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Global existence for time-dependent damped wave equations with nonlinear memory

  • Mokhtar Kirane , Ahmad Z. Fino , Ahmed Alsaedi EMAIL logo and Bashir Ahmad
Published/Copyright: November 18, 2023

Abstract

In this article, we consider the Cauchy problem for a semi-linear wave equation with time-dependent damping and memory nonlinearity. Conditions for global existence are presented in the energy space H 1 ( R n ) × L 2 ( R n ) , n 1 .

MSC 2010: 35L71; 35A01

1 Introduction

This article concerns the Cauchy problem for the following semi-linear damped wave equation:

(P) u t t Δ u + b ( t ) u t = 0 t ( t s ) γ u ( s ) p d s , t > 0 , x R n , u ( 0 , x ) = u 0 ( x ) , u t ( 0 , x ) = u 1 ( x ) , x R n ,

where the unknown function u is real-valued, n 1 , 0 < γ < 1 , and p > 1 . Here, the kernel is weakly singular. The coefficient of the damping term is given as follows:

b ( t ) b 0 ( 1 + t ) β ,

with b 0 > 0 , and 0 β < 1 . Throughout this article, we assume that the initial data are in the energy space

(IC) ( u 0 , u 1 ) A m ( L m ( R n ) H 1 ( R n ) ) × ( L m ( R n ) L 2 ( R n ) ) ,

where 1 m 2 . Here, q and H 1 ( 1 q ) stand for the usual L q ( R n ) -norm and H 1 ( R n ) -norm, respectively.

The nonlinear nonlocal term can be considered as an approximation (with suitable change of variables) of the nonlinearity of the following semi-linear damped wave equation:

u t t Δ u + b ( t ) u t = u ( t ) p ,

since the limit

lim γ 1 s + γ = Γ ( 1 γ ) δ ( s )

exists in the distributional sense, where Γ is the Euler gamma function.

Before presenting our main results, let us dwell on the available literature on the topic. Li and Zhou [10] showed in 1995 that the local solution of the equation must blow up in a finite time if n 2 , 1 < p 1 + 2 n , and the average of the data is positive:

(P1) u t t Δ u + u t = u ( t ) p .

In 2001, Todorova and Yordanov [14] developed a weighted energy method and determined the critical exponent of ( P 1 ) as follows:

p c = 1 + 2 n ,

which is well known as Fujita’s critical exponent for the heat equation u t Δ u = u p (see [5]). More precisely, they proved small data global existence when p > 1 + 2 n and blow-up of all solutions of ( P 1 ) with positive average data when 1 < p < 1 + 2 n . Later on, Zhang [16] and Kirane and Qafsasoui [9] independently showed that the critical exponent p = 1 + 2 n belongs to the blow-up region. Todorova and Yordanov [14] assumed the data to have compact support and essentially used this property in their analysis. However, in 2005, Ikehata and Tanizawa [7] removed this assumption.

Recently, Nishihara [12] in 2011 and Lin et al. [11] in 2012 considered the semi-linear wave equation with time-dependent damping

u t t Δ u + b ( t ) u t = u p ,

where

b ( t ) = b 0 ( 1 + t ) β , β ( 1 , 1 ) ,

and found the critical exponent

p c = 1 + 2 n .

This shows that time-dependent coefficients of damping term of the above form do not influence the critical exponent. For more results about damped wave equations with memory terms, we refer the interested readers to Fino [4] and D’Abbicco [1,2].

On the other hand, problem ( P ) has recently been studied by Kaddour and Reissig [8]. They proved the small data global (in time) well-posedness of a solution in C ( [ 0 , ) ; H σ ( R n ) ) when σ ( 0 , 1 ) and in C ( [ 0 , ) ; H σ ( R n ) ) C 1 ( [ 0 , ) ; H σ 1 ( R n ) ) for σ ( 1 , n 2 ) by using the standard energy method and the fractional Gagliardo-Nirenberg inequality. Our goal is to complete this study for σ = 1 by proving the small data global well-posedness of a solution in the standard energy space C ( [ 0 , ) ; H 1 ( R n ) ) C 1 ( [ 0 , ) ; L 2 ( R n ) ) by employing the same method. For β = 1 , this result improves the global existence result proved by Fino [4] in 2012. For the problem ( P ) , it has been noted that the standard energy method works better than the weighted energy method developed in the study by Ikehata and Tanizawa [7] and Todorova and Yordanov [14], and used in the study by Lin et al. [12] and and Nishihara [11].

This article is organized as follows: in Section 2, we present some definitions and properties concerning the linear homogeneous and inhomogeneous equations related to ( P ) ; Section 3 is devoted to our main results; and finally, we prove the theorems on global existence (Theorems 3, 4, and 5) in Section 4. Here, we emphasize that we can easily prove Theorems 69 in a similar manner. Throughout this article, C denotes a universal positive constant that may change from line to line.

2 Preliminaries

In this section, we give some preliminary properties that will be used in the proof of main results.

In order to define the mild solution of equation (P), we consider the corresponding linear homogeneous equation

(1) u t t Δ u + b ( t ) u t = 0 , t > 0 , x R n , u ( 0 , x ) = u 0 ( x ) , u t ( 0 , x ) = u 1 ( x ) , x R n .

It is well known that there exists a unique strong solution u of equation (1) for any ( u 0 , u 1 ) H 2 ( R n ) × H 1 ( R n ) , for instance, see [6, Theorem 2.27]. Let us denote by R ( t , s ) the operator, which maps the initial data ( u ( s ) , u t ( s ) ) H 2 ( R n ) × H 1 ( R n ) given at time s 0 to the solution u ( t ) H 2 ( R n ) at the time t s , i.e., the solution u of equation (1) is defined by u ( t ) = R ( t , 0 ) ( u 0 , u 1 ) . The operator R ( t , s ) can uniquely be extended as R ( t , s ) : H 1 ( R n ) × L 2 ( R n ) C ( [ s , ) , H 1 ( R n ) ) C 1 ( [ s , ) , H 1 ( R n ) ) (see [15, Appendix]).

Now, we consider the linear inhomogeneous equation

(2) u t t Δ u + b ( t ) u t = F ( t , x ) , t > 0 , x R n , u ( 0 , x ) = u 0 ( x ) , u t ( 0 , x ) = u 1 ( x ) , x R n .

Definition 1

(Mild solution) Let ( u 0 , u 1 ) H 1 ( R n ) × L 2 ( R n ) and F C ( [ 0 , ) ; L 2 ( R n ) ) . We say that u is a mild solution of equation (2) if u C ( [ 0 , ) ; H 1 ( R n ) ) C 1 ( [ 0 , ) ; L 2 ( R n ) ) and u satisfies the initial data u ( 0 ) = u 0 and u t ( 0 ) = u 1 and the integral equation

u ( t , x ) = R ( t , 0 ) ( u 0 , u 1 ) + 0 t S ( t , s ) F ( s , x ) d s

in the sense of H 1 , where S ( t , s ) g R ( t , s ) ( 0 , g ) for g H 1 ( R n ) .

