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Orders of inner-diagonal automorphisms of some simple groups of Lie type

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Published/Copyright: July 27, 2022

Abstract

We refer to the set of element orders of a finite group 𝐺 as the spectrum of 𝐺. For the simple groups PSL n ( q ) , PSU n ( q ) , E 6 ( q ) , and E 6 2 ( q ) , we describe the spectra of extensions of these groups by diagonal automorphisms.

1 Introduction

We refer to the set of element orders of a finite group 𝐺 as the spectrum of 𝐺 and denote it by ω ( G ) . Let μ ( G ) be the subset of ω ( G ) consisting of the elements maximal with respect to divisibility. Since ω ( G ) is closed under taking divisors, it is uniquely determined by any subset ν ( G ) such that μ ( G ) ν ( G ) ω ( G ) , and if such a subset is known, we say that the spectrum of 𝐺 is known or described.

The spectra of all finite nonabelian simple groups are described (see [4] and references therein), and our next goal is to describe the spectra of almost simple groups, that is, the groups 𝐺 satisfying L G Aut L for a nonabelian simple group 𝐿. If 𝐿 is alternating or sporadic, then either 𝐺 is the symmetric group S n for some 𝑛 or the conjugacy classes of 𝐺 are known by [9]. Thus we may assume that 𝐿 is a group of Lie type.

Let 𝐿 be a finite simple group of Lie type. By Steinberg’s theorem [16, Theorem 30], every automorphism of 𝐿 is a composite of inner, diagonal, field, and graph automorphisms. The group generated by inner and diagonal automorphisms is a normal subgroup of Aut L and denoted by Inndiag L .

The spectra of extensions by field and graph-field automorphisms, where “field” and “graph-field” are understood as in [12, Definition 2.5.13], are known [14]. Also if 𝑞 is odd, 𝐿 is one of the groups PSL n ( q ) , PSU n ( q ) , P Ω 2 n + ( q ) , or P Ω 2 n - ( q ) , and 𝛾 is the graph automorphisms of 𝐿 of order 2, then the spectrum of L γ is known [13, 15].

The goal of the present paper is to describe the spectrum of Inndiag L for L = E 6 ( q ) or E 6 2 ( q ) . It is convenient to write L = E 6 ε ( q ) , where ε { + , - } , E 6 + ( q ) = E 6 ( q ) , and E 6 - ( q ) = E 6 2 ( q ) . Since Inndiag L L if and only if 3 divides q - ε , where q - ε is a short for q - ε 1 , we may assume that 3 divides q - ε . Given a prime 𝑝 and a positive integer 𝑛, we denote by p ( n ) the minimal power of 𝑝 that is greater than 𝑛. So, for example, p ( 7 ) is equal to, respectively, 8, 9, 25, 49, or 𝑝 according as p = 2 , 3 , 5 , 7 or p > 7 .

Theorem 1

Let 𝐺 be the group of inner-diagonal automorphisms of the simple group E 6 ε ( q ) , where ε { + , - } , 𝑞 is a power of a prime 𝑝, and 3 divides q - ε . Define the set ν ( G ) to be the union of the following sets:

  1. { q 6 - 1 3 , q 6 + ε q 3 + 1 , ( q 2 + ε q + 1 ) ( q 4 - q 2 + 1 ) , ( q 2 - 1 ) ( q 4 + 1 ) , ( q + ε ) ( q 5 - ε ) , ( q - ε ) ( q 2 + 1 ) ( q 3 + ε ) } ;

  2. p { q 6 - 1 q - ε , q 5 - ε , ( q 3 + ε ) ( q - ε ) } ;

  3. p ( 2 ) { ( q 3 - ε ) ( q + ε ) , q 4 + q 2 + 1 , q 4 - 1 } ;

  4. p ( 5 ) { q 2 - 1 , q 2 + ε q + 1 } ;

  5. p ( 7 ) { q - ε } ;

  6. { p ( 11 ) } .

Then μ ( G ) ν ( G ) ω ( G ) .

In fact, if 𝐿 is an arbitrary simple group of Lie type, then the orders of unipotent elements of Inndiag L are the same as those of 𝐿, and so are given by [17, Proposition 0.5]. The orders of semisimple elements of Inndiag L are exactly the same as those of the universal version L ^ u of the dual group L ^ (see Lemma 2.7). Since, for L = E 6 ε ( q ) , we have L ^ = L and the spectrum of L u is found in [3], to prove Theorem 1, it remains to describe the orders of elements whose unipotent and semisimple parts are both nontrivial.

Our proof is based on Carter’s description [6] of connected centralizers of semisimple elements and similar to that in [3]. In particular, we study the element orders of reductive subgroups of maximal rank. One of the subgroups requiring a large amount of calculations within this standard approach is the subgroup with root system of type A 1 . The center of this reductive subgroup is a maximal torus in a subsystem subgroup of type A 5 . To reduce calculations, it would be convenient to know the spectra of a certain version of A 5 ( q ) or A 5 2 ( q ) .

We consider a more general situation. Similarly to E 6 ± ( q ) , we denote PSL n ( q ) by PSL n + ( q ) and PSU n ( q ) by PSL n - ( q ) , with the same convention applied to the notation SL n ± ( q ) , GL n ± ( q ) and so on. We describe the spectrum of H / Z , where SL n ε ( q ) H GL n ε ( q ) and 𝑍 is a central subgroup of 𝐻. Besides covering the required versions of A 5 ( q ) , A 5 2 ( q ) (Corollary 2), this provides the spectra of almost simple groups with socle PSL n ε ( q ) contained in PGL n ε ( q ) = Inndiag PSL n ε ( q ) (Corollary 1). If m 1 , m 2 , , m k are positive integers, then ( m 1 , m 2 , , m k ) and [ m 1 , m 2 , , m k ] denote the greatest common divisor and the least common multiple of these numbers respectively.

Theorem 2

Let SL n ε ( q ) H GL n ε ( q ) , where n 2 , ε { + , - } , and 𝑞 is a power of a prime 𝑝. Suppose that the index of 𝐻 in GL n ( q ) is equal to d 1 and 𝑍 is a subgroup of the center of 𝐻 of order d 2 . Then d 2 divides ( n ( q - ε ) d 1 , q - ε ) = | Z ( H ) | and ω ( H / Z ) consists of the divisors of the following numbers:

  1. q n - ε n d 1 d 2 ;

  2. [ q n 1 - ε n 1 , q n 2 - ε n 2 ] ( d 1 , d 2 , n / ( n 1 , n 2 ) ) for n 1 , n 2 > 0 such that n 1 + n 2 = n ;

  3. [ q n 1 - ε n 1 , q n 2 - ε n 2 , , q n s - ε n s ] for s 3 and n 1 , n 2 , , n s > 0 such that n 1 + n 2 + + n s = n ;

  4. p k q n 1 - ε n 1 ( d 1 , n 1 d 2 , n ) for k , n 1 > 0 such that p k - 1 + 1 + n 1 = n ;

  5. p k [ q n 1 - ε n 1 , q n 2 - ε n 2 , , q n s - ε n s ] for s 2 and k , n 1 , n 2 , n s > 0 such that p k - 1 + 1 + n 1 + n 2 + + n s = n ;

  6. p k q - ε d 1 d 2 ( n , d 1 ) if p k - 1 + 1 = n for k > 0 ;

  7. p q 2 - 1 d 1 d 2 ( 2 , d 1 ) if n = 4 .

Almost simple groups H / Z in Theorem 2 can be obtained by taking d 1 to be a divisor of ( n , q - ε ) and d 2 = q - ε . Thus we have the following description of the spectra of diagonal extensions of PSL n ε ( q ) .

Corollary 1

Let PSL n ε ( q ) G PGL n ε ( q ) , where n 2 , ε { + , - } , and 𝑞 is a power of a prime 𝑝. If the index of 𝐺 in PGL n ε ( q ) is equal to 𝑑, then ω ( G ) consists of the divisors of the following numbers:

  1. q n - ε n d ( q - ε ) ;

  2. [ q n 1 - ε n 1 , q n 2 - ε n 2 ] ( d , n / ( n 1 , n 2 ) ) for n 1 , n 2 > 0 such that n 1 + n 2 = n ;

  3. [ q n 1 - ε n 1 , q n 2 - ε n 2 , , q n s - ε n s ] for s 3 and n 1 , n 2 , , n s > 0 such that n 1 + n 2 + + n s = n ;

  4. p k q n 1 - ε n 1 d for k , n 1 > 0 such that p k - 1 + 1 + n 1 = n ;

  5. p k [ q n 1 - ε n 1 , q n 2 - ε n 2 , , q n s - ε n s ] for s 2 and k , n 1 , n 2 , n s > 0 such that p k - 1 + 1 + n 1 + n 2 + + n s = n ;

  6. p k if p k - 1 + 1 = n for k > 0 .

