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Multiplicity of normalized semi-classical states for a class of nonlinear Choquard equations

  • Jinxia Wu and Xiaoming He EMAIL logo
Published/Copyright: September 23, 2024

Abstract

This article is concerned with the existence of multiple normalized solutions for a class of Choquard equations with a parametric perturbation

ε 2 Δ u + V ( x ) u = λ u + ε α ( I α * F ( u ) ) f ( u ) , x R N , R N u 2 d x = a 2 ε N ,

where a > 0 is a constant, ε > 0 is a parameter, N 3 , α ( 0 , N ) , λ R is unknown and appears as a Lagrange multiplier, f is a continuous function with L 2 -subcritical growth, and V : R N [ 0 , ) is a continuous function, satisfying del Pino and Felmer’s local conditions. With the help of the penalization method, and Lusternik-Schnirelmann theory, we investigate the relationship between the number of positive normalized solutions and the topology of the set, where the potential V attains its minimum value if the parameter ε > 0 is small.

MSC 2010: 35A15; 35B33; 35J20; 35J60

1 Introduction and main results

In this article, we study the existence of multiple normalized semi-classical states to the following Choquard equation:

(1.1) ε 2 Δ u + V ( x ) u = λ u + ε α ( I α * F ( u ) ) f ( u ) , x R N ,

where a , ε > 0 , N 3 , α ( 0 , N ) , λ R , F ( t ) = 0 t f ( s ) d s . The Ruiz potential I α : R N R is the Riesz potential defined as follows:

I α ( x ) Γ N α 2 Γ N 2 π N 2 2 α 1 x N α , x R N \ { 0 } .

When λ R is a fixed and assigned parameter or even with an additional external, the existence of nontrivial solutions of (1.1) has been studied during the last decade. For example, when λ = 1 , ε = 1 , α = 2 , and F ( u ) = u 2 , (1.1) comes back to the description of the quantum theory of a polaron at rest by Pekar [39] and the modeling of an electron trapped in its own hole (in the work of Choquard in 1976), in a certain approximation to the Hartree-Fock theory of one-component plasma [29]. The equation is also known as the Schrödinger-Newton equation, which was proposed by Penrose [40] in 1996 as a model of self-gravitating matter. Under this condition, the existence of nontrivial solutions was investigated by various variational methods by Lieb [29] and Menzala [30] and also by ordinary differential equations methods [14,26,31,44]. There are also many articles investigating the Choquard equation under the general pure nonlinearity condition. In 2013, Moroz and Van Schaftingen [32] considered the semilinear elliptic problem:

(1.2) Δ u + u = ( I α * u p ) u p 2 u , x R N ,

where N 3 , α ( 0 , N ) . They proved that there is a positive ground state solution to (1.2) when N + α N < p < N + α N 2 . In 2015, Moroz and Van Schaftingen [33] also considered semi-classical states of nonlocal problems:

(1.3) ε 2 Δ u + V u = ε α ( I α * u p ) u p 2 u , x R N ,

where N 1 , α ( 0 , N ) , and ε > 0 is a small parameter. By using variational methods and a new nonlocal penalization technique, they proved that equation (1.3) has a family of solutions centered on the local minimum of potential V for each small ε > 0 . Moroz and Schaftingen [36] proved problem (1.3) has a groundstate solution if ε = 1 , λ = 0 , V ( x ) 1 and the nonlinearity satisfies the following almost necessary conditions:

  1. there exists C > 0 such that for every s R , s f ( s ) C ( s N + α N + s N + α N 2 ) ;

  2. lim s 0 F ( s ) s N + α N = 0 and lim s F ( s ) s N + α N 2 = 0 ;

  3. there exists s 0 R \ { 0 } such that F ( s 0 ) = 0 .

So far as we know, the case that the parameter λ in (1.1) is fixed and assigned has been extensively studied, and we refer to [3437] for more results on problem (1.1) without prescribed mass. However, since physicists are often interested in “normalized” solutions, i.e., solutions with prescribed L 2 -norm, it is interesting for us to study whether problem (1.1) has a couple of weak solution ( u c , λ c ) H 1 ( R N ) × R such that R N u 2 d x = c for any fixed c > 0 . In the past years, normalized solutions to nonlinear elliptic problems have been well studied. In the seminal article [21], Jeanjean studied the normalized solutions to the Schrödinger equation:

(1.4) Δ u = λ u + g ( u ) , x R N , R N u 2 d x = a 2 , u H 1 ( R N ) ,

where g ( s ) is of the type g ( s ) = i = 1 m a i s σ 1 s with for a i > 0 , 0 < σ i < N N 2 for N 3 , and σ i > 0 if N = 1 , 2 , and i = 1 , , m with m N . Since then, the study of normalized solutions for Schrödinger equations is attracting much attention of more and more researchers in the past few years, and there have been many scholars devoted to the existence of multiple normalized solution, for instances, we refer to Bartsch et al. [7], Hirata and Tanaka [19], Ikoma and Tanaka [20], Bartsch and Soave [11], Bartsch and de Valeriola [10], Jeanjean and Lu [22], Cingolani and Jeanjean [12], Lan et al. [25], Noris et al. [38], Jeanjean and Le [23,24], Guo and Jeanjean [17], Soave [42,43], Wang and Sun [45], and the references therein.

We notice that some scholars have studied the normalized solutions for Schrödinger equations with nonconstant potentials in recent years. Especially, Bartsch et al. [9] studied the normalized solutions for mass supercritical Schrödinger equations with potential

(1.5) Δ u + V ( x ) u + λ u = u p 2 u , x R N .

They proved the existence of a solution ( u , λ ) H 1 ( R N ) × R + with prescribed L 2 -norm u 2 = ρ under various conditions on the potential V : R N R , positive and vanishing at infinity, including potentials with singularities, by using a new min-max argument. Alves [1] focused on existence of multiple normalized solutions to the following Schrodinger equation with nonconstant potential

(1.6) Δ u = λ u + h ( ε x ) f ( u ) , x R N , R N u 2 d x = a 2 ,

where a , ε > 0 , f has L 2 -subcritical growth, and h : R N [ 0 , ) is a continuous function with the following assumptions:

  1. h C ( R N ) and 0 < h 0 = inf x R N h ( x ) max x R N h ( x ) = h max ;

  2. h = lim x + h ( x ) < h max ;

  3. h 1 ( { h max } ) = { a 1 , a 2 , , a l } with a 1 = 0 and a j a s if j s .

The author showed that when ε is sufficiently small, the number of normalized solutions in (1.6) is not less than the number of global maximum points of h . Alves and Thin [4,5] studied the existence and multiplicity of normalized solutions of the following Schrödinger equation with potential V ( x ) and a parameter ε

(1.7) Δ u + V ( ε x ) u = λ u + f ( u ) , x R N , R N u 2 d x = a 2 ,

where V satisfies the Rabinowitz’s global condition [41] or del Pino and Felmer’s local condition [15], and the Lusternik-Schnirelmann theory is applied.

When V ( x ) 0 and ε = 1 , Li and Ye [28] considered the normalized solution to equation (1.1) as follows:

(1.8) Δ u = λ u + ( I α * F ( u ) ) f ( u ) , x R N , R N u 2 d x = a 2 ,

where F satisfies some superlinear growth, but Sobolev subcritical conditions, they proved the existence of a positive solution of (1.8) under prescribed L 2 -norm by using minimax procedure and concentration compactness. Yuan et al. [48] revisited problem (1.8) under the weaker conditions imposed on the nonlinearity f , by using a minimax procedure and some new analytical techniques, and showed that for any a > 0 , (1.8) possesses at least a couple of weak solution. Recently, Bartsch et al. [8] proved the existence of a least energy solution of (1.8) based on a linking argument, and obtained the existence of infinitely many normalized solutions by using a cohomological index theory when f is odd in u . When f ( u ) = u 2 α * 2 u , and 2 α * = N + α N 2 is the Hardy-Littlewood-Sobolev critical exponent, problem (1.8) reduces to the following type of problem with a subcritical perturbation μ u q 2 u :

(1.9) Δ u = λ u + μ u q 2 u + ( I α * u 2 α * ) u 2 α * 2 u , x R N , R N u 2 d x = a 2 , u H 1 ( R N ) ,

where N 3 , μ , a > 0 , q ( 2 , 2 + 4 N ) . Li [27] showed the existence of the ground state, and its radial symmetry, exponential decay and orbital stability, instability. Ye et al. [47] proved that (1.9) with μ u q 2 u being replaced by a nonlocal perturbation μ ( I α u q ) u q 2 u has normalized ground states and mountain-pass type solutions, under the L 2 -subcritical growth, L 2 -critical, or L 2 -supercritical growth.

