Home Mathematics Multiple concentrating solutions for a fractional (p, q)-Choquard equation
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Multiple concentrating solutions for a fractional (p, q)-Choquard equation

  • Vincenzo Ambrosio EMAIL logo
Published/Copyright: April 5, 2024

Abstract

We focus on the following fractional (p, q)-Choquard problem: ( Δ ) p s u + ( Δ ) q s u + V ( ε x ) ( | u | p 2 u + | u | q 2 u ) = 1 | x | μ * F ( u ) f ( u )  in  R N , u W s , p ( R N ) W s , q ( R N ) , u > 0  in  R N , where ɛ > 0 is a small parameter, 0 < s < 1, 1 < p < q < N s , 0 < μ < sp, ( Δ ) r s , with r ∈ {p, q}, is the fractional r-Laplacian operator, V : R N R is a positive continuous potential satisfying a local condition, f : R R is a continuous nonlinearity with subcritical growth at infinity and F ( t ) = 0 t f ( τ ) d τ . Applying suitable variational and topological methods, we relate the number of solutions with the topology of the set where the potential V attains its minimum value.

2010 Mathematics Subject Classification: 35A15; 35B38; 35J60; 35R11; 45K05; 58E05

1 Introduction

In this paper, we are concerned with the multiplicity and concentration behavior of solutions for the following fractional (p, q)-Choquard problem:

(1.1) ( Δ ) p s u + ( Δ ) q s u + V ( ε x ) ( | u | p 2 u + | u | q 2 u ) = 1 | x | μ * F ( u ) f ( u )  in  R N , u W s , p ( R N ) W s , q ( R N ) , u > 0  in  R N ,

where ɛ > 0 is a small parameter, 0 < s < 1, 1 < p < q < N s and 0 < μ < sp. We assume that the potential V C ( R N , R ) satisfies the following conditions:

  1. there exists V 0 > 0 such that V 0 = inf x R N V ( x ) ,

  2. there exists an open bounded set Λ R N such that

    V 0 < min Λ V  and  0 M = { x Λ : V ( x ) = V 0 } ,

    and that the nonlinearity f C ( R , R ) fulfills the following hypotheses:

  3. lim | t | 0 | f ( t ) | | t | q 1 = 0 ,

  4. there exists σ q , q ( N μ ) N s q such that

    lim | t | | f ( t ) | | t | σ 1 = 0 ,

  5. for ϑ = 2q we have 0 < ϑ F ( t ) 2 f ( t ) t for all t > 0, where F ( t ) = 0 t f ( τ ) d τ ,

  6. the function t ( 0 , ) f ( t ) t q 1 is increasing.

Since we look for positive solutions to (1.1), we suppose that f(t) = 0 for t ≤ 0.

For r ∈ {p, q}, the operator ( Δ ) r s denotes the fractional r-Laplacian operator defined, up to a normalization constant, by setting

( Δ ) r s u ( x ) = 2 lim ϵ 0 B ϵ c ( x ) | u ( x ) u ( y ) | r 2 ( u ( x ) u ( y ) ) | x y | N + s r d y ( x R N ) ,

for every u C c ( R N ) . We stress that fractional and nonlocal operators are currently studied in the literature due to their application in several contexts such as, for instance, optimization, finance, crystal dislocations, phase transitions, conservation laws, quasi geostrophic flows, ultrarelativistic limits of quantum mechanics, material science, and water waves; see Refs. [1], [2] for more details. We notice that the fractional (p, q)-Laplacian operator ( Δ ) p s + ( Δ ) q s in (1.1) is nonhomogeneous in the sense that does not exist any υ R such that

( Δ ) p s + ( Δ ) q s ( t u ) = t υ ( Δ ) p s + ( Δ ) q s ( u )  for all  t > 0 .

As s → 1, the fractional (p, q)-Laplacian operator reduces to the (p, q)-Laplacian operator −Δ p − Δ q , which appears in the study of reaction-diffusion problems arising in biophysics, plasma physics, and chemical reaction design; see Ref. [3]. More precisely, the prototype for these problems can be written in the form

(1.2) u t = div [ D ( u ) u ] + c ( x , u ) , D ( u ) = | u | p 2 + | u | q 2 .

In this context, the function u in (1.2) denotes a concentration, div[D(u)∇u] represents the diffusion with diffusion coefficient D(u), and c(x, u) corresponds to the reaction term related to source and loss processes. On the other hand, the functional associated with the (p, q)-Laplacian operator falls in the realm of the following double-phase functional

F p , q ( u ; Ω ) = Ω ( | u | p + a ( x ) | u | q ) d x ,

where 0 ≤ a(x) ∈ L (Ω), which was introduced by Zhikov [4], [5] to describe the behavior of strongly anisotropic materials in the context of homogenization phenomena. We also recall that, from a regularity point of view, F p , q belongs to the class of nonuniformly elliptic functionals with nonstandard growth conditions of (p, q)-type, according to Marcellini’s terminology; see Ref. [6]. For more details on (p, q)-Laplacian problems, we refer the interested reader to Refs. [7]–[13] and the references therein.

When s ∈ (0, 1) and p = q, after rescaling and up to a multiplicative constant, Equation (1.1) boils down to the following nonlinear fractional p-Choquard equation

(1.3) ε s p ( Δ ) p s u + V ( x ) | u | p 2 u = 1 | x | μ * F ( u ) f ( u )  in  R N ,

for which different existence and multiplicity results have been achieved by means of appropriate variational and topological methods; see Refs. [14], [15], [16], [17], [18], [19], [20]. In particular, in Ref. [14] the author examined the multiplicity and concentration of solutions for (1.3) with p = 2, V fulfilling (V 1)–(V 2) and f is a subcritical continuous nonlinearity, whereas in Ref. [15] the author provided a multiplicity result for (1.3) with p ∈ (1, ∞) and requiring that the potential V satisfies the following global condition due to Rabinowitz [21]:

(1.4) lim inf | x | V ( x ) > inf x R N V ( x ) > 0 .

We observe that as s → 1, (1.3) becomes the well-known quasilinear Choquard equation

(1.5) ε p Δ p u + V ( x ) | u | p 2 u = 1 | x | μ * F ( u ) f ( u )  in  R N ,

which has been investigated in Refs. [22], [23], [24]. We remark that in Ref. [24] the authors obtained multiple concentrating solutions to (1.5) by assuming (V 1)–(V 2) and considering C 1 subcritical nonlinearities. We note that when N = 3, p = 2, V = μ = ɛ = 1 and F ( t ) = t 2 2 , (1.5) is the so-called Choquard–Pekar equation

(1.6) Δ u + u = 1 | x | * u 2 2 u  in  R 3 ,

which goes back to the description of the quantum theory of a polaron at rest by Pekar in 1954 [25] and which reemerged in 1976 in the work of Choquard on the modeling of an electron trapped in its own hole, in a certain approximation to Hartree–Fock theory of one-component plasma [26]. Equation (1.6) was also proposed in 1996 by Penrose as a model of self-gravitating matter and is known in that context as the Schrödinger–Newton equation [27]. For more details on the Choquard equation, one can see Refs. [28], [29], [30], [31], [32], [33] and the references therein.

For what concerns fractional (p, q)-Laplacian problems, some intriguing existence and multiplicity results appeared in the last years; see Refs. [34], [35], [36], [37], [38], [39], [40], [41]. In particular, for (1.1) in the absence of the convolution term, that is

( Δ ) p s u + ( Δ ) q s u + V ( ε x ) ( | u | p 2 u + | u | q 2 u ) = f ( u )  in  R N ,

the authors in Refs. [37], [38] combined variational methods and the Ljusternik–Schnirelmann category theory to get multiple solutions whenever ɛ > 0 is sufficiently small, under conditions (1.4) in Ref. [37] and (V 1)–(V 2) in Ref. [38], respectively.

Strongly motivated by Refs. [14], [24], [38], in this paper we analyze the multiplicity and concentration behavior as ɛ → 0 of solutions to (1.1). The main result of this work is the following.

Theorem 1.1.

Assume that (V 1)–(V 2) and (f 1)–(f 4) hold. Suppose in addition that V L ( R N ) . Then, for every δ > 0 such that

M δ = { x R N : d i s t ( x , M ) δ } Λ ,

there exists ɛ δ > 0 such that, for every ɛ ∈ (0, ɛ δ ), problem (1.1) has at least cat M δ ( M ) positive solutions. Moreover, if u ɛ denotes one of these solutions and x ε R N is a global maximum point of u ɛ , then

lim ε 0 V ( ε x ε ) = V 0 .

The proof of Theorem 1.1 is based on suitable variational and topological arguments. Inspired by Refs. [14], [24], [38], we adopt a del Pino–Felmer penalization approach [42] by modifying the nonlinearity f outside of the set Λ and introducing an auxiliary problem whose corresponding modified energy functional J ε satisfies all assumptions of the mountain-pass theorem [43]. Lastly, we check that, for ɛ > 0 small enough, the solutions of the modified problem are indeed solutions of the original one. In order to explore (1.1) via variational methods, we recall the following Hardy–Littlewood–Sobolev inequality which will be frequently used throughout the paper.

Theorem 1.2.

[44] Let r, t ∈ (1, ∞) and μ ∈ (0, N) with 1 r + μ N + 1 t = 2 . Let g L r ( R N ) and h L t ( R N ) . Then there exists a sharp constant C(N, μ, r) > 0, independent of g and h, such that

R 2 N g ( x ) h ( y ) | x y | μ d x d y C ( N , μ , r ) | g | r | h | t .

Remark 1.1.

By virtue of Theorem 1.2, we have that if μ ∈ (0, N) and r, t ∈ (1, ∞) are such that 1 r + μ N = 1 + 1 t , then

ϝ L r ( R N ) 1 | | μ * ϝ L t ( R N )

is a linear bounded operator.

We note that if μ ∈ (0, N), F ( t ) = | t | σ 0 for some σ 0 > 0 and u W s , p ( R N ) W s , q ( R N ) , then Theorem 1.2 implies that the term

(1.7) R N 1 | x | μ * F ( u ) F ( u ) d x

is well-defined whenever F ( u ) L τ ( R N ) with τ ∈ (1, ∞) such that 2 τ + μ N = 2 , i.e., τ = 2 N 2 N μ . Bearing in mind that W s , p ( R N ) W s , q ( R N ) is continuously embedded into L r ( R N ) for all r [ p , q s * ] , we have to require that τ σ 0 [ p , q s * ] , namely,

p 2 2 μ N σ 0 q s * 2 2 μ N .

Consequently, if F fulfills | F ( t ) | C | t | σ 1 + | t | σ 2 with p 2 2 μ N σ 1 σ 2 q s * 2 2 μ N , then the quantity in (1.7) is finite. Since we deal with the subcritical case and we aim to examine positivity, regularity and concentration behavior of solutions to (1.1), we impose the restrictions 0 < μ < sp and q < σ < q ( N μ ) N s q . Then, we will be able to treat the convolution 1 | x | μ * F ( u ) as a bounded term and we will use assumptions (f 3) and (f 4) to implement the penalization method. We underline that the presence of the convolution term and the fractional (p, q)-Laplacian operator make our study much more complicated with respect to Refs. [14], [24], [38] and a more refined analysis will be carried out to accomplish compactness; see Lemma 3.5. To produce multiple solutions for the modified problem, we follow the strategy due to Benci and Cerami [45], which consists in precise comparisons between the category of some sublevel sets of J ε and the category of the set M. We point out that, because f is merely continuous, standard Nehari manifold arguments for C 1 functionals are unusable and so we exploit the generalized Nehari manifold method proposed by Szulkin and Weth [46]. We could prove Theorem 1.1 without the additional condition V L ( R N ) ; see Remark 6.1. However, for the sake of simplicity, we assume here the boundedness of V. As far as we know, this is the first time that the penalization method and the Ljusternik–Schnirelmann category theory are combined to obtain multiple solutions to (1.1).

