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Skew-morphisms of cyclic p-groups

  • István Kovács EMAIL logo and Roman Nedela
Published/Copyright: May 19, 2017

Abstract

Let G be a finite group having a factorisation G=AB into subgroups A and B with B cyclic and AB=1, and let b be a generator of B. The associated skew-morphism is the bijective mapping f:AA well-defined by the equality baB=f(a)B, where aA. In this paper, we shall classify all skew-morphisms of cyclic p-groups, where p is an odd prime.

1 Introduction

Following Jajcay and Širáň [9], a skew-morphism of a finite group A is a bijective mapping f:AA fixing the identity element of A and having the property that f(xy)=f(x)fπ(x)(y) for all x,yA, where the integer π(x) depends only on x. We also refer to the mapping π:A as a power function corresponding to f. The original motivation to investigate skew-morphisms of groups come from the characterisation of regular Cayley maps proved by Jajcay and Širáň [9]: “A Cayley map CM(G;ρ), where G is a group and ρ is a cyclic permutation of the generators is regular if and only if ρ extends to a skew-morphism of G”. Note that the orbit of ρ is by definition closed under taking inverses and the existence of at least one generating orbit closed under taking inverses is a characteristic feature of skew-morphisms related to Cayley regular maps. Recall that to define a 2-cell embedding of a connected graph into an orientable surface combinatorially one needs to determine a cyclic permutation of arcs based at v for each vertex v. A Cayley map is an embedding of a Cayley graph into an orientable surface such that a chosen global orientation induces at each vertex the same cyclic permutation of generators. Cayley maps are vertex-transitive, since each Cayley automorphism of the graph extends to an automorphism of the map. If the group of map automorphisms is regular on arcs, the map itself is called regular. Another geometric motivation for investigation of skew-morphisms can be found in papers [8, 13], where skew-morphisms are studied in connection with highly symmetrical hypermaps and with regular embeddings of complete bipartite graphs.

Although the concept of a skew-morphism was introduced and investigated in the context of regular Cayley maps and hypermaps, see [3, 5, 8, 9], Conder, Jajcay and Tucker [4] pointed out that it appeared already in the context of factorisation of groups. Namely, let G be a finite group having a factorisation G=AB into subgroups A and B with B cyclic and AB=1, and let b be a generator of B. Then there exists a bijective mapping f:AA well-defined by the equality baB=f(a)B, where aA. It is not hard to show that f is a skew-morphism of A. Moreover, all skew-morphisms of A arise in this way. Every automorphism of A is a skew-morphism with the power function π(x)=1 for all xA; the converse, however, does not hold in general. In particular, the normality of A in G=AB, is a necessary and sufficient condition for a skew-morphism defined by this factorisation to be an automorphism. There are plenty of factorisations AB, where A is not normal and B is cyclic, and there are many skew-morphisms that are not automorphisms, even in the case when A is cyclic. Particular examples of skew-morphisms which are not group automorphisms were given in [1, 4, 12] for abelian groups and in [4, 14] for dihedral groups. The problem of determining all skew-morphisms for a given group arises. Since every automorphism is a skew-morphism, this problem is at least as hard as the problem of determining Aut(G) for a given group G, which is not an easy task in general. One of the problems one needs to overcome consists in the fact that the composition of two skew-morphisms of G may not be a skew-morphism. Even to determine the skew-morphisms of cyclic groups seems to be a difficult problem.

Problem.

Determine the skew-morphisms of cyclic groups.

In this paper, we make a step towards its solution by determining all skew-morphisms for cyclic p-groups, where p>2 is an odd prime. The next natural step to accomplish is a determination of skew-morphisms of cyclic 2-groups. A partial solution of the above problem appears in [5], where skew-morphisms containing a generating orbit closed under taking inverses are classified.

In [12], we investigated skew-morphisms of cyclic groups in connection with Schur rings of cyclic groups. Among others we proved the following decomposition theorem. In what follows we denote by Skew(n) the set of skew-morphisms of the cyclic additive group n, and by ϕ Euler’s totient function.

Theorem 1.1 (cf. [12, Theorem 1.1]).

Let n=n1n2, where gcd(n1,n2)=1, and gcd(n1,ϕ(n2))=gcd(ϕ(n1),n2)=1. Then σSkew(Zn) if and only if σ is of the form σ=σ1×σ2, where σ1Skew(Zn1) and σ2Skew(Zn2).

It was shown in [12, Corollary 4.10] (and reproved in [4, Theorem 6.4]) that the cyclic group p2 has exactly (p-1)(p2-2p+2) skew-morphisms, where p is an odd prime. In this paper, we generalise this result to the cyclic group pe of order pe with arbitrary e2 by proving

Theorem 1.2.

If e2 and p is an odd prime, then the cyclic group Zpe has exactly (p-1)(p2e-1-p2e-2+2)/(p+1) skew-morphisms.

Detailed description of the set Skew(pe) of skew-morphisms can be found in Theorems 5.4 and 5.5, which are the main results of the paper.

