1 Introduction
			Variational method is one of the important tools in studying periodic orbits in the N-body problem. Actually, back to the 1890s, Poincaré had tried to apply variational methods to periodic orbits in the N-body problem, but he did not succeed because of two major difficulties [7]: “One is the lack of coercivity due to the vanishing at infinity of the force fields. The other is the possible existence of collision: the Lagrangian action stays finite even when some of the bodies are colliding.” Until recently in 2000, Chenciner and Montgomery [8] considered the action minimizer over a suitable symmetric loop space and successfully overcame the two difficulties. In their celebrated paper [8], they showed the existence of the figure-eight orbit in the planar equal-mass three-body problem. Following their ideas of imposing symmetry constraints or topological constraints, many new periodic orbits have been discovered numerically and proved rigorously [8, 7, 3, 4, 5, 9, 10].
			Besides the existence of periodic orbits, the variational method has widely been applied to study the multiplicity of periodic orbits, see [11, 19, 18, 17] and the references therein. Instead of fixing energy, we fix two prescribed configurations and show the multiplicity of periodic orbits from a new perspective. Inspired by the works [8, 7, 12, 13, 1], we study the existence and multiplicity of periodic orbits connecting two fixed configurations in (1.1): a collinear configuration and a double isosceles configuration in the planar equal-mass four-body problem. Let N=4 and m1=m2=m3=m4=1. Let the row vectors qi(t)=(qix(t),qiy(t))∈ℝ2 (i=1,2,3,4) be the trajectories of the body mi. Set
			
				
					
						
							
								
									
										q
										
										
											(
											t
											)
										
									
									=
									
										[
										
											
												
													
														
															q
															1
														
														
														
															(
															t
															)
														
													
												
											
											
												
													
														
															q
															2
														
														
														
															(
															t
															)
														
													
												
											
											
												
													
														
															q
															3
														
														
														
															(
															t
															)
														
													
												
											
											
												
													
														
															q
															4
														
														
														
															(
															t
															)
														
													
												
											
										
										]
									
								
								,
							
						
						
						
					
				
			
			which is a (4×2)-matrix path. The standard Lagrangian action functional is as follows:
			
				
					
						
							
								
									𝒜
									=
									
										
											∫
											0
											1
										
										
											
												[
												
													
														K
														
														
															(
															
																
																	q
																	˙
																
																
																
																	(
																	t
																	)
																
															
															)
														
													
													+
													
														U
														
														
															(
															
																q
																
																
																	(
																	t
																	)
																
															
															)
														
													
												
												]
											
											
											
												𝑑
												t
											
										
									
								
								,
							
						
						
						
					
				
			
			where
			
				
					
						
							
								
									
										
											K
											
											
												(
												
													
														q
														˙
													
													
													
														(
														t
														)
													
												
												)
											
										
										=
										
											
												
													1
													2
												
												
												
													
														∑
														
															i
															=
															1
														
														4
													
													
														
															m
															i
														
														
														
															
																|
																
																	
																		
																			q
																			˙
																		
																		i
																	
																	
																	
																		(
																		t
																		)
																	
																
																|
															
															2
														
													
												
											
											 
											and
										
									
									 
									
										
											U
											
											
												(
												
													q
													
													
														(
														t
														)
													
												
												)
											
										
										=
										
											
												∑
												
													1
													≤
													i
													<
													j
													≤
													4
												
											
											
												
													
														m
														i
													
													
													
														m
														j
													
												
												
													|
													
														
															
																q
																i
															
															
															
																(
																t
																)
															
														
														-
														
															
																q
																j
															
															
															
																(
																t
																)
															
														
													
													|
												
											
										
									
								
								.
							
						
						
						
					
				
			
			For a given value of θ∈(0,π2), the two prescribed configurations are defined by
			
				
					(1.1)
					
						
							
								
									
										
											Q
											start
										
										=
										
											[
											
												
													
														0
													
													
														
															a
															1
														
													
												
												
													
														0
													
													
														
															b
															1
														
													
												
												
													
														0
													
													
														
															-
															
																c
																1
															
														
													
												
												
													
														0
													
													
														
															
																c
																1
															
															-
															
																a
																1
															
															-
															
																b
																1
															
														
													
												
											
											]
										
									
									,
									
										
											Q
											end
										
										=
										
											
												[
												
													
														
															0
														
														
															
																a
																2
															
														
													
													
														
															0
														
														
															
																b
																2
															
														
													
													
														
															
																-
																
																	c
																	2
																
															
														
														
															
																-
																
																	
																		
																			
																				a
																				2
																			
																			+
																			
																				b
																				2
																			
																		
																		2
																	
																
															
														
													
													
														
															
																c
																2
															
														
														
															
																-
																
																	
																		
																			
																				a
																				2
																			
																			+
																			
																				b
																				2
																			
																		
																		2
																	
																
															
														
													
												
												]
											
											
											R
											
											
												(
												θ
												)
											
										
									
								
								,
							
						
						
						
					
				
			
			where
			
				
					
						
							
								
									
										R
										
										
											(
											θ
											)
										
									
									=
									
										[
										
											
												
													
														cos
														
														
															(
															θ
															)
														
													
												
												
													
														sin
														
														
															(
															θ
															)
														
													
												
											
											
												
													
														-
														
															sin
															
															
																(
																θ
																)
															
														
													
												
												
													
														cos
														
														
															(
															θ
															)
														
													
												
											
										
										]
									
								
								.
							
						
						
						
					
				
			
			Without loss of generality, we assume the center of mass to be at the origin. That is, q∈χ, where
			
				
					
						
							
								
									χ
									=
									
										{
										
											q
											∈
											
												ℝ
												
													4
													×
													2
												
											
										
										:
										
											
												
													∑
													
														i
														=
														1
													
													4
												
												
													
														m
														i
													
													
													
														q
														i
													
												
											
											=
											0
										
										}
									
								
								.
							
						
						
						
					
				
			
			Let a→=(a1,b1,c1,a2,b2,c2). Given θ∈(0,π2) and a→∈ℝ6, the position matrices Qstart and Qend in (1.1) are fixed. We set P(Qstart,Qend) to be the path space connecting the two fixed ends Qstart and Qend:
			
				
					
						
							
								
									
										P
										
										
											(
											
												Q
												start
											
											,
											
												Q
												end
											
											)
										
									
									:=
									
										{
										
											
												q
												
												
													(
													t
													)
												
											
											∈
											
												
													H
													1
												
												
												
													(
													
														[
														0
														,
														1
														]
													
													,
													χ
													)
												
											
										
										:
										
											
												
													q
													
													
														(
														0
														)
													
												
												=
												
													Q
													start
												
											
											,
											
												
													q
													
													
														(
														1
														)
													
												
												=
												
													Q
													end
												
											
										
										}
									
								
								.
							
						
						
						
					
				
			
			It is known that there exists an action minimizer 𝒫 connecting the two fixed ends, which satisfies
			
				
					
						
							
								
									
										𝒜
										
										
											(
											𝒫
											)
										
									
									=
									
										
											inf
											
												{
												q
												
													(
													t
													)
												
												∈
												P
												
													(
													
														Q
														start
													
													,
													
														Q
														end
													
													)
												
												}
											
										
										
										𝒜
									
								
								.
							
						
						
						
					
				
			
			In general, the minimizer 𝒫 is not a part of a periodic solution. In order to find a periodic or quasi-periodic solution, we consider the following free boundary value problem:
			
				
					
						
							
								
									
										localmin
										
											{
											
												a
												→
											
											∈
											
												ℝ
												6
											
											}
										
									
									
										
											inf
											
												{
												q
												
													(
													t
													)
												
												∈
												P
												
													(
													
														Q
														start
													
													,
													
														Q
														end
													
													)
												
												}
											
										
										
										𝒜
									
								
								.
							
						
						
						
					
				
			
			For each fixed value of θ∈(0,π2), it is interesting to understand the existence and multiplicity of periodic orbits connecting Qstart and Qend defined by (1.1). Actually, we can show the existence of an action minimizer 𝒫0, which minimizes 𝒜 over a→∈ℝ6. The following theorem implies that 𝒫0 is a classical solution and also a part of a periodic or quasi-periodic orbit. Its proof follows by Theorem 2.1, Theorem 3.1 and Theorem 4.1. One of the main difficulties in proving Theorem 1.1 is to exclude possible triple collisions in 𝒫0. For this purpose, a local deformation argument is introduced in Lemma 3.4, which discusses all possible central configurations case by case.
			
				Theorem 1.1.
				
					For any given θ∈(0,π2), there exists a noncollision minimizing path P0≡P0(t∈[0,1]), which satisfies
				
				
					
						
							
								
									
										
											𝒜
											
											
												(
												
													𝒫
													0
												
												)
											
										
										=
										
											
												inf
												
													{
													
														a
														→
													
													∈
													
														ℝ
														6
													
													}
												
											
											
											
												
													inf
													
														{
														q
														
															(
															t
															)
														
														∈
														P
														
															(
															
																Q
																start
															
															,
															
																Q
																end
															
															)
														
														}
													
												
												
												𝒜
											
										
									
									.
								
							
							
							
						
					
				
				
					Furthermore, if θπ is rational, the minimizer P0 can be extended to a periodic orbit. Otherwise, it can be extended to a quasi-periodic orbit.
				
			 
			By taking θ=π5 in (1.1), a sample picture of the minimizer 𝒫0(t∈[0,1]) and its periodic extension is given in Figure 1.
			
			In order to find local action minimizers connecting Qstart and Qend in (1.1), we define several closed subsets in ℝ6 and minimize 𝒜 over a→ in these subsets. So 24 subsets are defined as follows. We assume a2≥b2 and c2≥0 in (1.1), which is equivalent to fix a partial order of the bodies on the configuration Qend. For the collinear configuration Qstart, it has 24 different orders. Hence, 24 different subsets Γi(i=1,2…,24) can be defined by setting a2≥b2, c2≥0 in Qend and fixing the order of the four bodies in Qstart. For example, Γ1 is defined by
			
				
					
						
							
								
									
										
											Γ
											1
										
										=
										
											{
											
												a
												→
											
											:
											
												
													
														a
														1
													
													≤
													
														b
														1
													
													≤
													
														-
														
															c
															1
														
													
													≤
													
														
															c
															1
														
														-
														
															a
															1
														
														-
														
															b
															1
														
													
												
												,
												
													
														
															a
															2
														
														≥
														
															b
															2
														
													
													,
													
														
															c
															2
														
														≥
														0
													
												
											
											}
										
									
									,
								
							
							
							
						
					
				
			
			which implies that the y-components of the four bodies at t=0 satisfy
			
				
					
						
							
								
									
										
											
												q
												
													1
													
													y
												
											
											
											
												(
												0
												)
											
										
										≤
										
											
												q
												
													2
													
													y
												
											
											
											
												(
												0
												)
											
										
										≤
										
											
												q
												
													3
													
													y
												
											
											
											
												(
												0
												)
											
										
										≤
										
											
												q
												
													4
													
													y
												
											
											
											
												(
												0
												)
											
										
									
									.
								
							
							
							
						
					
				
			
			By Theorem 2.1, for each Γi(i=1,2,…,24), there exists an action minimizer 𝒫Γi∈H1([0,1],χ) connecting Qstart and Qend in (1.1):
			
				
					
						
							
								
									
										
											𝒜
											
											
												(
												
													𝒫
													
														Γ
														i
													
												
												)
											
										
										=
										
											
												inf
												
													{
													
														a
														→
													
													∈
													
														Γ
														i
													
													}
												
											
											
											
												
													inf
													
														{
														q
														
															(
															t
															)
														
														∈
														P
														
															(
															
																Q
																start
															
															,
															
																Q
																end
															
															)
														
														}
													
												
												
												𝒜
											
										
									
									.
								
							
							
							
						
					
				
			
			It is clear that the 24 local action minimizers are all different. However, some of them may contain collisions on Qstart or Qend. Furthermore, different action minimizers can be extended to the same solution of the N-body problem. By applying the first variation formulas and analyzing the equivalence relation between action minimizers 𝒫Γi(i=1,2,…,24), we show the following:
			
				Theorem 1.2.
				
					Assume that θ∈(0,π2) and θπ is rational. If all the minimizers PΓi(i=1,2,…,24) are classical solutions of the N-body problem, then there are sixteen different periodic orbits connecting Qstart and Qend defined in (1.1).
				
			 
			The proof of Theorem 1.2 can be found in Theorem 5.1. As a numerical evidence, we draw the motions of all the sixteen periodic orbits for θ=π5.
			
				Structure of the paper.
				The paper is organized as follows. Section 2 introduces a general coercivity result and shows the existence of 24 local action minimizers. Section 3 shows that the minimizer 𝒫0 is free of collision. In Section 4, we prove that 𝒫0 can be extended to a periodic or quasi-periodic orbit. In Section 5, we show that under appropriate assumptions, the 24 local action minimizers can be extended to sixteen nontrivial periodic orbits. Numerical evidences for θ=π5 are presented in the end.
			