Motivated by the aforementioned works, in this article, we consider the normalized semiclassical states to the following Choquard problem:

(1.10) ε 2 Δ u + V ( x ) u = λ u + ε α ( I α * F ( u ) ) f ( u ) , x R N , R N u 2 d x = a 2 ε N ,

where a > 0 is a constant, ε > 0 is a parameter, N 3 , α ( 0 , N ) , λ R is unknown and appears as a Lagrange multiplier, and the potential V is a bounded continuous function and satisfies the following assumptions.

  1. V C ( R N , R ) L ( R N ) , V ( x ) 0 for each x R N ;

  2. There exists a bounded set Λ R N such that

    min x Λ ¯ V ( x ) < min x Λ V ( x ) = V .

    Without loss of generality, we usually assume that 0 Λ and V ( 0 ) = min x Λ ¯ V ( x ) .

The nonlinearity f is a continuous function with a L 2 -subcritical growth and satisfies the following conditions:
  1. f is an odd function and lim s 0 f ( s ) s q 0 1 = β > 0 , q 0 1 + α N , 1 + 2 + α N ;

  2. There are constants c 1 , c 2 > 0 and p 1 1 + α N , 1 + 2 + α N satisfying

    f ( s ) c 1 + c 2 s p 1 1 , s R ;

  3. There exists q q 0 , 1 + 2 + α N such that f ( s ) s q 1 is an increasing function for s ( 0 , + ) .

Remark 1.1

There exists f satisfying the above conditions, e.g.,

f ( s ) = s q 0 2 s + s p 2 s ln ( 1 + s ) , s R ,

for some 1 + α N < q 0 < p < 1 + 2 + α N < 2 * . Hence, ( f 3 ) holds by taking q = q 0 ; moreover, condition ( f 3 ) tells us that q p 1 .

Next, we define the sets

M = { x Λ ¯ : V ( x ) = V ( 0 ) }

and

M δ = { x Λ ¯ : dist ( x , M ) δ } ,

where δ > 0 and dist ( x , M ) is the distance between x and M in R N .

The main result of the article can be formulated as below.

Theorem 1.1

Assume that V satisfies the conditions ( V 1 ) ( V 2 ) and f satisfies the hypotheses ( f 1 ) ( f 3 ) . Then there are ε 0 , V * > 0 such that for any δ > 0 small enough and 0 < ε < ε 0 , V < V * , problem (1.10) has at least cat M δ ( M ) couples ( u k , λ k ) H 1 ( R N ) × R of weak solutions with R N u k 2 d x = a 2 ε N , λ k < 0 . Furthermore, if u ε is one of the solutions and η ε is the global maximum point of u ε , then lim ε 0 V ( η ε ) = 0 .

After a simple change of variables, problem (1.10) can be transformed into the following equivalent form:

(1.11) Δ u + V ( ε x ) u = λ u + ( I α * F ( u ) ) f ( u ) , x R N , R N u 2 d x = a 2 .

To study the existence of multiple normalized solutions of problem (1.11), we shall look for the critical points of the corresponding energy functional

I ( u ) = 1 2 R N u 2 d x + 1 2 R N V ( ε x ) u 2 d x 1 2 R N ( I α * F ( u ) ) F ( u ) d x ,

constrained to the S ( a ) given below:

(1.12) S ( a ) = { u H 1 ( R N ) : u 2 = a } .

We would like to recall that if Y is a closed subset of a topological space X , the Lusternik- Schnirelmann category cat X ( Y ) is the least number of closed and contractible sets in X which cover Y . If X = Y , we use the notation cat ( X ) . For more details about this subject, we refer to [46].

The main structure of the article is as follows: In Section 2, we consider the autonomous case of the equation (1.11) and show some technical results. In Section 3, we focus on the nonautonomous case and study the penalized problem by using truncation techniques. In this section, we prove that the modified energy functional satisfies the Palais-Smale condition, and obtain some useful tools, which are useful for the proof of the following main conclusions. In Section 4, we prove the Theorem 1.1.

Throughout this article, we use the notation p to denote the norm in L p ( R N ) and use C , C j , j = 1 , 2 , , to denote generic constants whose values might be irrelevant. But the ones which we need to emphasize will be denoted by the special characteristics.

2 The autonomous case

In this section, we first consider the autonomous case and prove some relevant conclusions to facilitate the subsequent argument. We start by reviewing the following two inequalities, which will be used frequently used.

The Gagliardo-Nirenberg inequality: If N 3 , then for each l [ 2 , 2 N N 2 ) , there exists C = C ( N , l ) > 0 such that

(2.1) u l l C u 2 ( 1 β l ) l u 2 β l l , in R N , β l = N 1 2 1 l .

Proposition 2.1

(Hardy-Littlewood-Sobolev inequality) Assume that t , r > 1 , and 0 < α < N with 1 t + α N + 1 r = 2 , f L t ( R N ) and h L r ( R N ) , then there exists a sharp constant C ( t , N , α , r ) independent of f , h satisfying

(2.2) R 2 N f ( x ) h ( y ) x y α d x d y C ( t , N , α , r ) f t h r .

If t = r = 2 N 2 N α , then

C ( t , N , α , r ) = C ( N , α ) = π α 2 Γ π 2 α 2 Γ N α 2 Γ π 2 Γ ( N ) 1 + α N .

In this case, there is equality in (2.2) if and only if f C h and

h ( x ) = A ( δ 2 + x x 0 2 ) 2 N α 2

for some A C , δ R \ { 0 } and x 0 R N .

Combined with (2.2), through a simple calculation, it is easy to obtain

(2.3) R N ( I α * F ( u ) ) F ( u ) d x C F ( u ) 2 N N + α 2 .

Next, we focus on the existence of a normalized solution to the following problem:

(2.4) Δ u + μ u = λ u + ( I α * F ( u ) ) f ( u ) , x R N , R N u 2 d x = a 2 ,

where a , μ > 0 , λ R is unknown and appears as a Lagrange multiplier and f satisfies ( f 1 ) ( f 3 ) . Our goal is to find the critical point of the energy functional:

I μ ( u ) = 1 2 R N u 2 d x + 1 2 R N μ u 2 d x 1 2 R N ( I α * F ( u ) ) F ( u ) d x

constrained to the sphere S ( a ) given in (1.12).

Our main conclusion in this section, is stated as follows.

Theorem 2.1

Assume that f satisfies the hypotheses ( f 1 ) ( f 3 ) . Then there exists V * > 0 such that for any μ [ 0 , V * ] , equation (2.4) has a couple solution ( u , λ ) , where u is positive, radial and λ < 0 .

To prove the Theorem 2.1, we first propose several lemmas.

Lemma 2.2

The functional I μ ( u ) in S ( a ) is bounded from below.

Proof

Using ( f 1 ) ( f 2 ) , we infer that there exists C 1 , C 2 > 0 such that

F ( t ) C 1 t q 0 + C 2 t p 1 , t R .

According to (2.1) and (2.3), for any u S ( a ) , we have

R N ( I α * F ( u ) ) F ( u ) d x C F ( u ) 2 N N + α 2 = C R N F ( u ) 2 N N + α d x N + α N C R N u 2 N q 0 N + α d x + R N u 2 N p 1 N + α d x N + α N C u 2 N q 0 N + α 2 q 0 + u 2 N p 1 N + α 2 p 1 C [ u 2 ( 2 N ) q 0 + N + α u 2 N q 0 N α + u 2 ( 2 N ) p 1 + N + α u 2 N p 1 N α ] .

Thus, one has

I μ ( u ) = 1 2 R N u 2 d x + 1 2 μ a 2 1 2 R N ( I α * F ( u ) ) F ( u ) d x 1 2 R N u 2 d x + 1 2 μ a 2 1 2 C [ a ( 2 N ) q 0 + N + α u 2 N q 0 N α + a ( 2 N ) p 1 + N + α u 2 N p 1 N α ] .