The paper is organised as follows. In the next section we recall some known facts for further use. Among others we state in Lemma 2.1 that the order of a skew-morphism of a cyclic group n divides nϕ(n). In particular, if n=pe for a prime p, the skew-morphisms split into two classes: the first class contains those skew-morphisms whose order is a power of p, the others form the complement of the first class. In Section 3 we define a two-parametrised family of skew-morphisms si,j and investigate its properties. Although the skew-morphisms of a group do not form a group in general, in the investigated case of cyclic p-groups, the skew-morphism si,j all “live” in a split metacyclic group G=CY of order p2e-1, where C is a normal cyclic subgroup of order pe and Y is cyclic of order pe-1, see Remark 3.2. In Section 4 the above family is generalised to a family of skew-morphisms si,j,k,l given by four integer parameters i,j,k,l. Finally, in the last section we prove that every skew-morphism in Skew(pe) is one of si,j,k,l, and that the skew-morphisms of the first class are exactly the skew-morphisms si,j=si,j,0,0, see Theorems 5.4 and 5.5. For the purpose of enumeration we clarify in Proposition 4.4 which 4-tuples of parameters determine the same skew-morphism.

A key role in our investigation is played by Huppert’s theorem [7, III.11.5] establishing the structure of the skew product group in case the order of the skew-morphism is a power of p, and also by a result of King [11] on presentations of metacyclic p-groups. In the proof that the parametrised family of skew-morphisms si,j,k,l equals Skew(pe), we use some essential information on automorphisms of split metacyclic p-groups obtained by Bidwell and Curran [2].

2 Preliminary results

Throughout the paper pe represents the cyclic group of order pe, where p is an odd prime. Let Sym(pe),Aut(pe) and Skew(pe) denote the set (group) of all permutations, automorphisms, and skew-morphisms of pe, respectively. In this paper we multiply permutations from the right to the left, that is, if f and g are in Sym(pe) and xpe, then (fg)(x)=f(g(x)). We set t to denote the translation of pe defined by t(x)=x+1.

Let sSkew(pn) be a skew-morphism with power function π. The skew product group of pe induced by s is the group t,s. Notice that the skew product group factorises as t,s=ts, and for every ipe,

(2.1)sti=ts(i)sπ(i).

Also, |t,s|=pe|s|, where |s| is the order of the permutation s. The following converse also holds (see [12, Proposition 2.2]): if fSym(pe), then

(2.2)f(0)=0 and |t,f|=pe|f|fSkew(pe).

The next result is in [12, Corollary 3.4], see [4, Theorem 6.1], as well.

Lemma 2.1.

Let sSkew(Zn). Then the order |s| of s divides nϕ(n). Moreover, if gcd(|s|,n)=1 or gcd(ϕ(n),n)=1, then s is an automorphism of Zn.

In the next lemma we collect a number of properties of skew-morphisms of pe proved in [12]. In fact, part (i) is [12, Lemma 4.4 (iii)], (ii) is [12, Lemma 4.4 (ii)], and (iii) is [12, Theorem 4.1].

Lemma 2.2.

Let sSkew(Zpe) be a skew-morphism of order pi with power function π.

  1. The power sp is also in Skew(pe).

  2. For all xpe, π(x)1(modp). In particular, if s has order p, then s is in Aut(pe).

  3. There exists an automorphism αAut(pe) of order pi such that the α-orbits coincide with the s-orbits.

It is well known that Aut(pe)(p-1)pe-1, and the automorphisms of order pi (1ie-1) are given as

(2.3)x(kpe-i+1)x,

where k{1,,pi-1} and pk (see, e.g., [10]). This implies that, for any k{0,,pn-1},

(2.4)gcd((p+1)k-1,pe)=pgcd(k,pe-1).

Lemma 2.3.

Let sSkew(Zpe) be a skew-morphism of order pi. Then

gcd(s(1)-1,pe)=pe-i.

Proof.

The statement is clear if i=0, let i1. According to Lemma 2.2 (iii), the orbit of 1 under s is equal to the orbit of 1 under α for some automorphism α of order pi. By (2.3), this orbit is Ω:={xpe-i+1:x{0,,pi-1}}. This in turn implies that s is regular on Ω, and thus s(1) is not in the orbit of 1 under sp. Since sp is a skew-morphism, see Lemma 2.2 (i), it follows that s(1){xpe-i+1+1:x{0,,pi+1-1}}. The lemma is proved. ∎

We end the section with a property of metacyclic p-groups.

Lemma 2.4.

Let G be a metacyclic p-group given by the presentation

G=x,yxpm=ypn=1,xy=x1+pm-n,

where m>n1. Then the order of the element xiyj is equal to max{|xi|,|yj|}, where |xi| and |yj| denote the order of xi and yj, respectively.

Proof.

We prove the lemma by induction on m. If m=2, then G is the unique non-abelian group of order p3 and of exponent p2. In this case the lemma follows by a straightforward computation.

Let m3 and N=xpm-1,ypn-1. We claim that Np2, N is normal in G. Indeed, setting z=ypn-1 and w=xpm-1, we have z-1xz=x1wk, for some k. It follows that x-1z-1x=wkz-1N, and so conjugation by both x and y fixes N=z,w. The factor group G/N admits the presentation

G/N=x¯,y¯x¯pm-1=y¯pn-1=1,x¯y¯=x¯1+pm-n,

where for gG, g¯ denotes the image of g under the natural homomorphism GG/N. The lemma holds trivially if either xi=1 or yj=1, hence we assume below that xi1 and yj1. Then we find, using the induction hypothesis, that the order of x¯iy¯j is equal to max{|x¯i|,|y¯j|}=1pmax{|xi|,|yj|}. Therefore, we are done if we show that x¯iy¯j has order 1p|xiyj|, where |xiyj| denotes the order of xiyj. Obviously, xiyj1. Let z be an element in xiyj of order p. If zN, then N,z is isomorphic to a group of order p3 and of exponent p. This implies that N,z is not metacyclic, contradicting the fact that every subgroup of G is metacyclic (cf. [7, III.11.1]). Therefore, zN, and thus x¯iy¯j has order 1p|xiyj|, as it is required. ∎

3 The skew-morphisms si,j

For the rest of the paper let aAut(pe) be the automorphism defined by

a(x)=(p+1)x.

