Startseite Sharp Singular Trudinger–Moser Inequalities Under Different Norms
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Sharp Singular Trudinger–Moser Inequalities Under Different Norms

  • Nguyen Lam , Guozhen Lu und Lu Zhang EMAIL logo
Veröffentlicht/Copyright: 12. April 2019

Abstract

The main purpose of this paper is to prove several sharp singular Trudinger–Moser-type inequalities on domains in N with infinite volume on the Sobolev-type spaces DN,q(N), q1, the completion of C0(N) under the norm uN+uq. The case q=N (i.e., DN,q(N)=W1,N(N)) has been well studied to date. Our goal is to investigate which type of Trudinger–Moser inequality holds under different norms when q changes. We will study these inequalities under two types of constraint: semi-norm type uN1 and full-norm type uNa+uqb1, a>0, b>0. We will show that the Trudinger–Moser-type inequalities hold if and only if bN. Moreover, the relationship between these inequalities under these two types of constraints will also be investigated. Furthermore, we will also provide versions of exponential type inequalities with exact growth when b>N.

MSC 2010: 26D10; 42B35; 46E35

1 Introduction

The Trudinger–Moser and Adams inequalities are the replacements for the Sobolev embeddings in the limiting case. When ΩN is a bounded domain and kp<N, it is well known that W0(Ω)k,pLq(Ω) for all q with 1qNpN-kp. However, we have W0k,Nk(Ω)L(Ω). For example, one could check that for any N>1, the unbounded function loglog(1+1|x|) is in W1,N(B1(0)). Nevertheless, in this situation, Trudinger [58] proved that W01,N(Ω)LφN(Ω), where LφN(Ω) is the Orlicz space associated with the Young function

φ N ( t ) = exp ( α | t | N N - 1 ) - 1

for some α>0 (see also Yudovich [18] and Pohozaev [54]):

Theorem A (Trudinger 1967).

Let Ω be a domain with finite measure in Euclidean N-space RN, N2. Then there exists a constant α>0 such that

1 | Ω | Ω exp ( α | u | N N - 1 ) 𝑑 x c 0

for any uW01,N(Ω) with uN1.

These results were refined in the 1971 paper [51] by J. Moser. In fact, Moser showed that the best possible constant α in the above theorem is

α N = N ω N - 1 1 N - 1 ,

where ωN-1 is the area of the surface of the unit N-ball, in the sense that if α>αN, then the above inequality can no longer hold with some c0 independent of u. This inequality is by now known as the Trudinger–Moser inequality. This type of result has been studied and extended in many directions.

It can be noted that the Trudinger–Moser–Adams inequalities are senseless when the domains have infinite volume. Thus, it is interesting to investigate versions of the Trudinger–Moser–Adams inequalities in this setting. We will state here two such results:

Theorem B.

Denote

A ( α ) := sup u N 1 1 u N N N ϕ N ( α | u | N N - 1 ) 𝑑 x ,
B ( α ) := sup u N N + u N N 1 N ϕ N ( α N | u | N N - 1 ) 𝑑 x ,

where

ϕ N ( t ) = e t - j = 0 N - 2 t j j ! .

Then

(1.1) A ( α ) is finite for any  α < α N ,
(1.2) B ( α ) is finite for any  α α N .

Moreover, the constant αN is sharp in the sense that limααNA(α)=, and if α>αN, then B(α) is infinite.

We have the following remarks: There are attempts to extend the Trudinger–Moser inequality to the singular case by Adimurthi and Sandeep in [2], to infinite volume domains by Cao [6], Ogawa [52, 53] in dimension two and by do Ó [3], Adachi and Tanaka [1], and Kozono, Sato and Wadade [19] in higher dimension. Interestingly enough, the Trudinger–Moser-type inequality can only be established for the subcritical case when only the seminorm uN is used in the restriction of the function class. Indeed, (1.1) has been proved in [3] and [1] if α<αN. Moreover, their results are actually sharp in the sense that the supremum is infinity when ααN. To achieve the critical case α=αN, Ruf [55] and then Li and Ruf [37] need to use the full form in W1,N, namely, (uNN+uNN)1N. Again αN is sharp. In all the above works, the symmetrization argument is very crucial. An alternative proof of (1.2) without using symmetrization has been given by the first two authors in [24, Section 6]. Different proofs of (1.1) and (1.2) have also been given without using symmetrization in settings such as on the Heisenberg group or high and fractional order Sobolev spaces where symmetrization is not available (see the work by the first two authors [23], and by Tang and the first two authors, [27] which extend the earlier work by Cohn and Lu [9] on finite domains). The arguments developed in these works [23, 24, 27] are from local inequalities to global ones using the level sets of functions under consideration. This argument has also be used in other contexts (see [8, 12, 28, 31, 32, 33, 40, 41, 42, 43, 46, 45, 59, 60]). In the recent paper [30], it was proved that these two versions of the above sharp subcritical and critical Trudinger–Moser-type inequalities are indeed equivalent. Indeed, an identity of these suprema was also given. Moreover, it was also showed in [30] that for a,b>0,

sup u N a + u N b 1 N ϕ N ( α N | u | N N - 1 ) 𝑑 x < b N .

We also refer the reader to [57] for a generalization of the equivalence result in [30] to the equivalence of critical and subcritical suprema of the Trudinger–Moser inequalities in Lorentz–Sobolev norms.

We also mention that extremal functions for Trudinger–Moser inequalities on bounded domains were first established by Carleson and Chang in their celebrated work [7], and has been extended in a number of settings by de Figueiredo, do Ó, and Ruf [10], Flucher [14], Lin [39], and on Riemannian manifolds by Y. X. Li [34, 35], and on infinite volume domains by Ruf [55], Li and Ruf [37], Li and Ndiaye [36], Lu and Yang [47], Zhu [61], Ishiwata [16] and Ishiwata, Nakamura and Wadade [17], Dong and Lu [13], Lam [22, 20, 21], Lam, Lu and Zhang [29], Dong, Lam and Lu [12], Lu and Zhu [48]. In particular, using the identity which exhibits the relationship between the suprema of the critical and subcritical Trudinger–Moser inequalities developed in [30], the authors established in [29] the existence and nonexistence of extremal functions for a large class of Trudinger–Moser inequalities on the entire spaces without using the blow-up analysis of the associated Euler–Lagrange equations. The symmetry of extremal functions have also been established for the first time in the literature. Moreover, they evaluate precisely the values of the suprema for the first time for a class of Trudinger–Moser inequalities for certain small parameters. (The main results of [29] were already described in [13] as Theorems C, D and E.) The method developed in [29] has been successfully used in [22, 20, 21].

The main purpose of this paper is to study several sharp versions of the Trudinger–Moser inequalities on the Sobolev-type spaces DN,q(N),q1, the completion of C0(N) under the norm uN+uq. Our results have a close connection to the study of the well-known Caffarelli–Kohn–Nirenberg inequalities first proved in [5]. See [12] and also [11, 26] for related results. We note that when q=N, then DN,q(N)=W1,N(N).

In this paper, we will always assume that

(C) N 2 , 0 β < N , 0 α < α N , q 1 .

In the study of the Trudinger–Moser-type inequalities, we need to choose a function ΦN,q,β that behaves like an exponential function at infinity, and has reasonable power near 0 by the Sobolev embeddings. Recall that by the Caffarelli–Kohn–Nirenberg inequalities, we have DN,q(N)Lp(N;dx|x|β) continuously with p>q(1-βN) (pq if β=0) (see Section 2). Hence it is natural to consider the following function:

(F) Φ N , q , β ( t ) = { j , j > q ( N - 1 ) N ( 1 - β N ) t j j ! if  β > 0 , j , j q ( N - 1 ) N t j j ! if  β = 0 .

