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On the large solutions to a class of k-Hessian problems

  • Haitao Wan EMAIL logo
Published/Copyright: April 3, 2024

Abstract

In this paper, we consider the k-Hessian problem S k (D 2 u) = b(x)f(u) in Ω, u = +∞ on Ω, where Ω is a C -smooth bounded strictly (k − 1)-convex domain in R N with N ≥ 2, b ∈ C(Ω) is positive in Ω and may be singular or vanish on Ω, fC[0, ∞) ∩ C 1(0, ∞) (or f C 1 ( R ) ) is a positive and increasing function. We establish the first expansions (equalities) of k-convex solutions to the above problem when f is borderline regularly varying and Γ-varying at infinity respectively. For the former, we reveal the exact influences of some indexes of f and principal curvatures of Ω on the first expansion of solutions. For the latter, we find the principal curvatures of Ω have no influences on the expansions. Our results and methods are quite different from the existing ones (including k = N). Moreover, we know the existence of k-convex solutions to the above problem (including k = N) is still an open problem when b possesses high singularity on Ω and f satisfies Keller–Osserman type condition. For the radially symmetric case in the ball, we give a positive answer to this open problem, and then we further show the global estimates for all radial large solutions.

MSC 2020: 35J60; 35J25; 35B40; 35J67

1 Introduction

This presentation is to investigate the following k-Hessian problem

(1.1) S k ( D 2 u ) = S k ( λ ) = b ( x ) f ( u )  in  Ω , u = +  on  Ω ,

where Ω R N ( N 2 ) is a C -smooth bounded strictly (k − 1)-convex domain, k ∈ {1, …, N}, λ = ( λ 1 , , λ N ) and λ 1, ⋅⋅⋅, λ N are the eigenvalues of the Hessian of uC 2(Ω), and

S k ( λ ) = 1 i 1 < < i k N λ i 1 λ i k

denotes kth elementary symmetric function given in [1] and [2]; furthermore, S 0 ( λ ) = 1 given in [3]. The last condition u = +∞ on Ω means that u(x) → +∞ as d(x) ≔ dist(x, Ω) → 0 and the solution is called “large solution”, “blow-up solution” or “explosive solution”. The weight b and nonlinearity f satisfy

  • (b 1 ) bC (Ω) is positive in Ω;

  • (f 1 ) fC[0, ∞) ∩ C 1(0, ∞) is positive and increasing on (0, ∞) with f(0) = 0 (or ( f 01 ) f C 1 ( R ) is positive and increasing on R );

  • (f 2 ) the Keller–Osserman type condition t ( F ( s ) ) 1 / ( k + 1 ) d s < , t > 0 , F ( t ) = 0 t f ( s ) d s .

We obtain by Definition 1.1 of [3] that uC 2(Ω) is (strictly) k-convex if S i ( D 2 u ) = S i ( λ ) ( > ) 0  in  Ω  for  i = 1 , , k . Moreover, it follows by Definition 1.2 of [3] that Ω is (strictly) l-convex if

(1.2) S i ( κ ( x ̄ ) ) ( > ) 0  on  Ω  for  i = 1 , , l N 1 ,  with  κ ( x ̄ ) = ( κ 1 ( x ̄ ) , , κ N 1 ( x ̄ ) ) ,

where κ i ( x ̄ ) ( i = 1 , , N 1 ) are the principal curvatures of Ω at x ̄ .

If k = 1, then problem (1.1) reduces to the semilinear elliptic problem

(1.3) Δ u = b ( x ) f ( u )  in  Ω , u = +  on  Ω .

The study to this problem on the existence, uniqueness and boundary behavior has a long history. In 1916, problem (1.3) first appeared in the work of Bieberbach [4] for N = 2 in connection with geometric problem of Riemannian surfaces of constant negative curvatures. Then, Rademacher [5], using the idea of Bieberbach, showed the results still hold for N = 3. Later, Lazer and McKenna [6] extended the above results in bounded domain Ω R N ( N 1 ) with a uniform outer sphere condition. Let b ≡ 1, f satisfy (f 1 ), Keller [7] and Osserman [8] showed problem (1.3) has solutions if and only if (f 2 ) holds with k = 1. For further insights on problem (1.3) and some related problems, we refer the readers to [9], [10], [11], [12], [13], [14], [15], [16], [17], [18], [19] and the references therein.

Now, let us return to problem (1.1). If k = N, then the problem is Monge–Ampère problem

(1.4) det ( D 2 u ) = b ( x ) f ( u )  in  Ω , u = +  on  Ω .

Problem (1.4) arised from a few geometric problems and was first studied by Cheng and Yau [20], [21] for f(u) = exp(Ku). Many related works have been considered after Cheng and Yau’s results to problem (1.4). Lazer and McKenna [22] studied the existence, uniqueness and global estimate of strictly convex solutions to problem (1.4), where 0 < b C ( Ω ̄ ) , f(u) = u γ or f(u) = exp(u). Especially, when f(u) = u γ with γ ∈ (0, N], they investigated the nonexistence of solutions. Matero [23], for a class of more general Monge–Ampère problem (i.e., b(x)f(u) in (1.4) is replaced by f ̃ ( x , u ) ), studied the existence, uniqueness and boundary behavior of strictly convex solutions. Guan and Jian [24] generalized the results of Cheng and Yau [20], [21], in which various existence and nonexistence results were shown for rather general Monge–Ampère equations with gradient terms in bounded (strictly) convex domains. In particular, they also studied the global estimate of strictly convex solutions to the problem in bounded strictly convex domains. Then, the results were extended by Jian [25] to the k-Hessian problem, where the existence and global estimate of viscosity solutions and the nonexistence of classical solutions were established. In [26], Mohammed studied the existence of strictly convex solutions to problem (1.4) when the following Dirichlet problem

(1.5)  det  D 2 u ( x ) = b ( x ) , x Ω , u | Ω = 0

has a strictly convex solution. In Theorem 1.1 of [27], Caffarelli et al. showed that problem (1.5) admits a convex solution if b C ( Ω ̄ ) . Cheng and Yau [28] proved that problem (1.5) possesses a strictly convex solution if 0 < b(x) < C(d(x)) δN−1 in Ω for some constants δ > 0 and C > 0. Mohammed [29] showed that if b(x) > C(d(x))N−1 in Ω with C > 0, then problem (1.5) has no strictly convex solution. Let b C ( Ω ̄ ) be positive in Ω and nonnegative on Ω. Under suitable conditions on f, Cîrstea and Trombetti [30] investigated the existence of strictly convex solutions to problem (1.4) in smooth, bounded, strictly convex domains. And they further gave the boundary behavior and uniqueness of strictly convex solutions by using Karamata regular variation theory. Then, the results were further generalized by Huang [31] to problem (1.1). When f(u) = exp(u) or f(u) = u γ , γ > N, and b satisfies (b 1 ) and grows like a negative power of d(x) near boundary, Yang and Chang [32] showed the existence, uniqueness, nonexistence and global estimate of strictly convex solutions to problem (1.4). And when Ω is a ball, they obtained the exact boundary behavior of large solutions. Recently, under the hypotheses (f 1 ), (f 2 ) and some additional structural conditions, the existence and boundary behavior of solutions were further studied by Zhang and Du [33] and Zhang [34], [35], [36] to problem (1.4) and by Ma and Li [37], Wan and Shi [38], Zhang and Feng [39] and Zhang [40] to problem (1.1). Especially, the authors in [37] investigated the existence and boundary behavior of viscosity solutions, and the author in [35] studied the asymptotic behavior of solutions when some indexes (which is relevant to b) tend to the corresponding critical values. For other related works, we refer the readers to [3], [41], [42], [43], [44], [45], [46], [47], [48], [49], [50], [51], [52], [53], [54], [55], [56], [57] and the references therein.

For convenience, we introduce the class of Karamata regularly varying functions as below.

Definition 1.1.

A positive continuous function f defined on [a , ∞) ((0, a 0]), for some a > 0 (a 0 > 0), is called regularly varying at infinity (zero) with index ρ, written fRV ρ  (RVZ ρ ), if for each C > 0 and some ρ R ,

(1.6) lim t f ( C t ) f ( t ) = C ρ lim t 0 + f ( C t ) f ( t ) = C ρ .

A subclass of RV ρ  (RV Z ρ ) is NRV ρ  (N RV Z ρ ) defined by Proposition A.3 (A.4) in Appendix A.

In this paper, we first establish the first expansion (equality) of k-convex solutions near the boundary when f is borderline regularly varying at infinity (i.e., fN RV k ) and has a lower term. We reveal that the most accurate influences of some indexes of f and principal curvatures of Ω on the first expansion of solutions. It should be pointed out that the boundary behavior of solutions to problem (1.1) is a hard issue when f is borderline regularly varying at infinity. We analyze briefly the cause of the difficulty by Remark 2.3 (see page 5). Then, we establish the first expansion of solutions to problem (1.1) when f is a Γ-varying function at infinity (defined on page 5) and b may be vanishing or singular (including borderline singular) on Ω. We find the principal curvatures of Ω have no influence on the expansions. As we know, Γ-varying functions is a class of very special rapidly varying functions defined by Appendix A.1 (see Appendix A). By analyzing the first boundary expansions of solutions, we find an interesting fact: Roughly speaking, if fN RV k  (f ∈ Γ), then the solutions near the boundary can be expressed by a rapidly (slowly) varying function. Our results and methods are quite different from the existing ones. On the other hand, if Ω is a ball, b is radially symmetric in Ω and has high singularity on Ω, f satisfies the following Keller–Osserman type condition

(1.7) 1 ( F ( t ) ) 1 / ( k + 1 ) d t = ,

we prove problem (1.1) has infinitely many positive k-convex radial solutions, which give a positive answer to the open problem (where Ω is a general (k − 1)-convex domain, b satisfies (b 1 ) and has high singularity on Ω, f satisfies (1.7)) in the case of radial symmetry in the ball. Our result and method are quite different from the ones of Zhang in [35] and Feng and Zhang in [43]. Furthermore, we study the global estimates of all positive radial solutions to this radially symmetric problem.

2 Main results

First, we study the influences of some indexes of f and principal curvatures of Ω on the first expansion of k-convex large solutions when f is borderline regularly varying at infinity. To our aim, we show some further hypotheses on b and f as follows:

  • (b 2 ) there exist positive constants b 0 , δ ̃ , δ 0 ( δ ̃ δ 0 ) and non-increasing function θ ∈ Λ such that

    b ( x ) = b 0 θ k + 1 ( d ( x ) ) , x Ω δ ̃ ,

    where Ω δ ̃ { x Ω : d ( x ) < δ ̃ } , Λ (following [11], [12], [30] and [19]) denotes the set of all positive monotonic functions θC 1(0, δ 0] ∩ L 1(0, δ 0] which satisfy

    lim t 0 + d d t Θ ( t ) θ ( t ) D θ [ 0 , ) , Θ ( t ) = 0 t θ ( s ) d s .

  • (f 3 ) there exist some constant t 0 > 0 and functions f 1, f 2 such that f(t) ≔ f 1(t) + f 2(t), tt 0, where f 1C 2[t 0, ∞), g ( t ) t f 1 ( t ) f 1 ( t ) k , t t 0 . And g, f 2 satisfy the following conditions:

  • (S 1 ) g ( t ) 0 , t t 0 , lim t g ( t ) = 0 , lim t t g ( t ) g ( t ) = 0 ,

    lim t t g ( t ) g 2 ( t ) = K g 0 , 1 k + 1 + K g 0  and  lim t t k f 1 ( t ) g 3 ( k + 1 ) ( t ) = 0 ;

  • (S 2 ) for any ξ > 0, lim t f 2 ( ξ t ) f 2 ( t ) = ξ k , and there exists C 1 0 such that

    lim t f 2 ( t ) g ( t ) f 1 ( t ) = C 1 ,

    or

  • (S 3 ) lim t f 2 ( t ) g ( t ) f 1 ( t ) = 0 and there exists μk such that for any ξ > 0,

    lim t f 2 ( ξ t ) f 2 ( t ) = ξ μ .

Theorem 2.1.

Let b satisfy (b 1 ), (b 2 ), f satisfy (f 1 ) (or (f 01 )), (f 2 ), (f 3 ) and (S 1 )(S 3 ), then any k-convex solution u to problem (1.1) satisfies

(2.1) u ( x ) = exp ( A 0 ) ψ ( B ( x ) Θ ( d ( x ) ) ) ( 1 + o ( 1 ) )  as  d ( x ) 0 ,

where ψ is uniquely determined by

(2.2) ψ ( t ) d s ( s f 1 ( s ) ) 1 / ( k + 1 ) = t ,

(2.3) A 0 = 1 k + 1 C 2 1 k + 1 + K g ( 1 D θ ) , C 2 = C 1 ,  if  ( S 2 )  holds , 0 ,  if  ( S 3 )  holds ,

(2.4) B ( x ) = b 0 S k 1 ( E ( x ) ) 1 / ( k + 1 ) ,

and

(2.5) E ( x ) = ( E 1 ( x ) , , E N 1 ( x ) )  with  E i ( x ) = κ i ( x ̄ ( x ) ) 1 κ i ( x ̄ ( x ) ) d ( x ) , x Ω  near  Ω ,

where κ i ( x ̄ ( x ) ) ( i = 1 , , N 1 ) are principal curvatures of Ω at x ̄ defined by | x x ̄ | = d ( x ) .

Remark 2.2.

A typical example is f ( t ) = c 1 t k ( 1 + α ln t ) 1 α + c 2 t β 1 ( ln t ) β 2 , t t 0 , where c 1 R + , α ∈ (0, 1/3(k + 1)), c 2 , β 1 , β 2 R . By a straightforward calculation, we have

g ( t ) = 1 1 + α ln t , t t 0 , K g = α , C 2 = c 2 c 1 α α 1 α , if  β 1 = k , β 2 = 1 α 1 , 0 , if  β 1 < k or  β 2 < 1 α 1

and ψ ( t ) = exp ( 1 / α ) exp 1 α ( k + 1 ) k + 1 c 1 1 k + 1 α ( k + 1 ) α ( k + 1 ) 1 t α ( k + 1 ) α ( k + 1 ) 1 α , t > 0 .

Remark 2.3.