By (2.3), a has order pe-1. Consider the permutation tajSym(pe) for some j{0,1,,pe-1-1}. Recall that t is the translation t(x)=x+1. By Lemma 2.4, taj has order pe, and thus it is a full cycle. Therefore, there exists a unique permutation bjSym(pe) such that bj(0)=0 and the conjugate

(3.1)tbj:=bjtbj-1=taj.

In fact, for xpe with x0, the permutation bj can be expressed as

(3.2)bj(x)=1+(p+1)j++(p+1)(x-1)j.

Define the permutations

(3.3)si,j=bj-1aibj,i,j{0,1,,pe-1-1}.

Proposition 3.1.

Every permutation si,j defined in (3.3) is a skew-morphism of Zpe.

Proof.

By definition, the order |si,j|=|ai|. Assume at first that pi, or equivalently, si,j has order pe-1. It is clear that si,j(0)=0. Thus by (2.2), it is enough to show that |t,si,j|=p2e-1. We have

|t,si,j|=|t,si,jbj|=|tbj,si,jbj|=|taj,ai|=p2e-1,

therefore si,j is a skew-morphism. The last equality comes from the following observation: assuming tajai1 we get that some power of a centralises t, a contradiction with the definition of a and t.

Now, suppose that i=pki,pi. As si,j is a skew-morphism of pe, and

si,j=si,jpk,

it follows from Lemma 2.2 (i) that si,j is a skew-morphism too. ∎

Remark 3.2.

The reader might observe that in case a skew-morphism of the cyclic group of order pe has order pe-1, then the skew product G has the following canonical presentation:

G=x,yxpe=ype-1=1,xy=x1+p.

In the above notation t=x and conjugation by y is the automorphism a. Besides the canonical factorisation G=xy, we have a factorisation G=xyjy, for any j. By Lemma 2.4, xyj has order pe, so y gives another skew-morphism of the cyclic group of order pe (generated by different element of order pe). Given two factorisations G=BY=CY, where Y=y, |B|=|C|=pe for any cC there is a unique bB such that c=byi. Thus there is a bijection σ:CB that provides a “change of coordinates”. Let ϕ and ψ be the two skew-morphisms determined by y with respect to the two factorisations CY and BY. Then ycY=ϕ(c)Y and ycY=yσ(c)Y=ψ(σ(c))Y. The last term is by the factorisation BY. To convert back to CY, we use σ-1, thus ϕ=σ-1ψσ. The skew-morphisms si,j all live in the split metacyclic p-group G and are obtained by left multiplication on xjy, to be precise, they are conjugate to yi by the permutation bj.

Notice that the skew-morphism si,j is not uniquely determined by the parameters i and j. For instance, s0,j is the identity mapping for every j. The rest of the section is devoted to the proof of following theorem.

Theorem 3.3.

Let e2, and i,i,j,j{0,1,,pe-1-1}. Then

si,j=si,ji=i and jj(modpe-2/gcd(i,pe-2)).

The theorem will be derived in a sequence of lemmas.

Lemma 3.4.

Let e2, and j,j{0,1,,pe-1-1} such that jj(modpu) for some u{0,1,,e-1}. Then for all x,xZpe with xx(modpe-1-u),

bj(x)-bj(x)=bj(x)-bj(x).

Proof.

We divide the proof into four steps.

Claim 1.

We have bj(pe-1-u)=bj(pe-1-u).

We start by the observation that if x,y,zpe, then

(3.4)(txay)z=txby(z)ayz.

It follows that

(taj)pe-1-u=tbj(pe-1-u)ajpe-1-u,(taj)pe-1-u=tbj(pe-1-u)ajpe-1-u.

Since ajpe-1-u=ajpe-1-u, Claim 1 is equivalent to

(taj)pe-1-u=(taj)pe-1-u.

Recall that an arbitrary p-group G is regular if for all x,yG,

(xy)p=xpypc1cr,

where all ci belong to the commutator x,y. In the case when p>2, a sufficient condition for G to be regular is that its commutator subgroup G is cyclic (see [7, III.10.2)]). In particular, it follows that t,a is a regular p-group. Thus by [7, III.10.6],

(taj)pe-1-u=(taj)pe-1-u

is equivalent to

((taj)-1taj)pe-1-u=1.

Putting j-j=j0pu, for some j0, we get

((taj)-1taj)pe-1-u=(aj0pu)pe-1-u=1.

Claim 2.

We have bj(xpe-1-u)=bj(xpe-1-u) for all x{0,1,,pu+1-1}.