		
		
			
			2 Variational Settings and Coercivity
			In this section, we introduce a general coercivity result (Theorem 2.1) of the Lagrangian action functional 𝒜 under structural prescribed boundary conditions in the N-body problem. Let χ={q∈ℝN×d:∑i=1Nmiqi=0}. We set
			
				
					
						
							
								
									
										
											Q
											start
										
										=
										
											[
											
												
													
														
															
																q
																1
															
															
															
																(
																
																	a
																	1
																
																,
																…
																,
																
																	a
																	k
																
																)
															
														
													
												
												
													
														⋮
													
												
												
													
														
															
																q
																N
															
															
															
																(
																
																	a
																	1
																
																,
																…
																,
																
																	a
																	k
																
																)
															
														
													
												
											
											]
										
									
									,
									
										
											Q
											end
										
										=
										
											[
											
												
													
														
															
																q
																1
															
															
															
																(
																
																	b
																	1
																
																,
																…
																,
																
																	b
																	s
																
																)
															
														
													
												
												
													
														⋮
													
												
												
													
														
															
																q
																N
															
															
															
																(
																
																	b
																	1
																
																,
																…
																,
																
																	b
																	s
																
																)
															
														
													
												
											
											]
										
									
								
								,
							
						
						
						
					
				
			
			where qi∈ℝd(i=1,2,…,N,d=1,2,or3) are row vectors, and Qstart,Qend∈χ. Our variational argument is a two-step minimizing procedure. First, we consider a fixed-end boundary value problem, which is also known as the Bolza problem. For given values of a1,…,ak and b1,…,bs, the two matrices Qstart and Qend are fixed. There exists an action minimizer 𝒫, which satisfies
			
				
					
						
							
								
									
										𝒜
										
										
											(
											𝒫
											)
										
									
									=
									
										
											inf
											
												{
												q
												
													(
													t
													)
												
												∈
												P
												
													(
													
														Q
														start
													
													,
													
														Q
														end
													
													)
												
												}
											
										
										
										𝒜
									
									=
									
										
											inf
											
												{
												q
												
													(
													t
													)
												
												∈
												P
												
													(
													
														Q
														start
													
													,
													
														Q
														end
													
													)
												
												}
											
										
										
										
											
												∫
												0
												1
											
											
												
													[
													
														
															K
															
															
																(
																
																	
																		q
																		˙
																	
																	
																	
																		(
																		t
																		)
																	
																
																)
															
														
														+
														
															U
															
															
																(
																
																	q
																	
																	
																		(
																		t
																		)
																	
																
																)
															
														
													
													]
												
												
												
													𝑑
													t
												
											
										
									
								
								,
							
						
						
						
					
				
			
			where P(Qstart,Qend) is defined as follows:
			
				
					
						
							
								
									
										P
										
										
											(
											
												Q
												start
											
											,
											
												Q
												end
											
											)
										
									
									:=
									
										{
										
											
												q
												
												
													(
													t
													)
												
											
											∈
											
												
													H
													1
												
												
												
													(
													
														[
														0
														,
														1
														]
													
													,
													χ
													)
												
											
										
										:
										
											
												
													q
													
													
														(
														0
														)
													
												
												=
												
													Q
													start
												
											
											,
											
												
													q
													
													
														(
														1
														)
													
												
												=
												
													Q
													end
												
											
										
										}
									
								
								.
							
						
						
						
					
				
			
			If one wants 𝒫 to be a part of a periodic solution, the boundaries must be special and they should meet certain structural prescribed boundary conditions (SPBC). Hence, we introduce a second minimizing procedure. Instead of fixing the boundaries, we free several parameters on the boundaries q(0)=Qstart and q(1)=Qend. The Lagrangian action functional is then minimized over these parameters. The resulting minimizing path may be extended to a periodic or quasi-periodic solution. There are mainly three challenges to show the existence of such classical solutions. The first one is the coercivity of the Lagrangian action functional under the boundary constraints. The second one is to show the minimizer is collision-free on the boundaries. The third one is whether the minimizing path can be extended to a periodic or quasi-periodic solution. With an appropriate choice of SPBC, all the three challenges can be resolved. A general coercivity theorem [1] is introduced here to resolve the first challenge. For the reader’s convenience, a proof of the theorem is also given. The other two challenges will be resolved in Section 3 and Section 4.
			
				Theorem 2.1.
				
					Let
				
				
					
						
							
								
									
										
											
												Q
												start
											
											=
											
												[
												
													
														
															
																
																	q
																	1
																
																
																
																	(
																	
																		a
																		1
																	
																	,
																	…
																	,
																	
																		a
																		k
																	
																	)
																
															
														
													
													
														
															⋮
														
													
													
														
															
																
																	q
																	N
																
																
																
																	(
																	
																		a
																		1
																	
																	,
																	…
																	,
																	
																		a
																		k
																	
																	)
																
															
														
													
												
												]
											
										
										,
										
											
												Q
												end
											
											=
											
												[
												
													
														
															
																
																	q
																	1
																
																
																
																	(
																	
																		b
																		1
																	
																	,
																	…
																	,
																	
																		b
																		s
																	
																	)
																
															
														
													
													
														
															⋮
														
													
													
														
															
																
																	q
																	N
																
																
																
																	(
																	
																		b
																		1
																	
																	,
																	…
																	,
																	
																		b
																		s
																	
																	)
																
															
														
													
												
												]
											
										
									
									,
								
							
							
							
						
					
				
				
					where Qstart,Qend∈χ, qi∈Rd, i=1,…,N, and a1,…,ak,b1,…,bs are independent variables. The matrix Qstart is linear with respect to ai(i=1,2,…,k) and Qend is linear with respect to bj(j=1,2,…,s). Let (a1,…,ak)∈S1,(b1,…,bs)∈S2, where S1⊂Rk and S2⊂Rs are closed subsets. Set S1∪S2=S. Assume that
				
				
					
						
							
								
									
										
											
												{
												
													Q
													start
												
												:
												
													
														(
														
															a
															1
														
														,
														…
														,
														
															a
															k
														
														)
													
													∈
													
														ℝ
														k
													
												
												}
											
											∩
											
												{
												
													Q
													end
												
												:
												
													
														(
														
															b
															1
														
														,
														…
														,
														
															b
															s
														
														)
													
													∈
													
														ℝ
														s
													
												
												}
											
										
										=
										
											{
											
												0
												→
											
											}
										
									
									.
								
							
							
							
						
					
				
				
					Then there exist a path sequence {Pnl} and a minimizer P0 in H1([0,1],χ) such that for each nl,
				
				
					
						
							
								
									
										
											
												𝒜
												
												
													(
													
														𝒫
														
															n
															l
														
													
													)
												
											
										
										
											
												
													
													=
													
														
															inf
															
																{
																q
																
																	(
																	0
																	)
																
																=
																
																	Q
																	start
																
																,
																q
																
																	(
																	1
																	)
																
																=
																
																	Q
																	end
																
																,
																q
																
																	(
																	t
																	)
																
																∈
																
																	H
																	1
																
																
																	(
																	
																		[
																		0
																		,
																		1
																		]
																	
																	,
																	χ
																	)
																
																,
																
																	a
																	i
																
																=
																
																	a
																	
																		i
																		
																			n
																			l
																		
																	
																
																,
																
																	b
																	j
																
																=
																
																	
																		b
																		
																			j
																			
																				n
																				l
																			
																		
																	
																
																
																	(
																	i
																	=
																	1
																	,
																	…
																	,
																	k
																	,
																	j
																	=
																	1
																	,
																	…
																	,
																	s
																	)
																
																}
															
														
														
														𝒜
													
												
												,
											
										
									
									
										
											
												𝒜
												
												
													(
													
														𝒫
														0
													
													)
												
											
										
										
											
												
												=
												
													
														inf
														
															{
															
																(
																
																	a
																	1
																
																,
																…
																,
																
																	a
																	k
																
																,
																
																	b
																	1
																
																,
																…
																,
																
																	b
																	s
																
																)
															
															∈
															𝒮
															}
														
													
													
													
														
															inf
															
																{
																q
																
																	(
																	0
																	)
																
																=
																
																	Q
																	start
																
																,
																q
																
																	(
																	1
																	)
																
																=
																
																	Q
																	end
																
																,
																q
																
																	(
																	t
																	)
																
																∈
																
																	H
																	1
																
																
																	(
																	
																		[
																		0
																		,
																		1
																		]
																	
																	,
																	χ
																	)
																
																}
															
														
														
														𝒜
													
												
											
										
									
									
										
										
											
												
													
													=
													
														
															inf
															
																{
																q
																
																	(
																	0
																	)
																
																=
																
																	Q
																	start
																
																,
																q
																
																	(
																	1
																	)
																
																=
																
																	Q
																	end
																
																,
																q
																
																	(
																	t
																	)
																
																∈
																
																	H
																	1
																
																
																	(
																	
																		[
																		0
																		,
																		1
																		]
																	
																	,
																	χ
																	)
																
																,
																
																	a
																	i
																
																=
																
																	a
																	
																		i
																		0
																	
																
																,
																
																	b
																	j
																
																=
																
																	
																		b
																		
																			j
																			0
																		
																	
																
																
																	(
																	i
																	=
																	1
																	,
																	…
																	,
																	k
																	,
																	j
																	=
																	1
																	,
																	…
																	,
																	s
																	)
																
																}
															
														
														
														𝒜
													
												
												.
											
										
									
								
							
							
							
						
					
				
				
					For t∈[0,1], Pnl(t) converges to P0(t) uniformly. In particular,
				
				
					
						
							
								
									
										
											
												
													lim
													
														
															n
															l
														
														→
														∞
													
												
												
												
													a
													
														i
														
															n
															l
														
													
												
											
											=
											
												a
												
													i
													0
												
											
										
										,
										
											
												
													
														lim
														
															
																n
																l
															
															→
															∞
														
													
													
													
														b
														
															j
															
																n
																l
															
														
													
												
												=
												
													b
													
														j
														0
													
												
											
											,
											
												
													i
													=
													
														1
														,
														…
														,
														k
													
												
												,
												
													j
													=
													
														1
														,
														…
														,
														s
													
												
											
										
									
									.
								
							
							
							
						
					
				
			 
			
				Proof.
				Note that L=K+U≥0, hence there exists some M0≥0 such that
				
					
						
							
								
									
										
											
												inf
												
													{
													
														(
														
															a
															1
														
														,
														…
														,
														
															a
															k
														
														,
														
															b
															1
														
														,
														…
														,
														
															b
															s
														
														)
													
													∈
													𝒮
													}
												
											
											
											
												
													inf
													
														{
														q
														
															(
															0
															)
														
														=
														
															Q
															start
														
														,
														q
														
															(
															1
															)
														
														=
														
															Q
															end
														
														,
														q
														
															(
															t
															)
														
														∈
														
															H
															1
														
														
															(
															
																[
																0
																,
																1
																]
															
															,
															χ
															)
														
														}
													
												
												
												𝒜
											
										
										=
										
											M
											0
										
									
									.
								
							
							
							
						
					
				
				The proof follows by the Arzelà–Ascoli theorem. Basically, we can find a sequence 𝒫n, such that the action of the sequence 𝒜(𝒫n) approaches M0. Then we show the uniform boundedness and equicontinuity of the sequence. Hence, by the Arzelà–Ascoli theorem, there is a subsequence 𝒫nl which converges uniformly to a minimizer 𝒫0. Note that there exist sequences ain and bjn such that the minimum action value M0 can be reached by a path sequence 𝒫n∈H1([0,1],χ), which satisfies
				
					
						
							
								
									
										
											𝒜
											
											
												(
												
													𝒫
													n
												
												)
											
										
										=
										
											
												inf
												
													{
													q
													
														(
														0
														)
													
													=
													
														Q
														start
													
													,
													q
													
														(
														1
														)
													
													=
													
														Q
														end
													
													,
													q
													
														(
														t
														)
													
													∈
													
														H
														1
													
													
														(
														
															[
															0
															,
															1
															]
														
														,
														χ
														)
													
													,
													
														a
														i
													
													=
													
														a
														
															i
															n
														
													
													,
													
														b
														j
													
													=
													
														
															b
															
																j
																n
															
														
													
													
														(
														i
														=
														1
														,
														…
														,
														k
														,
														j
														=
														1
														,
														…
														,
														s
														)
													
													}
												
											
											
											𝒜
										
									
									,
								
							
							
							
						
					
				
				and 𝒜(𝒫n)∈[M0,M0+12n]. It is clear that 𝒜(𝒫n)∈[M0,M0+1] for all n∈ℕ.
				Next, we show the path sequence {𝒫n} is uniformly bounded. Let q(n)(t) be the position matrix path for {𝒫n}. We rewrite Qstart and Qend as (dN×1)-vectors:
				
					
						
							
								
									
										
											
												
													Q
													start
												
												~
											
											=
											
												[
												
													
														
															
																
																	q
																	1
																	T
																
																
																
																	(
																	
																		a
																		1
																	
																	,
																	…
																	,
																	
																		a
																		k
																	
																	)
																
															
														
													
													
														
															⋮
														
													
													
														
															
																
																	q
																	N
																	T
																
																
																
																	(
																	
																		a
																		1
																	
																	,
																	…
																	,
																	
																		a
																		k
																	
																	)
																
															
														
													
												
												]
											
										
										,
										
											
												
													Q
													end
												
												~
											
											=
											
												[
												
													
														
															
																
																	q
																	1
																	T
																
																
																
																	(
																	
																		b
																		1
																	
																	,
																	…
																	,
																	
																		b
																		s
																	
																	)
																
															
														
													
													
														
															⋮
														
													
													
														
															
																
																	q
																	N
																	T
																
																
																
																	(
																	
																		b
																		1
																	
																	,
																	…
																	,
																	
																		b
																		s
																	
																	)
																
															
														
													
												
												]
											
										
									
									.
								
							
							
							
						
					
				
				Similarly, we can rewrite q(n)(t) as a (dN×1)-vector path q~(n)(t). By assumption, the two linear spaces satisfy
				
					
						
							
								
									
										
											
												{
												
													Q
													start
												
												:
												
													
														(
														
															a
															1
														
														,
														…
														,
														
															a
															k
														
														)
													
													∈
													
														ℝ
														k
													
												
												}
											
											∩
											
												{
												
													Q
													end
												
												:
												
													
														(
														
															b
															1
														
														,
														…
														,
														
															b
															s
														
														)
													
													∈
													
														ℝ
														s
													
												
												}
											
										
										=
										
											{
											
												0
												→
											
											}
										
									
									.
								