Since q 0 , p 1 1 + α N , 1 + 2 + α N , then N q 0 N α , N p 1 N α < 2 . That completes the proof.□

From the previous lemma, we know that the real number

μ , a = inf u S ( a ) I μ ( u )

is well defined. Next, we discuss some properties of I μ .

Lemma 2.3

There exists V * > 0 such that μ , a < 0 holds for any μ [ 0 , V * ] and a > 0 .

Proof

From the condition ( f 1 ) , we obtain lim t 0 q 0 F ( t ) t q 0 = β > 0 , so that there exists δ > 0 such that

(2.5) q 0 F ( t ) t q 0 β 2 , t [ 0 , δ ] .

Given a nonnegative function u 0 S ( a ) L ( R N ) , we define

H ( u 0 , s ) ( x ) = e N s 2 u 0 ( e s x ) , x R N and s R .

It is easy to obtain

(2.6) R N H ( u 0 , s ) ( x ) 2 d x = a 2 .

Consequently,

(2.7) I μ ( H ( u 0 , s ) ) = 1 2 R N H ( u 0 , s ) 2 d x + 1 2 R N μ H ( u 0 , s ) 2 d x 1 2 R N ( I α * F ( H ( u 0 , s ) ) ) F ( H ( u 0 , s ) ) d x = 1 2 e 2 s u 0 2 2 + 1 2 μ a 2 1 2 e s ( N + α ) R N ( I α * F ( e N s 2 u 0 ) ) F ( e N s 2 u 0 ) d x .

When s < 0 and s large enough, one can derive that

0 e N s 2 u 0 ( x ) δ , x R N .

Combined with (2.5), we deduce to

(2.8) R N ( I α * F ( e N s 2 u 0 ) ) F ( e N s 2 u 0 ) d x β 2 q 0 2 e N s q 0 R N ( I α * u 0 q 0 ) u 0 q 0 d x .

Thus, according to (2.7) and (2.8), we know

I μ ( H ( u 0 , s ) ) 1 2 e 2 s u 0 2 2 + 1 2 μ a 2 1 2 β 2 q 0 2 e N s q 0 s ( N + α ) R N ( I α * u 0 q 0 ) u 0 q 0 d x .

As q 0 1 + α N , 1 + 2 + α N , then N s q 0 s ( N + α ) ( 2 s , 0 ) . From (2.2), it can be derived that

R N ( I α * u 0 q 0 ) u 0 q 0 d x C u 0 2 N q 0 N + α 2 q 0 .

By q 0 1 + α N , 1 + 2 + α N , we can obtain 2 N q 0 N + α 2 , 2 + 4 N + α , so R N ( I α * u 0 q 0 ) u 0 q 0 d x is bounded.

By increasing s appropriately, we can deduce

(2.9) 1 2 e 2 s u 0 2 2 1 2 β 2 q 0 2 e N s q 0 s ( N + α ) R N ( I α * u 0 q 0 ) u 0 q 0 d x D s < 0 .

Next, we take the constant V * > 0 small enough to satisfy

(2.10) D s + 1 2 V * a 2 < 0 ,

then for all μ [ 0 , V * ] , one can obtain

I μ ( H ( u 0 , s ) ) D s + 1 2 V * a 2 < 0 .

Lemma 2.4

For V * in Lemma 2.3, we fix μ [ 0 , V * ] and set 0 < a 1 < a 2 , then a 1 2 a 2 2 μ , a 2 < μ , a 1 < 0 .

Proof

Let γ > 1 be a constant and satisfies a 2 = γ a 1 , and take the sequence of nonnegative functions { u n } S ( a 1 ) being a minimizing sequence of μ , a 1 , which exists since for any u H 1 ( R N ) , I μ ( u ) = I μ ( u ) holds. In other words,

I μ ( u n ) μ , a 1 , n + .

Let v n = γ u n , then v n S ( a 2 ) . It is known that F ( t ) t q is an increasing function on ( 0 , + ) from ( f 3 ) . Thus, we can obtain

F ( t s ) t q F ( s ) , t 1 , s > 0

and

(2.11) μ , a 2 I μ ( v n ) = γ 2 I μ ( u n ) + 1 2 γ 2 R N ( I α * F ( u n ) ) F ( u n ) d x 1 2 R N ( I α * F ( γ u n ) ) F ( γ u n ) d x γ 2 I μ ( u n ) + 1 2 ( γ 2 γ 2 q ) R N ( I α * F ( u n ) ) F ( u n ) d x .

Claim 1. We assert that there must be a positive constant C > 0 and n 0 N such that for each n n 0 ,

R N ( I α * F ( u n ) ) F ( u n ) d x C .

Indeed, suppose by contradiction that, there is a subsequence { u n } , still denoted as { u n } , satisfied

R N ( I α * F ( u n ) ) F ( u n ) d x 0 , n ,

then

0 > μ , a 1 + o n ( 1 ) = I μ ( u n ) 1 2 R N ( I α * F ( u n ) ) F ( u n ) d x .

Taking n , we obtain a contradiction. Combining Claim 1 and the fact γ 2 γ 2 q < 0 , one has

μ , a 2 γ 2 I μ ( u n ) + 1 2 C ( γ 2 γ 2 q ) ,

for n N large enough. Thus, let n , it shows that

μ , a 2 γ 2 μ , a 1 + 1 2 C ( γ 2 γ 2 q ) < γ 2 μ , a 1 ,

i.e.,

a 1 2 a 2 2 μ , a 2 < μ , a 1 .

Next we will introduce the compactness theorem on S ( a ) , which plays an important role in the analysis of both autonomous case and nonautonomous case.

Theorem 2.5

(Compactness theorem on S(a)) Let { u n } S ( a ) be a minimizing sequence of μ , a and μ [ 0 , V * ] . Then, one of the following two holds for some subsequence:

  1. The subsequence { u n } is strongly convergent.

  2. There is { y n } R N and y n such that v n ( x ) = u n ( x + y n ) converges strongly to the function v S ( a ) with I μ ( v ) = μ , a .

Proof

Because I μ is coercive on S ( a ) for fixed μ [ 0 , V * ] , then the sequence { u n } is bounded. Suppose that u n u in H 1 ( R N ) for some subsequence. If u 0 and u 2 = b a , we claim b ( 0 , a ) . From the Brézis-Lieb lemma [46],

(2.12) u n 2 2 = u n u 2 2 + u 2 2 + o n ( 1 ) .

Besides, we see that F is a C 1 function with a subcritical growth in the Sobolev sense, it follows that

R N ( I α * F ( u n ) ) F ( u n ) d x = R N ( I α * F ( u n u ) ) F ( u n u ) d x + R N ( I α * F ( u ) ) F ( u ) d x .

Let v n = u n u and v n 2 = d n d , taking the limit n in (2.12), one can obtain a 2 = b 2 + d 2 . When n is large enough, one can obtain d n ( 0 , a ) and

μ , a + o n ( 1 ) = I μ ( u n ) = I μ ( v n ) + I μ ( u ) + o n ( 1 ) μ , d n + μ , b + o n ( 1 ) .

Next, Lemma 2.4 is used to obtain

μ , a + o n ( 1 ) d n 2 a 2 μ , a + μ , b + o n ( 1 ) .

Taking n , then

(2.13) μ , a d 2 a 2 μ , a + μ , b .

As b ( 0 , a ) , combined (2.13) and Lemma 2.4, we can derive

μ , a > d 2 a 2 μ , a + b 2 a 2 μ , a = d 2 a 2 + b 2 a 2 μ , a = μ , a ,

a contradiction. Therefore, one obtain u 2 = a , that is, u S ( a ) .

Since u n 2 = u 2 = a , u n u in L 2 ( R N ) and L 2 ( R N ) is reflexive, it can deduce

(2.14) u n u , in L 2 ( R N ) ,

which combined with ( f 1 ) ( f 2 ) and the interpolation theorem, we infer to

(2.15) R N ( I α * F ( u n ) ) F ( u n ) d x R N ( I α * F ( u ) ) F ( u ) d x .

According to (2.15) and μ , a = lim n I μ ( u n ) , we obtain

μ , a I μ ( u ) .

By u S ( a ) and the definition of μ , a , we know I μ ( u ) = μ , a , so that

lim n I μ ( u n ) = I μ ( u ) ,

and together with (2.14) and (2.15) one has

u n H 1 u H 1 ,

which means u n u in H 1 ( R N ) .

