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Global boundedness in a two-dimensional chemotaxis system with nonlinear diffusion and singular sensitivity

  • Guoqiang Ren EMAIL logo and Xing Zhou
Published/Copyright: February 1, 2024

Abstract

In this study, we investigate the two-dimensional chemotaxis system with nonlinear diffusion and singular sensitivity:

u t = ( u θ 1 u ) χ u v v , x Ω , t > 0 , v t = Δ v v + u + g ( x , t ) , x Ω , t > 0 , ( )

in a bounded domain with smooth boundary. We present the global boundedness of weak solutions to the model ( ) if θ > 3 2 and (1.10)–(1.11). This result improves our recent work.

1 Introduction and sketch of the main results

In 1970, Keller and Segel proposed a mathematical model concerning about cell’s life cycle, especially an aggregation process. In this model, “chemotaxis” plays an essential role to induce the aggregation process of the cell. When cells are starving, cells move toward increasing concentrations of the signal substance that is produced by cells [12]:

(1.1) n t = ( D n ( n , w ) n ) ( χ ( n , w ) v ) + F 1 ( n , w ) , x Ω , t > 0 , w t = D w ( n , w ) Δ w + F 2 ( n , w ) , x Ω , t > 0 ,

where n denotes the cell density and w is the chemical concentration. The simplified model of Model (1.1) was proposed by Nanjundiah [24]:

(1.2) n t = Δ n χ ( n w ) , x Ω , t > 0 , τ w t = Δ w w + n , x Ω , t > 0 .

The mathematical analysis of (1.2) and the variants thereof mainly concentrates on the boundedness and blow-up of the solutions (refer to, e.g., [3,11,22,23,25,32,36,38] and references therein). When τ w t = Δ w w + n is replaced by w t = Δ w , Li et al. [22] proved that a multidimensional chemotaxis system is ill-posedness in B ˙ 2 N , r 3 2 × ( B ˙ 2 N , r 1 2 ) N as 1 r < N due to the lack of continuity of the solution for the Cauchy problem. When n t = Δ n χ ( n w ) is replaced by n t = Δ ( γ ( w ) n ) + a n b n θ and τ = 0 , Lyu and Wang [23] explored how strong the logistic damping can warrant the global boundedness of solutions and further established the asymptotic behavior of solutions on top of the conditions. Keller and Segel [13] introduced a phenomenological model of wave-like solution behavior without any type of cell kinetics, a prototypical version of which is given by:

(1.3) u t = Δ u χ u v v , x Ω , t > 0 , v t = Δ v u v , x Ω , t > 0 ,

where u represents the density of bacteria and v denotes the concentration of the nutrient. The second equation models the consumption of the signal. In the first equation, the chemotactic sensitivity is determined according to the Weber-Fechner law, which says that the chemotactic sensitivity is proportional to the reciprocal of signal density. Winkler [39] proved that if initial data satisfies appropriate regularity assumptions, System (1.3) possesses at least one global generalized solution in two-dimensional bounded domains. Moreover, he took asymptotic behavior of solutions to System (1.3) into account and proved that v ( , t ) * 0 in L ( Ω ) and v ( , t ) 0 in L p ( Ω ) as t provided Ω u 0 m , Ω ln v 0 v 0 L ( Ω ) M , where m and M are positive constants. When u v is replaced by g ( u ) v , g C 1 ( R ) and 0 g ( u ) u β , β ( 0 , 1 ) , χ ( 0 , 1 ) and any sufficiently regular initial data, Lankeit and Viglialoro [20] showed that System (1.3) has a global classical solution. Moreover, if additionally m = u 0 L 1 ( Ω ) is sufficiently small, then also their boundedness is achieved. When System (1.3) has a logistic source f ( u ) , Lankeit and Lankeit [17] showed that System (1.3) possesses a global generalized solution for any χ 0 , r 0 , and μ > 0 if f ( u ) = κ u μ u 2 . As f ( u ) = r u μ u k and 1 v is replaced by ϕ ( v ) , ϕ ( v ) C 1 ( 0 , ) satisfying ϕ ( v ) 0 as v . Zhao and Zheng [50] proved that System (1.3) possesses a unique positive global classical solution provided k > 1 with N = 1 or k > 1 + N 2 with N 2 . For more recent outcomes, one can see [16,19,33,34,40,45].

When v does not stand for a nutrient consumed but for a signaling substance produced by the bacteria themselves, which is given by:

(1.4) u t = Δ u χ u v v , x Ω , t > 0 , v t = Δ v v + u , x Ω , t > 0 ,

and when 1 v is replaced by χ ( v ) , χ ( v ) χ 0 ( 1 + α v ) k with some χ 0 > 0 , α > 0 , and k > 1 , Winkler [35] proved that for any choice of appropriate initial data, System (1.4) possesses a unique global classical solution that is bounded in Ω × ( 0 , ) for N 1 . Stinner and Winkler [31] showed that for any λ ( 0 , min { 1 , 1 χ 2 } ) , System (1.4) admits at least one couple ( u , v ) of nonnegative functions defined in Ω × ( 0 , ) such that ( u , v ) is a global weak power- λ solution of (1.4) for N 2 . Winkler [37] proved that 0 < χ < 2 N and then for any such data, there exists a global-in-time classical solution. Moreover, global existence of weak solutions is established whenever 0 < χ < N + 2 3 N 4 . The boundedness of solution is left as an open problem. Fujie [7] solved the open problem of uniform-in-time boundedness of solutions for 0 < χ < 2 N , which was conjectured by Winkler [37]. Recently, Winkler and Yokota [44] proved that System (1.4) possesses a uniquely determined global classical solution if χ ( 0 , χ 0 ] and χ 2 δ , where χ 0 ( 0 , 2 N ) , δ > 0 are the constants. Furthermore, the solution of (1.4) converges to the homogeneous steady state ( u ¯ 0 , u ¯ 0 ) at an exponential rate with respect to the norm in ( L ( Ω ) ) 2 as t , where u ¯ 0 = 1 Ω Ω u 0 . Lankeit and Winkler [21] introduced an apparently novel type of generalized solution and proved that under the hypothesis: (i) χ < if N = 2 ; (ii) χ < 8 if N = 3 ; (iii) χ < N N 2 if N 4 , for all initial data satisfying suitable assumptions on regularity and positivity, an associated no-flux initial-boundary value problem admits a globally defined generalized solution. This solution inter alia has the property that u L loc 1 ( Ω ¯ × [ 0 , ) ) . Recently, when u t = Δ u χ u v v is replaced by ε u t = Δ u χ u v v , Winkler [43] proved that if N 3 and χ > N N 2 , a statement on spontaneous emergence of arbitrarily large values of u for appropriately small ε is derived. When the second equation degenerates into an elliptic equation, v v is replaced by χ ( v ) , χ C loc 2 + ω ( ( 0 , ) ) with some ω ( 0 , 1 ) , χ > 0 , χ ( v ) 0 as v , Fujie and Senba [8] showed that System (1.4) admits a global classical positive solution that is uniformly bounded. Black [4] showed that System (1.4) admits at least one global generalized solution if 0 < χ < N N 2 . Zhigun [53] showed that System (1.4) admits a generalized supersolution with appropriate condition and assumed that ( u , v ) satisfies additional conditions and that the generalized supersolution is a classical solution. When System (1.4) has a logistic source f ( u ) = r u μ u 2 , Fujie et al. [9] proved that System (1.4) possesses global bounded classical solutions if r > χ 2 4 for 0 < χ 2 , or r > χ 1 for χ > 2 in two-dimensional bounded domains. When v t = Δ v v + u is replaced by 0 = Δ v α 1 v + β 1 u , r , and μ are replaced by r ( x , t ) and μ ( x , t ) , respectively, and r ( x , t ) and μ ( x , t ) are Hölder continuous in t R with exponent γ > 0 uniformly with respect to x Ω ¯ , continuous in x Ω ¯ uniformly with respect to t R , and there are positive constants r i , μ i ( i = 1 , 2 ) such that 0 < r 1 r ( x , t ) r 2 and 0 < μ 1 μ ( x , t ) μ 2 , Kurt and Shen [14] showed that in any space dimensional setting, logistic kinetics is sufficient to enforce the global existence of classical solutions and hence prevents the occurrence of finite-time blow-up even for arbitrarily large χ . In addition, the solutions are shown to be uniformly bounded under the conditions r inf > α 1 χ 2 4 for 0 < χ 2 , or r inf > α 1 ( χ 1 ) for χ > 2 , where r inf = inf x Ω ¯ , t R r ( x , t ) . For the fully parabolic system, Zhao and Zheng [49] proved that System (1.4) possesses a global bounded classical solution if r > χ 2 4 for 0 < χ 2 , or r > χ 1 for χ > 2 in two-dimensional bounded domains. Based on existent results in [49], Zheng et al. [52] showed that the global bounded solution ( u , v ) exponentially converges to the steady state ( r μ , r μ ) . Zhao and Zheng [51] generalized their own work [49] to the higher-dimensional case. When r u μ u 2 is replaced by r u μ u k , Zhao [48] proved that System (1.4) admits globally bounded classical solutions whenever χ ( 0 , min { 1 2 , 1 2 ( N 1 ) } ) . This means that the singular sensitive coefficient χ suitably small does benefit the global boundedness of classical solutions, which is independent of the dampening exponent k > 1 in the logistic kinetics. For more recent outcomes, one can see [1,5,6,10,15,18,28,42,46,47].

