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Hyperbolic and cubical rigidities of Thompson’s group V

  • Anthony Genevois EMAIL logo
Published/Copyright: November 3, 2018

Abstract

In this article, we state and prove a general criterion allowing us to show that some groups are hyperbolically elementary, meaning that every isometric action of one of these groups on a Gromov-hyperbolic space either fixes a point at infinity, or stabilises a pair of points at infinity, or has bounded orbits. Also, we show how such a hyperbolic rigidity leads to fixed-point properties on finite-dimensional CAT(0) cube complexes. As an application, we prove that Thompson’s group V is hyperbolically elementary, and we deduce that it satisfies Property (FW), i.e., every isometric action of V on a finite-dimensional CAT(0) cube complex fixes a point. It provides the first example of a (finitely presented) group acting properly on an infinite-dimensional CAT(0) cube complex such that all its actions on finite-dimensional CAT(0) cube complexes have global fixed points.

1 Introduction

A major theme in geometric group theory is to make a given group act on a metric space which belongs to a specific class 𝒞 in order to deduce some information about it. However, not every group is sensitive to a given class of spaces, meaning that every isometric action of a fixed group on any one of these spaces may turn out to be trivial in some sense. Nevertheless, although the machinery of group actions on spaces of 𝒞 cannot be applied, it turns out that the non-existence of good actions provides interesting information as well. Roughly speaking, it implies some rigidity phenomena.

The first occurrence of such an idea was Serre’s Property (FA). A group satisfies Property (FA) if every isometric action on a simplicial tree fixes a point. We refer to [45, Section 6] for more information about this property. For instance, Property (FA) imposes restrictions on how to embed a given group into another (see for instance [24] in the context of 3-manifolds), and more generally on the possible homomorphisms between them (see for instance [21, Corollary 4.37] in the context of relatively hyperbolic groups). Also, such a rigidity has been applied in [33] to determine when the fundamental groups of two graphs of groups whose vertex-groups satisfy Property (FA) are isomorphic.

Another famous fixed-point property is Kazhdan’s Property (T). Usually, Property (T) is defined using representation theory, but alternatively, one can say that a (discrete) group satisfies Property (T) if every affine isometric action on a Hilbert space has a global fixed point, or equivalently if every isometric action on a median space has bounded orbits. See [2] and [13] for more information. Property (T) for a group imposes, for instance, strong restrictions on the possible homomorphisms starting from that group (for a geometric realisation of this idea, see for example [42], whose main construction has been very inspiring in other contexts), and plays a fundamental role in several rigidity statements, including the famous Margulis’ superrigidity. We refer to [2], and in particular to its introduction, for more information about Property (T).

In this article, we are mainly interested in the class of Gromov-hyperbolic spaces. We say that a group is hyperbolically elementary if every isometric action on a hyperbolic space either fixes a point at infinity, or stabilises a pair of points at infinity, or has bounded orbits. Once again, such a property imposes restrictions on the possible homomorphisms between two groups. For instance, it is proved in [32] that higher rank lattices are hyperbolically elementary, from which it is deduced that any morphism from a higher rank lattice to the mapping class group of a closed surface with punctures must have finite image (a statement originally due to Farb, Kaimanovich and Masur). It is worth noticing that a hyperbolically elementary group either satisfies Serre’s Property (FA) or surjects onto or D, so that being hyperbolically elementary is essentially a generalisation of Property (FA), which is not necessarily much harder to prove, see for instance [20] about branch groups.

We emphasise the fact that it is not reasonable to remove the possibility of fixing a point at infinity from the definition of hyperbolic elementarity. Indeed, any infinite group admits a proper and parabolic action on a hyperbolic space; see for instance the classical construction explained in [35, Section 4]. However, being hyperbolically elementary does not mean that any isometric action on a hyperbolic space is completely trivial, since the definition does not rule out lineal actions (i.e., actions on a quasi-line) nor quasi-parabolic actions (i.e., actions with loxodromic isometries all sharing a point at infinity). And these actions may provide interesting information on a group. For instance, admitting lineal actions is related to the existence of quasimorphisms; and admitting a quasi-parabolic action implies the existence of free sub-semigroups, so that the group must have exponential growth.

The first main objective of our article is to prove a general criterion leading to some hyperbolic rigidity. More precisely, we have the following theorem.

Theorem 1.1.

Let G be a group. Suppose that there exist two subsets ABG satisfying the following conditions.

  1. G is boundedly generated by A, i.e., there exists some N0 such that every element of G is the product of at most N elements of A.

  2. For every a,bB, there exist g,hG such that

    [gag-1,a]=[gag-1,hgag-1h-1]=[hgag-1h-1,b]=1.
  3. For every a,bG, there exist some h,h1,,hrB such that the following holds. For every kA, there exists some fh1hr such that the elements fkf-1h, fkf-1ha and fkf-1hb all belong to B.

Then any isometric action of G on a hyperbolic space fixes a point at infinity, or stabilises a pair of points at infinity, or has bounded orbits.

Correction added on 17 January 2019 after online publication: The second item has been modified (producing a more general statement). The previous statement and its proof were correct, but the new formulation allowed us to correct a mistake in the proof of Theorem 4.6 below.

Our main motivation in proving this criterion is to show that Thompson’s group V is hyperbolically elementary.

Theorem 1.2.

Any isometric action of Thompson’s group V on a Gromov-hyperbolic space either fixes a point at infinity or has bounded orbits.

The groups F, T and V were defined by Richard Thompson in 1965. Historically, Thompson’s groups T and V are the first explicit examples of finitely presented simple groups. Thompson’s groups were also used in [39] to construct finitely presented groups with unsolvable word problems, and in [47] to show that a finitely generated group has a solvable word problem if and only if it can be embedded into a finitely generated simple subgroup of a finitely presented group. We refer to [10] for a general introduction to these three groups. Since then, plenty of articles have been dedicated to Thompson’s groups, and they have been the source of inspiration for the introduction of many classes of groups, now referred to as Thompson-like groups; see for instance [34, 7, 46, 6, 25, 5, 3]. Nevertheless, Thompson’s groups remain mysterious, and many questions are still open. For instance, it is a major open question to know whether F is amenable, and the structure of subgroups of V is still essentially unknown [8].

Our initial motivation in proving Theorem 1.2 came from another fixed-point property, in the class of CAT(0) cube complexes. A group G

  1. satisfies Property (FWn), for some n0, if every isometric action of G on an n-dimensional CAT(0) cube complex has a global fixed point,

  2. satisfies Property (FW) if it satisfies Property (FWn) for every n0,

  3. satisfies Property (FW) if every isometric action of G on a CAT(0) cube complex has a global fixed point.

Property (FW) was introduced by Barnhill and Chatterji in [1][1], asking the difference between Kazhdan’s Property (T) and Property (FW). It turns out that in general Property (T) is quite different from Property (FW) or Property (FW). For instance, it is conjectured in [18] that higher rank lattices satisfy Property (FW), but such groups may be far from satisfying Property (T) since some of them are a-T-menable. For positive results in this direction, see [14, Corollary 1.7], [17, Example 6.A.7], [18, Theorem 6.14]. For some (very) recent developments related to Property (FW), see [11, 38, 19].

The second main result of our article shows how to deduce Property (FW) from some hyperbolic rigidity. More explicitly:

Theorem 1.3.

A finitely generated group all of whose finite-index subgroups

  1. are hyperbolically elementary,

  2. and do not surject onto

satisfies Property (FW).

We emphasise that the property of being hyperbolically elementary is not stable under taking finite-index subgroups, as shown by Example 5.3. Since Thompson’s group V is a simple group, the combination of our two main theorems immediately implies that V satisfies Property (FW).

