is the unique positive eigenfunction and μ is the only positive eigenvalue with positive eigenfunctions. Furthermore, μ is the spectral radius of 𝒜s-1s,β. If we set λs,β=μ-1, we obtain (A.5). It is also classical that λs,β can be defined by

(A.7) λ s , β := inf { S + N - 1 ω 𝒜 s ω 𝑑 S : ω W 0 s , 2 ( S + N - 1 ) , ω 0 , S + N - 1 ω s , β ω 𝑑 S = 1 } .

Using (A.1), Lemma A.2 and the monotone convergence theorem, we derive that the mapping

β S + N - 1 ω s , β ω 𝑑 S

is increasing and continuous. This implies that βλs,β is decreasing and continuous. Since

S + N - 1 ω s , β ω 𝑑 S

when βN, expression (A.7) implies that λs,β0 when βN. Next, if ω0 is an element of W0s,2(S+N-1) such that

S + N - 1 ω s , β ω 𝑑 S = 1 ,

we derive from the Poincaré inequality [16] and (A.4) that

ω W 0 s , 2 ( S + N - 1 ) 2 c 38 ω L 2 ( S + N - 1 ) 2 c 38 c 35 .

Since c350 when βN-2s, we infer that limβN-2sλs,β=. Consequently, the mapping βλs,β is a decreasing homeomorphism from (N-2s,N) onto (0,) and there exists a unique βs(N-2s,N) such that λs,βs=1. The following expression of the Martin kernel in +N is classical:

M s + N ( x , y ) = c N , s x N s | x - y | - N for all  x + N , y + N .

Hence if y=0, it is a separable singular s-harmonic function expressed in spherical coordinates with x=(r,σ) by

M s + N ( ( r , σ ) , 0 ) = c N , s r s - N ( sin ϕ ) s .

This means that the function σω(σ)=(sinϕ)s, which vanishes on S-N-1¯ and belongs to

W 0 s , 2 ( S + N - 1 ) L ( S + N - 1 ) ,

satisfies

𝒜 s ω - s , N - s ω = 0 .

The uniqueness of the positive eigenfunction implies that this function is ψ1 and β=N-s. ∎

A.2 The Nonlinear Problem

A.2.1 Separable Solutions in N

If we look for separable positive solutions of

(A.8) ( - Δ ) s u + u p = 0 in  N

under the form u(x)=r-2s/(p-1)ω(σ), where x=(r,σ)+×SN-1, then ω satisfies

(A.9) 𝒜 s ω - s , 2 s p - 1 ω + ω p = 0 in  S N - 1 .

Proposition A.8.

Assume N2 and s(0,1).

  1. If p p 3 * , then there exists no positive solution of ( A.9 ).

  2. If p 1 * < p < p 3 * , then the unique positive solution of ( A.9 ) is a constant function with value

    s , p = ( c 35 ) 1 p - 1 ,

    where c 35 is the constant defined in Lemma A.6.

Proof.

If pp3*, we assume that there exists a solution ω0 of (A.9). Then ω satisfies

S N - 1 ω 𝒜 s ω 𝑑 S - S N - 1 ω s , 2 s p - 1 ω 𝑑 S + S N - 1 ω p + 1 𝑑 S = 0 .

Since pp3*, we have cs0, which implies

S N - 1 ω s , 2 s p - 1 ω 𝑑 S 0 .

Then ω=0 since the two other integrals are nonnegative.

Next, if p1*<p<p3*, it is clear that if ω is a constant nonnegative solution of (A.9), then we have

ω 0 1 S N - 1 ( τ - 2 s p - 1 - 1 ) ( τ N - 1 - τ N - 1 + c s ) ( 1 + τ 2 - 2 τ σ , η ) N 2 + s 𝑑 S ( η ) 𝑑 τ = ω p for all  σ S N - 1 .

Using invariance by rotation of the integral term on SN-1, we derive the claim. Conversely, assume ω is any bounded nonconstant positive solution; then it belongs to C2(SN-1) by [27]. Let σ0SN-1, where ω is maximal. Then 𝒜sω(σ0)0, and thus

ω p ( σ 0 ) s , 2 s p - 1 ω ( σ 0 ) ω ( σ 0 ) 0 1 S N - 1 ( τ - 2 s p - 1 - 1 ) ( τ N - 1 - τ N - 1 + c s ) ( 1 + τ 2 - 2 σ 0 , η ) N 2 + s 𝑑 S ( η ) 𝑑 τ = c 35 ω ( σ 0 ) .

