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The group of self-homotopy equivalences of A n 2-polyhedra

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Published/Copyright: March 20, 2020

Abstract

Let X be a finite type A n 2 -polyhedron, n 2 . In this paper, we study the quotient group ( X ) / * ( X ) , where ( X ) is the group of self-homotopy equivalences of X and * ( X ) the subgroup of self-homotopy equivalences inducing the identity on the homology groups of X. We show that not every group can be realised as ( X ) or ( X ) / * ( X ) for X an A n 2 -polyhedron, n 3 , and specific results are obtained for n = 2 .

1 Introduction

Let ( X ) denote the group of homotopy classes of self-homotopy equivalences of a space X, and let * ( X ) denote the normal subgroup of self-homotopy equivalences inducing the identity on the homology groups of X. Problems related to ( X ) have been extensively studied, with Kahn’s realisability problem deserving a special mention, having been placed first to solve in [2] (see also [1, 11, 12, 14]). It asks whether an arbitrary group can be realised as ( X ) for some simply connected X, and though the general case remains an open question, it has recently been solved for finite groups [7]. As a way to approach Kahn’s problem, in [9, Problem 19], the question of whether an arbitrary group can appear as the distinguished quotient ( X ) / * ( X ) is raised.

In this paper, we work with ( n - 1 ) -connected ( n + 2 ) -dimensional CW-complexes for n 2 , the so-called A n 2 -polyhedra. Homotopy types of these spaces have been classified by Baues in [4, Ch. I, § 8] using the long exact sequence of groups associated to simply connected spaces introduced by J. H. C. Whitehead in [15]. The author of [6] uses that classification to study the group of self-homotopy equivalences of an A 2 2 -polyhedron X. He associates to X a group 4 ( X ) that is isomorphic to ( X ) / * ( X ) and asks if any group can be realised as such a quotient in this context, that is, if A 2 2 -polyhedra provide an adequate framework to solve the realisability problem.

Here, in the general setting of an A n 2 -polyhedra X, n 2 , we also construct a group n + 2 ( X ) (see Definition 2.4) that is isomorphic to ( X ) / * ( X ) (see Proposition 2.5). We show that there exist many groups (for example / p , p odd, Corollary 1.2) for which the question above does not admit a positive answer. This fact should illustrate that A n 2 -polyhedra might not be the right setting to answer [9, Problem 19].

We show, for instance, that under some restrictions on the homology groups of X, n + 2 ( X ) is infinite, which in particular implies that ( X ) is infinite (see Proposition 3.6 and Proposition 3.9). Or for example, in many situations the existence of odd order elements in the homology groups of X implies the existence of involutions in n + 2 ( X ) (see Lemma 3.4 and Lemma 3.5).

In this paper, we prove the following result.

Theorem 1.1.

Let X be a finite type A n 2 -polyhedron, n 3 . Then B n + 2 ( X ) is either the trivial group or it has elements of even order.

As an immediate corollary, we obtain the following.

Corollary 1.2.

Let G be a non-trivial group with no elements of even order. Then G is not realisable as B n + 2 ( X ) for X a finite type A n 2 -polyhedron, n 3 .

The case n = 2 is more complicated. Detailed group-theoretical analysis shows that a finite type A 2 2 -polyhedra might realise finite groups of odd order only under very restrictive conditions. Recall that, for a group G, rank G is the smallest cardinal of a set of generators for G [13, p. 91]. We have the following result.

Theorem 1.3.

Suppose that X is a finite type A 2 2 -polyhedron with a non-trivial finite B 4 ( X ) of odd order. Then the following holds:

  1. rank H 4 ( X ) 1 ,

  2. π 3 ( X ) and H 3 ( X ) are 2 -groups, H 2 ( X ) is an elementary abelian 2 -group,

  3. rank H 3 ( X ) 1 2 rank H 2 ( X ) ( rank H 2 ( X ) + 1 ) - rank H 4 ( X ) rank π 3 ( X ) ,

  4. the natural action of 4 ( X ) on H 2 ( X ) induces a faithful representation

    4 ( X ) Aut ( H 2 ( X ) ) .

All our attempts to find a space satisfying the hypothesis of Theorem 1.3 were unsuccessful. We therefore make the following conjecture.

Conjecture 1.4.

Let X be an A 2 2 -polyhedron. If 4 ( X ) is a non-trivial finite group, then it necessarily has an element of even order.

This paper is organised as follows. In Section 2, we give a brief introduction to Whitehead’s and Baues’s results for the classification of homotopy types of A n 2 -polyhedra, or equivalently, isomorphism classes of certain long exact sequences of abelian groups (see Theorem 2.3). In Section 3, we study how restrictions on X affect the group n + 2 ( X ) . Finally, Section 4 is devoted to the proof of our main results, Theorem 1.1 and Theorem 1.3.