This article is concerned with the following chemotaxis system with singular sensitivity and signal production:

(1.5) u t = ( u θ 1 u ) χ u v v , x Ω , t > 0 , v t = Δ v v + u + g ( x , t ) , x Ω , t > 0 , u ν = v ν = 0 , x Ω , t > 0 , u ( x , 0 ) = u 0 ( x ) , v ( x , 0 ) = v 0 ( x ) , x Ω ,

where Ω R 2 is a bounded convex domain with smooth boundary Ω and ν denotes the derivative with respect to the outer normal of Ω , u represents the cell density, and v denotes the concentration of the chemical signal. χ > 0 , θ > 1 is a given parameter and initial data u 0 and v 0 are the known functions satisfying

(1.6) u 0 W 1 , ( Ω ) with u 0 0 and u 0 0 in Ω , v 0 W 1 , ( Ω ) with v 0 > 0 in Ω ¯ .

The additional external production of the signal chemical

(1.7) g is a nonnegative function and belongs to C 1 ( Ω ¯ × [ 0 , ) ) .

Recently, Ren and Ma [29] have proved that if θ > 2 , System (1.5) possesses at least one global weak solution, which is locally bounded in the sense that

sup t ( 0 , T ) ( u ( , t ) L ( Ω ) + v ( , t ) W 1 , q ( Ω ) ) < , for all T > 0 and q > 2 .

When the first equation in (1.6) is replaced by u t = ( u θ 1 u ) χ u v v u v + B 1 ( x , t ) and the second equation in (1.6) is replaced by v t = Δ v v + u v + B 2 ( x , t ) , Rodríguez and Winkler [30] obtained the only result on the global boundedness of weak solution to urban crime nonlinear diffusion system in the two-dimensional case when θ > 3 2 .

Now, we state the main result in this article.

Theorem 1.1

Let Ω R 2 be a bounded convex domain with smooth boundary, χ > 0 . Assume that g fulfills (1.7), and that

(1.8) θ > 3 2 .

Then, for any choice of initial data ( u 0 , v 0 ) that satisfies (1.6), System (1.5) possesses at least one global weak solution in the sense of Definition 2.1, which is locally bounded in the sense that

(1.9) sup t ( 0 , T ) ( u ( , t ) L ( Ω ) + v ( , t ) W 1 , q ( Ω ) ) < , f o r a l l T > 0 and q > 2 .

Furthermore, suppose g satisfies (1.7) and

(1.10) sup ( x , t ) Ω × ( 0 , ) g ( x , t ) <

as well as

(1.11) liminf t Ω g ( x , t ) d x > 0 .

Then, System (1.5) possesses at least one global weak solution in the sense of Definition 2.1, which is globally bounded in the sense that

(1.12) sup t > 0 ( u ( , t ) L ( Ω ) + v ( , t ) W 1 , q ( Ω ) ) < , for a l l q > 2 .

Remark 1.2

Theorem 1.1 improves our recent work [29, Theorem1.1].

In this article, we use symbols C i and c i ( i = 1 , 2 , ) as some generic positive constants that may vary in the context. For simplicity, u ( x , t ) is written as u , the integral Ω u ( x ) d x is written as Ω u ( x ) , and 0 t Ω u ( x , t ) d x d t is written as 0 t Ω u ( x , t ) .

The contents of this article are as follows. In Section 2, we first introduce the concept of weak solutions and then give the global existence result for System (1.5). In Section 3, we give some fundamental estimates for the solution to System (1.5) and prove Theorem 1.1.

2 Preliminaries

Under the assumptions of u , the first equation of System (1.5) may be degenerate at u = 0 . Therefore, System (1.5) does not allow for classical solvability in general as the well-known porous medium equations. We introduce the following definition of weak solutions.

Definition 2.1

Assume that θ 1 , χ > 0 , and (1.6) and (1.7) hold. Then, a pair ( u , v ) of functions u L loc θ ( Ω ¯ × [ 0 , ) ) and v L loc 1 ( [ 0 , ) ; W 1 , 1 ( Ω ) ) will be called a global weak solution of (1.5) if u 0 and v > 0 a.e. in Ω × ( 0 , ) , if

u v v belongs to L loc 1 ( Ω ¯ × [ 0 , ) ; R 2 ) ,

the integral identities

(2.1) 0 Ω u ψ t Ω u 0 ψ ( , 0 ) = 1 θ 0 Ω u θ Δ ψ + χ 0 Ω u v v ψ

and

(2.2) 0 Ω v ψ t Ω v 0 ψ ( , 0 ) = 0 Ω v ψ 0 Ω v ψ + 0 Ω u ψ + 0 Ω g ψ

hold for all ψ C 0 ( Ω ¯ × [ 0 , ) ) fulfilling ψ ν = 0 on Ω × ( 0 , ) .

In order to construct weak solutions by an approximation procedure, we introduce the following regularized problems:

(2.3) u ε t = ( ( u ε + ε ) θ 1 u ε ) χ u ε v ε v ε , x Ω , t > 0 , v ε t = Δ v ε v ε + u ε 1 + ε u ε + g ( x , t ) , x Ω , t > 0 , u ε ν = v ε ν = 0 , x Ω , t > 0 , u ε ( x , 0 ) = u 0 ( x ) , v ε ( x , 0 ) = v 0 ( x ) , x Ω ,

for ε ( 0 , 1 ) . All of these problems (2.3) are, indeed, globally solvable in the classical sense.

Lemma 2.2

Let Ω R 2 be a bounded domain with smooth boundary, χ > 0 . Assume that g fulfills (1.7), and let θ > 1 and ε ( 0 , 1 ) . Then, there exist functions

u ε C 0 ( Ω ¯ × [ 0 , ) ) C 2 , 1 ( Ω ¯ × ( 0 , ) ) , v ε p > 2 C 0 ( [ 0 , ) ; W 1 , p ( Ω ) ) C 2 , 1 ( Ω ¯ × ( 0 , ) ) ,

which solve (2.3) classically in Ω ¯ × [ 0 , ) and which are such that u ε > 0 in Ω ¯ × ( 0 , ) and v ε > 0 in Ω ¯ × [ 0 , ) .

