Home Nonlinear elliptic equations with self-adjoint integro-differential operators and measure data under sign condition on the nonlinearity
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Nonlinear elliptic equations with self-adjoint integro-differential operators and measure data under sign condition on the nonlinearity

  • Tomasz Klimsiak EMAIL logo
Published/Copyright: January 3, 2025

Abstract

We study the existence problem for semilinear equations (E): −Au = f(⋅, u) + μ, with Borel measure μ and operator A that generates a symmetric Markov semigroup. We merely assume that the nonlinear part f is a Carathéodory function satisfying the so-called sign condition. We extend the method of sub and supersolutions for (E) and prove that if such exist, then there exists a solution to (E) (we do not even assume that the subsolution is less than or equal to the supersolution!). We further show that for any μ there exists a unique metric projection μ ̂ of μ onto the set of good measures, i.e. Borel measures for which there exists a solution to (E).

Mathematics Subject Classification (2020): 45K05; 35J61; 35R06; 35R11; 35S15

1 Introduction

1.1 Formulation of the problem

Let E be a locally compact separable metric space and m be a full support positive Radon measure on E. Consider a self-adjoint operator ( A , D ( A ) ) on L 2(E; m) generating a Markov semigroup (T t ), a Carathéodory function f : E × R R satisfying the sign condition:

(1) f ( x , u ) u 0 , u R , m a.e. x E ,

and Borel measure μ on E which obeys E ρ d|μ| < ∞ for a strictly positive weight ρ : E R (class of such measures shall be denoted by M ρ ). In the present paper, we study the existence problem for the following equation:

(2) A u = f ( , u ) + μ .

Throughout the paper, we assume that there exists Green’s function G for A (see Section 2.2), and T t ρρ m-a.e. for any t ≥ 0 (e.g. both ρ ≡ 1 and ρ being the principal eigenfunction for −A satisfy the last requirement). By a solution to (2), we mean a Borel function u on E (finite m-a.e.) such that f ( , u ) L ρ 1 ( E ; m ) , and

(3) u ( x ) = E G ( x , y ) f ( y , u ( y ) ) m ( d y ) + E G ( x , y ) μ ( d y ) , m a.e. x E .

Let ( E , D ( E ) ) be the Dirichlet form generated by ( A , D ( A ) ) :

E ( w , v ) ( A w , A v ) , w , v D ( E ) D ( A ) ,

and Cap be the capacity generated by A: for open UE,

(4) C a p ( U ) inf { E ( w , w ) : w 1 U m a.e. , w D ( E ) } ,

and for arbitrary BE, Cap(B) = inf{Cap(V): BV, V is open}. Using this subadditive set function, we may consider a unique decomposition:

μ = μ d + μ c

of any measure μ M ρ , where μ c  ⊥ Cap and μ d Cap. It is well known (see [1]) that if μCap, then there exists a solution to (2). On the other hand, by [2], Theorem 4.14], for any measure μ M ρ with non-trivial μ c , one can find a function f (even non-increasing and independent of xE) satisfying the above conditions such that there is no solution to (2) with A = Δ on a bounded domain D R d with zero Dirichlet boundary condition. This shows that the presence of the non-trivial concentrated part μ c of measure μ completely changes the picture. Our goal is to study the existence and non-existence mechanism for (2) hidden behind the relation between operator A, right-hand side f and concentrated part μ c .

1.2 Main results of the paper

Fix a strictly positive bounded Borel function ϱL 1(E; m) ∩ L 2(E; m) such that

R ϱ E G ( , y ) ϱ ( y ) m ( d y ) ρ m a.e. ,

and is bounded (the required function always exists, see e.g. [3], Lemma 6.1]). For the existence results, we need one more assumption on f, namely that for any u ̲ , u ̄ L ϱ 1 ( E ; m ) such that f ( , u ̲ ) , f ( , u ̄ ) L ρ 1 ( E ; m ) we have

x sup y [ u ̲ ( x ) , u ̄ ( x ) ] | f ( x , y ) | L ρ 1 ( E ; m ) .

The above condition is satisfied e.g. provided that f is non-increasing with respect to y or there exists an increasing function g on R such that c 1 g ( y ) | f ( x , y ) | c 2 g ( y ) , x E , y R for some c 1, c 2 > 0. In Section 4, we extend Perron’s method of supersolutions and subsolutions and prove the following result (Theorem 1).

Theorem M.1.

Let A, f, μ be as in the foregoing but without imposing (1). Assume that there exists a subsolution u ̲ to (2) and a supersolution u ̄ to (2) such that u ̲ u ̄ , m -a.e. Then, there exists a maximal solution u to (2) such that u ̲ u u ̄ , m -a.e.

The above theorem is a far reaching generalization of [4], Theorem 1.1], where the authors considered equation (2) with A = Δ|D and smooth D.

In order to go further, we extend in Section 5 the theory of reduced measures introduced by Brezis, Marcus and Ponce in [2], [5] for the classical Dirichlet Laplacian and monotone f. Let G ( f ) be a class of measures μ M ρ for which there exists a solution to (2), and for given ν M ρ denote by G ν ( f ) (resp. G ν ( f ) ) the class of measures μ G ( f ) satisfying μν (resp. μν). The measures belonging to G ( f ) are called good measures. As we mentioned before in general G ( f ) M ρ . It appears that for any μ M ρ such that G μ ( f ) , we can always find the biggest measure μ *,f less than μ such that μ * , f G ( f ) – such measure is called a reduced measure. This is, in particular, the content of our second main result (Theorem 2).

Theorem M.2.

Let A, f, μ be as in the foregoing. Assume that G μ ( f ) .

  1. There exists μ * , f G μ ( f ) such that

    μ * , f = max G μ ( f ) .

  2. Let ϕ be a strictly positive function in L ρ 1 ( E , m ) . For any n ≥ 1 there exists a maximal solution u n to

    A u = max { n ϕ , f } ( , u ) + μ .

    Moreover, u n u *,f , where u *,f is a maximal solution to

    A u = f ( , u ) + μ * , f .

  3. μ * , f = μ d μ c + ν for a Borel measure ν on E satisfying 0 ν μ c + .

Notice that ϕ ≡ 1 can be taken provided that ρL 1(E; m).

Clearly, when μ is a good measure, then μ = μ *,f and so, by assertion (2) of the above theorem, for any μ G ( f ) there exists a maximal solution to (2). For brevity, and when there is no risk of confusion, we mostly omit the superscript f on μ *,f and u *,f .

In case G μ ( f ) , we may also consider the problem of the existence of the smallest good measure greater than μ. By a simple calculation we find that

μ * , f ( μ ) * , f ̃ ,

where f ̃ ( x , y ) f ( x , y ) , x E , y R , is a solution to the latter problem. Therefore, by Theorem M.2 provided G μ ( f ) , we get the existence of μ * , f G ( f ) such that

μ * , f = min G μ ( f ) .

Using the notion of reduced measures and the results of Theorems M.1 and M.2, we get the following result (we follow the idea of A.C. Ponce).

Theorem M.3.

Let A, f, μ be as in the foregoing. Assume that there exists a subsolution and a supersolution to (2). Then there exists a maximal solution to (2).

Observe that contrary to Theorem M.1, we do not demand in Theorem M.3 that the subsolution be less than or equal to the supersolution m-a.e.!

In Section 6, we prove a series of results concerning the properties of the set G ( f ) and the reduction operator μμ*. They exhibit that the properties of these two mathematical objects, proved before in the literature for Dirichlet Laplacian and non-increasing f, extend to the general framework considered here. The only troublesome property turns out to be the continuity of μμ*. The proofs of this property known in the literature make essential use of the monotonicity of f and even give Lipschitz continuity of μμ*. Here, due to merely sign condition imposed on f we are forced to adopt a different strategy. Therefore, the main concern of Section 6 will be continuity of the reduction operator. We also observe that certain mapping defined via the reduction operator is a continuous metric projection onto G ( f ) .

Theorem M.4.

Let A, f, μ be as in the foregoing. The set G ( f ) is a convex and closed subset of M ρ equipped with the total variation norm ‖μ ρ E ρ d|μ|. Moreover, the mapping

Π f : M ρ G ( f )

defined as Π f ( μ ) ( μ + ) * + ( μ ) is a continuous metric projection onto G ( f ) , i.e.

Π f ( μ ) μ ρ = inf ν G ( f ) ν μ ρ .

Moreover, if Q : M ρ G ( f ) is a metric projection onto G ( f ) , with a property that for any orthogonal μ , ν M ρ ,

Q ( μ + ν ) = Q ( μ ) + Q ( ν ) ,

then Q = Π f .

One of the illustrative results concerning the structure of the set G ( f ) , easily following from the results of Section 6, is the following equality

G ( f ) = A ( f ) + L ρ 1 ( E ; m ) ,

where A ( f ) is the class of admissible measures: it consists of measures μ M ρ such that | f ( , R μ ) | L ρ 1 ( E ; m ) . In Section 7, we prove much stronger result. Namely, let us set B L ρ 1 ( 0 , r ) u L ρ 1 ( E ; m ) : u L ρ 1 ( E ; m ) r .

Theorem M.5.

Let A, f, μ be as in the foregoing. Moreover, assume that ρ is bounded and there exists ɛ > 0 such that sup | y | ε | f ( , y ) | L ρ 1 ( E ; m ) .

  1. if μ G ( f ) , then u n u in L ϱ 1 ( E ; m ) and 1 n f ( , u n ) 0 in L ρ 1 ( E ; m ) , where

    A u n = 1 n f ( , u n ) + μ , A u = μ .

  2. For any r > 0

    G ( f ) = A ( f ) + B L ρ 1 ( 0 , r ) .

  3. Let cl denote the closure operator in ( M ρ , ρ ) . Then

    G ( f ) = c l A ( f ) .

The last assertion implies that for any g, satisfying the same conditions as f, if

f ( u ) g ( u ) , | u | ,

then μ *,f = μ *,g for positive μ M ρ (see Corollary 10). In other words, the reduction operator and the class of good measures, for f independent of the state variable, depend only on the behavior of f at infinity.

1.3 Some comments on the literature related to the problem

Concerning the existence results for (2) with μCap, we mention the paper by Brezis and Strauss [6], and by Konishi [7], where f is assumed to be non-increasing and independent of xE, and μL 1(E; m), the article by the author of the present paper and A. Rozkosz [8], where f is non-increasing, and their another paper [9], where f merely satisfies the sign condition.

As to the existence results for (2) with general measure data, above all, Bénilan and Brezis’ paper [10] should be mentioned. It was published in 2004, however it summarizes, among other things, the existence and non-existence results on the problem (2), with A = Δ and non-increasing f, achieved in the period 1975–2004 (see Appendix A in [10]).

In 2004 Brezis, Marcus and Ponce [2], [5] introduced the notion of reduced measures for (2) with A = Δ and f being non-increasing. Since then the research on equations of the form (2) has flourished once more, mostly with A being the Dirichlet Laplacian or Dirichlet (rarely regional) fractional Laplacian. We limit ourselves to mentioning [4], [11], [12], [13], [14], [15] in case of Dirichlet Laplacian or divergence form diffusion operators and [16], [17], [18], [19], [20] in case of the fractional Laplacian.

The theory of reduced measures introduced in [2], [5] for the Laplace operator has been generalized by the author of the present paper in [21] to the class of Dirichlet operators considered here but with f being non-increasing as in [2], [5]. The goal of the present paper is to analyze equation (2) under the assumption that f merely satisfies the sign condition (1).

The main results of the present paper may be divided into three groups. Theorem M.2 belongs to the first one and it is the extension to f’s satisfying sign condition (1) of the theory of reduced measure that is the main concern of [21] (also a slight strengthening it since in [21] we assumed that f(⋅, y) = 0 for y ≤ 0). The second group (Theorems M.1 and M.3) consists of problems that are only in (substantial) question for non-monotone f and has been considered before solely for diffusion/Laplace operator (see [4], [15]). Theorems M.4 and M.5 fall into the third group that consists of the results that partially strengthen the existing results for monotone f and generalize them to f satisfying sign condition (1).