2 The Γ-sequence of an A n 2 -polyhedron

Let Ab denote the category of abelian groups. In [15], J. H. C. Whitehead constructed a functor Γ : Ab Ab , known as Whitehead’s universal quadratic functor, and an exact sequence, which are useful to our purposes and introduced in this section. The Γ-functor is defined as follows. Let A and B be abelian groups and η : A B a map (of sets) between them. The map η is said to be quadratic if

  1. η ( a ) = η ( - a ) for all a A ,

  2. the map A × A B taking ( a , a ) to η ( a + a ) - η ( a ) - η ( a ) is bilinear.

For an abelian group A, Γ ( A ) is the only abelian group for which there exists a quadratic map γ : A Γ ( A ) such that every other quadratic map η : A B factors uniquely through γ. This means that there is a unique group homomorphism η : Γ ( A ) B such that η = η γ . The quadratic map γ : A Γ ( A ) is called the universal quadratic map of A.

The Γ-functor acts on morphisms as follows. Let f : A B be a group homomorphism, and γ : A Γ ( A ) and γ : B Γ ( B ) the universal quadratic maps. Then γ f : A Γ ( B ) is a quadratic map, so there exists a unique group homomorphism ( γ f ) : Γ ( A ) Γ ( B ) such that ( γ f ) γ = γ f . Define Γ ( f ) = ( γ f ) .

We now list some of its properties that will be used later in this paper.

Proposition 2.1 ([5, pp. 16–17]).

The Γ functor has the following properties:

  1. Γ ( ) = .

  2. Γ ( n ) is 2 n if n is even, or n if n is odd.

  3. Let I be an ordered set and A i an abelian group for each i I . Then

    Γ ( I A i ) = ( I Γ ( A i ) ) ( i < j A i A j ) .

    Moreover, the groups Γ ( A i ) and A i A j are respectively generated by elements γ ( a i ) and a i a j , with a i A i , a j A j , i < j , and

    γ ( a i + a j ) = γ ( a i ) + γ ( a j ) + a i a j 𝑓𝑜𝑟 a i A i , a j A j , i < j

    (see [ 15 , § 5, § 7] ).

We now introduce Whitehead’s exact sequence. Let X be a simply connected CW-complex. For n 1 , the n-th Whitehead Γ-group of X is defined as

Γ n ( X ) = Im ( i * : π n ( X n - 1 ) π n ( X n ) ) .

Here, i : X n - 1 X n is the inclusion of the ( n - 1 ) -skeleton of X into its n-skeleton. Then Γ n ( X ) is an abelian group for n 1 . This group can be embedded into a long exact sequence of abelian groups

(2.1) H n + 1 ( X ) b n + 1 Γ n ( X ) i n - 1 π n ( X ) h n H n ( X ) ,

where h n is the Hurewicz homomorphism and b n + 1 is a boundary representing the attaching maps.

For each n 2 , a functor Γ n 1 : Ab Ab is defined as follows. Let Γ 2 1 = Γ be the universal quadratic functor, and for n 3 , Γ n 1 = - 2 . It turns out that if X is ( n - 1 ) -connected, then Γ n 1 ( H n ( X ) ) Γ n + 1 ( X ) (see [5, Theorem 2.1.22]). Thus the final part of the long exact sequence (2.1) can be written as

(2.2) H n + 2 ( X ) b n + 2 Γ n 1 ( H n ( X ) ) i n π n + 1 ( X ) h n + 1 H n + 1 ( X ) 0 .

Now, for each n 2 , we define the category of A n 2 -polyhedra as the category whose objects are ( n + 2 ) -dimensional ( n - 1 ) -connected CW-complexes and whose morphisms are continuous maps between objects. Homotopy types of these spaces are classified through isomorphism classes in a category whose objects are sequences like (2.2) [4, Ch. I, § 8].

Definition 2.2 ([3, Ch. IX, § 4]).

Let n 2 be an integer. We define the category Γ-sequences n + 2 as follows. Objects are exact sequences of abelian groups

H n + 2 Γ n 1 ( H n ) π n + 1 H n + 1 0 ,

where H n + 2 is free abelian. Morphisms are triples of group homomorphisms f = ( f n + 2 , f n + 1 , f n ) , f i : H i H i , such that there exists a group homomorphism Ω : π n + 1 π n + 1 making the diagram

commutative. Objects in Γ -sequences n + 2 are called Γ-sequences, and morphisms in the category are called Γ-morphisms.

On the one hand, we can assign to an A n 2 -polyhedron X an object in Γ-sequences n + 2 by considering the associated exact sequence (2.2). We call such an object the Γ-sequence of X . On the other hand, to a continuous map α : X X of A n 2 -polyhedra, we can assign a morphism between the corresponding Γ-sequences by considering the induced homomorphisms

Therefore, we have a functor A n 2 -polyhedra Γ -sequences n + 2 which clearly restricts to the homotopy category of A n 2 -polyhedra, o A n 2 -polyhedra . It is obvious that this functor sends homotopy equivalences to isomorphisms between the corresponding Γ-sequences. Thus we can classify homotopy types of A n 2 -polyhedra through isomorphism classes of Γ-sequences.

