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Fixed-point subgroups of GL3(๐‘ž)

  • John Cullinan EMAIL logo
Published/Copyright: May 7, 2019

Abstract

Let V be a vector space over a field k. We call a subgroup GโŠ‚GLโข(V) a fixed-point subgroup if detโก(1-g)=0 for all gโˆˆG. Let q be a power of a prime. In this paper, we classify the fixed-point subgroups of GL3โข(q).

1 Introduction

1.1 Motivation

Let X/๐ be a smooth, projective algebraic variety and โ„“ a rational prime. Then there are โ„“-adic representations

ฯโ„“:Galโข(๐ยฏ/๐)โ†’Autโก(Hรฉtiโข(X๐ยฏ,๐โ„“))

on the รฉtale cohomology groups of X, and the image of such a representation can have interesting consequences for the arithmetic of the variety X. For example, when X is an elliptic curve and ฯโ„“ is the โ„“-adic representation on the Tate module, then the image of ฯโ„“ gives information on the โ„“-power torsion structure of Xโข(๐). A concrete instance of this stems from a question of Lang, answered by Katz [10]. Namely, if X is an elliptic curve over ๐ such that, for all but finitely many primes p, the numbers #โขXpโข(๐…p) are divisible by โ„“n (where Xp denotes the reduction of X modulo a good primes p), then it is true that at least one of the curves Xโ€ฒ in the isogeny class of X has #โขXโ€ฒโข(๐) divisible by โ„“n. By translating to Galois representations, this result amounts to a classification of subgroups G of GL2โข(๐™โ„“) such that detโก(1-g)โ‰ก0(modโ„“n) for all gโˆˆG. One can ask for a similar classification of subgroups of symplectic similitude groups with a view towards higher-dimensional abelian varieties with divisibilities on their number of points modulo p; we provided such classifications in dimensions 4 and 6 in [3, 5, 4, 6] for the groups GSp4โข(๐…โ„“) and GSp6โข(๐…โ„“).

This raises a natural question: If k is a finite field, can one classify the irreducible subgroups of GLnโข(k) such that every element has a fixed point? (By โ€œirreducible subgroupโ€ we mean a subgroup GโŠ‚GLnโข(k) that acts irreducibly on the underlying vector space kn.) Let us call a subgroup G of GLnโข(k) a fixed-point subgroup if every element fixes a point in its natural representation.

By an exercise of Serre [14, Exercise 1], there are no irreducible fixed-point subgroups of GL2โข(k). One of the main results of [10] is that there are no irreducible fixed-point subgroups of GSp4โข(๐…โ„“), where ๐…โ„“ is the field of โ„“ elements. In [3, 5, 4], we classified the fixed-point subgroups of GSp6โข(๐…โ„“) and showed that none are irreducible. However, we recall an example of [4], originally communicated to us by Serre [15]. If L3โข(2) is the simple group of order 168, then the Steinberg representation

๐–ฒ๐—:L3โข(2)โ†’Sp8โข(๐…2)

is absolutely irreducible, and ๐–ฒ๐—โข(L3โข(2)) is a fixed-point subgroup of Sp8โข(๐…2). As an application of this observation, if A is an abelian fourfold defined over a number field K such that the image of the modulo-2 representation

ฯ2ยฏ:Galโข(Kยฏ/K)โ†’Autโก(Aโข[2])

coincides with ๐–ฒ๐—โข(L3โข(2)), then A has the property that, for all but finitely many primes ๐”ญ, the number of points #โขAยฏ๐”ญโข(๐…๐”ญ) on the reduction modulo ๐”ญ of A is even, while no member of the isogeny class of A has an even number of K-rational torsion points. An interesting related question is whether such a fourfold can be realized over ๐.

Leaving the case of abelian varieties and symplectic groups, we focus on three-dimensional representations, which arise naturally in an arithmetic context as well. Using [7] as motivation, one can consider modular forms for congruence subgroups ฮ“0โข(N) of SL3โข(๐™). Given a cuspidal eigenform fโˆˆH3โข(ฮ“0โข(N),๐‚), let ๐f denote the number field generated by the Hecke eigenvalues of f. Let ฮปโˆˆ๐f be a prime dividing โ„“. Then we have attached to f the ฮป-adic Galois representation

ฯฮป:Galโข(๐ยฏ/๐)โ†’GL3โข(๐f,ฮป).

(See [7, ยงโ€‰3] for an explicit example of how such compatible families of representations arise.) The residual representation ฯฮปยฏ then provides a natural setting for studying subgroups of GL3โข(k), where k is a finite field. In the aforementioned example, if imโกฯฮปยฏ is a fixed-point subgroup of GL3โข(k), then we get additional information on congruence properties of the number of points on the variety modulo p, for all but finitely many p, by the Chebatorev density theorem. For this reason, and the ones mentioned above with respect to abelian varieties, the fixed-point subgroups of linear groups have special arithmetic interest.

In this paper, we continue our classification of fixed-point linear groups and determine all fixed-point subgroups of GL3โข(k), where k is a finite field. Unlike the classifications in [3, 5, 4] for the groups GSp4โข(๐…โ„“) and GSp6โข(๐…โ„“), the main theorem of this paper allows for k to be an arbitrary finite field of any characteristic.

1.2 The main theorem

We postpone a review of notation until the next section, except to remark that the maximal subgroups of a finite linear group fall into eight geometric classes ๐’ž1,โ€ฆ,๐’ž8, together with a class ๐’ฎ of exceptional subgroups; we refer the reader to [1] for the details of the classification.

There are certain subgroups of GL3โข(q) that are easily identifiable as fixed-point subgroups, for example, those conjugate to

(1**0**0**)โˆˆGL3โข(q),

and we do not wish to include them in our classification. We therefore declare a subgroup G of GL3โข(q) to be a trivial fixed-point group if the semisimplification of the underlying three-dimensional representation contains the trivial representation. Henceforth, we work exclusively with semisimple groups in this paper as these will have the same fixed-point properties as the parabolic groups they lie in. Our main theorem is as follows; see the following sections for all notational definitions.

Theorem 1.1.