2 Notation, basic notions and standing assumptions

As it was said in the introduction A is assumed to be a self-adjoint operator on L 2(E; m) generating a strongly continuous Markov semigroup ( T t ) t 0 on L 2(E; m) so called Dirichlet operators. Thus, ( T t ) t 0 is a contraction on L 2(E; m) and, as a result, (0, ∞) is a subset of the resolvent set for ( T t ) t 0 . By ( J α ) α > 0 we denote the resolvent family for ( T t ) t 0 on L 2(E; m). Throughout the paper, we assume that ( T t ) t 0 is transient, i.e. there exists a strictly positive function gL 2(E; m) such that

J 0 g esssup n 1 0 n T t g d t < m a.e.

Moreover, we assume that there exists the Green function G for A. The precise meaning of this condition shall be explained in Section 3.

In what follows we fix a strictly positive excessive function (see Section 2.2) ρ and strictly positive bounded Borel measurable function ϱL 1(E; m) ∩ L 2(E; m) such that J 0 ϱ is bounded and

(5) J 0 ϱ ρ m a.e.

For the existence of ϱ see e.g. [3], Lemma 6.1]. Observe that if m(E) < ∞ and E is Green bounded, i.e.

sup x E E G ( x , y ) m ( d y ) < ,

then we may take ϱρ ≡ const. We also consider the following condition

  1. for any u ̲ , u ̄ L ϱ 1 ( E ; m ) such that u ̲ u ̄ and f ( , u ̲ ) , f ( , u ̄ ) L ρ 1 ( E ; m ) we have

x sup y [ u ̲ ( x ) , u ̄ ( x ) ] | f ( x , y ) | L ρ 1 ( E ; m ) .

Observe that (A1) is easily verified provided f is non-increasing with respect to y or there exists an increasing function g : R R such that c 1 g ( y ) | f ( x , y ) | c 2 g ( y ) , x E , y R for some c 1, c 2 > 0. By M ρ we denote the set of Borel measures on E such that

μ ρ E ρ d | μ | < .

B ( E ) stands for the set of Borel measurable function on E, and B b ( E ) (resp. B + ( E ) ) is a subset of B ( E ) consisting of bounded (resp. positive) functions. For given Borel measure μ on E and η B ( E ) such that E |η| d|μ| < ∞ we let

η , μ E η d μ .

We also denote by ημ a Borel measure on E defined by

ξ , η μ ξ η , μ , ξ B b ( E ) .

By ( E , D ( E ) ) , we denote a symmetric Dirichlet form on L 2(D; m) generated by ( A , D ( A ) ) defined as follows: D ( E ) D ( A ) , and E ( u , v ) ( A u , A v ) , u , v D ( E ) . Throughout the paper, we assume that ( E , D ( E ) ) is regular, i.e. C c ( E ) D ( E ) is dense in D ( E ) with the norm  E 1 E ( , ) + ( , ) L 2 ( E ; m ) 1 / 2 and in C c (E) with the uniform convergence norm. Self-adjoint Dirichlet operators with regular associated form ( E , D ( E ) ) shall be called regular.

2.1 Elements of potential theory

Let us remind that Cap is a set function defined by (4). We say that a property P holds quasi-everywhere (q.e. for short) on E if it holds except a set BE such that Cap(B) = 0. An increasing sequence {F n } of closed subsets of E is called a nest iff Cap(E\F n ) → 0, n → ∞. A function u on E is called quasi-continuous iff for any ɛ > 0 there exists a closed set F ɛ E such that Cap(E\F ɛ ) ≤ ɛ and u | F ε is continuous. By [22], Theorem 2.1.2], u is quasi-continuous if and only if there exists a nest {F n } such that for any n ≥ 1, u | F n is continuous. An increasing sequence {F n } of closed subsets of E is called a generalized nest iff for every compact KE, Cap(K\F n ) → 0, n → ∞. A Borel measure μ on E is called smooth iff it is absolutely continuous with respect to Cap, and there exists a generalized nest {F n } such that |μ|(F n ) < ∞, n ≥ 1. M ρ 0 stands for a subset of M ρ consisting of smooth measures. We say that a measurable function u on E is quasi-integrable iff for every ɛ > 0 there exists a closed set F ɛ E such that Cap(E\F ɛ ) ≤ ɛ and 1 F ε u L 1 ( E ; m ) . We say that a measurable function u on E is locally quasi-integrable iff for every compact KE, 1 K u is quasi-integrable.

Proposition 1.

A measurable function u on E is locally quasi-integrable iff there exists a generalized nest {F n } such that 1 F n u L 1 ( E ; m ) , n 1 .

Proof.

Sufficiency. Consider a compact set KE. We shall show that 1 K u is quasi-integrable. Fix ɛ > 0. Let V be a relatively compact open set such that KV. By the assumption there exists a closed set F n ε such that C a p ( V ̄ \ F n ε ) ε and 1 F n ε u L 1 ( E ; m ) . Set F ε = V c F n ε . Then 1 F ε K u L 1 ( E ; m ) and

C a p ( E \ F ε ) = C a p ( V \ F n ε ) C a p ( V ̄ \ F n ε ) ε .

Necessity. Let {E n } be an increasing sequence of relatively compact open sets such that ⋃ n≥1 E n = E. By the assumption for every n ≥ 1 there exists closed F k n E n such that C a p ( E n \ F k n ) 1 n and 1 F k n u L 1 ( E ; m ) . Set

F n = j = 1 n F k j .

Clearly {F n } is an increasing sequence of closed sets and 1 F n u L 1 ( E ; m ) , n 1 . Let KE be a compact set. Then there exists n 0 ≥ 1 such that KE n , nn 0. For nn 0,

C a p ( K \ F n ) C a p ( E n \ F k n ) 1 n .

Therefore, {F n } is a generalized nest.□

Since we assumed that (T t ) is transient, there exists a strictly positive function g on E such that

E | u | g d m E ( u , u ) 1 / 2 , u D ( E ) .

Therefore, there exists the extension D e ( E ) of D ( E ) such that: D e ( E ) L 1 ( E ; g m ) , D ( E ) = D e ( E ) L 2 ( E ; m ) , and for any u D e ( E ) , there exists a sequence { u n } D ( E ) that is a Cauchy sequence in the norm  E and satisfies u n u in L 1(E; gm) and E ( u n , u n ) E ( u , u ) (see [22], Theorem 1.5.1, Theorem 1.5.2]). Clearly, ( E , D e ( E ) ) is a Hilbert space. By [22], Theorem 2.1.7], any u D e ( E ) possesses an m-version which is quasi-continuous. In what follows for u D e ( E ) we denote by u ̃ quasi-continuous m-version of u.

2.2 Probabilistic potential theory

Let be either an isolated point added to E provided E is compact or a one-point compactification of E provided E is not compact. We let E E ∪ {}. Throughout the paper, we adopt the convention that whenever f is a function defined on BE, then it is automatically extended to B ∪ {} by putting f() = 0. Let

Ω ω : [ 0 , ) E : ω  is c ádlág, and  ω ( s ) = , s t  whenever  ω ( t ) = .

Recall that a function ω: [0, ∞) → E is called cádlág if it is right-continuous on [0, ∞) and left-limited on (0, ∞). We endow Ω with the Skorohod topology d. Then (Ω, d) is a separable metric space (see [23], Section 12]). We also consider shift operators ( θ t ) t 0 :

θ t : Ω Ω , θ t ( ω ) ( s ) ω ( s + t ) , s , t 0 ,

and a family of projection operators (also called the canonical process) X t : Ω → E , t ≥ 0, X t (ω) ≔ ω(t), ω ∈ Ω. Let F t 0 σ ( X s 1 ( B ) : s t , B B ( E ) ) . By [22], Theorem 7.2.1], there exists a family ( P x ) x E of Borel probability measures on Ω and a right-continuous filtration ( F t ) t 0 on Ω such that X ( P x ) x E , ( F t ) t 0 is a Hunt process on E associated with ( A , D ( A ) ) , i.e. for any f B b ( E ) L 2 ( E ; m ) ,

(6) T t f ( x ) = Ω f ( X t ( ω ) ) P x ( d ω ) , t 0 , m -a.e.

By the very definition of a Hunt process, F t 0 F t , t 0 . The question of uniqueness of X is treated in [22], Theorem 4.2.8]. Let ζ stand for the lifetime of process X , i.e.

ζ ( ω ) inf { t 0 : X t ( ω ) = } .

We let F σ ( F t : t 0 ) . For t ∈ [0, ∞], we denote by b F t a set of bounded real valued F t measurable functions. In what follows, we consider the following notation

E x F Ω F ( ω ) P x ( d ω ) , F b F

We define for any f B + ( E ) ,

P t f ( x ) E x f ( X t ) , R α f ( x ) E x 0 e α s f ( X s ) d s , t 0 , α 0 , x E .

We let RR 0. We say that a property P holds almost surely (a.s.) (resp. quasi almost surely (q.a.s.)) on Ω if it holds P x -a.s. for any xE (resp. for q.e. xE). A Borel measurable positive function f on E is called α -excessive, where α ≥ 0, if

sup t > 0 e α t P t f ( x ) = f ( x ) , x E .

In case α = 0, we just say that f is excessive.

Recall that a family ( A t ) t 0 of R { + } valued functions on Ω is called an additive functional of X if there exist Λ F and NE such that

  1. θ t (Λ) ⊂ Λ, t ≥ 0, Cap(N) = 0, P x (Λ) = 1, xE\N,

    furthermore, for any ω ∈ Λ,

  2. A t+s (ω) = A s (ω) + A t (θ s ω), s, t ≥ 0,

  3. |A t (ω)| < ∞, t ∈ [0, ζ(ω)),

  4. tA t (ω) is cádlág on [0, ζ(ω)),

  5. A t (ω) = A ζ(ω)(ω), tζ(ω),

  6. for any t ≥ 0, A t is F t -measurable, and A 0(ω) = 0.

Λ is called a defining set of (A t ), and N is called an exceptional set of (A t ). An additive functional (AF for short) (A t ) of X is said to be positive if A t (ω) ≥ 0, t ≥ 0, ω ∈ Λ. We say that an AF (A t ) of X is continuous if tA t (ω) is continuous on [0, ∞) for any ω ∈ Λ. In what follows, we frequently use the notion of positive continuous additive functionals (PCAF for short) of X . We say that (A t ) is a martingale additive functional (MAF for short) of X if it is an AF of X and an ( F t ) -martingale under measure P x for any xE\N. Analogously, we say that (A t ) is a local MAF of X if it is an AF of X , and it is a local ( F t ) -martingale under measure P x for any xE\N. By [22], Theorem 5.1.4] there is a ono-to-one correspondence between PCAFs of X and positive smooth measures so called Revuz duality. PCAF (A t ) of X and positive smooth measure ν on E are in Revuz duality if for any positive f B ( E ) ,

E x 0 f ( X r ) d A r = E G ( x , y ) f ( y ) ν ( d y ) , x E \ N .

By [22], Theorem 5.1.3, Theorem 5.1.4], there exists a unique PCAF of X satisfying the above identity for any f B + ( E ) . We shall denote it by A ν . We say that ν is strictly smooth if the exceptional set N of A ν is empty.

Proposition 2.

A positive Borel measure μ on E is smooth iff it is absolutely continuous with respect to Cap and there exists a strictly positive quasi-continuous function u on E such that E u dμ < ∞.

Proof.

Sufficiency. Since u is quasi-continuous there exists a nest {F n } such that u | F n is quasi-continuous for every n ≥ 1. Let {E n } be an increasing sequence of relatively compact open sets such that ⋃ n≥1 E n = E. Set F ̃ n = E ̄ n F n . Obviously, { F ̃ n } is a generalized nest. Moreover, by continuity of u | F n and compactness of E ̄ n , inf F ̃ n u = c n > 0 . Thus

μ ( F ̃ n ) 1 c n E u d μ < , n 1 .

Necessity. Let ϕ be a strictly positive bounded function such that is bounded (see [24], Corollary 1.3.6]) and ϕL 1(E; m). Set

η ( x ) E x 0 ζ ϕ ( X r ) e A r μ d r , x E .

By [22], Lemma 5.1.5], η, are quasi-continuous, and

E x 0 ζ η ( X r ) d A r μ R ϕ ( x ) , q.e.

From this and [22], Theorem 5.1.3],

E η R ϕ d μ = E E x 0 ζ η ( X r ) d A r μ ϕ ( x ) m ( d x ) R ϕ , ϕ R ϕ ϕ L 1 ( E ; m ) .

Function u = ηRϕ fullfils the requirements.□

Corollary 1.

Let u be a measurable function on E. Then u is locally quasi-integrable iff

P x 0 t | u ( X r ) | d r < , t < ζ = 1 , q.e.