Proposition 1

[15, Proposition 9.15] Let ( u 0 , u 1 ) H 1 ( R n ) × L 2 ( R n ) and F C ( [ 0 , ) ; L 2 ( R n ) ) , then there exists a unique mild solution u of equation (2).

Nonlinear equations do not always admit global-in-time solutions. Therefore, we consider the solution defined on an interval [ 0 , T ) for T > 0 . We call such a solution as local-in-time solution (or local solution); if T = , then we call it global-in-time solution (or global solution).

Definition 2

(Mild solution) Let ( u 0 , u 1 ) H 1 ( R n ) × L 2 ( R n ) . We say that u is a mild solution of ( P ) if

u C ( [ 0 , T ) ; H 1 ( R n ) ) C 1 ( [ 0 , T ) ; L 2 ( R n ) )

satisfies the initial data u ( 0 ) = u 0 and u t ( 0 ) = u 1 and the integral equation

(3) u ( t , x ) = R ( t , 0 ) ( u 0 , u 1 ) + Γ ( δ ) 0 t S ( t , τ ) J 0 τ δ ( u p ) d τ u lin ( t ) + u n l ( t )

in the sense of H 1 , where J 0 τ δ is the Riemann-Liouville left-sided fractional integral (e.g., see [13, Chapter 1]) of order δ = 1 γ ( 0 , 1 ) defined by

J 0 τ δ ( u p ) = 1 Γ ( δ ) 0 τ ( τ s ) γ u ( s ) p d s .

Set

a = a m n 2 1 m 1 2

and

I 0 = ( u 0 , u 1 ) A m = u 0 m + u 0 H 1 + u 1 m + u 1 2 .

The following theorems present key estimate on u lin and u n l defined in equation (3).

Theorem 1

([3, Theorem A])

u lin ( t ) 2 C I 0 ( 1 + t ) a ( β + 1 ) ,

u lin ( t ) 2 C I 0 ( 1 + t ) ( a + 1 2 ) ( β + 1 ) ,

and

t u lin ( t ) 2 C I 0 ( 1 + t ) a ( β + 1 ) 1 .

Set

B ( t , τ ) = τ t 1 b ( τ ) d τ = B ( t , 0 ) B ( τ , 0 ) ,

and

B ( t , 0 ) = 0 t 1 b ( τ ) d τ = ( 1 + t ) β + 1 1 .

Theorem 2

([3, Theorem 3])

u n l ( t ) 2 C 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a J 0 τ δ ( u p ) L m L 2 d τ ,

u n l ( t ) 2 C 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 2 J 0 τ δ ( u p ) L m L 2 d τ

and

t u n l ( t ) 2 C ( 1 + t ) β 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 J 0 τ δ ( u p ) L m L 2 d τ .

The following lemma plays a crucial role in the proof of global existence theorems.

Lemma 1

[8, Lemma 5.1] Assume that 0 < γ < 1 , a 0 , b > 1 , and r ( 1 , 1 ) . Then, we have

0 t ( 1 + τ ) r ( 1 + B ( t , τ ) ) a 0 τ ( τ s ) γ ( 1 + s ) b d s d τ C ( 1 + t ) min { a ( 1 r ) ; γ } , if max { a ; γ + r } > 1 , ( 1 + t ) min { a ( 1 r ) ; γ } ln ( 2 + t ) , if max { a ; γ + r } = 1 , ( 1 + t ) 1 a ( 1 r ) γ r , if max { a ; γ + r } < 1 .

3 Main results

For m 2 , note that

a = n 2 1 m 1 2 0 .

Later, we need the following condition:

2 m p n ( n 2 ) + ,

i.e., we need to suppose for n 3 that

n 4 ( 2 m ) + .

So, by this condition, we have

n 4 ( 2 m ) + 4 m ( 2 m ) + ,

which implies that

0 a = n 2 1 m 1 2 1 .

Due to technical reasons, we study three cases: γ β < 1 , γ β = 1 , and γ β > 1 .

We start with the case: γ β < 1 , where we have to distinguish the following cases: a [ 1 2 , 1 ) , a [ 0 , 1 2 ) , and a = 1 .

Theorem 3

(Global existence: case of γ β < 1 and a [ 1 2 , 1 ) ) Let n 2 , γ ( 0 , 1 ) , 0 β < 1 , m [ 1 , 2 ) , 1 2 a < 1 , and γ β < 1 . Suppose that n 4 2 m when n 3 , and

2 m p n ( n 2 ) + .

If

p > 2 + 2 n m ( 1 a ) ( β + 1 ) ( n 2 ) ( 1 a ) ( β + 1 ) + 2 γ p 1 * ,

then there exists a small enough positive constant 0 < ε 0 1 such that, for any initial data satisfying

I 0 ε 0 ,

there is a uniquely global (in time) mild solution

u C ( [ 0 , ) , H 1 ( R n ) ) C 1 ( [ 0 , ) , L 2 ( R n ) ) .

Moreover, the solution satisfies the following estimates:

u ( t ) 2 C ( 1 + t ) ( 1 a ) ( β + 1 ) γ ,

u ( t ) 2 C ( 1 + t ) γ , if a > 1 2 , ( 1 + t ) γ ln ( 2 + t ) , if a = 1 2 ,

and

t u ( t ) 2 C ( 1 + t ) β γ .

Remark

We exclude the case n = 1 in Theorem 3 because

a = 1 2 1 m 1 2 1 4 .

Theorem 4

(Global existence: case of γ β < 1 and a [ 0 , 1 2 ) ) Let n 1 , γ ( 0 , 1 ) , 0 β < 1 , m [ 1 , 2 ] , a < 1 2 , and γ β < 1 . Suppose that n 4 ( 2 m ) + when n 3 , and

2 m p n ( n 2 ) + .

We also suppose that γ > ( 2 m n ) ( β + 1 ) 2 m . If

p > 2 m + n ( β + 1 ) ( n 2 m ) ( β + 1 ) + 2 m γ p 2 * ,

then there exists a small enough positive constant 0 < ε 0 1 such that, for any initial data satisfying

I 0 ε 0 ,

there is a uniquely global (in time) mild solution

u C ( [ 0 , ) , H 1 ( R n ) ) C 1 ( [ 0 , ) , L 2 ( R n ) ) .

Moreover, the solution satisfies the following estimates:

u ( t ) 2 C ( 1 + t ) ( 1 a ) ( β + 1 ) γ ,

u ( t ) 2 C ( 1 + t ) ( 1 2 a ) ( β + 1 ) γ ,

and

t u ( t ) 2 C ( 1 + t ) β γ , if a > 0 , ( 1 + t ) β γ ln ( 2 + t ) , if a = 0 .

Theorem 5

(Global existence: case of γ β < 1 and a = 1 ) Let n = 4 , γ ( 0 , 1 ) , 0 β < 1 , m [ 1 , 2 ) , a = 1 , and γ β < 1 . Suppose that

2 m p n n 2 .

If

p > 1 γ ,

then there exists a small enough positive constant 0 < ε 0 1 such that, for any initial data satisfying

I 0 ε 0 ,

there is a uniquely global (in time) mild solution

u C ( [ 0 , ) , H 1 ( R n ) ) C 1 ( [ 0 , ) , L 2 ( R n ) ) .