Proof

This can be seen by a straightforward adaptation of the reasoning in [42] on the basis of standard results on local existence and extensibility, as provided by the general theory in [2]. This completes the proof.□

Lemma 2.3

[41] Let μ > 0 , T > 0 and suppose that the nonnegative function y C 0 ( [ 0 , T ) ) C 1 ( ( 0 , T ) ) such that

y ( t ) + μ y ( t ) g ( t ) , for a l l t ( 0 , T ) ,

where the nonnegative function g L loc 1 ( R ) has the property that

1 τ t t + τ g ( s ) d s a , for a l l t ( 0 , T τ ) ,

with some 0 < τ < T and a > 0 . Then,

y ( t ) y ( 0 ) + a τ 1 e μ τ , for a l l t [ 0 , T ) .

Definition 2.4

Let L : ( 0 , ) ( 0 , ) . We say that L fulfills ( L ) if L has the property that

sup T > 0 L ( T ) < whenever (1.10) and (1.11) hold .

Lemma 2.5

Let θ > 1 . Then, there exists L : ( 0 , ) ( 0 , ) satisfying ( L ) such that for all T > 0 ,

(2.4) 1 v ε ( x , t ) L ( T ) in Ω × ( 0 , T ) , for a l l ε ( 0 , 1 )

and

(2.5) Ω u ε ( , t ) L ( T ) , for all t ( 0 , T ) and ε ( 0 , 1 )

as well as

(2.6) Ω v ε ( , t ) L ( T ) , for all t ( 0 , T ) and ε ( 0 , 1 ) .

Proof

The essential idea has been illustrated in [7, Lemma 2.1] and [29, Lemmas 2.3 and 2.4]. We here alternatively show the short proof. Using a known result for the Neumann heat semigroup e t Δ , we can obtain the pointwise estimate from the following:

e t Δ w ( x ) 1 4 π t e ( diam Ω ) 2 4 t Ω w > 0 , for all nonnegative w C 0 ( Ω ¯ ) , ( x , t ) Ω × ( 0 , ) ,

where diam Ω max x , y Ω ¯ x y . First, by the positivity of v 0 > 0 in Ω ¯ and the maximum principle, we have

v ε ( , t ) min x Ω ¯ v 0 ( x ) e t , for all t 0 .

Now, fix τ > 0 . Then, it follows that

v ε ( , t ) min x Ω ¯ v 0 ( x ) e τ η 1 > 0 , for all t [ 0 , τ ] .

Next, the representation formula of v , the maximal principle, and (2.3) imply that

v ε ( , t ) = e t ( Δ 1 ) v 0 + 0 t e ( t s ) ( Δ 1 ) u ε 1 + ε u ε ( , s ) d s + 0 t e ( t s ) ( Δ 1 ) g ( , s ) d s e t ( Δ 1 ) v 0 + 0 t e ( t s ) ( Δ 1 ) g ( , s ) d s 0 t 1 4 π ( t s ) e ( ( t s ) + ( d i a m Ω ) 2 4 ( t s ) ) Ω g ( , s ) d x d s = inf s > τ Ω g ( , s ) 0 t 1 4 π r e ( r + ( d i a m Ω ) 2 4 r ) d r inf s > τ Ω g ( , s ) τ t 1 4 π r e ( r + ( diam Ω ) 2 4 r ) d r η 2 > 0 , for all t ( τ , ) .

Therefore, we have v ε ( , t ) min { η 1 , η 2 } for all t 0 . We obtain (2.4) immediately. (2.5) and (2.6) follow almost immediately from integrating the first and second equations of (2.3), and we omit giving details here. The proof is complete.□

3 Proof of Theorem 1.1

In this section, we will obtain the integral inequalities of u ε over Ω , whose core is to improve the regularity of v ε with regard to W 1 , q ( Ω ) for any q > 2 and to obtain the L -boundedness of u ε by applying a standard Moser-type recursive argument.

Lemma 3.1

(Lemma 3.1 in [29]) Assume that θ > 1 , and let p ( 0 , 1 ) . Then, there exists L : ( 0 , ) ( 0 , ) fulfilling ( L ) such that for all T > 1 ,

(3.1) t t + 1 Ω v ε p 2 v ε 2 L ( T ) , for all t ( 0 , T 1 ) and ε ( 0 , 1 ) .

Lemma 3.2

(Lemma 3.2 in [29]) Assume that θ > 1 , and let q [ 1 , 2 ) close to 2. Then, there exists L : ( 0 , ) ( 0 , ) fulfilling ( L ) with the property that for all T > 2 , any ε ( 0 , 1 ) , and each t ( 2 , T ) , we can find t = t ( t , ε ) ( t 2 , t 1 ) such that

(3.2) v ε ( , t ) W 1 , q ( Ω ) L ( T ) .

Lemma 3.3

Let θ > 3 2 . Then, there exists L : ( 0 , ) ( 0 , ) fulfilling ( L ) such that for all T > 1 ,

(3.3) t t + 1 Ω ( u ε + ε ) 2 θ 4 u ε 2 L ( T ) , if θ 3 2 , 2 , t t + 1 Ω ( u ε + ε ) θ 2 u ε 2 L ( T ) , if θ [ 2 , ) ,

for all t ( 0 , T 1 ) and ε ( 0 , 1 ) .

Proof

The proof is divided into two cases.

Case 1: θ [ 2 , ) . Multiplying the first equation in (2.3) by 1 + ln u ε and integrating by parts, we have

(3.4) d d t Ω u ε ln u ε + Ω ( u ε + ε ) θ 1 u ε u ε 2 = χ Ω u ε v ε v ε ,

for all t ( 0 , T ) and ε ( 0 , 1 ) . From Lemmas 2.5 and 3.1, there exist l i : ( 0 , ) ( 0 , ) , ( i = 1 , 2 , 3 ) such that ( L ) holds and that for all T > 1 ,

(3.5) v ε 1 l 1 ( T ) in Ω × ( 0 , T ) , for all ε ( 0 , 1 ) ,

(3.6) Ω u ε l 2 ( T ) , for all t ( 0 , T ) all ε ( 0 , 1 ) ,

and

(3.7) t t + 1 Ω v ε 3 2 v ε 2 l 3 ( T ) , for all t ( 0 , T 1 ) all ε ( 0 , 1 ) .

As for the right-hand side of (3.4), in accordance with the positivity of u ε , we can find ε ( 0 , 1 ) such that

(3.8) u ε + ε > ε > 0 .

