1 Introduction
Recently, there has been considerable interest in word maps on finite, algebraic and topological groups; see, for example, [1, 7, 8, 10, 11, 14, 15, 16] and a survey [17].
Recall that a group word ω=ω(x1,…,xd) is an element of a free group Fd with free generators x1,…,xd.
We may write ω=xi1m1…xikmk, where ij∈{1,…,d} and mj are integers.
We say that ω is a power word if ω=υm for m>1 and some word υ.
For a group G and g1,…,gd∈G, we write
ω(g1,…,gd)=gi1m1…gikmk∈G.
The corresponding map ω:Gd→G is called a word map, and its image is denoted by ω(G).
Many papers are devoted to estimate the size of ω(G).
In [15], Larsen and Shalev proved the following:
Theorem 1.1.
Let G be a finite simple group of Lie type and of rank n, and let ω≠1 be a word.
Then there exists N=N(ω) such that, if G is not of type An or An2 and |G|⩾N, then
|ω(G)|⩾cn-1|G|
for some absolute constant c>0.
Notice that c depends on ω in Theorem 1.1.
Later, in [16], Nikolov and Pyber found a weaker lower bound for the groups of type An and An2.
In the expository article [17], Shalev conjectured that Theorem 1.1 holds for all groups of Lie type.
Conjecture 1.2 ([17, Conjecture 5.6]).
For every word ω≠1, there exists a number N=N(ω) such that, if G is an alternating group of degree n or a finite simple group of Lie type of rank n and |G|⩾N, then
|ω(G)|⩾cn-1|G|,
where c>0 is an absolute constant.
Furthermore, Shalev states as a problem that, in the case of non-power words, a stronger conclusion might hold.
Problem 1.3 ([17, Problem 5.7 (i)]).
Suppose ω is not a power word, and let G be a finite simple group.
Is it true that there exist N,c>0 depending on ω such that, if |G|⩾N, then |ω(G)|⩾c|G|?
This problem shows that power words are of considerable interest, and, in this case, one could expect the lowest bound on |ω(G)|.
In this article, we explore the Shalev conjecture for finite groups of type An and An2 and for power words ω=xM.
It is clear that, if ω=xi1m1…xikmk∉Fd′ and M is the smallest positive absolute value of the sum of the exponents of a fixed variable xi in ω, then |ω(G)|⩾|ω¯(G)|, where ω¯=xM.
In the paper, we restrict ourself to the consideration of power words of type ω=xM.
Throughout the paper, we assume that ω=xM and fix symbols ω and M for this situation.
First, we show by an example that the constant c in the conjecture depends on the word ω.
Next, we prove that, for power words ω=xM, the conjecture is true (see Theorem 4.5).
Moreover, we improve the bound as follows:
Theorem 1.4.
Let ω=xM be a nontrivial power word, and let G=PSLnε(q).
Then there exists a positive constant N depending only on M such that, if |G|⩾N, then
|ω(G)|⩾ln(n)2n⋅M2|G|.
We believe that, for the estimate in Theorem 1.4, it is possible to prove a better bound |ω(G)|⩾clnk(n)n|G|, where k is any fixed power.
Notice also that, in view of Theorem 4.5, there exists N such that, if G=PSLnε(q) and |G|⩾N, then |ω(G)|⩾|G|2nM, and this bound could be better than the bound in Theorem 1.4.
2 Preliminaries
Our notation is standard and, in general, agrees with that of [3, 13, 5].
For integers m1,…,ms, by (m1,…,ms) or gcd{m1,…,ms} we denote their greatest common divisor, and by [m1,…,ms] or lcm{m1,…,ms} we denote their least common multiple.
We write H⩽G and H⊴G if H is a subgroup or H is a normal subgroup of G, respectively.
We recall some relations about gcd.
Lemma 2.1 ([18, Lemma 6 (iii)]).
Let a,s,t∈N.
