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K-stability of Casagrande–Druel varieties

  • Ivan Cheltsov ORCID logo , Tiago Duarte Guerreiro ORCID logo , Kento Fujita ORCID logo , Igor Krylov ORCID logo and Jesus Martinez-Garcia ORCID logo EMAIL logo
Published/Copyright: October 15, 2024

Abstract

We introduce a new subclass of Fano varieties (Casagrande–Druel varieties) that are 𝑛-dimensional varieties constructed from Fano double covers of dimension n 1 . We conjecture that a Casagrande–Druel variety is K-polystable if the double cover and its base space are K-polystable. We prove this for smoothable Casagrande–Druel threefolds, and for Casagrande–Druel varieties constructed from double covers of P n 1 ramified over smooth hypersurfaces of degree 2 d with n > d > n 2 > 1 . As an application, we describe the connected components of the K-moduli space parametrizing smoothable K-polystable Fano threefolds in the families № 3.9 and № 4.2 in the Mori–Mukai classification.

Throughout this paper, all varieties are defined over ℂ.

1 Introduction

Let 𝑉 be a Fano variety with Kawamata log terminal singularities, and let 𝐿 be a line bundle on 𝑉 such that the divisor ( K V + L ) is ample, and | 2 L | contains a non-zero effective divisor. Let 𝑅 be a divisor in | 2 L | , and let η : B V be the double cover ramified over 𝑅. Then 𝐵 can be explicitly constructed as follows. Let Y = P ( O V O V ( L ) ) , let π : Y V be the natural projection, and let 𝜉 be the tautological line bundle on 𝑌. Set H = π ( L ) . Then we have the isomorphisms

H 0 ( Y , O Y ( ξ ) ) H 0 ( V , O V ) H 0 ( V , O V ( L ) ) , H 0 ( Y , O Y ( ξ H ) ) H 0 ( V , O V ) H 0 ( V , O V ( L ) ) .

Using these isomorphisms, fix sections u + H 0 ( Y , O Y ( ξ ) ) and u H 0 ( Y , O Y ( ξ H ) ) that correspond to 1 H 0 ( V , O V ) under the isomorphisms above. Set S ± = { u ± = 0 } . Then we have S S + = and S + S + H . Take f H 0 ( V , O V ( 2 L ) ) that defines 𝑅. Then we can identify 𝐵 with the divisor { π ( f ) ( u ) 2 = ( u + ) 2 } | 2 S + | , where the double cover 𝜂 is induced by 𝜋.

Remark 1.1

We allow 𝑅 to be singular, so 𝐵 can be very singular (and even reducible). However, if the log pair ( V , 1 2 R ) has Kawamata log terminal singularities, then the double cover 𝐵 is a Fano variety with Kawamata log terminal singularities [29]. So, for simplicity, we will always say that 𝐵 is a Fano double cover (even if 𝐵 is non-normal or reducible).

Let F = π ( R ) , and let ϕ : X Y be the blow up of the intersection S + F . Then

X is smooth Y and B are smooth V and R are smooth .

Moreover, the variety 𝑋 is also a Fano variety (see Section 2).

Definition 1.2

If the Fano variety 𝑋 has at most Kawamata log terminal singularities, then 𝑋 is called the Casagrande–Druel variety constructed from η : B V (or from the ramification divisor R V ). Note that L Pic V is uniquely determined by 𝑅.

The group Aut ( Y ) contains a subgroup Γ G m that fixes both S and S + pointwise, and the action of Γ lifts to Aut ( X ) , so we can identify Γ with a subgroup in Aut ( X ) . In Section 2, we will show that Aut ( X ) also contains an involution 𝜄 such that

Γ , ι G m μ 2 ,

and 𝜄 swaps the proper transforms of the sections S and S + . Set G = Γ , ι and θ = π ϕ . Then we have the commutative diagram

and the composition 𝜃 is a 𝐺-equivariant conic bundle such that 𝐺 acts trivially on 𝑉.

Remark 1.3

Our construction of Casagrande–Druel varieties is inspired by the paper [12]. See [12, Lemma 3.1 (iii)]. But it goes back to the construction of de Jonquieres involutions using hyperelliptic curves instead of Fano double covers. See also [33, 11, 43, 20].

The del Pezzo surface of degree 6 (blow up of P 2 at three general points) is the unique smooth Casagrande–Druel surface. Smooth Casagrande–Druel threefolds form 3 families. To present them, we use labeling of smooth Fano threefolds from [7].

Example 1.4

Let V = P 2 , let L = O P 2 ( 1 ) , let 𝑅 be an arbitrary smooth conic in | 2 L | . Then B P 1 × P 1 , and 𝑋 is the unique smooth Fano threefold in the family № 3.19.

Example 1.5

Let V = P 2 , let L = O P 2 ( 2 ) , let 𝑅 be any smooth quartic curve in | 2 L | . Then 𝐵 is a del Pezzo surface of degree 2, and 𝑋 is a Fano threefold in the family № 3.9.

Example 1.6

Let V = P 1 × P 1 , let L = O V ( 1 , 1 ) , let 𝑅 be any smooth curve in | 2 L | . Then 𝐵 is a del Pezzo surface of degree 4, and 𝑋 is a Fano threefold in the family № 4.2.

All smooth Casagrande–Druel threefolds are K-polystable; see [27, Theorem 6.1] and [7]. In fact, K-polystable Casagrande–Druel varieties exist in every dimension.

Example 1.7

Example 1.7 ([16, 17])

Suppose that V = P n 1 , L = O P n 1 ( 1 ) , 𝑅 is smooth, n 2 . Then 𝑋 can be obtained by blowing up the 𝑛-dimensional smooth quadric at two points. The variety 𝑋 is spherical, and it is known that 𝑋 is K-polystable [17, §4.4.2].

In this paper, we prove the following theorem.

Theorem 1.8

Suppose that V = P n 1 , L = O P n 1 ( r ) , 𝑅 is smooth, n > r > n 2 > 1 . Then 𝑋 is K-polystable.

We obtain this result as an application of the following K-polystability criteria.

Theorem 1.9

Suppose that both 𝑉 and 𝑅 are smooth (or equivalently 𝑋 is smooth), and K V Q a L , where a Q > 0 such that a > 1 . Let 𝜇 be the smallest rational number such that μ L is very ample. Set n = dim ( X ) (so dim ( V ) = n 1 ), set d = L n 1 , set

k n ( a , d , μ ) = a n + 1 ( a 1 ) n + 1 ( n + 1 ) ( a n ( a 1 ) n ) d μ n 2 + a n + 1 ( a + n ) ( a 1 ) n 2 ( n + 1 ) ( a n ( a 1 ) n )

and set

γ = min { 1 k n ( a , d , μ ) , ( n + 1 ) ( a n ( a 1 ) n ) ( n + 1 a ) a n + ( a 1 ) n + 1 , a δ ( V ) ( n + 1 ) ( a n ( a 1 ) n ) n ( a n + 1 ( a 1 ) n + 1 ) } ,

where δ ( V ) is the 𝛿-invariant of the Fano variety 𝑉. If n 3 , d μ n 2 2 and γ > 1 , then the Casagrande–Druel variety 𝑋 is K-polystable.

Remark 1.10

In the notation of Theorem 1.9, if n 2 and d μ n 2 < 2 , then we have d μ n 2 = 1 , which gives V = P n 1 and L = O P n 1 ( 1 ) , so 𝑋 is K-polystable; see Example 1.7.

In this paper, we also prove the following two theorems about K-polystability of several singular Casagrande–Druel 3-folds.

Theorem 1.11

Suppose V = P 1 × P 1 , L = O V ( 1 , 1 ) , and 𝑅 is one of the following curves:

  1. C 1 + C 2 , where C 1 and C 2 are smooth curves in | L | such that | C 1 C 2 | = 2 ;

  2. 1 + 2 + 3 + 4 , where 1 and 2 are two distinct smooth curves of degree ( 1 , 0 ) , and 3 and 4 are two distinct smooth curves of degree ( 0 , 1 ) ;

  3. 2 C , where 𝐶 is a smooth curve in | L | .

Then 𝑋 is K-polystable.

Theorem 1.12

Suppose V = P 2 , L = O P 2 ( 2 ) , and 𝑅 is one of the following curves:

  1. a singular reduced curve in | 2 L | with at most A 1 or A 2 singularities;

  2. C 1 + C 2 , where C 1 and C 2 are smooth conics that are tangent at two points;

  3. C + 1 + 2 , where 𝐶 is a smooth conic, 1 and 2 are distinct lines tangent to 𝐶;

  4. 2 C , where 𝐶 is a smooth conic.

Then 𝑋 is K-polystable.

To present their applications, let M n , v Kss be the K-moduli functor of Fano varieties that have dimension 𝑛 and anticanonical volume v Q > 0 in the sense of [47, Theorem 2.17]. Then M n , v Kss is an Artin stack of finite type [28, 9, 45]. Moreover, as in [30, Theorem 1.3], it admits a separated good moduli space (see [5, 10]) M n , v Kss M n , v Kps in the sense of [4], where M n , v Kps is a proper [8, 30] and projective [14, 47] scheme whose points parametrize K-polystable Fano varieties of dimension 𝑛 and anticanonical volume 𝑣. Let M ( 3.9 ) Kps and M ( 4.2 ) Kps be the closed subvarieties of M 3 , 26 Kps and M 3 , 28 Kps whose general points parametrize smooth Fano threefolds in the families № 3.9 and № 4.2, respectively. Then Theorems 1.11 and 1.12 imply the following two results (see Section 6 and cf. [24]).

Corollary 1.13

Let V = P 1 × P 1 , L = O V ( 1 , 1 ) , Γ = ( SL 2 ( C ) × SL 2 ( C ) ) μ 2 and T = P ( H 0 ( V , O V ( 2 , 2 ) ) ) . Let T ss T be the GIT semistable open subset with respect to the natural Γ-action, and let 𝑀 be the GIT quotient T ss / / Γ . Then there is a morphism

where X f is the Casagrande–Druel threefold that is constructed from R = { f = 0 } | 2 L | . Furthermore, the morphism Φ is an isomorphism onto M ( 4.2 ) Kps , and M ( 4.2 ) Kps is a connected component of the scheme M 3 , 28 Kps .

Corollary 1.14

Let V = P 2 , L = O P 2 ( 2 ) , Γ = SL 3 ( C ) , T = P ( H 0 ( P 2 , O P 2 ( 4 ) ) ) . Let T ss T be the GIT semistable open subset with respect to the natural Γ-action, and let 𝑀 be the GIT quotient T ss / / Γ . Then there exists a morphism

where X f is the Casagrande–Druel threefold that is constructed from R = { f = 0 } | 2 L | . Furthermore, the morphism Φ is an isomorphism onto M ( 3.9 ) Kps , and M ( 3.9 ) Kps is a connected component of the scheme M 3 , 26 Kps .

If 𝐵 is the smooth del Pezzo surface from Examples 1.4, 1.5, 1.6, then 𝐵 is K-polystable. If 𝐵 is the Fano manifold from Theorem 1.8, then 𝐵 is K-polystable [19, Theorem 1.1]. If 𝐵 is the singular del Pezzo surface from Theorems 1.11 and 1.12 such that 𝑅 is reduced, then 𝐵 is also K-polystable [35]. Inspired by this, we pose the following conjecture.

Conjecture 1.15

If 𝑉 and 𝐵 are K-polystable Fano varieties, then 𝑋 is K-polystable.

If 𝐵 is a K-polystable Fano variety, the log Fano pair ( V , 1 2 R ) is also K-polystable [31]. Thus, our conjecture is closely related to the following recent result.

Theorem 1.16

Theorem 1.16 ([32])

Suppose that K V Q a L , where a Q > 0 such that a > 1 . Set

λ n ( a ) = a n + 1 ( a + n ) ( a 1 ) n 2 ( n + 1 ) ( a n ( a 1 ) n ) ,

where n = dim X . Then 𝑋 is K-semistable if and only if ( V , λ n ( a ) R ) is K-semistable.

The K-polystability of 𝑉 in Conjecture 1.15 is necessary.

Example 1.17

Example 1.17 (Yuchen Liu)

Let V = P ( 1 , 1 , 4 ) , let L = O V ( 4 ) , let 𝑅 be a general curve in | 2 L | , and let λ ( 0 , 3 4 ) Q . Then ( V , λ R ) is a log Fano pair. One can show that

δ ( V , λ R ) 1 ( δ ( V , λ R ) > 1 , respectively ) λ 3 8 ( λ > 3 8 , respectively ) ,

so that the singular del Pezzo surface 𝐵 is K-polystable, but ( V , 9 52 R ) is not K-semistable. Hence, the threefold 𝑋 is not K-semistable by Theorem 1.16.

Let us say few words about the proofs of Theorems 1.9 and 1.12. In Section 2, we will show that X / ι Y , and we have the following commutative diagram:

where 𝜌 is the quotient map, which is a double cover ramified over our divisor B | 2 S + | . Thus, using [31], we see that

X is K-polystable the log Fano pair ( Y , 1 2 B ) is K-polystable .

In Section 3, we will prove the following result, which implies Theorem 1.9.

Theorem 1.18

Suppose that 𝑉 and 𝑅 are smooth (so 𝐵 is smooth), and K V Q a L , where a Q > 0 such that a > 1 . Let 𝜇 be a rational number such that μ L is very ample. Set n = dim Y (so dim V = n 1 ) and d = L n 1 . Suppose n 3 and d μ n 2 2 . Then

δ ( Y , 1 2 B ) min { 1 k n ( a , d , μ ) , ( n + 1 ) ( a n ( a 1 ) n ) ( n + 1 a ) a n + ( a 1 ) n + 1 , a δ ( V ) ( n + 1 ) ( a n ( a 1 ) n ) n ( a n + 1 ( a 1 ) n + 1 ) } ,

where k n ( a , d , μ ) is defined in Theorem 1.9.

Proof of Theorem 1.9

Indeed, notice that the right-hand side of the inequality in Theorem 1.18 is precisely 𝛾 as defined in Theorem 1.9. By assumption, γ > 1 , and so, by [31], it follows that 𝑋 is K-polystable. ∎

We refer the reader to the excellent survey [46] for an overview on K-stability and to [7, 22] for extensive applications of the celebrated Abban–Zhuang theory introduced in [2]. In these applications (especially in Sections 4 and 5, we will make extensive use of Zhuang’s result [49] that equivariant K-polystability for reductive groups implies K-polystability. We will also make frequent use of the result in [31] to determine K-stability of branched covers.

Let us describe the structure of this paper. First, in Section 2, we will prove a few basic properties of Casagrande–Druel varieties. Then, in Section 3, we will prove Theorem 1.18. In Sections 4 and 5, we will give proofs of Theorem 1.11 and Theorem 1.12, respectively. Finally, in Section 6, we will prove Corollary 1.13, and we will show that M ( 4.2 ) Kps P ( 1 , 2 , 3 ) . We will omit the proof of Corollary 1.14, since it is similar to the proof of Corollary 1.13.

2 Preliminaries

Let 𝑉 be a (possibly non-projective) variety, let L 1 and L 2 be line bundles on 𝑉 such that L 1 + L 2 0 and | L 1 + L 2 | , and let f H 0 ( V , O V ( L 1 + L 2 ) ) that defines a non-zero effective divisor 𝑅 on 𝑉. Set

Y 1 = P ( O V O ( L 1 ) ) , Y 2 = P ( O V O ( L 2 ) ) .

Now, let π 1 : Y 1 V and π 2 : Y 2 V be the natural projections, and let ξ 1 and ξ 2 be the tautological line bundles on Y 1 and Y 2 , respectively. We have the isomorphisms

H 0 ( Y 1 , O Y 1 ( ξ 1 ) ) H 0 ( V , O V ) H 0 ( V , O V ( L 1 ) ) , H 0 ( Y 1 , O Y 1 ( ξ 1 π 1 ( L 1 ) ) ) H 0 ( V , O V ) H 0 ( V , O V ( L 1 ) ) , H 0 ( Y 2 , O Y 2 ( ξ 2 ) ) H 0 ( V , O V ) H 0 ( V , O V ( L 2 ) ) , H 0 ( Y 2 , O Y 2 ( ξ 2 π 2 ( L 2 ) ) ) H 0 ( V , O V ) H 0 ( V , O V ( L 2 ) ) .

Using these isomorphisms, fix sections

u 1 + H 0 ( Y 1 , O Y 1 ( ξ 1 ) ) , u 1 H 0 ( Y 1 , O Y 1 ( ξ 1 π 1 ( L 1 ) ) ) , u 2 + H 0 ( Y 2 , O Y 2 ( ξ 2 ) ) , u 2 H 0 ( Y 2 , O Y 2 ( ξ 2 π 2 ( L 2 ) ) )

that correspond to the section 1 H 0 ( V , O V ) . Let

S 1 = { u 1 = 0 } Y 1 , S 1 + = { u 1 + = 0 } Y 1 , S 2 = { u 2 = 0 } Y 2 , S 2 + = { u 2 + = 0 } Y 2 .

For i { 1 , 2 } , the divisors S i and S i + are disjoint sections of the natural projection π i such that S i | S i L i S i + | S i + , where we use isomorphisms S i V S i + induced by π i .

Now, we set Q = Y 1 × V Y 2 . Then we have the canonical isomorphisms

P ( O Y 1 O Y 1 ( π 1 ( L 2 ) ) ) Q P ( O Y 2 O Y 2 ( π 2 ( L 1 ) ) ) ,

so that we have the commutative Cartesian diagram

where ρ 1 and ρ 2 are natural projections. Set ϑ = π 1 ρ 1 = π 2 ρ 2 .

Set F 1 = π 1 ( R ) Y 1 . Let ϕ 1 : X Y 1 be the blow up along the intersection F 1 S 1 + , and let E 1 be the ϕ 1 -exceptional divisor. Note that F 1 + S 1 corresponds to

π 1 ( f ) u 1 H 0 ( Y 1 , O Y 1 ( ξ 1 + π 1 ( L 2 ) ) )

and S 1 + corresponds to u 1 + H 0 ( Y 1 , O Y 1 ( ξ 1 ) ) . Thus, the ideal sheaf I O Y 1 of F 1 S 1 + admits the surjection

O Y 1 ( ξ 1 + π 1 ( L 2 ) ) O Y 1 ( ξ 1 ) I 0 .

Therefore, there is a natural closed embedding X Q over 𝑉 such that its image is the effective divisor defined by the zeroes of the section

ϑ ( f ) u 1 u 2 u 1 + u 2 + H 0 ( Q , O Q ( ρ 1 ( ξ 1 ) + ρ 2 ( ξ 2 ) ) ) ,

where we identified H 0 ( Q , O Q ( ρ i ( D ) ) ) = H 0 ( Y i , O Y i ( D ) ) for every D Pic ( Y i ) .

Let us identify 𝑋 with its image in 𝑄. Set θ = π 1 ϕ 1 . Then 𝜃 is induced by 𝜗, it is a conic bundle, and 𝑅 is its discriminant divisor. Set

S 1 = ϕ 1 ( S 1 ) , S 2 = ϕ 1 ( S 1 + ) E 1 , E 2 = ϕ 1 ( F 1 ) E 1 .

Then S 1 , S 2 , E 2 are effective Cartier divisors on the variety 𝑋; these are the proper transforms of the divisors S 1 , S 1 + , F 1 , respectively. Moreover, the divisors S 1 and S 2 are mutually disjoint sections of the conic bundle 𝜃. Furthermore, we have

S 1 | S 1 L 1 and S 2 | S 2 L 2 ,

where we use isomorphisms S 1 V and S 2 V induced by 𝜃. Similarly, we see that the divisor E 1 + E 2 is given by zeroes of the section

θ ( f ) H 0 ( X , O X ( θ ( L 1 + L 2 ) ) ) H 0 ( V , O V ( L 1 + L 2 ) ) .

Set F 2 = π 2 ( R ) Y 2 , and let ϕ 2 : X Y 2 be the morphism induced by ρ 2 : Q Y 2 . Since the defining equation of X Q is symmetric, we conclude that ϕ 2 is the blow up along the scheme-theoretic intersection F 2 S 2 + , the ϕ 2 -exceptional divisor is E 2 , and there exists the following commutative diagram:

This is an elementary transformation of the P 1 -bundle π 1 in the sense of Maruyama [33]. Now, using [33, Theorem 1.4] and [33, Proposition 1.6], we see that

S 1 = ϕ 2 ( S 2 + ) E 2 , S 2 = ϕ 2 ( S 2 ) , E 1 = ϕ 2 ( F 1 ) E 2 .

Remark 2.1

Let U = P ( O V O V ( L 1 ) O V ( L 2 ) ) , let ξ U be the tautological line bundle on the variety 𝑈, let π U : U V be the natural projection. We have the isomorphisms

H 0 ( U , O U ( ξ U ) ) H 0 ( V , O V ) H 0 ( V , O V ( L 1 ) ) H 0 ( V , O V ( L 2 ) ) , H 0 ( U , O U ( ξ U + π U ( L 1 ) ) ) H 0 ( V , O V ) H 0 ( V , O V ( L 1 ) ) H 0 ( V , O V ( L 1 L 2 ) ) , H 0 ( U , O U ( ξ U + π U ( L 2 ) ) ) H 0 ( V , O V ) H 0 ( V , O V ( L 2 ) ) H 0 ( V , O V ( L 2 L 1 ) ) .

Using these isomorphisms, fix sections

v 0 H 0 ( U , O U ( ξ U ) ) , v 1 H 0 ( U , O U ( ξ U + π U ( L 1 ) ) ) , v 2 H 0 ( U , O U ( ξ U + π U ( L 2 ) ) ) ,

which correspond to the section 1 H 0 ( V , O V ) . Recall that Q / V P 1 × P 1 . Projecting from the section u 1 = u 2 = 0 , we get a birational map Q U . Since X / V is a ( 1 , 1 ) divisor on Q / V which does not pass through the point (section) we project from, the map restricts to an isomorphism of 𝑋 on its image. The image of 𝑋 on 𝑈 is a conic given by the equation

π U ( f ) v 0 2 v 1 v 2 = 0 ,

so that we can identify 𝑋 with a Cartier divisor on 𝑈 such that X 2 ξ U + π U ( L 1 + L 2 ) .

Proposition 2.2

Suppose that 𝑉 is normal and projective, and K V is ℚ-Cartier. Then 𝑋 is normal, and K X is ℚ-Cartier. Moreover, the following assertion holds:

K X is ample K V , K V L 1 , K V L 2 are ample .

Proof

The normality of the variety 𝑋 follows from Remark 2.1 and [25, Proposition 5.24]. Similarly, using notation introduced in Remark 2.1, we see that

K U Q 3 ξ U + π U ( K V L 1 L 2 ) ,

so K X is ℚ-Cartier by the adjunction formula, because 𝑋 is a Cartier divisor on 𝑈.

To prove the remaining assertion, suppose that K V , K V L 1 , K V L 2 are ample. Then ξ U + π U ( K V ) in Remark 2.1 is ample. Then so is K X Q ( ξ U + π U ( K V ) ) | X . Alternatively, we can prove the ampleness of K X directly. Namely, observe that

(2.1) K X Q S 1 + S 2 + θ ( K V ) .