Let x{0,1,,pu+1-1}. Recall that tbj=taj. By this and (3.4),

(txpe-1-u)bj=(taj)xpe-1-u=tbj(xpe-1-u)axpe-1-uj,
(txpe-1-u)bj=(taj)xpe-1-u=tbj(xpe-1-u)axpe-1-uj.

Thus Claim 2 is equivalent to (txpe-1-u)bj=(txpe-1-u)bj. Since this holds for x=1 by Claim 1, it also holds for all x>1.

Claim 3.

We have pe-1-ubj(xpe-1-u) for all x{0,1,,pu+1-1}.

The order of taj is pe. This implies that (taj)xpe-u-1=tbj(xpe-1)ajxpe-u-1 has order at most pu+1. As ajxpe-u-1 has order at most pu, it follows from Lemma 2.4 that tbj(xpe-u-1) has order at most pu+1. This yields Claim 3.

Claim 4.

We have bj(x)-bj(x)=bj(x)-bj(x) for all x,xZpn with xx(modpe-1-u).

Put x=x+x0pe-1-u and j=j+j0pu. By (3.2) and Claim 2,

bj(x)-bj(x)=bj(x)+(p+1)jxbj(x0pe-1-u)-bj(x)
=(p+1)jx(p+1)j0puxbj(x0pe-1-u)
=(p+1)jx(p+1)j0puxbj(x0pe-1-u).

By (2.3), (p+1)j0pux1(modpu+1). Thus we find, using also Claim 3, that

(p+1)j0puxbj(x0pe-1-u)=bj(x0pe-1-u).

Therefore,

bj(x)-bj(x)=(p+1)jxbj(x0pe-1-u)=bj(x)-bj(x).

This completes the proof. ∎

Lemma 3.5.

Let e2 and i{0,,pe-1-1}. Then for all xZpe,

si,j(x)x(modpgcd(i,pe-1)).

Proof.

By (3.3), the order of si,j is pe-1/gcd(i,pe-1). By Lemma 2.2 (iii), there exists an automorphism αAut(pe) of the same order such that the α-orbits coincide with the si,j-orbits. It follows that αagcd(i,pe-1). Let xpe. Then there exists some l{0,,pe-1-1} with gcd(i,pe-1)l such that

si,j(x)=al(x),

and hence

(3.5)si,j(x)(p+1)lx(modpe).

By (2.4), (p+1)l1(modpgcd(l,pe-1)). Since gcd(i,pe-1)gcd(l,pe-1), it follows that (p+1)l1(modpgcd(i,pe-1)). Substituting this in (3.5), the lemma follows. ∎

Lemma 3.6.

Let e2, and i,j,j{0,,pe-1-1}. Then

(3.6)si,j=si,jjj(modpe-2/gcd(i,pe-2)).

Proof.

The statement holds if i=0, and hence below we assume that i>0.

() Let si,j=si,j, and π be the power function of si,j. By (2.1),

si,jt=tsi,j(1)si,jπ(1)

holds in t,si,j. This implies in t,si,jbj=taj,ai,

t(p+1)iai+j=ai(taj)=(taj)si,j(1)(ai)π(1)=tbj(si,j(1))asi,j(1)j+π(1)i.

As bj(si,j(1))=(bjsi,j)(1)=(aibj)(1)=(p+1)i, we get

(3.7)ai+j=asi,j(1)j+π(1)i.

Since si,j=si,j, the same argument yields ai+j=asi,j(1)j+π(1)i. Thus

a(j-j)(si,j(1)-1)=1,

and hence

(3.8)jj(modpe-1/gcd(si,j(1)-1,pe-1)).

By (3.3), the order of si,j is pe-1/gcd(i,pe-1). This and Lemma 2.3 yield gcd(si,j(1)-1,pe)=pgcd(i,pe-1). Since i0, gcd(i,pe-1)=gcd(i,pe-2) and gcd(si,j(1)-1,pe)=gcd(si,j(1)-1,pe-1), and thus

gcd(si,j(1)-1,pe-1)=pgcd(i,pe-2).

This and (3.8) yield the right side of (3.6).

() Put pu=pe-2/gcd(i,pe-2). Then order of ai is pe-1/gcd(i,pe-2)=pu+1, and hence by (2.3),

(3.9)(p+1)i=zpe-u-1+1for some z{1,,pu+1-1},pz.

For two arbitrary mappings f,g:pepe, their sumf+g, differencef-g, and productfg are the mappings from pe to pe defined in the usual way, that is, for xpe,

(f+g)(x)=f(x)+g(x),(f-g)(x)=f(x)-g(x),(fg)(x)=f(g(x)).

Let j=j+j0pu, for some j0. For every xpe with x0,

((p+1)j0pux-1)((p+1)jx-(p+1)jx).

Therefore, pu+1((p+1)jx-(p+1)jx). This and (3.2) imply

(bj-bj)(x)0(modpu+1)for all xpe.

This and (3.9) yield ai(bj-bj)=bj-bj. Also, by Lemma 3.5,

si,j(x)x(modpe-u-1)for all xpe.

Therefore, by Lemma 3.4,

(bj-bj)(si,j(x))=(bj-bj)(x)for allxpe.

Consequently, (bj-bj)si,j=bj-bj=ai(bj-bj). Thus

aibj-aibj=bjsi,j-bjsi,j=bjsi,j-aibj;

and we get si,j=bj-1aibj=si,j. ∎

Theorem 3.3 follows from Lemma 3.6 and the following lemma.