Moreover, the solution satisfies the following estimates:

u ( t ) 2 C ( 1 + t ) γ ln ( 2 + t ) ,

u ( t ) 2 C ( 1 + t ) γ ,

and

t u ( t ) 2 C ( 1 + t ) β γ .

Next, we consider the case when γ β > 1 .

Theorem 6

(Global existence: case of γ β > 1 ) Let n 1 , γ ( 0 , 1 ) , 0 β < 1 , m [ 1 , 2 ) , 0 a 1 , and γ β > 1 . Suppose that n 4 2 m when n 3 , and

2 m p n ( n 2 ) + .

If

p > 2 + 2 n m ( 1 a ) ( β + 1 ) ( n 2 ) ( 1 a ) ( β + 1 ) + 2 γ = p 1 * ,

then there exists a small enough positive constant 0 < ε 0 1 such that, for any initial data satisfying

I 0 ε 0 ,

there is a uniquely global (in time) mild solution

u C ( [ 0 , ) , H 1 ( R n ) ) C 1 ( [ 0 , ) , L 2 ( R n ) ) .

Moreover, the solution satisfies the following estimates:

u ( t ) 2 C ( 1 + t ) a ( β + 1 ) ,

u ( t ) 2 C ( 1 + t ) min { ( a + 1 2 ) ( β + 1 ) ; γ } ,

and

t u ( t ) 2 C ( 1 + t ) min { ( a + 1 ) ( β + 1 ) ; γ } β .

Finally, for the case of γ β = 1 , we have to distinguish three cases: a = 0 , a ( 0 , 1 2 ] , and a ( 1 2 , 1 ] .

Theorem 7

(Global existence: case of γ β = 1 and a = 0 ) Let n 2 , γ ( 0 , 1 ) , 0 β < 1 , a = 0 (i.e., m = 2 ), and γ β = 1 . Suppose that

1 < p n ( n 2 ) + .

If

p > 2 + 2 n m ( 1 a ) ( β + 1 ) ( n 2 ) ( 1 a ) ( β + 1 ) + 2 γ = p 1 * ,

then there exists a small enough positive constant 0 < ε 0 1 such that, for any initial data satisfying

I 0 ε 0 ,

there is a uniquely global (in time) mild solution

u C ( [ 0 , ) , H 1 ( R n ) ) C 1 ( [ 0 , ) , L 2 ( R n ) ) .

Moreover, the solution satisfies the following estimates:

u ( t ) 2 C ln ( 2 + t )

u ( t ) 2 C ( 1 + t ) γ 2 ln ( 2 + t ) ,

and

t u ( t ) 2 C ( 1 + t ) 1 ln ( 2 + t ) .

Theorem 8

(Global existence: case of γ β = 1 and a ( 0 , 1 2 ] ) Let n 1 , γ ( 0 , 1 ) , 0 β < 1 , m [ 1 , 2 ] , a ( 0 , 1 2 ] , and γ β = 1 . Suppose that n 4 ( 2 m ) + when n 3 , and

2 m p n ( n 2 ) + .

We also suppose that γ > ( 2 m n ) ( β + 1 ) 2 m . If

p > 2 m + n ( β + 1 ) ( n 2 m ) ( β + 1 ) + 2 m γ = p 2 * ,

then there exists a small enough positive constant 0 < ε 0 1 such that, for any initial data satisfying

I 0 ε 0 ,

there is a uniquely global (in time) mild solution

u C ( [ 0 , ) , H 1 ( R n ) ) C 1 ( [ 0 , ) , L 2 ( R n ) ) .

Moreover, the solution satisfies the following estimates:

u ( t ) 2 C ( 1 + t ) a γ ln ( 2 + t )

u ( t ) 2 C ( 1 + t ) ( a + 1 2 ) γ ln ( 2 + t ) ,

and

t u ( t ) 2 C ( 1 + t ) 1 .

Theorem 9

(Global existence: case of γ β = 1 and a ( 1 2 , 1 ] ) Let n = 4 , γ ( 0 , 1 ) , 0 β < 1 , m [ 1 , 2 ) , a ( 1 2 , 1 ] , and γ β = 1 . Suppose that

2 m p n n 2 .

If

p > 1 γ ,

then there exists a small enough positive constant 0 < ε 0 1 such that, for any initial data satisfying

I 0 ε 0 ,

there is a uniquely global (in time) mild solution

u C ( [ 0 , ) , H 1 ( R n ) ) C 1 ( [ 0 , ) , L 2 ( R n ) ) .

Moreover, the solution satisfies the following estimates:

u ( t ) 2 C ( 1 + t ) a γ ln ( 2 + t )

u ( t ) 2 C ( 1 + t ) γ ,

and

t u ( t ) 2 C ( 1 + t ) 1 .

4 Proof of Theorems 3–5

Proof of Theorem 3

We start by introducing, for T > 0 , the space of energy solutions

X ( T ) = C ( [ 0 , T ] , H 1 ( R n ) ) C 1 ( [ 0 , T ] , L 2 ( R n ) )

equipped with the norm

v X ( T ) = sup 0 t T { ( 1 + t ) ( a 1 ) ( β + 1 ) + γ v ( t ) 2 + ( 1 + t ) γ v ( t ) 2 + ( 1 + t ) γ β t v ( t ) 2 }

when a > 1 2 , and

v X ( T ) = sup 0 t T { ( 1 + t ) ( a 1 ) ( β + 1 ) + γ v ( t ) 2 + ( 1 + t ) γ ( ln ( 2 + t ) ) 1 v ( t ) 2 + ( 1 + t ) γ β t v ( t ) 2 }

when a = 1 2 , for any v X ( T ) . We will use the Banach fixed-point theorem. Let us define the complete metric space: B R ( T ) = { v X ( T ) ; v X ( T ) 2 R } , where R > 0 is a positive constant that will be chosen later. We also suppose that I 0 ε 0 , where 0 < ε 0 1 is a positive constant, small enough to be determined later. By Proposition 1, we define a mapping Φ : B R ( T ) X ( T ) such that

Φ ( u ) ( t ) Φ ( u ) lin ( t ) + Φ ( u ) n l ( t ) = R ( t , 0 ) ( u 0 , u 1 ) + Γ ( δ ) 0 t S ( t , τ ) J 0 τ δ ( u p ) d τ for  u B R ( T ) .

Our goal is to prove that Φ : B R ( T ) B R ( T ) is a contraction map.

Φ : B R ( T ) B R ( T ) . Let u B R ( T ) .

Case of a > 1 2 .

Estimation of Φ ( u ) ( t ) 2 ̲ : Using Theorem 1, and γ β < 1 , we have

(4) u lin ( t ) 2 C I 0 ( 1 + t ) a ( β + 1 ) C ε 0 ( 1 + t ) ( 1 a ) ( β + 1 ) γ .

On the other hand, by Theorem 2, we have

u n l ( t ) 2 C 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a J 0 τ δ ( u p ) L m L 2 d τ C 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 0 τ ( τ s ) γ ( u ( s ) m p p + u ( s ) 2 p p ) d s d τ .