By Lemma B.3 (ix) (see Appendix B), we see that in Theorem 2.1, any solution of problem (1.1) is expressed near the boundary by the rapidly varying function defined by Definition A.1 (see Appendix A). As we know, the rapidly varying function is extremely sensitive to the microvariations of independent variable. For instance, without loss of generality, in Remark 2.2 for small enough (no matter how small) ɛ > 0, we have

lim t 0 + ψ ( ( 1 ε ) t ) ψ ( t ) =  and  lim t 0 + ψ ( ( 1 + ε ) t ) ψ ( t ) = 0 .

This implies that ψ(t) can not be effectively controlled by ψ((1 ±ɛ)t) near zero. Furthermore, the following hold

lim ε 0 + lim sup t 0 + ψ ( t ) ψ ( ( 1 ε ) t ) = 0  and  lim ε 0 + lim inf t 0 + ψ ( t ) ψ ( ( 1 + ε ) t ) = .

So, we see that it is incorrect to describe the asymptotic behavior of ψ(t) at zero by ψ((1 ∓ ɛ)t).

Next, we show the first expansions of k-convex solutions to problem (1.1) when f is Γ-varying at infinity. For convenience, we introduce Γ-varying functions as below:

Definition 2.4.

A non-decreasing function f defined on (A , ∞) is Γ-varying at infinity (written f ∈ Γ) if lim t→∞ f(t) = ∞ and there exists χ : (A , ∞) → (0, ∞) such that

lim t f ( t + λ χ ( t ) ) f ( t ) = e λ , λ R .

Some typical Γ-varying functions are

  1. f(t) = exp(t p ), p > 0, t > 0, where the auxiliary function χ(t) = p −1 t 1−p ;

  2. f(t) = exp(tlnt), t > 0, where the auxiliary function is given by

    χ ( t ) = 1 ,  if  t ( 0,1 ] , ( ln t ) 1 ,  if  t ( 1 , ) ;

  3. f(t) = exp(exp(t)), t > 0, where the auxiliary function χ(t) = exp(−t).

If f is non-decreasing on (0, ∞), then by Theorem 1.28 in [58] we see that the following statements are equivalent:

  1. f is Γ-varying at infinity;

  2. there exist some constant B > 0 and positive function TC 1[B , ∞) with lim t→∞ T′(t) = 0 such that

    (2.6) f ( t ) f ̂ ( t ) exp B t d s T ( s )  as  t ,

    where “ f ( t ) f ̂ ( t ) as t → ∞” means that f ( t ) / f ̂ ( t ) 1 as t → ∞;

  3. lim t f ( t ) 0 t F ( s ) d s ( F ( t ) ) 2 = 1 ,  where  F ( t ) = 0 t f ( s ) d s .

Theorem 2.5.

Let b satisfy (b 1 ) and the following condition

  • (b 3 ) there exist positive constants b 1, b 2 and θ ∈ Λ with D θ > 0 such that

b 1 lim inf d ( x ) 0 b ( x ) θ k + 1 ( d ( x ) ) lim sup d ( x ) 0 b ( x ) θ k + 1 ( d ( x ) ) b 2 ,

f ∈ Γ satisfy (f 1 ) (or (f 01 )), then any k-convex solution u to problem (1.1) satisfies

(2.7) u ( x ) = L ( ( Θ ( d ( x ) ) ) 1 ) ( 1 + o ( 1 ) )  as  d ( x ) 0 ,

where L is defined by

(2.8) L ( t ) k 1 ( s ) f ̂ ( s ) d s = 1 t k + 1  for large  t > 0

and is a normalized slowly varying function with

(2.9) lim t t L ( t ) ( L ( t ) ) = 1 ,

where f ̂ is given by (2.6).

Remark 2.6.

In fact, Theorem 2.5 does not include the case that b is borderline singular on the boundary. To consider the first expansion of large solutions in this case, we introduce some classes of Karamata functions as follows. Let L denote the set of Karamata functions defined on (0, δ 2] by

L ( t ) = c exp t δ 2 z ( s ) s d s , c > 0 , z C ( 0 , δ 2 ]  and  z ( t ) 0  as  t 0 + .

Define

L 1 L L : 0 δ 2 L ( s ) s d s <  and  L 2 L L : 0 δ 2 L ( s ) s d s = .

Theorem 2.7.

Let b satisfy (b 1 ) and the following condition

  • (b 4 ) there exist positive constants b 3, b 4 and L L 1 such that

b 3 lim inf d ( x ) 0 b ( x ) ( d ( x ) ) ( k + 1 ) L k ( d ( x ) ) lim sup d ( x ) 0 b ( x ) ( d ( x ) ) ( k + 1 ) L k ( d ( x ) ) b 4 ,

f ∈ Γ satisfy (f 1 ) (or (f 01 )), then any k-convex solution u to problem (1.1) satisfies

u ( x ) = L ( ( r ( d ( x ) ) ) 1 ) ( 1 + o ( 1 ) )  as  d ( x ) 0 ,

where

r ( d ( x ) ) = 0 d ( x ) L ( s ) s d s k / ( k + 1 ) ,

L and are defined by (2.8), (2.9).

Remark 2.8.

Since Γ-varying functions are rapidly varying at infinity, it is clear that if f ∈ Γ, then (f 2 ) holds naturally.

When Ω is a spherical region, we show the existence of positive k-convex radial solutions to problem (1.1) as follows. Without loss of generality, we suppose Ω is a unit ball.

Theorem 2.9.

Let Ω be a unit ball, bC(Ω) with b ( x ) = b ̃ ( r ) and

(2.10) 0 1 0 r b ̃ ( t ) d t 1 / k d r = ,

f satisfy (f 1 ) (or (f 01 )) and (1.7) hold, then problem (1.1) has infinitely many positive k-convex radial solutions.

Remark 2.10.

By the proof of Theorem 2.9, we find that in Theorem 2.9, if Ω = R N and we replace (2.10) by

(2.11) 0 R r k N 0 r t N 1 b ̃ ( t ) d t 1 / k d r =  with  R = ,

and other conditions still hold, then the entire blow-up problem

S k ( D 2 u ) = b ̃ ( | x | ) f ( u )  in  R N , u ( | x | )  as  | x |

has infinitely many positive entire k-convex radial solutions.

In fact, by a simple calculation, we see that (2.10) is equivalent to (2.11) with R = 1.

To investigate the global estimates of radial solutions, we extend the class of functions L 2 by the following way. For each L L 2 , let L ̃ C 1 ( 0 , ) be a positive differential extension of L. Define

L ̃ 2 { L ̃ : L L 2 } .

For two functions h 1 and h 2 defined on S, h 1(x) ≍ h 2(x), xS means that there exist positive constants c 1, c 2 such that c 1 h 1(x) ≤ h 2(x) ≤ c 2 h 1(x), xS. Without loss of generality, let Ω be still a unit ball. We next show the global estimates of positive k-convex radial solutions to problem (1.1).

Theorem 2.11.

Let Ω be a unit ball in R N , b = b ̃ ( r ) satisfy (b 1 ) and the following condition

  • (b 5 ) there exists L ̃ L ̃ 2 such that t t γ L ̃ k ( t ) ( γ k + 1 ) is non-increasing on (0, r 0] (r 0 > 1) and the following holds

(2.12) b ( x ) = b ̃ ( r ) ( 1 r ) γ L ̃ k ( 1 r ) , r < 1  close to  1 ,

f satisfy (f 1 ) (or (f 01 )) and f ( t ) f ̃ ( t ) for t > 0, where f ̃ C [ 0 , ) R V Z p 0 R V p with p 0k and p < k. In particular, if p 0 = k, we need to verify

(2.13) 0 1 ( F ̃ ( s ) ) 1 / ( k + 1 ) d s < , F ̃ ( t ) = 0 t f ̃ ( s ) d s .

Then any positive k-convex radial solution v to problem (1.1) satisfies

(2.14) Φ 1 ( v ( r ) ) ( ν ( 1 r 2 ) ) k / ( k + 1 ) , r [ 0,1 ) ,

where Φ−1 is the inverse of Φ which is uniquely determined by

(2.15) 0 Φ ( t ) ( ( k + 1 ) F ̃ ( s ) ) 1 / ( k + 1 ) d s = t , F ̃ ( t ) = 0 t f ̃ ( s ) d s ;

and

(2.16) ν ( t ) = t r 0 k s r 0 τ γ L ̃ k ( τ ) d τ 1 / k d s .

Remark 2.12.

In Theorem 2.11, p 0 < k and p < k imply that (2.13) and the following hold

1 ( F ̃ ( s ) ) 1 / ( k + 1 ) d s = .

Theorem 2.13.

Let Ω be a unit ball in R N , b ( x ) = b ̃ ( r ) satisfy (b 1 ) and (b 5 ), f satisfy (f 1 ) (or (f 01 )) and f ( t ) f ̃ ( t ) for t > 0, where f ̃ C [ 0 , ) and satisfies

(2.17) lim sup t ( F ̃ ( t ) ) k / ( k + 1 ) f ̃ ( t ) <  and  lim inf t ( F ̃ ( t ) ) k / ( k + 1 ) f ̃ ( t ) > 0 .

Let C * be an arbitrary positive constant, we have

  1. if γ > k + 1 in (b 5 ), then any positive k-convex radial solution v with v ( 0 ) > C * to problem (1.1) satisfies (2.14), where Φ−1 is the inverse of Φ which is uniquely determined by

    (2.18) C * Φ ( t ) ( ( k + 1 ) F ̃ ( s ) ) 1 / ( k + 1 ) d s = t , F ̃ ( t ) = 0 t f ̃ ( s ) d s ;

  2. if γ = k + 1 in (b 5 ) and lim sup t 0 + L ̃ ( t ) < , then any positive k-convex radial solution v with v ( 0 ) > C * to problem (1.1) satisfies Φ−1(v(r)) ≍ ν(1 − r 2), r ∈ [0, 1), where Φ−1 is the inverse of Φ which is uniquely determined by (2.18), ν is given by (2.16).

Corollary 2.14.

Let b satisfy the hypotheses in Theorem 2.13, f satisfy (f 1 ) (or (f 01 )) and f(t) ≍ t k for t ≥ 1, then the results of Theorem 2.13 hold with

Φ 1 ( t ) = ln t , t > 1 .

Remark 2.15.

The condition (2.13) is unnecessary in Theorem 2.13 and Corollary 2.14.

Obviously, in Theorems 2.11, 2.13 and Corollary 2.14, b ̃ ( r ) is controlled by a regularly varying function. Now, we consider the global estimate of positive k-convex radial solutions to problem (1.1) when b ̃ ( r ) is controlled by a function which is rapidly varying to infinity at zero. For convenience, we now introduce a new class of rapidly varying functions as follows.

Let Λ denote the set of all positive decreasing functions θ C 1(0, 1] which satisfy

(2.19) lim t 0 + d d t Θ ( t ) θ ( t ) = 0 , Θ ( t ) = t 1 θ ( s ) d s .

Theorem 2.16.

Let Ω be a unit ball in R N , b ( x ) = b ̃ ( r ) satisfy (b 1 ) and the following condition

(b 6 ) there exists θ ∈ Λ such that b ̃ ( r ) θ ( 1 r 2 ) , r < 1 close to 1.

  1. If f satisfies the hypotheses in Theorem 2.11, then any positive k-convex radial solution v to problem (1.1) satisfies

    (2.20) Φ 1 ( v ( r ) ) Θ ( 1 r 2 ) , r [ 0,1 ) ,

    where Φ−1 is the inverse of Φ which is uniquely determined by (2.15).

  2. If f satisfies the hypotheses in Theorem 2.13 and C * is an arbitrary positive constant, then any positive k-convex radial solution v with v ( 0 ) > C * to problem (1.1) satisfies (2.20), where Φ is replaced by the solution of (2.18).

Remark 2.17.

By Lemma B.2 (iv) (see Appendix B), we obtain that θ is rapidly varying to infinity at zero. So, we have θ (1 − r 2) can not be controlled by θ (1 − r). This implies that the condition b ̃ ( r ) θ ( 1 r 2 ) can not be replaced by b ̃ ( r ) θ ( 1 r ) in Theorem 2.16.

Let Q (see [33], [39]) denote the set of all the decreasing functions qC(0, ∞) which satisfy

0 1 ( Q ( t ) ) 1 / k d t =  and  1 ( Q ( t ) ) 1 / k d t < ,  where  Q ( t ) = t 1 q ( s ) d s .

For more general class Q , we have the following results.

Theorem 2.18.

Under the hypotheses in Theorem 2.11, if we replace (b 5 ) by the condition

(2.21) b ̃ ( r ) q ( 1 r 2 ) , r < 1  close to  1  for some  q Q

and other conditions still hold, then the results of Theorem 2.11 hold, where ν is replaced by

(2.22) ν ( t ) = t ( k Q ( s ) ) 1 / k d s .

Theorem 2.19.

Under the hypotheses in Theorem 2.13, if we replace (b 5 ) by (2.21) and other conditions still hold. Then

  1. When

    lim inf t 0 + ( k Q ( t ) ) k + 1 k q ( t ) t ( k Q ( s ) ) 1 / k d s > 0 ,

    the results of (i) in Theorem 2.13 still hold, where ν is replaced by (2.22).

  2. When

    lim sup t 0 + ( Q ( t ) ) k + 1 k q ( t ) < ,

    the results of (ii) in Theorem 2.13 still hold, where ν is replaced by (2.22).

3 Some preliminary results

In this section, we collect some well-known results which are important to our results on the boundary behaviors of solutions.

Lemma 3.1.

Let Ω be a bounded domain, b satisfy (b 1 ), f satisfy (f 1 ) (or (f 01 )) and u , v C ( Ω ̄ ) C 2 ( Ω ) be k-convex functions with uv on Ω. If for any x ∈ Ω,

S k ( D 2 u ( x ) ) b ( x ) f ( u ( x ) )  and  S k ( D 2 v ( x ) ) b ( x ) f ( v ( x ) ) ,

then uv in Ω.

Proof.

The proof is similar to the one of Lemma 2.1 of Jian’s paper [25] and we omit it here.□

Lemma 3.2.

(Lemma 14.16 of [59]) Let Ω be a bounded domain and Ω ∈ C m for m ≥ 2. Then there exists a positive constant δ 1 depending on Ω such that d C m ( Ω δ 1 ) , where Ω δ 1 is given as shown in (b 2 ) (please refer to page 3), i.e., Ω δ 1 { x Ω : d ( x ) < δ 1 } .

Lemma 3.3.