Let F ¯ be the algebraic closure of the field of order 𝑞 and G ¯ = SL n ( F ¯ ) . Then SL n ε ( q ) = G ¯ σ for some suitable Frobenius endomorphism 𝜎. Furthermore, every Z 1 Z ( G ¯ ) is 𝜎-invariant, so we may define G = ( G ¯ / Z 1 ) σ . If Z 1 = Z ( G ¯ ) , then G PGL n ( q ) . More generally, if Z 1 is a Hall subgroup of the finite group Z ( G ¯ ) , that is, | Z 1 | is coprime to | Z ( G ¯ ) : Z 1 | , then 𝐺 is isomorphic to H / Z of Theorem 2 for some suitable d 1 and d 2 . Namely, if | Z 1 | = m and ( a ) m denotes the largest divisor of an integer 𝑎 coprime to 𝑚, then one should take d 1 to be ( q - ε ) m and d 2 = ( q - ε ) / d 1 (see Lemma 3.3). So another consequence of Theorem 2 is the following.

Corollary 2

Let Z 1 be the Hall subgroup of Z ( SL n ( F ¯ ) ) of order 𝑚, and let 𝜎 be a Frobenius endomorphism of SL n ( F ¯ ) such that ( SL n ( F ¯ ) ) σ = SL n ε ( q ) . Then the spectrum of ( SL n ( F ¯ ) / Z 1 ) σ consists of the divisors of the following numbers:

  1. q n - ε n q - ε ;

  2. [ q n 1 - ε n 1 , q n 2 - ε n 2 , , q n s - ε n s ] for s 2 and n 1 , n 2 , , n s > 0 such that n 1 + n 2 + + n s = n ;

  3. p k q n 1 - ε n 1 ( n , q - ε , n 1 ) m for k , n 1 > 0 such that p k - 1 + 1 + n 1 = n ;

  4. p k [ q n 1 - ε n 1 , q n 2 - ε n 2 , , q n s - ε n s ] for s 2 and k , n 1 , n 2 , n s > 0 such that p k - 1 + 1 + n 1 + n 2 + + n s = n ;

  5. ( n , q - ε ) m p k if p k - 1 + 1 = n for k > 0 ;

  6. 2 p ( q + ε ) if n = 4 and m = 1 .

The structure of the paper is as follows. In Section 2, we give the necessary notation and preliminary results including Carter’s parameterization of reductive subgroups of maximal rank. In Section 3, we consider linear and unitary groups and prove Theorem 2. In Section 4, we prove Theorem 1. The proof of Theorem 1 involves calculations in Magma [1], and the results of these calculations are represented in Tables 48 at the end of the paper.

2 Preliminaries

Let 𝑝 be a prime. If 𝑎 is an integer, then ( a ) p is the 𝑝-part of 𝑎, that is, the highest power of 𝑝 dividing 𝑎, and ( a ) p is the ratio | a | / ( a ) p . For an integer 𝑚, similarly, ( a ) m is the product of ( a ) p with 𝑝 running over all prime divisors of 𝑚 and ( a ) m = | a | / ( a ) m .

Given a finite group 𝐺, we write exp ( G ) for the exponent of 𝐺, that is, the smallest positive integer 𝑘 such that g k = 1 for all g G , and exp p ( G ) for the exponent of a Sylow 𝑝-subgroup of 𝐺. Also ω p ( G ) denotes the set of orders of 𝑝-regular elements of 𝐺, that is, ω p ( G ) = { a ω ( G ) ( a , p ) = 1 } .

The next two lemmas are well known.

Lemma 2.1

Let a 2 , k 1 be positive integers and ε { + , - } .

  1. If 𝑝 is an odd prime divisor of a - ε , then ( a k - ε k ) r = ( k ) r ( a - ε ) r .

  2. If a ε ( mod 4 ) or 𝑘 is odd, then ( a k - ε k ) 2 = ( k ) 2 ( a - ε ) 2 .

  3. If a - ε ( mod 4 ) and 𝑘 is even, then ( a k - ε k ) 2 = ( k ) 2 ( a + ε ) 2 .

Lemma 2.2

If 𝑎, 𝑏, and 𝑐 are positive integers, 𝑏 and 𝑐 divide 𝑎, then

[ a / b , a / c ] = a / ( b , c ) .

As we mentioned in the introduction, our proof is based on Carter’s work [6], and we proceed with stating the necessary facts and results of this work.

Throughout this paper, F ¯ is the algebraic closure of the field of order 𝑝, G ¯ is a connected reductive algebraic group over F ¯ , and 𝜎 is a Steinberg endomorphism of G ¯ (that is, 𝜎 is a surjective endomorphism of G ¯ and C G ¯ ( σ ) is finite). The finite group C G ¯ ( σ ) is denoted by G ¯ σ . Also T ¯ is a 𝜎-stable maximal torus of G ¯ , W = N G ¯ ( T ¯ ) / T ¯ is the Weyl group of G ¯ , and 𝜋 is the natural homomorphism from N G ¯ ( T ¯ ) to 𝑊.

Let g G ¯ σ , and let 𝑠 and 𝑢 be the semisimple and unipotent parts of 𝑔 respectively. Then g C G ¯ ( s ) 0 , the connected component of C G ¯ ( s ) , and R ¯ = C G ¯ ( s ) 0 is a 𝜎-stable reductive subgroup of G ¯ of maximal rank. We refer to R = R ¯ σ as a reductive subgroup of G ¯ σ of maximal rank. It is clear that | u | divides the 𝑝-exponent of 𝑅 and | s | divides the exponent of the center of this group. Thus | g | divides the number exp p ( R ) exp ( Z ( R ) ) . Conversely, exp p ( R ) exp ( Z ( R ) ) is an element of ω ( G ¯ σ ) . So to find ω ( G ¯ σ ) , we need to find the set { exp p ( R ) exp ( Z ( R ) ) } , where 𝑅 runs over all reductive subgroups of G ¯ σ of maximal rank.

By [6, Section 1.2], every 𝜎-stable reductive subgroup of G ¯ of maximal rank is equal to R ¯ g , where R ¯ is a 𝜎-stable reductive subgroup of G ¯ containing T ¯ , g N G ¯ ( T ¯ ) and g σ g - 1 N G ¯ ( T ¯ ) N G ¯ ( R ¯ ) . Let R ¯ be a 𝜎-stable reductive subgroup of G ¯ containing T ¯ , and let W 1 be the Weyl group of R ¯ . Then W 1 is 𝜎-invariant, and so 𝜎 acts on N W ( W 1 ) / W 1 . Two elements W 1 w 1 and W 1 w 2 are 𝜎-conjugate if there is w W such that W 1 w 2 = ( W 1 w ) σ ( W 1 w 1 ) ( W 1 w ) - 1 .

Lemma 2.3

The G ¯ σ -orbits of the set of 𝜎-stable conjugates of R ¯ in G ¯ are in bijective correspondence with 𝜎-conjugacy classes in N W ( W 1 ) / W 1 , with bijection inducing by R ¯ g W 1 π ( g σ g - 1 ) .

Proof

See [7, Proposition 3].∎

Let Φ 1 be the root system of R ¯ (with respect to T ¯ ), Φ 1 the set of roots orthogonal to every root of Φ 1 and W 2 the subgroup of 𝑊 generated by reflections in roots of Φ 1 . Also let Π 1 and Δ 1 be the fundamental system and Dynkin diagram of Φ 1 respectively.

Lemma 2.4

The group W 1 × W 2 is a normal subgroup of N W ( W 1 ) , and W 2 is a normal subgroup of N W ( W 1 ) . Also we have the following isomorphisms: N W ( W 1 ) / W 1 N W ( Π 1 ) and N W ( Π 1 ) / W 2 A u t W ( Δ 1 ) .

Proof

See [7, Section 2.3]. ∎

Lemma 2.5

Suppose that R ¯ g is 𝜎-stable. Then exp p ( ( R ¯ g ) σ ) is equal to the minimal power of 𝑝 greater than the maximal height of a root in Φ 1 .

Proof

This is an easy consequence of [17, Proposition 0.5]. ∎

The maximal heights of roots for the systems A l , D l and E 6 are given in Table 1, with m h ( Ψ ) denoting the maximal height of a root in a system Ψ.

Table 1

Maximal height of a root in a root system Ψ

Ψ A l D l E 6
m h ( Ψ ) 𝑙 2 l - 3 11
Lemma 2.6

Suppose that R ¯ g is 𝜎-stable, g N G ¯ ( T ¯ ) , and π ( g σ g - 1 ) = w . Then Z ( ( R ¯ g ) σ ) is conjugate in G ¯ to Z ( R ¯ ) T ¯ σ w .