							
							
							
						
					
				
				Hence, Uk≡{Qstart~:(a1,…,ak)∈ℝk} is a k-dimensional linear space, Vs≡{Qend~:(b1,…,bs)∈ℝs} is a s-dimensional linear space, and Uk∩Vs={0}. Let {u1,…,uk} be an orthonormal basis of Uk and let {v1,…,vs} be an orthonormal basis of Vs.
				For any nonzero vectors u→∈Uk and v→∈Vs, there exist constants gi,hj(1≤i≤k, 1≤j≤s) such that
				
					
						
							
								
									
										
											
												
													u
													→
												
												
													|
													
														u
														→
													
													|
												
											
											=
											
												
													
														g
														1
													
													
													
														u
														1
													
												
												+
												…
												+
												
													
														g
														k
													
													
													
														u
														k
													
												
											
										
										,
										
											
												
													∑
													
														i
														=
														1
													
													k
												
												
													g
													i
													2
												
											
											=
											1
										
									
									,
								
							
							
							
						
					
				
				and
				
					
						
							
								
									
										
											
												
													v
													→
												
												
													|
													
														v
														→
													
													|
												
											
											=
											
												
													
														h
														1
													
													
													
														v
														1
													
												
												+
												…
												+
												
													
														h
														s
													
													
													
														v
														s
													
												
											
										
										,
										
											
												
													∑
													
														j
														=
														1
													
													s
												
												
													h
													j
													2
												
											
											=
											1
										
									
									.
								
							
							
							
						
					
				
				Note that gi and hj(1≤i≤k,1≤j≤s) satisfy ∑i=1kgi2=∑j=1shj2=1. So they are on a compact set. It follows that the inner product of u→|u→| and v→|v→|,
				
					
						
							
								
									
										
											〈
											
												
													u
													→
												
												
													|
													
														u
														→
													
													|
												
											
											,
											
												
													v
													→
												
												
													|
													
														v
														→
													
													|
												
											
											〉
										
										=
										
											
												∑
												
													
														1
														≤
														i
														≤
														k
													
													,
													
														 1
														≤
														j
														≤
														s
													
												
											
											
												
													g
													i
												
												
												
													h
													j
												
												
												
													〈
													
														u
														i
													
													,
													
														v
														j
													
													〉
												
											
										
										=
										
											cos
											
											
												(
												
													u
													→
												
												,
												
													v
													→
												
												)
											
										
									
									,
								
							
							
							
						
					
				
				can reach its maximum K0. If K0=1, there exist two vectors
				
					
						
							
								
									
										
											u
											→
										
										∈
										
											U
											k
										
										=
										
											{
											
												
													Q
													start
												
												~
											
											:
											
												
													(
													
														a
														1
													
													,
													…
													,
													
														a
														k
													
													)
												
												∈
												
													ℝ
													k
												
											
											}
										
									
									 
									
										
											and
											 
											
												v
												→
											
										
										∈
										
											V
											s
										
										=
										
											{
											
												
													Q
													end
												
												~
											
											:
											
												
													(
													
														b
														1
													
													,
													…
													,
													
														b
														s
													
													)
												
												∈
												
													ℝ
													s
												
											
											}
										
									
								
							
							
							
						
					
				
				such that u→|u→|=v→|v→|∈Uk∩Vs. Contradiction! Hence,
				
					
						(2.1)
						
							
								
									
										
											
												cos
												
												
													(
													
														u
														→
													
													,
													
														v
														→
													
													)
												
											
											≤
											
												K
												0
											
											<
											1
										
										 
										
											
												
													for any nonzero vectors 
													
													
														u
														→
													
												
												∈
												
													U
													k
												
											
											,
											
												
													v
													→
												
												∈
												
													V
													s
												
											
										
									
									.
								
							
							
							
						
					
				
				On the other hand, 𝒜(𝒫n)≤M0+1. If 0≤t1<t2≤1, we have
				
					
						
							
								
									
										
											
												
													m
													j
												
												
												
													
														|
														
															
																
																	q
																	j
																	
																		(
																		n
																		)
																	
																
																
																
																	(
																	
																		t
																		2
																	
																	)
																
															
															-
															
																
																	q
																	j
																	
																		(
																		n
																		)
																	
																
																
																
																	(
																	
																		t
																		1
																	
																	)
																
															
														
														|
													
													2
												
											
											
												2
												
												d
												
												
													(
													
														
															t
															2
														
														-
														
															t
															1
														
													
													)
												
											
										
										≤
										
											
												∫
												
													t
													1
												
												
													t
													2
												
											
											
												
													
														
															
																m
																j
															
															
															
																
																	|
																	
																		
																			
																				q
																				˙
																			
																			j
																		
																		
																		
																			(
																			t
																			)
																		
																	
																	|
																
																2
															
														
														2
													
												
												
												
													𝑑
													t
												
											
										
										≤
										
											𝒜
											
											
												(
												
													𝒫
													n
												
												)
											
										
										≤
										
											
												M
												0
											
											+
											1
										
									
									.
								
							
							
							
						
					
				
				This implies that for any 1≤j≤N and any t1, t2 satisfying 0≤t1<t2≤1,
				
					
						(2.2)
						
							
								
									
										
											|
											
												
													
														q
														j
														
															(
															n
															)
														
													
													
													
														(
														
															t
															2
														
														)
													
												
												-
												
													
														q
														j
														
															(
															n
															)
														
													
													
													
														(
														
															t
															1
														
														)
													
												
											
											|
										
										≤
										
											
												
													2
													
													d
													
													
														(
														
															
																t
																2
															
															-
															
																t
																1
															
														
														)
													
													
													
														(
														
															
																M
																0
															
															+
															1
														
														)
													
												
												
													m
													j
												
											
										
									
									.
								
							
							
							
						
					
				
				Let m*=min{m1,m2,…,mN}. Then for all 1≤j≤N,
				
					
						
							
								
									
										
											|
											
												
													
														q
														j
														
															(
															n
															)
														
													
													
													
														(
														
															t
															2
														
														)
													
												
												-
												
													
														q
														j
														
															(
															n
															)
														
													
													
													
														(
														
															t
															1
														
														)
													
												
											
											|
										
										≤
										
											
												
													2
													
													d
													
													
														(
														
															
																M
																0
															
															+
															1
														
														)
													
												
												
													m
													*
												
											
										
									
									.
								
							
							
							
						
					
				
				In each 𝒫n, its element
				
					
						
							
								
									
										
											q
											
												(
												n
												)
											
										
										
										
											(
											t
											)
										
									
									=
									
										[
										
											
												
													
														q
														1
														
															(
															n
															)
														
													
												
											
											
												
													⋮
												
											
											
												
													
														q
														N
														
															(
															n
															)
														
													
												
											
										
										]
									
								
							
							
							
						
					
				
				can be rewritten as
				
					
						
							
								
									
										
											
												
													q
													~
												
												
													(
													n
													)
												
											
											
											
												(
												t
												)
											
										
										=
										
											[
											
												
													
														
															
																(
																
																	q
																	1
																	
																		(
																		n
																		)
																	
																
																)
															
															T
														
													
												
												
													
														⋮
													
												
												
													
														
															
																(
																
																	q
																	N
																	
																		(
																		n
																		)
																	
																
																)
															
															T
														
													
												
											
											]
										
									
									.
								
							
							
							
						
					
				
				Then for any t∈[0,1],
				
					
						(2.3)
						
							
								
									
										
											|
											
												
													
														
															q
															~
														
														
															(
															n
															)
														
													
													
													
														(
														0
														)
													
												
												-
												
													
														
															q
															~
														
														
															(
															n
															)
														
													
													
													
														(
														t
														)
													
												
											
											|
										
										≤
										
											N
											
											
												
													
														2
														
														d
														
														
															(
															
																
																	M
																	0
																
																+
																1
															
															)
														
													
													
														m
														*
													
												
											
										
									
									.
								
							
							
							
						
					
				
				Note that by (2.1), the angle between any two nonzero vectors
				
					
						
							
								
									
										
											
												
													q
													~
												
												
													(
													n
													)
												
											
											
											
												(
												0
												)
											
										
										∈
										
											{
											
												
													Q
													start
												
												~
											
											:
											
												
													(
													
														a
														1
													
													,
													…
													,
													
														a
														k
													
													)
												
												∈
												
													𝒮
													1
												
											
											}
										
									
									,
									
										
											
												
													q
													~
												
												
													(
													n
													)
												
											
											
											
												(
												1
												)
											
										
										∈
										
											{
											
												
													Q
													end
												
												~
											
											:
											
												
													(
													
														b
														1
													
													,
													…
													,
													
														b
														s
													
													)
												
												∈
												
													𝒮
													2
												
											
											}
										
									
								
							
							
							
						
					
				
				satisfies
				
					
						
							
								
									
										
											〈
											
												
													
														
															q
															~
														
														
															(
															n
															)
														
													
													
													
														(
														0
														)
													
												
												
													|
													
														
															
																q
																~
															
															
																(
																n
																)
															
														
														
														
															(
															0
															)
														
													
													|
												
											
											,
											
												
													
														
															q
															~
														
														
															(
															n
															)
														
													
													
													
														(
														1
														)
													
												
												
													|
													
														
															
																q
																~
															
															
																(
																n
																)
															
														
														
														
															(
															1
															)
														
													
													|
												
											
											〉
										
										=
										
											cos
											
											
												(
												
													
														
															q
															~
														
														
															(
															n
															)
														
													
													
													
														(
														0
														)
													
												
												,
												
													
														
															q
															~
														
														
															(
															n
															)
														
													
													
													
														(
														1
														)
													
												
												)
											
										
										≤
										
											K
											0
										
										<
										1
									
									.
								
							
							
							
						
					
				
				It follows that
				
					
						
							
								
									
										
											
												
													2
													
													d
													
													
														N
														2
													
													
													
														(
														
															
																M
																0
															
															+
															1
														
														)
													
												
												
													m
													*
												
											
										
										≥
										
											
												|
												
													
														
															
																q
																~
															
															
																(
																n
																)
															
														
														
														
															(
															0
															)
														
													
													-
													
														
															
																q
																~
															
															
																(
																n
																)
															
														
														
														
															(
															1
															)
														
													
												
												|
											
											2
										
									
								
								
								
							
						
						
							
								
									
										
										=
										
											
												
													
														|
														
															
																
																	q
																	~
																
																
																	(
																	n
																	)
																
															
															
															
																(
																0
																)
															
														
														|
													
													2
												
												+
												
													
														|
														
															
																
																	q
																	~
																
																
																	(
																	n
																	)
																
															
															
															
																(
																1
																)
															
														
														|
													
													2
												
											
											-
											
												2
												
												
													|
													
														
															
																q
																~
															
															
																(
																n
																)
															
														
														
														
															(
															0
															)
														
													
													|
												
												
												
													|
													
														
															
																q
																~
															
															
																(
																n
																)
															
														
														
														
															(
															1
															)
														
													
													|
												
												
												
													cos
													
													
														(
														
															
																
																	q
																	~
																
																
																	(
																	n
																	)
																
															
															
															
																(
																0
																)
															
														
														,
														
															
																
																	q
																	~
																
																
																	(
																	n
																	)
																
															
															
															
																(
																1
																)
															
														
														)
													
												
											
										
									
								
								
								
							
						
						
							
								
									
										
										≥
										
											
												
													
														|
														
															
																
																	q
																	~
																
																
																	(
																	n
																	)
																
															
															
															
																(
																0
																)
															
														
														|
													
													2
												
												+
												
													
														|
														
															
																
																	q
																	~
																
																
																	(
																	n
																	)
																
															
															
															
																(
																1
																)
															
														
														|
													
													2
												
											
											-
											
												2
												
												
													K
													0
												
												
												
													|
													
														
															
																q
																~
															
															
																(
																n
																)
															
														
														
														
															(
															0
															)
														
													
													|
												
												
												
													|
													
														
															
																q
																~
															
															
																(
																n
																)
															
														
														
														
															(
															1
															)
														
													
													|
												
											
										
									
								
								
								
							
						
						
							
								
									
										
										=
										
											
												
													[
													
														
															
																K
																0
															
															
															
																|
																
																	
																		
																			q
																			~
																		
																		
																			(
																			n
																			)
																		
																	
																	
																	
																		(
																		0
																		)
																	
																
																|
															
														
														-
														
															|
															
																
																	
																		q
																		~
																	
																	
																		(
																		n
																		)
																	
																
																
																
																	(
																	1
																	)
																
															
															|
														
													
													]
												
												2
											
											+
											
												
													(
													
														1
														-
														
															K
															0
															2
														
													
													)
												
												
												
													
														|
														
															
																
																	q
																	~
																
																
																	(
																	n
																	)
																
															
															
															
																(
																0
																)
															
														
														|
													
													2
												
											
										
									
								
								
								
							
						
						
							
								
									
										
											
											≥
											
												
													(
													
														1
														-
														
															K
															0
															2
														
													
													)
												
												
												
													
														|
														
															
																
																	q
																	~
																
																
																	(
																	n
																	)
																
															
															
															
																(
																0
																)
															
														
														|
													
													2
												
											
										
										.
									
								
								
								
							
						
					
				
				Hence
				
					
						(2.4)
						
							
								
									
										
											|
											
												
													
														q
														~
													
													
														(
														n
														)
													
												
												
												
													(
													0
													)
												
											
											|
										
										≤
										
											
												
													2
													
													d
													
													
														N
														2
													
													
													
														(
														
															
																M
																0
															
															+
															1
														
														)
													
												
												
													
														m
														*
													
													
													
														(
														
															1
															-
															
																K
																0
																2
															
														
														)
													
												
											
										
									
									.
								
							
							
							
						
					
				
				By inequalities (2.3) and (2.4), it follows that for any t∈[0,1],
				
					
						
							
								
									
										
											|
											
												
													
														q
														~
													
													
														(
														n
														)
													
												
												
												
													(
													t
													)
												
											
											|
										
										≤
										
											
												|
												
													
														
															
																q
																~
															
															
																(
																n
																)
															
														
														
														
															(
															0
															)
														
													
													-
													
														
															
																q
																~
															
															
																(
																n
																)
															
														
														
														
															(
															t
															)
														
													
												
												|
											
											+
											
												|
												
													
														
															q
															~
														
														
															(
															n
															)
														
													
													
													
														(
														0
														)
													
												
												|
											
										
										≤
										
											
												N
												
												
													
														
															2
															
															d
															
															
																(
																
																	
																		M
																		0
																	
																	+
																	1
																
																)
															
														
														
															m
															*
														
													
												
											
											+
											
												N
												
												
													
														
															2
															
															d
															
															
																(
																
																	
																		M
																		0
																	
																	+
																	1
																
																)
															
														
														
															
																m
																*
															
															
															
																(
																
																	1
																	-
																	
																		K
																		0
																		2
																	
																
																)
															
														
													
												
											
										
									
									,
								
							
							
							
						
					
				
				which is a uniform bound for |q~(n)(t)|. Therefore, the path sequence 𝒫n=𝒫n(t) is uniformly bounded.
				Next, we show the path sequence {𝒫n=𝒫n(t)} is equicontinuous. In fact, by inequality (2.2),
				
					
						
							
								
									
										
											|
											
												
													
														q
														j
														
															(
															n
															)
														
													
													
													
														(
														
															t
															2
														
														)
													
												
												-
												
													
														q
														j
														
															(
															n
															)
														
													
													
													
														(
														
															t
															1
														
														)
													
												
											
											|
										
										≤
										
											
												
													
														2
														
														d
														
														
															(
															
																
																	M
																	0
																
																+
																1
															
															)
														
													
													
														m
														*
													
												
											
											
											
												
													|
													
														
															t
															2
														
														-
														
															t
															1
														
													
													|
												
												
													1
													2
												
											
										
									
									.
								
