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Double-phase parabolic equations with variable growth and nonlinear sources

  • Rakesh Arora and Sergey Shmarev EMAIL logo
Published/Copyright: September 8, 2022

Abstract

We study the homogeneous Dirichlet problem for the parabolic equations

u t div ( A ( z , u ) u ) = F ( z , u , u ) , z = ( x , t ) Ω × ( 0 , T ) ,

with the double phase flux A ( z , u ) u = ( u p ( z ) 2 + a ( z ) u q ( z ) 2 ) u and the nonlinear source F . The initial function belongs to a Musielak-Orlicz space defined by the flux. The functions a , p , and q are Lipschitz-continuous, a ( z ) is nonnegative, and may vanish on a set of nonzero measure. The exponents p , and q satisfy the balance conditions 2 N N + 2 < p p ( z ) q ( z ) < p ( z ) + r 2 with r = r ( p , N ) , p = min Q ¯ T p ( z ) . It is shown that under suitable conditions on the growth of F ( z , u , u ) with respect to the second and third arguments, the problem has a solution u with the following properties:

u t L 2 ( Q T ) , u p ( z ) + δ L 1 ( Q T ) for every 0 δ < r , u s ( z ) , a ( z ) u q ( z ) L ( 0 , T ; L 1 ( Ω ) ) with s ( z ) = max { 2 , p ( z ) } .

Uniqueness is proven under stronger assumptions on the source F . The same results are established for the equations with the regularized flux A ( z , ( ε 2 + u 2 ) 1 / 2 ) u , ε > 0 .

MSC 2010: 35K65; 35K67; 35B65; 35K55; 35K99

1 Introduction

Let Ω R N be a smooth bounded domain, N 2 , and 0 < T < . We consider the following parabolic problem with the homogeneous Dirichlet boundary conditions:

(1.1) u t div ( u p ( z ) 2 u + a ( z ) u q ( z ) 2 u ) = F ( z , u , u ) in Q T , u = 0 on Γ T , u ( x , 0 ) = u 0 ( x ) in Ω ,

where z = ( x , t ) denotes the point in the cylinder Q T = Ω × ( 0 , T ] and Γ T = Ω × ( 0 , T ) is the lateral boundary of the cylinder. The nonlinear source has the following form

(1.2) F ( z , v , v ) = f 0 ( z ) + Ψ ( z , v ) + Φ ( z , v ) .

Here, a 0 , p , q , f 0 , Ψ , and Φ are given functions of their arguments.

Equations given in (1.1) are often termed “the double-phase equations.” This name, introduced in [17,18], reflects the fact that the flux function ( u p ( z ) 2 + a ( z ) u q ( z ) 2 ) u includes two terms with different properties. If p ( z ) q ( z ) a.e. in the problem domain and a ( z ) is allowed to vanish on a set of nonzero measure in Q T , then the growth of the flux is determined by p ( z ) on the set, where a ( z ) = 0 and by q ( z ) wherever a ( z ) > 0 .

1.1 Previous work

The study of the double-phase problems started in the late 80th by the works of Zhikov [47,48], where the models of strongly anisotropic materials were considered in the context of homogenization. Later on, the double-phase functionals

u Ω ( u p + a ( x ) u q ) d x

attracted attention of many researchers. On the one hand, the study of these functionals is a challenging mathematical problem. On the other hand, the double-phase functionals appear in a variety of physical models. We refer here to [8,46] for applications in the elasticity theory, [6] for transonic flows, [9] for quantum physics, and [13] for reaction-diffusion systems.

Equations (1.1) with p q are also referred to as the equations with the ( p , q ) -growth because of the gap between the coercivity and growth conditions: If p q and 0 a ( x ) L , then for every ξ R N ,

ξ p ( ξ p 2 + a ( x ) ξ q 2 ) ξ 2 C ( 1 + ξ q ) , C = const > 0 .

These equations fall into the class of equations with nonstandard growth conditions, which have been actively studied during the last decades in the cases of constant or variable exponents p and q . We refer to the works [2,14,17,18,24,26,27,28,31,34,35,39,40,45] and references therein for the results on the existence and regularity of solutions, including optimal regularity results [24].

Results on the existence of solutions to the evolution double-phase equations can be found in papers [10,43,44]. These works deal with the Dirichlet problem for systems of parabolic equations of the form

(1.3) u t div a ( x , t , u ) = 0 ,

where the flux a ( x , t , u ) is assumed to satisfy the ( p , q ) -growth conditions and certain regularity assumptions. As a partial case, the class of equations (1.3) includes equation (1.1) with constant exponents p q and a nonnegative bounded coefficient a ( x , t ) . It is shown in [10, Th.1.6] that if

2 p q < p + 4 N + 2 ,

then problem (1.1) with F 0 has a very weak solution:

u L p ( 0 , T ; W 0 1 , p ( Ω ) ) L loc q ( 0 , T ; W loc 1 , q ( Ω ) ) with u t L p q 1 0 , T ; W 1 , p q 1 ( Ω ) ,

provided that u 0 W 0 1 , r ( Ω ) , r = p ( q 1 ) p 1 . Moreover, u is bounded on every strictly interior cylinder Q T Q T separated away from the parabolic boundary of Q T . In [43], these results were extended to the case

2 N N + 2 < p < 2 , p q < p + 4 N + 2 .

The paper [44] deals with weak solutions of systems of equations of the type (1.3) with ( p , q ) growth conditions. When applied to problem (1.1) with constant p and q , F f 0 ( z ) , and a ( , t ) C α ( Ω ) with some α ( 0 , 1 ) for a.e. t ( 0 , T ) , the result of [44] guarantees the existence of a weak solution:

u L p ( 0 , T ; W 0 1 , p ( Ω ) ) L loc q ( 0 , T ; W loc 1 , q ( Ω ) ) L ( 0 , T ; L 2 ( Ω ) ) ,

provided that the exponents p and q obey the inequalities:

2 N N + 2 < p < q < p + α min { 2 , p } N + 2 .

The proofs of the existence theorems in [10,43,44] rely on the property of local higher integrability of the gradient, u p + δ L 1 ( Q T ) for every sub-cylinder Q T Q T . The maximal possible value of δ > 0 indicates the admissible gap between the exponents p and q and vary in dependence on the type of the solution.

Equation (1.1) with constant exponents p and q furnishes a prototype of the equations recently studied in papers [11,21,29,36] in the context of weak or variational solutions. The proofs of existence also use the local higher integrability of the gradient, but for the existence of variational solutions, a weaker assumption on the gap q p is required. For the solutions of the evolution p ( x , t ) -Laplace equation, global higher integrability of the gradient up to the lateral boundary of the cylinder was proven in [1] for very weak solutions and under mild restrictions on the regularity of the data. In [5], this property was established in the whole of the cylinder Q T but under stronger assumptions on the data.

Nonhomogeneous parabolic equations of the form (1.3) with the flux a ( x , t , u ) controlled by a generalized N -function were studied in [16] in the framework of Musielak-Orlicz spaces. The class of equations studied in [16] includes, as a partial case, equation (1.1) with F = f 0 ( z ) and variable exponents p , q . It is shown that problem (1.1) with bounded data u 0 and f 0 admits a unique solution u L ( 0 , T ; L 2 ( Ω ) ) L 1 ( 0 , T ; W 0 1 , 1 ( Ω ) ) with u L M ( Q T ; R N ) , where L M denotes the Musielak-Orlicz space defined by the flux a ( x , t , ξ ) . We refer here to [16,25], the survey article [14], and references therein for the issues of solvability of elliptic and parabolic equations in the Musielak-Orlicz spaces. A comprehensive review of the current state of the theory of double-phase problems is given in [38].

In the last years, the double-phase stationary problems with nonlinear convection terms were in the focus of attention of many researchers, see, e.g., papers [7,27,37], monograph [41], and references therein. However, to the best of our knowledge, there are no results on the counterpart evolution problems with nonlinear sources of the variable growth.

1.2 Description of results

In the present work, we prove the existence of strong solutions to problem (1.1). By the strong solution, we mean a solution whose time derivative is not a distribution but an element of a Lebesgue space, and the flux has better integrability properties than the properties prompted by the energy equality (the rigorous formulation is given in Definition 3.1).

  • We consider first the case of the given source independent of the solution: F = f 0 ( z ) . It is shown that if the exponents p , q and the data a , u 0 , and f 0 are sufficiently smooth, and if the gap between the exponents satisfies the condition

    (1.4) 2 N N + 2 < p ( z ) q ( z ) < p ( z ) + 2 p ( N + 2 ) p + 2 N in Q T ,

    where p = inf Q T p ( z ) , then problem (1.1) has a strong solution u with

    (1.5) u t L 2 ( Q T ) , ess sup ( 0 , T ) ( u ( , t ) , t ) < , ( u ( , t ) , t ) Ω ( u p ( z ) + a ( z ) u q ( z ) ) d x .

    Moreover, the solution possesses the property of global higher integrability of the gradient:

    (1.6) Q T u p ( z ) + r d z C for every 0 < r < 4 p ( N + 2 ) p + 2 N ,

    with a finite constant C depending only on ( u 0 , 0 ) , N , r , and the properties of p ( ) and q ( ) . The same existence result is valid for problem (1.1) with the regularized nondegenerate flux:

    ( ε 2 + u 2 ) p ( z ) 2 2 + a ( z ) ( ε 2 + u 2 ) q ( z ) 2 2 u , ε > 0 .

  • If the source F depends on u and u , the existence of strong solutions of problem (1.1) with the property of global higher integrability (1.6) is proven for the nonlinear source function F of the form (1.2) subject to specific growth restrictions, which lead to an additional assumption on p . We assume that

    Ψ C 0 ( Q ¯ T × R ) , Ψ ( z , 0 ) = 0 , Ψ ( z , r ) C r σ ( z ) 1 , Ψ ( z , v ) C ( v σ ( z ) 1 ( 1 + ln v ) + v σ ( z ) 2 v ) ,

    with a constant C and a function σ C 0 ( Q ¯ T ) such that

    2 inf Q T σ ( z ) sup Q T σ ( z ) < min p , 1 + p N + 2 2 N .

    The growth of F with respect to u is subject to the following restrictions:

    Φ C 0 ( Q ¯ T × R N ) , Φ ( z , s ) L s p ( z ) 1 if s < 1 , M 1 2 s p ( z ) 2 if s 1

    with positive constants L , and M . The functions Ψ and Φ are not assumed to be sign-definite. An example of admissible Ψ and Φ is furnished by

    Φ ( z , s ) = c ( z ) s p ( z ) 1 1 + s p ( z ) 2 1 , Ψ ( z , v ) = b ( z ) v σ ( z ) 2 v ,

    with

    b ( z ) , c ( z ) C 0 ( Q ¯ T ) , b , Q T const , σ , Q T const .

    If Ψ 0 , the restriction on p ( z ) transforms into p 2 . For the uniqueness of strong solutions, we assume that Φ 0 and either Ψ ( z , v ) is monotone decreasing with respect to v for a.e. z Q T or Ψ ( z , v ) = b ( z ) v .

In both cases, property (1.6) of global higher integrability of the gradient turns out to be crucial for the proof of the existence of a strong solution. A traditional approach to the double-phase equations involves regularization of the equation and derivation of a local estimate (1.6) with the use of Caccioppoli-type inequalities, which is sufficient for the proof of the existence of weak solutions. As distinguished from this method, we find a solution as the limit of a sequence of finite-dimensional Galerkin’s approximations. These approximations do not solve the equation, but they are smooth up to the parabolic boundary of the cylinder Q T . The higher regularity of the approximations allows us to prove global in Q T uniform higher integrability of their gradients by means of the Gagliardo-Nirenberg inequality.

All results remain true for the multiphase equations:

u t div u p ( z ) 2 u + i = 1 K a i ( z ) u q i ( z ) 2 u = F ( z , u , u ) ,

provided the exponents p ( z ) and q i ( z ) satisfy the balance condition (1.4) and the source F is subject to the above-described growth conditions.

2 The function spaces

We begin with a brief description of the Lebesgue and Sobolev spaces with variable exponents. A detailed insight into the theory of these spaces and a review of the bibliography can be found in [20,22,32,41]. Let Ω R N be a bounded domain with the Lipschitz continuous boundary Ω . Define the set

P ( Ω ) { measurable functions on Ω with values in ( 1 , ) } .