Using (3.5) and Young’s inequality, we obtain

(3.9) χ Ω u ε v ε v ε ε θ 2 2 Ω u ε 2 + χ 2 2 ε θ 2 Ω v ε 2 v ε 2 ε θ 2 2 Ω u ε 2 + χ 2 2 ε θ 2 l 1 1 2 ( T ) Ω v ε 3 2 v ε 2 ,

for all t ( 0 , T ) and ε ( 0 , 1 ) . Inserting (3.9) into (3.4), we deduce

(3.10) d d t Ω u ε ln u ε + Ω ( u ε + ε ) θ 2 ε θ 2 2 u ε 2 χ 2 2 ε θ 2 l 1 1 2 ( T ) Ω v ε 3 2 v ε 2

for all t ( 0 , T ) and ε ( 0 , 1 ) . Owing to (3.8) and θ 2 , it is easy to see

( u ε + ε ) θ 2 ε θ 2 2 ε θ 2 ε θ 2 2 = ε θ 2 2 ,

which, in conjunction with (3.10), yields that

(3.11) d d t Ω u ε ln u ε + ε θ 2 2 Ω u ε 2 χ 2 2 ε θ 2 l 1 1 2 ( T ) Ω v ε 3 2 v ε 2 ,

for all t ( 0 , T ) and ε ( 0 , 1 ) . By the Gagliardo-Nirenberg inequality, Young’s inequality, (3.6), and the fact Ω u ε ln u ε c 1 Ω u ε 3 2 with a constant c 1 > 0 , we obtain

(3.12) Ω u ε ln u ε c 1 Ω u ε 3 2 c 1 C G N u ε L 2 ( Ω ) 1 3 u ε L 1 ( Ω ) 2 3 + C G N u ε L 1 ( Ω ) 3 2 c 1 C G N 3 2 u ε L 2 ( Ω ) 1 2 u ε L 1 ( Ω ) + u ε L 1 ( Ω ) 3 2 ε θ 2 2 u ε L 2 ( Ω ) 2 + c 2 u ε L 1 ( Ω ) 3 2 + 1 ε θ 2 2 u ε L 2 ( Ω ) 2 + c 2 l 2 3 2 ( T ) + 1 ,

for all t ( 0 , T ) and ε ( 0 , 1 ) with some constants C G N > 0 and c 2 > 0 . Combining (3.11) and (3.12), we derive

(3.13) d d t Ω u ε ln u ε + Ω u ε ln u ε χ 2 2 ε θ 2 l 1 1 2 ( T ) Ω v ε 3 2 v ε 2 + c 2 l 2 3 2 ( T ) + 1 ,

for all t ( 0 , T ) and ε ( 0 , 1 ) . Denoting y ( t ) Ω u ε ( , t ) ln u ε ( , t ) and g ( t ) χ 2 2 ε θ 2 l 1 1 2 ( T ) Ω v ε 3 2 ( , t ) v ε ( , t ) 2 + c 2 l 2 3 2 ( T ) + 1 , and thus,

y ( t ) + y ( t ) g ( t ) , for all t ( 0 , T ) ,

by (3.7), we estimate

t t + 1 g ( s ) d s = χ 2 2 ε θ 2 l 1 1 2 ( T ) t t + 1 Ω v ε 3 2 v ε 2 + c 2 l 2 3 2 ( T ) + 1 l 4 ( T ) χ 2 2 ε θ 2 l 1 1 2 ( T ) l 3 ( T ) + c 2 l 2 3 2 ( T ) + 1 ,

for all t ( 0 , T 1 ) and ε ( 0 , 1 ) . In accordance with Lemma 2.3, we have

y ( t ) = Ω u ε ln u ε l 5 ( T ) Ω u 0 ln u 0 + l 4 ( T ) 1 e 1 , for all t ( 0 , T ) .

By means of (3.11), we immediately conclude that

ε θ 2 2 t t + 1 Ω u ε 2 l 5 ( T ) + Ω e + χ 2 2 ε θ 2 l 1 1 2 ( T ) l 3 ( T ) ,

for all t ( 0 , T 1 ) and ε ( 0 , 1 ) . Integrating (3.10) over ( t , t + 1 ) and using the fact u ε ln u ε 1 e , we obtain

t t + 1 Ω ( u ε + ε ) θ 2 u ε 2 Ω u ε ( , t + 1 ) ln u ε ( , t + 1 ) + Ω u ε ( , t ) ln u ε ( , t ) + ε θ 2 2 t t + 1 Ω u ε 2 + χ 2 2 ε θ 2 l 1 1 2 ( T ) t t + 1 Ω v ε 3 2 v ε 2 l 6 ( T ) 2 Ω e + 2 l 5 ( T ) + χ 2 2 ε θ 2 l 1 1 2 ( T ) l 3 ( T ) ,

for all t ( 0 , T 1 ) and ε ( 0 , 1 ) . This proves the second inequality in (3.3).

Case 2: θ 3 2 , 2 . We multiply the first equation in (2.3) by ( u ε + ε ) θ 2 , integrate by parts, and use Young’s inequality (3.5) to infer that

(3.14) 1 θ 1 d d t Ω ( u ε + ε ) θ 1 = ( 2 θ ) Ω ( u ε + ε ) 2 θ 4 u ε 2 + ( 2 θ ) χ Ω ( u ε + ε ) θ 3 u ε v ε u ε v ε 2 θ 2 Ω ( u ε + ε ) 2 θ 4 u ε 2 + χ 2 ( 2 θ l 1 1 2 ( T ) ) 2 Ω v ε 3 2 v ε 2 ,

for all t ( 0 , T ) and ε ( 0 , 1 ) . Since θ 3 2 , 2 , using Young’s inequality and (3.6), we deduce

(3.15) Ω ( u ε + ε ) θ 1 Ω ( u ε + ε ) + c 3 l 2 ( T ) + ε Ω + c 3 ,

for all t ( 0 , T ) and ε ( 0 , 1 ) with some constant c 3 > 0 . Therefore, integrating (3.14) over ( t , t + 1 ) and using (3.15) as well as (3.7), we can obtain the first inequality in (3.3). The proof is complete.□

Lemma 3.4

Let θ > 3 2 . Then, there exists L : ( 0 , ) ( 0 , ) fulfilling ( L ) such that for all T > 1 ,

(3.16) t t + 1 Ω u ε 2 θ 1 L ( T ) , if θ 3 2 , 2 , t t + 1 Ω u ε θ + 1 L ( T ) , if θ [ 2 , )

for all t ( 0 , T 1 ) and ε ( 0 , 1 ) .

Proof

The proof is divided into two cases.

Case 1: θ 3 2 , 2 . From Lemmas 2.5 and 3.1, there exist l i : ( 0 , ) ( 0 , ) , ( i = 1 , 2 ) such that ( L ) holds and that for all T > 1 ,

(3.17) Ω ( u ε + ε ) l 1 ( T ) , for all t ( 0 , T ) all ε ( 0 , 1 )

and

(3.18) t t + 1 Ω ( u ε + ε ) 2 θ 4 u ε 2 l 2 ( T ) , for all t ( 0 , T 1 ) all ε ( 0 , 1 ) .

Using the Gagliardo-Nirenberg inequality, we obtain

(3.19) u ε + ε L 2 θ 1 ( Ω ) 2 θ 1 = ( u ε + ε ) θ 1 L 2 θ 1 θ 1 ( Ω ) 2 θ 1 θ 1 C G N 2 θ 1 θ 1 ( u ε + ε ) θ 1 L 2 ( Ω ) 2 θ 2 2 θ 1 ( u ε + ε ) θ 1 L 1 θ 1 ( Ω ) 1 2 θ 1 + ( u ε + ε ) θ 1 L 1 θ 1 ( Ω ) 2 θ 1 θ 1 2 θ θ 1 C G N 2 θ 1 θ 1 ( u ε + ε ) θ 1 L 2 ( Ω ) 2 ( u ε + ε ) θ 1 L 1 θ 1 ( Ω ) 1 θ 1 + ( u ε + ε ) θ 1 L 1 θ 1 ( Ω ) 2 θ 1 θ 1 2 θ θ 1 C G N 2 θ 1 θ 1 ( θ 1 ) 2 l 1 ( T ) Ω ( u ε + ε ) 2 θ 4 u ε 2 + 2 θ θ 1 C G N 2 θ 1 θ 1 l 1 2 θ 1 ( T ) ,

for all t ( 0 , T ) and ε ( 0 , 1 ) . In accordance with (3.18), we integrate (3.19) over ( t , t + 1 ) to imply that

t t + 1 Ω u ε 2 θ 1 t t + 1 Ω ( u ε + ε ) 2 θ 1 2 θ θ 1 C G N 2 θ 1 θ 1 ( θ 1 ) 2 l 1 ( T ) l 2 ( T ) + 2 θ θ 1 C G N 2 θ 1 θ 1 l 1 2 θ 1 ( T ) ,

for all t ( 0 , T 1 ) and ε ( 0 , 1 ) , which yields the first inequality in (3.16).

