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Jacobian of weak limits of Sobolev homeomorphisms

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Published/Copyright: June 21, 2016

Abstract

Let Ω be a domain in n, where n=2,3. Suppose that a sequence of Sobolev homeomorphisms fk:Ωn with positive Jacobian determinants, J(x,fk)>0, converges weakly in W1,p(Ω,n), for some p1, to a mapping f. We show that J(x,f)0 a.e. in Ω. Generalizations to higher dimensions are also given.

MSC 2010: 26B10; 46E35

1 Introduction

The main goal of this note is to establish when the sign of the Jacobian is preserved under W1,p-weak convergence. Such a question pops out naturally in the variational approach to Geometric Function Theory (GFT) [2, 14, 22] and Nonlinear Elasticity (NE) [1, 4, 6, 19, 24, 25]. Both theories GFT and NE deal with minimizing sequences of Sobolev homeomorphisms. In the context of NE, one typically deals with two-dimensional or three-dimensional models and require that the deformation gradients belong to M+n×n, where Mm×n={real m×n matrices}, and M+n×n={AMn×n:detA>0}. The infimum of the energy is not attained, in general, at a homeomorphism; interpenetration of matter may occur. Even in a special case of Dirichlet energy injectivity is often lost when passing to the weak limit of the minimizing sequence, [3, 13, 15, 16]. Further examinations are needed to know the properties of such singular minimizers.

Throughout this text Ω will be a domain in n. The class of Sobolev mappings f:Ωn with nonnegative Jacobian determinant, J(x,f)=detDf(x)0 almost everywhere, is closed under the weak convergence in W1,p(Ω,n) provided pn (see [14, Theorem 8.4.2]). However, if p<n, passing to the weak W1,p-limit of a sequence with nonnegative Jacobians one may lose the sign of the Jacobian. Indeed, there exists a sequence of Sobolev mappings fk:Ωn with J(x,fk)>0 almost everywhere such that the sequence converges weakly in W1,p(Ω,n), p<n, to the mapping f(x)=(-x1,x2,,xn), see [14, p. 181]. Moreover, following the construction in [18] such mappings fk can be made continuous. However, it is not obvious at all as to whether one can make a similar example with fk being homeomorphisms. This is the subject of our result here. Here [n2] denotes the integer part, i.e. [22]=1, [32]=1 and so on.

Theorem 1.

Let ΩRn be a domain and let p1 for n{2,3} and p>[n2] for n4. Suppose that a sequence of Sobolev homeomorphisms fk:ΩRn with J(x,fk)0 converges weakly in W1,p(Ω,Rn) to a mapping f and further assume that J(x,fk) is not a.e. zero. Then J(x,f)0 a.e. in Ω.

It is worth noting that in Theorem 1 the Jacobian J(x,f) can have very different behavior than the Jacobians in the sequence without knowing that J(x,fk)>0 on a set of positive measure. Indeed, there exists a sequence of Sobolev homeomorphisms fk with J(x,fk)=0 a.e., converging weakly in W1,p(Ω,n), 1p<n, to the mapping f(x)=x. Let us briefly sketch this using the construction from [10]: we cover Ω by cubes of diameter less than 1k and on each cube we follow the construction from [10] to obtain a homeomorphism with zero Jacobian a.e. It is possible to make the W1,p-norm of the sequence uniformly bounded and hence find a weakly convergent subsequence. Furthermore, it follows from the construction that the sequence fk converges uniformly to the identity. This also shows that there is a sequence with J(x,fk)=0 a.e. converging weakly in W1,p(Ω,n), 1p<n, to f(x)=(-x1,x2,,xn).

Recently it was shown in [12] and [5] that a Jacobian of a Sobolev homeomorphism can change sign in dimension n4 for 1p<[n2].

2 Preliminaries

2.1 Degree and Jacobian

There are two basic approaches to the notion of local degree for a mapping, the algebraic (see e.g. Dold [7]) and the analytic (see e.g. Lloyd [17]). Both of these notions try to capture the idea of counting the preimages of a target point. For a continuous mapping f:Ωn and ynf(Ω) the degree of f at y with respect to Ω is denoted by deg(f,Ω,y). If f:Ωn is a homeomorphism, then deg(f,Ω,y) is either 1 or -1 for all yf(Ω), see e.g. [17, Section IV.5] or [21, Section II.2.4, Theorem 3]. We say that a homeomorphism f is sense-preserving if deg(f,Ω,y)1. For a linear map A:nn with detA0, it is easy to check from the definition that

(1)deg(A,Ω,y)=sgndetA.