Lemma 3.7.

If si,j=si,j, then i=i.

Proof.

Let si,j=si,j, and let π be the power function of si,j. We prove the lemma by induction on the order of si,j. The statement holds obviously if si,j is the identity permutation, that is, if i=0. Thus for the rest of the proof assume that i0. By (3.7),

a(si,j(1)-1)j=ai(1-π(1))anda(si,j(1)-1)j=ai(1-π(1)).

Then

sip,j=si,jp=si,jp=sip,j.

Thus by the induction hypothesis, ipip(modpe-1). As p(π(1)-1), see Lemma 2.2 (ii), we conclude i(1-π(1))=i(1-π(1))(modpe-1). Thus the above equalities reduce to jj(modpe-1/gcd(pe-1,si,j(1)-1)). Since it has already been shown that gcd(si,j(1)-1,pe-1)=pgcd(pe-2,i), it follows that jj(modpe-2/gcd(pe-2,i)). Thus by Lemma 3.6, si,j=si,j, and we get si,j=si,j=si,j. It is obvious that this implies that i=i. ∎

4 The skew-morphisms si,j,k,l

For the rest of the paper we set b to be an automorphism of pe of order p-1. Define the permutations

(4.1)si,j,k,l=bj-1aibkblbj,

where the integers i,j,k,l satisfy the following conditions:

  1. i,l{0,,pe-1-1}, k{0,,p-2}, j{0,,pe-2-c-1}, where pc=gcd(i,pe-2).

  2. If i=0 or k=0, then l=0.

  3. If i0 and k0, then pcj and pmax{c,e-2-c}l.

A 4-tuple (i,j,k,l) of integers satisfying conditions (C0), (C1) and (C2) will be called admissible.

Note that the permutations si,j,k,l include all skew-morphisms in the form si,j. Namely, given any skew-morphism si,j, in view of Theorem 3.3 we may assume that j<pe-2-c for c=gcd(i,pe-2-), and thus by (3.3) and (4.1), si,j=si,j,0,0.

Before we prove that all permutations si,j,k,l are skew-morphisms, we give two lemmas.

Lemma 4.1.

Let G be a split metacyclic p-group given by the presentation

G=x,yxpm=ypn=1,xy=x1+pm-n,

where m>n1. Then the automorphisms in Aut(G) are the mappings θu,v,w, where u,v{0,,pm-1} with pu, pm-nv, and w{0,,pn-1} with p2n-mw whenever 2n>m, defined as

θu,v,w(xiyj)=xui+vjywi+jfor all xiyjG.

In particular, |Aut(G)|=(p-1)pm-1+n+min{n,m-n}.

Proof.

This is a corollary of the more general result [2, Theorem 3.1]. ∎

Lemma 4.2.

With the notation of Lemma 4.1, let u{0,,pm-1}, pu such that u1, and as a unit of the ring Zpm, u has order d with pd. Then the automorphism θu,0,w has order d.

Proof.

A straightforward computation gives

(θu,0,w)k(xiyj)=xukiywi(1+u++uk-1)+j.

Therefore, the order |θu,0,w|d. Also, pm(ud-1). On the other hand, since the order of the unit u1 is not divisible by p, it follows that p(u-1) as well. We conclude from these that pm(1+u++ud-1). Using also that n<m, we find (θu,0,w)d(xiyj)=xiyj, and thus |θu,0,w|=d. ∎

Theorem 4.3.

Every permutation si,j,k,l defined in (4.1) is a skew-morphism of Zpe.

Proof.

Let si,j,k,l be a permutation defined in (4.1). If k=0, then si,j,k,l=si,j and the statement holds. For the rest of the proof it is assumed that k0.

Let i=0. Then j=0 by (C0) and l=0 by (C1). We get si,j,k,l=bk, which is an automorphism in Skew(pe). Now, suppose that i0. Since k0, we have tbk=tu for some u{2,,pe-1}, pu, and as unit of pe, u has order d with pd. Let pc=gcd(i,pe-2). Let G=taj,ai,bkbl and P=taj,ai. It follows from (C2) that P=t,ai and there exists a1ai such that P admits the presentation

P=t,a1tpe=(a1)pe-1-c=1,ta1=t1+pc+1.

Clearly, a1=ai for a some i satisfying gcd(i,pe-2)=pc. This and (C2) yield pe-2/gcd(i,pe-2)l, and so si,l=si,0=ai follows from Theorem 3.3. In other words, bl commutes with a1=ai. Now, we can write

(4.2)tbkbl=tualand(a1)bkbl=a1.

The group a1 is equal to apc. On the other hand, by (C2), pcl, and so al=a1w for some w{0,,pe-1-c-1}. This and (4.2) yield that P is normal in G. We claim that bkbl acts on P by conjugation as the automorphism θu,0,w described in Lemma 4.1. In fact, we have to show that pe-2-2c divides w whenever 2(e-1-c)>e. In order to see that this indeed holds, observe that al=a1w=aiw, gcd(i,pe-2)=pc, and finally pe-2-cl, by (C2).

