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An example related to Whitney’s extension problem for L 2,p (R2) when 1 < p < 2

  • Jacob Carruth EMAIL logo and Arie Israel
Published/Copyright: May 31, 2024

Abstract

In this paper, we prove the existence of a bounded linear extension operator T : L 2 , p ( E ) L 2 , p ( R 2 ) when 1 < p < 2, where E R 2 is a certain discrete set with fractal structure. Our proof makes use of a theorem of Fefferman–Klartag (“Linear extension operators for Sobolev spaces on radially symmetric binary trees,” Adv. Nonlinear Stud., vol. 23, no. 1, p. 20220075, 2023) on the existence of linear extension operators for radially symmetric binary trees.

1 Introduction

Let X ( R n ) be a space of continuous, real-valued functions on R n equipped with a norm (or seminorm) ‖ ⋅ ‖. For any subset Ω R n , define the trace norm (or seminorm) of a continuous function f : Ω R by

f X ( Ω ) = inf { F : F | Ω = f } .

The trace space X ( Ω ) is then defined to be the space of continuous functions f : Ω R with finite trace norm.

We say that a linear map T : X ( Ω ) X ( R n ) is a linear extension operator for X ( Ω ) provided that (Tf)|Ω = f for all f X ( Ω ) . We say that X ( Ω ) admits a bounded linear extension operator if there exists a constant C (determined only by the function space X ( R n ) ) such that there exists a bounded linear extension operator for X ( Ω ) with operator norm at most C. One formulation of the Whitney extension problem for X ( R n ) asks whether X ( Ω ) admits a bounded linear extension operator for every subset Ω R n .

Let X ( R n ) = L m , p ( R n ) denote the (homogeneous) Sobolev space of all functions F : R n R whose (distributional) partial derivatives of order m belong to L p ( R n ) , equipped with the seminorm F L m , p ( R n ) = m F L p ( R n ) . We assume that n m < p < , so that functions F L m , p ( R n ) are continuous – this ensures that the trace space L m,p (Ω) is well-defined for an arbitrary subset Ω R n .

In Ref. [1], the second-named author, C. Fefferman, and G. K. Luli proved that L m,p (Ω) admits a bounded linear extension operator when p > n, with operator norm at most a constant C = C(m, n, p), for an arbitrary subset Ω R n . When p is in the range m n < p n , however, it is unknown whether such an operator exists in general.

The first nontrivial case in this range is the space X = L 2 , p ( R 2 ) for 1 < p < 2 (when p = 2, it is easy to construct a bounded linear extension operator thanks to the Hilbert space structure). In this paper, we construct a bounded linear extension operator for L 2,p (E) for a particular set E R 2 to be defined below. This set E appears to be exceptional. For a variety of sets Ω R 2 it is possible to construct a bounded linear extension operator for L 2,p (Ω) by making certain analogies with the case p > 2. Our construction for L 2,p (E), however, requires completely new ideas.

We now define the set E. We introduce a real number ɛ ∈ (0, 1/2). We assume that ɛ is smaller than some absolute constant. For an integer L ≥ 1, we define

Δ = ε L .

The set E is of the form

E = E 1 E 2 ,

where

E 1 = { ( Δ Z ) [ 1,1 ] } × { 0 } and E 2 = ( z , Δ ) : z = = 1 L s ε , s { 1 , + 1 } ,

Accordingly, E 1 is a set of equispaced Δ-separated points on the line x 2 = 0, and E 2 is a set of points of separation Δ on the line x 2 = Δ. For convenience, we assume that for every (x, Δ) ∈ E 2 we have (x, 0) ∈ E 1. We can ensure this by, e.g., taking ɛ = 1/N for a large, positive integer N.

In this paper, we prove the following theorem.

Theorem 1.

Let 1 < p < 2 and let E R 2 be the set defined above. There exists a bounded linear extension operator T : L 2 , p ( E ) L 2 , p ( R 2 ) , depending on p, satisfying

T f L 2 , p ( R 2 ) C f L 2 , p ( E ) for any f L 2 , p ( E )

for some constant C depending only on p.

We now say a bit about the construction of the operator T. We fix a square Q 0 R 2 containing E with diameter 1 . Given f : E R , we will describe how to produce a function FL 2,p (Q 0) satisfying F| E = f and having the property that

(1) F L 2 , p ( Q 0 ) C G L 2 , p ( R 2 )

for any G L 2 , p ( R 2 ) for which G| E = f. Once we accomplish this, it is not difficult to deduce Theorem 1.

We first partition the square Q 0 into a Calderón–Zygmund decomposition CZ, which is a finite family of dyadic squares QQ 0 with pairwise disjoint interiors. Briefly, every Q ∈ CZ has sidelength δ Q ≈ Δ + dist(Q, E) and satisfies #(1.1QE) ≤ 1. In particular, the smallest squares in CZ have sidelength proportional to Δ and distance to E bounded by CΔ – see Section 3 for further details. Our function FL 2,p (Q 0) takes the form

(2) F ( x ) = Q CZ θ Q ( x ) P Q ( x ) ,

where { θ Q } Q CZ is a Whitney partition of unity subordinate to CZ – more precisely, (1) ∑ Q θ Q = 1 on Q 0, (2) supp(θ Q ) ⊂ 1.1Q, and (3) | k θ Q | δ Q k for each Q ∈ CZ – and each P Q is an affine polynomial satisfying

(3) P Q = f  on  1.1 Q E .