Corollary 1.4.

Any isometric action of Thompson’s group V on a finite-dimensional CAT(0) cube complex fixes a point.

We emphasise that it was previously known that V (as well as F and T) does not act properly on a finite-dimensional CAT(0) cube complex. In fact, since V contains a free abelian group of arbitrarily large rank, it follows that V cannot act properly on any contractible finite-dimensional complex.

Corollary 1.4 contrasts with the known fact that V acts properly on a locally finite infinite-dimensional CAT(0) cube complex. (Indeed, Guba and Sapir showed in [31, Example 16.6] that V coincides with the braided diagram group Db(𝒫,x), where 𝒫 is the semigroup presentation xx2=x; and Farley constructed in [22] CAT(0) cube complexes on which such groups act.) As a consequence, V provides another negative answer to [1, Question 5.3], i.e., V is a new example of a group satisfying Property (FW) but not Property (T). Indeed, as a consequence of [41], a group acting properly on a CAT(0) cube complex does not satisfy Property (T); in fact such a group must be a-T-menable, according to [40], which is a strong negation of Kazhdan’s Property (T).

So V provides an example of a tough transition between finite and infinite dimensions, since on the one hand, V has the best possible cubical geometry in infinite dimension: it acts properly on a locally finite CAT(0) cube complex; and on the other hand, it has the worst possible cubical geometry in finite dimension: every isometric action of V on a finite-dimensional CAT(0) cube complex has a global fixed point. Using the vocabulary of [17], Thompson’s group V satisfies Property PW and Property (FWn) for every n0. It seems to be the first such example in the literature.

We would like to emphasise the fact that, although our article is dedicated to Thompson’s group V, we expect that Theorem 1.1 applies to most of the generalisations of V. For instance, without major modifications, our arguments apply to Higman–Thompson groups Vn,r (n2, r1), to the group of interval exchange transformations IET([0,1]), and to Neretin’s group. However, since there does not exist a common formalism to deal with all the generalisations of V, we decided to illustrate our strategy by considering only V. Therefore, our paper should not be regarded as proving a specific statement about V, but as proposing a general method to prove hyperbolic and cubical rigidities of groups looking like V. In particular, we expect that our strategy works for higher-dimensional Thompson groups.

Finally, we would like to mention that Thompson’s group F is also hyperbolically elementary, since it does not contain any non-abelian free subgroup, but it does not satisfy Property (FW) since its abelianisation is infinite. About Thompson’s group T, the situation is less clear, and our strategy does not work. So we leave it as an open question:

Question 1.5.

Is Thompson’s group T hyperbolically elementary? Does it satisfy Property (FW)?[2]

The paper is organised as follows. First, Section 2 is dedicated to basic definitions and preliminary lemmas about hyperbolic spaces and CAT(0) cube complexes. In Section 3, we introduce and study a family of particular elements of V, named reducible elements. Finally, in Sections 4 and 5 respectively, we prove our general criteria, namely Theorems 1.1 and 1.3, and we prove Theorem 1.2 and Corollary 1.4 by applying them to V.

2 Preliminaries

2.1 Hyperbolic spaces

In this section, we recall some basic definitions about Gromov-hyperbolic spaces, we fix the notation that will be used in the paper, and we prove a few preliminary lemmas which will be useful later on. For more general information about hyperbolic spaces, we refer to [30, 29, 16, 4].

Definition 2.1.

Let X be a metric space. For every x,y,zX, the Gromov product(x,y)z is defined as

12(d(z,x)+d(z,y)-d(x,y)).

Fixing some δ0, the space X is δ-hyperbolic if the inequality

(x,z)wmin((x,y)w,(y,z)w)-δ

is satisfied for every x,y,z,wX.

The following definitions will also be needed:

  1. A map f:XY between two metric spaces is an (A,B)-quasi-isometric embedding, where A>0 and B0, if

    1Ad(x,y)-Bd(f(x),f(y))Ad(x,y)+B

    for every x,yX. If f is moreover every point of Y is at distance at most B from the image of f, then f is an (A,B)-quasi-isometry. A quasi-isometry (resp. a quasi-isometric embedding) is a map which an (A,B)-quasi-isometry (resp. an (A,B)-quasi-isometric embedding) for some A>0 and B0.

  2. Given a metric space X and two constants A>0 and B0, an (A,B)-quasigeodesic is an (A,B)-quasi-isometric embedding from a segment of or (depending on whether the metric of X is discrete) to X. A quasigeodesic is an (A,B)-quasigeodesic for some A>0 and B0.

  3. Given a geodesic metric space X and a constant K0, a subspace YX is K-quasiconvex if every geodesic between two points of Y stays in the K-neighbourhood of Y.

  4. Given a metric space X and a subspace YX, the nearest-point projection of a point xX onto Y is the set of all the points of Y minimising the distance to x. The nearest-point projection of another subspace ZX onto Y is the union of all the nearest-point projections of the points of Z onto Y.

Usually, it is easier to work with geodesic metric spaces instead of general metric spaces. The following lemma explains a classical trick which allows us to restrict our study to hyperbolic graphs.

Lemma 2.2.

Let X be metric space. If Y denotes the graph whose vertices are the points of X and whose edges link two points at distance at most one, then the inclusion XY is a (1,0)-quasi-isometry such that any isometry of X extends uniquely to an isometry of Y. As a consequence, if X is hyperbolic, then so is Y.

From now on, all our (hyperbolic) metric spaces will be graphs.

Fixing a graph X, three vertices x,y,zX and a geodesic triangle

Δ=[x,y][y,z][z,x],

there exists a unique tripod T and a unique map f:ΔT such that:

  1. f(x),f(y),f(z) are the endpoints of T,

  2. f restricts to an isometry on each [x,y], [y,z], [z,x].

The data (T,f) is the comparison tripod of Δ, and the three (not necessarily distinct) points of Δ sending to the center of T define the intriple of Δ.

The following statement is an alternative definition of hyperbolic spaces (among geodesic metric spaces). We refer to the proof of [29, Proposition 2.21] for more information.

Proposition 2.3.

Let X be a δ-hyperbolic graph. For all vertices x,y,zX and every geodesic triangle Δ=Δ(x,y,z), if (T,f) denotes the comparison tripod of T, then d(a,b)4δ for every a,bΔ satisfying f(a)=f(b).

The next statement is a fundamental property satisfied by hyperbolic spaces, often referred to as the Morse Property. See for instance [4, Theorem III.H.1.7].

Theorem 2.4.

Let X be a δ-hyperbolic graph. For every A>0 and every B0, there exists some M(δ,A,B), called the Morse constant, such that: for every x,yX, any two (A,B)-quasigeodesics between x and y stay at Hausdorff distance at most M(δ,A,B).

Now, let us prove two preliminary lemmas which will be useful in the next sections.

Lemma 2.5.

Let X be a δ-hyperbolic graph and let γ1,γ2 be two lines which are K-quasiconvex for some K0. For every x1γ1 and x2γ2, any geodesic [x1,x2] between x1 and x2 intersects the M(δ,1,2(4δ+K))-neighbourhood of the nearest-point projection of x1 onto γ2.

Proof.

Fix two points x1γ1 and x2γ2, and a geodesic [x1,x2] between them. Let pγ2 be a nearest-point projection of x1 onto γ2. Fixing some geodesics [x1,p] and [p,x2], we claim that [x1,p][p,x2] is a (1,2(4δ+K)-quasigeodesic.