Then
(as-1,at-1)=a(s,t)-1,
(as+1,at+1)={a(s,t)+1if boths/(s,t)𝑎𝑛𝑑t/(s,t)are odd,(2,a+1)𝑜𝑡ℎ𝑒𝑟𝑤𝑖𝑠𝑒,
(as-1,at+1)={a(s,t)+1𝑖𝑓s/(s,t)is even andt/(s,t)is odd,(2,a+1)𝑜𝑡ℎ𝑒𝑟𝑤𝑖𝑠𝑒.
Recall that any finite abelian group A can be uniquely presented as a product of cyclic groups A=ℤd1×…×ℤdk, where ℤdi is a cyclic group of order di and d1 divides d2, d2 divides d3, …, dk-1 divides dk.
We use the notation A=d1×…×dk and refer to it as a standard decomposition of A for brevity.
By p we always denote some prime number, and q is a power of p; 𝔽q denotes a finite field of q elements, and 𝔽¯q is an algebraic closure of 𝔽q.
The symmetric group on n elements is denoted by Symn.
By diag(λ1,λ2,…,λn) we denote a diagonal n×n-matrix with λ1,λ2,…,λn on the diagonal.
By bd(T1,T2,…,Tn) we denote a block-diagonal matrix with square blocks T1,T2,…,Tn on the diagonal.
Let G¯ be a connected simple algebraic group over an algebraic closure 𝔽¯p of a finite field 𝔽p.
We say that an algebraic group endomorphism σ of G¯ is a Steinberg endomorphism (or a Frobenius map), if the set G¯σ of σ-stable points of G¯ is finite.
Any group G=Op′(G¯σ) is called a finite group of Lie type.
If G¯ is of type An, then Op′(G¯σ) is a homomorphic image of either SLn+1(q) or SUn+1(q) for some q, and we say that G is a group Anε(q) in this case, where ε∈{+,-} and An+(q) is a homomorphic image of SLn+1(q), while An-(q) is a homomorphic image of SUn+1(q).
Recall that an element is regular if the dimension of its centralizer in the corresponding group over the algebraic closure of 𝔽q is equal to the Lie rank of the group G.
In particular, a semisimple element is regular if and only if the connected component of its centralizer is a maximal torus.
Thus every regular semisimple element belongs to exactly one maximal torus.
Recall also that every semisimple element of G¯σ lies in a σ-stable maximal torus T¯ of G¯.
If T¯ is a maximal σ-stable torus of G¯, then T=T¯∩G is called a maximal torus of G, and N(G,T)=NG¯(T¯)∩G is called an algebraic normalizer.
Clearly, N(G,T)⩽NG(T), and the next lemma gives a sufficient condition for the equality.
Lemma 2.2.
Let T be a maximal torus of a finite group of Lie type G=Op′(G¯σ).
Assume also that T contains a regular element t.
Then N(G,T)=NG(T).
Proof.
Since t is regular, we obtain
T¯⩽CG¯(T)0⩽CG¯(t)0=T¯.
Now CG¯(T)0⊴NG¯(T), so NG¯(T)⩽NG¯(T¯), and the lemma follows.
∎
We denote the Weyl group NG¯(T¯)/T¯ of An-1 by W.
Since all maximal tori are conjugate, W does not depend on a particular choice of T¯ and is isomorphic to Symn.
If we fix a σ-stable torus H¯ of G¯, then σ leaves NG¯(H¯) invariant and so induces an automorphism on W=NG¯(H¯)/H¯, and we denote this automorphism also by σ.
We say that u,w∈W are σ-conjugate if there exists v∈W such that u=v-1wvσ.
There is a bijection between the G-classes of σ-stable maximal tori of G¯ and the σ-conjugacy classes of W (see [4, Propositions 3.3.1, 3.3.3]).
Moreover, by [4, Proposition 3.3.6], if a torus T=H¯g∩G corresponds to an element w of W, we have
N(G,T)/T≃CW,σ(w)={x∈W∣x-1wxσ=w}.
Given w∈W, we denote a representative of the corresponding conjugacy class of maximal tori by Tw, and we denote N(G,T)/T by W(T).