In addition, assume that u = 0 , then u n 0 in H 1 ( R N ) . With the same proof as Claim 1 in Lemma 2.4, we can obtain that there is C > 0 such that

(2.16) R N ( I α * F ( u n ) ) F ( u n ) d x C , n n 0 .

We claim that there must exist R , η > 0 and y n R N such that the following inequality holds:

(2.17) B R ( y n ) u n 2 d x η , n N .

Otherwise we will obtain u n 0 in L t ( R N ) for any t ( 2 , 2 * ) , and then

R N ( I α * F ( u n ) ) F ( u n ) d x 0 ,

which contradicts (2.16). Thus, setting u ˜ n ( x ) = u n ( x + y n ) , obviously { u ˜ n } S ( a ) , and it is also a minimizing sequence of μ , a . Furthermore, there is u ˜ H 1 ( R N ) \ { 0 } satisfied

u ˜ n u ˜ , in H 1 ( R N ) , u ˜ n ( x ) u ˜ ( x ) , a.e. in R N .

Then following the first part of the proof, we can obtain u ˜ n u ˜ in H 1 ( R N ) . This completes the proof.□

We now turn to the proof of Theorem 2.1.

Proof of Theorem 2.1

Fix μ [ 0 , V * ] . According to Lemma 2.3, there is a bounded minimizing sequence { u n } S ( a ) of μ , a , i.e., I μ ( u n ) μ , a . Then, using Theorem 2.5, there exists u S ( a ) such that I μ ( u ) = μ , a . Hence, from the Lagrange multiplier, there is λ a R satisfied

(2.18) I μ ( u ) = λ a Ψ ( u ) , in ( H 1 ( R N ) ) ,

where Ψ : H 1 ( R N ) R is defined as follows:

Ψ ( u ) = 1 2 R N u 2 d x , u H 1 ( R N ) .

Thus, by (2.18), it follows

Δ u + μ u = λ a u + ( I α * F ( u ) ) f ( u ) .

In addition, since I μ ( u ) = μ , a < 0 , one can obtains λ a < 0 .

The next thing to state is that u can be chosen to be positive. Considering the definition of the functional I μ , we can deduce I μ ( u ) = I μ ( u ) . Furthermore, the fact u S ( a ) leads to u S ( a ) , so one obtain

μ , a = I μ ( u ) = I μ ( u ) μ , a ,

that is, I μ ( u ) = μ , a , and thus, we can replace u by u . On the other hand, if we represent the Schwarz’s Symmetrization of u in terms of u * , it is known that

R N u 2 d x R N u * 2 d x , R N u 2 d x = R N u * 2 d x , R N ( I α * F ( u ) ) F ( u ) d x = R N ( I α * F ( u * ) ) F ( u * ) d x ,

and then u * S ( a ) with I μ ( u * ) = μ , a , which shows that we can replace u by u * .

Next, we prove that u ( x ) > 0 for any x R N . In the following, we prove it using Harnack inequality (see [18, Theorem 8.20]). By contradiction, suppose that there is x 0 R N such that u ( x 0 ) = 0 . Because u 0 , there is x 1 R N such that u ( x 1 ) > 0 . Now, we fix R > 0 large enough satisfied x 0 , x 1 B R ( 0 ) . By Theorem [18, Theorem 8.20], there is C > 0 satisfied

sup y B R ( 0 ) u ( y ) C inf y B R ( 0 ) u ( y ) ,

but in this case,

sup y B R ( 0 ) u ( y ) > 0 and inf y B R ( 0 ) u ( y ) = 0 ,

a contradiction. So this completes the proof.□

The following corollary can be obtained from Theorem 2.1 immediately.

Corollary 2.6

Let 0 μ 1 < μ 2 V * and fix a > 0 , then μ 1 , a < μ 2 , a < 0 .

Proof

Let u μ 2 , a S ( a ) such that I μ 2 ( u μ 2 , a ) = μ 2 , a . Thus,

μ 1 , a I μ 1 ( u μ 2 , a ) < I μ 2 ( u μ 2 , a ) = μ 2 , a .

3 The penalized problem

First, we set σ , d > 0 satisfying f ( d ) d q 1 = σ and define

f ˜ ( t ) f ( t ) , 0 t d , σ t q 2 t , t d ,

where q is fixed in ( f 3 ) . In addition, we introduce the penalized nonlinearity g : R N × R R defined as follows:

g ( x , t ) χ Λ ¯ ( x ) f ( t ) + ( 1 χ Λ ¯ ( x ) ) f ˜ ( t ) ,

where χ Λ ¯ is the characteristic function on Λ ¯ .

From ( f 1 ) ( f 3 ) , we know that g is an odd Carathéodory function with the following properties:

  1. lim t 0 g ( x , t ) t = 0 uniformly in x R N ;

  2. g ( x , t ) σ t q 1 , for any x Λ ¯ c and t R ;

  3. There exists C > 0 satisfied g ( x , t ) C ( t q 0 1 + t q 1 ) for each x R N and t R ;

  4. 0 g ( x , t ) f ( t ) , x R N , t 0 ; g ( x , t ) t f ( t ) t , x R N , t R ;

  5. G ( x , t ) 0 t g ( x , s ) d s F ( t ) , x R N , t R .

By ( f 1 ) ( f 3 ) , we can derive items ( g 1 ) and ( g 3 ) hold immediately. Now, we just need to prove the ( g 2 ) , ( g 4 ) , and ( g 5 ) . First, we show that ( g 2 ) holds. For any x Λ ¯ c and t d , we see

(3.1) g ( x , t ) = σ t q 1 = σ t q 1 .

Moreover, for all x Λ ¯ c and t ( 0 , d ] , the condition ( f 3 ) leads to

(3.2) f ( t ) = f ( t ) t q 1 t q 1 f ( d ) d q 1 t q 1 = σ t q 1 ,

which together with (3.1) and the definition of g ensure that

(3.3) g ( x , t ) = f ( t ) σ t q 1 = σ t q 1 , x Λ ¯ c and t 0 .

When x Λ ¯ c and t 0 , using (3.3) and the fact g is odd can obtain

g ( x , t ) = g ( x , t ) = g ( x , t ) = g ( x , t ) σ ( t ) q 1 = σ t q 1 ,

which proves item ( g 2 ) . Now, we focus on proving item ( g 4 ) . For any x Λ ¯ c and t d , one has

(3.4) g ( x , t ) = σ t q 1 = f ( d ) d q 1 t q 1 .

In view of ( f 3 ) , we have

(3.5) f ( d ) d q 1 f ( t ) t q 1 , t d .

From (3.4) and (3.5), we obtain g ( x , t ) f ( t ) for each x Λ ¯ c and t d . When x Λ ¯ c and 0 t d , then g ( x , t ) = f ˜ ( t ) = f ( t ) . On the other hand, for any x Λ ¯ , g ( x , t ) = f ( t ) , this proves the first half of ( g 4 ) . Since both g ( x , t ) t and f ( t ) t are even functions of the variable t , it follows naturally that the second half of ( g 4 ) holds. And for item ( g 5 ) , because both g ( x , t ) and f ( t ) are odd functions about the variable t , both G ( x , t ) and F ( t ) are even functions about the variable t . Together with ( g 4 ) , we can prove ( g 5 ) .

Next, we will consider the modified problem:

(3.6) Δ u + V ( ε x ) u = λ u + ( I α * G ε ( x , u ) ) g ε ( x , u ) , in R N R N u 2 d x = a 2 ,

where g ε ( x , t ) = g ( ε x , t ) , G ε ( x , t ) = 0 t g ε ( x , s ) d s , for all x R N and t R .

Suppose that u ε is a solution of (3.6) satisfied

u ε ( x ) d , x Λ ¯ ε c , Λ ¯ ε { x R N , ε x Λ ¯ } ,

then u ε is a solution of (1.11).

It is well known that a solution of problem (3.6) satisfied R N u 2 d x = a 2 corresponds to a critical point of the following functional

J ε ( u ) = 1 2 R N u 2 d x + 1 2 R N V ( ε x ) u 2 d x 1 2 R N ( I α * G ε ( x , u ) ) G ε ( x , u ) d x

constrained in the sphere S ( a ) given in (1.12). Moreover, it is obviously that J ε C 1 ( H 1 ( R N ) , R ) and

J ε ( u ) v = R N u v d x + R N V ( ε x ) u v d x R N ( I α * G ε ( x , u ) ) g ε ( x , u ) v d x .