Using (3) and the support condition on θ Q , we see that the function F will satisfy F| E = f. For each Q ∈ CZ, P Q is of the form

P Q ( x ) = L Q ( x ) + η Q x ( 2 ) for x = ( x ( 1 ) , x ( 2 ) ) R 2 ,

where η Q is a real number and L Q is an affine polynomial satisfying ∂2 L Q = 0. Due to the structure of the set E 1, our hand is essentially forced when it comes to choosing the L Q ’s – specifically, we demand that each L Q agrees with the function f at two suitably chosen points of the set E 1. The bulk of the work, then, is in choosing the numbers { η Q } Q CZ to ensure a certain natural compatibility condition on the family { P Q } Q CZ , namely, the condition:

(4) Q , Q CZ , Q Q δ Q 2 p | P Q P Q | p G L 2 , p ( R 2 ) p ,

where QQ′ denotes the property that 1.1Q ∩ 1.1Q′ ≠ ∅ for two squares Q, Q′ ∈ CZ (we say that Q “touches” Q′), and G L 2 , p ( R 2 ) is any function satisfying G| E = f. Estimate (4) is the essential ingredient in the proof of the norm bound (1) for the function F defined in (2).

Roughly speaking, each η Q corresponds to the average x (2)-partial derivative of F on the square Q. Since the value of f near points of the set E 2 is our only source of information about the x (2)-partial derivative of F, we make use of a natural hierarchical clustering C of the set E 2 to choose the η Q ’s.

Elements C C correspond to the subsets of E 2 of the form C ( s 1 , , s k ) ( z , Δ ) : z = = 1 L s ε , s k + 1 , , s L { 1 , + 1 } for fixed (s 1, …, s k ) ∈ {−1,+1} k . The smallest clusters correspond to the 2 L different singleton sets in E 2 (when k = L), and the largest cluster corresponds to C = E 2 (when k = 0). Distinct clusters are “well-separated” in the sense that dist(C 1, C 2) ≫ max{diam(C 1), diam(C 2)} for C 1 , C 2 C , C 1C 2.

The set of clusters C has the structure of a rooted binary tree of depth L. The clusters corresponding to the leaves of the tree are the singletons {z} (zE 2), and E 2 is the root of C .

To every square Q ∈ CZ, we associate a cluster C Q C . If 1.1QE 2 ≠ ∅ then Q is associated to the singleton cluster C Q = {x Q } where x Q is a point of 1.1QE 2. To every other square Q we associate a cluster C Q C that is nearby to Q.

We then introduce real numbers { η C } C C and postulate that

(5) η Q = η C Q for every Q CZ .

For each z = (z (1), Δ) ∈ E 2, we define

η { z } = f ( z ) f ( z ( 1 ) , 0 ) Δ .

This is natural, as for squares Q ∈ CZ satisfying 1.1QE 2 ≠ ∅ we will need to choose η Q = η { x Q } where x Q ∈ 1.1QE 2, to ensure that P Q satisfies (3).

Now that we have chosen ( η { z } ) z E 2 , we need to choose the remaining η C so as to establish the compatibility condition (4) for the P Q . We use the following theorem of C. Fefferman and B. Klartag, proved in [2].

Theorem 2.

(Fefferman–Klartag [2]). Consider a full, binary tree of depth N with vertices V. Let V k denote the set of vertices of depth k. For any vV k (k = 1, , N), let π(v) denote the parent of v.

Write ∂VV to denote the set of leaves of V (i.e., ∂V = V N ). Let R V and R V denote the sets of real-valued functions on V and ∂V, respectively.

Given weights w 1, …, w N > 0, define the L 1,p (V)-seminorm by

(6) Φ L 1 , p ( V ) = k = 1 N w k v V k | Φ ( π ( v ) ) Φ ( v ) | p 1 / p for any Φ R V .

Define the L 1,p trace seminorm by

ϕ L 1 , p ( V ) = inf Φ L 1 , p ( V ) : Φ | E = ϕ for any ϕ R V .

There exists a linear operator H : R V R V with the following properties:

  1. H is an extension operator, i.e.,

    H ϕ | V = ϕ for any ϕ R V .

  2. For any ϕ R V , we have

    H ϕ L 1 , p ( V ) ϕ L 1 , p ( V ) .

We apply Theorem 2 to the binary tree C equipped with a natural set of edge weights, and choose the η C by applying the extension operator H to the data { η { z } } z E 2 ; because the resulting choice of {η C } minimizes the seminorm (6), one can show the resulting polynomials {P Q } defined in terms of the {η Q } (which are related to the {η C } in (5)) will satisfy (4). As mentioned before, the norm bound (1) follows as a consequence of this condition.

Because the η {z} depend linearly on f, and the η C depend linearly on { η { z } } z E 2 , it is obvious that the P Q depend linearly on f, and so, F depends linearly on f.

It is finally trivial to extend F : Q 0 R to a function F ̃ : R 2 R satisfying F ̃ L 2 , p ( R 2 ) C F L 2 , p ( Q 0 ) and F ̃ | Q 0 = F (in particular, F ̃ | E = f ). Since FL 2,p (Q 0) is an extension of f satisfying the norm bound (1), we deduce that F ̃ L 2 , p ( R 2 ) is an extension of f satisfying F ̃ L 2 , p ( R 2 ) C G L 2 , p ( R 2 ) for any G L 2 , p ( R 2 ) with G| E = f. Thus, we can set T f = F ̃ , and T is a bounded linear extension operator for L 2,p (E).

This concludes our overview of the proof of Theorem 1.