(Lemma 14.17 of [59]) Let Ω and δ 1 satisfy the condition of Lemma 3.2 and let x Ω δ 1 , x ̄ Ω such that | x x ̄ | = d ( x ) . Then, in terms of a principal coordinate system at x ̄ , we have

D 2 d ( x ) = diag E ( x ) , 0  and  d ( x ) = ( 0 , , 0,1 ) ,

where E ( x ) = ( E 1 ( x ) , , E N 1 ( x ) ) is given by (2.5) .

By Lemma 3.3, we see that

D i d ( x ) = 0 ,  if  i N ; 1 ,  if  i = N ,  and  D i j d ( x ) = 0 ,  if  i j , i N  and  j N ; E i ( x ) ,  if  i = j N ; 0 ,  if  i = j = N .

Lemma 3.4.

(Corollary 2.3 of [31]) Let hC 2(0, δ 1) and Ω be bounded with Ω ∈ C m for m ≥ 2. Assume that x Ω δ 1 and x ̄ Ω is the nearest point to x, i.e., | x x ̄ | = d ( x ) , then

S k ( D 2 h ( d ( x ) ) ) = ( h ( d ( x ) ) ) k S k ( E ( x ) ) + ( h ( d ( x ) ) ) k 1 h ( d ( x ) ) S k 1 ( E ( x ) ) ,

where E is given by (2.5).

Our proofs of Theorems are given in Sections 49. Some auxiliary lemmas and preliminaries of Karamata regular (rapid) variation theory are given in Appendix A and B.

4 Proof of Theorem 2.1

In this section, we prove Theorem 2.1.

Proof.

Let

ε ( 0 , ( | A 0 | + 1 ) / 2 )

and

(4.1) A ± A 0 ± ε  and  τ ± exp ( A ± ) ,

where A 0 is given by (2.3). It is clear that

exp 3 ( | A 0 | + 1 ) 2 < τ < τ + < exp 3 ( | A 0 | + 1 ) 2 .

Take δ * ( 0 , min { δ 1 , δ ̃ } / 2 ) (δ 1 is given in Lemma 3.2 and δ ̃ is given in (b 2 )), σ ∈ (0, δ *) and define

D σ Ω 2 δ * \ Ω ̄ σ  and  D + σ Ω 2 δ * σ .

Let

u + ( x ) τ + ψ ( B ( x ) Θ ( d ( x ) ) ) , x D σ  and  u ( x ) τ ψ ( B ( x ) Θ + ( d ( x ) ) ) , x D + σ ,

where B is given by (2.4) and

Θ ( d ( x ) ) Θ ( d ( x ) ) Θ ( σ ) .

Since Ω is a bounded C -smooth domain, for any m ≥ 4 we have Ω is a C m -smooth domain. By Lemma 3.3, we can always adjust δ * (small enough) such that for any x Ω ̄ 2 δ * , there hold

κ i ( x ̄ ( x ) ) = D i i d ( x ) 1 d ( x ) D i i d ( x )  for  i = 1 , , N 1 .

It follows by Lemma 3.2 (with m ≥ 4) that κ i ( x ̄ ) C m 2 ( Ω ̄ 2 δ * ) . Moreover, the strict (k − 1)-convexity of Ω implies that we can further adjust δ * such that S k 1 ( E ) > 0 in Ω ̄ 2 δ * . So, we arrive at B C m 2 ( Ω ̄ 2 δ * ) .

A straightforward calculation shows that

D i j u ± ( x ) = τ ± ψ ( B ( x ) Θ ( d ( x ) ) ) D i B ( x ) D j B ( x ) Θ 2 ( x ) + D j B ( x ) D i d ( x ) B ( x ) Θ ( d ( x ) ) θ ( d ( x ) ) + D i B ( x ) D j d ( x ) B ( x ) Θ × ( d ( x ) ) θ ( d ( x ) ) + B 2 ( x ) θ 2 ( d ( x ) ) D i d ( x ) D j d ( x ) + τ ± ψ B ( x ) × Θ ( d ( x ) ) Θ ( d ( x ) ) D i j B ( x ) + θ ( d ( x ) ) D i B ( x ) D j d ( x ) + θ ( d ( x ) ) D i d ( x ) D j B ( x ) + B ( x ) θ ( d ( x ) ) D j d ( x ) D i d ( x ) + B ( x ) θ ( d ( x ) ) D i j d ( x ) .

So, we arrive at

  1. If ij, iN and jN, then

    D i j u ± ( x ) = τ ± ψ ( B ( x ) Θ ( d ( x ) ) ) Θ 2 ( d ( x ) ) D i B ( x ) D j B ( x ) + τ ± ψ × ( B ( x ) Θ ( d ( x ) ) ) Θ ( d ( x ) ) D i j d ( x ) = ψ ( B ( x ) Θ ( d ( x ) ) ) Θ 2 × ( d ( x ) ) τ ± D i B ( x ) D j B ( x ) + τ ± B ( x ) D i j B ( x ) ψ ( B ( x ) Θ ( d ( x ) ) ) ψ ( B ( x ) Θ ( d ( x ) ) ) B ( x ) Θ ( d ( x ) ) ;

  2. If i = N and jN, then

    D i j u ± ( x ) = τ ± ψ ( B ( x ) Θ ( d ( x ) ) ) Θ 2 ( d ( x ) ) D N B ( x ) D j B ( x ) + B ( x ) Θ × ( d ( x ) ) θ ( d ( x ) ) D j B ( x ) + τ ± ψ ( B ( x ) Θ ± ( d ( x ) ) ) Θ ( d ( x ) ) D N j B ( x ) + θ ( d ( x ) ) D j B ( x ) = ψ ( B ( x ) Θ ( d ( x ) ) ) Θ ( d ( x ) ) θ ( d ( x ) ) τ ± Θ ( d ( x ) ) θ ( d ( x ) ) D N B ( x ) D j B ( x ) + τ ± B ( x ) D j B ( x ) + ψ ( B ( x ) Θ ( d ( x ) ) ) ψ ( B ( x ) Θ ( d ( x ) ) ) B ( x ) Θ ( d ( x ) ) × τ ± B ( x ) Θ ( d ( x ) ) θ ( d ( x ) ) D N j B ( x ) + τ ± B ( x ) D j B ( x ) ;

  3. If iN and j = N, then

    D i j u ± ( x ) = τ ± ψ ( B ( x ) Θ ( d ( x ) ) ) Θ 2 ( d ( x ) ) D i B ( x ) D N B ( x ) + B ( x ) Θ × ( d ( x ) ) θ ( d ( x ) ) D i B ( x ) + τ ± ψ ( B ( x ) Θ ( d ( x ) ) ) Θ ( d ( x ) ) D i N B ( x ) + θ ( d ( x ) ) D i B ( x ) = ψ ( B ( x ) Θ ( d ( x ) ) ) Θ ( d ( x ) ) θ ( d ( x ) ) τ ± Θ ( d ( x ) ) θ ( d ( x ) ) D i B ( x ) D N × B ( x ) + τ ± B ( x ) D i B ( x ) + ψ ( B ( x ) Θ ( d ( x ) ) ) ψ ( B ( x ) Θ ( d ( x ) ) ) B ( x ) Θ ( d ( x ) ) × τ ± B ( x ) Θ ( d ( x ) ) θ ( d ( x ) ) D i N B ( x ) + τ ± B ( x ) D i B ( x ) ;

  4. If i = j = N, then

    D i j u ± ( x ) = τ ± ψ ( B ( x ) Θ ( d ( x ) ) ) Θ ± 2 ( d ( x ) ) ( D N B ( x ) ) 2 + 2 B ( x ) Θ ( d ( x ) ) θ × ( d ( x ) ) D N B ( x ) + B 2 ( x ) θ 2 ( d ( x ) ) + τ ± ψ ( B ( x ) Θ ( d ( x ) ) ) × Θ ( d ( x ) ) D N N B ( x ) + 2 θ ( d ( x ) ) D N B ( x ) + B ( x ) θ ( d ( x ) ) = ψ ( B ( x ) Θ ( d ( x ) ) ) θ 2 ( d ( x ) ) τ ± ( D N B ( x ) ) 2 Θ ( d ( x ) ) θ ( d ( x ) ) 2 + 2 τ ± Θ ( d ( x ) ) θ ( d ( x ) ) B ( x ) D N B ( x ) + τ ± B 2 ( x ) + τ ± × ψ ( B ( x ) Θ ( d ( x ) ) ) ψ ( B ( x ) Θ ( d ( x ) ) ) B ( x ) Θ ( d ( x ) ) Θ ( d ( x ) ) θ ( d ( x ) ) 2 D N N B ( x ) × B ( x ) + 2 B ( x ) Θ ( d ( x ) ) θ ( d ( x ) ) D N B ( x ) + B 2 ( x ) Θ ( d ( x ) ) θ ( d ( x ) ) θ 2 ( d ( x ) ) ;

  5. If i = jN, then

    D i j u ± ( x ) = τ ± ψ ( B ( x ) Θ ( d ( x ) ) ) ( D i B ( x ) ) 2 Θ 2 ( d ( x ) ) + τ ± ψ × ( B ( x ) Θ ( d ( x ) ) ) Θ ( d ( x ) ) D i i B ( x ) + B ( x ) θ ( d ( x ) ) D i i d ( x ) = ψ ( B ( x ) Θ ( d ( x ) ) ) θ ( d ( x ) ) A i ± ( x ) ,

    where

    A i ± ( x ) = τ ± ψ ( B ( x ) Θ ( d ( x ) ) ) B ( x ) Θ ( d ( x ) ) ψ ( B ( x ) Θ ( d ( x ) ) ) Θ ( d ( x ) ) θ ( d ( x ) ) ( D i B ( x ) ) 2 B ( x ) τ ± Θ ( d ( x ) ) θ ( d ( x ) ) D i i B ( x ) B ( x ) E i ( x ̄ ( x ) ) .

    The condition (b 2 ) implies that θ is a non-increasing function. We conclude by the above (i)(v), Lemma B.1, Lemma B.3 (i), (ii), (ix)(xi) (see Appendix B) and the calculation of the sum of principal minors of size k to the Hessian D 2 u ±(x) that

    S k ( D 2 u ± ( x ) ) = ψ ( B ( x ) Θ ( d ( x ) ) ) θ 2 ( d ( x ) ) τ ± ( D N B ( x ) ) 2 Θ ( d ( x ) ) θ ( d ( x ) ) 2 + 2 τ ± Θ ( d ( x ) ) θ ( d ( x ) ) B ( x ) × D N B ( x ) + τ ± B 2 ( x ) + τ ± ψ ( B ( x ) Θ ( d ( x ) ) ) ψ ( B ( x ) Θ ( d ( x ) ) ) B ( x ) Θ ( d ( x ) ) B ( x ) Θ ( d ( x ) ) θ ( d ( x ) ) 2 D N N B ( x ) + 2 B ( x ) Θ ( d ( x ) ) θ ( d ( x ) ) D N B ( x ) + B 2 ( x ) Θ ( d ( x ) ) θ ( d ( x ) ) θ 2 ( d ( x ) ) × ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) k 1 θ k 1 ( d ( x ) ) S k 1 A 1 ± ( x ) , , A N 1 ± ( x ) + O ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) k 2 θ k 2 ( d ( x ) ) ψ ( B ( x ) Θ ( d ( x ) ) ) Θ 2 ( d ( x ) ) + O ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) k θ k ( d ( x ) ) = ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) k 1 ψ ( B ( x ) Θ ( d ( x ) ) ) θ k + 1 ( d ( x ) ) × τ ± B 2 ( x ) ψ ( B ( x ) Θ ( d ( x ) ) ) ψ ( B ( x ) Θ ( d ( x ) ) ) B ( x ) Θ ( d ( x ) ) Θ ( d ( x ) ) θ ( d ( x ) ) θ 2 ( d ( x ) ) + τ ± B 2 ( x ) + τ ± ( D N B ( x ) ) 2 B ( x ) × Θ ( d ( x ) ) θ 2 ( d ( x ) ) B ( x ) Θ ( d ( x ) ) g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) + 2 τ ± B ( x ) Θ ( d ( x ) ) g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) × g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) θ ( d ( x ) ) D N B ( x ) + τ ± ψ ( B ( x ) Θ ( d ( x ) ) ) ψ ( B ( x ) Θ ( d ( x ) ) ) B ( x ) Θ ( d ( x ) ) B ( x ) Θ 2 ( d ( x ) ) g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) × g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) θ 2 ( d ( x ) ) D N N B ( x ) + 2 B ( x ) Θ ( d ( x ) ) D N B ( x ) g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) θ ( d ( x ) ) × τ ± k 1 B k 1 ( x ) S k 1 ( E ( x ) ) + O ψ ( B ( x ) Θ ( d ( x ) ) ) B ( x ) Θ ( d ( x ) ) ψ ( B ( x ) Θ ( d ( x ) ) ) B ( x ) Θ ( d ( x ) ) g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) × g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) θ ( d ( x ) ) + O ψ ( B ( x ) Θ ( d ( x ) ) ) ψ ( B ( x ) Θ ( d ( x ) ) ) B ( x ) Θ ( d ( x ) ) Θ ( d ( x ) ) θ ( d ( x ) ) = ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) k 1 ψ ( B ( x ) Θ ( d ( x ) ) ) θ k + 1 ( d ( x ) ) τ ± k B k + 1 ( x ) × ψ ( B ( x ) Θ ( d ( x ) ) ) ψ ( B ( x ) Θ ( d ( x ) ) ) B ( x ) Θ ( d ( x ) ) Θ ( d ( x ) ) θ ( d ( x ) ) θ 2 ( d ( x ) ) + 1 + o ( g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) ) × S k 1 ( E ( x ) ) + o ( g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) ) + o ( g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) ) = ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) k 1 ψ ( B ( x ) Θ ( d ( x ) ) ) θ k + 1 ( d ( x ) ) τ ± k B k + 1 ( x ) × ψ ( B ( x ) Θ ( d ( x ) ) ) ψ ( B ( x ) Θ ( d ( x ) ) ) B ( x ) Θ ( d ( x ) ) Θ ( d ( x ) ) θ ( d ( x ) ) θ 2 ( d ( x ) ) S k 1 ( E ( x ) ) + S k 1 ( E ( x ) ) + o ( g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) ) = f 1 ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) θ k + 1 ( d ( x ) ) τ ± k B k + 1 ( x ) × ψ ( B ( x ) Θ ( d ( x ) ) ) f 1 ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) k k + 1 f 1 ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) g ( B ( x ) Θ ( d ( x ) ) ) B ( x ) Θ ( d ( x ) ) Θ ( d ( x ) ) θ ( d ( x ) ) θ 2 ( d ( x ) ) S k 1 ( E ( x ) ) + ( g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) ) 1 k + 1 1 + ψ ( B ( x ) Θ ( d ( x ) ) ) f 1 ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) f 1 ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) S k 1 ( E ( x ) ) + o ( 1 ) .