The condition

2 m p n ( n 2 ) + ,

allows us to use the following Gagliardo-Nirenberg inequality:

u ( s ) j p p C u ( s ) 2 p ( 1 θ ( j p ) ) u ( s ) 2 p θ ( j p ) C ( 1 + s ) β j u X ( T ) p , j = 2 , m ,

where

θ ( j p ) n 1 2 1 j p and β j p ( a 1 ) ( β + 1 ) 1 n 2 + γ + n j ( a 1 ) ( β + 1 ) , j = 2 , m .

As m < 2 , we can easily see that

β 2 > β m ,

and then

u ( s ) m p p , u ( s ) 2 p p C ( 1 + s ) β m u X ( T ) p ,

therefore

u n l ( t ) 2 C u X ( T ) p 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 0 τ ( τ s ) γ ( 1 + s ) β m d s d τ .

Note that β m > 1 p > p 1 * , which implies, using the fact that max { a , γ β } < 1 and Lemma 1, that

(5) u n l ( t ) 2 C ( 1 + t ) ( 1 a ) ( β + 1 ) γ u X ( T ) p .

By equations (4) and (5), we obtain

(6) ( 1 + t ) ( a 1 ) ( β + 1 ) + γ Φ ( u ) ( t ) 2 C ε 0 + C u X ( T ) p .

Estimation of Φ ( u ) ( t ) 2 ̲ : Using Theorems 1 and 2, and the fact that a > 1 2 and γ β < 1 , we obtain

(7) u lin ( t ) 2 C I 0 ( 1 + t ) ( a + 1 2 ) ( β + 1 ) C ε 0 ( 1 + t ) γ

and

u n l ( t ) 2 C 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 2 0 τ ( τ s ) γ ( u ( s ) m p p + u ( s ) 2 p p ) d s d τ .

Similar to the estimation of Φ ( u ) ( t ) 2 , we have

u ( s ) m p p , u ( s ) 2 p p C ( 1 + s ) β m u X ( T ) p ,

which implies that

u n l ( t ) 2 C u X ( T ) p 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 2 0 τ ( τ s ) γ ( 1 + s ) β m d s d τ .

Note that β m > 1 p > p 1 * , which implies, using the fact that max { a + 1 2 , γ β } = a + 1 2 > 1 and Lemma 1, that

(8) u n l ( t ) 2 C ( 1 + t ) γ u X ( T ) p .

By equations (7) and (8), we obtain

(9) ( 1 + t ) γ Φ ( u ) ( t ) 2 C ε 0 + C u X ( T ) p .

Estimation of t Φ ( u ) ( t ) 2 ̲ : By Theorems 1 and 2, and the fact that a > 0 and γ β < 1 , we obtain

(10) t u lin ( t ) 2 C I 0 ( 1 + t ) a ( β + 1 ) 1 C ε 0 ( 1 + t ) β γ

and

t u n l ( t ) 2 C ( 1 + t ) β 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 0 τ ( τ s ) γ ( u ( s ) m p p + u ( s ) 2 p p ) d s d τ .

In addition, as above, we have

u ( s ) m p p , u ( s ) 2 p p C ( 1 + s ) β m u X ( T ) p ,

therefore

t u n l ( t ) 2 C u X ( T ) p ( 1 + t ) β 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 0 τ ( τ s ) γ ( 1 + s ) β m d s d τ .

As p > p 1 * β m > 1 and using the fact that max { a + 1 , γ β } = a + 1 > 1 and Lemma 1, we have

(11) t u n l ( t ) 2 C ( 1 + t ) β γ u X ( T ) p .

By equations (10) and (11), we obtain

(12) ( 1 + t ) γ β t Φ ( u ) ( t ) 2 C ε 0 + C u X ( T ) p .

Summing up equations (6), (9), and (12) and using u B R ( T ) , we conclude that

Φ ( u ) X ( T ) C ε 0 + C u X ( T ) p C ε 0 + C R p .

At this stage, we first choose R > 0 such that C R p 1 1 , and then, we take 0 < ε 0 1 such that R C ε 0 . In consequence, we obtain

Φ ( u ) X ( T ) 2 R ,

i.e., Φ ( u ) B R ( T ) .

Case of a = 1 2 .

Estimation of Φ ( u ) ( t ) 2 ̲ : As in the case of a > 1 2 , we have

(13) u lin ( t ) 2 C I 0 ( 1 + t ) a ( β + 1 ) C ε 0 ( 1 + t ) ( 1 a ) ( β + 1 ) γ

and

u n l ( t ) 2 C 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 0 τ ( τ s ) γ ( u ( s ) m p p + u ( s ) 2 p p ) d s d τ ,

where

u ( s ) j p p C u ( s ) 2 p ( 1 θ ( j p ) ) u ( s ) 2 p θ ( j p ) , j = 2 , m .

Due to the condition a = 1 2 , we obtain

u ( t ) 2 C ( 1 + t ) γ ln ( 2 + t ) u X ( T ) C ( 1 + t ) γ + δ u X ( T )

for δ 1 to be chosen later. Therefore, we have

u ( s ) j p p C ( 1 + s ) β j + δ p θ ( j p ) u X ( T ) p , j = 2 , m .

As m < 2 , we can easily see that β 2 > β m and θ ( m p ) < θ ( 2 p ) , and so

u ( s ) m p p , u ( s ) 2 p p C ( 1 + s ) β m + δ p θ ( 2 p ) u X ( T ) p .

Thus, we obtain

u n l ( t ) 2 C u X ( T ) p 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 0 τ ( τ s ) γ ( 1 + s ) β m + δ p θ ( 2 p ) d s d τ .

Note that β m > 1 p > p 1 * , so by choosing δ 1 , namely δ < ( β m 1 ) ( p θ ( 2 p ) ) , we obtain β m δ p θ ( 2 p ) > 1 , which implies, using the fact that max { a , γ β } < 1 and Lemma 1, that

(14) u n l ( t ) 2 C ( 1 + t ) ( 1 a ) ( β + 1 ) γ u X ( T ) p .

By equations (13) and (14), we arrive at

(15) ( 1 + t ) ( a 1 ) ( β + 1 ) + γ Φ ( u ) ( t ) 2 C ε 0 + C u X ( T ) p .

Estimation of Φ ( u ) ( t ) 2 ̲ : By Theorems 1 and 2, and the fact that a = 1 2 and γ β < 1 , we obtain

(16) u lin ( t ) 2 C I 0 ( 1 + t ) ( β + 1 ) C ε 0 ( 1 + t ) γ ln ( 2 + t )

and

u n l ( t ) 2 C 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) 1 0 τ ( τ s ) γ ( u ( s ) m p p + u ( s ) 2 p p ) d s d τ .

Similar to the estimation of Φ ( u ) ( t ) 2 , we have

u ( s ) m p p , u ( s ) 2 p p C ( 1 + s ) β m + δ p θ ( 2 p ) u X ( T ) p ,

therefore

u n l ( t ) 2 C u X ( T ) p 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) 1 0 τ ( τ s ) γ ( 1 + s ) β m + δ p θ ( 2 p ) d s d τ .