If G=Anε(q), then we may choose H¯ so that σ acts trivially on NG¯(H¯)/H¯ (in this case, H¯σ is of order (q-ε1)n), so, in this case, there is a bijection between the G-classes of σ-stable maximal tori of G¯ and the conjugacy classes of W.
In particular, for a maximal torus T=Tw, the identity W(T)≃CW(w) holds.
Each element of Symn can be uniquely expressed as a product of disjoint cycles.
The lengths of these cycles define a set of integers, which is called the cycle-type of the element.
Two permutations are conjugate if and only if they have the same cycle-type.
Thus the conjugacy classes of Symn are in one-to-one correspondence with the partitions of n, and so the conjugacy classes of maximal tori in An-1ε(q) are in one-to-one correspondence with the partitions of n.
The structure of maximal tori in linear groups is well known.
For our purposes, we will use the description from [2].
Proposition 2.3 ([2, Proposition 2.1]).
Let T be a maximal torus of G=SLnε(q) corresponding to the partition n1+n2+…+nm=n.
Let U be a subgroup of GLn(F¯p) consisting of all diagonal matrices of the form bd(D1,D2,…,Dm), where
Di=diag(λi,λiεq,…,λi(εq)ni-1)
and λi(εq)ni=λi for i∈{1,2,…,m}.
Then T and U∩SLnε(F¯p) are conjugate in GLn(F¯p).
Proposition 2.4 ([2, Theorem 2.1]).
Let n⩾2 and n1+n2+…+ns=n be a partition, and choose a maximal torus T of SLn(q) corresponding to the partition.
For 1⩽i⩽s, define
di=lcm1⩽j1<…<ji⩽sgcd{qnj1-1,…,qnji-1}.
Then di divides di′ for i>i′, and
T=d1×d2×…×ds-1×dsq-1
is the standard decomposition of T.
Let T~ be the image of T in PSLn(q).
Put d=(n,q-1) and d′=(n/(n1,…,ns),q-1).
Then
T~=d1d(q-1)
is the standard decomposition of T~ if s=1, and
T~=d1×d2×…×ds-2×ds-1d′×d′dsd(q-1)
is the standard decomposition of T~ if s>1.
Proposition 2.5 ([2, Theorem 2.2]).
Let n⩾2 and n1+n2+…+ns=n be a partition, and consider a maximal torus T of SUn(q2) corresponding to the partition.
For 1⩽i⩽s, define
di=lcm1⩽j1<…<ji⩽sgcd{qnj1-(-1)nj1,…,qnji-(-1)nji}.
Then di divides di′ for i>i′, and
T=d1×d2×…×ds-1×dsq+1
is the standard decomposition of T.
Let T~ be the image of T in PSUn(q2).
Put d=(n,q+1) and d′=(n/(n1,…,ns),q+1).
Then
T~≃d1d(q+1)
is the standard decomposition of T~ if s=1, and
T~≃d1×d2×…×ds-2×ds-1d′×d′dsd(q+1)
is the standard decomposition of T~ if s>1.
If G is GLn(q),Un(q),SLn(q),SUn(q), a semisimple element is regular if and only if its minimal polynomial is equal to its characteristic polynomial, i.e., if and only if its characteristic polynomial has no repeated roots (see [6]).
We briefly describe the general idea of proofs of the main results.
We need to compute the lower and upper bounds for the ratio |w(G)||G|.
We obtain the bounds only for regular semisimple elements and then apply them to obtain the bounds for the whole group.
So we need to consider maximal tori of G.
Since any regular semisimple element belongs to a unique maximal torus, we can take the union (and this union is disjoint) of tori, thus avoiding repetition.
Finally, instead of considering all maximal tori, we could restrict ourselves to a finite number (in our paper, one or two) maximal tori and then multiply the bound by the index of normalizer.
3 Example
In this section, we give an example that the constant c in the conjecture depends on the word ω.
Lemma 3.1.
Assume that G≃An-1ε(q), and let Gss be the set of all semisimple elements of G.