Proof.

Follows from [22], Theorem 5.1.4] and Proposition 1.□

3 Green’s functions

We say that a Borel measurable function G : E × E R + { + } is the Green function for A if

R f ( x ) = E G ( x , y ) f ( y ) m ( d y ) , x E , f B + ( E ) ,

and G(x, ⋅), G(⋅, y) are excessive for any x, yE. By [22], Theorem 4.2.4], there exists the Green function for −A if and only if P t f(x) = 0 for any xE and t > 0 provided f B + ( E ) and E f dm = 0. Furthermore, by [22], Lemma 4.2.4], there exists the Green function for A if and only if R α f(x) = 0 for any xE and α > 0 provided f B + ( E ) and E f dm = 0.

At this point, we would like to formulate a general condition guaranteeing the existence of the Green function for the operator A. For f B ( E ) , we let |f| ≔ sup xE |f(x)|. We also let C (E) denote the set of fC b (E) such that for any ɛ > 0 there exists compact set K ɛ E such that sup xE\K |f(x)| ≤ ɛ. In the result below we denote by f ̄ continuous m-version of a function fL 2(E; m) provided that it exists.

Proposition 3.

Let ( E , D ( E ) ) be a regular symmetric Dirichlet form with the associated semigroup (T t ) that is Feller:

  1. T t (C (E)) ⊂ C (E), t > 0 in the sense that each function T t f, with fC (E), possesses continuous m-version T t f ̄ that belongs to C (E);

  2. | T t f ̄ f | 0 as t → ∞ for any fC (E).

Furthermore, suppose that its resolvent ( J α ) α > 0 is strongly Feller: for some α > 0 (hence for any α > 0) J α (L 2(E; m) ∩ L (E; m)) ⊂ C b (E) (inclusion is understood as in (i)). Then there exists the Green function for A.

Proof.

The semigroup S t f T t f ̄ is a Feller semigroup on C (E). By [25], Theorem I.9.4] there exists a Hunt process X such that (6) holds for any xE and fC (E) but with T t replaced by S t . By the Riesz theorem there exists kernel p t (x, dy) such that

S t f ( x ) = E f ( y ) p t ( x , d y ) m ( d y ) , x E , f C ( E ) .

By the definition of S t and strong Feller property of (T t ) we conclude the result.□

Let φ : R + R + be a strictly increasing function with φ(0) = 0 and

(7) A u ( x ) = lim r 0 R d \ B ( x , r ) a ( x , y ) ( u ( x ) u ( y ) ) | x y | d φ ( | x y | ) d y .

with symmetric a B ( R d × R d ) . Consider the following conditions:

  1. there exist c 1, c 2 > 0 such that

    c 1 a ( x , y ) c 2 , x , y R d ,

  2. there exists c 3 > 0 such that

    0 r s φ ( s ) d s c 3 r 2 φ ( r ) , r > 0 ,

  3. there exist c 4, c 5, δ 1, δ 2 > 0 such that

    c 4 R r δ 1 φ ( R ) φ ( r ) c 5 R r δ 2 , 0 < r R .

By [26], Theorem 1.2], we get the following result.

Proposition 4.

Let A be the operator of the form (7) satisfying (A)–(C). Then A generates a regular symmetric Dirichlet form ( E , D ( E ) ) and there exists the Green function for A.

3.1 Part of A on an open set DE

For a given self-adjoint Dirichlet operator A and an open set DE, we may define self-adjoint Dirichlet operator A |D as follows: let

E | D ( u , v ) E ( u , v ) , u , v D ( E | D ) { w D ( E ) : w ̃ = 0 q.e. on  E \ D } .

By [22], Theorem 4.4.3], E | D is a Dirichlet form, and if E is regular, then E | D is regular too. Therefore, by [22], Theorem 1.3.1, Theorem 1.4.1], there exists a unique self-adjoint Dirichlet operator ( B , D ( B ) ) on L 2(D; m) (⊂ L 2(E; m)) such that D ( B ) D ( E | D ) , and

( B u , v ) L 2 ( D ; m ) = E | D ( u , v ) , u D ( B ) , v D ( E | D ) .

We let A |D B. The operator A |D is called a part of A on D (or restriction of A to D). This operation on a Dirichlet operator A is often used when approaching the Dirichlet problem on D for A.

3.2 Perturbation of A by a smooth measure

Let ν be a positive smooth measure on E, and A be a regular self-adjoint Dirichlet operator on L 2(E; m). Define

E ν ( u , v ) E ( u , v ) + E u ̃ v ̃ d ν , u , v D ( E ν ) { w D ( E ) : w ̃ L 2 ( E ; ν ) } .

By [27], Theorem IV.4.4], E ν is a symmetric Dirichlet form on L 2(E; m). Therefore, there exists a unique self-adjoint operator B on L 2(E; ν) such that D ( B ) D ( E ν ) , and

( B u , v ) L 2 ( E ; m ) = E ν ( u , v ) , u D ( B ) , v D ( E ν ) .

We set A ν B. Formally, −A ν = −A + ν, so −A ν may be called a perturbation of −A be the measure ν.

3.3 Resurrected (censored) operator

Let A be a regular self-adjoint Dirichlet operator on L 2(E; m) with regular symmetric Dirichlet form ( E , D ( E ) ) . By the Beurling–Deny formulae (see [22], Theorem 3.2.1]) for any u , v C c ( E ) D ( E ) ,

(8) E ( u , v ) = E ( c ) ( u , v ) + E × E \ diag ( u ( x ) u ( y ) ) ( v ( x ) v ( y ) ) J ( d x , d y ) + E u v d κ ,

where E ( c ) is a symmetric form, with domain D ( E ( c ) ) = D ( E ) C c ( E ) , which satisfies the strong local property:

E ( c ) ( u , v ) = 0  for  u , v D ( E ( c ) )

such that v is constant on a neighbourhood of supp[u]. J is a symmetric positive Radon measure on E × E\ diag and κ is a positive Radon measure on E. Such E ( c ) , J , κ are uniquely determined by ( E , D ( E ) ) . Let E res ( u , v ) E ( u , v ) E u v d κ . By [28], Theorem 5.2.17], ( E res , D ( E res ) ) is a regular symmetric Dirichlet form on L 2(E; m) with D ( E res ) described in [28], (5.2.25)]. Therefore, there exists a unique self-adjoint Dirichlet operator ( B , D ( B ) ) such that D ( B ) D ( E res ) and

( B u , v ) = E res ( u , v ) , u D ( B ) , v D ( E res ) .

We let A res B. Operator A res is very useful when trying to interpret the Dirichlet problem on D for purely jumping Dirichlet operators A (see e.g. [29]).

Proposition 5.

Let ( A , D ( A ) ) be a regular self-adjoint Dirichlet operator on L 2(E; m). Suppose that there exists the Green function G for −A.

  1. If D is an open subset of E, then there exists the Green function for −A |D .

  2. If ν is a strictly smooth positive measure on E, then there exists the Green function for −A ν .

  3. If the killing measure κ from decomposition (8) is strictly smooth, then there exists the Green function for −A res .

Proof.

(1) It follows from [22], Theorem 4.4.2]. For (2), see [22], Theorem A.2.12]. Ad (3). Let ϕ(x) = 1, xE. Clearly, ϕ(X t ) = 1 {t<ζ}. By the comment preceding Lemma 5.3.3 in [22],

ϕ ( X t ) ϕ ( X 0 ) = A t κ + M t , t 0

is the Doob–Meyer decomposition of supermartingale ϕ(X), where A κ is a PCAF associated with killing measure κ appearing in the Beurling–Deny formulae (8), and M is a martingale additive functional of X . By [30], Theorem 62.19] a family of measures (Q x ) given by

(9) Q x ( F 1 { T < ζ } ) P x ( F m T ) , F b F T , x E , T 0 ,

constitutes a Right Markov process on E, where

m t ϕ ( X t ) ϕ ( X 0 ) e A t κ = ϕ ( X t ) e A t κ = 1 { t < ζ } e A t κ , t 0 .

By [28], Theorem 5.2.17], ((Q x ), X) is a Hunt process associated with E res . By (9), Q x is equivalent to P x for any xE. Thus, there exists the Green function for −A res .□

4 Method of sub- and supersolutions

In what follows f : E × R R . Consider the following conditions.

  • (Car) f is a Carathéodory function, i.e.

    1. xf(x, y) is Borel measurable for any y R ,

    2. yf(x, y) is continuous for m-a.e. xE;

  • (Sig) for any u R , f(x, u)u ≤ 0 m-a.e. xE;

  • (Int) for any u ̲ , u ̄ L 1 ( E ; ϱ m ) such that f ( , u ̲ ) , f ( , u ̄ ) L ρ 1 ( E ; m ) we have

    x sup y [ u ̲ ( x ) , u ̄ ( x ) ] | f ( x , y ) | L ρ 1 ( E ; m ) ;

  • (qM) for any M > 0 the mapping Ex ⟼ sup|y|≤M |f(x, y)| is locally quasi-integrable.

  • (M) for any M > 0 the mapping E x sup | y | M | f ( x , y ) | L ρ 1 ( E ; m ) .

For any μ M ρ , we let μ d denote the part of μ, which is absolutely continuous with respect to Cap, and by μ c we denote the part of μ, which is orthogonal to Cap. Observe that μ d is a smooth measure. Indeed, by the very definition μ d Cap. Now, let g L 2 ( E ; m ) B ( E ) be strictly positive. We have

E R 1 ( ρ g ) d | μ d | E ρ d | μ | < .

We used here the fact that ρ is excessive. Clearly, ηR 1(ρg) is strictly positive. By [22], Theorem 4.2.3], η is quasi-continuous. Therefore, by Proposition 2, μ d is smooth.

Remark 1.

Throughout the paper, we frequently use without special mentioning the following facts.

  1. If μ M ρ , then R|μ| < ∞ q.e. and, as a result, R|μ| is quasi-continuous. The last assertion follows from [21], Theorem 3.1]. At the same time,

    E R | μ | ϱ d m = E R ϱ d | μ | E ρ d | μ | < .

    Thus, since ϱ is strictly positive, we obtain that R|μ| < ∞ m-a.e. By [28], Theorem A.2.13(v)], we have that, in fact, R|μ| < ∞ q.e. (see [22], Lemma 2.1.4]).

  2. If u 1, u 2 are quasi-continuous functions on E, then u 1u 2 m-a.e. if and only if u 1u 2 q.e.

  3. Let B B ( E ) . If Cap(B) = 0, then P x ( t≥0: X t B) = 0 q.e. (see [22], Theorem 4.2.1]).

    Recall that a measurable function τ: Ω → [0, ∞] is called a stopping time if { ω Ω : τ ( ω ) t } F t for any t ≥ 0. We say that a non-decreasing sequence {τ k } of stopping times is a reducing sequence for a measurable function u on E if τ k ζζ q.a.s., and

    E x sup t τ k | u ( X t ) | < , k 0 q.e.

Lemma 1.

Let μ M ρ . Set wR|μ|, u(x) ≔ (x), xE\N and zero on N, where N = {xE: w(x) = ∞}. Then, there exists a local MAF M such that, for any xE\N,

(10) u ( X t ) = u ( X 0 ) 0 t d A r μ d + 0 t d M r , t 0 P x a.s.

Moreover, for τ k ≔ inf{t > 0: w(X t ) ≥ k}∧ k, we have

(11) E x sup t τ k | u ( X t ) | + E x sup t τ k | M t | < , k 0 , x E \ N .

In particular, {τ k } is a reducing sequence for u.

Proof.

By [21], Theorem 3.7], we obtain (10). From the fact that w(X) is a positive supermartingale under the measure P x , for any xE\N (see e.g. [25], Theorem II.2.12]) and from [30], Theorem 51.1], we infer (11). The last assertion is obvious.□

Definition 1.

Let μ M ρ . We say that a measurable function u is a solution to (2) if f ( , u ) L ρ 1 ( E ; m ) and

(12) u ( x ) = E G ( x , y ) f ( y , u ( y ) ) m ( d y ) + E G ( x , y ) μ ( d y ) , m a.e.

Remark 2.

By Remark 1, R|f(⋅, u)| < ∞ q.e., R|μ| < ∞ q.e., and Rf(⋅, u), are quasi-continuous. As a result, one sees that a solution to (2) has always a quasi-continuous m-version. Observe also that by (5), u L ϱ 1 ( E ; m ) .