    This implies that

    S k ( D 2 u + ( x ) ) b ( x ) f ( u + ( x ) ) = f 1 ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) θ k + 1 ( d ( x ) ) τ + k B k + 1 ( x ) × ψ ( B ( x ) Θ ( d ( x ) ) ) f 1 ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) k k + 1 f 1 ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) g ( B ( x ) Θ ( d ( x ) ) ) B ( x ) Θ ( d ( x ) ) × Θ ( d ( x ) ) θ ( d ( x ) ) θ 2 ( d ( x ) ) S k 1 ( E ( x ) ) + 1 k + 1 ( g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) ) 1 × 1 + ψ ( B ( x ) Θ ( d ( x ) ) ) f 1 ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) f 1 ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) S k 1 ( E ( x ) ) + o ( 1 ) b ( x ) f 1 ( u + ( x ) ) + f 2 ( u + ( x ) ) f 1 ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) θ k + 1 ( d ( x ) ) τ + k B k + 1 ( x ) I ( σ , x ) ,

    and

    S k ( D 2 u ( x ) ) b ( x ) f ( u ( x ) ) f 1 ( ψ ( B ( x ) Θ + ( d ( x ) ) ) ) g ( ψ ( B ( x ) Θ + ( d ( x ) ) ) ) × θ k + 1 ( d ( x ) ) τ k B k + 1 ( x ) I + ( σ , x ) ,

    where

    I ( σ , x ) = S k 1 ( E ( x ) ) ψ ( B ( x ) Θ ( d ( x ) ) ) f 1 ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) k k + 1 f 1 ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) B ( x ) Θ ( d ( x ) ) × Θ ( d ( x ) ) θ ( d ( x ) ) θ 2 ( d ( x ) ) + ( g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) ) 1 k + 1 × 1 + ψ ( B ( x ) Θ ( d ( x ) ) ) f 1 ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) f 1 ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) f 1 ( τ ± ψ ( B ( x ) Θ ( d ( x ) ) ) ) τ ± k f 1 ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) f 2 ( τ ± ψ ( B ( x ) Θ ( d ( x ) ) ) ) τ ± k f 1 ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) + o ( 1 ) .

    By Lemma B.1 (i), Lemma B.3 (vi)(viii) (see Appendix B) and (4.1), we obtain

    lim ( σ , d ( x ) ) ( 0,0 ) I ( σ , x ) = ( A 0 ln τ ± ) S k 1 ( κ ( x ̄ ) ) = ε S k 1 ( κ ( x ̄ ) ) ,

    where κ ( x ̄ ) is given by (1.2). So, we can take small enough constants δ ɛ δ * and σ ∈ (0, δ ɛ ) such that u + and u are, respectively, supersolution and subsolution in D σ and D + σ , where

    (4.2) D σ Ω 2 δ ε \ Ω ̄ σ  and  D + σ Ω 2 δ ε σ .

    In fact, we can always adjust δ ɛ such that for j = 1, …, k,

    S j ( D 2 u ± ( x ) ) = ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) j 1 ψ ( B ( x ) Θ ( d ( x ) ) ) θ j + 1 ( d ( x ) ) τ ± j × B j + 1 ( x ) ψ ( B ( x ) Θ ( d ( x ) ) ) ψ ( B ( x ) Θ ( d ( x ) ) ) B ( x ) Θ ( d ( x ) ) × Θ ( d ( x ) ) θ ( d ( x ) ) θ 2 ( d ( x ) ) S j 1 ( E ( x ) ) + S j 1 ( E ( x ) ) + o ( g ( ψ ( B ( x ) Θ ( d ( x ) ) ) ) ) > 0 , x D σ ,

    i.e., u + and u are strictly k-convex upper and lower solutions of problem (1.1) in D σ and D + σ , respectively.

    Let u be an arbitrary k-convex solution to problem (1.1). Now, we prove there exists a large positive constant M such that

    (4.3) u ( x ) u + ( x ) + M , x D σ  and  u ( x ) u ( x ) + M , x D + σ .

    It is clear that we can choose some large positive constant M (independent of σ) such that

    (4.4) u u + + M  on  { x Ω : d ( x ) = 2 δ ε }

    and

    (4.5) u u + M  on  { x Ω : d ( x ) = 2 δ ε σ } .

    On the other hand, it is easy to see

    u < u + =  on  { x Ω : d ( x ) = σ }  and  u < u =  on  Ω .

    Take a small enough constant ρ ∈ (0, δ ɛ ) such that

    (4.6) sup x D σ u ( x ) u + ( x ) , x D σ \ D ̃ σ  and  sup x D + σ u ( x ) u ( x ) , x D + σ \ D ̃ + σ ,

    where

    D ̃ σ Ω 2 δ ε \ Ω ̄ ( 1 + ρ ) σ  and  D ̃ + σ Ω 2 δ ε σ \ Ω ̄ ρ .

    It follows from (f 1 ) (or (f 01 )) we see that u + + M and u + M are both supersolutions in D ̃ σ and D ̃ + σ , respectively. By (4.4)(4.6) and Lemma 3.1, we obtain

    u u + + M  in  D ̃ σ  and  u u + M  in  D ̃ + σ .

    This fact, combined with (4.6), shows that (4.3) holds. Passing to σ → 0, we have for any x Ω 2 δ ε , there hold

    u ( x ) ψ ( B ( x ) Θ ( d ( x ) ) ) τ + + M ψ ( B ( x ) Θ ( d ( x ) ) )  and  u ( x ) ψ ( B ( x ) Θ ( d ( x ) ) ) τ M ψ ( B ( x ) Θ ( d ( x ) ) ) .

    By Lemma B.3 (i) (see Appendix B), we arrive at

    lim sup d ( x ) 0 u ( x ) ψ ( B ( x ) Θ ( d ( x ) ) ) τ +  and  lim inf d ( x ) 0 u ( x ) ψ ( B ( x ) Θ ( d ( x ) ) ) τ .

    Letting ɛ → 0, we obtain (2.1). □

5 Proof of Theorem 2.5

In this section, we prove Theorem 2.5. Since Γ-varying functions are rapidly varying to infinity at infinity, we find by Lemma B.4 (iv) (see Appendix B) that L is slowly varying at zero. We know that slowly varying functions are insensitive to the perturbations of independent variable. So, we will prove the first expansion of solutions by using a simpler method than the above.

Proof.

Define

(5.1) M k = max x ̄ Ω S k 1 ( κ ( x ̄ ) )  and  m k = min x ̄ Ω S k 1 ( κ ( x ̄ ) ) ,

where κ ( x ̄ ) is given by (1.2). Let

ε ( 0 , min { 1 , b 1 / 2 ( C 0 + k + 1 ) } ) , C 0 > b 1 + b 2 2

and

τ b 1 ( k + 1 + C 0 ) ε D θ ( k + 1 ) M k 1 / ( k + 1 )  and  τ + b 2 + ( k + 1 + C 0 ) ε D θ ( k + 1 ) m k 1 / ( k + 1 ) .

It follows that

b 1 2 D θ ( k + 1 ) M k 1 / ( k + 1 ) < τ < τ + < 3 b 2 2 D θ ( k + 1 ) m k 1 / ( k + 1 ) .

As before, for any δ > 0, we define

Ω δ { x Ω : 0 < d ( x ) < δ } .

Next, we consider the following two cases.

Case (I) θ is non-increasing on (0, δ 0]. From (b 3 ), Lemma B.1 (i) and Lemma B.4 (i) and (iv) (see Appendix B), we see that there exists sufficiently small δ ɛ < min{δ 0, δ 1}/2 such that for any ( x , r ) Ω 2 δ ε × ( 0 , δ ε ) , there hold

(5.2) m k 1 + ε < S k 1 ( E ( x ) ) < M k 1 ε ;

(5.3) b 1 ε C 0 1 ε < b ( x ) θ k + 1 ( d ( x ) ) < b 2 + ε C 0 1 + ε ;

(5.4) L ( 1 / ( τ Θ ( d ( x ) ) ) ) > 0 , L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) < 0 ;

(5.5) A i ( x , Θ ( d ( x ) ) ) Θ ( d ( x ) ) θ ( d ( x ) ) θ 2 ( d ( x ) ) τ i + 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) τ i + 1 2 τ i + 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) > 0  for  i = 1 , , k ;

(5.6) A 1 ( x , Θ ( d ( x ) ) ) τ k + 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) Θ ( d ( x ) ) θ ( d ( x ) ) S k ( E ( x ) ) ( 1 ε ) + Θ ( d ( x ) ) θ ( d ( x ) ) θ 2 ( d ( x ) ) 2 × L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) + 1 Θ ( d ( x ) ) θ ( d ( x ) ) θ 2 ( d ( x ) ) ( 1 D θ ) M k < ε / 2 ;

(5.7) A 2 ( Θ ( d ( x ) ) ) ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) k L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) × f ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) k ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) k + 1 + 1 k + 1 < ε 2 ( b 2 + C 0 ) ,  where  Θ ( d ( x ) ) = Θ ( d ( x ) ) Θ ( r ) > 0 .

Let σ ∈ (0, δ ɛ ) and define

u ( x ) = L ( 1 / ( τ Θ ( d ( x ) ) ) ) , x D σ ,  with  Θ ( d ( x ) ) = Θ ( d ( x ) ) Θ ( σ ) ,

where D σ are defined as (4.2). By Lemma 3.4, (5.2)(5.7), we have for any x D σ , there holds

S k ( D 2 u ( x ) ) b ( x ) f ( u ( x ) ) = ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) k 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( τ Θ ( d ( x ) ) ) 2 ( k + 1 ) θ k + 1 ( d ( x ) ) × τ k + 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) Θ ( d ( x ) ) θ ( d ( x ) ) S k ( E ( x ) ) + τ k + 1 2 τ k + 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) + τ k + 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) Θ ( d ( x ) ) θ ( d ( x ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) θ 2 ( d ( x ) ) × S k 1 ( E ( x ) ) + b ( x ) θ k + 1 ( d ( x ) ) f ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) ( τ Θ ( d ( x ) ) ) 2 ( k + 1 ) ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) k 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) k 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( τ Θ ( d ( x ) ) ) 2 ( k + 1 ) ( 1 ε ) 1 θ k + 1 ( d ( x ) ) × τ k + 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) Θ ( d ( x ) ) θ ( d ( x ) ) S k ( E ( x ) ) ( 1 ε ) + τ k + 1 2 τ k + 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) + τ k + 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) × Θ ( d ( x ) ) θ ( d ( x ) ) θ 2 ( d ( x ) ) M k + ( b 1 ε C 0 ) f ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) k ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) k + 1 × L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) k ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) k 1 ( 1 ε ) 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( τ Θ ( d ( x ) ) ) 2 ( k + 1 ) θ k + 1 ( d ( x ) ) × A 1 ( x , Θ ( d ( x ) ) ) + ( b 1 ε C 0 ) A 2 ( Θ ( d ( x ) ) ) + τ k + 1 D θ M k b 1 ε C 0 k + 1 0 ,

i.e., u is a supersolution of Eq. (1.1) in D σ . In a similar way, we can show that u + is a subsolution of Eq. (1.1) in D + σ . Moreover, A i ( x , Θ ( d ( x ) ) ) > 0 for i = 1, ⋅⋅⋅, k imply that u and u + are strictly k-convex in D σ and D + σ , respectively.

Case (II) θ is non-decreasing on (0, δ 0]. From Lemma B.1 and Lemma B.4 (see Appendix B), we see that there exists sufficiently small δ ɛ < min{δ 0, δ 1}/2 such that for any x Ω 2 δ ε , (5.2), (5.3) and the following hold

(5.8) L ( 1 / ( τ Θ ( d ( x ) ) ) ) > 0  and  L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) < 0 ,

(5.9) A i ( x , Θ ( d ( x ) ) ) > 0  for  i = 1 , , k , A 1 ( x , Θ ( d ( x ) ) ) < ε / 2

and

(5.10) A 2 ( Θ ( d ( x ) ) ) < ε 2 ( b 2 + C 0 ) ,

where A i , A 1 and A 2 are defined as shown in (5.5)-(5.7).

Let σ ∈ (0, δ ɛ ) and define

u ( x ) = L ( 1 / ( τ Θ ( d ( x ) ) ) ) , x D σ ,

where d (x) = d(x) ∓ σ and D σ are defined as (4.2). Combining (5.8)(5.10) with (5.2), (5.3), we obtain by Lemma 3.4 that for any x D σ , there holds

S k ( D 2 u ( x ) ) b ( x ) f ( u ( x ) ) = ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) k 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( τ Θ ( d ( x ) ) ) 2 ( k + 1 ) θ k + 1 ( d ( x ) ) × τ k + 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) Θ ( d ( x ) ) θ ( d ( x ) ) S k ( E ( x ) ) + τ k + 1 2 τ k + 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) + τ k + 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) Θ ( d ( x ) ) θ ( d ( x ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) θ 2 ( d ( x ) ) × S k 1 ( E ( x ) ) + b ( x ) θ k + 1 ( d ( x ) ) f ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) ( τ Θ ( d ( x ) ) ) 2 ( k + 1 ) ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) k 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( L ( 1 / ( τ ε Θ ( d ( x ) ) ) ) ) k 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( τ Θ ( d ( x ) ) ) 2 ( k + 1 ) ( 1 ε ) 1 θ k + 1 ( d ( x ) ) × τ k + 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) Θ ( d ( x ) ) θ ( d ( x ) ) S k ( E ( x ) ) ( 1 ε ) + τ k + 1 2 τ k + 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) + τ k + 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) × Θ ( d ( x ) ) θ ( d ( x ) ) θ 2 ( d ( x ) ) M k + ( b 1 ε C 0 ) f ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) k ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) k + 1 × L ( 1 / ( τ Θ ( d ( x ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( 1 / ( τ Θ ( d ( x ) ) ) ) k ( L ( 1 / ( τ Θ ( d ( x ) ) ) ) ) k 1 L ( 1 / ( τ Θ ( d ( x ) ) ) ) ( τ Θ ( d ( x ) ) ) 2 ( k + 1 ) ( 1 ε ) 1 θ k + 1 ( d ( x ) ) × A 1 ( x , Θ ( d ( x ) ) ) + ( b 1 ε C 0 ) A 2 ( Θ ( d ( x ) ) ) + τ k + 1 D θ M k b 1 ε C 0 k + 1 0 ,

i.e., u is a supersolution of Eq. (1.1) in D σ . In a similar way, we can show that u + is a subsolution of Eq. (1.1) in D + σ . As before, A i ( x , Θ ( d ( x ) ) ) > 0  for  i = 1 , , k imply that u and u + are strictly k-convex in D σ and D + σ , respectively.