Let ω be a power word xM.
Assume that there exists N such that the inequality |ω(T)|⩽|T|N holds for every maximal torus T of G.
Then
|ω(Gss)|⩽|G|N.
Proof.
Let Tλ be a maximal torus corresponding to a partition λ, and let σλ be a representative of the conjugacy class of Symn corresponding to λ.
Then Gss=⋃λTλG, where λ runs through all partitions of n.
Since the number of conjugate tori in TλG equals |G||NG(Tλ)| and
|NG(Tλ)|⩾|N(G,Tλ)|=|Tλ|⋅|CW(σλ)|,
that number is not greater than |G||Tλ|⋅|CW(σλ)|.
Hence we have
|ω(TλG)|⩽∑T∈TλG|ω(T)|⩽|G||Tλ|⋅|CW(σλ)||ω(Tλ)|⩽|G||Tλ|⋅|CW(σλ)||Tλ|N=|G|N|CW(σλ)|.
Notice that
∑λ1|CW(σλ)|=∑λ|Cl(σλ)||Symn|
=1|Symn|∑λ|Cl(σλ)|=1,
where Cl(σλ) is the conjugacy class of σλ in Symn.
Therefore,
|ω(Gss)|=|ω(⋃λTλG)|=|⋃λω(TλG)|⩽∑λ|ω(TλG)|⩽∑λ|G|N|CW(σλ)|=|G|N.∎
The following lemma is clear.
Lemma 3.2.
Assume T=d1×d2×…×ds is the standard decomposition of a finite abelian group T and ω(x)=xM is a power word.
Then
ω(T)=d1(M,d1)×d2(M,d2)×…×ds(M,ds)
is the standard decomposition of ω(T).
Lemma 3.3.
Let n⩾2 be a positive integer, and let p be a prime.
Choose odd l so that (l,n)=1 (in particular, l could be equal to 1).
Assume that T~ is a maximal torus of G~=PSLnε(pl).
Consider ω(x)=xM, where M=pn-(ε1)n.
Then
|w(T~)|⩽n|T~|p-1.
Proof.
Denote pl by q for brevity.
In view of the remarks after Lemma 2.2, T~ corresponds to a partition of n.
Let n=n1+…+ns be the corresponding partition.
Assume that s=1 first.
Then
T~≃d1d(q-ε1)=qn-(ε1)nd(q-ε1),
where d=(n,q-ε1).
By Lemma 3.2, we have
ω(T~)≃qn-(ε1)nd(q-ε1)(M,qn-(ε1)nd(q-ε1)).
Notice that, for a,b,c∈ℕ with b dividing a, we have (ab,c)⩾1b(a,c).
Therefore,
(M,qn-(ε1)nd(q-ε1))=(pn-(ε1)n,pln-(ε1)n(n,q-ε1)(pl-ε1))⩾1n(pn-(ε1)n,pln-(ε1)npl-ε1).
Since (l,n)=1, by Lemma 2.1, both pn-(ε1)n and pl-ε1 divide pln-(ε1)n, so [pn-(ε1)n,pl-ε1] divides pln-(ε1)n.
Since (l,n)=1, Lemma 2.1 implies that (pn-(ε1)n,pl-ε1) divides p-ε1, so (pn-(ε1)n)(pl-ε1)p-ε1 equals pln-(ε1)n.
Therefore,
(M,qn-(ε1)nd(q-ε1))⩾1n(pn-(ε1)n,pln-(ε1)npl-ε1)⩾1n⋅pn-(ε1)np-ε1.
Hence
|w(T~)|=|T~|(M,qn-(ε1)nd(q-ε1))⩽|T~|n(p-ε1)pn-(ε1)n⩽|T~|np-1.
If s>1, then
T~≃d1×d2×…×ds-2×ds-1d′×d′dsd(q-ε1).
It follows from the definition of di that q-ε1 divides di for all 1⩽i⩽s.
By Lemma 2.1,
(M,di)⩾(pn-(ε1)n,q-ε1)⩾p-1,(M,ds-1d′)⩾1n(M,ds-1)⩾p-1n.
