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Asymptotic expansion of holonomy

  • Erlend Grong EMAIL logo and Pierre Pansu
Published/Copyright: June 30, 2018

Abstract

Given a principal bundle with a connection, we look for an asymptotic expansion of the holonomy of a loop in terms of its length. This length is defined relative to some Riemannian or sub-Riemannian structure. We are able to give an asymptotic formula that is independent of choice of gauge. We also show how our results from sub-Riemannian geometry can give improved approximations for the case of studying expansions of holonomy of principal bundles over the Euclidean space.

MSC 2010: 53C29; 41A99; 53C17

Communicated by Anna Wienhard


Funding source: Norges Forskningsråd

Award Identifier / Grant number: 249980/F20

Award Identifier / Grant number: project SRGI

Award Identifier / Grant number: ANR-15-CE40-0018

Award Identifier / Grant number: AFR 4736116

Award Identifier / Grant number: OPEN Project GEOMREV

Funding statement: The first author is supported by the Fonds National de la Recherche Luxembourg (AFR 4736116 and OPEN Project GEOMREV) and by the Research Council of Norway (project number 249980/F20). The second author acknowledges support from ANR, project SRGI, ANR-15-CE40-0018.

A Approximation of ODEs in Lie groups

Let G be a connected Lie group with Lie algebra 𝔤. For any continuous curve [0,t1]𝔤, tA(t), consider the initial value problem on G:

a˙(t)=A(t)a(t),a(0)=1.

Assume that for any t[0,t1] the curve Q(t)=exp-1a(t) in 𝔤 is well defined. Note that if exp:𝔤G is the group exponential, then

dexp:TA𝔤TexpAG,Bexp(A)f(adA)B,f(z)=1-e-zz.

Hence,

f(adQ(t))Q˙(t)=A(t),Q(0)=0,

and

(A.1)Q˙(t)=g(adQ(t))A(t),g(z)=z1-e-z.

Consider 𝔤 as a subalgebra of 𝔤𝔩(q,) for some q>0 and let be a Banach algebra norm on 𝔤𝔩(q,). Write

AL[0,t]=sups[0,t]A(s).

Lemma A.1.

Define constants B1 and B2 such that on the disk {zC:|z|π},

|g(z)|B1,|g(z)|B2.

Define

ad=sup{ad(A1)A2:A1=A2=1}.

Then there exists ε>0, depending on B1, B2 and ad, such that for any A:[0,T]g with

tAL[0,t]<ε

we have

Q(t)-0tA(s)𝑑sadt2B221-adB2εAL[0,t]2.

Proof.

We want to estimate Q(t) using the Picard iteration. For any t>0, write Mt=sups[0,t]A(s). If q:[0,T]𝔤 is an arbitrary continuous curve, then

𝒜(q)(t)=0tg(adq(s))A(s)𝑑s.

Note that

𝒜(q)L[0,t]tMtB1whenever qL[0,t]πad,

and for any pair of curves q1 and q2 we have

𝒜(q1-q2)L[0,t]tMtB2adq1-q2L[0,t].

Define B=max{B1ad/π,B2ad} and assume that tMt<1B. Then it follows that Q(t)=limn𝒜n(0) is the solution of (A.1) and

Q(t)-𝒜(0)(t)Q-𝒜(0)L[0,t]tMtB2adQ(t)L[0,t]t2Mt2B221-tMtB2.

The result follows from choosing ε1B. ∎

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Received: 2017-02-09
Revised: 2018-02-26
Published Online: 2018-06-30
Published in Print: 2018-11-01

© 2018 Walter de Gruyter GmbH, Berlin/Boston

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