The only point to verify is that, given two points a[x1,p] and b[p,x2], the inequality

d(a,b)d(a,p)+d(p,b)-2(4δ+K)

holds. Let us consider a geodesic triangle Δ=Δ(a,b,p), and let {q1,q2,q3} denote its intriple where q1[a,b], q2[a,p] and q3[b,p]. Notice that, since γ2 is K-quasiconvex, there exists some qγ2 satisfying d(q3,q)K. One has

d(a,b)=d(a,q1)+d(q1,b)=d(a,q2)+d(b,q3)
=d(a,p)-d(p,q2)+d(p,b)-d(q3,p)
=d(a,p)+d(p,b)-2d(p,q2).

On the other hand,

d(x1,q2)+d(q2,p)=d(x1,γ2)d(x1,q)
d(x1,q2)+d(q2,q3)+d(q3,q)
d(x1,q2)+4δ+K,

hence d(p,q2)4δ+K. Our claim follows. We register our conclusion for future use.

Fact 2.6.

Let X be a δ-hyperbolic graph, γ a K-quasiconvex line, and aX, bγ two vertices. If pγ denotes a nearest-point projection of a onto γ, then any concatenation [a,p][p,b] defines a (1,2(4δ+K))-quasigeodesic.

Now, we conclude from the Morse property that the Hausdorff distance between [x1,x2] and [x1,p][p,x2] is at most M(δ,1,2(4δ+K)). The desired conclusion follows. ∎

Lemma 2.7.

Let X be a δ-hyperbolic graph, x,yX two vertices and let γ be a K-quasiconvex line. Fix two nearest-point projections x,yγ respectively of x,y onto γ, and suppose that d(x,y)>36δ+5K. Then

d(x,x)+d(x,y)+d(y,y)-4(6δ+K)d(x,y)
d(x,x)+d(x,y)+d(y,y).

Proof.

The right-hand side of our inequality is a consequence of the triangle inequality, so we only have to prove its left-hand side.

Fix some geodesics [x,y], [x,y], [x,x], [y,y] and [x,y]. Let {p1,p2,p3} be the intriple of the geodesic triangle Δ(x,y,x), where p1[x,x], p2[x,y], p3[x,y]; and similarly let {q1,q2,q3} be the intriple of the geodesic triangle Δ(x,y,y) where q1[y,y], q2[x,y], q3[x,y]. Notice that, since γ is K-quasiconvex, there exists some qγ satisfying d(q2,q)K. The configuration is summarised by Figure 1. Notice that

d(y,q1)+d(q1,y)=d(y,γ)d(y,q)
d(y,q1)+d(q1,q2)+d(q2,q)
d(y,q1)+4δ+K,

hence d(y,q1)4δ+K. Now, we distinguish two cases.

Figure 1 The configuration of points in the proof of Lemma 2.7.
Figure 1

The configuration of points in the proof of Lemma 2.7.

Case 1: Suppose that d(x,p3)d(x,q3). In this case, there exists some p3[x,y] satisfying d(p3,p3)4δ, and because γ is K-quasiconvex, there exists some p3′′γ satisfying d(p3,p3′′)K. One has

d(x,p1)+d(p1,x)=d(x,x)=d(x,γ)d(x,p3′′)
d(x,p1)+d(p1,p3)+d(p3,p3)+d(p3,p3′′)
d(x,p1)+4δ+4δ+K,

hence d(x,p1)8δ+K. Next, notice that

d(x,y)=d(x,p2)+d(p2,y)=d(x,p1)+d(y,p3)
=d(x,x)-d(x,p1)+d(y,x)-d(x,p3)
=d(x,x)+d(y,x)-2d(x,p1)

and that

d(y,x)=d(y,q3)+d(q3,x)=d(y,q1)+d(x,q2)
=d(y,y)-d(y,q1)+d(x,y)-d(y,q2)
=d(y,y)+d(x,y)-2d(y,q1).

We conclude that

d(x,y)=d(x,x)+d(x,y)+d(y,y)-2(d(x,p1)+d(y,q1))
d(x,x)+d(x,y)+d(y,y)-4(6δ+K).

Case 2: Suppose that d(x,p3)>d(x,q3). As a consequence, there exists some q3[x,x] satisfying d(q3,q3)4δ. Notice that

d(x,q3)+d(q3,x)=d(x,γ)d(x,q)
d(x,q3)+d(q3,q3)+d(q3,q2)+d(q2,q)
d(x,q3)+4δ+4δ+K,

hence d(q3,x)4(6δ+K). Therefore,

d(x,y)d(x,q3)+d(q3,q3)+d(q3,q1)+d(q1,y)
4(6δ+K)+4δ+4δ+(4δ+K),

i.e., d(x,y)36δ+5K. This contradicts our assumptions, so our second case cannot happen. ∎

Corollary 2.8.

Let X be a δ-hyperbolic graph, x,yX two vertices, [x,y] a geodesic between x and y, and γ a K-quasiconvex line. Fix two nearest-point projections x,yγ respectively of x,y onto γ, and suppose that d(x,y)>36δ+5K. Then d(x,y)d(x,x), so that there exists a unique point a[x,y] satisfying d(x,a)=d(x,x), and moreover d(a,x)2M(δ,1,4(6δ+K)).

Proof.

First of all, notice that, as a consequence of Lemma 2.7, one has

d(x,y)d(x,x)+d(x,y)+d(y,y)-4(6δ+K)
>d(x,x)+36δ+5K-4(6δ+K)d(x,x),

which proves the first assertion of our statement.

Fix some geodesics [x,x], [y,y], [x,y]. As a consequence of Fact 2.6 and Lemma 2.7, we know that [x,x][x,y][y,y] defines a (1,4(6δ+K))-quasigeodesic between x and y. It follows from the Morse property that there exists some a[x,y] satisfying d(x,a)M(δ,1,4(6δ+K)). One has

d(a,x)d(a,a)+d(a,x)d(a,a)+M(δ,1,4(6δ+K)).

On the other hand,

|d(x,a)-d(x,x)|d(a,x)M(δ,1,4(6δ+K)),

so

d(a,a)=|d(x,a)-d(x,a)|=|d(x,x)-d(x,a)|
M(δ,1,4(6δ+K)).

The desired conclusion follows. ∎

Corollary 2.9.

Let X be a δ-hyperbolic graph, γ a K-quasiconvex line and let x,yX be two points. If x,yγ are nearest-point projections onto γ of x,y respectively, then

d(x,y)d(x,y)+36δ+5K.

Proof.

If d(x,y)36δ+5K, there is nothing to prove, so we suppose that d(x,y)>36δ+5K. As a consequence of Lemma 2.7,

d(x,y)d(x,y)-4(6δ+K)d(x,y)-36δ-5K,

which concludes the proof of our corollary. ∎

Now, let X be a δ-hyperbolic graph and gIsom(X) an isometry. The translation length of g is

[g]=inf{d(x,gx)xX};

and the minimal set of g is

Cg={xXd(x,gx)=[g]}.

It is worth noticing that, because X is a graph, the infimum in the definition of [g] turns out to be a minimum, so that Cg is non-empty.

Definition 2.10.

Let X be a hyperbolic graph and gIsom(X) a loxodromic isometry. An axis of g is a concatenation =kgk[x,gx] for some xCg.

Noticing that an axis of g is a [g]-local geodesic, the following lemma follows from [4, Theorem III.Γ.1.13].

Lemma 2.11.

Let X be a δ-hyperbolic graph and let gIsom(X) be a loxodromic isometry satisfying [g]>32δ. Any axis of g is 12δ-quasiconvex.

We conclude this section with a last preliminary lemma, which will be fundamental in the proof of the hyperbolic rigidity of Thompson’s group V.

Lemma 2.12.

Let X be a hyperbolic graph and g,hIsom(X) two isometries. Suppose that g is loxodromic of translation length at least 525δ and that h is elliptic. Fix an axis of g. If hg is elliptic, then there exists a point x such that

d(x,hx)8M(δ,1,62δ)+243δ.