Since bkbl fixes 0 and P is transitive on pe, Zbkbl(P)=1. Equivalently, bkbl acts faithfully on P, in particular, |bkbl|=|θu,0,l|. Now, by Lemma 4.2, |bkbl|=d. Thus |G|=|P|d. This implies that the stabiliser G0 of 0 in G has order |G0|=pe-1-cd. Also, as ai commutes with bkbl, we find

|aibkbl|=pe-1-cd=|G0|,

implying that G0=aibkbl, and G factorises as G=tajaibkbl. Therefore, the conjugate group G(bj)-1 factorises as G(bj)-1=tsi,j,k,l, and hence si,j,k,l is a skew-morphism by (2.2). ∎

Proposition 4.4.

Every permutation si,j,k,l in (4.1) is uniquely determined by the admissible 4-tuple (i,j,k,l). In particular, there is a bijection between the set of admissible 4-tuples of integers and the set of skew-morphisms si,j,k,l.

Proof.

Suppose that si,j,k,l and si,j,k,l are two skew-morphisms defined in (4.1) for which si,j,k,l=si,j,k,l. We are going to prove that

(i,j,k,l)=(i,j,k,l).

It follows that these skew-morphisms have order

pe-1(p-1)gcd(i,pe-1)gcd(k,p-1)=pe-1(p-1)gcd(i,pe-1)gcd(k,p-1).

In particular, gcd(i,pe-1)=gcd(i,pe-1).

Let i=0 or i=0. Then we get i=i=0, hence j=j=0, and l=l=0, by condition (C1). Thus bk=s0,0,k,0=s0,0,k,0=bk, implying that k=k, and so

(i,j,k,l)=(i,j,k,l).

Now, suppose that none of i and i is equal to 0. Let gcd(i,pe-2)=pc (so gcd(i,pe-2)=pc as well). By (3.3) and (4.1),

si,jbj-1bkblbj=si,jbj-1bkblbj.

Both si,j and si,j have order pe-1-c1, and both bj-1bkblbj and bj-1bkblbj have the same order not divisible by p. We have proved above that

[si,j,bj-1bkblbj]=[si,j,bj-1bkblbj]=1

also hold, and we deduce from these that si,j=si,j and

bj-1bkblbj=bj-1bkblbj.

Since both j and j are in {0,,pe-2-c-1}, it follows by Theorem 3.3 that i=i and j=j. This implies that bkbl=bkbl. From this by (3.2), we obtain bk(1)=(bkbl)(1)=(bkbl)(1)=bk(1). This in turn implies that k=k and bl=bl. Then, by (3.2) again, (p+1)l=bl(2)-1=bl(2)-1=(p+1)l, from which l=l. This completes the proof of the proposition. ∎

5 Skew-morphisms of pe

In this section we prove that skew-morphisms si,j,k,l comprise all skew-morphisms of pe. Our argument is divided in two cases depending on whether the order of the skew-morphism is a p-power or not.

5.1 Skew-morphisms of p-power order

Let G be a skew product group of pe induced by a skew-morphism s of some p-power order. Then G factorises as ts, hence by a result of Huppert [6] (cf. also [7, III.11.5]) G is metacyclic. Note that this implies that the commutator subgroup G is cyclic, and therefore, Gs=1. Indeed, as G is characteristic in G, any of its subgroups is normal in G, on the other hand, no non-trivial normal subgroup of G is contained in s. Also, since t<G acts regularly on pe, it follows that the center Z(G)t, in particular, Z(G) is a cyclic group. These observations will be used below.

Lemma 5.1.

Let G=Zpes be a skew product group of Zpe of order pe+i, where 1ie-1. If G is a split metacyclic group, then its commutator subgroup G has order pi, and the exponent exp(G/G)=pmax{i,e-i}.

Proof.

Since G is a split metacyclic and non-abelian group, it has a presentation in the form

G=x,yxpk=1,ypl=1,xy=x1+pk-m,

where 1mmin{l,k-1}. The order |G|=pk+l, and hence k+l=e+i. The elements in G of order p generate the subgroup xpk-1,ypl-1p2. On the other hand, G=ts, where sSkew(pe). We have observed above that the center Z(G) is a cyclic group. Therefore, Z(G)y=1, from which l=m<k. We conclude that exp(G)=pk, and thus k=e, i=l=m, G=xpe-i, and finally, exp(G/G)=pmax{i,e-i}. ∎

Let us consider the skew product groups of pe induced by the skew-morphisms si,j. Theorem 3.3 implies that these groups can be listed as the groups G(i,j), where G(0,0):=t; and for e2,

(5.1)G(i,j):=t,spe-1-i,j,i{1,,e-1},j{0,,pi-1-1}.

Notice that |G(i,j)|=pe+i.

Lemma 5.2.

Let e2 and let G(i,j) be a group defined in (5.1). Then G(i,j) is a split metacyclic group if and only if pe-1-ij.

Proof.

We have G(i,j)bj=taj,ape-1-i, see the proof of Proposition 3.1. Let G=taj,ape-1-i. This shows that, if pe-1-ij, then G is a split metacyclic group. It remains to prove that, if G is a split metacyclic group, then pe-1-ij. In fact, we prove that pe-1-ij forces that G is a non-split metacyclic group.

Let pm=gcd(j,pe-1), and assume that e-1-i>m. By (5.1),

(5.2)0mi-2.

The commutator [x,y] of two elements x,yG is given by

[x,y]:=xyx-1y-1.