Proposition 6.

Assume that μ M 1 , and R 1 ( B b ( E ) ) C b ( E ) or uL 1(E; m), R 1(C b (E)) ⊂ C b (E). Then u is a solution to (2) if and only if u is a renormalized solution to (2):

  1. T k ( u ) min { k , max { u , k } } D e ( E ) , k > 0 ;

  2. f(⋅, u) ∈ L 1(E; m);

  3. There exists a family ( ν k ) k 0 M 1 of smooth measures such that ν k μ c in the narrow topology, as k → ∞;

  4. For any bounded η D ( E ) ,

E ( T k ( u ) , η ) = f ( , u ) , η + μ d , η ̃ + ν k , η ̃ .

Proof.

It follows from [31], Theorem 4.9].□

Definition 2.

Let μ M ρ . We say that a measurable function u is a subsolution (resp. supersolution) to (2) if f ( , u ) L ρ 1 ( E ; m ) and there exists a positive measure ν M ρ such that

(13) u ( x ) = E G ( x , y ) f ( y , u ( y ) ) m ( d y ) + E G ( x , y ) μ ( d y ) E G ( x , y ) ν ( d y ) , m a.e.

(resp.)

(14) u ( x ) = E G ( x , y ) f ( y , u ( y ) ) m ( d y ) + E G ( x , y ) μ ( d y ) + E G ( x , y ) ν ( d y ) , m a.e.

Throughout the paper, unless stated otherwise, we always consider quasi-continuous m-versions of solutions, supersolutions and subsolutions to (2). These versions may be defined as right-hand sides of (12), (13) or (14), where finite, and zero otherwise.

Proposition 7

Let u, w be subsolutions to (2). Then uw is a subsolution to (2).

Proof.

By the definitions of sub- and supersolution to (2) there exist positive ν 1 , ν 2 M ρ such that

(15) u = R f ( , u ) + R μ R ν 1 , w = R f ( , u ) + R μ R ν 2 , q.e.

By Lemma 1 there exist local MAFs M, N such that

u ( X t ) = u ( X 0 ) 0 t f ( X r , u ( X r ) ) d r 0 t d A r μ d + 0 t d A r ν d 1 + 0 t d M r , t 0 ,

w ( X t ) = w ( X 0 ) 0 t f ( X r , w ( X r ) ) d r 0 t d A r μ d + 0 t d A r ν d 2 + 0 t d N r , t 0 ,

q.a.s. By the Tanaka-Meyer formula (see, e.g., [32], IV.Theorem 70]) there exists an increasing càdlàg process C, with C 0 = 0, such that

( u w ) ( X t ) = ( u w ) ( X 0 ) 0 t 1 { u w } ( X r ) f ( X r , u ( X r ) ) d r 0 t 1 { u w } ( X r ) d A r μ d + 0 t 1 { u w } ( X r ) d A r ν d 1 + 0 t 1 { u w } ( X r ) d M r 0 t 1 { w > u } ( X r ) f ( X r , w ( X r ) ) d r 0 t 1 { w > u } ( X r ) d A r μ d + 0 t 1 { w > u } ( X r ) d A r ν d 2 + 0 t 1 { w > u } ( X r ) d N r + 0 t d C r , t 0 , q.a.s.

Hence,

(16) ( u w ) ( X t ) = ( u w ) ( X 0 ) 0 t f ( X r , ( u w ) ( X r ) ) d r 0 t d A r μ d + 0 t 1 { u w } ( X r ) d A r ν d 1 + 0 t 1 { w > u } ( X r ) d A r ν d 2 + 0 t d C r + 0 t 1 { u w } ( X r ) d M r + 0 t 1 { w > u } ( X r ) d N r , t 0 , q.a.s.

From the above formula, we deduce that C is an additive functional of X . Thus, C is a positive AF of X . Moreover, since X is a Hunt process and u, w are quasi-continuous, u(X), w(X), M, N have only totally inaccessible jumps (see [22], Theorem 4.2.2, Theorem A.2.1, Theorem A.3.6]). Therefore, dual predictable projection C ̃ of C is continuous. By [22], Theorem A.3.16], C ̃ is a PCAF. Consequently, by [22], Theorem 5.1.4], there exists a positive smooth measure β such that C ̃ = A β . Let {τ k } be a reducing sequence for uw. Then, by (16),

(17) ( u w ) ( x ) = E x ( u w ) ( X τ k ) + E x 0 τ k f ( X r , ( u w ) ( X r ) ) d r + E x 0 τ k d A r μ d E x 0 τ k 1 { u w } ( X r ) d A r ν d 1 E x 0 τ k 1 { w > u } ( X r ) d A r ν d 2 E x 0 τ k d A r β , q.e.

By [21], Theorem 3.7],

E x u ( X τ k ) R μ c ( x ) R ν c 1 ( x ) , E x w ( X τ k ) R μ c ( x ) R ν c 2 ( x ) , q.e.

Moreover, by [21], Theorem 3.7, Theorem 6.3],

E x | u ( X τ k ) w ( X τ k ) | R | ν c 1 ν c 2 | ( x ) , q.e.

Thus,

lim k E x ( u w ) ( X τ k ) = lim k 1 2 E x u ( X τ k ) + E x w ( X τ k ) + E x | u ( X τ k ) w ( X τ k ) | = R μ c ( x ) 1 2 R ν c 1 + ν c 2 | ν c 1 ν c 2 | ( x ) = R μ c ( x ) R ν c 1 ν c 2 ( x ) , q.e.

Therefore, letting k → ∞ in (17), we get

u w = R f ( , u w ) + R μ R 1 { u w } ν d 1 R 1 { w > u } ν d 2 R β R ν c 1 ν c 2 , q.e.

From the fact that uuw and [21], Lemma 4.6], we infer that β M ρ . Therefore, uw is a subsolution to (2).□

Proposition 8.

Assume (Car). Let μ M ρ . Suppose that there exist positive g L ρ 1 ( E ; m ) and c > 0 such that

(18) | f ( x , y ) | c g ( x ) , x E , y R .

Then there exists a solution to (2).

Proof.

Set r c g L ρ 1 ( E ; m ) + μ M ρ . For uL 1(E; ϱm), we let

Φ ( u ) = R f ( , u ) + R μ .

Observe that by (18)

(19) | Φ ( u ) | c R g + R | μ | .

Hence

Φ ( u ) L 1 ( E ; ϱ m ) r .

By (18) and (Car), we get easily that Φ is continuous. Let {u n } ⊂ L 1(E; ϱm). Observe that

Φ ( u n ) = R f + ( , u n ) R f ( , u n ) + R μ

By [33], Lemma 94, page 306], R f + ( , u n ) , R f ( , u n ) have subsequence (still denoted by (n)) convergent m-a.e. Thus, up to subsequence, {Φ(u n )} is convergent m-a.e. By (19) the Lebesgue dominated convergence theorem is applicable, and so, {Φ(u n )} is convergent in L 1(E; ϱm). By Schauder’s fixed point theorem, we get the result.□

Proposition 9.

Assume (Sig). Let u be a subsolution to (2) and w be a supersolution to (2). Then

  1. u + + R f ( , u ) R 1 { u > 0 } μ d + + R μ c + , q.e., and

    f ( , u ) L ρ 1 ( E ; m ) 1 { u > 0 } μ d + M ρ + μ c + M ρ ,

  2. w + R f + ( , w ) R 1 { w 0 } μ d + R μ c , q.e., and

    f + ( , w ) L ρ 1 ( E ; m ) 1 { w 0 } μ d M ρ + μ c M ρ .

Proof.

The proofs of (1) and (2) are analogous. We shall give the proof of (1). Since u is a subsolution, there exists a positive ν M ρ such that

u = R f ( , u ) + R μ R ν , q.e.

By Lemma 1 and the Meyer-Itô formula (see [32], Theorem IV.70])

u + ( x ) E x 0 τ k 1 { u > 0 } ( X r ) f ( X r , u ( X r ) ) d r E x u + ( X τ k ) + E x 0 τ k 1 { u > 0 } ( X r ) d A r μ d E x 0 τ k 1 { u > 0 } ( X r ) d A r ν d , q.e. ,

where {τ k } is a reducing sequence for u. From this and (Sig), we infer that

u + ( x ) + E x 0 τ k f ( X r , u ( X r ) ) d r E x u + ( X τ k ) + E x 0 τ k 1 { u > 0 } ( X r ) d A r μ d , q.e.

Letting k → ∞ and using [21], Theorem 3.7, Theorem 6.3] yields

u + + R f ( , u ) R μ c + + R ( 1 { u > 0 } μ d ) , q.e.

By [21], Lemma 4.6], we get (1).□

Theorem 1.

Let μ M ρ . Assume (Car), (Int).

  1. Let ψL 1(E; ϱm) be such that f ( , ψ ) L ρ 1 ( E ; m ) . Suppose that there exists a subsolution u ̲ to (2) such that u ̲ ψ m -a.e. Then there exists a maximal subsolution u* to (2) such that u* ≤ ψ m-a.e.

  2. Assume that there exists a subsolution u ̲ to (2) and a supersolution u ̄ to (2) such that u ̲ u ̄ , m -a.e. Then there exists a maximal solution u to (2) such that u ̲ u u ̄ , m -a.e. The maximal solution u is at the same time a maximal subsolution lying between u ̲ and u ̄ m -a.e.

  3. Assume (Sig). For any subsolution u ̲ to (2) we have u ̲ R μ + m -a.e.

  4. Assume (Sig). Let ψ : E R { + } be a Borel measurable function. Suppose that there exists a subsolution u ̲ to (2) such that u ̲ ψ m -a.e. Then there exists a maximal subsolution u* to (2) such that u* ≤ ψ m-a.e.

Proof.

Ad (1). Set

S ψ = { v : v is a subsolution to (3) and v ψ m a.e. }

By assumptions S ψ is nonempty. By Remark 2, S ψ L 1 ( E ; ϱ m ) . Let

α = sup v S ψ E v ϱ d m .

By the assumptions made on ψ, α < ∞. Let { v n } S ψ be such that E v n ϱ dmα. Set

u n = max { v 1 , , v n } , n 1 .

By Proposition 7, { u n } S ψ . Set u* = sup n≥1 u n . Clearly, u ̲ u * ψ m -a.e. By the assumptions made on ψ and (Int), we have f ( , u * ) L ρ 1 ( E ; m ) . Since u n is a subsolution to (2) there exists a positive ν n M ρ such that

(20) u n = R f ( , u n ) + R μ R ν n q.e.

Clearly,

(21) u 1 u n u * , n 1 q.e.

Hence

| f ( , u n ) | sup y u 1 , u * | f ( , y ) | g 1 .

By (Int), g 1 L ρ 1 ( E ; m ) . Therefore, by the Lebesgue dominated convergence theorem,

E | R f ( , u n ) R f ( , u * ) | ϱ d m E | f ( , u n ) f ( , u * ) | ρ d m 0 , n .

Thus, up to subsequence, lim n→∞ Rf(⋅, u n ) = Rf(⋅, u*) m-a.e. This in turn implies that ( R ν n ) n 1 is convergent m-a.e. Let η ≔ lim n→∞ n m-a.e. By [33], Lemma 94, page 306], η has an m-version (still denoted by η) such that η is an excessive function. By (20), (21), we have

R ν n R | f ( , u n ) | + R | f ( , u 1 ) | + R | μ | + R | ν 1 | q.e.

Letting n → ∞ and using [25], page 197] yields

η R | f ( , u * ) | + R | f ( , u 1 ) | + R | μ | + R | ν 1 | .

By [34], Proposition 3.9], there exists a positive Borel measure β on E such that η = . From the above inequality and [21], Lemma 4.6], we conclude that β M ρ . Going back to (20) and letting n → ∞, we deduce from what has been already proven that

u * = R f ( , u * ) + R μ R β q.e.

Thus, u * S ψ . What is left is to show that u* is maximal. Let v S ψ . Clearly vu n vu*. By Proposition 7, v u n S ψ . Thus,

α = lim n E v n ϱ d m lim n E u n ϱ d m lim n E v u n ϱ d m α .

By the Lebesgue monotone convergence theorem

E u * ϱ d m = E v u * ϱ d m = α .

Therefore,

E ( v u * u * ) ϱ d m = 0 .

Hence, u* ≤ vu* m-a.e., which implies that vu* m-a.e.