Proof

It is not difficult to see that n = g σ g - 1 normalizes R ¯ and that we have ( R ¯ g ) σ = R ¯ σ n . By [8, Proposition 3.6.8], Z ( R ¯ σ n ) is equal to ( Z ( R ¯ ) ) σ w , which is in turn equal to Z ( R ¯ ) T ¯ σ w . ∎

Lemma 2.7

Let 𝐿 be a finite simple group of Lie type in characteristic 𝑝. Let L ^ = C l ( q ) if L = B l ( q ) , L ^ = B l ( q ) if L = C l ( q ) , and L ^ = L otherwise. If L ^ u is the universal version of L ^ , then ω p ( Inndiag L ) = ω p ( L ^ u ) .

Proof

Since Inndiag L and L ^ u are in duality (in the sense of [8, Proposition 4.3.1]), these groups have isomorphic maximal tori by [8, Proposition 4.4.1]. ∎

3 Linear and unitary groups

In this section, we will prove Theorem 2. We write I k for the identity k × k matrix, diag ( a 1 , , a k ) for the diagonal matrix with a 1 , , a k along the diagonal, F q for the field of order 𝑞, and F × for the multiplicative group of a field 𝐹.

Let 𝐻 and 𝑍 be as in the hypothesis of the theorem. Then

H = { g GL n ( q ) ( det g ) ( q - ε ) / d 1 = 1 } and Z = { μ I n μ F q × , μ d 2 = 1 } .

Observe that μ I n H if and only if μ n ( q - ε ) / d 1 = 1 , and so

| Z ( H ) | = ( n ( q - ε ) d 1 , q - ε ) ,

as stated.

As explained in Section 2, every element order of the group G = H / Z divides the number

η ( R ) = exp p ( R ) exp ( ( Z ( R ) H ) / Z )

for some reductive subgroup 𝑅 of maximal rank of GL n ε ( q ) . Every such reductive subgroup 𝑅 is conjugate in GL n ( F ¯ ) to a group R 1 of the form

(3.1) GL m 1 ε l 1 ( q l 1 ) × GL m 2 ε l 2 ( q l 2 ) × × GL m k ε l k ( q l k ) × GL 1 ε ( q n 1 ) × GL 1 ε ( q n 2 ) × × GL 1 ε ( q n s ) ,

where k , s 0 , m i 2 for m = 1 , 2 , k , and

m 1 l 1 + m 2 l 2 + + m k l k + n 1 + n 2 + + n s = n .

The precise structure of the group R 1 is described in [2, Propositions 2.1 and 2.2], and we will use this description throughout this section without further reference. If 𝑅 is conjugate to the group of the form (3.1), then we say that 𝑅corresponds to the partition n = m 1 l 1 + m 2 l 2 + + m k l k + n 1 + n 2 + + n s .

We begin with calculating η ( R ) in two special cases: when k = 0 (𝑅 is a maximal torus) and when k = 1 , l 1 = 1 .

Lemma 3.1

Let 𝑇 be a maximal torus of GL n ε ( q ) corresponding to a partition n = n 1 + + n s , and let 𝑆 be the image of T H in 𝐺. Then exp ( S ) is equal to

  1. exp ( T ) / ( d 1 d 2 ) if s = 1 ;

  2. exp ( T ) / ( d 1 , d 2 , n ( n 1 , n 2 ) ) if s = 2 ;

  3. exp ( T ) if s > 2 .

Proof

If s = 1 , then 𝑇 is cyclic, so (1) is straightforward. If s > 2 , then by [5, Theorems 2.1 and 2.2], the exponents of 𝑇 and the image of T SL n ε ( q ) in PSL n ε ( q ) coincide. This proves (3).

Let s = 2 . For i = 1 , 2 , take the matrix D i to be the diagonal matrix of size n i × n i with elements λ i , λ i ( ε q ) , , λ i ( ε q ) n i - 1 along the diagonal, where λ i is an element of F ¯ × of order q n i - ε n i . Then det D i = λ i ( ( ε q ) n i - 1 ) / ( ε q - 1 ) , and hence det D i is an element of F ¯ × of order q - ε . We can choose λ 1 and λ 2 so that det D 1 and det D 2 are equal to the same element 𝜆 of F ¯ × of order q - ε , that is,

λ 1 ( ε q ) n 1 - 1 ε q - 1 = λ 2 ( ε q ) n 2 - 1 ε q - 1 = λ .

Put u = diag ( D 1 , I n 2 ) and v = diag ( I n 1 , D 2 ) . Then 𝑇 is conjugate in GL n ( F ¯ ) to the group u × v .

Since det u = det v = λ , it follows that ( det u x v y ) ( q - ε ) / d 1 = 1 if and only if d 1 divides x + y , so T H is conjugate to the group generated by u v - 1 and v d 1 . Denote the image of an element g T H in 𝑆 by g ¯ . Then exp S = [ | u v - 1 ¯ | , | v d 1 ¯ | ] . It is easily seen that | v d 1 ¯ | = | v d 1 | = | v | / d 1 .

To calculate | u v - 1 ¯ | , observe that ( u v - 1 ) x Z if and only if λ 1 x d 2 = λ 2 x d 2 = 1 and λ 1 x = λ 2 - x . The first condition implies that 𝑥 is divisible by ( q n 1 - ε n 1 ) / d 2 and ( q n 2 - ε n 2 ) / d 2 . Since ( q n 1 - ε n 1 , q n 2 - ε n 2 ) = q ( n 1 , n 2 ) - ε ( n 1 , n 2 ) , we have that

x = ( ( ε q ) n 1 - 1 ) ( ( ε q ) n 2 - 1 ) ( ( ε q ) ( n 1 , n 2 ) - 1 ) d 2 y

for some integer 𝑦. Then the second condition is equivalent to ( λ ε q - 1 d 2 ) c y = 1 , where

c = ( ε q ) n 2 - 1 ( ε q ) ( n 1 , n 2 ) - 1 + ( ε q ) n 1 - 1 ( ε q ) ( n 1 , n 2 ) - 1 .

Since

c n 2 ( n 1 , n 2 ) + n 1 ( n 1 , n 2 ) ( mod q - ε )

and n 1 + n 2 = n , we see that | u v - 1 ¯ | = | u v - 1 | / ( d 2 , n ( n 1 , n 2 ) ) .

It remains to show that the least common multiple of the numbers a = | v | / d 1 and b = | u v - 1 | / ( d 2 , n ( n 1 , n 2 ) ) is equal to

f = | u v - 1 | / ( d 1 , d 2 , n ( n 1 , n 2 ) ) .

Let r π ( | u v - 1 | ) . If 𝑟 is coprime to q - ε or n / ( n 1 , n 2 ) , then ( a ) r divides ( b ) r , and so ( [ a , b ] ) r = ( b ) r = ( f ) r , as required. If 𝑟 divides ( q - ε , n ( n 1 , n 2 ) ) , then ( n 1 ) r = ( n 2 ) r and | v | r = | u | r = | u v - 1 | r by Lemma 2.1, so ( [ a , b ] ) r = ( f ) r by Lemma 2.2. ∎

Lemma 3.2

Let 𝑅 be a reductive group of GL n ε ( q ) corresponding to a partition n = m 1 1 + n 1 + + n s , and let 𝑆 be the image of Z ( R ) H in 𝐺. Then exp ( S ) is equal to

  1. ( q n 1 - ε n 1 ) / ( d 1 , n 1 d 2 , n ) if s = 1 ;

  2. [ q n 1 - ε n 1 , , q n s - ε n s ] if s > 1 .

Proof

Let D = λ I m 1 with λ ε q - 1 = 1 . For i = 1 , , s , let D i be the diagonal matrix of size n i × n i with elements λ i , λ i ε q , , λ i ( ε q ) n i - 1 along the diagonal, where λ i ( ε q ) n i - 1 = 1 . The center of 𝑅 is conjugate in GL n ( F ¯ ) to the group of diagonal matrices with blocks D , D 1 , , D s along the diagonal. Let 𝑇 be the subgroup of Z ( R ) conjugated to the subgroup consisting of matrices with D = I m 1 . If s > 1 , then T H has the same exponent as 𝑇 and intersects 𝑍 trivially. Hence exp ( S ) = exp ( T ) , as required.

Suppose that s = 1 . Let 𝑢 be a generator of the center of GL n ε ( q ) , and let 𝑣 be a generator of 𝑇. Without loss of generality, we may assume that u = det v I n . Then the intersection Z ( R ) H is conjugate to the group generated by u v - n and v d 1 . The order of v d 1 modulo 𝑍 is equal to | v | / d 1 . Since 𝑍 is generated by u ( q - ε ) / d 2 , the order of u v - n modulo 𝑍 is equal to [ ( q - ε ) / d 2 , | v | / ( n , | v | ) ] . Thus

exp ( S ) = [ | v | d 1 , | v | ( n , | v | ) , q - ε d 2 ] .

