Bezout rings without non-central idempotents
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Askar A. Tuganbaev
Abstract
Let A be a Bezout ring without non-central idempotents. If A is a right or left Rickartian ring, then A is an Hermitian ring. If A is an exchange ring, then every rectangular matrix over A is diagonalizable.
Funding
This work was supported by the Russian Science Foundation (project no. 16-11-10013).
Note: Originally published in Diskretnaya Matematika (2016) 28, №2, 133–145 (in Russian).
Acknowledgment
The author thanks B.V. Zabavsky and I.B. Kozhukhov for useful discussions.
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Artikel in diesem Heft
- Conjugacy word problem in the tree product of free groups with a cyclic amalgamation
- Independent sets in graphs
- Successive partition of edges of bipartite graph into matchings
- Limit theorems for the number of successes in random binary sequences with random embeddings
- Bezout rings without non-central idempotents
Artikel in diesem Heft
- Conjugacy word problem in the tree product of free groups with a cyclic amalgamation
- Independent sets in graphs
- Successive partition of edges of bipartite graph into matchings
- Limit theorems for the number of successes in random binary sequences with random embeddings
- Bezout rings without non-central idempotents
