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Polygons as maximizers of Dirichlet energy or first eigenvalue of Dirichlet-Laplacian among convex planar domains

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Published/Copyright: November 11, 2022

Abstract

We prove that solutions to several shape optimization problems in the plane, with a convexity constraint on the admissible domains, are polygons. The main terms of the shape functionals we consider are either the Dirichlet energy E f ( Ω ) of the Laplacian in the domain Ω or the first eigenvalue λ 1 ( Ω ) of the Dirichlet-Laplacian. Usually, one considers minimization of such functionals (often with measure constraint), as for example for the famous Saint-Venant and Faber-Krahn inequalities. By adding the convexity constraint (and possibly other natural constraints), we instead consider the rather unusual and difficult question of maximizing these functionals. This paper follows a series of papers by the authors, where the leading idea is that a certain concavity property of the shape functional that is minimized leads optimal shapes to locally saturate their convexity constraint, which geometrically means that they are polygonal. In these previous papers, the leading term in the shape functional was usually the opposite of the perimeter, for which the aforementioned concavity property was rather easy to obtain through computations of its second order shape derivative. By carrying classical shape calculus, a similar concavity property can be observed for the opposite of E f ( Ω ) or λ 1 ( Ω ) when shapes are smooth and convex. The main novelty in the present paper is the proof of a weak convexity property of E f ( Ω ) and λ 1 ( Ω ) among planar convex shapes, namely rather nonsmooth shapes. This involves new computations and estimates of the second order shape derivatives of E f ( Ω ) and λ 1 ( Ω ) interesting for themselves.


Communicated by Frank Duzaar


Award Identifier / Grant number: ANR-18-CE40-0013 SHAPO

Award Identifier / Grant number: RGPIN 261879-2013

Funding statement: This work was partially supported by the project ANR-18-CE40-0013 SHAPO financed by the French Agence Nationale de la Recherche (ANR). Jimmy Lamboley acknowledges the support of the University of Ottawa for his visits in Canada. Arian Novruzi acknowledges the support of the Natural Sciences and Engineering Research Council of Canada (NSERC) [RGPIN 261879-2013], as well as of the École Normale Supérieure de Rennes and of the Université Paris-Dauphine for his visits in France.

A Appendix

The following proposition gives a complete expression for E f ′′ ( Ω ) ( V , V ) in terms of boundary integrals in cases when Ω is smooth or convex, and extends the definition of | U | 2 as an element of ( W 1 , ( Ω ) ) in the case Ω is convex.

Proposition A.1.

Under the assumptions of Theorem 2.4, except for Ω, formula (2.5) holds if:

  1. Ω is of class C 2 , σ , for any σ ( 0 , 1 ) , where the term Ω | U | 2 | V | 2 is understood with the curvature in the classical sense, or

  2. Ω is convex, and in this case the term with is understood as

    (A.1) Ω | U | 2 | V | 2 := - Ω [ j i U ] i ( j U | V | 2 ) = lim ε 0 Ω ε ε | U | 2 | V | 2 𝑑 s ε .

Similarly, under the assumptions of Theorem 2.7, the same statements as above hold for λ 1 ′′ ( Ω ) ( V , V ) given by

λ 1 ′′ ( Ω ) ( V , V ) = Ω | U 1 | 2 + Ω ( 1 2 λ 1 ( Ω ) ( ν | U 1 | 2 ) ( V ν ) 2 + Ω 1 2 ( ν U 1 ) 2 | V | 2 + ( ν U 1 ) 2 ( V τ ) ( s V ν ) ) 𝑑 s .

Proof.

First we prove the result for E f ′′ ( Ω ) . In both (i) and (ii) cases we follow the proof of Theorem 2.4.

In case (i), we can repeat all the calculus of Theorem 2.4 with Ω ε replaced by Ω (and so, without the need to consider the limits of different terms as ε tends to zero).