2.1 Variable Lebesgue spaces

Throughout the rest of the paper, we assume that Ω R N , N 2 , is a bounded domain with the boundary Ω C 2 . Given r P ( Ω ) , we introduce the modular

(2.1) A r ( ) ( f ) = Ω f ( x ) r ( x ) d x ,

and the set

L r ( ) ( Ω ) = { f : Ω R measurable on Ω , A r ( ) ( f ) < } .

The set L r ( ) ( Ω ) equipped with the Luxemburg norm

f r ( ) , Ω = inf λ > 0 : A r ( ) f λ 1

becomes a Banach space. By convention, from now on, we use the notation

r ess min x Ω r ( x ) , r + ess max x Ω r ( x ) .

If r P ( Ω ) and 1 < r r ( x ) r + < in Ω , then the following properties hold.

  1. L r ( ) ( Ω ) is a reflexive and separable Banach space.

  2. For every f L r ( ) ( Ω ) ,

    (2.2) min { f r ( ) , Ω r , f r ( ) , Ω r + } A r ( ) ( f ) max { f r ( ) , Ω r , f r ( ) , Ω r + } .

  3. For every f L r ( ) ( Ω ) and g L r ( ) ( Ω ) , the generalized Hölder inequality holds:

    (2.3) Ω f g 1 r + 1 ( r ) f r ( ) , Ω g r ( ) , Ω 2 f r ( ) , Ω g r ( ) , Ω ,

    where r = r r 1 is the conjugate exponent of r .

  4. If p 1 , p 2 P ( Ω ) and satisfy the inequality p 1 ( x ) p 2 ( x ) a.e. in Ω , then L p 1 ( ) ( Ω ) is continuously embedded in L p 2 ( ) ( Ω ) and for all u L p 2 ( ) ( Ω )

    (2.4) u p 1 ( ) , Ω C u p 2 ( ) , Ω , C = C ( Ω , p 1 ± , p 2 ± ) .

  5. For every sequence { f k } L r ( ) ( Ω ) and f L r ( ) ( Ω ) ,

    (2.5) f k f r ( ) , Ω 0 iff A r ( ) ( f k f ) 0 as k .

2.2 Variable Sobolev spaces

The variable Sobolev space W 0 1 , r ( ) ( Ω ) is the set of functions:

W 0 1 , r ( ) ( Ω ) = { u : Ω R u L r ( ) ( Ω ) W 0 1 , 1 ( Ω ) , u L r ( ) ( Ω ) }

equipped with the norm

u W 0 1 , r ( ) ( Ω ) = u r ( ) , Ω + u r ( ) , Ω .

If r C 0 ( Ω ¯ ) , the Poincaré inequality holds: for every u W 0 1 , r ( ) ( Ω ) ,

(2.6) u r ( ) , Ω C u r ( ) , Ω .

Inequality (2.6) means that the equivalent norm of W 0 1 , r ( ) ( Ω ) is given by

(2.7) u W 0 1 , r ( ) ( Ω ) = u r ( ) , Ω .

Let us denote by C log ( Ω ¯ ) the subset of P ( Ω ) composed of the functions continuous on Ω ¯ with the logarithmic modulus of continuity:

p C log ( Ω ¯ ) p ( x ) p ( y ) ω ( x y ) x , y Ω ¯ , x y < 1 2 ,

where ω is a nonnegative function such that

limsup s 0 + ω ( s ) ln 1 s = C , C = const .

If r C log ( Ω ¯ ) , then the set C c ( Ω ) of smooth functions with finite support is dense in W 0 1 , r ( ) ( Ω ) (see Proposition 2.2). This property allows one to use the equivalent definition of the space W 0 1 , r ( ) ( Ω ) :

W 0 1 , r ( ) ( Ω ) = { the closure of C c ( Ω ) with respect to the norm W 1 , r ( ) ( Ω ) } .

2.3 Spaces of functions depending on x and t

For the study of parabolic problem (1.1), we need the spaces of functions depending on z = ( x , t ) Q T . Given a function q C log ( Q ¯ T ) , we introduce the spaces:

V q ( , t ) ( Ω ) = { u : Ω R u L 2 ( Ω ) W 0 1 , 1 ( Ω ) , u q ( x , t ) L 1 ( Ω ) } , t ( 0 , T ) , W q ( ) ( Q T ) = { u : ( 0 , T ) V q ( , t ) ( Ω ) u L 2 ( Q T ) , u q ( z ) L 1 ( Q T ) } .

The norm of W q ( ) ( Q T ) is defined by

u W q ( ) ( Q T ) = u 2 , Q T + u q ( ) , Q T .

Since q C log ( Q ¯ T ) , the space W q ( ) ( Q T ) is the closure of C c ( Q T ) with respect to this norm.

2.4 Musielak-Sobolev spaces

Let a 0 : Ω [ 0 , ) be a given function, a 0 C 0 , 1 ( Ω ¯ ) . Assume that the exponents p , q C 0 , 1 ( Ω ¯ ) take values in the intervals ( p , p + ) , ( q , q + ) , and p ( x ) q ( x ) in Ω . Set

r ( x ) = max { 2 , p ( x ) } , s ( x ) = max { 2 , q ( x ) }

and consider the function

( x , t ) = t r ( x ) + a 0 ( x ) t s ( x ) , t 0 , x Ω .

The set

L ( Ω ) = u : Ω R u is measurable , ρ ( u ) = Ω ( x , u ) d x <

equipped with the Luxemburg norm

u = inf λ > 0 : ρ u λ 1

becomes a Banach space. The space L ( Ω ) is separable and reflexive [25]. By W 1 , ( Ω ) , we denote the Musielak-Sobolev space

W 1 , ( Ω ) = { u L ( Ω ) : u L ( Ω ) }

with the norm

u 1 , = u + u .

2.5 Dense sets in W 0 1 , p ( ) ( Ω ) and W 1 , ( Ω )

Let { ϕ i } and { λ i } be the eigenfunctions and the corresponding eigenvalues of the Dirichlet problem for the Laplacian:

(2.8) ( ϕ i , ψ ) 2 , Ω = λ i ( ϕ i , ψ ) ψ H 0 1 ( Ω ) .

The functions ϕ i form an orthonormal basis of L 2 ( Ω ) and are mutually orthogonal in H 0 1 ( Ω ) . If Ω C k , k 1 , then ϕ i C ( Ω ) H k ( Ω ) . Let us denote by H D k ( Ω ) the subspace of the Hilbert space H k ( Ω ) composed of the functions f for which

f = 0 , Δ f = 0 , , Δ [ k 1 2 ] f = 0 on Ω , H D 0 ( Ω ) = L 2 ( Ω ) .

The relations

[ f , g ] k = ( Δ k 2 f , Δ k 2 g ) 2 , Ω if k is even , ( Δ k 1 2 f , Δ k 1 2 g ) H 1 ( Ω ) if k is odd

define an equivalent inner product on H D k ( Ω ) : [ f , g ] k = i = 1 λ i k f i g i , where f i , and g i are the Fourier coefficients of f , and g in the basis { ϕ i } of L 2 ( Ω ) . The corresponding equivalent norm of H D k ( Ω ) is defined by f H D k ( Ω ) 2 = [ f , f ] k . Let f ( m ) = i = 1 m f i ϕ i be the partial sums of the Fourier series of f L 2 ( Ω ) . The following assertion is well known.

Proposition 2.1

Let Ω C k , k 1 . A function f can be represented by the Fourier series in the system { ϕ i } , convergent in the norm of H k ( Ω ) , if and only if f H D k ( Ω ) . If f H D k ( Ω ) , then the series i = 1 λ i k f i 2 is convergent, its sum is bounded by C f H k ( Ω ) with an independent of f constant C, and f ( m ) f H k ( Ω ) 0 as m . If k [ N 2 ] + 1 , then the Fourier series in the system { ϕ i } of every function f H D k ( Ω ) converges to f in C k N 2 1 ( Ω ¯ ) .

Proposition 2.2

([23], Th. 4.7, Proposition 4.10). Let Ω L i p and p C log ( Ω ¯ ) . Then the set C c ( Ω ) is dense in W 0 1 , p ( ) ( Ω ) .

Given a function u W 0 1 , p ( ) ( Ω ) with p C log ( Ω ¯ ) , the smooth approximations of u in W 0 1 , p ( ) ( Ω ) are obtained by means of mollification. The proof relies on the boundedness of the maximal Hardy-Littlewood operator in L p ( ) ( Ω ) with p C log ( Ω ¯ ) .

Let us denote P m = span { ϕ 1 , , ϕ m } , where ϕ i are the solutions of problem (2.9).

Lemma 2.1

If Ω C k , q C log ( Ω ¯ ) and

(2.9) k N 1 2 + 1 N 1 q + , q + = max Ω ¯ q ( x ) ,

then m = 1 P m is dense in W 0 1 , q ( ) ( Ω ) .

Proof

Given v W 0 1 , q ( ) ( Ω ) we have to show that for every ε > 0 , there is m N and v m P m such that v v m W 0 1 , q ( ) ( Ω ) < ε . Fix some ε > 0 . By Proposition 2.2, there is v ε C c ( Ω ) H D k ( Ω ) such that v v ε W 0 1 , q ( ) ( Ω ) < ε / 2 . By Proposition 2.1 v ε ( m ) ( x ) = i = 1 m v i ϕ i ( x ) H k ( Ω ) and v ε ( m ) v ε in H k ( Ω ) , therefore for every δ > 0 , there is m N such that v ε v ε ( m ) H k ( Ω ) < δ . Since k , N , and q satisfy condition (2.10), the embeddings H D k ( Ω ) W 0 1 , q + ( Ω ) W 0 1 , q ( ) ( Ω ) are continuous:

w W 0 1 , q ( ) ( Ω ) C w W 0 1 , q + ( Ω ) C w H k ( Ω ) w H D k ( Ω )

with independent of w constants C , C . Set C δ = ε / 2 . Then

v ε v ε ( m ) W 0 1 , q ( ) ( Ω ) C v ε v ε ( m ) H k ( Ω ) < C δ = ε 2 .

It follows that

v v ε ( m ) W 0 1 , q ( ) ( Ω ) v v ε W 0 1 , q ( ) ( Ω ) + v ε v ε ( m ) W 0 1 , q ( ) ( Ω ) < ε 2 + C δ = ε .

Corollary 2.1

If p C log ( Q ¯ T ) and condition (2.9) is fulfilled, then

v ( x , t ) : v = i = 1 v i ( t ) ϕ i ( x ) , v i ( t ) C 0 , 1 [ 0 , T ] i s d e n s e i n W p ( ) ( Q T ) .

Since Ω C k with k 1 and r ( x ) , s ( x ) 2 , then W 1 , ( Ω ) W 1 , 2 ( Ω ) and the elements of W 1 , ( Ω ) have traces on Ω . Let us denote by

W 0 1 , ( Ω ) { u W 1 , ( Ω ) : u = 0 on Ω in the sense of traces }

the closed subspace of W 1 , ( Ω ) .

Proposition 2.3

Let Ω C 1 and a 0 , p , q C 0 , 1 ( Ω ¯ ) . If p ( x ) q ( x ) in Ω and

s + r 1 + 1 N , s + = max Ω ¯ { max { 2 , q ( x ) } } , r = min Ω ¯ { max { 2 , p ( x ) } } ,

then W 0 1 , ( Ω ) = D 1 , ( Ω ) , where D 1 , ( Ω ) is the closure of C c ( Ω ) W 1 , ( Ω ) with respect to the norm of W 1 , ( Ω ) .

The assertion of Proposition 2.3 can be derived from [15, Th. 3.1] or [30, Ch. 6]. For a straightforward construction of the approximating sequence, one may adapt the proof of Proposition 2.2. The properties of the maximal operator and mollifiers in the space L ( Ω ) needed for the proof are established in [30, Th. 4.3.4, Th. 4.3.7]. It is proven in [19, Theorem 2.23] that the function satisfies all conditions of these theorems.

Lemma 2.2

If a 0 , p , q C 0 , 1 ( Ω ¯ ) and Ω C k with

(2.10) k N 1 2 + 1 N 1 s + ,

then m = 1 P m is dense in W 0 1 , ( Ω ) .