For Cases (I)-(II), let u be an arbitrary k-convex solution to problem (1.1). Now, we show there exists a large constant M > 0 independent of σ such that

u ( x ) u ( x ) + M , x D σ  and  u + ( x ) u ( x ) + M , x D + σ .

By similar arguments as in the proof of Theorem 2.1, we obtain for any x Ω 2 δ ε , the following hold

u ( x ) L ( 1 / ( τ Θ ( d ( x ) ) ) ) 1 + M L ( 1 / ( τ Θ ( d ( x ) ) ) )  and  u ( x ) L ( 1 / ( τ + Θ ( d ( x ) ) ) ) 1 M L ( 1 / ( τ + Θ ( d ( x ) ) ) ) .

Consequently, from (2.8), Lemma B.4 (iv) (see Appendix B) and Proposition A.2 (see Appendix A), we have

lim d ( x ) 0 u ( x ) L ( 1 / Θ ( d ( x ) ) ) = 1 .

This implies that (2.7) holds. The proof is finished.□

6 Proof of Theorem 2.7

In this section, we prove Theorem 2.7.

Proof.

Let

ε ( 0 , min { 1 , b 3 / 2 ( C 1 + k + 1 ) } ) , C 1 > b 3 + b 4 2

and

τ ( b 3 ( C 1 + k + 1 ) ε ) ( k + 1 ) k 1 k k M k 1 / ( k + 1 ) , τ + ( b 4 + ( C 1 + k + 1 ) ε ) ( k + 1 ) k 1 k k m k 1 / ( k + 1 ) ,

where M k and m k are given by (5.1). So, we have

b 3 ( k + 1 ) k 1 2 k k M k 1 / ( k + 1 ) < τ < τ + < 3 b 4 ( k + 1 ) k 1 2 k k m k 1 / ( k + 1 ) .

From (b 4 ), Lemma B.4 and Lemma B.5 (see Appendix B), we see there exist small enough δ ε 1 , δ ε 2 ( 0 , min { δ 1 , δ 2 } / 2 ) (where δ 2 is given in Remark 2.6) such that for any

( x , t , r ) Ω δ ε 1 × 0 , δ ε 1 × 0,2 δ ε 2 ,

Equation (5.2) and the following hold

(6.1) b 3 ε C 1 1 ε < b ( x ) ( d ( x ) ) ( k + 1 ) L k ( d ( x ) ) < b 4 + ε C 1 1 + ε ;

(6.2) L ( 1 / r ) > 0  and  L ( 1 / r ) ( 1 / r ) L ( 1 / r ) < 0 ;

(6.3) τ k + 1 k k + 1 k + 1 L ( t ) 0 t L ( s ) s d s 2 k + 1 k + 1 k k + 1 k L ( 1 / r ) L ( 1 / r ) ( 1 / r ) L ( t ) 0 t L ( s ) s d s k k + 1 k L ( 1 / r ) L ( 1 / r ) ( 1 / r ) 1 L ( t ) t L ( t ) > 0 ;

(6.4) B 1 ( x , t , r ) = τ k + 1 k k + 1 k L ( 1 / r ) t L ( 1 / r ) ( 1 / r ) S k ( E ( x ) ) + k k + 1 k + 1 × L ( t ) 0 t L ( s ) s d s 2 k + 1 k + 1 k k + 1 k L ( 1 / r ) L ( 1 / r ) ( 1 / r ) L ( t ) 0 t L ( s ) s d s + k k + 1 k L ( 1 / r ) L ( 1 / r ) ( 1 / r ) L ( t ) t L ( t ) k k + 1 k L ( 1 / r ) L ( 1 / r ) ( 1 / r ) + 1 M k < ε / 2

and

(6.5) B 2 ( r ) = f ( L ( 1 / r ) ) k ( L ( 1 / r ) ) ( 1 / r ) k + 1 L ( 1 / r ) L ( 1 / r ) ( 1 / r ) ( L ( 1 / r ) ) L ( 1 / r ) ( 1 / r ) k + 1 k + 1 < ε 2 ( b 4 + C 1 ) .

Take σ 0 , δ ε 2 with

σ < b 3 ( k + 1 ) k 1 2 k k M k 1 / ( k + 1 ) 0 δ ε 1 L ( s ) s d s k / ( k + 1 )

and let u be an arbitrary k-convex solution to problem (1.1). Define

D σ Ω δ ε 1 \ Ω σ , D + σ Ω δ ε 1 \ Ω ̄ δ ε 1 δ * ,

where

Ω σ = x Ω δ 1 ε : τ 0 d ( x ) L ( s ) s d s k / ( k + 1 ) σ

and δ * 0 , δ ε 1 is an appropriate constant such that

L τ + 0 d ( x ) L ( s ) s d s k / ( k + 1 ) + σ 1 u ( x ) , x Ω δ ε 1 δ * .

In fact, by adjusting δ ε 1 if necessary, we always assume that

3 b 4 ( k + 1 ) k 1 2 k k m k 1 / ( k + 1 ) 0 d ( x ) L ( s ) s d s k / ( k + 1 ) < δ 2 ε , x Ω δ ε 1 .

Let

u ( x ) = L ( 1 / r ) , x D σ ,

where

r ( d ( x ) ) = τ 0 d ( x ) L ( s ) s d s k / ( k + 1 ) σ .

By Lemma 3.4, (5.2) and (6.1)(6.5), we obtain for any x D σ , there holds

S k ( D 2 u ( x ) ) b ( x ) f ( u ( x ) ) = ( L ( 1 / r ) ) k 1 L ( 1 / r ) r 2 ( k + 1 ) ( d ( x ) ) ( k + 1 ) L k ( d ( x ) ) τ k + 1 k k + 1 k L ( 1 / r ) L ( 1 / r ) ( 1 / r ) × r r + σ d ( x ) S k ( E ( x ) ) + τ k + 1 k k + 1 k + 1 L ( d ( x ) ) 0 d ( x ) L ( s ) s d s 2 τ k + 1 k k + 1 k + 1 × L ( 1 / r ) L ( 1 / r ) ( 1 / r ) L ( d ( x ) ) 0 d ( x ) L ( s ) s d s τ k + 1 k k + 1 k 1 k + 1 L ( 1 / r ) L ( 1 / r ) ( 1 / r ) r r + σ L ( d ( x ) ) 0 d ( x ) L ( s ) s d s τ ε k + 1 k k + 1 k L ( 1 / r ) L ( 1 / r ) ( 1 / r ) r r + σ 1 L ( d ( x ) ) d ( x ) L ( d ( x ) ) S k 1 ( E ( x ) ) + b ( x ) ( d ( x ) ) ( k + 1 ) L k ( d ( x ) ) f ( L ( 1 / r ) ) r 2 ( k + 1 ) ( L ( 1 / r ) ) k 1 L ( 1 / r ) ( L ( 1 / r ) ) k 1 L ( 1 / r ) r 2 ( k + 1 ) ( d ( x ) ) ( k + 1 ) L k ( d ( x ) ) ( 1 ε ) 1 τ k + 1 L ( 1 / r ) L ( 1 / r ) ( 1 / r ) × k k + 1 k d ( x ) S k ( E ( x ) ) ( 1 ε ) + τ k + 1 k k + 1 k + 1 L ( d ( x ) ) 0 d ( x ) L ( s ) s d s 2 τ k + 1 k k + 1 k + 1 × L ( 1 / r ) L ( 1 / r ) ( 1 / r ) L ( d ( x ) ) 0 d ( x ) L ( s ) s d s τ k + 1 k k + 1 k 1 k + 1 L ( 1 / r ) L ( 1 / r ) ( 1 / r ) L ( d ( x ) ) 0 d ( x ) L ( s ) s d s τ k + 1 k k + 1 k L ( 1 / r ) L ( 1 / r ) ( 1 / r ) 1 L ( d ( x ) ) d ( x ) L ( d ( x ) ) M k + ( b 3 ε C 1 ) f ( L ( 1 / r ) ) k ( L ( 1 / r ) ) ( 1 / r ) k + 1 × L ( 1 / r ) L ( 1 / r ) ( 1 / r ) ( L ( 1 / r ) ) L ( 1 / r ) ( 1 / r ) k ( L ( 1 / r ) ) k 1 L ( 1 / r ) r 2 ( k + 1 ) ( d ( x ) ) ( k + 1 ) L k ( d ( x ) ) ( 1 ε ) 1 B 1 ( x , d ( x ) , r ) + ( b 3 ε C 1 ) × B 2 ( r ) + τ k + 1 k k + 1 k M k b 3 C 1 ε k + 1 0 ,

i.e., u is a supersolution of Eq. (1.1) in D σ . In a similar way, we can show that u + is a subsolution of Eq. (1.1) in D + σ . In fact, by Lemma 3.4, Lemma B.4 (iv) and Lemma B.5 (see Appendix B), we can always adjust δ ε 1 and δ ε 2 such that for any x D σ , there hold

S j ( D 2 u ( x ) ) = ( L ( 1 / ( r ) ) ) j 1 ψ ( 1 / ( r ) ) r 2 ( j + 1 ) 0 d ( x ) L ( s ) s d s k j k + 1 ( d ( x ) ) ( j + 1 ) L j ( d ( x ) ) k τ k + 1 j × L ( 1 / r ) L ( 1 / r ) ( 1 / r ) d ( x ) r r ± σ S j ( E ( x ) ) + k τ k + 1 2 L ( 1 / r ) L ( 1 / r ) ( 1 / r ) + 1 L ( d ( x ) ) 0 d ( x ) L ( s ) s d s 1 k + 1 L ( 1 / r ) L ( 1 / r ) ( 1 / r ) r r ± σ L ( d ( x ) ) 0 d ( x ) L ( s ) s d s + L ( 1 / r ) L ( 1 / r ) ( 1 / r ) r r ± σ L ( d ( x ) ) d ( x ) L ( d ( x ) ) L ( d ( x ) ) × S j 1 ( E ( x ) ) > 0  for  j = 1 , , k .

We see that u and u + are strictly k-convex in D σ and D + σ , respectively.

The following process is similar to that of Theorem 2.5. So we omit it here.□

7 Proof of Theorem 2.9

Proof.

Let

N ( r ) 0 r t k N 0 t C N 1 k 1 1 k s N 1 b ̃ ( s ) d s 1 / k d t , r [ 0,1 ) .

For any a > 0, let

(7.1) F a ( t ) a t ( F ( s ) ) 1 / ( k + 1 ) d s , t a .

From (1.7), we get

F a ( ) lim t F a ( t ) =  and  F a ( t ) = ( F ( t ) ) 1 / ( k + 1 ) > 0 , t > a .

This implies that F a has the increasing inverse function F a 1 on [0, ∞) with

(7.2) F a 1 ( 0 ) = a  and  F a 1 ( ) lim t F a 1 ( t ) = .

A straightforward calculation shows that vC 2[0, 1) is a positive radial solution to Eq. (1.1) if and only if v is the solution of the following initial problem

(7.3) C N 1 k 1 v ( r ) r k 1 v + C N 1 k v ( r ) r k = k 1 C N 1 k 1 r 1 N ( r N k ( v ) k ) = b ̃ ( r ) f ( v ( r ) ) , r [ 0,1 ) , v ( 0 ) > 0 , v ( 0 ) = 0 .

So, we investigate the existence of the above problem with the following initial conditions

(7.4) v ( 0 ) = a > 0  and  v ( 0 ) = 0 .

Problem (7.3) with (7.4) is equivalent to

v ( r ) = a + 0 r t k N 0 t C N 1 k 1 1 k s N 1 b ̃ ( s ) f ( v ( s ) ) d s 1 / k d t , r [ 0,1 ) .

To establish the existence of the positive k-convex solution to this equation, we use successive approximation method. Let { v m } m 1 be the sequence of positive continuous functions defined by

v 1 ( r ) = a , v 2 ( r ) = a + 0 r t k N 0 t C N 1 k 1 1 k s N 1 b ̃ ( s ) f ( v 1 ( s ) ) d s 1 / k d t , v m ( r ) = a + 0 r t k N 0 t C N 1 k 1 1 k s N 1 b ̃ ( s ) f ( v m 1 ( s ) ) d s 1 / k d t ,

By (f 1 ) (or (f 01 )), we obtain

v m ( r ) = r k N 0 r C N 1 k 1 1 k s N 1 b ̃ ( s ) f ( v m 1 ( s ) ) d s 1 / k > 0 , r > 0

and

(7.5) v m ( r ) > a + ( f ( a ) ) 1 / k N ( r ) .

Hence the sequence { v m } m 1 is an increasing sequence of positive increasing functions. We note that v m satisfies

( r N k v m k ) = C N 1 k 1 1 k r N 1 b ̃ ( r ) f ( v m 1 ( r ) ) , m 1 .

And by the monotonicity of { v k } k 1 , we have

(7.6) ( r N k v m k ) C N 1 k 1 1 k r N 1 b ̃ ( r ) f ( v m ( r ) ) , m 1 .

For an arbitrary r * ∈ (0, 1), let

B r * max 0 r r * C N 1 k 1 1 k b ̃ ( r ) .

Using this and v m 0 , we see that (7.6) yields

k v m k 1 v m B r * f ( v m )  on  [ 0 , r * ] .

Multiply this by v m and integrate to obtain

(7.7) ( v m ( r ) ) k + 1 k + 1 k B r * a v m ( r ) f ( t ) d t , r [ 0 , r * ] .

This implies that

a v m ( r * ) a t f ( s ) d s 1 / ( k + 1 ) d t k + 1 k B r * 1 / ( k + 1 ) r * R * .

From (7.1), we see that

F a ( v m ) R * .

This fact, combined with (7.2), shows that

(7.8) v m F a 1 ( R * )  on  [ 0 , r * ] .

