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Testing for a unit root against ESTAR stationarity

  • David I. Harvey , Stephen J. Leybourne and Emily J. Whitehouse EMAIL logo
Published/Copyright: June 16, 2017

Abstract

In this paper we examine the local power of unit root tests against globally stationary exponential smooth transition autoregressive [ESTAR] alternatives under two sources of uncertainty: the degree of nonlinearity in the ESTAR model, and the presence of a linear deterministic trend. First, we show that the KSS test (Kapetanios, G., Y. Shin, and A. Snell. 2003. “Testing for a Unit Root in the Nonlinear STAR Framework.” Journal of Econometrics 112: 359–379) for nonlinear stationarity has local asymptotic power gains over standard Dickey-Fuller [DF] tests for certain degrees of nonlinearity in the ESTAR model, but that for other degrees of nonlinearity, the linear DF test has superior power. Second, we derive limiting distributions of demeaned, and demeaned and detrended KSS and DF tests under a local ESTAR alternative when a local trend is present in the DGP. We show that the power of the demeaned tests outperforms that of the detrended tests when no trend is present in the DGP, but deteriorates as the magnitude of the trend increases. We propose a union of rejections testing procedure that combines all four individual tests and show that this captures most of the power available from the individual tests across different degrees of nonlinearity and trend magnitudes. We also show that incorporating a trend detection procedure into this union testing strategy can result in higher power when a large trend is present in the DGP.

A Appendix

Due to the invariance of all statistics to μ in (4), we set μ = 0 in what follows, without loss of generality.

Proof of Lemma 1

The DFμ test statistic is given by

DFμ=t=2Tyμ,t1Δytσ^2t=2Tyμ,t12

where σ^2 denotes the error variance estimate from the OLS regression of Δyt on yμ,t1. Considering first the numerator of DFμ, we can write

T1t=2Tyμ,t1Δyt=T1t=2T(yt1y¯)(βcTut1G(θ,ut1)+εt)=cT2t=2T(yt1y¯)ut1G(θ,ut1)+T1t=2T(yt1y¯)εt+op(1).

Evaluating each term separately, and defining t¯=T1t=1Tt , u¯=T1t=1Tut,

cT2t=2T(yt1y¯)ut1G(θ,ut1)=cT2t=2T{β(t1t¯)+ut1u¯}ut1G(θ,ut1)=cT1t=2T{κσT1(tt¯)+T1/2(ut1u¯)}T1/2ut1G(θ,ut1)+op(1)dσ2c01(κ(r12)+Xμ(r))X(r)G(g2X(r)2)dr

and

T1t=2T(yt1y¯)εt=T1/2t=2T{κσT1(tt¯)+T1/2(ut1u¯)}εt+op(1)dσ201(κ(r12)+Xμ(r))dW(r).

In the denominator of DFμ, it is easily shown that σ^2pσ2, and

T2t=2T(yt1y¯)2=T1t=2T(κσT1(tt¯)+T1/2(ut1u¯))2dσ201(κ(r12)+Xμ(r))2dr.

The DFμ test statistic therefore has the limiting distribution

DFμd01(κ(r12)+Xμ(r))dW(r)c01(κ(r12)+Xμ(r))X(r)G(g2X(r)2)dr01(κ(r12)+Xμ(r))2dr.

The KSSμ test statistic is given by

KSSμ=t=2Tyμ,t13Δytσ^2t=2Tyμ,t16

where σ^2 denotes the error variance estimate from the OLS regression of Δyt on yμ,t13. In the numerator,

T2t=2Tyμ,t13Δyt=T2t=2T(yt1y¯)3(βcTut1G(θ,ut1)+εt)=κσT5/2t=2T(yt1y¯)3cT3t=2T(yt1y¯)3ut1G(θ,ut1)+T2t=2T(yt1y¯)3εtdκσ401(κ(r12)+Xμ(r))3drcσ401(κ(r12)+Xμ(r))3X(r)G(g2X(r)2)dr+σ401(κ(r12)+Xμ(r))3dW(r)

while in the denominator, σ^2pσ2 and

T4t=2Tyμ,t16dσ601(κ(r12)+Xμ(r))6dr

giving the limit for KSSμ as

KSSμdκ01(κ(r12)+Xμ(r))3dr+01(κ(r12)+Xμ(r))3dW(r)c01(κ(r12)+Xμ(r))3X(r)G(g2X(r)2)dr01(κ(r12)+Xμ(r))6dr.

The test statistics based on demeaned and detrended data are invariant to β, hence we set β = 0 without loss of generality in the remainder of this proof. The DFτ test statistic is

DFτ=t=2Tyτ,t1Δyτ,tσ^2t=2Tyτ,t12

where σ^2 denotes the error variance estimate from the OLS regression of Δyτ,t on yτ,t1. Here,

Δyτ,t=Δytβ^=cTut1G(θ,ut1)+εtβ^

and

T1/2β^=T5/2t=1T(tt¯)ytT3t=1T(tt¯)2d1201(r12)X(r)dr.