Case 2: θ [ 2 , ) . At first, we fix ϱ C 0 ( [ 0 , ) ) such that ϱ 0 on [ 0 , 1 ] , ϱ ( ζ ) = ( ζ + ε ) θ 2 1 for all ζ 2 , and 0 ϱ ( ζ ) ( ζ + ε ) θ 2 1 for all ζ 0 . Let f ( ζ ) = 0 ζ ϱ ( σ ) d σ for ζ 0 . Then, f C 1 ( [ 0 , ) ) and fulfills f ( ζ ) ( ζ + ε ) θ 2 θ 2 as well as

(3.20) f ( ζ ) 2 ζ ϱ ( σ ) d σ = ( ζ + ε ) θ 2 ( 2 + ε ) θ 2 θ 2 c 1 ( ζ + ε ) θ 2 , for all ζ 3 ,

with c 1 1 ( 2 + ε 3 ) θ 2 θ 2 > 0 . Since f ( ζ ) 2 ( ζ + ε ) θ 2 θ and ϱ ( ζ ) ( ζ + ε ) θ 2 1 , then from Lemma 3.3, there exists l 3 : ( 0 , ) ( 0 , ) such that ( L ) holds and that for all T > 1 ,

f ( u ε ) L θ 2 ( Ω ) 2 θ θ 2 2 θ Ω ( u ε + ε ) θ 2 2 θ l 1 ( T ) ,

for all t ( 0 , T ) and ε ( 0 , 1 ) , and

t t + 1 f ( u ε ) L 2 ( Ω ) 2 = t t + 1 Ω ϱ 2 ( u ε ) u ε 2 { u ε 1 } u ε 2 θ 4 u ε 2 Ω ( u ε + ε ) 2 θ 4 u ε 2 l 3 ( T ) for all t > 0 and ε ( 0 , 1 ) .

Here, we used the fact θ 2 . By the Gagliardo-Nirenberg inequality, we obtain

t t + 1 Ω f 2 ( θ + 1 ) θ ( u ε ) C G N 2 ( θ + 1 ) θ t t + 1 f ( u ε ) L 2 ( Ω ) θ θ + 1 f ( u ε ) L 2 θ ( Ω ) 1 θ + 1 + f ( u ε ) L 2 θ ( Ω ) 2 ( θ + 1 ) θ 2 θ + 2 θ C G N 2 ( θ + 1 ) θ t t + 1 f ( u ε ) L 2 ( Ω ) 2 f ( u ε ) L 2 θ ( Ω ) 1 θ + f ( u ε ) L 2 θ ( Ω ) 2 θ l 4 ( T ) 2 θ + 2 θ C G N 2 ( θ + 1 ) θ l 1 ( T ) l 3 ( T ) + 2 θ + 2 θ C G N 2 ( θ + 1 ) θ l 1 θ + 1 ( T ) ,

for all t ( 0 , T 1 ) and ε ( 0 , 1 ) . From the aforementioned inequality together with (3.20), we deduce

t t + 1 Ω u ε θ + 1 t t + 1 Ω ( u ε + ε ) θ + 1 c 1 2 ( θ + 1 ) θ t t + 1 Ω f 2 ( θ + 1 ) θ ( u ε ) c 1 2 ( θ + 1 ) θ l 4 ( T ) ,

for all t ( 0 , T 1 ) and ε ( 0 , 1 ) . Because of the fact that u ε θ + 1 3 θ + 1 in { u ε 3 } , we derive the desired result of (3.16). The proof is complete.□

Lemma 3.5

Let θ > 3 2 . Then, there exists L : ( 0 , ) ( 0 , ) fulfilling ( L ) such that for all T > 0 ,

(3.21) v ε ( , t ) W 1 , 2 θ 1 ( Ω ) L ( T ) , if θ 3 2 , 2 , v ε ( , t ) W 1 , θ + 1 ( Ω ) L ( T ) , if θ [ 2 , ) ,

for all t ( 0 , T ) and ε ( 0 , 1 ) .

Proof

The proof can be found in our recent work [29, Lemma 3.5]; for the reader’s convenience, we present the detailed proof here. The following proof is divided into two cases.

Case 1: θ 3 2 , 2 . Let p 2 θ 1 ; owing to θ > 3 2 , it is easy to see that p > 2 . By the continuous embedding W 1 , p ( Ω ) L ( Ω ) L 1 ( Ω ) , there exists c 1 > 0 such that

(3.22) ϕ L ( Ω ) c 1 ϕ W 1 , p ( Ω ) α ϕ L 1 ( Ω ) 1 α , for all ϕ W 1 , p ( Ω ) ,

with α = 2 p 3 p 2 ( 0 , 1 ) ; thanks to 2 p 2 3 p + 2 = 2 ( p 1 ) 2 + p > 0 , we have

1 p + p 1 p α = 1 p + ( p 1 ) ( 3 p 2 ) 2 p 2 = 3 p 2 3 p + 2 2 p 2 > 1 2 ,

and thus, we can choose q ( 1 , 2 ) close to 2 such that

(3.23) 1 q < 1 p + p 1 p α .

From the well-known Neumann heat semigroup ( e δ Δ ) δ 0 on Ω [36], there exist k 1 , k 2 , k 3 > 0 satisfying

(3.24) e δ Δ ϕ W 1 , p ( Ω ) k 1 δ 1 q 1 p ϕ W 1 , q ( Ω ) , for all δ ( 0 , 2 ) and ϕ C 1 ( Ω ¯ )

and

(3.25) e δ Δ ϕ W 1 , p ( Ω ) k 2 ϕ W 1 , ( Ω ) , for all δ ( 0 , 2 ) and ϕ C 1 ( Ω ¯ )

as well as

(3.26) e δ Δ ϕ W 1 , p ( Ω ) k 3 δ 1 2 ϕ L p ( Ω ) , for all δ ( 0 , 2 ) and ϕ C 0 ( Ω ¯ ) .

From Lemmas 2.5 and 3.4, there exist c 1 ( T ) , c 2 ( T ) > 0 such that for all T > 0 ,

(3.27) v ε ( , t ) L 1 ( Ω ) c 1 ( T ) , for all t ( 0 , T ) and ϕ C 0 ( Ω ¯ )

and

(3.28) ( t 2 ) + t Ω u ε p c 2 ( T ) , for all t ( 0 , T ) and ϕ C 0 ( Ω ¯ )

and that for any such T , each t ( 0 , T ) , and arbitrary ε ( 0 , 1 ) , we can find t ˜ t ˜ ( t , ε ) 0 such that

(3.29) t ˜ ( ( t 2 ) + , ( t 1 ) + ) and v ε ( , t ˜ ) W 1 , q ( Ω ) c 3 ( T ) , if t 2

and that

(3.30) t ˜ = 0 and v ε ( , t ˜ ) W 1 , ( Ω ) c 4 v 0 W 1 , ( Ω ) , if t ( 0 , 2 ) .