We remark that when ɛ is bounded away from a certain “critical value” ɛ 0 = (1/2)1/(2−p), it is possible to prove Theorem 1 without invoking Theorem 2. In particular, one can construct an extension operator for L 2,p (E) by making certain analogies with the case p > 2. When ɛ = ɛ 0, however, we know of no such construction.

Throughout this paper we write C, C′, C″, … to denote positive constants. Such constants are allowed to depend only on p (but not on ɛ, L). We write C X , C X , for positive constants depending on some quantity X. For positive real numbers A, B we write AB if there exists a constant C such that ACB and A X B if AC X B. We write AB if AB and AB.

We thank Charles Fefferman, Anna Skorobogatova, and Ignacio Uriarte-Tuero, for helpful conversations. We also thank Pavel Shvartsman for suggesting that we use the Hardy–Littlewood maximal function; this greatly simplified some of the arguments. Finally, we thank the anonymous referee for helpful comments that led to the improvement of this article.

2 Preliminaries

For a (Lebesgue) measurable function F defined on a measurable set S R 2 with |S| > 0, we write (F) S ≔ |S|−1 S F dx. We begin by stating a couple of standard inequalities for Sobolev spaces. For details see, e.g., [3].

Given an annulus A = x R 2 : r | x x 0 | R with inner radius r and outer radius R, the thickness ratio of A is defined to be the quantity R/r.

Lemma 1.

Let Ω R 2 be a square, a ball, or an annulus with thickness ratio at most C 0 ∈ [1, ∞). Then the following hold.

  1. Let 1 < r < 2, and r′ = 2r/(2 − r). Then for any F L 2 , r ( R 2 ) we have

    Ω | F ( x ) ( F ) Ω | r d x 1 / r r , C 0 F L 2 , r ( Ω ) .

  2. Let q > 2. Then for any FL 1,q (Ω) we have (after potentially redefining F on a set of measure 0) that

    | F ( x ) F ( y ) | q , C 0 | x y | 1 2 / q F L 1 , q ( Ω ) for any x , y Ω .

We use these inequalities to prove the following basic lemma.

Lemma 2.

Let Ω R 2 be a square, a ball, or an annulus with thickness ratio at most C 0 ∈ [1, ∞) and let 1 < r < 2. For any FL 2,r (Ω) and any x ∈ Ω, we define a function T x , Ω ( F ) : R 2 R by

T x , Ω ( F ) ( y ) = F ( x ) + ( F ) Ω ( y x ) .

We then have, for any y R 2 , that

| T x , Ω ( F ) ( y ) T z , Ω ( F ) ( y ) | r , C 0 F L 2 , r ( Ω ) | x z | 2 2 / r for any x , z Ω .

In particular,

F T x , Ω ( F ) L ( Ω ) r , C 0 d i a m ( Ω ) 2 2 / r F L 2 , r ( Ω ) .

Proof.

Let r′ = 2r/(2 − r). For any y R 2 define G y : Ω R by

G y ( x ) = T x , Ω ( F ) ( y ) .

By Part 1 of Lemma 1, we have

G y L 1 , r ( Ω ) r , C 0 F L 2 , r ( Ω ) .

Note that r′ > 2, since r < 2. Applying Part 2 of Lemma 1 to the function G y proves the lemma. □

Let B(z, r) denote the ball of radius r > 0 centered at z R 2 , and let M denote the uncentered Hardy–Littlewood maximal operator, i.e.,

( M f ) ( x ) = sup B ( z , r ) x 1 | B ( z , r ) | B ( z , r ) f ( y ) d y for any f L loc 1 ( R 2 ) .

Recall that M is a bounded operator from L q ( R 2 ) to L q ( R 2 ) for any 1 < q ≤ ∞ (see, e.g., [4]).

3 The CZ decomposition

We will work with squares in R 2 ; by this we mean an axis parallel square of the form Q = [a 1, b 1) × [a 2, b 2). We let δ Q denote the sidelength of such a square Q. To bisect a square Q is to partition Q into squares Q 1, Q 2, Q 3, Q 4, where δ Q i = δ Q / 2 for each i = 1, 2, 3, 4. We refer to the Q i as the children of Q.

We define a square Q 0 = [−4, 4) × [−4, 4); note that EQ 0. A dyadic square Q is one that arises from repeated bisection of Q 0. Every dyadic square QQ 0 is the child of some square Q′; we call Q′ the parent of Q and denote this by (Q)+ = Q′.

We say that two dyadic square Q, Qtouch if (1.1Q ∩ 1.1Q′) ≠ ∅. We write QQ′ to denote that Q touches Q′.

For any dyadic square Q, we define a collection CZ(Q), called the CalderónZygmund decomposition of Q, by setting

CZ ( Q ) = { Q } if  # ( 3 Q E ) 1 ,

and

CZ ( Q ) = { CZ ( Q ) : ( Q ) + = Q } if # ( 3 Q E ) 2 .

We write CZ = CZ(Q 0). Note that CZ ≠ {Q 0} because #(3Q 0E) = #E ≥ 2. Then CZ is a partition of Q 0 into dyadic squares Q satisfying

(7) δ Q Δ 9 .

To see this, observe that for any Q ∈ CZ we have #(3Q +E) ≥ 2 and 3Q + ⊂ 9Q. Since points of E are Δ-separated, we have δ Q ≥Δ/9, as claimed.

We now summarize some basic properties of the collection CZ.

Lemma 3.