							
							
							
						
					
				
				Then for any ϵ>0, let δ=ϵ2m*2d(M0+1). Whenever |t2-t1|≤δ, the following inequality holds:
				
					
						
							
								
									
										
											|
											
												
													
														q
														j
														
															(
															n
															)
														
													
													
													
														(
														
															t
															2
														
														)
													
												
												-
												
													
														q
														j
														
															(
															n
															)
														
													
													
													
														(
														
															t
															1
														
														)
													
												
											
											|
										
										≤
										
											
												
													
														2
														
														d
														
														
															(
															
																
																	M
																	0
																
																+
																1
															
															)
														
													
													
														m
														*
													
												
											
											
											
												
													|
													
														
															t
															2
														
														-
														
															t
															1
														
													
													|
												
												
													1
													2
												
											
										
										=
										ϵ
									
									.
								
							
							
							
						
					
				
				It implies that for each j=1,2,…,N, qj(n)(t) is equicontinuous. It follows that the path sequence 𝒫n is equicontinuous.
				By the Arzelà–Ascoli theorem, there exists a subsequence {𝒫nl} which converges uniformly. The limit 𝒫0=𝒫0(t) is in H1([0,1],χ) and it satisfies
				
					
						
							
								
									
										
											
												
													lim
													
														
															n
															l
														
														→
														∞
													
												
												
												
													
														𝒫
														
															n
															l
														
													
													
													
														(
														t
														)
													
												
											
											=
											
												
													𝒫
													0
												
												
												
													(
													t
													)
												
											
										
										 
										
											
												for all 
												
												t
											
											∈
											
												[
												0
												,
												1
												]
											
										
									
									.
								
							
							
							
						
					
				
				In particular,
				
					
						
							
								
									
										
											
												
													lim
													
														
															n
															l
														
														→
														∞
													
												
												
												
													
														𝒫
														
															n
															l
														
													
													
													
														(
														0
														)
													
												
											
											=
											
												
													𝒫
													0
												
												
												
													(
													0
													)
												
											
										
										,
										
											
												
													lim
													
														
															n
															l
														
														→
														∞
													
												
												
												
													
														𝒫
														
															n
															l
														
													
													
													
														(
														1
														)
													
												
											
											=
											
												
													𝒫
													0
												
												
												
													(
													1
													)
												
											
										
									
									.
								
							
							
							
						
					
				
				It follows that
				
					
						
							
								
									
										
											
												
													lim
													
														
															n
															l
														
														→
														∞
													
												
												
												
													a
													
														i
														
															n
															l
														
													
												
											
											=
											
												a
												
													i
													0
												
											
										
										,
										
											
												
													
														lim
														
															
																n
																l
															
															→
															∞
														
													
													
													
														b
														
															j
															
																n
																l
															
														
													
												
												=
												
													b
													
														j
														0
													
												
											
											,
											
												
													i
													=
													
														1
														,
														…
														,
														k
													
												
												,
												
													j
													=
													
														1
														,
														…
														,
														s
													
												
											
										
									
									,
								
							
							
							
						
					
				
				and 𝒫0 satisfies
				
					
						
							
								
									
										
											𝒜
											
											
												(
												
													𝒫
													0
												
												)
											
										
										=
										
											
												inf
												
													{
													q
													
														(
														0
														)
													
													=
													
														Q
														start
													
													,
													q
													
														(
														1
														)
													
													=
													
														Q
														end
													
													,
													q
													
														(
														t
														)
													
													∈
													
														H
														1
													
													
														(
														
															[
															0
															,
															1
															]
														
														,
														χ
														)
													
													,
													
														a
														i
													
													=
													
														a
														
															i
															0
														
													
													,
													
														b
														j
													
													=
													
														
															b
															
																j
																0
															
														
													
													
														(
														i
														=
														1
														,
														…
														,
														k
														,
														j
														=
														1
														,
														…
														,
														s
														)
													
													}
												
											
											
											𝒜
										
									
									.
								
							
							
							
						
					
				
				The proof is complete. ∎
			 
			As an application of Theorem 2.1, we first check if the two configurations Qstart and Qend defined in (1.1) satisfy the assumptions in Theorem 2.1. Recall that
			
				
					
						
							
								
									
										
											Q
											start
										
										=
										
											[
											
												
													
														0
													
													
														
															a
															1
														
													
												
												
													
														0
													
													
														
															b
															1
														
													
												
												
													
														0
													
													
														
															-
															
																c
																1
															
														
													
												
												
													
														0
													
													
														
															
																c
																1
															
															-
															
																a
																1
															
															-
															
																b
																1
															
														
													
												
											
											]
										
									
									,
									
										
											Q
											end
										
										=
										
											
												[
												
													
														
															0
														
														
															
																a
																2
															
														
													
													
														
															0
														
														
															
																b
																2
															
														
													
													
														
															
																-
																
																	c
																	2
																
															
														
														
															
																-
																
																	
																		
																			
																				a
																				2
																			
																			+
																			
																				b
																				2
																			
																		
																		2
																	
																
															
														
													
													
														
															
																c
																2
															
														
														
															
																-
																
																	
																		
																			
																				a
																				2
																			
																			+
																			
																				b
																				2
																			
																		
																		2
																	
																
															
														
													
												
												]
											
											
											R
											
											
												(
												θ
												)
											
										
									
								
								,
							
						
						
						
					
				
			
			where a→=(a1,b1,c1,a2,b2,c2)∈ℝ6, and
			
				
					
						
							
								
									
										R
										
										
											(
											θ
											)
										
									
									=
									
										[
										
											
												
													
														cos
														
														
															(
															θ
															)
														
													
												
												
													
														sin
														
														
															(
															θ
															)
														
													
												
											
											
												
													
														-
														
															sin
															
															
																(
																θ
																)
															
														
													
												
												
													
														cos
														
														
															(
															θ
															)
														
													
												
											
										
										]
									
								
								.
							
						
						
						
					
				
			
			For any given θ∈(0,π2), it is clear that
			
				
					
						
							
								
									
										
											{
											
												Q
												start
											
											:
											
												
													a
													→
												
												∈
												
													ℝ
													6
												
											
											}
										
										∩
										
											{
											
												Q
												end
											
											:
											
												
													a
													→
												
												∈
												
													ℝ
													6
												
											
											}
										
									
									=
									
										{
										
											0
											→
										
										}
									
								
								.
							
						
						
						
					
				
			
			By Theorem 2.1, there exists an action minimizer 𝒫0∈H1([0,1],χ) and a vector a→0 such that
			
				
					
						
							
								
									
										𝒜
										
										
											(
											
												𝒫
												0
											
											)
										
									
									=
									
										
											inf
											
												{
												
													a
													→
												
												∈
												
													ℝ
													6
												
												}
											
										
										
										
											
												inf
												
													{
													q
													
														(
														t
														)
													
													∈
													P
													
														(
														
															Q
															start
														
														,
														
															Q
															end
														
														)
													
													}
												
											
											
											𝒜
										
									
									=
									
										
											inf
											
												{
												q
												
													(
													t
													)
												
												∈
												P
												
													(
													
														Q
														start
													
													,
													
														Q
														end
													
													)
												
												,
												
													a
													→
												
												=
												
													
														a
														→
													
													0
												
												}
											
										
										
										𝒜
									
								
								.
							
						
						
						
					
				
			
			In order to find local action minimizers, one can fix the order of the four bodies on Qend. We assume a2≥b2 and c2≥0, which means that at t=1, on the configuration Qend⋅R(-θ), body 1 is above body 2 on the y-axis and body 3 is on the left of body 4. We can then set different orders of the four bodies at t=0. Basically, the four bodies have 24 different orders on the y-axis at t=0. For each given order of the four bodies at t=0, we can define a subset Γi(i=1,2,…,24) of a→. It follows that we can define 24 different subsets of a→. For example, we define Γ1 as follows:
			
				
					
						
							
								
									
										Γ
										1
									
									=
									
										{
										
											a
											→
										
										:
										
											
												
													a
													1
												
												≤
												
													b
													1
												
												≤
												
													-
													
														c
														1
													
												
												≤
												
													
														c
														1
													
													-
													
														a
														1
													
													-
													
														b
														1
													
												
											
											,
											
												
													
														a
														2
													
													≥
													
														b
														2
													
												
												,
												
													
														c
														2
													
													≥
													0
												
											
										
										}
									
								
								,
							
						
						
						
					
				
			
			which implies that the y-components of the four bodies at t=0 satisfy
			
				
					
						
							
								
									
										
											q
											
												1
												
												y
											
										
										
										
											(
											0
											)
										
									
									≤
									
										
											q
											
												2
												
												y
											
										
										
										
											(
											0
											)
										
									
									≤
									
										
											q
											
												3
												
												y
											
										
										
										
											(
											0
											)
										
									
									≤
									
										
											q
											
												4
												
												y
											
										
										
										
											(
											0
											)
										
									
								
								.
							
						
						
						
					
				
			
			The other 23 subsets Γi(i=2,3,…,24) can be defined similarly. By Theorem 2.1, it follows that for each Γi(1≤i≤24), there exists a minimizer 𝒫Γi∈H1([0,1],χ) such that
			
				
					
						
							
								
									
										𝒜
										
										
											(
											
												𝒫
												
													Γ
													i
												
											
											)
										
									
									=
									
										
											inf
											
												{
												
													a
													→
												
												∈
												
													Γ
													i
												
												}
											
										
										
										
											
												inf
												
													{
													q
													
														(
														t
														)
													
													∈
													P
													
														(
														
															Q
															start
														
														,
														
															Q
															end
														
														)
													
													}
												
											
											
											𝒜
										
									
								
								.
							
						
						
						
					
				
			
			
				Remark.
				Note that the boundary points of each Γi(1≤i≤24) are collisions. The possible collisions in the minimizer 𝒫Γi could be eliminated by using the level estimate method in [4, 5] or local deformation arguments in [16, 15] .
			 
		
		
			
			3 Exclusion of Collisions in 𝒫0
			In this section, we prove the following:
			
				Theorem 3.1.
				
					The minimizing path P0 has no collision.
				
			 
			Note that the minimizing path 𝒫0 is defined for t∈[0,1]. By the celebrated results of Marchal [12] and Chenciner [7], 𝒫0 has no collision in (0,1). So we only need to exclude the possible collisions on boundaries q(0)=Qstart and q(1)=Qend. To exclude possible collision singularities of Qstart and Qend in the minimizer 𝒫0, we introduce the following theorem [1]:
			
				Theorem 3.2 ([1, Theorem 4.3]).
				
					Let S=Rk+s. If the intersection of the two configuration subsets is at origin, i.e.
				
				
					
						
							
								
									
										
											
												{
												
													Q
													start
												
												:
												
													
														(
														
															a
															1
														
														,
														…
														,
														
															a
															k
														
														)
													
													∈
													
														ℝ
														k
													
												
												}
											
											∩
											
												{
												
													Q
													end
												
												:
												
													
														(
														
															b
															1
														
														,
														…
														,
														
															b
															s
														
														)
													
													∈
													
														ℝ
														s
													
												
												}
											
										
										=
										
											{
											
												0
												→
											
											}
										
									
									,
								
							
							
							
						
					
				
				
					the action minimizer P0∈H1([0,1],χ) in Theorem 2.1 has no binary collision.
				
			 
			As an application, in our case a→=(a1,b1,c1,a2,b2,c2)∈ℝ6, it follows that there is no binary collision in 𝒫0.
			Note that Qstart is a collinear configuration. We can then apply Chen’s result [3, 6] on collinear configurations to exclude possible collisions on Qstart:
			
				Theorem 3.3 ([3, Theorem 2.1]).
				
					In the minimizer P0, the collinear configuration Qstart has no collision singularity.
				
			 
			Furthermore, it is known that the bodies involved in a partial collision or total collision will approach a set of central configurations. More information can be known if the solution under concern is an action minimizer:
			
				Lemma 3.1 ([14, Theorem 4.1.18] or [7, Section 3.2.1]).
				
					If a minimizer q of the fixed-ends problem on time interval [τ1,τ2] has an isolated collision of k≤N bodies, then there is a parabolic homothetic collision-ejection solution q^ of the k-body problem which is also a minimizer of the fixed-ends problem on [τ1,τ2].
				
			 
			
				Lemma 3.2 ([3, Proposition 5] or [9, Section 7]).
				
					Let X be a proper linear subspace of Rd. Suppose that a local minimizer x of At0,t1 on Bt0,t1(x(t0),X):={x∈H1([t0,t1],(Rd)N):x(t0) is fixed, xi(t1)∈X,i=1,2,…,N} has an isolated collision of k≤N bodies at t=t1. Then there is a homothetic parabolic solution y¯ of the k-body problem with y¯(t1)=0 such that y¯ is a minimizer of Aτ,t1* on Bτ,t1(y¯(τ),X) for any τ<t1. Here Aτ,t1* denotes the action of this k-body subsystem.
				