By Lemma 3.2, we have
|ω(T~)|⩽d1(M,d1)⋯ds-2(M,ds-2)⋅ds-1d′(M,ds-1/d′)⋅d′dsd(q-ε1)⩽d1p-1⋯ds-2p-1⋅ds-1nd′(p-1)⋅d′dsd(q-ε1)=|T~|n(p-1)s-1⩽|T~|np-1.∎
Thus we have the following:
Theorem 3.4.
Let n⩾2 be a positive integer, and let p be a prime.
Choose odd l so that (l,n)=1 (in particular, l could be equal to 1).
Assume that T is a maximal torus of G=PSLnε(pl).
Consider ω(x)=xM, where M=pn-(ε1)n.
Then
|ω(G)|⩽4n|G|p-1.
Proof.
By Lemma 3.3, we have |ω(T)|⩽|T|np-1 for any maximal torus T of G.
By Lemma 3.1,
|ω(Gss)|⩽|G|(p-1)/n=|G|np-1.
According to [9, Theorem 1.1], we have (recall that pl=q)
|Gss|⩾|G|(1-3q-1-2(q-1)2),
so |G∖Gss|⩽5q-1|G|.
Now we have
|ω(G)|⩽|ω(Gss)|+|G∖Gss|⩽|G|np-1+5p-1|G|<4|G|np-1.∎
As a corollary to Theorem 3.4, we get an example showing that the constant c in the conjecture does depend on ω.
Example 3.5.
Consider G≃PSLnε(q), n⩾2.
For a constant c, choose a prime p such that p-1>4n2c.
Let ω(x)=xM, where M=pn-(ε1)n.
For any number N=N(ω), there exist infinitely many odd numbers l such that (l,n)=1 and |PSLnε(pl)|⩾N.
Then, by Theorem 3.4, we have
|ω(G)|⩽4|G|np-1<c|G|n.
4 Estimate for power words in SLnε(q)
The following lemma shows that it is enough to prove Theorem 1.4 for SLnε(q).
Lemma 4.1.
Let π:G→H be a surjective homomorphism of finite groups, and let ω be a word.
Then
|ω(H)||H|⩾|ω(G)||G|.
Proof.
As π is a homomorphism, for g1,g2,…,gd∈G, it is straightforward to check that π(ω(g1,g2,…,gd))=ω(π(g1),π(g2),…,π(gd)).
Thus we have ω(g1,g2,…,gd)∈π-1(ω(π(g1),π(g2),…,π(gd))).
Hence the inclusion
ω(G)⊂π-1(ω(H))
holds, and we have |ω(G)|⩽|ker(π)|⋅|ω(H)|.
Thus
|ω(H)||H|⩾|ω(G)||ker(π)|⋅|H|=|ω(G)||G|.∎
For any subset S of a maximal torus, denote by Sreg the set of regular semisimple elements in S.
Lemma 4.2.
For every ω=xM, there exists a number N=N(ω) such that, if T is a maximal torus of G=SLnε(q) corresponding to the partition {n} of n, then
|ω(T)reg|⩾|T|2M
for |G|⩾N.
Proof.
Consider the subgroup
U={diag(λ,λεq,…,λ(εq)n-1)∣λqn-(ε1)nq-ε1=1}
of GLn(𝔽¯p).
Then T and U are conjugate by Proposition 2.3.
Recall that an element diag(λ1,…,λn) of GLn(𝔽¯p) is regular if and only if λi≠λj for all i≠j.
If n=2, then U is a cyclic group of order q+ε1, and U∖Ureg consists of E and -E, where E is the identity matrix.
So
|ω(U)reg|⩾|ω(U)|-2⩾|U|M-2⩾|U|2M
if |G|=1(2,q-1)q(q2-1) is big enough,
and thus there exists N2 such that, if |G|⩾N2, then the inequality |ω(T)reg|⩾|T|2M holds.