The collection CZ has the following properties:

  1. For any Q ∈ CZ, we have #(1.1QE) ≤ 1 and #(3Q +E) ≥ 2.

  2. For any Q, Q′ ∈ CZ with QQ′, we have 1 2 δ Q δ Q 2 δ Q .

  3. For any Q ∈ CZ, we have

    # { Q : Q Q } 1 .

  4. For any x R 2 ,

    # { Q C Z : x 1.1 Q } 1 .

  5. For any Q ∈ CZ with #(1.1QE) = 0, we have δ Q ≈ dist(Q, E).

We omit the proof of Lemma 3, as this type of decomposition is standard in the literature; see, e.g., [5].

We say that Q ∈ CZ is a boundary square if 1.1Q ∩ ∂Q 0 ≠ ∅. Denote the set of boundary squares by ∂CZ.

Observe that every Q ∈ ∂CZ satisfies δ Q ≥ 1. Indeed, this follows because E ⊂ [−1, 1] × [−1, 1], and if Q is a dyadic square intersecting the boundary of Q 0 with δ Q = 1 then 3Q is disjoint from E. We denote z 0 ≔ (−1, 0), w 0 ≔ (1, 0) to be the points of maximal separation in E 1. Note that

(8) z 0 , w 0 50 Q  for all  Q CZ .

We say that a square Q ∈ CZ is of Type I if #(1.1QE 1) = 1, Type II if #(1.1QE 2) = 1, and Type III if #(1.1QE) = 0. We denote the collection of squares of Type I, II, and III by CZI, CZII, and CZIII, respectively. These collections form a partition of CZ because #(3QE) ≤ 1 for any Q ∈ CZ by construction.

Observe that ∂CZ ⊂ CZIII.

From Property 1 of Lemma 3, it is easy to deduce that

(9) δ Q Δ for every Q CZ I CZ II .

From Property 5 of Lemma 3 we have

δ Q dist ( Q , E ) for every Q CZ III .

Combining this with (7), and using that points of E are Δ-separated, we get

δ Q dist ( Q , E 1 ) for every Q CZ III .

Combining this with (7) and (9) gives

(10) δ Q ( Δ + dist ( Q , E 1 ) ) for any Q CZ .

For each Q ∈ CZII we let x Q be the unique point in (1.1Q) ∩ E = (1.1Q) ∩ E 2. Note that x Q is undefined for Q ∈ CZ\CZII.

For each Q ∈ CZ we associate a pair of points z Q , w Q E 1. We list the key properties of these points in the next lemma.

Lemma 4.

For each Q ∈ CZ there exist points z Q , w Q ∈ (50Q) ∩ E 1, satisfying the conditions below.

  1. |z Q w Q | ≈ δ Q .

  2. If Q ∈ CZI then z Q ∈ (1.1Q) ∩ E 1.

  3. If Q ∈ CZII then z Q = ( x Q ( 1 ) , 0 ) , where x Q = ( x Q ( 1 ) , Δ ) is the unique point in 1.1QE 2.

  4. If Q ∈ ∂CZ then z Q = z 0 and w Q = w 0.

Proof.

We first check that for each Q ∈ CZ there exist points z Q , w Q ∈ (50Q) ∩ E 1 satisfying |z Q w Q | ≈ δ Q . Fix Q ∈ CZ. By definition of the Calderón–Zygmund stopping rule, the set 3Q +E is nonempty; also, 3Q + ⊂ 9Q by properties of dyadic squares, so 9QE is nonempty. Thus, either 9QE 1 ≠ ∅ or 9QE 2 ≠ ∅. We claim that 30QE 1 is nonempty in either case. This is true if 9QE 1 ≠ ∅. On the other hand if 9QE 2 ≠ ∅, we let y Q be a point of 9QE 2, and note that dist(y Q , E 1) = Δ ≤ 9δ Q , hence, (30Q) ∩ E 1 ≠ ∅. In any case, we have shown (30Q) ∩ E 1 ≠ ∅. Once that is established, by the definition of E 1 as a sequence of Δ-separated points and because 9δ Q ≥Δ, we see that 50QE 1 contains at least two points. Thus, we can order the points of ( 50 Q ) E 1 R × { 0 } according to the order on the real number line and let z Q and w Q be the distinct minimal and maximal points in the set (50Q) ∩ E 1. Obviously then |z Q w Q | ≈ δ Q .

We make small modifications to the construction to establish conditions 2–4 of the lemma.

If Q ∈ CZI then we instead select z Q ∈ (1.1)QE 1 and then let w Q E 1 be adjacent to z Q so that |z Q w Q | = Δ ≈ δ Q . Since 9δ Q ≥Δ, it follows that w Q ∈ 50Q, so w Q ∈ 50QE 1, as desired.

If Q ∈ CZII then we instead choose z Q E 1 to be the point directly below x Q ∈ (1.1Q) ∩ E 2 so that |z Q x Q | = Δ. We then let w Q E 1 be a point adjacent to z Q , so that |w Q z Q | = Δ ≈ δ Q . As before, since x Q ∈ 1.1Q and 9δ Q ≥Δ, we see that z Q , w Q ∈ 50Q, as desired.

If Q ∈ ∂CZ then we define z Q = z 0 and w Q = w 0, where z 0 = (−1, 0) and w 0 = (1, 0). Note that |z Q w Q | ≈ 1 ≈ δ Q . Before we established that z 0, w 0 ∈ 50Q, so, in particular, z Q , w Q ∈ 50QE 1, as desired. □

4 Constructing the interpolant

Let f : E R . In this section, we will construct a function F : Q 0 R satisfying F| E = f.