The maximal, non-trivial and semisimple fixed-point subgroups of GL3โข(q) are as follows:

Dimensions of simple factorsIsomorphism typeConditions
(1,1,1)C2ร—C2q odd
(2,1)Dq-1q odd
Dq+1q odd
IrreducibleSym4q odd
SO3โข(q)q odd
Alt55โˆˆ๐…qร—2, pโ‰ 2,3

Remark 1.2.

As a corollary of our theorem, we obtain that there are no irreducible fixed-point subgroups of GL3โข(q) in characteristic 2. In particular, the groups SO3โข(q) and Sym4, each of which is naturally a subgroup of GL3โข(q), fix a line in characteristic 2 (for the former, see [1, Theorem 1.5.41] while the latter is deduced from the Brauer table of Sym4 in characteristic 2).

1.3 Notation and setup

Let k be a finite field of characteristic p (we choose p instead of โ„“ for consistency in the group theory literature), and write k=๐…q, where q=pn. We follow the classification and notational scheme of [1], which is based on Aschbacherโ€™s original classification of the subgroups of the finite classical groups.

Since GL3โข(q) is not a fixed-point group itself, any fixed-point subgroup must lie in a maximal subgroup of GL3โข(q) and hence in one of the eight geometric classes ๐’ž1,โ€ฆ,๐’ž8, or the exceptional class ๐’ฎ. We use the standard notation from finite group theory, basing much of our notational scheme on that of [1]. In particular, we set

  1. Altn: the alternating group on n letters,

  2. Symn: the symmetric group on n letters,

  3. Cn: the cyclic group of order n,

  4. Eq: the elementary abelian group of exponent p and rank n,

  5. Am+n: if A is elementary abelian, then Am+n has elementary abelian normal subgroup Am and quotient An,

  6. p+1+2โขn: the extra-special p group of order p1+2โขn and exponent p,

  7. d: the center of SL3โข(q),

  8. Zโข(q): the center (scalar matrices) of GL3โข(q),

  9. Lnโข(q): the projective special linear group PSLnโข(q),

  10. Aโ‰€B: the wreath product of A and B, where Bโ†ชPermโก(Aร—โ‹ฏร—A),

  11. Nโข.โขQ denotes a non-split extension of Q by N,

  12. Nโข:โขQ denotes a split extension of Q by N,

  13. N.Q denotes an arbitrary extension of Q by N.

Our strategy for proving Theorem 1.1 is roughly as follows. Given a subgroup G of GL3โข(q), we intersect with SL3โข(q) and use the classification of maximal subgroups of SL3โข(q) outlined in [1, Chapter 2] to determine the fixed-point subgroups of SL3โข(q). We then lift back to GL3โข(q) to find the maximal fixed-point subgroups. The issue is that we may encounter novel subgroups โ€“ maximal subgroups M of GL3โข(q) such that MโˆฉSL3โข(q) is not maximal in SL3โข(q). We will address any novelties as they arise. Toward that end, we record the maximal subgroups of SL3โข(q) in Table 1 below; see [1, Table 8.3] for complete details on the subgroup structure of SL3โข(q).

Remark.

There is a typographical error in [1, Table 8.3]: in class ๐’ž1, the group labelled Eq3โข:โขGL2โข(q) should be Eq2โข:โขGL2โข(q). We have corrected this in Table 1.

We also note that the papers [9, 13] provide a classification of the ternary linear groups over finite fields, from which one could recover [1, Table 8.3]; however, we prefer to begin with the classification scheme of [1] due to the modern notation and language.

Table 1

Maximal subgroups of SL3โข(q)

ClassIsomorphism type
๐’ž1Eq2โข:โขGL2โข(q), Eq1+2โข:โข(q-1)2, GL2โข(q)
๐’ž2(q-1)2โข:โขSym3, qโ‰ฅ5
๐’ž3(q2+q+1)โข.3, qโ‰ 4
๐’ž5SL3โข(q0).(q-1q0-1,3) if q=q0r, r prime
๐’ž63+1+2.Q8.(q-1,9)3 if p=qโ‰ก1(mod3)
๐’ž8dร—SO3โข(q) if q is odd
(q0-1,3)ร—SU3โข(q) if q=q02
๐’ฎdร—L2โข(7) if q=pโ‰ก1,2,4(mod7), qโ‰ 2
3โข.โขA6 if q=pโ‰ก1,4(mod15) or q=p2, p=2,3(mod5), pโ‰ 3

The groups in class ๐’ž1 are the parabolic subgroups of GL3โข(q) and we treat them separately in the next section. We then focus the rest of the paper on the irreducible fixed-point subgroups of GL3โข(q).

2 Parabolic fixed-point subgroups of GL3โข(q)

Let G be a semisimple subgroup of GL3โข(q). We break the proof of Theorem 1.1 into two cases, depending on whether the action of G on k3 is reducible or irreducible. In case of a reducible representation, G lies in a parabolic subgroup (type ๐’ž1) of GL3โข(q), and the irreducible factors are either all one-dimensional, or consist of a two-dimensional and one-dimensional factor. (In both cases, we replace the representations with their semisimplifications.) Moreover, we require the classification of subgroups of a direct product, given by Goursatโ€™s lemma [2, p.โ€‰864].

Theorem (Goursatโ€™s lemma).

Let A and B be finite groups. The subgroups G of Aร—B are in one-to-one correspondence with the tuples (G1,G2,G3,ฯˆ), where G1โŠ‚A, G2โŠ‚B, G3โขโŠฒโขG2, and ฯˆ:G1โ†’G2/G3 is a surjective homomorphism.

Beginning with the case where G is a subgroup of the diagonal subgroup Cq-13 of GL3โข(q), we write GโŠ‚(Cq-1ร—Cq-1)ร—Cq-1. We can describe G via two โ€œGoursat tuplesโ€

(H1,H2,H3,ฯˆ),whereโขH1โŠ‚Cq-1ร—Cq-1,H2โŠ‚Cq-1,
(D1,D2,D3,ฯ•),whereโขD1โŠ‚Cq-1,D2โŠ‚Cq-1,

and (D1,D2,D3,ฯ•) is the Goursat tuple corresponding to H1โŠ‚Cq-1ร—Cq-1.