We are now ready to state our main results. We will adapt the notations of constants TMCa,b(q,N,β) to denote the suprema of the critical Trudinger–Moser inequalities and TMSC(q,N,α,β) to denote the suprema of the subcritical Trudinger–Moser inequalities with the corresponding parameters.

As our first aim in this paper, we will prove that

Theorem 1.1.

Let p>q(1-βN) (pq if β=0). Then there exists a positive constant CN,p,q,α,β>0 such that for all uDN,q(RN), uN1,

N exp ( α ( 1 - β N ) | u | N N - 1 ) | u | p | x | β 𝑑 x C N , p , q , α , β u q q ( 1 - β N ) .

Moreover, this constant αN is the best possible in the sense that if ααN, then the constant CN,p,q,α,β cannot be uniform in functions u.

As a consequence of Theorem 1.1 in the special case p=q=N and the fact that there exists Cα,N>0 such that for all u,

exp ( α ( 1 - β N ) | u | N N - 1 ) | u | N C α , N ϕ N ( α ( 1 - β N ) | u | N N - 1 ) ,

we have the singular Trudinger–Moser-type inequality in the spirit of Adachi and Tanaka [1]:

Corollary 1.1.

There exists a constant CN,α,β>0 such that for all uW1,N(RN), uN1,

N ϕ N ( α ( 1 - β N ) | u | N N - 1 ) d x | x | β C N , α , β u N N - β .

The constant αN is sharp.

Another consequence of our Theorem 1.1 is the following inequality:

Corollary 1.2.

Let p>q(1-βN) (pq if β=0). Then we have the constant

TMSC ( q , N , α , β ) = sup u N 1 1 u q q ( 1 - β N ) N Φ N , q , β ( α ( 1 - β N ) | u | N N - 1 ) | x | β 𝑑 x < .

The constant αN is sharp.

We note here that when ααN-, TMSC(q,N,α,β). Hence Corollary 1.2 is subcritical in this sense. Thus we may ask what the magnitude of TMSC(q,N,α,β) is when ααN-, and what the critical version of Corollary 1.2 is. Our next goal is to provide the answers for these questions. Indeed, we will show that:

Theorem 1.2.

Let a>0 and b>0. Then

TMC a , b ( q , N , β ) = sup u N a + u q b 1 N Φ N , q , β ( α N ( 1 - β N ) | u | N N - 1 ) | x | β 𝑑 x < b N .

The constant αN is sharp in the sense that if α>αN, then the above supremum will be infinite. Also, there exist constants c(N,β,q) and C(N,β,q)>0 such that when ααN,

c ( N , β , q ) ( 1 - ( α α N ) N - 1 ) q ( 1 - β N ) N TMSC ( q , N , α , β ) C ( N , β , q ) ( 1 - ( α α N ) N - 1 ) q ( 1 - β N ) N .

Moreover, we have the following identity:

TMC a , b ( q , N , β ) = sup α ( 0 , α N ) ( 1 - ( α α N ) N - 1 N a ( α α N ) b N - 1 N ) q b ( 1 - β N ) TMSC ( q , N , α , β ) .

Having studied the Trudinger–Moser inequalities under the norm constraint uNa+uqb1 (for bN), it is natural to ask what kind of inequalities will hold in the case b>N. In particular, if we like to have the norm constraint uNa+uqb1 (for b>N), then can we still have a valid Trudinger–Moser-type inequality? Indeed, we will answer the above question by the following versions of the Trudinger–Moser inequality on DN,q(N) which are new even when q=N. We remark that the following results (Theorem 1.3, Theorem 1.4, Corollary 1.3, Corollary 1.4, Theorem 1.5) are Trudinger–Moser inequalities of exact growth. These type of inequalities were studied earlier by Ibrahim, Masmoudi and Nakanishi [15], Lam and Lu [25], Masmoudi and Sani [49, 50], Lu and Tang [41], Lu, Tang and Zhu [44]. Our results below are improved versions of the aforementioned ones.

Theorem 1.3.

Let a>0,k>1 and pq1. Then there exists a constant C=C(N,p,q,β,a,k)>0 such that for all uDN,q(RN), uNa+uqkN1, there holds

N Φ N , q , β ( α N ( 1 - β N ) u N N - 1 ) ( 1 + | u | p N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | x | β 𝑑 x C .

Moreover, the inequality does not hold when p<q.

An equivalent version of Theorem 1.3 is the following:

Theorem 1.4.

Let a>0,k>1 and pq1. Then there exists a constant C=C(N,p,q,β,a,k)>0 such that for all uDN,q(RN), uNa+uqN1, there holds

N Φ N , q , β ( α N ( 1 - β N ) u N N - 1 ) ( 1 + | u | p N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | x | β 𝑑 x C u q q ( 1 - 1 k ) ( 1 - β N ) .

Moreover, the inequality does not hold when p<q.

As consequences of our results, we have:

Corollary 1.3.

Let k1. There holds

sup u N k N + u N k N 1 N ϕ N ( α N ( 1 - β N ) u N N - 1 ) ( 1 + | u | N N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | x | β < ,
sup u N N + u N N 1 1 u N N ( 1 - 1 k ) ( 1 - β N ) N ϕ N ( α N ( 1 - β N ) u N N - 1 ) ( 1 + | u | N N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | x | β < .

Since it can be verified easily that the constant C(N,p,q,β,a,k) in Theorem 1.4 tends to a constant C(N,p,q,β,a) as k, by Fatou’s lemma, we get:

Corollary 1.4.

Let a>0 and pq1. Then there exists a constant C=C(N,p,q,β,a)>0 such that for all uDN,q(RN), uNa+uqN1, there holds

N Φ N , q , β ( α N ( 1 - β N ) u N N - 1 ) ( 1 + | u | p N - 1 ( 1 - β N ) ) | x | β 𝑑 x C u q q ( 1 - β N ) .

Moreover, the inequality does not hold when p<q.

Our last aim of this paper is to extend further the above proposition. Namely, we will study a Trudinger–Moser inequality with exact growth:

Theorem 1.5.

Let pq1. Then there exists a constant C=C(N,p,q,β)>0 such that for all uDN,q(RN), uN1, there holds

(1.3) N Φ N , q , β ( α N ( 1 - β N ) u N N - 1 ) ( 1 + | u | p N - 1 ( 1 - β N ) ) | x | β 𝑑 x C u q q ( 1 - β N ) .

Moreover, the inequality does not hold when p<q.

The organization of the paper is as follows. In Section 2, we will recall and establish some necessary lemmas which are required to prove our main theorems. Section 3 provides the proof of Theorem 1.1, a subcritical Trudinger–Moser inequality. In Section 4, we establish the critical Trudinger–Moser inequalities, i.e., Theorem 1.2. Section 5 offers the proofs of Theorems 1.3, 1.4, 1.5. In Section 6, we justify the sharpness of Theorems 1.1, 1.2, 1.3, 1.4, 1.5.

2 Some Useful Preliminaries

In this section, we introduce some useful results that will be used in our proofs. We first recall the definition of rearrangement and some useful inequalities. Let ΩN, N2, be a measurable set. We denote by Ω# the open ball BRN centered at 0 of radius R>0 such that |BR|=|Ω|.