Ad (2). Set

f ̂ ( x , y ) = f ( x , ( y u ̄ ( x ) ) u ̲ ( x ) ) , x E , y R .

By (Int), f ̂ satisfies (18) with g ( x ) sup y [ u ̲ ( x ) , u ̄ ( x ) ] | f ( x , y ) | , x E . Therefore, there exists a solution u ̂ to (2) with f replaced by f ̂ . Since u ̲ is a subsolution to (2), there exists a positive measure ν M ρ such that

u ̲ = R f ( , u ̲ ) + R μ R ν q.e.

By Lemma 1 and the Tanaka-Meyer formula

( u ̲ ( x ) u ̂ ( x ) ) + E x ( u ̲ ( X τ k ) u ̂ ( X τ k ) ) + + E x 0 τ k 1 { u ̲ > u ̂ } ( X r ) ( f ( X r , u ̲ ( X r ) ) f ̂ ( X r , u ̂ ( X r ) ) ) d r E x 0 τ k 1 { u ̲ > u ̂ } ( X r ) d A r ν d q.e.

Observe that, by the definition of f ̂ , 1 { u ̲ > u ̂ } ( f ( , u ̲ ) f ̂ ( , u ̂ ) ) 0 . Thus,

( u ̲ ( x ) u ̂ ( x ) ) + E x ( u ̲ ( X τ k ) u ̂ ( X τ k ) ) + q.e.

Letting k → ∞ and using [21], Theorem 3.6, Theorem 6.3] yields

( u ̲ ( x ) u ̂ ( x ) ) + R ( ν c ) + = 0 q.e. ,

and so u ̲ u ̂ m -a.e. Analogous reasoning for u ̂ , u ̄ shows that u ̂ u ̄ m -a.e. Consequently, f ̂ ( , u ̂ ) = f ( , u ̂ ) m -a.e. Therefore, u ̂ is, in fact, a solution to (2) and u ̲ u ̂ u ̄ m -a.e. Now, we shall show the existence of a maximal solution to (2) lying between u ̲ , u ̄ . Applying (1) with ψ = u ̄ gives the existence of a maximal subsolution u* to (2) such that u ̲ u * u ̄ m -a.e. By what has been already proven, there exists a solution u ̂ to (2) such that u * u ̂ u ̄ m -a.e. On the other hand, since u ̂ also is a subsolution to (2), u ̂ u * m -a.e. Thus, u ̂ = u * m -a.e. Now, we easily deduce that u* is a maximal solution to (2).

Ad (3) Let w = +, and v be a subsolution to (2). By the definition of a subsolution to (2) there exists a positive ν M ρ such that

v = R f ( , v ) + R μ R ν q.e.

By Lemma 1 and the Tanaka-Meyer formula

( v ( x ) w ( x ) ) + E x ( v ( X τ k ) w ( X τ k ) ) + + E x 0 τ k 1 { v > w } ( X r ) f ( X r , v ( X r ) ) d r E x 0 τ k 1 { u > w } ( X r ) d A μ d E x 0 τ k 1 { u > w } ( X r ) d A ν d ,

where {τ k } is a reducing sequence for vw. Since w is positive, we have, by (Sig), that 1 {v>w} f(⋅, v) ≤ 0. Consequently,

( v ( x ) w ( x ) ) + E x ( v ( X τ k ) w ( X τ k ) ) + q.e.

By [21], Theorem 3.7, Theorem 6.3],

lim k E x ( v ( X τ k ) w ( X τ k ) ) + = R μ c ν c μ c + + ( x ) = 0 q.e.

Therefore, vw m-a.e.

Ad (4). We maintain the notation of the proof of (1). The proof of (4) runs exactly the same lines as the proof of (1) but with different justification of the facts that α < ∞ and f ( , u * ) L ρ 1 ( E ; m ) . The first property is a consequence of (3). For the second one, observe that, by (Sig),

(22) | f ( , u * ) | = f ( , u * ) + f ( , ( u * ) ) .

By Proposition 9,

f ( , u n ) L ρ 1 ( E ; m ) μ M ρ

By Fatou’s lemma f ( , u * ) L ρ 1 ( E ; m ) . At the same time, we have

u 1 ( u * ) 0 .

Therefore by (Int), f ( , ( u * ) ) L ρ 1 ( E ; m ) . Consequently, by (22), f ( , u * ) L ρ 1 ( E ; m ) .□

Proposition 10.

Assume (Car), (Int). Let u ̲ (resp. u ̄ ) be a subsolution (resp. supersolution) to (2). Let μ ̃ M ρ , f ̃ be a measurable function on E × R , and u ̃ be a solution to (2) with f, μ replaced by f ̃ , μ ̃ such that u ̲ u ̃ u ̄ m -a.e. Let u be a maximal solution to (2) such that u ̲ u u ̄ m -a.e. Assume that f ̃ ( , u ̃ ) f ( , u ̃ ) m -a.e. and μ ̃ μ . Then u ̃ u m -a.e.

Proof.

Observe that

A u ̃ = f ( , u ̃ ) + μ ( f ( , u ̃ ) f ̃ ( , u ̃ ) ) ( μ μ ̃ ) .

By (Int), f ( , u ̃ ) L ρ 1 ( E ; m ) . Therefore, u ̃ is a subsolution to

A u = f ( , u ) + μ .

By Theorem 1(2), u is a maximal subsolution to the above problem lying between u ̲ and u ̄ m -a.e. Thus, u ̃ u m -a.e.□

5 Existence of maximal and minimal good measure

5.1 Standing assumption

In the remainder of the paper, we assume that conditions (Car), (Sig), (Int) and (qM) are in force.

We begin with the following lemma which will be crucial in our proof techniques when passing to the limit in variety of semilinear equations.

Lemma 2.

Assume that {u n } is a sequence of quasi-continuous functions on E, u B ( E ) and {τ k } is a non-decreasing sequence of stopping times such that τ k ζ q.a.s. Suppose that for some p > 0 and any k ≥ 1,

(23) E x sup 0 t τ k | u n ( X t ) u ( X t ) | p 0 , as n q . e .

Then u is quasi-continuous.

Proof.

By [22], Theorem 4.2.2] process u n (X) is right-continuous on [0, ∞) q.a.s. Therefore, by (23), u shares this property too. Consequently, by [22], Theorem 4.6.1, Theorem A.2.7], u is quasi-continuous.□

We say that μ M ρ is a good measure iff there exists a solution to (2). We let G ( f ) denote the set of all good measures. It is clear that G ( f ) also depends on A.

Theorem 2.

Assume that there exists a subsolution u ̲ to (2). Let u* be a maximal subsolution to (2) (cf. Theorem 1(4)). Set

(24) μ * A u * f ( , u * )

in the sense that μ* = μν, where ν comes from the definition of a subsolution to (2) applied to u* (see Definition 2). Then ( μ * ) d = μ d , μ* is the largest measure less then μ such that (2) has a solution with μ replaced by μ*, and u* is a maximal solution to

(25) A v = f ( , v ) + μ * .

Moreover, for any n ≥ 1 and strictly positive ϕL 1(E, ρm), there exists a maximal solution u n to

(26) A v = max { n ϕ , f } ( , v ) + μ ,

and u n u* m-a.e. Furthermore, for any solution u to (25), and any reducing sequence {τ k } for u, we have

(27) E x u ( X τ k ) R ( μ * ) c ( x ) , q.e.

Proof.

Let ϕ be a strictly positive bounded Borel function on E such that ϕ L ρ 1 ( E ; m ) . Set

f n ( x , y ) = f ( x , y ) ( n ϕ ) , x E , y R .

Clearly, f n satisfies (Sig) and f n f n+1f, n ≥ 1. Let w +. Observe that

0 f n ( , w ) = f n ( , w ) n ϕ .

Thus, f n ( , w ) L ρ 1 ( E ; m ) . Moreover,

A w = f n ( , w ) + μ + ( f n ( , w ) + μ ) .

Consequently, w is a supersolution to (26). Set u ̄ w . Since u ̲ is a subsolution to (2), there exists a positive ν M ρ such that

A u ̲ = f ( , u ̲ ) + μ ν .

Therefore,

A u ̲ = f n ( , u ̲ ) + μ ( f n ( , u ̲ ) f ( , u ̲ ) ) ν .

Hence, u ̲ is a subsolution to (26). By Theorem 1(3), u ̲ u ̄ m -a.e. Consequently, by Theorem 1, there exists a maximal solution u n to (26) such that u ̲ u n u ̄ m -a.e. By Proposition 10, u n u n+1, n ≥ 1 q.e. Put u = inf n≥1 u n q.e. By Proposition 9,

(28) | u n | + R | f n ( , u n ) | R | μ | , q.e. , f n ( , u n ) L ρ 1 ( E ; m ) μ M ρ .

Therefore, by Fatou’s lemma and (Car),

(29) | u | + R | f ( , u ) | R | μ | , q.e. , f ( , u ) L ρ 1 ( E ; m ) μ M ρ .

Let {δ k } be a common reducing sequence for u ̲ , u ̄ . Let

σ k = inf { t 0 : | u ̲ ( X t ) | + | u ̄ ( X t ) | k } k , σ ̂ k , j = inf { t 0 : 0 t sup | y | k | f ( X r , y ) | d r j } .

By the definition of a reducing sequence lim k→∞ δ k ζ = ζ. Since u ̲ , u ̄ are quasi-continuous, lim k→∞ σ k ζ = ζ (see [22], Theorem 4.2.2]). Finally, by (qM) and Corollary 1, lim j σ ̂ k , j ζ = ζ . Let τ k , j δ k σ k σ ̂ k , j . Observe that

(30) τ k , j τ k δ k σ k , j .

By Lemma 1,

(31) u n ( X t τ k , j ) = E x u n ( X τ k , j ) + t τ k , j τ k , j f n ( X r , u n ( X r ) ) d r + t τ k , j τ k , j d A r μ d F t τ k , j q.a.s.

By [35], Lemma 6.1], for any q ∈ (0, 1), there exists c q > 0 such that

( E x sup 0 t τ k , j | u n ( X t ) u l ( X t ) | q ) 1 / q c q E x | u n ( X τ k , j ) u l ( X τ k , j ) | + 0 τ k , j | f n ( X r , u n ( X r ) ) f l ( X r , u l ( X r ) ) | d r q.e .

Due to the choice of {τ k,j } and Remark 1(c), the right-hand side of the above equation tends to zero as n, l → ∞. Consequently, by Lemma 2, u is quasi-continuous. Taking t = 0 in (31), we get

(32) u n ( x ) = E x u n ( X τ k , j ) + E x 0 τ k , j f n ( X r , u n ( X r ) ) d r + E x 0 τ k , j d A r μ d q.e.

Letting n → ∞ and using properties of {τ k,j } and Remark 1(c) yields

(33) u ( x ) = E x u ( X τ k , j ) + E x 0 τ k , j f ( X r , u ( X r ) ) d r + E x 0 τ k , j d A r μ d q.e.

Applying (29), (30) and the fact that {τ k } is a reducing sequence for u, we find, by letting j → ∞ in (33), that

(34) u ( x ) = E x u ( X τ k ) + E x 0 τ k f ( X r , u ( X r ) ) d r + E x 0 τ k d A r μ d q.e.

Now, we shall show that there exists β M ρ such that u = . For this, observe that

(35) u n = v n w n q . e . ,

where v n = R f n + ( , u n ) + R μ + and w n = R f n ( , u n ) + R μ . Clearly, v n , w n are excessive functions. Moreover, by (28)

(36) v n 2 R | μ | , w n 2 R | μ | q.e.

Therefore, by [33], Lemma 94, page 306] there exists a subsequence (still denoted by (n)) and excessive functions v, w such that v n v and w n w m-a.e. By [34], Proposition 3.9], there exist positive Borel measures β 1, β 2 such that v = 1, w = 2. By (36) and [21], Lemma 4.6], β 1 , β 2 M ρ . Set β = β 1β 2. Due to (35), and the fact that u, are quasi-continuous, see Remark 1, we get u = q.e. Consequently, by [21], Theorem 3.7]

E x u ( X τ k ) R β c ( x ) , q.e.

Therefore, letting k → ∞ in (34) and using (29) yields

(37) u = R f ( , u ) + R μ d + R β c , q.e.

Since uu n , we get, by the inverse maximum principle (see [21], Theorem 6.1]) that β c μ c . Observe that

A u = f ( , u ) + μ ( μ c β c ) .