Then [ape-1-i,taj]=t(p+1)pe-1-i-1. Let N=t(p+1)pe-1-i-1. Clearly, we have NG. Notice that N is normal in G, and G/N is abelian. This implies that NG, and therefore, G=N. By (2.4), |G|=pi. On the other hand, |ttaj|=pm+1. Thus |Gtaj|=pmin{i,m+1}, from which we obtain |Gtaj|=pm+1 by (5.2). Also, Gt, hence Ga=1 (this follows also from the observation preceding Lemma 5.1), and so

exp(G/G)=pmax{e-1-m,i}=pe-m-1

because we assumed e-1-i>m. Finally, as e-m-1 is larger than both i and e-i, exp(G/G)>pmax{i,e-i}. Now, Lemma 5.1 gives that G is a non-split metacyclic group. ∎

Lemma 5.3.

Let e2 and 1ie-1. The number of non-isomorphic non-split skew product groups of Zpe of order pe+i is at most min{i-1,e-1-i}.

Proof.

By [11, Theorem 3.2], every metacyclic non-split p-group G has up to isomorphism a presentation in the form:

(5.3)G=x,yxpm=1,ypn=xpm-u,xy=x1+pm-c,

where

(5.4)max{1,m-n+1}u<min{c,m-c+1}.

Now, suppose that G is a non-split skew product group of pe of order pe+i induced by some sSkew(pe). Consider the presentation of G described in (5.3). Since G is non-split, m<e. The exponent exp(G)=pe. On the other hand, (5.3) shows that exp(G)=pmax{m,n+u}, and it follows that e=n+u. Thus the order |y|=pn+u=pe, and we obtain |Z(G)y|=pe-c.

We compute next |Z(G)y| in another way. Since y has order pe, it acts on pe as a full cycle. In particular, G=y,s. Suppose that s centralises y1y. Then s(y1(0))=y1(s(0))=y1(0), and so y1(0) is fixed by s. Conversely, suppose that s(t)=t for some tpe. Then t=y2(0) for a unique y2y, and we find [s,y2-1] fixes 0. As G is normal and cyclic, it is semi-regular on pe. We conclude that [s,y2-1]=1, and y2 is centralised by s. By these we have shown

|Z(G)y|=|{tpe:s(t)=t}|.

Lemma 2.2 (iii) implies

|{tpe:s(t)=t}|=pe-i,

and so |Z(G)y|=pe-i also holds; and therefore, c=i. From (5.3), we have |G|=pm+n. As |G|=pe+i and |y|=pn+u=pe, we get n=e-u and m=i+u. In view of (5.4), the number of possible groups in (5.3) is bounded above by the number of solutions of the inequalities

max{1,i-e+2u+1}u<min{i,u+1}

with variable u. This number is min{i-1,e-1-i}, and the lemma follows. ∎

We are ready to prove the main result of the subsection.

Theorem 5.4.

The skew-morphisms of Zpe of p-power order are exactly the skew-morphisms si,j defined in (3.3).

Proof.

Let s be a skew-morphism of order pi, and let G=t,s. We show below that G is isomorphic to one of the groups G(i,j) defined in (5.1).

Suppose that G is a split metacyclic group. We have proved in Lemma 5.1 that exp(G)=pe, and this implies that GG(i,0).

Suppose that G is non-split. Then by Lemma 5.3, 2ie-2-i. Furthermore, by Lemma 5.2, each of the groups G(i,pj), j{0,,min{i-2,e-2-i}} is a non-split metacyclic group. Also, we have computed in the proof of Lemma 5.2 that exp(G(i,pj)/G(i,pj))=pe-1-j, and therefore, the above groups are pairwise non-isomorphic. This and Lemma 5.3 yield that G is isomorphic to one of the above groups G(i,pj).

Now, we may assume without loss of generality that G is a subgroup of t,a. Then the skew-morphism s and its power function π can be described as follows: there exists a factorisation G=xy such that |x|=pe, |y|=pi (thus xy=1), Z(G)y=1, and for every kpe,

(5.5)yxk=xs(k)yπ(k).

Now, x=tuav and y=twaz for some u,v,w,z{0,,pe-1-1}. Since |x|=pe, it follows that pu, see Lemma 2.4. Suppose that y is fixed-point free. This gives ((p+1)z-1)X=-w has no solution for Xpe, or equivalently, gcd(w,pe)<gcd((p+1)z-1,pe). This in turn implies that |tw|>|az|, and tpe-1twaz=y. As tpe-1Z(t,a), Z(G)y1, a contradiction. Therefore, y has a fixed point. It follows from this that y can be mapped into a under conjugation by some element x1x. Thus yx1=am for some m{0,,pe-1-1}, and after conjugation by x1, equation (5.5) becomes

amxk=xs(k)(am)π(k),

and hence

am(tuav)k=(tuav)s(k)(am)π(k).

This and (3.4) yield tuam(bv(k)))=tubv(s(k)). Since pu, this implies

(ambv)(k)=(bvs)(k)

for all kpe, and so ambv=bvs, from which s=bv-1ambv=sm,v. This completes the proof of the theorem. ∎

5.2 Skew-morphisms whose order is not a p-power

We complete the classification of all skew-morphisms of pe by proving the following theorem.

Theorem 5.5.

The skew-morphisms of Zpe whose order is not a p-power are exactly the skew-morphisms si,j,k,l, k0, defined in (4.1).

Proof.