Proof.

For convenience, fix a G-equivariant map π:X sending every point of X to one of its nearest-point projections, and set M=2M(δ,1,62δ). Because h is elliptic, we know from [4, Lemma III.Γ.3.3] that there exists some xX such that hx has diameter at most 17δ.

Suppose that there exists some yX such that the distances d(π(x),π(y)) and d(π(hy),π(hx)) are both greater than 96δ. Fix a geodesic [x,y]. We know from Corollary 2.8 that there exists a point z[x,y] satisfying d(x,z)=d(x,π(x)) such that d(z,π(x))2M. Similarly, we know from Corollary 2.8 that there exists a point wh[x,y] satisfying d(hx,w)=d(hx,π(hx)) such that

d(w,π(hx))2M.

Notice that

d(hz,w)=|d(hx,w)-d(hx,hz)|=|d(hx,π(hx))-d(x,π(x))|
d(x,hx)+d(π(x),π(hx))130δ,

where the last inequality is justified by Corollary 2.9. Consequently,

d(z,hz)d(z,π(x))+d(π(x),π(hx))+d(π(hx),w)+d(w,hz)
2M+(17δ+96δ)+2M+130δ=4M+243δ.

We conclude that π(x) is a point satisfying the conclusion of our lemma, since

d(π(x),hπ(x))d(z,hz)+2d(z,π(x))8M+243δ.

Next, suppose that for every yX satisfying d(π(x),π(y))>96δ one has

d(π(hy),π(hx))96δ.

Consequently, since

d(π(x),π(gx))=d(π(x),gπ(x))=[g]>96δ,

it follows that d(π(hx),π(hgx))96δ. So

d(π(gx),π(ghgx))=d(π(x),π(hgx))
d(π(x),π(hx))+d(π(hx),π(hgx))
d(x,hx)+96δ+96δ209δ,

where the first inequality of the second line is justified by Corollary 2.9. Next, since

d(π(x),π(ghgx))d(π(x),π(gx))-d(π(gx),π(ghgx))
[g]-209δ>96δ,

we deduce from Lemma 2.7 that

d(x,ghgx)d(x,π(x))+d(π(x),π(ghgx))+d(π(ghgx),ghgx)-72δ.

By noticing that

d(π(x),π(ghgx))d(π(x),π(gx))-d(π(gx),π(ghgx)[g]-209δ

and that

d(π(ghgx),ghgx)=d(π(hgx),hgx)d(hgx,x)-d(x,π(hgx))
d(x,hgx)-d(x,π(x))-d(π(x),π(hgx))
d(x,hgx)-d(x,π(x))-209δ,

the previous inequality becomes

d(x,ghgx)d(x,π(x))+[g]-209δ+d(x,hgx)
-d(x,π(x))-209δ-72δ
d(x,hgx)+[g]-490δ,

hence

d(x,(hg)2x)d(x,ghgx)-d(x,hx)d(x,hgx)+[g]-507δ.

Since [g]>525δ by assumption, it follows that

d(x,(hg)2x)>d(x,hgx)+18δ.

According to [29, Corollaire 8.22], this inequality implies that hg is loxodromic, contradicting our hypotheses. ∎

2.2 CAT(0) cube complexes

In this paper, we suppose that the reader is familiar with the basic definitions and properties of CAT(0) cube complexes. For details, we refer to [44, 48]. Nevertheless, we recall the following fundamental property of cubical complexes, which will be used several times in Section 5 without mentioning it. We refer to [43, Theorem 11.9] for a proof.

Theorem 2.13.

Let G be a group acting on some CAT(0) cube complex X. If G has a bounded orbit, then G stabilises a cube. As a consequence, the action has a global fixed point.

The rest of this section is dedicated to some properties of the Roller boundary of CAT(0) cube complexes and of the hyperbolic model introduced in [28]. These statements will be useful in Section 5.

Roller boundary.

Let X be a CAT(0) cube complex. An ultrafilter σ is a collection of halfspaces of X such that

  1. σ contains exactly one of the two halfspaces delimited by a given hyperplane,

  2. if D1 and D2 are two halfspaces satisfying D1D2, then D1σ implies that D2σ.

For every vertex xX, the collection σx of all the halfspaces of X containing x is the principal ultrafilter defined by x.

The Roller compactification of X is the graph X¯ whose vertices are the ultrafilters of X and whose edges link two ultrafilters whenever their symmetric difference has cardinality two. The Roller compactification is usually not connected, but each connected component turns out to be a median graph (which we identify canonically with a CAT(0) cube complex; see [15]). Moreover, the map xσx defines an embedding X(1)X¯ whose image is a connected component of X¯. We refer to the connected components of X¯ as its cubical components, and we identify X with the cubical component of the principal ultrafilters. The Roller boundary of X is X:=X¯\X.

Finally, we define a topology on X¯, and a fortiori on X, as follows. By labelling the two halfspaces delimited by a given hyperplane with 0 and 1, we can naturally think of X¯ as a subset of {0,1}, where denotes the set of all the hyperplanes of X. The topology of X¯ is the topology induced by the product topology on {0,1}. Since X¯ is closed in {0,1}, it follows that X¯ is compact. More details about Roller boundary can be found in [44, 43].

The following statement provides a useful trick when arguing by induction on the dimension.

Lemma 2.14.

Let X be a finite-dimensional CAT(0) cube complex. For every cubical component YRX, the inequality dim(Y)<dim(X) holds.

A proof can be found for instance in [23, Proposition 4.29], in the more general context of median spaces.

Hyperbolic model of cube complexes.

In [28], we introduced a hyperbolic model (depending on a parameter) of CAT(0) cube complexes. Below, we recall the first definitions and properties, and we prove a proposition related to its Gromov-boundary.

Definition 2.15.

Let X be a CAT(0) cube complex and L0 an integer. A facing triple is the data of three pairwise disjoint hyperplanes such that no one separates the other two. Two hyperplanes J1,J2 are L-well-separated if they are not transverse and if every collection of hyperplanes transverse to both J1 and J2 which does not contain any facing triple has cardinality at most L. An isometry gIsom(X) is L-contracting if it skewers a pair of L-well-separated hyperplanes, i.e., if there exist two L-well-separated hyperplanes J1,J2 delimiting two halfspaces D1,D2 respectively such that gD2D1D2.

The terminology “L-contracting isometry” is justified as follows. In an arbitrary metric space X, a contracting isometry usually refers to an isometry gIsom(X) such that there exists some point x0X satisfying the following two conditions:

  1. the orbit map ngnx0 defines a quasi-isometric embedding X,

  2. there exists some B0 such that the nearest-point projection of any ball disjoint from gx0 onto gx0 has diameter at most B.

In [27, Theorem 3.13], we proved the following characterization:

Proposition 2.16.

Let X be a CAT(0) cube complex. An isometry gIsom(X) is contracting if and only if there exists some L0 such that g is L-contracting.

Consequently, our terminology agrees with the usual terminology which can be found in the literature.

Given a CAT(0) cube complex X and an integer L0, one next defines a new metric on (the set of vertices of) X by

δL:(x,y)maximal number of pairwise L-well-separated
hyperplanes separating x and y.

We showed in [28] that δL is indeed a metric, and we proved the following statement:

Theorem 2.17.

Let X be a CAT(0) cube complex and L0 some integer. The metric space (X,δL) is hyperbolic, and an isometry of X defines a loxodromic isometry of (X,δL) if and only if it L-contracting.