We recall the following corollary [2, Corollary 2.8.2]. Given a homeomorphism f:Ωn suppose that f is differentiable at x with J(x,f)0. Then we have

(2)deg(f,Ω,f(x))=sgnJ(x,f).

We will use the fact that the topological degree is stable under homotopy. That is for every continuous mapping H:Ω¯×[0,1]n and yn such that yH(Ω,t) for all t[0,1] we have

(3)deg(H(,0),Ω,y)=deg(H(,1),Ω,y).

2.2 Differentiability of Sobolev mappings

A Sobolev homeomorphism fW1,p(Ω,n) is differentiable almost everywhere if p>n-1, n3, and p1 for n=2, see [9, 20, 26]. We will also need a generalization of the concept of differentiability, which is obtained by replacing the ordinary limit by an approximate limit, see e.g. [8, Section 6.1.3]. It is known that a Sobolev mapping fWloc1,1(Ω,n) is approximatively differentiable almost everywhere, see e.g. [8, Section 6.1.2, Theorem 2]. Moreover, such a mapping is L1-differentiable almost everywhere [27]; that is, for almost every xΩ we have

(4)limr0B(x,r)|f(x)-f(x)-Df(x)(x-x)r|dx=0.

Hereafter, the notation B(x,r) means the integral average over the n-dimensional ball

B(x,r)={xn:|x-x|<r}.

In order to illustrate our ideas and for reader’s comprehension, we first prove Theorem 1 in the simpler cases p1, n=2; and p>n-1, n3, where we can avoid some technicalities.

3 Proof of Theorem 1 for p>n-1, n3, and p1, n=2

Each homeomorphism fj is either sense-preserving or sense-reversing. Under our assumptions there exists a point xj such that fj is differentiable at xj, see Section 2.2, and J(xj,fj)>0. By (2) we know that the degree of fj is one and hence each fj is sense-preserving.

As fjf in Lp, p>1, we know that Ω|Df|p is uniformly bounded and hence we can find a Radon measure μ and a subsequence (which we will denote again as fj) such that

|Dfj|pw*μ in measures.

Moreover, for p=1 we can use De La Vale Pousin characterization of weak convergence in L1 and we can find an continuous convex function Φ:[0,)[0,) such that

(5)Φ(t)t is increasing,limtΦ(t)t=andΩΦ(|Dfj|)1.

It follows that we can find a Radon measure μ and a subsequence (which we will denote again as fj) such that

Φ(|Dfj|)w*μ in measures.

It is well known that for almost every xΩ we have

(6)Mμ(x):=supr>0μ(B(x,r)Ω)|B(x,r)|<.

Let δ>0. For the contrary we suppose that there is xΩ such that (4) and (6) hold at x and

J(x,f)<0.

Without loss of generality we may and do assume that

(7)Df(x)=(10001000-1).

Using (4) we can find 0<r1 small enough such that for all 0<r<r1 we have

B(x,r)|f(x)-f(x)-Df(x)(x-x)r|dx<δn2.

Since the sequence of mappings fj converges to f weakly in W1,p(Ω,n), we have that the sequence of mappings fj converges to f strongly in Lloc1(Ω,n). Now, we may pick up an index j large enough such that for all jj,

Ω|f(x)-fj(x)|dx<|B(0,1)|rn+1δn2.

The last two inequalities imply that for all 0<r<r1 we have

(8)B(x,r)|fj(x)-f(x)-Df(x)(x-x)r|dx<δn.

Our next goal is to prove the following:

  1. if p>n-1, then there exists a constant C (depending only on p and n) such that for all 0<r<r1 and jj,

    δn-1-prnCB(x,r)|Dfj|p,
  2. if n=2 and p=1, there exist a constant C and such that for all 0<r<r1 and jj there is a set AB(x,r) such that

    |A|<Cδ|B(x,r)| and r2CA|Dfj|.

These would lead to a desired contradiction. Indeed, choose 0<r<r1 such that μ(B(x,r))=0 and in case (i) we obtain after passing to a limit in j that

δn-1-pClimjB(x,r)|Dfj|p=Cμ(B(x,r)Ω)|B(x,r)|CMμ(x).

After passing δ0+ we obtain a contradiction with (6). In case (ii) we can use Jensen’s inequality and (5) to obtain

B(x,r)Φ(|Dfj|)|A|r2AΦ(|Dfj|)|A|r2Φ(A|Dfj|)|A|r2Φ(Cr2|A|)CδΦ(Cδ).