Theorem 2.3 ([4, Ch. I, § 8]).

The functor H o A n 2 -polyhedra Γ -sequences n + 2 previously defined is full. Moreover, for any object in Γ -sequences n + 2 , there exists an A n 2 -polyhedron whose Γ-sequence is the given object in Γ -sequences n + 2 . In fact, there exists a 1–1 correspondence between homotopy types of A n 2 -polyhedra and isomorphism classes of Γ-sequences.

Following the ideas of [6], we introduce the following.

Definition 2.4.

Let X be an A n 2 -polyhedron. We denote by n + 2 ( X ) the group of Γ-isomorphisms of the Γ-sequence of X.

Let Ψ : ( X ) n + 2 ( X ) be the map that associates to α ( X ) the Γ-isomorphism Ψ ( α ) = ( H n + 2 ( α ) , H n + 1 ( α ) , H n ( α ) ) . Then Ψ is a group homomorphism: its kernel is the subgroup of self-homotopy equivalences inducing the identity map on the homology groups of X, that is, * ( X ) . Also, Ψ is onto as a consequence of Theorem 2.3. Hence, we immediately obtain the following result.

Proposition 2.5.

Let X be an A n 2 -polyhedron, n 2 . Then

n + 2 ( X ) ( X ) / * ( X ) .

3 Self-homotopy equivalences of finite type A n 2 -polyhedra

Henceforth, an A n 2 -polyhedron will mean an ( n - 1 ) -connected, ( n + 2 ) -dimensional CW-complex of finite type. Recall that, for simply connected and finite type spaces, the homology and homotopy groups H n ( X ) and π n ( X ) are finitely generated and abelian for n 1 .

The Γ-sequence tool introduced in Section 2 will help us to illustrate, from an algebraic point of view, how different restrictions on an A n 2 -polyhedron X affect the quotient group ( X ) / * ( X ) . We devote this section to that matter. We also obtain several results that are needed in the proof of Theorem 1.1 and Theorem 1.3. The following result is a generalisation of [6, Theorem 4.5].

Proposition 3.1.

Let X be an A n 2 -polyhedron and suppose that the Hurewicz homomorphism h n + 2 : π n + 2 ( X ) H n + 2 ( X ) is onto. Then every automorphism of H n + 2 ( X ) is realised by a self-homotopy equivalence of X.

Proof.

As part of the exact sequence (2.1) for X, we have

π n + 2 ( X ) h n + 2 H n + 2 ( X ) b n + 2 Γ n 1 ( H n ( X ) ) π n + 1 ( X ) .

Then, since h n + 2 is onto by hypothesis, b n + 2 is the trivial homomorphism. Thus, for every f n + 2 Aut ( H n + 2 ( X ) ) , we have b n + 2 f n + 2 = b n + 2 = 0 , so if Ω = id , ( f n + 2 , id , id ) n + 2 ( X ) . Then there exists f ( X ) with H n + 2 ( f ) = f n + 2 , H n + 1 ( f ) = id , H n ( f ) = id . ∎

We can easily prove that automorphism groups can be realised; a result that can also be obtained as a consequence of [14, Theorem 2.1].

Example 3.2.

Let G be a group isomorphic to Aut ( H ) for some finitely generated abelian group H. Then, for any integer n 2 , there exists an A n 2 -polyhedron X such that G n + 2 ( X ) : take the Moore space X = M ( H , n + 1 ) , which in particular is an A n 2 -polyhedron. The Γ-sequence of X is

H n + 2 ( X ) = 0 Γ n 1 ( H n ( X ) ) = 0 H = H 0 .

Then, for every f Aut ( H ) , taking Ω = f , we see that ( id , f , id ) n + 2 ( X ) , and those are the only possible Γ-isomorphisms. Thus n + 2 ( X ) Aut ( H ) G .

The use of Moore spaces is not required in the n = 2 case.

Example 3.3.

Let G be a group isomorphic to Aut ( H ) for some finitely generated abelian group H. Consider the following object in Γ-sequences 4 :

(3.1) b 4 Γ ( 2 ) = 4 H = H 0 .

By Theorem 2.3, there exists an A 2 2 -polyhedron X realising this object. In particular, H 4 ( X ) = , H 3 ( X ) = π 3 ( X ) = H and H 2 ( X ) = 2 . It is clear from (3.1) that ( id , f , id ) is a Γ-isomorphism for every f Aut ( H ) . Now, Aut ( 2 ) is the trivial group while Aut ( ) = { - id , id } . It is immediate to check that ( - id , f , id ) is not a Γ-isomorphism since id b 4 b 4 ( - id ) . Then we obtain 4 ( X ) Aut ( H ) .