The paper is organized as follows. In Section 2 we fix the notations and recall some technical results. In Section 3 we introduce the modified problem and we study the corresponding modified energy functional. In Section 4 we focus on the limiting problem associated with (1.1). In Section 5 we provide a multiplicity result for the modified problem. The last section is devoted to the proof of Theorem 1.1.

2 Preliminary results

Let p ∈ [1, ∞] and A R N be a measurable set. With A c = R N \ A we denote the complement of A. We will use | | L p ( A ) to denote the L p (A)-norm. When A = R N , we simply write |⋅| p . For a generic function u : R N R , we set u + = max{u, 0} and u = min{u, 0}.

Let s ∈ (0, 1), p ∈ (1, ∞) and N > sp. The space D s , p ( R N ) is given by the closure of C c ( R N ) with respect to

[ u ] s , p = R 2 N | u ( x ) u ( y ) | p | x y | N + s p d x d y 1 p ,

or equivalently

D s , p ( R N ) = u L p s * ( R N ) : [ u ] s , p < ,

where p s * = N p N s p is the fractional critical Sobolev exponent. The fractional Sobolev space W s , p ( R N ) is defined as

W s , p ( R N ) = u L p ( R N ) : [ u ] s , p < .

The space W s , p ( R N ) is endowed with the norm

u W s , p ( R N ) = | u | p p + [ u ] s , p p 1 p .

We recall that W s , p ( R N ) is a separable reflexive Banach space (see Ref. [47]). For u , v W s , p ( R N ) , we put

u , v s , p = R 2 N | u ( x ) u ( y ) | p 2 ( u ( x ) u ( y ) ) ( v ( x ) v ( y ) ) | x y | N + s p d x d y .

The next embeddings are well-known.

Theorem 2.1.

[2] Let s ∈ (0, 1), p ∈ (1, ∞) and N > sp. Then there exists a constant S p = S(N, s, p) > 0 such that

S p | u | p s * p [ u ] s , p p  for all  u D s , p ( R N ) .

Moreover, W s , p ( R N ) is continuously embedded into L t ( R N ) for all t p , p s * and compactly embedded into L loc t ( R N ) for all t [ 1 , p s * ) .

The following vanishing Lions type-result will be frequently used along the paper.

Lemma 2.1.

[1] Let s ∈ (0, 1), p ∈ (1, ∞), N > sp and r [ p , p s * ) . If { u n } n N is a bounded sequence in W s , p ( R N ) and if

lim n sup y R N B R ( y ) | u n | r d x = 0 ,

for some R > 0, then u n → 0 in L t ( R N ) for all t ( p , p s * ) .

Let s ∈ (0, 1) and p, q ∈ (1, ∞) be such that p < q. We introduce the space

W = W s , p ( R N ) W s , q ( R N )

equipped with the norm

u W = u W s , p ( R N ) + u W s , q ( R N ) .

Obviously, W is a separable reflexive Banach space. For each ɛ > 0, we consider the space

X ε = u W : R N V ( ε x ) | u | p + | u | q d x <

endowed with the norm

u X ε = u V ε , p + u V ε , q ,

where

u V ε , t = [ u ] s , t t + R N V ( ε x ) | u | t d x 1 t  for  t { p , q } .

Let X be a real Banach space, X′ its topological dual and J C 1 ( X , R ) . We say that { u n } n N X is a Palais–Smale sequence for J at the level c R (a (PS) c sequence for short) whenever J(u n ) → c and J′(u n ) → 0 in X′. The functional J is said to satisfy the Palais–Smale condition at the level c R (the (PS) c condition for short) if each (PS) c sequence has a convergent subsequence in X.

3 The modified problem

We adapt the del Pino–Felmer penalization type approach [42] to our problem (1.1). Fix 0 > 0 such that

V 0 0 < lim t f ( t ) t q 1 ( 0 , ] ,

and let a > 0 be the unique number such that

f ( a ) = V 0 0 a q 1 .

We define

f ̃ ( t ) = f ( t )  if  t a , V 0 0 t q 1  if  t > a ,

and

g ( x , t ) = χ Λ ( x ) f ( t ) + ( 1 χ Λ ( x ) ) f ̃ ( t )  if  t > 0 , 0  if  t 0 ,

where χ A stands for the characteristic function of A R N . Put G ( x , t ) = 0 t g ( x , τ ) d τ . In light of (f 1)–(f 4), we see that g : R N × R R is a Carathéodory function satisfying the following conditions:

  1. lim t 0 g ( x , t ) t p 1 = 0 uniformly with respect to x R N ,

  2. g(x, t) ≤ f(t) for all x R N and t > 0,

  3. (i) 0 < ϑG(x, t) ≤ 2g(x, t)t for all x ∈ Λ and t > 0,

  4. ( i i ) 0 < q G ( x , t ) g ( x , t ) t V 0 0 ( t p + t q ) for all x ∈ Λ c and t > 0,

  5. for each fixed x R N , the functions t g ( x , t ) t q 2 1 and t G ( x , t ) t q 2 are increasing in (0, ∞).

Let us consider the auxiliary problem

(3.1) ( Δ ) p s u + ( Δ ) q s u + V ( ε x ) ( | u | p 2 u + | u | q 2 u ) = 1 | x | μ * G ( ε x , u ) g ( ε x , u )  in  R N , u W s , p ( R N ) W s , q ( R N ) , u > 0  in  R N .

Clearly, if u ɛ is a solution to (3.1) such that u ɛ (x) ≤ a for all x Λ ε c , where Λ ε = { x R N : ε x Λ } , then u ɛ is also a solution to (1.1). The energy functional J ε : X ε R associated with (3.1) is given by

J ε ( u ) = 1 p u V ε , p p + 1 q u V ε , q q 1 2 R N 1 | x | μ * G ( ε x , u ) G ( ε x , u ) d x .

From the growth assumptions on g, Theorems 1.2 and 2.1, we deduce that J ε C 1 ( X ε , R ) and

J ε ( u ) , φ = u , φ s , p + R N V ( ε x ) | u | p 2 u φ d x + u , φ s , q + R N V ( ε x ) | u | q 2 u φ d x R N 1 | x | μ * G ( ε x , u ) g ( ε x , u ) φ d x  for all  u , φ X ε .

The next lemma ensures that J ε possesses a mountain pass geometry [43].

Lemma 3.1.

The functional J ε satisfies the following properties:

  1. J ε ( 0 ) = 0 .

  2. There exist α, ρ > 0 such that J ε ( u ) α for all u X ε such that u X ε = ρ .

  3. There exists e X ε such that e X ε > ρ and J ε ( e ) < 0 .

Proof.

(i) Of course, J ε ( 0 ) = 0 . (ii) It follows from (g 1), (g 2) and (f 2) that for each ξ > 0 there exists C ξ > 0 such that

(3.2) | g ( x , t ) | ξ | t | p 1 + C ξ | t | σ 1  for  ( x , t ) R N × R ,

and

(3.3) | G ( x , t ) | ξ | t | p p + C ξ | t | σ σ  for  ( x , t ) R N × R .

In view of Theorem 1.2 and (3.3), we see that

R N 1 | x | μ * G ( ε x , u ) G ( ε x , u ) d x C | G ( ε , u ) | τ | G ( ε , u ) | τ C R N ξ | u | p + C ξ | u | σ τ d x 2 τ ,

where τ = 2 N 2 N μ . Since μ ∈ (0, sp) and σ ( q , q ( N μ ) N s q ) , we know that τ p ( p , p s * ) and τ σ ( q , q s * ) . Then Theorem 2.1 implies

R N 1 | x | μ * G ( ε x , u ) G ( ε x , u ) d x C 0 ξ 2 u V ε , p 2 p + C ξ 2 u V ε , q 2 σ .

Consequently,

J ε ( u ) 1 p u V ε , p p C 0 2 ξ 2 u V ε , p 2 p + 1 q u V ε , q q C 0 2 C ξ 2 u V ε , q 2 σ .

Pick u X ε = ρ ( 0,1 ) . Using p < q and u V ε , p < 1 , we have u V ε , p p u V ε , p 2 p and u V ε , p p u V ε , p q . Choosing ξ 0 , 2 p C 0 , we obtain some C 1 > 0 such that

1 p u V ε , p p C 0 2 ξ 2 u V ε , p 2 p C 1 u V ε , p p .

Hence, recalling that

(3.4) a r + b r 2 1 r ( a + b ) r  for all  a , b 0  and  r 1 ,

we arrive at

J ε ( u ) C 1 u V ε , p p + 1 q u V ε , q q C 2 u V ε , q 2 σ C 1 u V ε , p q + 1 q u V ε , q q C 2 u V ε , q 2 σ C 3 u X ε q C 4 u X ε 2 σ .

Because 2σ > q, we can choose ρ 0 , min 1 , C 3 C 4 1 2 σ q so that

inf u X ε : u X ε = ρ J ε ( u ) ρ q C 3 C 4 ρ 2 σ q = α > 0 .

(iii) Select a nonnegative function u 0 X ε \ { 0 } with supp(u 0) ⊂ Λ ɛ . Observe that G(ɛ⋅, u 0) = F(u 0). Define

ς ( t ) = F t u 0 u 0 X ε  for  t > 0 ,

where

(3.5) F ( u ) = 1 2 R N 1 | x | μ * F ( u ) F ( u ) d x .

By virtue of (f 3), we see that for all t > 0,

(3.6) ς ( t ) = F t u 0 u 0 X ε , u 0 u 0 X ε = R N 1 | x | μ * F t u 0 u 0 X ε f t u 0 u 0 X ε u 0 u 0 X ε d x = 2 q t R N 1 2 1 | x | μ * F t u 0 u 0 X ε 1 q f t u 0 u 0 X ε t u 0 u 0 X ε d x 2 q t ς ( t ) .

Integrating (3.6) over [ 1 , t u 0 X ε ] with t > 1 u 0 X ε , we obtain

ς ( t u 0 X ε ) ς ( 1 ) ( t u 0 X ε ) 2 q ,

which yields

F ( t u 0 ) F u 0 u 0 X ε u 0 X ε 2 q t 2 q .

Therefore, for all t > 1 u 0 X ε ,

J ε ( t u 0 ) = t p p u 0 V ε , p p + t q q u 0 V ε , q q F ( t u 0 ) C 5 ( t p + t q ) C 6 t 2 q .

Since 2q > q > p, the assertion follows by taking e = tu 0 with t sufficiently large. □

In light of Lemma 3.1 and a variant of the mountain pass theorem without the Palais–Smale condition (see Ref. [48]), we can find a Palais–Smale sequence { u n } n N X ε for J ε at the mountain pass level c ε defined by

c ε = inf γ Γ ε max t [ 0,1 ] J ε ( γ ( t ) ) ,

where

Γ ε = { γ C ( [ 0,1 ] , X ε ) : γ ( 0 ) = 0  and  J ε ( γ ( 1 ) ) < 0 } .

Note that, thanks to (g 4), c ε can be characterized as

c ε = inf u X ε \ { 0 } max t > 0 J ε ( t u ) .

Because supp(u 0) ⊂ Λ ɛ , there exists κ > 0, independent of ɛ, 0, and a, such that

c ε < κ  for small  ε > 0 .

Let us define

B = u X ε : u V ε , p p + u V ε , q q ϑ q ϑ q ( κ + 1 ) ,

and we set

K ̃ ε ( u ) ( x ) = 1 | x | μ * G ( ε x , u ) = R N G ( ε y , u ( y ) ) | x y | μ d y .

Lemma 3.2.

There exists 0 > 0 such that

sup u B | K ̃ ε ( u ) | 0 < 1 2  for all  ε > 0 .

Proof.

Let us start by proving that there exists C ̃ 0 > 0 such that

(3.7) sup u B | K ̃ ε ( u ) | C ̃ 0 .

In view of (3.3), we know that

| G ( x , t ) | C ( | t | p + | t | σ )  for  ( x , t ) R N × R .