Similarly as above we obtain in the limit that

CδΦ(Cδ)CMμ(x)

and now passing to a limit δ0+ we obtain a contradiction using (5).

Proof of (i).

We simplify the notation and write

φj(x)=|fj(x)-f(x)-Df(x)(x-x)|andBs=B(x,s).

In the following we use the notation k(A) for the k-dimensional Hausdorff measure of the set A. We claim that the set of radii

IG={s[0,r]:n-1({xBs:φj(x)δr})<5nδn-1n-1(Bs)}

has measure at least 3r4, i.e. |IG|3r4, otherwise

Br|φj(x)r|dx1|Br|0r45nδn-1n-1(Bs)|δrr|ds=5nδn|Br4||Br|

which contradicts (8).

On the other hand, the key point in our argument is that for xΩ and for every s(0,r) we can find β=β(s)Bs such that

(9)φj(β)45sfor every j=1,2,.

Finding such a point β is the only place where we use the homeomorphism assumption of fj. Suppose on the contrary that (9) fails for every βBs and for some j{1,2,}. For xBs and t[0,1] we consider the following homotopy:

H(x,t):=(1-t)(fj(x)-f(x))+tDf(x)(x-x).

By (7) we know that Df(x) is an isometry and thus |Df(x)z|=|z|. Furthermore, if (9) does not hold, then for all xBs we have

|H(x,t)||Df(x0)(x-x0)|-(1-t)|fj(x)-f(x0)-Df(x0)(x-x0)|s-(1-t)45s>0.

It follows that H(x,t)0 for every xBs and all t[0,1]. Thus, by (3) and (1),

deg(fj,Bs,f(x))=sgndet(Df(x))=-1.

This contradicts the fact that fj is sense-preserving.

We apply the Sobolev embedding theorem [8, Theorem 3 (i), p. 143] on the (n-1)-dimensional spheres. This way for almost every s(0,r) and for all z1,z2B(x,s) we have

(10)|fj(z1)-fj(z2)|C(n,p)|z1-z2|1-n-1p(Bs|Dfj|p)1p.

Now let us fix sIG so that (10) is satisfied on the sphere Bs. Since sIG, we find α=α(s)Bs satisfying

φj(α)<δrand|α-β|C0δs,

where C0 is some fixed constant (which depends only on n). Combining this with (9) we have found α,βBs such that

45s-δr-2C0δs|φj(β)|-|φj(α)|-2|α-β||fj(α)-fj(β)|.

This together with (10) implies that for sIG[r2,r] and δ small enough

(11)Csp(45s-δr-2C0δs)pC(n,p)(δs)p-n+1Bs|Dfj|p.

Integrating inequality (11) over the set IG[r2,r] we obtain (i), finishing the proof of Theorem 1 in the case p>n-1. ∎

Proof of (ii).

We proceed as above. For sIG we can find β=β(s)Bs so that (9) holds. In fact we consider the measurable set

A:={xBr:φj(x)>δr}.

By Chebyshev’s inequality and (8) we obtain

|A|1δrBr|φj(x)|dx1δrδ2r2r=Cδ|Br|.

Let sIG[r2,r]. The point βBs with (9) clearly belongs to ABs and the closest point α on the relative boundary of BsA satisfies

|φj(α)|=δr

by the definition of A. It follows that for every sIG[r2,r] we have

sCBsA|Dfj|.

Integrating this over IG[r2,r] we obtain

r2CA|Dfj|

finishing the proof of (ii). ∎

The above proof was based on the Sobolev embedding theorem on spheres and therefore does not work for p<n-1. To overcome these difficulties we follow Hencl and Malý [11] and use the theory of linking numbers and its topological invariance. For the convenience of the reader we recall the needed properties of linking numbers here.

4 Linking number

We use the notation 𝔹d for the unit ball in d and 𝕊d-1 for the unit sphere. By 𝔹¯d(c,r) we denote the closed ball with center c and radius r>0.

Let n,t,q be positive integers with t+q=n-1. Let us consider the mapping Φ(ξ,η):𝔹¯t+1×𝔹¯q+1n defined coordinatewise as Φ(ξ,η)=x, where

x1=(2+η1)ξ1,
xt+1=(2+η1)ξt+1,
xt+2=η2,
xt+q+1=ηq+1.

Denote by 𝔸 the anuloid

Φ(𝕊t×𝔹q+1)={xn:(x12++xt+12-2)2+xt+22++xn2<1}.