Lemma 3.1

The functional J ε is bounded from below in S ( a ) .

Proof

For any u S ( a ) , from the property ( g 3 ) , there is C > 0 such that

G ε ( x , t ) C ( t q 0 + t q ) , x R N , t R ,

and combining with the well-known Hardy-Littlewood-Sobolev inequality (2.2) and the Gagliardo-Nirenberg inequality (2.1), we obtain

R N ( I α * G ε ( x , u ) ) G ε ( x , u ) d x C G ε ( x , u ) 2 N N + α 2 = C R N G ε ( x , u ) 2 N N + α d x N + α N C R N u 2 N q 0 N + α d x + R N u 2 N q N + α d x N + α N C u 2 N q 0 N + α 2 q 0 + u 2 N q N + α 2 q C [ a ( 2 N ) q 0 + N + α u 2 N q 0 N α + a ( 2 N ) q + N + α u 2 N q N α ] .

Thus, one has

J ε ( u ) 1 2 R N u 2 d x 1 2 C ( a ( 2 N ) q 0 + N + α u 2 N q 0 N α + a ( 2 N ) q + N + α u 2 N q N α ) .

Since 1 + α N < q 0 q < 1 + 2 + α N , thus N q 0 N α , N q N α < 2 . This implies that J ε ( u ) is bounded from below.□

By Lemma 3.1, we know that the real number

J ε , a = inf u S ( a ) J ε ( u )

makes sense. Next, let’s talk about some properties of J ε , a .

Lemma 3.2

There exists V * > 0 and Γ = Γ ( V * ) > 0 independent of σ > 0 and ε > 0 satisfied J ε , a < Γ for V < V * and for each σ > 0 .

Proof

The condition ( f 1 ) leads that lim t 0 + q 0 F ( t ) t q 0 = β > 0 , then there exists δ ( 0 , d ) such that

(3.7) q 0 F ( t ) t q 0 β 2 , t ( 0 , δ ] .

Given a nonnegative function u 0 S ( a ) C 0 ( R N ) , we define

H ( u 0 , s ) ( x ) = e N s 2 u 0 ( e s x ) , x R N and s R .

It is easy to obtain

0 e N s 2 u 0 ( e s x ) δ , x R N

for s < 0 and s large enough. According to the definition of g , we have

G ε ( x , H ( u 0 , s ) ( x ) ) = F ( H ( u 0 , s ) ( x ) ) , x R N .

Thus,

R N H ( u 0 , s ) ( x ) 2 d x = a 2

and

R N ( I α * G ε ( x , H ( u 0 , s ) ) ) G ε ( x , H ( u 0 , s ) ) d x = R N ( I α * F ( H ( u 0 , s ) ) ) F ( H ( u 0 , s ) ) d x = e s ( N + α ) R N ( I α * F ( e N s 2 u 0 ) ) F ( e N s 2 u 0 ) d x .

By (3.7), we have

R N ( I α * G ε ( x , H ( u 0 , s ) ) ) G ε ( x , H ( u 0 , s ) ) d x β 2 q 0 2 e N s q 0 s ( N + α ) R N ( I α * u 0 q 0 ) u 0 q 0 d x ,

and then

J ε ( H ( u 0 , s ) ) e 2 s 2 R N u 0 2 d x + V 2 a 2 1 2 β 2 q 0 2 e N s q 0 s ( N + α ) R N ( I α * u 0 q 0 ) u 0 q 0 d x .

Since q 0 1 + α N , 1 + 2 + α N , so N s q 0 s ( N + α ) ( 2 s , 0 ) . Meanwhile, R N ( I α * u 0 q 0 ) u 0 q 0 d x is bounded. Similar to (2.9), by increasing s if necessary, we can derive

e 2 s 2 R N u 0 2 d x 1 2 β 2 q 0 2 e N s q 0 s ( N + α ) R N ( I α * u 0 q 0 ) u 0 q 0 d x D s < 0 .

Hence,

J ε ( H ( u 0 , s ) ) D s + 1 2 V a 2 .

Similar to (2.10), we fix V * > 0 small enough to satisfy

D s + 1 2 V * a 2 < 0 .

Thus, if V < V * and Γ = ( D s + V * 2 a 2 ) > 0 , one has

J ε ( H ( u 0 , s ) ) < Γ ,

which proves the lemma.□

For the sake of argument, we denote by I 0 , I : H 1 ( R N ) R the following functionals:

I 0 ( u ) = 1 2 R N u 2 d x + 1 2 R N V ( 0 ) u 2 d x 1 2 R N ( I α * F ( u ) ) F ( u ) d x

and

I ( u ) = 1 2 R N u 2 d x + 1 2 R N V u 2 d x 1 2 R N ( I α * F ( u ) ) F ( u ) d x .

In addition, we use 0 , a and , a to represent the following real numbers:

0 , a = inf u S ( a ) I 0 ( u ) and , a = inf u S ( a ) I ( u ) .

As 0 < V = min x Λ V ( x ) < + , combined with Corollary 2.6, we obtain

(3.8) 0 , a < , a < 0 .

We take 0 < ρ 1 = 1 2 ( , a 0 , a ) . In the following lemma, we will analyze the relationship between J ε , a , , a and 0 , a .

Lemma 3.3

There exists ε 0 > 0 satisfied J ε , a < , a for each ε ( 0 , ε 0 ) .

Proof

Let u 0 S ( a ) satisfying I 0 ( u 0 ) = 0 , a . We define u ˜ ε ( x ) = u 0 ( ε x x 0 ε ) S ( a ) with x 0 Λ and V ( x 0 ) = V ( 0 ) . It is easy to obtain

J ε , a J ε ( u ˜ ε ) = 1 2 R N u 0 2 d x + 1 2 R N V ( ε x + x 0 ) u 0 2 d x 1 2 R N I α * G ε ε x + x 0 ε , u 0 G ε ε x + x 0 ε , u 0 d x .

Taking ε 0 + , then

limsup ε 0 + J ε , a limsup ε 0 + J ε ( u ˜ ε ) = I 0 ( u 0 ) = 0 , a .

Thereby, combined with (3.8), we obtain J ε , a < , a for ε small enough.□

From now on, we fix ε ( 0 , ε 0 ) , where ε 0 is given in Lemma 3.3.

Lemma 3.4

There exists σ * > 0 independent of ε ( 0 , ε 0 ) such that if σ ( 0 , σ * ) , then the following conclusion can be drawn: If { u n } S ( a ) such that J ε ( u n ) c and c < 0 , a + ρ 1 < 0 with u n u in H 1 ( R N ) , then u 0 .

Proof

Similar to the proof of Lemma 3.1, it can be deduced by applying the properties ( g 1 ) ( g 3 ) that

R N ( I α * G ε ( x , u ) ) G ε ( x , u ) d x C Λ ¯ ε u 2 N q 0 N + α d x + Λ ¯ ε u 2 N q N + α d x N + α N + C Λ ¯ ε c σ 2 N N + α u 2 N q N + α d x N + α N ,

and then

J ε ( w ) 1 2 R N w 2 d x 1 2 C Λ ¯ ε w 2 N q 0 N + α d x + Λ ¯ ε w 2 N q N + α d x N + α N 1 2 C Λ ¯ ε c σ 2 N N + α w 2 N q N + α d x N + α N .

By the Gagliardo-Nirenberg inequality (2.1), we obtain for w S ( a ) ,

J ε ( w ) 1 2 R N w 2 d x C σ 2 a ( 2 N ) q + ( N + α ) w 2 N q ( N + α ) C Λ ¯ ε w 2 N q 0 N + α d x + Λ ¯ ε w 2 N q N + α d x N + α N ,

by changing the constant C appropriately, still denoted as C .

Next, we define the function E : [ 0 , + ) [ 0 , + ) as follows:

(3.9) E ( t ) = 1 2 t C σ 2 a ( 2 N ) q + N + α t N q ( N + α ) 2 , t 0 ,

as q q 0 , 1 + 2 + α N , so N q ( N + α ) 2 ( 0 , 1 ) , there must be t σ > 0 satisfying

0 > E ( t σ ) = min t 0 E ( t ) .