Thus, { v m } m 1 is uniformly bounded on [0, r *] for any r * ∈ (0, 1). Moreover, by (7.7) and (7.8), we see that v m m 1 is uniformly bounded on [0, r *]. By Arzela-Ascoli’s theorem, we can choose a subsequence of { v m } m 1 , still denoted by { v m } m 1 , such that v m v on [0, r *]. By the arbitrariness of r *, we obtain that v is a positive k-convex solution to problem (7.3), (7.4). Since (2.10) is equivalent to (2.11) with R = 1, we obtain by (7.5) and (2.10) that v(r) → ∞ as r → 1. By the arbitrariness of a, we see problem (1.1) possesses infinitely many positive k-convex radial solutions.□

8 Proofs of Theorems 2.11, 2.13 and 2.16

8.1 Proof of Theorem 2.11

Proof.

By Proposition A.9 (i) (see Appendix A) and Lemma B.5 (see Appendix B), we obtain

(8.1) lim t 0 + k t r 0 s γ L ̃ k ( s ) d s ( k + 1 ) / k t γ L ̃ k ( t ) ν ( t ) = γ k 1 γ 1 ,  if  γ > k + 1 ; 0 ,  if  γ = k + 1 ,

where L ̃ L ̃ 2 and ν is given by (2.16). Moreover, since t t γ L ̃ ( t ) is non-increasing on (0, r 0], by a direct calculation, we obtain

(8.2) k t r 0 s γ L ̃ k ( s ) d s ( k + 1 ) / k t γ L ̃ k ( t ) ν ( t ) = ( k + 1 ) t r 0 s γ L ̃ k ( s ) k s r 0 τ γ L ̃ k ( τ ) d τ 1 / k d s t γ L ̃ k ( t ) t r 0 k s r 0 τ γ L ̃ k ( τ ) d τ 1 / k d s k + 1 .

Let

y ( r ) 1 r 2 , ω ( r ) Φ ( c ( ν ( y ( r ) ) ) k / ( k + 1 ) ) , r [ 0,1 ) ,

where Φ is the solution of (2.14) and c is a positive constant to be determined. Then, we have

lim t 0 + Φ ( t ) = 0 , lim t Φ ( t ) =

and

(8.3) ( Φ ( t ) ) k 1 Φ ( t ) = f ̃ ( Φ ( t ) ) , Φ ( t ) t Φ ( t ) = ( ( k + 1 ) F ̃ ( Φ ( t ) ) ) k k + 1 f ̃ ( Φ ( t ) ) 0 Φ ( t ) ( ( k + 1 ) F ̃ ( s ) ) 1 / ( k + 1 ) d s .

By a direct calculation, we obtain

ω ( r ) = 2 c k k + 1 Φ ( c ( ν ( y ( r ) ) ) k / ( k + 1 ) ) ( ν ( y ( r ) ) ) 1 k + 1 y ( r ) r 0 k s γ L ̃ k ( s ) d s 1 / k r

and

ω ( r ) = 2 c k k + 1 2 Φ ( c ( ν ( y ( r ) ) ) k / ( k + 1 ) ) ( ν ( y ( r ) ) ) 2 k + 1 × y ( r ) r 0 k s γ L ̃ k ( s ) d s 2 / k r 2 2 2 c k ( k + 1 ) 2 Φ ( c ( ν ( y ( r ) ) ) k / ( k + 1 ) ) × ( ν ( y ( r ) ) ) k + 2 k + 1 y ( r ) r 0 k s γ L ̃ k ( s ) d s 2 / k r 2 + 2 2 c k k + 1 Φ × ( c ( ν ( y ( r ) ) ) k / ( k + 1 ) ) ( ν ( y ( r ) ) ) 1 k + 1 y ( r ) r 0 k s γ L ̃ k ( s ) d s ( 1 k ) / k × ( y ( r ) ) γ L ̃ k ( y ( r ) ) r 2 + 2 c k k + 1 Φ ( c ( ν ( y ( r ) ) ) k / ( k + 1 ) ) ( ν ( y ( r ) ) ) 1 k + 1 y ( r ) r 0 k s γ L ̃ k ( s ) d s 1 / k .

So, we further obtain

(8.4) C N 1 k 1 ω ( r ) r k 1 ω ( r ) + C N 1 k ω ( r ) r k = 2 k k + 1 k c k + 1 ( Φ ( c ( ν ( y ( r ) ) ) k / ( k + 1 ) ) ) k 1 Φ ( c ( ν ( y ( r ) ) ) k / ( k + 1 ) ) ( y ( r ) ) γ L ̃ k ( y ( r ) ) F ( c , r ) = 2 k k + 1 k c k + 1 f ̃ ( ω ( r ) ) ( y ( r ) ) γ L ̃ k ( y ( r ) ) F ( c , r ) ,

where

(8.5) F ( c , r ) 2 C N 1 k 1 k y ( r ) r 0 k s γ L ̃ k ( s ) d s ( k + 1 ) / k r 2 ( k + 1 ) ν ( y ( r ) ) ( y ( r ) ) γ L ̃ k ( y ( r ) ) + Φ ( c ( ν ( y ( r ) ) ) k / ( k + 1 ) ) C N 1 k 1 + C N 1 k Φ ( c ( ν ( y ( r ) ) ) k / ( k + 1 ) ) c ( ν ( y ( r ) ) ) k / ( k + 1 ) × k y ( r ) r 0 s γ L ̃ k ( s ) d s ( y ( r ) ) γ L k ( y ( r ) ) + 2 C N 1 k 1 Φ ( c ( ν ( y ( r ) ) ) k / ( k + 1 ) ) r 2 Φ ( c ( ν ( y ( r ) ) ) k / ( k + 1 ) ) c ( ν ( y ( r ) ) ) k / ( k + 1 ) 1 y ( r ) r 0 k s γ L ̃ k ( s ) d s ( k + 1 ) / k ( k + 1 ) ν ( y ( r ) ) ( y ( r ) ) γ L ̃ k ( y ( r ) ) .

By (8.3) and Lemma B.6 (iv) (see Appendix B), we see that

(8.6) lim t 0 + Φ ( t ) Φ ( t ) t = k p 0 p 0 + 1 0  and  lim t Φ ( t ) Φ ( t ) t = k p p + 1 > 0 .

This, combined with (8.1), (8.2) and the definition of y, implies that there exist constants m 1 and m 2 (m 1 and m 2 can be chosen to be independent of c) with

m 1 > 0 ,  if  p 0 < k ( or  p 0 = k , c 1 ) m 1 = 0 ,  if  p 0 = k  and  c < 1

such that

(8.7) m 1 < F ( c , r ) < m 2  for  ( c , r ) ( 0 , ) × [ 0,1 ) .

On the other hand, it follows from the definition of y that

(8.8) y ( r ) = 1 r 2 1 r  and  y ( r ) = ( 1 r ) ( 1 + r ) 2 ( 1 r )  for  r [ 0,1 ) .

Since t t γ L ̃ k ( t ) is non-increasing on (0, ∞), we conclude by (8.8) that

( 2 ( 1 r ) ) γ L ̃ k ( 2 ( 1 r ) ) ( y ( r ) ) γ L ̃ k ( y ( r ) ) ( 1 r ) γ L ̃ k ( 1 r ) .

Since L ̃ N R V Z 0 defined in Proposition A.4 (see Appendix A), we can obtain by Proposition A.2 that there exist positive constants c 1 and c 2 such that

c 1 ( 1 r ) γ L ̃ k ( 1 r ) ( y ( r ) ) γ L ̃ k ( y ( r ) ) c 2 ( 1 r ) γ L ̃ k ( 1 r )  for  r [ 0,1 ) ,

i.e.,

(8.9) ( y ( r ) ) γ L ̃ k ( y ( r ) ) ( 1 r ) γ L ̃ k ( 1 r ) , r [ 0,1 ) .

On the other hand, by (2.12) we obtain

b ̃ ( r ) ( 1 r ) γ L ̃ k ( 1 r ) , r [ 0,1 ) .

This combined with (8.9) shows that

(8.10) b ̃ ( r ) ( y ( r ) ) γ L ̃ k ( y ( r ) ) , r [ 0,1 ) .

By (8.7), (8.10) and f ( u ) f ̃ ( u ) , u > 0 , we can take a small enough constant c = c 1 < 1 and a large enough constant c = c 2 > 1 such that

(8.11) C N 1 k 1 ω 1 ( r ) r k 1 ω 1 ( r ) + C N 1 k ω 1 ( r ) r k b ̃ ( r ) f ( ω 1 ) , r [ 0,1 )

and

(8.12) C N 1 k 1 ω 2 ( r ) r k 1 ω 2 ( r ) + C N 1 k ω 2 ( r ) r k b ̃ ( r ) f ( ω 2 ) , r [ 0,1 ) ,

where

ω i = Φ ( c i ( ν ( y ( r ) ) ) k / ( k + 1 ) ) , r [ 0,1 ) , i = 1,2

with

(8.13) ω 1 ( r ) < ω 2 ( r ) , r [ 0,1 ) .

Take any c ∈ (ω 1(0), ω 2(0)) and let v c be the unique solution of the following initial value problem

C N 1 k 1 v ( r ) r k 1 v ( r ) + C N 1 k v ( r ) r k = b ̃ ( r ) f ( v ) , v ( 0 ) = c , v ( 0 ) = 0 .

It follows from Lemma 5.1 and Lemma 5.2 of [39] that

ω 1 ( r ) v c ( r ) ω 2 ( r ) , r [ 0,1 )  with  v c ( r ) > 0 , v c ( r ) > 0 , r ( 0,1 ) .

Since ω 1(r) → ∞ as r → 1, we obtain v c (r) → ∞ as r → 1. Hence v c is a k-convex radial solution of problem (1.1) and satisfies (2.14). In fact, for any c > 0, we can always take a sufficiently small constant c 1 > 0 and a sufficiently large constant c 2 > 0 such that c ∈ (ω 1(0), ω 2(0)). This implies that (2.14) holds for any positive k-convex solution v c with v(0) = c.□

8.2 Proof of Theorem 2.13

Proof.

Case (I) γ > k + 1. Let

(8.14) V ( t ) ( F ̃ ( t ) ) k / ( k + 1 ) f ̃ ( t ) , t > 0 .

It follows from (2.17) that there exist a large positive constant T * and two positive constants m * and m* such that

(8.15) m * < V ( t ) < m * , t T * .

Moreover, by (8.14), we obtain the following equation

d F ̃ ( t ) d t = ( F ̃ ( t ) ) k / ( k + 1 ) V ( t ) , i . e . , d F ̃ ( t ) F k / ( k + 1 ) ( t ) = d t V ( t ) .

Integration it from T * to t > T *, we obtain

( F ̃ ( t ) ) 1 / ( k + 1 ) = F ̃ ( T * ) + 1 k + 1 T * t d s V ( s ) .

This fact, combined with (8.15), shows that

( F ̃ ( t ) ) 1 / ( k + 1 ) = F ̃ ( T * ) + 1 k + 1 T * t d s V ( s ) 1 > F ̃ ( T * ) + t T * m * ( k + 1 ) 1 .

So, we have

(8.16) C * ( F ̃ ( s ) ) 1 / ( k + 1 ) d s = .

As before, let

y ( r ) 1 r 2 , ω ( r ) Φ ( c ( ν ( y ( r ) ) ) k / ( k + 1 ) ) , r [ 0,1 ) ,

where Φ is the solution of (2.18), ν is given by (2.16) and c is a positive constant to be determined. By (8.16) and (2.18) we obtain

(8.17) lim t 0 + Φ ( t ) = C *  and  lim t Φ ( t ) =

and

(8.18) ( Φ ( t ) ) k 1 Φ ( t ) = f ̃ ( Φ ( t ) ) , Φ ( t ) Φ ( t ) = ( k + 1 ) k / ( k + 1 ) V ( Φ ( t ) ) , t > 0 .

Moreover, by (8.14), we see that

(8.19) lim t 0 + Φ ( t ) Φ ( t ) = ( k + 1 ) k / ( k + 1 ) V ( C * ) = ( k + 1 ) k / ( k + 1 ) ( F ̃ ( C * ) ) k / ( k + 1 ) f ̃ ( C * ) > 0 .

And by (8.17), we see that there exists a large constant t * > 0 such that

Φ ( t ) T * , t t * .

This together with (8.15) and (8.18) implies that

(8.20) ( k + 1 ) k / ( k + 1 ) m * < Φ ( t ) Φ ( t ) < ( k + 1 ) k / ( k + 1 ) m * , t t * .

On the other hand, by the same calculation as (8.4), we obtain

C N 1 k 1 ω ( r ) r k 1 ω ( r ) + C N 1 k ω ( r ) r k = 2 k k + 1 k c k f ̃ ( ω ( r ) ) ( y ( r ) ) γ L ̃ k ( y ( r ) ) c F ( c , r ) ,

where F ( c , r ) is given by (8.5). Combining (8.1) with (8.19), (8.20), we can also take a sufficiently large constant c > 1 and some positive constant m 3 such that

c F ( c , r ) > m 3 .

Moreover, we can take a sufficiently small constant c < 1 and some positive constant m 4 such that

c F ( c , r ) < m 4 ,

where m 3 and m 4 can be chosen to be independent of c.

Case (II) γ = k + 1 and lim sup t 0 + L ̃ ( t ) < .

By Proposition A.9 (i) (see Appendix A), we see that

(8.21) lim sup t 0 + t r 0 k s k 1 L ̃ k ( s ) d s ( k + 1 ) / k t k 1 L ̃ k ( t ) = lim sup t 0 + L ̃ ( t ) < .

Let

ω ( r ) Φ ( c ν ( y ( r ) ) ) , y ( r ) 1 r 2 , r [ 0,1 ) ,

where Φ is the solution of (2.18). A direct calculation shows that

ω ( r ) = 2 c Φ ( c ν ( y ( r ) ) ) y ( r ) r 0 k s k 1 L ̃ k ( s ) d s 1 / k r

and

ω ( r ) = ( 2 c ) 2 Φ ( c ν ( y ( r ) ) ) y ( r ) r 0 k s k 1 L ̃ k ( s ) d s 2 / k r 2 + 2 2 c Φ ( c ν ( y ( r ) ) ) ( y ( r ) ) k 1 L ̃ k ( y ( r ) ) r 2 × y ( r ) r 0 k s k 1 L ̃ k ( s ) d s ( 1 k ) / k + 2 c Φ ( c ν ( y ( r ) ) ) y ( r ) r 0 k s k 1 L ̃ k ( s ) d s 1 / k .

