Home Spinless Particle in a Magnetic Field Under Minimal Length Scenario
Article Publicly Available

Spinless Particle in a Magnetic Field Under Minimal Length Scenario

  • S.M. Amirfakhrian EMAIL logo
Published/Copyright: May 26, 2016

Abstract

In this article, we studied the Klein–Gordon equation in a generalised uncertainty principle (GUP) framework which predicts a minimal uncertainty in position. We considered a spinless particle in this framework in the presence of a magnetic field, applied in the z-direction, which varies as 1x2. We found the energy eigenvalues of this system and also obtained the correspounding eigenfunctions, using the numerical method. When GUP parameter tends to zero, our solutions were in agreement with those obtained in the absence of GUP.

PACS: 04.60.-m

1 Introduction

One of the fundamental principles of quantum mechanics is the Heisenberg uncertainty principle, expressing that position and momentum of a particle cannot be measured simultaneously. But at high energy limit where gravity effects gain so much importance and space-time discreteness may occur, this uncertainty principle should be modified as the so-called generalised uncertainty principle (GUP). This generalisation leads to a nonzero minimal uncertainty in position measurements. Various candidates of quantum gravity, such as the string theory, loop quantum gravity, and quantum geometry, all indicate the existence of such a minimal measurable length of the order of the Planck length lp=Gc2=1.6×1035 m, [1, 2].

In recent years, the study of relativistic wave equations, particularly the Klein–Gordon (K-G) equation, has been taken under much consideration. Quantum gravitational corrections to the real K-G field in the presence of a minimal length have been considered [2, 3]. The authors obtained the exact solution of the K-G equation in the presence of a minimal length; also, the exact solution of K-G equation was obtained for charged particles in a magnetic field with the shape invariant method.

In this article, we study spinless particles in the presence of a magnetic field within the GUP framework that predicts minimal uncertainty in position. In Section 2, we state the GUP. In Section 3, we find the generalised K-G equation which describes the spinless particles that have reshaped under Lorentz invariants the GUP deformed relativity equation that describes these particles. In Section 4, we solve the generalised K-G equation in the presence of a magnetic field with specific gauge 1x2. In part two of Section 4, we gain a generalised 4-degree K-G equation where we explain particles with zero spin that have reshaped under Lorentz invariants. We solve these equations for special magnetic fields with zero scalar fields and specified vector fields that we reach from the shown answers in these sections. Moreover, we study the mentioned differential equation for a special state of vector potential in which the stagnation magnetic field is along the z axis and it charges as 1x2. Finally, we present our conclusions in Section 5.

2 Generalised Uncertainty Principle

We consider the GUP proposed by Kempf et al. [46]:

(1)ΔXΔP(/2)(1+β(ΔP)2+γ), (1)

where β is the GUP parameter and γ is a positive constant. We also have β=β0/(MPlc)2, where MPl is the Planck mass and β0 is of order one. The equation’s inequality relation results in the existence of an absolute minimal length uncertainty as (Δx)min=β. In one dimension, the following deformed commutation relation is

(2)[X,P]=i(1+βP2), (2)

which leads to an inequality relation. As Kempf, Mangano, and Mann mentioned in their seminal article [5], X and P can be written as

(3)Pϕ(p)=pϕ(p),   Xϕ(p)=i(1+βP2)pϕ(p), (3)

in momentum space representation. In (3), p can be interpreted as the momentum operator at low energies and P as the momentum operator at high energies. Using (3), the Hamiltonian

(4)H=P22m+V(x), (4)

is transformed into

(5)H=H0+βH1+O(β2), (5)

where H0=p22m+V(x) and H1=p43m. In the quantum domain, the Hamiltonian equation results in the following generalised Schrödinger equation:

(6)22m2ψ(x)x2+βp43mψ(x)+V(x)ψ(x)+O(β2)=Eψ(x), (6)

which has an extra term in comparison to an ordinary Schrödinger equation due to the modified commutation relation. It is not an easy task to solve this equation, because it is a fourth-order differential equation. Therefore, the perturbation method is used in order to obtain the solutions.