Observe that not every group G is isomorphic to the automorphism group of an abelian group (for example p if p is odd). Hence, examples from above only provide a partial positive answer to the realisability problem for n + 2 ( X ) . Indeed, the automorphism group of an abelian group (other than 2 ) has elements of even order. The following results go in that direction.

Lemma 3.4.

Let X be an A n 2 -polyhedron, n 2 . If H n ( X ) is not an elementary abelian 2-group, then B n + 2 ( X ) has an element of order 2.

Proof.

Since H n ( X ) is not an elementary abelian 2-group, it admits a non-trivial involution - id : H n ( X ) H n ( X ) . But Γ n 1 ( - id ) = id for every n 2 , so we have ( id , id , - id ) n + 2 ( X ) , and the result follows. ∎

Notice a key difference between the n = 2 and the n 3 cases: Γ 2 1 ( A ) = Γ ( A ) is never an elementary abelian 2-group when A is finitely generated and abelian, as can be deduced from Proposition 2.1. However, for n 3 , Γ n 1 ( A ) = A 2 is always an elementary abelian 2-group. Taking advantage of this fact we can prove the following result.

Lemma 3.5.

Let X be an A n 2 -polyhedron, n 3 . If any of the homology groups of X is not an elementary abelian 2-group (in particular, if H n + 2 ( X ) 0 ), then B n + 2 ( X ) contains a non-trivial element of order 2.

Proof.

Under our assumptions, Γ n 1 ( H n ( X ) ) is an elementary abelian 2-group. For Ω = - id , the triple ( - id , - id , - id ) is a Γ-isomorphism of order 2 unless H n + 2 ( X ) , H n + 1 ( X ) and H n ( X ) are all elementary abelian 2-groups. ∎

We remark that this result does not hold for A 2 2 -polyhedra. Indeed, if we consider the construction in Example 3.3 for H = 2 , then 4 ( X ) Aut ( 2 ) = { * } does not contain a non-trivial element of order 2 although H 4 ( X ) = is not an elementary abelian 2-group.

We now prove some results regarding the finiteness of n + 2 ( X ) .

Proposition 3.6.

Let X be an A n 2 -polyhedron, n 2 , with rank H n + 2 ( X ) 2 and every element of Γ n 1 ( H n ( X ) ) of finite order. Then B n + 2 ( X ) is an infinite group.

Proof.

Since rank H n + 2 ( X ) 2 , we may write H n + 2 ( X ) = 2 G , G a (possibly trivial) free abelian group. Consider the Γ-sequence of X,

2 G b n + 2 Γ n 1 ( H n ( X ) ) i n π n + 1 ( X ) h n + 1 H n + 1 ( X ) 0 .

Since b n + 2 ( 2 ) Γ n 1 ( H n ( X ) ) is a finitely generated -module with finite order generators, it is a finite group. Define k = exp ( b n + 2 ( 2 ) ) , and consider the automorphism of 2 given by the matrix

( 1 k 0 1 ) GL 2 ( ) ,

which is of infinite order. If we take f id G Aut ( 2 G ) , then we have b n + 2 ( f id ) = b n + 2 , thus ( f id G , id , id ) n + 2 ( X ) , which is an element of infinite order. ∎

As previously mentioned, Γ n 1 ( H n ( X ) ) is an elementary abelian 2-group for n 3 . Hence, from Proposition 3.6 we get:

Corollary 3.7.

Let X be an A n 2 -polyhedron, n 3 , with rank H n + 2 ( X ) 2 . Then B n + 2 ( X ) is an infinite group.

This result does not hold, in general, for n = 2 . However, if A is a finite group, Proposition 2.1 implies that Γ ( A ) is finite as well, so from Proposition 3.6, we get the following.

Corollary 3.8.

Let X be an A 2 2 -polyhedron with rank H 4 ( X ) 2 and H 2 ( X ) finite. Then B 4 ( X ) is an infinite group.

We end this section with one more result on the infiniteness of n + 2 ( X ) .

Proposition 3.9.

Let X be an A n 2 -polyhedron, n 3 . If H n ( X ) = Z 2 G for a certain abelian group G, then B n + 2 ( X ) is an infinite group.

Proof.

If H n ( X ) = 2 G , then

Γ n 1 ( H n ( X ) ) = H n ( X ) 2 = 2 2 ( G 2 ) .

Hence GL 2 ( ) Aut ( H n ( X ) ) and GL 2 ( 2 ) Aut ( H n ( X ) 2 ) . Moreover, for every f GL 2 ( ) , we have f id G Aut ( H n ( X ) ) , which yields, through Γ n 1 , an automorphism ( f id G ) 2 = ( f 2 ) id G 2 Aut ( H n ( X ) 2 ) . This means that the functor Γ n 1 restricts to GL 2 ( ) GL 2 ( 2 ) . Moreover, we have that - 2 : GL 2 ( ) GL 2 ( 2 ) has an infinite kernel. Hence, there are infinitely many morphisms f Aut ( H n ( X ) ) such that f 2 = id . For any such a morphism f, ( id , id , f ) is an element of n + 2 ( X ) . Therefore, n + 2 ( X ) is infinite. ∎

4 Obstructions to the realisability of groups

We have seen in Section 3 that the group n + 2 ( X ) contains elements of even order unless strong restrictions are imposed on the homology groups of the A n 2 -polyhedron X. Since we are interested in realising an arbitrary group G as n + 2 ( X ) for X a finite type A n 2 -polyhedron, in this section, we focus our attention on the remaining situations and prove Theorems 1.1 and 1.3. We first give some previous results.