Applying the variation-of-constants formula of v ε ( , t ) and (3.26), we have

(3.31) v ε ( , t ) W 1 , p ( Ω ) = e ( t t ˜ ) ( Δ 1 ) v ε ( , t ˜ ) + t ˜ t e ( t s ) ( Δ 1 ) u ε ( , s ) 1 + ε u ε ( , s ) d s + t ˜ t e ( t s ) ( Δ 1 ) g ( , s ) d s W 1 , p ( Ω ) e ( t t ˜ ) e ( t t ˜ ) Δ v ε ( , t ˜ ) W 1 , p ( Ω ) + k 3 t ˜ t ( t s ) 1 2 e ( t s ) u ε ( , s ) 1 + ε u ε ( , s ) L p ( Ω ) d s + k 2 t ˜ t e ( t s ) g ( , s ) L p ( Ω ) d s ,

for all t ( t ˜ , t ) . If t 2 , by (3.24),

(3.32) e ( t t ˜ ) e ( t t ˜ ) Δ v ε ( , t ˜ ) W 1 , p ( Ω ) k 1 ( t t ˜ ) 1 q 1 p v ε ( , t ˜ ) W 1 , q ( Ω ) k 1 c 3 ( T ) ( t t ˜ ) 1 q 1 p ,

for all t ( t ˜ , t ] . As 0 < t < 2 , from (3.25) and (3.29), we obtain

(3.33) e ( t t ˜ ) e ( t t ˜ ) Δ v ε ( , t ˜ ) W 1 , p ( Ω ) k 2 v ε ( , t ˜ ) W 1 , ( Ω ) k 2 c 4 ,

and (1.7) guarantees that

(3.34) k 2 t ˜ t e ( t s ) g ( , s ) L p ( Ω ) d s k 2 c 5 t ˜ t e ( t s ) d s = k 2 c 5 ( 1 e t ˜ t ) k 2 c 5 ,

for all t ( t ˜ , t ] . For the second last summand on the right of (3.30), as t 2 , we obtain

(3.35) k 3 t ˜ t ( t s ) 1 2 e ( t s ) u ε ( , s ) 1 + ε u ε ( , s ) L p ( Ω ) d s k 3 t ˜ t ( t s ) 1 2 e ( t s ) u ε ( , s ) L p ( Ω ) d s k 3 t ˜ t Ω u ε p 1 p t ˜ t ( t s ) p 2 ( p 1 ) d s p 1 p k 3 c 2 ( T ) 1 p c 6 2 1 p 2 ( p 1 ) ,

where c 6 0 1 ( 1 σ ) p 2 ( p 1 ) d σ is finite because of p 2 ( p 1 ) < 1 . If 0 < t < 2 , in a way similar to (3.28), so we omit it. Collecting (3.31)–(3.35), we obtain the first inequality in (3.44).

Case 2: θ [ 2 , ) . Similarly, we can take p θ + 1 satisfying p > 2 in line with θ 2 , and by following the same procedure, we can obtain the second inequality in (3.44). The proof is complete.□

Lemma 3.6

Let θ > 3 2 and p > max { 2 , θ 1 + 2 θ 3 2 θ 1 } . Then, there exists L : ( 0 , ) ( 0 , ) fulfilling ( L ) such that for all T > 0 ,

(3.36) Ω u ε p L ( T ) , for all t ( 0 , T ) and ε ( 0 , 1 ) .

Proof

Multiplying the first equation in (2.3) by u ε p 1 and using Young’s inequality, we have

(3.37) 1 p d d t Ω u ε p + 2 ( p 1 ) ( p + θ 1 ) 2 Ω u ε p + θ 1 2 2 = p 1 2 Ω u ε p + θ 3 u ε 2 ( p 1 ) Ω u ε p 2 ( u ε + ε ) θ 1 u ε 2 + ( p 1 ) χ Ω u ε p 1 u ε v ε v ε p 1 2 Ω u ε p + θ 3 u ε 2 ( p 1 ) Ω u ε p 2 ( u ε + ε ) θ 1 u ε 2 + p 1 2 Ω u ε p + θ 3 u ε 2 + ( p 1 ) χ 2 2 Ω u ε p θ + 1 v ε 2 v ε 2 ( p 1 ) χ 2 2 Ω u ε p θ + 1 v ε 2 v ε 2 .

From Lemmas 2.2 and 3.5, there exists a c 1 ( T ) > 0 such that if T > 0 , then

(3.38) Ω v ε 2 θ 1 v ε 2 θ 1 c 1 ( T ) , if θ 3 2 , 2 , Ω v ε θ + 1 v ε θ + 1 c 1 ( T ) , if θ [ 2 , ) .

On the one hand, if θ 3 2 , 2 , applying Hölder’s inequality, we obtain

(3.39) ( p 1 ) χ 2 2 Ω u ε p θ 1 v ε 2 v ε 2 ( p 1 ) χ 2 2 Ω u ε ( 2 θ 1 ) ( p θ + 1 ) 2 θ 3 2 θ 3 2 θ 1 Ω v ε 2 θ 1 v ε 2 θ 1 2 2 θ 1 c 2 ( T ) Ω u ε ( 2 θ 1 ) ( p θ + 1 ) 2 θ 3 2 θ 3 2 θ 1 ,

for all t ( 0 , T ) and ε ( 0 , 1 ) with c 2 ( T ) ( p 1 ) χ 2 2 c 1 ( T ) 2 θ 3 2 θ 1 . Since p > θ 1 + 2 θ 3 2 θ 1 , it is easy to see that 2 p + θ 1 < 2 p + θ 1 ( 2 θ 1 ) ( p θ + 1 ) 2 θ 3 . By the Gagliardo-Nirenberg inequality, there exists c 3 = c 3 ( p ) > 0 such that

Ω u ε ( 2 θ 1 ) ( p θ + 1 ) 2 θ 3 2 θ 3 2 θ 1 = u ε p + θ 1 2 L 2 p + θ 1 ( 2 θ 1 ) ( p θ + 1 ) 2 θ 3 ( Ω ) 2 ( p θ + 1 ) p + θ 1 c 3 u ε p + θ 1 2 L 2 ( Ω ) 2 ( p θ + 1 ) p + θ 1 a 1 u ε p + θ 1 2 L 2 p + θ 1 ( Ω ) 2 ( p θ + 1 ) p + θ 1 ( 1 a 1 ) + c 3 u ε p + θ 1 2 L 2 p + θ 1 ( Ω ) 2 ( p θ + 1 ) p + θ 1 , for all t > 0 and ε ( 0 , 1 ) ,

where a 1 ( 2 θ 1 ) ( p θ + 1 ) 2 θ + 3 ( 2 θ 1 ) ( p θ + 1 ) ( 0 , 1 ) and

2 ( p θ + 1 ) p + θ 1 a 1 2 = 2 ( 2 θ 1 ) ( p θ + 1 ) 2 θ + 3 ( 2 θ 1 ) ( p + θ 1 ) 2 = 2 ( 2 θ 1 ) ( 2 θ + 2 ) 2 θ + 3 ( 2 θ 1 ) ( p + θ 1 ) = 2 2 ( θ 1 ) p + θ 1 2 2 θ 3 ( 2 θ 1 ) ( p + θ 1 ) < 0 .

Using Young’s inequality, we derive

(3.40) c 2 ( T ) Ω u ε ( 2 θ 1 ) ( p θ + 1 ) 2 θ 3 2 θ 3 2 θ 1 c 4 ( T ) u ε p + θ 1 2 L 2 ( Ω ) 2 ( p θ + 1 ) p + θ 1 a 1 + c 4 ( T ) ( p 1 ) ( p + θ 1 ) 2 Ω u ε p + θ 1 2 2 + c 5 ( T ) ,

for all t ( 0 , T ) and ε ( 0 , 1 ) . Applying the Gagliardo-Nirenberg inequality once more, there exists c 6 = c 6 ( p ) > 0 such that

1 p u ε L p ( Ω ) p = 1 p u ε p + θ 1 2 L 2 p p + θ 1 ( Ω ) 2 p + θ 1 c 6 u ε p + θ 1 2 L 2 ( Ω ) 2 p + θ 1 a 2 u ε p + θ 1 2 L 2 p + θ 1 ( Ω ) 2 p + θ 1 ( 1 a 2 ) + c 6 u ε p + θ 1 2 L 2 p + θ 1 ( Ω ) 2 p + θ 1 ,

with a 2 1 1 p . Since θ > 3 2 , it is easy to see that a 2 p + θ 1 < 1 ; by Young’s inequality again, there exists c 7 ( T ) > 0 such that

(3.41) 1 p u ε L p ( Ω ) p ( p 1 ) ( p + θ 1 ) 2 Ω u ε p + θ 1 2 2 + c 7 ( T ) .