Let u:Ω be a real-valued measurable function that vanishes at infinity, that is, |{x:|u(x)|>t}| is finite for all t>0. The distribution function of u is the function

μ u ( t ) = | { x Ω : | u ( x ) | > t } |

and the decreasing rearrangement of u is the right-continuous, nonincreasing function u that is equi-measurable with u:

u ( s ) = sup { t 0 : μ u ( t ) > s } .

It is clear that suppu[0,|Ω|]. We also define

u ( s ) = 1 s 0 s u ( t ) 𝑑 t u ( s ) .

Moreover, we define the spherically symmetric decreasing rearrangement of u:

u # : Ω # [ 0 , ] , u # ( x ) = u ( σ N | x | N ) ,

where σN is the volume of the unit ball in N.

Then we have the following important result that could be found in [38]:

Lemma 2.1 (Pólya–Szegő Inequality).

Let uW1,p(Rn), p1. Then f#W1,p(Rn) and

f # p f p .

Lemma 2.2.

Let f and g be nonnegative functions on RN, vanishing at infinity. Then

N f ( x ) g ( x ) 𝑑 x N f # ( x ) g # ( x ) 𝑑 x

in the sense that when the left side is infinite so is the right. Moreover, if f is strictly symmetric-decreasing, then there is equality if and only if g=g#.

Now, we recall a compactness lemma of Strauss [4, 56].

Lemma 2.3.

Let P and Q:RR be two continuous functions satisfying

P ( s ) Q ( s ) 0 as  | s |    𝑎𝑛𝑑    P ( s ) Q ( s ) 0 as  s 0

Let (un) be a sequence of measurable functions un:RNR such that

sup n N | Q ( u n ( x ) ) | 𝑑 x <

and

P ( u n ( x ) ) n v ( x ) a.e.,    lim | x | | u n ( x ) | = 0 uniformly with respect to  n .

Then P(un)v in L1(RN).

Using Lemma 2.3, we will study the continuity and compactness of the embeddings from Drad1,N(N)Lq(N) into La(N) and La(N;dx|x|β). More precisely, we have the following lemma:

Lemma 2.4.

Let N2, 0<t<N. Then the embedding

D rad 1 , N ( N ) L q ( N ) L r ( N )

is continuous when rq and compact for all r>q. Moreover, the embedding

D rad 1 , N ( N ) L q ( N ) L r ( N ; d x | x | t )

is compact for all rq.

Proof.

By the Caffarelli–Kohn–Nirenberg inequality [5], there exists a positive constant C such that for all uC0(N),

| x | γ u r C | x | α | u | p a | x | β u q 1 - a ,

where

p , q 1 , r > 0 , 0 a 1 , 1 p + α N , 1 q + β N , 1 r + γ N > 0 ,
γ = a σ + ( 1 - a ) β , 1 r + γ N = a ( 1 p + α - 1 N ) + ( 1 - a ) ( 1 q + β N ) ,

and

0 α - σ if  a > 0 ,
α - σ 1 if  a > 0  and  1 p + α - 1 N = 1 r + γ N .

Then we can obtain the continuity of the embedding

D N , q ( N ) L r ( N ; d x | x | t )

with r>q(1-tN) (rq if t=0). Indeed, we choose p=N, α=β=0, γ=-tr, a=1-qr(1-tN).

Now, let r>q, we now will prove that the embedding

D rad 1 , N ( N ) L q ( N ) L r ( N )

is compact. Indeed, let {un}Drad1,N(N)Lq(N) be bounded. Then we can assume that

u n u weakly in  D rad 1 , N ( N ) L q ( N ) .

Set

v n = u n - u .

By the Radial Lemma, we get

lim | x | | v n ( x ) | = 0 uniformly with respect to  n .

Also, using Lemma 2.3 with

P ( s ) = s r , Q ( s ) = s q + s r + 1 ,

we can conclude that vn converges to 0 in L1. It means that un converges to u in Lr.

Now, let rq; we will prove that the embedding

D rad 1 , N ( N ) L q ( N ) L r ( N ; d x | x | t )

is compact. First, let {un}Drad1,N(N)Lq(N) be bounded. Again, we can assume that

u n u weakly in  D rad 1 , N ( N ) L q ( N ) .

Choose p such that 1<p<Nt, then for R arbitrary, we get

| x | < R | u n - u | r d x | x | t ( | x | < R | u n - u | r p 𝑑 x ) 1 p ( | x | < R 1 | x | t p 𝑑 x ) 1 p
C R N p - t ( | x | < R | u n - u | r p 𝑑 x ) 1 p .

Also,

| x | R | u n - u | r d x | x | t 1 R t | x | R | u n - u | r 𝑑 x C R t .

Using the compactness of the embedding Drad1,N(N)Lq(N)Lrp(N), choosing R sufficiently large, we get that un converges to u in Lr(N;dx|x|t). ∎

Now, we will prove a variant of [42, Lemma 2.2]:

Lemma 2.5.

Given any sequence s={sk}k0, let

s 1 = k = 0 | s k | , s N = ( k = 0 | s k | N ) 1 N , s ( e ) = ( k = 0 | s k | q e k ) 1 q

and

μ ( h ) = inf { s ( e ) : s 1 = h , s N 1 } .

Then for h>1, we have

μ ( h ) exp ( h N N - 1 q ) h 1 N - 1 .

Proof.

Since μ(h) is increasing in h, we just need to show that

μ ( n 1 - 1 N ) e n q n 1 N for all natural number  n .

Choose

s k = { 1 n 1 N if  k n - 1 , 0 if  k > n - 1 .

It is clear that

s N = 1 , s 1 = n 1 - 1 N , s ( e ) e n q n 1 N

so

μ ( n 1 - 1 N ) e n q n 1 N .

Now, assume that for some ε1, n1 and sequence s,

s N = 1 s 1 = n , s ( e ) ε e n q n 1 N

It means that for kn,

| s k | ε e n - k q n 1 N .

Consider the new sequence (bk) with bk=sk, kn, and bk=0, k>n, we get

b 1 = s 1 - j > n | s j | n 1 - 1 N - C ε n 1 N .

Hence

b 1 N N - 1 ( n 1 - 1 N - C ε n 1 N ) N N - 1 = n ( 1 - C ε n ) N N - 1 n - C ε .

On the other hand,

b 1 N N - 1 = ( b 1 2 ) N 2 ( N - 1 ) n - 1 2 N N - 1 j , k n ( s j - s k ) 2 2 n 1 - 2 N .

Hence

j , k n ( s j - s k ) 2 ε n 1 - 2 N .

Choose mn such that

min j n | s j | = | s m | .

Then

b 1 - n | s m | ε n 1 - 1 N .

Hence

| s m | 1 n 1 N

and we get

s ( e ) e n q n 1 N ,

which is a contradiction. ∎

Using the above lemma, we can now prove a Radial Sobolev inequality in the spirit of Ibrahim, Masmoudi and Nakanishi [15]:

Theorem 2.1 (Radial Sobolev Inequality).

There exists a constant C>0 such that for any radially nonnegative nonincreasing function φDN,q(RN) satisfying u(R)>1 and

ω N - 1 R | φ ( t ) | N t N - 1 𝑑 t K

for some R,K>0, then we have

exp [ α N K φ N N - 1 ( R ) ] φ q N - 1 ( R ) R N C R | φ ( t ) | q t N - 1 𝑑 t K q N - 1 .