It is easy to obtain E ( t σ ) 0 when σ 0 . As a result, there is σ * > 0 satisfying

(3.10) 0 > E ( t σ ) > 1 2 ( 0 , a + , a ) , σ ( 0 , σ * ) .

Suppose that u = 0 , then

1 2 ( 0 , a + , a ) = 0 , a + ρ 1 > c = J ε ( u n ) + o n ( 1 ) E ( t σ ) C Λ ¯ ε u n 2 N q 0 N + α d x + Λ ¯ ε u n 2 N q N + α d x N + α N = E ( t σ ) + o n ( 1 ) ,

that is,

1 2 ( 0 , a + , a ) > E ( t σ ) + o n ( 1 ) .

Let n + , then

1 2 ( 0 , a + , a ) E ( t σ ) ,

which contradicts (3.10).□

Lemma 3.5

Let { u n } S ( a ) be a ( P S ) c sequence for J ε constrained to S ( a ) with c < 0 , a + ρ 1 < 0 and u n u ε in H 1 ( R N ) , i.e.,

J ε ( u n ) c , ( J ε S ( a ) ) ( u n ) 0 , n + .

Assume v n = u n u ε 0 in H 1 ( R N ) , decreasing ε 0 if necessary, then there exists ζ > 0 independent of ε ( 0 , ε 0 ) and σ ( 0 , σ * ) satisfied

liminf n + u n u ε 2 2 ζ .

Proof

Let the functional Ψ : H 1 ( R N ) R be defined as follows:

Ψ ( u ) = 1 2 R N u 2 d x ,

then we have S ( a ) = Ψ 1 ( a 2 2 ) . Thereby, from Willem [46, Proposition 5.12], there is { λ n } R satisfying

J ε ( u n ) λ n Ψ ( u n ) ( H 1 ( R N ) ) 0 as n + .

Because { u n } is bounded in H 1 ( R N ) , then { λ n } is also bounded. Hence, we suppose that λ n λ ε when n + , and thus,

J ε ( u n ) λ ε Ψ ( u n ) ( H 1 ( R N ) ) 0 as n +

and

J ε ( u ε ) λ ε Ψ ( u ε ) = 0 in ( H 1 ( R N ) ) .

Arguing as in reference [2, Lemma 2.8-iv)], we have

J ε ( u n ) = J ε ( u ε ) + J ε ( v n ) + o n ( 1 )

and

Ψ ( u n ) = Ψ ( u ε ) + Ψ ( v n ) + o n ( 1 ) .

It follows that

J ε ( u n ) λ ε Ψ ( u n ) = J ε ( u ε ) λ ε Ψ ( u ε ) + J ε ( v n ) λ ε Ψ ( v n ) + o n ( 1 ) = J ε ( v n ) λ ε Ψ ( v n ) + o n ( 1 ) ,

which leads to

(3.11) J ε ( v n ) λ ε Ψ ( v n ) ( H 1 ( R N ) ) 0 as n + .

From ( f 3 ) , we can obtain q F ( t ) f ( t ) t for any t 0 . As a result,

0 > ρ 1 + 0 , a liminf n + J ε ( u n ) = liminf n + J ε ( u n ) 1 2 J ε ( u n ) u n + 1 2 λ n a 2 1 2 λ ε a 2 ,

which implies that

limsup ε 0 λ ε 2 ( ρ 1 + 0 , a ) a 2 < 0 .

Therefore, there exists λ * > 0 independent of ε and σ satisfied

λ ε λ * < 0 , ε ( 0 , ε 0 ) .

In view of (3.11), one has

R N v n 2 d x + R N V ( ε x ) v n 2 d x λ ε R N v n 2 d x = R N ( I α * G ε ( x , v n ) ) g ε ( x , v n ) v n d x ,

which together with ( g 1 ) , ( g 4 ) and the well-known Hardy-Littlewood-Sobolev inequality imply that

R N v n 2 d x + C 0 R N v n 2 d x C 2 v n 2 N p N + α 2 p + o n ( 1 ) .

The appropriate positive constant C 0 is chosen here, and C 0 is independent of the values of ε ( 0 , ε 0 ) and p 1 + α N , 1 + 2 + α N . Through the continuous Sobolev embedding H 1 ( R N ) L 2 N p N + α ( R N ) , where 2 N p N + α ( 2 , 2 + 4 N + α ) ( 2 , 2 + 4 N ) , we infer to

(3.12) v n H 1 ( R N ) 2 C 3 v n 2 N p N + α 2 p + o n ( 1 ) C 4 v n H 1 ( R N ) 2 p + o n ( 1 ) ,

where C 3 , C 4 > 0 are independent of ε . As v n 0 in H 1 ( R N ) , there are some subsequence of { v n } , still denoted by { v n } , we suppose that liminf n + v n H 1 ( R N ) > 0 . Hence, by (3.12), we know

(3.13) liminf n + v n H 1 ( R N ) 1 C 4 1 2 p 2 .

By (3.12) and (3.13),

liminf n + v n 2 N p N + α 2 p C 5 ,

for some C 5 > 0 independent of ε .

By using the Gagliardo-Nirenberg inequality, we can derive

(3.14) liminf n + v n 2 N p N + α 2 p C ( liminf n + v n 2 ) ( 2 N ) p + N + α K N p N α ,

where K > 0 is a constant independent of ε ( 0 , ε 0 ) satisfied v n 2 K . Finally, lemma can be proved according to (3.13) and (3.14).□

In the following argument, we fix 0 < ρ < min 1 2 , ζ a 2 ( , a 0 , a ) ρ 1 .

Lemma 3.6

Decreasing if necessary σ * > 0 , then for any ε ( 0 , ε 0 ) , the functional J ε satisfies the ( P S ) c condition constrained to S ( a ) for c < 0 , a + ρ .

Proof

Suppose that u n u in H 1 ( R N ) , we set v n = u n u . If v n 0 in H 1 ( R N ) , we can derive by Lemma 3.5 that

(3.15) liminf n + v n 2 2 ζ .

Similar to Lemma 3.5, for ζ > 0 that does not depend on ε ( 0 , ε 0 ) , one can obtain

(3.16) J ε ( v n ) λ n Ψ ( v n ) ( H 1 ( R N ) ) 0 as n + .

By ( f 3 ) , we know that q F ( t ) f ( t ) t for each t 0 . Therefore,

0 > ρ 1 + 0 , a liminf n + J ε ( u n ) = liminf n + J ε ( u n ) 1 2 J ε ( u n ) u n + 1 2 λ n a 2 1 2 λ ε a 2 ,

where λ n λ ε . Thus,

limsup ε 0 λ ε 2 ( ρ 1 + 0 , a ) a 2 = 1 a 2 ( 0 , a + , a ) < 0 .

Decreasing if necessary ε 0 , there exists λ * > 0 independent of ε and σ satisfying

λ ε λ * < 0 , ε ( 0 , ε 0 ) .

According to (3.16), ( g 2 ) , ( g 4 ) , and the Gagliardo-Nirenberg inequality, one has

R N v n 2 d x + R N V ( ε x ) v n 2 d x λ ε R N v n 2 d x = R N ( I α * G ε ( x , v n ) ) g ε ( x , v n ) v n d x + o n ( 1 ) C R N g ε ( x , v n ) v n 2 N N + α d x N + α N + o n ( 1 ) C Λ ¯ ε g ε ( x , v n ) v n 2 N N + α d x N + α N + C Λ ¯ ε c g ε ( x , v n ) v n 2 N N + α d x N + α N + o n ( 1 ) C σ 2 R N v n 2 N q N + α d x N + α N + C Λ ¯ ε f ( v n ) v n 2 N N + α d x N + α N + o n ( 1 ) C σ 2 a ( 2 N ) q + N + α R N v n 2 d x N q ( N + α ) 2 + C Λ ¯ ε f ( v n ) v n 2 N N + α d x N + α N + o n ( 1 ) ,

consequently,

R N v n 2 d x + λ * R N v n 2 d x C σ 2 a ( 2 N ) q + N + α R N v n 2 d x N q ( N + α ) 2 + C Λ ¯ ε f ( v n ) v n 2 N N + α d x N + α N + o n ( 1 ) .