Moreover, applying the adjunction formula to the sections S 1 and S 2 , we get

K X | S 1 Q K V L 1 , K X | S 2 Q K V L 2 ,

where we used S 1 V and S 2 V . Hence, if K V , K V L 1 , K V L 2 are ample, then the divisor K X is also ample by Kleiman’s ampleness criterion.

This also shows that both divisors K V L 1 , K V L 2 are ample if K X is ample. Observe that E 1 E 2 R . Using this isomorphism and (2.1), we get K V | R K X | R . On the other hand, we have

2 K V Q ( K V L 1 ) + ( K V L 2 ) + R .

Hence, using Kleiman’s criterion again, we see that K V is ample if K X is ample. ∎

From now on, we assume, in addition, that 𝑉 is normal and projective.

Example 2.3

Suppose V = P 1 × P 1 , and L 1 and L 2 are divisors of degrees ( 1 , 0 ) and ( 0 , 1 ) , and 𝑅 is a smooth divisor in | L 1 + L 2 | . Then 𝑋 is a smooth Fano 3-fold by Proposition 2.2. One can show that 𝑋 is the unique smooth Fano 3-fold in the deformation family № 4.7. Note that 𝑋 is K-polystable [7, §3.3].

Remark 2.4

Remark 2.4 ([21, Lemma 9.8])

Suppose that 𝑉 is a smooth Fano variety, and assume K V Q a L , where 𝐿 is an ample divisor in Pic ( V ) , and a Q > 0 . Suppose 𝑅 and 𝑋 are smooth, and

L 1 Q a 1 L , L 2 Q a 2 L ,

where a 1 and a 2 are rational numbers such that a 1 a 2 . It follows from Proposition 2.2 that 𝑋 is a Fano variety if and only if a > a 1 . Further, if 𝑋 is a Fano variety, then it follows from the proof of [21, Lemma 9.8] that

β ( S 2 ) < 0 a 1 > a 2 .

Therefore, if a > a 1 > a 2 , then 𝑋 is a K-unstable Fano variety.

From now on, we also assume that L 1 = L 2 . Set L = L 1 . Then R | 2 L | . Set

Y = P ( O V O ( L ) ) .

let π : Y V be the natural projection, and let 𝜉 be the tautological line bundle on 𝑌. Note that Y Y 1 Y 2 . Using the isomorphisms

H 0 ( Y , O Y ( ξ ) ) H 0 ( V , O V ) H 0 ( V , O V ( L ) ) , H 0 ( Y , O Y ( ξ π ( L ) ) ) H 0 ( V , O V ) H 0 ( V , O V ( L ) ) ,

fix u + H 0 ( Y , O Y ( ξ ) ) and u H 0 ( Y , O Y ( ξ π ( L ) ) ) that correspond to 1 H 0 ( V , O V ) . Let S = { u = 0 } and S + = { u + = 0 } . Then S + S + π ( L ) .

Proposition 2.5

There is a double cover X Y ramified in a divisor B | 2 S + | such that the projection 𝜋 induces a double cover B V that is ramified in 𝑅.

Proof

Let T = P ( O V O V ( L ) ) O V ( 2 L ) ) , let ϖ : T V be the natural projection, and let ξ T be the tautological line bundle on 𝑇. Observe that

H 0 ( T , O T ( ξ T ) ) H 0 ( V , O V ) H 0 ( V , O V ( L ) ) H 0 ( V , O V ( 2 L ) ) , H 0 ( T , O T ( ξ T + ϖ ( L ) ) ) H 0 ( V , O V ) H 0 ( V , O V ( L ) ) H 0 ( V , O V ( L ) ) , H 0 ( T , O T ( ξ T + ϖ ( 2 L ) ) ) H 0 ( V , O V ) H 0 ( V , O V ( 2 L ) ) H 0 ( V , O V ( L ) ) .

Using these isomorphisms, fix sections

t 0 H 0 ( T , O T ( ξ T ) ) , t 1 H 0 ( T , O T ( ξ T + ϖ ( L ) ) ) , t 2 H 0 ( T , O T ( ξ T + ϖ ( 2 L ) ) ) ,

which corresponds to 1 H 0 ( V , O V ) . Then

{ t 0 = 0 } P ( O V ( L ) O V ( 2 L ) ) , { t 1 = 0 } P ( O V O V ( 2 L ) ) , { t 2 = 0 } P ( O V O V ( L ) ) .

Now, we consider the homomorphism

(2.2) O Q O Q ( ϑ ( L ) ) O Q ( ϑ ( 2 L ) ) O Q ( ρ 1 ( ξ 1 ) + ρ 2 ( ξ 2 ) )

defined by the composition of

( 1 0 0 0 1 2 0 0 1 2 0 0 0 1 ) : O Q O Q ( ϑ ( L ) ) O Q ( ϑ ( 2 L ) ) O Q O Q ( ϑ ( L ) ) O Q ( ϑ ( L ) ) O Q ( ϑ ( 2 L ) )

and the surjection

O Q O Q ( ϑ ( L ) ) O Q ( ϑ ( L ) ) O Q ( ϑ ( 2 L ) ) O Q ( ρ 1 ( ξ 1 ) + ρ 2 ( ξ 2 ) )

obtained by the tensor product of the pullbacks of the following natural surjections:

O Y 1 O Y 1 ( π 1 ( L 1 ) ) O Y 1 ( ξ 1 ) , O Y 2 O Y 2 ( π 2 ( L 2 ) ) O Y 2 ( ξ 2 ) .

Then (2.2) is surjective. This gives the morphism ρ : Q T over 𝑉 with

ρ ( t 0 ) = u 1 u 2 , ρ ( t 1 ) = 1 2 ( u 1 + u 2 + u 1 u 2 + ) , ρ ( t 2 ) = u 1 + u 2 + ,

where we identified H 0 ( Q , O Q ( ρ i ( D ) ) ) = H 0 ( Y i , O Y i ( D ) ) for D Pic ( Y i ) .

Using the local criterion for flatness, we see that 𝜌 is flat. Further, 𝜌 is finite of degree 2. Now, using [23, I (6.11)] and [23, I (6.12)], we see that the morphism 𝜌 is branched over the divisor B T | 2 ( ξ T + ϖ ( L ) ) | that is given by t 1 2 t 0 t 2 = 0 .

Let Y 0 be the divisor in | ξ T + ϖ ( 2 L ) | that is given by ϖ ( f ) t 0 t 2 = 0 , and let π 0 : Y 0 V be the morphism induced by 𝜛. Then X = ρ ( Y 0 ) as Cartier divisors, so that the restriction X Y 0 is a double cover branched over B T | Y 0 . Moreover, using the exact sequence

0 O V ( 2 L ) ( f 0 1 ) O V O V ( L ) O V ( 2 L ) ( 1 0 f 0 1 0 ) O V O V ( L ) 0 ,

we get an isomorphism Y 0 Y over 𝑉. Hence, we identify Y = Y 0 .

Set B = B T | Y . Then 𝐵 is defined by

( u + ) 2 π ( f ) ( u ) 2 = 0 ,

which implies the remaining assertions of the proposition. ∎

Let ι Aut ( X ) be the Galois involution of the double cover X Y in Proposition 2.5. Then ι ( S 1 ) = S 2 and ι ( E 1 ) = E 2 , and it follows from the proof of Proposition 2.5 that the conic bundle θ : X V is ι -equivariant with 𝜄 acting trivially on 𝑉.

Proposition 2.6

Suppose that 𝑉 is smooth, 𝐿 is nef, 𝑋 has Kawamata log terminal singularities, and K X is ample. Then the deformations of 𝑋 are unobstructed.

Proof

By Remark 2.1, 𝑋 can be embedded into U = P V ( O V O V ( L ) O V ( L ) ) such that X | 2 ξ U + 2 π U ( L ) | , where ξ U is the tautological line bundle and π U is the natural projection. Therefore, since 𝑈 is smooth, the variety 𝑋 has at worst canonical singularities, and 𝑋 has at worst local complete intersection singularities. Hence, it follows from [42, Theorem 2.3.2], [42, Theorem 2.4.1], [42, Corollary 2.4.2] that the deformation functor

Def X : A ( Sets )

has a semi-universal formal element in the sense of [42, Definition 2.2.6], where 𝒜 is the category of local ℂ-algebras with the residue field ℂ. Thus, by [41, Proposition 2.4] and [41, Proposition 2.6], the deformations of 𝑋 are unobstructed if Ext O X 2 ( Ω X 1 , O X ) = 0 .

Let us show that Ext O X 2 ( Ω X 1 , O X ) = 0 . Set n = dim ( X ) . As in [41, §1.2], we have

Ext O X 2 ( Ω X 1 , O X ) Ext O X 2 ( Ω X 1 ω X , ω X ) H n 2 ( X , Ω X 1 ω X ) .

Since K V and K V L are ample by Proposition 2.2 and 𝐿 is nef, we see that

ξ U + π U ( K V )

is ample, and ξ U + π U ( L ) is nef. In particular, both divisors

K U 3 ξ U + π U ( K V + 2 L ) , K U X ξ U + π U ( K V )

are ample. On the other hand, using the exact sequence of sheaves

0 O U ( X ) | X Ω U 1 | X Ω X 1 0 ,

we get the following exact sequence:

H n 2 ( X , Ω U 1 | X ω X ) H n 2 ( X , Ω X 1 ω X ) H n 1 ( X , O U ( X ) | X ω X ) .

Moreover, using the Kawamata–Viehweg vanishing theorem, we get

H n 1 ( X , O U ( X ) | X ω X ) H 1 ( X , K X + ( K U ) | X ) = 0 .

Furthermore, using the exact sequence of sheaves

0 Ω U 1 ω U Ω U 1 ω U ( X ) Ω U 1 | X ω X 0 ,

we get the exact sequence

H n 2 ( U , Ω U 1 ω U ( X ) ) H n 2 ( X , Ω U 1 | X ω X ) H n 1 ( U , Ω U 1 ω U ) .

Since both ω U and ω U ( X ) are anti-ample, the Akizuki–Nakano vanishing theorem gives

H n 2 ( U , Ω U 1 ω U ( X ) ) = H n 1 ( U , Ω U 1 ω U ) = 0 .

This gives Ext O X 2 ( Ω X 1 , O X ) = 0 , which completes the proof. ∎

3 K-polystability criteria

The goal of this section is to prove Theorem 1.18. To do so, we will apply the theory of Abban–Zhuang [2], as applied in [7, §1.7] and [22], consisting on bounding delta-invariants below by picking a specific flag.

Fix a positive integer n 3 . Let 𝑉 be a smooth projective variety of dimension n 1 , and let 𝐿 be an ample Cartier divisor on 𝑉. Set d = L n 1 . Fix μ Q > 0 such that μ L is very ample. Let Y = P ( O V O V ( L ) ) , and let π : Y V be the natural projection. Set H = π ( L ) . Let S and S + be disjoint sections of the projection 𝜋 such that S + S + H .

Remark 3.1

Unlike Section 1, we do not assume that 𝑉 is a Fano variety.

Fix a positive rational number a 1 . Let D ( a ) = S + a H . Then D ( a ) is nef and big. Moreover, if a > 1 , then D ( a ) is ample.

Lemma 3.2

Lemma 3.2 (cf. [48])

Let 𝑃 be a point in S . Then

δ P ( Y ; D ( a ) ) min { ( n + 1 ) ( a n ( a 1 ) n ) ( n + 1 a ) a n + ( a 1 ) n + 1 , δ ( V ; L ) ( n + 1 ) ( a n ( a 1 ) n ) n ( a n + 1 ( a 1 ) n + 1 ) } ,

where δ P ( Y ; D ( a ) ) is the (local) 𝛿-invariant of the variety 𝑌 polarized by the divisor D ( a ) , and δ ( V ; L ) is the 𝛿-invariant of 𝑉 polarized by 𝐿. Further, if δ ( V ; L ) a , then

δ P ( Y ; D ( a ) ) δ ( V ; L ) ( n + 1 ) ( a n ( a 1 ) n ) n ( a n + 1 ( a 1 ) n + 1 ) .

Proof

It follows from [2, 7] that

δ P ( Y ; D ( a ) ) min { 1 S D ( a ) ( S ) , inf F / S P C S ( F ) A S ( F ) S ( W , S ; F ) } ,

where S ( W , S ; F ) is defined in [7, Section 1.7], and the infimum is taken over all prime divisors over S whose centers on S contain 𝑃. This easily implies the required assertion.

Indeed, take u R 0 . Then D ( a ) u S R ( 1 u ) S + a H , so that

D ( a ) u S is nef D ( a ) u S is pseudo-effective u 1 .

Thus, since vol ( D ( a ) ) = D ( a ) n = d ( a n ( a 1 ) n ) , we have

S D ( a ) ( S ) = 1 D ( a ) n 0 vol ( D ( a ) u S ) d u = 1 d ( a n ( a 1 ) n ) 0 1 ( ( 1 u a ) n ( 1 ) n + 1 d + a n d ) d u = ( n + 1 a ) a n + ( a 1 ) n + 1 ( n + 1 ) ( a n ( a 1 ) n ) .

Using S V , we get ( D ( a ) u S ) | S R ( a + u 1 ) H | S R ( a + u 1 ) L .

Let 𝐹 be any prime divisor over S . Then it follows from [7, Section 1.7] that

S ( W , S ; F ) = n D ( a ) n 0 1 0 vol ( ( D ( a ) u S ) | S v F ) d v d u = n D ( a ) n 0 1 0 vol ( ( a + u 1 ) L v F ) d v d u = n D ( a ) n 0 1 ( a + u 1 ) n 0 vol ( L v F ) d v d u = n d ( a n ( a 1 ) n ) a n + 1 ( a 1 ) n + 1 n + 1 0 vol ( L v F ) d v = n n + 1 a n + 1 ( a 1 ) n + 1 d ( a n ( a 1 ) n ) L n 1 S L ( F ) = n n + 1 a n + 1 ( a 1 ) n + 1 a n ( a 1 ) n S L ( F ) .

This gives

A S ( F ) S ( W , S ; F ) = A S ( F ) S L ( F ) n + 1 n a n ( a 1 ) n a n + 1 ( a 1 ) n + 1 δ P ( V ; L ) n + 1 n a n ( a 1 ) n a n + 1 ( a 1 ) n + 1 ,

which implies the first part of the assertion.

We now assume δ ( V ; L ) a and we want to show

( n + 1 ) ( a n ( a 1 ) n ) ( n + 1 a ) a n + ( a 1 ) n + 1 δ ( V ; L ) ( n + 1 ) ( a n ( a 1 ) n ) n ( a n + 1 ( a 1 ) n + 1 ) .

This inequality is equivalent to

δ ( V ; L ) n ( a n + 1 ( a 1 ) n + 1 ) ( n + 1 a ) a n + ( a 1 ) n + 1 .

We must show that the right-hand side of the inequality above is at least 𝑎. But

n ( a n + 1 ( a 1 ) n + 1 ) ( n + 1 a ) a n + ( a 1 ) n + 1 > a a n + 1 ( a 1 ) ( a 1 ) n + 1 ( a + n ) > 0 ,

which is clearly true. ∎

Now, fix a smooth divisor B | 2 S + | . Let η : B V be the morphism induced by 𝜋. Suppose that 𝜂 is the double cover ramified over a smooth divisor R | 2 L | . Set Δ = 1 2 B . Note that B S = . Let k n ( a , d , μ ) be the number defined in Theorem 1.9.

Proposition 3.3

Let 𝑃 be a point in Y S . Suppose that d μ n 2 2 . Then

δ P ( Y , Δ ; D ( a ) ) 1 k n ( a , d , μ ) ,

where δ P ( Y , Δ ; D ( a ) ) is the (local) 𝛿-invariants of the pair ( Y , Δ ) polarized by D ( a ) .

This result together with Lemma 3.2 implies Theorem 1.18.

Proof of Theorem 1.18.

Note that 𝑉 is a Fano variety and K V Q a L . Then

K Y 2 S + π ( K V + L ) Q 2 S + + ( a 1 ) H ,

which gives

( K Y + Δ ) Q S + + ( a 1 ) H Q S + a H = D ( a ) ,

so that ( Y , Δ ) is the log Fano pair and

δ ( Y , Δ ) = δ ( Y , Δ ; D ( a ) ) ,

where δ ( Y , Δ ) is the 𝛿-invariant of the log Fano pair ( Y , Δ ) . Now, we can apply Lemma 3.2 and Proposition 3.3 to get the required assertion. ∎

In the remaining part of the section, we will prove Proposition 3.3 by induction on 𝑛.

3.1 Base of induction

Let 𝑉 be a smooth projective surface, let 𝐿 be an ample Cartier divisor on 𝑉, let 𝜇 be the smallest rational number such that μ L is very ample, let

Y = P ( O V O V ( L ) ) ,

and let π : Y V be the natural projection. Set H = π ( L ) . Let S and S + be disjoint sections of the projection 𝜋 such that S + S + H , and let 𝐵 be an irreducible normal surface in | 2 S + | such that 𝜋 induces a double cover B V which is ramified in a reduced curve R | 2 L | . Fix a Q such that a 1 . Let D ( a ) = S + a H . Then D ( a ) is nef and big, and D ( a ) is ample for a > 1 . Set Δ = 1 2 B and d = L 2 .

Remark 3.4

Since μ L is very ample and 𝐿 is Cartier, we have d μ = ( μ L ) L Z > 0 and

d μ 2 = ( μ L ) 2 Z > 0 .

Moreover, if d μ = 1 , then μ = 1 , d = L 2 = 1 , V = P 2 and L = O P 2 ( 1 ) .

Suppose, in addition, that d μ 2 . Set

k 3 ( a , d , μ ) = 8 d μ a 3 + 6 ( 1 2 d μ ) a 2 + 8 ( d μ 1 ) a 2 d μ + 3 8 ( 3 a 2 3 a + 1 ) .

Let 𝑃 be a point in 𝑌 such that P S and P Sing ( B ) .

Proposition 3.5

One has δ P ( Y , Δ ; D ( a ) ) 1 k 3 ( a , d , μ ) .

In the remaining part of this subsection, we will prove this result. We will only consider the case P B , because the case P B is much simpler.

Let V 1 be a general curve in | μ L | that contains the point π ( P ) , and let Y 1 = π ( V 1 ) . Then V 1 is a smooth curve, and Y 1 is a smooth surface. For simplicity, we set D = D ( a ) . Take u R 0 . Then D u Y 1 R S + ( a μ u ) H , so that D u Y 1 is pseudo-effective if and only if u a μ . We have

( D u Y 1 ) | S R ( S + ( a μ u ) H ) | S R ( a 1 μ u ) L ,

where we use isomorphism S V induced by 𝜋. Hence, the divisor D u Y 1 is nef if and only if u a 1 μ . Moreover, the Zariski decomposition of D u Y 1 is

P ( u ) R { S + ( a μ u ) H if u [ 0 , a 1 μ ] , ( a μ u ) ( S + H ) = ( a μ u ) S + if u [ a 1 μ , a μ ] ,

and

N ( u ) = { 0 if u [ 0 , a 1 μ ] , ( μ u + 1 a ) S if u [ a 1 μ , a μ ] ,

where P ( u ) is the positive part, and N ( u ) is the negative part.

Note that H 3 = 0 , H 2 S = d , H ( S ) 2 = d , ( S ) 3 = d . Then

S D ( Y 1 ) = 1 D 3 0 a μ vol ( D u Y 1 ) d u = 1 ( S + a H ) 3 ( 0 a 1 μ ( S + ( a μ u ) H ) 3 d u + a 1 μ a μ ( ( a μ u ) ( S + H ) ) 3 d u ) = ( 2 a 1 ) ( 2 a 2 2 a + 1 ) 4 μ ( 3 a 2 3 a + 1 ) .

Let 𝑓 be the fiber of the P 1 -bundle 𝜋 that contains 𝑃. Then there are two cases to consider: either 𝐵 intersects 𝑓 transversely at 𝑃 or tangentially. For each case, we consider an appropriate plt blow up h : Y ̃ 1 Y 1 at the point 𝑃 with smooth exceptional curve 𝐸. We let Δ 1 = Δ | Y 1 , and we denote by Δ ̃ 1 the proper transform on Y ̃ 1 of the divisor Δ 1 . Then it follows from [2, 7, 22] that

δ P ( Y , Δ ) min { 1 S D ( Y 1 ) , A Y 1 , Δ 1 ( E ) S ( V , Y 1 ; E ) , inf Q E A E , Δ E ( Q ) S ( V , , Y ̃ 1 , E ; Q ) } .

where S ( V , Y 1 ; E ) and S ( V , , Y ̃ 1 , E ; Q ) are defined in [7, Section 1.7], and Δ E is the different computed via the adjunction formula

K E + Δ E = ( K Y ̃ 1 + Δ ̃ 1 + E ) | E .

For instance, if ℎ is the ordinary blow up at the point 𝑃, then Δ E = Δ ̃ 1 | E . For simplicity, we rewrite the last inequality as

(3.1) 1 δ P ( Y , Δ ) max { S D ( Y 1 ) , S ( V , Y 1 ; E ) A Y 1 , Δ 1 ( E ) , sup Q E S ( V , , Y ̃ 1 , E ; Q ) A E , Δ E ( Q ) } .

Thus, to prove Proposition 3.5, it is enough to bound each term in (3.1) by k 3 ( a , d , μ ) .

We set S 1 = S | Y 1 , H 1 : = H | Y 1 , B 1 : = B | Y 1 , D 1 = P ( u ) | Y 1 . Note that H 1 d μ f and

D 1 { S 1 + ( a μ u ) d μ f if u [ 0 , a 1 μ ] , ( a μ u ) ( S 1 + d μ f ) if u [ a 1 μ , a μ ] .

We denote by S ̃ 1 , B ̃ 1 , f ̃ the proper transforms on Y ̃ 1 of the curves S 1 , B 1 , 𝑓, respectively. Recall that Y 1 is a P 1 -bundle over the smooth curve V 1 . In Lemmas 3.6 and 3.7, we estimate δ P ( Y , Δ ; D ( a ) ) when 𝐵 and 𝑓 intersect transversely or tangentially, respectively. Notice that Y ̃ 1 has Picard rank 3 and its Mori cone is generated by the divisors S ̃ 1 , f ̃ and 𝐸.

Lemma 3.6

Suppose 𝐵 intersects 𝑓 transversally. Then δ P ( Y , Δ ; D ( a ) ) 1 k 3 ( a , d , μ ) .

Proof

Let h : Y ̃ 1 Y 1 be the ordinary blow up at 𝑃, where 𝐸 is the ℎ-exceptional curve. We have S ̃ 1 h ( S 1 ) and f ̃ h ( f ) E . Take v R 0 . Then

h ( D 1 ) v E { S ̃ 1 + ( a μ u ) d μ f ̃ + ( ( a μ u ) d μ v ) E if u [ 0 , a 1 μ ] , ( a μ u ) ( S ̃ 1 + d μ f ̃ ) + ( ( a μ u ) d μ v ) E if u [ a 1 μ , a μ ] .

We have the following intersection numbers:

S ̃ 1 f ̃ 𝐸
S ̃ 1 d μ 1 0
f ̃ 1 −1 1
𝐸 0 1 −1

This shows that h ( D 1 ) v E is pseudo-effective if and only if v ( a μ u ) d μ .