3 Generalised K-G Equation in the Presence of a Magnetic Field

In this section, we study the spinless particles in the presence of a magnetic field. For this purpose, first we write the Lagrangian density of a complex field without considering the gravity effects, and then we obtain the generalised form of the K-G equation. The Lagrangian density of complex field in the presence of magnetic field is written as

(7)L=[(iμ+qAμ)ϕ][(iμqAμ)ϕ]m2ϕϕ, (7)

where Aμ is the four axis magnetic potential, ϕ, ϕ* are the complex fields, q is the charge of particle, and m is considered to be the mass of the particle. Using the Euler Lagrange equation, we obtained the K-G equation with gauge invariant as

(8)[(iμ+qAμ)(iμqAμ)m2]ψ(x)=0. (8)

Also, we could obtain this relation by using the K-G equation with a gauge invariant pμ pμ Aμ . Thus, we have

(9)[μμ+m2+U(x)]ψ(x)=0. (9)

In (9), U(x) includes scalar and vector potential

(10)U(x)=iqμAμ+iqAμμq2AμAμ, (10)
(11)=iμVμ+iVμμ+S, (11)

where

(12)S=q2AμAμ,Vμ=qAμ. (12)

We obtained the following equation by expanding (8):

(13)[(1+β)2iq(1+β)μAμiqAμ(1+β)μ+q2AμAμm2]ψ(x)=0, (13)

where c=ℏ=1 is chosen as a unique unit. With a look at (13), it is clear that if β→0, we reach (9), that is, the K-G equation. By taking this algebra into account, the simplified form of (13) is as follows:

(14)[(1+β)2β+m2+UG(x)]ψ(x)=0, (14)

where UG(x) is written as

(15)UG(x)=i(1+β)μVμ+iVμ(1+β)μS. (15)

In (15), Vμ and S are the scalar and vector potentials, respectively. If we disregard the sentences with β2 and higher, (14) is reduces to

(16)[(1+2β)+iq(1+β)μAμ+iqAμ(1+β)μq2AμAμ+m2]ψ(x)=0. (16)

Now, in order to find the plane wave solutions of (16), we choose ψ=ceikx and replace it in (16) to obtain some volumes of K which, according to them, ψ is an answer of (16).

(17)[(1+qβA.K)K2+2β(K2)2+q2A2+m2]=0. (17)

We use coulomb gauge A=0 and specific state A0=0. Then, K2 is obtained as follows:

(18)K2=(1+qAK)±(1+qβAK)28β(q2A2+m2)4β. (18)

By considering the vector field as

(19)A=a0ei(Krωt), (19)

and using the coulomb gauge, we obtain A=iKA=0. So, limitation of β is obtained as

β<18(q2A2+m2).

According to what Moayedi et al. [7] have shown, in the same study in this condition we have

(20)[M+]2=K+2=[(1+22βM)1/2+(122βM)1/222β]2, (20)
(21)[M]2=K2=[(1+22βM)1/2(122βM)1/222β]2. (21)

In (20) and (21) relations, M2=q2A2+m2. The important point is that if M+=M=2M, then it will be β=18M2. By knowing that K2=KμKμ=K02K2,K0=ω and by applying relations in (20) and (21), the reformed energy momentum relation will be achieved for this system as

(22)Ep(+)2=M+2+|p|2,Ep()2=M2+|p|2,Ep±=ωk(±). (22)

The effective masses M+ and M could be rewritten in (20) and (21) up to O(β) as

(23)M+=12βM222β (23)
(24)M=M+βM3, (24)

for β=0, the effective mass M reduces to the usual mass, M. By putting (24) in (22), we can determine the shape of the energy momentum relation in the gravitational framework as follows:

(25)Ep()2=M2+|p|2+2βM4. (25)

By comparing this equation with (27) in work by Moayedi et al. [7], it will be clarified that the general mathematical shape of energy momentum relation is the same for free particles in the presence of a magnetic field, and it is different only in the volume of M, which is dependent on vector potential and the ruling magnetic field.