Let { θ Q } Q CZ be a partition of unity subordinate to CZ constructed so that the following properties hold. For any Q ∈ CZ, we have:

  • (POU1) supp(θ Q ) ⊂ 1.1Q.

  • (POU2) For any |α| ≤ 2, α θ Q L δ Q | α | .

  • (POU3) 0 ≤ θ Q ≤ 1.

    For any xQ 0, we have

  • (POU4) Q∈CZ θ Q (x) = 1.

Our interpolant F will then be of the form

(11) F = Q CZ P Q θ Q ,

where each P Q is an affine polynomial on R 2 of the form

P Q ( x ) = L Q ( x ) + η Q x ( 2 ) for x = ( x ( 1 ) , x ( 2 ) ) R 2 .

Here, L Q is an affine polynomial satisfying ∂2 L Q = 0 and η Q is a real number.

In the previous section we have associated to each square Q ∈ CZ the points z Q , w Q E 1. We now define L Q to be the unique affine polynomial satisfying:

(12) L Q | { z Q , w Q } = f | { z Q , w Q }  and  2 L Q = 0 .

Thanks to Property 4 of Lemma 4 there exists an affine polynomial L 0 for which

L Q = L 0 for all Q CZ .

We will choose the η Q later in Sections 6 and 7.

We now compute a simple upper bound for the L 2,p -seminorm of F.

Lemma 5.

(The Patching Lemma). The function F satisfies

F L 2 , p ( Q 0 ) p Q , Q CZ : Q Q L Q L Q L ( Q ) p δ Q 2 2 p + | η Q η Q | p δ Q 2 p .

Proof.

Fix a square Q′ ∈ CZ. Observe that

F ( x ) = Q CZ θ Q ( x ) P Q ( x ) P Q ( x ) + P Q ( x ) .

By Property 4 of Lemma 3, there are a bounded number of squares Q ∈ CZ for which x ∈ (1.1Q) ∩ Q′. Therefore, by (POU1), there are a bounded number of Q ∈ CZ with supp(θ Q ) ∩ Q′ ≠ ∅. Taking 2nd derivatives, using (POU2), and integrating pth powers then gives

F L 2 , p ( Q ) p Q CZ : Q Q δ Q 2 2 p P Q P Q L ( Q ) p + δ Q 2 p | P Q P Q | .

For any affine polynomial P we have | P | δ Q 1 P L ( Q ) , and thus

F L 2 , p ( Q ) p Q CZ : Q Q δ Q 2 2 p P Q P Q L ( Q ) p .

By the triangle inequality, and the fact that |z (2)| ≤ Q whenever z ∈ 1.1Q,

P Q P Q L ( Q ) L Q L Q L ( Q ) + | η Q η Q | z ( 2 ) L ( Q ) L Q L Q L ( Q ) + | η Q η Q | δ Q .

Therefore,

F L 2 , p ( Q ) p Q CZ : Q Q δ Q 2 2 p L Q L Q L ( Q ) p + δ Q 2 p | η Q η Q | p .

Since CZ is partition of Q 0, summing over Q′ ∈ CZ proves the lemma. □

5 Establishing compatibility of the L Q

In this section we will prove that for any function G L 2 , p ( R 2 ) with G| E = f we have

(13) Q , Q CZ : Q Q L Q L Q L ( Q ) p δ Q 2 2 p G L 2 , p ( R 2 ) p .

Fix some r satisfying 1 < r < p. We claim that for any Q, Q′ ∈ CZ with QQ′ we have

(14) L Q L Q L ( Q ) r δ Q 2 r 2 G L 2 , r ( 250 Q ) r .

Observe that for any xQ we have

L Q ( x ) L Q ( x ) = f ( z Q ) + ( L Q ) ( x z Q ) f ( z Q ) L Q x z Q .

Since G z Q = f ( z Q ) , and since z Q ( 2 ) = z Q ( 2 ) = 0 , we have

T z Q , 250 Q ( G ) ( z Q ) = f ( z Q ) + ( 1 G ) 250 Q ( z Q ( 1 ) z Q ( 1 ) ) .

Therefore, since ∂2 L Q = ∂2 L Q = 0, we have

L Q L Q L ( Q ) | f ( z Q ) T z Q , 250 Q ( G ) ( z Q ) | + | ( 1 G ) 250 Q 1 L Q | δ Q + | ( 1 G ) 250 Q 1 L Q | δ Q .

Recall that for any Q, Q′ ∈ CZ with QQ′ we have 1 2 δ Q δ Q 2 δ Q (see Lemma 3), and therefore 50Q′ ⊂ 250Q. In particular, we have

z Q , w Q , z Q , w Q ( 250 Q ) E 1 .

Since G| E = f, Lemma 2 then implies

| f ( z Q ) T z Q , 250 Q ( G ) ( z Q ) | δ Q 2 2 / r G L 2 , r ( 250 Q ) , | f ( z Q ) f ( w Q ) ( 1 G ) 250 Q ( z Q ( 1 ) w Q ( 1 ) ) | δ Q 2 2 / r G L 2 , r ( 250 Q ) , | f ( z Q ) f ( w Q ) ( 1 G ) 250 Q ( z Q ( 1 ) w Q ( 1 ) ) | δ Q 2 2 / r G L 2 , r ( 250 Q ) ;

we deduce (14).