By Lemma 2.2, we have

[ | v | d 1 , | v | ( n , | v | ) ] = | v | ( d 1 , n , | v | ) = | v | ( d 1 , n ) .

Expressing ( q - ε ) / d 2 as the ratio of | v | and | v | d 2 / ( q - ε ) and applying Lemma 2.2 once again, we see that exp ( S ) = | v | / ( d 1 , n , | v | d 2 / ( q - ε ) ) . Since

| v | q - ε = q n 1 - ε n 1 q - ε n 1 ( mod q - ε ) ,

it follows that exp ( S ) = | v | / ( d 1 , n , n 1 d 2 ) , and this proves (1). ∎

Proof of Theorem 2

It is sufficient to prove that, for every reductive subgroup 𝑅 of GL n ε ( q ) of maximal rank, the number η ( R ) divides some number in items (1)–(7), and every number in items (1)–(7) is equal to η ( R ) for some 𝑅.

If 𝑅 is a maximal torus, then η ( R ) = exp ( ( R H ) / Z ) is given in Lemma 3.1. These numbers are listed in items (1)–(3).

Suppose that 𝑅 is not a maximal torus. By repeating the argument used in [2, Propositions 2.3 and 2.4], one can show that if n 4 , then η ( R ) divides η ( R 1 ) for some reductive group R 1 of maximal rank corresponding to a partition of the form m 1 1 + n 1 + + n s . The same is true if n = 4 and 𝑅 is not isomorphic to GL 2 ( q 2 ) .

Let 𝑅 be a group corresponding to the partition n = m 1 1 + n 1 + + n s . If s 1 , then exp ( ( Z ( R ) H ) / Z ) is calculated in Lemma 3.2. If s = 0 , then R = GL n ε ( q ) , and so

exp ( ( Z ( R ) H ) / Z ) = | Z ( H ) | d 2 = ( n ( q - ε ) / d 1 , q - ε ) d 2 .

The number exp p ( R ) is equal to p t , where 𝑡 is defined by the condition

p t + 1 > m 1 p t - 1 + 1 .

If m 1 > p t - 1 + 1 , then η ( R ) divides η ( R 1 ) , where R 1 corresponds to the partition

n = ( p t - 1 + 1 ) 1 + n 1 + + n s + 1 + + 1 .

If m 1 = p t - 1 + 1 , then η ( R ) is listed in items (4)–(6).

It remains to consider the case when n = 4 and 𝑅 is isomorphic to GL 2 ( q 2 ) . The center of 𝑅 is conjugate in GL 4 ( F ¯ ) to the subgroup consisting of the matrices diag ( λ , λ , λ ε q , λ ε q ) , where λ q 2 - 1 = 1 . So the order of Z ( R ) H is equal to

( q 2 - 1 , 2 ( q + ε ) ( q - ε ) / d 1 ) = ( q 2 - 1 ) ( 2 , d 1 ) / d 1 .

Dividing by d 2 , we have item (7), and this completes the proof. ∎

Lemma 3.3

Let Z 1 be the Hall subgroup of Z ( SL n ( F ¯ ) ) of order 𝑚. Suppose that 𝐻 and 𝑍 are as in Theorem 2 with d 1 = ( q - ε ) m and d 2 = ( q - ε ) / d 1 . Then ( SL n ( F ¯ ) / Z 1 ) σ H / Z .

Proof

Let T ¯ be the subgroup of diagonal matrices in SL n ( F ¯ ) . We may assume that 𝜎 acts on T ¯ as follows: diag ( t 1 , , t n ) σ = diag ( t 1 ε q , , t n ε q ) .

Since Z 1 is a Hall subgroup, we have ( n ) p = m d with ( m , d ) = 1 . Let H 1 be the preimage of ( SL n ( F ¯ ) / Z 1 ) σ in SL n ( F ¯ ) . By [12, Theorem 2.1.8], it follows that SL n ( q ) is a normal subgroup of H 1 of index 𝑚. Let μ F ¯ × , | μ | = m ( q - ε ) m , and let 𝑔 be the diagonal matrix diag ( μ n - 1 , μ - 1 , , μ - 1 ) . Then g H 1 and the order of 𝑔 modulo SL n ( q ) is equal to 𝑚, so H 1 = SL n ( q ) , g .

Let h = diag ( μ n , 1 , , 1 ) and z = diag ( μ , μ , , μ ) . Observe that h = g z . Since

( n , m ( q - ε ) m ) = ( ( n ) p , m ( q - ε ) m ) = m ( d , ( q - ε ) m ) = m ,

it follows that | det h | = ( q - ε ) m , and so H = SL n ( q ) , h is of index ( q - ε ) m in GL n ( q ) . If Z ~ = z , then H 1 Z ~ = H Z ~ , and so H 1 / ( H 1 Z ~ ) H / ( H Z ~ ) . Since a scalar matrix diag ( t , t , , t ) lies in H 1 if and only if t n = 1 , t m ( q - ε ) = 1 , we have

| H 1 Z ~ | = ( n , m ( q - ε ) , m ( q - ε ) m ) = m ,

and hence H 1 Z ~ = Z 1 . Also diag ( t , t , , t ) lies in 𝐻 if and only if t q - ε = 1 and t n ( q - ε ) m = 1 . It follows that

| H Z ~ | = ( q - ε , n ( q - ε ) m , m ( q - ε ) m ) = ( q - ε ) m = d 2 .

This completes the proof. ∎

Note that, for a non-Hall subgroup Z 1 , there are 𝑞 such that ( SL n ( F ¯ ) / Z 1 ) σ is not a section of GL n ( q ) as in Theorem 2. Let, for example, n = 4 , ε = + , m = 2 , and q = 9 . The factor of the group G = ( SL 4 ( F ¯ ) / Z 1 ) σ by its center has index 2 in PGL 4 ( 9 ) . So if G = H / Z for some 𝐻 and 𝑍, then d 1 = 2 , and so d 2 = 4 . It follows that Z ( GL 4 ( 9 ) ) lies in 𝐻 but not in SL 4 ( 9 ) Z , and therefore H / Z 2 × ( PSL 4 ( 9 ) : 2 ) .

4 The groups E 6 ( q ) and E 6 2 ( q )

In this section, we prove Theorem 1. Our numbering of fundamental roots in the system E 6 is given in Figure 1, where r 0 denotes the root of maximal height. We denote the root a 1 r 1 + + a 6 r 6 by ( a 1 , , a 6 ) . So r 0 = ( 1 , 2 , 2 , 3 , 2 , 1 ) . We also put r 7 = ( 1 , 0 , 1 , 1 , 1 , 1 ) .

Figure 1 
               Extended Dynkin diagram of 
                     
                        
                           
                              E
                              6
                           
                        
                        
                        E_{6}
                     
                  .
Figure 1

Extended Dynkin diagram of E 6 .

Let L ¯ be the universal version of the simple algebraic group of type E 6 over F ¯ , Z ¯ = Z ( L ¯ ) , and let L ~ be the corresponding adjoint version. We identify L ~ with L ¯ / Z ¯ . We fix a maximal torus T ¯ of L ¯ , put T ~ = T ¯ / Z ¯ , and let Φ be the root system of L ¯ with respect to T ¯ . Denote by Π some fundamental system of Φ. Let x r ( s ) , h r ( t ) with r Φ , s F ¯ , t F ¯ × be Chevalley generators of L ¯ . If r = r i , then h i ( t ) = h r i ( t ) .

For a power 𝑞 of 𝑝, let 𝐪 be the endomorphism of L ¯ that maps x r ( s ) to x r ( s q ) . Suppose that 𝜌 is the nontrivial symmetry of the Dynkin diagram of Φ, and let 𝜏 be the corresponding graph automorphism. There is a unique element w 0 of the Weyl group 𝑊 of L ¯ such that Π w 0 = - Π and - w 0 acts on Π as 𝜌. Let n 0 be a preimage of w 0 in N L ¯ ( T ¯ ) , and define - q to be the composition of 𝐪, 𝜏, and the conjugation by n 0 . Then ( L ¯ ) - q is conjugate in L ¯ to ( L ¯ ) q τ , the universal version of the simple group E 6 2 ( q ) . Observe that - q maps h r ( s ) to h - r ( s q ) .