As above, by choosing δ 1 , namely δ < ( β m 1 ) ( p θ ( 2 p ) ) , we obtain β m δ p θ ( 2 p ) > 1 , which implies, using the fact that max { 1 , γ β } = 1 > γ and Lemma 1, that

(17) u n l ( t ) 2 C ( 1 + t ) γ ln ( 2 + t ) u X ( T ) p .

By equations (16) and (17), we obtain

(18) ( 1 + t ) γ ( ln ( 2 + t ) ) 1 Φ ( u ) ( t ) 2 C ε 0 + C u X ( T ) p .

Estimation of t Φ ( u ) ( t ) 2 ̲ : Using Theorems 1 and 2, and the fact that a > 0 , β 0 , we obtain

(19) t u lin ( t ) 2 C I 0 ( 1 + t ) a ( β + 1 ) 1 C ε 0 ( 1 + t ) β γ

and

t u n l ( t ) 2 C ( 1 + t ) β 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 0 τ ( τ s ) γ ( u ( s ) m p p + u ( s ) 2 p p ) d s d τ .

In the same way, as before, we have

u ( s ) m p p , u ( s ) 2 p p C ( 1 + s ) β m + δ p θ ( 2 p ) u X ( T ) p ,

therefore

t u n l ( t ) 2 C u X ( T ) p ( 1 + t ) β 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 0 τ ( τ s ) γ ( 1 + s ) β m + δ p θ ( 2 p ) d s d τ .

As above, using the same choice of δ and the fact that β m > 1 , we have β m δ p θ ( 2 p ) > 1 , which implies, using max { a + 1 , γ β } = a + 1 > 1 and Lemma 1, that

(20) t u n l ( t ) 2 C ( 1 + t ) β γ u X ( T ) p .

By equations (19) and (20), we obtain

(21) ( 1 + t ) γ β t Φ ( u ) ( t ) 2 C ε 0 + C u X ( T ) p .

Summing up equations (15), (18), and (21) and using the fact that u B R ( T ) , we conclude that

Φ ( u ) X ( T ) C ε 0 + C u X ( T ) p C ε 0 + C R p .

By choosing R > 0 such that C R p 1 1 , and 0 < ε 0 1 such that R C ε 0 , we arrive at

Φ ( u ) X ( T ) 2 R ,

i.e., Φ ( u ) B R ( T ) .

Φ is a contraction. Let u , v B R ( T ) .

Case of a > 1 2 .

Estimation of ( Φ ( u ) Φ ( v ) ) ( t ) 2 ̲ : By Theorem 2, we have

(22) ( Φ ( u ) Φ ( v ) ) ( t ) 2 C 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 0 τ ( τ s ) γ ( u ( s ) p v ( s ) p m + u ( s ) p v ( s ) p 2 ) d s d τ .

Using the estimation

u p v p C ( p ) u v ( u p 1 + v p 1 )

and Hölder’s inequality, we obtain

u ( s ) p v ( s ) p j u ( s ) v ( s ) j p ( u ( s ) j p p 1 + v ( s ) j p p 1 ) , j = 2 , m .

Let us estimate u ( s ) v ( s ) j p for j = 2 , m . By Gagliardo-Nirenberg inequality, we obtain

u ( s ) v ( s ) j p C u ( s ) v ( s ) 2 1 θ ( j p ) ( u ( s ) v ( s ) ) 2 θ ( j p ) C ( 1 + s ) ( 1 θ ( j p ) ) ( 1 a ) ( β + 1 ) γ u v X ( T ) .

Similarly, we have

u ( s ) j p p 1 C u ( s ) 2 ( 1 θ ( j p ) ) ( p 1 ) u ( s ) 2 θ ( j p ) ( p 1 ) C ( 1 + s ) ( p 1 ) ( ( 1 θ ( j p ) ) ( 1 a ) ( β + 1 ) γ ) u X ( T ) p 1

and

v ( s ) j p p 1 C v ( s ) 2 ( 1 θ ( j p ) ) ( p 1 ) v ( s ) 2 θ ( j p ) ( p 1 ) C ( 1 + s ) ( p 1 ) ( ( 1 θ ( j p ) ) ( 1 a ) ( β + 1 ) γ ) v X ( T ) p 1 .

Therefore, we conclude that

(23) u ( s ) p v ( s ) p j C ( 1 + s ) β j ( u X ( T ) p 1 + v X ( T ) p 1 ) u v X ( T ) , j = 2 , m .

Plugging equation (23) into equation (22), we arrive at

( Φ ( u ) Φ ( v ) ) ( t ) 2 C ( u X ( T ) p 1 + v X ( T ) p 1 ) u v X ( T ) 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a × 0 τ ( τ s ) γ ( ( 1 + s ) β m + ( 1 + s ) β 2 ) d s d τ .

As m < 2 , we can easily see that β 2 > β m , and then

( Φ ( u ) Φ ( v ) ) ( t ) 2 C R p 1 u v X ( T ) 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 0 τ ( τ s ) γ ( 1 + s ) β m d s d τ ,

where we have used the fact that u , v B R ( T ) . Note that β m > 1 p > p 1 * , which implies, using the fact that max { a , γ β } < 1 and Lemma 1, that

( Φ ( u ) Φ ( v ) ) ( t ) 2 C ( 1 + t ) ( 1 a ) ( β + 1 ) γ R p 1 u v X ( T ) .

Hence, we have

(24) ( 1 + t ) ( a 1 ) ( β + 1 ) + γ ( Φ ( u ) Φ ( v ) ) ( t ) 2 C R p 1 u v X ( T ) p .

Estimation of Φ ( u ) ( t ) Φ ( v ) ( t ) 2 ̲ : By Theorem 2, we have

Φ ( u ) ( t ) Φ ( v ) ( t ) 2 C 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 2 0 τ ( τ s ) γ ( u ( s ) p v ( s ) p m + u ( s ) p v ( s ) p 2 ) d s d τ .

As in the estimation of ( Φ ( u ) Φ ( v ) ) ( t ) 2 , we obtain

Φ ( u ) ( t ) Φ ( v ) ( t ) 2 C R p 1 u v X ( T ) 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 2 0 τ ( τ s ) γ ( 1 + s ) β m d s d τ .

Moreover, as β m > 1 p > p 1 * , it follows by max { a + 1 2 , γ β } = a + 1 2 > 1 and Lemma 1 that

Φ ( u ) ( t ) Φ ( v ) ( t ) 2 C ( 1 + t ) γ R p 1 u v X ( T ) ,

i.e.,

(25) ( 1 + t ) γ Φ ( u ) ( t ) Φ ( v ) ( t ) 2 C R p 1 u v X ( T ) .

Estimation of t Φ ( u ) ( t ) t Φ ( v ) ( t ) 2 ̲ : By Theorem 2, we have

t Φ ( u ) ( t ) t Φ ( v ) ( t ) 2 C ( 1 + t ) β 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 0 τ ( τ s ) γ ( u ( s ) p v ( s ) p m + u ( s ) p v ( s ) p 2 ) d s d τ .