Lemma 2.1.

Suppose G, acting diagonally on Fq3, is a fixed-point subgroup that does not fix a line. Then q is odd, and Gโ‰ƒC2ร—C2.

Proof.

With all notation as above, we assume GโŠ‚(Cq-1ร—Cq-1)ร—Cq-1 is given by the Goursat tuple (H1,H2,H3,ฯˆ), where H1โŠ‚(Cq-1ร—Cq-1), and H1 is given by the Goursat tuple (D1,D2,D3,ฯ•). Let S be the subset of H1 consisting of pairs (x,y) such that neither x nor y is 1. We will show that, unless G is the group specified in the statement of the lemma, the size of S forces G to fix a line. We make several elementary observations:

  1. S lies in kerโกฯˆ (G is a fixed-point group).

  2. H3 is trivial (G contains the elements of the form (kerโกฯˆ,H3), SโŠ‚kerโกฯˆ, and G is a fixed-point group).

  3. Therefore, ฯˆ:H1โ†’H2 is a surjective homomorphism.

We will give several estimates of #โขS below, and so we set the following notation:

hi=#โขHi,di=#โขDi,k=#โขkerโกฯˆ,l=#โขkerโกฯ•.

Combining the observations, we immediately see that

(2.2)k=h1/h2โ‰ฅ#โขS+1,

where the โ€œ+1โ€ is due to the identity of H1.

Since H1 is given by the Goursat tuple (D1,D2,D3,ฯ•), we have h1=d1โขd3. We can estimate the size of S by writing #โขS=h1 minus the number of elements (x,y) of H1 with at least one x or y trivial; that is,

#โขS=d1โขd3-l-d3+1.

Comparing this to (2.2), we get our first estimate

(2.3)d1โขd3/h2โ‰ฅd1โขd3-l-d3+2.

But since lโ‰คd1, we can refine (2.3) to get our second estimate

(2.4)d1โขd3/h2โ‰ฅd1โขd3-d1-d3+2=(d1-1)โข(d3-1)+1.

It is easy to check that the only integer triples

(d1,d3,h2)โ€ƒwithโ€ƒd3โ‰ฅ1โขandโขd1,h2โ‰ฅ2

(recall that G is a non-trivial fixed-point group) satisfying (2.4) are of the form (d1,2,2) or (2,d3,2).

If q is even, then there is no such subgroup of G since q-1 is odd, so we suppose q is odd. We will work through the details of the case (d1,2,2) and omit those of the case (2,d3,2) since they are nearly identical. Therefore, we consider the group

H1={(g,ฯ•โข(g))โˆฃgโˆˆD1โขandโขฯ•:D1โ†’D2/{ยฑ1}}.

In general, there are 2โขd1/d2+1 pairs in H1 with a 1 in one of the components. Therefore, there are

2โขd1-(2โขd1/d2+1)

with both components non-trivial. We impose this condition on the estimate of k:

kโ‰ฅ2โขd1-(2โขd1/d2+1)+1=2โขd1-2โขd1/d2.

Notice that if d2>2, then G would be a trivial fixed-point group since we would have kerโกฯˆ=H1, and so H2 would coincide with H3, which is trivial. Therefore, we may assume d2=2.

Since d2=d3=2, this means D2=D3={ยฑ1}, and so H1 is a direct product H1=D1ร—{ยฑ1}. Including the identity, there are at least d1 elements of H1 that must lie in kerโกฯˆ:

(1,1),(g,-1),โ€ฆ,(gd1-1,-1),

where g is a generator of D1. Since kerโกฯˆ is a subgroup of H1, it follows that (g2,1)โˆˆkerโกฯˆ as well. Unless g2=1, this forces kerโกฯˆ=H1 and G to be a trivial fixed-point group. We conclude that H1={ยฑ1}ร—{ยฑ1}. Together with

[H2โข:โขH3]=2โ€ƒandโ€ƒH3=1,

we get exactly the group C2ร—C2 as claimed in the lemma, which is given explicitly in terms of matrices as

(ฯต1ฯต2ฯต1โขฯต2),

where ฯตiโˆˆ{ยฑ1}. โˆŽ

Next suppose that GโŠ‚GL2โข(q)ร—GL1โข(q) is semisimple with irreducible projection onto GL2โข(q). Since G is a subgroup of a direct product, it is given by a Goursat tuple (H1,H2,H3,ฯˆ), with H1โŠ‚GL2โข(q). As above, we only classify those G which are not direct products, that is, H2โ‰ H3.

Observation.

If GโŠ‚GL2โข(q)ร—GL1โข(q) is a fixed-point subgroup that does not fix a line and is given by the Goursat tuple (H1,H2,H3,ฯˆ), then H3 is trivial. This follows because any gโˆˆH1 without a fixed point is paired via ฯˆ with H3.

Lemma 2.5.

With all notation as above, if G is a fixed-point subgroup of

GL2โข(q)ร—GL1โข(q)

that does not fix a line, then H1 is a proper subgroup of GL2โข(q).

Proof.

It is an elementary counting problem to show that more than half the elements of GL2โข(q) do not have a fixed point once q>2 โ€“ use the fact that there are

  1. q2โข(q-1)2/2 elements with eigenvalues in a quadratic extension,

  2. q-2 non-trivial central elements,

  3. (q-2)โข(q-1)โข(q+1) non-diagonalizable elements without a fixed point.

Dividing by the size of GLโข(2,q), we get

q2โข(q-1)2/2+(q-2)+(q-2)โข(q-1)โข(q+1)q4-q3-q2+q=q3-3โขq2โขq3-2โขq2-2โขq+2>12.