			 
			By Theorem 3.3, we are left to exclude possible collisions on Qend. The matrix form of Qend in (1.1) implies that Qend can be a double isosceles, a kite or a diamond. Hence it may have binary collisions, triple collisions and total collision. By Theorem 3.2, there is no binary collision on Qend. Hence, we need to exclude possible triple collisions and total collision on Qend of 𝒫0. We will use the level estimate method [4, 5] to exclude the total collision first.
			
				Lemma 3.3.
				
					In the minimizer P0, there is no total collision at t=1.
				
			 
			
				Proof.
				We assume that at t=1, Qend experiences a total collision. Note that q∈χ. By Chen’s binary decomposition method [2, 5], the action can be written into the following form:
				
					
						
							
								
									
										
											𝒜
											=
											
												
													
														
															∫
															0
															1
														
													
													
														
															
																∑
																
																	i
																	=
																	1
																
																4
															
														
														
															
																
																	1
																	2
																
															
															
															
																
																	|
																	
																		
																			q
																			˙
																		
																		i
																	
																	|
																
																2
															
														
													
												
												+
												
													
														
															∑
															
																1
																≤
																i
																<
																j
																≤
																4
															
														
													
													
														
															
																
																	1
																	
																		|
																		
																			
																				q
																				i
																			
																			-
																			
																				q
																				j
																			
																		
																		|
																	
																
															
														
														
														d
														
														t
													
												
											
											=
											
												
													
														
															1
															4
														
													
													
													
														
															
																∑
																
																	1
																	≤
																	i
																	<
																	j
																	≤
																	4
																
															
														
														
															
																
																	∫
																	0
																	1
																
															
															
																
																	
																		1
																		2
																	
																
																
																
																	
																		|
																		
																			
																				
																					q
																					˙
																				
																				i
																			
																			-
																			
																				
																					q
																					˙
																				
																				j
																			
																		
																		|
																	
																	2
																
															
														
													
												
												+
												
													
														
															
																4
																
																	|
																	
																		
																			q
																			i
																		
																		-
																		
																			q
																			j
																		
																	
																	|
																
															
														
													
													
													d
													
													t
												
											
										
										.
									
								
								
								
							
						
					
				
				By the estimates in [2, 5], if qi and qj(1≤i<j≤4) has a collision when t∈[0,1], the following inequality holds:
				
					
						
							
								
									
										
											
												
													
														
															∫
															0
															1
														
													
													
														
															
																1
																2
															
														
														
														
															
																|
																
																	
																		
																			q
																			˙
																		
																		i
																	
																	-
																	
																		
																			q
																			˙
																		
																		j
																	
																
																|
															
															2
														
													
												
												+
												
													
														
															
																4
																
																	|
																	
																		
																			q
																			i
																		
																		-
																		
																			q
																			j
																		
																	
																	|
																
															
														
													
													
													d
													
													t
												
											
											≥
											
												
													
														3
														2
													
												
												
												
													
														(
														
															16
															
															
																π
																2
															
														
														)
													
													
														1
														3
													
												
											
										
										.
									
								
								
								
							
						
					
				
				It follows that the action 𝒜totalcollision of a total collision path satisfies
				
					
						
							
								
									
										
											𝒜
											
												
													total
												
												
												collision
											
										
										≥
										
											
												
													6
													4
												
												×
												
													3
													2
												
											
											
											
												
													(
													
														16
														
														
															π
															2
														
													
													)
												
												
													1
													3
												
											
										
										≥
										12.16
									
									.
								
							
							
							
						
					
				
				For any given θ∈(0,π2), note that at t=1, the double isosceles configuration can be degenerated to a diamond configuration. A testing path can be defined as follows:
				
					
						
							
								
									
										
											
												
													q
													¯
												
												1
											
											=
											
												
													2
												
												
												
													e
													
														
															(
															
																
																	θ
																	
																	t
																
																+
																
																	π
																	2
																
															
															)
														
														
														i
													
												
											
										
										,
										
											
												
													
														q
														¯
													
													2
												
												=
												
													-
													
														
															q
															¯
														
														1
													
												
											
											,
											
												
													
														
															q
															¯
														
														3
													
													=
													
														e
														
															
																[
																
																	
																		
																			(
																			
																				θ
																				-
																				
																					π
																					2
																				
																			
																			)
																		
																		
																		t
																	
																	+
																	
																		π
																		2
																	
																
																]
															
															
															i
														
													
												
												,
												
													
														
															q
															¯
														
														4
													
													=
													
														-
														
															
																q
																¯
															
															3
														
													
												
											
										
									
									.
								
							
							
							
						
					
				
				The action 𝒜¯ of this testing path is 
				
					
						
							
								
									
										
											𝒜
											¯
										
										=
										
											
												
													
														∫
														0
														1
													
												
												
													
														[
														
															
																2
																
																
																	θ
																	2
																
															
															+
															
																
																	(
																	
																		
																			
																				π
																				2
																			
																		
																		-
																		θ
																	
																	)
																
																2
															
															+
															
																
																	1
																	
																		2
																		
																		
																			2
																		
																	
																
															
															+
															
																
																	1
																	2
																
															
														
														]
													
													
													
														𝑑
														t
													
												
											
											+
											
												
													
														∫
														0
														1
													
												
												
													
														2
														
															|
															
																
																	
																		2
																	
																	
																	
																		e
																		
																			
																				(
																				
																					
																						θ
																						
																						t
																					
																					+
																					
																						π
																						2
																					
																				
																				)
																			
																			
																			i
																		
																	
																
																+
																
																	e
																	
																		
																			[
																			
																				
																					
																						(
																						
																							θ
																							-
																							
																								π
																								2
																							
																						
																						)
																					
																					
																					t
																				
																				+
																				
																					π
																					2
																				
																			
																			]
																		
																		
																		i
																	
																
															
															|
														
													
												
											
											+
											
												
													
														
															2
															
																|
																
																	
																		
																			2
																		
																		
																		
																			e
																			
																				
																					(
																					
																						
																							θ
																							
																							t
																						
																						+
																						
																							π
																							2
																						
																					
																					)
																				
																				
																				i
																			
																		
																	
																	-
																	
																		e
																		
																			
																				[
																				
																					
																						
																							(
																							
																								θ
																								-
																								
																									π
																									2
																								
																							
																							)
																						
																						
																						t
																					
																					+
																					
																						π
																						2
																					
																				
																				]
																			
																			
																			i
																		
																	
																
																|
															
														
													
												
												
												d
												
												t
											
										
									
								
								
								
							
						
						
							
								
									
										
										=
										
											
												2
												
												
													θ
													2
												
											
											+
											
												
													(
													
														
															
																π
																2
															
														
														-
														θ
													
													)
												
												2
											
											+
											
												
													1
													
														2
														
														
															2
														
													
												
											
											+
											
												
													1
													2
												
											
											+
											
												
													
														∫
														0
														1
													
												
												
													
														2
														
															
																3
																+
																
																	2
																	
																	
																		2
																	
																	
																	
																		cos
																		
																		
																			(
																			
																				t
																				
																				
																					π
																					2
																				
																			
																			)
																		
																	
																
															
														
													
												
											
											+
											
												
													
														
															2
															
																
																	3
																	-
																	
																		2
																		
																		
																			2
																		
																		
																		
																			cos
																			
																			
																				(
																				
																					t
																					
																					
																						π
																						2
																					
																				
																				)
																			
																		
																	
																
															
														
													
												
												
												d
												
												t
											
										
									
								
								
								
							
						
						
							
								
									
										
											
											≤
											
												
													2
													
													
														θ
														2
													
												
												+
												
													
														(
														
															
																
																	π
																	2
																
															
															-
															θ
														
														)
													
													2
												
												+
												
													
														1
														
															2
															
															
																2
															
														
													
												
												+
												
													
														1
														2
													
												
												+
												3.3386
											
										
										.
									
								
								
								
							
						
					
				
				Note that θ∈(0,π2), it follows that
				
					
						
							
								
									
										
											
												𝒜
												¯
											
										
										
											
												
													
													≤
													
														
															2
															
															
																θ
																2
															
														
														+
														
															
																(
																
																	
																		π
																		2
																	
																	-
																	θ
																
																)
															
															2
														
														+
														
															1
															
																2
																
																
																	2
																
															
														
														+
														
															1
															2
														
														+
														3.3386
													
													<
													
														
															
																π
																2
															
															2
														
														+
														
															1
															
																2
																
																
																	2
																
															
														
														+
														
															1
															2
														
														+
														3.3386
													
													<
													9.13
													<
													12.16
												
												.
											
										
									
								
							
							
							
						
					
				
				Therefore, there is no total collision at t=1 in the minimizer 𝒫0. The proof is complete. ∎
			 
			To exclude the possible triple collisions on Qend of the minimizer 𝒫0, we will apply the blow-up results in Lemma 3.1 and Lemma 3.2. Possible central configurations are discussed case by case so that we can lower the action by perturbation in each case. A local deformation argument is introduced in Lemma 3.4.
			
				Lemma 3.4.
				
					The minimizer P0 has no triple collision at t=1.
				
			 
			
				Proof.
				The possible triple collisions in Qend could be a collision involving bodies 1, 3 and 4, or a collision involving bodies 2, 3 and 4. Note that in either case, the three bodies form an isosceles triangle configuration. Without loss of generality, we assume that the collision bodies are {1,3,4} and q2 is away from them on Qend. Note that θ∈(0,π2) is always fixed. For simplicity, we may shift the collision time from t=1 to t=0 and assume Qend to be
				
					
						(3.1)
						
							
								
									
										[
										
											
												
													0
												
												
													
														a
														2
													
												
											
											
												
													0
												
												
													
														b
														2
													
												
											
											
												
													
														-
														
															c
															2
														
													
												
												
													
														-
														
															
																
																	
																		a
																		2
																	
																	+
																	
																		b
																		2
																	
																
																2
															
														
													
												
											
											
												
													
														c
														2
													
												
												
													
														-
														
															
																
																	
																		a
																		2
																	
																	+
																	
																		b
																		2
																	
																
																2
															
														
													
												
											
										
										]
									
									.
								
							
							
							
						
					
				
				In the above configuration (3.1), the triple collision among bodies 1, 3 and 4 happens at t=0 when c2=0 and a2=-a2+b22≠b2.
				By the analysis of the blow-up in Lemma 3.1 and Lemma 3.2, there exists a parabolic homothetic solution qi(t)=ait23(i=1,3,4), which is also a minimizer of the three-body problem on [0,τ] for any τ>0. For convenience, we denote the minimizer by q=(q1,q3,q4). Furthermore, (a1,a3,a4) forms a central configuration, and the three vectors a1, a3 and a4 satisfy the energy constraint
				
					
						
							
								
									
										
											
												
													∑
													
														i
														=
														
															1
															,
															3
															,
															4
														
													
												
												
													
														1
														2
													
													
													
														
															|
															
																
																	2
																	3
																
																
																
																	a
																	i
																
															
															|
														
														2
													
												
											
											-
											
												
													∑
													
														
															i
															<
															
																j
																,
																i
															
														
														,
														
															j
															∈
															
																{
																1
																,
																3
																,
																4
																}
															
														
													
												
												
													1
													
														|
														
															
																a
																i
															
															-
															
																a
																j
															
														
														|
													
												
											
										
										=
										0
									
									.
								
							
							
							
						
					
				
				Note that by the formula of Qend in (3.1), q1, q3 and q4 always form an isosceles triangle at t=0. To exclude the triple collision of q1, q3 and q4 at t=0, we need to show that the action 𝒜* of the subsystem (q=(q1,q3,q4) with qi=ait23(i=1,3,4)) can be lowered by deforming this parabolic homothetic solution under the boundary constraint at t=0. In fact, under this boundary constraint, it is challenging to apply the averaging method [12, 7, 9]. For this reason, the analysis of local deformation is done case by case for every possible central configuration.
				Fix ϵ>0. When the central configuration of (q1,q3,q4) is an equilateral triangle, we use complex notations for simplicity. In fact, one can assume that a1=γeiθ0 with θ0∈[0,π] and γ=(332)13. The case when θ0∈[π,2π) can be handled similarly. Since there is no constraint on the order of body 3 and body 4 on the horizontal line, we can further assume that a3=a1e23πi,a4=a3e23πi. Now consider
				
					
						
							
								
									
										
											
												
													q
													~
												
												1
											
											=
											
												r
												
												
													(
													t
													)
												
												
												
													e
													
														i
														
														θ
														
														
															(
															t
															)
														
													
												
											
										
										,
										
											
												
													
														q
														~
													
													3
												
												=
												
													
														
															q
															~
														
														1
													
													
													
														e
														
															
																2
																3
															
															
															π
															
															i
														
													
												
											
											,
											
												
													
														q
														~
													
													4
												
												=
												
													
														
															q
															~
														
														3
													
													
													
														e
														
															
																2
																3
															
															
															π
															
															i
														
													
												
											
										
									
									,
								
							
							
							
						
					
				
				where
				
					
						
							
								
									
										r
										
										
											(
											t
											)
										
									
									=
									
										{
										
											
												
													
														
															γ
															
															
																
																	(
																	
																		
																			ϵ
																			N
																		
																	
																	)
																
																
																	2
																	3
																
															
														
														,
													
												
												
													
														
															0
															≤
															t
															≤
															
																
																	ϵ
																	N
																
															
														
														,
													
												
											
											
												
													
														
															γ
															
															
																t
																
																	2
																	3
																
															
														
														,
													
												
												
													
														
															
																
																	ϵ
																	N
																
															
															≤
															t
															≤
															ϵ
														
														,
													
												
											
										
									
								
							
							
							
						
					
				
				and θ(t)=(θ0-π2)tϵ+π2. At t=0, q~1(0)=r(0)eiθ(0), q~3(0)=q~1(0)e23πi and q~4(0)=q~3(0)e23πi, which satisfies the configuration Qend in (3.1). At t=ϵ, q~i(ϵ)=qi(ϵ)(i=1,3,4). Let 𝒜* be the action of the parabolic homothetic ejection solution qi(t)=ait23(i=1,2,4). Let 𝒜~* be the action of the perturbed path q~=(q~1,q~3,q~4). It follows that
				
					
						
							
								
									
										
											
												
													𝒜
													~
												
												*
											
											-
											
												𝒜
												*
											
										
										=
										
											
												(
												
													
														
															(
															
																
																	
																		9
																		
																		
																			γ
																			2
																		
																	
																	14
																
																+
																
																	
																		6
																		
																		
																			γ
																			2
																		
																	
																	
																		7
																		
																		
																			N
																			
																				7
																				3
																			
																		
																	
																
															
															)
														
														
														
															
																(
																
																	
																		θ
																		0
																	
																	-
																	
																		π
																		2
																	
																
																)
															
															2
														
													
													-
													
														
															
																2
																
																
																	γ
																	2
																
															
															+
															
																
																	2
																	
																	
																		3
																	
																
																γ
															
														
														
															N
															
																1
																3
															
														
													
												
												)
											
											
											
												ϵ
												
													1
													3
												
											
										
									
									.
								