Again, using the foregoing arguments, we obtain

t Φ ( u ) ( t ) t Φ ( v ) ( t ) 2 C R p 1 u v X ( T ) ( 1 + t ) β 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 0 τ ( τ s ) γ ( 1 + s ) β m d s d τ .

In addition, β m > 1 p > p 1 * , which implies, using the fact that max { a + 1 , γ β } = a + 1 > 1 and Lemma 1, that

t Φ ( u ) ( t ) t Φ ( v ) ( t ) 2 C R p 1 ( 1 + t ) β γ u v X ( T ) ,

i.e.,

(26) ( 1 + t ) γ β t Φ ( u ) ( t ) t Φ ( v ) ( t ) 2 C R p 1 u v X ( T ) .

Summing up equations (24), (25), and (26), we conclude that

Φ ( u ) Φ ( v ) X ( T ) C R p 1 u v X ( T ) ,

and therefore

Φ ( u ) Φ ( v ) X ( T ) 1 2 u v X ( T ) ,

where R > 0 has been chosen such that C R p 1 1 2 . This establishes that Φ is a contraction.

Case of a = 1 2 .

Estimation of Φ ( u ) ( t ) Φ ( v ) ( t ) 2 ̲ : By Theorem 2, we obtain

Φ ( u ) ( t ) Φ ( v ) ( t ) 2 C 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 0 τ ( τ s ) γ ( u ( s ) p v ( s ) p m + u ( s ) p v ( s ) p 2 ) d s d τ .

As a = 1 2 , we have

u ( t ) v ( t ) 2 C ( 1 + t ) γ ln ( 2 + t ) u v X ( T ) C ( 1 + t ) γ + δ u v X ( T ) ,

where δ 1 has been chosen as above, namely δ < ( β m 1 ) ( p θ ( 2 p ) ) . Therefore, as in the case of a > 1 2 , we obtain

Φ ( u ) ( t ) Φ ( v ) ( t ) 2 C R p 1 u v X ( T ) 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a × 0 τ ( τ s ) γ ( ( 1 + s ) β m + δ p θ ( m p ) + ( 1 + s ) β 2 + δ p θ ( 2 p ) ) d s d τ .

As m < 2 , we can easily see that β 2 > β m and θ ( m p ) < θ ( 2 p ) , and therefore,

Φ ( u ) ( t ) Φ ( v ) ( t ) 2 C R p 1 u v X ( T ) 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 0 τ ( τ s ) γ ( 1 + s ) β m + δ p θ ( 2 p ) d s d τ .

Note that β m > 1 p > p 1 * , so by our choice of δ , we obtain β m δ p θ ( 2 p ) > 1 , which implies, using the fact that max { a , γ β } < 1 and Lemma 1, that

Φ ( u ) ( t ) Φ ( v ) ( t ) 2 C R p 1 ( 1 + t ) ( 1 a ) ( β + 1 ) γ u v X ( T ) ,

i.e.,

(27) ( 1 + t ) ( a 1 ) ( β + 1 ) + γ Φ ( u ) ( t ) Φ ( v ) ( t ) 2 C R p 1 u v X ( T ) .

Estimation of Φ ( u ) ( t ) Φ ( v ) ( t ) 2 ̲ : By Theorem 2, we have

Φ ( u ) ( t ) Φ ( v ) ( t ) 2 C 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) 1 0 τ ( τ s ) γ ( u ( s ) p v ( s ) p m + u ( s ) p v ( s ) p 2 ) d s d τ .

Likewise, we arrive at

Φ ( u ) ( t ) Φ ( v ) ( t ) 2 C R p 1 u v X ( T ) 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) 1 0 τ ( τ s ) γ ( 1 + s ) β m + δ p θ ( 2 p ) d s d τ ,

which implies, using the fact that β m δ p θ ( 2 p ) > 1 , max { 1 , γ β } = 1 > γ , and Lemma 1, that

Φ ( u ) ( t ) Φ ( v ) ( t ) 2 C R p 1 ( 1 + t ) γ ln ( 2 + t ) u v X ( T ) ,

i.e.,

(28) ( 1 + t ) γ ( ln ( 2 + t ) ) 1 Φ ( u ) ( t ) Φ ( v ) ( t ) 2 C R p 1 u v X ( T ) .

Estimation of t Φ ( u ) ( t ) t Φ ( v ) ( t ) 2 ̲ : By Theorem 2, we obtain

t Φ ( u ) ( t ) t Φ ( v ) ( t ) 2 C ( 1 + t ) β 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 × 0 τ ( τ s ) γ ( u ( s ) p v ( s ) p m + u ( s ) p v ( s ) p 2 ) d s d τ .

By using the same arguments as before, we conclude that

t Φ ( u ) ( t ) t Φ ( v ) ( t ) 2 C R p 1 u v X ( T ) ( 1 + t ) β 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 0 τ ( τ s ) γ ( 1 + s ) β m + δ p θ ( 2 p ) d s d τ ,

which implies, using β m δ p θ ( 2 p ) > 1 , that

t Φ ( u ) ( t ) t Φ ( v ) ( t ) 2 C R p 1 ( 1 + t ) β γ u v X ( T ) ,

i.e.,

(29) ( 1 + t ) γ β t Φ ( u ) ( t ) t Φ ( v ) ( t ) 2 C R p 1 u v X ( T ) .

Summing up equations (27), (28), and (29), we conclude that

Φ ( u ) Φ ( v ) X ( T ) C R p 1 u v X ( T ) .

Choosing R > 0 such that C R p 1 1 2 , we arrive at

Φ ( u ) Φ ( v ) X ( T ) 1 2 u v X ( T ) ,

i.e., Φ is a contraction.

Hence, by the Banach fixed point theorem, there exists a unique mild solution u X ( T ) to problem ( P ) . This completes the proof of Theorem 3.□

Proof of Theorem 4

The proof of Theorem 4 is very similar to that of Theorem 3. So, the repeated arguments will be omitted. Let us consider, for T > 0 , the same space of energy solutions X ( T ) equipped with the norm

u X ( T ) = sup 0 t T ( 1 + t ) ( a 1 ) ( β + 1 ) + γ u ( t ) 2 + ( 1 + t ) ( a 1 2 ) ( β + 1 ) + γ u ( t ) 2 + ( 1 + t ) γ β t u ( t ) 2

when a > 0 (i.e., m < 2 ), and

u X ( T ) = sup 0 t T ( 1 + t ) ( a 1 ) ( β + 1 ) + γ u ( t ) 2 + ( 1 + t ) ( a 1 2 ) ( β + 1 ) + γ u ( t ) 2 + ( 1 + t ) γ β ( ln ( 2 + t ) ) 1 t u ( t ) 2

when a = 0 (i.e., m = 2 ), for any v X ( T ) .

Φ : B R ( T ) B R ( T ) . Let u B R ( T ) .

Case of a > 0 .