Thus if H1=GL2โข(q), then kerโกฯˆ=GL2โข(q), and so H2=H3. But since H3 is trivial by the observation above, we have that H2 is trivial. If q=2, then H2 is trivial. โˆŽ

By Lemma 2.5, H1 must lie in a proper subgroup of GL2โข(q) and hence lies in a maximal subgroup of GL2โข(q). By [12, Theorem 2.3], the subgroups H of GL2โข(q) not containing SL2โข(q) are described as follows (we use PH to denote the image of H in PGL2โข(q)):

  1. If H contains an element of order q, then either G lies in a Borel subgroup or SL2โข(q)โŠ‚H;

  2. PH is cyclic, and H is contained in a Cartan group;

  3. PH is dihedral, and H is contained in the normalizer of a Cartan group but not in the Cartan subgroup itself;

  4. PH is isomorphic to Alt4, Sym4 or Alt5.

Returning to our setup, if H1 lies in a Borel or a Cartan, then H1 is not irreducible. We therefore focus only on cases (3) and (4) of the subgroup classification of GL2โข(q). We recall from [16, ยงโ€‰3] the explicit description of the normalizers of the Cartan subgroups of GL2โข(q) and adopt that notation in what follows.

Let Csโข(q) and Cnsโข(q) denote the maximal split and non-split Cartan subgroups, respectively. Then Csโข(q)โ‰ƒ๐…qร—ร—๐…qร— and Cnsโข(q)โ‰ƒ๐…q2ร—, and each Cartan group has index 2 in its normalizer, which we denote by Cs+โข(q) and Cns+โข(q), respectively, borrowing the notation of [16]. Each normalizer has a distinguished dihedral subgroup, ๐–ฃsโข(q) and ๐–ฃnsโข(q), respectively, where

๐–ฃsโข(q)โˆฉCsโข(q)=Csโข(q)โˆฉSL2โข(q)โ€ƒandโ€ƒ๐–ฃnsโข(q)โˆฉCnsโข(q)=Cnsโข(q)โˆฉSL2โข(q).

That is, the โ€œrotationโ€ group of ๐–ฃsโข(q) (resp. ๐–ฃnsโข(q)) consists of the elements of Csโข(q) (resp. Cnsโข(q)) of determinant (norm) 1. It follows that

๐–ฃsโข(q)โ‰ƒDq-1โ€ƒandโ€ƒ๐–ฃnsโข(q)โ‰ƒDq+1.

Each dihedral group admits a surjective homomorphism to C2 and, when q is odd, we can realize that homomorphism in the Goursat tuples

Dq-1โ‰ƒ(๐–ฃsโข(q),{ยฑ1},1,ฯˆ)โ€ƒandโ€ƒDq+1โ‰ƒ(๐–ฃnsโข(q),{ยฑ1},1,ฯˆ).

It is easy to check that both dihedral groups are fixed-point subgroups of

GL2โข(q)ร—GL1โข(q)

with irreducible projection to GL2โข(q) that do not fix a line in ๐…q3. We will show in Proposition 2.6 below that these are the only such groups. In preparation for the proof we make some observations.

Observation.

Let GโŠ‚GL2โข(q)ร—GL1โข(q) have Goursat tuple (H1,H2,H3,ฯˆ), and suppose H1 is an irreducible subgroup of GL2โข(q) that normalizes a Cartan subgroup. Let G be a fixed-point group.

  1. The normalizer of the split Cartan group has exactly 3โขq-4 elements with a fixed point; by fixing a basis, we can write these elements explicitly as

    {(x00y):xโขorโขy=1}โˆช{(0zz-10):zโ‰ 0}.
  2. The normalizer of the non-split Cartan group has exactly q non-trivial elements with a fixed point, all of which belong to the non-trivial coset of the Cartan subgroup.

  3. If G does not fix a line, then H1 must contain at least

    #โขH1โ‹…#โขH2-1#โขH2

    elements with a fixed point.

Proposition 2.6.

Let GโŠ‚GL2โข(q)ร—GL1โข(q) be a fixed point group with Goursat tuple (H1,H2,H3,ฯˆ), and suppose H1 normalizes a Cartan subgroup.

If q is even, then H2 is trivial, and so G fixes a line in Fq3. If q is odd, then either H2 is trivial (and so G fixes a line), or G is dihedral with Goursat data (Dsโข(q),{ยฑ1},1,ฯˆ) or (Dnsโข(q),{ยฑ1},1,ฯˆ).

Proof.

We only sketch the proof since it comes down to an exercise in matrix manipulation. Suppose H2 is non-trivial. Because H1 normalizes a split Cartan subgroup, its maximal order is 2โข(3โขq-4) in the split case and 2โข(q+1) in the non-split case, by combining observations (2) and (3) above. When q is odd, in order to create a subgroup H1 (and not merely a subset) satisfying the hypotheses of the proposition, matrix manipulation shows that H1 must be a subgroup of ๐–ฃsโข(q) in the split case and ๐–ฃnsโข(q) in the non-split case and H2={ยฑ1}. When q is even, #โขH2 is odd, and so at least 23 of the elements of H1 must have a fixed point, and H1 must admit a cyclic odd-order quotient with all non-kernel elements having a fixed point. No such subgroup exists. โˆŽ

We conclude this section by analyzing the subgroups of GL2โข(q) with projective image Alt4, Sym4 and Alt5. Let PโขHโˆˆ{Alt4,Sym4,Alt5}. The central extensions of PH are classified by the Schur multiplier. Neither Alt4 nor Alt5 has an ordinary two-dimensional irreducible representation; hence any central extension HโŠ‚GL2โข(q) of PH must be non-trivial for these groups. When PโขH=Sym4, the trivial central extensions of Sym4 do occur as subgroups of GL2โข(q).

In all cases, the Schur multiplier of PH has exponent 2; hence any central extension has the form 2.PโขH times a group of scalar matrices, the order of which can be deduced from [16, Lemma 3.21]. The isomorphism types of 2.PโขH that occur as subgroups of GL2โข(q) are

2.Alt4โ‰ƒSL2โข(3),
2.Alt5โ‰ƒSL2โข(5),
2.Sym4โ‰ƒ{21.Sym4โ‰ƒAlt4โ‹ŠC4,22.Sym4โ‰ƒSL2โข(3).C2โข(non-split),23.Sym4โ‰ƒGL2โข(3),24.Sym4โ‰ƒC2ร—Sym4.

The complexity of the groups 2.Sym4 is due to the fact that the Schur multiplier H2โข(Sym4,C2)โ‰ƒC2ร—C2. We now investigate the groups H for their fixed-point properties.