Take 𝜎 to be 𝐪 or - q with ε = + or - respectively. Then L ¯ σ / Z ( L ¯ σ ) is the simple group E 6 ε ( q ) . Denoting the endomorphism of L ~ induced by 𝜎 by the same symbol, we have that L ~ σ is isomorphic to the group of inner-diagonal automorphisms of E 6 ε ( q ) (see [12, Lemma 2.5.8]). Observe for both ε = + and ε = - , the 𝜎-conjugacy in 𝑊 is an ordinary conjugacy.

As we explained in Section 2, the spectrum of G = L ~ σ can be determined as the set of all divisors of the numbers

η ( R ) = exp p ( R ) exp ( Z ( R ) ) ,

where 𝑅 runs over reductive subgroups of 𝐺 of maximal rank. Furthermore, by Lemma 2.3, we may assume that R = ( R ~ g ) σ , where R ~ is a 𝜎-stable reductive subgroup of L ~ containing T ~ , g N L ~ ( T ~ ) , π ( g σ g - 1 ) normalizes the Weyl group W 1 of R ~ , and W 1 π ( g σ g - 1 ) runs over representatives of conjugacy classes of N W ( W 1 ) / W 1 .

By Lemma 2.7, we have that ω p ( G ) = ω p ( E 6 ε ( q ) u ) . The structure of maximal tori of the group E 6 ε ( q ) u = L ¯ σ is found in [11]. Maximal (under divisibility) orders of semisimple elements derived from this information are given in [3, Theorem 2]. These numbers are reproduced in item (1) of Theorem 1. Thus we may assume that R ~ is not a torus, that is, the root system Φ 1 of R ~ is not empty.

Recall that m h ( Ψ ) is the maximal height of a root in Ψ and p ( n ) is the minimal power of 𝑝 greater than 𝑛. By Lemmas 2.5 and 2.6, it follows that

(4.1) exp p ( R ) = p ( m h ( Φ 1 ) )

and

(4.2) exp ( Z ( R ) ) = exp ( Z ( R ~ ) σ w ) = exp ( Z ( R ~ ) T ~ σ w ) ,

where w = π ( g σ g - 1 ) . So along with the notation η ( R ) , we will use

η ( Φ 1 , w ) = p ( m t ( Φ 1 ) ) exp ( Z ( R ~ ) T ~ σ w ) .

Equivalence classes of non-empty subsystems of E 6 are given in Table 2. They are divided into two classes α ( Φ ) and β ( Φ ) . The next lemma shows that, to find the orders of 𝑝-singular elements of 𝐺, it is sufficient to consider reductive subgroups with Φ 1 α ( Φ ) .

Table 2

Subsystems of Φ = E 6

α ( Φ ) A 1 , A 1 2 , A 2 , A 1 3 , A 1 4 , A 2 2 , A 4 , D 4 , A 5 , D 5 , A 2 3 , E 6
β ( Φ ) A 2 × A 1 , A 3 , A 2 × A 1 2 , A 3 × A 1 , A 2 2 × A 1 , A 3 × A 1 2 , A 4 × A 1 , A 5 × A 1
Lemma 4.1

Suppose that p 3 . Then every element of ω ( G ) that is a multiple of 𝑝 divides η ( ( R ~ g ) σ ) for some R ~ with Φ 1 α ( Φ ) and π ( g σ g - 1 ) permuting irreducible components of Φ 1 cyclically.

Proof

Suppose that Φ 1 β ( Φ ) and R ~ is a 𝜎-stable reductive group containing T ~ with root system Φ 1 . Take g N L ~ ( T ~ ) such that w = π ( g σ g - 1 ) normalizes W 1 . It suffices to prove that η ( ( R ~ g ) σ ) divides η ( ( ( R ~ ) g ) σ ) , where R ~ is some reductive subgroup containing T ~ such that 𝑤 normalizes the Weyl group W 1 of R ~ and the root system of R ~ lies in α ( Φ ) .

Suppose that there is a 𝑤-invariant subsystem Φ 1 of Φ 1 such that

p ( m h ( Φ 1 ) ) = p ( m h ( Φ 1 ) ) ,

and take R ~ to be the reductive subgroup with root system Φ 1 . Then w N W ( W 1 ) and (4.1) and (4.2) show that η ( ( R ~ g ) σ ) divides η ( ( ( R ~ ) g ) σ ) by the choice of Φ 1 and the fact that Z ( R ~ ) Z ( R ~ ) .

This argument excludes all reducible root systems having non-isomorphic irreducible components. The only remaining case is Φ 1 = A 3 . Let Ψ 1 be a subsystem of Φ 1 of type A 2 . Since Ψ 1 w is also a subsystem of Φ 1 of type A 2 , there is w 1 W 1 such that Ψ 1 w w 1 = Ψ 1 . Note that p ( m h ( A 3 ) ) = p ( m h ( A 2 ) ) because p 3 . By Lemma 2.3, we may replace 𝑤 by w w 1 and proceed as above. The proof is complete. ∎

Table 3

Relations for Z ( R ¯ )

Φ 1 Π 1 Z ( R ¯ )
A 1 - r 0 t 2 = 1
A 1 2 - r 0 , r 7 t 2 = 1 , t 6 = t 1 - 1
A 1 3 - r 0 , r 7 , r 4 t 2 = 1 , t 6 = t 1 - 1 , t 5 = t 3 - 1 t 4 2
A 1 4 - r 0 , r 1 , r 4 , r 6 t 2 = 1 , t 3 = t 1 2 , t 5 = t 6 2 , t 4 2 = t 1 2 t 6 2
A 2 - r 0 , r 2 t 2 = t 4 = 1
A 2 2 - r 0 , r 2 , r 5 , r 6 t 2 = t 4 = 1 , t 5 = t 6 2 , t 6 3 = 1
A 2 3 - r 0 , r 1 , r 2 , r 3 , r 5 , r 6 t 2 = t 4 = 1 , t 3 = t 1 2 , t 1 3 = 1 , t 5 = t 6 2 , t 6 3 = 1
A 4 - r 0 , r 2 , r 4 , r 5 t 2 = t 4 = 1 , t 3 = t 5 - 1 , t 6 = t 5 2
D 4 - r 0 , r 2 , r 4 , r 7 t 2 = t 4 = 1 , t 3 = t 5 - 1 , t 6 = t 1 - 1
A 5 - r 0 , r 2 , r 4 , r 5 , r 6 t 2 = t 4 = 1 , t 3 = t 5 - 1 , t 6 = t 5 2 , t 5 3 = 1
D 5 - r 0 , r 2 , r 4 , r 5 , r 7 t 2 = t 4 = 1 , t 3 = t 5 - 1 , t 6 = t 5 2 , t 1 = t 5 - 2
E 6 Π t 2 = t 4 = 1 , t 5 = t 1 , t 3 = t 6 = t 1 2 , t 1 3 = 1

In Table 3, we list subsystems of Φ lying in α ( Φ ) . The first and second columns give, respectively, the type of the subsystem and the chosen fundamental system. The last column gives the conditions for h T ¯ to lie in Z ( R ¯ ) , where R ¯ is the full preimage of R ~ in L ¯ . Using the formula

x r ( s ) h i ( t ) = x r ( s t r , r i ) ,

where r , r i = 2 ( r , r i ) / ( r i , r i ) , we see that h = h 1 ( t 1 ) h 6 ( t 6 ) centralizes x r ( s ) for all r Π 1 if and only if

t 1 r , r 1 t 6 r , r 6 = 1 for all r Π 1 .

Observe that Z ( R ~ ) = Z ( R ¯ ) / Z ¯ since x r ( s ) h x r ( s ) - 1 is a unipotent element, so it lies in Z ¯ if and only if it is trivial.

Fix some w N W ( W 1 ) . It is clear that Z ( R ~ ) T ~ σ w = ( Z ( R ¯ ) S ¯ ) / Z ¯ , where S ¯ is the full preimage of T ~ σ w in T ¯ . If r i w = a i 1 r 1 + + a i k r k , then

h i ( t ) ( σ w ) = h 1 ( t ε q a i 1 ) h k ( t ε q a i k ) .

So S ¯ consists of the elements satisfying

h 1 ( t 1 ) h k ( t k ) = h 1 ( t 1 ε q a 11 t k ε q a k 1 ) h k ( t 1 ε q a 1 k t k ε q a k k ) z

for some z Z ¯ . By the last row of Table 3, we have z = h 1 ( t 0 v 1 ) h k ( t 0 v 6 ) , where t 0 3 = 1 and v = ( 1 , 0 , 2 , 0 , 1 , 2 ) . Therefore, if we put M w = ( a i j ) , then the relation matrix of S ¯ is

(4.3) ( ε q M w - 1 0 v 3 ) .