In the rest of the section, we would like to link the Gromov-boundary of (X,δL) with the Roller boundary of X. Notice that it is not clear whether or not (X,δL) is a geodesic metric space, so, given a basepoint x0X, the boundary will be defined as the quotient of the collection of sequences (xi) satisfying

(xi,xj)x0i,j++

modulo the equivalence relation

(yi)(zi)if (yi,zi)x0i,j++.

(Nevertheless, it follows from [28, Lemma 6.55] that (X,δL) is a quasigeodesic metric space, so the boundary can also be defined as the asymptotic classes of quasigeodesic rays.) Our main statement is:

Proposition 2.18.

Let X be a CAT(0) cube complex and L0 an integer. There exists an Isom(X)-equivariant map sending a point of (X,δL) to a subset of diameter at most L in a cubical component of RX .

First, we recall [28, Lemma 6.55], which essentially states that the quasigeodesics in (X,δL) fellow-travel the geodesics in X.

Lemma 2.19.

Let X be a CAT(0) cube complex and x,y,zX three vertices such that z belongs to a geodesic between x and y in X. Then

δL(x,z)+δL(z,y)-2(L+3)δL(x,y)δL(x,z)+δL(z,y).

As a consequence of the previous lemma, we are able to estimate the Gromov product in (X,δL). (In the following, Gromov products will always refer to the distance δL.)

Lemma 2.20.

Let X be a CAT(0) cube complex, L0 an integer and x,y,zX three vertices. Then

|(x,y)z-δL(z,m(x,y,z))|3(L+3),

where m(x,y,z) denotes the median point of x,y,z.

Proof.

For convenience, set m=m(x,y,z). By applying Lemma 2.19, we get

|(x,y)z-δL(z,m(x,y,z))|
=12|δL(z,x)+δL(z,y)-δL(x,y)-2δL(z,m)|
12|δL(z,m)+δL(m,x)+δL(z,m)+δL(m,y)
-δL(x,m)-δL(m,y)-2δL(z,m)|+3(L+3)
3(L+3),

which concludes the proof. ∎

Proof of Proposition 2.18..

For every ξ(X,δL), we denote by R(ξ) the set of all the accumulation points in X¯ of all the sequence of vertices representing ξ. We want to prove that ξR(ξ) is the map we are looking for. First of all, notice that R(ξ) is non-empty for every ξ(X,δL), as a consequence of the compactness of X¯, and that our map is clearly Isom(X)-equivariant.

Next, we claim that R(ξ)X for every ξ(X,δL). Indeed, let (xi) be a sequence representing ξ and zX¯ one of its accumulation points. For convenience, suppose that (xi) converges to z in X¯. Because

d(x0,xi)δL(x0,xi)
=δL(x0,m(x0,xi,xi))
(xi,xi)x0-3(L+3)i++,

where the last inequality is justified by Lemma 2.20, it is clear that z cannot belong to X, so it must belong to X.

Finally, we need to verify that, given some ξ(X,δL), if (yi) and (zi) are two sequences representing ξ and converging respectively to y and z in X¯, then y and z belong to the same cubical component and there the distance between them is at most L.

Let J1,,Jk be k hyperplanes such that, for every 1ik, the ultrafilters y and z does not contain the same halfspace delimited by Ji. Set

D=max1ikd(x0,Ji).

By the definition of the topology of X¯, there exists some N1 such that, for every iN and every halfspace D delimited by one the hyperplanes Jr, D belongs to the principal ultrafilter defined by yi if and only if Dy and similarly D belongs to the principal ultrafilter defined by zi if and only if Dz. It follows that the hyperplanes Jr separate yi and zi for every iN. We also want to choose N sufficiently large so that (yi,zi)x0D+2+3(L+3) for every iN. Now, fix some iN. As a consequence of Lemma 2.20, we have

δL(x0,m(x0,yi,zi))(yi,zi)x0-3(L+3)D+2.

Consequently, there exist pD+2 pairwise L-well-separated hyperplanes H1,,Hp separating x0 and m:=m(x0,yi,zi). Without loss of generality, suppose that Hj separates Hj-1 and Hj+1 for every 2jp-1 and that H1 separates x0 from Hp. For every 1jk, notice that Jj intersects the halfspace delimited by Hp which contains yi and zi since it separates these two vertices; on the other hand, Jj cannot be included into the halfspace delimited by HD+1 which contains m since the distance between x0 and Jj is at most D, so we conclude that Jj must be transverse to HD+1 and HD+2. Since HD+1 and HD+2 are L-well-separated, and since {J1,,Jk} does not contain a facing triple, we deduce that kL.

The distance (possibly infinite) between y and z in the graph X¯ being half the cardinality of the symmetric difference between y and z, we conclude that y and z are at distance at most L in X¯. This concludes the proof of our claim, and finally of our proposition. ∎

Corollary 2.21.

Let G be a group acting on some CAT(0) cube complex X. Fix some integer L0. If the induced action G(X,δL) fixes a point at infinity, then G stabilises a cube in the Roller boundary RX.

Proof.

If G fixes a point at infinity in (X,δL), it follows from Proposition 2.18 that G stabilises some cubical component Y of X and that the induced action GY has a bounded orbit. Consequently, G stabilises a cube in X. ∎

Remark 2.22.

It can be shown that the set R(ξ) we associated to a given point ξ(X,δL) in the proof of Proposition 2.18 is not only a small subset in a cubical component of X but it is a small cubical component: R(ξ) is a cubical component of X of diameter at most L. As a consequence, the boundary of (X,δ0) coincides with the set of strongly separated ultrafilters in X defined in [36] (and they have the same topology since they are both Cantor sets). However, we do not need this stronger statement, Proposition 2.18 will be sufficient for our purpose in Section 5.

3 Reducible elements in Thompson’s group V

This section is dedicated to the study of reducible elements (defined below) of Thompson’s group V. It is the key starting point of our proof of the hyperbolic rigidity of V. First of all, let us recall the definition of V as a homeomorphism group of the Cantor set. For more information, we refer to [10].

Definition 3.1.

A dyadic decomposition of [0,1] is a collection of intervals (Ik) of the form [j2m,j+12m] covering [0,1] such that the intersection between any two intervals contains at most one point. Given two dyadic decompositions 𝔄,𝔅 of [0,1] and a bijection σ:𝔄𝔅, the map defined on the Cantor set [0,1] by sending A to σ(A) via an affine map induces a homeomorphism of . Thompson’s groupV is the group of the homeomorphisms of which decompose in this way.

Here are the fundamental objects of our paper.

Definition 3.2.

An element gV is reducible if there exists some non-trivial dyadic interval on which g is the identity. Its thickness is the maximal diameter of such an interval.

Our first lemma shows that V is boundedly generated by reducible elements with controlled thickness.

Lemma 3.3.

Every element of V is a product of four reducible elements of thickness at least 18.

Proof.

Let a,bV be the elements defined by Figures 2 and 3 respectively. These elements satisfy the following properties:

  1. a fixes 34 and, for every dyadic interval I(12,1), length(anI)n+0,

  2. the restriction of b over [0,34] is a translation of length 18.

Notice also that they are reducible elements of thickness at least 18. Fix some gV.

Figure 2 The element a in the proof of Lemma 3.3.
Figure 2

The element a in the proof of Lemma 3.3.

Figure 3 The element b in the proof of Lemma 3.3.
Figure 3

The element b in the proof of Lemma 3.3.

Claim 3.4.

There exist n,mZ such that bmgan([34,78]) is a dyadic interval contained into [12,1].