Proof.

By scaling, we can assume that R=1, K=1, i.e., ωN-11|φ(t)|NtN-1𝑑t1. Set

h k = α N N - 1 N φ ( e k N ) , s k = h k - h k + 1 0 ;

then

s 1 = h 0 = α N N - 1 N φ ( 1 ) .

Also

s k = h k - h k + 1 = α N N - 1 N [ φ ( e k N ) - φ ( e k + 1 N ) ] = α N N - 1 N e k + 1 N e k N u ( t ) 𝑑 t
α N N - 1 N ( e k N e k + 1 N | u ( t ) | N t N - 1 𝑑 t ) 1 N ( e k N e k + 1 N 1 t 𝑑 t ) N - 1 N
( ω N - 1 e k N e k + 1 N | u ( t ) | N t N - 1 𝑑 t ) 1 N .

Hence

s N 1 .

Now

1 | φ ( t ) | q t N - 1 𝑑 t = k 0 e k N e k + 1 N | φ ( t ) | q t N - 1 𝑑 t k 0 | φ ( e k + 1 N ) | q e k N e k + 1 N t N - 1 𝑑 t
k 0 | φ ( e k + 1 N ) | q e k + 1 k 0 | h k + 1 | q e k + 1
= k 1 | h k | q e k k 1 | s k | q e k .

Thus

s ( e ) q = k = 0 | s k | q e k = s 0 q + k 1 | s k | q e k h 0 q + 1 | φ ( t ) | q t N - 1 𝑑 t .

Also, for 1<r<exp(12NN-1N),

h 0 - α N N - 1 N φ ( r ) = α N N - 1 N φ ( 1 ) - α N N - 1 N φ ( r ) = α N N - 1 N r 1 u ( t ) 𝑑 t
α N N - 1 N ( 1 r | u ( t ) | N t N - 1 𝑑 t ) 1 N ( 1 r 1 t 𝑑 t ) N - 1 N
< 1 2 h 0 2 .

Hence

h 0 φ ( r ) .

So

1 | φ ( t ) | q t N - 1 𝑑 t 1 e 1 2 n | φ ( t ) | q t N - 1 𝑑 t h 0 q .

Now, we can conclude that

1 | φ ( t ) | q t N - 1 𝑑 t s ( e ) q exp ( h 0 N N - 1 ) h 0 q N - 1 = C e α N φ N N - 1 ( 1 ) ( φ ( 1 ) ) q N - 1 .

3 Subcritical Trudinger–Moser Inequalities: Proof of Theorem 1.1

We prove Theorem 1.1 in this section. This is a subcritical version of the Trudinger–Moser inequalities.

Proof.

Suppose that uC0(N){0},u0 and uN1. We write

N exp ( α ( 1 - β N ) | u | N N - 1 ) | u | p | x | β 𝑑 x = I 1 + I 2 ,

where

I 1 = { u > 1 } exp ( α ( 1 - β N ) | u | N N - 1 ) | u | p | x | β 𝑑 x ,
I 2 = { u 1 } exp ( α ( 1 - β N ) | u | N N - 1 ) | u | p | x | β 𝑑 x .

First, by Lemma 2.4, we get

I 2 e α | x | - β p u p p C N , p , q , α , β u q q ( 1 - β N ) .

Now, set

v = u - 1 on  Ω ( u ) = { u > 1 } .

Then

v W 0 1 , N ( Ω ( u ) ) and v N 1 .

Now

I 1 = Ω ( u ) e α ( 1 - β N ) | v + 1 | N N - 1 + p ln ( v + 1 ) | x | β 𝑑 x Ω ( u ) e α ( 1 - β N ) ( | v | + 1 ) N N - 1 + p | v | | x | β 𝑑 x
C N , p , q , α , β Ω ( u ) e ( α ( 1 - β N ) + ε ) | v | N N - 1 + C ( ε ) | x | β 𝑑 x

for ε=αN(1-βN)-α(1-βN) and C(ε)=CN,p,q,α,β sufficient large. Hence, by the singular Trudinger–Moser inequality, we obtain

I 1 C N , p , q , α , β | Ω ( u ) | 1 - β N .

However, it can be deduced easily that

| Ω ( u ) | = Ω ( u ) 1 𝑑 x Ω ( u ) | u | q 𝑑 x = u q q .

Hence, we get

N exp ( α ( 1 - β N ) | u | N N - 1 ) | u | p | x | β 𝑑 x C N , p , q , α , β u q q ( 1 - β N ) for all  u D N , q ( N ) , u N 1 .

4 Critical Trudinger–Moser Inequalities: Proof of Theorem 1.2

In this section, Theorem 1.2 will be proved via the following series of lemmas.

Lemma 4.1.

We have

TMSC ( q , N , α , β ) C ( N , β , q ) ( 1 - ( α α N ) N - 1 ) q ( 1 - β N ) N .

Proof.

Let uC0(N), uN1, uq=1 and u0 and set

Ω = { x : u ( x ) > ( 1 - ( α α N ) N - 1 ) 1 N } .

Then

| Ω | = Ω 1 𝑑 x Ω u ( x ) q ( 1 - ( α α N ) N - 1 ) q N 𝑑 x 1 ( 1 - ( α α N ) N - 1 ) q N .

We have by the Caffarelli–Kohn–Nirenberg inequality that for some ε=ε(q,β,N)0 with ε=0 when β=0 and ε>0 when β>0,

N Ω Φ N , q , β ( α ( 1 - β N ) | u | N N - 1 ) | x | β 𝑑 x { u 1 } Φ N , q , β ( α ( 1 - β N ) | u | N N - 1 ) | x | β 𝑑 x
e α { u 1 } u q ( 1 - β N ) + ε | x | β 𝑑 x C ( N , β , q ) .

Now, we consider

I = Ω Φ N , q , β ( α ( 1 - β N ) | u | N N - 1 ) | x | β 𝑑 x Ω exp ( α ( 1 - β N ) | u | N N - 1 ) | x | β 𝑑 x .

On Ω, we set

v ( x ) = u ( x ) - ( 1 - ( α α N ) N - 1 ) 1 N .

Then it is clear that vW01,N(Ω) and vN1. Also, on Ω, with ε=αNα-1,

| u | N ( | v | + ( 1 - ( α α N ) N - 1 ) 1 N ) N
( 1 + ε ) | v | N + ( 1 - 1 ( 1 + ε ) N - 1 ) 1 1 - N | ( 1 - ( α α N ) N - 1 ) 1 N | N
= α N α | v | N + 1 .

Hence, by the singular Trudinger–Moser inequality,

I Ω exp ( α ( 1 - β N ) | u | N N - 1 ) | x | β 𝑑 x Ω exp ( α N ( 1 - β N ) | v | N + α ) | x | β 𝑑 x
C ( N , β , q ) | Ω | 1 - β N C ( N , β , q ) ( 1 - ( α α N ) N - 1 ) q ( 1 - β N ) N .

In conclusion, we have

TMSC ( q , N , α , β ) C ( N , β , q ) ( 1 - ( α α N ) N - 1 ) q ( 1 - β N ) N .

Lemma 4.2.

We have TMCa,b(q,N,β)< when bN.

Proof.

Let uDN,q(N){0}, uNa+uqb1. Assume that

u N = θ ( 0 , 1 ) , u q b 1 - θ a .