Hence ω(σ0)<s,p. Similarly, minSN-1ω>s,p, which is a contradiction. ∎

Corollary A.9.

Assume N2, s(0,1) and p1*<p<p3*. Then the only positive separable solution u of (A.8) in RN{0} is

x U ( x ) = s , p | x | - 2 s p - 1 .

A.2.2 Separable Solutions in +N

If we consider separable solutions xu(x)=r-2sp-1ω(σ) of problem (1.12), then ω satisfies (1.13).

Proof of Theorem 1.7.

We prove this in three steps. Step 1: Nonexistence. Assume that such a solution ω0 exists; then

S + N - 1 ω 𝒜 s ω 𝑑 S - S + N - 1 ω s , 2 s p - 1 ω 𝑑 S + S + N - 1 ω p 𝑑 S = 0 .

Hence,

( λ s , 2 s p - 1 - 1 ) S + N - 1 ω s , 2 s p - 1 ω 𝑑 S + S + N - 1 ω p 𝑑 S 0 .

If λs,2s/(p-1)1, equivalently pp2*, the only nonnegative solution is the trivial one.

Step 2: Existence. Consider the following functional with domain W0s,2(S+N-1)Lp+1(S+N-1):

ω 𝒥 ( ω ) := S + N - 1 ω 𝒜 s ω 𝑑 S + 1 p + 1 S + N - 1 | ω | p + 1 𝑑 S - S + N - 1 ω s , 2 s p - 1 ω 𝑑 S .

Because of Lemma A.6, 𝒥(ω) when ωW0s,2(S+N-1)+ωLp+1(S+N-1). Furthermore, for ε>0, we have

𝒥 ( ε ψ 1 ) = ε 2 ( λ s , 2 s p - 1 - 1 ) S + N - 1 ψ 1 s , 2 s p - 1 ψ 1 𝑑 S + ε p + 1 p + 1 S + N - 1 | ψ 1 | p + 1 𝑑 S .

This implies that inf𝒥(ω)<0 if λs,2s/(p-1)<1, and thus the infimum of 𝒥 in W0s,2(S+N-1)L+p+1(S+N-1) is achieved by a nontrivial nonnegative solution of (1.13).

Step 3: Uniqueness.

(i) Existence of a maximal solution. By [27], any solution ω is smooth. Hence, at its maximum σ0 it satisfies 𝒜sω(σ0)0, and thus

ω ( σ 0 ) p s , 2 s p - 1 ω ( σ 0 ) ω ( σ 0 ) c 35 .

This implies that supωs,p. From this inequality the set W0s,2(S+N-1) of positive solutions of (1.13) is bounded in W0s,2(S+N-1)L(S+N-1), and thus in Cs(SN-1)C2(S+N-1) by [27]. We put ω¯(σ)=sup{ω(σ):ω}. There exists a countable dense set 𝒮:={σn}S+N-1 and a sequence of functions {ωn} such that

lim n ω n ( σ k ) = ω ¯ ( σ k ) .

Furthermore, this sequence {ωn} can be constructed such that {ωn(σk)} is nondecreasing for any k. Finally, by a local compactness estimate, {ωn} converges to ω¯ in Cs-δ(SN-1)C2(S+N-1) for any δ(0,s) and weakly in W0s,2(S+N-1). This implies that ω¯ belongs to . It follows from [27, Theorem 1.2] that any ω satisfies

(A.10) ω ( σ ) c 40 ( dist ( σ , S + N - 1 ) ) s = c 40 ϕ s for all  σ S + N - 1 .

(ii) Existence of a minimal solution. From Theorem 3.7 follows that uk+Nu+N and u+N is self-similar and it is the minimal solution of (1.14) in +N which satisfies

lim x 0 u + N ( x ) M s + N ( x , 0 ) = .