Of course, given x𝔸¯ we can find a unique ξ𝕊t and η𝔹¯q+1 such that Φ(ξ,η)=x. We will denote these as ξ(x) and η(x).

A link is a pair (φ,ψ) of parametrized surfaces φ:𝕊tn, ψ:𝕊qn. The linking number of the link (φ,ψ) is defined as the topological degree

(φ,ψ)=deg(L,𝔸,0),

where the mapping L=Lφ,ψ:𝔸¯n is defined as

L(x)=φ(ξ(x))-ψ¯(-η(x)),

or equivalently

L(Φ(ξ,η))=φ(ξ)-ψ¯(-η),ξ𝕊t,η𝔹q+1,

where ψ¯ is an arbitrary continuous extension of ψ to 𝔹¯q+1 (of course, the degree does not depend on the way how we extend ψ, it depends only on the values on the boundary 𝔸=Φ(𝕊t×𝕊q)). Geometrically speaking, for t=q=1, the linking number is the number of loops of a curve φ around a curve ψ counting orientation into account as +1 or -1. For the introductions to the linking number in 3 and its application to the theory of knots see [23].

The canonical link is the pair (μ,ν), where

μ(ξ)=Φ(ξ,0),ξ𝕊t,
ν(η)=Φ(𝐞1,η),η𝕊q.

For example in dimension n=3 we get that

μ(𝕊1)={x3:x3=0,x12+x22=4},
ν(𝕊1)={x2=0,(x1-2)2+x32=1}.

It is well known that the linking number is a topological invariant. The simple proof of the following proposition can be found in [11].

Proposition 2.

Let n,t,q be positive integers with t+q=n-1. Let f:Bn(4)Rn be a homeomorphism. Then L(fμ,fν) is 1 if f is sense preserving and -1 if f is sense reversing.

Analogously, we can pick a𝔹¯q+1(0,110) and b𝔹¯t+1(𝐞1,110)𝔹¯t+1 and consider the pair

μa(ξ)=Φ(ξ,a),ξ𝕊t,
νb(η)=Φ(b,η),η𝕊q.

Similarly to the previous proposition we have:

Proposition 3.

Let n,t,q be positive integers with t+q=n-1, aB¯q+1(0,110) and bB¯t+1(e1,110)B¯t+1. Let f:Bn(4)Rn be a homeomorphism. Then L(fμa,fνb) is 1 if f is sense preserving and -1 if f is sense reversing.

5 Proof of Theorem 1 for p>[n2], n3, and p1, n=3

Our argument is similar to the proof given in Section 3 and therefore some details are only sketched. By μ we again denote the w* limit of (some subsequence) |Dfj|p for p>[n2] and of Φ(|Dfj|) for p=1 and n=3.

By C1 and C2 we denote a fixed constants whose exact value will be determined later. We fix δ>0 and we choose a point x0 such that (4) and (6) hold and without loss of generality we assume that the derivative of f at x is given by (7).

We fix r1>0 such that for all 0<r<r1 we have

B(x,4r)|f(x)-f(x)-Df(x)(x-x)r|dx<C1δn2

and again for all jj we obtain

(12)B(x,4r)|fj(x)-f(x)-Df(x)(x-x)r|dx<C1δn.

We fix t,q[n2] such that t+q=n-1 (e.g. t=q=n-12 for n odd and t=n-22, q=n2 for n even). Our goal is to prove the following:

  1. if p>[n2] and n3, then there exists a constant C (depending only on p and n) such that for all 0<r<r1 and jj,

    δmin{t,q}-prnCB(x,4r)|Dfj|p,
  2. if p=1 and n=3, we have AB(x,4r) such that

    |A|<C2δ|B(x,4r)|andr3CA|Dfj|.

Analogously to reasoning in Section 3 we obtain a contradiction using min{t,q}-p<0 for p>[n2] and (5) for p=1 and n=3.

Proof of (i).

Without loss of generality we will assume that x=0. We write

φj(x)=|fj(rx)-f(0)-Df(0)rx|.

Let us fix yμa(𝕊t) and denote

Bμa(𝕊t)(y,δ)={xμa(𝕊t):|x-y|<δ},

the ball of radius δ on the link μa(𝕊t). We can clearly choose a constant C1 small enough at the beginning of the proof so that (12) implies that the set of good links

Ia={a𝔹¯q+1(0,110):t(xμa(𝕊t):φj(x)δr)<t(Bμa(𝕊t)(y,δ))},
Ib={b𝔹¯t+1(𝐞1,110)𝔹¯t+1:q(xνb(𝕊q):φj(x)δr)<q(Bνb(𝕊q)(y,δ))}

has measure at least

q+1(Ia)>12|𝔹q+1(0,110)|andt+1(Ib)>12|𝔹t+1(𝐞1,110)𝔹t+1|.