If u [ 0 , a 1 μ ] , the positive part of the Zariski decomposition of h ( D 1 ) v E is

P ̃ ( u , v ) { S ̃ 1 + ( a μ u ) d μ f ̃ + ( ( a μ u ) d μ v ) E if v [ 0 , 1 ] , S ̃ 1 + ( ( a μ u ) d μ + 1 v ) f ̃ + ( ( a μ u ) d μ v ) E if v [ 1 , 1 d μ 2 u + a d μ d μ ] , d μ 2 u + a d μ v d μ 1 ( S ̃ 1 + d μ f ̃ + ( d μ 1 ) E ) if v [ 1 d μ 2 u + a d μ d μ , ( a μ u ) d μ ] ,

and the negative part is

N ̃ ( u , v ) = { 0 if v [ 0 , 1 ] , ( v 1 ) f ̃ if v [ 1 , 1 d μ 2 u + a d μ d μ ] , d μ ( μ u a + v ) d μ 1 f ̃ + d μ 2 u a d μ + d μ + v 1 d μ 1 S ̃ 1 if v [ 1 d μ 2 u + a d μ d μ , ( a μ u ) d μ ] .

Similarly, if u [ a 1 μ , a μ ] , the positive part of the Zariski decomposition of h ( D 1 ) v E is

P ̃ ( u , v ) { ( a μ u ) ( S ̃ 1 + d μ f ̃ ) + ( ( a μ u ) d μ v ) E if v [ 0 , a μ u ] , 1 d μ 1 ( d μ 2 u + a d μ v ) ( S ̃ 1 + d μ f ̃ + ( d μ 1 ) E ) if v [ a μ u , ( a μ u ) d μ ] .

and the negative part is

N ̃ ( u , v ) = { 0 if v [ 0 , a μ u ] , 1 d μ 1 ( d μ ( μ u a + v ) f ̃ + ( μ u a + v ) S ̃ 1 ) if v [ a μ u , ( a μ u ) d μ ] .

Now, using results from [7, Section 1.7], we compute

S ( W , Y ̃ 1 ; E ) = 3 D 3 0 a μ 0 ( a μ u ) d μ vol ( D 1 v F ) d v d u = 3 ( S + a H ) 3 0 a μ 0 ( a μ u ) d μ P ̃ ( u , v ) 2 d v d u = 4 a 3 d μ + 6 ( 1 d μ ) a 2 + 4 ( d μ 2 ) a d μ + 3 4 ( 3 a 2 3 a + 1 ) .

Moreover, we have A Y 1 , Δ 1 ( E ) = 2 1 2 = 3 2 , so that

S ( W , Y 1 ; E ) A Y 1 , Δ 1 ( E ) = 4 a 3 d μ + 6 ( 1 d μ ) a 2 + 4 ( d μ 2 ) a d μ + 3 6 ( 3 a 2 3 a + 1 ) .

Let 𝑄 be a point in 𝐸. Then, using results from [7, Section 1.7], we compute

S ( W , , Y ̃ 1 , E ; Q ) = 3 ( S + a H ) 3 0 a μ 0 ( a μ u ) d μ ( P ̃ ( u , v ) E ) 2 d v d u + F q ( W , , Y ̃ 1 , E ) = 6 a 2 8 a + 3 4 ( 3 a 2 3 a + 1 ) + F Q ( W , , Y ̃ 1 , E ) ,

where

F Q ( W , , Y ̃ 1 , E ) = 6 ( S + a H ) 3 0 a μ 0 ( a μ u ) d μ ( P ̃ ( u , v ) E ) ord Q ( N ̃ ( u , v ) | E ) d v d u ,

because P Supp ( N ( u ) ) for u [ 0 , a μ ] . Notice that

F Q ( W , , Y ̃ 1 , E ) 0

only when Q f ̃ . Thus, there are three cases to consider.

  • Q = E f ̃ . Then

    F Q ( W , , Y ̃ 1 , E ) = 3 8 a + 6 a 2 + d μ 4 a d μ + 6 a 2 d μ 4 a 3 d μ 4 ( 3 a 2 3 a + 1 )

    and A E , Δ E ( Q ) = 1 since Q B ̃ 1 . Hence, we have

    S ( W , , Y ̃ 1 , E ; Q ) A E , Δ E ( Q ) = d μ ( 2 a 1 ) ( 2 a 2 2 a + 1 ) 4 ( 3 a 2 3 a + 1 ) .

  • Q E B ̃ 1 . Then A E , Δ E ( Q ) = 1 2 , so that

    S ( W , , Y ̃ 1 , E ; Q ) A E , Δ E ( Q ) = 6 a 2 8 a + 3 2 ( 3 a 2 3 a + 1 ) .

  • Q E away from f ̃ and B ̃ 1 . Then A E , Δ E ( Q ) = 1 , so that

    S ( W , , Y ̃ 1 , E ; Q ) A E , Δ E ( Q ) = 6 a 2 8 a + 3 4 ( 3 a 2 3 a + 1 ) .

The third case is smaller than the previous one (exactly half), so we do not consider it. So, using (3.1), we obtain the inequality

(3.2) 1 δ P ( Y , Δ ) max { ( 2 a 1 ) ( 2 a 2 2 a + 1 ) 4 μ ( 3 a 2 3 a + 1 ) , 4 a 3 d μ + 6 ( 1 d μ ) a 2 + 4 ( d μ 2 ) a d μ + 3 6 ( 3 a 2 3 a + 1 ) , d μ ( 2 a 1 ) ( 2 a 2 2 a + 1 ) 4 ( 3 a 2 3 a + 1 ) , 6 a 2 8 a + 3 2 ( 3 a 2 3 a + 1 ) } .

Recall from Remark 3.4 that d μ 2 1 . This allows us to conclude

d μ ( 2 a 1 ) ( 2 a 2 2 a + 1 ) 4 ( 3 a 2 3 a + 1 ) ( 2 a 1 ) ( 2 a 2 2 a + 1 ) 4 μ ( 3 a 2 3 a + 1 ) ,

so we can discard the first term in (3.2). Moreover, since d μ 2 , we have

4 a 3 d μ + 6 ( 1 d μ ) a 2 + 4 ( d μ 2 ) a d μ + 3 6 ( 3 a 2 3 a + 1 ) k 3 ( a , d , μ ) , d μ ( 2 a 1 ) ( 2 a 2 2 a + 1 ) 4 ( 3 a 2 3 a + 1 ) k 3 ( a , d , μ ) , 6 a 2 8 a + 3 2 ( 3 a 2 3 a + 1 ) k 3 ( a , d , μ ) ,

which gives δ P ( Y , Δ ; D ( a ) ) 1 k 3 ( a , d , μ ) . ∎

Now, we deal with the case when 𝑓 is tangent to 𝐵 at the point 𝑃.

Lemma 3.7

Suppose 𝐵 and 𝑓 are tangent at 𝑃. Then δ P ( Y , Δ ; D ( a ) ) 1 k 3 ( a , d , μ ) .

Proof

Now, we let h : Y ̃ 1 Y 1 be the ( 1 , 2 ) -weighted blow up of the point 𝑃 such that the curves B ̃ 1 and f ̃ are disjoint. Then f ̃ = h ( f ) 2 E . Take v R 0 . Then

h ( D 1 ) v E { S ̃ 1 + ( a μ u ) d μ f ̃ + ( 2 ( a μ u ) d μ v ) E if u [ 0 , a 1 μ ] , ( a μ u ) ( S ̃ 1 + d μ f ̃ ) + ( 2 ( a μ u ) d μ v ) E if u [ a 1 μ , a μ ] .

Moreover, we have the following intersection numbers:

S ̃ 1 f ̃ 𝐸
S ̃ 1 d μ 1 0
f ̃ 1 −2 1
𝐸 0 1 1 2

Thus, the divisor h ( D 1 ) v E is pseudo-effective if and only if v 2 ( a μ u ) d μ .

If u [ 0 , a 1 μ ] , the positive part of the Zariski decomposition of h ( D 1 ) v E is

P ̃ ( u , v ) { S ̃ 1 + ( a μ u ) d μ f ̃ + ( 2 ( a μ u ) d μ v ) E if v [ 0 , 1 ] , S ̃ 1 + ( ( a μ u ) d μ + 1 v 2 ) f ̃ + ( 2 ( a μ u ) d μ v ) E if v [ 1 , 2 d μ 2 u + 2 a d μ 2 d μ + 1 ] , 2 d μ 2 u + 2 a d μ v 2 d μ 1 ( S ̃ 1 + d μ f ̃ + ( 2 d μ 1 ) E ) if v [ 2 d μ 2 u + 2 a d μ 2 d μ + 1 , 2 ( a μ u ) d μ ] ,

and the negative part is

N ̃ ( u , v ) = { 0 if v [ 0 , 1 ] , v 1 2 f ̃ if v [ 1 , 2 d μ 2 u + 2 a d μ 2 d μ + 1 ] , d μ ( μ u a + v ) 2 d μ 1 f ̃ + 2 d μ 2 u 2 a d μ + 2 d μ + v 1 2 d μ 1 S ̃ 1 if v [ 2 d μ 2 u + 2 a d μ 2 d μ + 1 , 2 ( a μ u ) d μ ] .

Similarly, if u [ a 1 μ , a μ ] , the positive part of the Zariski decomposition of h ( D 1 ) v E is

P ̃ ( u , v ) { ( a μ u ) ( S ̃ 1 + d μ f ̃ ) + ( 2 ( a μ u ) d μ v ) E if v [ 0 , a μ u ] , 2 d μ 2 u + 2 a d μ v 2 d μ 1 ( S ̃ 1 + d μ f ̃ + ( 2 d μ 1 ) E ) if v [ a μ u , 2 ( a μ u ) d μ ] ,

and the negative part is

N ̃ ( u , v ) = { 0 if v [ 0 , a μ u ] , d μ ( μ u a + v ) 2 d μ 1 f ̃ + μ u a + v 2 d μ 1 S ̃ 1 if v [ a μ u , 2 ( a μ u ) d μ ] .

Now, using results from [7, Section 1.7], we compute

S ( W , Y 1 ; E ) = 3 D 3 0 a μ 0 2 ( a μ u ) d μ vol ( D 1 v F ) d v d u = 3 ( S + a H ) 3 0 a μ 0 2 ( a μ u ) d μ P ̃ ( u , v ) d v d u = 1 4 8 a 3 d μ + 6 ( 1 2 d μ ) a 2 + 8 ( d μ 1 ) a 2 d μ + 3 3 a 2 3 a + 1

Moreover, since A Y 1 , Δ 1 ( E ) = 2 , we have

S ( W , Y 1 ; E ) A Y 1 , Δ 1 ( E ) = 1 8 8 a 3 d μ + 6 ( 1 2 d μ ) a 2 + 8 ( d μ 1 ) a 2 d μ + 3 3 a 2 3 a + 1 .

Let 𝑄 be a point in 𝐸. Using results from [7, Section 1.7], we get

S ( W , , Y ̃ 1 , E ; Q ) = 3 ( S + a H ) 3 0 a μ 0 2 ( a μ u ) d μ ( P ̃ ( u , v ) E ) 2 d v d u + F Q ( W , , Y ̃ 1 , E ) = 1 8 6 a 2 8 a + 3 3 a 2 3 a + 1 + F Q ( W , , Y ̃ 1 , E ) ,

where

F Q ( W , , Y ̃ 1 , E ) = 6 ( S + a H ) 3 0 a μ 0 2 ( a μ u ) d μ ( P ̃ ( u , v ) E ) ord Q ( N ̃ ( u , v ) | E ) d v d u .

There are three cases to consider.

  • Q = E f ̃ . Then

    F Q ( W , , Y ̃ 1 , E ) = 1 8 8 a 3 d μ 6 ( 2 d μ 1 ) a 2 + 8 ( d μ + 1 ) a 2 d μ 3 3 a 2 3 a + 1

    and A E , Δ E ( Q ) = 1 since Q B ̃ 1 . Hence, we have

    S ( W , , Y ̃ 1 , E ; Q ) A E , Δ E ( Q ) = d μ 4 ( 2 a 1 ) ( 2 a 2 2 a + 1 ) 3 a 2 3 a + 1 .

  • Q E B ̃ . Then A E , Δ E ( Q ) = 1 2 , so that

    S ( W , , Y ̃ 1 , E ; Q ) A E , Δ E ( Q ) = 1 4 6 a 2 8 a + 3 3 a 2 3 a + 1 .

  • Q E is the A 1 singularity. Then A E , Δ E ( Q ) = 1 2 , and so

    S ( W , , Y ̃ 1 , E ; Q ) A E , Δ E ( Q ) = 1 4 6 a 2 8 a + 3 3 a 2 3 a + 1 .

We have the inequality

1 δ P ( Y , Δ ) max { ( 2 a 1 ) ( 2 a 2 2 a + 1 ) 4 μ ( 3 a 2 3 a + 1 ) , 1 8 8 a 3 d μ + 6 ( 1 2 d μ ) a 2 + 8 ( d μ 1 ) a 2 d μ + 3 3 a 2 3 a + 1 , d μ 4 ( 2 a 1 ) ( 2 a 2 2 a + 1 ) 3 a 2 3 a + 1 , 1 4 6 a 2 8 a + 3 3 a 2 3 a + 1 } .

Now, arguing as in the end of the proof of Lemma 3.6, we find

1 δ P ( Y , Δ ) 1 8 8 a 3 d μ + 6 ( 1 2 d μ ) a 2 + 8 ( d μ 1 ) a 2 d μ + 3 3 a 2 3 a + 1 ,

and the result follows. ∎

Proof of Proposition 3.5.

This is a combination of Lemmas 3.6 and 3.7. ∎

3.2 The induction

Let us use all assumptions and notation introduced in Section 3. Recall that 𝜇 is the smallest rational number for which μ L is a very ample Cartier divisor on the variety 𝑉 and d = L n 1 . Then μ n 1 d = ( μ L ) n 1 1 . Let us prove Proposition 3.3 by induction on dim ( Y ) = n 3 ; the base of induction (the case when n = 3 ) is done in Section 3.1.

Therefore, we suppose that Proposition 3.3 holds for varieties of dimension n 1 3 . Let 𝑃 be a point in 𝑌 such that P S . We must prove that

δ P ( Y , Δ ; D ( a ) ) 1 k n ( a , d , μ ) ,

where k n ( a , d , μ ) is presented in Theorem 1.9. We will only consider the case when P B , since the case P B is simpler and similar. Thus, we suppose that P B .

Let V n 1 be a general divisor in | μ L | that contains the point π ( P ) . Set

Y n 1 = π ( V n 1 ) .

For simplicity, set D = D ( a ) . First, let us compute S D ( Y n 1 ) . Take u R 0 . Then

D ( a ) u Y n 1 R S + ( a μ u ) H ,

so D ( a ) u Y n 1 is pseudo-effective if and only if u a μ . For u [ 0 , a μ ] , let P ( u ) be the positive part of the Zariski decomposition of D ( a ) u Y n 1 , and let N ( u ) be its negative part. Then

P ( u ) { S + ( a μ u ) H = D ( a μ u ) if u [ 0 , a 1 μ ] , ( a μ u ) ( S + H ) = ( a μ u ) D ( 1 ) if u [ a 1 μ , a μ ] ,

and

N ( u ) = { 0 if u [ 0 , a 1 μ ] , ( μ u + 1 a ) S if u [ a 1 μ , a μ ] .

Recall that S S + = . Note that ( S ) n = ( 1 ) n + 1 d and ( S + ) n = d . Hence, we have

D ( a ) n = ( S + a H ) n = ( ( 1 a ) S + a S + ) n = d ( a n ( a 1 ) n ) .

Now, we compute

S D ( Y n 1 ) = 1 D ( a ) n 0 vol ( D ( a ) u Y n 1 ) d u = 1 D ( a ) n 0 a 1 μ ( S + ( a μ u ) H ) n d u + 1 D ( a ) n a 1 μ a μ ( ( a μ u ) ( S + H ) ) n d u = 1 D ( a ) n 0 a 1 μ d ( ( 1 ) n + 1 ( 1 a + μ u ) n + ( a μ u ) n ) d u + 1 D ( a ) n a 1 μ a μ d ( a μ u ) n d u = a n + 1 ( a 1 ) n + 1 μ ( n + 1 ) ( a n ( a 1 ) n ) .

Set

Res n ( a ) = a n + 1 ( a + n ) ( a 1 ) n 2 ( n + 1 ) ( a n ( a 1 ) n ) .

Lemma 3.8

One has k n ( a , d , μ ) = S D ( a ) ( Y n 1 ) d μ n 1 + Res n ( a ) and Res n ( a ) > 0 .

Proof

The equality follows from the formulas for k n ( a , d , μ ) and S D ( a ) ( Y n 1 ) . Let us show that Res n ( a ) > 0 . We may assume that a > 1 . The denominator is clearly positive. Hence, we only need to verify that a n + 1 ( a + n ) ( a 1 ) n > 0 . But

( a a 1 ) n = ( 1 + 1 a 1 ) n = i = 0 n ( n i ) ( 1 a 1 ) i > 1 + n a 1 > 1 + n a = a + n a ,

which gives a n + 1 ( a + n ) ( a 1 ) n > 0 . This shows that Res n ( a ) > 0 . ∎

Set Δ n 1 = Δ | Y n 1 . Then S D ( Y n 1 ) k n ( a , d , μ ) by Lemma 3.8, since d μ n 1 1 . Therefore, using [2], we see that δ P ( Y , Δ ; D ) 1 k n ( a , d , μ ) provided that

(3.3) S ( V , Y n 1 ; E ) k n ( a , d , μ ) A Y n 1 , Δ n 1 ( E )

for every prime divisor 𝐸 over the variety Y n 1 such that its center on Y n 1 contains 𝑃, where A Y n 1 , Δ n 1 ( E ) is the log discrepancy, and S ( V , Y n 1 ; E ) is defined in [7, Section 1.7].

Suppose that n 4 . Let us prove (3.3) using Proposition 3.3 applied to ( Y n 1 , Δ n 1 ) . Let 𝐸 be a prime divisor over Y n 1 whose center in Y n 1 contains 𝑃. Since P S , it follows from [7, Corollary 1.108] that

S ( V , Y n 1 ; E ) = n D n 0 a μ ( 0 vol ( P ( u ) | Y n 1 v E ) d v ) d u
= n D n 0 a 1 μ 0 vol ( S + ( a μ u ) H v E ) d v d u
+ n D n a 1 μ a μ 0 vol ( ( a μ u ) ( S + H ) v E ) d v d u
= n D n 0 a 1 μ 0 vol ( S + ( a μ u ) H v E ) d v d u
+ n D n a 1 μ a μ ( a μ u ) n 0 vol ( S + H v E ) d v d u .
Now, applying Proposition 3.3 (induction step), we get

0 vol ( S + ( a μ u ) H v E ) d v k n 1 ( a μ u , d μ , μ ) ( S + ( a μ u ) H ) n 1 A Y n 1 , Δ n 1 ( E )

and

0 vol ( S + H v E ) d v k n 1 ( 1 , d μ , μ ) ( S + H ) n 1 A Y n 1 , Δ n 1 ( E ) .

Hence, combining, we obtain

S ( V , Y n 1 ; E ) n D n 0 a 1 μ k n 1 ( a μ u , d μ , μ ) ( S + ( a μ u ) H ) n 1 A Y n 1 , Δ n 1 ( E ) d u + n D n a 1 μ a μ ( a μ u ) n k n 1 ( 1 , d μ , μ ) ( S + H ) n 1 A Y n 1 , Δ n 1 ( E ) d u = A Y n 1 , Δ n 1 ( E ) n D n 0 a 1 μ k n 1 ( a μ u , d μ , μ ) ( S + ( a μ u ) H ) n 1 d u + A Y n 1 , Δ n 1 ( E ) n D n a 1 μ a μ ( a μ u ) n k n 1 ( 1 , d μ , μ ) ( S + H ) n 1 d u .

Let us compute these two integrals separately. We have

A 1 := 0 a 1 μ k n 1 ( a μ u , d μ , μ ) ( S + ( a μ u ) H ) n 1 d u = d μ n 1 0 a 1 μ d μ ( ( 1 ) n 1 ( 1 a + μ u ) n + ( a μ u ) n ) μ n d u + 0 a 1 μ d μ ( ( a μ u ) n ( a μ u + n 1 ) ( a μ u 1 ) n 1 ) 2 n d u = d 2 μ n 1 μ n ( n + 1 ) ( a n + 1 ( a 1 ) n + 1 1 ) + d 2 n ( n + 1 ) ( a n + 1 ( a + n ) ( a 1 ) n 1 )

and

A 2 := a 1 μ a μ ( a n μ u ) n k n 1 ( 1 , d μ , μ ) ( S + H ) n 1 d u = d ( 2 d μ n 2 + 1 ) 2 n ( n + 1 ) = d 2 μ n 1 μ n ( n + 1 ) + d 2 n ( n + 1 ) .

Adding these two integrals, we get

n D ( a ) n ( A 1 + A 2 ) = d μ n 1 μ ( n + 1 ) a n + 1 ( a 1 ) n + 1 a n ( a 1 ) n + 1 2 ( n + 1 ) a n + 1 ( a + n ) ( a 1 ) n a n ( a 1 ) n = S D ( a ) ( Y n 1 ) d μ n 1 + Res n ( a ) .

This gives S ( V , Y n 1 ; E ) k n ( a , d , μ ) A Y n 1 , Δ n 1 ( E ) by Lemma 3.8, which proves (3.3) and completes the proof of Proposition 3.3.

3.3 Applications

The only application of Theorem 1.9 we could find is Theorem 1.8. Let us use assumptions and notation of Theorem 1.9. Let V = P n 1 and L = O P n 1 ( r ) . Suppose that 1 < n 2 < r < n . Then μ = 1 r , d = r n 1 and a = n r .

Lemma 3.9

One has k n ( a , d , μ ) < 1 .

Proof

One has

k n ( a , d , μ ) = ( 2 d μ n 2 + 1 ) a n + 1 ( a + n ) ( a 1 ) n 2 d μ n 2 ( a 1 ) n + 1 2 ( n + 1 ) ( a n ( a 1 ) n ) .

Thus, it is enough to show that

2 ( n + 1 ) ( a n ( a 1 ) n ) ( ( 2 d μ n 2 + 1 ) a n + 1 ( a + n ) ( a 1 ) n 2 d μ n 2 ( a 1 ) n + 1 ) > 0 .

Substituting μ = 1 r , d = r n 1 , a = n r , and multiplying by r n + 1 , we get the inequality

( n n ( n r ) n ( r + 1 ) ) ( 2 r n ) > 0 ,

which holds since 2 r n > 0 and n > r > n 2 by assumption. ∎

Lemma 3.10

One has

( n + 1 ) ( a n ( a 1 ) n ) ( n + 1 a ) a n + ( a 1 ) n + 1 > 1 .

Proof

The inequality is equivalent to

( n + 1 ) ( a n ( a 1 ) n ) > ( n + 1 a ) a n + ( a 1 ) n + 1 .

Substituting a = n r , multiplying by r n , and dividing by 𝑛, we get n n ( r + 1 ) ( n r ) n > 0 , which holds since 1 < n 2 < r < n . ∎

Lemma 3.11

One has

a δ ( V ) ( n + 1 ) ( a n ( a 1 ) n ) n ( a n + 1 ( a 1 ) n + 1 ) > 1 .