Hence u+N(r,σ)=r-2sp-1ω¯(σ) and ω¯ is the minimal positive solution of (1.13). Furthermore, it follows from (3.30) that

(A.11) ω ¯ ( σ ) c 41 ( dist ( σ , S + N - 1 ) ) s = c 41 ϕ s for all  σ S + N - 1

if ϕ=ϕ(σ) is the latitude of σ.

(iii) End of the uniqueness proof. By combining (A.10) and (A.11), we infer that there exists K>1 such that

ω ¯ K ω ¯ in  S + N - 1 .

Assume ω¯ω¯; then

ω 1 := ω ¯ - 1 2 K ( ω ¯ - ω ¯ )

is a positive supersolution (by convexity) of (1.13). Moreover,

ω 2 := ( 1 2 + 1 2 K ) ω ¯

is a positive subsolution of (1.13) smaller than ω1, hence also than ω¯. It follows by classical construction that there exists a solution ω~ of (1.13) which satisfies ω2ω~ω1, which contradicts the minimality of ω¯. ∎

References

[1] N. Abatangelo, Large S-harmonic functions and boundary blow-up solutions for the fractional Laplacian, Discrete Contin. Dyn. Syst. 35 (2015), no. 12, 5555–5607. 10.3934/dcds.2015.35.5555Suche in Google Scholar

[2] M.-F. Bidaut-Véron and L. Vivier, An elliptic semilinear equation with source term involving boundary measures: The subcritical case, Rev. Mat. Iberoam. 16 (2000), no. 3, 477–513. 10.4171/RMI/281Suche in Google Scholar

[3] K. Bogdan, The boundary Harnack principle for the fractional Laplacian, Studia Math. 123 (1997), no. 1, 43–80. 10.4064/sm-123-1-43-80Suche in Google Scholar

[4] K. Bogdan, Representation of α-harmonic functions in Lipschitz domains, Hiroshima Math. J. 29 (1999), no. 2, 227–243. 10.32917/hmj/1206125005Suche in Google Scholar

[5] K. Bogdan and T. Byczkowski, Potential theory for the α-stable Schrödinger operator on bounded Lipschitz domains, Studia Math. 133 (1999), no. 1, 53–92. 10.4064/sm-133-1-53-92Suche in Google Scholar

[6] K. Bogdan, T. Byczkowski, T. Kulczycki, M. Ryznar, R. Song and Z. Vondraček, Potential Analysis of Stable Processes and its Extensions, Lecture Notes in Math. 1980, Springer, Berlin, 2009. 10.1007/978-3-642-02141-1Suche in Google Scholar

[7] K. Bogdan, T. Kulczycki and M. Kwaśnicki, Estimates and structure of α-harmonic functions, Probab. Theory Related Fields 140 (2008), no. 3–4, 345–381. 10.1007/s00440-007-0067-0Suche in Google Scholar

[8] L. A. Caffarelli and Y. Sire, On some pointwise inequalities involving nonlocal operators, Harmonic Analysis, Partial Differential Equations and Applications, Appl. Numer. Harmon. Anal., Birkhäuser/Springer, Cham (2017), 1–18. 10.1007/978-3-319-52742-0_1Suche in Google Scholar

[9] H. Chen, S. Alhomedan, H. Hajaiej and P. Markowich, Complete study of the existence and uniqueness of solutions for semilinear elliptic equations involving measures concentrated on boundary, Complex Var. Elliptic Equ. 62 (2017), no. 12, 1687–1729. 10.1080/17476933.2016.1278441Suche in Google Scholar

[10] H. Chen, P. Felmer and A. Quaas, Large solutions to elliptic equations involving fractional Laplacian, Ann. Inst. H. Poincaré Anal. Non Linéaire 32 (2015), no. 6, 1199–1228. 10.1016/j.anihpc.2014.08.001Suche in Google Scholar

[11] H. Chen and L. Véron, Semilinear fractional elliptic equations involving measures, J. Differential Equations 257 (2014), no. 5, 1457–1486. 10.1016/j.jde.2014.05.012Suche in Google Scholar

[12] H. Chen and L. Véron, Weakly and strongly singular solutions of semilinear fractional elliptic equations, Asymptot. Anal. 88 (2014), no. 3, 165–184. 10.3233/ASY-141216Suche in Google Scholar