So, we have

C N 1 k 1 ω ( r ) r k 1 ω ( r ) + C N 1 k ω ( r ) r k = ( 2 c ) k ( Φ ( c ν ( y ( r ) ) ) ) k 1 Φ ( c ν ( y ( r ) ) ) ( y ( r ) ) ( k + 1 ) L ̃ k ( y ( r ) ) F ( c , r ) = ( 2 c ) k f ̃ ( ω ( r ) ) ( y ( r ) ) ( k + 1 ) L ̃ k ( y ( r ) ) F ( c , r ) ,

where

F ( c , r ) 2 c C N 1 k 1 y ( r ) r 0 k s k 1 L ̃ ( s ) d s ( k + 1 ) / k r 2 ( y ( r ) ) k 1 L ̃ k ( y ( r ) ) + 2 C N 1 k 1 Φ ( c ν ( y ( r ) ) ) r 2 Φ ( c ν ( y ( r ) ) ) + y ( r ) r 0 k s k 1 L ̃ k ( s ) d s ( y ( r ) ) k 1 L ̃ k ( y ( r ) ) Φ ( c ν ( y ( r ) ) ) C N 1 k 1 + C N 1 k Φ ( c ν ( y ( r ) ) ) .

By (8.19)(8.21), we obtain that there exist positive constants m 5 and m 6 such that

m 5 < F ( c , r ) < m 6  for  ( c , r ) ( 0 , ) × [ 0,1 ) .

The rest of the proof is similar to the one of Theorem 2.11 and thus is omitted.□

8.3 Proof of Theorem 2.16

Proof

Case (I) When f satisfies the conditions in Theorem 2.11, let

ω ( r ) Φ ( c Θ ( y ( r ) ) ) , y ( r ) 1 r 2 , r [ 0,1 ) ,

where Φ is the solution of (2.15) and c is a positive constant to be determined. By a direct calculation, we obtain

ω ( r ) = 2 c Φ ( c Θ ( y ( r ) ) ) θ ( y ( r ) ) r

and

ω ( r ) = ( 2 c ) 2 Φ ( c Θ ( y ( r ) ) ) θ 2 ( y ( r ) ) r 2 2 2 c Φ ( c Φ ( y ( r ) ) ) θ ( y ( r ) ) r 2 + 2 c Φ ( c Θ ( y ( r ) ) ) .

So, we have

C N 1 k 1 ω ( r ) r k 1 ω ( r ) + C N 1 k ω ( r ) r k = ( 2 c ) k + 1 f ̃ ( ω ( r ) ) θ k + 1 ( y ( r ) ) F ( c , r ) ,

where

F ( c , r ) C N 1 k 1 r 2 Φ ( c Θ ( y ( r ) ) ) C N 1 k 1 Φ ( c Θ ( y ( r ) ) ) c Θ ( y ( r ) ) Θ ( y ( r ) ) θ ( y ( r ) ) θ 2 ( y ( r ) ) + Θ ( y ( r ) ) θ ( y ( r ) ) Φ ( c Θ ( y ( r ) ) ) C N 1 k 1 + C N 1 k 2 Φ ( c Θ ( y ( r ) ) ) c Θ ( y ( r ) ) .

By Lemma B.2 (i), (ii) (see Appendix B) and (8.6), we see that there exist constants m 7 and m 8 (m 7 and m 8 can be chosen to be independent of c) with

m 7 > 0 ,  if  p 0 < k ( or  p 0 = k , c 1 ) m 7 = 0 ,  if  p 0 = k  and  c < 1

such that

(8.22) m 7 < F ( c , r ) < m 8  for  ( c , r ) ( 0 , ) × [ 0,1 ) .

On the other hand, it follows from (b 6 ) that

b ̃ ( r ) θ ( y ( r ) ) , r [ 0,1 ) .

This combined with (8.22) implies that we can take a small enough constant c = c 1 < 1 and a large constant c = c 2 such that (8.11), (8.12) hold, where

ω i ( r ) = Φ ( c i Θ ( y ( r ) ) ) , r [ 0,1 ) , i = 1,2

with (8.13) holds here.

The rest of the proof is similar to the one of Theorem 2.11 and thus is omitted.

Case (II) When f satisfies the conditions in Theorem 2.13, let

ω ( r ) Φ ( c Θ ( y ( r ) ) ) , y ( r ) 1 r 2 , r [ 0,1 ) ,

where Φ is the solution of (2.18) and c is a positive constant to be determined. A straightforward calculation shows that

C N 1 k 1 ω ( r ) r k 1 ω ( r ) + C N 1 k ω ( r ) r k = 2 k + 1 c k f ̃ ( ω ( r ) ) θ k + 1 ( y ( r ) ) c F ( c , r ) .

Combining (8.19), (8.20) with Lemma B.2 (i), (ii) (see Appendix B), we can take a sufficiently large constant c > 1 and some positive constant m 9 such that

c F ( c , r ) > m 9 .

Moreover, we can take a sufficiently small constant c < 1 and some positive constant m 10 such that

c F ( c , r ) < m 10 ,

where m 9 and m 10 can be chosen to be independent of c.

The proof of the rest of the theorem is same as the above arguments, thus we omit it here.□

9 Proofs of Theorems 2.18–2.19

Proof.

The proofs are quite similar to the ones in Theorems 2.11, 2.13, so we omit them here.□

In section, we introduce some Appendixes.


Corresponding author: Haitao Wan, School of Mathematics and Information Science, Shandong Technology and Business University, Yantai, Shandong 264005, P.R. China, E-mail:

Acknowledgments

The author is greatly indebted to the anonymous referees for the invaluable suggestions and comments which quite highly improved the quality of the presentation.

  1. Research ethics: Not applicable.

  2. Author contributions: The author has accepted responsibility for the entire content of this manuscript and approved its submission.

  3. Competing interests: The author states no conflict of interest.

  4. Research funding: The research of the author is supported by NSF of Shandong Province of China under Grant No.ZR2021MA007.

  5. Data availability: Not applicable.

Appendix A

In this appendix, we introduce some basic facts of Karamata regular (rapid) variation theory, which come from Bingham, Goldie and Teugels’ book [60], Geluk and de Hann’s book [58] and Resnick’s book [61]. Some new results on rapidly varying functions, we refer to the paper [62].

Definition A.1.

A positive continuous function f defined on [a , ∞) ((0, a 0]), for some a > 0 (a 0 > 0), is called rapidly varying to infinity at infinity (zero), written f R f R 0 , if for each C ( 0,1 ) ( C ( 1 , ) ) ,

lim t f ( C t ) f ( t ) = 0 lim t 0 + f ( C t ) f ( t ) = 0 .

A positive continuous function f is called general rapidly varying to infinity at infinity (zero), written f G f G 0 , if for each m > 0,

lim t t m f ( t ) = ( lim t 0 + t m f ( t ) = ) .

By Theorem 1.1 and Remark 1.2 in [62], we see that R G , and by the similar argument as the ones of Theorem 1.1 and Remark 1.2 in [62], we can obtain R 0 G 0 .

Proposition A.2.

(Uniform Convergence Theorem). If fRV(Z) ρ , then (1.6) holds uniformly for C [ c 1 , c 2 ] with 0 < c 1 < c 2.

Proposition A.3.

(Representation Theorem) A function L is slowly varying at infinity if and only if it may be written in the form

L ( t ) = ς ( t ) exp a t y ( s ) s d s , t a ,

for some a > 0, where the functions ς and y are continuous and for t → ∞, y (t) → 0 and ς (t) → c , with c > 0. We call that

L ( t ) = c exp a t y ( s ) s d s , t a ,

is normalized slowly varying at infinity and f(t) = t ρ L (t) is normalized regularly varying at infinity with index ρ (and written fNRV ρ ).

Proposition A.4.

A function L 0 is slowly varying at zero if and only if it may be written in the form

L 0 ( t ) = ς 0 ( t ) exp t a 0 y 0 ( s ) s d s , t a 0 ,

for some a 0 > 0, where the functions ς 0 and y 0 are continuous and for t → 0+, y 0(t) → 0 and ς 0(t) → c 0, with c 0 > 0. We call that

L 0 ( t ) = c 0 exp t a 0 y 0 ( s ) s d s , t a 0 ,

is normalized slowly varying at zero and h(t) = t ρ L 0(t) is normalized regularly varying at zero with index ρ (and written hNRVZ ρ ).

Proposition A.5.

A function f C 1 a , ) ( f C 1 ( 0 , a 0 ), for some a > 0 (a 0 > 0), belongs to NRV ρ  (NRVZ ρ ) if and only if lim s t f ( t ) f ( t ) = ρ lim t 0 + t f ( t ) f ( t ) = ρ .

Proposition A.6.

If h 1 N R V μ 1 , h 2 N R V μ 2 with lim t h 2 ( t ) = , then h 1 h 2 N R V μ 1 μ 2 ;

Proposition A.7.

If h 1 N R V μ 1 , h 2 N R V μ 2 , then h 1 h 2 N R V μ 1 + μ 2 .

Proposition A.8.

If functions L, L 1 are slowly varying at zero, then

  1. L ρ (for every ρ R ), c 1 L + c 2 L 1 (c 1 ≥ 0, c 2 ≥ 0 with c 1 + c 2 > 0), LL 1 (if L 1(t) → 0 as t → 0+), are also slowly varying at zero;

  2. for every ρ > 0 and t → 0+, t ρ L(t) → 0 and t ρ L(t) → ∞;

  3. for ρ R and t → 0+, lnL(t)/lnt → 0 and ln(t ρ L(t))/lntρ.

Proposition A.9.

(Asymptotic Behavior) Let L be a slowly varying function at infinity.

  1. t s ρ L ( s ) d s ( ρ 1 ) 1 t 1 + ρ L ( t ) , t ,  for ρ < 1 ;

  2. 0 t s ρ L ( s ) d s ( ρ + 1 ) 1 t 1 + ρ L ( t ) , t ,  for  ρ > 1 .

Appendix B

Lemma B.1.

Let θ ∈ Λ, then

  1. lim t 0 + Θ ( t ) θ ( t ) = 0 and lim t 0 + Θ ( t ) θ ( t ) θ 2 ( t ) = 1 D θ ;

  2. if θ is non-decreasing, then D θ ∈ [0, 1]; if θ is non-increasing, then D θ ∈ [1, ∞);

  3. if D θ > 0, then θ N R V Z ( 1 D θ ) / D θ .

Proof.

(i)(iii) By a direct calculation, we see that (i)(iii) hold.□

Lemma B.2.

Let θ ∈ Λ, then

  1. θ ( t ) < 0 , t ∈ (0, 1] and lim t 0 + Θ ( t ) θ ( t ) θ 2 ( t ) = 1 ;

  2. lim t 0 + Θ ( t ) θ ( t ) = 0  and  lim t 0 + Θ ( t ) t θ ( t ) = 0 ;

  3. lim t 0 + t θ ( t ) θ ( t ) = ;

  4. θ R 0 , i.e., θ is rapidly varying to infinity at zero.

Proof.

  1. It follows from the definition of Λ that (i) holds.

  2. We conclude by (2.19) that there exists function ϑC(0, 1] satisfying ϑ(t) → 0 as t → 0+ such that

    d d t Θ ( t ) θ ( t ) = ϑ ( t ) , t > 0 .

    Further more, we have

    Θ ( t ) θ ( t ) = 0 t ϑ ( s ) d s .

    This implies that

    lim t 0 + Θ ( t ) θ ( t ) = 0 .

    By L’Hôpital’s rule, we obtain

    lim t 0 + Θ ( t ) t θ ( t ) = 0 .

  3. The result follows from (i)-(ii).

  4. It follows by (ii) that

    (10.1) lim t 0 + t 1 θ ( s ) d s θ ( t ) t = lim t 0 + 1 1 / t θ ( t τ ) θ ( t ) d τ = 0 .

    We prove for any μ ∈ (1, ∞), lim t 0 + θ ( μ t ) θ ( t ) = 0 . Suppose the contrary, that exist μ * > 1, ϱ * > 0 and some decreasing sequence, denoted by { t n } n = 1 with t n ∈ (0, 1) and t n → 0 as n → ∞ such that

    θ ( μ * t n ) θ ( t n ) > ϱ * .

    This fact, combined with (10.1), shows the contradiction

    0 = lim n 1 1 / t n θ ( t n τ ) θ ( t n ) d τ lim n 1 μ * θ ( t n τ ) θ ( t n ) d τ lim n 1 μ * θ ( t n μ * ) θ ( t n ) d τ ϱ * ( μ * 1 ) < 0 .

Lemma B.3.

Let f satisfy (f 1 ) (or (f 01 )), (f 2 ), (f 3 ) and (S 1 )(S 3 ), ψ be the unique solution of (2.2). Then

  1. ψ ( t ) = ( ψ ( t ) f 1 ( ψ ( t ) ) ) 1 / ( k + 1 ) and lim t 0 + ψ ( t ) = ;

  2. ( ψ ( t ) ) k 1 ψ ( t ) = 1 k + 1 ( f 1 ( ψ ( t ) ) + ψ ( t ) f 1 ( ψ ( t ) ) ) ;

  3. lim t ( g ( t ) ) 1 f 1 ( ξ t ) ξ k f 1 ( t ) 1 = ln ξ , ξ > 0 ;

  4. lim t f 2 ( ξ t ) ξ k g ( t ) f 1 ( t ) = C 2 , where ξ > 0 and C 2 is given by (2.3);

  5. lim t ( t f 1 ( t ) ) k / ( k + 1 ) g ( t ) f 1 ( t ) t ( s f 1 ( s ) ) 1 / ( k + 1 ) d s = 1 k + 1 + K g ;

  6. lim t 0 + ( g ( ψ ( t ) ) ) 1 1 k + 1 1 + ψ ( t ) f 1 ( ψ ( t ) ) f 1 ( ψ ( t ) ) f 1 ( ξ ψ ( t ) ) ξ k f 1 ( ψ ( t ) ) = 1 k + 1 ln ξ , ξ > 0 ;

  7. lim t 0 + f 2 ( ξ ψ ( t ) ) ξ k g ( ψ ( t ) ) f 1 ( ψ ( t ) ) = C 2 , where ξ > 0 and C 2 is given by (2.3);

  8. lim t 0 + ( ψ ( t ) f 1 ( ψ ( t ) ) ) k / ( k + 1 ) t g ( ψ ( t ) ) f 1 ( ψ ( t ) ) = 1 k + 1 + K g ;

  9. lim t 0 + ψ ( t ) ψ ( t ) t = 0 , lim t 0 + ψ ( t ) ψ ( t ) t = 0 and ψ , ψ , ψ R 0 ;

  10. lim t 0 + t g 2 ( ψ ( t ) ) = 0 ;

  11. lim t 0 + ψ ( t ) t ψ ( t ) t g ( ψ ( t ) ) = 0 .