Proof

We have δ ( V ) = δ ( P n 1 ) = 1 . Thus, the required inequality is equivalent to

n ( a n + 1 ( a 1 ) n + 1 ) a ( n + 1 ) ( a n ( a 1 ) n ) < 0 .

Substituting a = n r , multiplying by r n + 1 , and dividing by 𝑛, we get n n ( r + 1 ) ( n r ) n > 0 , which holds since 1 < n 2 < r < n . ∎

Theorem 1.8 follows from Lemmas 3.9, 3.10, 3.11 and Theorem 1.9.

4 Proof of Theorem 1.11

The goal of this section is to prove Theorem 1.11 and describe singular K-polystable limits of smooth Fano 3-folds in the deformation family № 4.2. We start with the following (probably well-known) result, which we fail to find in the literature.

Proposition 4.1

Let 𝐶 be a ( 2 , 2 ) -curve in P 1 × P 1 . Then 𝐶 is

  • GIT stable for PGL 2 ( C ) × PGL 2 ( C ) -action if and only if it is smooth,

  • GIT strictly polystable if and only if it is one of the curves in Theorem 1.11.

Proof

Choose homogeneous coordinates x , y of degree ( 1 , 0 ) on P 1 × P 1 , and choose homogeneous coordinates u , v of degree ( 0 , 1 ) . Then 𝐶 is given by

i = 0 2 j = 0 2 a i j x 2 i y i u 2 j v j = 0 .

Observe that any one-parameter subgroup λ : C PSL 2 ( C ) × PSL 2 ( C ) is conjugate to a diagonal one of the form

t ( ( t r 0 0 0 t r 0 ) , ( t r 1 0 0 t r 1 ) )

for some integers r 1 r 0 0 and r 1 > 0 , which we will write as λ = ( r 0 , r 0 , r 1 , r 1 ) . Then the Hilbert–Mumford function is

μ ( f , λ ) = max { r 0 ( 2 2 i ) + r 1 ( 2 2 j ) , a i j 0 } .

Clearly, if μ ( f , λ ) 0 , then a 00 = a 10 = a 01 = 0 . Moreover, if this inequality is strict, then we additionally have a 11 = 0 . Furthermore, we have μ ( x 2 v 2 , λ ) = μ ( y 2 u 2 , λ ) . So at least one of a 20 and a 02 is zero. Without loss of generality, we assume that a 20 = 0 . Therefore, if μ ( f , λ ) < 0 , then a 00 = a 10 = a 01 = a 11 = a 20 = 0 .

Suppose that 𝐶 is singular at the point ( [ 1 : 0 ] , [ 1 : 0 ] ) , so that a 00 = a 10 = a 01 = 0 , and consider the one-parameter subgroup λ = ( 1 , 1 , 1 , 1 ) . Then μ ( f , λ ) = 4 2 ( i + j ) , which is non-positive if and only if i + j 2 . But, since a i j = 0 whenever i + j < 2 , we conclude that μ ( f , λ ) 0 and 𝐶 is not stable.

Conversely, suppose there exists a one-parameter subgroup 𝜆 for which μ ( f , λ ) 0 . Note that μ ( x 2 i y i u 2 j v j , λ ) > 0 for any one-parameter subgroup 𝜆 provided that i + j < 2 . This gives a 00 = a 10 = a 01 = 0 , so that the curve 𝐶 is singular at ( [ 1 : 0 ] , [ 1 : 0 ] ) .

Now, let us describe the unstable locus. Suppose a 00 = a 10 = a 01 = a 11 = a 20 = 0 . Consider the one-parameter subgroup λ = ( 1 , 1 , 2 , 2 ) . Then

μ ( f , λ ) = 6 2 ( i + 2 j ) ,

which is negative if and only if i + 2 j > 3 . But since a i j = 0 whenever i + 2 j 3 , it follows that μ ( f , λ ) < 0 . Similarly, one can show that 𝐶 is GIT-unstable if it can be given by

a 02 x 2 v 2 + a 12 x y v 2 + a 21 y 2 u v + a 22 y 2 v 2 = 0 .

This describes all possibilities for the curve 𝐶 to be GIT-semistable, which easily implies the description of GIT-polystable ( 2 , 2 ) -curves. ∎

Now, we set V = P 1 × P 1 . Let L = O V ( 1 , 1 ) , let 𝑅 be a curve in | 2 L | , set

Y = P ( O V O V ( L ) ) ,

let π : Y V be the natural projection, let S and S + be disjoint sections of 𝜋 such that

S + S + π ( L ) .

Finally, we set F = π ( R ) , and let ϕ : X Y be the blow up at the intersection S + F . If 𝑅 is smooth, then 𝑋 is K-polystable [7]. Theorem 1.11 says that 𝑋 is also K-polystable in the case when 𝑅 is one of the following singular curves:

  1. C 1 + C 2 , where C 1 and C 2 are smooth curves in | L | such that | C 1 C 2 | = 2 ;

  2. 1 + 2 + 3 + 4 , where 1 and 2 are two distinct smooth curves of degree ( 1 , 0 ) , and 3 and 4 are two distinct smooth curves of degree ( 0 , 1 ) ;

  3. 2 C , where 𝐶 is a smooth curve in | L | .

Now, let us prove Theorem 1.11. We start with the following remark.

Remark 4.2

Suppose that R = 1 + 2 + 3 + 4 , where 1 and 2 are two distinct smooth curves in 𝑉 of degree ( 1 , 0 ) , and 3 and 4 are two distinct smooth curves of degree ( 0 , 1 ) . Then 𝑋 is toric, and it corresponds to the moment polytope in M R whose vertices are

( 0 , 0 , 1 ) , ( 1 , 0 , 1 ) , ( 1 , 1 , 1 ) , ( 0 , 1 , 1 ) , ( 1 , 1 , 0 ) , ( 1 , 1 , 0 ) , ( 1 , 1 , 0 ) , ( 1 , 1 , 0 ) , ( 0 , 0 , 1 ) , ( 1 , 0 , 1 ) , ( 1 , 1 , 1 ) , ( 0 , 1 , 1 ) .

The barycenter of the moment polytope is the origin, so 𝑋 is K-polystable. See also [24].

Our next step is the following simple lemma.

Lemma 4.3

Suppose R = 2 C for a smooth curve C | L | . Then 𝑋 is K-polystable.

Proof

Here, the morphism 𝜙 is a weighted blow up at the intersection π ( C ) S + , and 𝑋 has non-isolated singularities along a smooth curve, which we will denote by C ̄ . The threefold 𝑋 can be obtained in a slightly different way. Let us describe it.

Set W = V × P 1 , let ϖ : W V be the natural projection, let S ̃ and S ̃ + be its disjoint sections, and let E ̃ = ϖ ( C ) . Then there exists commutative diagram

such that

  • 𝛼 is the blow up along the intersection curves E ̃ S ̃ and E ̃ S ̃ + ,

  • 𝜓 contracts the proper transform of the surface E ̃ to the curve C ̄ ,

  • ϕ ψ maps the proper transforms of the surfaces S ̃ and S ̃ + to the surfaces S and S + , respectively.

Let E ̂ be the proper transform on the threefold 𝑈 of the surface E ̃ . We may assume that the curve 𝐶 is the diagonal curve in V = P 1 × P 1 . Using this, we see that

Aut ( X ) Aut ( U ) Aut ( W , E ̃ + S ̃ + S ̃ + ) PGL 2 ( C ) × ( G m μ 2 ) × μ 2 .

Indeed, we have that Aut ( X ) lifts to 𝑈 since 𝜓 is a blow up along the singular locus. In particular, 𝜓 is Aut ( U ) -equivariant. On the other hand, 𝛼 is Aut ( U ) -equivariant as well. By construction, Aut ( X ) Aut ( W , E ̃ + S ̃ + S ̃ + ) is an isomorphism. Finally, 𝑊 is a product and the last isomorphism follows.

Observe that E ̂ is the only Aut ( X ) -invariant prime divisor over 𝑋. Thus, using [49], we conclude that the threefold 𝑋 is K-polystable if β ( E ̂ ) > 0 . Let us compute β ( E ̂ ) .

We let F and F + be 𝛼-exceptional surfaces such that α ( F ) S ̃ and α ( F + ) S ̃ + , let S ̂ and S ̂ + be the proper transforms on 𝑈 of the surfaces S and S + , respectively. Further, set H 1 = ( pr 1 α ) ( O P 1 ( 1 ) ) , H 2 = ( pr 2 α ) ( O P 1 ( 1 ) ) , H 3 = ( pr 3 α ) ( O P 1 ( 1 ) ) , where pr 1 , pr 2 , pr 3 are projections W P 1 such that pr 1 and pr 2 factors through 𝜛. Then

ψ ( K X ) K U 2 ( H 1 + H 2 + H 3 ) F F + 2 E ̂ + S ̂ + S ̂ + + 2 ( F + F + ) .

Now, we take u R 0 . Then the divisor ψ ( K X ) u E ̂ is ℝ-rationally equivalent to

( 2 u ) ( H 1 + H 2 ) + 2 H 3 + ( u 1 ) ( F + F + ) R ( 2 u ) E ̂ + S ̂ + S ̂ + + 2 ( F + F + ) ,

and S ̂ + S ̂ + + 2 ( F + F + ) is not big, so ψ ( K X ) u E ̂ is pseudo-effective if and only if u 2 . Moreover, if u [ 0 , 1 ] , then the divisor ψ ( K X ) u E ̂ is nef. Furthermore, if u [ 1 , 2 ] , then the Zariski decomposition of the divisor ψ ( K X ) u E ̂ is given by

ψ ( K X ) u E ̂ R ( 2 u ) ( H 1 + H 2 ) + 2 H 3 positive part + ( u 1 ) ( F + F + ) negative part .

Hence, we have

β ( E ̂ ) = 1 1 ( K X ) 3 0 2 vol ( ψ ( K X ) u E ̂ ) d u = 1 1 28 0 1 ( ( 2 u ) ( H 1 + H 2 ) + 2 H 3 + ( u 1 ) ( F + F + ) ) 3 d u 1 28 1 2 ( ( 2 u ) ( H 1 + H 2 ) + 2 H 3 ) 3 d u = 1 0 1 8 u 3 24 u 2 + 28 d u 1 2 12 ( 2 u ) 2 d u = 1 14 > 0 ,

which implies that 𝑋 is K-polystable. ∎

To complete the proof of Theorem 1.11, let us present 𝑋 as a codimension two complete intersection in a toric variety. Let T = ( C 7 Z ( I ) ) / G m 2 , where the G m 2 -action is given by

( x y z w u v s 1 1 1 1 1 0 2 0 0 0 0 1 1 0 ) ,

and 𝐼 is the irrelevant ideal x , y , z , w , s u , v . Let P ̃ = Proj ( O P 3 O P 3 ( 1 ) ) . Then we can identify P ̃ with the hypersurface in 𝑇 given by s = f ( x , y , z , w ) , where f ( x , y , z , w ) is any non-zero homogeneous polynomial of degree 2. Since 𝑌 can be obtained by blowing up the quadric cone over the surface { x y = z w } P 3 at the vertex, we can identify 𝑌 with the complete intersection in 𝑇 given by

{ x y = z w , s = f ( x , y , z , w ) .

Then the projection π : T V is given by ( x , y , z , w , u , v , s ) ( x , y , z , w ) , where we identify 𝑉 with { x y = z w } P 3 . Then the surface S is cut out on 𝑌 by v = 0 . Moreover, we can assume that S + is cut out on 𝑌 by u = 0 , and we can identify 𝑅 with the curve in S + that is cut out by s = 0 .

Let φ : T ̄ T be the blow up of 𝑇 along u = s = 0 . Then T ̄ = ( C 8 Z ( I ̄ ) ) / G m 3 , where the torus action is given by the matrix

( x y z w u v s t 1 1 1 1 1 0 2 0 0 0 0 0 1 1 0 0 0 0 0 0 1 0 1 1 )

and the irrelevant ideal

I ̄ = x , y , z , w , s x , y , z , w , t u , v u , s v , t .

Then 𝜑 induces the blow up of 𝑌 along 𝑅. Thus, we can identify 𝑋 with the complete intersection in the toric variety T ̄ given by

{ x y = z w , s t = f ( x , y , z , w ) .

Now, the subgroup Γ G m of the group Aut ( X ) mentioned in Section 1 can be explicitly seen – it consists of all automorphisms ( x , y , z , w , u , v , s , t ) ( x , y , z , w , λ u , v , s , t ) , where λ C . Similarly, we can choose the involution ι Aut ( X ) to be the involution

( x , y , z , w , u , v , s , t ) ( x , y , z , w , v , u , t , s ) .

Note that 𝜄 is not canonically defined, since we can conjugate it with an element in Γ.

Suppose that R = C 1 + C 2 , where C 1 and C 2 are smooth curves in | L | that meet transversally at two points. Then, up to a change of coordinates, we may assume that

f ( x , y , z , t ) = x y λ ( z 2 + w 2 ) ,

where λ C such that λ { 0 , 2 , 2 } . Then 𝑋 is the complete intersection in T ̄ given by

{ x y = z w , s t = x y λ ( z 2 + w 2 ) .

We can see from the equation f = 0 of R = C 1 + C 2 that the group Aut ( V , C 1 + C 2 ) contains G m μ 2 2 , where the two involutions swap coordinates x , y or z , w , and the G m is defined by

( x , y , z , w ) ( μ x , y μ , z , w ) .

It follows that Aut ( X ) contains automorphisms

( x , y , z , w , u , v , s , t ) ( μ x , y μ , z , w , u , v , s , t ) ,

where μ C . Similarly, the group Aut ( X ) contains two involutions

( x , y , z , w , u , v , s , t ) ( y , x , z , w , u , v , s , t ) , ( x , y , z , w , u , v , s , t ) ( x , y , w , z , u , v , s , t ) .

Let 𝐺 be the subgroup in Aut ( X ) that is generated by all automorphisms described above. Then G G m 2 μ 2 3 , and we have the following result.

Lemma 4.4

The following assertions hold:

  1. 𝑋 does not contain 𝐺-fixed points,

  2. 𝑋 does not contain 𝐺-invariant irreducible curves,

  3. 𝑋 contains two 𝐺-invariant irreducible surfaces – they are cut out by z ± w = 0 .

Proof

Left to the reader. ∎

Now, we can complete the proof of Theorem 1.11. Suppose that 𝑋 is not K-polystable. Using [49], we see that there is a 𝐺-invariant prime divisor 𝐅 over 𝑋 such that β ( F ) 0 . Let 𝑍 be the center of this divisor on 𝑋. By Lemma 4.4, 𝑍 is a surface and Z ( π ϕ ) ( L ) . Then, as in [21], we compute β ( F ) = β ( Z ) > 0 . This shows that 𝑋 is K-polystable.

5 Proof of Theorem 1.12

In this section, we prove Theorem 1.12. This result describes all singular K-polystable limits of smooth Fano 3-folds in the family № 3.9. To show this, we need the following theorem.

Theorem 5.1

Theorem 5.1 ([26, Theorem 2], [34, Example 7.13], [3])

Let 𝐶 be a quartic curve in P 2 . Then the curve 𝐶 is

  • GIT stable for PGL 3 ( C ) -action if and only if it is smooth or has A 1 or A 2 -singularities,

  • GIT strictly polystable if and only if it is one of the remaining curves in Theorem 1.12.

Let us prove Theorem 1.12. Set V = P 2 , L = O P 2 ( 2 ) and Y = P ( O V O V ( L ) ) . Let π : Y V be the natural projection, set H = π ( L ) , let S and S + be disjoint sections of 𝜋 such that S + S + H , and let 𝑅 be one of the following curves:

  1. a reduced quartic curve with at most A 1 or A 2 singularities;

  2. C 1 + C 2 , where C 1 and C 2 are smooth conics that are tangent at two points;

  3. C + 1 + 2 , where 𝐶 is a smooth conic, 1 and 2 are distinct lines tangent to 𝐶;

  4. 2 C , where 𝐶 is a smooth conic in | L | .

Set F = π ( R ) , and let ϕ : X Y be the blow up at the complete intersection S + F . Then 𝑋 is a singular Fano threefold, and our Theorem 1.12 claims that 𝑋 is K-polystable. To prove this, we start with the most singular (and the most symmetric case).

Lemma 5.2

Suppose that R = 2 C for a smooth conic C P 2 . Then 𝑋 is K-polystable.

Proof

In this case, the threefold 𝑋 has non-isolated singularities along a smooth curve, and the proof is very similar to the proof of Lemma 4.3. Namely, we have

(5.1) Aut ( X ) PGL 2 ( C ) × ( G m μ 2 ) ,

and there exists exactly one Aut ( X ) -invariant prime divisor over 𝑋, the exceptional divisor of the blow up of 𝑋 along the curve Sing ( X ) . So, to check that 𝑋 is K-polystable, it is enough to compute the 𝛽-invariant of this prime divisor. Let us give details.

As in the proof of Lemma 4.3, we set W = V × P 1 . Let ϖ : W V be the natural projection, let S ̃ and S ̃ + be its disjoint sections, and let E ̃ = ϖ ( C ) . Then there exists the commutative diagram

(5.2)

such that

  • 𝛼 is a blow up along the curves E ̃ S ̃ and E ̃ S ̃ + ,

  • 𝜓 is a contraction of the proper transform of E ̃ to the curve Sing ( X ) ,

  • ϕ ψ maps the proper transforms of S ̃ and S ̃ + to S and S + , respectively.

This easily implies (5.1). Similarly, we see that (5.2) is Aut ( X ) -equivariant.

Let E ̂ be the 𝜓-exceptional divisor. Then E ̂ is the only Aut ( X ) -invariant prime divisor over the threefold 𝑋. Thus, if β ( E ̂ ) > 0 , them 𝑋 is K-polystable [49].

We let F and F + be 𝛼-exceptional surfaces such that α ( F ) S ̃ and α ( F + ) S ̃ + , let S ̂ and S ̂ + be the proper transforms on 𝑈 of the surfaces S and S + , respectively. Set H 1 = ( pr 1 α ) ( O P 1 ( 1 ) ) for the projection pr 1 : W P 1 , set H 2 = ( ϖ α ) ( O V ( 1 ) ) . Then E ̂ 2 H 2 F F + , which gives

ψ ( K X ) K U 2 H 1 + 3 H 2 F F + Q 2 H 1 + 3 2 E ̂ + 1 2 ( F + F + ) .

Take u R 0 . Then

ψ ( K X ) u E ̂ R 2 H 1 + ( 3 2 u ) H 2 + ( u 1 ) ( F + F + ) R 2 H 1 + 3 2 u 2 E ̂ + 1 2 ( F + F + ) .

This shows that ψ ( K X ) u E ̂ is pseudo-effective if and only if u 3 2 . Moreover, if we have u [ 0 , 1 ] , then the divisor ψ ( K X ) u E ̂ is nef. If 1 < u 3 2 , its Zariski decomposition is

ψ ( K X ) u E ̂ R 2 H 1 + ( 3 2 u ) H 2 positive part + ( u 1 ) ( F + F + ) negative part .

Hence, we have

β ( E ̂ ) = 1 1 ( K X ) 3 0 3 2 vol ( ψ ( K X ) u E ̂ ) d u = 1 1 26 0 1 ( 2 H 1 + ( 3 2 u ) H 2 + ( u 1 ) ( F + F + ) ) 3 d u 1 26 1 3 2 ( 2 H 1 + ( 3 2 u ) H 2 ) 3 d u = 1 1 26 0 1 16 u 3 36 u 2 + 26 d u 1 26 1 3 2 24 u 2 72 u + 54 d u = 7 26 > 0 ,

which implies that 𝑋 is K-polystable. ∎

Similarly, we can show that 𝑋 is K-polystable if R = C 1 + C 2 , where C 1 and C 2 are smooth conics that are tangent at two points. Indeed, in this case, the full automorphism group Aut ( X ) contains a subgroup 𝐺 such that G ( G m ) 2 μ 2 2 , the threefold 𝑋 does not contains 𝐺-fixed points, and the only 𝐺-invariant irreducible curve in 𝑋 is a smooth fiber of the conic bundle π ϕ . Therefore, arguing exactly as in the proofs of [7, Lemma 4.64] and [7, Lemma 4.66], we see that 𝑋 is K-polystable.

However, this approach fails in the case when 𝑅 has a singular point of type A 1 or A 2 , since, in general, 𝑋 would not have as many symmetries. To overcome this difficulty, we will use another approach described in the end of Section 1. Namely, we proved in Section 2 that Aut ( X ) contains an involution 𝜄 such that 𝜄 swaps the proper transforms of S and S + , X / ι Y , and the following diagram commutes:

where 𝜌 is the quotient map. Moreover, we also proved that the double cover 𝜌 is ramified over a divisor B | 2 S + | such that the morphism B V induced by 𝜋 is a double cover ramified in the curve 𝑅. Set Δ = 1 2 B . Then K X Q ρ ( K Y + Δ ) , and ( Y , Δ ) has Kawamata log terminal singularities. Therefore, ( Y , Δ ) is a log Fano pair. Moreover, it follows from [31] that

X is K-polystable ( Y , 1 2 B ) is K-polystable .

However, everything in life comes with a price: the action of the group Γ G m described earlier in Section 1 does not descent to 𝑌 via 𝜌, because Γ does not commute with 𝜄. Thus, the group Aut ( Y , Δ ) is much smaller than the group Aut ( X ) .

To explicitly describe B Y , consider 𝑌 as the toric variety ( C 5 Z ( I ) ) / G m 2 such that the torus action is given by the matrix

( x 1 x 2 x 3 x 4 x 5 1 1 1 2 0 0 0 0 1 1 ) ,

with irrelevant ideal I = x 1 , x 2 , x 3 x 4 , x 5 . Let us also consider x 1 , x 2 , x 3 as coordinates on V = P 2 , so that the projection 𝜋 is given by ( x 1 , x 2 , x 3 , x 4 , x 5 ) ( x 1 , x 2 , x 3 ) . Then S = { x 5 = 0 } . Moreover, we may assume that S + = { x 4 = 0 } , and 𝐵 is given by

x 4 2 f 4 ( x 1 , x 2 , x 3 ) x 5 2 = 0 ,

where f 4 ( x 1 , x 2 , x 3 ) is a quartic polynomial such that R = { f 4 ( x 1 , x 2 , x 3 ) = 0 } .

In the remaining part of the section, we will prove that the pair ( Y , Δ ) is K-polystable. Recall that H = π ( L ) . Note also that

( K Y + Δ ) Q S + 3 2 H .

We will split the proof in several lemmas and propositions. We start with the following lemma.

Lemma 5.3

Let 𝑃 be a point in S . Then δ P ( Y , Δ ) > 1 .

Proof

Let us apply Lemma 3.2. We have

δ P ( Y , Δ ) = δ P ( Y ; D ( a ) ) min { 4 ( a 3 ( a 1 ) 3 ) ( 4 a ) a 3 + ( a 1 ) 4 , 4 ( a 3 ( a 1 ) 3 ) 3 ( a 4 ( a 1 ) 4 ) δ ( V ; L ) } ,

where D ( a ) = ( K Y + Δ ) and a = 3 2 . Thus, we have

δ P ( Y , Δ ) min { 26 17 , 13 15 δ ( V ; L ) } .