We omit the details of the proof which imitates the proof of Lemma 2.1: by Proposition 2.3 C c ( Ω ) is dense in W 0 1 , ( Ω ) , and since C c ( Ω ) H D ( k ) ( Ω ) , every v ε H D k ( Ω ) can be approximated by v ε ( m ) P m .

3 Assumptions and main results

Let p , q : Q T R be measurable functions satisfying the conditions

(3.1) 2 N N + 2 < p p ( z ) p + in Q ¯ T , 2 N N + 2 < q q ( z ) q + in Q ¯ T , p ± , q ± = const .

Assume that p , q W 1 , ( Q T ) as functions of variables z = ( x , t ) : there exist positive constants C , C , C , C such that

(3.2) ess sup Q T p C < , ess sup Q T p t C , ess sup Q T q C < , ess sup Q T q t C .

The modulating coefficient a ( ) is assumed to satisfy the following conditions:

(3.3) a ( z ) 0 in Q ¯ T , a C ( [ 0 , T ] ; C 0 , 1 ( Ω ¯ ) ) , ess sup Q T a t C a ,

C a = const . We do not impose any condition on the null set of the function a in Q ¯ T . If F = f 0 ( z ) , we do not distinguish between the cases of degenerate and singular equations. It is possible that p ( z ) < 2 and q ( z ) > 2 at the same point z Q T . To study the equation with the nonlinear source, we assume p 2 .

Definition 3.1

A function u : Q T R is called strong solution of problem (1.1) if

  1. u W q ( ) ( Q T ) , u t L 2 ( Q T ) , u L ( 0 , T ; L s ( ) ( Ω ) ) with s ( z ) = max { 2 , p ( z ) } ,

  2. for every ψ W q ( ) ( Q T ) ,

    (3.4) Q T u t ψ d z + Q T ( u p ( z ) 2 + a ( z ) u q ( z ) 2 ) u ψ d z = Q T F ( z , u , u ) ψ d z ,

  3. for every ϕ C 0 1 ( Ω )

    Ω ( u ( x , t ) u 0 ( x ) ) ϕ d x 0 as t 0 .

The main results are given in the following theorems.

Theorem 3.1

Let Ω R N , N 2 , be a bounded domain with the boundary Ω C k , k 2 + N 2 . Assume that p ( ) , and q ( ) satisfy conditions (3.1), and (3.2), and there exists a constant,

r ( 0 , r ) , r = 4 p p ( N + 2 ) + 2 N ,

such that

(3.5) p ( z ) q ( z ) p ( z ) + r 2 i n Q ¯ T .

If a ( ) satisfies conditions (3.3) and F f 0 ( z ) , then for every f 0 L 2 ( 0 , T ; W 0 1 , 2 ( Ω ) ) and u 0 W 0 1 , ( Ω ) with

(3.6) Ω ( u 0 2 + u 0 p ( x , 0 ) + a ( x , 0 ) u 0 q ( x , 0 ) ) d x = K < ,

problem (1.1) has a unique strong solution u. This solution satisfies the estimate

(3.7) u t 2 , Q T 2 + ess sup ( 0 , T ) Ω ( u s ( z ) + a ( z ) u q ( z ) ) d x + Q T u p ( z ) + r d z C

with the exponent s ( z ) = max { 2 , p ( z ) } and a constant C, which depends on N , Ω , T , p ± , q ± , r , the constants in conditions (3.2), (3.3), f 0 L 2 ( 0 , T ; W 0 1 , 2 ( Ω ) ) , and K .

Assume that the source F may depend on the solution and its gradient. Let F be defined by (1.2) with Ψ and Φ satisfying the following conditions:

(3.8) Ψ C 0 ( Q ¯ T × R ) , Ψ ( z , 0 ) = 0 , Ψ ( z , r ) C r σ ( z ) 1 , Ψ ( z , v ) C ( v σ ( z ) 1 ( 1 + ln v ) + v σ ( z ) 2 v ) with a constant C and a continuous function σ in Q ¯ T such that 2 σ σ + < , σ = inf Q T σ ( z ) , σ + = sup Q T σ ( z ) ,

and

(3.9) Φ C 0 ( Q ¯ T × R N ) , there exist constants L, M such that for all z Q ¯ T Φ ( z , s ) L s p ( z ) 1 if s < 1 , M s p ( z ) 2 if s 1 .

Theorem 3.2

Let in the conditions of Theorem 3.1, Ψ 0 and/or Φ 0 .

  1. Assume that Ψ satisfies conditions (3.8) and Φ satisfies conditions (3.9). If

    (3.10) 2 < p , σ + < min p , 1 + p N + 2 2 N ,

    then for every f 0 L 2 ( 0 , T ; W 0 1 , 2 ( Ω ) ) and u 0 W 0 1 , ( Ω ) , problem (1.1) has at least one strong solution u. The solution u satisfies estimate (3.7) with the constant depending on the same quantities as in the case F = f 0 ( z ) , the constants in conditions (3.8), (3.9), and σ ± . If Ψ 0 , the assertion is true if (3.10) is substituted by the inequality p 2 .

  2. The strong solution is unique if p ( ) , q ( ) satisfy the conditions of Theorem 3.1, Φ 0 , and either Ψ ( z , u ) = b ( z ) u with a bounded coefficient b ( z ) or Ψ ( z , s ) is monotone decreasing with respect to s for a.e. z Q T .

An outline of the work. In Section 4, we collect several auxiliary assertions. We present estimates on the gradient trace on Ω for the functions from variable Sobolev spaces and formulate the interpolation inequality, which enables us to prove global higher integrability of the gradient. This property turns out to be the key element in the proof of the existence theorems for problem (1.1) and the counterpart regularized problems (problem (5.1)).

A solution of problem (1.1) is obtained as the limit of the family of solutions of the nondegenerate problems (5.1) with the regularized fluxes:

( ε 2 + u 2 ) p ( z ) 2 2 + a ( z ) ( ε 2 + u 2 ) q ( z ) 2 2 u , ε > 0 .

For every ε ( 0 , 1 ) , problem (5.1) is solved with the method of Galerkin. In Section 5, we formulate the problems for the approximations. Section 6 is devoted to derive a priori estimates on the approximate solutions and their derivatives. For the convenience of presentation, we separate the cases F = f 0 ( z ) when the source is independent of the solution and its gradient, and the general case (1.2). In the latter case, the derivation of the a priori estimates requires additional restrictions on the range of the exponent p and the rate of growth of F ( z , u , u ) with respect to the second and third arguments. The a priori estimates of Section 6 involve higher-order derivatives of the approximate solutions. This is where we make use of the interpolation inequalities of Section 4 to obtain the global higher integrability of the gradient which, in turn, yields uniform boundedness of the L q ( ) ( Q T ) -norms of the gradients of the approximate solutions. Despite the fact that the initial datum belongs to a Musielak-Orlicz space, it turns out that the approximate solutions form a uniformly bounded sequence in a variable Sobolev space. This property is crucial in the study of convergence of the sequence of approximations and the regularity of its limit.

Theorems 3.1 and 3.2 are proven in Section 7. We show first that for every ε > 0 , the constructed sequence of Galerkin’s approximations contains a subsequence, which converges to a strong solution u ε of the regularized problem (5.1). The proof relies on the compactness and monotonicity of the fluxes. To pass to the limit in the nonlinear source term, we need the pointwise convergence of the gradients, which turns out to be a byproduct of the uniform higher integrability. Existence of a solution to problem (1.1) is established in a similar way.

Remark 3.1

The condition on the regularity of Ω allows us to use Galerkin’s finite-dimensional approximations in the proof of better regularity of the solution. However, this assumption is not necessary. It can be relaxed by means of approximation of the domain with the boundary Ω C 2 by an expanding family of smooth domains. The family of the corresponding solutions converges to the solution of the problem in the approximated domain.

Remark 3.2

The Lipschitz continuity of the modulating coefficient a ( x , t ) and the exponents p ( x , t ) , q ( x , t ) at t = 0 is essential for approximation of the initial datum u 0 via density of smooth functions in the Musielak-Orlicz-Sobolev space. The proof relies on results of the recent work [19] where this regularity of the data was assumed. When t > 0 , the same regularity of the data is assumed for the derivation of the interpolation inequalities, which involve second-order derivatives.

Notation: Throughout the rest of the text, the symbol C will be used to denote the constants that can be calculated or estimated through the data but whose exact values are unimportant. The value of C may vary from line to line even inside the same formula. Whenever it does not cause a confusion, we omit the arguments of the variable exponents of nonlinearity and the coefficients. We will use the shorthand notation v x x 2 = i , j = 1 N v x i x j 2 .

4 Auxiliary propositions

Until the end of this section, the notation p ( ) , q ( ) , a ( ) is used for functions not related to the exponents and coefficient in (1.1) and (5.1).

Lemma 4.1

(Lemma 1.32, [4]) Let Ω Lip and p C 0 ( Q ¯ T ) . Assume that u L ( 0 , T ; L 2 ( Ω ) ) W 0 1 , p ( ) ( Q T ) and

ess sup ( 0 , T ) u ( , t ) 2 , Ω 2 + Q T u p ( z ) d z = M < .

Then

u p ( ) , Q T C , C = C ( M , p ± , N , ω ) ,

where ω is the modulus of continuity of the exponent p ( ) .

The proof in [4] is given for the case Ω = B R ( x 0 ) . To adapt it to the general case, it is sufficient to consider the zero continuation of u to a circular cylinder containing Q T .

Let us accept the notation

(4.1) β ε ( s ) = ε 2 + s 2 , γ ε ( z , s ) = ( ε 2 + s 2 ) p ( z ) 2 2 + a ( z ) ( ε 2 + s 2 ) q ( z ) 2 2 , s R N , z Q T , ε > 0 .

With certain abuse of notation, we will denote by γ ε ( x , s ) the same function but with the exponents p , and q and the coefficient a depending on the variable x Ω .

Lemma 4.2

(Lemma 4.1, [5]) Let Ω C 1 , u C 2 ( Ω ¯ ) and u = 0 on Ω . Assume that

(4.2) p : Ω [ p , p + ] , p ± = const , 2 N N + 2 < p , p ( ) C 0 ( Ω ¯ ) , ess sup Ω p = L , Ω β ε p ( x ) 2 2 ( u ) u x x 2 d x < , Ω u 2 d x = M 0 , Ω u p ( x ) d x = M 1 .

Then for every

(4.3) 2 N + 2 r < r < r 4 p p ( N + 2 ) + 2 N

and every δ ( 0 , 1 )

(4.4) Ω β ε p ( x ) + r 2 2 ( u ) u 2 d x δ Ω β ε p ( x ) 2 2 ( u ) u x x 2 d x + C 1 + Ω u p ( x ) d x

with an independent of u constant C = C ( Ω , δ , p ± , N , r , M 0 , M 1 ) .

Theorem 4.1

(Theorem 4.1, [5]) Let Ω C 1 , u C 0 ( [ 0 , T ] ; C 2 ( Ω ¯ ) ) and u = 0 on Ω × [ 0 , T ] . Assume that

(4.5) p : Q T [ p , p + ] , p ± = c o n s t , p C 0 ( Q ¯ T ) w i t h t h e m o d u l u s o f c o n t i n u i t y ω 2 N N + 2 < p , ess sup Q T p = L , Q T β ε p ( z ) 2 2 ( u ) u x x 2 d z < , sup ( 0 , T ) u ( t ) 2 , Ω 2 = M 0 , Q T u p ( z ) d z = M 1 .

Then for every

2 N + 2 = r < r < r = 4 p p ( N + 2 ) + 2 N

and every δ ( 0 , 1 ) , the function u satisfies the inequality

(4.6) Q T β ε p ( z ) + r 2 2 ( u ) u 2 d z δ Q T β ε p ( z ) 2 2 ( u ) u x x 2 d z + C 1 + Q T u p ( z ) d z

with an independent of u constant C = C ( N , Ω , T , δ , p ± , ω , r , M 0 , M 1 ) .

Lemma 4.3

Let Ω R N , N 2 be a bounded domain with the boundary Ω C 2 , and a W 1 , ( Ω ) be a given nonnegative function. Assume that v W 3 , 2 ( Ω ) W 0 1 , 2 ( Ω ) and denote

(4.7) K = Ω a ( x ) ( ε 2 + v 2 ) p ( x ) 2 2 ( Δ v ( v n ) ( v n ) v ) d S ,

where n stands for the exterior normal to Ω . There exists a constant L = L ( Ω ) such that

K L Ω a ( x ) ( ε 2 + v 2 ) p ( x ) 2 2 v 2 d S .