If n=3, then U is a cyclic group of order q2+εq+1, and U∖Ureg consists of E, λE and λ2E, where λ is a cubic root of the unity in 𝔽q.
So
|ω(U)reg|⩾|ω(U)|-3⩾|U|M-3⩾|U|2M
if |G|=1(2,q-ε1)q3(q2-1)(q3-ε1) is big enough,
and thus there exists N3 such that, if |G|⩾N3, then the inequality |ω(T)reg|⩾|T|2M holds.
Now assume that n⩾4.
Suppose u=diag(λ,λεq,…,λ(εq)n-1)∈U, and uM is not regular.
Then λM(εq)k=λM(εq)l for some n-1⩾k>l⩾0.
Thus we have
(4.1)λM(εq)l((εq)r-1)=1 forr=k-l.
Since |λ| divides |U|=1+εq+…+(εq)n-1, we have (|λ|,q)=1.
Therefore, |λ|=|λ(εq)l| and λM((εq)r-1)=1.
Hence, applying Lemma 2.1, we obtain that the number of solutions to (4.1) is equal to
(qn-(ε1)nq-ε1,M((εq)r-1))⩽M(qn-(ε1)n,(εq)r-1)⩽M(q(n,r)+1).
Further, since (r,n)=(n-r,n)⩽n/2, we have q(r,n)+1<2qn/2. Then the total number of elements u∈U such that uM is not regular is not greater than
∑0⩽l<k⩽n-1M(q(n,k-l)+1)⩽∑0⩽l<k⩽n-12Mq(n,k-l)⩽n2Mqn/2.
It follows that
(4.2)|ω(U)reg|⩾|ω(U)|-n2Mqn/2⩾|U|M-n2Mqn/2.
We show that there exists N such that
(4.3)n2Mqn/2<|U|2M
if |G|⩾N.
If (4.3) is true, then, from (4.2), we obtain |ω(U)reg|>|U|2M.
Thus it remains to show that there exists N such that, for every G with |G|⩾N, inequality (4.3) holds.
First notice that
|U|=qn-1+εqn-2+ε2qn-3+⋯>qn-1+εqn-2⩾qn-2(q-1),
so inequality (4.3) would follow from
(4.4)qn-n/2-2(q-1)2M>n2M.
Since q⩾2, inequality (4.4) holds if 2n/2>8n2M2.
Clearly, there exists n0 such that, for every n⩾n0, the last inequality holds.
Thus, for every G of rank at least n0, inequality (4.4) holds.
If n<n0, then clearly, for every n, there exists qn such that, for every q⩾qn, inequality (4.4) holds.
Denote qn2n2 by Nn.
Since |G|<q2n2, we obtain that, if G is of rank n and |G|⩾Nn, then q>qn, so inequality (4.4) holds.
Denote max{Nn∣2⩽n⩽n0} by N.
If |G|⩾N, then either n⩾n0 or |G|>Nn.
In both cases, inequality (4.4) holds and the lemma follows.
∎
Lemma 4.3.
For every ω=xM, there exists N=N(ω) such that, for every maximal torus T corresponding to a partition i+(n-i), where 1⩽i⩽n-1, of G=SLnε(q), the inequality
|ω(T)reg|⩾|T|2M2
holds if |G|⩾N.
Proof.
We use similar arguments as in the proof of Lemma 4.2.
Let
U={diag(λ,λεq,…,λ(εq)i-1,μ,μεq,…,μ(εq)n-i-1)∣λqi-(ε1)i=μqn-i-(ε1)n-i=1;λqi-(ε1)iq-ε1⋅μqn-i-(ε1)n-iq-ε1=1}
be a subgroup of GLn(𝔽¯p).
Then, by Proposition 2.3, the subgroups T and U are conjugate in GLn(𝔽¯p).
We want to bound |ω(U)reg|.
Suppose u∈U and uM is not regular.
We have
uM=diag(λM,λMεq,…,λMεqi-1,μ,μMεq,…,μMεqn-i-1).