The inequality (14) implies that

L Q L Q L ( Q ) r δ Q 2 r M ( | 2 G | r ) ( z ) for any z Q ,

where M is the Hardy–Littlewood maximal operator (see Section 2). Taking (p/r)th powers and integrating gives

L Q L Q L ( Q ) p δ Q 2 p 2 M ( | 2 G | r ) L p / r ( Q ) p / r .

By Properties 2 and 3 of Lemma 3, we deduce

Q , Q CZ : Q Q L Q L Q L ( Q ) p δ Q 2 2 p Q CZ M ( | 2 G | r ) L p / r ( Q ) p / r .

Since CZ is a pairwise disjoint collection of squares, we have

Q CZ M ( | 2 G | r ) L p / r ( Q ) p / r M ( | 2 G | r ) L p / r ( R 2 ) p / r .

We use the boundedness of the Hardy–Littlewood maximal operator from L q to L q for 1 < q ≤ ∞ to deduce (13).

6 Step I of choosing the η Q : clustering

For each 0 ≤ L and fixed s = ( s 1 , , s ) { 1 , + 1 } we define a set C ( s ) ( z , Δ ) : z = k = 1 L s k ε k , s + 1 , , s L { 1 , + 1 } E 2 . We refer to C ( s ) as a cluster of E 2 at depth . (By convention, in the edge case = 0, s 0 is the empty list and C ( s 0 ) = E 2 .) Note that the clusters of depth L are singletons.

Accordingly, for fixed there are 2 distinct clusters of E 2 of depth . The convex hulls of distinct clusters are disjoint (assuming ɛ ≤ 1/2), and thus, the clusters of depth inherit an order from the real number line. We shall order the clusters of E 2 of depth by C 1 , C 2 , …, C 2 – the following properties are apparent:

  1. # C i = 2 L ,

  2. d i a m C i ε + 1 (for = 0, …, L − 1), and

  3. C i i = 1 2 is a partition of E 2.

We write C C i i = 1 2 to denote the set of all clusters of E 2 of depth . We then define the set of all clusters

C = = 0 L C .

The set of all clusters forms a full, binary tree via the relation of set inclusion, with clusters of depth corresponding to vertices of depth . Any C C with ≥ 1 therefore has a unique parent cluster π ( C ) C 1 .

To every cluster C C for = 0, …, L − 1 we associate a ball B C and to every cluster C C for = 1, …, L − 1 we associate a ball B ̂ C . For convenience, we’ll assume that B C , B ̂ C are centered at the same point and that radius ( B ̂ C ) = 1 0 M + 1 radius ( B C ) for a positive integer M (independent of the cluster C). We require these balls to satisfy the following properties:

  1. For every C C ( = 0, …, L − 1), we have

    1. diam(B C ) ≈ diam(C) ≈ ɛ +1, and

    2. CB C .

  2. For every C C ( = 1, …, L − 1), we have

    1. d i a m ( B ̂ C ) d i a m ( π ( C ) ) ε , and

    2. B C B ̂ C B π ( C ) .

  3. For distinct clusters C , C C , we have

    1. dist(B C , B C) > ( = 0, …, L − 1), and

    2. dist ( B ̂ C , B ̂ C ) > c ε ( = 1, …, L − 1).

We remark that (after taking ɛ smaller than some absolute constant) the last bullet point implies that, for fixed , each of the families { B C } C C and { B ̂ C } C C is pairwise disjoint.

Given f : E R , for each x = (x (1), Δ) ∈ E 2 we define

(15) η x = f ( x ) f ( x ( 1 ) , 0 ) Δ .

For each Q ∈ CZII there is a single point in (1.1QE 2), denoted by x Q . We then define

(16) η Q = η x Q for every Q CZ II .

To any square Q ∈ CZ we associate a cluster C Q as follows. If Q ∈ CZ\CZII, then we define C Q to be equal to the cluster C C ( = 0, 1, …, L − 1) of smallest diameter for which QB C if such a cluster exists and equal to E 2 (recall that E 2 is the unique cluster of depth 0) if no such cluster exists. If Q ∈ CZII, then we set C Q = { x Q } C L , where x Q is the unique point in 1.1QE 2. Observe that for all Q ∈ ∂CZ we have C Q = E 2.

Observe that C Q C L if and only if 1.1QE 2 ≠ ∅. In particular, if 1.1QE 2 = ∅ then C Q C ( = 0, …, L − 1) has cardinality at least 2.

For each cluster C C we introduce a real number η C . Recall that every cluster C C L satisfies #(C) = 1; we let x C denote the unique point in C. We then define

(17) η C = η x C for every C C L .

(Recall that η x is defined by (15).) We defer choosing { η C } C C for = 0, …, L − 1 until Section 7.

We determine the η Q in terms of the {η C } by specifying that

(18) η Q = η C Q for all Q CZ .

According to the above definitions, we have

η Q = η C Q = η x Q  for all  Q CZ II ,

where C Q = {x Q } = 1.1QE 2. From this property, observe that, independently of how we choose the remaining η Q , the function F satisfies

F | E = f ,

as claimed.

We now work to bound the expression

Q , Q CZ Q Q | η Q η Q | p δ Q 2 p

appearing on the right-hand side of the patching lemma (Lemma 5).