Since we are interested only in elements lying in Z ( R ¯ ) , we can reduce the number of equations. Suppose that elements of Z ( R ¯ ) satisfy t i = t ( i ) c (in additive notation), where t ( i ) = ( t 1 , , t i - 1 , t i + 1 , , t 6 ) and 𝑐 is an integer column vector of size 5. Then

( ( t 1 , , t k ) M w ) i = ( ( t 1 , , t k ) M w ) ( i ) c

since Z ( R ¯ ) is 𝑤-invariant and also v i = v ( i ) c . So the equation

t i = ε q ( ( t 1 , , t k ) M w ) i + v i

is a corollary of the equations t i = t ( i ) c and t ( i ) = ε q ( ( t 1 , , t k ) M w ) ( i ) + v ( i ) . It follows that we can remove the 𝑖th column of the matrix (4.3). Also, after adding the 𝑖th row multiplied by c j to the 𝑗th row for all j i , we can remove the 𝑖th row of this matrix. We apply this transformation for all 𝑖 with t i = t ( i ) c and denote the resulting matrix by 𝑀. Also let 𝑋 and 𝑦 be the blocks of 𝑀 obtained from the blocks ε q M w - 1 and 𝑣 respectively. Observe that 𝑦 depends only on relations of Z ( R ¯ ) , and so does not depend on 𝑤.

Sometimes, we resolve the system corresponding to 𝑀 by hand, but in most cases, we find, with help of [1], invertible integer matrices 𝐴 and 𝐵 such that A X B is diagonal and y B has a single non-zero entry modulo 3. If

A X B = diag ( m 1 , , m t )

and y B has 𝑗th non-zero entry, then the group defining by 𝑋 and 𝑦 is the direct product of cyclic groups of orders m i with 1 i t , where m i = m i if i j and m j = 3 m j . Furthermore, the 𝑖th factor of this product consists of

h 1 ( s i a i 1 ) h 6 ( s i a i 6 ) ,

where a i 1 , , a i 6 are calculated from A [ i ] , the 𝑖th row of 𝐴, and relations for deleted t k , so if A [ i ] is congruent to ± y modulo 3, then Z ¯ is contained in the 𝑖th factor. The matrices 𝑋, 𝐴, 𝐵, the diagonal matrix A X B , the row y B mod 3 , and some row of 𝐴 congruent to ± y modulo 3 are given in Tables 48.

Table 4

Φ 1 = A 1 2 , Π 1 = { - r 0 , r 7 } , t 2 = 1 , t 6 = t 1 - 1 , y = ( 1 , 2 , 0 , 1 )

M w = ( 1 1 2 2 1 0 0 - 1 0 0 0 0 0 0 - 1 0 0 0 0 0 0 - 1 0 0 0 0 0 0 - 1 0 0 1 1 2 2 1 ) , X = ( q - 1 q 0 - q 0 - q - 1 0 0 0 0 - q - 1 0 0 0 0 - q - 1 ) , A = ( 1 0 0 0 0 1 0 0 0 0 1 0 - q 2 - q - 1 0 1 ) , B = ( - q - 1 0 0 - q 0 - 1 0 0 0 0 - 1 0 - q - 1 0 - q + 1 ) , A X B = diag ( 1 , q + 1 , q + 1 , q 2 - 1 ) exp = q 2 - 1

M w = ( 1 1 1 1 0 0 0 - 1 - 1 - 2 - 1 0 0 0 0 0 1 0 0 0 0 1 0 0 0 0 1 0 0 0 0 1 0 1 1 1 ) , X = ( q - 1 q 0 - q 0 - 1 0 q 0 0 q - 1 0 0 q 0 - 1 ) , A = ( 1 0 0 0 1 1 0 0 0 0 1 0 - q 2 - q - 1 0 1 ) , B = ( - q - 1 0 0 - q q + 1 1 0 q 0 0 1 0 1 1 0 1 ) , A X B = diag ( 1 , q - 1 , q - 1 , q 2 - 1 ) exp = q 2 - 1

M w = ( 1 1 2 2 1 0 0 - 1 0 - 1 - 1 0 0 0 - 1 - 1 - 1 0 0 0 0 0 1 0 0 0 0 1 0 0 0 1 1 1 1 1 ) , X = ( q - 1 q q 0 0 - q - 1 - q - q 0 0 - 1 q 0 0 q - 1 ) , A = ( 1 0 0 0 0 1 0 0 q + 1 1 1 0 - q 2 - q - q 2 - q + 1 0 1 ) , B = ( - 1 0 q 0 - q - q - 1 - q - q q + 1 q + 1 1 q 0 1 q 1 ) , A X B = diag ( 1 , 1 , q 2 - 1 , q 2 - 1 ) exp = q 2 - 1

M w = ( 1 1 1 2 1 0 0 - 1 - 1 - 1 0 0 0 0 0 - 1 0 0 0 0 0 0 - 1 0 0 0 1 1 1 0 0 1 0 1 1 1 ) , X = ( q - 1 q q 0 0 - 1 - q 0 0 0 - 1 - q 0 q q q - 1 ) , A = ( 1 0 0 0 0 0 1 0 - 1 - 1 q - 1 0 - q 3 - q - q 2 + q - 1 2 q 3 - 3 q 2 + 3 q - 2 1 ) , B = ( - q 2 - 1 q 2 q 2 - q - q 2 q 2 + 1 - q 2 + 1 - q 2 + q - 1 q 2 - q q - 1 q - q 1 - 1 - 1 1 ) , A X B = diag ( 1 , 1 , q - 1 , ( q 2 + 1 ) ( q - 1 ) ) , exp = ( q 2 + 1 ) ( q - 1 )

M w = ( 1 1 1 2 1 0 0 - 1 - 1 - 1 - 1 0 0 0 0 - 1 - 1 0 0 0 0 0 1 0 0 0 1 1 0 0 0 1 0 1 1 1 ) , X = ( q - 1 q q 0 0 - 1 - q - q 0 0 - 1 q 0 q q - 1 ) , A = ( 1 0 0 0 0 1 0 0 0 0 1 0 - q 3 - 1 q 4 - 2 q 3 + 2 q - 2 - q 4 + q 3 - q 2 + 1 1 ) , B = ( - q 2 - q - 1 q 3 - q 2 - q - q 3 - q - q 3 q 2 + q - q 3 + q 2 + 2 q - 1 q 3 q 3 - q - q q 2 - 2 q - q 2 + q - 1 - q 2 + q - 1 q - 2 - q + 1 - q + 1 ) , A X B = diag ( 1 , 1 , 1 , ( q 3 + 1 ) ( q - 1 ) ) , exp = ( q 3 + 1 ) ( q - 1 )

In all cases, A [ 4 ] y ( mod 3 ) , y B ( 0 , 0 , 0 , 2 ) ( mod 3 )
Table 5

Φ 1 = A 1 3 , Π 1 = { - r 0 , r 7 , r 4 } , t 2 = 1 , t 6 = t 1 - 1 , t 5 = t 3 - 1 t 4 2 , y = ( 1 , 2 , 0 )

M w = ( 0 1 0 1 1 1 0 - 1 - 1 - 2 - 1 0 1 0 1 1 1 0 - 1 0 - 1 - 1 - 1 - 1 0 0 1 1 1 1 1 1 1 1 0 0 ) , X = ( - q - 1 - q 0 q - 1 0 - q q q - 1 ) , A = ( 1 0 0 q + 1 1 0 0 1 1 ) , B = ( - 1 q 0 1 - q - 1 0 - 1 q + 1 1 ) , A [ 2 ] 2 y ( mod 3 ) , y B ( 1 , 0 , 0 ) ( mod 3 ) , A X B = diag ( 1 , q 2 + q + 1 , q - 1 ) , exp = [ 3 , ( q 2 + q + 1 ) / 3 , q - 1 ] = ( q 3 - 1 ) / 3

M w = ( 0 0 1 0 0 0 1 1 2 3 2 1 0 1 0 1 1 1 - 1 - 2 - 2 - 3 - 2 - 1 1 1 1 1 0 0 0 0 0 0 1 0 ) , X = ( - 1 q 0 - q - q - 1 0 q 0 - q - 1 ) , A = ( 1 0 0 1 0 - 1 - q 2 - 2 q - 1 1 q 2 + q + 1 ) , B = ( - 1 - q - q 2 - q 0 - 1 - q - 1 - 1 - q + 1 - q 2 ) , A [ 3 ] 2 y ( mod 3 ) , y B ( 2 , 0 , 0 ) ( mod 3 ) , A X B = diag ( 1 , 1 , ( q 2 + q + 1 ) ( q + 1 ) ) , exp = [ 3 , ( q 2 + q + 1 ) ( q + 1 ) / 3 ] = ( q 2 + q + 1 ) ( q + 1 )
Table 6