2.1 Projective image Alt4

Let q be coprime to 6. Let H be a subgroup of GL2โข(q) such that PโขHโ‰ƒAlt4. There are three inequivalent absolutely irreducible ordinary representations ฯƒ1, ฯƒ2 and ฯƒ3 of SL2โข(3), with character values as follows (ฯ‰ denotes a fixed primitive third root of unity):

Class123โขA3โขB46โขA6โขB
ฯ‡12-2-1-1011
ฯ‡22-21+ฯ‰-ฯ‰0ฯ‰-1-ฯ‰
ฯ‡32-2-ฯ‰1+ฯ‰0-1-ฯ‰ฯ‰

The representation ฯƒ1 is defined over ๐™, and ฯƒ1โข(SL2โข(3))โŠ‚SL2โข(q); ฯƒ2โข(SL2โข(3)) and ฯƒ3โข(SL2โข(3)) define subgroups of GL2โข(q) when qโ‰ก1(mod3). In any of the three representations, the only class with a fixed point is the identity.

Lemma 2.7.

Let H be a maximal preimage of Alt4 in GL2โข(q). Let

GโŠ‚GL2โข(q)ร—GL1โข(q)

be a fixed point subgroup of GL3โข(q) with Goursat tuple (H1,H2,H3,ฯˆ). Suppose H1 is an irreducible subgroup of H. Then H2 is trivial.

Proof.

If H is a maximal preimage of Alt4, then it is a product of scalar matrices and the non-trivial extension 2.Alt4 of Alt4. Since all elements of H without a fixed point must belong to kerโกฯˆ, it follows that 2.Alt4 is a subgroup of kerโกฯˆ as well as the group of scalar matrices. Thus ฯˆ is the trivial homomorphism; whence H2 is trivial. โˆŽ

Now we consider the special cases of modular characteristic. If q is even, then any group H such that PโขH=Alt4 is not irreducible in GL2โข(q) [11, Lemma 6.1]. If q is a power of 3, then the isomorphism 2.Alt4โ‰ƒSL2โข(3) shows that 2.Alt4 occurs naturally as a subfield subgroup of GL2โข(q). The same counting argument of Lemma 2.5 shows that more than half the elements of H do not have a fixed point, and hence H cannot give rise to a non-trivial fixed-point subgroup of GL3โข(q).

2.2 Projective image Alt5

Let q be coprime to 30. Then there are two inequivalent ordinary absolutely irreducible representations ฯƒ1 and ฯƒ2 of SL2โข(5) with the following character data:

Class12345โขA5โขB610โขA10โขB
ฯ‡12-2-10-1+52-1-5211+521-52
ฯ‡22-2-10-1-52-1+5211-521+52

In both representations, the only element with a fixed point is the identity.

Lemma 2.8.

Let H be a maximal preimage of Alt5 in GL2โข(q). Let

GโŠ‚GL2โข(q)ร—GL1โข(q)

be a fixed point subgroup of GL3โข(q) with Goursat tuple (H1,H2,H3,ฯˆ). Suppose H1 is an irreducible subgroup of H. Then H2 is trivial.

Proof.

The proof is identical to that of Lemma 2.7. โˆŽ

In modular characteristic, if q is even, then the isomorphism

Alt5โ‰ƒSL2โข(4)=PSL2โข(4)

shows that Alt5 occurs as a subfield subgroup of SL2โข(q) (once q>4). The same counting argument of Lemma 2.5 shows that more than half the elements of H do not have a fixed point, and hence H cannot give rise to a non-trivial fixed-point subgroup of GL3โข(q). The same argument applies when q is a power of 5 via the isomorphism 2.Alt5โ‰ƒSL2โข(5).

If q is a power of 3, then 2.Alt5 only occurs as a subgroup of GL2โข(q) when q is an even power of 3 since it is required that 5โˆˆ(๐…qร—)2. And if q is an even power of 3, then ๐…q contains ๐…9, so it suffices to work in GL2โข(9). In GL2โข(9), the group 2.Alt5 has 15 elements without a fixed point; hence kerโกฯˆ=2.Alt5, and so H2 is trivial.

2.3 Projective image Sym4

Let q be coprime to 6. We consider the four groups 2i.Sym4 for i=1,2,3,4 separately. The group 21.Sym4 has no faithful irreducible degree-2 ordinary representations, and we do not consider unfaithful representations in this analysis for fixed-point subgroups.

The group 22.Sym4 has two faithful irreducible ordinary degree-2 representations ฯƒ1, ฯƒ2 with the following character data:

Class1234โขA4โขB68โขA8โขB
ฯ‡12-2-10012-2
ฯ‡22-2-1001-22

In the representations ฯƒ1 and ฯƒ2, the group 22.Sym4 has no non-trivial elements with a fixed point.

Lemma 2.9.

Let H be a maximal preimage of Sym4 in GL2โข(q) that contains 22.Sym4. Let GโŠ‚GL2โข(q)ร—GL1โข(q) be a fixed point subgroup of GL3โข(q) with Goursat tuple (H1,H2,H3,ฯˆ). Suppose H1 is an irreducible subgroup of H. Then H2 is trivial.

Proof.

The proof is identical to that of Lemma 2.7. โˆŽ

The group 23.Sym4 has two faithful irreducible ordinary degree-2 representations ฯƒ1, ฯƒ2 with the following character data:

Class12โขA2โขB3468โขA8โขB
ฯ‡12-20-101--2-2
ฯ‡22-20-101-2--2

In both representations, there are exactly 35 elements without a fixed point.

Lemma 2.10.

Let H be a maximal preimage of Sym4 in GL2โข(q) that contains 23.Sym4. Let GโŠ‚GL2โข(q)ร—GL1โข(q) be a fixed point subgroup of GL3โข(q) with Goursat tuple (H1,H2,H3,ฯˆ). Suppose H1 is an irreducible subgroup of H. Then H2 is trivial.

Proof.

Any element of 23.Sym4 without a fixed point belongs to kerโกฯˆ; whence kerโกฯˆ contains 23.Sym4 and the scalar matrices. Thus kerโกฯˆ=H1, and so H2 is trivial. โˆŽ

The group 24.Sym4 has two unfaithful irreducible degree-2 representations, and we do not consider unfaithful representations in this analysis.