Thus, u is a subsolution to (2), which in turn implies that uu*. On the other hand, by Proposition 10, u* ≤ u n , n ≥ 1. Thus u = u*. Consequently, μ* = μ d + β c , and so ( μ * ) d = μ d . What is left is to show that μ* is the maximal measure less then μ for which there exists a solution to (2) with μ replaced by μ*. Let γ M ρ , γμ and v be a solution to

A v = f ( , v ) + γ .

Since γμ, we have that γ d μ d and γ c μ c . We have already proved that ( μ * ) d = μ d . So that, we only have to prove that γ c ( μ * ) c . Since γμ, v is a subsolution to (2). Thus, vu*. By the inverse maximum principle γ c ( μ * ) c .□

Analogous reasoning, but for supersolutions, leads to the following result.

Theorem 3.

Assume that there exists a supersolution u ̄ to (2). Let u be a minimal supersolution to (2). Set

μ A u f ( , u ) .

Then ( μ ) d = μ d , μ is the smallest measure greater then μ such that (2) has a solution with μ replaced by μ , and u is a minimal solution to

(38) A v = f ( , v ) + μ .

Moreover, for any n ≥ 1 and strictly positive ϕL 1(E, ρm), there exists a minimal solution u n to

A v = min { n ϕ , f } ( , v ) + μ ,

and u n u .

Remark 3.

By Theorems 2 and 3 if μ G ( f ) , then u* is a maximal solution (subsolution) to (2) and u is a minimal solution (supersolution) to (2).

Proposition 11.

Let μ 1 , μ 2 M ρ and f 1, f 2 satisfy (Car), (Sig), (Int) and (qM). Assume that μ 1μ 2 and f 1f 2. Let u 1, u 2 be solutions to

A v = f 1 ( , v ) + μ 1 , A v = f 2 ( , v ) + μ 2 ,

respectively.

  1. If u 2 is maximal and f 2 ( , h ) L ρ 1 ( E ; m ) for some hL 1(E; ϱm) that satisfies hu 1 m-a.e., then u 1u 2 m-a.e.

  2. If u 1 is minimal and f 1 ( , h ) L ρ 1 ( E ; m ) for some hL 1(E; ϱm) that satisfies u 2h m-a.e., then u 1u 2 m-a.e.

Proof.

The proofs of both results are analogous, so that we only give the the proof of (1).

Step 1. Suppose that f 2 ( , u 1 ) L ρ 1 ( E ; m ) . Observe that

A u 1 = f 2 ( , u 1 ) + μ 2 + ( f 1 ( , u 1 ) f 2 ( , u 1 ) ) + ( μ 1 μ 2 ) .

Therefore, u 1 is a subsolution to −Av = f 2(⋅, v) + μ 2. By Remark 3, u 1u 2 m-a.e.

Step 2. The general case. By Theorem 2, there exists a maximal solution u 1 * to −Av = f 1(⋅, v) + μ 1. By the same theorem, there exist sequences u 1 n , u 2 n such that u 1 n is a maximal solution to A v = f 1 n ( , v ) + μ 1 , u 2 n is a maximal solution to A v = f 2 n ( , v ) + μ 2 , and u 1 n u 1 * , u 2 n u 2 m -a.e. Here f i n ( x , y ) = max { n ϕ ( x ) , f i ( x , y ) } , x E , y R , i = 1, 2, and ϕ is as in Theorem 2. By Theorem 1(3), h u 1 u 1 n R μ 1 + m -a.e. By the assumptions made on h, and by (Int), f 2 n , u 1 n L ρ 1 ( E ; m ) . By Step 1, u 1 n u 2 n m -a.e. Hence, u 1u 2 m-a.e.□

6 The class of good measures and the reduction operator

In this section we shall investigate the class of good measures. Our goal is to provide some properties of the set G ( f ) and the mapping μμ*. The main results of this section are Theorem 4, in which, by applying some basic properties of the mentioned objects, we prove an existence result for (2), and Theorems 5 and 6 devoted to continuity of the operator μμ* and built up from it metric projection onto G ( f ) . Proposition 16 also deserves attention. It is the first result concerning the structure of G ( f ) . In the next section we considerably strengthen this result (Theorem 7).

In what follows we set for given μ M ρ ,

G μ ( f ) = { ν G ( f ) : ν μ } G μ ( f ) = { ν G ( f ) : ν μ } .

Let us note that by Theorems 2 and 3, μ*, μ are well defined iff  G μ ( f ) , G μ ( f ) , respectively, and then

μ * = sup G μ ( f ) , μ = inf G μ ( f ) .

Let M ̌ ρ { μ M ρ : G μ ( f ) } . We call the mapping

M ̌ ρ μ μ * G ( f )

the reduction operator.

Remark 4.

Notice that if there exist a positive g L ρ 1 ( E ; m ) and M ≤ 0 such that f(x, y) ≤ g(x), xE, yM, then M ̌ ρ = M ρ . Indeed, observe that u ̲ R μ (resp. u ̄ 0 ) is a subsolution (resp. supersolution) to

A u = f ( , u ) μ .

Therefore, by Theorem 1, there exists a solution w to the above equation. Thus, μ G ( f ) . Clearly, −μ μ.

6.1 Basic properties of good measures and the reduction operator: application to the existence problem

Proposition 12.

We have the following.

  1. M ρ 0 G ( f ) .

  2. Suppose that ν M ρ , μ M ̌ ρ , and μν. Then μ* ≤ ν*.

  3. If μ , ν G ( f ) , then μ ν , μ ν G ( f ) .

  4. If μ is a positive measure, then μ* ≥ 0.

Proof.

Ad (1). It follows from the existence result proved in [1]. Ad (2). By the assumptions there exist μ*, ν*. By Theorem 2, μ* ≤ μ, and so μ* ≤ ν. By Theorem 2 again, μ* ≤ ν*. Ad (3). Since μ is a good measure, there exists a solution u to (2). Observe that u is also a subsolution to (2) with μ replaced by μν. Thus, there exists (μν)*. By Theorem 2, (μν)* ≤ μν. On the other hand, by (2)

μ = μ * ( μ ν ) * , ν = ν * ( μ ν ) * .

So that (μν)* = μν. Thus, μ ν G ( f ) . Analogous reasoning for the minimum gives that μ ν G ( f ) . Ad (4). By (1), 0 G ( f ) . We assumed that 0 ≤ μ. Therefore by (2), 0 = 0* ≤ μ*.□

Proposition 13.

Let μ , ν M ρ and μ ν M ̌ ρ . Then (μν)* = μ* ∧ ν*.

Proof.

First observe that μ ν M ̌ ρ implies that μ , ν M ̌ ρ . By Theorem 2, μ* ≤ μ, ν* ≤ ν. Hence μ* ∧ ν* ≤ μν. By (2) and (3) of Proposition 12, μ* ∧ ν* ≤ (μν)*. On the other hand, by Proposition 12(2), μ* ≥ (μν)* and ν* ≥ (μν)*. Thus, μ* ∧ ν* ≥ (μν)*.□

Theorem 4.

Assume that there exists a subsolution and a supersolution to (2). Then there exists a solution to (2).

Proof.

Thanks to the assumptions made, there exist a subsolution u ̲ and a supersolution u ̄ to (2). Therefore, according to the definition of these objects, there exist two positive measures ν 1 , ν 2 M ρ such that

A u ̲ = f ( , u ̲ ) + μ ν 1 , A u ̄ = f ( , u ̄ ) + μ + ν 2 .

In particular, μ ν 1 G μ ( f ) , μ + ν 2 G μ ( f ) . Thus, there exist μ , μ*. Obviousely, μ , μ * G ( f ) . Let w ̄ be a maximal solution to −Av = f(⋅, v) + μ (see Remark 3). By Theorems 2 and 3, μ* ≤ μμ . Therefore, by Proposition 11, u * w ̄ . Observe that u is a subsolution to (2) and w ̄ is a supersolution to (2). By Theorem 1, there exists a solution to (2).□

As a corollary to the above result, we obtain the following useful properties of the set G ( f ) .

Proposition 14.

Assume that μ 1 , μ 2 G ( f ) , μ M ρ and μ 1μμ 2. Then μ G ( f ) .

Proof.

Since μ 1 , μ 2 G ( f ) . There exists a solution u 1 to (2) with μ replaced by μ 1, and a solution u 2 to (2) with μ replaced by μ 2. Since μ 1μμ 2, u 1 is a subsolution to (2) and u 2 is a supersolution to (2). By Theorem 4, there exists a solution to (2). So, μ G ( f ) .□

Corollary 2.

Let μ M ̌ ρ . Then μ G ( f ) if and only if μ + G ( f ) .

Proof.

If μ G ( f ) , then by Proposition 12.(3), μ + G ( f ) . Suppose that μ + G ( f ) . We have μμ +. At the same time, since μ M ̌ ρ , there exists ν G ( f ) such that νμ. Therefore, by Proposition 14, μ G ( f ) .□

Proposition 15.

We have G ( f ) + M ρ 0 G ( f ) .

Proof.

Let γ G ( f ) and β M ρ 0 . Write

γ = ( γ + β ) + ( β ) .

Once we show that for any μ M ρ , ν M ρ 0 such that μ + ν G ( f ) we have that μ G ( f ) , then we conclude the result by taking μ = γ + β, ν = −β. So, let μ M ρ , ν M ρ 0 and μ + ν G ( f ) . Set

σ ̄ = max { μ + ν , μ d } , σ ̲ = min { μ + ν , μ d } .

Since μ + ν G ( f ) , we get by Proposition 12 (1), (3) that σ ̲ , σ ̄ G ( f ) . Observe that

σ ̄ = μ d + max { μ c + ν , 0 } = μ d + ( μ c + ν ) + = μ d + μ c + + ν + μ ,

and

σ ̲ = μ d + min { μ c + ν , 0 } = μ d ( μ c + ν ) = μ d μ c ν μ .

Thus, σ ̲ μ σ ̄ . By Proposition 14, μ G ( f ) .□

Corollary 3.

We have that μ G ( f ) if and only if μ c G ( f ) .

6.2 Further properties of the reduction operator and good measures the class of admissible measures

We let

A ( f ) = μ M ρ : f ( , R μ ) L ρ 1 ( E ; m ) .

Elements of A ( f ) shall be called admissible measures.

Proposition 16.

We have A ( f ) + L ρ 1 ( E ; m ) = G ( f ) .

Proof.

The inclusion “⊂” follows directly from Proposition 15. Suppose that μ G ( f ) . Therefore, there exists a solution u to (2). Set νμ + f(⋅, u). Then ν A ( f ) since = u and by the very definition of a solution to (2), we have f(⋅, u) ∈ L 1(E, ρm). Thus, μ = ν f ( , u ) A ( f ) + L ρ 1 ( E ; m ) .□

Proposition 17.

The set G ( f ) is closed in ( M ρ , M ρ ) .

Proof.

Let ( μ n ) n 1 G ( f ) . Let μ M ρ and μ n μ M ρ 0 , n . Set μ 0 = 0. We may assume that n 1 μ n + 1 μ n M ρ < . Then μ = n≥0(μ n+1μ n ), where the limit is understood in the norm  M ρ . Observe that

σ ̲ n 0 ( μ n + 1 μ n ) μ n n 0 ( μ n + 1 μ n ) + σ ̄

Since μ n G ( f ) , there exist σ ̲ * , σ ̄ * and by Proposition 12(2), σ ̲ * μ n σ ̄ * . Letting n → ∞ yields σ ̲ * μ σ ̄ * . By Proposition 14, μ G ( f ) .□

Proposition 18.

Assume that μ M ̌ ρ . Then |μ*| ≤ |μ|.

Proof.

By Theorem 1(3), u* ≤ w, where w = +, and vu*, where v = − . By the inverse maximum principle μ c ( μ * ) c μ c + . Hence | ( μ * ) c | | μ c | . Since ( μ * ) d = μ d , we get the result.□

Corollary 4.

Assume that μ , ν M ̌ ρ , and μ ⊥ ν. Then μ* ⊥ ν*.

Proposition 19.

Let μ , ν M ̌ ρ , and μ ⊥ ν. Then (μ + ν)* = μ* + ν*.

Proof.