Φ 1 = D 4 , Π 1 = { - r 0 , r 2 , r 4 , r 7 } , t 2 = t 4 = 1 , t 3 = t 5 - 1 , t 6 = t 1 - 1 , y = ( 1 , 1 )

M w = I , X = ( q - 1 0 0 q - 1 ) , A = ( 1 0 1 1 ) , B = ( 1 0 - 1 1 ) , A [ 2 ] y ( mod 3 ) , y B ( 0 , 1 ) ( mod 3 ) , A X B = X , exp = q - 1

M w = ( 0 0 - 1 0 0 0 0 1 0 0 0 0 - 1 0 0 0 0 0 1 0 1 1 1 1 0 0 0 0 0 - 1 0 0 0 0 - 1 0 ) , X = ( - 1 q q - 1 ) , A = ( 1 0 q 2 + q - 1 1 ) , B = ( - q - 1 q - 1 1 ) , A [ 2 ] y ( mod 3 ) , y B ( 0 , 2 ) ( mod 3 ) , A X B = diag ( 1 , q 2 - 1 ) , exp = q 2 - 1

M w = ( - 1 - 1 - 2 - 2 - 1 0 0 1 0 0 0 0 0 0 0 0 0 - 1 1 0 1 1 1 1 - 1 0 0 0 0 0 0 - 1 - 1 - 2 - 2 - 1 ) , X = ( - q - 1 - q q - 1 ) , A = ( 1 0 q + 1 1 ) , B = ( - 1 q 1 - q - 1 ) , A [ 2 ] y ( mod 3 ) , y B ( 0 , 2 ) ( mod 3 ) , A X B = diag ( 1 , q 2 + q + 1 ) , exp = q 2 + q + 1
Table 7

Φ 1 = A 2 , Π 1 = { - r 0 , r 2 } , t 2 = t 4 = 1 , y = ( 1 , 2 , 1 , 2 )

M w = ( 0 0 0 0 1 1 - 1 - 2 - 2 - 3 - 2 - 1 0 0 0 0 0 - 1 1 1 1 2 1 1 0 0 1 0 0 0 - 1 0 - 1 0 0 0 ) , X = ( - 1 0 q q 0 - 1 0 - q 0 q - 1 0 - q - q 0 - 1 ) , A = ( 1 0 0 0 0 1 0 0 0 0 1 0 q 4 - q - 1 q 4 - q 3 - q - 1 - q 4 - q 2 + 1 1 ) , B = ( q 3 - q - 1 q 3 - q 2 - q - q 3 - q 3 + q q q - 1 - q - q q 2 q 2 - q - q 2 - 1 - q 2 - 1 - 1 1 1 ) , A [ 4 ] 2 y ( mod 3 ) , y B ( 0 , 0 , 0 , 2 ) ( mod 3 ) , A X B = diag ( 1 , 1 , 1 , q 4 - 1 ) , exp = q 4 - 1

M w = ( 0 0 0 0 - 1 0 - 1 - 2 - 2 - 3 - 2 - 1 0 0 0 0 1 1 1 1 2 2 1 0 0 0 - 1 0 0 0 - 1 0 0 0 0 0 ) , X = ( - 1 0 - q 0 0 - 1 q q 0 - q - 1 0 - q 0 0 - 1 ) , A = ( 1 0 0 0 0 1 0 0 1 1 1 0 - q - q 3 - q q 2 + 1 1 ) , B = ( - q - 1 - q 2 - q q - q 3 0 - 1 0 - q 1 q + 1 - 1 q 2 - 1 - q - 1 1 - q 2 - 1 ) , A [ 4 ] 2 y ( mod 3 ) , y B ( 0 , 0 , 2 , 0 ) ( mod 3 ) A X B = diag ( 1 , 1 , 1 , q 4 + q 2 + 1 ) , exp = [ 3 , ( q 4 + q 2 + 1 ) / 3 ] = q 4 + q 2 + 1

M w = ( - 1 0 - 1 0 0 0 0 1 0 0 0 0 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 - 1 ) , X = ( - q - 1 - q 0 0 q - 1 0 0 0 0 q - 1 q 0 0 0 - q - 1 ) , A = ( 1 0 0 0 q + 1 1 0 0 0 0 1 0 q 2 - 1 0 q 2 + q 1 ) , B = ( - 1 q 0 0 1 - q - 1 0 0 - q 0 - q - 1 q q - 1 0 q - q + 1 ) , A [ 4 ] ( 0 , 0 , 2 , 1 ) ( mod 3 ) , y B ( 0 , 0 , 0 , 1 ) ( mod 3 ) , A X B = diag ( 1 , q 2 + q + 1 , 1 , q 2 - 1 ) , exp = [ q 2 + q + 1 , 3 ( q 2 - 1 ) ] = ( q 3 - 1 ) ( q + 1 )
Table 8

Φ 1 = A 4 , Π 1 = { - r 0 , r 2 , r 4 , r 5 } , t 2 = t 4 = 1 , t 3 = t 5 - 1 , t 6 = t 5 2 , y = ( 1 , 1 )

M w = I , X = ( q - 1 0 0 q - 1 ) , A = ( 1 0 1 1 ) , B = ( 1 0 - 1 1 ) , A [ 2 ] y ( mod 3 ) , y B ( 0 , 1 ) ( mod 3 ) , A X B = X , exp = q - 1

M w = ( - 1 0 0 0 0 0 0 1 0 0 0 0 1 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 1 ) , X = ( - q - 1 0 - q q - 1 ) , A = ( 0 1 - 1 q 2 + q ) , B = ( - q q - 1 - q - 1 q ) , A [ 2 ] 2 y ( mod 3 ) , y B ( 0 , 1 ) ( mod 3 ) , A X B = diag ( 1 , q 2 - 1 ) , exp = q 2 - 1

Also, in some cases, we apply the relation of the form t i k = 1 to 𝑋 and diagonalize the resulting matrix X instead of 𝑋. The following examples show how the exponent of ( Z ( R ¯ ) S ¯ ) / Z ¯ can be readily seen from 𝐴, 𝐵, A X B , and y B .

Example 1

Let ε = + , Φ 1 = A 1 2 , and Π 1 = { - r 0 , r 7 } . Suppose that

M w = ( 1 1 2 2 1 0 0 - 1 0 0 0 0 0 0 - 1 0 0 0 0 0 0 - 1 0 0 0 0 0 0 - 1 0 0 1 1 2 2 1 ) .

The relations for Z ( R ¯ ) are t 2 = 1 and t 6 = t 1 - 1 . Hence, to obtain the reduced relation matrix 𝑀 from the matrix (4.3), we remove the second and sixth columns, subtract the sixth row from the first one and remove the second and sixth rows. So

M = ( q - 1 q 0 - q 0 0 - q - 1 0 0 0 0 0 - q - 1 0 0 0 0 0 - q - 1 0 1 2 0 1 3 ) ,

𝑋 is equal to the upper-left 4 × 4 -block of 𝑀, and y = ( 1 , 2 , 0 , 1 ) . By the first item of Table 4, if

A = ( 1 0 0 0 0 1 0 0 0 0 1 0 - q 2 - q - 1 0 1 ) and B = ( - q - 1 0 0 - q 0 - 1 0 0 0 0 - 1 0 - q - 1 0 - q + 1 ) ,

then

A X B = ( 1 0 0 0 0 q + 1 0 0 0 0 q + 1 0 0 0 0 q 2 - 1 )

and

y B = ( - 2 q - 1 , - 3 , 0 , - 2 q + 1 ) ( 0 , 0 , 0 , 2 ) ( mod 3 ) .

So the group Z ( R ¯ ) S ¯ is isomorphic to ( q + 1 ) × ( q + 1 ) × 3 ( q 2 - 1 ) (for brevity, we write 𝑚 instead of the cyclic group of order 𝑚 in such direct products). Furthermore, since the last row of 𝐴 is equal to 𝑦 modulo 3, it follows that Z ¯ is contained in the last direct factor. Hence the exponent of ( Z ( R ¯ ) S ¯ ) / Z ¯ is equal to q 2 - 1 .

Example 2

Let ε = + , Φ 1 = A 1 4 , and Π 1 = { - r 0 , r 1 , r 4 , r 6 } . The only conjugacy class cyclically permuting the irreducible components can be represented by 𝑤 with

M w = ( - 1 - 2 - 2 - 3 - 2 - 1 0 0 1 1 1 0 0 1 1 1 0 0 1 0 0 0 0 0 - 1 0 - 1 - 1 0 0 0 0 0 1 0 0 ) .