But

δ ( V ; L ) = δ ( V ; 2 3 ( K V ) ) = 3 2 δ ( V ; K V ) = 3 2 δ ( V ) = 3 2 δ ( P 2 ) = 3 2 ,

so that δ P ( Y , Δ ) 13 10 . ∎

Similarly, applying Proposition 3.5, we obtain the following lemma.

Lemma 5.4

Let 𝑃 be a point 𝑌 such that P Sing ( B ) . Then δ P ( Y , Δ ) > 1 .

Proof

By Lemma 5.3, we may assume that P S . Then Proposition 3.5 gives

δ P ( Y , Δ ) = δ P ( Y ; D ( a ) ) 8 ( 3 a 2 3 a + 1 ) 8 d μ a 3 + 6 ( 1 2 d μ ) a 2 + 8 ( d μ 1 ) a 2 d μ + 3 ,

where D ( a ) = ( K Y + Δ ) , a = 3 2 , d = L 2 = 4 , μ = 1 2 . This gives δ P ( Y , Δ ) 52 49 . ∎

The two most difficult parts of the proof that ( Y , Δ ) is K-polystable are the following two propositions, which will be proved in Sections 5.1 and 5.2 later.

Proposition 5.5

Let 𝑃 be a point in 𝐵 such that 𝐵 has singular point of type A 1 at 𝑃, and let 𝐅 be a prime divisor over 𝑌 such that P = C Y ( F ) . Then β Y , Δ ( F ) > 0 .

Proposition 5.6

Let 𝑃 be a point in 𝐵 such that 𝐵 has singular point of type A 2 at 𝑃, and let 𝐅 be a prime divisor over 𝑌 such that P = C Y ( F ) . Then β Y , Δ ( F ) > 0 .

By Lemmas 5.3 and 5.4 and Propositions 5.5 and 5.6, the log pair ( Y , Δ ) is K-stable in the case when 𝑅 is a reduced plane quartic curve that has at most A 1 or A 2 singularities. Therefore, to complete the proof, we may assume that 𝑅 is one of the following curves:

  1. C 1 + C 2 , where C 1 and C 2 are smooth conics that are tangent at two points;

  2. C + 1 + 2 , where 𝐶 is a smooth conic, 1 and 2 are distinct lines tangent to 𝐶;

  3. 2 C , where 𝐶 is a smooth conic in | L | .

Hence, appropriately changing coordinates x 1 , x 2 , x 3 , we may assume that

f 4 ( x 1 , x 2 , x 3 ) = ( x 1 x 2 x 3 2 ) ( x 1 x 2 λ x 3 2 ) ,

where one of the following three cases holds:

  1. λ { 0 , 1 } , R = C 1 + C 2 , where C 1 = { x 1 x 2 = x 3 2 } and C 2 = { x 1 x 2 = λ x 3 2 } ;

  2. λ = 0 , R = C + 1 + 2 , where C = { x 1 x 2 = x 3 2 } , 1 = { x 1 = 0 } and 2 = { x 2 = 0 } ;

  3. λ = 1 , R = 2 C , where C = { x 1 x 2 = x 3 2 } .

In each case, the group Aut ( Y , Δ ) contains an involution 𝜏 such that

τ ( x 1 , x 2 , x 3 , x 4 , x 5 ) = ( x 2 , x 1 , x 3 , x 4 , x 5 ) .

Lemma 5.7

Suppose that λ { 0 , 1 } . Then ( Y , Δ ) is K-polystable.

Proof

Suppose ( Y , Δ ) is not K-polystable. It follows from [49] that there is a τ -invariant prime divisor 𝐅 over 𝑌 such that β Y , Δ ( F ) 0 . Let 𝑃 be a general point in C Y ( F ) . Then δ P ( Y , Δ ) 1 . But P Sing ( B ) , since Sing ( B ) consists of two singular points that are swapped by 𝜏. Then δ P ( Y , Δ ) > 1 by Lemmas 5.3 and 5.4, which is a contradiction. ∎

Lemma 5.8

Suppose λ = 0 . Then ( Y , Δ ) is K-polystable.

Proof

The surface 𝐵 has a singular point of type A 1 , and two singular points of type A 3 , that are swapped by 𝜏. Arguing as in the proof of Lemma 5.7 and using Propositions 5.5, we see that 𝑋 is K-polystable. ∎

Lemma 5.9

Lemma 5.9 (cf. Lemma 5.2)

Suppose λ = 1 . Then ( Y , Δ ) is K-polystable.

Proof

In this case, we have R = 2 C , where 𝐶 is an irreducible conic. Then we have B = B 1 + B 2 , where B 1 and B 2 are smooth surfaces in | S + | that intersect transversally along a smooth curve such that π ( B 1 B 2 ) = C .

We already know from Lemma 5.2 that the threefold 𝑋 is K-polystable in this case, so that ( Y , Δ ) is also K-polystable [31]. Let us prove this directly for consistency.

Let W = V × P 1 , let ϖ : W V be the natural projection, let S ̃ , B ̃ 1 , B ̃ 2 be its disjoint sections, and let E ̃ = ϖ ( C ) . Then there exists the commutative diagram

such that 𝛼 is a blow up along the curve E ̃ S ̃ , the morphism 𝜓 is a contraction of the proper transform of the surface E ̃ to the intersection curve B 1 B 2 such that 𝜓 maps the proper transforms of the surfaces S ̃ , B ̃ 1 , B ̃ 2 to the surfaces S , B 1 , B 2 , respectively. Then

Aut ( Y , Δ ) Aut ( U ) Aut ( W , B ̃ 1 + B ̃ 2 + E ̃ + S ̃ ) PGL 2 ( C ) × μ 2 .

Note that the commutative diagram above is Aut ( Y , Δ ) -equivariant.

Let 𝐹 be 𝛼-exceptional surface, let E ̂ be the 𝜓-exceptional surface, let B ̂ 1 and B ̂ 2 be the proper transforms on 𝑈 of the surfaces B 1 and B 2 , respectively. Set Δ ̂ = 1 2 ( B ̂ 1 + B ̂ 2 ) . Then K U + Δ ̂ Q ψ ( K Y + Δ ) , so that 𝜓 is log crepant for ( U , Δ ̂ ) . Then A Y , Δ ( E ̂ ) = 1 .

First, we compute β Y , Δ ( E ̂ ) . Set H 1 = ( pr 1 α ) ( O P 1 ( 1 ) ) and H 2 = ( ϖ α ) ( O V ( 1 ) ) , where pr 1 is the natural projection W P 1 . Then Δ ̂ Q H 1 and E ̂ 2 H 2 F , so that

ψ ( K Y + Δ ) Q K U + Δ ̂ Q H 1 + 3 H 2 F Q H 1 + 3 2 E ̂ + 1 2 F .

Let 𝑢 be a non-negative real number. Then

ψ ( K Y + Δ ) u E ̂ R H 1 + ( 3 2 u ) H 2 + ( u 1 ) F R H 1 + 3 2 u 2 E ̂ + 1 2 F ,

and this divisor is pseudo-effective if and only if u 3 2 . For u [ 0 , 3 2 ] , let P ( u ) be the positive part of the Zariski decomposition of ψ ( K Y + Δ ) u E ̂ , and let N ( u ) be the negative part. Then

P ( u ) R { H 1 + ( 3 2 u ) H 2 + ( u 1 ) F if 0 u 1 , H 1 + ( 3 2 u ) H 2 if 1 u 3 2 ,

and

N ( u ) = { 0 if 0 u 1 , ( u 1 ) F if 1 u 3 2 .

This gives

β Y , Δ ( E ̂ ) = A Y , Δ ( E ̂ ) 1 ( K Y Δ ) 3 0 3 2 ( P ( u ) ) 3 d u = 1 1 13 0 1 ( 2 H 1 + ( 3 2 u ) H 2 + ( u 1 ) F ) 3 d u 1 13 1 3 2 ( 2 H 1 + ( 3 2 u ) H 2 ) 3 d u = 1 0 1 8 u 3 18 u 2 + 13 d u 1 3 2 12 u 2 36 u + 27 d u = 7 26 > 0 .

Suppose that ( Y , Δ ) is not K-polystable. By [49], there exists an Aut ( Y , Δ ) -invariant prime divisor 𝐅 over 𝑌 such that β Y , Δ ( F ) 0 . Let 𝑍 be its center on 𝑌. Then δ P ( Y , Δ ) 1 for every point P Z . Hence, it follows from Lemmas 5.3 and 5.4 that Z B 1 B 2 . Hence, since 𝑍 is a Aut ( Y , Δ ) -invariant irreducible subvariety, we see that Z = B 1 B 2 .

Let Z ̂ be the center of the divisor 𝐅 on the threefold 𝑈. Then Z ̂ E ̂ , since β ( E ̂ ) > 0 . Moreover, since Z ̂ E ̂ and Z ̂ is Aut ( U ) -invariant, we see that Z ̂ is a Aut ( U ) -invariant section of the natural projection E ̂ Z . Set A = K U + Δ ̂ . Then

0 β Y , Δ ( F ) = A Y , Δ ( F ) S A ( F ) = A U , Δ ̂ ( F ) S A ( F ) ,

because K U + Δ ̂ Q ψ ( K Y + Δ ) . Moreover, it follows from [2, 7, 22] that

1 A U , Δ ̂ ( F ) S A ( F ) min { 1 S A ( E ̂ ) , 1 S A ( W , E ̂ ; Z ̂ ) } ,

where S A ( W , E ̂ ; Z ̂ ) is defined in [7, Section 1.7]. But S A ( E ̂ ) = 19 26 , so S A ( W , E ̂ ; Z ̂ ) 1 .

Let us compute S A ( W , E ̂ ; Z ̂ ) . Using [7, Corollary 1.109], we see that

S A ( W , E ̂ ; Z ̂ ) = 3 A 3 0 3 2 ( P ( u ) | E ̂ ) 2 ord Z ̂ ( N ( u ) | E ̂ ) + 3 A 3 0 3 2 0 vol ( P ( u ) | E ̂ v Z ̂ ) d v d u ,

which is easy to compute, because E ̂ P 1 × P 1 . Let us do this.

Let s = F E ̂ . Then 𝐬 is a section of the projection E ̂ Z . Let 𝐟 be a fiber of this projection. Then

P ( u ) | E ̂ = { ( 6 4 u ) f + u s if 0 u 1 , ( 6 4 u ) f + s if 1 u 3 2 ,

and

N ( u ) | E ̂ = { 0 if 0 u 1 , ( u 1 ) s if 1 u 3 2 .

Thus, we see that S A ( W , E ̂ ; Z ̂ ) S A ( W , E ̂ ; s ) and

S A ( W , E ̂ ; s ) = 3 13 1 3 2 ( ( 6 4 u ) f + s ) 2 ( u 1 ) d u + 3 13 0 1 0 u ( ( 6 4 u ) f + ( u v ) s ) 2 d v d u + 3 13 1 3 2 0 1 ( ( 6 4 u ) f + ( 1 v ) s ) 2 d v d u = 3 13 1 3 2 2 ( 6 4 u ) ( u 1 ) d u + 3 13 0 1 0 u 2 ( 6 4 u ) ( u v ) d v d u + 3 13 1 3 2 0 1 2 ( 6 4 u ) ( 1 v ) d v d u = 5 13 < 1 ,

which is a contradiction. ∎

In the remaining part of this sections, we will prove Proposition 5.5 and 5.6.

5.1 Proof of Proposition 5.5

Let us use notation introduced earlier in this section before Proposition 5.5, and let 𝑃 be an isolated ordinary double point of the surface 𝐵. Then, up to a change of coordinates, we may assume that P = ( 0 , 0 , 1 , 0 , 1 ) and

f 4 ( x 1 , x 2 , 1 ) = x 1 2 + x 2 2 + higher order terms .

Let ρ : Y 0 Y be the blow up at 𝑃; note that 𝜌 is a log resolution of ( Y , B ) . Then Y 0 is the toric variety ( C 6 Z ( I 0 ) ) / G m 3 for the torus action given by

M = ( x 0 x 1 x 2 x 3 x 4 x 5 0 1 1 1 2 0 0 0 0 0 1 1 1 0 0 1 1 0 )

with irrelevant ideal

I 0 = x 1 , x 2 , x 3 x 1 , x 2 , x 4 x 4 , x 5 x 0 , x 3 x 0 , x 5 .

To describe its fan, denote the vector generating the ray corresponding to x i by v i . Then

v 0 = ( 1 , 1 , 1 ) , v 1 = ( 1 , 0 , 0 ) , v 2 = ( 0 , 1 , 0 ) , v 3 = ( 1 , 1 , 2 ) , v 4 = ( 0 , 0 , 1 ) , v 5 = ( 0 , 0 , 1 ) .

The cone structure can be derived from the irrelevant ideal I 0 , and it can be visualized via the following diagram:

Let F i = { x i = 0 } Y 0 , and let C i j = F i F j for i j such that dim ( F i F j ) = 1 . Geometrically, the divisors F i are as follows.

  • F 0 is the exceptional divisor of the blow up ρ : Y 0 Y .

  • Let D π C be a pullback of a line and suppose 𝐷 contains 𝑃; then strict transform ρ 1 D of 𝐷 on Y 0 is linearly equivalent to F 1 and F 2 .

  • And for pullback, we have ρ D F 3 .

  • Divisors F 4 and F 5 are the proper transforms of the positive and negative sections of 𝜋 on Y 0 , respectively.

Consider the Z 3 -grading of Pic ( Y 0 ) given by 𝑀. If D 1 and D 2 are two divisors in Pic ( Y 0 ) , then it follows from [15, Chapter 5] that

D 1 D 2 deg M ( D 1 ) = deg M ( D 2 ) .

Moreover, we have

Eff ( Y 0 ) ̄ = F 0 , F 1 , F 5 and NE ( Y 0 ) ̄ = C 12 , C 15 , C 01 .

In particular, a divisor 𝐷 with deg M ( D ) = ( a , b , c ) is effective if and only if all a , b , c 0 . Note that curve C 01 is a line in the exceptional divisor F 0 , C 12 is the proper transform of a fiber of 𝜋 passing through 𝑃, and C 15 is a pullback of the negative section of ρ ( F 1 ) F 2 .

Lemma 5.10

Intersections of divisors F 0 , F 1 , F 5 are given by the following table:

F 0 3 F 0 2 F 1 F 0 2 F 5 F 0 F 1 2 F 0 F 1 F 5 F 0 F 5 2 F 1 3 F 1 2 F 5 F 1 F 5 2 F 5 3
1 −1 0 1 0 0 −1 1 −2 4

Proof

Recall that, for distinct torus-invariant divisors F i , F j , F k , we may compute their intersection using the fan and the cone structure (or the irrelevant ideal)

F i F j F k = { 0 , x i x j x k I 0 , 1 | det { v i , v j , v k } | otherwise .

This fact together with the linear equivalences implies the required assertion. ∎

Using Lemma 5.10, we obtain the following intersection table:

F 0 F 1 F 5
C 12 1 −1 1
C 15 0 1 −2
C 01 −1 1 0

Now, we set A = ( K Y + Δ ) . Take u R 0 . Set

L ( u ) = ρ ( A ) u F 0 .

Then L ( u ) R ( 3 u ) F 0 + 3 F 1 + F 5 . So the divisor L ( u ) is pseudo-effective if and only if u 3 . Let us find a Zariski decomposition of the divisor L ( u ) for u [ 0 , 3 ] .

The divisor L ( u ) is nef for u [ 0 , 1 ] . We have L ( 1 ) C 12 = 0 . Since C 12 is a flopping curve, we have to consider a small ℚ-factorial modification Y 0 Y 1 such that

Y 1 = ( C 6 Z ( I 1 ) ) / G m 3 ,

where the torus action is the same (given by the matrix 𝑀) and the irrelevant ideal

I 1 = x 1 , x 2 x 4 , x 5 x 0 , x 3 ,

which is obtained from I 0 by replacing x 0 , x 5 with x 1 , x 2 . The fan of Y 1 is generated by the same vectors, but the cone structure is different:

Abusing our previous notation, we denote the divisor { x i = 0 } Y 1 also by F i , and we let C i j = F i F j for i j such that F i F j is a curve. As above, we see that

NE ( Y 1 ) ̄ = C 01 , C 15 , C 05 .

Moreover, intersections of divisors on Y 1 are described in the following table:

F 0 3 F 0 2 F 1 F 0 2 F 5 F 0 F 1 2 F 0 F 1 F 5 F 0 F 5 2 F 1 3 F 1 2 F 5 F 1 F 5 2 F 5 3
0 0 −1 0 1 −1 0 0 −1 3

Using these intersections, we obtain the following intersection table:

F 0 F 1 F 5
C 05 −1 1 −1
C 15 1 0 −1
C 01 0 0 1

The proper transform on Y 1 of the divisor L ( u ) is nef for u [ 1 , 2 ] , and it intersects the curve C 15 trivially for u = 2 . Note that C 15 C 25 on the surface F 5 , which implies that the divisor F 5 is contained in the negative part of the Zariski decomposition of the proper transform of the divisor L ( u ) . In fact, we have N ( u ) = ( u 2 ) F 5 and

P ( u ) = ( 3 u ) ( F 0 + F 5 ) + 3 F 1 ,

where N ( u ) is the negative part of the decomposition, and P ( u ) is the positive part.

Lemma 5.11

One has A Y , Δ ( F 0 ) = 2 and S A ( F 0 ) = 49 26 , so that

A Y , Δ ( F 0 ) S A ( F 0 ) = 52 49 .

Proof

The equality A Y , Δ ( F 0 ) = 2 is obvious. Moreover, we have

vol ( L ( u ) ) = { u 3 + 13 , u [ 0 , 1 ] , 3 u 2 + 3 u + 12 , u [ 1 , 2 ] , 3 u 3 18 u 2 + 27 u , u [ 2 , 3 ] .

Thus, we compute

S A ( F 0 ) = 1 A 3 0 3 vol ( L ( u ) ) d u = 49 26 ,

as claimed. ∎

Now, we construct a common toric resolution Y ̃ for Y 0 and Y 1 . Such variety is easy to see from the fans of Y 0 and Y 1 ; we want to add the following ray:

v 6 = ( 1 , 1 , 0 ) v 1 , v 2 v 0 , v 5 .

Set Y ̃ to be the toric variety corresponding to v 0 , , v 6 with the following cone structure:

Let φ 0 : Y ̃ Y 0 and φ 1 : Y ̃ Y 1 be the corresponding toric birational maps. Then

  • φ 0 is the blow up of Y 0 along the curve C 12 ,

  • φ 1 is the blow up of Y 1 along the curve C 05 .

Set F ̃ i = { x i = 0 } Y ̃ . Then F ̃ 6 is the exceptional divisor of φ 0 and φ 1 .

The Zariski decomposition of the divisor φ 0 ( L ( u ) ) can be described as follows:

P ̃ ( u ) R { ( 3 u ) F ̃ 0 + 3 F ̃ 1 + F ̃ 5 + 3 F ̃ 6 , u [ 0 , 1 ] , ( 3 u ) F ̃ 0 + 3 F ̃ 1 + F ̃ 5 + ( 4 u ) F ̃ 6 , u [ 1 , 2 ] , ( 3 u ) ( F ̃ 0 + F ̃ 5 ) + 3 F ̃ 1 + ( 6 2 u ) F ̃ 6 , u [ 2 , 3 ] ,

and

N ̃ ( u ) = { 0 , u [ 0 , 1 ] , ( u 1 ) F ̃ 6 , u [ 1 , 2 ] , ( u 2 ) F ̃ 5 + ( 2 u 3 ) F ̃ 6 , u [ 2 , 3 ] ,

where P ̃ ( u ) is the positive part, and N ̃ ( u ) is the negative part.

Let σ : F ̃ 0 F 0 be the morphism induced by φ 0 . Recall that F 0 is the exceptional divisor of the blow up 𝜌 at a smooth point 𝑃. Then, since 𝜎 is a blow up at one point, we have F ̃ 0 F 1 . Let 𝐞 be the 𝜎-exceptional curve, and let 𝐟 be a fiber of the natural projection F ̃ 0 P 1 . Then F ̃ 0 | F ̃ 0 e f , F ̃ 1 | F ̃ 0 f , F ̃ 5 | F ̃ 0 0 , F ̃ 6 | F ̃ 0 = e , which gives

P ̃ ( u ) | F ̃ 0 = { u ( f + e ) , u [ 0 , 1 ] , u f + e , u [ 1 , 2 ] , u f + ( 3 u ) e , u [ 2 , 3 ] ,

and

N ̃ ( u ) | F ̃ 0 = { 0 , u [ 0 , 1 ] , ( u 1 ) e , u [ 1 , 2 ] , ( 2 u 3 ) e , u [ 2 , 3 ] .

We are ready to apply [2, 7, 22]. Set B F 0 = ρ 1 ( B ) | F 0 ; since 𝐵 has a node at 𝑃, we see that B F 0 is a conic. We set Δ F 0 = 1 2 B F 0 and we set

δ ( F 0 , Δ F 0 ; V , F ̃ 0 ) = inf E / F ̃ 0 A F 0 , Δ F 0 ( E ) S ( W , F ̃ 0 ; E ) ,

where the infimum is taken over all prime divisors 𝐸 over F ̃ 0 , and

S ( W , F ̃ 0 ; E ) = 3 A 3 0 3 ( P ̃ ( u ) | F ̃ 0 ) 2 ord E ( N ̃ ( u ) | F ̃ 0 ) d u + 3 A 3 0 3 0 vol ( P ̃ ( u ) | F ̃ 0 v E ) d v d u .

Let 𝐅 be a prime divisor over 𝑌 such that P = C Y ( F ) . Recall that

β Y , Δ ( F ) = A Y , Δ ( F ) S A ( F ) = A Y , Δ ( F ) 1 A 3 0 vol ( A u F ) d u .

It follows from [22, Theorem 4.8] and [22, Corollary 4.9] that

(5.3) A Y , Δ ( F ) S A ( F ) δ P ( Y , Δ ) min { A Y , Δ ( F 0 ) S A ( F 0 ) , δ ( F 0 , Δ F 0 ; V , F ̃ 0 ) } .

Suppose β Y , Δ ( F ) 0 . Then it follows from (5.3) and Lemma 5.11 that there is a prime divisor 𝐸 over F ̃ 0 such that

(5.4) S ( W , F ̃ 0 ; E ) A F 0 , Δ F 0 ( E ) .

Let 𝑍 be the center of the divisor 𝐸 on the surface F ̃ 0 . Note that σ ( e ) B F 0 .

Lemma 5.12

One has Z e = .

Proof

Note that A F 0 , Δ F 0 ( e ) = 2 . Let us compute S ( W , F ̃ 0 ; e ) . For u [ 0 , 3 ] , let

t ( u ) = sup { v R 0 P ̃ ( u ) | F ̃ 0 v e is pseudo-effective } .