Collecting (3.36), (3.42), and (3.40), we have

1 p d d t Ω u ε p + 1 p Ω u ε p c 6 ( T ) + c 7 ( T ) , for all t ( 0 , T ) and ε ( 0 , 1 ) .

The desired result is directly from ordinary differential equations comparison argument.

On the other hand, if θ [ 2 , ) ,

(3.42) ( p 1 ) χ 2 2 Ω u ε p θ 1 v ε 2 v ε 2 ( p 1 ) χ 2 2 Ω u ε ( θ + 1 ) ( p θ + 1 ) θ 1 θ 1 θ + 1 Ω v ε θ + 1 v ε θ + 1 2 θ + 1 c 8 ( T ) Ω u ε ( θ + 1 ) ( p θ + 1 ) θ 1 θ 1 θ + 1 ,

for all t ( 0 , T ) and ε ( 0 , 1 ) with c 8 ( T ) ( p 1 ) χ 2 2 c 1 ( T ) 2 θ + 1 , and by following the same procedure, we can obtain the (3.36). The proof is complete.□

Lemma 3.7

Let θ > 3 2 and q > 2 . Then, there exists L : ( 0 , ) ( 0 , ) fulfilling ( L ) such that for all T > 0 ,

(3.43) v ε ( , t ) W 1 , q ( Ω ) C 8 ( T ) , for all t ( 0 , T ) and ε ( 0 , 1 ) .

Proof

Based on

(3.44) W 1 , 2 θ 1 ( Ω ) L ( Ω ) , if θ 3 2 , 2 , W 1 , θ + 1 ( Ω ) L ( Ω ) , if θ [ 2 , ) ,

we can use Lemma 3.6 and equation (1.7) to assert c 1 : ( 0 , ) ( 0 , ) with the property ( L ) such that by defining f ε ( x , t ) = u ε 1 + ε u ε ( x , t ) + g ( x , t ) for ( x , t ) Ω × ( 0 , ) , we can verify that for all T > 0 , f ε ( x , t ) L p ( Ω ) c 1 ( T ) for all t ( 0 , T ) and ε ( 0 , 1 ) . Then, (3.41) can be obtained by the Neumann heat semigroup; the procedures are similar to Lemma 3.5; to avoid repetition, we omit giving details here. The proof is complete.□

Lemma 3.8

Let θ > 3 2 . Then, there exists L : ( 0 , ) ( 0 , ) fulfilling ( L ) such that for all T > 0 ,

(3.45) u ε ( , t ) L ( Ω ) L ( T ) , for all t ( 0 , T ) and ε ( 0 , 1 ) .

Proof

The proof is similar to our recent work [27]; to avoid repetition, we omit giving details here. The proof is complete.□

Lemma 3.9

Let θ > 3 2 . Then, there exists L : ( 0 , ) ( 0 , ) fulfilling ( L ) such that for all T > 0 ,

(3.46) t t + 1 Ω ( u ε + ε ) 3 θ 2 u ε 2 L ( T ) , for all t ( 0 , T ) and ε ( 0 , 1 ) .

Proof

Multiplying the first equation in (2.3) by ( u ε + ε ) 2 θ , integrating by parts, and using Young’s inequality, we have

(3.47) 1 2 θ + 1 d d t Ω ( u ε + ε ) 2 θ + 1 + θ Ω ( u ε + ε ) 3 θ 2 u ε 2 = θ Ω ( u ε + ε ) 3 θ 2 u ε 2 + 2 θ χ Ω ( u ε + ε ) 2 θ 1 u ε v ε u ε c ε θ χ 2 Ω ( u ε + ε ) θ + 2 v ε 2 v ε 2 , for all t ( 0 , T ) and ε ( 0 , 1 ) .

By Lemmas 2.5, 3.1, and 3.8, there exist l i : ( 0 , ) ( 0 , ) ( i = 1 , 2 , 3 ) fulfilling ( L ) such that

(3.48) v ε 1 l 1 ( T ) in Ω × ( 0 , T ) , for all ε ( 0 , 1 )

and

(3.49) t t + 1 Ω v ε 3 2 v ε 2 l 2 ( T ) , for all t ( 0 , T 1 ) all ε ( 0 , 1 )

as well as

(3.50) u ε ( , t ) L ( Ω ) l 3 ( T ) , for all t ( 0 , T ) all ε ( 0 , 1 ) .

Inserting equations (3.48) and (3.50) into equation (3.47), we obtain

(3.51) 1 2 θ + 1 d d t Ω ( u ε + ε ) 2 θ + 1 + θ Ω ( u ε + ε ) 3 θ 2 u ε 2 θ χ 2 l 1 1 2 ( T ) ( l 3 ( T ) + 1 ) θ + 2 Ω v ε 3 2 v ε 2 ,

for all t ( 0 , T ) and ε ( 0 , 1 ) . Integrating (3.51) over ( t , t + 1 ) and invoking (3.49) together with (3.50) imply that

t t + 1 Ω ( u ε + ε ) 3 θ 2 u ε 2 ( l 3 ( T ) + 1 ) 2 θ + 1 Ω θ ( 2 θ + 1 ) + θ χ 2 l 1 1 2 ( T ) l 2 ( T ) ( l 3 ( T ) + 1 ) θ + 2 ,

for all t ( 0 , T 1 ) and ε ( 0 , 1 ) . The proof is complete.□

Lemma 3.10

Let θ > 3 2 and γ 3 θ 2 . Then, for all T > 0 , there exists C ( γ , T ) > 0 such that

(3.52) 0 T Ω ( u ε + ε ) γ 2 C ( γ , T ) , for all ε ( 0 , 1 ) .

Proof

From Lemma 3.8, given T > 0 , we can find c 1 ( T ) > 0 satisfying

(3.53) u ε c 1 ( T ) in Ω × ( 0 , T ) , for all ε ( 0 , 1 ) .

Owing to γ 3 θ 2 , we have 2 γ 3 m , and thus,

(3.54) ( u ε + ε ) γ 2 = γ 2 { ( u ε + ε ) 3 θ 2 u ε 2 } ( u ε + ε ) 2 γ 3 θ { ( u ε + ε ) 3 θ 2 u ε 2 } ( c 1 ( T ) + 1 ) 2 γ 3 θ

in Ω × ( 0 , T ) for all ε ( 0 , 1 ) . Integrating (3.54) over ( 0 , T ) and using Lemma 3.9, we readily obtain (3.52). The proof is complete.□

Lemma 3.11

Let θ > 3 2 and γ 2 θ + 1 . Then, for all T > 0 , there exists C ( γ , T ) > 0 such that

(3.55) 0 T t ( u ε + ε ) γ ( W 2 , 2 ( Ω ) ) d t C ( γ , T ) , for all ε ( 0 , 1 ) .