Then, for all fixed u B , we can see that for a.e. x R N ,

(3.8) | K ̃ ε ( u ) ( x ) | = R N G ( ε y , u ( y ) ) | x y | μ d y | x y | 1 G ( ε y , u ( y ) ) | x y | μ d y + | x y | > 1 G ( ε y , u ( y ) ) | x y | μ d y C | x y | 1 | u ( y ) | p + | u ( y ) | σ | x y | μ d y + C R N ( | u ( y ) | p + | u ( y ) | σ ) d y C | x y | 1 | u ( y ) | p + | u ( y ) | σ | x y | μ d y + C ̄ ,

where in the last line we have used Theorem 2.1 and u B . Now, recalling that 0 < μ < sp and that q < σ < q ( N μ ) N s q , we can choose

t N N μ , N N s p  and  r N N μ , N q σ ( N s q ) .

Exploiting Hölder’s inequality, Theorem 2.1 and u B , we obtain

(3.9) | x y | 1 | u ( y ) | p | x y | μ d y | x y | 1 | u ( y ) | t p d y 1 t | x y | 1 1 | x y | t μ t 1 d y t 1 t C 0 1 ρ N 1 t μ t 1 d ρ t 1 t < ,

because of N 1 t μ t 1 > 1 . Similarly, we get

(3.10) | x y | 1 | u ( y ) | σ | x y | μ d y | x y | 1 | u ( y ) | r σ d y 1 r | x y | 1 1 | x y | r μ r 1 d y r 1 r C 0 1 ρ N 1 r μ r 1 d ρ r 1 r < ,

thanks to N 1 r μ r 1 > 1 . In view of (3.9) and (3.10), we arrive at

| x y | 1 | u ( y ) | p + | u ( y ) | σ | x y | μ d y C ̃  for a.e.  x R N ,

which combined with (3.8) yields (3.7). Thus we can find 0 > 0 such that

sup u B | K ̃ ε ( u ) | 0 C ̃ 0 0 < 1 2 .

This concludes the proof of the lemma. □

Henceforward, we assume that 0 > 0 and consider the penalized nonlinearity g with this choice of 0. Let us now introduce the Nehari manifold N ε associated with J ε :

N ε = u X ε \ 0 : J ε ( u ) , u = 0 ,

and we set

c ε = inf u N ε J ε ( u ) .

Let S ε = { u X ε : u X ε = 1 } be the unit sphere in X ε . Define the tangent space of S ε at u by

T u S ε = v X ε : u , v s , p + u , v s , q + R N V ( ε x ) ( | u | p 2 u v + | u | q 2 u v ) d x = 0 .

To overcome the non-differentiability of N ε (due to the fact that f is only continuous), we will use the results below.

Lemma 3.3.

The following properties hold:

  1. For each u X ε \ { 0 } , let h u : [ 0 , ) R be defined by h u ( t ) = J ε ( t u ) . Then, there is a unique t u > 0 such that

    h u ( t ) > 0  for all  t ( 0 , t u ) , h u ( t ) < 0  for all  t ( t u , ) .

  2. There exists τ > 0, independent of u, such that t u τ for all u S ε . Moreover, for each compact set K S ε , there is a constant C K such that t u C K for all u K .

  3. The map m ̂ ε : X ε \ { 0 } N ε given by m ̂ ε ( u ) = t u u is continuous and m ε = m ̂ ε | S ε is a homeomorphism between S ε and N ε . Moreover, m ε 1 ( u ) = u u X ε .

Proof.

(i) From the proof of Lemma 3.1, we deduce that h u (0) = 0, h u (t) > 0 for t > 0 small enough and h u (t) < 0 for t > 0 sufficiently large. Therefore, max t [ 0 , ) h u ( t ) is achieved at some t u > 0 so that h u ( t u ) = 0 and t u u N ε . We claim that t u > 0 is the unique number such that h u ( t u ) = 0 . Take t 1, t 2 > 0 such that h u ( t 1 ) = h u ( t 2 ) = 0 . Hence,

t 1 p 1 u V ε , p p + t 1 q 1 u V ε , q q = R N 1 | x | μ * G ( ε x , t 1 u ) g ( ε x , t 1 u ) u d x , t 2 p 1 u V ε , p p + t 2 q 1 u V ε , q q = R N 1 | x | μ * G ( ε x , t 2 u ) g ( ε x , t 2 u ) u d x ,

from which

(3.11) u V ε , p p t 1 q p + u V ε , q q = R 2 N 1 | x y | μ G ( ε y , t 1 u ( y ) ) ( t 1 u ( y ) ) q 2 g ( ε x , t 1 u ( x ) ) ( t 1 u ( x ) ) q 2 1 ( u ( x ) ) q 2 ( u ( y ) ) q 2 d x d y ,

and

(3.12) u V ε , p p t 2 q p + u V ε , q q = R 2 N 1 | x y | μ G ( ε y , t 2 u ( y ) ) ( t 2 u ( y ) ) q 2 g ( ε x , t 2 u ( x ) ) ( t 2 u ( x ) ) q 2 1 ( u ( x ) ) q 2 ( u ( y ) ) q 2 d x d y .

Subtracting (3.12) from (3.11), we find

1 t 1 q p 1 t 2 q p u V ε , p p = R 2 N 1 | x y | μ G ( ε y , t 1 u ( y ) ) ( t 1 u ( y ) ) q 2 g ( ε x , t 1 u ( x ) ) ( t 1 u ( x ) ) q 2 1 G ( ε y , t 2 u ( y ) ) ( t 2 u ( y ) ) q 2 g ( ε x , t 2 u ( x ) ) ( t 2 u ( x ) ) q 2 1 ( u ( x ) ) q 2 ( u ( y ) ) q 2 d x d y .

Exploiting the above identity, (g 4) and p < q, we infer that t 1 = t 2.

(ii) Let u S ε . In view of (i), there exists a unique t u > 0 such that h u ( t u ) = 0 , that is,

t u p u V ε , p p + t u q u V ε , q q = R N 1 | x | μ * G ( ε x , t u u ) g ( ε x , t u u ) t u u d x .

If t u ∈ [1, ∞), then we are done. Let t u ∈ (0, 1). From (3.2), (3.3), Theorem 1.2 and 2.1, we have that for each fixed ξ > 0 there exists C ξ > 0 such that

t u p u V ε , p p + t u q u V ε , q q C 0 ξ 2 t u 2 p u V ε , p 2 p + C 0 C ξ t u 2 σ u V ε , q 2 σ .

Because t u ∈ (0, 1), we know that t u 2 p t u p , and since 1 = u X ε u V ε , p implies that u V ε , p 2 p u V ε , p p , we can see that

1 C 0 ξ 2 t u p u V ε , p p + t u q u V ε , q q C 1 t u 2 σ u X ε 2 σ = C 1 t u 2 σ .

Pick ξ ( 0 , 1 C 0 ) . Then, using t u q t u p (due to t u ∈ (0, 1) and p < q), u V ε , p q u V ε , p p (thanks to u V ε , p 1 and p < q), (3.4), and u X ε = 1 , we obtain

C 2 t u q = C 2 t u q u X ε q t u q 1 C 0 ξ 2 u V ε , p q + u V ε , q q t u q 1 C 0 ξ 2 u V ε , p p + u V ε , q q C 1 t u 2 σ .

By virtue of 2σ > q, we can take δ = C 2 C 1 1 2 σ q > 0 so that t u δ. Consequently, t u τ = min{δ, 1} for all u S ε .

Let now K S ε be a compact set. Suppose by contradiction that there exists { u n } n N K such that t n = t u n . Because K is compact, there exists u K such that, up to a subsequence, u n u in X ε . Thus, by Theorem 2.1, (3.3), the continuity of t R G ( x , t ) for a.e. x R N , and the dominated convergence theorem, we infer that

G ( ε , u n ) G ( ε , u )  in  L 2 N 2 N μ ( R N ) ,

which together with Remark 1.1 leads to

1 | | μ * G ( ε , u n ) 1 | | μ * G ( ε , u )  in  L 2 N μ ( R N ) .

Therefore,

(3.13) R N 1 | x | μ * G ( ε x , u n ) G ( ε x , u n ) d x R N 1 | x | μ * G ( ε x , u ) G ( ε x , u ) d x > 0 .

Reasoning as in the proof of Lemma 3.1-(iii), and exploiting u n V ε , t 1 for all n N and t ∈ {p, q}, t n → ∞, p < q, and (3.13), we see that

(3.14) J ε ( t n u n ) t n 2 q t n p 2 q p + t n q q 1 2 R N 1 | x | μ * G ( ε x , u n ) G ( ε x , u n ) d x .

On the other hand, if v N ε , then J ε ( v ) , v = 0 , (g 3) and p < q < ϑ yield

(3.15) J ε ( v ) = J ε ( v ) 1 ϑ J ε ( v ) , v = 1 p 1 ϑ v V ε , p p + 1 q 1 ϑ v V ε , q q 1 2 R N 1 | x | μ * G ( ε x , v ) G ( ε x , v ) d x + 1 ϑ R N 1 | x | μ * G ( ε x , v ) g ( ε x , v ) v d x 1 q 1 ϑ v V ε , p p + v V ε , q q > 0 .

Taking v = t n u n N ε in (3.15), we arrive at

J ε ( t n u n ) 0  for all  n N ,

which contradicts (3.14). Then there exists C K > 0 such that t u C K for all u K .

(iii) In view of (i) and (ii), we can argue as in the proof of Proposition 8 in Ref. [46] to deduce the assertion. □

Remark 3.1.

There exists ϱ > 0, independent of ɛ, such that u X ε ϱ for all u N ε . The proof is similar to Lemma 3.3-(ii). If u X ε 1 for all u N ε , then we are done. Now we suppose that there exists u N ε such that u X ε < 1 . Using (3.2), (3.3), Theorem 1.2 and 2.1, we see that for each fixed ξ > 0 there exists C ξ > 0 such that

u V ε , p p + u V ε , q q = R N 1 | x | μ * G ( ε x , u ) g ( ε x , u ) u d x C 0 ξ 2 u V ε , p 2 p + C ξ u V ε , q 2 σ .

Select ξ ( 0 , 1 C 0 ) . Recalling that u V ε , p < 1 and p < q, we derive from u V ε , p 2 p u V ε , p p , u V ε , p q u V ε , p p and (3.4) that

C 2 u X ε q 1 C 0 ξ 2 u V ε , p q + u V ε , q q 1 C 0 ξ 2 u V ε , p p + u V ε , q q C 1 u X ε 2 σ .

Setting δ = C 2 C 1 1 2 σ q , we have u X ε δ . In conclusion, u X ε ϱ = min { δ , 1 } for all u N ε .

Let us consider the maps

ψ ̂ ε : X ε \ { 0 } R  and  ψ ε : S ε R ,

given by ψ ̂ ε ( u ) = J ε ( m ̂ ε ( u ) ) and ψ ε = ψ ̂ ε | S ε . From Lemma 3.3 and arguing as in the proofs of Proposition 9 and Corollary 10 in Ref. [46], we may obtain the next result.

Proposition 3.1.

The following properties hold:

  1. ψ ̂ ε C 1 ( X ε \ { 0 } , R ) and

    ψ ̂ ε ( u ) , v = m ̂ ε ( u ) X ε u X ε J ε ( m ̂ ε ( u ) ) , v  for all  u X ε \ { 0 }  and  v X ε .

  2. ψ ε C 1 ( S ε , R ) and

    ψ ε ( u ) , v = m ε ( u ) X ε J ε ( m ε ( u ) ) , v  for all  v T u S ε .

  3. If { u n } n N is a (PS) c sequence for ψ ɛ , then { m ε ( u n ) } n N is a (PS) c sequence for J ε . If { u n } n N N ε is a bounded (PS) c sequence for J ε , then m ε 1 ( u n ) n N is a (PS) c sequence for ψ ɛ .