Lemma 4.3 follows from the well-known assertions, see, e.g., [33, Ch. 1, Sec. 1.5] for the case a 1 , N = 2 , 3 , or [3, Lemma A.1] for the case of an arbitrary dimension.

Lemma 4.4

Let Ω be a Lipschitz-continuous surface and a ( ) be a nonnegative function on Ω ¯ . Assume that a , q W 1 , ( Ω ) , with

q , Ω L < , a , Ω L 0 < .

There exists a constant δ = δ ( Ω ) such that for every u W 1 , q ( ) ( Ω )

(4.8) δ Ω a ( x ) ( ε 2 + u 2 ) q ( x ) 2 2 u 2 d S C Ω ( a ( x ) u q ( x ) 1 u + a ( z ) u q ( x ) ln u + u q ( x ) + 1 ) d x

with a constant C = C ( q + , L , L 0 , N , Ω ) .

The assertion immediately follows from [5, Lemma 4.4].

Corollary 4.1

Under the conditions of Lemma 4.4, for every λ ( 0 , 1 ) and ε ( 0 , 1 )

(4.9) Ω a ( x ) ( ε 2 + u 2 ) q ( x ) 2 2 u 2 d S λ Ω a ( x ) ( ε 2 + u 2 ) q ( x ) 2 2 u 2 d x + L 0 Ω u q ( x ) d x + L Ω a ( z ) u q ( x ) ln u d x + K

with independent of u constants K, L , L 0 .

Theorem 4.2

Let Ω C 2 , u C 2 ( Ω ¯ ) and u = 0 on Ω . Assume that a ( ) satisfies the conditions of Lemma 4.4, p ( ) satisfies the conditions of Lemma 4.2, and

q : Ω [ q , q + ] 2 N N + 2 , , q W 1 , ( Ω ) , ess sup Ω q = L .

If for a.e. x Ω

q ( x ) < p ( x ) + r w i t h 2 N + 2 < r < 4 p p ( N + 2 ) + 2 N ,

then for every λ ( 0 , 1 )

(4.10) Ω γ ε ( x , u ) u 2 d S λ Ω γ ε ( x , u ) u x x 2 d x + C 1 + Ω u p ( x ) d x

with a constant C depending on λ and the constants p ± , N , L , L 0 , but independent of u.

We omit the proof that follows from Lemma 4.4 and Corollary 4.1 – see the proofs of Theorem 4.2 and Corollary 4.1 in [5].

Since P m C 1 ( Ω ¯ ) H 0 3 ( Ω ) , the interpolation inequalities of this section remain true for every function w P m , m N .

5 Regularized problem

Given ε > 0 , let us consider the following family of regularized double-phase parabolic equations:

(5.1) t u div ( γ ε ( z , u ) u ) = F ( z , u , u ) in Q T , u = 0 on Γ T , u ( 0 , . ) = u 0 in Ω , ε ( 0 , 1 ) ,

where F ( z , u ) is defined in (1.2), γ ε ( z , s ) is introduced in (4.1), and γ ε ( z , u ) u is the regularized flux function. The solution of problem (5.1) is understood in the sense of Definition 3.1.

5.1 Galerkin’s method

Let ε > 0 be a fixed parameter. The sequence { u ε ( m ) } of finite-dimensional Galerkin’s approximations for the solutions of the regularized problem (5.1) is sought in the form

(5.2) u ε ( m ) ( x , t ) = j = 1 m u j ( m ) ( t ) ϕ j ( x ) ,

where ϕ j W 0 1 , 2 ( Ω ) and λ j > 0 are the eigenfunctions and the corresponding eigenvalues of problem (2.8). The coefficients u j ( m ) ( t ) are defined as the solutions of the Cauchy problem for the system of m ordinary differential equations:

(5.3) ( u j ( m ) ) ( t ) = Ω γ ε ( z , u ε ( m ) ) u ε ( m ) ϕ j d x + Ω F ( z , u ε ( m ) , u ε ( m ) ) ϕ j d x , u j ( m ) ( 0 ) = ( u 0 ( m ) , ϕ j ) 2 , Ω , j = 1 , 2 , , m ,

where γ ε is defined in (4.1). By Lemma 2.2, the functions u 0 ( m ) P m can be chosen so that

(5.4) u 0 ( m ) = j = 1 m ( u 0 , ϕ j ) 2 , Ω ϕ j span { ϕ 1 , ϕ 2 , , ϕ m } , u 0 ( m ) u 0 in W 0 1 , ( Ω ) .

By the Carathéodory existence theorem, for every finite m , system (5.3) has a solution ( u 1 ( m ) , u 2 ( m ) , , u m ( m ) ) in the extended sense on an interval ( 0 , T m ) , and the functions u i ( m ) ( t ) are absolutely continuous and differentiable a.e. in ( 0 , T m ) . The a priori estimates derived in Section 6 show that for every m the function u ε ( m ) ( x , T m ) belongs to span { ϕ 1 , , ϕ m } and satisfies the estimate

u ε ( m ) ( , T m ) 2 , Ω 2 + ( u ε ( , T m ) , T m ) C + f 0 2 , Q T 2 + u 0 ( m ) 2 , Ω 2 + ( u 0 ( m ) , 0 )

with the function defined in (1.5) and a constant C independent of m and ε . This estimate allows one to continue each of u ε ( m ) to the maximal existence interval ( 0 , T ) .

6 A priori estimates

6.1 A priori estimates I: the case Φ 0 and Ψ 0

Lemma 6.1

Let Ω be a bounded domain with the boundary Ω Lip , p ( ) , q ( ) satisfy (3.1), a ( ) satisfies (3.3), u 0 L 2 ( Ω ) , and f 0 L 2 ( Q T ) . The function u ε ( m ) satisfies the estimates

(6.1) sup t ( 0 , T ) u ε ( m ) ( , t ) 2 , Ω 2 + Q T γ ε ( z , u ε ( m ) ) u ε ( m ) 2 d z C 1 e T ( f 0 2 , Q T 2 + u 0 2 , Ω 2 )

and

(6.2) Q T ( u ε ( m ) p ( z ) + a ( z ) u ε ( m ) q ( z ) ) d z C 2 Q T γ ε ( z , u ε ( m ) ) u ε ( m ) 2 d z + C 3 ,

where the constants C i are independent of ε and m .

Proof

By multiplying j th equation of (5.3) by u j ( m ) ( t ) and then by summing up the results for j = 1 , 2 , , m , we obtain

(6.3) 1 2 d d t u ε ( m ) ( , t ) 2 , Ω 2 = j = 1 m u j ( m ) ( t ) ( u j ( m ) ) ( t ) = Ω γ ε ( z , u ε ( m ) ) u ε ( m ) 2 d x + Ω f 0 ( x , t ) u ε ( m ) d x .

By the Cauchy inequality,

(6.4) 1 2 d d t u ε ( m ) ( , t ) 2 , Ω 2 + Ω γ ε ( z , u ε ( m ) ) u ε ( m ) 2 d x 1 2 f 0 ( , t ) 2 , Ω 2 + 1 2 u ε ( m ) ( , t ) 2 , Ω 2 .

Now, rewriting the last inequality in the equivalent form,

1 2 d d t ( e t u ε ( m ) ( , t ) L 2 ( Ω ) 2 ) + e t Ω γ ε ( z , u ε ( m ) ) u ε ( m ) 2 d x e t 2 f 0 ( , t ) 2 , Ω 2 ,

and integrating with respect to t , we arrive at the inequality

(6.5) sup t ( 0 , T ) u ε ( m ) ( , t ) L 2 ( Ω ) 2 + Q T γ ε ( z , u ε ( m ) ) u ε ( m ) 2 d z C e T ( f 0 2 , Q T 2 + u 0 2 , Ω 2 ) ,

where the constant C is independent of ε and m . Since a ( z ) is a nonnegative bounded function, the second assertion follows from (6.5) and the inequality

(6.6) a ( z ) u ε ( m ) q ( z ) a ( z ) ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 2 a ( z ) ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 2 u ε ( m ) 2 if u ε ( m ) ε , ( 2 ε 2 ) q ( z ) 2 a ( z ) 2 q + 2 a ( z ) otherwise .

Lemma 6.2

Let Ω be a bounded domain with Ω C k , k 2 + N 2 . Assume that p ( ) , q ( ) satisfies (3.1), (3.2), and (3.5) and a ( ) satisfy (3.3). If u 0 W 0 1 , 2 ( Ω ) and f 0 L 2 ( ( 0 , T ) ; W 0 1 , 2 ( Ω ) ) , then for a.e. t ( 0 , T ) , the following inequality holds:

(6.7) 1 2 d d t u ε ( m ) ( , t ) 2 , Ω 2 + C 0 Ω γ ε ( z , u ε ( m ) ) ( u ε ( m ) ) x x 2 d x C 1 1 + Ω u ε ( m ) p ( z ) d x + u ε ( m ) ( , t ) 2 , Ω 2 + f 0 ( , t ) W 0 1 , 2 ( Ω ) 2

with independent of m and ε constants 0 < C 0 < min { p 1 , 1 } and C 1 > 0 .

Proof

Let us multiply each of equations in (5.3) by λ j u j ( m ) and sum up the results for j = 1 , 2 , , m :

(6.8) 1 2 d d t u ε ( m ) ( , t ) 2 , Ω 2 = j = 1 m λ j ( u j ( m ) ) ( t ) u j ( m ) ( t ) = j = 1 m λ j u j ( m ) Ω div ( γ ε ( z , u ε ( m ) ) u ε ( m ) ) ϕ j d x + j = 1 m λ j u j ( m ) Ω f 0 ( x , t ) ϕ j d x = Ω div ( γ ε ( z , u ε ( m ) ) u ε ( m ) ) Δ u ε ( m ) d x Ω f 0 ( x , t ) Δ u ε ( m ) d x .

Since Ω C k with k 2 + [ N 2 ] , then u ε ( m ) ( , t ) P m H 0 3 ( Ω ) C 1 ( Ω ¯ ) . Therefore, the first term on the right-hand of (6.8) can be transformed by means of the Green formula:

Ω div ( γ ε ( z , u ε ( m ) ) u ε ( m ) ) Δ u ε ( m ) d x = Ω k = 1 N ( u ε ( m ) ) x k x k i = 1 N ( γ ε ( z , u ε ( m ) ) ( u ε ( m ) ) x i ) x i d x = Ω Δ u ε ( m ) γ ε ( z , u ε ( m ) ) ( u ε ( m ) n ) d S + Ω k , i = 1 N ( u ε ( m ) ) x k x k x i γ ε ( z , u ε ( m ) ) ( u ε ( m ) ) x i d x = Ω γ ε ( z , u ε ( m ) ) k , i = 1 N ( ( u ε ( m ) ) x k x k ( u ε ( m ) ) x i n i ( u ε ( m ) ) x k x i ( u ε ( m ) ) x i n k ) d S Ω k , i = 1 N ( u ε ( m ) ) x k x i ( γ ε ( z , u ε ( m ) ) ( u ε ( m ) ) x i ) x k d x = Ω γ ε ( z , u ε ( m ) ) ( u ε ( m ) ) x x 2 d x + J 1 + J 2 + J Ω + J a ,

where n = ( n 1 , , n N ) is the outer normal vector to Ω ,

J 1 Ω ( 2 p ( z ) ) ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 2 1 k = 1 N ( u ε ( m ) ( u ε ( m ) ) x k ) 2 d x + Ω ( 2 q ( z ) ) a ( z ) ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 2 1 k = 1 N ( u ε ( m ) ( u ε ( m ) ) x k ) 2 d x , J 2 = Ω k , i = 1 N ( u ε ( m ) ) x k x i ( u ε ( m ) ) x i ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 2 p x k 2 ln ( ε 2 + u ε ( m ) 2 ) d x Ω k , i = 1 N ( u ε ( m ) ) x k x i ( u ε ( m ) ) x i a ( z ) ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 2 q x k 2 ln ( ε 2 + u ε ( m ) 2 ) d x , J Ω = Ω γ ε ( z , u ε ( m ) ) ( Δ u ε ( m ) ( u ε ( m ) n ) u ε ( m ) ( u ε ( m ) n ) ) d S , J a = Ω i , k = 1 N a x k ( u ε ( m ) ) x i ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 2 ( u ε ( m ) ) x k x i .