The key point of our argument is that for every a𝔹¯q+1(0,110) and every b𝔹¯t+1(𝐞1,110)𝔹¯t+1 we can find ξ𝕊t and η𝕊q such that

(13)

φj(μa(ξ))=|fj(rμa(ξ))-f(0)-Df(0)rμa(ξ)|>r10or 
φj(νb(η))=|fj(rνb(η))-f(0)-Df(0)rνb(η)|>r10.

We prove the observation by contradiction and we suppose that (13) does not hold. We define

fs(x)=(1-s)(f(0)+Df(0)rx)+sfj(rx)

and we consider the homotopy H(𝔸¯×[0,1])n defined as

H(Φ(ξ,η),s)=(fsμa)(ξ)-(fsνb)¯(-η),

where (fsνb)¯ denotes a continuous extension of fsνb to 𝔹¯q+1 as in the definition of the linking number, which in addition depends continuously on s. From [11] we know that the mapping fjW1,p, p>[n2], with nonnegative and nonzero Jacobian is sense preserving. By Proposition 3 we get that

deg(H(x,1),𝔸,0)=1.

On the other hand

deg(H(x,0),𝔸,0)=-1

since the affine mapping f(0)+Df(0)rx is sense reversing. To obtain a contradiction (with the preservation of the degree under homotopy) it is now enough to show that for every ξ𝕊t, for every η𝕊q and for every s[0,1] we have H(Φ(ξ,η),s)0. It is easy to see that

dist((f0μa)(𝕊t),(f0νb)(𝕊q))dist((f0μ)(𝕊t),(f0ν)(𝕊q))-6r103r10.

Since (13) does not hold, we obtain from the definition of fs that

dist((fsμa)(𝕊t),(fsνb)(𝕊q))3r10-r10-r10

which implies H(Φ(ξ,η),s)0.

By (13) and the symmetry we may assume without loss of generality that

I~a={aIa:there exists ξ𝕊t such that φj(μa(ξ))>r10}

satisfies q+1(I~a)>14|𝔹q+1(0,110)|. Since p>[n2]t, we can use the Sobolev embedding theorem on the t-dimensional space rμa(𝕊t) and we have for almost every aI~a and for all z1,z2rμa(𝕊t),

(14)|fj(z1)-fj(z2)|C|z1-z2|1-tp(rμa(𝕊t)|Dfj|p)1p.

Now let us fix aI~a so that (14) is satisfied and find ξ𝕊t so that for β=μa(ξ) we have φj(β)>r10 as in the definition of I~a. Using aIa we find αμa(𝕊t) satisfying

φj(α)<δrand|α-β|δ.

Thus we have found α,βμa(𝕊t) such that

r10-3δr|φj(β)|-|φj(α)|-2r|α-β||fj(rα)-fj(rβ)|.

This together with (14) implies that for almost every aI~a and δ small enough we have

(15)rtCδp-trμa(𝕊t)|Dfj|p.

Integrating inequality (15) over the set I~A we obtain (i). ∎

Proof of (ii).

If p=1 and n=3, then for each aI~a we can find ξ𝕊(t) so that (13) holds for β=μa(ξ). The measurable set

A:={xB(x,4r):φj(x)>δr}

satisfies |A|Cδ|B(x,4r)| by inequality (12) and Chebyshev’s inequality. Now clearly ξ with (13) satisfies rβ=rμa(ξ)A. In (14) and (15) instead of integrating over the entire rμa(𝕊t) we integrate only over the set rμa(𝕊t)A. Integrating over I~a we obtain the desired conclusion. ∎


Communicated by Juha Kinnunen


Award Identifier / Grant number: DMS-1301570

Award Identifier / Grant number: ERC CZ grant LL1203

Funding statement: Stanislav Hencl was supported by the ERC CZ grant LL1203 of the Czech Ministry of Education. Jani Onninen was supported by the NSF grant DMS-1301570.

Acknowledgements

The authors would like to thank the referee for carefully reading the manuscript and for his comments that helped to improve it.

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Received: 2016-2-7
Revised: 2016-6-2
Accepted: 2016-6-3
Published Online: 2016-6-21
Published in Print: 2018-1-1

© 2017 Walter de Gruyter GmbH, Berlin/Boston

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