  4. u is a critical point of ψ ɛ if and only if m ɛ (u) is a critical point for J ε . Moreover, the corresponding critical values of ψ ɛ and J ε coincide and

    inf S ε ψ ε = inf N ε J ε .

Remark 3.2.

As in Ref. [46], we have the following variational characterization of the infimum of J ε over N ε :

c ε = inf u N ε J ε ( u ) = inf u X ε \ { 0 } max t > 0 J ε ( t u ) = inf u S ε max t > 0 J ε ( t u ) .

In particular, c ε = c ε .

Next we establish the boundedness of Palais–Smale sequences for J ε .

Lemma 3.4.

Let c ∈ [c ɛ , κ]. Let { u n } n N X ε be a (PS) c sequence for J ε . Then { u n } n N is bounded in X ε . Furthermore, there exists n 0 N such that

u n V ε , p p + u n V ε , q q ϑ q ϑ q ( κ + 1 )  for all  n n 0 .

Proof.

With the help of (g 3) and p < q, we see that

c + o n ( 1 ) u n X ε J ε ( u n ) 1 ϑ J ε ( u n ) , u n = 1 p 1 ϑ u n V ε , p p + 1 q 1 ϑ u n V ε , q q 1 2 R N 1 | x | μ * G ( ε x , u n ) G ( ε x , u n ) d x + 1 ϑ R N 1 | x | μ * G ( ε x , u n ) g ( ε x , u n ) u n d x 1 q 1 ϑ u n V ε , p p + u n V ε , q q = C ̃ u n V ε , p p + u n V ε , q q ,

where C ̂ = ϑ q ϑ q > 0 because of ϑ > q. In order to accomplish the boundedness of { u n } n N in X ε , we argue by contradiction and suppose that, up to a subsequence, u n X ε . We consider the following three cases:

  1. u n V ε , p and u n V ε , q ;

  2. u n V ε , p and u n V ε , q is bounded;

  3. u n V ε , q and u n V ε , p is bounded.

In case (1), for n large, we have u n V ε , q q p 1 , that is u n V ε , q q u n V ε , q p . Hence, recalling (3.4),

C ( 1 + u n X ε ) C ̂ u n V ε , p p + u n V ε , q p C 1 ( u n V ε , p + u n V ε , q ) p = C 1 u n X ε p ,

and this provides a contradiction. In case (2), we obtain, for n large,

C ( 1 + u n V ε , p + u n V ε , q ) = C ( 1 + u n X ε ) C ̃ u n V ε , p p

and so

C 1 u n V ε , p p + 1 u n V ε , p p 1 + u n V ε , q u n V ε , p p C ̃ .

As p > 1, letting n → ∞, we get 0 < C ̃ 0 , that is a contradiction. The last case is similar to case (2), so we omit the proof. Therefore, { u n } n N is bounded in X ε . Additionally, since c ∈ [c ɛ , κ], we can find n 0 N such that

u n V ε , p p + u n V ε , q q ϑ q ϑ q ( κ + 1 )  for all  n n 0 .

The proof of the lemma is now complete. □

Remark 3.3.

We may always assume that every (PS) c sequence { u n } n N of J ε is nonnegative. Indeed, by Lemma 3.4, we have that { u n } n N is bounded in X ε . Thanks to the reflexivity of X ε and Theorem 2.1, we may suppose, by passing to a subsequence if needed, that u n u in X ε , u n u in L loc r ( R N ) for all r [ 1 , q s * ) and u n u a.e. in R N . Exploiting J ε ( u n ) , u n = o n ( 1 ) , where u n = min { u n , 0 } , the following inequality

(3.16) | x y | r 2 ( x y ) ( x y ) | x y | r  for all  x , y R  and  r ( 1 , ) ,

and the fact that g(ɛ⋅, t) = 0 for t ≤ 0, we see that

u n V ε , p p + u n V ε , q q o n ( 1 ) ,

which implies u n 0 in X ε . Thus, for t ∈ {p, q}, u n V ε , t t = u n + V ε , t t + o n ( 1 ) and u n , φ s , t = u n + , φ s , t + o n ( 1 ) for all φ X ε , which give J ε ( u n ) = J ε u n + + o n ( 1 ) and J ε ( u n ) = J ε u n + + o n ( 1 ) . In conclusion, J ε u n + = c + o n ( 1 ) and J ε u n + = o n ( 1 ) .

In what follows, we prove the Palais–Smale compactness condition for J ε .

Lemma 3.5.

The functional J ε satisfies the (PS) c condition at every level c ∈ [c ɛ , κ].

Proof.

Take c ∈ [c ɛ , κ]. Let { u n } n N X ε be a (PS) c sequence for J ε . From Lemma 3.4, we know that { u n } n N is bounded in X ε and that there exists n 0 N such that

u n V ε , p p + u n V ε , q q ϑ q ϑ q ( κ + 1 )  for all  n n 0 .

Going to a subsequence if necessary, we may assume that u n u in X ε , u n u in L loc r ( R N ) for all r [ 1 , q s * ) and u n u a.e. in R N . Furthermore, by Lemma 3.2, we have that

(3.17) sup n n 0 | K ̃ ε ( u n ) | 0 2 .

Let us first verify that u is a critical point of J ε . Owing to u n u in X ε , for all ϕ C c ( R N ) , it holds

(3.18) u n , φ s , t + R N V ( ε x ) | u n | t 2 u n ϕ d x u , φ s , t + R N V ( ε x ) | u | t 2 u ϕ d x  for  t { p , q } .

On the other hand, since { G ( ε , u n ) } n N is bounded in L 2 N 2 N μ ( R N ) , u n u a.e. in R N , and t R G ( x , t ) is continuous for a.e. x R N , we see that

G ( ε , u n ) G ( ε , u )  in  L 2 N 2 N μ ( R N ) ,

which combined with Remark 1.1 gives

K ̃ ε ( u n ) K ̃ ε ( u )  in  L 2 N μ ( R N ) .

Because g(ɛ⋅, u n ) → g(ɛ⋅, u) in L loc r ( R N ) for all r [ 1 , q s * σ 1 ) , we deduce that, for all ϕ C c ( R N ) ,

(3.19) R N K ̃ ε ( u n ) g ( ε x , u n ) ϕ d x R N K ̃ ε ( u ) g ( ε x , u ) ϕ d x .

Therefore, the relation J ε ( u n ) , ϕ = o n ( 1 ) for all ϕ C c ( R N ) , (3.18) and (3.19) ensure that J ε ( u ) , ϕ = 0 for all ϕ C c ( R N ) . By the density of C c ( R N ) in X ε , we obtain that u is a critical point of J ε . Next we show that for each ξ > 0 there exists R = R(ξ) > 0 such that

(3.20) lim sup n B R c ( 0 ) R N | u n ( x ) u n ( y ) | p | x y | N + s p + | u n ( x ) u n ( y ) | q | x y | N + s q d y + V ( ε x ) | u n | p + | u n | q d x < ξ .

For all R > 0, let ψ R C ( R N ) be such that 0 ≤ ψ R ≤ 1, ψ R = 0 in B R 2 ( 0 ) , ψ R = 1 in B R c ( 0 ) , and | ψ R | C R , for some constant C > 0 independent of R. Since { ψ R u n } n N is bounded in X ε , it follows that J ε ( u n ) , ψ R u n = o n ( 1 ) , that is

(3.21) R 2 N | u n ( x ) u n ( y ) | p | x y | N + s p ψ R ( x ) d x d y + R 2 N | u n ( x ) u n ( y ) | q | x y | N + s q ψ R ( x ) d x d y + R N V ( ε x ) | u n | p ψ R d x + R N V ( ε x ) | u n | q ψ R d x = o n ( 1 ) + R N K ̃ ε ( u n ) g ( ε x , u n ) ψ R u n d x R 2 N | u n ( x ) u n ( y ) | p 2 ( u n ( x ) u n ( y ) ) ( ψ R ( x ) ψ R ( y ) ) | x y | N + s p u n ( y ) d x d y R 2 N | u n ( x ) u n ( y ) | q 2 ( u n ( x ) u n ( y ) ) ( ψ R ( x ) ψ R ( y ) ) | x y | N + s q u n ( y ) d x d y .

Choose R > 0 such that Λ ε B R 2 ( 0 ) . Then, using 0 ≤ ψ R ≤ 1, supp ( ψ R ) Λ ε c , (g 3)-(ii), (3.17), and (V 1), we have that for all nn 0,

R N K ̃ ε ( u n ) g ( ε x , u n ) ψ R u n d x R N sup n n 0 | K ̃ ε ( u n ) | V 0 0 | u n | p + | u n | q ψ R d x 1 2 R N V ( ε x ) | u n | p + | u n | q ψ R d x ,

which together with (3.21) yields

(3.22) R 2 N | u n ( x ) u n ( y ) | p | x y | N + s p ψ R ( x ) d x d y + R 2 N | u n ( x ) u n ( y ) | q | x y | N + s q ψ R ( x ) d x d y + 1 2 R N V ( ε x ) | u n | p + | u n | q ψ R d x o n ( 1 ) R 2 N | u n ( x ) u n ( y ) | p 2 ( u n ( x ) u n ( y ) ) ( ψ R ( x ) ψ R ( y ) ) | x y | N + s p u n ( y ) d x d y R 2 N | u n ( x ) u n ( y ) | q 2 ( u n ( x ) u n ( y ) ) ( ψ R ( x ) ψ R ( y ) ) | x y | N + s q u n ( y ) d x d y .

Now, we notice that, for t ∈ {p, q}, the Hölder inequality and the boundedness of { u n } n N in X ε imply

(3.23) R 2 N | u n ( x ) u n ( y ) | t 2 ( u n ( x ) u n ( y ) ) ( ψ R ( x ) ψ R ( y ) ) | x y | N + s t u n ( y ) d x d y C R 2 N | ψ R ( x ) ψ R ( y ) | t | x y | N + s t | u n ( y ) | t d x d y 1 t .

Exploiting 0 ≤ ψ R ≤ 1, | ψ R | C R , polar coordinates and the boundedness of { u n } n N in X ε , we have

(3.24) R 2 N | ψ R ( x ) ψ R ( y ) | t | x y | N + s t | u n ( x ) | t d x d y = R N | y x | > R | ψ R ( x ) ψ R ( y ) | t | x y | N + s t | u n ( x ) | t d x d y + R N | y x | R | ψ R ( x ) ψ R ( y ) | t | x y | N + s t | u n ( x ) | t d x d y C 1 R N | u n ( x ) | t | y x | > R d y | x y | N + s t d x + C 2 R t R N | u n ( x ) | t | y x | R d y | x y | N + s t t d x C 3 R N | u n ( x ) | t d x R d ρ ρ s t + 1 + C 4 R t R N | u n ( x ) | t d x 0 R d ρ ρ s t t + 1 C 5 R s t R N | u n ( x ) | t d x + C 6 R t R s t + t R N | u n ( x ) | t d x C 7 R s t R N | u n ( x ) | t d x C 8 R s t .

In light of (3.23) and (3.24), we obtain that, for t ∈ {p, q},

(3.25) R 2 N | u n ( x ) u n ( y ) | t 2 ( u n ( x ) u n ( y ) ) ( ψ R ( x ) ψ R ( y ) ) | x y | N + s t u n ( y ) d x d y C R s .

Combining (3.22) with (3.25), we arrive at

(3.26) B R c ( 0 ) R N | u n ( x ) u n ( y ) | p | x y | N + s p d x d y + B R c ( 0 ) R N | u n ( x ) u n ( y ) | q | x y | N + s q d x d y + 1 2 B R c ( 0 ) V ( ε x ) | u n | p + | u n | q d x R 2 N | u n ( x ) u n ( y ) | p | x y | N + s p ψ R ( x ) d x d y + R 2 N | u n ( x ) u n ( y ) | q | x y | N + s q ψ R ( x ) d x d y + 1 2 R N V ( ε x ) | u n | p + | u n | q d x o n ( 1 ) + C R s .