Estimation of Φ ( u ) ( t ) 2 ̲ : Using Theorems 1 and 2 and the fact that γ β < 1 , we have

(30) u lin ( t ) 2 C I 0 ( 1 + t ) a ( β + 1 ) C ε 0 ( 1 + t ) ( 1 a ) ( β + 1 ) γ

and

u n l ( t ) 2 C 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 0 τ ( τ s ) γ ( u ( s ) m p p + u ( s ) 2 p p ) d s d τ .

By Gagliardo-Nirenberg inequality, we obtain

u ( s ) j p p C u ( s ) 2 p ( 1 θ ( j p ) ) u ( s ) 2 p θ ( j p ) C ( 1 + s ) β j u X ( T ) p , j = 2 , m ,

where

β j = p n 2 m 1 ( β + 1 ) + γ n ( β + 1 ) 2 j , j = 2 , m .

As m < 2 , we can see that β 2 > β m and

u ( s ) m p p , u ( s ) 2 p p C ( 1 + s ) β m u X ( T ) p ,

whereupon

u n l ( t ) 2 C u X ( T ) p 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 0 τ ( τ s ) γ ( 1 + s ) β m d s d τ .

Note that β m > 1 p > p 2 * , which implies, using the fact that max { a , γ β } < 1 and Lemma 1, that

(31) u n l ( t ) 2 C ( 1 + t ) ( 1 a ) ( β + 1 ) γ u X ( T ) p .

By equations (30) and (31), we obtain

(32) ( 1 + t ) ( a 1 ) ( β + 1 ) + γ Φ ( u ) ( t ) 2 C ε 0 + C u X ( T ) p .

Estimation of Φ ( u ) ( t ) 2 ̲ : By γ β < 1 and Theorems 1 and 2, we obtain

(33) u lin ( t ) 2 C I 0 ( 1 + t ) ( a + 1 2 ) ( β + 1 ) C ε 0 ( 1 + t ) ( 1 2 a ) ( β + 1 ) γ

and

u n l ( t ) 2 C 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 2 0 τ ( τ s ) γ ( u ( s ) m p p + u ( s ) 2 p p ) d s d τ .

Similar to the estimation of Φ ( u ) ( t ) 2 , we have

u ( s ) m p p , u ( s ) 2 p p C ( 1 + s ) β m u X ( T ) p ,

therefore

u n l ( t ) 2 C u X ( T ) p 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 2 0 τ ( τ s ) γ ( 1 + s ) β m d s d τ .

Note that β m > 1 p > p 2 * , which implies, using the fact that max { a + 1 2 , γ β } < 1 and Lemma 1, that

(34) u n l ( t ) 2 C ( 1 + t ) ( 1 2 a ) ( β + 1 ) γ u X ( T ) p .

By equations (33) and (34), we obtain

(35) ( 1 + t ) ( a 1 2 ) ( β + 1 ) + γ Φ ( u ) ( t ) 2 C ε 0 + C u X ( T ) p .

Estimation of t Φ ( u ) ( t ) 2 ̲ : Using Theorems 1 and 2, and the fact that a > 0 , γ β < 1 , we have

(36) t u lin ( t ) 2 C I 0 ( 1 + t ) a ( β + 1 ) 1 C ε 0 ( 1 + t ) β γ

and

t u n l ( t ) 2 C ( 1 + t ) β 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 0 τ ( τ s ) γ ( u ( s ) m p p + u ( s ) 2 p p ) d s d τ .

As above,

u ( s ) m p p , u ( s ) 2 p p C ( 1 + s ) β m u X ( T ) p ,

therefore

t u n l ( t ) 2 C u X ( T ) p ( 1 + t ) β 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) a 1 0 τ ( τ s ) γ ( 1 + s ) β m d s d τ .

Note that β m > 1 p > p 2 * , which implies, using the fact that max { a + 1 , γ β } = a + 1 > 1 and Lemma 1, that

(37) t u n l ( t ) 2 C ( 1 + t ) β γ u X ( T ) p .

By equations (36) and (37), we obtain

(38) ( 1 + t ) γ β t Φ ( u ) ( t ) 2 C ε 0 + C u X ( T ) p .

Summing up equations (32), (35), and (38) and using the fact that u B R ( T ) , we conclude that

Φ ( u ) X ( T ) C ε 0 + C u X ( T ) p C ε 0 + C R p .

At this stage, letting first R > 0 such that C R p 1 1 , and then taking 0 < ε 0 1 such that R C ε 0 , we arrive at

Φ ( u ) X ( T ) 2 R ,

i.e., Φ ( u ) B R ( T ) .

Case of a = 0 .

Estimation of Φ ( u ) ( t ) 2 ̲ : Using same calculations as in the last case ( a > 0 ), we obtain

u lin ( t ) 2 C I 0 ( 1 + t ) a ( β + 1 ) C ε 0 ( 1 + t ) ( 1 a ) ( β + 1 ) γ

and

u n l ( t ) 2 C ( 1 + t ) ( 1 a ) ( β + 1 ) γ u X ( T ) p .

Therefore,

(39) ( 1 + t ) ( a 1 ) ( β + 1 ) + γ Φ ( u ) ( t ) 2 C ε 0 + C u X ( T ) p .

Estimation of Φ ( u ) ( t ) 2 ̲ : As argued in the last case ( a > 0 ), we have

u lin ( t ) 2 C I 0 ( 1 + t ) ( a + 1 2 ) ( β + 1 ) C ε 0 ( 1 + t ) ( 1 2 a ) ( β + 1 ) γ

and

u n l ( t ) 2 C ( 1 + t ) ( 1 2 a ) ( β + 1 ) γ u X ( T ) p .

Therefore, we have

(40) ( 1 + t ) ( a 1 2 ) ( β + 1 ) + γ Φ ( u ) ( t ) 2 C ε 0 + C u X ( T ) p .

Estimation of t Φ ( u ) ( t ) 2 ̲ : Using Theorems 1 and 2, and the fact that a = 0 , γ β < 1 , we have

(41) t u lin ( t ) 2 C I 0 ( 1 + t ) 1 C ε 0 ( 1 + t ) β γ ln ( 2 + t )

and

t u n l ( t ) 2 C ( 1 + t ) β 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) 1 0 τ ( τ s ) γ ( u ( s ) m p p + u ( s ) 2 p p ) d s d τ .

In addition,

u ( s ) m p p , u ( s ) 2 p p C ( 1 + s ) β m u X ( T ) p

and

t u n l ( t ) 2 C u X ( T ) p ( 1 + t ) β 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) 1 0 τ ( τ s ) γ ( 1 + s ) β m d s d τ .

As β m > 1 p > p 2 * and using the fact that max { 1 , γ β } = 1 and Lemma 1, we have

(42) t u n l ( t ) 2 C ( 1 + t ) β γ ln ( 2 + t ) u X ( T ) p .

By equations (41) and (42), we obtain

(43) ( 1 + t ) γ β ( ln ( 2 + t ) ) 1 t Φ ( u ) ( t ) 2 C ε 0 + C u X ( T ) p .

Summing up equations (39), (40), and (43) and using the fact that u B R ( T ) , we conclude that

Φ ( u ) X ( T ) C ε 0 + C u X ( T ) p C ε 0 + C R p .