Substitution into (6.8) leads to the inequality

(6.9) 1 2 d d t u ε ( m ) ( , t ) 2 , Ω 2 + Ω γ ε ( z , u ε ( m ) ) ( u ε ( m ) ) x x 2 d x = J 1 + J 2 + J Ω + J a Ω f 0 u ε ( m ) d x J 1 + J 2 + J Ω + J a + 1 2 u ε ( m ) ( , t ) 2 , Ω 2 + 1 2 f 0 ( , t ) W 0 1 , 2 ( Ω ) 2 .

The terms on the right-hand side of (6.9) are estimated in three steps.

Step 1: Estimate on J 1 . Since a ( z ) 0 and p ( z ) < q ( z ) in Q T , the term J 1 is merged on the left-hand side.

Indeed:

J 1 = { x Ω : p ( z ) 2 } ( 2 p ( z ) ) + { x Ω : p ( z ) < 2 } ( 2 p ( z ) ) + { x Ω : q ( z ) 2 } ( 2 q ( z ) ) + { x Ω : q ( z ) < 2 } ( 2 q ( z ) ) { p ( z ) < 2 } ( 2 p ( z ) ) ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 2 1 k = 1 N ( u ε ( m ) ( u ε ( m ) ) x k ) 2 d x + { q ( z ) < 2 } ( 2 q ( z ) ) a ( z ) ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 2 1 k = 1 N ( u ε ( m ) ( u ε ( m ) ) x k ) 2 d x ,

whence

J 1 max { 0 , 2 p } Ω ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 2 ( u ε ( m ) ) x x 2 d x + max { 0 , 2 q } Ω a ( z ) ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 2 ( u ε ( m ) ) x x 2 d x .

Step 2: Estimate on J 2 . By the Cauchy inequality, for every δ 0 > 0 ,

(6.10) J 2 1 2 p , Ω Ω ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 4 k , i = 1 N ( u ε ( m ) ) x k x i ( u ε ( m ) ) x i ln ( ε 2 + u ε ( m ) 2 ) ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 4 d x + 1 2 q , Ω Ω ( a ( z ) ) 1 2 ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 4 k , i = 1 N ( u ε ( m ) ) x k x i ( a ( z ) ) 1 2 ( u ε ( m ) ) x i ln ( ε 2 + u ε ( m ) 2 ) ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 4 d x δ 0 Ω γ ε ( z , u ε ( m ) ) k , i = 1 N ( u ε ( m ) ) x k x i 2 d x + C 1 Ω ln 2 ( ε 2 + u ε ( m ) 2 ) γ ε ( z , u ε ( m ) ) u ε ( m ) 2 d x

with a constant C 1 = C 1 ( C , C , N , δ 0 ) . Let us denote

= C 1 Ω ln 2 ( ε 2 + u ε ( m ) 2 ) γ ε ( z , u ε ( m ) ) u ε ( m ) 2 d x .

For μ 1 ( 0 , 1 ) and y > 0 , the following inequality holds:

(6.11) y p 2 ln 2 y y p + μ 1 2 y μ 1 2 ln 2 ( y ) C ( μ 1 , p + ) y p + μ 1 2 if y 1 , y p 2 ln 2 ( y ) C ( p ) if y ( 0 , 1 ) .

Let

(6.12) r = 2 N + 2 and r = 4 p p ( N + 2 ) + 2 N .

Take the numbers r 1 and r 2 such that

r 1 ( r , r ) , r 2 ( 0 , 1 ) , q ( z ) + r 2 p ( z ) + r 1 < p ( z ) + r

and estimate applying (6.11):

C 1 + Ω ( ε 2 + u ε ( m ) 2 ) p ( z ) + r 1 2 2 u ε ( m ) 2 d x + Ω a ( z ) ( ε 2 + u ε ( m ) 2 ) q ( z ) + r 2 2 2 u ε ( m ) 2 d x

with a constant C = C ( C 1 , r 1 , r 2 ) . Let us transform the integrand of the second integral using the following inequality:

(6.13) ( ε 2 + u ε ( m ) 2 ) q ( z ) + r 2 2 2 u ε ( m ) 2 ( ε 2 + u ε ( m ) 2 ) q ( z ) + r 2 2 1 + ( ε 2 + u ε ( m ) 2 ) p ( z ) + r 1 2 1 + ( 2 ε 2 ) p ( z ) + r 1 2 if u ε ( m ) < ε , 2 ( ε 2 + u ε ( m ) 2 ) p ( z ) + r 1 2 2 u ε ( m ) 2 if u ε ( m ) ε .

By using (6.13) and the interpolation inequality of Lemma 4.2, we finally obtain

(6.14) C 1 + Ω ( ε 2 + u ε ( m ) 2 ) p ( z ) + r 1 2 2 u ε ( m ) 2 d x δ 1 Ω ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 2 ( u ε ( m ) ) x x 2 d x + C 1 + Ω u ε ( m ) p ( z ) d x

with any δ 1 ( 0 , 1 ) and C = C ( δ 1 ) . Gathering (6.10) and (6.14), we finally obtain:

J 2 ( δ 0 + δ 1 ) Ω ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 2 ( u ε ( m ) ) x x 2 d x + C 1 + Ω u ε ( m ) p ( z ) d x

with a constant C depending on δ i and a ( , t ) , Ω , but independent of ε and m .

Step 3: Estimates on J a and J Ω . Let ρ ( r , r ) be such that 2 q ( z ) p ( z ) < p ( z ) + ρ < p ( z ) + r . Applying Young’s inequality and (6.13), we obtain the estimate

J a Ω i , k = 1 N a x k ( u ε ( m ) ) x i ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 2 ( u ε ( m ) ) x k x i d x a , Ω Ω ( ε 2 + u ε ( m ) 2 ) 2 q ( z ) p ( z ) 4 ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 4 ( u ε ( m ) ) x x d x δ ˜ Ω ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 2 ( u ε ( m ) ) x x 2 d x + C ( δ ˜ ) Ω ( ε 2 + u ε ( m ) 2 ) 2 q ( z ) p ( z ) 2 d x δ ˜ Ω ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 2 ( u ε ( m ) ) x x 2 d x + C 1 + Ω ( ε 2 + u ε ( m ) 2 ) p ( z ) + ρ 2 d x δ ˜ Ω ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 2 ( u ε ( m ) ) x x 2 d x + C 1 + Ω ( ε 2 + u ε ( m ) 2 ) p ( z ) + ρ 2 2 u ε ( m ) 2 d x ,

where C = C ( a , Ω , N , q ) is independent of ε and m . By Lemma 4.2, we obtain

J a δ 2 Ω ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 2 ( u ε ( m ) ) x x 2 d x + C 1 + Ω u ε ( m ) p ( z ) d x

for any δ 2 ( 0 , 1 ) and a constant C independent of ε and m .

To estimate J Ω , we use Lemma 4.3 and Theorem 4.2:

J Ω Ω γ ε ( z , u ε ( m ) ) ( Δ u ε ( m ) ( u ε ( m ) n ) u ε ( m ) ( u ε ( m ) n ) ) d S C Ω γ ε ( z , u ε ( m ) ) u ε ( m ) 2 d S δ 3 Ω γ ε ( z , u ε ( m ) ) ( u ε ( m ) ) x x 2 d x + C 1 + Ω u ε ( m ) p ( z ) d x

with an arbitrary δ 3 ( 0 , 1 ) and C depending on δ 3 , p , q , a , Ω , and their differential properties, but not on ε and m . To complete the proof and obtain (6.7), we gather the estimates of J 1 , J 2 , J a , and J Ω and choose δ i so small that

min { 1 , p 1 } i = 0 3 δ i = η > 0 .

Lemma 6.3

Under the conditions of Lemma 6.2

(6.15) sup ( 0 , T ) u ε ( m ) ( , t ) 2 , Ω 2 + Q T γ ε ( z , u ε ( m ) ) ( u ε ( m ) ) x x 2 d z C e C T ( 1 + u 0 2 , Ω 2 + f 0 L 2 ( 0 , T ; W 0 1 , 2 ( Ω ) ) 2 )

and for every 0 < r < 4 p p ( N + 2 ) + 2 N ,

(6.16) Q T u ε ( m ) q ( z ) d z + Q T u ε ( m ) p ( z ) + r d z C

with constants C , C , and C independent of m and ε .

Proof

Multiplying (6.7) by e 2 C 1 t and simplifying, we obtain the following differential inequality:

d d t ( e 2 C 1 t u ε ( m ) ( , t ) 2 , Ω 2 ) C e 2 C 1 t 1 + Ω u ε ( m ) p ( z ) d x + f 0 ( , t ) W 0 1 , 2 ( Ω ) 2 .

Integrating it with respect to t and taking into account (6.1) and (6.2), we arrive at the following estimate: for every t [ 0 , T ] ,

u ε ( m ) ( , t ) 2 , Ω 2 C e 2 C 1 T ( u 0 2 , Ω 2 + e T ( 1 + u 0 2 , Ω 2 + f 0 2 , Q T 2 ) + f 2 , Q T 2 ) C e C T ( 1 + u 0 W 0 1 , 2 ( Ω ) 2 + f 0 L 2 ( 0 , T ; W 0 1 , 2 ( Ω ) ) 2 ) .

Substitution of the aforementioned estimate into (6.7) gives

1 2 d d t u ε ( m ) ( , t ) 2 , Ω 2 + C 0 Ω γ ε ( z , u ε ( m ) ) ( u ε ( m ) ) x x 2 d x C 1 1 + Ω u ε ( m ) p ( z ) d x + u 0 2 , Ω 2 + f 0 ( , t ) W 0 1 , 2 ( Ω ) 2 .

Integrating it with respect to t and using (6.2) to estimate the integral of u ε ( m ) p ( z ) on the right-hand side, we obtain

Q T γ ε ( z , u ε ( m ) ) ( u ε ( m ) ) x x 2 d z C e C T ( 1 + u 0 2 , Ω 2 + f 0 L 2 ( 0 , T ; W 0 1 , 2 ( Ω ) ) 2 ) .

To prove estimate (6.16), we make use of Theorem 4.1. Let us fix a number r ( r , r ) with r , r defined in (6.12). Split the cylinder Q T into the two parts Q T + = Q T { p ( z ) + r 2 } and Q T = Q T { p ( z ) + r < 2 } and represent

Q T u ε ( m ) p ( z ) + r d z = Q T + u ε ( m ) p ( z ) + r d z + Q T u ε ( m ) p ( z ) + r d z I + + I .

Since

I + Q T + ( ε 2 + u ε ( m ) 2 ) p ( z ) + r 2 2 u ε ( m ) 2 d z Q T ( ε 2 + u ε ( m ) 2 ) p ( z ) + r 2 2 u ε ( m ) 2 d z ,

the estimate on I + follows immediately from Theorem 4.1 and (6.15). To estimate I , we set B + = Q T { z : u ε ( m ) ε } , B = Q T { z : u ε ( m ) < ε } . The estimate on I follows from Theorem 4.1 and (6.15) because

I = B + B u ε ( m ) p ( z ) + r d z = B + ( u ε ( m ) 2 ) p ( z ) + r 2 2 u ε ( m ) 2 d z + B ε p ( z ) + r d z 2 2 r p 2 B + ( ε 2 + u ε ( m ) 2 ) p ( z ) + r 2 2 u ε ( m ) 2 d z + ε p + r T Ω C 1 + Q T ( ε 2 + u ε ( m ) 2 ) p ( z ) + r 2 2 u ε ( m ) 2 d z .

By combining the aforementioned estimates, using the Young inequality, and applying (6.15), (6.2), and Theorem 4.1, we obtain (6.16) with r ( r , r ) :

Q T u ε ( m ) q ( z ) d z + Q T u ε ( m ) p ( z ) + r d z 1 + Q T u ε ( m ) p ( z ) + r d z C 1 + Q T γ ε ( z , u ε ( m ) ) ( u ε ( m ) ) x x 2 d z + Q T u ε ( m ) p ( z ) d z C .

If r ( 0 , r ] , the required inequality follows from Young’s inequality.□

Corollary 6.1

Under the conditions of Lemma 6.3

(6.17) Q T ( ε 2 + u ε ( m ) 2 ) p ( z ) + r 2 d z C , ε ( 0 , 1 ) ,

with an independent of ε and m constant C.