Without loss of generality, we may suppose that there exists a dyadic interval A(0,1) with 34 as its left endpoint which is sent by g to a dyadic interval B. Let n0 be sufficiently large so that an([34,78])A. As a consequence, we have that gan([34,78]) is a dyadic interval. Moreover, we can also choose n sufficiently large so that gan([34,78]) has length at most 18. If gan([34,78]) is included into [12,1], we are done. Otherwise, gan([34,78]) is included into [0,58], we can translate it by a power of b, say bm, into the interval [12,1]. Thus, we have found n,m0 such that bmgan([34,78])[12,1], proving our claim.

Now, let cV be any element which sends the dyadic interval bmgan([34,78]) to [34,78] and which is the identity over [0,14]. Then c is a reduced element of thickness at least 14, and by construction cbmgan fixes [34,78] so that it must be a reduced element of thickness at least 18. Our lemma follows from the equality

g=b-mc-1cbmgana-n

and from the observation that any power of a reducible element of thickness at least 18 is again a reduced element of thickness at least 18. ∎

Our second lemma essentially shows that any reducible element generates a direct product with at least one of its conjugates.

Lemma 3.5.

Let gV be a reducible element and IFix(g) a dyadic interval. There exists some hV such that supp(hgh-1)I.

Proof.

Let aV be a permutation sending the dyadic interval I to a dyadic interval J containing 1, and let dV be the element defined by Figure 4. Notice that d satisfies the following property: for every dyadic interval K containing 1,

length(dnK)n+1.
Figure 4 The element d in the proof of Lemma 3.5.
Figure 4

The element d in the proof of Lemma 3.5.

Therefore, there exists some n0 such that dnJ has length at least 1-length(I)2. As a consequence, the image of supp(g) by dna has diameter at most 12length(I). It follows that there exists a permutation bV such that bdna sends supp(g) inside I. Thus, if we set h=bdna, then

supp(hgh-1)=hsupp(g)I,

which concludes the proof of our lemma. ∎

Our third lemma shows that two arbitrary elements of V can be made reducible simultaneously in many different ways.

Lemma 3.6.

For every g1,g2V, there exist a reducible hV and a dyadic interval I(0,1) such that fh, fhg1 and fhg2 are all reducible for every fV satisfying supp(f)I.

Proof.

Let g1,g2V be two elements.

Claim 3.7.

There exist two disjoint dyadic intervals A,B such that g1(A) and g2(B) are also two disjoint dyadic intervals.

Fix two disjoint dyadic interval A0,B0 such that A0 contains 0 and B0 contains 1, and such that g1(A0) and g2(B0) are dyadic intervals. If one of the endpoints of g1(A0) does not belong to g2(B0), then there exists a dyadic subinterval AA0 such that g1(A) and g2(B0) are disjoint, and we are done. Similarly, if one of the endpoints of g2(B0) does not belong to g1(A0), then there exists a dyadic subinterval BB0 such that g1(A0) and g2(B) are disjoint, and we are done. The only remaining case to consider is g1(A0)=g2(B0). Here, set A as the first fourth of A0 and B as the last fourth of B0. Then g1(A) and g2(B) are disjoint. This concludes the proof of our claim.

Now, fix two dyadic intervals A,B given by our claim. Notice that, up to replacing A with one of its halves, we may suppose without loss of generality that ABg1(A)g2(B) does not cover all the dyadic intervals of [0,1]. Fix a dyadic interval disjoint from ABg1(A)g2(B), and let I,J denote its two halves. Because A, B, g1(A), g2(B), I and J are pairwise disjoint, it follows that there exists some hV sending g1(A) to A, g2(B) to B and fixing IJ. Notice that h is a reducible element. Now, let fV be an arbitrary element satisfying supp(f)I. Notice that

fhg1(A)=f(A)=A,fhg2(B)=f(B)=B,fh(J)=f(J)=J,

so fh, fhg1 and fhg2 are all reducible. This concludes the proof of our lemma. ∎

Finally, our fourth and last lemma shows how to conjugate a reducible element, in a controlled way, in order to include its support into a given dyadic interval.

Figure 5 Examples of elements Pl,Pr,Tl,Tr,P,T,Q∈V{P_{l},P_{r},T_{l},T_{r},P,T,Q\in V} from the proof of Lemma 3.8.
Figure 5

Examples of elements Pl,Pr,Tl,Tr,P,T,QV from the proof of Lemma 3.8.

Lemma 3.8.

For every dyadic interval I(0,1) and every ϵ>0, there exist reducible h1,,h8V such that F:=h1h8 satisfies the following. For every reducible element gV of thickness at least ϵ, there exists some fF such that fgf-1 fixes Ic.

Proof.

Fix a dyadic interval I(0,1), and real number ϵ>0. Without loss of generality, we will suppose that ϵ is a negative power of two which is sufficiently small so that [0,ϵ] and [1-ϵ,ϵ] are included into Ic and so that ϵ<12length(I). Fix some elements Pl,Pr,Tl,Tr,P,T,QV satisfying the following properties (such elements are illustrated by Figure 5 for ϵ=12):

  1. Pl fixes [0,ϵ2], and length(PlnK)n+1 for every dyadic interval K containing 0 and ϵ,

  2. Pr fixes [1,1-ϵ2], and length(PlnK)n+1 for every dyadic interval K containing 1 and 1-ϵ,

  3. Tl fixes [0,ϵ2] and is a translation of length ϵ2 to the left on [ϵ,1],

  4. Tr fixes [1,1-ϵ2] and is a translation of length ϵ2 to the right on [0,1-ϵ],

  5. P fixes [0,ϵ4][1-ϵ4,1], and length(PnK)n+1-ϵ2 for every dyadic interval K containing 12 in its interior,

  6. T fixes [0,ϵ4][1-ϵ4,1] and is a translation of length ϵ4 to the right on [ϵ4,1-ϵ2],

  7. Q sends [0,ϵ2][1-ϵ2,1] into [ϵ4,12-ϵ4] and is the identity on [12,1-ϵ2].

Let gV be a reduced element of thickness at least ϵ, and let J[0,1] be a dyadic interval of length at least ϵ on which g is the identity. Setting

F=TlPlTrPrTQPT,

our goal is to show that fgf-1Fix(Ic) for some fF. If g=1, there is nothing to prove, so from now on we suppose that g1.

Case 1: 0 belongs to J. Notice that ϵ belongs to J since J has length at least ϵ. Thus, there exists some n0 such that PlnJ has length at least 1-12length(I), so that supp(PlngPl-n)=Plnsupp(g) is included into the dyadic segment K which contains 1 and which has length at most 12length(I). Now, let m0 be such that Tlm(K)I. So

supp(TlmPlngPl-nTl-m)=TlmPlnsupp(g)Tlm(K)I,

which shows that TlmPlngPl-nTl-m belongs to Fix(Ic).

Case 2: 1 belongs to J. The situation is symmetric to the previous one: just replace Pl and Tl with Pr and Tr respectively.

Case 3: J does not contain 0 and 1. Up to extracting a dyadic subinterval from J, we may suppose that J is disjoint from [0,ϵ4][1-ϵ4,1] and has length at least ϵ2. There exists some n such that Tn(J) contains 12 in its interior. Next, there exists some m0 such that PmTn(J) has length at least 1-2ϵ3. Consequently, the support of PmTngT-nP-m is included into [0,ϵ3][1-ϵ3,1], and a fortiori into [0,ϵ2][1-ϵ2,1]. Because Q sends [0,ϵ2][1-ϵ2,1] into an interval K of length at most 2ϵ3 inside [ϵ4,12-ϵ4], there exists some p such that Tp(K)I. One has

supp(TpQPmTngT-nP-mQ-1T-p)=TpQsupp(PmTngT-nP-m)
TpQ([0,ϵ3][1-ϵ3,1])
Tp(K)I,

hence TpQPmTngT-nP-mQ-1T-pFix(Ic). ∎

4 Hyperbolic rigidity

We begin this section by proving the main criterion of our article, namely:

Theorem 4.1.