Lemma 4.1.

For G an elementary abelian 2-group, Γ ( - ) : Aut ( G ) Aut ( Γ ( G ) ) is injective.

Proof.

Let us show that the kernel of Γ ( - ) is trivial. Assume that G is generated by { e j j J } , J an ordered set. If f Aut ( G ) is in the kernel of Γ ( - ) , then, for each j J , there exists a finite subset I j J such that f ( e j ) = i I j e i , and

γ ( e j ) = Γ ( f ) γ ( e j ) = γ f ( e j ) = γ ( i I j e i ) = i I j γ ( e i ) + i < k e i e k ,

as a consequence of Proposition 2.1 (3), so I j = { j } and f ( e j ) = e j for every j J . ∎

Lemma 4.2.

Let H 2 = i = 1 n Z 2 , and let χ Γ ( H 2 ) be an element of order 4. If there exists a non-trivial automorphism of odd order f Aut ( H 2 ) such that Γ ( f ) ( χ ) = χ , then there exists g Aut ( H 2 ) of order 2 such that Γ ( g ) ( χ ) = χ .

Proof.

Notice that according to [15, p. 66], we can write h h = 2 γ ( h ) for any element h H 2 . Therefore, given a basis { h 1 , h 2 , , h n } of H 2 , and replacing 3 γ ( h i ) by γ ( h i ) + h i h i if needed, we can write

χ = i = 1 n a ( i ) γ ( h i ) + i , j = 1 n a ( i , j ) h i h j ,

where every coefficient a ( i ) , a ( i , j ) is either 0 or 1. We now inductively construct a basis { e 1 , e 2 , , e n } of H 2 as follows. Without loss of generality, assume a ( 1 ) = 1 , and define e 1 = i = 1 n a ( i ) h i . Then { e 1 , h 2 , , h n } is again a basis of H 2 and

χ = γ ( e 1 ) + α 1 e 1 e 1 + β 1 e 1 ( s = 2 n b ( 1 , s ) h s ) + i , j > 1 n a 1 ( i , j ) h i h j ,

where every coefficient in the equation is either 0 or 1. Assume a basis

{ e 1 , , e r , h r + 1 , , h n }

has been constructed such that

χ = γ ( e 1 ) + j = 1 r α j e j e j + j = 1 r - 1 β j e j e j + 1 + β r e r ( s = r + 1 n b ( r , s ) h s ) + i , j > r n a r ( i , j ) h i h j ,

where every coefficient is either 0 or 1. We may assume b ( r , r + 1 ) = 1 and define e r + 1 = s = r + 1 n b ( r , s ) h s . Thus { e 1 , , e r + 1 , h r + 2 , , h n } is again a basis of H 2 and

χ = γ ( e 1 ) + j = 1 r + 1 α j e j e j + j = 1 r β j e j e j + 1 + β r + 1 e r + 1 ( s = r + 2 n b ( r + 1 , s ) h s ) + i , j > r + 1 n a r + 1 ( i , j ) h i h j .

Finally, we obtain a basis { e 1 , e 2 , , e n } of H 2 such that

(4.1) χ = γ ( e 1 ) + j = 1 n α j e j e j + j = 1 n - 1 β j e j e j + 1

for some coefficients

α j { 0 , 1 } , j = 1 , 2 , , n , and β j { 0 , 1 } , j = 1 , 2 , , n - 1 .

Now, for n = 1 , H 2 = 2 has a trivial group of automorphisms, so the result holds. For n = 2 , assume that there exists f Aut ( H 2 ) such that Γ ( f ) ( χ ) = χ . From equation (4.1), χ = Γ ( f ) ( γ ( e 1 ) ) + Γ ( f ) ( P ) , where

P Ω 1 ( Γ ( H 2 ) ) = { h Γ ( H 2 ) : ord ( h ) 2 } .

Then Γ ( f ) ( γ ( e 1 ) ) has a multiple of γ ( e 1 ) as its only summand of order 4, which implies f ( e 1 ) = e 1 . Then either f ( e 2 ) = e 2 , so f is trivial, or f ( e 2 ) = e 1 + e 2 , so f has order 2.

For n 3 , we define g Aut ( H 2 ) by g ( e j ) = e j for j = 1 , 2 , , n - 2 , and g ( e n - 1 ) and g ( e n ) , depending on α n - j and β n - 1 - j , for j = 0 , 1 , in equation (4.1), according to the following table.