Also,

T1/2yτ,rT=T1/2yrTT1/2μ^T1/2β^r=T1/2yrT(T1/2y¯T1/2β^T1t¯)T1/2β^rdX(r)01X(s)ds12(r12)01(s12)X(s)ds=X(r)+(6r4)01X(s)ds+(612r)01sX(s)dsXτ(r).

The numerator of DFτ is then given by

T1t=2Tyτ,t1Δyτ,t=T1t=2Tyτ,t1εtcT2t=2Tyτ,t1ut1G(θ,ut1)T1/2β^T3/2t=2Tyτ,t1dσ201Xτ(r)dW(r)cσ201Xτ(r)X(r)G(g2X(r)2)dr

and for the denominator we obtain

T2t=2Tyτ,t12dσ201Xτ(r)2dr

giving

DFτd01Xτ(r)dW(r)c01Xτ(r)X(r)G(g2X(r)2)dr01Xτ(r)2dr.

Finally, the KSSτ test statistic is

KSSτ=t=2Tyτ,t13Δyτ,tσ^2t=2Tyτ,t16

where σ^2 is the error variance estimate from the OLS regression of Δyτ,t on yτ,t13. Now σ^2pσ2 as before,

T2t=2Tyτ,t13Δyτ,t=T2t=2Tyτ,t13εtcT3t=2Tyτ,t13ut1G(θ,ut1)T1/2β^T5/2t=2Tyτ,t13dσ201Xτ(r)3dW(r)cσ201Xτ(r)3X(r)G(g2X(r)2)dr1201(r12)X(r)dr01Xτ(r)3dr

and

T4t=2Tyτ,t16d01Xτ(r)6dr

so

KSSτd01Xτ(r)3dW(r)c01Xτ(r)3X(r)G(g2X(r)2)dr1201(r12)X(r)dr01Xτ(r)3dr01Xτ(r)6dr.

Proof of Lemma 2

As before, the DFμ test statistic is given by

DFμ=t=2Tyμ,t1Δytσ^2t=2Tyμ,t12

where σ^2 is the error variance estimate from the OLS regression of Δyt on yμ,t1. We find

T3/2t=2Tyμ,t1Δyt=T3/2t=2T(σκ(tt¯)+ut1u¯)(σκ+εtcTut1G(θ,ut1))+op(1)=σκT3/2t=2T(tt¯)εtσκcT5/2t=2T(tt¯)ut1G(θ,ut1)+op(1)dσ2κ01(r12)dW(r)σ2κc01(r12)X(r)G(g2X(r)2)dr

and

T3t=2Tyμ,t12=T3t=2T(β(t1t¯)+ut1u¯)2=σ2κ2T3t=2T(tt¯)2+op(1)pσ2κ2/12.

Also,

σ^2=T1t=2T(Δyts=2T(ys1y¯)Δyss=2T(ys1y¯)2(yt1y¯))2=T1t=2T(ΔytT3/2s=2T(ys1y¯)ΔysT3s=2T(ys1y¯)2T3/2(yt1y¯))2=T1t=2T(Δyt)2+op(1)=σ2κ2+T1t=2Tεt2+op(1)pσ2(κ2+1).

Therefore the DFμ test statistic has the limiting distribution

DFμd01(r12)dW(s)c01(r12)X(r)G(g2X(r)2)dr(κ2+1)/12.

For KSSμ we again have

KSSμ=t=2Tyμ,t13Δytσ^2t=2Tyμ,t16

where σ^2 is the error variance estimate from the OLS regression of Δyt on yμ,t13. We obtain

T7/2t=2Tyμ,t13Δyt=T7/2t=2T(σκ(tt¯)+ut1u¯)3(σκcTut1G(θ,ut1)+εt)+op(1)=3σ3κ3T7/2t=2T(tt¯)2(ut1u¯)+σ3κ3T7/2t=2T(tt¯)3εtcσ3κ3T9/2t=2T(tt¯)3ut1G(θ,ut1)+op(1)d3σ4κ301(r12)2Xμ(r)dr+σ4κ301(r12)3dW(r)cσ4κ301(r12)3X(r)G(g2X(r)2)dr

and

T7t=2Tyμ,t16=σ6κ6T7t=2T(tt¯)6+op(1)pσ6κ6/448

together with

σ^2=T1t=2T(ΔytT7/2s=2T(ys1y¯)3ΔysT7s=2T(ys1y¯)6T7/2(yt1y¯)3)2=T1t=2T(Δyt)2+op(1)pσ2(κ2+1)

giving the KSSμ limit distribution

KSSμd301(r12)2Xμ(r)dr+01(r12)3dW(r)c01(r12)3X(r)G(g2X(r)2)dr(κ2+1)/448.

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Supplemental Material

The online version of this article offers supplementary material (DOI: https://doi.org/10.1515/snde-2016-0076).


Published Online: 2017-6-16

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