Then we have the following three possibilities:
(4.5)λM(εq)k=λM(εq)lfor 0⩽l<k⩽i-1,
(4.6)μM(εq)k=μM(εq)lfor 0⩽l<k⩽n-i-1,
(4.7)λM(εq)k=μM(εq)lfor 0⩽k⩽i-1, 0⩽l⩽n-i-1.
Applying the same arguments as in the proof of Lemma 4.2, we could deal with the cases (4.5) and (4.6).
We have that the total number of elements u∈U such that uM is not regular in these two cases is not greater than 2n2Mqn/2.
In the case (4.7), without loss of generality, we can assume i⩾n-i.
Raising to the (εq)i-k-th power both parts of (4.7), we obtain
μM(εq)l+i-k=λM(εq)i=λM.
Therefore, (λμ-(εq)l+i-k)M=1.
The equation xM=1 has at most M solutions in 𝔽¯p.
Hence, for each fixed element μ, we have at most M possibilities for λ.
In the torus U, we have qn-i-(ε1)n-i possibilities for μ.
Hence the number of elements u=u(λ,μ)∈U such that uM is not regular in the case (4.7) is at most M(qn-i-(ε1)n-i)⩽2Mqn/2.
The total number of such elements is not greater than
∑k=0i-1∑l=0n-i-12Mqn/2⩽n2Mqn/2.
Finally, we have
|ω(U)reg|⩾|ω(U)|-2n2Mqn/2-n2Mqn/2=|ω(U)|-3n2Mqn/2.
As in the proof of Lemma 4.2, we can find N such that |U|2M2>3n2Mqn/2 if |G|⩾N.
So we have
|ω(U)reg|⩾|U|M2-3n2Mqn/2>|U|2M2
for |G|⩾N.
∎
Lemma 4.4.
For every ω=xM, there exists N=N(ω) such that, for every maximal torus T corresponding to a partition i+(n-i), where 1⩽i⩽n-1, of G=SLnε(q), the inequality
|ω(TG)reg|⩾|G|2M2|W(T)|
holds if |G|⩾N.
Proof.
Take N from the conclusion of Lemma 4.3.
Then |ω(T)reg|⩾|T|2M2, in particular, Treg≠∅.
By Lemma 2.2, we have |NG(T)|=|N(G,T)|=|T|⋅|W(T)|.
Then the number k of conjugates of the torus T in G is equal to
|G||NG(T)|=|G||T|⋅|W(T)|.
Since ω(T1∪T2)=ω(T1)∪ω(T2) and (T1∪T2)reg=(T1)reg∪(T2)reg, we have
|ω(TG)reg|=|(ω(⋃i=1kTgi))reg|=|(⋃i=1kω(Tgi))reg|=|⋃i=1k(ω(Tgi))reg|,
where g1,…,gk is the right transversal of NG(T).
Since every regular semisimple element lies only in one maximal torus, it follows that
|⋃i=1k(ω(Tgi))reg|=∑i=1k|ω(Tgi)reg|=∑i=1k|ω(T)reg|.
Applying Lemma 4.3, we get
|ω(TG)reg|=∑i=1k|ω(T)reg|⩾|G||T||W(T)|⋅|T|2M2=|G|2M2|W(T)|,
and the lemma follows.
∎
Now we are ready to give an affirmative answer to the conjecture.
Theorem 4.5.
If G≃SLnε(q), then, for every ω=xM, there exists N=N(ω) such that
|ω(G)|⩾12nM|G|
for |G|⩾N.
Proof.
Let T be a maximal torus of G corresponding to a partition n, and choose N from the conclusion of Lemma 4.2.
Since the inequality |ω(T)reg|⩾|T|2M holds, T contains regular elements.
By Lemma 2.2, we have
|NG(T)|=|N(G,T)|=|T|⋅|W(T)|=|T|⋅n.
Then, applying Lemma 4.2 and arguments from the proof of the Lemma 4.4, we obtain
|ω(G)|⩾|ω(TG)|⩾|G|2M|W(T)|=|G|2nM
and the theorem follows.
∎