Let G be a group. Suppose that there exist two subsets ABG satisfying the following conditions.

  1. G is boundedly generated by A, i.e., there exists some N0 such that every element of G is the product of at most N elements of A.

  2. For every a,bB, there exist g,hG such that

    [gag-1,a]=[gag-1,hgag-1h-1]=[hgag-1h-1,b]=1.
  3. For every a,bG, there exist some h,h1,,hrB such that the following holds. For every kA, there exists some fh1hr such that the elements fkf-1h, fkf-1ha and fkf-1hb all belong to B.

Then any isometric action of G on a hyperbolic space fixes a point at infinity, or stabilises a pair of points at infinity, or has bounded orbits.

Correction added on 17 January 2019 after online publication: The second item has been modified (producing a more general statement). The previous statement and its proof were correct, but the new formulation allowed us to correct a mistake in the proof of Theorem 4.6 below.

From now on, we fix a group G and two subsets ABG satisfying the above conditions. We recall from Section 2.1 that we may suppose without loss of generality that our hyperbolic spaces are graphs. Our statement will be an easy consequence of the following two lemmas.

Lemma 4.2.

Let G act on some hyperbolic graph. If G does not fix a point at infinity nor stabilises a pair of points at infinity, then all the elements of B are elliptic.

Proof.

Suppose that there is some element gB which is not elliptic. Let be the set of points at infinity fixed by g (so has cardinality one if g is parabolic, or two if g is loxodromic). Given any other element hB, we claim that h stabilises .

By assumption, we know that there exist g,hG such that

[gag-1,a]=[gag-1,hgag-1h-1]=[hgag-1h-1,b]=1.

For convenience, set a¯=gag-1. Notice that, as a and a¯ are conjugate and commute, the sets of points at infinity fixed by a and a¯ coincide, ie., is also the set of points at infinity fixed by a¯. Similarly, as a¯ and ha¯h-1 are conjugate and commute, coincides with the set of points at infinity fixed by ha¯h-1. Next, because b and ha¯h-1 commute, it follows that b has to stabilise , concluding the proof of our claim.

Since G is generated by B (as B contains the generating set A), it follows that G stabilises . Consequently, G fixes a point at infinity or stabilises a pair of points at infinity. ∎

Correction added on 17 January 2019 after online publication: The proof of Lemma 4.2 has been adapted to the new formulation of Theorem 4.1, but the argument remains essentially the same.

Lemma 4.3.

Let G act on some δ-hyperbolic graph X. If the action does not fix a point at infinity nor stabilises a pair of points at infinity, and if all the elements of B are elliptic, then G has bounded orbits.

Proof.

Suppose for a contradiction that G has unbounded orbits and does not fix any point at infinity. As a consequence, there exist two independent loxodromic isometries g1,g2G (see [30, Paragraph 8.2.E]). Fix two axes 1,2 of g1,g2 respectively. Let h,h1,,hrB be the elements given in the statement of Theorem 4.1. By assumptions, the hi’s are elliptic, so, as a consequence of [4, Lemma III.Γ.3.3], for every 1ir there exists some xiX such that the orbit hixi has diameter at most 17δ. Set F=h1hr.

Claim 4.4.

Fix a basepoint x0X. For every element kA,

d(x0,kx0)(19+8r)D+Δ+4(2+17r)δ

where

D=max{d(x0,x1),,d(x0,xr),
d(x0,proj2(1))+diam(proj2(1)),d(x0,hx0)}

and M=M(δ,1,62δ) is the Morse constant.

Fix some kA. By assumption, there exists some fF such that fkf-1h, fkf-1hg1 and fkf-1hg2 all belong to B. As a consequence, they are elliptic isometries. It follows from Lemma 2.12 that there exist points x11 and x22 which are moved within distance at most Δ:=8M+243δ by fkf-1h. Fix a geodesic [x1,x2] in X between x1 and x2. As a consequence of Lemma 2.5, [x1,x2] intersects the M-neighbourhood of the nearest-point projection of 1 onto 2. Let x be a point which belongs to this intersection. By 8δ-convexity of the metric (see [16, Corollary 10.5.3]), fkf-1h moves x within distance at most Δ+8δ. On the other hand,

d(fkf-1hx,x)=d(f-1hfkf-1hx,f-1hx)
d(f-1hfkx,x)-2d(f-1hx,x)
d(kx,f-1h-1fx)-2d(f-1hx,x)
d(kx,x)-d(f-1h-1fx,x)-2d(f-1hx,x).

Consequently,

d(x,kx)d(f-1h-1fx,x)+2d(f-1hx,x)+Δ+8δ
4d(x,fx)+3d(x,hx)+Δ+8δ
4d(x0,fx0)+3d(x0,hx0)+14d(x0,x)+Δ+8δ.

By combining the observation that

d(x0,x)d(x0,proj2(1))+diam(proj2(1))D

together with the next claim, we deduce that

d(x0,kx0)d(x,kx)+2d(x,x0)4r(2D+17δ)+19D+Δ+8δ
(19+8r)D+Δ+4(2+17r)δ

concluding the proof of our claim.

Claim 4.5.

For every fF, d(x0,fx0)r(2D+17δ).

Write f=h1n1hrnr for some n1,,nr. Then

d(x0,fx0)i=1rd(hinix0,x0)i=1r(d(hinixi,xi)+2d(xi,x0))
2rmax1ird(x0,xi)+i=1rd(hinixi,xi)
2rmax1ird(x0,xi)+17rδ.

This proves the claim.

Now, we are ready to conclude the proof of our lemma. Indeed, by combining Lemma 3.3 with Claim 4.4, it follows that there exists some constant K such that d(gx0,x0)K for every gG. In other words, G has a bounded orbit, contradicting our starting hypothesis. ∎

Proof of Theorem 4.1..

Let X be a hyperbolic graph on which G acts. If the action fixes a point at infinity or stabilises a pair of points at infinity, we are done. Otherwise, it follows from Lemma 4.2 that the elements of B must be elliptic, and we conclude from Lemma 4.3 that G has a bounded orbit. Thus, we have proved the desired statement for hyperbolic graphs. But the general case reduces to hyperbolic graphs according to Lemma 2.2, so the proof is concluded. ∎

We are ready to prove that Thompson’s group V is hyperbolically elementary.

Theorem 4.6.

Any isometric action of Thompson’s group V on a Gromov-hyperbolic space either fixes a unique point at infinity or has a bounded orbit.

Proof.

We claim that V satisfies the hypotheses of Theorem 4.1 if B denotes the set of reducible elements and A the set of reducible elements of thickness at least 18. The first item of Theorem 4.1 is a direct consequence of Lemma 3.3.

Next, let a,bV be two reducible elements. If the supports of a and b do not cover the Cantor set , set g=1. Otherwise, if the supports of a and b cover , there exist two disjoint dyadic intervals I and J on which a and b respectively are the identity. According to Lemma 3.5, there exists some element gV such that the support of gag-1 is included into I. Now, the point is that a and gag-1 commute (since they have disjoint supports) and that gag-1 and b are both the identity on some dyadic interval J. Again according to Lemma 3.5, there exists some hV such that the support of hgag-1h-1 is included into J. By construction, the support of hgag-1h-1 is disjoint from the supports of b and gag-1, so that hgag-1h-1 has to commute with both b and gag-1. This proves the second item of Theorem 4.1.

Correction added on 17 January 2019 after online publication: The previous paragraph has been rewritten to correct a mistake.