First we show that (μ + ν)* is well defined and μ* + ν* ≤ (μ + ν)*. Clearly, μ* + ν* ≤ μ + ν. So, it is enough to prove that μ * + ν * G ( f ) since then G μ + ν ( f ) , and, by Proposition 12.(2), μ* + ν* ≤ (μ + ν)*. By Proposition 18, μ* ⊥ ν*. Thus

μ * ν * = ( μ * + ν * ) + , μ * ν * = ( μ * + ν * ) μ * + ν * μ + ν .

Therefore, by Proposition 12.(3), G μ + ν ( f ) and ( μ * + ν * ) + G ( f ) . Hence, by Corollary 2, μ * + ν * G ( f ) . For the inequality μ* + ν* ≥ (μ + ν)* observe that

(39) ( μ + ν ) * = s μ μ + s ν ν ,

where

s μ = d ( μ + ν ) * d ( | μ | + | ν | ) d | μ | d μ , s ν = d ( μ + ν ) * d ( | μ | + | ν | ) d | ν | d ν .

By Proposition 18, s μ , s ν are well defined and |s μ | ≤ 1, |s ν | ≤ 1. Therefore, from (39) and the fact that μ ⊥ ν, we infer that

[ ( μ + ν ) * ] s μ μ [ ( μ + ν ) * ] + , [ ( μ + ν ) * ] s ν ν [ ( μ + ν ) * ] + .

By Proposition 12(3), [ ( μ + ν ) * ] + , [ ( μ + ν ) * ] G ( f ) . Therefore, by Proposition 14, s μ μ , s ν ν G ( f ) . By (39), s μ μ + s ν νμ + ν. From this and the fact that μ ⊥ ν, we conclude that s μ μμ, s ν νν. Consequently, since s μ μ , s ν ν G ( f ) , we have s μ μμ*, s ν νν*. This combined with (39) gives (μ + ν)* ≤ μ* + ν*.□

Corollary 5.

Let μ M ̌ ρ and A B ( E ) . Then ( μ A ) * = μ A * .

Proof.

First we show that G μ A ( f ) . For this it is enough to prove that ν G μ ( f ) implies ν A G μ A ( f ) . But this follows easily from Proposition 12.(3) and Proposition 14 since −ν ν A ν +. By Proposition 19,

( μ * ) A + ( μ * ) A c = ( μ A ) * + μ A c *

Applying Proposition 18 yields | ( μ * ) A | , | ( μ A ) * | | μ | A and | ( μ * ) A c | , | μ A c * | | μ | A c . From this and the above equality, we get the result.□

Corollary 6.

Let μ , ν M ̌ ρ . Then (μν)* = μ* ∨ ν*.

Proof.

It is enough to repeat step by step the proof of [2], Theorem 4.9].□

Corollary 7.

Let μ M ̌ ρ and ν M ρ 0 . Then (μ + ν)* = μ* + ν.

Proof.

Observe that by Proposition 12.(1), G μ + ν ( f ) . Next, by Proposition 19 and Proposition 12.(1),

( μ + ν ) * = ( μ c ) * + ( μ d + ν ) * = ( μ c ) * + μ d + ν = ( μ c ) * + μ d * + ν = ( μ c + μ d ) * + ν = μ * + ν .

Corollary 8.

Let μ M ̌ ρ . Then ( μ c ) * = ( μ * ) c .

Proof.

Let β G μ ( f ) . Then, by Corollary 3, β c G μ c ( f ) . Thus, G μ c ( f ) . By Corollary 7 and Theorem 2,

( μ * ) c = μ * ( μ * ) d = μ * μ d = ( μ c + μ d ) * μ d = ( μ c ) * .

From now on for every μ M ρ without ambiguity we may write μ c * .

Proposition 20.

Let μ M ̌ ρ . Then

μ * = μ d μ c + μ c + * .

Proof.

Let β G μ ( f ) . Then β c μ c . By Proposition 12.(3) and Corollary 3, β c G ( f ) . Thus, G μ c ( f ) . By Proposition 14, μ c * = μ c . From this and Corollary 7, we get

μ * = μ d + μ c + * + μ c * = μ d μ c + μ c + * .

6.3 Continuity of the reduction operator

The main result of the present subsection is continuity of the reduction operator with respect to the norm M ρ . Note that if we assume additionally that f is non-increasing with respect to the second variable, then the reduction operator is even Lipschitz continuous (see [21], Theorem 5.10]).

Lemma 3.

Let μ n M ρ , n 1 , μ M ̌ ρ , and μμ n+1μ n , n ≥ 1. Assume that μ n μ in the norm  M ρ . Then μ n * μ * in the norm  M ρ .

Proof.

By Proposition 12, μ n * is a nondecreasing sequence and

μ * μ n * μ n , n 1 .

Since μ n * is nondecreasing, we may set β = lim n μ n * , where the limit is understood in the norm  M ρ . Letting n → ∞ in the above inequality yields μ* ≤ βμ. Since μ * β μ 1 * , we have by Proposition 14 that β G μ ( f ) . Thus, β = μ*.□

Theorem 5.

Let μ , μ n M ρ , n 1 . Assume that G μ ( f ) , G μ n ( f ) , n 1 , and μ n μ in the norm  M ρ . Then, μ n * μ * in the norm  M ρ .

Proof.

All the convergences of measures considered in the proof below will be understood in the norm  M ρ .

Step 1. We assume additionally that 0 ≤ μμ n , n ≥ 1. Let (n k ) be a subsequence of (n). By [36], Proposition 4.2.4], there exists a further subsequence ( n k l ) , and positive β M ρ such that

| μ n k l μ | 1 l β , l 1 .

Thus,

μ μ n k l μ + 1 l β , l 1 .

By Proposition 12,

μ * μ n k l * μ + 1 l β * , l 1 .

By Lemma 3, ( μ + 1 l β ) * μ * . From this and the above inequality μ n k l * μ * . Since (n k ) was an arbitrary subsequence of (n), we conclude that μ n * μ * .

Step 2. We assume additionally that 0 ≤ μ n μ, n ≥ 1. Then μ n = s n μ for some Borel function s n on E such that 0 ≤ s n ≤ 1. Since μ n μ, we have that s n → 1 in L 1(E; μ). Let a ∈ (0, 1). Observe that for any positive ν M ρ ,

(40) a ν * ( a ν ) * .

Set A n = {s n a}. Then

(41) a μ A n μ n μ , n 1 .

Moreover,

(42) μ A n c = μ ( | 1 s n | > 1 a ) 1 1 a E | 1 s n | d μ 0 .

By (40), (41), Proposition 12 and Corollary 5

a ( μ * ) A n μ n * μ * , n 1 .

From this and (42), we conclude at once that for any non-negative ηL 1(E; μ)

a E η d μ * lim inf n E η d μ n * lim sup n E η d μ n * E η d μ * .

Since a ∈ (0, 1) was arbitrary, we get μ n * μ * .

Step 3. We assume additionally that μ n ≥ 0, n ≥ 1. Then observe that

(43) 0 μ μ n μ n μ μ n , n 1 .

Clearly, μμ n μ and μμ n μ. Therefore, by Step 1 and Step 2, ( μ μ n ) * μ * and ( μ μ n ) * μ * . By (43) and Proposition 12,

( μ μ n ) * μ n * ( μ μ n ) * , n 1 .

Thus, μ n * μ * .

Step 4. The general case. By Proposition 20,

(44) μ n * = ( μ n ) d μ n c + μ n + c * , μ * = μ d μ c + μ c + * .

Since μ n μ, we have ( μ n ) d μ d , μ n c μ c , μ n + c μ c + . By Step 3, μ n + c * μ c + * . As a result, by (44), μ n * μ * .□

6.4 Existence and continuity of the metric projection onto good measures

In what follows, in order to emphasize the dependence of the reduction operator on the nonlinearity f, we shall denote by μ *,f and μ *,f the measure μ* and μ appearing in the assertions of Theorem 2 and Theorem 3, respectively.

We let

Π f ( μ ) μ * , f , μ M ̌ ρ .

We also let M ̂ ρ { μ M ρ : G μ } . By Proposition 14, M ̌ ρ M ̂ ρ = G ( f ) . Thus, we may extend operator Π f :

(45) Π f ( μ ) = μ * , f , μ M ̌ ρ μ * , f , μ M ̂ ρ .

Since for μ M ̌ ρ M ̂ ρ , we have μ *,f = μ *,f = μ, the operator Π f is well defined on M ̌ ρ M ̂ ρ .

We denote

f ̃ ( x , y ) f ( x , y ) , x E , y R .

We get at once that if f satisfies one of the conditions (Int), (Car), (qM), (Sig), then f ̃ satisfies it too.

Remark 5.

Observe that by Theorems 2 and 3 for any μ M ̂ ρ ,

Π f ̃ ( μ ) = ( μ ) * , f ̃ = μ * , f .

Proposition 21.

The mapping

Π f : M ̌ ρ M ̂ ρ G ( f )

is the metric projection onto G ( f ) . Moreover,

(46) | μ Π f ( μ ) | ( μ ν ) + , μ M ̌ ρ , ν G ( f ) ,

and

(47) | μ Π f ( μ ) | ( ν μ ) + , μ M ̂ ρ , ν G ( f ) .

Furthermore, for any μ M ̌ ρ M ̂ ρ , the measure Π f (μ) is the only one element of G ( f ) satisfying

μ Π f ( μ ) M ρ = inf ν G ( f ) μ ν M ρ .

Proof.

Let ν G ( f ) and μ M ̌ ρ . The last relation implies that there exists β G ( f ) such that βμ. Thus, βνμνν. By Proposition 12 and Proposition 14, μ ν G ( f ) . This in turn implies that μν ≤ (μν)*,f = μ *,f ν (see Proposition 13). Consequently,

(48) | μ Π f ( μ ) | = | μ μ * , f | = μ μ * , f μ μ * , f ν μ μ ν = ( μ ν ) + | μ ν | .

Therefore, μ Π f ( μ ) M ρ μ ν M ρ for any ν G ( f ) . This completes the proof of case μ M ̌ ρ . Now, let μ M ̂ ρ . Observe that μ M ̌ ρ . Therefore, by Remark 5

μ Π f ( μ ) M ρ = μ ( Π f ̃ ( μ ) ) M ρ = inf ν G ( f ̃ ) ν ( μ ) M ρ = inf ν G ( f ) ν + μ M ρ .

Applying (48) with −μ in place of μ yields (47). For the proof of the last assertion of the proposition suppose that μ M ̌ ρ (the proof of the second case is analogous) and suppose that ν G ( f ) realizes the distance between μ and G ( f ) . Notice that

(49) μ μ ν M ρ = ( μ ν ) + M ρ .

Since μ M ̌ ρ , there exists γ G ( f ) such that γμ. Hence, γνμνν. By Proposition 14, μ ν G ( f ) . Therefore, since ν realizes the distance between μ and G ( f ) , we have

μ ν M ρ μ μ ν M ρ .

This combined with (49) yields (μν) = 0, so that νμ. The last inequality is crucial since it implies that νμ *,f . We also have, Π f (μ) = μ *,f μ. On the other hand, since Π f (μ) and ν realize the distance between μ and G ( f ) , we have

μ Π f ( μ ) M ρ = μ ν M ρ .

Therefore, we deduce at once that Π f (μ) = ν.□

Finally, we define the operator

Π f : M ρ G ( f )

as follows:

Π f ( μ ) Π f ( μ + ) + Π f ( μ ) = Π f ( μ + ) Π f ̃ ( μ ) = ( μ + ) * , f ( μ ) * , f ̃ = ( μ + ) * , f + ( μ ) * , f .

By Propositions 18, 19, Π f ( μ ) G ( f ) for any μ M ρ .

Theorem 6.

Π f : M ρ G ( f ) is a continuous metric projection onto G ( f ) . Moreover,

| μ Π f ( μ ) | | μ ν | , μ M ρ , ν G ( f ) .

Furthermore, if Q : M ρ G ( f ) is a metric projection, with the property: μ ⊥ ν implies Q(μ + ν) = Q(μ) + Q(ν), then Q = Π f .

Proof.

Continuity of Π f follows from Theorem 5. Let ν G ( f ) and μ M ρ . Clearly, Π f ( μ ) G ( f ) . Moreover, by Proposition 21, for any ν 1 G ( f ) , ν 2 G ( f ̃ ) = G ( f )

| μ Π f ( μ ) | = | μ + Π f ( μ + ) | + | μ Π f ̃ ( μ ) | μ + ν 1 + + μ ν 2 + .