Let s be a skew-morphism of order pcd, pd and d>1. Notice that c{0,,e-1} and d(p-1) because of Lemma 2.1.

Let c=0. Then by Lemma 2.1, s is in Aut(pe) and it has order d. Thus s=bk for some k{2,,p-2}, and so s=s0,0,k,0.

For the rest of the proof it will be assumed that c0. Write s=s1s2, where s1 has order pc and s2 has order d. Let G=t,s and let P be a Sylow p-subgroup of G containing t. The group P factorises as P=ts1. Now, (2.2) yields that s1 is a skew-morphism of pe of order pc. By Theorem 5.4, s1=si,j for some i{0,,pe-1} and j{0,,pc-1-1}. In particular, P=G(c,j). Since |G:P|=d and d(p-1), by the Sylow Theorems, P is normal in G. The permutation s2 fixes 0 and P is transitive on pe. These yield that Zs2(P)=1, and thus s2 acts by conjugation on P as an automorphism of order d. We conclude, using the known fact (cf. [2]) that the automorphism group of a non-split metacyclic group is also a p-group, that P=G(c,j) is a split metacyclic group. By Lemma 5.2, this is equivalent to the condition

(5.6)gcd(i,pe-2)=pe-1-cj.

Let us consider the conjugate group Gbj. Then Gbj=taj,ai,s3, where s3=s2bj, Pbj=taj,ai is normal in Gbj, and s3 acts on Pbj as an automorphism of order d. There exists a1ai such that Pbj admits the presentation

Pbj=t,a1tpe=(a1)pc=1,ta1=t1+pe-c.

Clearly, a1=ai for a some i satisfying

gcd(i,pe-1)=gcd(i,pe-1)=pe-1-c.

According to Lemma 4.1 the element s3 acts on Pbj by conjugation as an automorphism θu,v,w, where u is a unit of pe, v{0,,pe-1}, and w{0,,pc-1} such that p2c-ew if 2c>e. As s3 commutes with a1, we find

a1=a1s3=θu,v,w(a1)=tva1,

hence v=0. Also,

ts3=θu,0,w(t)=tua1w=tuaiw.

This implies that s3=bkbiw, where k{0,,p-2} and k0. Then

sbj=(s1s2)bj=(si,js2)bj=ais3=aibkbiw,

and thus s=bj-1aibkbiwbj=si,j,k,l, where l=iw.

To finish the proof of the theorem it remains to verify that the 4-tuple (i,j,k,l) is admissible. We have i,l{0,,pe-1} with i0, j{0,,pc-1-1}, and k{0,,p-2} with k0. Now, j belongs to the required interval because gcd(i,pe-2)=pe-c-1, and we obtain that (C0) holds.

Since both i0 and k0, we need to check whether (C2) holds. The first part follows from (5.6). The second part is equivalent to pmax{e-1-c,c-1}l. Since l=iw and gcd(i,pe-1)=gcd(i,pe-1)=pe-1-c, the divisibility pe-1-cl follows. We are done if e-1-cc-1, thus suppose that e-1-c<c-1. In this case 2c>e, hence p2c-ew, and we get pc-1iw=l, as claimed. This completes the proof of the theorem. ∎

5.3 Enumeration

Finally, we are ready to count the number of skew-morphisms. In view of Proposition 4.4 and Theorems 5.4 and 5.5, this is equivalent to counting the number of admissible 4-tuples (i,j,k,l). Theorem 1.2 follows from the following theorem.

Theorem 5.6.

If e2 and p is an odd prime, then the number of admissible 4-tuples (i,j,k,l) is equal to (p-1)(p2e-1-p2e-2+2)/(p+1).

Proof.

Let 𝒩1 denote the number admissible 4-tuples (i,j,k,l) with k=0, and let 𝒩2 denote the number of those with k0. By (C1), 𝒩1 is equal to the number of admissible 4-tuples (i,j,0,0). Therefore,

𝒩1=1+c=0e-2i{1,,pe-1-1}gcd(i,pe-2)=pcpe-2-c
=1+c=0e-2(pe-1-c-pe-2-c)pe-2-c
=p(p2e-3+1)p+1.

Furthermore, using (C0) and (C2), we find

𝒩2p-2=1+c=0e-2i{1,,pe-1-1}gcd(i,pe-2)=pcpmax{0,e-2-2c}+e-1-max{c,e-2-c}
=1+c=0e-2(pe-1-c-pe-2-c)pe-1-c
=p2e-1+1p+1.

Therefore, (p+1)(𝒩1+𝒩2)=p(p2e-3+1)+(p-2)(p2e-1+1), and hence 𝒩1+𝒩2=(p-1)(p2e-1-p2e-2+2)/(p+1). ∎


Communicated by Andrea Lucchini


Funding statement: The first author was supported in part by the Slovenian Research Agency (research program P1-0285, and research projects N1-0032, N1-0038, J1-5433 and J1-6720). The second author was supported by the grant APVV-15-0220, by the project LO1506 of the Czech Ministry of Education, Youth and Sports, and Project P202/12/G061 of Czech Science Foundation.

Acknowledgements

We would like to thank the referee for the valuable comments.

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Received: 2015-11-11
Revised: 2017-3-22
Published Online: 2017-5-19
Published in Print: 2017-11-1

© 2017 Walter de Gruyter GmbH, Berlin/Boston

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