Finally, fix two elements a,bV. Let hV and let I(0,1) be the element of V and the dyadic interval given by Lemma 3.6, and let h1,,h8V be the elements given by Lemma 3.8 for I and ϵ=18. Set F=h1h8. Given a reducible element kV of thickness at least 18, we deduce from Lemma 3.8 there exists some fF such that the support of fkf-1 is included into I. It follows from Lemma 3.6 that fkf-1h, fkf-1ha and fkf-1hb are all reducible elements. This proves the third item of Theorem 4.1.

Therefore, Theorem 4.1 applies, proving that any isometric action of V on a hyperbolic space fixes a unique point at infinity, or stabilises a pair of points at infinity, or has a bounded orbit. It remains to show that V cannot stabilise a pair of points at infinity, or equivalently:

Claim 4.7.

Any isometric action of V on a quasi-line must have a bounded orbit.

Since an action on a quasi-line with an unbounded orbit produces a quasi-morphism (i.e., a map φ:V satisfying the following conditions: there exists a constant D0 such that |φ(gh)-φ(g)-φ(h)|D for every g,hV) which is unbounded (i.e., such that φ(V) is not bounded in ), it is sufficient to show that any quasi-morphism of V is necessarily bounded. We refer to [9] for more information on quasi-morphisms. The last observation is a straightforward consequence of the fact that V is uniformly simple [26, Corollary 6.6], meaning that there exists a constant N1 such that, for every non-trivial elements f,gV, f can be written as a product of at most N conjugates of g or g-1. ∎

5 Cubical rigidity

Our last section is dedicated to cubical rigidity, and more precisely, how to deduce it from hyperbolic rigidity.

Theorem 5.1.

A finitely generated group all of whose finite-index subgroups

  1. are hyperbolically elementary,

  2. and do not surject onto

satisfies Property (FW).

Proof.

We want to prove by induction that, for every n0, a group all of whose finite-index subgroups are hyperbolically elementary and do not surject onto satisfies Property (FWn). For n=0, there is nothing to prove; so suppose that our statement is true for some n0, and fix a group G, all of whose finite-index subgroups are hyperbolically elementary and do not surject onto , acting on an (n+1)-dimensional CAT(0) cube complex X.

Suppose first that G fixes a point at infinity in X (i.e., in the visual boundary). It follows from [14, Proposition 2.26] that G contains a finite-index subgroup H which stabilises a cubical component YX. As dim(Y)<dim(X) according to Lemma 2.14, our induction hypothesis implies that H fixes a point of Y, so that H fixes a point in X; up to taking a finite-index subgroup of H, we may suppose without loss of generality that H fixes a vertex in the Roller boundary. It follows from [14, Theorem B.1] that H virtually surjects onto a free abelian group of rank kdim(X) with a kernel which is locally elliptic (in X). Since the finite-index subgroups of G do not surject onto , necessarily k=0, so H is virtually locally elliptic, and finally elliptic since H is finitely generated. We conclude that G has a bounded orbit in X, and finally that it fixes a point. Notice that we have proved the following statement, which we record for future use:

Fact 5.2.

If G contains a finite-index subgroup fixing a vertex of RX, then G has to fix a point of X.

From now on, suppose that G does not fix a point at infinity in X. According to [12, Proposition 3.5], up to taking a convex subcomplex of X, we may suppose that the action is essential. If X is bounded, then G fixes a point, so suppose that X is unbounded. As a consequence of [12, Proposition 2.6], X decomposes as a product of irreducible CAT(0) cube complexes X1××Xr and G contains a finite-index subgroup H lying in Isom(X1)××Isom(Xr). If r2 (i.e., if X is reducible), then dim(Xi)<dim(X) for every 1ir, so that our induction hypothesis implies that all the induced actions HXi have global fixed points. Consequently, H fixes a point in X, and it follows that G has a bounded orbit in X, and finally that it fixes a point.

From now on, suppose that X is irreducible. It follows from [12, Theorem 6.3] that G contains a contracting isometry of X, so that Theorem 2.17 implies that there exists some L0 such that G acts on the hyperbolic space (X,δL) defined in Section 2.2 with a loxodromic isometry. Because G is hyperbolically elementary, it must contain a subgroup G of index at most two which fixes a point at infinity in (X,δL). This implies, according to Corollary 2.21, that G stabilises a cube in the Roller boundary of X, so that some finite-index subgroup HG fixes a vertex in X. We conclude from Fact 5.2 that G fixes a point in X.

Thus, we have proved that G necessarily fixes a point of X. This concludes the proof of our theorem. ∎

Proof of Corollary 1.4..

First of all, since V is a finitely generated simple group, it does not contain any proper finite-index subgroup. We also know from Theorem 4.6 that V is hyperbolically elementary, and, once again because V is a simple group, it does not surject onto . Consequently, Theorem 5.1 applies, implying that V satisfies Property (FW). ∎

We conclude this section by an example, which was communicated to us by Pierre-Emmanuel Caprace, showing that the property of being hyperbolically elementary is not stable under taking finite-index subgroups. Consequently, in order to apply Theorem 5.1, we really need to check the hyperbolic elementarity for all the finite-index subgroups of the group we are looking at.

Example 5.3.

Let H be a non-elementary hyperbolic group, say a free group of rank two. Then the wreath product H2=(H×H)2 contains the group H×H as a finite-index subgroup which is not hyperbolically elementary, but turns out to be hyperbolically elementary itself as justified by the argument below.

Let H2 act on a Gromov-hyperbolic space X. For convenience, let H1 (resp. H2) denote the first copy of H (resp. the second copy of H) in the decomposition H2=(H×H)2. Notice that, if H1 has a bounded orbit, then so does H2 since H1 and H2 are conjugate. Consequently, if H1 has a bounded orbit, then so does H2. From now on, we suppose that H1 has unbounded orbits.

Suppose that H1 contains two independent loxodromic isometries f and h. Let denote the union of the two pairs of points at infinity stabilised by f and h. If f denotes the element of H2 conjugate to f, then f has to stabilise as it commutes with both f and g. This implies that f must be elliptic, which is impossible since it is conjugate to f which loxodromic. Thus, H1 cannot contain two independent loxodromic isometries.

It follows that H1 fixes a unique point at infinity ξ or stabilises a pair of points at infinity {ξ1,ξ2}; set ={ξ} or ={ξ1,ξ2} depending on the situation. Notice that, for every hH2, h is also stabilised by H1 since h commutes with any element of H1. On the other hand, H1 does not have a bounded orbit so it cannot stabilise a subset of cardinality at least three in the boundary of X, hence h= for every hH2. Therefore, is stabilised by both H1 and H2. It follows that H2 stabilises a finite set in X. If this subset has cardinality at least three, then H2 has a bounded orbit; otherwise, H2 fixes a point at infinity or stabilises a pair of points at infinity.

Thus, we have proved that H2 is hyperbolically elementary.


Communicated by Pierre-Emmanuel Caprace


Funding statement: The author was supported by the Ernst Mach Grant ICM-2017-06478 financed by the Austrian Federal Ministry of Education, Science and Research (BMBWF), under the supervision of Goulnara Arzhantseva.

Acknowledgements

I am grateful to Yves Cornulier, for his comments on an earlier version of this paper, which lead to a great improvement of the presentation; and to Pierre-Emmanuel Caprace, for all his relevant comments; and to Sam Shepherd for having pointed out to me a mistake in the proof of Theorem 4.6 in an earlier version. I also would like to thank the university of Vienna for its hospitality during the elaboration of this work. Finally, I am grateful to the anonymous referee for his comments on the article.

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Received: 2018-04-19
Revised: 2018-09-16
Published Online: 2018-11-03
Published in Print: 2019-03-01

© 2020 Walter de Gruyter GmbH, Berlin/Boston

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