α n β n - 1 α n - 1 β n - 2 g ( e n - 1 ) g ( e n )
0 0 0  or  1 0  or  1 e n - 1 e n - 1 + e n
0 1 0 0 e n e n - 1
0 1 0 1 e n - 2 + e n e n - 2 + e n - 1
0 1 1 0 e n - 1 + e n e n
0 1 1 1 e n - 2 + e n - 1 + e n e n
1 0 0 0 e n - 2 + e n - 1 e n
1 0 0 1 e n - 2 + e n - 1 e n - 2 + e n
1 0 1 0 e n e n - 1
1 0 1 1 e n - 2 + e n - 1 e n
1 1 0  or  1 0  or  1 e n - 1 e n - 1 + e n

A simple computation shows that, in all cases, g has order 2 and Γ ( g ) ( χ ) = χ , so the result follows. ∎

Definition 4.3.

Let f : H K be a morphism of abelian groups. We say that a non-trivial subgroup A K is f-split if there exist groups B H and C K such that H A B , K = A C and f can be written as

id A g : A B A C for some g : B C .

Henceforward, we will make extensive use of this notation applied to

h n + 1 : π n + 1 ( X ) H n + 1 ( X ) ,

the Hurewicz morphism. We prove the following.

Lemma 4.4.

Let X be an A n 2 -polyhedron, n 2 . Let A H n + 1 ( X ) be an h n + 1 -split subgroup; thus H n + 1 ( X ) = A C for some abelian group C. Then, for every f A Aut ( A ) , there exists f E ( X ) inducing ( id , f A id C , id ) B n + 2 ( X ) .

Proof.

By hypothesis, H n + 1 ( X ) = A C , π n + 1 ( X ) A B for some abelian group B, and h n + 1 can be written as id A g for some morphism g : B C . Thus, for every f A Aut ( A ) , we have a commutative diagram

Hence ( id , f A id C , id ) n + 2 ( X ) , and by Theorem 2.3, there exists f ( X ) such that H n + 1 ( f ) = f A id C , H n + 2 ( f ) = id and H n ( f ) = id . ∎

The following lemma is crucial in the proof of Theorems 1.1 and 1.3.

Lemma 4.5.

Let X be an A n 2 -polyhedron, n 2 . Suppose that there exist h n + 1 -split subgroups of H n + 1 ( X ) .

  1. If n 3 , then n + 2 ( X ) is either trivial or it has elements of even order.

  2. If 4 ( X ) is finite and non-trivial, then it has elements of even order.

Proof.

First of all, observe that we just need to consider when H n ( X ) is an elementary abelian 2-group. Otherwise, the result is a consequence of Lemma 3.4.

Let A be an arbitrary h n + 1 -split subgroup of H n + 1 ( X ) . If A 2 , there is an involution ι Aut ( A ) that induces an element ( id , ι id , id ) n + 2 ( X ) of order 2 by Lemma 4.4, and the result follows. Hence we can assume that every h n + 1 -split subgroup of H n + 1 ( X ) is 2 .

Both assumptions, namely H n ( X ) being an elementary abelian 2-group and every h n + 1 -split subgroup of H n + 1 ( X ) being 2 , imply that H n + 1 ( X ) is a finite 2-group. Indeed, since H n ( X ) is finitely generated, Γ n 1 ( H n ( X ) ) is a finite 2-group and so is coker b n + 2 . Then, since H n + 1 ( X ) is also finitely generated, any direct summand of H n + 1 ( X ) which is not a 2-group would be h n + 1 -split, contradicting our assumption that every h n + 1 -split subgroup of H n + 1 ( X ) is 2 .

To prove our lemma, we start with the case A = H n + 1 ( X ) is h n + 1 -split. When H n + 2 ( X ) = 0 , the Γ-sequence of X becomes then the short exact sequence

0 Γ n 1 ( H n ( X ) ) Γ n 1 ( H n ( X ) ) 2 2 0 .

Notice that any automorphism of order 2 in H n ( X ) yields an automorphism of order 2 in Γ n 1 ( H n ( X ) ) since Γ n 1 is injective on morphisms: it is immediate for n 3 , and for n = 2 , apply Lemma 4.1. As our sequence is split, any f Aut ( H n ( X ) ) induces the Γ-isomorphism ( id , id , f ) of the same order. Hence, for H n ( X ) 2 , it suffices to consider an involution. For H n ( X ) = 2 , since by hypothesis

H n + 1 ( X ) = 2 and H n + 2 ( X ) = 0 ,

the only Γ-isomorphism is ( id , id , id ) , and therefore n + 2 ( X ) is trivial as claimed.