In case (ii), we need to identify lim ε 0 K 3 ( ε ) . For this we use the following extensions for the normal and tangential vectors on Ω ε , ν ε = - U | U | , τ ε = ν ε = - U | U | . Then we have

K 3 ( ε ) = Ω ε ε | U | 2 | V | 2
= - Ω ε | U | 2 ( ν ε s ε τ ) | V | 2
= - Ω ε | U | 2 ( ν ε [ U | U | ] U | U | ) | V | 2
= - Ω ε | U | 2 ( ν ε i [ j i U | U | - i U j k U k U | U | 3 ] j U | U | ) | V | 2
= - Ω ε ν ε i ( [ j i U ] j U | V | 2 ) + Ω ε ( ν i i U ) [ j k U k U j U | U | 2 ] | V | 2
= - Ω ε i ( [ j i U ] j U | V | 2 )
(A.2) = - Ω ε [ j i U ] i ( j U | V | 2 ) ε 0 - Ω [ j i U ] i ( j U | V | 2 ) = : Ω | U | 2 | V | 2 .

The proof of the result for λ 1 ′′ ( Ω ) is similar to the proof for E f ′′ ( Ω ) and we do not present it here. ∎

Remark A.2.

In the case Ω is convex, | U | 2 is not well defined because, for example, is unbounded and | U | is zero at a corner. However, as the calculus proceeding (A.2) holds with | V | 2 = w ¯ , for every w W 1 , ( Ω ) and w ¯ the extension of w given by Lemma 1.12, it implies that (A.1) holds with | V | 2 = w ¯ . This defines | U | 2 as an element of ( W 1 , ( Ω ) ) , the dual space of W 1 , ( Ω ) .

We conclude with an interesting consequence of Theorem 2.4. A priori we expect a continuity property with respect to V for the norm of differentiability which is W 1 , . But one can actually get the following improved continuity property.

Corollary A.3.

For v = ( v 1 , v 2 ) W 1 , ( Ω ; R 2 ) let V = ( v ¯ 1 , v ¯ 2 ) be the extension of v as given by Lemma 1.12. Then, under the same assumptions as in theorem 2.4 we have:

  1. The map v W 1 , ( Ω ; 2 ) E f ( Ω ) ( V ) extends continuously in L 1 ( Ω ; 2 ) and the extension is given by ( 2.7 ).

  2. Similarly, the map v W 1 , ( Ω ; 2 ) E f ′′ ( Ω ) ( V , V ) extends continuously in H 1 ( Ω ; 2 ) L ( Ω ; 2 ) and the extension is given by ( 2.5 ).

Proof.

First we note that the extension H of Lemma 1.12 extends continuously in L 1 ( Ω ) and H 1 ( Ω ) . Then for (i) we note that (2.7) is continuous with respect to V L 1 ( Ω ; 2 ) , so the claim follows from the continuity of H in L 1 . For claim (ii), first we note that all the terms of (2.5) except Ω ( ν U ) 2 | V | 2 are continuous in H 1 ( Ω ) with respect to V, so they are continuous with respect to v in H 1 ( Ω ; 2 ) thanks to the continuity of H in H 1 . For the term Ω ( ν U ) 2 | V | 2 , from (A.1) with w ¯ = | V | 2 we see that this term is continuous with respect to V in H 1 ( Ω ; 2 ) L ( Ω ; 2 ) and we conclude using again the continuity of H in H 1 L . ∎

Lemma A.4.

The equivalence of seminorms (4.10) holds.

Proof.

It is classical, see for example [7], that for h H 1 / 2 ( Ω ) , its seminorm is given by

(A.3) | h | H 1 / 2 ( B ) 2 = B 𝑑 s y B | h ( x ) - h ( y ) | 2 | x - y | 2 𝑑 s x .