Note that any distinct Q, Q′ ∈ CZ with QQ′ for which η Q η Q necessarily satisfy either (1), C Q = π C Q , (2) C Q = π(C Q ), or (3) C Q , C Q C L , C Q C Q and π ( C Q ) = π C Q . Therefore,

(19) Q Q | η Q η Q | p δ Q 2 p = 1 L C C | η π ( C ) η C | p ( Q , Q ) Q C δ Q 2 p + C , C C L : π ( C ) = π ( C ) | η C η C | p Q , Q CZ C Q = C , C Q = C δ Q 2 p ,

where Q C is defined for C C ( = 1, …, L) by

Q C ( Q , Q ) CZ × CZ : Q Q , C Q = C , C Q = π ( C ) .

We first bound the second sum on the right-hand side of (19). Note that for C C L there are a bounded number of Q ∈ CZ with C Q = C (any such Q satisfies that 1.1QE 2 = {x Q } = C). For any such Q, it holds that δ Q ≈ Δ = ɛ L . Similarly, for C C L there are a bounded number of Q′ ∈ CZ with C Q = C′. If π(C) = π(C′) then we can use the triangle inequality to estimate |η C η C| ≤ |η C η π(C)| + |η Cη π(C′)|. Thus,

(20) C , C C L : π ( C ) = π ( C ) | η C η C | p Q , Q CZ C Q = C , C Q = C δ Q 2 p ε L ( 2 p ) C C L | η C η π ( C ) | p .

Note that for any cluster C C , = 1, …, L − 1, we have

(21) Δ / 9 δ Q c ε + 1 for any Q CZ for which C Q = C .

Indeed, see (7), and note that if Q and C are as above then QB C and so δ Q ≤ diam(B C ) ≈ ɛ +1.

Observe that # Q C 1 for any C C L , simply because there are at most a bounded number of squares Q with C Q = C (any such square satisfies 1.1QE = C Q ), and each of these squares Q touches a bounded number of squares Q′. Since any Q with C Q = C for C C L satisfies δ Q ≈ Δ = ɛ L , we get

(22) ( Q , Q ) Q C δ Q 2 p ε L ( 2 p ) for any C C L .

Now fix C C for = 1, …, L − 1. We claim that

(23) # ( Q , Q ) Q C : δ Q = δ 1 for every δ > 0 .

Suppose ( Q , Q ) Q C with δ Q = δ. Then, since QB C , Q′⊄B C , and QQ′, it must be the case that Q, Q′ are contained in a Q -neighborhood of the boundary of B C for some absolute constant c. By (10), it is also the case that Q, Q′ are at most distance cδ Q from the x (1)-axis for another absolute constant c′. Here, δ Q = δ is fixed. A simple packing argument then yields (23). Combining (21) and (23), we show that

(24) ( Q , Q ) Q C δ Q 2 p k log 2 ( c ε + 1 ) ( Q , Q ) Q C , δ Q = 2 k ( 2 k ) 2 p k log 2 ( c ε + 1 ) 2 k ( 2 p ) ε ( + 1 ) ( 2 p ) ( C C , = 1 , , L 1 ) .

(Note that we’ve used the assumption (2 − p) > 0.)

Combining (20) with (22) and (24), allows us to continue the bound in (19),

(25) Q Q | η Q η Q | p δ Q 2 p = 1 L 1 ε ( + 1 ) ( 2 p ) C C | η π ( C ) η C | p + ε L ( 2 p ) C C L | η π ( C ) η C | p .

For = 1, …, L we define

(26) ν = ε ( + 1 ) ( 2 p ) for = 1 , , L 1 , ε L ( 2 p ) for = L .

We then rewrite inequality (25) as

(27) Q Q | η Q η Q | p δ Q 2 p = 1 L ν C C | η π ( C ) η C | p .

In the next section we will choose the remaining η C (for C C with = 0, 1, …, L − 1) and prove that our choices satisfy suitable estimates. Finally, in the last section we will explain how to use those estimates to complete the proof of Theorem 1.

7 Step II of choosing the η Q : minimizing F L 2 , p

Recall that we have already defined η C for C C L in (17).

The goal of this section is to choose η C for each C C ( = 0, 1, …, L − 1) so that for any G L 2 , p ( R 2 ) with G| E = f we have

(28) = 1 L ν C C | η π ( C ) η C | p G L 2 , p ( R 2 ) p .

This is easy to do, thanks to Theorem 2. Recall ν are defined in (26).

The following is an immediate corollary of Theorem 2.

Corollary 1.

There exist η C for each C C ( = 1, …, L − 1), depending linearly on { η C } C C L , so that the following holds. Let { γ C } C C be a collection of real numbers with γ C = η C for each C C L . Then

= 1 L ν C C | η π ( C ) η C | p = 1 L ν C C | γ π ( C ) γ C | p .

We fix the definition of { η C } C C as in Corollary 1. Recall that { η C } C C L depend linearly on the data f – see (15) and (17). Thus, η C depends linearly on f for each C C .

We claim that for any G L 2 , p ( R 2 ) with G| E = f we have

(29) = 1 L 1 ε ( + 1 ) ( 2 p ) C C | ( 2 G ) B π ( C ) ( 2 G ) B C | p G L 2 , p ( R 2 ) p .

We will later show that (29) and Corollary 1 allow us to deduce estimate (28) for the { η C } C C , completing the task of this section.

For every C C , = 1, …, L − 1, let r C , x C denote the radius and center, respectively, of the ball B C . For k ≥ 0 define the annulus

A C , k = x R 2 : 1 0 k r C | x x C | < 1 0 k + 1 r C .

Recall (see Section 6) that B ̂ C is also centered at x C and that

radius ( B ̂ C ) = 1 0 M + 1 r C .

for some positive integer M. Define another annulus

A C = k = 0 M A C , k .