For every v [ 0 , t ( u ) ] , let us denote by P ( u , v ) and N ( u , v ) the positive and the negative parts of the Zariski decompositions of the divisor P ̃ ( u ) | F ̃ 0 v e , respectively. Then

S ( W , F ̃ 0 ; e ) = 3 A 3 0 3 ( P ( u , 0 ) ) 2 ord e ( N ̃ ( u ) | F ̃ 0 ) d u + 3 A 3 0 3 0 t ( u ) ( P ( u , v ) ) 2 d v d u .

Observe that

ord e ( N ̃ ( u ) | F ̃ 0 ) = { 0 , u [ 0 , 1 ] , u 1 , u [ 1 , 2 ] , 2 u 3 , u [ 2 , 3 ] .

Moreover, we have

t ( u ) = { u , u [ 0 , 1 ] , 1 , u [ 1 , 2 ] , 3 u , u [ 2 , 3 ] .

Furthermore, we have N ( u , v ) = 0 for every u [ 0 , 3 ] and v [ 0 , t ( u ) ] . Finally, we have

P ( u , v ) = { u f + ( u v ) e , u [ 0 , 1 ] , v [ 0 , u ] , u f + ( 1 v ) e , u [ 1 , 2 ] , v [ 0 , 1 ] , u f + ( 3 u v ) e , u [ 2 , 3 ] , v [ 0 , 3 u ] ,

which gives

( P ( u , v ) ) 2 = { u 2 v 2 , u [ 0 , 1 ] , v [ 0 , u ] , u 2 ( 1 v u ) 2 , u [ 1 , 2 ] , v [ 0 , 1 ] , u 2 ( 3 2 u v ) 2 , u [ 2 , 3 ] , v [ 0 , 3 u ] .

Integrating, we get S ( W , F ̃ 0 ; e ) = 20 13 < 2 = A F 0 , Δ F 0 ( e ) , so that Z e by (5.4).

Suppose that Z e . Let 𝑂 be a point of the intersection Z e . Then it follows from [22, Theorem 4.17] and [22, Corollary 4.18] that

A F 0 , Δ F 0 ( E ) S ( W , F ̃ 0 ; E ) min { 2 S ( W , F ̃ 0 ; e ) , 1 S ( W , , , F ̃ 0 , e ; O ) } = min { 13 10 , 1 S ( W , , F ̃ 0 , e ; O ) } ,

where

S ( W , , F ̃ 0 , e ; O ) = 3 A 3 0 3 0 t ( u ) ( P ( u , v ) e ) 2 d v d u .

Integrating, we get S ( W , , F ̃ 0 , e ; O ) = 20 13 , which contradicts (5.4). ∎

Thus, we see that 𝑍 is disjoint from 𝐞. In particular, we see that

Z Supp ( N ̃ ( u ) | F ̃ 0 ) =

for every u [ 0 , 3 ] . This will simplify some formulas in the following.

Let B F ̃ 0 be the strict transform on F ̃ 0 of the curve B F 0 . Then B F ̃ 0 is a smooth irreducible curve in | 2 ( e + f ) | . Set Δ F ̃ 0 = 1 2 B F ̃ 0 . Let 𝑂 be a point in 𝑍. We may assume that O f . Then there are three cases to consider:

  1. O B F ̃ 0 ,

  2. O B F ̃ 0 f , and 𝐟 intersects B F ̃ 0 transversely at the point 𝑂,

  3. O = B F ̃ 0 f , and 𝐟 is tangent to B F ̃ 0 at the point 𝑂.

Let θ : F ̂ 0 F ̃ 0 be a plt blow up of the point 𝑂 defined as follows:
  • the map 𝜃 is an ordinary blow up in the case when O B F ̃ 0 , or when O B F ̃ 0 f , and the fiber 𝐟 intersects the curve B F ̃ 0 transversely at the point 𝑂,

  • the map 𝜃 is a weighted blow up at the point O = B F ̃ 0 f with weights ( 1 , 2 ) such that the proper transforms on F ̂ 0 of the curves B F ̃ 0 and 𝐟 are disjoint in the case when the fiber 𝐟 is tangent to the curve B F ̃ 0 at the point 𝑂.

Let 𝐶 be the 𝜃-exceptional curve. We have C P 1 . Let B F ̂ 0 be the proper transform on the surface F ̂ 0 of the curve B F ̂ 0 . Set Δ F ̂ 0 = 1 2 B F ̂ 0 . Let Δ C be the effective ℚ-divisor on the curve 𝐶 known as the different, which can be defined via the adjunction formula

K C + Δ C = ( K F ̂ 0 + Δ F ̂ 0 ) | C .

If 𝜃 is a usual blow up, then Δ C = Δ F ̂ 0 | C . Similarly, if 𝜃 is a weighted blow up, then

Δ C = Δ F ̂ 0 | C + 1 2 o ,

where 𝐨 is the singular point of the surface F ̂ 0 contained in 𝐶 (𝐨 is an ordinary double point, which is not contained in the proper transforms of the curves B F ̃ 0 and 𝐟).

Now, for u [ 0 , 3 ] , we let

t ̂ ( u ) = sup { v R 0 θ ( P ̃ ( u ) | F ̃ 0 ) v C is pseudo-effective } .

For every v [ 0 , t ̂ ( u ) ] , let us denote by P ̂ ( u , v ) and N ̂ ( u , v ) the positive and the negative parts of the Zariski decompositions of the divisor θ ( P ̃ ( u ) | F ̃ 0 ) v C , respectively. Then

(5.5) 1 A F 0 , Δ F 0 ( E ) S ( W , F ̃ 0 ; E ) min { A F 0 , Δ F 0 ( C ) S ( W , F ̃ 0 ; C ) , inf Q C A C , Δ C ( Q ) S ( W , , F ̂ 0 , C ; Q ) }

by (5.4) and [22, Corollary 4.18], where the infimum is taken by all points Q C , and

S ( W , , , F ̂ 0 , C ; Q ) = 3 A 3 0 3 0 t ̂ ( u ) ( P ̂ ( u , v ) C ) 2 d v d u + F Q ( W , , F ̂ 0 , C )

for

F Q ( W , , F ̂ 0 , C ) = 6 A 3 0 3 0 t ̂ ( u ) ( P ̂ ( u , v ) C ) ord Q ( N ̂ ( u , v ) | C ) d v d u .

Denote by e ̂ and f ̂ the proper transforms of the curves 𝐞 and 𝐟, respectively.

Lemma 5.13

Suppose that 𝜃 is an ordinary blow up. Let 𝑄 be a point in 𝐶. Then

A F 0 , Δ F 0 ( C ) S ( W , F ̃ 0 ; C ) 39 29 and A C , Δ C ( Q ) S ( W , , F ̂ 0 , C ; Q ) 13 10 .

Proof

One has

θ ( P ̃ ( u ) | F ̃ 0 ) R { u ( f ̂ + e ̂ + C ) , u [ 0 , 1 ] , u ( f ̂ + C ) + e ̂ , u [ 1 , 2 ] , u ( f ̂ + C ) + ( 3 u ) e ̂ , u [ 2 , 3 ] .

This easily implies that t ̂ ( u ) = u and

N ̂ ( u , v ) = { 0 , u [ 0 , 1 ] , v [ 0 , u ] , 0 , u [ 1 , 2 ] , v [ 0 , 1 ] , ( v 1 ) f ̂ , u [ 1 , 2 ] , v [ 1 , u ] , 0 , u [ 2 , 3 ] , v [ 0 , 3 u ] , ( v + u 3 ) f ̂ , u [ 2 , 3 ] , v [ 3 u , u ] ,

so that

P ̂ ( u , v ) = { u ( f ̂ + e ̂ ) + ( u v ) C , u [ 0 , 1 ] , v [ 0 , u ] , u f ̂ + ( u v ) C + e ̂ , u [ 1 , 2 ] , v [ 0 , 1 ] , ( u v + 1 ) f ̂ + ( u v ) C + e ̂ , u [ 1 , 2 ] , v [ 1 , u ] , u f ̂ + ( u v ) C + e ̂ , u [ 2 , 3 ] , v [ 0 , 3 u ] , ( 3 v ) f ̂ + ( u v ) C + ( 3 u ) e ̂ , u [ 2 , 3 ] , v [ 3 u , u ] ,

which gives

( P ̂ ( u , v ) ) 2 = { u 2 v 2 , u [ 0 , 1 ] , v [ 0 , u ] , v 2 + 2 u 1 , u [ 1 , 2 ] , v [ 0 , 1 ] , 2 u 2 v , u [ 1 , 2 ] , v [ 1 , u ] , 3 u 2 v 2 + 12 u 9 , u [ 2 , 3 ] , v [ 0 , 3 u ] , 2 u 2 + 2 u v + 6 u 6 v , u [ 2 , 3 ] , v [ 3 u , u ] .

Thus, integrating, we get S ( W , F ̃ 0 ; C ) = 29 26 . Note that

A F 0 , Δ F 0 ( C ) = { 3 2 , O B F ̃ 0 , 2 , O B F ̃ 0 .

This gives the first required inequality. Similarly, we compute

S ( W , , F ̂ 0 , C ; Q ) = 9 26 + F Q ( W , , F ̂ 0 , C ) , where F Q ( W , , F ̂ 0 , C ) = { 11 26 , Q = f ̂ C , 0 otherwise .

Observe that

A C , Δ C ( Q ) = { 1 2 , Q B F ̂ 0 , 1 , Q B F ̂ 0 .

Moreover, if O B F ̃ 0 f , the intersection C f ̂ consists of a single point, which is not contained in B F ̂ 0 . Thus, we have

A C , Δ C ( Q ) S ( W , , F ̂ 0 , C ; Q ) = { 13 10 , Q = C f ̂ , 13 9 , Q = C B F ̂ 0 , 26 9 otherwise ,

which implies the second required inequality. ∎

Thus, it follows from (5.5) and Lemma 5.13 that O = B F ̃ 0 f , so 𝐟 and B F ̃ 0 are tangent at the point 𝑂. Then 𝜃 is a weighted blow up with weights ( 1 , 2 ) . We have

θ ( P ̃ ( u ) | F ̃ 0 ) R { u ( f ̂ + e ̂ + 2 C ) , u [ 0 , 1 ] , u ( f ̂ + 2 C ) + e ̂ , u [ 1 , 2 ] , u ( f ̂ + 2 C ) + ( 3 u ) e ̂ , u [ 2 , 3 ] .

This gives t ̂ ( u ) = 2 u . Moreover, we have

N ̂ ( u , v ) = { 0 , u [ 0 , 1 ] , v [ 0 , u ] , ( v u ) ( f ̂ + e ̂ ) , u [ 0 , 1 ] , v [ u , 2 u ] , 0 , u [ 1 , 2 ] , v [ 0 , 1 ] , v 1 2 f ̂ , u [ 1 , 2 ] , v [ 1 , 2 u 1 ] , ( v u ) f ̂ + ( v 2 u + 1 ) e ̂ , u [ 1 , 2 ] , v [ 1 , 2 u 1 ] , 0 , u [ 2 , 3 ] , v [ 0 , 3 u ] , v + u 3 2 f ̂ , u [ 2 , 3 ] , v [ 0 , 3 u 3 ] , ( v u ) f ̂ + ( v + 3 3 u ) e ̂ , u [ 2 , 3 ] , v [ 3 u 3 , 2 u ] ,

and

P ̂ ( u , v ) = { ( 2 u v ) C + u f ̂ + u e ̂ , u [ 0 , 1 ] , v [ 0 , u ] , ( 2 u v ) ( C + f ̂ + e ̂ ) , u [ 0 , 1 ] , v [ u , 2 u ] , ( 2 u v ) C + u f ̂ + e ̂ , u [ 1 , 2 ] , v [ 0 , 1 ] , ( 2 u v ) C + 2 u v + 1 2 f ̂ + e ̂ , u [ 1 , 2 ] , v [ 1 , 2 u 1 ] , ( 2 u v ) ( C + f ̂ + e ̂ ) , u [ 1 , 2 ] , v [ 1 , 2 u 1 ] , ( 2 u v ) C + u f ̂ + ( 3 u ) e ̂ , u [ 2 , 3 ] , v [ 0 , 3 u ] , ( 2 u v ) C + u v + 3 2 f ̂ + ( 3 u ) e ̂ , u [ 2 , 3 ] , v [ 0 , 3 u 3 ] , ( 2 u v ) ( C + f ̂ + e ̂ ) , u [ 2 , 3 ] , v [ 3 u 3 , 2 u ] .

Then

( P ̂ ( u , v ) ) 2 = { u 2 v 2 2 , u [ 0 , 1 ] , v [ 0 , u ] , ( 2 u v ) 2 2 , u [ 0 , 1 ] , v [ u , 2 u ] , 2 u 1 v 2 2 , u [ 1 , 2 ] , v [ 0 , 1 ] , 2 u v 1 2 , u [ 1 , 2 ] , v [ 1 , 2 u 1 ] , ( 2 u v ) 2 2 , u [ 1 , 2 ] , v [ 1 , 2 u 1 ] , 12 u 9 3 u 2 v 2 2 , u [ 2 , 3 ] , v [ 0 , 3 u ] , ( 5 u 2 v 3 ) ( u 3 ) 2 , u [ 2 , 3 ] , v [ 0 , 3 u 3 ] , ( 2 u v ) 2 2 , u [ 2 , 3 ] , v [ 3 u 3 , 2 u ] .

Now, integrating, we get S ( W , F ̃ 0 ; C ) = 49 26 . Thus, since A F 0 , Δ F 0 ( C ) = 2 , we get

A F 0 , Δ F 0 ( C ) S ( W , F ̃ 0 ; C ) = 52 49 ,

so it follows from (5.5) that there is a point Q C such that S ( W , , F ̂ 0 , C ; Q ) A C , Δ C ( Q ) . On the other hand, we compute

S ( W , , F ̂ 0 , C ; Q ) = 9 52 + F Q ( W , , F ̂ 0 , C ) ,

where

F Q ( W , , F ̂ 0 , C ) = { 3 4 , Q = C f ̂ , 0 otherwise .

Recall that B F ̂ 0 and f ̂ are disjoint and do not contain the singular point of the surface F ̂ 0 . Moreover, we have

A C , Δ C ( Q ) = { 1 2 , Q = C B F ̂ 0 , 1 2 , Q = Sing ( F ̂ 0 ) , 1 otherwise .

Thus, summarizing, we get

A C , Δ C ( Q ) S ( W , , F ̂ 0 , C ; Q ) = { 13 12 Q = C f ̂ , 26 9 , Q = C B F ̂ 0 , 26 9 , Q = Sing ( F ̂ 0 ) , 52 9 otherwise .

In particular, we see that S ( W , , F ̂ 0 , C ; Q ) < A C , Δ C ( Q ) in every possible case. The obtained contradiction completes the proof of Proposition 5.5.

5.2 Proof of Proposition 5.6

Let us use notation introduced earlier in this section before Proposition 5.6, and let 𝑃 be a singular point of type A 2 of the surface B | 2 S + | . Then, up to a change of coordinates, we may assume that P = ( 0 , 0 , 1 , 0 , 1 ) and

f 4 ( x 1 , x 2 , 1 ) = x 1 2 + x 2 3 + higher order terms .

Let ρ : Y 0 Y be the blow up of the point 𝑃 with weights ( 3 , 2 , 3 ) with respect to variables ( x 1 , x 2 , x 4 ) ; note that 𝜌 is a toroidal log resolution of ( Y , B ) . We may describe Y 0 as a toric variety given as ( C 6 Z ( I 0 ) ) / G m 3 , where the action is given by the matrix

M = ( x 0 x 1 x 2 x 3 x 4 x 5 0 1 1 1 2 0 0 0 0 0 1 1 1 0 1 3 3 0 ) ,

where the irrelevant ideal is

I 0 = x 1 , x 2 , x 3 x 1 , x 2 , x 4 x 4 , x 5 x 0 , x 3 x 0 , x 5 .

To describe the fan of the toric threefold Y 0 , we denote by v i the vector generating the ray corresponding to x i . Then

v 0 = ( 3 , 2 , 3 ) , v 1 = ( 1 , 0 , 0 ) , v 2 = ( 0 , 1 , 0 ) , v 3 = ( 1 , 1 , 2 ) , v 4 = ( 0 , 0 , 1 ) , v 5 = ( 0 , 0 , 1 ) ,

and the cone structure can be visualized with the following diagram:

Let F i = { x i = 0 } Y 0 and C i j = F i F j for i j such that dim ( F i F j ) = 1 . The geometric identifications of F i and C i j are the same as in previous section. Then

Eff ( Y 0 ) ̄ = F 0 , F 1 , F 5 and NE ( Y 0 ) ̄ = C 12 , C 15 , C 01 .

Intersections of divisors F 0 , F 1 , F 5 are described in following table:

F 0 3 F 0 2 F 1 F 0 2 F 5 F 0 F 1 2 F 0 F 1 F 5 F 0 F 5 2 F 1 3 F 1 2 F 5 F 1 F 5 2 F 5 3
1 18 1 6 0 1 2 0 0 3 2 1 −2 4

This gives the following intersection table:

F 0 F 1 F 5
C 12 1 3 −1 1
C 15 0 1 −2
C 01 1 6 1 2 0

Now, we set A = ( K Y + Δ ) . Take u R 0 . Set L ( u ) = ρ ( A ) u F 0 . Then we have L ( u ) R ( 9 u ) F 0 + 3 F 1 + F 5 , so L ( u ) is pseudo-effective if and only if u 9 . Let us find the Zariski decomposition for L ( u ) .

Observe that L ( u ) is nef for u [ 0 , 3 ] . Since L ( 3 ) C 12 = 0 and C 12 is unique in its numerical equivalence class, we consider a small ℚ-factorial modification Y 0 Y 1 along the curve C 12 such that Y 1 = ( C 6 Z ( I 1 ) ) / G m 3 , where the torus action is the same, and the irrelevant ideal is I 1 = x 1 , x 2 x 4 , x 5 x 0 , x 3 . The fan of Y 1 is generated by the same vectors, but the cone structure is different:

Abusing our previous notation, we denote the divisor { x i = 0 } Y 1 also by F i , and we let C i j = F i F j for i j such that F i F j is a curve. Then NE ( Y 1 ) ̄ = C 01 , C 15 , C 05 , and intersections on Y 1 are described in the following two tables:

F 0 3 F 0 2 F 1 F 0 2 F 5 F 0 F 1 2 F 0 F 1 F 5 F 0 F 5 2 F 1 3 F 1 2 F 5 F 1 F 5 2 F 5 3
0 0 1 6 0 1 2 1 2 0 1 2 1 2 5 2
F 0 F 1 F 5
C 05 1 6 1 2 1 2
C 15 1 2 1 2 1 2
C 01 0 0 1 2

Thus, we see that the proper transform on Y 1 of the divisor L ( u ) is nef for u [ 3 , 5 ] , and it intersects the curve C 15 trivially for u = 5 . Since C 15 is unique in its numerical equivalence class, we consider another small ℚ-factorial modification Y 1 Y 2 such that

Y 2 = ( C 6 Z ( I 2 ) ) / G m 3 ,

where the torus action is again given by the matrix 𝑀 and the irrelevant ideal

I 2 = x 1 , x 2 x 4 , x 5 x 1 , x 5 x 0 , x 2 , x 3 x 0 , x 3 , x 4 .

Then the fan of Y 2 is generated by the same vectors, but the cone structure is different:

We abuse our notation again and denote the divisor { x i = 0 } Y 2 also by F i . Similarly, we let C i j = F i F j for i j such that F i F j is a curve. Then NE ̄ ( Y 2 ) = C 01 , C 03 , C 05 , and intersections on Y 2 are described in the following two tables:

F 0 3 F 0 2 F 1 F 0 2 F 5 F 0 F 1 2 F 0 F 1 F 5 F 0 F 5 2 F 1 3 F 1 2 F 5 F 1 F 5 2 F 5 3
1 2 1 2 1 3 1 2 0 −1 1 2 0 0 3
F 0 F 1 F 5
C 05 1 3 0 −1
C 03 2 3 1 1
C 01 1 2 1 2 0

The proper transform on Y 2 of the divisor L ( u ) is nef for u [ 5 , 6 ] , and it intersects both curves C 01 and C 05 trivially for u = 6 . Furthermore, if u [ 6 , 9 ] , then the negative part of the Zariski decomposition of the divisor L ( u ) on the threefold Y 2 is

N ( u ) = ( u 6 ) F 1 + u 6 3 F 5 ,

while the positive part is P ( u ) R ( 9 u ) ( F 0 + F 1 + 1 3 F 5 ) . This gives

vol ( L ( u ) ) = { 13 u 3 18 , u [ 0 , 3 ] , u 2 + 3 + 23 2 , u [ 3 , 5 ] , 1 2 u 3 8 u 2 + 3 2 u , u [ 5 , 6 ] , 1 9 u 3 + 3 u 2 27 u + 81 , u [ 6 , 9 ] .

Integrating, we get S A ( F 0 ) = 127 26 . Since A Y , Δ ( F 0 ) = 5 , we get

A Y , Δ ( F 0 ) S A ( F 0 ) = 130 127 > 1 .

Next we construct a partial common toric resolution for Y 0 , Y 1 , Y 2 , which is easy to see from fan toric picture: we want to add the rays

v 6 = ( 3 , 2 , 0 ) v 1 , v 2 v 0 , v 5 , v 7 = ( 1 , 0 , 1 ) v 0 , v 3 v 0 , v 3 , v 8 = ( 3 , 1 , 0 ) v 1 , v 2 v 0 , v 3 .

Set Y ̃ be the toric variety corresponding to v 0 , , v 8 with the following cone structure:

Then we have the following toric diagram:

where toric maps can be described as follows:

Map Center Weights Exceptional divisor Relation
ψ 0 x 1 = x 2 = 0 ( 3 , 2 ) { x 6 = 0 } 3 v 1 + 2 v 2 = v 6
ψ 1 x 0 = x 5 = 0 ( 1 , 3 ) { x 6 = 0 } v 0 + 3 v 5 = v 6
σ 1 x 1 = x 5 = 0 ( 1 , 1 ) { x 7 = 0 } v 1 + v 5 = v 7
σ 2 x 0 = x 3 = 0 ( 1 , 2 ) { x 7 = 0 } v 0 + 2 v 3 = v 7
ψ x 1 = x 5 = 0 ( 1 , 1 ) { x 7 = 0 } v 1 + v 5 = v 7
σ x 0 = x 5 = 0 ( 1 , 3 ) { x 6 = 0 } v 0 + 3 v 5 = v 6
ψ 01 x 1 = x 6 = 0 1 2 ( 3 , 1 ) { x 8 = 0 } 3 v 1 + v 6 = 2 v 8
σ 12 x 0 = x 7 = 0 1 2 ( 1 , 3 ) { x 8 = 0 } v 1 + 3 v 7 = 2 v 8

Here, 1 2 ( a , b ) indicates that the variety has an A 1 -singularity along the center of blow up.

