A new route for the preparation of (Me 3 Ge) 3 N (2 a) using Me 3 GeCl and (Me 3 Sn) 3 N is described. Cp′TiCl 3 (Cp′ = Me 5 C 5 (la) and Me 3 SiC 5 H 4 (lb)) reacts with (Me 3 Sn) 3 N to yield (Cp′TiClNSnMe 3 ) 2 (3a) and (3b). (Me 5 C 5 TiFNSnMe 3 ) 2 (3c) is formed when Me 5 C 5 TiF 3 is treated with (Me 3 Sn) 3 N. The X-ray structures of 3a and (Me 3 SiC 5 H 4 TiClNtBu) 2 (5) are reported. 3a and 5 consist in the solid state of four-membered Ti 2 N 2 rings with the substituents in different positions.
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June 2, 2014
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June 2, 2014
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