4 Solving Generalised K-G Equation in the Presence of a Magnetic Field with Specific Gauge 1x2

In this section, we consider a specified gauge introduced by Maharana [8] as

(26)A=(Ax=0,Ay=αx,Az=0),A0=0. (26)

Therefore, magnetic field will be B=×A=(Bx=0,By=0,Bz=αx2) where α is a constant. By considering vector potential and then separating time and position apart from the wave as ψ(x, y, z, t)=ϕ(x, y, z)eiEt and putting this relation into (16), we obtain the following relation:

(27)(E2+2βE4+m2)ϕ(x,y,z)=[(1+4βE2)2+2β(2)2+iqαxy(1+β(E2+2))+q2α2x2]ϕ(x,y,z) (27)

The third and fourth sentences from the right-hand side of (27) are clearly dependent on x, so it is possible to have ϕ(x,y,z)=u(x)ei(Kyy+Kzz). By putting this relation in (27), we obtain the following fourth-order differential equation:

(28)2βd4udx4+ad2udx2+[b+q2α2x2cx]u=0, (28)

which contains the expressions

(29)a=1+4β(E2Ky2Kz2),ωα=qα,b=(Ky2+Kz2)[1+4βE22β(Ky2+Kz2)]+(E2+2βE4+m2),c=ωαKy[1+β(E2Ky2Kz2)]. (29)

In (28), if β→0, it reduces to (15), obtained by Setare and Hatami [9]. To solve the differential of (28), we have used two methods. Initially the perturbation method and secondly the variational iteration method (VIM) was suggested by studying various research of others [1013]. Now, we return to the modified K-G (28), and as previously has been said, the solution of this differential equation is complicated. We tried to obtain the rest energy correction up to O(β) in β via the usual perturbation method of quantum mechanics. Because the amount of energy was calculated by Setare and Hatami [9] without the gravitational effects and differential (28) gained this energy regardless of β, thus the perturbation Hamiltonian is Hpert=2βd4dx4.

(30)[H0+Hpert]u(x)=0, (30)
(31)H0=ad2dx2+[b+q2α2x2cx]. (31)

From Setare and Hatami [9], we have

(32)Enβ=0=±m2+Ky2+Kz2ωα2Ky2(n+1/2+1/4+ωα2)2, (32)

and

(33)un(x)=xa0eb0a0+nxLn2a01(2b0a0+nx), (33)

which a0=1/2+1/4+ωα2 and b0=ωαKy. In Figure 1, we have shown (33) with different values, and mode n=3 will be as following. In Figure 1, the function u(x) is presented. In this figure, the gravity effect is omitted. As can be seen, figures with different modes have the same general shape.

Figure 1: The diagram of the spin-less wave function in special magnetic field without gravity.
Figure 1:

The diagram of the spin-less wave function in special magnetic field without gravity.

In the following, we use the perturbation theory in quantum mechanics to obtain the first correction in the energy levels. For this goal, the expectation value of the eigenfunction (33) was considered:

(34)ΔEnβ=un(x)|Hpert|un(x)un(x)|un(x);   Enβ=Enβ=0+ΔEnβ. (34)

As we describe, the VIM provides efficient algorithm for analytic approximate solutions and numeric simulations for real world applications in sciences [1317]. In order to solve the fourth ODEs, we have used the following relation as in Wazwaz [10]:

(35)un+1(x)=un(x)+13!0x(tx)3Lun(t)dt, (35)

where L is the linear operator that in this research is 2βd4dt4+ad2dt2+[b+q2α2t2ct]. The final answer is u(x)=limn→0un(x). In this method, with respect to the order of differential equation (fourth-order in this case), we need four initial conditions. Because initial conditions were not clear, we selected general form:

(36)u(0)=A,   u(0)=,   u(0)=C,   u(0)=D, (36)
(37)u0(x)=u(0)+u(0)1!+u(0)2!+u(0)3!+. (37)

As it was indicated, we put the different n’s as n=0, 1, 2, … into (30), and we are able to obtain u0, u1, u2, …, un as

(38)u0(x)=A+x+C2x2+D6x3, (38)
(39)u1(x)=1720x6bC+1120x5(c2)C124x4(a+ωα22)C+x2C2,u2(x)= (39)

To calculate (39) using (35), answers do not necessarily converge to zero. Therefore, to avoid this problem, we considered coefficients containing these sentences as zero. Hence, A=0,=ωβKyq2αC. To obtain (39) according to a complex form, general response 𝒟 has been omitted. Equation (28) is a differential equation with coefficient variables of the fourth-order. This form of coefficients and u1(x) informs us that we must go a long route ahead to obtain u2(x). Therefore, we let the general form remain as u1(x) and use numerical methods to obtain eigenfunction. We found the graph of function of (28) by using Matlab software.