Now, we set φ 0 = ψ 01 ψ ψ 0 , φ 1 = ψ 01 ψ ψ 1 , φ 2 = σ 12 σ σ 2 . Let F ̃ i be the toric divisor { x i = 0 } Y ̃ . Then

φ 0 ( F 0 ) Q F ̃ 0 , φ 0 ( F 1 ) Q F ̃ 1 + 3 F ̃ 6 + F ̃ 7 + 3 F ̃ 8 , φ 0 ( F 5 ) Q F ̃ 5 + F ̃ 7 , φ 1 ( F 0 ) Q F ̃ 0 + F ̃ 6 + 1 2 F ̃ 8 , φ 1 ( F 1 ) Q F ̃ 1 + F ̃ 7 + 3 2 F ̃ 8 , φ 1 ( F 5 ) Q F ̃ 5 + 3 F ̃ 6 + F ̃ 7 + 3 2 F ̃ 8 , φ 2 ( F 0 ) Q F ̃ 0 + F ̃ 6 + F ̃ 7 + 2 F ̃ 8 , φ 2 ( F 1 ) Q F ̃ 1 , φ 2 ( F 5 ) Q F ̃ 5 + 3 F ̃ 6 .

Using this, we describe the Zariski decomposition of the divisor φ 0 ( L ( u ) ) as follows:

P ̃ ( u ) R { ( 9 u ) F ̃ 0 + 3 F ̃ 1 + F ̃ 5 + 9 F ̃ 6 + 4 F ̃ 7 + 9 F ̃ 8 , u [ 0 , 3 ] , ( 9 u ) F ̃ 0 + 3 F ̃ 1 + F ̃ 5 + ( 12 u ) F ̃ 6 + 4 F ̃ 7 + 21 u 2 F ̃ 8 , u [ 3 , 5 ] , ( 9 u ) F ̃ 0 + 3 F ̃ 1 + F ̃ 5 + ( 12 u ) F ̃ 6 + ( 9 u ) F ̃ 7 + 2 ( 9 u ) F ̃ 8 , u [ 5 , 6 ] , ( 9 u ) ( F ̃ 0 + F ̃ 1 + 1 3 F ̃ 5 + 2 F ̃ 6 + F ̃ 7 + 2 F ̃ 8 ) , u [ 6 , 9 ] ,

and

N ̃ ( u ) = { 0 , u [ 0 , 3 ] , ( u 3 ) F ̃ 6 + u 3 2 F ̃ 8 , u [ 3 , 5 ] , ( u 3 ) F ̃ 6 + ( u 5 ) F ̃ 7 + ( 2 u 9 ) F ̃ 8 , u [ 5 , 6 ] , ( u 6 ) F ̃ 1 + u 3 F ̃ 5 + ( 2 u 9 ) F ̃ 6 + ( u 5 ) F ̃ 7 + ( 2 u 9 ) F ̃ 8 , u [ 6 , 9 ] .

where P ̃ ( u ) is the positive part, and N ̃ ( u ) is the negative part.

Now, we describe P ̃ ( u ) | F ̃ 0 and N ̃ ( u ) | F ̃ 0 for every u [ 0 , 9 ] . We have

Y ̃ = ( C 9 I ̃ ) / G m 6 ,

where the torus action is given by the matrix

M ̃ = ( x 0 x 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 0 1 1 1 2 0 0 0 0 0 0 0 0 1 1 0 0 0 1 0 1 3 3 0 0 0 0 0 0 1 3 6 0 1 0 0 0 0 1 1 3 0 0 1 0 0 0 2 3 6 0 0 0 1 )

and the irrelevant ideal

I ̃ = x 0 , x 3 x 0 , x 5 x 0 , x 7 x 1 , x 2 x 1 , x 5 x 1 , x 6 x 2 , x 7 x 2 , x 8 x 3 , x 6 x 3 , x 8 x 4 , x 5 x 4 , x 6 x 4 , x 7 x 4 , x 8 x 5 , x 8 .

To obtain a similar description of the surface F ̃ 0 , set x 0 = 0 , eliminate the first row in M ̃ , and set x 3 = x 5 = x 7 = 1 , since I ̃ x 0 , x 3 x 0 , x 5 x 0 , x 7 . The resulting matrix is

( x 1 x 2 x 4 x 6 x 8 3 2 3 0 0 0 0 3 1 0 0 1 3 0 1 ) .

Using this, we see that F ̃ 0 = ( C 5 Z ( I F ̃ 0 ) ) / G m 3 , where the torus action is given by

( z 1 z 2 z 3 z 4 z 5 1 1 2 0 0 0 1 0 1 0 0 1 1 0 1 ) ,

and I F ̃ 0 = z 1 , z 3 z 1 , z 4 z 2 , z 4 z 2 , z 5 z 3 , z 5 . We can see from the matrices that

x 1 | F ̃ 0 = z 1 , x 2 3 | F ̃ 0 = z 3 , x 4 | F ̃ 0 = z 2 , x 6 3 | F ̃ 0 = z 4 , x 8 3 | F ̃ 0 = z 5 .

The fan of the toric surface F ̃ 0 is given by

w 1 = ( 1 , 0 ) , w 2 = ( 1 , 2 ) , w 3 = ( 0 , 1 ) , w 4 = ( 1 , 2 ) , w 5 = ( 1 , 1 )

with obvious cone structure. Note that we can also recover this structure by noticing that F 0 P ( 1 , 1 , 2 ) is the exceptional divisor of the weighted blow up 𝜌 and that the maps ψ 0 and ψ 01 restrict to F 0 as weighted blow ups. For i { 1 , 2 , 3 , 4 , 5 } , let C i be the curve in F ̃ 0 given z i = 0 . The cone of effective divisors of the surface F ̃ 0 is generated by the curves C 1 , C 4 , C 5 , and their intersection form is given in the following table:

C 1 C 4 C 5
C 1 1 2 0 1
C 4 0 −1 1
C 5 1 1 −2

Further, we compute

P ̃ ( u ) | F ̃ 0 R { u 3 C 1 + u 3 C 4 + u 3 C 5 , u [ 0 , 3 ] , u 3 C 1 + C 4 + ( 1 2 + u 6 ) C 5 , u [ 3 , 5 ] , u 3 C 1 + C 4 + ( 3 u 3 ) C 5 , u [ 5 , 6 ] , ( 6 2 u 3 ) C 1 + ( 3 u 3 ) C 4 + ( 3 u 3 ) C 5 , u [ 6 , 9 ] ,

and

N ̃ ( u ) | F ̃ 0 = { 0 , u [ 3 , 5 ] , u 3 6 ( 2 C 4 + C 5 ) , u [ 3 , 5 ] , u 3 3 C 4 + 2 u 9 3 C 5 , u [ 5 , 6 ] , ( u 6 ) C 1 + 2 u 9 3 ( 2 C 4 + C 5 ) , u [ 6 , 9 ] .

Let θ : F ̃ 0 F 0 be the morphism induced by φ 0 . Then 𝜃 is a birational morphism that contracts C 4 and C 5 . Set C ̄ 1 = θ ( C 1 ) , C ̄ 2 = θ ( C 2 ) , C ̄ 3 = θ ( C 3 ) , identify F 0 = P ( 1 , 1 , 2 ) with coordinates z ̄ 1 , z ̄ 2 , z ̄ 3 such that C ̄ 1 = { z ̄ 1 = 0 } , C ̄ 2 = { z ̄ 2 = 0 } , C ̄ 3 = { z ̄ 3 = 0 } , where z ̄ 1 and z ̄ 2 are coordinates of weight 1, and z ̄ 3 is a coordinate of weight 2. Then

θ ( C 4 ) = θ ( C 5 ) = C ̄ 1 C ̄ 3 = [ 0 : 1 : 0 ] ,

and 𝜃 is a composition of the ordinary blow up at the point [ 0 : 1 : 0 ] with the consecutive blow up at the point on the proper transform of the curve C ̄ 3 . Note that C 5 is the proper transform of the exceptional curve for the first blow up and C 4 is the exceptional curve for the second blow up.

Let B 0 be the proper transform on Y 0 of the surface 𝐵. Set Δ 0 = 1 2 B 0 and B F 0 = B 0 | F 0 . Then, changing the coordinates z ̄ 1 , z ̄ 2 , z ̄ 3 , we may also assume that

B F 0 = { z ̄ 1 2 + z ̄ 2 2 = z ̄ 3 } F 0 .

This curve is smooth, it does not contain the singular point of F 0 , and [ 0 : 1 : 0 ] B F 0 . The geometry of the surface F 0 can be illustrated by the following picture:

Note that the surface Y 0 is singular along the curve C ̄ 3 . We set

Δ F 0 = 1 2 B F 0 + 2 3 C ̄ 3 .

Then

K F 0 + Δ F 0 Q ( K Y 0 + Δ 0 ) | F 0 ,

and Δ F 0 is the corresponding different [40].

Now, we are ready to apply [2, 7, 22]. Let 𝑄 be a point in F 0 , let 𝐶 be a smooth curve in the surface F 0 that contains 𝑄, let C ̃ be its proper transform on F ̃ 0 . For u [ 0 , 9 ] , let

t ( u ) = inf { v R 0 the divisor P ̃ ( u ) | F ̃ 0 v C ̃ is pseudo-effective } .

For a real number v [ 0 , t ( u ) ] , let P ( u , v ) and N ( u , v ) be the positive part and the negative part of the Zariski decomposition of the divisor P ̃ ( u ) | F ̃ 0 v C ̃ , respectively. Set

S L ( W , F 0 ; C ) = 3 A 3 0 9 ( P ̃ ( u ) | F ̃ 0 ) 2 ord C ̃ ( N ̃ ( u ) | F ̃ 0 ) d u + 3 A 3 0 9 0 t ( u ) ( P ( u , v ) ) 2 d v d u .

Write θ ( C ) = C ̃ + Σ for an effective divisor Σ on the surface F ̃ 0 . For u [ 0 , 9 ] , write

N ̃ ( u ) | F ̃ 0 = d ( u ) C ̃ + N ( u ) ,

where d ( u ) = ord C ̃ ( N ̃ ( u ) | F ̃ 0 ) , and N ( u ) is an effective divisor on F ̃ 0 . Set

S ( W , , F 0 , C ; Q ) = 3 A 3 0 9 0 t ( u ) ( P ( u , v ) C ̃ ) 2 d v d u + F Q ( W , , F 0 , C )

for

F Q ( W , , F 0 , C ) = 6 A 3 0 9 0 t ( u ) ( P ( u , v ) C ̃ ) ord Q ( ( N ( u ) + N ( u , v ) ( v + d ( u ) ) Σ ) | C ̃ ) d v d u ,

where we consider 𝑄 as a point in C ̃ using the isomorphism C ̃ C induced by 𝜃.

We will choose 𝐶 such that the pair ( F 0 , C + Δ F 0 ord C ( Δ F 0 ) C ) has purely log terminal singularities. In this case, the curve 𝐶 is equipped with an effective divisor Δ C such that

K C + Δ C Q ( K F 0 + C + Δ F 0 ord C ( Δ F 0 ) C ) | C ,

and the pair ( C , Δ C ) has Kawamata log terminal singularities. The ℚ-divisor Δ C is known as the different, and it can be computed locally near any point in 𝐶; see [40] for details.

Let 𝐅 be a prime divisor over 𝑌 such that P = C Y ( F ) . Recall that

β Y , Δ ( F ) = A Y , Δ ( F ) S A ( F ) = A Y , Δ ( F ) 1 A 3 0 vol ( A u F ) d u .

Suppose β Y , Δ ( F ) 0 . Then, using [22, Corollary 4.18], we obtain

1 A Y , Δ ( F ) S A ( F ) δ P ( Y , Δ ) min { A Y , Δ ( F 0 ) S A ( F 0 ) , inf Q F 0 min { A F 0 , Δ F 0 ( C ) S A ( W , F 0 ; C ) , A C , Δ C ( Q ) S ( W , , F 0 , C ; Q ) } } ,

where the choice of 𝐶 in the infimum depends on 𝑄. Thus, since

A Y , Δ ( F 0 ) S A ( F 0 ) 1 ,

we have

inf Q F 0 min { A F 0 , Δ F 0 ( C ) S A ( W , F 0 ; C ) , A C , Δ C ( Q ) S ( W , , F 0 , C ; Q ) } 1 .

In fact, since

A Y , Δ ( F 0 ) S A ( F 0 ) = 130 127 > 1 ,

it follows from [22, Corollary 4.18] and [2, Theorem 3.3] that we have a strict inequality

inf Q F 0 min { A F 0 , Δ F 0 ( C ) S A ( W , F 0 ; C ) , A C , Δ C ( Q ) S ( W , , F 0 , C ; Q ) } < 1 .

Let us use this to obtain a contradiction, which would finish the proof of Proposition 5.6.

Namely, we will show that, for every point Q F 0 , there exists a smooth irreducible curve C F 0 such that Q C , the log pair ( F 0 , C + Δ F 0 ord C ( Δ F 0 ) C ) has purely log terminal singularities, and the following two inequalities hold:

(5.6) S A ( W , F 0 ; C ) A F 0 , Δ F 0 ( C ) ,
(5.7) S ( W , , F 0 , C ; Q ) A C , Δ C ( Q ) .
To be precise, we will choose the curve 𝐶 as follows:
  • if Q C ̄ 1 , we let C = C ̄ 1 ;

  • if Q C ̄ 1 and Q C ̄ 3 , we let C = C ̄ 3 ;

  • if Q C ̄ 1 C ̄ 3 , we let 𝐶 be the unique curve in | C ̄ 1 | such that Q C .

Lemma 5.14

Let 𝑄 be a point in C ̄ 1 . Set C = C ̄ 1 . Then (5.6) and (5.7) hold.

Proof

Note that A F 0 , Δ F 0 ( C ) = 1 and Σ = C ̄ 4 + C ̄ 5 . We have

d ( u ) = { 0 , u [ 0 , 6 ] u 6 , u [ 6 , 9 ] , and t ( u ) = { u 3 , u [ 0 , 6 ] , 6 2 u 3 , u [ 6 , 9 ] .

Moreover, we have

N ( u , v ) = { v ( C 4 + C 5 ) , u [ 0 , 3 ] , v [ 0 , u 3 ] , v 2 C 5 , u [ 3 , 5 ] , v [ 0 , u 3 1 ] , 3 v + 3 u 3 C 4 + 6 v + 3 u 6 C 5 , u [ 3 , 5 ] , v [ u 3 1 , u 3 ] , 0 , u [ 5 , 6 ] , v [ 0 , u 5 ] , v + 5 u 2 C 5 , u [ 5 , 6 ] , v [ u 5 , u 3 1 ] , 3 v + 3 u 3 C 4 + 3 v + 9 2 u 3 C 5 , u [ 5 , 6 ] , v [ u 3 1 , u 3 ] , 0 , u [ 6 , 9 ] , v [ 0 , 3 u 3 ] , 3 v + u 9 3 ( C 4 + C 5 ) , u [ 6 , 9 ] , v [ 3 u 3 , 6 2 u 3 ] ,

and

P ( u , v ) R { u 3 v 3 ( C 1 + C 4 + C 5 ) , u [ 0 , 3 ] , v [ 0 , u 3 ] , u 3 v 3 C 1 + C 4 + 3 + u 3 v 6 C 5 , u [ 3 , 5 ] , v [ 0 , u 3 1 ] , u 3 v 3 ( C 1 + C 4 + C 5 ) , u [ 3 , 5 ] , v [ u 3 1 , u 3 ] , u 3 v 3 C 1 + C 4 + 9 u 3 C 5 , u [ 5 , 6 ] , v [ 0 , u 5 ] , u 3 v 3 C 1 + C 4 + 3 + u 3 v 6 C 5 , u [ 5 , 6 ] , v [ u 5 , u 3 1 ] , u 3 v 3 ( C 1 + C 4 + C 5 ) , u [ 5 , 6 ] , v [ u 3 1 , u 3 ] , ( 18 2 u 3 v 3 C 1 + 9 u 3 ( C 4 + C 5 ) , u [ 6 , 9 ] , v [ 0 , 3 u 3 ] , 18 2 u 3 v 3 ( C 1 + C 4 + C 5 ) , u [ 6 , 9 ] , v [ 3 u 3 , 6 2 u 3 ] ,

which gives

( P ( u , v ) ) 2 = { ( u 3 v ) 2 18 , u [ 0 , 3 ] , v [ 0 , u 3 ] , u 3 v 1 2 , u [ 3 , 5 ] , v [ 0 , u 3 1 ] , ( u 3 v ) 2 18 , u [ 3 , 5 ] , v [ u 3 1 , u 3 ] , u 2 2 + u v v 2 2 13 + 16 3 u 6 v , u [ 5 , 6 ] , v [ 0 , u 5 ] , u 3 v 1 2 , u [ 5 , 6 ] , v [ u 5 , u 3 1 ] , ( u 3 v ) 2 18 , u [ 5 , 6 ] , v [ u 3 1 , u 3 ] , 2 u + 9 + u 2 9 v 2 2 , u [ 6 , 9 ] , v [ 0 , 3 u 3 ] , ( 18 2 u 3 v ) 2 18 , u [ 6 , 9 ] , v [ 3 u 3 , 6 2 u 3 ] ,

and

P ( u , v ) C = { u 3 v 6 , u [ 0 , 3 ] , v [ 0 , u 3 ] , 1 2 , u [ 3 , 5 ] , v [ 0 , u 3 1 ] , u 3 v 6 , u [ 3 , 5 ] , v [ u 3 1 , u 3 ] , 6 u + v 2 , u [ 5 , 6 ] , v [ 0 , u 5 ] , 1 2 , u [ 5 , 6 ] , v [ u 5 , u 3 1 ] , u 3 v 6 , u [ 5 , 6 ] , v [ u 3 1 , u 3 ] , v 2 , u [ 6 , 9 ] , v [ 0 , 3 u 3 ] , 18 2 u 3 v 6 , u [ 6 , 9 ] , v [ 3 u 3 , 6 2 u 3 ] .

Integrating, we get

S ( W , F 0 ; C ) = 10 13 < 1 = A F 0 , Δ F 0 ( C ) ,

so (5.6) holds.

Similarly, we compute

S ( W , , F 0 , C ; Q ) = 9 52 + F Q ( W , , F 0 , C ) ,

where

F Q ( W , , F 0 , C ) = { 1 12 , Q = C ̄ 1 C ̄ 3 , 0 otherwise .

Observe that

A C , Δ C ( Q ) = { 1 2 , Q = C ̄ 1 B F 0 , 1 2 , Q = C ̄ 1 C ̄ 2 , 1 3 , Q = C ̄ 1 C ̄ 3 , 1 otherwise .

Thus, we have

A C , Δ C ( Q ) S ( W , , F 0 , C ; Q ) = { 13 10 Q = C ̄ 1 C ̄ 3 , 26 9 Q = C ̄ 1 C ̄ 2 , 26 9 , Q = C ̄ 1 B F 0 , 52 9 otherwise ,

which implies (5.7). ∎

Lemma 5.15

Let 𝑄 be a point in C ̄ 3 C ̄ 1 . Set C = C ̄ 3 . Then (5.6) and (5.7) hold.

Proof

For u [ 0 , 9 ] , we have d ( u ) = 0 , N ( u ) = N ̃ ( u ) | F ̃ 0 . As C ̃ C 3 + 2 C 4 + C 5 , we have

t ( u ) = { u 6 , u [ 0 , 6 ] , 9 u 3 , u [ 6 , 9 ] .

We compute

N ( u , v ) = { 2 v C 4 + v C 5 , u [ 0 , 3 ] , v [ 0 , u 6 ] , 0 , u [ 3 , 5 ] , v [ 0 , u 3 6 ] , u 3 6 ( 2 C 4 + C 5 ) , u [ 3 , 5 ] , v [ u 3 6 , u 6 ] , 0 , u [ 5 , 6 ] , v [ 0 , 6 u 3 ] , 3 v + u 6 3 ( C 4 ) , u [ 5 , 6 ] , v [ 6 u 3 , 2 u 9 3 ] 6 v + 3 u 3 ( C 4 ) + v + 9 2 u 3 ( C 4 ) , u [ 5 , 6 ] , v [ 2 u 9 3 , u 6 ] , 2 u 9 3 ( C 4 + C 5 ) , u [ 6 , 9 ] , v [ 0 , 9 u 3 ] ,

and

P ( u , v ) { u 6 v 3 ( C 1 + C 4 + C 5 ) , u [ 0 , 3 ] , v [ 0 , u 6 ] , u 6 v 3 C 1 + 3 + u 6 v 6 C 5 + C 4 , u [ 3 , 5 ] , v [ 0 , u 3 6 ] , u 6 v 3 ( C 1 + C 4 + C 5 ) , u [ 3 , 5 ] , v [ u 3 6 , u 6 ] , u 6 v 3 C 1 + 9 u 3 v 3 C 5 + C 4 , u [ 5 , 6 ] , v [ 0 , 6 u 3 ] , u 6 v 3 C 1 + 9 u 3 v 3 ( C 5 + C 4 ) , u [ 5 , 6 ] , v [ 6 u 3 , 2 u 9 3 ] , u 6 v 3 ( C 1 + C 4 + C 5 ) , u [ 5 , 6 ] , v [ 2 u 9 3 , u 6 ] , 9 u 3 v 3 ( 2 C 1 + C 4 + C 5 ) , u [ 6 , 9 ] , v [ 0 , 9 u 3 ] ,

which gives

( P ( u , v ) ) 2 = { u 2 18 + 2 v 2 2 3 u v , u [ 0 , 3 ] , v [ 0 , u 6 ] , u 3 2 v 1 2 , u [ 3 , 5 ] , v [ 0 , u 3 6 ] , u 2 18 + 2 v 2 2 3 u v , u [ 3 , 5 ] , v [ u 3 6 , u 6 ] , 16 3 u 2 v 13 2 u 2 , u [ 5 , 6 ] , v [ 0 , 6 u 3 ] , 4 u 6 v 9 7 18 u 2 + v 2 + 2 3 u v , u [ 5 , 6 ] , v [ 6 u 3 , 2 u 9 3 ] 9 6 v 2 u + v 2 + u 2 9 + 2 3 u v , u [ 5 , 6 ] , v [ 2 u 9 3 , u 6 ] , 2 u 9 3 ( C 4 + C 5 ) , u [ 6 , 9 ] , v [ 0 , 9 u 3 ] ,

and

P ( u ) C = { u 3 2 v , u [ 0 , 3 ] , v [ 0 , u 6 ] , 1 , u [ 3 , 5 ] , v [ 0 , u 3 6 ] , u 3 2 v , u [ 3 , 5 ] , v [ u 3 6 , u 6 ] , 1 , u [ 5 , 6 ] , v [ 0 , 6 u 3 ] , 3 v u 3 , u [ 5 , 6 ] , v [ 6 u 3 , 2 u 9 3 ] , u 3 2 v , u [ 5 , 6 ] , v [ 2 u 9 3 , u 6 ] , 3 u 3 v , u [ 6 , 9 ] , v [ 0 , 9 u 3 ] .

Thus, integrating we get

S ( W , F 0 ; C ) = 10 39 < 1 3 = A F 0 , Δ F 0 ( C ) ,

so (5.6) holds.

Since Q C ̄ 1 C ̄ 3 , we have F Q ( W , , F 0 , C ) = 0 , which gives S ( W , , F 0 , C ̄ 3 ; Q ) = 9 26 . But

A C , Δ C ( Q ) = { 1 2 , Q B F 0 , 1 , Q B F 0 .