At this stage, choosing first R > 0 such that C R p 1 1 , and then taking 0 < ε 0 1 such that R C ε 0 , we arrive at

Φ ( u ) X ( T ) 2 R ,

i.e. Φ ( u ) B R ( T ) .

Using the calculations similar to the ones used in the proof of Theorem 3, we can easily deduce that Φ is a contraction. Therefore, by the Banach fixed point theorem, there exists a unique mild solution u X ( T ) of problem ( P ) . This completes the proof of Theorem 4.□

Proof of Theorem 5

Let us introduce, for T > 0 , the same space of energy solutions X ( T ) equipped with the norm

u X ( T ) = sup 0 t T { ( 1 + t ) γ ( ln ( 2 + t ) ) 1 u ( t ) 2 + ( 1 + t ) γ u ( t ) 2 + ( 1 + t ) γ β t u ( t ) 2 }

for any v X ( T ) .

Φ : B R ( T ) B R ( T ) . Let u B R ( T ) .

Estimation of Φ ( u ) ( t ) 2 ̲ : Using Theorems 1 and 2, and γ β < 1 , we obtain

(44) u lin ( t ) 2 C I 0 ( 1 + t ) ( β + 1 ) C ε 0 ( 1 + t ) γ ln ( 2 + t )

and

u n l ( t ) 2 C 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) 1 0 τ ( τ s ) γ ( u ( s ) m p p + u ( s ) 2 p p ) d s d τ .

By Gagliardo-Nirenberg inequality, we have

u ( s ) j p p C u ( s ) 2 p ( 1 θ ( j p ) ) u ( s ) 2 p θ ( j p ) , j = 2 , m .

As a = 1 , we have

u ( t ) 2 C ( 1 + t ) γ ln ( 2 + t ) u X ( T ) C ( 1 + t ) γ + δ u X ( T )

for δ 1 to be chosen later. Therefore, we obtain

u ( s ) j p p C ( 1 + s ) β + δ p ( 1 θ ( j p ) ) u X ( T ) p , j = 2 , m ,

where

β = p γ , j = 2 , m .

As m < 2 , we have θ ( m p ) < θ ( 2 p ) , and then,

u ( s ) m p p , u ( s ) 2 p p C ( 1 + s ) β + δ p ( 1 θ ( m p ) ) u X ( T ) p .

Hence, we have

u n l ( t ) 2 C u X ( T ) p 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) 1 0 τ ( τ s ) γ ( 1 + s ) β + δ p ( 1 θ ( m p ) ) d s d τ .

Note that β > 1 p > 1 γ , so by choosing δ 1 , namely δ < ( β 1 ) ( p ( 1 θ ( m p ) ) ) , we obtain β + δ p ( 1 θ ( m p ) ) > 1 , which implies, using the fact that max { a , γ β } = 1 and Lemma 1, that

(45) u n l ( t ) 2 C ( 1 + t ) γ ln ( 2 + t ) u X ( T ) p .

Note that θ ( m p ) < θ ( 2 p ) 1 , i.e., θ ( m p ) < 1 . By equations (44) and (45), we obtain

(46) ( 1 + t ) γ ( ln ( 2 + t ) ) 1 Φ ( u ) ( t ) 2 C u X ( T ) p .

Estimation of Φ ( u ) ( t ) 2 ̲ : By Theorems 1 and 2, and γ β < 1 , we obtain

(47) u lin ( t ) 2 C I 0 ( 1 + t ) 3 2 ( β + 1 ) C ε 0 ( 1 + t ) γ

and

u n l ( t ) 2 C 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) 3 2 0 τ ( τ s ) γ ( u ( s ) m p p + u ( s ) 2 p p ) d s d τ .

As in the estimation of Φ ( u ) ( t ) 2 , we have

u ( s ) m p p , u ( s ) 2 p p C ( 1 + s ) β + δ p ( 1 θ ( m p ) ) u X ( T ) p ,

which yields

u n l ( t ) 2 C u X ( T ) p 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) 3 2 0 τ ( τ s ) γ ( 1 + s ) β + δ p ( 1 θ ( m p ) ) d s d τ .

Note that β > 1 p > 1 γ , so by the same choice of δ , we arrive at β + δ p ( 1 θ ( m p ) ) > 1 , which implies, using the fact that max { 3 2 , γ β } = 3 2 > 1 and Lemma 1, that

(48) u n l ( t ) 2 C ( 1 + t ) γ u X ( T ) p .

By equations (47) and (48), we obtain

(49) ( 1 + t ) γ Φ ( u ) ( t ) 2 C u X ( T ) p .

Estimation of t Φ ( u ) ( t ) 2 ̲ : Using Theorems 1 and 2, and γ β < 1 , we have

(50) t u lin ( t ) 2 C I 0 ( 1 + t ) ( β + 1 ) 1 C ε 0 ( 1 + t ) β γ

and

t u n l ( t ) 2 C ( 1 + t ) β 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) 2 0 τ ( τ s ) γ ( u ( s ) m p p + u ( s ) 2 p p ) d s d τ .

In addition,

u ( s ) m p p , u ( s ) 2 p p C ( 1 + s ) β + δ p ( 1 θ ( m p ) ) u X ( T ) p ,

whereupon

t u n l ( t ) 2 C u X ( T ) p ( 1 + t ) β 0 t ( 1 + τ ) β ( 1 + B ( t , τ ) ) 2 0 τ ( τ s ) γ ( 1 + s ) β + δ p ( 1 θ ( m p ) ) d s d τ .

Note that β > 1 p > 1 γ . Then, using the fact that β + δ p ( 1 θ ( m p ) ) > 1 , max { 2 , γ β } = 2 > 1 and Lemma 1, we find that

(51) t u n l ( t ) 2 C ( 1 + t ) β γ u X ( T ) p .

By equations (50) and (51), we obtain

(52) ( 1 + t ) γ β t Φ ( u ) ( t ) 2 C u X ( T ) p .

Summing up equations (46), (49), (52) and using the fact that u B R ( T ) , we conclude that

Φ ( u ) X ( T ) C ε 0 + C u X ( T ) p C ε 0 + C R p .

Choosing R > 0 such that C R p 1 1 , and then taking 0 < ε 0 1 such that R C ε 0 , we arrive at

Φ ( u ) X ( T ) 2 R ,

i.e., Φ ( u ) B R ( T ) . Using the similar calculations as in the proof of Theorem 3, we can easily prove that Φ is a contraction. Thus, by the Banach fixed point theorem, there exists a unique mild solution u X ( T ) of problem ( P ) . This completes the proof of Theorem 5.□

Acknowledgments

Dr. M. Kirane thanks Khalifa University for its support.

  1. Funding information: This research work was funded by Institutional Fund Projects under grant no. (IFPIP: 367-130-1443). The authors gratefully acknowledge technical and financial support provided by the Ministry of Education and King Abdulaziz University, DSR, Jeddah, Saudi Arabia.

  2. Conflict of interest: The authors state that there is no conflict of interest.

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Received: 2023-02-18
Revised: 2023-09-01
Accepted: 2023-09-27
Published Online: 2023-11-18

© 2023 the author(s), published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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