Let ν G ( f ) . Then ν + G ( f ) and ν G ( f ) . Therefore,

| μ Π f ( μ ) | ( μ + ν + ) + + ( μ ν ) + | μ ν | .

This implies the inequality asserted in the theorem, and the fact that Π f is the metric projection onto G ( f ) . For the last assertion of the theorem, observe that operator Π f shares additivity property formulated in the assertion of the theorem for Q. Therefore, if Π f = Q on M ̌ ρ M ̂ ρ , then Π f = Q on M ρ . The fact that Π f = Q on M ̌ ρ M ̂ ρ follows easily from Proposition 21.□

7 Characterization of the class of good measures

Proposition 22.

Assume that {μ n } is a sequence of positive Borel measures such that sup n≥1 n < ∞ q.e. Suppose that n → 0 m-a.e. Then there exists a subsequence (not relabeled) such that n → 0 q.e.

Proof.

By [37], Lemma 5.1], there exists a subsequence (not relabeled) such that k n → 0 q.e. for any k ≥ 1. As a result, since sup n≥1 n < ∞ q.e., we infer from this convergence that up to subsequence n → 0 q.e.□

Theorem 7.

Let μ M ρ .

  1. μ G ( f ) if and only if there exists a sequence { g n } L ρ 1 ( E ; m ) such that

    1. g n + μ A ( f ) , n 1 .

    2. g n → 0 in L loc 1 ( E ; ρ m ) .

  2. Assume that ρ is bounded and there exists ɛ > 0 such that sup | y | ε | f ( , y ) | L ρ 1 ( E ; m ) , then μ G ( f ) if and only if there exists a sequence { g n } L ρ 1 ( E ; m ) such that condition (i) and the following one

    • (ii’) g n → 0 in L ρ 1 ( E ; m )

hold.

Furthermore, in both cases ((1) and (2)), if μ is positive (resp. negative) then g n may be taken negative (resp. positive).

Proof.

Sufficiency (in both cases) follows from Corollary 5 and Proposition 17. Let μ G ( f ) . Set

f n , m ( x , y ) 1 m f + ( x , y ) 1 n f ( x , y ) , x E , y R .

Since μ G ( f ) , there exists a solution u to −Av = f(⋅, v) + μ. Hence

A u = f n , m ( , u ) + ( μ f n , m ( , u ) + f ( , u ) ) .

Clearly, f n , m ( , u ) L ρ 1 ( E ; m ) . Therefore, from the above equation, μ f n , m ( , u ) + f ( , u ) G ( f n , m ) . Thus, by Proposition 15, μ G ( f n , m ) . Consequently, by Theorem 2, there exists a maximal solution u n,m to

A v = f n , m ( , v ) + μ .

By Proposition 11, u n,m u n+1,m , u n,m u n,m+1, n, m ≥ 1 q.e. Set

w n lim m u n , m = inf m 1 u n , m , z m lim n u n , m = sup n 1 u n , m q.e.

and

w lim n w n = sup n 1 w n , z lim m z m = inf m 1 z m q.e.

Observe that

0 u n , m + u n , 1 + , m 1 q.e.

Thus, by (Int),

f ( , u n , m ) = | f ( , u n , m + ) | sup 0 y u n , 1 + | f ( , y ) | L ρ 1 ( E ; m ) .

From this, we conclude that, up to subsequence,

R f ( , u n , m ) R f ( , w n ) m a.e.

By Proposition 9,

(50) | u n , m | + R | f n , m ( , u n , m ) | R | μ | q.e.

By [33], Lemma 94, page 306], up to subsequence, 1 m R f + ( , u n , m ) e n , m , m -a.e. for some excessive function e n . By [34], Proposition 3.9], there exists a positive Borel measure β n such that e n = n . Therefore,

(51) w n = R β n 1 n R f ( , w n ) + R μ m a.e.

Now, we shall show that w n is quasi-continuous and β n  ⊥ Cap. Set hR|μ|. By Remark 1(a), h is quasi-continuous. Set

τ k inf { t 0 : h ( X t ) k } k , σ ̂ k , j inf { t 0 : 0 t sup | y | k | f ( X r , y ) | d r j } .

Since h is quasi-continuous, lim k→∞ τ k = ζ. By (qM) and Corollary 1, lim j σ ̂ k , j = ζ for any k ≥ 1. Thus, lim k→∞lim j→∞ τ k,j ζ, where τ k , j τ k σ ̂ k , j . By Lemma 1, {σ k } is a reducing sequence for h, hence {τ k,j } is a reducing sequence for h for fixed j ≥ 1. Therefore, by (50), the last sentence also is in force with h replace by any of the following functions: u n,m , w n , z n , w, z. By Lemma 1,

(52) u n , m ( X t τ k , j ) = E x u n , m ( X τ k , j ) + 1 m t τ k , j τ k , j f + ( , u n , m ) ( X r ) d r 1 n t τ k , j τ k , j f ( , u n , m ) ( X r ) d r + t τ k , j τ k , j d A r μ d F t τ k , j q.a.s.

By [35], Lemma 6.1], for any q ∈ (0, 1) there exists c q > 0 such that

E x sup t τ k , j | u n , m ( X t ) u n , l ( X t ) | q 1 / q c q E x | u n , m ( X τ k , j ) u n , l ( X τ k , j ) |

(53) + 1 m 0 τ k , j f + ( , u n , m ) ( X r ) d r + 1 l 0 τ k , j f + ( , u n , l ) ( X r ) d r

(54) + 1 n 0 τ k , j | f ( , u n , m ) ( X r ) f ( , u n , l ) ( X r ) | d r q.e.

By Remark 1(c) and the choice of {τ k,j }, we obtain that the right-hand side of the above inequality tends to zero as m, l → ∞. Consequently, by Lemma 2, w n is quasi-continuous. Taking t = 0 in (52), we get

(55) u n , m ( x ) = E x u n , m ( X τ k , j ) + 1 m E x 0 τ k , j f + ( , u n , m ) ( X r ) d r 1 n E x 0 τ k , j f ( , u n , m ) ( X r ) d r + E x 0 τ k , j d A r μ d q.e.

Letting m → ∞ and using the definition of τ k,j and Remark 1(c) yields

w n ( x ) = E x w n ( X τ k , j ) 1 n E x 0 τ k , j f ( , w n ) ( X r ) d r + E x 0 τ k , j d A r μ d q.e.

Now, letting j → ∞, and using quasi-continuity of w n and the fact that (τ k ) is a reducing sequence for w n (and τ k,j τ k ), we find that

w n ( x ) = E x w n ( X τ k ) 1 n E x 0 τ k f ( , w n ) ( X r ) d r + E x 0 τ k d A r μ d q.e.

On the other hand, since w n is quasi-continuous, we have by Remark 1(a)–(b) that, in fact, (51) holds q.e. Therefore, by [21], Theorem 3.7], letting k → ∞ in the above equation gives

w n = R ( μ + β n ) c 1 n R f ( , w n ) + R μ d q.e.

Thus,

w n = R ( β n ) c 1 n R f ( , w n ) + R μ q.e.

From this and (51), we conclude that ( β n ) c = β n . Since u n,m u n,1, n, m ≥ 1 q.e., we have w n u n,1, n ≥ 1 q.e. Therefore, by the inverse maximum principle (see [21], Theorem 6.1]), β n + μ c μ c . Hence, β n = 0. Consequently,

(56) w n = 1 n R f ( , w n ) + R μ q.e.

Repeating the reasoning (50)(56), with u n,m replaced by w n (and this time letting n → ∞) and with w n replaced by w, we find that w = q.e. Analogous reasoning shows that z = q.e. Set u n = u n,n , f n = f n,n , then

A u n = f n ( , u n ) + μ .

Observe that w n u n z n q.e. Thus, u n q.e. By (50) [33], Lemma 94, page 306], and Proposition 22, there exist excessive functions e 1, e 2 such that, up to subsequence,

e 1 n 1 n R f + ( , u n ) e 1 , e 2 n 1 n R f ( , u n ) e 2 , q.e.

By [34], Proposition 3.9] and once again (50), there exist positive Borel measures β 1, β 2 such that e 1 = 1, e 2 = 2. At the same time, since u n u q.e., we have 1 n R f ( , u n ) 0 q.e. Thus, e 1 = e 2, and so β 1 = β 2. By Lemma 1

e 1 n ( x ) = E x e 1 n ( X τ k ) + 1 n E x 0 τ k f + ( , u n ) q.e.

By the choice of {τ k } and Remark 1(c), we obtain, by letting n → ∞, that e 1 ( x ) = E x e 1 ( X τ k ) q.e. Thus, by [21], Theorem 3.7], e 1 = R ( β 1 ) c . Consequently, R ( β 1 ) c = R β 1 , so that ( β 1 ) c = β 1 . By [31], Proposition 3.7], there exists positive smooth measures λ n , λ M ρ such that

u n + = e 2 n + R μ + R λ n , u + = R μ + R λ .

Letting n → ∞ and using (50) and [34], Proposition 3.9], we deduce that there exists a positive measure λ 0 M ρ such that

u + = R β 1 + R μ + R λ 0 , u + = R μ + R λ .

Thus, λ 0 + β 1 = λ. Since λ is smooth and ( β 1 ) c = β 1 , we conclude that β 1 = 0. Consequently, e 1 = e 2 = 0. As a result, we obtain that

R | f n ( , u n ) | 0 q.e.

From this and (50) we infer that for any positive smooth measure ν such that ρ we have

(57) E | f n ( , u n ) | R ν d m 0 as n .

Set F ≔ {R|μ| > ɛ} and hρ1 F . Let e h be the smallest excessive function less than or equal to h. Clearly, e h ≤ |ρ| R|μ|∧ ρ. Therefore, by [34], Proposition 3.9], there exists a positive measure ν M ρ such that e h = . Since e h is bounded, ν is a smooth measure. Consequently, (57) holds. We have

| f n ( , u n ) | ρ = 1 F | f n ( , u n ) | ρ + 1 F c | f n ( , u n ) | ρ | f n ( , u n ) | e h + sup | y | ε | f n ( , y ) | ρ = | f n ( , u n ) | R ν + 1 n sup | y | ε | f ( , y ) | ρ .

By (57) and the assumptions made on f, we get the result. The last assertion of the theorem is obvious from the construction.□

We let B L 1 ( 0 , r ) u L ρ 1 ( E ; m ) : u L ρ 1 ( E ; m ) r .

Corollary 9.

Under the notation and assumptions of Theorem 7(2), we have

  1. for any r > 0, A ( f ) + B L 1 ( 0 , r ) = G ( f ) ,

  2. c l A ( f ) = G ( f ) , where cl denotes closure in the total variation norm ‖ ⋅‖ ρ .

Proof.

It follows directly from Theorem 7.□

Remark 6

Assume that g is a function satisfying (Car), (Sig), (Int). Furthermore, assume that f, g satisfy (M). Suppose that there exist constants c 1, c 2, r > 0 such that

(58) c 1 | f ( x , y ) | | g ( x , y ) | c 2 , m a.e. , | y | r .

Then G ( f ) = G ( g ) .

Proof.

By (58), we easily get that A ( f ) = A ( g ) . Therefore, by Corollary 9, G ( f ) = G ( g ) .□

Corollary 10.

Under assumptions of Remark 6, we have Π f = Π g . In particular, for positive μ M ρ , μ *,f = μ *,g .


Corresponding author: Tomasz Klimsiak, Faculty of Mathematics and Computer Science, Nicolaus Copernicus University, Chopina 12/18, 87-100 Toruń, Poland; and Institute of Mathematics, Polish Academy of Sciences, Śniadeckich 8, 00-656 Warsaw, Poland, E-mail: 

Funding source: This work was supported by Polish National Science Centre

Award Identifier / Grant number: Grant No. 2017/25/B/ST1/00878

  1. Research ethics: Not applicable.

  2. Informed consent: Not applicable.

  3. Author contributions: The author has accepted responsibility for the entire content of this manuscript and approved its submission.

  4. Use of Large Language Models, AI and Machine Learning Tools: None declared.

  5. Conflict of interest: The author states no conflict of interest.

  6. Research funding: This work was supported by Polish National Science Center, Grant No. 2017/25/B/ST1/00878.

  7. Data availability: Not applicable.

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Received: 2024-05-11
Accepted: 2024-10-14
Published Online: 2025-01-03

© 2024 the author(s), published by De Gruyter, Berlin/Boston

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