Corollary 6.2

Let condition (3.5) be fulfilled. Under the conditions of Lemma 6.3

(6.18) ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 2 u ε ( m ) q ( ) , Q T C ,

with a constant C independent of m and ε .

Proof

Condition (3.5) entails the inequality

q ( z ) ( p ( z ) 1 ) q ( z ) 1 q ( z ) p ( z ) + r .

By Young’s inequality, the assertion follows then from (6.17):

Q T ( ε 2 + u ε ( m ) 2 ) q ( z ) ( p ( z ) 1 ) 2 ( q ( z ) 1 ) d z C 1 + Q T u ε ( m ) p ( z ) + r d z C .

Lemma 6.4

Assume that in the conditions of Lemma 6.2, u 0 W 0 1 , 2 ( Ω ) W 0 1 , ( Ω ) . Then

(6.19) ( u ε ( m ) ) t 2 , Q T 2 + sup ( 0 , T ) Ω γ ε ( z , u ε ( m ) ) u ε ( m ) 2 d x C 1 + Ω ( u 0 p ( x , 0 ) + a ( x , 0 ) u 0 q ( x , 0 ) ) d x + f 0 2 , Q T 2 ,

with an independent of m and ε constant C , which depends on the constants in conditions (3.2).

Proof

By multiplying (5.3) with ( u j ( m ) ) t and summing over j = 1 , 2 , , m , we obtain the equality

(6.20) Ω ( u ε ( m ) ) t 2 d x + Ω γ ε ( z , u ε ( m ) ) u ε ( m ) ( u ε ( m ) ) t d x = Ω f 0 ( u ε ( m ) ) t d x .

By using the identity

a ( z ) ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 2 u ε ( m ) ( u ε ( m ) ) t = d d t a ( z ) ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 q ( z ) + a ( z ) q t ( z ) ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 q 2 ( z ) × 1 q ( z ) 2 ln ( ( ε 2 + u ε ( m ) 2 ) ) a t ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 q ( z ) ,

we rewrite (6.20) as:

(6.21) ( u ε ( m ) ) t ( , t ) 2 , Ω 2 + d d t Ω ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 p ( z ) + a ( z ) ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 q ( z ) d x = Ω f 0 ( u ε ( m ) ) t d x Ω p t ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 p 2 ( z ) 1 p ( z ) 2 ln ( ε 2 + u ε ( m ) 2 ) d x Ω a ( z ) q t ( z ) ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 q 2 ( z ) 1 q ( z ) 2 ln ( ( ε 2 + u ε ( m ) 2 ) ) d x + Ω a t ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 q ( z ) d x Ω f 0 ( u ε ( m ) ) t d x + J 1 + J 2 + J 3 .

The first term on the right-hand side of (6.21) is estimated by the Cauchy inequality:

(6.22) Ω f 0 ( u ε ( m ) ) t d x 1 2 ( u ε ( m ) ) t ( , t ) 2 , Ω 2 + 1 2 f 0 ( , t ) 2 , Ω 2 .

To estimate J i , we use (6.1), (6.2), (6.11), (6.14), and (6.16). Fix two numbers r 1 ( r , r ) , r 2 ( 0 , 1 ) such that

q ( z ) + r 2 < p ( z ) + r 1 < p ( z ) + r .

Then

i = 1 3 J i C 1 1 + Ω u ε ( m ) p ( z ) d x + Ω u ε ( m ) q ( z ) d x + C 2 Ω ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 ln ( ε 2 + u ε ( m ) 2 ) d x + C 3 Ω ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 ln ( ε 2 + u ε ( m ) 2 ) d x C 4 1 + Ω ( ε 2 + u ε ( m ) 2 ) p ( z ) + r 1 2 d x .

The required inequality (6.19) follows after gathering the aforementioned estimates, integrating the result in t and applying (5.4).□

6.2 A priori estimates II: the case Φ 0 and/or Ψ 0

We proceed to derive a priori estimates in the case when the equation contains the nonlinear source that depends on the solution and its gradient. The difference in the arguments consists in the necessity to estimate the integrals of the terms that appear after multiplication of F ( z , u ε ( m ) , u ε ( m ) ) by u ε ( m ) , Δ u ε ( m ) , and u ε t ( m ) .

(1) Let us multiply j th equation of (5.3) by u j ( m ) and sum up. In the result we arrive at equality (6.3) with the right-hand side containing the additional terms,

0 Ω Ψ ( z , u ε ( m ) ) u ε ( m ) d x + Ω Φ ( z , u ε ( m ) ) u ε ( m ) d x .

Assume that Ψ satisfies (3.8) and Φ satisfies (3.9) with 1 < σ + < p . Using the Cauchy, Young, and Poincaré inequalities we find that for every t ( 0 , T )

0 C δ + δ Ω u ε ( m ) p d x + C δ Ω u ε ( m ) 2 d x + δ Ω Φ 2 ( z , u ε ( m ) ) d x C δ ( 1 + u ε ( m ) 2 , Ω 2 ) + δ C ^ Ω u ε ( m ) p d x + δ M 2 Ω { u ε ( m ) 1 } u ε ( m ) p ( z ) d x + δ L 2 Ω { u ε ( m ) < 1 } d x C δ ( 1 + u ε ( m ) 2 , Ω 2 ) + δ ( C ^ + M 2 ) Ω u ε ( m ) p ( z ) d x ,

where δ ( 0 , 1 ) is an arbitrary constant and C ^ is the constant from inequality (2.6) with r = p . We plug this estimate into (6.4) and use (6.6) with a 1 and q substituted by p . Choosing δ sufficiently small, we transform (6.4) to the form

1 2 d d t u ε ( m ) 2 , Ω 2 + C Ω γ ε ( z , u ε ( m ) ) u ε ( m ) 2 d x C ( 1 + f 0 2 , Ω 2 + u ε ( m ) 2 , Ω 2 ) .

Integrating this inequality in t , we obtain the following counterpart of Lemma 6.1.

Lemma 6.5

Assume that a ( ) , p ( ) , q ( ) , u 0 , and f 0 satisfy the conditions of Lemma 6.1. If Ψ and Φ satisfy conditions (3.8) and (3.9), respectively, then

(6.23) sup t ( 0 , T ) u ε ( m ) ( , t ) 2 , Ω 2 + Q T γ ε ( z , u ε ( m ) ) u ε ( m ) 2 d z C 1 e C 2 T ( f 0 2 , Q T 2 + u 0 2 , Ω 2 ) + C 0

and

(6.24) Q T ( u ε ( m ) p ( z ) + a ( z ) u ε ( m ) q ( z ) ) d x d t C 2 Q T γ ε ( z , u ε ( m ) ) u ε ( m ) 2 d z + C 3

with independent of ε and m constants C i .

(2) Estimate on u ε ( m ) ( t ) 2 , Ω . We follow the proof of Lemma 6.2: by multiplying each of equations in (5.3) by λ j u j ( m ) and summing the results, we arrive at equality (6.8) with the additional terms on the right-hand side:

1 ( 1 ) + 1 ( 2 ) Ω Ψ ( z , u ε ( m ) ) u ε ( m ) Δ u ε ( m ) d x + Ω Φ ( z , u ε ( m ) ) Δ u ε ( m ) d x .

Estimate of 1 ( 1 ) . By the Green formula and by virtue of (3.8),

1 ( 1 ) Ω Ψ ( z , u ε ( m ) ) u ε ( m ) d x C Ω u ε ( m ) σ ( z ) 2 u ε ( m ) 2 d x + C Ω u ε ( m ) σ ( z ) 1 u ε ( m ) d x + C Ω u ε ( m ) σ ( z ) 1 ln ( u ε ( m ) ) u ε ( m ) d x K 1 + K 2 + K 3 .

Since σ + < p by assumption, we may apply (6.11) with a constant μ chosen so small that σ + 1 + 2 μ p 1 . Then

K 3 δ Ω u ε ( m ) p d x + C 1 + Ω u ε ( m ) ( σ ( z ) 1 + μ ) p p 1 d x C + δ Ω u ε ( m ) p d x + δ Ω u ε ( m ) p d x C + δ ( 1 + C ) Ω u ε ( m ) p ( z ) d x

with arbitrary δ > 0 and independent of ε and m constants. K 2 is estimated likewise:

K 2 C Ω u ε ( m ) σ ( z ) 1 u ε ( m ) d x δ Ω u ε ( m ) p d x + C δ Ω u ε ( m ) ( σ ( z ) 1 ) p p 1 d x C + δ ( 1 + C ) Ω u ε ( m ) p ( z ) d x .

To estimate K 1 , we assume 2 σ σ + < p . By the inequalities of Young and Poincaré,

K 1 δ Ω u ε ( m ) p d x + C δ Ω u ε ( m ) p σ ( z ) 2 p 2 d x C + δ ( 1 + C ) Ω u ε ( m ) p ( z ) d x .

Observe that in the case Ψ 0 , we have 1 ( 1 ) = 0 , and the assumption 2 < p becomes superfluous.

Estimate on 2 ( 2 ) . Assume that p ( z ) 2 in Q T , fix t ( 0 , T ) and denote Ω + = Ω { u ε ( m ) 1 } and Ω = Ω { u ε ( m ) < 1 } . By the Cauchy inequality,

Ω Φ ( z , u ε ( m ) ) Δ u ε ( m ) d x L Ω u ε ( m ) p 2 u ε ( m ) p 2 2 Δ ε ( m ) u d x δ Ω ( ε 2 + u ε ( m ) 2 ) p 2 2 Δ u ε ( m ) 2 d x + C δ , L Ω ,

Ω + Φ ( z , u ε ( m ) ) Δ u ε ( m ) d x Ω + Φ ( z , u ε ( m ) ) u ε ( m ) p 2 2 Δ u ε ( m ) d x M Ω + u ε ( m ) p 2 u ε ( m ) p 2 2 Δ u ε ( m ) d x δ Ω ( ε 2 + u ε ( m ) 2 ) p 2 2 Δ u ε ( m ) 2 d x + C δ , M Ω u ε ( m ) p d x .

Following the proof of Lemma 6.3, we arrive at the inequality

(6.25) sup ( 0 , T ) u ε ( m ) ( , t ) 2 , Ω 2 + Q T γ ε ( z , u ε ( m ) ) ( u ε ( m ) ) x x 2 d z C e C T u 0 2 , Ω 2 + f 0 L 2 ( 0 , T ; W 0 1 , 2 ( Ω ) ) 2 + Q T u ε ( m ) p ( z ) d z + Q T u ε ( m ) p ( z ) d z + 1

with new constants C and C , which do not depend on ε and m . The last term on the right-hand side of this inequality is estimated by virtue of Lemma 4.1 and estimates (6.23) and (6.24).

Lemma 6.6

Under the conditions of Lemma 6.5,

(6.26) sup ( 0 , T ) u ε ( m ) ( , t ) 2 , Ω 2 + Q T γ ε ( z , u ε ( m ) ) ( u ε ( m ) ) x x 2 d z C e C T ( C ^ + u 0 W 0 1 , 2 ( Ω ) 2 + f 0 L 2 ( 0 , T ; W 0 1 , 2 ( Ω ) ) 2 )

with an independent of ε and m constants C, C , and a constant C ^ depending only on T, and the quantities on the right-hand sides of (6.1), (6.2). If Ψ 0 , estimate (6.26) holds for p 2 .

(3) Estimate on u ε t ( m ) 2 , Q T . We follow the proof of Lemma 6.4. Multiplying (5.3) by ( u ε ( m ) ) t and summing the results, we obtain equality (6.21) with the additional terms on the right-hand side:

0 Ω Ψ ( z , u ε ( m ) ) u ε ( m ) u ε t ( m ) d x + Ω Φ ( z , u ε ( m ) ) u ε t ( m ) d x .

By (3.8), (3.9), and Young’s inequality,

0 C 0 + C 1 Ω u ε ( m ) 2 ( σ + 1 ) d x + C 2 Ω u ε ( m ) p ( z ) d x + δ Ω ( u ε ( m ) ) t 2 d x .

Let us make use of the Gagliardo-Nirenberg inequality. If θ = 1 2 σ + 2 σ + 1 1 2 + 1 N 1 p [ 0 , 1 ] , then for every v W 0 1 , p ( Ω ) ,

v 2 ( σ + 1 ) , Ω C v p , Ω θ v 2 , Ω 1 θ

with an independent of v constant C . The inclusion θ [ 0 , 1 ] holds if

2 σ + < σ = 1 + N p 2 ( N p ) if p < N , if p N .