The relations of Z ( R ¯ ) are t 2 = 1 , t 3 = t 1 2 , t 5 = t 6 2 , and t 4 2 = t 1 2 t 6 2 . Hence we add the doubled third row to the first one and the doubled fifth row to the sixth one, and then remove the first, third, and fifth rows and columns (we do not take into account the last relation for a while). So we obtain the reduced matrix

M = ( - q - 1 - q - q 0 q - 1 0 0 - 2 q - q - 1 0 1 0 2 3 ) .

Put

A = ( 1 0 0 0 1 0 - q 2 - q + 1 q 3 + q 2 - 2 q 1 ) , B = ( - 1 q - q - q q 2 - 1 - q 2 q + 1 - q 2 - q q 2 + q + 1 ) .

Then

A ( - q - 1 - q - q q - 1 0 - 2 q - q - 1 ) , B = ( 1 0 0 0 1 0 0 0 ( q 2 - 1 ) ( q + 1 ) ) ,

and

( 1 , 0 , 2 ) B = ( 2 q + 1 , - 2 q 2 - q , 2 q 2 + q + 2 ) ( 0 , 0 , 2 ) ( mod 3 ) .

It follows that

t 1 = s - q 2 - q + 1 , t 4 = s q 3 + q 2 - 2 q and t 6 = s ,

where s 3 ( q 2 - 1 ) ( q + 1 ) = 1 . Now t 4 2 = t 1 2 t 6 2 implies

s 2 q 3 + 2 q 2 - 4 q = s - 2 q 2 - 2 q + 2 s 2 ,

or equivalently, s 2 ( q 2 - 1 ) ( q + 2 ) = 1 . Since

( 3 ( q + 1 ) , 2 ( q + 2 ) ) = 3 ( 2 , q - 1 ) ,

it follows that Z ( R ¯ ) T ¯ σ w is a cyclic group of order ( q 2 - 1 ) ( 2 , q - 1 ) . Hence η ( A 1 4 , w ) = p ( q 2 - 1 ) ( 2 , q - 1 ) .

Observe that the argument for the corresponding case in [3] was incorrect, but the statement that η ( A 1 4 , w ) for the simple group E 6 ε ( q ) does not lie in μ ( E 6 ε ( q ) ) is true. This follows, for example, from the current calculation. Indeed, the simple group E 6 ε ( q ) contains an element of order p ( q 4 - 1 ) by [3, Theorem 1], which is a multiple of p ( q 2 - 1 ) ( 2 , q - 1 ) .

Proof of Theorem 1

We assume that ε = + . Results for E 6 2 ( q ) can be obtained by replacing 𝑞 with - q . For brevity, we denote the group Z ( R ¯ ) S ¯ by 𝐶. Also denote the torus generated by h r ( t ) with r Φ 1 by T ¯ 1 .

We consider all Φ 1 α ( Φ ) case by case. The structure and conjugacy classes of N W ( W 1 ) / W 1 N W ( Π 1 ) are calculated in Magma, but also they can be taken from [10].

Suppose that Φ 1 = A 1 and Π 1 = { - r 0 } . Then Φ 1 is of type A 5 with fundamental roots r 1 , r 3 , r 4 , r 5 , and r 6 and N W ( W 1 ) = W 1 × W 2 . Denote by Q ~ the subsystem subgroup of L ~ corresponding to Φ 1 . By Table 3, we see that Z ( R ~ ) is a maximal torus of Q ~ . So the groups Z ( R ~ ) σ w with w W 2 are exactly the maximal tori of the finite group Q ~ σ . The group Q ~ is a simple group of type A 5 and can be identified with SL 6 ( F ¯ ) / Z 1 , where Z 1 is a subgroup of Z ( SL 6 ( F ¯ ) ) of order 3. Hence the spectrum of Q ~ σ is given in Corollary 2 with m = 2 . Thus the numbers η ( A 1 , w ) that are maximal with respect to divisibility are p ( q 6 - 1 ) / ( q - 1 ) , p ( q 5 - 1 ) , p ( q 4 - 1 ) , and p ( q 3 - 1 ) ( q + 1 ) . The first two numbers are in item (2), while the other divide some numbers in item (3).

Let Φ 1 = A 1 2 . There are five conjugacy classes in N W ( W 1 ) / W 1 whose representatives permute the irreducible components of Φ 1 . Using Table 4, we calculate that the numbers η ( A 1 2 , w ) that are maximal under divisibility are p ( q 2 + 1 ) ( q - 1 ) and p ( q 3 + 1 ) ( q - 1 ) . The first number divides p ( 2 ) ( q 4 - 1 ) , and the second one is in item (2).

Let Φ 1 = A 1 3 . By Table 5, the group 𝐶 is isomorphic to

3 × ( q 2 + q + 1 ) × ( q - 1 ) or 3 × ( q 2 + q + 1 ) ( q + 1 ) ;

in both cases, the second factor contains Z ¯ . So exp ( C / Z ¯ ) is equal to

[ q 2 + q + 1 , q - 1 ] = ( q 3 - 1 ) / 3 or [ 3 , ( q 2 + q + 1 ) ( q + 1 ) / 3 ] = ( q 2 + q + 1 ) ( q + 1 ) .

Both these numbers divide ( q 3 - 1 ) ( q + 1 ) .

Let Φ 1 = A 1 4 . By Example 2, the exponent of C / Z ¯ divides ( q 2 - 1 ) ( 2 , q - 1 ) .

Let Φ 1 = A 2 . By [3, Corollary 1], every η ( A 2 , w ) divides one of the numbers p ( 2 ) ( q 3 - 1 ) ( q + 1 ) , p ( 2 ) ( q 4 + q 2 + 1 ) , and p ( 2 ) ( q 4 - 1 ) comprising item (3). By Table 7, the last three numbers appear as η ( A 2 , w ) for some 𝑤.

Let Φ 1 = A 2 2 and Π 1 = { - r 0 , r 2 , r 5 , r 6 } . Then Φ 1 = A 2 with fundamental roots r 1 , r 3 and Z ( R ¯ ) is generated by h i ( t i ) for i 2 , 4 with t 5 = t 6 2 , t 6 3 = 1 . In other words, Z ( R ¯ ) = T ¯ 1 × Z ¯ . Since 𝑤 normalizes both factors T ¯ 1 and Z ¯ , it follows that C = ( T ¯ 1 ) σ w × Z ¯ , and therefore C / Z ¯ ( T ¯ 1 ) σ w . Also we have N W ( Π 1 ) = W 2 × w S 3 × Z 2 , where w maps r 1 and r 2 to their negatives (see [10, p. 119]). It follows that the groups ( T ¯ 1 ) σ w are exactly the maximal tori of SL 3 ( q ) and SU 3 ( q ) , and so their exponents give nothing new to item (3).

If Φ 1 = A 2 3 , then exp ( Z ( R ¯ ) ) = 3 , and again we have nothing new.

Let Φ 1 = A 4 or Φ 1 = D 4 . By Tables 8 and 6, the exponent of C / Z ¯ is equal to q - 1 , q 2 - 1 , or q 2 + q + 1 . Since m h ( A 4 ) = 4 and m h ( D 4 ) = 5 , this gives item (4).

Let Φ 1 = A 5 and Π 1 = { - r 0 , r 2 , r 4 , r 5 , r 6 } . Then Φ 1 = A 1 with fundamental root r 1 , and by Table 3, we see that Z ( R ¯ ) = T ¯ 1 × Z ¯ . Also N W ( Π 1 ) = W 2 , so arguing as in the case Φ 1 = A 2 2 , we conclude that C / Z ¯ ( T ¯ 1 ) σ w and that ( T ¯ 1 ) σ w are maximal tori of SL 2 ( q ) . The numbers p ( 5 ) ( q ± 1 ) divide the number p ( 5 ) ( q 2 - 1 ) of item (4).

Let Φ 1 = D 5 and Π 1 = { - r 0 , r 2 , r 4 , r 5 , r 7 } . Then N W ( Π 1 ) = 1 by [10, p. 121] and h Z ( R ¯ ) has the form h 1 ( t - 2 ) h 3 ( t - 1 ) h 5 ( t ) h 6 ( t 2 ) . For w = 1 , the group 𝐶 is defined by t q - 1 t 0 = 1 , t 0 3 = 1 , so C / Z ¯ has exponent q - 1 . Since m h ( D 5 ) = 7 , this gives item (5).

Finally, if Φ 1 = Φ , then Z ( R ~ ) = 1 . Since m h ( E 6 ) = 11 , item (6) follows. This completes the proof. ∎

Award Identifier / Grant number: FWNF-2022-000

Funding statement: This work was supported by RAS Fundamental Research Program, project FWNF-2022-000.

Acknowledgements

  1. Communicated by: Christopher W. Parker

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Received: 2021-11-21
Revised: 2022-05-06
Published Online: 2022-07-27
Published in Print: 2023-01-01

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