If 12<θ<1, then again we set

v ( x ) = u ( λ x ) θ , λ = ( ( 1 - θ a ) q b θ q ) 1 N > 0 .

Hence

v N = u N θ = 1 ,
v q q = N | v | q 𝑑 x = 1 θ q N | u ( λ x ) | q 𝑑 x = 1 θ q λ N u q q ( 1 - θ a ) q b θ q λ N = 1 .

We have

N Φ N , q , β ( α N ( 1 - β N ) | u | N ) | x | β 𝑑 x = N Φ N , q , β ( α N ( 1 - β N ) | u ( λ x ) | N ) | λ x | β d ( λ x )
λ N - β N Φ N , q , β ( θ N α N ( 1 - β N ) | v | N N - 1 ) | x | β 𝑑 x
λ N - β TMSC β , q ( θ N α N )
( ( 1 - θ a ) q b θ q ) 1 - β N C ( N , β , q ) ( 1 - ( θ N α N α N ) N - 1 ) q ( 1 - β N ) N
( ( 1 - θ a ) q b ) 1 - β N ( 1 - θ N ) q ( 1 - β N ) N C ( N , β , q ) C ( N , β , q , a , b )  since  b N .

If 0<θ12, then with

v ( x ) = 2 u ( 2 q N x )

we have

v N = 2 u N 1 , v q 1 .

Hence

N Φ N , q , β ( α N | u | N ) | x | β 𝑑 x 2 q N Φ N , q , β ( α N ( 1 - β N ) 2 N | v | N N - 1 ) | x | β 𝑑 x C ( q , N , β ) .

Lemma 4.3.

If TMCa,b(q,N,β)<, then

TMC a , b ( q , N , β ) = sup α ( 0 , α N ) ( 1 - ( α α N ) N - 1 N a ( α α N ) b N - 1 N ) q b ( 1 - β N ) TMSC ( q , N , α , β ) .

Proof.

Let uDN,q(N), uN1, uq=1. Set

v ( x ) = ( α α N ) N - 1 N u ( λ x ) , λ = ( ( α α N ) b N - 1 N 1 - ( α α N ) N - 1 N a ) q b N .

Then

v q = ( α α N ) N - 1 N 1 λ N q , v N = ( α α N ) N - 1 N u N ( α α N ) N - 1 N

Hence vNa+vqb1. By the definition of TMCa,b(q,N,β), we obtain

N Φ N , q , β ( α ( 1 - β N ) | u | N N - 1 ) | x | β 𝑑 x = N Φ N , q , β ( α ( 1 - β N ) | u ( λ x ) | N N - 1 ) | λ x | β d ( λ x )
= λ N - β N 1 | x | β Φ N , q , β ( α N ( 1 - β N ) | v ( x ) | N N - 1 ) 𝑑 x
( ( α α N ) b N - 1 N 1 - ( α α N ) N - 1 N a ) q b ( 1 - β N ) TMC a , b ( q , N , β ) .

Hence

TMC a , b ( q , N , β ) sup α ( 0 , α N ) ( 1 - ( α α N ) N - 1 N a ( α α N ) b N - 1 N ) q b ( 1 - β N ) TMSC ( q , N , α , β ) .

By the same process as above, by beginning with the function v such that vQa+vQb1, and defining the function u as follows:

u ( x ) = v ( λ x ) v N , λ = ( 1 - v N a v N b ) q b N > 0 ,

we have that

TMC a , b ( q , N , β ) > sup α ( 0 , α N ) ( 1 - ( α α N ) N - 1 N a ( α α N ) b N - 1 N ) q b ( 1 - β N ) TMSC ( q , N , α , β )

is impossible. Hence

TMC a , b ( q , N , β ) = sup α ( 0 , α N ) ( 1 - ( α α N ) N - 1 N a ( α α N ) b N - 1 N ) q b ( 1 - β N ) TMSC ( q , N , α , β ) .

Lemma 4.4.

We have

TMSC ( q , N , α , β ) c ( N , β , q ) ( 1 - ( α α N ) N - 1 ) q ( 1 - β N ) N when  α α N .

Proof.

Consider the following sequence:

u n ( x ) = { ( 1 ω N - 1 ) 1 N ( n N - β ) N - 1 N , 0 | x | e - n N - β , ( N - β ω N - 1 n ) 1 N log ( 1 | x | ) , e - n N - β < | x | < 1 , 0 , | x | 1 .

Then we can see easily that

u n N = 1

and for sufficiently large n, say when nM1,

u n q q = 0 e - n N - β ( 1 ω N - 1 ) q N ( n N - β ) q ( N - 1 ) N r N - 1 𝑑 r + e - n N - β 1 ( N - β ω N - 1 n ) q N ( log ( 1 r ) ) q r N - 1 𝑑 r
n q ( N - 1 ) N 0 e - n N - β r N - 1 𝑑 r + 1 n q N 0 n N - β y q e - N y 𝑑 y
n q ( N - 1 ) N e - n N N - β + 1 n q N 1 n q N .

Now,

N Φ N , q , β ( α ( 1 - β N ) | u n | N N - 1 ) | x | β 𝑑 x Φ N , q , β ( α ( 1 - β N ) ( 1 ω N - 1 ) 1 N - 1 ( n N - β ) ) 0 e - n N - β r N - 1 - β 𝑑 r
Φ N , q , β ( α α N n ) e - n
e α α N n e - n for sufficiently large  n M 2  where  M 2  is independent of  α .

For ααN such that 11-ααN>10max{M1,M2}, we pick n=n(α) such that 1(1-ααN)n2, i.e., n11-ααN. Then

TMSC ( q , N , α , β ) 1 u n q q ( 1 - β N ) N Φ N , q , β ( α ( 1 - β N ) | u n | N N - 1 ) | x | β 𝑑 x
n q N ( 1 - β N ) e - 2 ( 1 1 - α α N ) q N ( 1 - β N ) 1 ( 1 - ( α α N ) N - 1 ) q ( 1 - β N ) N .

Lemma 4.5.

We have TMCa,b(q,N,β)< if and only if bN.

Proof.

Now, assume that there is some b>N such that TMCa,b(q,N,β) is finite. Then

lim sup α α N ( 1 - ( α α N ) N - 1 N a ( α α N ) b N - 1 N ) q b ( 1 - β N ) TMSC ( q , N , α , β ) TMC a , b ( q , N , β ) < .

By the above lemma,

lim sup α α N ( 1 - ( α α N ) N - 1 N a ( α α N ) q N - 1 N ) q N ( 1 - β N ) TMSC ( q , N , α , β ) > 0 .

Then

lim inf α α N ( 1 - ( α α N ) N - 1 N a ( α α N ) b N - 1 N ) q b ( 1 - β N ) ( ( α α N ) q N - 1 N 1 - ( α α N ) N - 1 N a ) q N ( 1 - β N ) < ,

which is impossible since b>N. ∎

5 Trudinger–Moser Inequality when b>N

5.1 Trudinger–Moser Inequality with Exact Growth – Proof of Theorem 1.5

Proof.

It is enough to prove inequality (1.3) when p=q. By the symmetrization arguments: the Pólya–Szegő inequality, the Hardy–Littlewood inequality and the density arguments, we may assume that u is a smooth, nonnegative and radially nonincreasing function (we just need to make sure that the function ΦN,q,β(αtNN-1)/(1+tq(1-βN)) is nondecreasing on + but it is easy since ΦN,q,β(αtNN-1)/tq(1-βN) and ΦN,q,β(αtNN-1) are both nondecreasing on +). Let R1=R1(u) be such that

B R 1 | u | N 𝑑 x = ω N - 1 0 R 1 | u r | N r N - 1 𝑑 r 1 - ε 0 ,
N B R 1 | u | N 𝑑 x = ω N - 1 R 1 | u r | N r N - 1 𝑑 r ε 0 .