We derive from (3.26) that (3.20) is true. Notice that (3.20) allows us to deduce that u n u in L r ( R N ) for all r [ p , q s * ) . Indeed, fixed ξ > 0 we can find R = R(ξ) > 0 such that (3.20) holds. According to u n u in L loc r ( R N ) for all r [ 1 , q s * ) and (V 1), we see that

lim sup n | u n u | p p = lim sup n | u n u | L p ( B R ( 0 ) ) p + | u n u | L p ( B R c ( 0 ) ) p = lim n | u n u | L p ( B R ( 0 ) ) p + lim sup n | u n u | L p ( B R c ( 0 ) ) p 2 p 1 lim sup n ( | u n | L p ( B R c ( 0 ) ) p + | u | L p ( B R c ( 0 ) ) p ) 2 p 1 V 0 lim sup n B R c ( 0 ) R N | u n ( x ) u n ( y ) | p | x y | N + s p d y + V ( ε x ) | u n | p d x + B R c ( 0 ) R N | u ( x ) u ( y ) | p | x y | N + s p d y + V ( ε x ) | u | p d x < 2 p V 0 ξ = C ̄ ξ .

Because ξ is arbitrary, the strong convergence in L p -norm follows. By interpolation, u n u in L r ( R N ) for all r [ p , q s * ) , as desired. Next we prove that u n u in X ε . Set

L n = L n p + L n q ,

where

L n t = u n , u n u s , t u , u n u s , t + R N V ( ε x ) | u n | t 2 u n | u | t 2 u ( u n u ) d x  for  t { p , q } .

Since for every r ∈ (1, ∞) it holds

| ζ 1 | r 2 ζ 1 | ζ 2 | r 2 ζ 2 ( ζ 1 ζ 2 ) > 0  for all  ζ 1 , ζ 2 R N : ζ 1 ζ 2 ,

and V(ɛ⋅) > 0 in R N , we know that L n t 0 for all n N and t ∈ {p, q}. Note that

L n = J ε ( u n ) , u n u J ε ( u ) , u n u + R N K ̃ ε ( u n ) g ( ε x , u n ) ( u n u ) d x R N K ̃ ε ( u ) g ( ε x , u ) ( u n u ) d x .

By virtue of J ε ( u n ) , u n u = o n ( 1 ) and J ε ( u ) , u n u = 0 , we have

L n = o n ( 1 ) + R N K ̃ ε ( u n ) g ( ε x , u n ) ( u n u ) d x R N K ̃ ε ( u ) g ( ε x , u ) ( u n u ) d x .

Exploiting (3.2) and (3.17), the Hölder inequality, the boundedness of { u n } n N in X ε , and u n u in L r ( R N ) for all r [ p , q s * ) , we obtain

R N K ̃ ε ( u n ) g ( ε x , u n ) ( u n u ) d x = o n ( 1 ) .

Analogously, using | K ̃ ε ( u ) | C (since u B ), (3.2), the Hölder inequality, and u n u in L r ( R N ) for all r [ p , q s * ) , we get

R N K ̃ ε ( u ) g ( ε x , u ) ( u n u ) d x = o n ( 1 ) .

Therefore, L n = o n ( 1 ) and so L n t = o n ( 1 ) for all t ∈ {p, q}. Now, we recall the following inequalities (see Ref. [49]): for every ζ 1 , ζ 2 R N ,

(3.27) | ζ 1 ζ 2 | r C 1 | ζ 1 | r 2 ζ 1 | ζ 2 | r 2 ζ 2 ( ζ 1 ζ 2 )  if  r [ 2 , ) ,

(3.28) | ζ 1 ζ 2 | r C 2 | ζ 1 | r 2 ζ 1 | ζ 2 | r 2 ζ 2 ( ζ 1 ζ 2 ) r 2 | ζ 1 | r + | ζ 2 | r 2 r 2  if  r ( 1,2 ) .

Let t ∈ {p, q}. If t ∈ [2, ∞) then (3.27) implies that

(3.29) u n u V ε , t t C 3 L n t .

If t ∈ (1, 2) then (3.28), the Hölder inequality and the boundedness of { u n } n N in X ε yield

(3.30) u n u V ε , t t C 4 L n t t 2 u n V ε , t t + u V ε , t t 2 t 2 C 5 L n t t 2 .

In view of L n t = o n ( 1 ) for all t ∈ {p, q}, (3.29) and (3.30), we arrive at

u n u X ε = u n u V ε , p + u n u V ε , q = o n ( 1 ) .

This completes the proof of the lemma. □

Corollary 3.1.

The functional ψ ɛ satisfies the (PS) c condition on S ε at every level c ∈ [c ɛ , κ].

Proof.

Pick c ∈ [c ɛ , κ]. Let { u n } n N S ε be a (PS) c sequence for ψ ɛ . Hence,

ψ ε ( u n ) c  and  ψ ε ( u n ) * 0 ,

where ‖ ⋅ ‖* denotes the norm in the dual space ( T u n S ε ) . By Proposition 3.1-(c), we have that { m ε ( u n ) } n N X ε is a (PS) c sequence for J ε . Thanks to Lemma 3.5, we infer that J ε fulfills the (PS) c condition in X ε . Then we can find u S ε such that, up to a subsequence,

m ε ( u n ) m ε ( u )  in  X ε .

Applying Lemma 3.3-(iii), we conclude that u n u in S ε . □

Finally, we establish an existence result for (3.1).

Theorem 3.1.

Assume that (V 1)–(V 2) and (f 1)–(f 4) hold. Then, for all ɛ > 0, (3.1) has a positive ground state solution.

Proof.

On account of Lemma 3.1, Remark 3.2 and Lemma 3.5, we can invoke the mountain pass theorem [43] to see that, for all ɛ > 0, there exists u ε X ε \ { 0 } such that J ε ( u ε ) = c ε and J ε ( u ε ) = 0 . Since J ε ( u ε ) , u ε = 0 , where u ε = min { u ε , 0 } , g(ɛ⋅, t) = 0 for t ≤ 0, and using (3.16), we have that

u ε V ε , p p + u ε V ε , q q 0 ,

which implies that u ε = 0 and so u ɛ ≥ 0 in R N . Arguing as in the proof of Lemma 3.2, we know that | K ̃ ε ( u ε ) | C . Then, observing that u ɛ solves

( Δ ) p s u + ( Δ ) q s u + V ( ε x ) ( u p 1 + u q 1 ) = K ̃ ε ( u ) g ( ε x , u )  in  R N ,

we can proceed as in the proof of Lemma 4.1 in Ref. [38] to deduce that u ε L r ( R N ) C 0 , α ( R N ) for all r ∈ [p, ∞] and that u ɛ (x) → 0 as |x| → ∞. We derive from the strong maximum principle [50] that u ɛ > 0 in R N . □

4 The limiting problem

In this section, we focus on the limiting problem associated with (1.1), namely,

(4.1) ( Δ ) p s u + ( Δ ) q s u + V 0 ( | u | p 2 u + | u | q 2 u ) = 1 | x | μ * F ( u ) f ( u )  in  R N , u W s , p ( R N ) W s , q ( R N ) , u > 0  in  R N .

The energy functional E V 0 : Y V 0 R associated with (4.1) is given by

E V 0 ( u ) = 1 p u s , p p + 1 q u s , q q F ( u ) ,

where F ( u ) is defined in (3.5), Y V 0 = W s , p ( R N ) W s , q ( R N ) is equipped with the norm

u Y V 0 = u s , p + u s , q ,

and

u s , t = [ u ] s , t t + V 0 | u | t t 1 t  for  t { p , q } .

It is easy to see that E V 0 C 1 ( Y V 0 , R ) and

E V 0 ( u ) , φ = u , φ s , p + u , φ s , q + V 0 R N | u | p 2 u φ d x + R N | u | q 2 u φ d x R N 1 | x | μ * F ( u ) f ( u ) φ d x  for all  u , φ Y V 0 .

We define the Nehari manifold M V 0 associated with E V 0 :

M V 0 = u Y V 0 \ { 0 } : E V 0 ( u ) , u = 0 ,

and we set d V 0 = inf u M V 0 E V 0 ( u ) . Let S V 0 = { u Y V 0 : u Y V 0 = 1 } be the unit sphere in Y V 0 . The tangent space of S V 0 at u is defined by

T u S V 0 = v Y V 0 : u , v s , p + u , v s , q + V 0 R N ( | u | p 2 u + | u | q 2 u ) v d x = 0 .

Arguing as in Section 3, we obtain the next results.

Lemma 4.1.

The following properties hold:

  1. For each u Y V 0 \ { 0 } , let h u : [ 0 , ) R be defined by h u ( t ) = E V 0 ( t u ) . Then, there is a unique t u > 0 such that

    h u ( t ) > 0  for all  t ( 0 , t u ) , h u ( t ) < 0  for all  t ( t u , ) .

  2. There exists τ > 0, independent of u, such that t u τ for all u S V 0 . Moreover, for each compact set K S V 0 there is a constant C K such that t u C K for all u K .

  3. The map m ̂ V 0 : Y V 0 \ { 0 } M V 0 given by m ̂ V 0 ( u ) = t u u is continuous and m V 0 = m ̂ V 0 | S V 0 is a homeomorphism between S V 0 and M V 0 . Moreover, m V 0 1 ( u ) = u u Y V 0 .

Let us define the maps

ψ ̂ V 0 : Y V 0 \ { 0 } R  and  ψ V 0 : S V 0 R ,

by setting ψ ̂ V 0 ( u ) = E V 0 ( m ̂ V 0 ( u ) ) and ψ V 0 = ψ ̂ V 0 | S V 0 .

Proposition 4.1.

The following properties hold:

  1. ψ ̂ V 0 C 1 ( Y V 0 \ { 0 } , R ) and

    ψ ̂ V 0 ( u ) , v = m ̂ V 0 ( u ) Y V 0 u Y V 0 E V 0 ( m ̂ V 0 ( u ) ) , v  for all  u Y V 0 \ { 0 }  and  v Y V 0 .

  2. ψ V 0 C 1 ( S V 0 , R ) and

    ψ V 0 ( u ) , v = m V 0 ( u ) Y V 0 E V 0 ( m V 0 ( u ) ) , v  for all  v T u S V 0 .

  3. If { u n } n N is a (PS) c sequence for ψ V 0 , then { m V 0 ( u n ) } n N is a (PS) c sequence for E V 0 . If { u n } n N M V 0 is a bounded (PS) c sequence for E V 0 , then m V 0 1 ( u n ) n N is a (PS) c sequence for ψ V 0 .

  4. u is a critical point of ψ V 0 if and only if m V 0 ( u ) is a nontrivial critical point for E V 0 . Moreover, the corresponding critical values of ψ V 0 and E V 0 coincide and

    inf S V 0 ψ V 0 = inf M V 0 E V 0 .

Remark 4.1.

As in Section 3, we have the following characterization of the infimum of E V 0 over M V 0 :

d V 0 = inf u M V 0 E V 0 ( u ) = inf u Y V 0 \ { 0 } max t > 0 E V 0 ( t u ) = inf u S V 0 max t > 0 E V 0 ( t u ) .

The next lemma allows us to assume that the weak limit of a ( P S ) d V 0 sequence of E V 0 is nontrivial.

Lemma 4.2.

Let { u n } n N Y V 0 be a ( P S ) d V 0 sequence for E V 0 such that u n ⇀ 0 in Y V 0 . Then,

  1. either u n → 0 in Y V 0 , or

  2. there is a sequence { y n } n N R N and constants R, β > 0 such that

    lim inf n B R ( y n ) | u n | q d x β .

Proof.

Suppose that (b) does not hold. Since { u n } n N is bounded in Y V 0 , from Lemma 2.1 we deduce that

(4.2) u n 0  in  L r ( R N )  for all  r q , q s * .