When H n + 2 ( X ) 0 , for n 3 , the result follows directly from Lemma 3.5. For n = 2 , we also assume that 4 ( X ) is finite and non-trivial. Hence, since H 2 ( X ) is an elementary abelian 2-group, Proposition 3.6 implies that H 4 ( X ) = . Then, if a Γ-isomorphism of the form ( - id , f , id ) exists, it is of even order. In particular, if Im b 4 is a subgroup of Γ ( H 2 ( X ) ) of order 2, ( - id , id , id ) is a Γ-isomorphism of even order.

Assume otherwise that Im b 4 is a group of order 4. If a Γ-isomorphism ( id , f , id ) of odd order exists, then Γ ( f ) b 4 = b 4 . In this situation, by Lemma 4.2 for χ = b 4 ( 1 ) , there exists g Aut ( H 2 ( X ) ) , an automorphism of order 2 such that Γ ( g ) b 4 ( 1 ) = b 4 ( 1 ) . Moreover, as we are in the case A = H 3 ( X ) being h 3 -split, ( id , g , id ) 4 ( X ) is a Γ-isomorphism of order 2.

We deal now with the case A H n + 1 ( X ) . Since A = 2 is a proper h n + 1 -split subgroup of H n + 1 ( X ) , there exist non-trivial groups B and C such that

π n + 1 ( X ) = 2 B h n + 1 2 C = H n + 1 ( X ) ,
( t , b ) ( t , g ( b ) )

for some group morphism B 𝑔 C . Moreover, H n + 1 ( X ) is a finite 2-group; thus C is a (non-trivial) finite 2-group, and there exists an epimorphism C 𝜏 2 .

Define

f Aut ( 2 C ) = Aut ( H n + 1 ( X ) ) ,
Ω Aut ( 2 B ) = Aut ( π n + 1 ( X ) )

to be the non-trivial involutions given by

f ( t , c ) = ( t + τ ( c ) , c ) and Ω ( t , b ) = ( t + τ ( g ( b ) ) , b ) .

By construction, h n + 1 Ω = f h n + 1 , and if ( t , b ) coker b n + 2 = ker h n + 1 (thus g ( b ) = 0 ), then Ω ( t , b ) = ( t , b ) . In other words, ( id , f , id ) n + 2 ( X ) , and it has order 2. ∎

We now prove our main results.

Proof of Theorem 1.1.

Assume that H n ( X ) and H n + 1 ( X ) are elementary abelian 2-groups, and H n + 2 ( X ) = 0 . Otherwise, there would already be elements of order 2 in n + 2 ( X ) as a consequence of Lemma 3.5.

Write H n ( X ) = I 2 , I an ordered set. Since n 3 , we have Γ n 1 = - 2 , so Γ n 1 ( H n ( X ) ) = H n ( X ) . We can also assume that there are no subgroups in H n + 1 ( X ) that are h n + 1 -split. Otherwise, we would deduce from Lemma 4.5 that there are elements of order 2 in n + 2 ( X ) . Thus H n + 1 ( X ) = J 2 with J I , and the Γ-sequence corresponding to X is

0 I 2 𝑏 ( I - J 2 ) ( J 4 ) J 2 0 .

We may rewrite the sequence as

0 ( I - J 2 ) ( J 2 ) 𝑏 ( I - J 2 ) ( J 4 ) J 2 0

and assume that b ( x , y ) = ( x , 2 y ) and h ( x , y ) = y mod  2 . It is clear that any f Aut ( I - J 2 ) induces a Γ-isomorphism ( 0 , id , f id ) of the same order.

On the one hand, for | I - J | 2 , I - J 2 has an involution, and therefore n + 2 ( X ) has elements of even order. On the other hand, for | I - J | < 2 , we consider the remaining possibilities.

Suppose that | I - J | = 1 . Then π n + 1 ( X ) = 2 ( J 4 ) . If J is trivial, then n + 2 ( X ) is clearly trivial as well. Otherwise, suppose that I - J = { i } and choose j J . Define

f Aut ( 2 2 ( I - { i , j } 2 ) ) by f ( x , y , z ) = ( x , x + y , z ) ,
g Aut ( 2 4 ( I - { i , j } 4 ) ) by g ( x , y , z ) = ( x , 2 x + y , z ) .

Then ( id , id , f ) is a Γ-isomorphism of order 2 since we have a commutative diagram

Suppose that I = J . If H n ( X ) = H n + 1 ( X ) = 2 , n + 2 ( X ) is trivial. If not, choose i , j I , and define maps

f Aut ( 2 2 ( I - { i , j } 2 ) ) by f ( x , y , z ) = ( y , x , z ) ,
g Aut ( 4 4 ( I - { i , j } 4 ) ) by g ( x , y , z ) = ( y , x , z ) .

We have the following commutative diagram:

Then ( 0 , f , f ) is a Γ-isomorphism of order 2. ∎

As a consequence, we obtain a negative answer to the problem of realising groups as self-homotopy equivalences of A n 2 -polyhedra.

Corollary 4.6.