Here ε0(0,1) is fixed and does not depend on u.

By Hölder’s inequality, we have

u ( r 1 ) - u ( r 2 ) r 1 r 2 - u r d r ( r 1 r 2 | u r | N r N - 1 𝑑 r ) 1 N ( ln r 2 r 1 ) N - 1 N
(5.1) ( 1 - ε 0 ω N - 1 ) 1 N ( ln r 2 r 1 ) N - 1 N for  0 < r 1 r 2 R 1

and

(5.2) u ( r 1 ) - u ( r 2 ) ( ε 0 ω N - 1 ) 1 N ( ln r 2 r 1 ) N - 1 N for  R 1 r 1 r 2 .

We define R0:=inf{r>0:u(r)1}[0,). Hence u(s)1 when sR0. Without loss of generality, we assume R0>0.

Now, we split the integral as follows:

N Φ N , q , β ( α | u | N N - 1 ) ( 1 + λ u q N - 1 ( 1 - β N ) ) | x | β 𝑑 x = B R 0 Φ N , q , β ( α | u | N N - 1 ) ( 1 + λ u q N - 1 ( 1 - β N ) ) | x | β 𝑑 x + N B R 0 Φ N , q , β ( α | u | N N - 1 ) ( 1 + λ u q N - 1 ( 1 - β N ) ) | x | β 𝑑 x
= I + J .

First, we will estimate J. Since u1 on NBR0, we have if β>0,

J = N B R 0 Φ N , q , β ( α | u | N N - 1 ) ( 1 + λ u q N - 1 ( 1 - β N ) ) | x | β 𝑑 x C { u 1 } | u | ( q N - 1 N ( 1 - β N ) + 1 ) N N - 1 | x | β 𝑑 x C u q q ( 1 - β N )

by Lemma 2.4. Similarly for the case β=0, we also have

J C u q q ( 1 - β N ) .

Hence, now, we just need to deal with the integral I.

Case 1: 0<R0R1. In this case, using (5.1), we have for 0<rR0,

u ( r ) 1 + ( 1 - ε 0 ω N - 1 ) 1 N ( ln R 0 r ) N - 1 N .

By using

( a + b ) N N - 1 ( 1 + ε ) a N N - 1 + A ( ε ) b N N - 1 ,

where

A ( ε ) = ( 1 - 1 ( 1 + ε ) N - 1 ) 1 1 - N ,

we get

u N N - 1 ( r ) ( 1 + ε ) ( 1 - ε 0 ω N - 1 ) 1 N - 1 ln R 0 r + C ( ε ) .

Thus, we can estimate the integral I as follows:

I = B R 0 Φ N , q , β ( α | u | N N - 1 ) ( 1 + λ u q N - 1 ( 1 - β N ) ) | x | β 𝑑 x
B R 0 exp ( α ( 1 + ε ) ( 1 - ε 0 ω N - 1 ) 1 N - 1 ln R 0 r + α A ( ε ) ) | x | β 𝑑 x
C R 0 α ( 1 + ε ) ( 1 - ε 0 ω N - 1 ) 1 N - 1 0 R 0 r N - 1 - α ( 1 + ε ) ( 1 - ε 0 ω N - 1 ) 1 N - 1 - β 𝑑 r
C R 0 N - β C ( B R 0 1 𝑑 x ) 1 - β N C u q q ( 1 - β N ) .

Case 2: 0<R1<R0. We have

I = B R 0 Φ N , q , β ( α | u | N N - 1 ) ( 1 + λ u q N - 1 ( 1 - β N ) ) | x | β 𝑑 x = B R 1 Φ N , q , β ( α | u | N N - 1 ) ( 1 + λ u q N - 1 ( 1 - β N ) ) | x | β 𝑑 x + B R 0 B R 1 Φ N , q , β ( α | u | N N - 1 ) ( 1 + λ u q N - 1 ( 1 - β N ) ) | x | β 𝑑 x
= I 1 + I 2 .

Using (5.2), we get

u ( r ) - u ( R 0 ) ( ε 0 ω N - 1 ) 1 N ( ln R 0 r ) N - 1 N for  r R 1 .

Hence

u ( r ) 1 + ( ε 0 ω N - 1 ) 1 N ( ln R 0 r ) N - 1 N .

Then we have

u N N - 1 ( r ) ( 1 + ε ) ( ε 0 ω N - 1 ) 1 N - 1 ln R 0 r + A ( ε ) for all  ε > 0 .

So

I 2 = B R 0 B R 1 Φ N , q , β ( α | u | N N - 1 ) ( 1 + λ u q N - 1 ( 1 - β N ) ) | x | β 𝑑 x
C R 1 R 0 exp ( α ( 1 + ε ) ( ε 0 ω N - 1 ) 1 N - 1 ln R 0 r + α A ( ε ) ) r N - 1 - β 𝑑 r
C R 0 α ( 1 + ε ) ( ε 0 ω N - 1 ) 1 N - 1 R 0 N - β - α ( 1 + ε ) ( ε 0 ω N - 1 ) 1 N - 1 - R 1 N - β - α ( 1 + ε ) ( ε 0 ω N - 1 ) 1 N - 1 N - β - α ( 1 + ε ) ( ε 0 ω N - 1 ) 1 N - 1
C N - β - α ( 1 + ε ) ( ε 0 ω N - 1 ) 1 N - 1 ( R 0 N - β - R 1 N - β ) C ( R 0 N - R 1 N ) 1 - β N C ( B R 0 B R 1 1 𝑑 x ) 1 - β N
C u q q ( 1 - β N )

(since ααN(1-βN), we can choose ε>0 such that N-β-α(1+ε)(ε0ωN-1)1N-1>0). So, we need to estimate

I 1 = B R 1 Φ N , q , β ( α | u | N N - 1 ) ( 1 + λ u q N - 1 ( 1 - β N ) ) | x | β 𝑑 x

with u(R1)>1. First, we define

v ( r ) = u ( r ) - u ( R 1 ) on  0 r R 1 .

It is clear that vW01,N(BR1) and that

B R 1 | v | N 𝑑 x = B R 1 | u | N 𝑑 x 1 - ε 0 .

Moreover, for 0rR1,

u N N - 1 ( r ) ( 1 + ε ) v N N - 1 ( r ) + A ( ε ) u N N - 1 ( R 1 ) .

Hence

I 1 = B R 1 Φ N , q , β ( α u N N - 1 ) ( 1 + λ u q N - 1 ( 1 - β N ) ) | x | β 𝑑 x 1 λ e α A ( ε ) u N N - 1 ( R 1 ) u q N - 1 ( 1 - β N ) ( R 1 ) B R 1 e ( 1 + ε ) α v N N - 1 ( r ) | x | β 𝑑 x
(5.3) = 1 λ e α A ( ε ) u N N - 1 ( R 1 ) u q N - 1 ( 1 - β N ) ( R 1 ) B R 1 e α w N N - 1 ( r ) | x | β 𝑑 x ,

where w=(1+ε)N-1Nv. It is clear that wW01,N(BR1) and

B R 1 | w | N 𝑑 x = ( 1 + ε ) N - 1 B R 1 | v | N 𝑑 x ( 1 + ε ) N - 1 ( 1 - ε 0 ) 1

if we choose 0<ε(11-ε0)1N-1-1. Hence, using the singular Trudinger–Moser inequality, we have

(5.4) B R 1 e α w N N - 1 ( r ) | x | β 𝑑 x C | B R 1 | 1 - β N C R 1 N - β .