By (f 1)–(f 2), we know that for each ξ > 0 there exists C ξ > 0 such that

(4.3) | f ( t ) | ξ | t | p 1 + C ξ | t | σ 1  for all  t R ,

and

(4.4) | F ( t ) | ξ | t | p p + C ξ | t | σ σ  for all  t R .

Using Theorem 1.2, (4.2)(4.4), we obtain that

R N 1 | x | μ * F ( u n ) f ( u n ) u n d x = o n ( 1 ) .

Thus, taking E V 0 ( u n ) , u n = o n ( 1 ) into account, we arrive at

u n s , p p + u n s , q q = o n ( 1 ) ,

and this shows that u n → 0 in Y V 0 . This completes the proof of the lemma. □

Remark 4.2.

If u is the weak limit of a ( P S ) d V 0 sequence { u n } n N for E V 0 , then we may assume that u ≢ 0. Indeed, if u n ⇀ 0 and u n 0 in Y V 0 , then we can apply Lemma 4.2 to find { y n } n N R N and R, β > 0 such that

lim inf n B R ( y n ) | u n | q d x β .

Set v n (x) = u n (x + y n ). Exploiting the invariance of R N by translation, we infer that { v n } n N is a bounded ( P S ) d V 0 sequence for E V 0 such that v n v in Y V 0 with v ≢ 0.

Now we establish the existence of a positive ground state solution to (4.1).

Theorem 4.1.

Problem (4.1) admits a positive ground state solution.

Proof.

Proceeding as in the proof of Lemma 3.1, we can check that E V 0 has a mountain pass geometry. Invoking a variant of the mountain-pass theorem without the Palais–Smale condition (see Ref. [48]), we can produce a ( P S ) d V 0 sequence { u n } n N Y V 0 for E V 0 . Reasoning as in the proof of Lemma 3.4, we see that { u n } n N is bounded in Y V 0 . So, the reflexivity of Y V 0 and Theorem 2.1 imply that by passing to a subsequence if necessary, we may assume that

u n u  in  Y V 0 , u n u  in  L loc r ( R N )  for all  r [ 1 , q s * ) , u n u  a.e. in  R N .

Arguing as in the proof of Lemma 3.5, we can verify that E V 0 ( u ) = 0 . From Remark 4.2, we may suppose that u ≢ 0. Using Lemmas 2.4 and 2.5 in Ref. [15], we know that

u n u s , t t = u n s , t t u s , t t + o n ( 1 )  for  t { p , q } ,

F ( u n ) F ( u n u ) F ( u ) = o n ( 1 ) ,

and

F ( u n ) F ( u n u ) F ( u ) , φ = o n ( 1 )  for all  φ Y V 0 : φ Y V 0 1 ,

and thus

E V 0 ( u n u ) = d V 0 E V 0 ( u ) + o n ( 1 )  and  E V 0 ( u n u ) = o n ( 1 ) .

On the other hand, by (f 3) and Fatou’s lemma, we have that

d V 0 E V 0 ( u ) 1 q E V 0 ( u ) , u lim inf n E V 0 ( u n ) 1 q E V 0 ( u n ) , u n = d V 0 ,

which yields d V 0 = E V 0 ( u ) . Hence,

E V 0 ( u n u ) = o n ( 1 )  and  E V 0 ( u n u ) = o n ( 1 ) ,

and so

lim sup n 1 p 1 ϑ u n u s , p p + 1 q 1 ϑ u n u s , q q lim sup n E V 0 ( u n u ) 1 ϑ E V 0 ( u n u ) , u n u = 0 .

As a result, u n u in Y V 0 . Finally, we prove that u is positive. From E V 0 ( u ) , u = 0 , f(t) = 0 for t ≤ 0, and (3.16), we derive that u ≥ 0 in R N . So, u ≥ 0 and u ≢ 0 in R N . Reasoning as in the proof of Lemma 3.2, we can verify that 1 | x | μ * F ( u ) L ( R N ) . Then, proceeding as in the proof of Lemma 4.1 in Ref. [38], we see that u L r ( R N ) C 0 , α ( R N ) for all r ∈ [p, ∞] and that u(x) → 0 as |x| → ∞. Using the strong maximum principle [50], we obtain that u > 0 in R N . □

The next lemma is a very useful compactness result for (4.1).

Lemma 4.3.

Let { u n } n N M V 0 be such that E V 0 ( u n ) d V 0 . Then, { u n } n N has a convergent subsequence in Y V 0 .

Proof.

Since { u n } n N M V 0 and E V 0 ( u n ) d V 0 , it follows from Lemma 4.1-(iii), Proposition 4.1-(d) and the definition of d V 0 that

v n = m V 0 1 ( u n ) = u n u n Y V 0 S V 0  for all  n N ,

and

ψ V 0 ( v n ) = E V 0 ( u n ) d V 0 = inf v S V 0 ψ V 0 ( v ) .

Applying the Ekeland variational principle (see Ref. [48]) to ψ V 0 , we can find a ( P S ) d V 0 sequence { v ̂ n } n N S V 0 for ψ V 0 such that v ̂ n v n Y V 0 = o n ( 1 ) . By Proposition 4.1-(c), { m V 0 ( v ̂ n ) } n N is a ( P S ) d V 0 sequence for E V 0 . Arguing as in the proof of Theorem 4.1, there exists v ̂ S V 0 such that, up to a subsequence, m V 0 ( v ̂ n ) m V 0 ( v ̂ ) in Y V 0 . This fact combined with Lemma 4.1-(iii) and v ̂ n v n Y V 0 = o n ( 1 ) shows that u n m V 0 ( v ̂ ) in Y V 0 . □

Remark 4.3.

The previous results remain valid if we replace V 0 by any ν > 0. Moreover, we can weaken hypotheses on f by assuming that there exist p < σ 1 σ 2 < q ( N μ ) N s q and C > 0 such that | f ( t ) | C | t | σ 1 1 + | t | σ 2 1 for all t R , there exists θ > q such that 0 < θF(t) ≤ 2f(t)t for all t > 0, and that the function t ( 0 , ) f ( t ) t q 2 1 is increasing.

Finally, we present an interesting relationship between the minimax levels c ɛ and d V 0 .

Lemma 4.4.

It holds lim ε 0 c ε = d V 0 .

Proof.

Let ω ɛ (x) = ψ ɛ (x)ω(x), where ω is a positive ground state of (4.1) (whose existence is guaranteed by Theorem 4.1), and ψ ɛ (x) = ψ(ɛx), with ψ C c ( R N ) such that 0 ≤ ψ ≤ 1, ψ(x) = 1 if |x| ≤ r and ψ(x) = 0 if |x|≥ 2r, for some r > 0. Because 0 ∈ Λ, we may assume that B 2r (0) ⊂ Λ. Thus, supp(ω ɛ ) ⊂ Λ ɛ . Invoking Lemma 2.3 in Ref. [51] and the dominated convergence theorem, we know that

(4.5) ω ε ω  in  W  and  E V 0 ( ω ε ) E V 0 ( ω ) = d V 0

as ɛ → 0. Now, for each ɛ > 0 there exists t ɛ > 0 such that

J ε ( t ε ω ε ) = max t 0 J ε ( t ω ε ) .

Hence, J ε ( t ε ω ε ) , t ε ω ε = 0 , that is,

(4.6) t ε p ω ε V ε , p p + t ε q ω ε V ε , q q = R N 1 | x | μ * F ( t ε ω ε ) f ( t ε ω ε ) t ε ω ε d x .

We claim that t ɛ → 1 as ɛ → 0. Assume by contradiction that, up to a subsequence, t ɛ → ∞. Since

t ε p q ω ε V ε , p p + ω ε V ε , q q = R N 1 | x | μ * F ( t ε ω ε ) t ε q 2 f ( t ε ω ε ) t ε q 2 1 ω ε d x = R 2 N 1 | x y | μ F ( t ε ω ε ( y ) ) ( t ε ω ε ( y ) ) q 2 f ( t ε ω ε ( x ) ) ( t ε ω ε ( x ) ) q 2 1 ( ω ε ( x ) ) q 2 ( ω ε ( y ) ) q 2 d x d y ,

and using (4.5), p < q, and the fact that (f 3) implies

lim t F ( t ) t q 2 = lim t f ( t ) t q 2 1 = ,

we deduce from Fatou’s lemma that ω s , q q = , which is a contradiction. Consequently, up to a subsequence, we may assume that t ɛ t 0 ∈ [0, ∞). Let us show that t 0 ∈ (0, ∞). Arguing indirectly, suppose that t 0 = 0. Thanks to (4.3), (4.4), and Theorem 1.2, we see that, fixed ξ > 0, it holds

ω ε V ε , p p + t ε q p ω ε V ε , q q C 0 ξ 2 t ε p ω ε V ε , p 2 p + C ξ t ε 2 σ p ω ε V ε , q 2 σ ,

which combined with t ɛ → 0, (4.5) and p < q < 2σ yields ω s , p p = 0 , a contradiction. Thus, t ɛ t 0 ∈ (0, ∞). Passing to the limit as ɛ → 0 in (4.6), we obtain

t 0 p q [ ω ] s , p p + [ ω ] s , q q + t 0 p q R N V 0 ω p d x + R N V 0 ω q d x = R N 1 | x | μ * F ( t 0 ω ) t 0 q 2 f ( t 0 ω ) t 0 q 2 1 ω d x .

From the above identity, ω M V 0 , p < q, and recalling that t f ( t ) t q 2 1 and t F ( t ) t q 2 are increasing in (0, ∞), we infer that t 0 = 1. Finally, we notice that

c ε max t 0 J ε ( t ω ε ) = J ε ( t ε ω ε ) = E V 0 ( t ε ω ε ) + t ε p p R N ( V ( ε x ) V 0 ) ω ε p d x + t ε q q R N ( V ( ε x ) V 0 ) ω ε q d x .

Observing that V(ɛ⋅) is bounded on the support of ω ɛ , we can use the dominated convergence theorem, (4.5), the continuity of V, t ɛ → 1 as ɛ → 0, and the above inequality to arrive at lim sup ε 0 c ε d V 0 . On the other hand, (V 1) implies that lim inf ε 0 c ε d V 0 , and so we conclude that lim ε 0 c ε = d V 0 . □

5 Multiple solutions for (3.1)

In this section, we establish a multiplicity result for the modified problem (3.1). Take δ > 0 such that

(5.1) M δ = { x R N : d i s t ( x , M ) δ } Λ ,

and let w Y V 0 be a positive ground state solution to (4.1) (see Theorem 4.1). Consider a nonincreasing function ηC ([0, ∞), [0, 1]) such that η(t) = 1 if 0 t δ 2 , η(t) = 0 if tδ and |η′(t)| ≤ c for some c > 0. For every yM, we define

Ψ ε , y ( x ) = η ( | ε x y | ) w ε x y ε ,

and Φ ε : M N ε given by

Φ ε ( y ) = t ε Ψ ε , y ,

where t ɛ > 0 fulfills

max t 0 J ε ( t Ψ ε , y ) = J ε ( t ε Ψ ε , y ) .

Clearly, by construction, Φ ɛ (y) has compact support for all yM.

Lemma 5.1.

The functional Φ ɛ satisfies the following limit:

lim ε 0 J ε ( Φ ε ( y ) ) = d V 0  uniformly in  y M .

Proof.

Assume by contradiction that there exist δ 0 > 0, { y n } n N M and ɛ n → 0 such that

(5.2) | J ε n ( Φ ε n ( y n ) ) d V 0 | δ 0 .

Note that for each n N and for all z B δ ε n ( 0 ) , we have ɛ n zB δ (0), and so

ε n z + y n B δ ( y n ) M δ Λ .