Let us claim that

2 θ ( σ + 1 ) p σ + 1 + p N + 2 2 N < σ .

Then by Young’s inequality

(6.27) Ω u ε ( m ) 2 ( σ + 1 ) d x C u ε ( m ) p , Ω 2 θ ( σ + 1 ) u ε ( m ) 2 , Ω 2 ( 1 θ ) ( σ + 1 ) C 1 + Ω u ε ( m ) p d x

with a constant C depending on u ε ( m ) 2 , Ω , already estimated in Lemma 6.5 for σ + < p . Combining these inequalities with (6.19), we obtain

(6.28) 1 2 ( u ε ( m ) ) t 2 , Q T 2 + sup ( 0 , T ) Ω γ ε ( z , u ε ( m ) ) u ε ( m ) 2 d x f 0 2 , Q T 2 + C 1 + Ω ( u 0 p ( x , 0 ) + a ( x , 0 ) u 0 q ( x , 0 ) ) d x + Q T u ε ( m ) p ( z ) .

The last integral on the right-hand side is estimated by virtue of Lemma 4.1 and the estimates of Lemma 6.5.

Lemma 6.7

Let in the conditions of Lemma 6.6

2 < p , 2 σ σ + < min p , 1 + p N + 2 2 N .

Then

(6.29) 1 2 ( u ε ( m ) ) t 2 , Q T 2 + sup ( 0 , T ) Ω γ ε ( z , u ε ( m ) ) u ε ( m ) 2 d x C 1 + Ω ( u 0 p ( x , 0 ) + a ( x , 0 ) u 0 q ( x , 0 ) ) d x + f 0 2 , Q T 2 ,

with a constant C independent of ε and m. If Ψ 0 , estimate (6.29) is true for p 2 .

7 Existence and uniqueness of strong solutions

7.1 Regularized problem

Theorem 7.1

Let u 0 , f , p , q , a , and Ω satisfy the conditions of Theorem 3.1. Then for every ε ( 0 , 1 ) , problem (5.1) has a unique solution u ε , which satisfies the estimates

(7.1) u ε W q ( ) ( Q T ) C 0 , ess sup ( 0 , T ) u ε ( , t ) 2 , Ω 2 + u ε t 2 , Q T 2 + ess sup ( 0 , T ) u ε ( , t ) 2 , Ω 2 + ess sup ( 0 , T ) Ω ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 + a ( z ) ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 d x C 0 ,

with a constant C 0 depending on the data but not on ε . Moreover, u ε possesses the property of global higher integrability of the gradient: for every,

δ ( 0 , r ) , r = 4 p p ( N + 2 ) + 2 N ,

there exists a constant C = C ( Ω , N , p ± , δ , u 0 W 0 1 , 2 ( Ω ) , f L 2 ( 0 , T ; W 0 1 , 2 ( Ω ) ) ) such that

(7.2) Q T u ε p ( z ) + δ d z C .

Proof

Let ε ( 0 , 1 ) be a fixed parameter. Under the assumptions of Theorem 3.1, there exists a sequence of Galerkin approximations u ε ( m ) defined by formulas (5.2). The functions u ε ( m ) satisfy estimates (6.1), (6.2), (6.15), (6.16), (6.18), and (6.19). These uniform in m and ε estimates enable one to extract a subsequence u ε ( m ) (for which we keep the same name), and functions u ε , η ε , χ ε such that

(7.3) u ε ( m ) u ε -weakly in L ( 0 , T ; L 2 ( Ω ) ) , ( u ε ( m ) ) t ( u ε ) t in L 2 ( Q T ) , u ε ( m ) u ε in ( L p ( ) ( Q T ) ) N , u ε ( m ) u ε in ( L q ( ) ( Q T ) ) N , ( ε 2 + u ε ( m ) 2 ) p ( z ) 2 2 u ε ( m ) η ε in ( L q ( ) ( Q T ) ) N , ( ε 2 + u ε ( m ) 2 ) q ( z ) 2 2 u ε ( m ) χ ε in ( L q ( ) ( Q T ) ) N .

In the third line, we made use of the uniform estimate

Q T ( ε 2 + u ε ( m ) 2 ) q ( z ) ( p ( z ) 1 ) 2 ( q ( z ) 1 ) d z C 1 + Q T u ε ( m ) p ( z ) + r d z C ,

which follows from (3.5) and (6.16). The functions u ε ( m ) and ( u ε ( m ) ) t are uniformly bounded in L ( 0 , T ; W 0 1 , p ( Ω ) ) and L 2 ( 0 , T ; L 2 ( Ω ) ) , respectively, and W 0 1 , q ( , t ) ( Ω ) W 0 1 , q ( Ω ) L 2 ( Ω ) . By [42, Sec. 8, Corollary 4], the sequence { u ε ( m ) } is relatively compact in C ( [ 0 , T ] ; L 2 ( Ω ) ) , i.e., there exists a subsequence { u ε ( m k ) } , which we assume coinciding with { u ε ( m ) } , such that u ε ( m ) u ε in C ( [ 0 , T ] ; L 2 ( Ω ) ) and a.e. in Q T . Let us define

P m = ϕ : ϕ = i = 1 m ψ i ( t ) ϕ i ( x ) , ψ i are absolutely continuous in [ 0 , T ] .

Fix some m N . By the method of construction u ε ( m ) P m . Since P k P m for k < m , then for every ξ k P k with k m ,

(7.4) Q T u ε t ( m ) ξ k d z + Q T γ ε ( z , u ε ( m ) ) u ε ( m ) ξ k d z = Q T f 0 ξ k d z .

Let ξ W q ( ) ( Q T ) . The space C ( [ 0 , T ] ; C 0 ( Ω ) ) is dense in W q ( ) ( Q T ) ; therefore, there exists a sequence { ξ k } such that ξ k P k and ξ k ξ W q ( ) ( Q T ) . If U m U in L q ( ) ( Q T ) , then for every V L q ( ) ( Q T ) , we have

a ( z ) V L q ( ) ( Q T ) and Q T a U m V d z Q T a U V d z .

Using this fact, we pass to the limit as m in (7.4) with a fixed k , and then, letting k , we conclude that

(7.5) Q T u ε t ξ d z + Q T η ε ξ d z + Q T a ( z ) χ ε ξ d z = Q T f 0 ξ d z

for all ξ W q ( ) ( Q T ) . To identify the limit vectors η ε and χ ε , we use the classical argument based on monotonicity. The flux function γ ε ( z , u ε ( m ) ) u ε ( m ) is monotone:

(7.6) ( γ ε ( z , ξ ) ξ γ ε ( z , ζ ) ζ , ξ ζ ) 0 for all ξ , ζ R N , z Q T , ε 0 ,

see, e.g., [5, Lemma 6.1] for the proof. By virtue of (7.6), for every ψ P m ,

(7.7) γ ε ( z , u ε ( m ) ) u ε ( m ) 2 = γ ε ( z , u ε ( m ) ) u ε ( m ) ( u ε ( m ) ψ ) + γ ε ( z , u ε ( m ) ) u ε ( m ) ψ γ ε ( z , ψ ) ψ ( u ε ( m ) ψ ) + γ ε ( z , u ε ( m ) ) u ε ( m ) ψ .

By taking ξ k = u ε ( m ) in (7.4), we obtain: for every ψ P k with k m ,

0 = Q T ( u ε ( m ) ) t u ε ( m ) d z + Q T γ ε ( z , u ε ( m ) ) u ε ( m ) 2 d z Q T f 0 u ε ( m ) d z Q T ( u ε ( m ) ) t u ε ( m ) d z + Q T γ ε ( z , ψ ) ψ ( u ε ( m ) ψ ) d z + Q T γ ε ( z , u ε ( m ) ) u ε ( m ) ψ d z Q T f 0 u ε ( m ) d z .

Notice that ( u ε ( m ) , ( u ε ( m ) ) t ) 2 , Q T ( u ε t , u ε ) 2 , Q T as m as the product of weakly and strongly convergent sequences. This fact together with (7.3) means that each term of the last inequality has a limit as m . Letting m and using (7.5), we find that for every ψ P k

0 Q T u ε u ε t d z + Q T γ ε ( z , ψ ) ψ ( u ε ψ ) d z + Q T ( η ε + a ( z ) χ ε ) ψ d z Q T f 0 u ε d z = Q T ( ε 2 + ψ 2 ) p ( z ) 2 2 ψ η ε ( u ε ψ ) d z + Q T a ( z ) ( ε 2 + ψ 2 ) q ( z ) 2 2 ψ χ ε ( u ε ψ ) d z .

By the density of k = 1 P k in W q ( ) ( Q T ) , the last inequality also holds for every ψ W q ( ) ( Q T ) . Take ψ = u ε + λ ξ with a constant λ > 0 and an arbitrary ξ W q ( ) ( Q T ) . Then

(7.8) λ Q T ( ε 2 + ( u ε + λ ξ ) 2 ) p ( z ) 2 2 ( u ε + λ ξ ) η ε ξ d z + Q T a ( z ) ( ε 2 + ( u ε + λ ξ ) 2 ) q ( z ) 2 2 ( u ε + λ ξ ) χ ε ξ d z 0 .

Simplifying and letting λ 0 we find that

Q T ( γ ε ( z , u ε ) u ε ( η ε + a ( z ) χ ε ) ) ξ d z 0 ξ W q ( ) ( Q T ) ,

which is possible only if

Q T ( γ ε ( z , u ε ) u ε ( η ε + a ( z ) χ ε ) ) ξ d z = 0 ξ W q ( ) ( Q T ) .

The initial condition for u ε is fulfilled by continuity because u ε C ( [ 0 , T ] ; L 2 ( Ω ) ) .

Uniqueness of the weak solution is an immediate byproduct of monotonicity. Let u and v are two solutions of problem (5.1). Take an arbitrary τ ( 0 , T ] . Choosing u v for the test function in equalities (3.4) for u and v in the cylinder Q τ = Ω × ( 0 , τ ) and subtracting the results and applying (7.6), we arrive at the inequality

1 2 u v 2 , Ω 2 ( τ ) = Q τ ( u v ) ( u v ) t d z 0 .

It follows that u ( x , τ ) = v ( x , τ ) a.e. in Ω for every τ [ 0 , T ] .

Estimates (7.1) follow from the uniform in m estimates on the functions u ε ( m ) and their derivatives, the properties of weak convergence (7.3), and lower semicontinuity of the modular. Inequality (6.17) yields that for every δ ( 0 , r ) the sequence { u ε ( m ) } contains a subsequence, which converges to u ε weakly in ( L p ( ) + δ ( Q T ) ) N , whence (7.2).□

Theorem 7.2

Let in the conditions of Theorem 7.1, Ψ 0 and/or Φ 0 .

  1. If a , p , q , Ψ , and Φ satisfy the conditions of Theorem 3.2, then for every ε ( 0 , 1 ) , problem (5.1) has at least one strong solution u ε , which satisfies estimates (7.1) and (7.2) and

    u ε σ ( z ) 2 u ε 2 , Q T C 1 , Φ ( z , u ε ) 2 , Q T C 2

    with independent of ε constants C i .

  2. The solution is unique if Φ 0 and either Ψ ( z , v ) b ( z ) v with a bounded b ( z ) , or Ψ ( z , v ) is monotone decreasing with respect to v for a.e. z Q T .

Proof

The estimates of Lemmas 6.56.7 allow one to extract a subsequence { u ε ( m ) } with the convergence properties (7.3). The sequences v m = Ψ ( z , u ε ( m ) ) and w m = Φ ( z , u ε ( m ) ) are uniformly bounded in L 2 ( Q T ) because of (6.27) and (6.24). It follows that v m and w m converge weakly in L 2 ( Q T ) to some functions v and w (up to a subsequence). Due to the pointwise convergence u ε ( m ) u ε , it is necessary that v = Ψ ( z , u ε ) a.e. in Q T . As in the proof of Theorem 7.1, we conclude that for every test-function ξ k P m , k m , u ε ( m ) satisfies (7.4) with f 0 substituted by F ( z , u ε ( m ) , u ε ( m ) ) , and for every ξ W q ( ) ( Q T ) , the limit u ε satisfies (7.5) with f 0 substituted by f 0 + Ψ ( z , u ) + w . By using (7.7), we find that

0 = Q T ( u ε ( m ) ) t u ε ( m ) d z + Q T γ ε ( z , u ε ( m ) ) u ε ( m ) 2 d z Q T F ( z , u ε ( m ) , u ε ( m ) ) u ε ( m ) d z Q T ( u ε ( m ) ) t u ε ( m ) d z + Q T γ ε ( z , ψ ) ψ ( u ε ( m ) ψ ) d z + Q T γ ε ( z , u ε ( m ) ) u ε ( m ) ψ d z Q T F ( z , u ε ( m ) , u ε ( m ) ) u ε ( m ) d z .