Thus, it follows that

E ( t σ ) + λ * R N v n 2 d x R N v n 2 d x C σ 2 a ( 2 N ) q + N + α R N v n 2 d x N q ( N + α ) 2 + λ * R N v n 2 d x C Λ ¯ ε f ( v n ) v n 2 N N + α d x N + α N + o n ( 1 ) ,

where E ( t ) is given in (3.9). Letting the limit of n + and employing (3.15), we obtain

E ( t σ ) + λ * ζ 0 , σ ( 0 , σ * ) .

Because E ( t σ ) 0 as σ 0 and λ * ζ > 0 , there is a contradiction when σ is small enough. Hence, decreasing if necessary σ * , we derive v n 0 in H 1 ( R N ) for σ ( 0 , σ * ) . That completes the proof.□

4 Multiplicity result

Let δ > 0 be fixed and w be a positive solution of the equation:

(4.1) Δ u + V ( 0 ) u = λ u + ( I α * F ( u ) ) f ( u ) , x R N , R N u 2 d x = a 2 , x R N ,

with I 0 ( w ) = 0 , a . Let η be a smooth nonincreasing cut-off function defined in [ 0 , ) satisfying

η ( s ) = 1 , 0 s δ 2 , 0 , s δ .

For any y M , we define

Ψ ε , y ( x ) = η ( ε x y ) w ε x y ε , Ψ ˜ ε , y ( x ) = a Ψ ε , y ( x ) Ψ ε , y 2 ,

and Φ ε : M S ( a ) by Φ ε ( y ) = Ψ ˜ ε , y . From the definition of Φ ε ( y ) , we know that it has compact support for each y M .

Lemma 4.1

The function Φ ε satisfies the limit

lim ε 0 J ε ( Φ ε ( y ) ) = 0 , a , uniformly i n y M .

Proof

Suppose by contradiction that, there is δ 0 > 0 , { y n } M and y n y M with ε n 0 satisfied

J ε n ( Φ ε n ( y n ) ) 0 , a δ 0 .

By the Lebesgue’s dominated convergence theorem, we obtain

lim n + R N Ψ ε n , y n 2 d x = lim n + R N η ( ε n x ) w ( x ) 2 d x = R N w 2 d x , lim n + R N Φ ε n ( y n ) 2 d x = lim n + R N a 2 Ψ ε n , y n 2 2 ( η ( ε n x ) w ( x ) ) 2 d x = R N w 2 d x , lim n + R N V ( ε n x ) Φ ε n ( y n ) 2 d x = V ( 0 ) R N w 2 d x ,

and

lim n + R N I α * G ε n x , a Ψ ε n , y n Ψ ε n , y n 2 G ε n x , a Ψ ε n , y n Ψ ε n , y n 2 d x = lim n + R N I α * G ε n x + y n , a Ψ ε n , y n 2 η ( ε n x ) w ( x ) G ε n x + y n , a Ψ ε n , y n 2 η ( ε n x ) w ( x ) d x = R N ( I α * F ( w ) ) F ( w ) d x .

Thereby,

lim n + J ε n ( Φ ε n ( y n ) ) = 1 2 R N w 2 d x + 1 2 V ( 0 ) R N w 2 d x 1 2 R N ( I α * F ( w ) ) F ( w ) d x = I 0 ( w ) = 0 , a ,

which is a contradiction.□

For any δ > 0 , let R = R ( δ ) > 0 satisfies M δ B R ( 0 ) . We define the mapping χ : R N R N given by

χ ( x ) = x , x R , R x x , x R .

Besides, let ζ ε : S ( a ) R N be defined as follows:

ζ ε ( u ) = R N χ ( ε x ) u 2 d x a 2 .

Lemma 4.2

The function Φ ε satisfies the limit

lim ε 0 ζ ε ( Φ ε ( y ) ) = y , uniformly i n y M .

Proof

Suppose by contradiction that, there is δ 0 > 0 , { y n } M and y n y M with ε n 0 satisfied

(4.2) ζ ε n ( Φ ε n ( y n ) ) y n δ 0 , n N .

In view of the definition of Φ ε n ( y n ) and ζ ε n with ε n 0 , one has

ζ ε n ( Φ ε n ( y n ) ) = y n + 1 a 2 R N ( χ ( ε n x + y n ) y n ) η ( ε n x ) w ( x ) 2 d x .

By the fact { y n } M B R ( 0 ) and the Lebesgue’s dominated convergence theorem, we derive as

ζ ε n ( Φ ε n ( y n ) ) y n 0 , n + ,

which contradicts (4.2).□

Let θ : [ 0 , + ) [ 0 , + ) be a positive function satisfying θ ( ε ) 0 when ε 0 . We define

(4.3) S ˜ ( a ) = { u S ( a ) : J ε ( u ) 0 , a + θ ( ε ) } .

From the Lemma 4.1, the function θ ( ε ) = sup y M J ε ( Φ ε ( y ) ) 0 , a satisfies θ ( ε ) 0 when ε 0 . As a result, Φ ε ( y ) S ˜ ( a ) for each y M .

Proposition 4.3

Let ε n 0 and { u n } S ( a ) satisfying J ε n ( u n ) 0 , a and J ε n S ( a ) ( u n ) = o n ( 1 ) for any n N . Then, there exists { y ˜ n } R N such that u ˜ n ( x ) = u n ( x + y ˜ n ) has a convergent subsequence in H 1 ( R N ) . Furthermore, up to a subsequence, y n = ε n y ˜ n y 0 for some y 0 M .

Proof

First, we claim that there exist R 0 , ξ > 0 and y ˜ n R N satisfied

B R 0 ( y ˜ n ) u n 2 d x ξ , n N .

If not, from Lions’ lemma, we can derive u n 0 in L p ( R N ) for any p ( 2 , 2 * ) , which implies that R N ( I α * F ( u n ) ) F ( u n ) d x 0 . Thus, one has lim n J ε n ( u n ) 0 , which is impossible since lim n J ε n ( u n ) = 0 , a < 0 . Therefore, we fix u ˜ n ( x ) = u n ( x + y ˜ n ) , then there exists u ˜ H 1 ( R N ) \ { 0 } satisfying u ˜ n u ˜ in H 1 ( R N ) up to a subsequence. Because { u ˜ n } S ( a ) and J ε n ( u n ) I 0 ( u n ) = I 0 ( u ˜ n ) 0 , a , we have I 0 ( u ˜ n ) 0 , a . By Theorem 2.5, u ˜ n u ˜ in H 1 ( R N ) , u ˜ S ( a ) and I 0 S ( a ) ( u ˜ ) = 0 .

Claim 1. lim n dist ( ε n y ˜ n , Λ ¯ ) = 0 . In fact, if the claim is not true, there are δ > 0 and a subsequence of { ε n y ˜ n } , still denoted by itself, satisfied

dist ( ε n y ˜ n , Λ ¯ ) δ , n N .

Hence, there is r > 0 satisfying

B r ( ε n y ˜ n ) Λ c , n N .

We note that J ε n S ( a ) ( u n ) = o n ( 1 ) , so

R N u ˜ n 2 d x + R N V ( ε n x + ε n y ˜ n ) u ˜ n 2 d x = λ n R N u ˜ n 2 d x + R N ( I α * G ( ε n x + ε n y ˜ n , u ˜ n ) ) g ( ε n x + ε n y ˜ n , u ˜ n ) u ˜ n d x + o n ( 1 ) ,

where { λ n } R satisfies

limsup n + λ n < 0 .

Then, there is λ * < 0 and n 0 N satisfying

λ n λ * , n n 0 .

By applying the well-known Hardy-Littlewood-Sobolev inequality, we have

R N ( I α * G ( ε n x + ε n y ˜ n , u ˜ n ) ) g ( ε n x + ε n y ˜ n , u ˜ n ) u ˜ n d x C R N g ( ε n x + ε n y ˜ n , u ˜ n ) u ˜ n 2 N N + α d x N + α N C B r ε n ( 0 ) g ( ε n x + ε n y ˜ n , u ˜ n ) u ˜ n 2 N N + α d x N + α N + C R N \ B r ε n ( 0 ) g ( ε n x + ε n y ˜ n , u ˜ n ) u ˜ n 2 N N + α d x N + α N ,

changing the number of C appropriately, still denoted as C . It follows from ( g 2 ) and ( g 4 ) that

R N ( I α * G ( ε n x + ε n y ˜ n , u ˜ n ) ) g ( ε n x + ε n y ˜ n , u ˜ n ) u ˜ n d x C σ 2 B r ε n ( 0 ) u ˜ n 2 N q N + α d x N + α N + C R N \ B r ε n ( 0 ) f ( u ˜ n ) u ˜ n 2 N N + α d x N + α N .