							
							
							
						
					
				
				By taking N=5, we have 𝒜~*-𝒜*<0 for every θ0∈[0,π].
				When the central configuration of (q1,q3,q4) is an Euler collinear configuration, there must be one body staying at the origin. We discuss it in several cases. If a1=(0,0), a3=(ξ3,η3) and a4=-a3, then we define a perturbed path as follows:
				
					
						
							
								
									
										
											
												
													q
													~
												
												1
											
											=
											
												q
												1
											
										
										,
										
											
												
													
														q
														~
													
													3
												
												=
												
													(
													
														
															ξ
															3
														
														
														
															ϵ
															
																2
																3
															
														
													
													,
													
														
															η
															3
														
														
														
															t
															
																2
																3
															
														
													
													)
												
											
											,
											
												
													
														q
														~
													
													4
												
												=
												
													-
													
														(
														
															
																ξ
																3
															
															
															
																ϵ
																
																	2
																	3
																
															
														
														,
														
															
																η
																3
															
															
															
																t
																
																	2
																	3
																
															
														
														)
													
												
											
										
									
									,
								
							
							
							
						
					
				
				where q~1(0)=(0,0), q~3(0)=(ξ3ϵ23,0) and q~4(0)=-(ξ3ϵ23,0) and at t=ϵ, q~i(ϵ)=qi(ϵ)(i=1,3,4). It is clear that 𝒜~*<𝒜* in this case.
				If a1≠(0,0), then one of the other two bodies must stay at the origin. Without loss of generality, we can assume a3=(0,0). Let a1=(ξ1,η1). If η1≠0, we define
				
					
						
							
								
									
										
											
												
													q
													~
												
												1
											
											=
											
												(
												
													
														ξ
														1
													
													
													
														t
														
															2
															3
														
													
												
												,
												
													
														η
														1
													
													
													
														ϵ
														
															2
															3
														
													
												
												)
											
										
										,
										
											
												
													
														q
														~
													
													3
												
												=
												
													(
													0
													,
													
														-
														
															
																
																	η
																	1
																
																2
															
															
															
																(
																
																	
																		ϵ
																		
																			2
																			3
																		
																	
																	-
																	
																		t
																		
																			2
																			3
																		
																	
																
																)
															
														
													
													)
												
											
											,
											
												
													
														q
														~
													
													4
												
												=
												
													(
													
														-
														
															
																ξ
																1
															
															
															
																t
																
																	2
																	3
																
															
														
													
													,
													
														-
														
															
																
																	η
																	1
																
																2
															
															
															
																(
																
																	
																		ϵ
																		
																			2
																			3
																		
																	
																	+
																	
																		t
																		
																			2
																			3
																		
																	
																
																)
															
														
													
													)
												
											
										
									
									,
								
							
							
							
						
					
				
				where q~1(0)=(0,η1ϵ23), q~3(0)=(0,-η12ϵ23) and q~4(0)=(0,-η12ϵ23) and at t=ϵ, q~i(ϵ)=qi(ϵ),(i=1,3,4). It follows that the kinetic energy is decreased, and
				
					
						
							
								
									
										
											
												|
												
													
														
															q
															~
														
														3
													
													-
													
														
															q
															~
														
														4
													
												
												|
											
											=
											
												|
												
													
														q
														3
													
													-
													
														q
														4
													
												
												|
											
										
										,
										
											
												|
												
													
														
															q
															~
														
														1
													
													-
													
														
															q
															~
														
														4
													
												
												|
											
											≥
											
												|
												
													
														q
														1
													
													-
													
														q
														4
													
												
												|
											
										
									
									.
								
							
							
							
						
					
				
				For t∈[0,ϵ],
				
					
						
							
								
									
										
											|
											
												
													
														q
														~
													
													1
												
												-
												
													
														q
														~
													
													3
												
											
											|
										
										=
										
											
												
													
														
															(
															
																
																	ξ
																	1
																	2
																
																+
																
																	
																		η
																		1
																		2
																	
																	4
																
															
															)
														
														
														
															t
															
																4
																3
															
														
													
													-
													
														
															3
															2
														
														
														
															η
															1
															2
														
														
														
															ϵ
															
																2
																3
															
														
														
														
															t
															
																2
																3
															
														
													
												
												+
												
													
														9
														4
													
													
													
														η
														1
														2
													
													
													
														ϵ
														
															4
															3
														
													
												
											
										
										≥
										
											
												
													
														(
														
															
																ξ
																1
																2
															
															+
															
																
																	η
																	1
																	2
																
																4
															
														
														)
													
													
													
														t
														
															4
															3
														
													
												
												+
												
													
														3
														4
													
													
													
														η
														1
														2
													
													
													
														ϵ
														
															4
															3
														
													
												
											
										
									
									.
								
							
							
							
						
					
				
				It implies that
				
					
						
							
								
									
										
											∫
											0
											ϵ
										
										
											
												d
												
												t
											
											
												|
												
													
														
															q
															~
														
														1
													
													-
													
														
															q
															~
														
														3
													
												
												|
											
										
									
									<
									
										
											∫
											0
											ϵ
										
										
											
												d
												
												t
											
											
												|
												
													
														q
														1
													
													-
													
														q
														3
													
												
												|
											
										
									
								
							
							
							
						
					
				
				and
				
					
						
							
								
									
										
											
												∫
												0
												ϵ
											
											
												
													d
													
													t
												
												
													|
													
														
															
																q
																~
															
															1
														
														-
														
															
																q
																~
															
															4
														
													
													|
												
											
										
										<
										
											
												∫
												0
												ϵ
											
											
												
													d
													
													t
												
												
													|
													
														
															q
															1
														
														-
														
															q
															4
														
													
													|
												
											
										
									
									.
								
							
							
							
						
					
				
				Hence, 𝒜~*<𝒜*.
				If η1=0 and ξ1≠0, then
				
					
						
							
								
									
										
											
												q
												1
											
											=
											
												(
												
													
														ξ
														1
													
													
													
														t
														
															2
															3
														
													
												
												,
												0
												)
											
										
										,
										
											
												
													q
													3
												
												=
												
													(
													0
													,
													0
													)
												
											
											,
											
												
													q
													4
												
												=
												
													(
													
														-
														
															
																ξ
																1
															
															
															
																t
																
																	2
																	3
																
															
														
													
													,
													0
													)
												
											
										
									
									.
								
							
							
							
						
					
				
				In this case we define
				
					
						
							
								
									
										
											
												
													q
													~
												
												1
											
											=
											
												(
												
													
														ξ
														1
													
													
													
														t
														
															2
															3
														
													
												
												,
												
													2
													
													δ
													
													
														(
														
															1
															-
															
																
																	t
																	
																		2
																		3
																	
																
																
																	ϵ
																	
																		2
																		3
																	
																
															
														
														)
													
												
												)
											
										
										,
										
											
												
													
														q
														~
													
													3
												
												=
												
													(
													0
													,
													
														-
														
															δ
															
															
																(
																
																	1
																	-
																	
																		
																			t
																			
																				2
																				3
																			
																		
																		
																			ϵ
																			
																				2
																				3
																			
																		
																	
																
																)
															
														
													
													)
												
											
											,
											
												
													
														q
														~
													
													4
												
												=
												
													(
													
														-
														
															
																ξ
																1
															
															
															
																t
																
																	2
																	3
																
															
														
													
													,
													
														-
														
															δ
															
															
																(
																
																	1
																	-
																	
																		
																			t
																			
																				2
																				3
																			
																		
																		
																			ϵ
																			
																				2
																				3
																			
																		
																	
																
																)
															
														
													
													)
												
											
										
									
									,
								
							
							
							
						
					
				
				where q~1(0)=(0,2δ), q~3(0)=(0,-δ) and q~4(0)=(0,-δ) and at t=ϵ, q~i(ϵ)=qi(ϵ)(i=1,3,4). We set
				
					
						
							
								
									
										δ
										=
										
											
												ϵ
												
													2
													3
												
											
											
												N
											
										
									
									.
								
							
							
							
						
					
				
				Let K* be the kinetic energy of the subsystem q=(q1,q3,q4). Let K~* be the kinetic energy of the perturbed path q~=(q~1,q~3,q~4). It follows that
				
					
						
							
								
									
										
											△
											
												K
												*
											
										
										=
										
											
												∫
												0
												ϵ
											
											
												
													(
													
														
															
																K
																~
															
															*
														
														-
														
															K
															*
														
													
													)
												
												
												
													𝑑
													t
												
											
										
										=
										
											
												4
												N
											
											
											
												ϵ
												
													1
													3
												
											
										
									
									.
								
							
							
							
						
					
				
				A direct calculation implies that
				
					
						
							
								
									
										
											
												|
												
													
														
															q
															~
														
														1
													
													-
													
														
															q
															~
														
														3
													
												
												|
											
											≥
											
												
													
														
															
																9
																
																
																	ξ
																	1
																	2
																
															
															
																
																	N
																	
																	
																		ξ
																		1
																		2
																	
																
																+
																9
															
														
													
												
												
												
													ϵ
													
														2
														3
													
												
											
										
										,
									
								
								
								
							
						
						
							
								
									
										
											
												|
												
													
														
															q
															~
														
														1
													
													-
													
														
															q
															~
														
														4
													
												
												|
											
											≥
											
												
													
														
															
																36
																
																
																	ξ
																	1
																	2
																
															
															
																
																	4
																	
																	N
																	
																	
																		ξ
																		1
																		2
																	
																
																+
																9
															
														
													
												
												
												
													ϵ
													
														2
														3
													
												
											
										
										,
									
								
								
								
							
						
						
							
								
									
										
											
												|
												
													
														
															q
															~
														
														3
													
													-
													
														
															q
															~
														
														4
													
												
												|
											
											=
											
												
													|
													
														ξ
														1
													
													|
												
												
												
													t
													
														2
														3
													
												
											
										
										.
									
								
								
								
							
						
					
				
				It follows that
				
					
						(3.2)
						
							
								
									
										
											
												
													𝒜
													~
												
												*
											
											-
											
												𝒜
												*
											
										
										≤
										
											
												[
												
													
														
															4
															N
														
														+
														
															
																(
																
																	
																		9
																		
																		
																			ξ
																			1
																			2
																		
																	
																	
																		
																			N
																			
																			
																				ξ
																				1
																				2
																			
																		
																		+
																		9
																	
																
																)
															
															
																-
																
																	1
																	2
																
															
														
														+
														
															
																(
																
																	
																		36
																		
																		
																			ξ
																			1
																			2
																		
																	
																	
																		
																			4
																			
																			N
																			
																			
																				ξ
																				1
																				2
																			
																		
																		+
																		9
																	
																
																)
															
															
																-
																
																	1
																	2
																
															
														
													
													-
													
														9
														
															2
															
															
																|
																
																	ξ
																	1
																
																|
															
														
													
												
												]
											
											
											
												ϵ
												
													1
													3
												
											
										
									
									.
								
							
							
							
						
					
				
				Note that in the Euler central configuration, ξ1=(458)13. By taking N=6 in (3.2), we have 𝒜~*-𝒜*<0.
				Therefore, for all possible central configurations of q=(q1,q3,q4), there always exists some perturbed path q~, such that
				
					
						
							
								
									
										
											
												
													𝒜
													~
												
												*
											
											-
											
												𝒜
												*
											
										
										<
										0
									
									.
								
							
							
							
						
					
				
				Contradiction! It implies that there is no triple collision among q1, q3 and q4 in the minimizer 𝒫0. Similarly, we can show that there is no triple collision among q2, q3 and q4 in 𝒫0. The proof is complete. ∎
			 
			The proof of Theorem 3.1 follows by Theorem 3.2, Theorem 3.3, Lemma 3.3 and Lemma 3.4. Hence, the minimizer 𝒫0=𝒫0(t∈[0,1]) is a classical solution of the N-body problem. However, it is hard to eliminate possible collisions in each 𝒫Γi(i=1,2,…,24). We will check them numerically.
		
		
			
			4 Extension of the Minimizer 𝒫0
			By the previous section, we know that 𝒫0(t∈[0,1]) is a classical solution of the N-body problem. In this section, we show that the minimizer 𝒫0(t∈[0,1]) can be extended to a periodic or quasi-periodic orbit. First variation formulas are applied to the variables a1,b1,c1 in Qstart and a2,b2,c2 in Qend of the minimizer 𝒫0, which imply several identities of the velocities on both boundaries. An extension formula of 𝒫0(t∈[0,1]) can then be defined by (4.2) in Theorem 4.1.
			
				Proposition 4.1.
				