We finish this section by considering the groups 22.Sym4 and 23.Sym4 in modular characteristic. If q is even, then neither 22.Sym4 nor 23.Sym4 is irreducible [11, Lemma 6.1]. If q is a power of 3, then the isomorphism 23.Sym4โ‰ƒGL2โข(3) shows that H1 occurs as a subfield subgroup of GL2โข(q). The same counting argument of Lemma 2.5 shows that more than half the elements of H do not have a fixed point, and hence H cannot give rise to a non-trivial fixed-point subgroup of GL3โข(q). Finally, 22.Sym4 contains SL2โข(3) as index-2 subgroup, and the full group 22.Sym4 is contained in GL2โข(9). Again, the same counting argument of Lemma 2.5 shows that there are no non-trivial fixed-point subgroups in this case.

3 The irreducible fixed-point subgroups of GL3โข(q)

In this section, we complete the proof of Theorem 1.1 in a case-by-case analysis based on the maximal subgroup classes.

3.1 Subgroups of type ๐’ž2

The maximal subgroup of GL3โข(q) of type ๐’ž2 is isomorphic to GL1โข(q)โ‰€Sym3 as long as qโ‰ฅ5. If G is a subgroup of GL1โข(q)โ‰€Sym3, then G fits into a split short exact sequence

1โ†’G0โ†’Gโ†’Pโ†’1,

where G0 is a subgroup of GL1โข(q)3 and P is subgroup of Sym3. If G is a fixed-point subgroup of GL1โข(q)โ‰€Sym3, then so is G0. By Lemma 2.1, either G0 fixes a line or G0โ‰ƒC2ร—C2.

Lemma 3.1.

Suppose G0 fixes a line. Then any lift G of G0 to GL1โข(q)โ‰€Sym3 fixes a line as well. Therefore, there are no irreducible fixed-point subgroups of type C2 when q is even, or when G0 fixes a line.

Proof.

If G0 fixes a line, then consider the permutation group P. If P is trivial or has order 2, then G is reducible and fixes a line. So we assume P contains a 3-cycle. Choosing a basis with respect to which G0 fixes the first coordinate, we see that G contains matrices of the form

Mโข(ฮฑ,ฮฒ)โข=defโข(1000ฮฑ000ฮฒ)โ€ƒandโ€ƒsโข=defโข(010001100).

In order for a matrix of the form Mโข(ฮฑ,ฮฒ)โขs to have a fixed point, we must take ฮฑโขฮฒ=1. Continuing, the product Mโข(ฮฑ,ฮฑ-1)โขs2โขMโข(ฮฑ,ฮฑ-1)2โขs has a fixed point if and only if ฮฑโˆˆ{ยฑ1}. Finally,

sโขMโข(-1,-1)โขs2=(-1000-10001),

which shows that G0 can only contain the identity matrix Mโข(1,1). But the full permutation group Sym3 fixes a line in this representation. Thus there are no irreducible fixed-point subgroups G such that G0 fixes a line. โˆŽ

Lemma 3.2.

Let q be odd. Suppose G is an irreducible fixed-point subgroup of GL1โข(q)โ‰€Sym3. Then G is isomorphic to Alt4 or Sym4.

Proof.

By Lemmas 2.1 and 3.1, we can assume G0โ‰ƒC2ร—C2, given explicitly by

{(ฯต1ฯต2ฯต1โขฯต2):ฯตiโˆˆ{ยฑ1}}.

An easy calculation shows that the full wreath product (C2ร—C2)โ‹ŠSym3โ‰ƒSym4 is an irreducible fixed-point subgroup of GL1โข(q)โ‰€S3, as well as its subgroup Alt4. โˆŽ

Remark.

It remains to discuss what happens for q<5. When q=2, the group of type ๐’ž2 is not maximal in SL3โข(q), but belongs to the reducible maximal subgroup class of type ๐’ž1. When q=3, the classes ๐’ž2 and ๐’ž8 coincide, in light of the isomorphism SO3โข(3)โ‰ƒSym4, so this group can be considered as an irreducible fixed-point subgroup of type ๐’ž8 as well. When q=4, the group GL1โข(4)โ‰€Sym3 is not a maximal subgroup of GL3โข(4) [1, Proposition 2.3.6].

3.2 Subgroups of type ๐’ž3

There are no irreducible fixed-point subgroups of GL3โข(q) in this class, as we now show. The maximal subgroup of GL3โข(q) in this class is isomorphic to GL1โข(q3)โข.3, with outer automorphisms given by the Galois group Galโข(๐…q3/๐…q).

Remark.

When q=4, the restriction of GL1โข(4)โข.3 to SL3โข(4) is not maximal (see Table 1) in SL3โข(4), but GL1โข(4)โข.3is maximal in GL3โข(4).

Let GโŠ‚GL1โข(q3)โข.3 be a fixed-point subgroup. Then G fits into the short exact sequence

1โ†’Nโ†’Gโ†’Qโ†’1,

where N is a cyclic group of order dividing q3-1 and Q is either trivial or isomorphic to C3.

Let g be a generator for the group GL1โข(q3) and ฯƒ a generator of Galโข(๐…q3/๐…q); in this representation, the eigenvalues of g have the form ฮณ,ฮณฯƒ,ฮณฯƒ2. Because GL1โข(q3) is cyclic and because the eigenvalues of any power of g are powers of ฮณ, ฮณฯƒ and ฮณฯƒ2, it follows that the only element of GL1โข(q3) with a fixed point is the identity. The trivial group lifts to a cyclic group of order 3 inside GL1โข(q3)โข.3, and every element of such a C3 has a fixed point, but the group is not irreducible.

3.3 Subgroups of type ๐’ž5

These are the field-restriction subgroups of GL3โข(q); that is, if we can write q=q0r, then GL3โข(q0) is naturally a subgroup of GL3โข(q). When r is prime, the group generated by GL3โข(q0) and the center Zโข(q) of GL3โข(q) is the maximal subgroup of GL3โข(q) of type ๐’ž5.