Also, using Theorem 2.1, we have

e α A ( ε ) u N N - 1 ( R 1 ) u q N - 1 ( 1 - β N ) ( R 1 ) R 1 N - β [ exp ( N α A ( ε ) N - β u N N - 1 ( R 1 ) ) u q N - 1 ( R 1 ) R 1 N ] 1 - β N ( C A ( ε ) q N - 1 N B R 1 | u | q 𝑑 x ) 1 - β N
(5.5) ( C u q q ) 1 - β N

if we choose ε=(11-ε0)1N-1-1. By (5.3), (5.4) and (5.5), the proof is now completed. ∎

5.2 Proof of Theorems 1.3 and 1.4

First we will prove that Theorem 1.4 is valid if and only if Theorem 1.3 is valid.

Suppose first that Theorem 1.4 is valid. Let uDN,q(N), uNa+uqkN1. Set

v ( x ) = u ( λ x ) ,
λ = ( u q N 1 - u N a ) q N 2 ( u q N u q k N ) q N 2 = 1 u q ( k - 1 ) q N .

Then

v N = u N , v q = 1 λ N q u q

and

v N a + v q N = u N a + 1 λ N 2 q u q N = 1 .

Since, by assumption, Theorem 1.4 holds, we have

N Φ N , q , β ( α N ( 1 - β N ) | u | N N - 1 ) ( 1 + | u | p N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | x | β 𝑑 x = λ N - β N Φ N , q , β ( α N ( 1 - β N ) | v | N N - 1 ) ( 1 + | v | p N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | x | β 𝑑 x
C λ N - β v q q ( 1 - 1 k ) ( 1 - β N ) = C λ N - β ( 1 λ N q u q ) q ( 1 - 1 k ) ( 1 - β N )
= C λ N - β k u q q ( 1 - 1 k ) ( 1 - β N ) C ( 1 u q ( k - 1 ) q N ) N - β k u q q ( 1 - 1 k ) ( 1 - β N ) = C .

Suppose now that Theorem 1.3 holds. Let vDN,q(N), vNa+vqN1. Set

u ( x ) = v ( λ x ) ,
λ = ( v q k N 1 - v N a ) q k N 2 ( v q k N v q N ) q k N 2 = v q ( 1 - 1 k ) q N .

Then

u N = v N , u q = 1 λ N q v q

and

u N a + u q k N = v N a + 1 λ k N 2 q v q k N = 1 .

Hence

N Φ N , q , β ( α N ( 1 - β N ) | v | N N - 1 ) ( 1 + | v | p N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | x | β 𝑑 x = λ N - β N Φ N , q , β ( α N ( 1 - β N ) | u | N N - 1 ) ( 1 + | u | p N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | x | β 𝑑 x
C λ N - β C v q ( 1 - 1 k ) q ( 1 - β N ) .

Now, we will provide a proof for Theorem 1.4.

Proof of Theorem 1.4.

Let uDN,q(N), uNa+uqN1. By Hölder’s inequality and Theorems 1.2 and 1.5, we get

{ u > 1 } Φ N , q , β ( α N ( 1 - β N ) | u | N N - 1 ) ( 1 + | u | p N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | x | β 𝑑 x { u > 1 } ( Φ N , q , β ( α N ( 1 - β N ) | u | N N - 1 ) | x | β ) 1 k ( Φ N , q , β ( α N ( 1 - β N ) | u | N N - 1 ) | u | p N - 1 ( 1 - β N ) | x | β ) 1 - 1 k 𝑑 x
[ { u > 1 } Φ N , q , β ( α N ( 1 - β N ) | u | N N - 1 ) | x | β 𝑑 x ] 1 k [ { u > 1 } Φ N , q , β ( α N ( 1 - β N ) | u | N N - 1 ) | u | p N - 1 ( 1 - β N ) | x | β 𝑑 x ] 1 - 1 k
C ( N , p , q , β , a , k ) u q q ( 1 - β N ) ( 1 - 1 k ) .

Also, it is easy to see

{ u 1 } Φ N , q , β ( α N ( 1 - β N ) | u | N N - 1 ) ( 1 + | u | p N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | x | β 𝑑 x C ( N , p , q , β , a , k ) u q q ( 1 - β N )
C ( N , p , q , β , a , k ) u q q ( 1 - β N ) ( 1 - 1 k ) .

6 Sharpness

We will verify that αN(1-βN) is sharp in Theorem 1.1, Corollary 1.1, Corollary 1.2, Theorem 1.2 and Theorem 1.5. Indeed, consider the following Moser’s sequence:

u n ( x ) = { ( 1 ω N - 1 ) 1 N ( n N - β ) N - 1 N , 0 | x | e - n N - β , ( N - β ω N - 1 n ) 1 N log ( 1 | x | ) , e - n N - β < | x | < 1 , 0 , | x | 1 .

Then we can see easily that

u n N = 1 , u n q = o n ( 1 ) .

Also

N exp ( α N ( 1 - β N ) | u n | N N - 1 ) | u n | p | x | β 𝑑 x
ω N - 1 exp ( α N ( 1 - β N ) ( 1 ω N - 1 ) 1 N - 1 ( n N - β ) ) ( 1 ω N - 1 ) p N ( n N - β ) p ( N - 1 ) N 0 e - n N - β r N - 1 - β 𝑑 r
ω N - 1 e n ( 1 ω N - 1 ) p N ( n N - β ) p ( N - 1 ) N e - n N - β

and

N [ exp ( α N ( 1 - β N ) | u n | N N - 1 ) - k = 0 N - 2 ( α N ( 1 - β N ) ) k k ! | u n | k N N - 1 ] | x | β 𝑑 x ω N - 1 N - β ( 1 - e - n k = 0 N - 2 n k k ! ) ,
N Φ N , q , β ( α N ( 1 - β N ) | u n | N N - 1 ) | x | β 𝑑 x ω N - 1 N - β Φ N , q , β ( n ) e - n .

Hence

1 u n q q ( 1 - β N ) N exp ( α N ( 1 - β N ) | u n | N N - 1 ) | u n | p | x | β 𝑑 x ,
1 u n q N - β N [ exp ( α N ( 1 - β N ) | u n | N N - 1 ) - k = 0 N - 2 ( α N ( 1 - β N ) ) k k ! | u n | k N N - 1 ] | x | β 𝑑 x ,
1 u n q q ( 1 - β N ) N Φ N , q , β ( α | u n | N N - 1 ) | x | β 𝑑 x .

Now, set

v n = c n u n ,

where cn>0 is chosen such that cna+cnbunqb=1. Then

v n N a + v n q b = 1 .

Noting that limncn=1, we have for α>αN(1-βN),

N Φ N , q , β ( α | v n | N N - 1 ) | x | β 𝑑 x = N Φ N , q , β ( α c n N N - 1 | u n | N N - 1 ) | x | β 𝑑 x ω N - 1 N - β Φ N , q , β ( α α N ( 1 - β N ) c n N N - 1 n ) e - n + .