					In the minimizer P0, the velocities q˙i(t)(i=1,2,3,4) satisfy
				
				
					
						
							
								
									
										
											
												
													q
													˙
												
												
													1
													
													y
												
											
											
											
												(
												0
												)
											
										
										=
										
											
												
													q
													˙
												
												
													2
													
													y
												
											
											
											
												(
												0
												)
											
										
										=
										
											
												
													q
													˙
												
												
													3
													
													y
												
											
											
											
												(
												0
												)
											
										
										=
										
											
												
													q
													˙
												
												
													4
													
													y
												
											
											
											
												(
												0
												)
											
										
										=
										0
									
									,
								
							
							
							
						
					
				
				
					and
				
				
					
						
							
								
									
										
											
												
													
														q
														˙
													
													1
												
												
												
													(
													1
													)
												
											
											=
											
												-
												
													
														
															q
															˙
														
														1
													
													
													
														(
														1
														)
													
													
													B
													
													R
													
													
														(
														
															2
															
															θ
														
														)
													
												
											
										
										,
									
								
								
								
							
							
								
									
										
											
												
													
														
															q
															˙
														
													
													3
												
												
												
													(
													1
													)
												
											
											=
											
												-
												
													
														
															q
															˙
														
														4
													
													
													
														(
														1
														)
													
													
													B
													
													R
													
													
														(
														
															2
															
															θ
														
														)
													
												
											
										
										,
									
								
								
								
							
						
						
							
								
									
										
											
												
													
														q
														˙
													
													2
												
												
												
													(
													1
													)
												
											
											=
											
												-
												
													
														
															q
															˙
														
														2
													
													
													
														(
														1
														)
													
													
													B
													
													R
													
													
														(
														
															2
															
															θ
														
														)
													
												
											
										
										,
									
								
								
								
							
							
								
									
										
											
												
													
														
															q
															˙
														
													
													4
												
												
												
													(
													1
													)
												
											
											=
											
												-
												
													
														
															q
															˙
														
														3
													
													
													
														(
														1
														)
													
													
													B
													
													R
													
													
														(
														
															2
															
															θ
														
														)
													
												
											
										
										,
									
								
								
								
							
						
					
				
				
					where
				
				
					
						
							
								
									
										
											B
											=
											
												
													[
													
														
															
																
																	-
																	1
																
															
															
																0
															
														
														
															
																0
															
															
																1
															
														
													
													]
												
												 
												𝑎𝑛𝑑
											
										
										 
										
											
												R
												
												
													(
													
														2
														
														θ
													
													)
												
											
											=
											
												[
												
													
														
															
																cos
																
																
																	(
																	
																		2
																		
																		θ
																	
																	)
																
															
														
														
															
																sin
																
																
																	(
																	
																		2
																		
																		θ
																	
																	)
																
															
														
													
													
														
															
																-
																
																	sin
																	
																	
																		(
																		
																			2
																			
																			θ
																		
																		)
																	
																
															
														
														
															
																cos
																
																
																	(
																	
																		2
																		
																		θ
																	
																	)
																
															
														
													
												
												]
											
										
									
									.
								
							
							
							
						
					
				
			 
			
				Proof.
				Note that there exists some a0→∈ℝ6 such that
				
					
						
							
								
									
										
											𝒜
											
											
												(
												
													𝒫
													0
												
												)
											
										
										=
										
											
												inf
												
													{
													q
													
														(
														t
														)
													
													∈
													P
													
														(
														
															Q
															start
														
														,
														
															Q
															end
														
														)
													
													,
													
														a
														→
													
													=
													
														
															a
															→
														
														0
													
													}
												
											
											
											𝒜
										
									
									.
								
							
							
							
						
					
				
				Let q=q(t) be the position matrix path of 𝒫0. Consider an admissible variation ξ(t)∈P(Qstart,Qend) satisfying ξ(0)∈{Qstart:(a1,…,ak)∈𝒮1} and ξ(1)∈{Qend:(b1,…,bs)∈𝒮2}; then the first variation δξ𝒜(q) satisfies
				
					
						
							
								
									
										0
										=
										
											
												δ
												ξ
											
											
											𝒜
											
											
												(
												q
												)
											
										
									
								
								
								
							
						
						
							
								
									
										
										=
										
											
												lim
												
													τ
													→
													0
												
											
											
											
												
													
														
															𝒜
															
															
																(
																
																	q
																	+
																	
																		τ
																		
																		ξ
																	
																
																)
															
														
														-
														
															𝒜
															
															
																(
																q
																)
															
														
													
													τ
												
											
										
									
								
								
								
							
						
						
							
								
									
										
										=
										
											
												
													
														∫
														0
														1
													
												
												
													
														
															1
															2
														
													
													
													
														
															
																∑
																
																	i
																	=
																	1
																
																4
															
														
														
															
																lim
																
																	τ
																	→
																	0
																
															
															
															
																
																	m
																	i
																
																
																
																	
																		
																			
																				
																					∥
																					
																						
																							
																								q
																								˙
																							
																							i
																						
																						+
																						
																							τ
																							
																							
																								
																									ξ
																									˙
																								
																								i
																							
																						
																					
																					∥
																				
																				2
																			
																			-
																			
																				
																					∥
																					
																						
																							q
																							˙
																						
																						i
																					
																					∥
																				
																				2
																			
																		
																		τ
																	
																
															
														
													
												
											
											+
											
												
													lim
													
														τ
														→
														0
													
												
												
												
													
														
															
																
																	
																		U
																		
																		
																			(
																			
																				q
																				+
																				
																					τ
																					
																					ξ
																				
																			
																			)
																		
																	
																	-
																	
																		U
																		
																		
																			(
																			q
																			)
																		
																	
																
																τ
															
														
													
													
													d
													
													t
												
											
										
									
								
								
								
							
						
						
							
								
									
										
										=
										
											
												
													∫
													0
													1
												
											
											
												
													(
													
														
															
																
																	∑
																	
																		i
																		=
																		1
																	
																	4
																
															
															
																
																	m
																	i
																
																
																
																	〈
																	
																		
																			q
																			˙
																		
																		i
																	
																	,
																	
																		
																			ξ
																			˙
																		
																		i
																	
																	〉
																
															
														
														+
														
															
																
																	∑
																	
																		i
																		=
																		1
																	
																	4
																
															
															
																〈
																
																	
																		
																			∂
																			
																				∂
																				
																				
																					q
																					i
																				
																			
																		
																	
																	
																	U
																	
																	
																		(
																		
																			q
																			
																			
																				(
																				t
																				)
																			
																		
																		)
																	
																
																,
																
																	ξ
																	i
																
																〉
															
														
													
													)
												
												
												
													𝑑
													t
												
											
										
									
								
								
								
							
						
						
							
								
									
										
										=
										
											
												
													∑
													
														i
														=
														1
													
													4
												
											
											
												(
												
													
														
															
																
																	m
																	i
																
																
																
																	〈
																	
																		
																			q
																			˙
																		
																		i
																	
																	,
																	
																		ξ
																		i
																	
																	〉
																
															
															|
														
														
															t
															=
															0
														
														
															t
															=
															1
														
													
													+
													
														
															
																∫
																0
																1
															
														
														
															
																〈
																
																	
																		-
																		
																			
																				m
																				i
																			
																			
																			
																				
																					q
																					¨
																				
																				i
																			
																		
																	
																	+
																	
																		
																			
																				∂
																				
																					∂
																					
																					
																						q
																						i
																					
																				
																			
																		
																		
																		U
																		
																		
																			(
																			
																				q
																				
																				
																					(
																					t
																					)
																				
																			
																			)
																		
																	
																
																,
																
																	ξ
																	i
																
																〉
															
															
															
																𝑑
																t
															
														
													
												
												)
											
										
									
								
								
								
							
						
						
							(4.1)
							
								
									
										
											
											=
											
												
													
														
															
																∑
																
																	i
																	=
																	1
																
																4
															
														
														
															
																m
																i
															
															
															
																〈
																
																	
																		q
																		˙
																	
																	i
																
																,
																
																	ξ
																	i
																
																〉
															
														
													
													|
												
												
													t
													=
													0
												
												
													t
													=
													1
												
											
										
										.
									
								
								
								
							
						
					
				
				Note that m1=m2=m3=m4=1. Let ξ(t)∈P(Qstart,Qend) such that
				
					
						
							
								
									
										
											
												ξ
												
												
													(
													0
													)
												
											
											=
											
												
													[
													
														
															
																0
															
															
																1
															
														
														
															
																0
															
															
																0
															
														
														
															
																0
															
															
																0
															
														
														
															
																0
															
															
																
																	-
																	1
																
															
														
													
													]
												
												 
												and
											
										
										 
										
											
												ξ
												
												
													(
													1
													)
												
											
											=
											0
										
									
									.
								
							
							
							
						
					
				
				By identity (4.1), it follows that
				
					
						
							
								
									
										
											
												
													
														q
														˙
													
													
														1
														
														y
													
												
												
												
													(
													0
													)
												
											
											-
											
												
													
														q
														˙
													
													
														4
														
														y
													
												
												
												
													(
													0
													)
												
											
										
										=
										0
									
									.
								
							
							
							
						
					
				
				Similarly, by taking different values of ξ(0), we have
				
					
						
							
								
									
										
											
												
													
														
															q
															˙
														
														
															2
															
															y
														
													
													
													
														(
														0
														)
													
												
												-
												
													
														
															q
															˙
														
														
															4
															
															y
														
													
													
													
														(
														0
														)
													
												
											
											=
											0
										
										,
										
											
												
													-
													
														
															
																q
																˙
															
															
																3
																
																y
															
														
														
														
															(
															0
															)
														
													
												
												+
												
													
														
															q
															˙
														
														
															4
															
															y
														
													
													
													
														(
														0
														)
													
												
											
											=
											0
										
									
									.
								
							
							
							
						
					
				
				Note that
				
					
						
							
								
									
										
											
												∑
												
													i
													=
													1
												
												4
											
											
												
													
														q
														˙
													
													
														i
														
														y
													
												
												
												
													(
													0
													)
												
											
										
										=
										0
									
									.
								
							
							
							
						
					
				
				It follows that
				
					
						
							
								
									
										
											
												
													q
													˙
												
												
													1
													
													y
												
											
											
											
												(
												0
												)
											
										
										=
										
											
												
													q
													˙
												
												
													2
													
													y
												
											
											
											
												(
												0
												)
											
										
										=
										
											
												
													q
													˙
												
												
													3
													
													y
												
											
											
											
												(
												0
												)
											
										
										=
										
											
												
													q
													˙
												
												
													4
													
													y
												
											
											
											
												(
												0
												)
											
										
										=
										0
									
									.
								
							
							
							
						
					
				
				Similar arguments on a2,b2,c2 imply that
				
					
						
							
								
									
										
											
												
													
														q
														˙
													
													1
												
												
												
													(
													1
													)
												
											
											=
											
												-
												
													
														
															q
															˙
														
														1
													
													
													
														(
														1
														)
													
													
													B
													
													R
													
													
														(
														
															2
															
															θ
														
														)
													
												
											
										
										,
									
								
								
								
							
							
								
									
										
											
												
													
														
															q
															˙
														
													
													3
												
												
												
													(
													1
													)
												
											
											=
											
												-
												
													
														
															q
															˙
														
														4
													
													
													
														(
														1
														)
													
													
													B
													
													R
													
													
														(
														
															2
															
															θ
														
														)
													
												
											
										
										,
									
								
								
								
							
						
						
							
								
									
										
											
												
													
														q
														˙
													
													2
												
												
												
													(
													1
													)
												
											
											=
											
												-
												
													
														
															q
															˙
														
														2
													
													
													
														(
														1
														)
													
													
													B
													
													R
													
													
														(
														
															2
															
															θ
														
														)
													
												
											
										
										,
									
								
								
								
							
							
								
									
										
											
												
													
														
															q
															˙
														
													
													4
												
												
												
													(
													1
													)
												
											
											=
											
												-
												
													
														
															q
															˙
														
														3
													
													
													
														(
														1
														)
													
													
													B
													
													R
													
													
														(
														
															2
															
															θ
														
														)
													
												
											
										
										,
									
								
								
								
							
						
					
				
				where
				
					
						
							
								
									
										
											B
											=
											
												
													[
													
														
															
																
																	-
																	1
																
															
															
																0
															
														
														
															
																0
															
															
																1
															
														
													
													]
												
												 
												and
											
										
										 
										
											
												R
												
												
													(
													
														2
														
														θ
													
													)
												
											
											=
											
												[
												
													
														
															
																cos
																
																
																	(
																	
																		2
																		
																		θ
																	
																	)
																
															
														
														
															
																sin
																
																
																	(
																	
																		2
																		
																		θ
																	
																	)
																
															
														
													
													
														
															
																-
																
																	sin
																	
																	
																		(
																		
																			2
																			
																			θ
																		
																		)
																	
																
															
														
														
															
																cos
																
																
																	(
																	
																		2
																		
																		θ
																	
																	)
																
															
														
													
												
												]
											
										
									
									.
								
							
							
							
						
					
				
				The proof is complete. ∎
			 
			The extension of the path 𝒫0(t∈[0,1]) then follows by Proposition 4.1 and the uniqueness of solutions of an ODE system.
			
				Theorem 4.1.
				
					Let θ∈(0,π2). If θπ is rational, the minimizer P0(t∈[0,1]) can be extended to a periodic orbit. Otherwise, P0(t∈[0,1]) can be extended to a quasi-periodic orbit.
				