Suppose r is prime, and let ๐’ข=ใ€ˆGL3โข(q0),Zโข(q)ใ€‰. Let G be an irreducible fixed-point subgroup of ๐’ข. Because no non-trivial element of Zโข(q) has a fixed point, it follows that G is an irreducible fixed-point subgroup of GL3โข(q0). Since we seek to classify the subgroups of type ๐’ž5, we may assume (by descent) that G is an irreducible fixed-point subgroup of GL3โข(p), hence lies in a subgroup class other than ๐’ž5. Therefore, the class ๐’ž5 contains no irreducible fixed-point subgroups of GL3โข(q) that are not already contained in another class.

3.4 Subgroups of type ๐’ž6

There are no irreducible fixed-point subgroups of GL3โข(q) in this class, as we now show. We first classify the fixed-point subgroups of SL3โข(q) in this class and then lift them to GL3โข(q). Recall from Table 1 that q=pโ‰ก1(mod3).

Lemma 3.3.

Let G be a non-trivial fixed-point subgroup of

3+1+2.Q8.(q-1,9)3โŠ‚SL3โข(q).

Then Gโ‰ƒQ8 or Gโ‰ƒC3.

Proof.

This is a finite computation, easily performed in Magma, and we omit the details. The result is that there are, up to isomorphism, two fixed-point subgroups of 3+1+2.Q8.(q-1,9)3: a cyclic group of order 3, and Q8. โˆŽ

Lemma 3.4.

There is no irreducible fixed-point subgroup of GL3โข(q) of type C6 that restricts to Q8.

Proof.

The group Q8 is normal in any subgroup of GL3โข(q) that restricts to

Q8โŠ‚SL3โข(q).

The three-dimensional representation of Q8 decomposes into a two-dimensional factor and a one-dimensional factor. By Cliffordโ€™s theorem, any lift of Q8 to GL3โข(q) retains this decomposition; whence there are no irreducible subgroups of GL3โข(q) restricting to Q8. โˆŽ

Lemma 3.5.

There is no irreducible fixed-point subgroup of GL3โข(q) of type C6 that restricts to the fixed-point C3โŠ‚3+1+2.Q8.(q-1,9)3โŠ‚SL3โข(q).

Proof.

Because qโ‰ก1(mod3), the representation of the fixed-point C3 is completely reducible and decomposes into three one-dimensional representations, one of which is trivial. By Cliffordโ€™s theorem, the representation of any subgroup of GL3โข(q) restricting to C3 is either a sum of three one-dimensional representations, or is irreducible. If it were irreducible, the three one-dimensional representations of C3 (upon restriction) would be conjugate. Since only one of the three is trivial and a non-trivial representation cannot be conjugate to a trivial, it follows that the representation of any overgroup C3.m of C3 is not irreducible. This proves the lemma. โˆŽ

3.5 Subgroups of type ๐’ž8

There are two isomorphism types of maximal subgroups of SL3โข(q) of type ๐’ž8, namely, dร—SO3โข(q) and (q0-1,3)ร—SU3โข(q0) if q=q02. Moreover, this class contains no novel subgroups. We first consider the case of dร—SO3โข(q).

The group SO3โข(q) is a fixed-point group [8, Proposition 6.10] and is irreducible in odd characteristic. If qโ‰ข1(mod3), then SO3โข(q) is maximal in SL3โข(q), while if qโ‰ก1(mod3), then dร—SO3โข(q) is maximal, with d a scalar group of order 3. Because d is scalar, the maximal fixed-point subgroup of dร—SO3โข(q) is SO3โข(q). Thus, for all q, the maximal fixed-point subgroup of SL3โข(q) of type ๐’ž8 is SO3โข(q).

It remains to determine whether there exist fixed-point groups H that fit into the sequence SO3โข(q)โŠ‚HโŠ‚GL3โข(q) of proper containments. The groups of type ๐’ž8 are scalar-normalizing [1, Definition 4.4.4] in the sense that any such group H has the presentation SO3โข(q)โขZ, where Z is a subgroup of the scalars of GL3โข(q). Thus any overgroup H properly containing SO3โข(q) is necessarily not a fixed-point group (some non-trivial element of Z multiplies the identity of SO3โข(q)). We therefore have the following result.

Lemma 3.6.

Let q be a power of an odd prime. The maximal irreducible fixed-point subgroup of GL3โข(q) containing SO3โข(q) is SO3โข(q).

Next we consider the case of the subgroup (q0-1,3)ร—SU3โข(q0) of SL3โข(q) and, more generally, the subgroup GU3โข(q0) of GL3โข(q). We will show that there are no additional irreducible fixed-point subgroups arising in this class that have not already been classified. First the group GU3โข(q0) is not itself a fixed-point group; hence any irreducible fixed-point subgroup must lie in one of its maximal subgroups. We list the non-parabolic maximal subgroups of GU3โข(q0) and SU3โข(q0).

  1. Type ๐’ž2: GU1โข(q0)โ‰€Sym3 is the maximal subgroup of GU3โข(q0) of type ๐’ž2. The same argument as in Lemma 3.2 applies and shows the maximal irreducible fixed-point subgroup is isomorphic to Sym4.

  2. Type ๐’ž3: GU1โข(q03)โข.3 is the maximal subgroup of GU3โข(q0) of type ๐’ž3. The same argument as in Section 3.2 applies and shows there are no irreducible fixed point subgroups in this class.

  3. Type ๐’ž5: there are two subgroups of SU3โข(q0) in this class,

    SU3(q1).(q+1q1+1,3)โ€ƒ(ifq0=q1rfor primer)โ€ƒandโ€ƒSO3(q).
  4. Type ๐’ž6: there is one maximal subgroup of SU3โข(q0) in this class,

    3+1+2.Q8.(q+1,9)3.
  5. Type ๐’ฎ: there are four isomorphism classes of subgroups of type ๐’ฎ of SU3โข(q):

    1. dร—L2โข(7) (d conjugates, q=pโ‰ก3,5,6(mod7), qโ‰ 5), where

      d=gcdโก(q+1,3),
    2. 3โข.โขAlt6 (3 conjugates, q=pโ‰ก11,14(mod15)),

    3. 3โข.โขAlt6โข.23 (3 conjugates, q=5),

    4. 3โข.โขAlt7 (3 conjugates, q=5).