Using the substitutions z = ε n x y n ε n and ζ = ε n y y n ε n , and the fact that G(x, t) = F(t) for ( x , t ) Λ × R , we can see that

(5.3) J ε n ( Φ ε n ( y n ) ) = t ε n p p Ψ ε n , y n V ε n , p p + t ε n q q Ψ ε n , y n V ε n , q q 1 2 R N 1 | x | μ * G ( ε n x , t ε n Ψ ε n , y n ) G ( ε n x , t ε n Ψ ε n , y n ) d x = t ε n p p [ η ( | ε n | ) w ] s , p p + R N V ( ε n z + y n ) ( η ( | ε n z | ) w ( z ) ) p d z + t ε n q q [ η ( | ε n | ) w ] s , q q + R N V ( ε n z + y n ) ( η ( | ε n z | ) w ( z ) ) q d z 1 2 R 2 N 1 | z ζ | μ F ( t ε n η ( | ε n ζ | ) w ( ζ ) ) F ( t ε n η ( | ε n z | ) w ( z ) ) d z d ζ = t ε n p p [ η ( | ε n | ) w ] s , p p + R N V ( ε n z + y n ) ( η ( | ε n z | ) w ( z ) ) p d z + t ε n q q [ η ( | ε n | ) w ] s , q q + R N V ( ε n z + y n ) ( η ( | ε n z | ) w ( z ) ) q d z F ( t ε n η ( | ε n | ) w ) .

In view of J ε n ( Φ ε n ( y n ) ) , Φ ε n ( y n ) = 0 and g(x, t) = f(t) for ( x , t ) Λ × R , we also obtain

(5.4) t ε n p Ψ ε n , y n V ε n , p p + t ε n q Ψ ε n , y n V ε n , q q = R 2 N 1 | z ζ | μ F ( t ε n η ( | ε n ζ | ) w ( ζ ) ) f ( t ε n η ( | ε n z | ) w ( z ) ) t ε n η ( | ε n z | ) w ( z ) d z d ζ .

Invoking Lemma 2.3 in Ref. [51] and the dominated convergence theorem, we know that, as n → ∞,

(5.5) Ψ ε n , y n V ε n , r w s , r ( 0 , )  for all  r { p , q } .

We claim that t ε n 1 as n → ∞. To this end, we borrow some ideas from Lemma 4.4. We start by proving that t ε n t 0 [ 0 , ) . Suppose by contradiction that, up to a subsequence, t ε n . Observe that (5.4) can be rewritten as

(5.6) t ε n p q Ψ ε n , y n V ε n , p p + Ψ ε n , y n V ε n , q q = R 2 N 1 | z ζ | μ F ( t ε n η ( | ε n ζ | ) w ( ζ ) ) ( t ε n η ( | ε n ζ | ) w ( ζ ) ) q 2 f ( t ε n η ( | ε n z | ) w ( z ) ) ( t ε n η ( | ε n z | ) w ( z ) ) q 2 1 × ( η ( | ε n ζ | ) w ( ζ ) ) q 2 ( η ( | ε n z | ) w ( z ) ) q 2 d z d ζ .

Let w ( z ̂ ) = min z B δ 2 ̄ ( 0 ) w ( z ) > 0 (recall that w is continuous and positive in R N ). Because η(|x|) = 1 for x B δ 2 ( 0 ) , B δ 2 ( 0 ) B δ ε n ( 0 ) for all n large enough, and the functions t f ( t ) t q 2 1 and t F ( t ) t q 2 are increasing in (0, ∞), we derive from (5.6) that

(5.7) t ε n p q Ψ ε n , y n V ε n , p p + Ψ ε n , y n V ε n , q q F ( t ε n w ( z ̂ ) ) ( t ε n w ( z ̂ ) ) q 2 f ( t ε n w ( z ̂ ) ) ( t ε n w ( z ̂ ) ) q 2 1 B δ 2 ( 0 ) × B δ 2 ( 0 ) | w ( z ) | q 2 | w ( ζ ) | q 2 | z ζ | μ d z d ζ .

Exploiting (5.5), p < q and t ε n , we find that

(5.8) t ε n p q Ψ ε n , y n V ε n , p p + Ψ ε n , y n V ε n , q q w s , q q .

On the other hand, (f 3) and t ε n yield

(5.9) lim n F ( t ε n w ( z ̂ ) ) ( t ε n w ( z ̂ ) ) q 2 = lim n f ( t ε n w ( z ̂ ) ) ( t ε n w ( z ̂ ) ) q 2 1 = .

Combining (5.7)(5.9), we reach a contradiction. Consequently, { t ε n } n N is bounded in R . So, up to considering a subsequence, we may assume that t ε n t 0 for some t 0 ∈ [0, ∞). From (4.3), (4.4), (5.4), (5.5), and Theorem 1.2, we infer that t 0 ∈ (0, ∞). Now we prove that t 0 = 1. Thanks to (5.5) and the dominated convergence theorem, we can pass to the limit as n → ∞ in (5.4) to obtain

t 0 p q w s , p p + w s , q q = R 2 N 1 | x y | μ F ( t 0 w ( y ) ) ( t 0 w ( y ) ) q 2 f ( t 0 w ( x ) ) ( t 0 w ( x ) ) q 2 1 ( w ( x ) ) q 2 ( w ( y ) ) q 2 d x d y .

Owing to w M V 0 , it holds

w s , p p + w s , q q = R 2 N F ( w ( y ) ) | x y | μ f ( w ( x ) ) w ( x ) d x d y .

Then, since p < q and the functions t f ( t ) t q 2 1 and t F ( t ) t q 2 are increasing in (0, ∞), we deduce that t 0 = 1. Therefore, letting n → ∞ in (5.3), and using (5.5), t ε n 1 , and F ( t ε n η ( | ε n | ) w ) F ( w ) , we arrive at

lim n J ε n ( Φ ε n , y n ) = E V 0 ( w ) = d V 0 ,

which contradicts (5.2). This concludes the proof of the lemma. □

For every δ > 0 satisfying (5.1), let ρ = ρ(δ) > 0 be such that M δ B ρ (0). Define Υ : R N R N by setting

Υ ( x ) = x  if  | x | < ρ , ρ x | x |  if  | x | ρ .

Let us consider the barycenter map β ε : N ε R N given by

β ε ( u ) = R N Υ ( ε x ) ( | u ( x ) | p + | u ( x ) | q ) d x R N ( | u ( x ) | p + | u ( x ) | q ) d x .

Because MB ρ (0), it follows from the definition of Υ and the dominated convergence theorem that (see Lemma 3.6 in Ref. [38])

(5.10) lim ε 0 β ε ( Φ ε ( y ) ) = y  uniformly in  y M .

The next compactness result plays an important role in verifying that the solutions of the modified problem are also solutions of the original one.

Lemma 5.2.

Let ɛ n → 0 and { u n } n N N ε n be such that J ε n ( u n ) d V 0 . Then there exists { y ̃ n } n N R N such that { v n } n N = { u n ( + y ̃ n ) } n N has a convergent subsequence in Y V 0 . Moreover, up to a subsequence, { y n } n N = { ε n y ̃ n } n N is such that y n y 0M.

Proof.

Proceeding as in the proof of Lemma 3.4, we see that u n X ε n C for all n N . Due to J ε n ( u n ) d V 0 > 0 , u n X ε n 0 . Then, arguing as in the proof of Lemma 4.2, we can find a sequence { y ̃ n } n N R N and constants R, β > 0 such that

lim inf n B R ( y ̃ n ) | u n | q d x β .

Put v n ( x ) = u n ( x + y ̃ n ) . Then, { v n } n N is bounded in Y V 0 , and, going to a subsequence if necessary, we may assume that v n v ≢ 0 in Y V 0 . For each n N , take t n > 0 such that v ̃ n = t n v n M V 0 , and set y n = ε n y ̃ n . From { u n } n N N ε n and (g 2), we derive that

d V 0 E V 0 ( v ̃ n ) J ε n ( t n u n ) J ε n ( u n ) = d V 0 + o n ( 1 ) ,

which ensures that

(5.11) E V 0 ( v ̃ n ) d V 0  and  { v ̃ n } n N M V 0 .

Furthermore, { v ̃ n } n N is bounded in Y V 0 , and thus, up to extracting a subsequence, v ̃ n v ̃ in Y V 0 . Utilizing standard arguments, we may suppose that, up to a subsequence, t n t 0 ∈ (0, ∞). From the uniqueness of the weak limit, we deduce that v ̃ = t 0 v 0 . By (5.11) and Lemma 4.3, we get v ̃ n v ̃ in Y V 0 , and so v n v in Y V 0 . Moreover,

E V 0 ( v ̃ ) = d V 0  and  E V 0 ( v ̃ ) , v ̃ = 0 .

In what follows, we show that { y n } n N admits a bounded subsequence in R N . Assume by contradiction that there exists a subsequence of { y n } n N , still denoted by itself, such that |y n | → ∞. From J ε n ( u n ) , u n = 0 and J ε n ( u n ) d V 0 , we can infer that u n B for all sufficiently large n N . Therefore, by Lemma 3.2, we know that

(5.12) | K ̃ ε n ( u n ) | 0 2  for all large  n .

Choose R > 0 such that Λ ⊂ B R (0). Then, for n large enough, |y n | > 2R, and for each x B R / ε n ( 0 ) we have

| ε n x + y n | | y n | | ε n x | > R .

Using J ε n ( u n ) , u n = 0 , a change of variable, (5.12), the definition of g, f ̃ ( t ) V 0 0 ( t p 1 + t q 1 ) , v n v in Y V 0 and the dominated convergence theorem, we see that

v n s , p p + v n s , q q 0 2 R N g ( ε n x + y n , v n ) v n d x 0 2 B R / ε n ( 0 ) f ̃ ( v n ) v n d x + 0 2 B R / ε n c ( 0 ) f ( v n ) v n d x 1 2 B R / ε n ( 0 ) V 0 | v n | p + | v n | q d x + o n ( 1 ) ,

which gives

v n s , p p + v n s , q q = o n ( 1 ) .

Since v n v ≢ 0 in Y V 0 , we reach a contradiction. Hence, { y n } n N is bounded in R N , and, up to a subsequence, we may assume that y n y 0. If y 0 Λ ̄ , then we can argue as above to achieve v n → 0 in Y V 0 , which is absurd. Thus, y 0 Λ ̄ . Now, suppose by contradiction that V(y 0) > V 0. From v ̃ n v ̃ in Y V 0 , Fatou’s lemma and the invariance of R N by translations, we deduce that

d V 0 = E V 0 ( v ̃ ) < lim inf n 1 p [ v ̃ n ] s , p p + 1 q [ v ̃ n ] s , q q + R N V ( ε n x + y n ) 1 p | v ̃ n | p + 1 q | v ̃ n | q d x 1 2 R N 1 | x | μ * F ( v ̃ n ) F ( v ̃ n ) d x lim inf n J ε n ( t n u n ) lim inf n J ε n ( u n ) = d V 0 ,

that is a contradiction. Therefore, V(y 0) = V 0 and y 0 Λ ̄ . Thanks to (V 2), y 0 ∉ ∂Λ, and so y 0M. The proof of the lemma is now complete. □

Let us define

N ̃ ε = u N ε : J ε ( u ) d V 0 + π ( ε ) ,

where π ( ε ) = sup y M | J ε ( Φ ε ( y ) ) d V 0 | . By Lemma 5.1, we know that π(ɛ) → 0 as ɛ → 0. By the definition of π(ɛ), we have that, for all yM and ɛ > 0, Φ ε ( y ) N ̃ ε and thus N ̃ ε . Now we prove an interesting relationship between N ̃ ε and the barycenter map.

Lemma 5.3.

For every δ > 0, it holds

lim ε 0 sup u N ̃ ε d i s t ( β ε ( u ) , M δ ) = 0 .

Proof.

Let ɛ n → 0 as n → ∞. Then there exists { u n } n N N ̃ ε n such that

d i s t ( β ε n ( u n ) , M δ ) = sup u N ̃ ε n d i s t ( β ε n ( u ) , M δ ) + o n ( 1 ) .