Thus, we have

A C , Δ C ( Q ) S ( W , F 0 ; C ) = { 13 10 , Q B F 0 , 26 9 , Q B F 0 ,

which implies (5.6). ∎

Lemma 5.16

Let 𝑄 be a point in F 0 such that Q C ̄ 1 C ̄ 3 , and let 𝐶 be the unique curve in the pencil | C ̄ 1 | that contains 𝑄. Then (5.6) and (5.7) hold.

Proof

Note that A F 0 , Δ F 0 ( C ) = 1 , and C ̃ C 1 + C 4 + C 5 . We have

t ( u ) = { u 3 , u [ 0 , 3 ] , 1 , u [ 3 , 6 ] , 9 u 3 , u [ 6 , 9 ] .

For every u [ 0 , 9 ] , we have d ( u ) = 0 and N ( u ) = N ̃ ( u ) | F ̃ 0 . We compute

N ( u , v ) = { 0 , u [ 0 , 3 ] , v [ 0 , u 3 ] , 0 , u [ 3 , 5 ] , v [ 0 , 1 ] , 0 , u [ 5 , 6 ] , v [ 0 , 6 u ] , ( v + u 6 ) C 1 , u [ 5 , 6 ] , v [ 6 u , 1 ] , v C 1 , u [ 6 , 9 ] , v [ 0 , 3 u 3 ] ,

and

P ( u , v ) { u 3 v 3 ( C 1 + C 4 + C 5 ) , u [ 0 , 3 ] , v [ 0 , u 3 ] , u 3 v 3 C 1 + ( 1 v ) C 4 + 3 + u 6 v 6 C 5 , u [ 3 , 5 ] , v [ 0 , 1 ] , u 3 v 3 C 1 + ( 1 v ) C 4 + 9 u 3 v 3 C 5 , u [ 5 , 6 ] , v [ 0 , 6 u ] , 18 2 u 6 v 3 C 1 + ( 1 v ) C 4 + 9 u 3 v 3 C 5 , u [ 5 , 6 ] , v [ 6 u , 1 ] , 9 u 3 v 3 ( 2 C 1 + C 4 + C 5 ) , u [ 6 , 9 ] , v [ 0 , 3 u 3 ] ,

which gives

( P ( u , v ) ) 2 = { ( u 3 v ) 2 18 , u [ 0 , 3 ] , v [ 0 , u 3 ] , 1 2 + u 3 1 3 u v + 1 2 v 2 , u [ 3 , 5 ] , v [ 0 , 1 ] , u 2 2 u v 3 + v 2 2 13 + 16 3 u , u [ 5 , 6 ] , v [ 0 , 6 u ] , 5 + 2 u v 3 + v 2 2 u 3 6 v , u [ 5 , 6 ] , v [ 6 u , 1 ] , ( 3 u 3 v ) 2 2 , u [ 6 , 9 ] , v [ 0 , 3 u 3 ] ,

and

P ( u ) C ̃ = { u 3 v 6 , u [ 0 , 3 ] , v [ 0 , u 3 ] , u 3 v 6 , u [ 3 , 5 ] , v [ 0 , 1 ] , u 3 v 6 , u [ 5 , 6 ] , v [ 0 , 6 u ] , 9 u 3 v 3 , u [ 5 , 6 ] , v [ 6 u , 1 ] , 9 u 3 v 3 , u [ 6 , 9 ] , v [ 0 , 3 u 3 ] .

Thus, integrating, we get

S ( W , F 0 ; C ) = 9 26 < 1 = A F 0 , Δ F 0 ( C ) ,

so (5.6) holds.

Since Q C ̄ 1 C ̄ 3 , we have F Q ( W , , F 0 , C ) = 0 and

A C , Δ C ( Q ) = { 1 2 , Q B F 0 , 1 , Q B F 0 .

Integrating, we get S ( W , , F 0 , C ; Q ) = 10 39 , so that

A C , Δ C ( Q ) S ( W , F 0 ; C ) = { 39 20 , Q B F 0 , 39 10 , Q B F 0 ,

which implies (5.6). ∎

Lemmas 5.14, 5.14, 5.16 complete the proof of Proposition 5.6.

6 On the K-moduli spaces

In this section, we prove Corollary 1.13. The proof of Corollary 1.14 is almost identical, so we omit it. To start with, let us present the following well-known assertion.

Lemma 6.1

Let 𝑋 be a smooth Fano threefold. Then

h 0 ( X , T X ) h 1 ( X , T X ) = χ ( X , T X ) = K X 3 2 18 + b 2 ( X ) b 3 ( X ) 2 ,

where b 2 ( X ) and b 3 ( X ) are the second and the third Betti numbers of 𝑋, respectively.

Proof

The required assertion immediately follows from the Akizuki–Nakano vanishing theorem and the Hirzebruch–Riemann–Roch theorem, since K X c 2 ( X ) = 24 . ∎

Now, let us use notation and assumptions introduced in Corollary 1.13.

Lemma 6.2

Let f T and let X f be the Casagrande–Druel 3-fold constructed from { f = 0 } . Suppose that 𝑓 is GIT semistable with respect to the Γ-action. Then X f is K-semistable.

Proof

There exists a one-parameter subgroup λ : G m Γ such that

[ f 0 ] = lim t 0 λ ( t ) [ f ]

is a GIT polystable point in 𝑇. Let X 0 be the corresponding Casagrande–Druel threefold constructed from { f 0 = 0 } . Then it follows from Theorem 1.11 that X 0 is K-polystable. On the other hand, the subgroup 𝜆 gives isotrivial flat degeneration of X f to X 0 , which implies that X f is K-semistable, because K-semistability is an open condition. ∎

Now, we are ready to prove Corollary 1.13.

Proof of Corollary 1.13

Since the construction of Casagrande–Druel 3-folds is functorial, there exists a Γ-equivariant flat morphism π T : X T T such that π T 1 ( [ f ] ) X f . We set X T ss = π T 1 ( T ss ) . Then the restriction morphism X T ss T ss is a Γ-equivariant flat family of K-semistable Fano 3-folds by Lemma 6.2.

Let { T ss / Γ } be the fibered category over ( Sch / C ) fppf in the sense of [36, Example 4.6.7]. Then the family X T ss T ss gives a morphism { T ss / Γ } M 3 , 28 Kss of fibered categories. This induces the morphism [ T ss / Γ ] M 3 , 28 Kss between Artin stacks, since [ T ss / Γ ] is the stackification of { T ss / Γ } (see [36, Remark 4.6.8]).

Since 𝑀 is the good moduli space of [ T ss / Γ ] , it follows from [4, Theorem 6.6] that there exists a natural morphism Φ : M M 3 , 28 Kps that maps [ f ] to [ X f ] . We claim that Φ is injective. Since 𝑀 is of Picard rank 1, it is enough to show this on the open subset of 𝑀 parametrizing [ f ] such that ( f = 0 ) is non-singular, so that the corresponding 3-fold X f is smooth. Suppose that f 1 and f 2 are points in 𝑇 and the corresponding Casagrande–Druel 3-folds X f 1 and X f 2 are both smooth and isomorphic. Let χ : X f 1 X f 2 be the isomorphism. Then 𝜒 maps any exceptional locus of the contraction of an extremal ray of X f 1 to an exceptional locus of the contraction of an extremal ray of X f 2 . There are exactly 4 such exceptional loci: S 1 , S 2 , E 1 and E 2 . Since S j and E k are not isomorphic to each other, the image of S 1 X f 1 via 𝜒 must be either S 1 X f 2 or S 2 X f 2 . In each case, the restriction of 𝜒 to S 1 gives a projective isomorphism between ( f 1 = 0 ) and ( f 2 = 0 ) . Thus, the points f 1 and f 2 are contained in one Γ-orbit. Hence, the morphism Φ is injective.

Observe that 𝑀 is normal. Take [ f ] M . Since the deformations of the 3-fold X f are unobstructed by Proposition 2.6, the variety M 3 , 28 Kps is also normal at [ X f ] by Luna’s étale slice theorem [6, Theorem 1.2]. Moreover, if X f is smooth, then

dim [ X f ] ( M 3 , 28 Kps ) h 1 ( X f , T X f ) = dim ( M )

by Lemma 6.1, since h 0 ( X , T X ) = dim ( Aut ( X ) ) = 1 . Therefore, using the injectivity of Φ, we see that the image Φ ( M ) M 3 , 28 Kps is a connected component, and Φ is an isomorphism onto this connected component by Zariski’s main theorem. ∎

The variety M ( 3.9 ) Kps is well-studied [26]. Let us describe M ( 4.2 ) Kps T ss / / Γ . Recall that

T = P ( H 0 ( V , O V ( 2 , 2 ) ) )

and Γ = ( SL 2 ( C ) × SL 2 ( C ) ) μ 2 , where V = P 1 × P 1 . Set Γ 0 = SL 2 ( C ) × SL 2 ( C ) .

Proposition 6.3

Proposition 6.3 (Noam Elkies)

One has T ss / / Γ 0 T ss / / Γ P ( 1 , 2 , 3 ) .

Proof

Let W = H 0 ( V , O V ( 2 , 2 ) ) , let 𝑆 be the symmetric algebra of W , let S Γ 0 be its subalgebra of invariants for the natural Γ 0 -action, and let H ( t ) be its Hilbert series

H ( t ) = k 0 dim ( ( Sym k ( W ) ) Γ 0 ) t k .

Then it follows from [39, §11.9] or [18, §4.6] that

H ( t ) = 0 1 0 1 2 z 1 2 z 1 2 2 2 z 2 2 z 2 2 2 j 1 , j 2 { 1 , 0 , 1 } 1 1 t z 1 2 j 1 z 2 2 j 2 d ϕ 1 d ϕ 2

with | t | < 1 , where z 1 = e 2 π 1 ϕ 1 and z 2 = e 2 π 1 ϕ 2 . This gives

H ( t ) = 1 ( 1 t 2 ) ( 1 t 3 ) ( 1 t 4 ) .

Let us find generators of S Γ 0 . Consider the standard basis

x 0 2 y 0 2 , x 0 2 y 0 y 1 , x 0 2 y 1 2 , x 0 x 1 y 0 2 , x 0 x 1 y 0 y 1 , x 0 x 1 y 1 2 , x 1 2 y 0 2 , x 1 2 y 0 y 1 , x 1 2 y 1 2

of the space 𝑊, let a 00 , a 01 , a 02 , a 10 , a 11 , a 12 , a 20 , a 21 , a 22 be the dual basis of the space W , and let J 2 , J 3 , J 4 be the coefficients of the characteristic polynomial of the matrix

( 1 2 a 11 a 10 a 01 2 a 00 a 12 1 2 a 11 2 a 02 a 01 a 21 2 a 20 1 2 a 11 a 10 2 a 22 a 21 a 12 1 2 a 11 )

such that J k Sym k ( W ) for k { 2 , 3 , 4 } . Then J 2 , J 3 , J 4 are Γ 0 -invariant, and these polynomials are algebraically independent, which gives S Γ 0 = C [ J 2 , J 3 , J 4 ] , so that

T ss / / Γ 0 P ( 2 , 3 , 4 ) P ( 1 , 2 , 3 ) .

Since the polynomials J 2 , J 3 , J 4 are also Γ-invariant, we also get T ss / / Γ 0 T ss / / Γ . ∎

Remark 6.4

In fact, Proposition 6.3 is a classical result – Peano [38] and Turnbull [44] showed that S Γ 0 is generated by J 2 , J 3 , J 4 ; see [44, §12] and [37, pages 242–246].

The surface M ( 4.2 ) Kps is a component of the K-moduli space of smoothable Fano threefolds. Another two-dimensional component of this K-moduli space has been described in [13], and all its one-dimensional components have been described in [1].

Award Identifier / Grant number: EP/V054597/1

Award Identifier / Grant number: EP/V055399/1

Award Identifier / Grant number: 22K03269

Award Identifier / Grant number: IBS-R003-D1

Funding statement: Ivan Cheltsov was supported by EPSRC grant EP/V054597/1, Tiago Duarte Guerreiro was supported by EPSRC grant EP/V055399/1, Kento Fujita was supported by JSPS KAKENHI Grant Number 22K03269, Igor Krylov was supported by IBS-R003-D1 grant, and Jesus Martinez-Garcia was supported by EPSRC grant EP/V055399/1.

Acknowledgements

This paper was written during our visit to the Gökova Geometry Topology Institute in April 2023. We are very grateful to the institute for its hospitality. We would like to thank Yuchen Liu for his help with the proof of Corollary 1.13, and we would like to thank Noam Elkies for his proof of Proposition 6.3.

References

[1] H. Abban, I. Cheltsov, E. Denisova, E. Etxabarri-Alberdi, A.-S. Kaloghiros, D. Jiao, J. Martinez-Garcia and T. Papazachariou, One-dimensional components in the K-moduli of smooth Fano 3-folds, preprint (2023), https://arxiv.org/abs/2309.12518; to appear in J. Algebraic Geom. 10.1090/jag/839Search in Google Scholar

[2] H. Abban and Z. Zhuang, K-stability of Fano varieties via admissible flags, Forum Math. Pi 10 (2022), Paper No. e15. 10.1017/fmp.2022.11Search in Google Scholar

[3] C. R. Alcántara and J. V. Aquino, Classification of unstable quartic plane curves, Bol. Soc. Mat. Mex. (3) 29 (2023), no. 1, Paper No. 6. 10.1007/s40590-022-00477-wSearch in Google Scholar

[4] J. Alper, Good moduli spaces for Artin stacks, Ann. Inst. Fourier (Grenoble) 63 (2013), no. 6, 2349–2402. 10.5802/aif.2833Search in Google Scholar

[5] J. Alper, H. Blum, D. Halpern-Leistner and C. Xu, Reductivity of the automorphism group of 𝐾-polystable Fano varieties, Invent. Math. 222 (2020), no. 3, 995–1032. 10.1007/s00222-020-00987-2Search in Google Scholar

[6] J. Alper, J. Hall and D. Rydh, A Luna étale slice theorem for algebraic stacks, Ann. of Math. (2) 191 (2020), no. 3, 675–738. 10.4007/annals.2020.191.3.1Search in Google Scholar

[7] C. Araujo, A.-M. Castravet, I. Cheltsov, K. Fujita, A.-S. Kaloghiros, J. Martinez-Garcia, C. Shramov, H. Süß and N. Viswanathan, The Calabi problem for Fano threefolds, London Math. Soc. Lecture Note Ser. 485, Cambridge University, Cambridge 2023. 10.1017/9781009193382Search in Google Scholar

[8] H. Blum, D. Halpern-Leistner, Y. Liu and C. Xu, On properness of K-moduli spaces and optimal degenerations of Fano varieties, Selecta Math. (N.S.) 27 (2021), no. 4, Paper No. 73. 10.1007/s00029-021-00694-7Search in Google Scholar

[9] H. Blum, Y. Liu and C. Xu, Openness of K-semistability for Fano varieties, Duke Math. J. 171 (2022), no. 13, 2753–2797. 10.1215/00127094-2022-0054Search in Google Scholar

[10] H. Blum and C. Xu, Uniqueness of K-polystable degenerations of Fano varieties, Ann. of Math. (2) 190 (2019), no. 2, 609–656. 10.4007/annals.2019.190.2.4Search in Google Scholar

[11] L. Bonavero, F. Campana and J. A. Wiśniewski, Variétés complexes dont l’éclatée en un point est de Fano, C. R. Math. Acad. Sci. Paris 334 (2002), no. 6, 463–468. 10.1016/S1631-073X(02)02284-7Search in Google Scholar

[12] C. Casagrande and S. Druel, Locally unsplit families of rational curves of large anticanonical degree on Fano manifolds, Int. Math. Res. Not. IMRN 2015 (2015), no. 21, 10756–10800. 10.1093/imrn/rnv011Search in Google Scholar

[13] I. Cheltsov and A. Thompson, K-moduli of Fano threefolds in the family 3.10, preprint (2023), https://arxiv.org/abs/2309.12524. Search in Google Scholar

[14] G. Codogni and Z. Patakfalvi, Positivity of the CM line bundle for families of 𝐾-stable klt Fano varieties, Invent. Math. 223 (2021), no. 3, 811–894. 10.1007/s00222-020-00999-ySearch in Google Scholar

[15] D. A. Cox, J. B. Little and H. K. Schenck, Toric varieties, Grad. Stud. Math. 124, American Mathematical Society, Providence 2011. 10.1090/gsm/124Search in Google Scholar

[16] T. Delcroix, K-stability of Fano spherical varieties, Ann. Sci. Éc. Norm. Supér. (4) 53 (2020), no. 3, 615–662. 10.24033/asens.2430Search in Google Scholar

[17] T. Delcroix, Examples of K-unstable Fano manifolds, Ann. Inst. Fourier (Grenoble) 72 (2022), no. 5, 2079–2108. 10.5802/aif.3505Search in Google Scholar

[18] H. Derksen and G. Kemper, Computational invariant theory, Encyclopaedia Math. Sci. 130, Springer, Heidelberg 2015. 10.1007/978-3-662-48422-7Search in Google Scholar

[19] R. Dervan, On K-stability of finite covers, Bull. Lond. Math. Soc. 48 (2016), no. 4, 717–728. 10.1112/blms/bdw029Search in Google Scholar

[20] K. Fujita, Fano manifolds having ( n 1 , 0 ) -type extremal rays with large Picard number, preprint (2012), https://arxiv.org/abs/1212.4977. Search in Google Scholar

[21] K. Fujita, On 𝐾-stability and the volume functions of ℚ-Fano varieties, Proc. Lond. Math. Soc. (3) 113 (2016), no. 5, 541–582. 10.1112/plms/pdw037Search in Google Scholar

[22] K. Fujita, On K-stability for Fano threefolds of rank 3 and degree 28, Int. Math. Res. Not. IMRN 2023 (2023), no. 15, 12601–12784. 10.1093/imrn/rnac190Search in Google Scholar

[23] T. Fujita, Classification theories of polarized varieties, London Math. Soc. Lecture Note Ser. 155, Cambridge University, Cambridge 1990. 10.1017/CBO9780511662638Search in Google Scholar

[24] L. Heuberger and A. Petracci, On K-moduli of Fano threefolds with degree 28 and Picard rank 4, preprint (2023), https://arxiv.org/abs/2303.12562. Search in Google Scholar

[25] C. Huneke and I. Swanson, Integral closure of ideals, rings, and modules, London Math. Soc. Lecture Note Ser. 336, Cambridge University, Cambridge 2006. Search in Google Scholar

[26] D. Hyeon and Y. Lee, Log minimal model program for the moduli space of stable curves of genus three, Math. Res. Lett. 17 (2010), no. 4, 625–636. 10.4310/MRL.2010.v17.n4.a4Search in Google Scholar

[27] N. Ilten and H. Süss, K-stability for Fano manifolds with torus action of complexity 1, Duke Math. J. 166 (2017), no. 1, 177–204. 10.1215/00127094-3714864Search in Google Scholar

[28] C. Jiang, Boundedness of ℚ-Fano varieties with degrees and alpha-invariants bounded from below, Ann. Sci. Éc. Norm. Supér. (4) 53 (2020), no. 5, 1235–1248. 10.24033/asens.2445Search in Google Scholar

[29] J. Kollár, Singularities of pairs, Algebraic geometry—Santa Cruz 1995, Proc. Sympos. Pure Math. 62, American Mathematical Society, Providence (1997), 221–287. 10.1090/pspum/062.1/1492525Search in Google Scholar

[30] Y. Liu, C. Xu and Z. Zhuang, Finite generation for valuations computing stability thresholds and applications to K-stability, Ann. of Math. (2) 196 (2022), no. 2, 507–566. 10.4007/annals.2022.196.2.2Search in Google Scholar

[31] Y. Liu and Z. Zhu, Equivariant 𝐾-stability under finite group action, Internat. J. Math. 33 (2022), no. 1, Article ID 2250007. 10.1142/S0129167X22500070Search in Google Scholar

[32] D. Mallory, On the K-stability of blow-ups of projective bundles, in preparation. Search in Google Scholar

[33] M. Maruyama, Elementary transformations in the theory of algebraic vector bundles, Algebraic geometry, Lecture Notes in Math. 961, Springer, Berlin (1982), 241–266. 10.1007/BFb0071286Search in Google Scholar

[34] S. Mukai, An introduction to invariants and moduli, Cambridge Stud. Adv. Math. 81, Cambridge University, Cambridge 2003. Search in Google Scholar

[35] Y. Odaka, C. Spotti and S. Sun, Compact moduli spaces of del Pezzo surfaces and Kähler–Einstein metrics, J. Differential Geom. 102 (2016), no. 1, 127–172. 10.4310/jdg/1452002879Search in Google Scholar

[36] M. Olsson, Algebraic spaces and stacks, Amer. Math. Soc. Colloq. Publ. 62, American Mathematical Society, Providence 2016. Search in Google Scholar

[37] P. J. Olver, Classical invariant theory, London Math. Soc. Stud. Texts 44, Cambridge University, Cambridge 1999. 10.1017/CBO9780511623660Search in Google Scholar

[38] G. Peano, Formazioni invariantive delle corrispondenze, Giornale Mat. Univ. Ital. 20 (1882), 79–100. Search in Google Scholar

[39] C. Procesi, Lie groups, Universitext, Springer, New York 2007. Search in Google Scholar

[40] Y. G. Prokhorov, Lectures on complements on log surfaces, MSJ Mem. 10, Mathematical Society of Japan, Tokyo 2001. Search in Google Scholar

[41] T. Sano, On deformations of ℚ-Fano 3-folds, J. Algebraic Geom. 25 (2016), no. 1, 141–176. 10.1090/jag/672Search in Google Scholar

[42] E. Sernesi, Deformations of algebraic schemes, Grundlehren Math. Wiss. 334, Springer, Berlin 2006. Search in Google Scholar

[43] T. Tsukioka, Classification of Fano manifolds containing a negative divisor isomorphic to projective space, Geom. Dedicata 123 (2006), 179–186. 10.1007/s10711-006-9122-8Search in Google Scholar

[44] H. Turnbull, Double binary forms. III, Proc. Roy. Soc. Edinburgh 43 (1922/23), 43–50. 10.1017/S037016460002246XSearch in Google Scholar

[45] C. Xu, A minimizing valuation is quasi-monomial, Ann. of Math. (2) 191 (2020), no. 3, 1003–1030. 10.4007/annals.2020.191.3.6Search in Google Scholar

[46] C. Xu, K-stability of Fano varieties: An algebro-geometric approach, EMS Surv. Math. Sci. 8 (2021), no. 1–2, 265–354. 10.4171/emss/51Search in Google Scholar

[47] C. Xu and Z. Zhuang, On positivity of the CM line bundle on K-moduli spaces, Ann. of Math. (2) 192 (2020), no. 3, 1005–1068. 10.4007/annals.2020.192.3.7Search in Google Scholar

[48] K. Zhang and C. Zhou, Delta invariants of projective bundles and projective cones of Fano type, Math. Z. 300 (2022), no. 1, 179–207. 10.1007/s00209-021-02787-7Search in Google Scholar

[49] Z. Zhuang, Optimal destabilizing centers and equivariant K-stability, Invent. Math. 226 (2021), no. 1, 195–223. 10.1007/s00222-021-01046-0Search in Google Scholar

Received: 2023-09-24
Revised: 2024-08-09
Published Online: 2024-10-15
Published in Print: 2025-01-01

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