Letting m , by using the convergence properties of the sequences { u ε ( m ) } , { v m } , { w m } , and then comparing the result with (7.5) with f 0 + Ψ ( z , u ε ) + w on the right-hand side, we conclude that the limit function satisfies (7.8) for every ξ W q ( ) ( Q T ) . The limits η ε and χ ε are identified then by monotonicity.

To prove that w = Φ ( z , u ε ) , it is enough to show that u ε ( m ) u ε a.e. in Q T . It follows from the weak convergence u ε ( m ) u ε in L q ( ) ( Q T ) , the strong convergence u ε ( m ) u ε in L 2 ( Q T ) , and the Mazur Lemma, see [12, Ch.3, Cor.3.8], that there exists a sequence { v ε ( m ) } such that v ε ( m ) P m , each v ε ( m ) is a convex combination of { u ε ( 1 ) , u ε ( 2 ) , , u ε ( m ) } , and

(7.9) v ε ( m ) u ε in W q ( ) ( Q T ) .

Let us define w m P m as follows:

u ε w m W q ( ) ( Q T ) = dist ( u ε , P m ) min { u ε w W q ( ) ( Q T ) : w P m } .

Because of (7.9) such w m exists and

(7.10) dist ( u ε , P m ) = u ε w m W q ( ) ( Q T ) u ε v ε ( m ) W q ( ) ( Q T ) 0 , m .

By the properties of the modular and the strong convergence u ε ( m ) u ε in L 2 ( Q T ) , we also have

(7.11) u ε ( m ) w m 2 , Q T 2 + Q T ( u ε w m ) q ( z ) d z 2 u ε ( m ) u ε 2 , Q T 2 + 2 u ε w m 2 , Q T 2 + Q T ( u ε w m ) q ( z ) d z 0

as m . Since u ε ( m ) satisfy identities (7.4) with f 0 substituted by F ( z , u ε ( m ) , u ε ( m ) ) , and u ε satisfy (3.4) with the regularized fluxes γ ε ( z , u ε ) u ε and the source f 0 + Ψ ( z , u ε ) + w , the functions u ε ( m ) , w m N m are admissible test functions in the integral identities for u ε ( m ) and u ε . By subtracting these identities and rearranging the result, we obtain

(7.12) Q T ( γ ε ( z , u ε ( m ) ) u ε ( m ) γ ε ( z , u ε ) u ε ) ( u ε ( m ) u ε ) d z = Q T ( ( u ε ( m ) ) t u ε t ) ( u ε ( m ) w m ) d z + Q T ( w m w ) ( u ε ( m ) w m ) d z + Q T ( Ψ ( z , u ε ( m ) ) Ψ ( z , u ε ) ) ( u ε ( m ) w m ) d z Q T ( γ ε ( z , u ε ( m ) ) u ε ( m ) γ ε ( z , u ε ) u ε ) ( u ε w m ) d z .

By the choice of w m and due to the convergence properties (7.3), all terms on the right-hand side of (7.12) tend to zero as m . The left-hand side is bounded from below because of the strict monotonicity of the function ( ε 2 + ξ 2 ) p 2 2 ξ with ε [ 0 , 1 ) , p 2 . By using (7.6) with p ( z ) 2 and (7.12) we find that ( u ε ( m ) u ε ) 0 in L p ( ) ( Q T ) . Hence, u ε ( m ) u ε a.e. in Q T up to a subsequence, and w = Φ ( z , u ε ) as required.

To prove the uniqueness we assume, for contradiction, that problem (5.1) with Φ 0 has two strong solutions u 1 , u 2 W q ( ) ( Q T ) . The function u 1 u 2 is an admissible test function in the integral identities (3.4) for u i . Combining these identities and using (7.6), we arrive at the inequality:

1 2 u 1 u 2 2 , Ω 2 ( t ) 0 t Ω ( Ψ ( z , u 1 ) Ψ ( z , u 2 ) ) ( u 1 u 2 ) d z .

If Ψ ( z , s ) = b ( z ) s , this inequality takes the form

1 2 u 1 u 2 2 , Ω 2 ( t ) B 0 t u 1 u 2 2 , Ω 2 ( τ ) d τ , t ( 0 , T ) , B = ess sup Q T b ( z ) ,

whence u 1 u 2 2 , Ω ( t ) = 0 in ( 0 , T ) by Grönwall’s inequality. Let Ψ ( z , s ) be monotone decreasing in s for a.e. z Q T . Then ( Ψ ( z , u 1 ) Ψ ( z , u 2 ) ) ( u 1 u 2 ) 0 a.e. in Q T and

1 2 u 1 u 2 2 , Ω 2 ( t ) 0 in ( 0 , T ) .

7.2 Degenerate problem. Proofs of Theorems 3.1 and 3.2

We begin with the proof of Theorem 3.1 and assume that F f 0 ( z ) . Let { u ε } be the family of strong solutions of the regularized problems (5.1) satisfying estimates (7.1). These uniform in ε estimates enable one to extract a sequence { u ε k } and find functions u W q ( ) ( Q T ) , η , χ ( L q ( ) ( Q T ) ) N with the following properties:

(7.13) u ε k u in L 2 ( Q T ) and a.e. in Q T , u ε k t u t in L 2 ( Q T ) , u ε k u in ( L q ( ) ( Q T ) ) N , ( ε k 2 + u ε k 2 ) p ( z ) 2 2 u ε k η in ( L q ( ) ( Q T ) ) N , ( ε k 2 + u ε k 2 ) q ( z ) 2 2 u ε k χ in ( L q ( ) ( Q T ) ) N .

In the third line, we make use of the uniform estimate

Q T ( ε 2 + u ε 2 ) q ( z ) ( p ( z ) 1 ) 2 ( q ( z ) 1 ) d z C 1 + Q T u ε p ( z ) + r d z C ,

which follows from (3.5) and (7.2). Moreover, u C ( [ 0 , T ] ; L 2 ( Ω ) ) . Each of u ε k satisfies the identity

(7.14) Q T u ε k t ξ d z + Q T γ ε k ( z , u ε k ) u ε k ξ d z = Q T f 0 ξ d z

for all ξ W q ( ) ( Q T ) , which yields

(7.15) Q T u t ξ d z + Q T ( η + a ( z ) χ ) ξ d z = Q T f 0 ξ d z ξ W q ( ) ( Q T ) .

To identify η and χ , we use the monotonicity argument. Take ξ = u ε k in (7.14):

(7.16) Q T u ε k t u ε k d z + Q T γ ε k ( z , u ε k ) u ε k u ε k d z = Q T f 0 u ε k d z .

According to (7.7), for every ϕ W q ( ) ( Q T ) ,

Q T γ ε k ( z , u ε k ) u ε k u ε k d z Q T γ ε k ( z , ϕ ) ( ϕ p 2 + a ϕ q 2 ) ϕ ( u ε k ϕ ) d z + Q T γ ε k ( z , u ε k ) u ε k ϕ d z + Q T ( ϕ p 2 + a ϕ q 2 ) ϕ ( u ε k ϕ ) d z J 1 , k + J 2 , k + J 3 , k ,

where

J 2 , k Q T ( η + a ( z ) χ ) ϕ d z , J 3 , k Q T ( ϕ p 2 + a ( z ) ϕ q 2 ) ϕ ( u ϕ ) d z as k .

Since ( γ ε k ( z , ϕ ) ϕ ( ϕ p 2 + a q 1 q ( z ) ϕ q 2 ) ϕ 0 a.e. in Q T as k , and because the integrand of J 1 , k has the majorant,

( ( ε k 2 + ϕ 2 ) p 2 2 ϕ p 2 ) ϕ p + a q 1 q ( z ) ( ε k 2 + ϕ 2 ) q 2 2 ϕ q 2 ϕ q C ( 1 + ϕ 2 ) p ( z ) 2 + a ( z ) ( 1 + ϕ 2 ) q ( z ) 2 C ( 1 + ϕ p ( z ) + a ( z ) ϕ q ( z ) ) ,

then J 1 , k 0 by the dominated convergence theorem. Combining (7.15) with (7.16) and letting k , we find that for every ϕ W q ( ) ( Q T ) ,

Q T ( ( ϕ p ( z ) 2 + a ( z ) ϕ q ( z ) 2 ) ϕ ( η + a ( z ) χ ) ) ( u ϕ ) d z 0 .

Choosing ϕ = u + λ ζ with λ > 0 and ζ W q ( ) ( Q T ) , simplifying, and then letting λ 0 + , we conclude that for every ζ W q ( ) ( Q T )

Q T ( ( u p ( z ) 2 u + a ( z ) u q ( z ) 2 u ) ( η + a ( z ) χ ) ) ζ d z 0 .

Since the sign of ζ is arbitrary, the last relation must be the equality. It follows that in (7.15) η + a ( z ) χ can be substituted by u p ( z ) 2 u + a ( z ) u q ( z ) 2 u . Since u C ( [ 0 , T ] ; L 2 ( Ω ) ) , the initial condition is fulfilled by continuity. Estimates (3.7) follow from the uniform in ε estimates of Theorem 7.1 and the lower semicontinuity of the modular exactly as in the proof of Theorem 7.1. Uniqueness of a strong solution is an immediate consequence of the monotonicity. Theorem 3.1 is proven.

Proof of Theorem 3.2. The sequence of solutions of the regularized problems (5.1) contains a subsequence { u ε k } that has the convergence properties (7.13) and satisfies the uniform estimates of Theorem 7.2 (i). It follows that there exist v , w L 2 ( Q T ) such that v k = Ψ ( z , u ε k ) v and w k Φ ( z , u ε k ) w in L 2 ( Q T ) . The pointwise convergence u ε u entails the equality v = Ψ ( z , u ) . Following the proof of Theorem 7.2, we conclude that the limit function u solves problem (1.1) with the source f 0 + Ψ ( z , u ) + w . The equality w = Φ ( z , u ) will follow if we show that u ε k u a.e. in Q T . Take u ε k u W q ( ) ( Q T ) for the test function in identities (3.4) for u ε k and u . Subtract these identities and rewrite the result in the following form:

Q T ( γ ε k ( z , u ε k ) u ε k γ ε k ( z , u ) u ) ( u ε k u ) d z = Q T ( u ε k u ) t ( u ε k u ) d z + Q T ( w k w ) ( u ε k u ) d z + Q T ( Ψ ( z , u ε k ) Ψ ( z , u ) ) ( u ε k u ) d z + Q T ( γ 0 ( z , u ) u γ ε k ( z , u ) u ) ( u ε k u ) d z .

The first two terms on the right-hand side of these inequality tend to zero when ε k 0 as the products of weakly and strongly convergent sequences. The third term tends to zero because u ε k u 2 , Q T 0 , while Ψ ( z , u ε k ) and Ψ ( z , u ) are uniformly bounded in L 2 ( Q T ) . To prove that the last term tends to zero, we use the same arguments as in the case of the integral J 1 , k in the proof of Theorem 3.1. By virtue of (7.6) and (2.5) u ε k u in ( L p ( ) ( Q T ) ) N and a.e. in Q T .

The uniqueness follows by the same arguments as in the case of the nondegenerate problem.



Acknowledgments

Rakesh Arora acknowledges the support of the Research Grant from Czech Science Foundation, project GJ19-14413Y for the second part of this work. Sergey Shmarev was supported by the Research Grant MCI-21-PID2020-116287GB-I00, Spain.

  1. Conflict of interest: The authors state no conflict of interest.

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Received: 2022-05-07
Accepted: 2022-07-18
Published Online: 2022-09-08

© 2023 Rakesh Arora and Sergey Shmarev, published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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