To accomplish our aim, it suffices to find { y n } n N M δ such that

(5.13) lim n | β ε n ( u n ) y n | = 0 .

Because E V 0 ( t u n ) J ε n ( t u n ) for all t ≥ 0 and n N , and { u n } n N N ̃ ε n N ε n , we have

d V 0 c ε n J ε n ( u n ) d V 0 + π ( ε n ) ,

which yields J ε n ( u n ) d V 0 . According to Lemma 5.2, there is { y ̃ n } R N such that { u n ( + y ̃ n ) } n N has a convergent subsequence in Y V 0 . Moreover, up to a subsequence, y n y 0M where { y n } n N = { ε n y ̃ n } n N . Hence,

β ε n ( u n ) = y n + R N Υ ( ε n z + y n ) y n ( | u n ( z + y ̃ n ) | p + | u n ( z + y ̃ n ) | q ) d z R N ( | u n ( z + y ̃ n ) | p + | u n ( z + y ̃ n ) | q ) d z y 0 .

Since y n M δ for all n sufficiently large, the sequence { y n } n N fulfills (5.13). □

We finalize this section by presenting a relationship between the topology of the set M and the number of solutions of the modified problem (3.1).

Theorem 5.1.

Assume that (V 1)–(V 2) and (f 1)–(f 4) hold. Then, for all δ > 0 such that M δ ⊂ Λ, there exists ε ̄ δ > 0 such that, for all ε ( 0 , ε ̄ δ ) , problem (3.1) has at least cat M δ ( M ) positive solutions.

Proof.

We argue as in the proof of Theorem 5.2 in Ref. [14]. For each ɛ > 0, we define α ε : M S ε by setting α ε ( y ) = m ε 1 ( Φ ε ( y ) ) . By Lemma 5.1, we know that

lim ε 0 ψ ε ( α ε ( y ) ) = lim ε 0 J ε ( Φ ε ( y ) ) = d V 0  uniformly in  y M .

Then we can find ε ̂ > 0 such that the set S ̃ ε = { w S ε : ψ ε ( w ) d V 0 + π 0 ( ε ) } is nonempty for all ε ( 0 , ε ̂ ) , due to α ε ( M ) S ̃ ε . Here π 0 ( ε ) = sup y M | ψ ε ( α ε ( y ) ) d V 0 | 0 as ɛ → 0. From the above considerations, and in light of Lemmas 3.3-(iii), 5.1, 5.3 and (5.10), we see that there exists ε ̄ = ε ̄ δ > 0 such that the following diagram is well-defined for every ε ( 0 , ε ̄ ) :

M Φ ε N ̃ ε m ε 1 S ̃ ε m ε N ̃ ε β ε M δ .

According to (5.10), for ɛ > 0 small enough, we can select a function θ(ɛ, y), with | θ ( ε , y ) | < δ 2 uniformly in yM, such that β ɛ ɛ (y)) = y + θ(ɛ, y) for all yM. Define H(t, y) = y + (1 − t)θ(ɛ, y) for (t, y) ∈ [0, 1] × M. Clearly, H [0, 1] × MM δ is continuous, H(0, y) = β ɛ ɛ (y)) and H(1, y) = y for all yM. As a result, H(t, y) is a homotopy between β ɛ ◦Φ ɛ = (β ɛ m ɛ )◦α ɛ and the inclusion map id: MM δ . Therefore, by Lemma 6.3.21 in Ref. [1],

(5.14) cat S ̃ ε ( S ̃ ε ) cat M δ ( M ) .

On the other hand, let us choose a function π(ɛ) > 0 such that π(ɛ) → 0 as ɛ → 0 and d V 0 + π ( ε ) is not a critical level for J ε . For ɛ > 0 small enough, we derive from Corollary 3.1 that ψ ɛ satisfies the Palais–Smale condition in S ̃ ε . Invoking Theorem 6.3.20 in Ref. [1], we deduce that ψ ɛ has at least cat S ̃ ε ( S ̃ ε ) critical points on S ̃ ε . By Proposition 3.1-(d) and (5.14), we conclude that J ε admits at least cat M δ ( M ) critical points in N ̃ ε . □

6 Proof of Theorem 1.1

This last section is devoted to the proof of Theorem 1.1. We begin with an auxiliary result which will play an important role in studying the behavior of the maximum points of solutions to (1.1).

Lemma 6.1.

Let ɛ n → 0 and { u n } n N N ̃ ε n be a sequence of solutions to (3.1). Then J ε n ( u n ) d V 0 , and there exists { y ̃ n } n N R N such that { v n } n N = { u n ( + y ̃ n ) } n N L ( R N ) and for some C > 0 it holds

| v n | C  for all  n N .

Moreover,

(6.1) v n ( x ) 0  as  | x |  uniformly in  n N .

Proof.

In view of J ε n ( u n ) d V 0 + π ( ε n ) , with π(ɛ n ) → 0 as n → ∞, we can argue as in the proof of Lemma 5.2 to show that J ε n ( u n ) d V 0 . Then, applying Lemma 5.2, there exists { y ̃ n } n N R N such that, up to a subsequence, { v n } n N = { u n ( + y ̃ n ) } n N strongly converges in Y V 0 and ε n y ̃ n y 0 M . Note that, for each n N , v n satisfies

( Δ ) p s v n + ( Δ ) q s v n + V ( ε n x + ε n y ̃ n ) v n p 1 + v n q 1 = K ̃ n ( v n ) g ( ε n x + ε n y ̃ n , v n )  in  R N ,

where

K ̃ n ( v n ) ( x ) = 1 | x | μ * G ( ε n x + ε n y ̃ n , v n ) .

Since { v n } n N is bounded in Y V 0 , we can proceed as in the proof of Lemma 3.2 to see that there exists C ̃ 0 > 0 such that

(6.2) sup n N K ̃ n ( v n ) C ̃ 0 .

On account of (3.2) and (6.2), we can repeat the Moser iteration argument developed in the proof of Lemma 4.1 in Ref. [38] to deduce that |v n |C 1 for all n N . This estimate and V L ( R N ) yield |ϰ n |C 2 for all n N , where

ϰ n ( x ) = V ( ε n x + ε n y ̃ n ) v n p 1 + v n q 1 + K ̃ n ( v n ) ( x ) g ( ε n x + ε n y ̃ n , v n ) .

Using the fact that ( Δ ) p s v n + ( Δ ) q s v n = ϰ n in R N , { v n } n N is bounded in L ( R N ) Y V 0 , { ϰ n } n N is bounded in L ( R N ) , and applying Corollary 2.1 in Ref. [38], we have that v n C 0 , α ( R N ) C 3 for all n N , where α ∈ (0, 1) is independent of n. Since { v n } n N strongly converges in Y V 0 , we conclude that v n (x) → 0 as |x| → ∞ uniformly in n N . □

Remark 6.1.

The condition V L ( R N ) is only used to obtain | ϰ n | C 2 for all n N (which permits to arrive at v n C 0 , α ( R N ) C 3 for all n N ). However, this restriction on V can be removed and we can prove that v n (x) → 0 as |x| → ∞ uniformly in n N by adapting the arguments performed in the proof of Theorem 1.1 in Ref. [47].

Proof of Theorem 1.1.

Fix δ > 0 such that M δ ⊂ Λ. We first prove that there exists ε ̃ δ > 0 such that, for every ε ( 0 , ε ̃ δ ) and every solution u ε N ̃ ε of (3.1), it holds

(6.3) | u ε | L Λ ε c < a .

Arguing by contradiction, we assume that, for some sequence ɛ n → 0, we can produce { u n } n N = { u ε n } n N N ̃ ε n such that J ε n ( u n ) = 0 and

(6.4) | u n | L Λ ε n c a .

Because J ε n ( u n ) d V 0 + π ( ε n ) , with π(ɛ n ) → 0 as n → ∞, we can proceed as in the proof of Lemma 5.2 to infer that J ε n ( u n ) d V 0 . Then, invoking Lemma 5.2, there is { y ̃ n } n N R N such that, up to a subsequence, v n = u n ( + y ̃ n ) v in Y V 0 and ε n y ̃ n y 0 M .

Let r > 0 be such that B r (y 0) ⊂ B 2r (y 0) ⊂ Λ. Hence, B r ε n ( y 0 ε n ) Λ ε n . Furthermore, for all y B r ε n ( y ̃ n ) , we have

y y 0 ε n | y y ̃ n | + y ̃ n y 0 ε n < 1 ε n ( r + o n ( 1 ) ) < 2 r ε n  for all  n  sufficiently large. 

Thus, for these values of n, we know that

Λ ε n c B r ε n c ( y ̃ n ) .

Taking (6.1) into account, there exists R > 0 such that

v n ( x ) < a  for all  | x | R  and  n N ,

and so

u n ( x ) < a  for all  x B R c ( y ̃ n )  and  n N .

On the other hand, there is n 0 N such that, for all nn 0,

Λ ε n c B r ε n c ( y ̃ n ) B R c ( y ̃ n ) .

As a result, u n (x) < a for all x Λ ε n c and nn 0, which contradicts (6.4).

Let ε ̄ δ > 0 be given by Theorem 5.1 and put ε δ = min { ε ̃ δ , ε ̄ δ } . Fix ɛ ∈ (0, ɛ δ ). Invoking Theorem 5.1, we obtain at least cat M δ ( M ) positive solutions to (3.1). If u ɛ is one of these solutions, we have that u ε N ̃ ε , and we can use (6.3) and the definition of g to deduce that g(ɛ⋅, u ɛ ) = f(u ɛ ). Therefore, u ɛ is a solution of (1.1), and so (1.1) admits at least cat M δ ( M ) positive solutions.

Now we consider ɛ n → 0 and take a sequence { u n } n N X ε n of solutions to (1.1) as above. Our purpose is to investigate the behavior of the maximum points of u n . We notice that thanks to the definition of g and (g 1), there exists ν ∈ (0, a) such that

(6.5) g ( x , t ) t V 0 0 ( t p + t q )  for all  x R N  and  0 t ν .

Arguing as before, we can find R > 0 such that

(6.6) | u n | L ( B R c ( y ̃ n ) ) < ν .

Up to a subsequence, we may also assume that

(6.7) | u n | L ( B R ( y ̃ n ) ) ν .

Indeed, if (6.7) is not valid, then |u n | < ν. Hence, exploiting J ε n ( u n ) , u n = 0 , the fact that

K ̃ ε n ( u n ) 0 2  for all large  n N ,

and (6.5), we arrive at

u n V ε n , p p + u n V ε n , q q R N K ̃ ε n ( u n ) g ( ε n x , u n ) u n d x V 0 2 R N | u n | p + | u n | q d x  for all large  n ,

which gives a contradiction. Consequently, (6.7) holds. Let now p n be a global maximum point of u n . On account of (6.6) and (6.7), we see that p n = y ̃ n + q n for some q n B R (0). Since ε n y ̃ n y 0 M and |q n | < R for all n N , we have that ɛ n p n y 0 which combined with the continuity of V yields

lim n V ( ε n p n ) = V ( y 0 ) = V 0 .

This completes the proof of Theorem 1.1. □


Corresponding author: Vincenzo Ambrosio, Dipartimento di Ingegneria Industriale e Scienze Matematiche, Università Politecnica Delle Marche, via Brecce Bianche, 12 60131 Ancona, Italy, E-mail:

  1. Research ethics: Not applicable.

  2. Author contributions: The author has accepted responsibility for the entire content of this manuscript and approved its submission.

  3. Competing interests: Author states no conflict of interest.

  4. Research funding: The author is partially supported by INdAM-GNAMPA Project CUP E53C23001670001.

  5. Data availability: Not applicable.

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Received: 2023-05-10
Accepted: 2024-01-11
Published Online: 2024-04-05

© 2024 the author(s), published by De Gruyter, Berlin/Boston

This work is licensed under the Creative Commons Attribution 4.0 International License.

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