Thus,

R N u ˜ n 2 d x λ * R N u ˜ n 2 d x C σ 2 B r ε n ( 0 ) u ˜ n 2 N q N + α d x N + α N + C R N \ B r ε n ( 0 ) f ( u ˜ n ) u ˜ n 2 N N + α d x N + α N .

Since u ˜ n u ˜ in H 1 ( R N ) , one has

B r ε n ( 0 ) u ˜ n 2 N q N + α d x N + α N R N u ˜ 2 N q N + α d x N + α N , n +

and

R N \ B r ε n ( 0 ) f ( u ˜ n ) u ˜ n 2 N N + α d x N + α N 0 , n + .

Consequently,

R N u ˜ 2 d x λ * R N u ˜ 2 d x C σ 2 R N u ˜ 2 N q N + α d x N + α N .

This together with the Gagliardo-Nirenberg inequality (2.1) imply that

R N u ˜ 2 d x λ * R N u ˜ 2 d x C σ 2 a ( 2 N ) q + N + α u ˜ 2 N q N α ,

and then

E ( t σ ) λ * a 2 R N u ˜ 2 d x C σ 2 a ( 2 N ) q + N + α u ˜ 2 N q N α λ * R N u ˜ 2 d x 0 ,

where E ( t ) is given in (3.9). As λ * < 0 independent of σ with E ( t σ ) 0 if σ 0 . Decreasing σ * if necessary, we can obtain E ( t σ ) λ * a 2 > 0 , which is impossible.

Claim 2. y 0 Λ . By ( g 5 ) , we have

0 , a + o n ( 1 ) = J ε n ( u n ) = 1 2 R N u n 2 d x + 1 2 R N V ( ε n x ) u n 2 d x 1 2 R N ( I α * G ε n ( x , u n ) ) G ε n ( x , u n ) d x = 1 2 R N u ˜ n 2 d x + 1 2 R N V ( ε n x + ε n y ˜ n ) u ˜ n 2 d x 1 2 R N ( I α * G ( ε n x + ε n y ˜ n , u ˜ n ) ) G ( ε n x + ε n y ˜ n , u ˜ n ) d x 1 2 R N u ˜ n 2 d x + 1 2 R N V ( ε n x + ε n y ˜ n ) u ˜ n 2 d x 1 2 R N ( I α * F ( u ˜ n ) ) F ( u ˜ n ) d x .

Passing the limit as n + , one has

0 , a 1 2 R N u ˜ 2 d x + 1 2 R N V ( y 0 ) u ˜ 2 d x 1 2 R N ( I α * F ( u ˜ ) ) F ( u ˜ ) d x .

Suppose that y 0 Λ , then V ( y 0 ) V , from where we know that

1 2 R N u ˜ 2 d x + 1 2 R N V ( y 0 ) u ˜ 2 d x 1 2 R N ( I α * F ( u ˜ ) ) F ( u ˜ ) d x , a > 0 , a ,

a contradiction. Thus, we prove that y 0 Λ .□

Lemma 4.4

Let δ > 0 and M δ = { x Λ ¯ : dist ( x , M ) δ } . Then the following limit holds:

lim ε 0 sup u S ˜ ( a ) inf z M δ ζ ε ( u ) z = 0 .

Proof

Let ε n 0 and u n S ˜ ( a ) satisfying

inf z M δ ζ ε n ( u n ) z = sup u S ˜ ( a ) inf z M δ ζ ε n ( u n ) z + o n ( 1 ) .

Thus, we just need to find a sequence { z n } M δ that satisfies

lim n + ζ ε n ( u n ) z n = 0 .

By u n S ˜ ( a ) , we have

0 , a I 0 ( u n ) J ε n ( u n ) 0 , a + θ ( ε n ) , n N ,

and then,

u n S ( a ) and J ε n ( u n ) 0 , a .

In view of the Proposition 4.3, there exists { z ˜ n } R N satisfied z n = ε n z ˜ n z for some z M . Meanwhile, the function u ˜ n ( x ) = u n ( x + z ˜ n ) converges strongly to u ˜ H 1 ( R N ) \ { 0 } . Thereby, { z n } M δ as n is large enough and

ζ ε n ( u n ) = z n + 1 a 2 R N ( χ ( ε n z + z n ) z n ) u ˜ n 2 d z ,

which leads to

ζ ε n ( u n ) z n = 1 a 2 R N ( χ ( ε n z + z n ) z n ) u ˜ n 2 d z 0 , as n + .

This completes the proof.□

After the aforementioned preparations, we are now ready to prove Theorem 1.1 as follows.

Proof of Theorem 1.1

In the following, we divide the proof into three parts:

Part I: Multiplicity of solutions to problem (3.6).

First, we set ε ( 0 , ε 0 ) . According to the Lemmas 4.1, 4.2, and 4.4, one can prove as in [13] to derive that ζ ε Φ ε is homotopic to the inclusion mapping i d : M M δ , and then

cat ( S ˜ ( a ) ) cat M δ ( M ) .

In view of Lemmas 3.1 and 3.6, we can obtain J ε is bounded from below on S ( a ) and J ε satisfies the ( P S ) c condition for c ( 0 , a , 0 , a + θ ( ε ) ) . Thus, we conclude that J ε has at least cat M δ ( M ) of critical points on S ( a ) according to the Lusternik-Schnirelmann category of critical points (see [16] and [46]).

Part II: Multiplicity of solutions to problem (1.11)

Let u ε be a solution of (3.6) with J ε ( u ε ) 0 , a + θ ( ε ) , where θ is given in (4.3). We just need to prove that

u ε ( x ) d for all x Λ ¯ ε c , Λ ¯ ε { x R N , ε x Λ ¯ } ,

decreasing ε 0 if necessary, which tells us that u ε is a solution of (1.11) for any ε ( 0 , ε 0 ) .

Similar to the proof in Proposition 4.3, for all ε n 0 , there exists y ˜ n R N satisfying y n = ε n y ˜ n y 0 and y 0 M . Besides, u ˜ n ( x ) = u n ( x + y ˜ n ) converges strongly to u ˜ H 1 ( R N ) and u ˜ 0 . Since u ˜ n is a solution of

Δ u ˜ n + V ( ε n x + y n ) u ˜ n = λ n u ˜ n + ( I α * F ( u ˜ n ) ) f ( u ˜ n ) , x R N ,

with

limsup ε 0 λ n 2 ( ρ 1 + 0 , a ) a 2 < 0 .

In view of the fact u ˜ n u ˜ in H 1 ( R N ) , we can prove the conclusion

lim x + u ˜ n ( x ) = 0 , uniformly in N

by the same method as in reference [3, Lemma 4.5]. Consequently, given σ > 0 , there exist R 1 > 0 and n 0 N satisfying

u ˜ n ( x ) d 2 for x R 1 and n n 0 .

Next, since y n = ε n y ˜ n y 0 Λ , there exists n 0 N satisfied that if x Λ ε n , then

x y ˜ n = 1 ε n ε n x y n r 1 2 ε n > R 1 , n n 0 ,

where r 1 = dist ( y 0 , Λ ) . Thereby,

u n ( x ) = u ˜ n ( x y ˜ n ) d 2 , x Λ ε n and n n 0 ,

which tells us the u n is a solution of (1.11). This proves the conclusion.

Part III: Concentration phenomena of the solutions to problem (1.11). The concentration phenomena of the solutions follows as in [4,6]. Its proof is omitted here.□

Acknowledgements

The authors would like to thank the reviewers for careful reading the manuscript and their valuable comments.

  1. Funding information: This work is supported by NSFC (12171497, 11771468, and 11971027).

  2. Author contributions: He proposed the idea for the study and led the implementation review and revision of the manuscript. Wu proposed research ideas and writing the original draft preparation. All authors have read and agreed to the published version of the manuscript.

  3. Conflict of interest: The authors state no conflict of interest.

  4. Data availability statement: Data sharing is not applicable to this article as no datasets were generated or analyzed during the current study.

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Received: 2024-06-02
Revised: 2024-07-02
Accepted: 2024-08-13
Published Online: 2024-09-23

© 2024 the author(s), published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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