For θ , η ( - π , π ) , x = ( cos θ , sin θ ) , y = ( cos η , sin η ) we set (with a slight abuse of notations) h ( θ ) = h ( x ) , h ( η ) = h ( y ) . Then (A.3) is equal to

| h | H 1 / 2 ( B ) 2 = - π π 𝑑 η - π π | h ( θ ) - h ( η ) ) | 2 4 sin 2 ( θ - η 2 ) 𝑑 θ = I 1 + I 2 + I 3 ,

where

I i = A i | h ( θ ) - h ( η ) | 2 4 sin 2 ( θ - η 2 ) 𝑑 θ 𝑑 η , i = 1 , 2 , 3 ,

and

A 1 = { ( θ , η ) ( - π , π ) 2 : - π < θ - η < π } ,
A 2 = { ( θ , η ) ( - π , π ) 2 : π < θ - η < 2 π } = { ( θ , η ) ( 0 , π ) × ( - π , 0 ) : π < θ - η < 2 π } ,
A 3 = { ( θ , η ) ( - π , π ) 2 : - 2 π < θ - η < - π } = { ( θ , η ) ( - π , 0 ) × ( 0 , π ) : - 2 π < θ - η < - π } .

Let θ ^ = θ - 2 π , η ^ = η , A ^ 2 = A 2 - ( 2 π , 0 ) . Then

I 2 = A 2 | h ( θ ) - h ( η ) ) | 2 4 sin 2 ( θ - η 2 ) 𝑑 θ 𝑑 η = A 2 | h ( θ ^ + 2 π ) - h ( η ^ ) | 2 4 sin 2 ( θ ^ - η ^ 2 + π ) 𝑑 θ 𝑑 η = A ^ 2 | h ( θ ^ ) - h ( η ^ ) | 2 4 sin 2 ( θ ^ - η ^ 2 ) 𝑑 θ ^ 𝑑 η ^ .

One can check that

A ^ 2 = { ( θ ^ , η ^ ) ( - 2 π , - π ) × ( - π , 0 ) : - π < θ ^ - η ^ < 0 } .

Similarly, let θ ^ = θ + 2 π , η ^ = η , A ^ 3 = A 3 + ( 2 π , 0 ) . Then

I 2 = A 3 | h ( θ ) - h ( η ) ) | 2 4 sin 2 ( θ - η 2 ) 𝑑 θ 𝑑 η = A 3 | h ( θ ^ - 2 π ) - h ( η ^ ) | 2 4 sin 2 ( θ ^ - η ^ 2 - π ) 𝑑 θ 𝑑 η = A ^ 3 | h ( θ ^ ) - h ( η ^ ) | 2 4 sin 2 ( θ ^ - η ^ 2 ) 𝑑 θ ^ 𝑑 η ^ .

Similarly to A ^ 2 , one can check that

A ^ 3 = { ( θ ^ , η ^ ) ( π , 2 π ) × ( 0 , π ) : 0 < θ ^ - η ^ < π } .

Therefore we get

| h | H 1 / 2 ( B ) 2 = I 1 + I 2 + I 3 = A ^ 1 A 2 A ^ 3 | h ( θ ^ ) - h ( η ^ ) | 2 4 sin 2 ( θ ^ - η ^ 2 ) 𝑑 θ ^ 𝑑 η ^ = - π π 𝑑 η { | θ - η | < π } | h ( θ ) - h ( η ) | 2 4 sin 2 ( θ - η 2 ) 𝑑 θ ,

because A 1 A ^ 2 A ^ 3 is the parallelogram { ( θ , η ) : η ( - π , π ) , | θ - η | < π } . Note that we have

1 π | θ - η | sin | θ - η 2 | | θ - η | 2 for all  ( θ , η ) A 1 A ^ 2 A ^ 3 ,

which combined with the last equality proves the claim. ∎

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Received: 2022-03-05
Revised: 2022-09-02
Accepted: 2022-09-05
Published Online: 2022-11-11
Published in Print: 2024-04-01

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