Note that the collection of annuli { A C } C C , = 1 , L 1 is pairwise disjoint.

We claim that for any 1 < r < p and for every C C ( = 1, …, L − 1) we have

(30) | ( 2 G ) B π ( C ) ( 2 G ) B C | p ε ( + 1 ) ( 2 p ) M ( | 2 G | r ) L p / r ( A C ) p / r .

Since the A C are pairwise disjoint, (30) implies

= 1 L 1 ε ( + 1 ) ( 2 p ) C C | ( 2 G ) B π ( C ) ( 2 G ) B C | p M ( | 2 G | r ) L p / r ( R 2 ) p / r ;

we use the boundedness of the Hardy–Littlewood maximal operator from L p/r to L p/r to deduce (29).

To prove (30), use Lemma 2 to get

| ( 2 G ) B C ( 2 G ) A C , 0 | ε ( + 1 ) ( 1 2 / r ) G L 2 , r ( B C A C , 0 ) ε + 1 M ( | 2 G | r ( z ) ) 1 / r

for any zA C,0. (Recall that r C ɛ +1.) Taking pth powers and integrating over A C,0, we get

| ( 2 G ) B C ( 2 G ) A C , 0 | p ε ( + 1 ) ( 2 p ) M ( | 2 G | r ) L p / r ( A C , 0 ) p / r .

Similarly, we can show

| ( 2 G ) A C , k ( 2 G ) A C , k + 1 | p ε ( + 1 ) ( 2 p ) 1 0 k ( p 2 ) M ( | 2 G | r ) L p / r ( A C , k ) p / r , | ( 2 G ) B π ( C ) ( 2 G ) A C , M | p ε ( + 1 ) ( 2 p ) 1 0 M ( p 2 ) M ( | 2 G | r ) L p / r ( A C , M ) p / r .

We apply the triangle inequality and use that p < 2 to get

| ( 2 G ) B C ( 2 G ) B π ( C ) | ε ( + 1 ) ( 2 / p 1 ) M ( | 2 G | r ) L p / r ( A C ) 1 / r k = 0 M 1 0 k ( 1 2 / p ) M ( | 2 G | r ) L p / r ( A C ) 1 / r ,

proving (30), and thus, proving (29).

We now explain how to prove (28). We fix G L 2 , p ( R 2 ) with G| E = f and define ( γ C ) C C in terms of G and ( η C ) C C . We take γ C = ( 2 G ) B C if C C for = 0, …, L − 1 and γ C = η C if C C L . Now, we apply Corollary 1 to deduce that

(31) = 1 L ν C C | η π ( C ) η C | p = 1 L 1 ε ( + 1 ) ( 2 p ) C C | ( 2 G ) B π ( C ) ( 2 G ) B C | p + ε L ( 2 p ) C C L | ( 2 G ) B π ( C ) η C | p .

Let C C L . Observe that η C = η x C = f ( x C ) f ( x C ( 1 ) , 0 ) Δ = G ( x C ) G ( x C ( 1 ) , 0 ) Δ . By Lemma 2, we easily get that

| ( 2 G ) B π ( C ) η C | p ε L ( 2 p ) G L 2 , p ( B π ( C ) ) p for any C C L .

The collection of balls { B π ( C ) } C C L has bounded overlap, so

ε L ( 2 p ) C C L | ( 2 G ) B π ( C ) η C | p G L 2 , p ( R 2 ) p .

Combining this estimate with (29) and (31), we complete the proof of (28).

8 Proof of main theorem

Combining Lemma 5 and the inequalities (13), (27), and (28) proves the following lemma.

Lemma 6.

Let { η C } C C be defined via (17) and Corollary 1, and let { η Q } Q CZ be defined in terms of { η C } C C in (18). Then the function FL 2,p (Q 0) defined by (11) satisfies:

  1. F| E = f

  2. For any G L 2 , p ( R 2 ) with G| E = f, we have

    F L 2 , p ( Q 0 ) G L 2 , p ( R 2 ) .

It is easy to deduce Theorem 1 from Lemma 6. Recall that there is some affine polynomial L 0 such that

L Q = L 0 for every Q CZ .

Similarly, recall that for every Q ∈ ∂CZ we have C Q = E 2. Writing η 0 = η E 2 , we thus have

η Q = η 0 for every Q CZ .

We define a function F ̃ : R 2 R by setting

F ̃ ( x ) = F ( x ) if  x Q 0 , L 0 ( x ) + η 0 x ( 2 ) if  x Q 0 .

Clearly, F ̃ | E = f and F ̃ L 2 , p ( R 2 ) = F L 2 , p ( Q 0 ) . This proves Theorem 1.


Corresponding author: Jacob Carruth, Mathematics Department, Princeton University, Fine Hall, Washington Road, Princeton, NJ, 08544, USA, E-mail: 

Dedicated to Robert Fefferman, with admiration.

This work was supported by AFOSR grant FA9550-19-1-0005.


  1. Research ethics: Not applicable.

  2. Author contributions: The authors have accepted responsibility for the entire content of this manuscript and approved its submission.

  3. Competing interests: The authors state no conflict of interest.

  4. Research funding: Supported by AFOSR grant FA9550-19-1-0005.

  5. Data availability: Not applicable.

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Received: 2024-01-19
Accepted: 2024-01-26
Published Online: 2024-05-31

© 2024 the author(s), published by De Gruyter, Berlin/Boston

This work is licensed under the Creative Commons Attribution 4.0 International License.

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