In the aforementioned figures, the function u(x) is presented. These figures represent wave functions for four particles with gravity effects. Figure 2a is ηc with quark content cc̅ and β=0.049, Figure 2b shows the η′ with quark content (uu¯+dd¯+cc¯)/6 and β=0.477, Figure 2c is π0 particle with (uu¯dd¯)/2 quark details with β=1.453, and Figure 2d is η with (uu¯+dd¯2ss¯)/6 with gravity coefficient β=24.027 [7]. It appears that the effects of gravity, i.e. β, is small, the figures limited to Figure 1, and whenever β is longer, the general figures shape out of exponential form.

Figure 2: Numerical results for u(x) with β≠0.
Figure 2:

Numerical results for u(x) with β≠0.

5 Conclusions

In this article, we considered a spinless particle in the presence of a magnetic field in the GUP framework that predicts a minimal uncertainty in position. We obtained the modifed K-G equation in this framework. Having investigated the plane wave, we found that there is no difference between the obtained equations and previous ones, and only the value of the magnetic field can lead to different mass and energy, which is consistent with the results of Moayedi et al. [7], but magnetic field can influence mass and energy of the particles. We tried to solve the generalised K-G equation for a special magnetic field by two methods. In the first method (pertubation theory) we provided a relation to the energy levels. In Section 4, we tried to solve the K-G equation for a special state of a magnetic field which, after mathematical process, we obtained as (28). Relation (34) and Figure 1, respectively, show the system energy and special state. When β→0, all states and limitations are established, and problems are created according to what is in (32) and (33). It is anticipated that the results and numerical answers in this study will stimulate further investigations.

References

[1] X. Calmet, Mod. Phys. Lett. A22, 2027 (2007).10.1142/S0217732307025261Search in Google Scholar

[2] M. Merad and M. Falek, Phys. Scr. 79, 015010 (2009).10.1088/0031-8949/79/01/015010Search in Google Scholar

[3] P. Pedram, M. Amirfakhrian, and H. Shababi, Int. Mod. Phys. A 24, 1550016 (2015).10.1142/S0218271815500169Search in Google Scholar

[4] C. Quesne and V. M. Tkachuk, J. Phys. A: Math. Gen. 38, 1747 (2005).10.1088/0305-4470/38/8/011Search in Google Scholar

[5] A. Kempf, G. Mangano, and R. B. Mann, Phys. Rev. D 52, 1108 (1995).10.1103/PhysRevD.52.1108Search in Google Scholar PubMed

[6] M. M. Stetsko and V. M. Tkachuk, Phys. Rev. A 74, 012101 (2006).10.1103/PhysRevA.74.012101Search in Google Scholar

[7] S. K. Moayedi, M. R. Setare, and H. Moayeri, arXiv:1004.0563v1.Search in Google Scholar

[8] K. Maharana, arXiv:math-ph/0306069v1.Search in Google Scholar

[9] M. R. Setare and O. Hatami, Theor. Phys. China 51, 10001002 (2009).10.1088/0253-6102/51/6/07Search in Google Scholar

[10] A. M. Wazwaz, Appl. Math. Comput. 212, 120134 (2009).10.1016/j.amc.2009.02.003Search in Google Scholar

[11] A. M. Wazwaz, Appl. Math. Comput. 105, 1119 (1999).10.1016/S0096-3003(98)10090-5Search in Google Scholar

[12] J. H. He, Appl. Math. Comput. 114, 115123 (2000).Search in Google Scholar

[13] J. H. He, J. Comput. Appl. Math. 207, 317 (2007).Search in Google Scholar

[14] H. T. Davis, Introduction to Nonlinear Dierential and Integral Equations, Dover, New York 1962.Search in Google Scholar

[15] H. Carslaw and J. Jaeger, Conduction of Heat in Solids, Oxford University Press, Oxford, UK 1947.Search in Google Scholar

[16] R. C. Roberts, Unsteady Flow of Gas through a Porous Medium, Proc. First U.S. Natl. Congr. Appl. Mech., Ann Arbor, MI, 773, 776 (1952).Search in Google Scholar

[17] R. E. Kidder, J. Appl. Mech. 27, 329 (1067).Search in Google Scholar

Received: 2015-11-9
Accepted: 2016-2-1
Published Online: 2016-5-26
Published in Print: 2016-6-1

©2016 by De Gruyter

Downloaded on 9.9.2025 from https://www.degruyterbrill.com/document/doi/10.1515/zna-2015-0474/html
Scroll to top button