Proof.

  • (i)(ii) By the definition of ψ and a direct calculation, we see that (i)-(ii) hold.

  • (iii) If ξ = 1, the result is obvious. If ξ ≠ 1, by fNRV k , we can see that

    (10.2) f 1 ( ξ t ) ξ k f 1 ( t ) 1 = exp t ξ t g ( τ ) τ d τ 1 , t t 0 .

    It follows by (f 3 ), gNRV 0 and Proposition A.2 that

    lim t g ( t s ) s = 0  and  lim t g ( t s ) g ( t ) = 1

    uniformly with respect to s ∈ [c 1, c 2], where c 1 and c 2 (c 2 > c 1) are positive constants. Hence we have

    lim t t t ξ g ( τ ) τ d τ = lim t 1 ξ g ( s t ) s d s = 0 .

    Moreover, by Proposition A.2, we have

    (10.3) lim t 1 ξ g ( s t ) s g ( t ) d s = 1 ξ s 1 d s = ln ξ .

    On the other hand, we see that

    (10.4) exp ( t ) 1 t  as  t 0

    and

    (10.5) lim t ( g ( t ) ) 1 exp t ξ t g ( τ ) τ d τ 1 t ξ t g ( τ ) τ d τ = 0 .

    It follows by (10.2)(10.5) that (iii) holds.

  • (iv) Since

    lim t f 2 ( ξ t ) ξ k g ( t ) f 1 ( t ) = lim t f 2 ( ξ t ) ξ k f 2 ( t ) lim t f 2 ( t ) g ( t ) f 1 ( t ) ,

    we see that if (S 2 ) holds, then

    lim t f 2 ( ξ t ) ξ k f 2 ( t ) = 1  and  lim t f 2 ( t ) g ( t ) f 1 ( t ) = C 1 ;

    if (S 3 ) holds, then

    lim t f 2 ( ξ t ) ξ k f 2 ( t ) = ξ μ k  and  lim t f 2 ( t ) g ( t ) f 1 ( t ) = 0 .

  • (v) By (f 3 ), (S 1 ) and L’Hôpital’s rule, we obtain

    lim t ( t f 1 ( t ) ) k / ( k + 1 ) g ( t ) f 1 ( t ) t ( s f 1 ( s ) ) 1 / ( k + 1 ) d s = lim t t k / ( k + 1 ) g ( t ) ( f 1 ( t ) ) 1 / ( k + 1 ) t ( s f 1 ( s ) ) 1 / ( k + 1 ) d s = lim t k k + 1 g ( t ) g ( t ) t 1 k + 1 g ( t ) f 1 ( t ) t f 1 ( t ) ( g ( t ) ) 2 = lim t g ( t ) t ( g ( t ) ) 2 + 1 k + 1 f 1 ( t ) t f 1 ( t ) k g ( t ) = 1 k + 1 + K g .

  • (vi)(viii) The results follow by (f 3 ) and (iii)(v).

  • (ix) By (f 3 ) and (S 1 ), we have

    (10.6) lim t 0 + ψ ( t ) f 1 ( ψ ( t ) ) f 1 ( ψ ( t ) ) = k .

    It follows by (i)(ii) and (viii) (or (v)) that

    lim t 0 + ψ ( t ) t ψ ( t ) = lim t 0 + ( k + 1 ) ( ψ ( t ) f 1 ( ψ ( t ) ) ) k / ( k + 1 ) f 1 ( ψ ( t ) ) 1 + ψ ( t ) f 1 ( ψ ( t ) ) f 1 ( ψ ( t ) ) t g ( ψ ( t ) ) g ( ψ ( t ) ) = 0

    and

    lim t 0 + ψ ( t ) t ψ ( t ) = lim t 0 + ( ψ ( t ) f 1 ( ψ ( t ) ) ) k / ( k + 1 ) f 1 ( ψ ( t ) ) g ( ψ ( t ) ) t g ( ψ ( t ) ) = 0 .

    Moreover, by the similar argument as the proof of Lemma B.2 (iv), we have ψ , ψ R 0 . Furthermore, by the Definition A.1 and the L’Hôpital’s rule, we obtain ψ R 0 .

  • (x) A straightforward calculation shows that

    lim t 0 + t g 2 ( ψ ( t ) ) = lim t 0 + 2 g ( ψ ( t ) ) g ( ψ ( t ) ) ψ ( ψ ( t ) ) 1 = lim s 2 g ( s ) g ( s ) ( s f 1 ( s ) ) 1 / ( k + 1 ) 1 = lim s 2 g ( s ) s g 2 ( s ) ( s f 1 ( s ) ) 1 / ( k + 1 ) g 3 ( s ) s 1 = lim s s k f 1 ( s ) ( g ( s ) ) 3 ( k + 1 ) 1 / ( k + 1 ) = 0 .

  • (xi) Since 1 k + 1 + K g 0 (see (S 1 ) on page 4), we obtain by (viii), (x) and (10.6) that

    lim t 0 + t ψ ( t ) ψ ( t ) t g ( ψ ( t ) ) = lim t 0 + f 1 ( ψ ( t ) ) 1 + ψ ( t ) f 1 ( ψ ( t ) ) f 1 ( ψ ( t ) ) t g ( ψ ( t ) ) ( k + 1 ) ( ψ ( t ) f 1 ( ψ ( t ) ) ) k / ( k + 1 ) t g 2 ( ψ ( t ) ) = lim t 0 + 1 k + 1 + K g 1 t g 2 ( ψ ( t ) ) = 0 .

Lemma B.4.

Under the hypotheses in Theorem 2.5, we have

  1. lim t f ( L ( t ) ) t k + 1 k ( L ( t ) ) = 1 k + 1 ;

  2. f ̂ 1 N R V 0 and ( f ̂ 1 ) N R V 1 ;

  3. f ̂ L N R V k + 1 ;

  4. L N R V 0 and L N R V 1 , i.e., lim t t L ( t ) L ( t ) = 1 .

Proof.

  1. By (2.8), we have

    (10.7) t L ( t ) ( L ( t ) ) = ( k + 1 ) f ̂ ( L ( t ) ) t k + 1 k ( L ( t ) ) .

    This fact, combined with (2.9), implies that (i) holds.

  2. By the definition of f ̂ in (2.6), we see that the inverse of f ̂ denoted by f ̂ 1 is the unique solution of the following integral equation

    exp B f ̂ 1 ( t ) d s T ( s ) = t , t > 0 .

    A simple calculation shows that

    lim t t ( f ̂ 1 ( t ) ) f ̂ 1 ( t ) = lim t T ( f ̂ 1 ( t ) ) f ̂ 1 ( t ) = lim t T ( t ) = 0

    and

    lim t t ( f ̂ 1 ( t ) ) ( f ̂ 1 ( t ) ) = lim t ( T ( f ̂ 1 ( t ) ) 1 ) = 1 .

    From Proposition A.5, we see that f ̂ 1 N R V 0 and ( f ̂ 1 ) N R V 1 .

  3. In (2.8), letting τ = f ̂ ( s ) , a direct calculation shows that

    (10.8) L ( t ) k 1 ( s ) f ̂ ( s ) d s = f ̂ ( L ( t ) ) k 1 ( f ̂ 1 ( τ ) ) ( f ̂ 1 ( τ ) ) τ d τ = 1 t k + 1 , t > 0 .

    Let

    A ( t ) = t k 1 ( f ̂ 1 ( τ ) ) ( f ̂ 1 ( τ ) ) τ d τ .

    Since NRV 0, f ̂ 1 N R V 0 and ( f ̂ 1 ) N R V 1 , by Propositions A.6, A.7, we arrive at

    ( k 1 f ̂ 1 ) ( f ̂ 1 ) N R V 1 .

    So, there exist some constant a > 0 and L NRV 0 such that

    k 1 ( f ̂ 1 ( t ) ) ( f ̂ 1 ( t ) ) = t 1 L ( t ) , t > a .

    It follows by using Proposition A.9 (i) that

    lim t t A ( t ) A ( t ) = 1 ,

    i.e., A N R V 1 . This together with (10.8) implies that A f ̂ L N R V ( k + 1 ) . Let A 1 denote the inverse of A , then A 1 is the unique solution of the following integral equation

    A 1 ( t ) k 1 ( f ̂ 1 ( τ ) ) ( f ̂ 1 ( τ ) ) τ d τ = A 1 ( t ) τ 2 L ( τ ) d τ = t .

    By using Proposition A.9 (i) and a direct calculation, we obtain

    lim t t ( A 1 ( t ) ) A 1 ( t ) = 1 ,

    i.e., A 1 N R V 1 . It follows by Proposition A.6 that

    f ̂ L = A 1 A f ̂ L N R V k + 1 .

  4. It follows by (ii), (iii) and Proposition A.6 that L = f ̂ 1 ( f ̂ L ) N R V 0 . In view of (2.8), we obtain

    L ( t ) k 1 ( L ( t ) ) + ( k 1 ) ( L ( t ) ) 2 k 2 ( L ( t ) ) ( L ( t ) ) = ( k + 1 ) ( k + 2 ) t k 3 f ̂ ( L ( t ) ) + ( k + 1 ) t k 2 ( f ̂ ( L ( t ) ) ) .

    We conclude by NRV 0, L N R V 0 , (10.7) and (iii) that

    lim t t L ( t ) L ( t ) = lim t ( L ( t ) ) L ( t ) ( L ( t ) ) t L ( t ) L ( t ) k 2 + lim t ( k + 1 ) t k 2 f ̂ ( L ( t ) ) k 1 ( L ( t ) ) L ( t ) f ̂ ( L ( t ) ) t f ̂ ( L ( t ) ) = 1 .

Lemma B.5.

(Lemma 2.3 of [63]) Let L L (see Remark 2.6), then

lim t 0 + L ( t ) t s 0 L ( s ) s d s = 0 .

If we further assume L L 1 , then

lim t 0 + L ( t ) 0 t L ( s ) s d s = 0 .

Lemma B.6.

Let f ̃ C [ 0 , ) R V Z p 0 R V p ( p 0 k and p < k) be positive on (0, ∞). We need to verify (2.13) if p 0 = k, F ̃ is given by (2.13). Then

  1. lim t 0 + ( F ̃ ( t ) ) 1 / ( k + 1 ) t = ;

  2. lim t 0 + F ̃ ( t ) t f ̃ ( t ) = 1 1 + p 0  and  lim t F ̃ ( t ) t f ̃ ( t ) = 1 1 + p ;

  3. lim t 0 + ( F ̃ ( t ) ) 1 / ( k + 1 ) t 0 t ( F ̃ ( s ) ) 1 / ( k + 1 ) d s = ,  if  f ̃ R V Z k , k + 1 k p 0 ,  if  f ̃ R V Z p 0  with  p 0 < k and

    lim t ( F ̃ ( t ) ) 1 / ( k + 1 ) t 0 t ( F ̃ ( s ) ) 1 / ( k + 1 ) d s = k + 1 k p .

  4. lim t 0 + ( k + 1 ) ( F ̃ ( t ) ) k / ( k + 1 ) f ̃ ( t ) 0 t ( F ̃ ( s ) ) 1 / ( k + 1 ) d s = k p 0 p 0 + 1 and lim t ( k + 1 ) ( F ̃ ( t ) ) k / ( k + 1 ) f ̃ ( t ) 0 t ( F ̃ ( s ) ) 1 / ( k + 1 ) d s = k p p + 1 .

Proof.

  1. We assume that it is false. This implies that there exist a positive constant c ̃ and an increasing sequence { t n } n = 1 of real numbers satisfying lim n→∞ t n = 0 and 2t n+1t n , n = 1, 2, ⋅⋅⋅, such that

    ( F ̃ ( t n ) ) 1 / ( k + 1 ) 1 / ( t n c ̃ ) .

    A direct calculation shows that

    > 0 t 1 ( F ̃ ( s ) ) 1 / ( k + 1 ) d s = n = 1 t n + 1 t n ( F ̃ ( s ) ) 1 / ( k + 1 ) d s n = 1 t n + 1 t n ( F ̃ ( t n ) ) 1 / ( k + 1 ) d s n = 1 t n + 1 t n 1 / ( t n c ̃ ) d s = i = 1 c ̃ 1 t n t n + 1 t n lim n n 2 c ̃ = .

    This is a contradiction. So, (i) holds.

  2. Since F ̃ ( t ) = 0 t f ̃ ( s ) d s , by the Lebesgue’s dominated convergence theorem we obtain

    lim t 0 + F ̃ ( t ) t f ̃ ( t ) = lim t 0 + 0 1 f ̃ ( t s ) f ̃ ( t ) d s = 0 1 s p 0 d s = 1 1 + p 0

    and

    lim t F ̃ ( t ) t f ̃ ( t ) = lim t 0 1 f ̃ ( t s ) f ̃ ( t ) d s = 0 1 s p d s = 1 1 + p .

  3. Because of (i), we can apply L’Hôpital’s rule to get

    lim t 0 + 0 t ( F ̃ ( s ) ) 1 / ( k + 1 ) d s t ( F ̃ ( t ) ) 1 / ( k + 1 ) = lim t 0 + 1 f ̃ ( t ) t ( k + 1 ) F ̃ ( t ) 1 = ,  if  f ̃ R V Z k , k + 1 k p 0 ,  if  f ̃ R V Z p 0  with  p 0 < k .

    On the other hand, since f ̃ R V p with p < k, we get

    lim t 0 t ( F ̃ ( s ) ) 1 / ( k + 1 ) d s = .

    It follows from L’Hôpital’s rule, we obtain

    lim t 0 t ( F ̃ ( s ) ) 1 / ( k + 1 ) d s t ( F ̃ ( t ) ) 1 / ( k + 1 ) = lim t t ( F ̃ ( t ) ) 1 / ( k + 1 ) 0 t ( F ̃ ( s ) ) 1 / ( k + 1 ) d s 1 = lim t 1 f ̃ ( t ) t ( k + 1 ) F ̃ ( t ) 1 = k + 1 k p .

  4. The results follow from (ii), (iii).□

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Received: 2023-03-21
Accepted: 2024-02-18
Published Online: 2024-04-03

© 2024 the author(s), published by De Gruyter, Berlin/Boston

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