Finally, we will show that pq are necessary in Theorem 1.5, Theorem 1.3 and Theorem 1.4. Recall that unN=1 and for sufficiently large n,

u n q q = 0 e - n N - β ( 1 ω N - 1 ) q N ( n N - β ) q ( N - 1 ) N r N - 1 𝑑 r + e - n N - β 1 ( N - β ω N - 1 n ) q N ( log ( 1 r ) ) q r N - 1 𝑑 r
n q ( N - 1 ) N 0 e - n N - β r N - 1 𝑑 r + 1 n q N 0 n N - β y q e - N y 𝑑 y
n q ( N - 1 ) N e - n N N - β + 1 n q N 1 n q N .

Now we consider the left-hand side of (1.3),

N Φ N , q , β ( α N ( 1 - β N ) | u n | N N - 1 ) ( 1 + λ | u n | l ) | x | β 𝑑 x 0 e - n N - β Φ N , q , β ( α N ( 1 - β N ) ( 1 ω N - 1 ) 1 N - 1 ( n N - β ) ) ( 1 + λ | ( 1 ω N - 1 ) 1 N ( n N - β ) N - 1 N | l ) r N - 1 - β 𝑑 r
0 e - n N - β Φ N , q , β ( n ) n l ( N - 1 ) N r N - 1 - β 𝑑 r Φ N , q , β ( n ) e - n n l ( N - 1 ) N 1 n l ( N - 1 ) N .

Note to make (1.3) true providing n sufficiently large, we need

1 n l ( N - 1 ) N u n q q ( 1 - β N ) 1 n q ( 1 - β N ) N l q N - 1 ( 1 - β N ) .

It is surprising that the direct calculations using the Moser sequence could not verify that pq are necessary in Theorem 1.3 and Theorem 1.4. Hence, in this case, we need to propose a new approach. Indeed, assume that p0 is such that

B := sup u N a + u q N 1 1 u q q ( 1 - 1 k ) ( 1 - β N ) N Φ N , q , β ( α N ( 1 - β N ) u N N - 1 ) ( 1 + [ α N ( 1 - β N ) ] p N ( 1 - 1 k ) ( 1 - β N ) | u | p N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | x | β 𝑑 x

is finite. We define

A ( α ) := sup u N 1 1 u q q ( 1 - β N ) N Φ N , q , β ( α ( 1 - β N ) | u | N N - 1 ) ( 1 + [ α ( 1 - β N ) ] p N ( 1 - 1 k ) ( 1 - β N ) | u | p N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | x | β 𝑑 x
= sup u N 1 ; u q = 1 N Φ N , q , β ( α ( 1 - β N ) | u | N N - 1 ) ( 1 + [ α ( 1 - β N ) ] p N ( 1 - 1 k ) ( 1 - β N ) | u | p N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | x | β 𝑑 x .

Let uDN,q(N), uN1, uq=1. Set

v ( x ) = ( α α N ) N - 1 N u ( λ x ) , λ = ( ( α α N ) N - 1 1 - ( α α N ) N - 1 N a ) q N 2 .

Then

v q = ( α α N ) N - 1 N 1 λ N q , v N = ( α α N ) N - 1 N u N ( α α N ) N - 1 N .

Hence vNa+vqN1. By the definition of B, we obtain

N Φ N , q , β ( α ( 1 - β N ) | u | N N - 1 ) ( 1 + [ α ( 1 - β N ) ] p N ( 1 - 1 k ) ( 1 - β N ) | u | p N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | x | β 𝑑 x
= N Φ N , q , β ( α ( 1 - β N ) | u ( λ x ) | N N - 1 ) ( 1 + [ α ( 1 - β N ) ] p N ( 1 - 1 k ) ( 1 - β N ) | u ( λ x ) | p N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | λ x | β d ( λ x )
= λ N - β N Φ N , q , β ( α N ( 1 - β N ) | v | N N - 1 ) ( 1 + [ α N ( 1 - β N ) ] p N ( 1 - 1 k ) ( 1 - β N ) | v | p N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | x | β 𝑑 x
( α α N ) N - 1 N q ( 1 - 1 k ) ( 1 - β N ) ( ( α α N ) N - 1 1 - ( α α N ) N - 1 N a ) q N 1 k ( 1 - β N ) B .

As a consequence,

(6.1) lim sup α α N ( 1 - α α N ) q N 1 k ( 1 - β N ) A ( α ) < .

Now, consider the Moser sequence. Recall that unN=1 and for sufficiently large n, say when nM1,

u n q q = 0 e - n N - β ( 1 ω N - 1 ) q N ( n N - β ) q ( N - 1 ) N r N - 1 𝑑 r + e - n N - β 1 ( N - β ω N - 1 n ) q N ( log ( 1 r ) ) q r N - 1 𝑑 r = O ( 1 n q N ) .

Now,

N Φ N , q , β ( α ( 1 - β N ) | u n | N N - 1 ) ( 1 + [ α ( 1 - β N ) ] p N ( 1 - 1 k ) ( 1 - β N ) | u n | p N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | x | β 𝑑 x
Φ N , q , β ( α ( 1 - β N ) ( 1 ω N - 1 ) 1 N - 1 ( n N - β ) ) 1 + [ α ( 1 - β N ) ] p N ( 1 - 1 k ) ( 1 - β N ) | ( 1 ω N - 1 ) 1 N ( n N - β ) N - 1 N | p N - 1 ( 1 - 1 k ) ( 1 - β N ) 0 e - n N - β r N - 1 - β 𝑑 r
Φ N , q , β ( α α N n ) n p N ( 1 - 1 k ) ( 1 - β N ) e - n e α α N n e - n n p N ( 1 - 1 k ) ( 1 - β N )

for sufficiently large nM2 where M2 is independent of α. Also, for ααN such that 11-ααN>10max{M1,M2}, we pick n=n(α) such that 1(1-ααN)n2, i.e., n11-ααN. Then

A ( α ) 1 u n q q ( 1 - β N ) N Φ N , q , β ( α ( 1 - β N ) | u n | N N - 1 ) ( 1 + [ α ( 1 - β N ) ] p N ( 1 - 1 k ) ( 1 - β N ) | u n | p N - 1 ( 1 - 1 k ) ( 1 - β N ) ) | x | β 𝑑 x
n q N ( 1 - β N ) e - 2 n p N ( 1 - 1 k ) ( 1 - β N ) C ( 1 1 - α α N ) [ q N - p N ( 1 - 1 k ) ] ( 1 - β N ) .

Hence

(6.2) lim inf α α N A ( α ) ( 1 - α α N ) [ q N - p N ( 1 - 1 k ) ] ( 1 - β N ) > 0 .

From (6.1) and (6.2), we have

lim sup α α N ( 1 - α α N ) q N 1 k ( 1 - β N ) ( 1 - α α N ) [ q N - p N ( 1 - 1 k ) ] ( 1 - β N ) <

or equivalently

p q .


Communicated by Julian Lopez Gomez


Funding source: US NSF grant DMS-1301595

Funding statement: Research of this work was partly supported by a US NSF grant DMS-1301595. The first author was partly supported by a fellowship from the Pacific Institute for the Mathematical Sciences and the second author was partly supported by a Simons Fellowship and collaboration grant from the Simons Foundation.

Acknowledgements

The authors wish to thank the referee for his careful reading and useful comments which have improved the exposition of the paper.

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Received: 2018-12-28
Revised: 2019-03-03
Accepted: 2019-03-05
Published Online: 2019-04-12
Published in Print: 2019-05-01

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