Proof

Fixed t > 0 and ψ C ( Ω ¯ ) , by the straightforward calculation, we have

(3.56) Ω t ( u ε + ε ) γ ψ = γ Ω ( u ε + ε ) γ 1 ψ { ( ( u ε + ε ) θ 1 u ε ) χ ( u ε v ε v ε ) } = γ ( γ 1 ) Ω ( u ε + ε ) γ + θ 3 u ε 2 ψ γ Ω ( u ε + ε ) γ + θ 2 u ε ψ + γ χ ( γ 1 ) Ω u ε ( u ε + ε ) γ 2 ( u ε v ε v ε ) ψ + γ χ Ω u ε ( u ε + ε ) γ 1 v ε v ε ψ ,

for all ε ( 0 , 1 ) . Given T > 0 , from Lemmas 3.8, 2.2, and 3.5, and equation (1.7), there exist c i ( T ) ( i = 1 , 2 , 3 , 4 ) such that for all ε ( 0 , 1 ) ,

(3.57) u ε c 1 ( T ) , c 2 ( T ) v ε c 3 ( T ) , and g c 4 ( T ) in Ω × ( 0 , T ) .

Using Young’s inequality, we have

(3.58) γ χ Ω u ε ( u ε + ε ) γ 1 v ε v ε ψ Ω v ε 3 2 v ε 2 + γ 2 χ 2 4 Ω u ε 2 ( u ε + ε ) 2 γ 2 v ε 1 2 ψ 2 Ω v ε 3 2 v ε 2 + γ 2 χ 2 4 c 1 2 ( T ) ( c 1 ( T ) + 1 ) 2 γ 2 c 2 1 2 ψ L 2 ( Ω ) 2 .

Thanks to γ 2 θ + 1 > 2 , we have

(3.59) γ ( γ 1 ) Ω ( u ε + ε ) γ + θ 3 u ε 2 ψ γ ( γ 1 ) ( c 1 ( T ) + ε ) γ 2 θ 1 Ω ( u ε + ε ) 3 θ 2 u ε 2 ψ L ( Ω )

and

(3.60) γ χ ( γ 1 ) Ω u ε ( u ε + ε ) γ 2 ( u ε v ε v ε ) ψ Ω v ε 3 2 v ε 2 + γ 2 ( γ 1 ) 2 χ 2 4 ( c 1 ( T ) + ε ) 2 γ 3 θ 2 c 2 1 2 × Ω ( u ε + ε ) 3 θ 2 u ε 2 ψ L ( Ω )

as well as

(3.61) γ Ω ( u ε + ε ) γ + θ 2 u ε ψ ( c 1 ( T ) + ε ) 2 γ θ 2 Ω ( u ε + ε ) 3 θ 2 u ε 2 + γ 2 4 ψ L 2 ( Ω ) 2 ,

for all t ( 0 , T ) and ε ( 0 , 1 ) . Since W 2 , 2 ( Ω ) L ( Ω ) , combining equations (3.55) with (3.57)–(3.60), then for each T > 0 , there exists c 5 ( T ) > 0 such that for all t ( 0 , T ) and ε ( 0 , 1 ) ,

(3.62) t ( u ε + ε ) ( W 2 , 2 ( Ω ) ) c 5 ( T ) Ω ( u ε + ε ) 3 θ 2 u ε 2 + Ω v ε 3 2 v ε 2 + 1 .

Integrating (3.62) over ( 0 , T ) and using Lemmas 3.1 and 3.9, we obtain (3.54). The proof is complete.□

Lemma 3.12

Let θ > 3 2 . Then, for all T > 0 , there exist ε = ε ( T ) ( 0 , 1 ) and C ( T ) > 0 such that

(3.63) v ε C ε , ε 2 ( Ω ¯ × [ 0 , T ] ) C ( T ) , for all ε ( 0 , 1 ) .

Proof

Let f ε u ε 1 + ε u ε + g in Ω × ( 0 , T ) for ε ( 0 , 1 ) ; from Lemma 3.8 and (1.7), we know that ( f ε ) ε ( 0 , 1 ) is bounded in L loc ( Ω ¯ × [ 0 , ) ) , and (3.63) is directly from standard theory on the Hölder regularity in parabolic equations [26]. The proof is complete.□

Now, we are preparing to extract a suitable sequence of number ε along with the respective solutions that approach a limit in appropriate topologies.

Lemma 3.13

Let θ > 3 2 . Then, there exist ( ε j ) j N ( 0 , 1 ) as well as functions

(3.64) u L loc ( Ω ¯ × [ 0 , ) ) , v C 0 ( Ω ¯ × [ 0 , ) ) q > 2 L loc ( [ 0 , ) ; W 1 , q ( Ω ) )

such that ε j 0 as j , that u 0 a.e. in Ω × ( 0 , ) , and v > 0 in Ω ¯ × [ 0 , ) , that as ε = ε j 0 , we have

(3.65) u ε u in p 1 L loc p ( Ω ¯ × [ 0 , ) ) and a.e. in Ω × ( 0 , ) ,

(3.66) v ε v in C loc 0 ( Ω ¯ × [ 0 , ) ) ,

(3.67) v ε * v in q > 2 L loc ( [ 0 , ) ; L q ( Ω ) ) ,

and that ( u , v ) is a global weak solution of equation (1.5) in the sense of Definition 2.1.

Proof

Taking any γ > 0 such that γ max { 3 θ 2 , 2 θ + 1 } = 2 θ + 1 if θ > 3 2 , from Lemmas 3.10 and 3.11, we have

{ ( u ε + ε ) γ } ε ( 0 , 1 ) is bounded in L 2 ( ( 0 , T ) ; W 1 , 2 ( Ω ) ) , for all T > 0

and

{ t ( u ε + ε ) γ } ε ( 0 , 1 ) is bounded in L 1 ( ( 0 , T ) ; ( W 2 , 2 ( Ω ) ) ) , for all T > 0 .

Thus, applying the Aubin-Lions lemma implies ( ε j ) j N ( 0 , 1 ) and nonnegative function u on Ω × ( 0 , ) such that ε j 0 as j and that as ε = ε j 0 , we have ( u ε + ε ) γ u γ in L loc 2 ( Ω ¯ × [ 0 , ) ) and a.e. in Ω × ( 0 , ) , and thus, in particular, we have u ε u a.e. in Ω × ( 0 , ) . From Lemma 3.8 and the Vitali convergence theorem, we know that (3.65) and the first result in (3.64) hold. From Lemma 3.7 and Lemma 3.12, the Arzelá-Ascoli theorem, and the Banach-Alaoglu theorem, we know that (3.66), (3.67), and the second result in (3.64) hold. Depending on (3.65)–(3.67) when taking ε = ε j 0 in the corresponding weak formulation associated with (2.3), we readily obtain (2.1) and (2.2). The proof is complete.□

Finally, we prove the main theorem.

Proof of Theorem 1.1

The global existence directly results from Lemma 3.13. Considering the global weak solution of (1.5) obtained in Lemma 3.13, it is straightforward that the boundedness of ( u ε ) ε ( 0 , 1 ) in L ( Ω × ( 0 , ) ) and ( v ε ) ε ( 0 , 1 ) in L ( ( 0 , T ) ; W 1 , q ( Ω ) ) for all q > 2 can be derived due to Lemmas 3.7 and 3.8 together with Hypotheses (1.10) and (1.11) and property ( L ). Accordingly, the additional Property (1.12) can be obtained by equations (3.65) and (3.67). The proof is complete.□

Acknowledgements

The authors would like to express their gratitude to Professor Bin Liu for helpful discussions during the preparation of this article and express their gratitude to the anonymous reviewers and editors for their valuable comments and suggestions that led to the improvement of the original manuscript.

  1. Funding information: Guoqiang Ren was supported by the NSFC (Nos 12001214, 12231008).

  2. Author contributions: Guoqiang Ren: Writing and Editing, Xing Zhou: Reviewing.

  3. Conflict of interest: The authors have no relevant financial or non-financial interests to disclose.

  4. Data availability statement: No data was used for the research described in the article.

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Received: 2023-01-17
Revised: 2023-10-17
Accepted: 2023-12-03
Published Online: 2024-02-01

© 2024 the author(s), published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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