Many of the same arguments as in the previous sections apply here as well. In particular,

  1. in class ๐’ž5, the same descent argument as in Section 3.3 shows that it is enough to classify the maximal subgroups of SU3โข(p);

  2. in class ๐’ž6, the same argument as in Section 3.4 applies as well: the only fixed-point subgroups of 3+1+2.Q8.(q+1,9)3 are C3 and Q8 and, by the same Cliffordโ€™s theorem argument, any lift to GU3โข(q) is reducible.

It remains to analyze the subgroups of type ๐’ฎ. We delay our treatment of dร—L2โข(7) and 3โข.โขAlt6 until the next section so that we can give a unified treatment of these two groups; they occur as maximal subgroups of SL3โข(q) for certain q and SU3โข(q) for others. We now consider the two subgroups 3โข.โขAlt6โข.23 and 3โข.โขAlt7 of SU3โข(5).

In both cases, we search in the subgroup lattices of 3โข.โขAlt6โข.23 and 3โข.โขAlt7 for fixed-point subgroups. One can check that the conjugacy classes of elements of order 1, 2, 5 have fixed points, while some of the classes of order 3, 4 and 6 do as well. The result of the search is that the following are the isomorphism types of fixed-point subgroups of 3โข.โขAlt6โข.23 and 3โข.โขAlt7:

{Cj}j=1,โ€ฆ,5,F20.

Setting aside the group C5, each of the fixed-point groups listed above is reducible, and the semisimplification of each representation consists of three one-dimensional representations, one of which is trivial. The identical Cliffordโ€™s theorem argument of Section 3.4 shows that none of these groups lifts to an irreducible fixed-point subgroup of GL3โข(25). For the group C5, the semisimplification consists of three trivial representations, so the Cliffordโ€™s theorem argument does not immediately rule out an irreducible fixed-point subgroup of GL3โข(25). However, a search for all subgroups of GL3โข(25) of the form C5.m that are irreducible fixed-point subgroups reveals none. All computations for this section were performed in Magma.

3.6 Subgroups of type ๐’ฎ

We complete the classification of irreducible fixed-point subgroups of GL3โข(q) with the groups of type ๐’ฎ, and we incorporate two of the type ๐’ฎ subgroups of GU3โข(q) into this section as well. We recall the conditions under which each of these groups occur.

Subgroup ofConditions
SL3โข(q)(q-1,3)ร—L2โข(7)q=pโ‰ก1,2,4(mod7), qโ‰ 2
3โข.โขAlt6q=pโ‰ก1,4(mod15)
q=p2, pโ‰ก2,3(mod5), pโ‰ 3
SU3โข(q)(q+1,3)ร—L2โข(7)q=pโ‰ก3,5,6(mod7), qโ‰ 5
3โข.โขAlt6q=pโ‰ก11,14(mod15)

The simple group L2โข(7) of order 168 has an absolutely irreducible three-dimensional representation over ๐…q when -7โˆˆ(๐…qร—)2, and the group 3โข.โขAlt6 has an absolutely irreducible representation over ๐…q when -3,5โˆˆ(๐…qร—)2. The conditions on q reflect these requirements. We start with dร—L2โข(7).

Lemma 3.7.

Let G be a maximal, irreducible fixed-point subgroup of

(q-1,3)ร—L2โข(7)โŠ‚SL3โข(q)โ€ƒ๐‘œ๐‘Ÿโ€ƒ(q+1,3)ร—L2โข(7)โŠ‚SU3โข(q),

subject to the conditions on q in the tables above. Then Gโ‰ƒSym4.

Proof.

In either case, a fixed-point subgroup intersects the center trivially; hence GโŠ‚L2โข(7). The maximal subgroup Sym4 of L2โข(7) is an absolutely irreducible fixed-point subgroup, so it remains to show that no element of order 7 has a fixed point for any allowable q.

Fix a primitive seventh root of unity ฯ‰โˆˆ๐…ยฏq. Then the characteristic polynomial on either class of order 7, evaluated at 1 is given by

43โขฯ‰โข(ฯ‰-1)โข(ฯ‰4+2โขฯ‰3+ฯ‰2+2โขฯ‰+1)โ‰ 0.

The inequality follows from the observation that if ฯ‰4+2โขฯ‰3+ฯ‰2+2โขฯ‰+1=0, then the resultant

Resโก(ฯ‰4+2โขฯ‰3+ฯ‰2+2โขฯ‰+1,ฯ‰6+ฯ‰5+ฯ‰4+ฯ‰3+ฯ‰2+ฯ‰+1)=72=0,

which is impossible since q is coprime to 7. โˆŽ

Lemma 3.8.

Let G be a maximal, irreducible fixed-point subgroup of

3โข.โขAlt6โŠ‚SL3โข(q).

Then Gโ‰ƒAlt4 or Alt5.

Proof.

Since 3โข.โขAlt6 contains the center of SL3โข(q), any fixed-point subgroup must be proper. There are five maximal subgroups of 3โข.โขAlt6:

3+1+2โข.4,dร—Alt4โข(two copies),dร—Alt5โข(two copies).

The group 3+1+2โข.4 was analyzed previously in Section 3.4 and does not possess any irreducible fixed-point subgroups. On the other hand, one can check that the (centerless) groups Alt4 and Alt5 of the remaining cases are each irreducible fixed-point subgroups. โˆŽ

The groups of type ๐’ฎ are scalar normalizing [1, Proposition 4.5.2], and so there are no irreducible fixed-point overgroups HโŠ‚GL3โข(q) that properly contain the Alt4, Sym4 or Alt5 of the lemmas above. This completes the classification of non-trivial fixed-point subgroups of GL3โข(q) stated in Theorem 1.1.


Communicated by Nigel Boston


Acknowledgements

We would like to thank the referee for pointing out several errors in an initial draft and for additional suggestions which improved the clarity and exposition of the paper.

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Received: 2018-08-13
Revised: 2019-03-15
Published Online: 2019-05-07
Published in Print: 2019-09-01

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