			 
			
				Proof.
				Let 
				
					
						
							
								
									
										
											
												
													q
													
													
														(
														t
														)
													
												
												=
												
													[
													
														
															
																
																	
																		q
																		1
																	
																	
																	
																		(
																		t
																		)
																	
																
															
														
														
															
																
																	
																		q
																		2
																	
																	
																	
																		(
																		t
																		)
																	
																
															
														
														
															
																
																	
																		q
																		3
																	
																	
																	
																		(
																		t
																		)
																	
																
															
														
														
															
																
																	
																		q
																		4
																	
																	
																	
																		(
																		t
																		)
																	
																
															
														
													
													]
												
											
											,
											
												t
												∈
												
													[
													0
													,
													1
													]
												
											
										
										,
									
								
								
								
							
						
					
				
				be the position matrix path of the minimizer 𝒫0(t∈[0,1]), where each qi(t)=(qix(t),qiy(t))(i=1,2,3,4) is a 2-dimensional row vector path. Its extension is defined as follows:
				
					
						(4.2)
						
							
								
									
										q
										
										
											(
											t
											)
										
									
									=
									
										{
										
											
												
													
														
															
																(
																
																	
																		q
																		1
																		T
																	
																	
																	
																		(
																		t
																		)
																	
																
																,
																
																	
																		q
																		2
																		T
																	
																	
																	
																		(
																		t
																		)
																	
																
																,
																
																	
																		q
																		3
																		T
																	
																	
																	
																		(
																		t
																		)
																	
																
																,
																
																	
																		q
																		4
																		T
																	
																	
																	
																		(
																		t
																		)
																	
																
																)
															
															T
														
														,
													
												
												
													
														
															t
															∈
															
																[
																0
																,
																1
																]
															
														
														,
													
												
											
											
												
													
														
															
																
																	(
																	
																		
																			q
																			1
																			T
																		
																		
																		
																			(
																			
																				2
																				-
																				t
																			
																			)
																		
																	
																	,
																	
																		
																			q
																			2
																			T
																		
																		
																		
																			(
																			
																				2
																				-
																				t
																			
																			)
																		
																	
																	,
																	
																		
																			q
																			4
																			T
																		
																		
																		
																			(
																			
																				2
																				-
																				t
																			
																			)
																		
																	
																	,
																	
																		
																			q
																			3
																			T
																		
																		
																		
																			(
																			
																				2
																				-
																				t
																			
																			)
																		
																	
																	)
																
																T
															
															
															B
															
															R
															
															
																(
																
																	2
																	
																	θ
																
																)
															
														
														,
													
												
												
													
														
															t
															∈
															
																[
																1
																,
																2
																]
															
														
														,
													
												
											
											
												
													
														
															
																
																	(
																	
																		
																			q
																			1
																			T
																		
																		
																		
																			(
																			
																				t
																				-
																				2
																			
																			)
																		
																	
																	,
																	
																		
																			q
																			2
																			T
																		
																		
																		
																			(
																			
																				t
																				-
																				2
																			
																			)
																		
																	
																	,
																	
																		
																			q
																			4
																			T
																		
																		
																		
																			(
																			
																				t
																				-
																				2
																			
																			)
																		
																	
																	,
																	
																		
																			q
																			3
																			T
																		
																		
																		
																			(
																			
																				t
																				-
																				2
																			
																			)
																		
																	
																	)
																
																T
															
															
															R
															
															
																(
																
																	2
																	
																	θ
																
																)
															
														
														,
													
												
												
													
														
															t
															∈
															
																[
																2
																,
																4
																]
															
														
														,
													
												
											
											
												
													
														
															q
															
															
																(
																
																	t
																	-
																	
																		4
																		
																		k
																	
																
																)
															
															
															R
															
															
																(
																
																	4
																	
																	k
																	
																	θ
																
																)
															
														
														,
													
												
												
													
														
															t
															∈
															
																[
																
																	4
																	
																	k
																
																,
																
																	
																		4
																		
																		k
																	
																	+
																	4
																
																]
															
														
														,
													
												
											
										
									
								
							
							
							
						
					
				
				where
				
					
						
							
								
									
										B
										=
										
											[
											
												
													
														
															-
															1
														
													
													
														0
													
												
												
													
														0
													
													
														1
													
												
											
											]
										
									
								
								
								
							
						
					
				
				and k∈ℤ. Recall that
				
					
						
							
								
									
										
											
												Q
												start
											
											=
											
												[
												
													
														
															0
														
														
															
																a
																1
															
														
													
													
														
															0
														
														
															
																b
																1
															
														
													
													
														
															0
														
														
															
																-
																
																	c
																	1
																
															
														
													
													
														
															0
														
														
															
																
																	c
																	1
																
																-
																
																	a
																	1
																
																-
																
																	b
																	1
																
															
														
													
												
												]
											
										
										,
										
											
												Q
												end
											
											=
											
												
													[
													
														
															
																0
															
															
																
																	a
																	2
																
															
														
														
															
																0
															
															
																
																	b
																	2
																
															
														
														
															
																
																	-
																	
																		c
																		2
																	
																
															
															
																
																	-
																	
																		
																			
																				
																					a
																					2
																				
																				+
																				
																					b
																					2
																				
																			
																			2
																		
																	
																
															
														
														
															
																
																	c
																	2
																
															
															
																
																	-
																	
																		
																			
																				
																					a
																					2
																				
																				+
																				
																					b
																					2
																				
																			
																			2
																		
																	
																
															
														
													
													]
												
												
												R
												
												
													(
													θ
													)
												
											
										
									
									.
								
							
							
							
						
					
				
				By Proposition 4.1, it follows that at t=1, q(t) is actually C1. Since q(t) satisfies the Newtonian equation, it follows that q(t) is smooth at t=1. And at t=2, the four bodies are on a line which is a counterclockwise 2θ rotation of the y-axis. Each velocity q˙i(i=1,2,3,4) at t=2 is perpendicular to the line of their configuration. Similarly, we can show that the orbit q(t) is smooth at t=2. Note that when t=4, the position matrix q and the velocity matrix q˙ satisfy
				
					
						
							
								
									
										
											
												
													q
													
													
														(
														4
														)
													
												
												=
												
													q
													
													
														(
														0
														)
													
													
													R
													
													
														(
														
															4
															
															θ
														
														)
													
												
											
											,
											
												
													
														q
														˙
													
													
													
														(
														4
														)
													
												
												=
												
													
														q
														˙
													
													
													
														(
														0
														)
													
													
													R
													
													
														(
														
															4
															
															θ
														
														)
													
												
											
										
										.
									
								
								
								
							
						
					
				
				By the uniqueness of solutions of an ODE system, the extension of q(t)(t∈[0,4]) is
				
					
						
							
								
									
										
											
												
													q
													
													
														(
														t
														)
													
												
												=
												
													q
													
													
														(
														
															t
															-
															
																4
																
																k
															
														
														)
													
													
													R
													
													
														(
														
															4
															
															k
															
															θ
														
														)
													
												
											
											,
											
												t
												∈
												
													[
													
														4
														
														k
													
													,
													
														
															4
															
															k
														
														+
														4
													
													]
												
											
										
										,
									
								
								
								
							
						
					
				
				where k∈ℤ. Therefore, the definition of q(t) in (4.2) is smooth for all t. If θπ=k1l1 is rational (k1,l1 are integers), then the minimizer 𝒫0(t∈[0,1]) can be extended to a periodic orbit with a period T=4l1. If θπ is irrational, then the extension of 𝒫0(t∈[0,1]) in (4.2) is quasi-periodic. The proof is complete. ∎
			 
			
				Remark.
				If the local action minimizers 𝒫Γi(t∈[0,1])(i=1,2,…,24) are collision-free, similar arguments can be applied to show that each 𝒫Γi(i=1,2,…,24) can be extended to a periodic or quasi-periodic orbit. And their extensions satisfy the same formula of q(t) in (4.2).
			 
		
		
			
			5 Equivalence of Action Minimizers
			In the last section, we discuss the equivalent class of all the 24 local action minimizers 𝒫Γi(i=1,2,…,24). By assuming that θπ is rational and each minimizer 𝒫Γi(i=1,2,…,24) is a classical solution, we show that these 24 action minimizers can actually generate sixteen different periodic orbits.
			Recall that each local action minimizer 𝒫Γi(i=1,2,…,24) satisfies
			
				
					
						
							
								
									
										𝒜
										
										
											(
											
												𝒫
												
													Γ
													i
												
											
											)
										
									
									=
									
										
											inf
											
												{
												
													a
													→
												
												∈
												
													Γ
													i
												
												}
											
										
										
										
											
												inf
												
													{
													q
													
														(
														t
														)
													
													∈
													P
													
														(
														
															Q
															start
														
														,
														
															Q
															end
														
														)
													
													}
												
											
											
											𝒜
										
									
								
								,
							
						
						
						
					
				
			
			where Γi is defined as follows. In every Γi(i=1,2,…,24), we assume that the variables on Qend always satisfy a2≥b2 and c2≥0. Then in the collinear configuration Qstart, the 24 different orders Δ=(α1,α2,α3,α4) of the four bodies at t=0 have a one-to-one correspondence to the 24 action minimizers 𝒫Γi(i=1,2,…,24). For example, we define Γ1 as
			
				
					
						
							
								
									
										Γ
										1
									
									=
									
										{
										
											a
											→
										
										:
										
											
												
													a
													1
												
												≤
												
													b
													1
												
												≤
												
													-
													
														c
														1
													
												
												≤
												
													
														
															-
															
																a
																1
															
														
														-
														
															b
															1
														
													
													+
													
														c
														1
													
												
											
											,
											
												
													
														a
														2
													
													≥
													
														b
														2
													
												
												,
												
													
														c
														2
													
													≥
													0
												
											
										
										}
									
								
								,
							
						
						
						
					
				
			
			which has the following order at t=0:
			
				
					
						
							
								
									
										
											q
											
												1
												
												y
											
										
										
										
											(
											0
											)
										
									
									≤
									
										
											q
											
												2
												
												y
											
										
										
										
											(
											0
											)
										
									
									≤
									
										
											q
											
												3
												
												y
											
										
										
										
											(
											0
											)
										
									
									≤
									
										
											q
											
												4
												
												y
											
										
										
										
											(
											0
											)
										
									
								
								.
							
						
						
						
					
				
			
			We denote it by (1,2,3,4). That is, the minimizer 𝒫Γ1 corresponds to an order (1,2,3,4) in Qstart. The following result shows that some of the orders in Qstart correspond to the same solution of the four-body problem.
			
				Lemma 5.1.
				
					Given a2≥b2,c2≥0, the orders Δ and σ1σ2Δ in Qstart correspond to the same periodic solution, where
				
				
					
						
							
								
									
										
											
												σ
												1
											
											=
											
												
													(
													12
													)
												
												
												
													(
													34
													)
												
											
										
										,
										
											
												σ
												2
											
											=
											
												(
												
													
														
															
																α
																1
															
														
														
															
																α
																2
															
														
														
															
																α
																3
															
														
														
															
																α
																4
															
														
													
													
														
															
																α
																4
															
														
														
															
																α
																3
															
														
														
															
																α
																2
															
														
														
															
																α
																1
															
														
													
												
												)
											
										
									
									.
								
							
							
							
						
					
				
			 
			
				Proof.
				Note that q(t) and -q(t) are considered as the same solution in the N-body problem. Assume that q(0) has an order Δ=(α1,α2,α3,α4) in Qstart; then -q(0) has an order
				
					
						
							
								
									
										
											(
											
												α
												4
											
											,
											
												α
												3
											
											,
											
												α
												2
											
											,
											
												α
												1
											
											)
										
										=
										
											
												σ
												2
											
											
											Δ
										
									
									,
								
							
							
							
						
					
				
				where
				
					
						
							
								
									
										
											σ
											2
										
										=
										
											(
											
												
													
														
															α
															1
														
													
													
														
															α
															2
														
													
													
														
															α
															3
														
													
													
														
															α
															4
														
													
												
												
													
														
															α
															4
														
													
													
														
															α
															3
														
													
													
														
															α
															2
														
													
													
														
															α
															1
														
													
												
											
											)
										
									
									.
								
							
							
							
						
					
				
				But the corresponding Qend in -q(t) has a2≤b2 and c2≤0. Let σ1=(12)(34). Then in the orbit corresponding to σ1σ2Δ, Qend satisfies a2≥b2 and c2≥0. It implies that Δ and σ1σ2Δ=σ2σ1Δ correspond to the same orbit. The proof is complete. ∎
			 
			
				Theorem 5.1.
				
					Assume that θ∈(0,π2) and θπ is rational. If all the minimizers PΓi(i=1,2,…,24) are classical solutions of the N-body problem, then there are sixteen different periodic orbits connecting Qstart and Qend defined in (1.1).
				
			 
			
				Proof.
				For convenience, we use Δα1α2α3α4 to represent the corresponding action minimizer. For example, 𝒫Γ1 corresponds to Δ1234. By Lemma 5.1, we know that the 24 action minimizers can be classified into the following sixteen sets:
				
					
						
							
								
									
										
											
												{
												
													Δ
													1234
												
												,
												
													Δ
													3412
												
												}
											
											,
											
												{
												
													Δ
													1243
												
												,
												
													Δ
													4312
												
												}
											
											,
											
												{
												
													Δ
													1324
												
												,
												
													Δ
													3142
												
												}
											
											,
											
												{
												
													Δ
													1423
												
												,
												
													Δ
													4132
												
												}
											
										
										,
									
								
								
								
							
						
						
							
								
									
										
											
												{
												
													Δ
													2134
												
												,
												
													Δ
													3421
												
												}
											
											,
											
												{
												
													Δ
													2143
												
												,
												
													Δ
													4321
												
												}
											
											,
											
												{
												
													Δ
													2314
												
												,
												
													Δ
													3241
												
												}
											
											,
											
												{
												
													Δ
													2413
												
												,
												
													Δ
													4231
												
												}
											
										
										,
									
								
								
								
							
						
						
							
								
									
										
											
												{
												
													Δ
													1342
												
												}
											
											,
											
												{
												
													Δ
													1432
												
												}
											
											,
											
												{
												
													Δ
													2341
												
												}
											
											,
											
												{
												
													Δ
													2431
												
												}
											
											,
											
												{
												
													Δ
													3124
												
												}
											
											,
											
												{
												
													Δ
													3214
												
												}
											
											,
											
												{
												
													Δ
													4123
												
												}
											
											,
											
												{
												
													Δ
													4213
												
												}
											
										
										.
									
								
								
								
							
						
					
				
				Therefore, there are sixteen different periodic orbits connecting Qstart and Qend defined in (1.1). The proof is complete. ∎
			 
			In the end, numerical results are presented for some rotation angle θ. Note that by the definitions of Qstart and Qend in (1.1), it is easy to check that 𝒫Γi(i=1,2,…,24) cannot be a relative equilibrium in the four-body problem. In other words, these sixteen periodic orbits are nontrivial. Numerically, we set θ=π5 and calculate the sixteen action minimizers by Matlab. The motions of the sixteen periodic orbits can then be drawn as in Figure 2. It is worth mentioning that some of the orbits are very complicated. It will be interesting if one can analytically prove their existences. For other values of θ∈(0,π2), similar multiplicity results of periodic orbits are expected.
			
				Figure 2
				
					Sixteen different periodic orbits connecting Qstart and Qend in (1.1) with θ=π5.