Let G be a non-nilpotent finite group of odd order. Then, for any n 3 and for any A n 2 -polyhedron X, we have G E ( X ) .

Proof.

Assume that there exists an A n 2 -polyhedron X such that ( X ) G . Then, if ( X ) * ( X ) , the quotient ( X ) / * ( X ) is a finite group of odd order, which contradicts Theorem 1.1. Thus G ( X ) = * ( X ) . However, since X is a 1-connected and finite-dimensional CW-complex, * ( X ) is a nilpotent group, [8, Theorem D], which contradicts the fact that G is non-nilpotent. ∎

We end this paper by proving our second main result.

Proof of Theorem 1.3.

By hypothesis, 4 ( X ) is a finite group of odd order. From Lemma 3.4, we deduce that H 2 ( X ) is an elementary abelian 2-group, and from Proposition 2.1, we deduce that Γ ( H 2 ( X ) ) is a 2-group. In particular, every element of Γ ( H 2 ( X ) ) is of finite order, and therefore rank H 4 ( X ) 1 by Proposition 3.6, so we have Theorem 1.3 (1). Now, any element in 4 ( X ) is of the form ( 0 , f 2 , f 3 ) if H 4 ( X ) = 0 , or ( id , f 2 , f 3 ) if H 4 ( X ) = . Notice that a Γ-morphism of the form ( - id , f 2 , f 3 ) has even order thus it cannot be a Γ-isomorphism under our hypothesis. Therefore, if H 4 ( X ) = , then b 4 ( 1 ) generates a 4 factor in Γ ( H 2 ( X ) ) , and under our hypothesis, the equation

rank Γ ( H 2 ( X ) ) = rank H 4 ( X ) + rank ( coker b 4 )

holds for rank H 4 ( X ) 1 .

Observe that any Γ-isomorphism of X induces a chain morphism of the short exact sequence

0 coker b 4 π 3 ( X ) missing H 3 ( X ) 0 .

We will draw our conclusions from this induced morphism, which can be seen as an automorphism of π 3 ( X ) that maps the subgroup i 2 ( coker b 4 ) to itself, thus inducing an isomorphism on the quotient, H 3 ( X ) .

As we mentioned above, Γ ( H 2 ( X ) ) is a 2-group. Then coker b 4 is a quotient of a 2-group so a 2-group itself. We claim that H 3 ( X ) is also a 2-group; otherwise, H 3 ( X ) has a summand whose order is either infinite or odd, and therefore this summand would be h 3 -split, which from Lemma 4.5 implies that 4 ( X ) has elements of even order, leading to a contradiction. Since coker b 4 and H 3 ( X ) are 2-groups, so is π 3 ( X ) , proving thus Theorem 1.3 (2).

Moreover, as a consequence of Lemma 4.5, no subgroup of H 3 ( X ) can be h 3 -split, and thus rank H 3 ( X ) rank ( coker b 4 ) = rank Γ ( H 2 ( X ) ) - rank H 4 ( X ) . We can compute rank Γ ( H 2 ( X ) ) using Proposition 2.1 and immediately obtain Theorem 1.3 (3).

Now, for a 2-group G, define the subgroup Ω 1 ( G ) = { g G : ord ( g ) 2 } . One can easily check that Ω 1 ( π 3 ( X ) ) i 2 ( coker b 4 ) , and from [10, Ch. 5, Theorem 2.4], we obtain that any automorphism of odd order of π 3 ( X ) acting as the identity on i 2 ( coker b 4 ) must be the identity.

Then, if ( id , f 3 , f 2 ) 4 ( X ) is a Γ-morphism with f 3 non-trivial, f 3 has odd order, so we may assume that Ω : π 3 ( X ) π 3 ( X ) (see Definition 2.2) has odd order too. By the argument above, it must induce a non-trivial homomorphism on i 2 ( coker b 4 ) , and therefore f 2 is non-trivial as well. So the natural action of 4 ( X ) on H 2 ( X ) must be faithful since any Γ-automorphism ( id , f 3 , f 2 ) 4 ( X ) induces a non-trivial f 2 Aut ( H 2 ( X ) ) . Then Theorem 1.3 (4) follows. ∎


Communicated by Radha Kessar


Award Identifier / Grant number: MTM2016-79661-P

Award Identifier / Grant number: MTM2016-78647-P

Award Identifier / Grant number: FPU14/05137

Funding statement: The first author was partially supported by Ministerio de Economía y Competitividad (Spain), grant MTM2016-79661-P. The second author was partially supported by Ministerio de Educación, Cultura y Deporte grant FPU14/05137, and by Ministerio de Economía y Competitividad (Spain) grants MTM2016-79661-P and MTM2016-78647-P. The third author was partially supported by Ministerio de Economía y Competitividad (Spain) grant MTM2016-78647-P.

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Received: 2018-10-26
Revised: 2020-02-27
Published Online: 2020-03-20
Published in Print: 2020-07-01

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