[13] H. Chen and J. Yang, Semilinear fractional elliptic equations with measures in unbounded domain, Nonlinear Anal. 145 (2016), 118–142. 10.1016/j.na.2016.08.003Suche in Google Scholar

[14] Z.-Q. Chen and R. Song, Estimates on Green functions and Poisson kernels for symmetric stable processes, Math. Ann. 312 (1998), no. 3, 465–501. 10.1007/s002080050232Suche in Google Scholar

[15] Z.-Q. Chen and R. Song, Martin boundary and integral representation for harmonic functions of symmetric stable processes, J. Funct. Anal. 159 (1998), no. 1, 267–294. 10.1006/jfan.1998.3304Suche in Google Scholar

[16] E. Di Nezza, G. Palatucci and E. Valdinoci, Hitchhiker’s guide to the fractional Sobolev spaces, Bull. Sci. Math. 136 (2012), no. 5, 521–573. 10.1016/j.bulsci.2011.12.004Suche in Google Scholar

[17] P. Felmer and A. Quaas, Boundary blow up solutions for fractional elliptic equations, Asymptot. Anal. 78 (2012), no. 3, 123–144. 10.3233/ASY-2011-1081Suche in Google Scholar

[18] A. Gmira and L. Véron, Boundary singularities of solutions of some nonlinear elliptic equations, Duke Math. J. 64 (1991), no. 2, 271–324. 10.1215/S0012-7094-91-06414-8Suche in Google Scholar

[19] P. Graczyk, T. Jakubowski and T. Luks, Martin representation and relative Fatou theorem for fractional Laplacian with a gradient perturbation, Positivity 17 (2013), no. 4, 1043–1070. 10.1007/s11117-012-0220-6Suche in Google Scholar

[20] M. Kwaśnicki, Ten equivalent definitions of the fractional Laplace operator, Fract. Calc. Appl. Anal. 20 (2017), no. 1, 7–51. 10.1515/fca-2017-0002Suche in Google Scholar

[21] M. Marcus and P.-T. Nguyen, Moderate solutions of semilinear elliptic equations with Hardy potential, Ann. Inst. H. Poincaré Anal. Non Linéaire 34 (2017), no. 1, 69–88. 10.1016/j.anihpc.2015.10.001Suche in Google Scholar

[22] M. Marcus and L. Véron, The boundary trace of positive solutions of semilinear elliptic equations: The subcritical case, Arch. Ration. Mech. Anal. 144 (1998), no. 3, 201–231. 10.1007/s002050050116Suche in Google Scholar

[23] M. Marcus and L. Veron, The boundary trace of positive solutions of semilinear elliptic equations: The supercritical case, J. Math. Pures Appl. (9) 77 (1998), no. 5, 481–524. 10.1016/S0021-7824(98)80028-7Suche in Google Scholar

[24] M. Marcus and L. Veron, Removable singularities and boundary traces, J. Math. Pures Appl. (9) 80 (2001), no. 9, 879–900. 10.1016/S0021-7824(01)01209-0Suche in Google Scholar

[25] M. Marcus and L. Véron, The boundary trace and generalized boundary value problem for semilinear elliptic equations with coercive absorption, Comm. Pure Appl. Math. 56 (2003), no. 6, 689–731. 10.1002/cpa.3037Suche in Google Scholar

[26] M. Marcus and L. Véron, Nonlinear Second Order Elliptic Equations Involving Measures, De Gruyter Ser. Nonlinear Anal. Appl. 21, De Gruyter, Berlin, 2014. 10.1515/9783110305319Suche in Google Scholar

[27] X. Ros-Oton and J. Serra, The Dirichlet problem for the fractional Laplacian: Regularity up to the boundary, J. Math. Pures Appl. (9) 101 (2014), no. 3, 275–302. 10.1016/j.matpur.2013.06.003Suche in Google Scholar

Received: 2017-12-04
Accepted: 2018-01-02
Published Online: 2018-02-07
Published in Print: 2018-04-01

© 2018 Walter de Gruyter GmbH, Berlin/Boston

This work is licensed under the Creative Commons Attribution 4.0 International License.

Heruntergeladen am 21.9.2025 von https://www.degruyterbrill.com/document/doi/10.1515/ans-2017-6048/html?lang=de
Button zum nach oben scrollen